\documentclass[reqno]{amsart}
\usepackage{hyperref}

\AtBeginDocument{{\noindent\small
\emph{Electronic Journal of Differential Equations},
Vol. 2018 (2018), No. 90, pp. 1--10.\newline
ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu}
\thanks{\copyright 2018 Texas State University.}
\vspace{8mm}}

\begin{document}
\title[\hfilneg EJDE-2018/90\hfil Fractional Laplace equation]
{Well-posed problems for the fractional Laplace equation with
integral boundary conditions}

\author[N. Tokmagambetov, B. T. Torebek \hfil EJDE-2018/90\hfilneg]
{Niyaz Tokmagambetov, Berikbol T. Torebek}

\address{Niyaz Tokmagambetov \newline
Al-Farabi Kazakh National University,
050040, Al-Farabi ave., 71,
Almaty, Kazakhstan. \newline
Institute of Mathematics and Mathematical Modeling,
050010, Pushkin st., 125,
Almaty, Kazakhstan}
\email{tokmagambetov@math.kz}

\address{Berikbol T. Torebek \newline
Institute of Mathematics and Mathematical Modeling,
050010, Pushkin st., 125,
Almaty, Kazakhstan. \newline
Al-Farabi Kazakh National University,
050040, Al-Farabi ave., 71,
Almaty, Kazakhstan}
\email{torebek@math.kz}

\thanks{Submitted February 8, 2018. Published April 12, 2018.}
\subjclass[2010]{35R30, 35K05, 35K20}
\keywords{Caputo operator; Riemann-Liouville operator; fractional Laplace; 
\hfill\break\indent Mittag-Leffler function;
self-adjoint operator;  boundary value problem}

\begin{abstract}
 In this remark we study the boundary-value problems for a fractional
 analogue of the Laplace equation with integral boundary conditions
 in rectangular and half-strip domains. We prove the existence and
 uniqueness of solutions by using the spectral decomposition  method.
\end{abstract}

\maketitle
\numberwithin{equation}{section}
\newtheorem{theorem}{Theorem}[section]
\newtheorem{lemma}[theorem]{Lemma}
\newtheorem{definition}[theorem]{Definition}
\newtheorem{corollary}[theorem]{Corollary}
\newtheorem{problem}[theorem]{Problem}
\allowdisplaybreaks


\section{Introduction}

In \cite{TT16}, a fractional analogue of the classical Sturm-Liouville problem
was found. Moreover, it stands for a symmetric fractional differential operator
of order $2\alpha$, ($1/2<\alpha<1$). Using the extension theory, we described
a class of self-adjoint boundary-value problems associated with the
fractional Sturm-Liouville equation.

Here, we aim at studying fractional operators in two dimensional cases,
that is, a fractional Laplace equation. The main difference of the
fractional Laplace equation, that we are going to introduce,
from an operator made of the Laplacian by taking it in a fractional
power is that the last one is a pseudo--differential operator with
the symbol $(\xi_{1}^2 + \xi_2^2)^{\beta}$ for some
$\beta\in\mathbb R$ nevertheless the first one is not.

The purpose of this paper is to study two boundary value problems for the
fractional Laplace equation.
Let $\Omega  = \{ {(x,y) \in \mathbb{R}^2: 0 < x < 1, -\infty<a < y < b<\infty} \}$
and $\Omega_\infty  = \{ {(x,y) \in \mathbb{R}^2: 0 < x < +\infty,
  -\infty<a < y < b<\infty} \}$. Now, we consider the equation
\begin{equation}\label{1.1}
\mathcal{D}_{x,0+}^\alpha \mathcal{D}_{x,0+}^\alpha u(x,y)
- \mathcal{D}_{y,a+}^\beta D_{y,b-}^\beta u(x,y) = 0,
\end{equation}
in $\Omega$, or in $\Omega_\infty$, where $0<\alpha<1$, $1/2<\beta<1$,
$$
\mathcal{D}_{t,p+}^\delta  u(t,z) = \frac{1}{{\Gamma (
{1 - \delta } )}}\int_p^t {( {t - s} )^{ -\delta }
\frac{{\partial u}}{{\partial s}}( {s,z} )}ds,\quad
-\infty\leq p<t<q\leq\infty
$$
is the left Caputo derivative of order $\delta  \in( {0,1}]$ of $u$ with
respect to $t$, and
$$
D_{z,d-}^\omega  u(t,z) = -\frac{1}{{\Gamma (
{1 - \omega } )}}\frac{\partial}{\partial z}\int_z^d {( {\xi-z} )^{ -
\omega } u( {r,\xi} )}d\xi,\quad
-\infty\leq c<z<d\leq\infty
$$
is the right Riemann-Liouville derivative of order
$\omega \in( {0,1}]$ of $u$ with respect to $z$, \cite{Kilbas2006}.

We say that the function $u \in C( {\bar \Omega } )$ is a regular solution of
 \eqref{1.1} if $u$ satisfies \eqref{1.1} and
$$
\mathcal{D}_{x,0+}^\alpha u\in C( \Omega  ), \quad
\mathcal{D}_{x,0+}^\alpha\mathcal{D}_{x,0+}^\alpha u \in C( \Omega  ), \quad
\mathcal{D}_{y,a+}^\beta D_{y,b-}^\beta u  \in C( \Omega  ).
$$
Since for $\alpha  = 1$, $\beta=1$ one has
$$
\mathcal{D}_{x,0+}^1 \mathcal{D}_{x,0+}^1 - \mathcal{D}_{y,a+}^1 D_{y,b-}^1 
= \frac{{\partial ^2}}{{\partial x^2 }} + \frac{{\partial ^2 }}{{\partial y^2 }} =
\Delta,
$$
Equation \eqref{1.1} is a fractional generalization of the Laplace equation.

\begin{problem} \label{prob1} \rm
 Find in the domain $\Omega$ a regular
solution of Equation \eqref{1.1}, satisfying the following
boundary value conditions:
\begin{gather}\label{1.2}
u( {0,y} ) = \varphi ( y ),u( {1,y} ) = \psi ( y ),{\rm{ }} a  \le y \le b,\\
\label{1.3}
I^{1-\beta}_{b-,y}u(x,a)=0,\quad I^{1-\beta}_{b-,y}u(x,b)=0,\quad
0 \le x \le 1.
\end{gather}
Here $\varphi ( y )$ and $\psi ( y )$ are given
sufficiently smooth functions.
\end{problem}

\begin{problem} \label{prob2} \rm
Find in the domain $\Omega_\infty$ a regular
solution of  \eqref{1.1}, satisfying the following
boundary value conditions:
\begin{gather}\label{1.4}
u( {0,y} ) = \phi ( y ),\, \lim_{x\to +\infty}|u( {x,y} )| \to 0,\quad
 a  \le y \le b,\\
\label{1.5}
I^{1-\beta}_{b-,y}u(x,a)=0,\quad
I^{1-\beta}_{b-,y}u(x,b)=0,\quad  0 \le x \le +\infty.
\end{gather}
where $\phi ( y )$ is a
sufficiently smooth function.
\end{problem}

Note that Problems \ref{prob1} and \ref{prob2} for  \eqref{1.1} when 
$\beta  = 1$ were studied
in \cite{TurmetovTorebek:2014,KiraneTT:2017}. Some questions
of solvability of boundary
value problems with fractional analogues of the Laplace operator
were studied in \cite{Masaeva:2012, Yakubovich:2012}.

The meed  to study boundary-value problems for \eqref{1.1} is
determined by using the fractal Laplace equations to describe the
production processes in mathematical modeling of socio-economic
systems \cite{Nakhushev:2007}.
We also note that in \cite{Nakhushev:2007} an attention was drawn to the
fact that the problem of finding a generalized two-factor Cobb-Douglas
function is reduced to the classical boundary value problems for a generalized
Laplace equation of a fractional order.

\section{Auxiliary statements}

In this section we start by recalling the  definitions that we need later.

\begin{definition} \label{def2.1} \rm
The left and right Riemann-Liouville
fractional integrals $I_{a+} ^\alpha$ and $I_{b-} ^\alpha$ of order
$\alpha\in\mathbb R$ ($\alpha>0$) are defined as
\begin{gather*}
I_{a+} ^\alpha  [ f ]( t ) = \frac{1}{{\Gamma ( \alpha )}}\int_a^t {(
{t - s} )^{\alpha  - 1} f( s )} ds, \quad t\in(a,b], \\
I_{b-} ^\alpha  [ f ]( t ) = \frac{1}{{\Gamma ( \alpha )}}\int_t^b {(
{s - t} )^{\alpha  - 1} f( s )} ds, \quad t\in[a,b),
\end{gather*}
respectively. Here $\Gamma$ stands for the Euler gamma function.
\end{definition}


\begin{definition} \label{def2.2} \rm
The left Riemann-Liouville fractional derivative $D_{a+} ^\alpha$ of order
$\alpha\in\mathbb R$ ($0<\alpha<1$) is given by
$$
D_{a+} ^\alpha [ f ]( t ) = \frac{{d }}{{dt
}}I_{a+} ^{1 - \alpha } [ f ]( t ), \quad  \forall t\in(a, b].
$$
Analogously, the right Riemann-Liouville
fractional derivative $D_{b-} ^\alpha$ of order $\alpha\in\mathbb R$
($0<\alpha<1$) is defined as
$$
D_{b-}^\alpha [ f ]( t ) = -\frac{{d }}{{dt }}I_{b-} ^{1 - \alpha } [ f ]( t
), \quad  \forall t\in[a, b).
$$
\end{definition}


\begin{definition} \label{def2.3} \rm
The left and right Caputo fractional derivatives of order $\alpha\in\mathbb R$
($0<\alpha<1$) are given by
\begin{gather*}
\mathcal{D}_{a+} ^\alpha  [ f ]( t ) = D_{a+}
^\alpha  [ f( t ) - f( a ) ], \quad  t\in(a, b], \\
\mathcal{D}_{b-} ^\alpha [ f ]( t ) = D_{b-} ^\alpha  [ f( t
) - f( b ) ], \quad  t\in[a, b),
\end{gather*}
respectively.
\end{definition}


Let $\lambda$ be a positive real number, $I = (0, 1)$,
$\bar I = [0, 1]$. Consider the  problem
\begin{gather}\label{2.1}
\mathcal{D}_{0+}^{\alpha }\mathcal{D}_{0+}^{\alpha } \nu( x)
- \lambda \nu(x) = 0,\quad t\in I,\\
\label{2.2}
\nu(0) = a_0,\,\nu(1) = a_1,
\end{gather}
where $a_0$ and $a_1$ are real numbers.

We recall that the solution of problem \eqref{2.1}-\eqref{2.2} is a function
$\nu \in C(\bar I)$, such that  $\mathcal{D}_{0+}^\alpha
\nu \in C(\bar I)$,
$\mathcal{D}_{0+}^\alpha \mathcal{D}_{0+}^\alpha \nu \in C( I )$.

\begin{lemma}[ \cite{KiraneTT:2017}] \label{lem1}
 The solution of problem \eqref{2.1}-\eqref{2.2} exists, and is unique.
 Moreover, it can be written in the form
\begin{equation}\label{1*}
\nu(x) = a_0C(\lambda x) + a_1S(\lambda x),
\end{equation} 
where
\begin{gather}\label{2.3}
C( {\lambda x} ) =
\frac{{E_{\alpha ,1} ( \sqrt{\lambda}  )E_{\alpha ,1} 
( { - \sqrt{\lambda} x^\alpha  } ) - E_{\alpha ,1} ( { - \sqrt{\lambda} }
)E_{\alpha ,1} ( {\sqrt{\lambda} x^\alpha  } )}}{{2\sqrt{\lambda}
E_{2\alpha ,\alpha  + 1} ( {\lambda } )}}, \\
\label{2.4}
S( {\lambda x} ) =
\frac{{x^\alpha  E_{2\alpha ,\alpha  + 1} ( {\lambda
x^{2\alpha } } )}}{{E_{2\alpha ,\alpha  + 1} ( {\lambda} )}}.
\end{gather}
 Here
 $$
E_{\alpha ,\mu } ( z) = \sum_{k = 0}^\infty {\frac{{z^k }}{{\Gamma (
{\alpha k + \mu } )}}}
$$ 
is the Mittag - Leffler type
function \cite{Kilbas2006}.
\end{lemma}

It is easy to see that the function 
$E_{\alpha ,1} ( {\pm\sqrt{\lambda} x^\alpha  } )$ for $0 < \alpha  < 1$ 
satisfies the equation
\begin{equation}\label{3*}
\nu''(x) \mp \lambda D^{2 - \alpha }_{0+} \nu(x) = 0, x\in I.
\end{equation}

\begin{lemma}[\cite{Nakhushev}]\label{lem1*} 
If the function $ \nu \in C( \bar{I} )
\cap C^2 ( I )$, $\nu(x) \ne Const$ is a solution of
Equation \eqref{3*}, then it can not attain its positive maximum
(negative minimum) within the segment $\bar{I}$.
\end{lemma}

\begin{lemma}[\cite{Kilbas2006}]\label{lem2}  
For $E_{\alpha ,\beta }( z )$ as $| z | \to \infty$ the following
asymptotic estimation holds 
\begin{equation}\label{2.5}
E_{\alpha,\beta } (z) = \frac{1}{\alpha }z^{\frac{{( {1 - \beta }
)}}{\alpha }} e^{z^{\frac{1}{\alpha }} }  - \sum_{k =1}^p 
{\frac{{z^{ - k} }} {{\Gamma ( {\beta  - \alpha k} )}}}  
+ O( {\frac{1}{{| z |^{p + 1} }} } ),
\end{equation} 
where $| {\arg z} | \le \rho _1\pi$, 
$\rho _1  \in ( {\frac{\alpha }{2},\min \{ {1,\alpha
} \}} ),\alpha \in ( {0,2} )$, and for
$\arg z = \pi$ 
\begin{equation}\label{2.6}
E_{\alpha ,\beta } (z) =
\frac{1}{{1 + | z |}},| z | \to \infty.
\end{equation}
\end{lemma}

It is easy to show that functions $C_k$ and $S_k$ are solutions of 
 \eqref{3*} and 
\begin{equation}
\begin{gathered}
C_k(0)=1,\quad C_k(1)=0,\\ 
S_k(0)=0,\quad S_k(1)=1.
\end{gathered}
\end{equation}

\begin{lemma}\label{lem3} 
For any $x \in [0,1]$ the following inequalities hold: 
$$
0 \le S( {\lambda x} ), \quad C( {\lambda x}) \le 1.
$$
\end{lemma}

An application of the Fourier method to Problem \ref{prob1} leads to the 
eigenvalue problem
\begin{equation}\label{3.1}
\mathcal{L}:=\mathcal{D}_{y,a+}^\beta D_{y,b-}^\beta \tau( y )  = \lambda \tau( y ), 
\quad a < y < b,
\end{equation}
with the conditions
\begin{equation}\label{3.2}
I_{y,b-}^{1-\beta}\tau( { a }) =0,\quad  I_{y,b-}^{1-\beta}\tau ( b ) = 0.
\end{equation}
For the fractional Sturm-Liouville problem \eqref{3.1}-\eqref{3.2} 
the following assertions are true \cite{TT16}.

\begin{lemma}\label{lem4}
The fractional Sturm-Liouville problem \eqref{3.1}-\eqref{3.2} 
is self-adjoint and positive in $L^2 ( {a, b})$.
\end{lemma}

\begin{lemma}\label{lem4*}
The spectrum of the fractional Sturm-Liouville problem \eqref{3.1}-\eqref{3.2} 
is discrete and positive, and the system of eigenfunctions is a complete 
orthogonal basis in $L^2 ( {a, b})$.
\end{lemma}

It is not difficult to show that the eigenvalue problem \eqref{3.1}-\eqref{3.2} 
is equivalent to the integral equation
\begin{equation}\label{IntEq} 
\mathcal{L}^{-1}\tau(y):=\int_a^b \mathcal{K}(y,\xi) \tau(\xi)d\xi
=\lambda^{-1}\tau(y),
\end{equation} 
where $\mathcal{K}(y,\xi)=\int_{\max\{y,\xi\}}^b\frac{(\zeta-y)^{\beta-1}(\zeta-\xi)^{\beta-1}}{\Gamma^2(\beta)}d\zeta$.

Now we state the following theorem proved by Delgado and Ruzhansky \cite{DR14}

\begin{theorem}\label{th_DR}
Let $M$ be a closed manifold of dimension $n$. Let $K$ belongs to the Sobolev 
space $H^\mu (M \times M)$ for some index $\mu > 0$. Then the integral operator 
$T$ on $L^2(M)$, defined by $$(Tf)=\int_M K(x,s)f(s)ds,$$ is in the Schatten 
classes $S_p(L^2(M))$ for $p>\frac{2n}{n+2\mu}$.
\end{theorem}

\begin{corollary}\label{cor_Schatten}
The operator $\mathcal{L}^{-1}$, defined on $L^2(a, b)$ by \eqref{IntEq} is 
in the Schatten classes $S_p(L^2(a,b))$ for $p>\frac{2}{1+4\beta}$.
\end{corollary}

The above corollary  provides a useful spectral property;
 that is, 
\begin{equation}\label{*}
\sum_{k=1}^\infty \frac{1}{\lambda_k^p}<\infty
\end{equation} 
for any $p>\frac{2}{1+4\beta}$.


\section{Well-posedness of Problem \ref{prob1}}

\begin{theorem}\label{th1} 
Let $0 < \delta  < 1$,
$\mathcal{D}_{y,a+}^\beta D_{y,b-}^\beta \varphi ( y ) \in C^{1+\delta} [ {a, b} ]$, 
$\mathcal{D}_{y,a+}^\beta D_{y,b-}^\beta \psi ( y ) \in C^{\delta} [ {a, b} ]$
 and 
\begin{gather*}
I_{y,b-}^{1-\beta}\varphi ( { a } )
 = I_{y,b-}^{1-\beta}\varphi ( b  ) = 0,\\
I_{y,b-}^{1-\beta}\psi ( { a } )
 = I_{y,b-}^{1-\beta}\psi ( b ) = 0.
\end{gather*}
Then the solution of Problem \ref{prob1} exists and is unique. Moreover, it can 
be written in the form
\begin{equation}\label{solution}
u({x,y} ) = \sum_{k = 1}^\infty  {[ {\varphi _{k} C( {\lambda_{k} x} ) 
+ \psi _{k} S( {\lambda_{k} x} )} ]} \tau_{k} ( y ),
\end{equation}
where $\varphi _{k}=(\varphi(y),\tau_k(y))$, $\psi _{k}=(\psi(y),\tau_k(y))$ 
and $\tau_k(y)$ are eigenfunctions of the problem \eqref{3.1}-\eqref{3.2} 
form an orthonormal basis in $L^2(a, b)$.
\end{theorem}

\begin{proof}
\textbf{Existence of the solution.}
Since the system of eigenfunctions
$\{\tau_k(y)\}_{k\in\mathbb{N}}$
of the fractional Sturm-Liouville problem \eqref{3.1}-\eqref{3.2} 
forms an orthonormal basis in $L^2(a, b)$, the function $u$ can be 
represented as follows 
\begin{equation}\label{5.1} 
u( {x,y} ) = \sum_{k = 1}^\infty  {\nu_{k} ( x )\tau_{k} ( y )},\quad 
\text{in }\ \Omega,
\end{equation} 
where $\nu_{k}(x)$ are unknown functions. It is well known that if 
$\varphi ( y )$ and $\psi ( y )$ satisfy the conditions of Theorem \ref{th1},
then they can be uniquely represented in uniformly and absolutely convergent 
Fourier series by $\{ {\tau_{k} (y)} \}$:
\begin{gather*}
\varphi ( y ) = \sum_{k = 1}^\infty  {\varphi _{k} \tau_{k}( y )},\\
\psi ( y ) = \sum_{k = 1}^\infty  {\psi _{k} \tau_{k}( y )},
\end{gather*}
where $\varphi _{k}  = ( {\varphi, \tau_{k}} )$, 
$\psi _{k}  = ( {\psi, \tau_{k}} )$.

Putting \eqref{5.1} into  \eqref{1.1} and boundary conditions \eqref{1.2}, 
for unknown functions $\nu_k (x )$, we obtain the problem
\begin{gather}\label{5.2}
\mathcal{D}_{0+}^{\alpha }\mathcal{D}_{0+}^{\alpha } \nu_{k} ( x) 
- \lambda_{k} \nu_{k} ( x ) = 0, \quad 0 <x < 1, \\
\label{5.3}
\nu_{k}( 0 ) = \varphi _{k},\quad \nu_{k} ( 1) = \psi _{k}.
\end{gather}

By Lemma \ref{lem1} the solution of \eqref{5.2}-\eqref{5.3}
exists, is unique and it can be written in the form 
$$
\nu_{k}( x ) = \varphi _{k} C( {\lambda_{k} x}) + \psi _{k} S( {\lambda_{k} x} ),
$$ 
where $C( {\lambda_{k} x} )$ and $S( {\lambda_{k} x} )$ are defined by \eqref{2.3} 
and \eqref{2.4}, respectively. Furthermore, according to Lemma \ref{lem3}  
inequalities 
$$
0 \le S( {\lambda_{k} x} ),\,C( {\lambda_{k}x} ) \le 1,x \in [ {0,1} ]
$$ 
are true.

If for $\varphi$ and $\psi$ the conditions of Theorem \ref{th1} hold then 
$$
|{\varphi_{k} } | \le \frac{C}{{\lambda_k^{2 + \delta }}},\,| {\psi_{k} } | 
\le \frac{C}{{\lambda_k^{1 + \delta } }},\quad C = \text{const}.
$$ 
For such functions,
we obtain 
\begin{equation}
| {\nu_{k} ( x)} | \le C\Big( {\frac{1}{{\lambda_k^{2 + \delta } }} +
\frac{1}{{\lambda_k^{1 + \delta } }}}\Big).\label{5.4}
\end{equation}
Then  taking into account the property \eqref{*} the convergence of the 
series \eqref{5.1} is obvious in $u( {x,y} ) \in C({\bar \Omega } )$.
Further, using estimates \eqref{2.5}
and \eqref{2.6}, we get
\begin{gather}\label{S(x)}
S_{k} ( {\lambda_{k} x}) 
= O( {\text{e}^{\lambda_{k}^{1/\alpha} ({x - 1} )} } ), \\
C( {\lambda_{k} x}) = O( {\frac{1}{{\sqrt{\lambda_{k}} }}} ). \nonumber
\end{gather}
Applying $\mathcal{D}_{y,a+}^\beta D_{y,b-}^\beta$ term by term of the 
series \eqref{5.1}, one obtains
$$
\mathcal{D}_{y,a+}^\beta D_{y,b-}^\beta u( {x,y} ) 
=  \sum_{k = 1}^\infty  {\lambda _{k} \nu_{k} ( x )\tau_{k} ( y )}.
$$
Then for all $x \ge x_0  > 0$, $a \le y \le b$, by taking into account 
inequalities \eqref{5.4}, we have
\begin{align*}
| {\mathcal{D}_{y,a+}^\beta D_{y,b-}^\beta u( {x,y} )} | 
& \le C\sum_{k = 1}^\infty  | {\lambda _{k}} || {\nu_{k} ( x )} | \\
& \le C\sum_{k = 1}^\infty \lambda^{- 1 - \delta }  
 + \lambda^{- \delta } e^{ - \lambda_{k} ( {1 - x} )}.
\end{align*}
Similarly, we can estimate the series 
$$
\mathcal{D}_{x,0+}^{\alpha } \mathcal{D}_{x,0+}^{\alpha } u( {x,y} ) 
= \sum_{k = 1}^\infty \lambda_{k} \nu_{k} ( x )\tau_{k} ( y ).
$$ 
Then $\mathcal{D}_{y,a+}^\beta D_{y,b-}^\beta u( {x,y} )$,
$\mathcal{D}_{x,0+}^{\alpha } \mathcal{D}_{x,0+}^{\alpha } u( {x,y} ) 
\in C( \Omega  )$.
\smallskip

\noindent\textbf{Uniqueness of the solution.} 
Suppose that there are two solutions $u_1 ( {x,y} )$ and $u_2 ( {x,y} )$ 
of Problem \ref{prob1}. Denote 
$$
u( {x,y}) = u_1 ( {x,y} ) - u_2 ( {x,y} ).
$$
Then the function $u( {x,y} )$ satisfies \eqref{1.1} and homogeneous conditions
\eqref{1.2} and \eqref{1.3}.

Let
\begin{equation}\label{5.2*}
u_{k} (x ) = \langle u(x,y),\tau_k(y)\rangle, k \in \mathbb{N}.
\end{equation}
Applying the operator $\mathcal{D}^\alpha_{0+}\mathcal{D}^\alpha_{0+}$ 
to Equation \eqref{5.2}, we have
\begin{align*}
\mathcal{D}^\alpha_{0+}\mathcal{D}^\alpha_{0+} u_{k} ( x) 
= \langle \mathcal{D}_{x,0+}^{\alpha } \mathcal{D}_{x,0+}^{\alpha }u(x,y),
\tau_k(y)\rangle 
=\langle \mathcal{D}_{a+,y}^{\beta}D^{\beta}_{b-,y}u(x,y),\tau_k(y)\rangle.
\end{align*}
Integrating by parts and taking into account the homogeneous
condition \eqref{1.2}, we obtain 
$$
\mathcal{D}^\alpha_{0+}\mathcal{D}^\alpha_{0+} u_{k} ( x)-\lambda_k u_k(x) = 0, \quad
u_{k}( 0 ) = 0,\quad  u_{k}( 1 ) =0.
$$
Consequently from Lemma \ref{lem1} we get $u_{k} ( x ) \equiv 0$.

Further, by the completeness of the system $\{\tau_k(x)\}_\mathbb{N}$ in 
$L^2 (a,b)$ we conclude that
$$
u({x,t} ) \equiv 0,\quad 0 \le x \le 1,\quad  a \le y \le b.
$$
Hence, the uniqueness of the solution of Problem \ref{prob1} is proved.
\end{proof}

\section{Well-posedness of Problem \ref{prob2}}

\begin{theorem}\label{th2} 
Let $0 < \delta  < 1$,
$\mathcal{D}_{y,a+}^\beta D_{y,b-}^\beta \phi ( y ) \in C^{1+\delta} [ {a, b} ]$ and 
$$
I_{y,b-}^{1-\beta}\phi ( { a } ) =
I_{y,b-}^{1-\beta}\phi ( b  ) = 0.
$$
Then the solution of Problem \ref{prob2} exists, is unique and can be represented as
\begin{equation}\label{solution2}
u({x,y} ) = \sum_{k = 1}^\infty \phi_{k} E_{\alpha,1}
(-\sqrt{\lambda_k} x^\alpha) \tau_k( y ),
\end{equation}
where $\phi _{k}=(\phi, \tau_k)$, and $\{\tau_k(y)\}_{k\in\mathbb N}$ 
is the system of eigenfunctions of the problem \eqref{3.1}-\eqref{3.2} 
forms an orthonormal basis in $L^2(a, b)$.
\end{theorem}

\begin{proof} 
By applying the Fourier method to solve Problem \ref{prob2}, we lead it to the
spectral problem \eqref{3.1}--\eqref{3.2}. The system 
$\{\tau_k(y)\}_{k\in\mathbb N}$ is an orthonormal basis in the space $L^2(a, b)$.
 Thus, a regular solution of Problem \ref{prob2} for all $x > 0$ can be represented as the
series
\begin{equation}\label{s1}
u(x,y)=\sum_{k=1}^\infty u_k(x)\tau_k(y),
\end{equation}
where $u_k(x)$ is an unknown function. We expand the function $\phi (y)$ into 
the Fourier series by the system $\{\tau_k(y)\}_{k\in\mathbb N}$, that is,
\begin{equation}\label{s2}
\phi(y)=\sum_{k=1}^\infty \phi_k\tau_k(y),
\end{equation}
where $\phi _{k}=(\phi,\tau_k)$.

Let us consider functions
\begin{equation}\label{s3}
u_{k} (x ) = \int_a^b u(x,y)\tau_k(y)dy, \quad k \in \mathbb{N}.
\end{equation}
Applying the operator $\mathcal{D}^\alpha_{0+}\mathcal{D}^\alpha_{0+}$ 
to the functions \eqref{s3} and by taking into account Equation \eqref{1.1}, 
we have
\[
\mathcal{D}^\alpha_{0+}\mathcal{D}^\alpha_{0+} u_{k} ( x) 
= \int_a^b \mathcal{D}_{x,0+}^{\alpha } \mathcal{D}_{x,0+}^{\alpha }u(x,y)\tau_k(y)dy 
=\int_a^b\mathcal{D}_{a+,y}^{\beta}D^{\beta}_{b-,y}u(x,y)\tau_k(y)dy.
\]
Twice integrating by parts the last integral and by using the conditions 
\eqref{1.4} and \eqref{1.5}, we obtain
\begin{gather}\label{s4}
\mathcal{D}_{x,0+}^{\alpha }\mathcal{D}_{x,0+}^{\alpha } u_{k} ( x) 
- \lambda_{k} u_{k} ( x ) = 0, \quad 0 <x < +\infty, \\
\label{s5}
u_{k}( 0 ) = \phi _{k},\quad \lim_{x\to+\infty} |u_{k} ( x)| \to 0.
\end{gather}
The general solution of Equation \eqref{s4} has the form
$$
u_k(x)=C_1 E_{\alpha,1}(\sqrt{\lambda_k} x^\alpha)
+C_2 E_{\alpha,1}(-\sqrt{\lambda_k} x^\alpha),
$$
where $C_1$ and $C_2$ are unknown constants. Since 
$E_{\alpha,1}(\sqrt{\lambda_k} x^\alpha)$ is completely monotonic \cite{Miller}, 
that is,
$$
E_{\alpha,1}(\sqrt{\lambda_k} x^\alpha)\to\infty,\quad x\to+\infty,
$$
we need to choose $C_1=0$ to have the second condition in \eqref{s5}. Then
$$
u_k(x)=C_2 E_{\alpha,1}(-\sqrt{\lambda_k} x^\alpha)
$$
and by the first condition in \eqref{s5} we have
$$
u_k(x)=\phi_k E_{\alpha,1}(-\sqrt{\lambda_k} x^\alpha).
$$
Furthermore, the identity \eqref{s3} directly implies the uniqueness of 
the solution of Problem \ref{prob2}: if $\phi (y) = 0$ on $[a, b]$ then 
$u_k (x) = 0$ on $[0,+\infty)$. Consequently, due to the completeness 
of the system $\{\tau_k (y)\}_{k\in\mathbb N}$ we obtain $u (x, y) = 0$ for all 
$(x, y)\in \Omega_\infty$.

Therefore, the formal solution of Problem \ref{prob2} can be represented as in \eqref{solution}. If
the function $\phi (y)$ satisfies conditions of Theorem \ref{th2}, then 
for the Fourier coefficients we get inequality:
$$
|\phi_k|\leq \frac{C}{\lambda_k^{1+\delta}}.
$$
Then for all $y\in [a, b]$, for each $x\in[0, +\infty)$ we conclude
$$
|u(x,y)|\leq \sum_{k=1}^\infty\frac{C}{\lambda_k^{1+\delta}}<\infty,
$$
i.e., the series \eqref{solution} converges uniformly in the domain 
$[a, b]\cap[0, \infty)$. Therefore, $u\in C(\bar\Omega_{\infty})$. 
Similarly, we show that $\mathcal{D}_{x,0+}^{\alpha } 
\mathcal{D}_{x,0+}^{\alpha }u\in C(\Omega_{\infty})$,
$\mathcal{D}_{y,a+}^{\beta}D^{\beta}_{y,b-}u\in C(\Omega_{\infty})$. 
The proof is complete.
\end{proof}

\section{Non-Homogeneous case}
In this section we study a non-homogeneous fractional Laplace equation
\begin{equation}\label{h.1}
\mathcal{D}_{x,0+}^\alpha \mathcal{D}_{x,0+}^\alpha u(x,y) 
- \mathcal{D}_{y,a+}^\beta D_{y,b-}^\beta u(x,y) = f(x, y), \quad  (x, y)\in \Omega,
\end{equation}
with the boundary conditions
\begin{gather}\label{h.2}
u( {0,y} ) = 0,\quad u( {1,y} ) = 0, \quad  a  \le y \le b, \\
\label{h.3}
I^{1-\beta}_{b-,y}u(x,a)=0,\quad I^{1-\beta}_{b-,y}u(x,b)=0,\quad  0 \le x \le 1,
\end{gather}
for some sufficiently smooth function $f$.

\begin{theorem}\label{th1-h}
Let $0 < \delta  < 1$. Assume that $f \in C( {\bar \Omega } )$.
Then there is a unique solution $u \in
C( {\bar \Omega } )$ of the problem \eqref{h.1}-\eqref{h.3} such that
$$
\mathcal{D}_{x,0+}^{\alpha } u\in C( \Omega  ), \quad
\mathcal{D}_{x,0+}^{\alpha } \mathcal{D}_{x,0+}^{\alpha }u \in C( \Omega  ), \quad
\mathcal{D}_{y,a+}^\beta D_{y,b-}^\beta u  \in C( \Omega  ).
$$
Moreover, we have the expansion
\begin{equation}\label{h-Solution-n}
\begin{split}
u( {x,y} ) 
&= \sum_{k = 1}^\infty  \tau_{k} ( y )\int^x_0(x-s)^{2\alpha-1}
 C_k(\lambda_k (x-s))f_k(s)ds\\
&\quad -\sum_{k = 1}^\infty  \tau_{k} ( y )S( {\lambda_{k} x} )
 \int^1_0(1-s)^{2\alpha-1}C_k(\lambda_k (1-s))f_k(s)ds.
\end{split}
\end{equation}
Here, $f_k(x)$ is from 
$$
f(x,y)=\sum_{k=1}^{\infty}f_k(x)\tau_k(y),
$$
where $\{\tau_{k}\}_{k=1}^{\infty}$ is an orthonormal basis in 
$L^2(a, b)$ and a system of eigenfunctions generated by the spectral
problem \eqref{3.1}--\eqref{3.2}; that is,
\begin{equation*}\label{h-3.1}
\mathcal{D}_{y,a+}^\beta D_{y,b-}^\beta \tau( y )  = \lambda \tau( y ), \quad
a  < y < b,
\end{equation*}
with the conditions
\begin{equation*}%\label{h-3.2}
I_{y,b-}^{1-\beta}\tau( { a }) =0,\quad I_{y,b-}^{1-\beta}\tau ( b ) = 0.
\end{equation*}
\end{theorem}

\begin{proof}
\textbf{Existence of the solution.} 
Since the system of eigenfunctions $\{\tau_k(y)\}_{k=\mathbb{N}}$ of 
the fractional problem \eqref{3.1}--\eqref{3.2} forms an orthonormal basis 
in $L^2(a, b)$, then for $u$ we obtain the representation
\begin{equation}\label{h-5.1}
u( {x,y} ) = \sum_{k = 1}^\infty  {\nu_{k} ( x )\tau_{k} ( y )}, \quad 
(x,y)\in\Omega,
\end{equation}
where $\nu_{k}(x)$ are unknown functions.

By using the representation \eqref{h-5.1}, from \eqref{h.1}--\eqref{h.2} 
for the unknown functions $\nu_k (x )$ we get the  problem
\begin{gather} \label{h-5.2}
\mathcal{D}_{x,0+}^{\alpha }\mathcal{D}_{x,0+}^{\alpha } \nu_{k} ( x)
 - \lambda_{k} \nu_{k} ( x ) = f_k(x), \quad 0 <x < 1, \\
\label{h-5.3}
\nu_{k}( 0 ) = 0,\quad \nu_{k} ( 1) = 0.
\end{gather}
Applying the method in \cite{TurmetovFCAA}, it is not difficult to show that 
the general solution of Equation \eqref{h-5.2} has the form 
\begin{equation}\label{nhom-eq-sol}
\begin{aligned}
\nu_k(x) & =C_1E_{\alpha,1}(\sqrt{\lambda_k}x^\alpha)
 + C_2E_{\alpha,1}(-\sqrt{\lambda_k}x^\alpha)\\ 
&\quad +\int^x_0(x-s)^{2\alpha-1}C_k(\lambda_k (x-s))f_k(s)ds.
\end{aligned}
\end{equation}
Using the boundary conditions \eqref{h-5.3}, we obtain the unique solution
 of the problem \eqref{h-5.2}-\eqref{h-5.3}
\begin{align*}
\nu_{k}( x ) 
&= \int^x_0(x-s)^{2\alpha-1}C_k(\lambda_k (x-s))f_k(s)ds\\
&\quad -S( {\lambda_{k} x} )\int^1_0(1-s)^{2\alpha-1}C_k(\lambda_k (1-s))f_k(s)ds,
\end{align*}
where $S( {\lambda_{k} x} )$ is defined by \eqref{2.4}. Furthermore, according 
to Lemma \ref{lem3},  the following inequality holds
$$
0 \le S( {\lambda_{k} x} ),\quad  C( {\lambda_{k} x} ) \le 1, \quad x \in [ {0,1} ].
$$
Now, By Lemma \ref{lem3}, $\nu_k$ satisfies 
\begin{align*}
&|\nu_{k}( x )| \\
&\leq \int^x_0(x-s)^{2\alpha-1}C_k(\lambda_k (x-s))|f_k(s)|ds
 +\int^1_0(1-s)^{2\alpha-1}C_k(\lambda_k (1-s))|f_k(s)|ds\\
&\leq \max_{x}|f_k|(x^{2\alpha} C_k(\lambda_k x)+C_k(\lambda_k ))\\
&\leq C\frac{\max_{x}|f_k|}{1+\lambda_k},
\end{align*}
where $C$ is a constant. 
Then the series \eqref{h-Solution-n} converges uniformly in the domain
$\bar \Omega$ and therefore $u( {x,y} ) \in C({\bar \Omega } )$.
Further, using the estimate
$$
S_{k} ( {\lambda_{k} x}) = O( {\text{e}^{\lambda_{k}^{1/\alpha} ({x - 1} )} } ),
$$
we can prove that $\mathcal{D}_{y,a+}^\beta D_{y,b-}^\beta u( {x,y} ),
\mathcal{D}_{x,0+}^{\alpha } \mathcal{D}_{x,0+}^{\alpha } u( {x,y} ) 
\in C( \Omega  )$.

Uniqueness of the solution of the problem \eqref{h.1}-\eqref{h.3} 
follows from the uniqueness of the solution of Problem \ref{prob1}.
\end{proof}


\subsection*{Acknowledgements}
N. Tokmagambetov was supported by the MESRK Grant No. AP05130994 of the
Committee of Science, Ministry of Education and Science of the
Republic of Kazakhstan. 
B. T. Torebek was supported by the
MESRK Grant No. AP05131756 of the Committee of Science, Ministry of
Education and Science of the Republic of Kazakhstan.

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\end{document}
