\documentclass[reqno]{amsart}
\usepackage{hyperref}

\AtBeginDocument{{\noindent\small
\emph{Electronic Journal of Differential Equations},
Vol. 2018 (2018), No. 98, pp. 1--19.\newline
ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu}
\thanks{\copyright 2018 Texas State University.}
\vspace{8mm}}

\begin{document}
\title[\hfilneg EJDE-2018/98\hfil Bifurcation of solutions from infinity]
{Bifurcation of solutions from infinity for certain nonlinear
eigenvalue problems of fourth-order ordinary differential equations}

\author[Z. S. Aliyev, N. A. Mustafayeva \hfil EJDE-2018/98\hfilneg]
{Ziyatkhan S. Aliyev, Natavan A. Mustafayeva}

\address{Ziyatkhan S. Aliyev \newline
Baku State University, Baku AZ1148, Azerbaijan.\newline
IMM NAS Azerbaijan, Baku, AZ1141, Azerbaijan}
\email{z\_aliyev@mail.ru}

\address{Natavan A. Mustafayeva \newline
Ganja State University, Ganja, AZ2000, Azerbaijan}
\email{natavan1984@gmail.com}

\dedicatory{Communicated by Paul H. Rabinowitz}

\thanks{Submitted January 26, 2018. Published April 27, 2018.}
\subjclass[2010]{34B24, 34C23, 34L15, 34L30, 47J10, 47J15}
\keywords{Nonlinear eigenvalue problems; bifurcation point; bifurcation interval;
\hfill\break\indent  bifurcation from infinity; global continua;
 nodal properties of solutions}

\begin{abstract}
 In this article, we study the global bifurcation from infinity of nonlinear
 eigenvalue problems for ordinary differential equations of fourth order.
 We prove the existence of unbounded continua of solutions emanating from
 asymptotically bifurcation points and intervals and having the usual nodal
 properties near these points and intervals.
\end{abstract}

\maketitle
\numberwithin{equation}{section}
\newtheorem{theorem}{Theorem}[section]
\newtheorem{lemma}[theorem]{Lemma}
\newtheorem{remark}[theorem]{Remark}
\newtheorem{corollary}[theorem]{Corollary}
\newtheorem{example}[theorem]{Example}
\allowdisplaybreaks

\section{Introduction}

We consider the  nonlinear eigenvalue problem
\begin{gather} \label{EQ11}
\ell y \equiv (py'')''  -(qy')' + r (x) y = \lambda \tau y
+ h (x, y, y', y'',y''',\lambda),\quad x \in (0, l), \\
 \label{EQ12}
\begin{gathered}
y'(0)\cos \alpha -(py'')(0)\sin \alpha = 0, \quad
y(0)\cos \beta + Ty(0)\sin \beta = 0, \\
y'(l)\cos \gamma + (py'')(l)\sin \gamma = 0, \quad
y(l)\cos \delta -Ty(l)\sin \delta =0,
\end{gathered}
\end{gather}
where $\lambda \in{\mathbb R}$ is a spectral parameter, $Ty\equiv (p y'')'-q y'$,
$p$ is positive, twice continuously differentiable function on $[0, l]$, $q$
is nonnegative, continuously differentiable function on $[0, l]$, $r$ is
real-valued continuous function on $[0, l]$, $\tau$ is positive continuous
function  on $[0, l]$ and $\alpha,\beta, \gamma,\delta \in [0,\pi/2]$.
The nonlinear term $h$ has the form $h = f + g$, where $f$ and $g$ are
real-valued continuous functions on $[0, l] \times \mathbb{R}^5$,
satisfying the conditions: there exists $M > 0$ and sufficiently large
$c_0 > 0$ such that
\begin{equation}\label{EQ13}
\begin{gathered}
\big| {\frac{{f(x,y,s,v,w,\lambda )}}{y}} \big| \le M,\\
 x \in [0,l],\; y,s,v,w \in \mathbb{R},\;
|y|+|s|+|v|+|w| \ge c_0,\; \lambda  \in \mathbb{R};
\end{gathered}
\end{equation}
for any bounded interval $\Lambda \subset \mathbb{R}$
\begin{equation}\label{EQ14}
g(x,y,s,v,w,\lambda ) = o(|y|+|s|+|v|+|w|)\quad \text{as }
|y|+|s|+|v|+ |w| \to \infty,
\end{equation}
uniformly for $x \in [0, l]$ and $\lambda \in \Lambda$.

In nonlinear analysis an important role is played by bifurcation theory
of nonlinear eigenvalue problems. The study of bifurcation of nonlinear
eigenvalue problems has an applied interest since problems of this type
arise in almost all fields of natural science (see, for example,
\cite{a3,a4,a5,a6,d2,k2}).
 Recently, in this direction have been obtained fundamental results for
a wide class of eigenvalue problems which are reflected in
\cite{a1,a2,a3,a4,a5,a6,b2,c2,d1,d2,g1,k2,k5,l1,l3,m1,m2,p2,p3,r1,r2,
 r3,r4,r5,r6,s1,s2,t1}
and some others.

In studying the global bifurcation of solutions of nonlinear eigenvalue
problems for ordinary differential equations, the nodal properties of
the solutions allow a more detailed analysis of the structure and behavior
 of connected components of a set of nontrivial solutions.
The oscillatory properties for the eigenfunctions of the ordinary
differential operators of the second and higher orders by various
methods were investigated by Sturm \cite{s3}, Kellogg \cite{k3,k4},
Pr\"{u}fer \cite{p1}, Gantmakher and Kerin \cite{g2}, Karlin \cite{k1},
Levin and Stepanov \cite{l2}, Elias \cite{e1}, Banks and Kurowski \cite{b1}.

If the continuous functions $f$ and $g$ on $[0, l] \times \mathbb{R}^{5}$ satisfy
the conditions
\begin{gather}\label{EQ15}
\big| {\frac{{f(x,y,s,v,w,\lambda )}}{y}} \big| \le M,\quad x \in [0,l],\;
0 < |y| \le 1, \; |s|,|v|,|w|\le 1,\; \lambda \in \mathbb{R},\\
 \label{EQ16}
g(x,y,s,v,w,\lambda ) = o(|y|+|s|+|v|+|w|)\quad\text{as}\quad|y|+|s|+|v|+ |w| \to 0,
\end{gather}
uniformly for $x \in [0, l]$ and $\lambda \in \Lambda$, then we can
 consider bifurcation from $y = 0$. Similar problems for Sturm-Liouville
equation have been considered before by Rabinowitz \cite{r1},
Berestycki \cite{b2}, Schmitt and Smith \cite{s1}, Rynne \cite{r4},
Ma and Dai \cite{m1}.
These authors prove the existence of two families of global continua of
solutions in $\mathbb{R} \times C^{1}$, corresponding to the usual nodal
properties and bifurcating from the eigenvalues and intervals
(in $\mathbb{R} \times \{0\}$, which we identify with $\mathbb{R}$)
surrounding the eigenvalues of the corresponding linear problem.
In \cite{a3,a4,a5,a6},
some elasticity models were studied that include higher-order
differential equations and nodal properties. In these papers,
using the nodal properties, were obtained similar global bifurcation
 results for the solutions of the considered mathematical models.
Similar results were also demonstrated in \cite{r6} for nonlinear eigenvalue
 problems for a special class of ordinary differential equations of
$2m$th order. But until recently it was not possible to obtain
similar results for the problem \eqref{EQ11}-\eqref{EQ12}
 under the conditions \eqref{EQ15} and \eqref{EQ16}.

Note that in nonlinear eigenvalue problems for ordinary differential equations
 of fourth order, the nodal properties of the solutions need not be
 preserved along continua, so it is not possible to investigate in detail
the structure and behavior of global continua of solutions using the
techniques of \cite[Theorem 2.3]{r1}.
Przybycin \cite{p3}, Lazer and McKenna \cite{l1}, Rynne \cite{r5,r6}, Ma and
Thompson \cite{m2}  obtained results similar to the
results by Rabinowitz \cite[Theorem 2.3]{r1},
for nonlinear eigenvalue problems of fourth order
(in the case of $f \equiv 0$).
In these papers for the
nonlinear term $g$ is used the smallness condition at $y = 0$ of the
form $g (x, y, s, v, w, \lambda) = o (|y|)$ to obtain the preservation of
nodal properties.

In recent papers by Aliyev \cite{a2}, the global bifurcation of solutions of
problem \eqref{EQ11}-\eqref{EQ12} (in the case of $r \equiv 0$)
under the conditions \eqref{EQ15} and \eqref{EQ16} is completely
investigated. To preserve the nodal properties in \cite{a2} by using an extension
of the Pr\"{u}fer transformation, the author constructed sets
$S_k^{\nu}$, $k \in \mathbb{N}$, $\nu =\{+,-\}$, of functions in
 Banach space $E = C^{3}[0,l] \cap B.C.$ with the usual norm
$\|\cdot\|_{3}$, where $\|y\|_{i}  = \sum_{j = 0}^i {\|y^{(j)} \|_\infty}$,
$i \in \mathbb{N}$, $\|y\|_\infty   = \max_{x \in [0, l]} |y(x)| $,
B.C.  is the set of functions satisfying boundary conditions \eqref{EQ12},
that have the nodal properties of eigenfunctions of the linear problem
\eqref{EQ11}-\eqref{EQ12} with $h \equiv 0$ and their derivatives
\cite[\S 3.1]{a2}. In this paper (see also \cite{a1}) the existence of two families
of unbounded continua of solutions of problem \eqref{EQ11}-\eqref{EQ12}
contained in these sets and bifurcating from the points and intervals of
the line of trivial solutions is proved.

If condition \eqref{EQ13} and \eqref{EQ14} hold, then we can consider
bifurcation from $y = \infty$. Similar problems for Sturm-Liouville equation
have been considered by Toland \cite{t1}, Stuart \cite{s2}, Rabinowitz \cite{r2},
Przbycin \cite{p2}, Rynne \cite{r3,r4}, Ma and Dai \cite{m1}. For such problems these authors
show the existence of two families of unbounded continua of solutions bifurcating
from the points and intervals in  $\mathbb{R} \times \{\infty\}$ and having the
usual nodal properties in the neighborhood of these points and intervals.
(However, the proofs of these assertions carried out in
\cite[Theorems 2.2 and 2.3]{m1} and \cite[Theorem 2]{p2} contain gaps.
In these papers the nonlinear term $f$ has a sublinear growth with respect
to $y$ satisfying $|y| > c_0$ and $|y'| > c_0$.
It follows from proofs of these theorems that if the solution $(\lambda, y)$
is near to the bifurcation interval (in $\mathbb{R} \times \{\infty\}$)
corresponding to the $k$th eigenvalue of the linear Sturm-Liouville problem
and is contained in a connected component of nontrivial solutions emanating
from this interval, then the function $y$ has exactly $k -1$ simple zeros
in $(0,l)$. But it is obvious that this function $y$ can not satisfy
the conditions $|y| > c_0$ and $|y'|>c_0$ for $k >1$.) It should be noted
that only Przybycin \cite{p3} for a special class of nonlinear fourth order
eigenvalue problems (in the case of $f \equiv 0$) demonstrates a similar
result using the smallness condition at $y = \infty$ of the form
$ g (x, y, s, v, w, \lambda) = o (|y|) $ for the nonlinear term $g$.

The purpose of this paper is to study the bifurcation of solutions of
 problem \eqref{EQ11}-\eqref{EQ12} in the cases:
(i) $f \equiv 0$ and for $g$ only the condition \eqref{EQ14} holds;
(ii) $f \equiv 0$ and for $g$ both of the conditions \eqref{EQ14}
and \eqref{EQ16} hold;
(iii) $f \not \equiv 0$ and for $f$ and $g$ the conditions \eqref{EQ13}
 and \eqref{EQ14} hold, respectively.

This paper is arranged as follows. In Section 2, we give some statements
for the problem \eqref{EQ11}-\eqref{EQ12} under
conditions \eqref{EQ15} and \eqref {EQ16},
which we will need in the sequel.
In Section 3 the existence of two families of unbounded continua of
solutions of problem \eqref{EQ11}-\eqref{EQ12} with $f \equiv 0$
under the condition \eqref{EQ14}, bifurcating from infinity and
having usual nodal properties in a neighborhood of infinity is proved.
In Section 4, problem \eqref{EQ11}-\eqref{EQ12} with
$f \equiv 0$ is considered when both conditions \eqref{EQ14}
and \eqref{EQ15} hold.
In Section 5, by extending the approximation technique from \cite{b2}
and combining it with the global bifurcation results in \cite{a2,d1,r1,r4},
we prove the existence of global sets of solutions of
problem \eqref{EQ11}-\eqref{EQ12} bifurcating from intervals
(in $\mathbb{R} \times \{\infty\}$) which are similar to those obtained
in \cite{r2,r4}.

\section{Preliminary results}

By  \cite[Theorem 1.2]{a2} the eigenvalues of the linear problem
\begin{equation}\label{EQ21}
\begin{gathered}
\ell (y)(x) = \lambda \tau (x) y(x), \quad x \in (0, l), \\
y \in B.C.\,,\\
\end{gathered}
\end{equation}
are real and simple and form an infinitely increasing sequence
$\{\lambda_k\}_{k = 1}^{\infty}$. Moreover, for each $k \in \mathbb{N}$
the eigenfunction $y_k (x)$ corresponding to the eigenvalue $\lambda_k$
lies in $S_k$ (therefore $y_k (x)$ has $k-1$ simple nodal zeros in
the interval $(0, l)$).

\begin{lemma}[{\cite[Lemma 2.2]{a2}}]  \label{lem2.1}
If $y \in \partial S_k^{\nu}$, $k \in \mathbb{N}$, $\nu \in \{+,-\}$,
 then $y(x)$ has at least one zero with multiplicity four on the
interval $[0, l]$.
\end{lemma}

Let $\mathcal{C} \subset \mathbb{R} \times E$ denote the set of solutions
of problem \eqref{EQ11}-\eqref{EQ12}. We say $(\lambda, \infty)$
is a bifurcation point (or asymptotic bifurcation point) for problem
\eqref{EQ11}-\eqref{EQ12} if every neighborhood of $(\lambda, \infty)$
contains solutions of this problem, i.e. there exists a sequence
$\{(\lambda_n, u_n)\}_{n=1}^{\infty} \subset \mathcal{C}$ such that
$\lambda_n \to \lambda$ and $\|u_n\|_3 \to +\,\infty$ as $n \to \infty$
(we add the points $\{(\lambda, \infty) : \lambda \in \mathbb{R}\}$ to space
$\mathbb{R} \times E$). Next for any $\lambda \in \mathbb{R}$, we say that
a subset $D \subset \mathcal{C}$ meets $(\lambda,\infty)$
(respectively, $(\lambda,0))$ if there exists a sequence
$\{(\lambda_n, u_n)\}_{n=1}^{\infty} \subset D$ such that
$\lambda_n \to \lambda$ and $\|u_n\|_3 \to +  \infty$
(respectively, $\|u_n\|_3 \to 0$) as $n \to \infty$.
Furthermore, we will say that $D \subset \mathcal{C}$ meets
$(\lambda,\infty)$ (respectively, $(\lambda,0))$ through
$\mathbb{R} \times S_k^{\nu}, k \in \mathbb{N}, \nu \in \{+,-\}$,
if the sequence $\{(\lambda_n, u_n)\}_{n=1}^{\infty} \subset D$
 can be chosen so that $u_n \in S_k^\nu$ for all $n \in \mathbb{N}$
(in this case we also say that $(\lambda,\infty)$ (respectively, $(\lambda,0))$
is a bifurcation point of \eqref{EQ11}-\eqref{EQ12} with respect to
the set $\mathbb{R} \times S_k^{\nu}$). If $I \in \mathbb{R}$ is a bounded
interval we say that $D \subset \mathcal{C}$ meets $I \times \{\infty\}$
(respectively, $I \times \{0\}$) if $D$ meets $(\lambda,\infty)$
(respectively, $(\lambda,0))$ for some $\lambda \in I$; we define
$D \subset \mathcal{C}$ meets $I \times \{\infty\}$
(respectively, $I \times \{0\}$) through $\mathbb{R} \times S_k^{\nu}$,
$k \in \mathbb{N}$, $\nu \in \{+,-\}$,
similarly (see \cite{r4}).

We suppose that the conditions \eqref{EQ15} and \eqref{EQ16} hold.
Then we have the following results.

\begin{theorem} \label{thm2.1}
 Let $f \equiv 0$. Then for each $k \in \mathbb{N}$ and each
$\nu \in \{+,-\}$ there exists a continuum $\mathfrak{L}_k^{\nu}$ of solutions
of problem \eqref{EQ11}-\eqref{EQ12} in
$(\mathbb{R} \times S_k^{\nu}) \cup \{(\lambda_k,0)\}$ which meets
 $(\lambda_k,0)$ and $\infty$ in $\mathbb{R} \times E$.
\end{theorem}

\begin{lemma} \label{lem2.2}
For each $k \in \mathbb{N}$ and each $\nu \in \{+,-\}$ the set of
bifurcation points for problem \eqref{EQ11}-\eqref{EQ12}
 with respect to the set $\,\mathbb{R} \times S_k^{\nu}$ is nonempty.
\end{lemma}

\begin{lemma} \label{lem2.3}
If $(\lambda, 0)$ is a bifurcation point for problem
\eqref{EQ11}-\eqref{EQ12} with respect to the set
$\mathbb{R} \times S_k^{\nu}, k \in \mathbb{N}, \nu \in \{+,-\}$,
then $\lambda \in I_k$, where
$I_k = [\lambda_k - \frac{M}{\tau_0},\lambda_k - \frac{M}{\tau_0}]$,
 $\tau_0 = \min _{x \in [0, l]} \tau (x)$.
\end{lemma}

For each $k \in \mathbb{N}$ and each $\nu \in \{+,-\}$,
 let $\tilde D_k^{\nu}$ denote the union of all the connected components
$D_{k,\lambda}^{\nu}$ of $\mathcal{C}$ emanating from bifurcation points
$(\lambda, 0) \in I_k \times \{0\}$ with respect to $\mathbb{R} \times S_k^{\nu}$.
Let $D_k^{\nu} = \tilde D_k^{\nu} \cup (I_k \times \{0\})$.
Note that $D_k^{\nu}$ is a connected subset of $\mathbb{R} \times E$,
but $\tilde D_k^{\nu}$ is not necessarily connected in $\mathbb{R} \times E$.

\begin{theorem} \label{thm2.2}
For each $k \in \mathbb{N}$ and each $\nu \in \{+,-\}$ the connected component
$D_k^{\nu}$ of $\mathcal{C}$ lies in
$(\mathbb{R} \times S_k^{\nu}) \cup (I_k \times \{0\})$ and is unbounded
in $\mathbb{R} \times E$.
\end{theorem}

The proofs of Theorem \ref{thm2.1}, Lemmas \ref{lem2.2} and  \ref{lem2.3} and
Theorem \ref{thm2.2} are similar to those
of \cite[Theorem 1.1]{a2}, \cite[Lemmas 5.3, 5.4]{a2} and
\cite[Theorem 1.3]{a2}, respectively,
by using \cite[Theorem 1.2]{a2}.


\section{Global bifurcation from infinity of solutions of problem
\eqref{EQ11}-\eqref{EQ12} for $f \equiv 0$}

Throughout this section we assume that only condition \eqref{EQ14} holds.
For any set $A \subset \mathbb{R} \times E$ we let $P_R (A)$ denote
the natural projection of $A$ onto $\mathbb{R} \times \{0\}$.

\begin{theorem} \label{thm3.1}
For each $k \in \mathbb{N}$ and each $\nu \in \{+,-\}$ there exists a
connected component $\mathcal{C}_k^{\nu}$ of $\mathcal{C}$ which meets
$(\lambda_k,\infty)$ and has the following properties:
\begin{itemize}
\item[(i)] there exists a neighborhood $Q_k$ of $(\lambda_k,\infty)$ in
$\mathbb{R} \times E$ such that
\[
Q_k \cap (\mathcal{C}_k^{\nu} \backslash (\lambda_k,\infty))
\subset \mathbb{R} \times S_k^{\nu};
\]

\item[(ii)] either $\mathcal{C}_k^{\nu}$ meets $\mathcal{C}_{k'}^{\nu'}$ through
$\mathbb{R} \times S_{k'}^{\nu'}$ for some $(k',\nu') \ne (k,\nu)$, or
$\mathcal{C}_k^{\nu}$ meets $(\lambda,0)$ for some $\lambda \in \mathbb{R}$,
or $P_R(\mathcal{C}_k^{\nu})$ is unbounded.
\end{itemize}
\end{theorem}

\begin{proof}
Assume that $\lambda = 0$ is not an eigenvalue of \eqref{EQ21}.
Then  problem \eqref{EQ11}-\eqref{EQ12}
can be converted to the equivalent integral equation
\begin{equation} \label{EQ31}
y (x)=\lambda \int _{0}^{l} K (x, t) \tau (t) y(t) dt
+\int _{0}^{1} K (x, t) \,g (t,y(t),y'(t),y''(t),y'''(t),\lambda ) dt,
\end{equation}
where $K (x, t)$ is the Green's function for the differential expression
$\ell (y)$ with boundary conditions \eqref{EQ12}.
Hence, it is sufficient to search for solution of
\eqref{EQ11}-\eqref{EQ12} in $\mathbb{R} \times E$.

Let the operator $L : E \to E$ be defined by
\[
(Ly) (x) = \int _{0}^{l} K (x, t) \tau (t) y(t) dt ,
\]
and $G : \mathbb{R} \times E \to E$ by
\[
(G (\lambda, y)) (x) =\int _{0}^{l} K (x, t) g (t, y (t), y'(t), y''(t), y'''(t),
\lambda ) dt.
\]
Hence the problem \eqref{EQ31} can be rewritten in the following form
\begin{equation} \label{EQ32}
y = \lambda Ly + G(\lambda,y).
\end{equation}
It is clear that $L$ is compact and linear in $E$ and has characteristic
values $\lambda_1$, \dots, $\lambda_k$, \dots,
which are the eigenvalues of the linear problem \eqref{EQ21}.
 The map $G$ is continuous on $\mathbb{R} \times E$. Using \eqref{EQ14}
and following
the corresponding arguments carried out in the proof of \cite[Theorem 2.4]{r2},
 we can show that
\begin{equation} \label{EQ33}
G(\lambda,y) = o(\|y\|_3) \quad \text{at } y = \infty,
\end{equation}
uniformly on bounded $\lambda$-intervals and
$\|y\|_3^{2}\, G (\lambda, \frac {y}{\|y\|_3^{2}}) \equiv H(\lambda,y)$
is compact in $E$.

For any nontrivial $(\lambda, y) \in \mathbb{R} \times E$ setting
$v = \frac {y}{\|y\|_3^2}$, we have $\|v\|_3 = \frac {1}{\|y\|_3}$ and
$y = \frac {v}{\|v\|_3^2}$. Dividing \eqref{EQ32} by $\|y\|_3^2$
yields the equation
\begin{equation} \label{EQ34}
v = \lambda L v + H (\lambda,v).
\end{equation}
Let $H (\lambda,0) = 0$. By our basic assumptions the operator
$H : \mathbb{R} \times E \to E$ is continuous and satisfy
\begin{equation} \label{EQ35}
H (\lambda,v) = o(\|v\|_3) \quad \text{at } v = 0,
\end{equation}
uniformly on bounded $\lambda$-intervals.

The transformation $(\lambda,y) \to  T (\lambda,y) = (\lambda,v)$
which was used in the papers \cite{r2,r4,s2,t1} turns a bifurcation
from infinity problem \eqref{EQ32} into a bifurcation from zero
problem \eqref{EQ34}. By  \eqref{EQ35}
 the global bifurcation results in \cite{d1} and \cite{r1} are applicable
to problem \eqref{EQ34}.

Let $ \mathcal{\tilde C} \subset \mathbb{R} \times E$ be the set of
nontrivial solutions of problem \eqref{EQ34}. By construction,
the transformation $(\lambda,y) \to  T (\lambda,y)$ maps $\mathcal{C}$ into
$\mathcal{\tilde C}$ and, heuristically, interchanges points at $y = \infty$
(respectively, $y = 0$) with points at $v = 0$ (respectively, $v = \infty$).
By \cite[Theorem 2]{d1} and \cite[Lemmas 1.24, 1.27 and Theorem 1.40]{r1}
for each $k \in \mathbb{N}$ and each $\nu \in \{+,-\}$ there exists a
connected component $\mathcal{\tilde C}_k^{\nu}$ of $\mathcal{\tilde C}$
with meets $(\lambda_k, 0)$ and has the following properties:
(a) there  exists a neighborhood $\tilde Q_k$ of $(\lambda_k, 0)$ in
 $\mathbb{R} \times E$  such that $\tilde Q_k \cap \left( {\mathcal{\tilde C}_k^{\nu}
 \backslash (\lambda_k,0)} \right) \subset \mathbb{R} \times S_k^{\nu}$;
(b) either $\mathcal{\tilde C}_k^{\nu}$ meets $\mathcal{\tilde C}_{k'}^{\nu'}$
respect to $\mathbb{R} \times S_{k'}^{\nu'}$ for some $(k',\nu') \ne (k,\nu)$,
or $\mathcal{\tilde C}_k^{\nu}$ is unbounded in $\mathbb{R} \times E$
(that is, there exists a sequence
$(\lambda_{k, n},v_{k, n}) \in \mathcal{\tilde C}_k^{\nu}$, $n=1, 2, 3, \dots$,
 such that $|\lambda_{k, n}| + \|v_{k, n}\|_3 \to +\infty$ as $n \to \infty$).
Then $\mathcal{C}_k^{\nu}$ and $Q_k$ are the inverse image
$T^{-1} (\mathcal{\tilde C}_k^{\nu})$ of $\mathcal{\tilde C}_k^{\nu}$ and
$T^{-1} (\tilde Q_k)$ of $\tilde Q_k$ under the transformation $T$ respectively.
Thus the statements (i) and (ii) of the theorem follows from properties
(a) and (b) of $\mathcal{\tilde C}_k^{\nu}$ respectively
(second and third alternatives in part (ii) of the theorem for correspond,
via $T$, to the various ways in which $\mathcal{C}_k^{\nu}$ can be unbounded).

Next, using the above ideas, together with an approximation argument
(see \cite[p. 468]{r2}) we can show that the statements of this theorem
are true also in the degenerate case in which $0$ is an eigenvalue of
linear problem \eqref{EQ21}. The proof is complete.
\end{proof}

\begin{remark} \label{rmk3.1}\rm
Unlike in the case of bifurcation from zero in Theorem \ref{thm2.1},
for bifurcation from infinity it need not be the case that
$\mathcal{C}_k^{\nu} \subset (\mathbb{R} \times S_k^{\nu})
\cup \{(\lambda_k ,\infty)\}$, in Theorem \ref{thm3.1}.
\end{remark}

\begin{example} \label{examp3.1}\rm
 We consider the following nonlinear eigenvalue problem (see \cite{p3})
\begin{equation} \label{EQ36}
y^{(4)} (x) =\lambda (y(x)  + 1),\quad  x \in (0, \pi), \;
 y(0) = y (\pi) = y''(0) = y''(\pi) = 0.
\end{equation}
The eigenvalues of the linear eigenvalue problem
\begin{equation} \label{EQ37}
y^{(4)} (x) =\lambda y(x)\;  x \in (0, \pi), \quad
y(0) = y (\pi) = y''(0) = y''(\pi) = 0
\end{equation}
are $\lambda \ne k^4$, $k \in \mathbb{N}$, and corresponding eigenfunctions are
$\sin kx$, $k \in \mathbb{N}$.

For $\lambda \ne k^4$, $k \in \mathbb{N}$, the solution of problem
\eqref{EQ36} is unique and given by
\[
y_\lambda  (x) =  - 1 + \cos \sqrt[4]{\lambda}x
+ \frac{{1 - \cos \sqrt[4]{\lambda}\pi}}
{{\sin \sqrt[4]{\lambda}\pi}}\sin \sqrt[4]{\lambda}x.
\]
If $k$ odd, then $y_\lambda  (x) \to \infty$ as $\lambda \to k^4$, and if $k$
is even, then $y_\lambda  (x) \to -1 + \cos kx \equiv y_{k^4} (x)$.
In addition to the solution $(k^4, y_{k^4})$, the problem \eqref{EQ36}
has also the family of solutions of the form
$(k^4, y_{k^4} + c \sin kx), c \in \mathbb{R}$.
 Hence, we have
\[
\mathcal{C}_1^ +  = \{ (\lambda, y_\lambda  ):\lambda  \in (0, 1)\}  \cup \{ (0,0)\} \, \cup \{ (1, \infty )\}
\]
and
\begin{align*}
\mathcal{C}_1^ -
&= \big\{ (\lambda ,y_\lambda  ):\lambda  \in (1, 81)\}
 \cup \{ (16,y_\lambda + c \sin 2x) : c  \in \mathbb{R}\} \\
&\quad  \cup \{ (1,\infty )\}  \cup \{ (16,\infty )\}
 \cup \{ (81,\infty )\}.
\end{align*}
Consequently, $\mathcal{C}_1^{+}  \not\subset ((\mathbb{R} \times S_{1}^{+})
\cup \{(1, \infty)\})$ and $\mathcal{C}_1^{-}  \not\subset
((\mathbb{R} \times S_{1}^{-}) \cup \{(1, \infty)\})$.
Moreover, $\mathcal{C}_1^{-}$ meets $\mathcal{C}_2^{\nu}, \nu \in \{+,-\}$,
as well as $\mathcal{C}_3^{+}$.
\end{example}

\begin{remark} \label{rmk3.2} \rm
If for each $\lambda \in \mathbb{R}$ there is an $x$ such that
$g (x, 0, 0, 0, 0,\lambda) \ne 0$ then the second alternative in part
 (ii) of the Theorem \ref{thm3.1} cannot hold.
\end{remark}

If we impose some additional conditions on the function $g$ we can obtain
stronger results on the structure of the set of solutions of
problem \eqref{EQ11}-\eqref{EQ12}.

\begin{corollary}  \label{coro3.1}
If additionally we assume that
\begin{align*}
g(x, u, s, v, w, \lambda)
&= g_1 (x, u, s, v, w, \lambda) u
+  g_2 (x, u, s, v, w, \lambda) s \\
&\quad + g_3 (x, u, s, v, w, \lambda) v
+ g_3 (x, u, s, v, w, \lambda) w
\end{align*}
 where $g_1, g_2, g_3$ and
 $g_4$ are continuous at $(u,s,v,w) = (0, 0, 0, 0)$, then
$C_k^{\nu} \backslash Q_k$ contains a subcontinuum lying in
$\mathbb{R} \times S_k^\nu$ and which is unbounded or meets $\mathcal{R} = \mathbb{R} \times \{0\}$.
\end{corollary}

\begin{proof}
It follows from Theorem \ref{thm3.1} that
$(\mathcal{C}_k^{+} \cap Q_k) \subset (\mathbb{R} \times S_k^{+})
\cup \{(\lambda_k, \infty)\}$. We denote by
$\mathcal{H}_k^{+}$ the maximal subcontinuum of $\mathcal{C}_k^{+}$ lying in
$\mathbb{R} \times S_k^{+}$. If $\mathcal{H}_k^{+}$ is bounded, then there
exists $(\lambda,y) \in \partial \mathcal{H}_k^{+} \cap (\mathbb{R}
\times \partial S_k^{+})$. Hence by Lemma \ref{lem2.1} the function $y$ has at least one zero
of multiplicity $4$. Then it follows by \cite[Lemma 1.1]{a2} that $y \equiv 0$.
The proof of corollary is complete.
\end{proof}

\begin{example} \label{examp3.2} \rm
Consider the  nonlinear eigenvalue problem
\begin{equation} \label{EQ38}
\begin{gathered}
 y^{(4)} (x) = \lambda y(x) + \lambda \tilde g(y(x))y(x), \quad 0 < x < l, \\
 y(0) = y''(0) = y(l) = y''(l) = 0,
 \end{gathered}
\end{equation}
where $\tilde g(t) = - 1$ if $|t| \le 1$, $\tilde g(t) = 0$ if $|t| \ge 2$
and $\tilde g(t)$ is linear if $1 < |t| < 2$. Note that problem
\eqref{EQ38} has no nontrivial solution $(\lambda, y)$ such that
$\|y\|_3 \le 1$. Hence this problem has no bifurcation points respect
to the line of trivial solutions. Consequently, for each $k \in \mathbb{N}$
and each $\nu \in \{+,-\}$ the set $\mathcal{C}_k^{\nu} \backslash Q_k$
contains an unbounded subcontinuum lying in $\mathbb{R} \times S_k^\nu$.
\end{example}

The following example shows that the second alternative of Corollary
\ref{coro3.1} holds.

\begin{example} \label{examp3.3}\rm
 Now we consider the boundary value problem
\begin{equation} \label{EQ39}
\begin{gathered}
 y^{(4)} (x) = \lambda (1 + (1+ y^{2} (x))^{-1})y(x), \quad 0 < x < l, \\
 y(0) = y''(0) = y(l) = y''(l) = 0.
 \end{gathered}
\end{equation}
Let $(\tilde \lambda, \tilde y (x))$ be a solution of problem \eqref{EQ39}.
Then $(\tilde \lambda, \tilde y (x))$ is an eigenpair of the
linear spectral problem
\begin{equation} \label{EQ310}
 \begin{gathered}
 y^{(4)} (x) = \lambda (1 + (1+ \tilde y^{2} (x))^{-1})y(x), \quad 0 < x < l, \\
 y(0) = y''(0) = y(l) = y''(l) = 0.
 \end{gathered}
\end{equation}

By \cite[Theorem 1.2]{a2} we have $\tilde y \in \cup_{m = 1}^\infty  {S_m}$.
Let now $\tilde y \in  S_k$. Then it follows by
\cite[Theorem 1.2]{a2} that $\tilde \lambda$ is the $k$-th eigenvalue
of linear problem \eqref{EQ310}. It is obvious that $\tilde \lambda > 0$. By the max-min property of
eigenvalues \cite[Ch. 6, \S 4]{k3}), the $k$-th eigenvalue $\tilde \lambda_k$
of problem \eqref{EQ310} is determined from the relation
\begin{equation} \label{EQ311}
\tilde \lambda _k  = \max _{V^{(k - 1)}} \min _{y\, \in B.C.}
\big\{ {\tilde R[y]:\int_0^l {y(x)\varphi (x)dx = 0, \,
\varphi (x) \in V^{(k - 1)}}} \big\},
\end{equation}
where $\tilde R(y)$ is the Rayleigh quotient
\begin{equation} \label{EQ312}
\tilde R[y] = \frac{{\int_0^l {\{y''^{2} (x) - \tilde \lambda \tilde \rho (x) y^{2} (x)\} dx}}}
{{\int_0^l {y^2 (x)dx}}}, \quad
\tilde \rho (x) = \frac{1}{{1 + \tilde y^2 (x)}}\,,
\end{equation}
and $V^{(k - 1)}$ is any arbitrary set of $k -1$ linearly independent functions
$\varphi_j (x) \in B.C.$, $1 \le j \le k-1$.

It is obvious that the $k$-th eigenvalue of problem \eqref{EQ37} (with $\pi$ replaced by $l$)
is characterized as
\begin{equation} \label{EQ313}
\lambda _k  = \max _{V^{(k - 1)}}
\min _{y\, \in B.C.} \big\{ { R [y]:\int_0^l {y(x)\varphi (x)dx = 0,
\,\varphi (x) \in V^{(k - 1)}}} \big\},
\end{equation}
where
\begin{equation} \label{EQ314}
R[y] = \frac{{\int_0^l {y''^{2} (x) dx}}}{{\int_0^l {y^2 (x)dx}}}.
\end{equation}
For any choice of $V^{(k-1)}$ from \eqref{EQ312} and \eqref{EQ314}
 we obtain
\[
R[y]- \tilde \lambda \le \tilde R[y] \le R[y].
\]
Hence it follows from \eqref{EQ311} and \eqref{EQ313} that
\[
\lambda_k - \tilde \lambda \le \tilde \lambda_k \le \lambda_k,
\]
which implies (by virtue of $\tilde \lambda_k = \tilde \lambda$) that
\[
\frac {\lambda_k}{2} \le \tilde \lambda \le \lambda_k.
\]
Thus, we have shown that if $(\tilde \lambda, \tilde y) \in \mathbb{R} \times S_k$
is a solution of problem \eqref{EQ39}, then
 $\tilde \lambda \in [ {\frac{{\lambda _k}}{2},\lambda _k} ]$.
Hence $\mathcal{C}_k^{\nu}$ lies in
$[ {\frac{{\lambda _k}}{2},\lambda _k} ] \times S_k^\nu$.

Let $\{(\lambda_{k, n},y_{k, n})\}_{n=1}^{\infty}  \subset  \mathbb{R}
\times S_k^\nu$ be a sequence of solutions of problem \eqref{EQ39}
converges to $(\hat \lambda, 0)$ in $\mathbb{R} \times E$.
 Setting $v_n = \frac {y_{k, n}}{\|y_{k, n}\|_3}$ we obtain that $v_n$
satisfies the relations
\begin{equation} \label{EQ315}
 \begin{gathered}
 v_n^{(4)} (x) = \lambda_{k, n} (1 + (1+ y_{k, n}^{2} (x))^{-1})v_n (x), \quad 0 < x < l, \\
 v_n(0) = v_n''(0) = v_n(l) = v_n''(l) = 0.
 \end{gathered}
\end{equation}
Since $v_n$ is bounded in $C^3[0, l]$, $1 + \frac {1}{1 + y_{k, n}^{2}}$
is bounded in $C [0, l]$, it follows from \eqref{EQ315} that
$v_n$ is bounded in $C^4 [0, l]$. Therefore, by the Arzel\`a-Ascoli theorem,
we may assume that $v_n \to v$ in $C^3 [0, l]$; $\|v\|_3 = 1$.
 Moreover, $v \in \overline {S_k^{\nu}} = S_k^{\nu} \cup \partial S_k^{\nu}$.
Since $\|v\|_3 = 1$ it follows from \cite[Lemma 1.1]{a2} that $v \in S_k^{\nu}$.
 Passing to the limit as $n \to \infty$ in \eqref{EQ315} we obtain
 \begin{gather*}
 v^{(4)} (x) = 2 \hat \lambda v (x), \quad 0 < x < l, \\
 v (0) = v''(0) = v(l) = v''(l) = 0.
 \end{gather*}
Since $v \in S_k^{\nu}$ it follows from \cite[Theorem 1.1]{a2}
 that $2 \hat \lambda$ is a $k$-th eigenvalue of the linear problem
 \begin{gather*}
y^{(4)} (x) =  \lambda y (x), \quad 0 < x < l, \\
y(0) = y''(0) = y(l) = y''(l) = 0,
\end{gather*}
which implies that $\hat \lambda = \frac {\lambda_k}{2}$.
Therefore, $\mathcal{C}_k^{\nu}$ meets $\mathcal{R}$ at
 $(\frac {\lambda_k}{2},0)$.
\end{example}

\begin{corollary} \label{coro3.2}
If $g$ is as in Corollary \ref{coro3.1} with
$g_i(x, 0, 0, 0, 0, \lambda) = 0, i = 1, 2, 3, 4$, and
$\mathcal{C}_k^{\nu}$ meets $\mathcal{R}$, then it does so at $(\lambda_k, 0)$.
\end{corollary}

\begin{proof}
The point at which $\mathcal{C}_k^{\nu}$ meets $\mathcal{R}$ corresponds
to an eigenvalue of problem \eqref{EQ21}.
But the only point $(\lambda_m, 0)$ which can be the limit of elements
$(\lambda, y)$ with $y \in S_k^{\nu}$ is $(\lambda_k, 0)$.
The proof of this corollary is complete.
\end{proof}

It should be noted that this fact is also true in the more general case
(see Theorem \ref{thm4.1}).


\section{Global bifurcation from zero and infinity of solutions of problem
\eqref{EQ11}-\eqref{EQ12} for $f\equiv 0$}


If $f \equiv 0$ and for $g$ the conditions \eqref{EQ14} and
\eqref{EQ16} both hold then we can improve Theorems \ref{thm2.1}
 and \ref{thm3.1} as follows.

\begin{theorem}  \label{thm4.1}
Let $f \equiv 0$ and the conditions \eqref{EQ14} and \eqref{EQ16} both hold.
Then for each $k \in \mathbb{N}$ and each $\nu \in \{+,-\}$ we have
$\mathcal{C}_k^{\nu} \subset \mathbb{R} \times S_k^\nu$ and the first part of alternative (ii)
of Theorem \ref{thm3.1} cannot hold. Furthermore, if $\mathfrak{L}_k^\nu$ meets
$(\lambda,\infty)$ for some $\lambda \in \mathbb{R}$, then $\lambda = \lambda_k$.
 Similarly, if $\mathcal{C}_k^\nu$ meets $(\lambda,0)$ for some
$\lambda \in \mathbb{R}$, then $\lambda = \lambda_k$.
\end{theorem}

\begin{proof}
It follows from \cite[Lemma 1.1]{a2} that if condition \eqref{EQ14} holds,
then $\mathcal{C} \cap (\mathbb{R} \times \partial S_k^\nu) = \emptyset$.
Hence the sets $\,\mathcal{C} \cap (\mathbb{R} \times S_k^\nu)$ and
$\mathcal{C} \backslash (\mathbb{R} \times S_k^\nu)$ are mutually separated in
$\mathbb{R} \times E$ (see \cite[Definition 26.4]{w1}). Thus it follows by
\cite[Corollary 26.6]{w1} that any component of $\mathcal{C}$ must be a
subset of one or another of these sets. Since $\mathcal{C}_k^\nu$ is a
component of $\mathcal{C}$ which intersect $\mathbb{R} \times S_k^\nu$,
then $\mathcal{C}_k^\nu$ must be a subset of $\mathbb{R} \times S_k^\nu$,
i.e.\ $\mathcal{C}_k^{\nu} \subset \mathbb{R} \times S_k^\nu$.
 But this shows that the first part of alternative (ii) of Theorem \ref{thm3.1} cannot hold.

Now suppose that $\mathfrak{L}_k^\nu$ meets $(\lambda,\infty)$ for some
$\lambda \in \mathbb{R}$. Then there exists a sequence
$\{(\lambda_{k, n}, y_{k, n})\}_{n=1}^{\infty} \subset \mathfrak{L}_k^\nu$
such that $\lambda_{k, n} \to \lambda$ and $\|y_{k, n}\|_3 \to \infty$ as
$n \to \infty$ and
\[
y_{k, n} = \lambda_{k, n} L y_{k, n} + G (\lambda_{k, n}, y_{k, n}).
\]
Let $v_{k, n} = \frac{y_{k, n}}{\|y_{k, n}\|_3}$, so $\|v_{k, n}\|_3 = 1$.
Dividing this equality by $\|y_{k, n}\|_3$ shows that $v_{k, n}$ satisfies
\[
v_{k, n} = \lambda_{k, n} L v_{k, n} + \frac {G (\lambda_{k, n},
y_{k, n})}{\|y_{k, n}\|_3}.
\]
Then it follows from the compactness of operator $L$ and the condition
\eqref{EQ33} that there exists a subsequence of the sequence
$\{(\lambda_{k, n}, v_{k, n})\}_{n=1}^{\infty}$ (which we will relabel
as $\{(\lambda_{k, n}, v_{k, n})\}_{n=1}^{\infty}$) which converges
in $\mathbb{R} \times E$ to $(\lambda, v)$. Letting $n \to \infty$
in the above equality we obtain
\[
v = \lambda L v.
\]
Hence $(\lambda, v)$ is eigenpair of problem \eqref{EQ21} and $v$
lies in the closure of $S_k^\nu$. Since $\|v\|_3 = 1$ it follows from
\cite[Lemma 1.1]{a2} that $v \in S_k^\nu$. Then by \cite[Theorem 1.2]{a2}
we have $\lambda = \lambda_k$ and $v = \nu y_k$. Thus $\mathfrak{L}_k^\nu$
can only meet $(\lambda,\infty)$ if $\lambda = \lambda_k$.
Similarly is proved that $\mathcal{C}_k^\nu$ can only meet $(\lambda,0)$
if $\lambda = \lambda_k$. The proof  is complete.
\end{proof}

The naturally question arises whether or not $\mathfrak{L}_k^\nu$
intersects $\mathcal{C}_k^\nu$. The following examples show that, both
cases are possible.

\begin{example} \label{examp4.1}\rm
 Now we consider the boundary problem
\begin{equation} \label{EQ41}
\begin{gathered}
 y^{(4)} (x) = \lambda y(x) + \lambda f (x, y(x), y'(x), y'' (x), y'''(x)) y(x),
\quad 0 < x < l, \\
 y(0) = y''(0) = y(l) = y''(l) = 0,
 \end{gathered}
\end{equation}

We assume that $f$  satisfies the following conditions:
\begin{itemize}
\item[(i)] there exist positive constants $K, \,d$ and $\theta$ such that
\[
|f(x,u,s,v,w)| \le K (|u|+|s|+|v|+|w|)^{-\theta}
\]
for all $(x,u,s,v,w) \in [0,l] \times \mathbb{R}^4$ with $|u|+|s|+|v|+|w| \ge d$;

\item[(ii)] $f$ is continuous in $[0,l] \times \mathbb{R}^4$ and $f(x, 0, 0, 0, 0) = 0$
for $x \in [0, l]$.
\end{itemize}
These two conditions ensure that for
$g(x, u, s, v, w,\lambda) = \lambda f (x, u, s, v, w)$
conditions \eqref{EQ14} and \eqref{EQ16} both hold.

Since $\lambda_1 > 0$ (in this case $\lambda_1 = \frac {l}{\pi}$),
for the location of continua $\mathfrak{L}_1^{\nu}$ and
 $\mathcal{C}_1^{\nu}, \nu \in \{+,-\}$, we have the following results.

(a) If $f (x, u, s, v, w) \ge 0$  for $(x,u,s,v,w) \in [0,l] \times \mathbb{R}^4$
and $(\lambda,y) \in \mathfrak{L}_1 \cup \,\mathcal{C}_1$, then
 $0 < \lambda < \lambda_1$. Indeed, if $(\lambda,y)$ be a solution
of \eqref{EQ41}, then multiplying both sides of equation in
 \eqref{EQ41} by $y$ and integrating this relation from $0$ to $l$,
using the formula for the integration by parts, and taking into account
 boundary conditions in \eqref{EQ41}, we obtain
\[
\int_0^l {(y''(x))^2 dx}  = \lambda \int_0^l
 \big\{ {1 + f(x,y(x),y'(x),y''(x),y'''(x))} \big\}y^2 (x)dx,
\]
which implies that $\lambda > 0$. If $(\lambda,y)$ be a solution of \eqref{EQ41} and $y \in S_1$, then
\begin{equation} \label{EQ42}
\begin{gathered}
 y^{(4)} (x) - \lambda f (x, y(x), y'(x), y'' (x), y'''(x)) y(x)
= \lambda y(x),\,\,  0 < x < l, \\
 y(0) = y''(0) = y(l) = y''(l) = 0,
 \end{gathered}
\end{equation}
which implies that $\lambda$ is the first eigenvalue of the problem
\begin{equation} \label{EQ43}
 \begin{gathered}
 v^{(4)} (x) - \lambda r_1 (x) v(x) = \mu v(x), \quad 0 < x < l, \\
 v(0) = v''(0) = v(l) = v''(l) = 0,
 \end{gathered}
\end{equation}
where $r_1 (x) = f (x, y(x), y'(x), y'' (x), y'''(x)) \ge 0$.
The first eigenvalue of problem \eqref{EQ43} can
be characterized as
\[
\mu _1  = \min _{v\in B.C.}
\frac{{\int_0^l {v''^{2} (x) dx - \lambda \int_0^l {r_1 (x)v^2 (x)dx}}}}
{{\int_0^l {v^2 (x)dx}}}\,.
\]
Since $\lambda > 0$ and $r_1 (x) \ge 0, x \in [0, l]$, it follows from the above
 equality that
\[
\lambda = \mu _1  < \min _{v \in B.C.}
\frac{  {\int_0^l {v''^{2} (x) dx}}}{{\int_0^l {v^2 (x)dx}}}=\lambda_1\,.
\]
Therefore, for $\mathcal{C}_1^\nu$, first alternative in part (ii) of
Theorem \ref{thm3.1} cannot hold. Hence by Theorem \ref{thm4.1} the set $\mathcal{C}_1^\nu$
must be unbounded in $[0, \lambda_1] \times E$ and so must bifurcate
from $(\lambda_1, 0)$. Also by Theorem \ref{thm2.1} and \ref{thm4.1}
the set $\mathfrak{L}_1^\nu$ must approach $(\lambda_1, \infty)$.
 Hence $\mathfrak{L}_1^\nu \cap \mathcal{C}_1^\nu \ne \emptyset$.

(b) If $f (x, u, s, v, w) \le 0$  for $(x,u,s,v,w) \in [0,l] \times \mathbb{R}^4$
 and $(\lambda,y) \in \mathfrak{L}_1 \cup \mathcal{C}_1$, then $\lambda > \lambda_1$.
Indeed, in this case $r_1 (x) \le 0, x \in [0, l]$, and consequently, we have
\begin{align*}
\lambda
&= \mu _1  = \min _{v \in B.C.} \frac{{\int_0^l {v''^{2} (x) dx
  - \lambda \int_0^l {r_1 (x)v^2 (x)dx}}}}{{\int_0^l {v^2 (x)dx}}} \\
&\,\,\,\,\,\,\,\,\,\,=\frac{{\int_0^l {y''^{2} (x) dx
  - \lambda \int_0^l {r_1 (x)y^2 (x)dx}}}}{{\int_0^l {y^2 (x)dx}}}\\
& > \frac{{\int_0^l {y''^{2} (x) dx}}}{{\int_0^l {y^2 (x)dx}}} 
\ge \min _{v\, \in B.C.} \frac{{\int_0^l {v''^{2} (x) dx}}}
 {{\int_0^l {v^2 (x)dx}}} = \lambda _1 .
\end{align*}
Let $f(x, u, s, v, w) = f_1(u^2 + s^2 + v^2 + w^2)$, where
$f_1(z) = -z$ if $|z| \le 1$, $f_1(z) = -1$ if $2 < |z| < 3$,
$f_1(z) = - \frac {16}{z}$ if $|z| \ge 4$ and is continuous for all $z$.
Then $\mathcal{C}_1^\nu = \{ \big( {\frac{{c^2}}{{c^2  - 16}},c\sin x} \big)
:\nu c \ge 4 \}$ and
$\mathfrak{L}_1^\nu  = \big\{ {\big( {\frac{1}{{1 - c^2}},
c\sin x} \big):0 \le \nu c \le 1} \big\}$. Thus
$\mathfrak{L}_1^\nu \cap \mathcal{C}_1^\nu = \emptyset$.
Moreover, for each $\nu \in \{+,-\}$ the continua $\mathfrak{L}_1^\nu$
and $\mathcal{C}_1^\nu$ are unbounded in $\mathbb{R} \times E$ and
lies in $[\lambda_1, \infty) \times  S_1^\nu$.
\end{example}

\section{Global bifurcation from infinity of solutions of problem
\eqref{EQ11}-\eqref{EQ12}}

Throughout this section we assume that $f \not \equiv 0$ and the conditions
\eqref{EQ13} and \eqref{EQ14} are satisfied.

Recall that to study the bifurcation from infinity of the solutions of
problem \eqref{EQ11}-\eqref{EQ12}, as in the papers
\cite{r2,r4,s2,t1} we use the inversion $(\lambda, y) \to T (\lambda, y)
= ( {\lambda, \frac{y}{{\|y\|_3^2}}})$ which transforms the bifurcation
from infinity problem \eqref{EQ11}-\eqref{EQ12} to the
corresponding bifurcation from zero problem. But in this case the set
$\{y \in E : |y| + |y'| + |y''| + |y'''| \ge c_0\}$ is not transformed to
the set of the form $\{v \in E : |y| + |y'| + |y''| + |y'''| \le r_0\}$
for some sufficiently small $r_0 > 0$. Consequently, it is impossible
to apply Theorem \ref{thm2.2}. Therefore, we need the following result to solve
this problem.

\begin{lemma} \label{lem5.1}
There  exists  functions
$f^{\ast}, g^{\ast} \in C \big( {[0,l] \times \mathbb{R}^5} \big)$ such that
$h$ can be also represented in the form $h = f^{\ast} + g^{\ast}$, and
$f^\ast$, $g^\ast$ satisfy the conditions:
\begin{gather}\label{EQ5 1}
\big| {\frac{{f^{\ast}(x,u,s,v,w,\lambda )}}{u}} \big|
\le M, \quad (x, u,s,v,w,\lambda) \in [0,l] \times \mathbb{R}^5,\; u \ne 0;\\
\label{EQ52}
g^{\ast}(x,u,s,v,w,\lambda ) = o(|u|+|s|+|v|+|w|), \quad\text{as }
|u| + |s| + |v| + |w| \to \infty,
\end{gather}
uniformly in $x \in [0, l]$ and in $\lambda \in \Lambda$, for any bounded
interval $\Lambda \subset \mathbb{R}$.
\end{lemma}

\begin{proof}
Let $U = (u,s,v,w) \in \mathbb{R}^{4}$ and $|U| = |u| + |s|+|v|+|w|$.
Suppose that $\zeta (U)$ is a continuous function in $\mathbb{R}^{4}$,
$0 \le \zeta \le 1$, such that
\[
\zeta (U) =\begin{cases}
 0  &\text{for } |U| \le c_0, \\
 1  &\text{for } |U| \ge c_0 + \kappa_0,
\end{cases}
\]
where $\kappa_0$ is a sufficiently small fixed positive number.
Then we can write
\[
f (x,U,\lambda) = \zeta (U) f (x,U,\lambda) + (1- \zeta (U)) f (x,U,\lambda).
\]
Hence the functions
\[
f_1 (x,U,\lambda) = \zeta (U) f (x,U,\lambda) \quad\text{and}\quad
f_2 (x,U,\lambda) = (1 - \zeta (U)) f (x,U,\lambda)
\]
are continuous in $[0, l] \times \mathbb{R}^5$ and by \eqref{EQ13}
satisfy the following conditions:
\begin{gather} \label{EQ5 3}
\big| {\frac{{f_1(x,U,\lambda )}}{u}} \big| \le M, \quad
 (x,U,\lambda) \in [0,l] \times \mathbb{R}^5, u \ne 0;\\
 \label{EQ5 4}
f_2 (x,U,\lambda ) = 0, \quad (x,U,\lambda) \in [0,l] \times \mathbb{R}^5,\;
 |U| \ge c_0 + \kappa_0.
\end{gather}
We define the functions $f^{\ast}, g^{\ast}: [0,l]
\times \mathbb{R}^5 \to \mathbb{R}$ as follows:
\[
f^{\ast} = f_1, \quad g^{\ast} = g + f_2.
\]
Then the function $h$ is represented in the form $h = f^\ast + g^\ast$,
 where $f^\ast$ and $g^\ast$ are continuous functions in
$[0,l] \times \mathbb{R}^5$ and by virtue of \eqref{EQ14}, \eqref{EQ5 3},
and \eqref{EQ5 4} satisfy the conditions \eqref{EQ5 1}
and \eqref{EQ52}, respectively. The proof  is complete.
\end{proof}

Recall that if $0$ is not an eigenvalue of the linear problem \eqref{EQ21},
then the nonlinear problem \eqref{EQ11}-\eqref{EQ12} is reduced
to the equivalent integral equation
\begin{equation}\label{EQ55}
\begin{aligned}
y (x)&=\lambda \int _{0}^{1} K (x, t) \,\tau(t) y(t) dt
 +\int _{0}^{1} K (x, t) f^{\ast} (t, y (t), y'(t), y''(t), y'''(t),\lambda )dt \\
&\quad +\int _{0}^{1} K (x, t) g^{\ast} (t,y(t),y'(t),y''(t),y'''(t),\lambda) \,dt.
\end{aligned}
\end{equation}
Let
\begin{gather} \label{EQ56}
F^{*} (\lambda,y)(x))=\int _{0}^{1} K (x, t) f^{\ast} (t, y (t), y'(t), y''(t),
 y'''(t),\lambda)dt, \\
 \label{EQ57}
G^{*} (\lambda, y)(x)=\int _{0}^{1} K (x, t)g^{\ast} (t, y (t), y'(t),
y''(t), y'''(t),\lambda)dt.
\end{gather}
Note that $F^{*} : \mathbb{R} \times E \to E$ is completely continuous,
$G^{*} : \mathbb{R} \times E \to E$ is continuous and satisfies the condition
\begin{equation} \label{EQ58}
G^{*} (\lambda,y) = o (\|y\|_3) \quad\text{at } y = \infty,
\end{equation}
uniformly on bounded $\lambda$-intervals. Also, the operator
$H^{*} : (\lambda, y) \to \|y\|_3^2 \,g^{\ast}
 ( {\lambda ,\frac{y}{{\|y\|_3^2}}})$ is compact.

By Lemma \ref{lem5.1} and \eqref{EQ55}-\eqref{EQ57},
 problem  \eqref{EQ11}-\eqref{EQ12} can be rewritten in the
 equivalent form
\begin{equation}\label{EQ59}
y=\lambda Ly + F^{*} (\lambda,y) + G^{*} (\lambda, y).
\end{equation}

Along with \eqref{EQ21} we consider the  linear spectral problem
\begin{equation} \label{EQ510}
\begin{gathered}
\ell y(x) + \varphi (x) y (x) = \lambda \tau (x) y(x), \quad x \in (0, l), \\
y \in B.C.\,,
\end{gathered}
\end{equation}
where $\varphi (x) \in C [0,1]$.
We need the following result which is basic in the sequel.

\begin{lemma} \label{lem5.2}
For each $k \in \mathbb{N}$ it holds
\begin{equation} \label{EQ511}
|\mu_k   - \lambda_k| \le  K /\tau _0,
\end{equation}
where $\mu_k$ is the $k$th eigenvalue of problem \eqref{EQ510},
$K = \sup_{x \in [0,l]} |\varphi (x)|$.
\end{lemma}

The proof of this lemma is similar to that of \cite[Lemma 4.1]{a2}.

\begin{remark}  \label{rmk5.1}\rm
Since the class of continuous functions $C [0,1]$ is dense in
$L_1[0,1]$, Lemma \ref{lem5.2} also holds for $\varphi (x) \in  L_1[0,1]$.
\end{remark}

To study the bifurcation from infinity of solutions of
\eqref{EQ11}-\eqref{EQ12}, we consider the approximate problem
\begin{equation} \label{EQ512}
\begin{gathered}
\begin{aligned}
\ell y &= \lambda \tau (x) y +  \frac { f^{*} (x, \|y\|_3^{\varepsilon} y,
 \|y\|_3^{\varepsilon} y', \|y\|_3^{\varepsilon} y'',
 \|y\|_3^{\varepsilon} y''', \lambda)}{\|y\|_3^{2 \varepsilon}} \\
&\quad   + g^{*} (x,y,y',y'',y''', \lambda), \quad x \in (0, l),
\end{aligned} \\
y \in B.C.\,,
\end{gathered}
\end{equation}
where $\varepsilon \in (0, 1]$.

\begin{lemma} \label{lem5.3}
Let $\delta > 0$ be the sufficiently small fixed number.
Then for each $k \in \mathbb{N}$ there exists sufficiently large
$R_k^{\ast} > 0$ such that for given any $\varepsilon \in (0,1]$
 problem \eqref{EQ512} has no nontrivial solution $(\lambda, y)$
which satisfied the conditions $\operatorname{dist} \,\{\lambda, I_k\} > \delta$,
$y \in S_k^{\nu}, \nu \in \{+,-\}$, and $\|y\|_3 > R_k^{\ast}$. 
\end{lemma}

\begin{proof}
On the contrary assume that  there exists $\varepsilon_0 \in (0, 1]$ and
sufficiently  large $n_0 \in \mathbb{N}$ such that for any $n \ge n_0$
problem \eqref{EQ33} for $\varepsilon = \varepsilon_0$ has a
nontrivial solution $(\lambda_n, y_n)$ satisfying
$\operatorname{dist}\{\lambda_n, I_k\} >  \delta$,
$y_n \in S_k^{\nu}, \nu \in \{+,-\}$, and $\|y_n\|_3 > n$.

For each $n \ge n_0$, we have
\begin{equation} \label{EQ513}
\begin{gathered}
\begin{aligned}
\ell y_n &= \lambda_n \tau (x) y_n
 + \frac {f^{\ast} (x, \|y_n\|_3^{\varepsilon_0} y_n, \|y_n\|_3^{\varepsilon_0} y'_n,
  \|y_n\|_3^{\varepsilon_0} y''_n, \|y_n\|_3^{\varepsilon_0} y'''_n,
  \lambda_n)}{\|y_n\|_3^{2 \varepsilon_0}} \\
&\quad +  g^{\ast} (x, y_n, y'_n, y''_n, y'''_n, \lambda_n), \,x \in (0,l),
\end{aligned} \\
y_n \in B.C.
\end{gathered}
\end{equation}

We define a function $\varphi_n (x), n \ge n_0, x \in  [0, l]$, as follows:
\begin{align*}
&\varphi _n (x) \\
&=\begin{cases}
 -\frac{ f^{\ast}\big( {x, \|y_n\|_3^{\varepsilon_0} y_n (x),
 \|y_n\|_3^{\varepsilon_0} y'_n (x), \|y_n\|_3^{\varepsilon_0} y''_n (x),
  \|y_n\|_3^{\varepsilon_0} y'''_n (x), \lambda _n} \big)}
 {\|y_n \|_3^{2\varepsilon_0} y_n (x)}  & \text{if }  y_n (x) \ne 0,  \\
  0&\text{if } y_n (x) = 0.
 \end{cases}
\end{align*}
Then  from \eqref{EQ513} it follows that $(\lambda_n, y_n), n \ge n_0$
 solves the nonlinear problem
\begin{equation}\label{EQ514}
\begin{gathered}
\ell y + \varphi_n (x) y = \lambda \tau (x) y + g^{\ast} (x, y, y', y'',
 y''',\lambda) , \,x \in (0, l), \\
y \in B.C.
\end{gathered}
\end{equation}
From \eqref{EQ5 1} we have
 $|\varphi_n  (x)| \le \frac {M}  {\|y_n (x)\|_3^{\varepsilon_0}}
 \le M$, $n \ge n_0$, $x \in [0,l]$.
Since $y_{n} (x), n \ge n_0$, has a finite number of zeros on $(0, l)$
 and is bounded on the closed interval $[0, l]$,
Remark \ref{rmk5.1} shows that the result of Lemma \ref{lem5.2} also holds for the linear problem
\begin{equation} \label{EQ515}
\begin{gathered}
\ell y + \varphi_{n} (x) y = \lambda \tau (x) y, \quad x \in (0, l), \\
y \in B.C.
\end{gathered}
\end{equation}
Then it follows from \eqref{EQ511} that the $k$-th
eigenvalue $\lambda_{k, n}$ of the linear problem \eqref{EQ515}
lies in $I_k$. By \cite[Ch. 4, \S 3, Theorem 3.1]{c1}
for each $n \ge n_0$ the point $(\lambda_{k,n}, \infty)$ is a unique
asymptotic bifurcation point of \eqref{EQ514} which corresponds
to a continuous branch of solutions that meets this point through
$\mathbb{R} \times S_k^{\nu}$. Hence for each sufficiently large $n > n_0$
we can assign a small $\delta_n > 0$ such that $\delta_n  < \delta$ and
$|\lambda_n - \lambda_{k,n}| < \delta_n$.
Then it follows that $\operatorname{dist} \{\lambda_n, I_k\} < \delta$,
contradicting $\operatorname{dist} \{\lambda_n, I_k\} > \delta$.
The proof is complete.
\end{proof}

\begin{lemma} \label{lem5.4}
For any sufficiently small $\epsilon > 0$ there exists sufficiently large
$\rho_{\epsilon} > 0$ such that for
$\lambda \in \Lambda$, $\|y\|_3 > \rho_{\epsilon}$,
\begin{equation}\label{EQ516}
|g^{\ast} (x, y,y',y'',y''',\lambda)| < \epsilon \|y\|_3, \quad x \in [0,l].
\end{equation}
\end{lemma}

\begin{proof}
It follows from \eqref{EQ52} that for any sufficiently small
$\epsilon > 0$ there exists sufficiently large $\varrho_{\epsilon} > 0$
such that for $x \in [0,l], \lambda \in \Lambda$,
$(u,s,v,w) \in \mathbb{R}^4$, and $|u| + |s| + |v| + |w| > \varrho_{\epsilon}$
the following relation holds
\begin{equation}\label{QrindEQ517}
|g^{\ast} (x,u,s,v,w,\lambda)| < \epsilon ( {|u| + |s| + |v| + |w|}).
\end{equation}
Moreover, by continuity of $g^{\ast}$ there exists $K_{\epsilon} > 0$
such that for $x \in [0,l], \lambda \in \Lambda$ and
$|u| + |s| + |v| + |w| \le \varrho_{\epsilon}$,
\begin{equation}\label{QrindEQ518}
|g^{\ast} (x,u,s,v,w,\lambda)| \le K_{\epsilon}.
\end{equation}

Let $\rho_{\epsilon} > \varrho_{\epsilon}$ such that
$\frac {K_{\epsilon}}{\rho_{\epsilon}} < \epsilon$ and $y \in E$ such that
$\|y\|_3 > \rho_{\epsilon}$. Introduce the sets
$A_{1, \epsilon} \subset [0,l]$, $A_{2, \epsilon} \subset [0,l]$
($A_{1, \epsilon} \cup A_{2, \epsilon} = [0,l]$) defined the following way:
\begin{gather*}
A_{1, \epsilon} = \{x \in [0,l] : |y(x)| + |y'(x)| + |y''(x)| + |y'''(x)|
\le \varrho_{\epsilon}\}, \\
A_{2, \epsilon} = \{x \in [0,l] : |y(x)| + |y'(x)| + |y''(x)| + |y'''(x)|
 > \varrho_{\epsilon}\}.
\end{gather*}
If $x \in A_{1, \epsilon}$, $\lambda \in \Lambda$, then it follows from
\eqref{QrindEQ518} that
\[
|g^{\ast} (x,y(x),y'(x),y''(x),y'''(x),\lambda)| \le K_{\epsilon}
= \frac {K_{\epsilon}}{\rho_{\epsilon}} \rho_{\epsilon} < \epsilon \,\|y\|_3.
\]
Moreover, if $x \in A_{2, \epsilon}, \lambda \in \Lambda$, then it follows
from \eqref{QrindEQ517} that
\begin{align*}
|g^{\ast} (x,y(x),y'(x),y''(x),y'''(x),\lambda)|
&< \epsilon \big( {|y(x)| + |y'(x)| + |y''(x)| + |y'''(x)|} \big) \\
&\le \epsilon \,\|y\|_3.
\end{align*}
The proof  is complete.
\end{proof}

Let $p_0 = \min _{x \in [0,l]} p(x)$. For
$k \in \mathbb{N}$ we define the numbers
\[
r_k  = p_0^{ - 1} \big\{ 2\|p\|_2  + \|q\|_1  + \|r\|_\infty
 +  ( |\lambda _k | + M /\tau _0 + 1 )\|\tau \|_\infty
  + M/R_k^ * \big\}.
\]

\begin{lemma} \label{lem5.5}
Let $\delta > 0$ and $\epsilon_k > 0, k \in \mathbb{N}$, be a sufficiently
small fixed number, and $\epsilon _k  < \frac{p_{0}}{{2le^{(r_k + 1)l}}}$.
Then for each $k \in \mathbb{N}$ there exists a sufficiently large
$R_k > \max \{R_k^{\ast}, \rho_{\epsilon_k}\}$ such that for any $R > R_k$
problem \eqref{EQ11}-\eqref{EQ12} has a solution
$(\lambda_{R, k}^{\nu}, v_{R, k}^{\nu})$ which satisfies conditions
$\operatorname{dist} \{\lambda_{R, k}^{\nu}, I_k\} \le \delta$,
 $v_{R, k}^{\nu} \in S_k^{\nu}, \nu \in \{+, -\}$, and
$\|v_{R, k}^{\nu}\|_{3} = R$.
\end{lemma}

\begin{proof}
Using \eqref{EQ59} we can write \eqref{EQ512} in an equivalent
form as follows:
\begin{equation}\label{QrindEQ519}
y = \lambda L y + \|y\|_3^{-2 \varepsilon}\,F^{*} (\lambda, \|y\|_3^{\varepsilon} \,y) +  G^{*} (\lambda, y).
\end{equation}
By \eqref{EQ5 1} it follows from \eqref{EQ56} that
\begin{equation} \label{QrindEQ520}
\|F^{*} (\lambda,\|y\|_3^{\varepsilon} y)\|_3 \le C_1 \|y\|_3^{1 + \varepsilon}.
\end{equation}
where $C_1 =c_1 M$ and $c_1$ depends on bounds for $K, K_x, K_{xx}$ and $K_{xxx}$.

In view of \eqref{QrindEQ520} we have
\begin{equation} \label{QrindEQ521}
\|y\|_3^{-2 \varepsilon} F^{*} (\lambda, \|y\|_3^{\varepsilon} \,y)
= o (\|y\|_3) \quad \text{as } \|y\|_3 \to \infty,
\end{equation}
uniformly in $\lambda \in \Lambda$. Then by  \eqref{EQ58}
and \eqref{QrindEQ521} it follows from Theorem \ref{thm3.1} that for each
$k \in \mathbb{N}$ and each $\nu \in \{+, -\}$ there exists an unbounded
component $C_{k, \varepsilon}^{\nu}$ of solutions of \eqref{QrindEQ519}
(or \eqref{EQ512}) which meets $(\lambda_k,\infty)$ and  there exists
 a neighborhood $\mathcal Q_{k, \varepsilon}$ of $(\lambda_k,\infty)$
such that $\mathcal Q_{k, \varepsilon} \cap
(C_{k, \varepsilon}^{\nu} {\rm \backslash} (\lambda_k,\infty)) \subset \mathbb{R}
\times S_k^{\nu}$ and either $C_{k, \varepsilon}^{\nu} \backslash
\mathcal Q_{k, \varepsilon}$ is bounded in $\mathbb{R} \times E$ in which case
$C_{k, \varepsilon}^{\nu} \backslash \mathcal Q_{k,\varepsilon}$ meets
$\mathcal{R}$ or $C_{k, \varepsilon}^{\nu} \backslash \mathcal Q_{k,\varepsilon}$
is unbounded in $\mathbb{R} \times E$. Moreover, if
$C_{k, \varepsilon}^{\nu} \backslash \mathcal Q_{k, \varepsilon}$ is unbounded
and has a bounded projection on $\mathbb{R}$, then this set meets
$(\lambda_{k'}^{\sigma'},\infty)$ through $\mathbb{R} \times S_{k'}^{\nu'}$
for some $(k',{\sigma}') \ne (k, \sigma)$. Hence by Lemma \ref{lem5.3}
it follows that for any $\varepsilon \in (0, 1)$ and each
$R > \max \{R^{\ast}_k, \,\rho_{\epsilon_k}\}$ there exists a solution
$(\lambda_{R, k, \varepsilon}^{\nu}, v_{R, k, \varepsilon}^{\nu})
\in \mathbb{R} \times E$ of \eqref{EQ512} such that
$\operatorname{dist} \{\lambda_{R, k, \varepsilon}^{\nu}, I_k\} \le \delta$ and
$\|v_{R, k, \varepsilon}^{\nu}\|_3 = R$. Following the proof of Lemma \ref{lem5.3}
one can show that there exists sufficiently large
$R_k > \max \{R_k^{\ast}, \rho_{\epsilon_k}\}$ such that
$v_{R, k, \varepsilon}^{\nu} \in S_k^{\nu}, \nu \in \{+, -\}$, for any $R > R_k$.

Let $R > R_k$ be fixed. Since
$\{ v_{R, k, \varepsilon}^{\nu}  \in E : 0 < \varepsilon \le 1\}$
is a bounded subset of $C^3 [0, 1]$, the functions $f^{*}$ and $g^{*}$
are continuous in $[0,1] \times \mathbb{R}^5$, satisfying the conditions
\eqref{EQ5 1} and \eqref{EQ52}, and the set
$\{ \lambda_{R,k, \varepsilon}^{\nu}  \in \mathbb{R} : 0 < \varepsilon \le 1\}$
is bounded in $\mathbb{R}$, it follows from \eqref{EQ512} that
$\{ v_{R, k, \varepsilon}^{\nu}  \in E\, :\, 0 < \varepsilon \le 1\}$ is also
bounded in $C^4[0, 1]$. Hence it is precompact in $E$ by the Arzel\`a-Ascoli
theorem.

Let $\{ \varepsilon _n \} _{n = 1}^\infty \subset (0,1)$ be a sequence such that
$\varepsilon_n  \to 0$ and
$(\lambda _{R, k, \varepsilon_n}^{\nu}, v_{R, k, \varepsilon_n}^{\nu} )
\to (\lambda_{R, k}^{\nu} ,v_{R, k}^{\nu})$ as $n  \to \infty$.
Taking the limit (as $n \to \infty$) in \eqref{EQ512} we see that
$(\lambda_{R, k}^{\,\nu},v_{R, k}^{\nu})$ is a solutions of
\eqref{EQ11}-\eqref{EQ12}, i.e. the following relations hold:
\begin{equation} \label{QrindEQ522}
\begin{gathered}
\begin{aligned}
\ell v_{R, k}^{\nu}
&= \lambda_{R, k}^{\,\nu} \,\tau (x) v_{R, k}^{\nu} + f^{*} (x, v_{R, k}^{\nu},
  (v_{R, k}^{\nu})', (v_{R, k}^{\nu})'', (v_{R, k}^{\nu})''',\lambda_{R, k}^{\nu}) \\
&\quad +  g^{*} (x, v_{R, k}^{\nu}, (v_{R, k}^{\nu})', (v_{R, k}^{\nu})'',
 (v_{R, k}^{\nu})''',\lambda_{R, k}^{\nu}),
\end{aligned}\\
v_{R, k}^{\nu} \in B.C.\,.
\end{gathered}
\end{equation}

Since $v_{R, k, \varepsilon_n}^{\nu} \in S_k^{\nu}$ it follows that
 $v_{R, k}^{\nu} \in \overline {S_k^\nu} = S_k^{\nu} \cup \partial S_k^{\nu}$.
If $v_{R, k}^{\nu} \in \partial S_k^{\nu}$, then by  Lemma \ref{lem2.1} there exists
$\varsigma \in [0,l]$ such that
$v_{R, k}^{\nu} (\varsigma) = (v_{R, k}^{\nu})' (\varsigma)
= (v_{R, k}^{\nu})'' (\varsigma) = (v_{R, k}^{\nu})''' (\varsigma)= 0$.
Let $w_{R, k}^{\nu} = \frac {v_{R, k}^{\nu}}{\|v_{R, k}^{\nu}\|_{3}}\,$.
Then we have $\|w_{R, k}^{\nu}\| = 1$.  Dividing \eqref{QrindEQ522}
 by $\|v_{R, k}^{\nu}\|_{3}$ shows that $w_{R, k}^{\nu}$ satisfies the equation
\begin{equation} \label{QrindEQ523}
\begin{aligned}
\ell w_{R, k}^{\nu}
& = \lambda_{R, k}^{\,\nu} \,\tau (x) w_{R, k}^{\nu}
 + \frac {f^{*} (x, v_{R, k}^{\nu}, (v_R^{\nu})', (v_{R, k}^{\nu})'',
  (v_{R, k}^{\nu})''', \lambda_{R, k}^{\nu})}{\|v_{R, k}^{\nu}\|_{3}} \\
&\quad  + \frac {g^{*} (x, v_{R, k}^{\nu}, (v_{R, k}^{\nu})',
 (v_{R, k}^{\nu})'',(v_{R, k}^{\nu})''', \lambda_{R, k}^{\nu})}
 {\|v_{R, k}^{\nu}\|_{3}}.
\end{aligned}
\end{equation}
By the relations \eqref{EQ5 1} and \eqref{EQ516} we get
\begin{gather} \label{QrindEQ524}
\big| {\frac { f^{*} (x, v_{R, k}^{\nu}, (v_{R, k}^{\nu})', (v_{R, k}^{\nu})'',
 (v_R^{\nu})''',\lambda_{R, k}^{\nu})}{\|v_{R, k}^{\nu}\|_{3}}} \big|
\le \frac {M}{R_k^{*}} | {w_{R, k}^{\nu}}|, \\
\label{QrindEQ525}
\big| {\frac {g^{*} (x, v_{R, k}^{\nu}, (v_{R, k}^{\nu})', (v_{R, k}^{\nu})'',
 (v_{R, k}^{\nu})''',\lambda_{R, k}^{\nu})}{\|v_{R, k}^{\nu}\|_{3}}} \big|
< \epsilon_k.
\end{gather}

In view of \eqref{QrindEQ524} and \eqref{QrindEQ525}, it is easy to we see
from \eqref{QrindEQ523} that
\begin{equation} \label{QrindEQ526}
| (w_{R, k}^{\nu})^{(4)}| \le r_k  \big( {|w_{R, k}^{\nu}|
+ |(w_{R, k}^{\nu})'|  +  |(w_{R, k}^{\nu})''|  + |(w_{R, k}^{\nu})'''|} \big)
+ p_{0}^{-1} \epsilon_k.
\end{equation}
Let the norm of $z_{R, k}^{\nu} = (w_{R, k}^{\nu}, (w_{R, k}^{\nu})',
(w_{R, k}^{\nu})'',(w_{R, k}^{\nu})''')$ in $\mathbb{R}^{4}$  be
\[
|z_{R, k}^{\nu}| = |w_{R, k}^{\nu}| + |(w_{R, k}^{\nu})'| + |(w_{R, k}^{\nu})''|
+ |(w_{R, k}^{\nu})'''|.
\]
 Then it follows from \eqref{QrindEQ526} that
\[
|(z_{R, k}^{\nu})'| \le (r_k + 1) |z_{R, k}^{\nu}| + p_{0}^{-1}\epsilon_k.
\]
Integrating both sides of this inequality  from $\varsigma$ to $x$ we obtain
\begin{equation} \label{QrindEQ527}
\big| {\int_\varsigma ^x {|(z_R^{\nu})'(t)|\,dt}} \big|
 \le (r_k + 1) \big| {\int_\varsigma ^x {|z_R^{\nu} (t)|\,dt}} \big|
 + p_{0}^{-1} l \epsilon _k.
\end{equation}
By $|z_{R, k}^{\nu} (\varsigma)| = 0$ it follows from \eqref{QrindEQ527} that
\begin{equation} \label{QrindEQ528}
|z_{R, k}^{\nu} (x)|
= \big| {\int_\varsigma ^x {(z_{R, k}^{\nu})' (t)dt}} \big|
 \le (r_k + 1) \big| {\int_\varsigma ^x {|z_{R, k}^{\nu} (t)|\,dt}} \big|
 + p_{0}^{-1} l \epsilon_k.
\end{equation}
Using Gronwall's inequality, from \eqref{QrindEQ528} we obtain
\[
|z_{R, k}^{\nu} (x)| \le p_{0}^{-1} l \epsilon_k e^{(r_k + 1) l}
 < \frac {1}{2}, \quad x \in [0,l],
\]
which yields the inequality $\|w_{R, k}^{\nu}\|_3 \le \frac {1}{2}$,
contradicting $\|w_{R, k}^{\nu}\|_3 = 1$. Therefore,
 $v_{R, k}^{\nu} \not \in \partial S_k^{\nu}$ which implies that
$v_{R, k}^{\nu} \in S_k^{\nu}$. The proof  is complete.
\end{proof}

\begin{corollary} \label{coro5.1}
The set of asymptotic bifurcation points of problem
\eqref{EQ11}-\eqref{EQ12} with respect to the set
$\mathbb{R} \times S_k^{\nu}$ is nonempty. Moreover, if $(\lambda,\infty)$
is a bifurcation point for \eqref{EQ11}-\eqref{EQ12} with
respect to the set $\,\mathbb{R} \times S_k^{\nu}$, then $\lambda \in I_k$.
\end{corollary}

For each $k \in \mathbb{N}$ and each $\nu \in \{+,-\}$ we define
the set $\mathcal{D}_k^{\nu} \subset \mathcal{C}$ to be the union of all the
components of $\mathcal{C}$ which meet $I_k \times \{\infty\}$
through $\mathbb{R} \times S_k^\nu$.
It follows from Corollary \ref{coro5.1} that this set is nonempty.
The set $\mathcal{D}_k^{\nu}$ may not be connected in $\mathbb{R} \times E$,
but the set $\mathcal{D}_k^{\nu} \cup (I_k \times \{\infty\})$ is
 connected in $\mathbb{R} \times E$.

\begin{remark} \label{rmk5.2} \rm
By \cite[Lemma 1.1]{a2}, if $(\lambda, y)$ is a nontrivial solution of
problem \eqref{EQ11}-\eqref{EQ12} in the case when the nonlinear
terms $f$ and $g$ satisfies the conditions \eqref{EQ15} and
\eqref{EQ16}, respectively, and $(\lambda, y) \in \partial S_k^{\nu}$,
then $y \equiv 0$. It is clear from the proof of Lemma \ref{lem5.5} that
this assertion does not hold for problem \eqref{EQ11}-\eqref{EQ12}
under the conditions \eqref{EQ13} and \eqref{EQ14}.
Consequently, the set $\mathcal{D}_k^{\nu}, k \in \mathbb{N}, \nu \in \{+,-\}$,
can intersect the set $\mathcal{D}_{k'}^{\nu'}$ for some $(k',\nu') \ne (k,\nu)$
outside of the set $ \{ (\lambda, y) \in \mathbb{R} \times E : \operatorname{dist}
\{\lambda, I_k\} \le \delta, \|y\|_3 > R_k\}$ (see Remark \ref{rmk5.3}).
\end{remark}

The main result of this article is the following theorem.

\begin{theorem} \label{thm5.1}
 For each $k \in \mathbb{N}$ and each $\nu \in \{+,-\}$ for the set
$\mathcal{D}_k^{\nu}$ at least one of the followings holds:
\begin{itemize}
\item[(i)]  $\mathcal{D}_k^{\nu}$ meets $I_{k'} \times \{\infty\}$ through
 $\mathbb{R} \times S_{k'}^{\nu'}$ for some $(k', \nu') \ne (k,\nu)$;

\item[(ii)] $\mathcal{D}_k^{\nu}$ meets $\mathcal{R}$ for some
 $\lambda \in \mathbb{R}$;

\item[(iii)] $P_R (\mathcal{D}_k^{\nu})$ is unbounded.
\end{itemize}
In addition, if the union $\mathcal{D}_k =  \mathcal{D}_k^{+} \cup \mathcal{D}_k^{-}$
does not satisfy (ii) or (iii) then it  must satisfy (i) with $k' \ne k$.
\end{theorem}

\begin{proof}
For any $(\lambda,v) \in \mathbb{R} \times E$, $ v \ne 0$, we define the functions
$\tilde f (\lambda, v), \tilde g (\lambda, v) \in C [0,l]$ as follows:
\begin{gather*}
\tilde f (\lambda, v) (x) = \begin{cases}
\|v\|_3^{2} f^{*} \big( {x, \frac {v(x)}{\|v\|_3^{2}}, \frac {v'(x)}{\|v\|_3^{2}},
\frac {v''(x)}{\|v\|_3^{2}}, \frac {v'''(x)}{\|v\|_3^{2}}, \lambda} \big),
&\text{if } v (x) \ne 0, \\
0  &\text{if } v (x)= 0,
\end{cases} \\
\tilde g (\lambda, v) (x) = \begin{cases}
 \|v\|_3^{2} \,g^{*} \big( {x,  \frac {v(x)}{\|v\|_3^{2}},
\frac {v'(x)}{\|v\|_3^{2}}, \frac {v''(x)}{\|v\|_3^{2}},
 \frac {v'''(x)}{\|v\|_3^{2}}, \lambda} \big),
&\text{if } v (x) \ne 0, \\
0&\text{if } v (x)= 0,
\end{cases}
\end{gather*}
for $x \in [0,l]$.
Because $f^{*}, g^{*} \in C( {[0,l] \times \mathbb{R}^5})$, by
 \eqref{EQ5 1} and \eqref{QrindEQ517} it follows that the functions
$\tilde f, \tilde g : \mathbb{R} \times E \to C [0,l]$ are continuous and
satisfy the following conditions:
\begin{gather}\label{QrindEQ529}
\|\tilde f (\lambda, v)\|_{\infty} \le M \|v\|_{\infty}; \\
\label{QrindEQ530}
\|\tilde g (\lambda, v)\|_{\infty} = o (\|v\|_3), \quad\text{as }
\|v\|_3 \to 0,
\end{gather}
uniformly in $\lambda \in \Lambda$ for any bounded interval
$\Lambda \subset \mathbb{R}$.

If $(\lambda, y) \in \mathbb{R} \times E$, $\|y\|_{3} \ne 0$, then dividing
\eqref{EQ11}-\eqref{EQ12} by $\|y\|_{3}^{2}$ and setting
$v= \frac {y} {\|y\|_{3}^{2}}$ we obtain
\begin{equation}\label{EQ5 31}
 \begin{gathered}
\ell (v) (x) = \lambda \tau (x) v (x) +  \tilde f (\lambda, v) (x)
+ \tilde g (\lambda, v) (x), \quad x \in (0,l), \\
v \in B.C.
\end{gathered}
\end{equation}
Note that $\|v\|_{3} = \frac {1}{\|y\|_{3}}$ and
$y = \frac {v} {\|v\|_{3}^{2}}$. Thus the transformation
$(\lambda,y) \to T(\lambda,y) = (\lambda,v)$ turns a bifurcation from
infinity problem \eqref{EQ11}-\eqref{EQ12} into a bifurcation
from zero problem \eqref{EQ5 31}. It should be noted that Theorem \ref{thm2.2}
cannot be directly applied to problem \eqref{EQ5 31} in view of
Remark \ref{rmk5.2}.
As equation in \eqref{EQ5 31} contains the nonlinear term
$\tilde f$ satisfying \eqref{QrindEQ529} problem \eqref{EQ5 31}
is not always linearizable in a neighborhood of zero. Hence we also
cannot immediately apply standard global bifurcation theory to prove
our theorem, as was done in \cite{d1,r1}. To deal with this problem
alongside \eqref{EQ5 31} we will consider the approximating problem
\begin{equation} \label{EQ5 32}
\begin{gathered}
\ell (v) (x) = \lambda \tau (x) v (x) +  \tilde f (\lambda,
\|v\|_3^{\varepsilon} v) (x) + \tilde g (\lambda, v) (x), x \in (0,l), \\
v \in B.C.,
\end{gathered}
\end{equation}
where $\varepsilon \in (0,1]$. It follows from the above definitions that
\eqref{EQ5 32} is equivalent to  \eqref{EQ512}. For fixed
$\varepsilon \in (0,1]$ by \eqref{QrindEQ529} we have
\begin{equation} \label{QrindEQ533}
\|\tilde f (\lambda, \|v\|_3^{\varepsilon}v)\|_{\infty} = o (\|v\|_3)
\quad \text{as } \|v\|_3 \to 0,
\end{equation}
so the global bifurcation results in \cite{a2,d1,r1} are applicable to
 problem \eqref{EQ5 32}. Also, from the proof of Lemma \ref{lem5.5}
it is obvious that \eqref{EQ5 32} approximates \eqref{EQ5 31}
as $\varepsilon \to 0$, in a suitable sense. We now choose some
fixed arbitrary $k_0 \in \mathbb{N}$ and we will prove the theorem
for $k = k_0$ and $\nu = +$ (the case of $\nu = -$ is considered similarly).

For any $k \in \mathbb{N}, \nu \in \{+,-\}$ and $\delta, R, \varrho > 0$, let
\begin{gather*}
U_k^{\nu} (\delta, R) = \{ (\lambda, y) \in \mathbb{R} \times E :
\operatorname{dist} \{\lambda, I_k\} \le \delta, \; y \in S_k^{\nu},\; \|y\|_3 > R\},
\\
\tilde U_k^{\nu} (\delta, \varrho)
= \{ (\lambda, v) \in \mathbb{R} \times E
: \operatorname{dist} \{\lambda, I_k\} \le \delta, \; v \in S_k^{\nu}, \;
\|v\|_3 <  \varrho\}.
\end{gather*}
It follows from Lemma \ref{lem5.5} and Corollary \ref{coro5.1} that
$U_k^{\nu} (0, R) \subset \mathcal{D}_k^{\nu}$ for $R = R_k$.

Let $\mathcal{\tilde C} \subset \mathbb{R} \times E$ be the set of
nontrivial solutions of \eqref{EQ5 31}. By construction,
the transformation $(\lambda,y) \to T(\lambda,y)$ maps $\mathcal{C}$
into $\mathcal{\tilde C}$ and ˜$U_k^{\nu} (\delta, R)$ into
$\tilde U_k^{\nu} (\delta, \varrho)$, where $\varrho = \frac{1}{R}$.
Let $\mathcal{\tilde D}_{k_0}^{+}$ be the union of all the components of
$\mathcal{\tilde C}$˜ which meet $I_{k_0} \times \{0\}$ through
$\mathbb{R} \times S_{k_0}^{+}$. Then
$\mathcal{\tilde D}_{k_0}^{+} = T^{-1}(\mathcal{D}_{k_0}^{+})$.
Thus to prove the theorem it suffices to show that the set
$\mathcal{\tilde D}_{k_0}^{+}$ either meets some interval
$I_k \times \{0\}$ through $\mathbb{R} \times S_k^{\nu}$ with
$(k,\nu) \ne (k_0,+)$ or is unbounded in $\mathbb{R} \times E$
(the alternatives $\rm (ii)$ and $\rm (iii)$ of this  theorem for
$\mathcal{D}_{k_0}^{+}$ correspond, via $T$, to the various ways
in which $\mathcal{\tilde D}_{k_0}^{+}$ can be unbounded).

Now suppose that the assertion of the theorem for $\mathcal{\tilde D}_{k_0}^{+}$
is not true. Then $\mathcal{\tilde D}_{k_0}^{+}$ is bounded and hence we can
choose a compact interval $\Lambda_0 \subset \mathbb{R}$ such that
$P_R (\mathcal{\tilde D}_{k_0}^{+}) \cup I_{k_0}$ is in the interior of
$\Lambda_0$ and $\Lambda_0$ contains only finitely many intervals
$I_k$ with $\partial \Lambda_0 \cap I_k = \emptyset$.

For any $\delta,  \varrho > 0$, let
\[
W_0^{+} (\delta, \varrho)
 = \cup_{(k,\nu ) \ne (k_0 , + )} {\tilde U_k^\nu  (\delta ,\varrho)}
\]
The set $W_0^{+} (\delta, \varrho)$ is open in $\mathbb{R} \times E$,
and we denote by $\overline {W_0^{+} (\delta, \varrho)}$ the closure of this set.
Since $\Lambda_0$ contains only finitely intervals $I_k$ it follows from
Lemmas \ref{lem5.3}  and \ref{lem5.5}
 that there exist $\delta_0, \varrho_0 > 0$ such that
\begin{equation} \label{QrindEQ534}
\mathcal{\tilde D}_{k_0}^{+} \cap \overline {W_0^{+} (\delta_0, \varrho_0)}
= \emptyset.
\end{equation}

By following the arguments in \cite[Theorem 3.1, p. 151]{r4}
we can find a neighborhood $\mathcal{\tilde Q^{+}}$ of
$\mathcal{\tilde D}_{k_0}^{+}$  such that
\begin{equation} \label{QrindEQ535}
\tilde U_{k_0}^{+} (\delta_0, \varrho_0) \subset \mathcal{\tilde Q^{+}}, \quad
\mathcal{\tilde Q^{+}} \cap \overline {W_0^{+} (\delta_0, \varrho_0)} = \emptyset, \quad
\partial \mathcal{\tilde Q^{+}} \cap \mathcal{\tilde C} = \emptyset.
\end{equation}

By \cite[Theorem 1.3]{r1}, \cite[Theorem 2]{d1} and Theorem \ref{thm2.1}
for each fixed $\varepsilon \in (0,1]$ there exists a component
$\mathcal{\tilde D}_{k_0}^{+} (\varepsilon) \subset \mathbb{R} \times E$
of nontrivial solutions of problem \eqref{EQ5 32} such that
$\mathcal{\tilde D}_{k_0}^{+} (\varepsilon)$ meets $(\lambda_{k_0},0)$
 through $\mathbb{R} \times S_{k_0}^{+}$ and is either
$\mathcal{\tilde D}_{k_0}^{+} (\varepsilon)$ unbounded in $\mathbb{R} \times E$
or $\tilde D_{k_0}^{+} (\varepsilon)$ meets $(\lambda_k,0)$ through
$\mathbb{R} \times S_k^{\nu}$ for some $(k, \nu) \ne (k_0,+)$.
Then the component $\mathcal{\tilde D}_{k_0}^{+} (\varepsilon)$ intersects
both $\mathcal{\tilde Q^{+}}$ and $(\mathbb{R} \times E)
\backslash \mathcal{\tilde Q^{+}}$ which implies that
$\mathcal{\tilde D}_{k_0}^{+} (\varepsilon) \cap \partial
\mathcal{\tilde Q^{+}} \ne \emptyset$. Thus, there exists
$(\lambda_\varepsilon,v_\varepsilon) \in \mathcal{\tilde D}_{k_0}^{+}
(\varepsilon) \cap \partial \mathcal{\tilde Q^{+}}$ for all
$\varepsilon \in (0,1]$. Since $\mathcal{\tilde Q^{+}}$ is bounded in
$\mathbb{R} \times E$, problem \eqref{EQ5 32} shows that the set
$\{(\lambda_{\varepsilon},v_{\varepsilon}) \in \mathbb{R} \times E
: 0 < \varepsilon \le 1\}$ is bounded in $\mathbb{R} \times C^{4} [0,l]$.
Therefore, we can find a sequence $\{\varepsilon_n\}_{n=1}^{\infty} \subset (0,1)$
such that $\varepsilon_n \to 0$ and $(\lambda_{\varepsilon_n},v_{\varepsilon_n})$
converges in $\mathbb{R} \times E$ to a solution $(\tilde \lambda,\tilde v)$
of \eqref{EQ5 31}. If $\tilde v = 0$, then by Theorem \ref{thm3.1} it follows
from the proof of Lemma \ref{lem5.3} that for sufficiently large $n \in \mathbb{N}$,
$(\lambda_{\varepsilon_n},v_{\varepsilon_n}) \in {W_0^{+} (\delta_0, \varrho_0)}$
which contradicts \eqref{QrindEQ535}. Hence $\tilde v \ne 0$, and consequently,
$(\tilde \lambda,\tilde v) \in \partial \mathcal{\tilde Q^{+}}
\cap \mathcal{\tilde C}$ that also contradicts \eqref{QrindEQ535}.
The proof  is complete.
\end{proof}

\begin{remark} \label{rmk5.3} \rm
Unlike Theorem \ref{thm2.2} for bifurcation from zero, it need not be case
$\mathcal{D}_k^{\nu} \subset (\mathbb{R} \times S_k^{\nu}) \cup (I_k
\times \{\infty\})$ in Theorem \ref{thm3.1} (a counterexample for $f \equiv 0$
is given in Example \ref{examp3.1}).
\end{remark}


\subsection*{Acknowledgements}
The authors are deeply grateful to Professor Paul H. Rabinowitz for
his valuable comments and suggestions which contributed to a significant
improvement in the text and an understanding of the results.

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