\documentclass[reqno]{amsart}
\usepackage{hyperref}

\AtBeginDocument{{\noindent\small
\emph{Electronic Journal of Differential Equations},
Vol. 2017 (2017), No. 77, pp. 1--21.\newline
ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu}
\thanks{\copyright 2017 Texas State University.}
\vspace{8mm}}

\begin{document}
\title[\hfilneg EJDE-2017/77\hfil Nonlinear perturbations]
{Nonlinear perturbations of the Kirchhoff equation}

\author[M. Milla Miranda, A. T. Louredo, L. A. Medeiros \hfil EJDE-2017/77\hfilneg]
{Manuel Milla Miranda, Aldo T. Louredo, Luiz A. Medeiros }

\address{Manuel Milla Miranda \newline
Universidade Estadual da Para\'iba, DM, PB, Brazil}
\email{milla@im.ufrj.br}

\address{Aldo T. Louredo \newline
Universidade Estadual da Para\'iba, DM, PB, Brazil}
\email{aldolouredo@gmail.com, Phone +55 (83) 3315-3340}

\address{Luiz A. Medeiros \newline
Universidade Federal do Rio de Janeiro, IM, RJ, Brazil}
\email{luizadauto@gmail.com}

\dedicatory{Communicated by Jerome A. Goldstein}

\thanks{Submitted January 24, 2017. Published March 21, 2017.}
\subjclass[2010]{35L15, 35L20, 35K55, 35L60, 35L70}
\keywords{Kirchhoff equation; nonlinear boundary condition; 
\hfill\break\indent existence of solutions}

\begin{abstract}
 In this article we study the existence and uniqueness of local solutions
 for the initial-boundary value problem for the Kirchhoff equation
 \begin{gather*}
 u'' - M(t,\|u(t)\|^{2})\Delta u + |u|^{\rho} =f \quad\text{in }
 \Omega \times (0, T_0), \\
 u=0\quad\text{on }\Gamma_0 \times ]0, T_0[, \\
 \frac{\partial u}{\partial \nu} + \delta h(u')=0 \quad\text{on }
 \Gamma_1 \times ]0, T_0[,
 \end{gather*}
 where $\Omega$ is a bounded domain of $\mathbb{R}^n$ with its boundary
 constiting of two disjoint parts $\Gamma_0$ and $\Gamma_1$;
 $\rho >1$ is a real number; $\nu(x)$ is the exterior unit normal vector at
 $x \in \Gamma_1$ and $\delta(x), h(s)$ are real functions defined in
 $\Gamma_1$ and $\mathbb{R}$, respectively.
 Our result is obtained using the Galerkin method with a special basis,
 the Tartar argument, the compactness approach, and a Fixed-Point method.
\end{abstract}

\maketitle
\numberwithin{equation}{section}
\newtheorem{theorem}{Theorem}[section]
\newtheorem{lemma}[theorem]{Lemma}
\newtheorem{proposition}[theorem]{Proposition}
\newtheorem{remark}[theorem]{Remark}
\allowdisplaybreaks

\section{Introduction}

Frist we do some preliminary considerations  to justify the mixed
problem we want to study.
 Milla Miranda and Medeiros \cite{mm-lam}
 analyzed the existence of solutions for problem
\begin{equation}\label{I1.1}
 \begin{gathered}
 u'' - \mu(t) \Delta u=0 \quad\text{in } \Omega \times (0, \infty), \\
 u=0 \quad\text{on } \Gamma_0 \times (0, \infty), \\
\mu(t) \frac{\partial u}{\partial \nu} + \delta(x) u'=0\quad\text{on }\Gamma_1 \times
(0, \infty), \\
u(x,0)=u_0(x),\quad u'(x,0)=u_1(x),\quad x \in\Omega.
 \end{gathered}
\end{equation}

When $\mu$ is a positive constant, existence and uniqueness of global solutions
for \eqref{I1.1} has been proved by Komornik and Zuazua
\cite{Komornik}, Lasiecka and Triggiane \cite{triggiane} and Quinn
and Russell \cite{Quinn e Russell33}, Goldstein \cite{Goldstein}
applying semigroup theory. This
method does not work for \eqref{I1.1} because the boundary condition \eqref{I1.1}$_3$
brings serious difficulties. For this reason, the authors of \cite{mm-lam} defined
a special basis of the space where lie the approximations of the initial data and
apply the Galerkin method. This approach works well for problem \eqref{I1.1}.

Motivated by \eqref{I1.1}, Milla Miranda and Jutuca \cite{Jutuca} analized
the initial-boundary value problem for the Kirchhoff equation
\begin{equation}\label{I1.2}
\begin{gathered}
 u'' - M\Big(t,\int_{\Omega}|\nabla u|^2dx \Big) \Delta u=f
\quad\text{in } \Omega \times (0, \infty), \\
 u=0 \quad\text{on } \Gamma_0 \times (0, \infty), \\
\mu(t) \frac{\partial u}{\partial \nu} + \delta(x) u'=0\quad\text{on }
\Gamma_1 \times
(0, \infty), \\
u(x,0)=u_0(x),\quad u'(x,0)=u_1(x),\quad x \in\Omega.
 \end{gathered}
\end{equation}
Following the ideas in \cite{mm-lam} but having much more difficulty,
the authors of \cite{Jutuca}, succeeded in the
construction of a special basis and the Galerkin method works well for
\eqref{I1.2}. They proved existence and
uniqueness of solutions for \eqref{I1.2}.
 See also \cite{Cavalcanti,Ong}.

An extensive list of references about the Kirchhoff equation can be found
in Medeiros, Limaco and Menezes \cite{silvano}.
In Medeiros et al.\ \cite{adautociceroejuan} was investigated the existence
and uniqueness of global solutions for the problem
\begin{equation}\label{I1.3}
\begin{gathered}
 u'' - \Delta u + |u|^\rho =f\quad\text{in }\Omega \times (0,\infty) \\
 u=0\quad\text{on }\Gamma \times (0, \infty) \\
 u(x,0)=u^0(x),\quad u'(x,0)=u^1(x),\quad x \in \Omega
 \end{gathered}
\end{equation}
There, Galerkin method and Tartar argument \cite{Tartar} were applied.

Motivated by the studies of \eqref{I1.1}-\eqref{I1.3}, we investigate the
 existence and uniqueness of local solutions of the initial
value problem for the nonlinear mixed problem of Kirchhoff type:
\begin{equation}\label{I1.4}
\begin{gathered}
 u'' - M\Big(t, \int_{\Omega}|\nabla u|^2dx \Big) \Delta u +|u|^\rho
=f \quad\text{in } \Omega \times (0, T_0), \\
 u=0 \quad\text{on } \Gamma_0 \times (0, T_0), \\
\frac{\partial u}{\partial \nu} + \delta (x) h(u')=0\quad\text{on }\Gamma_1 \times
(0, T_0), \\
u(x,0)=u^0(x),\quad u'(x,0)=u^1(x),\quad x \in\Omega.
 \end{gathered}
\end{equation}

By applying the Galerkin method with a special basis, a modification of the
Tartar approach, compactness method and fixed-point theorem, we obtain our result.

Note that the existence of global solutions for \eqref{I1.4} without the term
$|u|^\rho=0$, null Dirichlet boundary condition on
$\Gamma$ and $u^0 \in H_0^1(\Omega) \cap H^2(\Omega)$,
 $u^1\in H_0^1(\Omega)$ is a open question.

\section{Notation and statement of main results}

Let $\Omega$ be bounded open set of $\mathbb{R}^n$ with boundary $\Gamma$
of class $C^2$. It is assumed that
$\Gamma$ is constituted by two disjoint parts $\Gamma_0$ and $\Gamma_1$,
$\Gamma_0$ and $\Gamma_1$ with positive
measures, such that $\overline{\Gamma_0} \cap\overline{ \Gamma_1}= \emptyset$.
By $\nu(x)$ represents the unit normal vector at $x \in \Gamma_1$.

We denote by $H^m(\Omega)$ the Sobolev space of order $m$ and
by $(u,v)$ and $|u|$, the scalar product and norm, respectively,
in $L^2(\Omega)$.
We define the Hilbert space
$$
V=\{v\in H^1(\Omega): v=0\text{ on }\Gamma_0\},
$$
equipped with the scalar product
$$
((u,v))=\sum_{i=1}^n \int_{\Omega}\frac{\partial u}{\partial x_i}(x)
\frac{\partial v}{\partial x_i}(x)\,dx
$$
and norm $\|u\|^2=((u,u))$. All scalar functions considered in this article
 will be real-valued.
To state our main result, we introduce the following hypotheses:
\begin{itemize}
\item[(H1)] The function $M(t, \lambda)$ satisfies
$M \in W^{1,\infty }_{\rm loc}([0, \infty[^2 )$,
 $M(t, \lambda)\geq m_0>0$ for all $\{t, \lambda\} \in ([0, \infty[)^2$
 with $m_0$ constant.

\item[(H2)] The function $h$ is a Lipschitz continuous, $h(0)=0$,
and $h$ is strongly monotonous, that is, for a positive constant $d_0$,
\[
 (h(r)-h(s))(r-s)\geq d_0(r-s)^2,\quad \forall r,s \in
\mathbb{R}.
\]

\item[(H3)] $\delta \in W^{1, \infty}(\Gamma_1)$ and $\delta(x)\geq \delta_0$
for all $x \in \Gamma_1$ and a positive constant $\delta_0$.

\item[(H4)] The real number $\rho$ satisfies the following restrictions
\begin{equation}\label{q6}
\rho >1 \text{ if }n=1,2; \quad
\frac{n+1}{n} \leq \rho \leq \frac{n}{n-2} \text{ if } n\geq 3.
\end{equation}

\end{itemize}

Let $h: \mathbb{R}\to \mathbb{R}$ be a Lipschitz continuous function
with $h(0)=0$. In Marcus and Mizel
\cite{marcus} (see also \cite{cazenave}) it is shown that
$h(v) \in H^{1/2}(\Gamma_1)$ for $v \in H^{1/2}(\Gamma_1)$ and
$h: H^{1/2}(\Gamma_1) \to H^{1/2}(\Gamma_1)$, $v\mapsto h(v)$,
is continuous.

\begin{remark}\label{obs2.1}\rm
Consider the trace of order zero $\gamma_0: V \to H^{1/2}(\Gamma_1)$.
Then the map
\[
\widetilde{h}=h\circ \gamma_0, \quad \widetilde{h}: V \to H^{1/2}(\Gamma_1)
\]
is continuous.
\end{remark}

%\label{obs2.2} 
Throughout the article, to facilitate the notation,
the mapping $\widetilde{h}(v)$, $v \in V$, will be denoted by $h(v)$.


\begin{remark}\label{obs2.3} \rm
Let $\delta: \Gamma_1 \to \mathbb{R}$ be a function such that
$\delta \in W^{1, \infty}(\Gamma_1)$. Then $\delta v \in H^{1/2}(\Gamma_1)$
for $v \in H^{1/2}(\Gamma_1)$, and the linear operator
\[
\delta: H^{1/2}(\Gamma_1)\to H^{1/2}(\Gamma_1), \quad v \mapsto \delta v
\]
is continuous.

Also, the linear operators
\begin{gather*}
\delta: H^{1}(\Gamma_1)\to H^{1}(\Gamma_1),\quad v \mapsto \delta v, \\
\delta: L^2(\Gamma_1) \to L^2(\Gamma_1),~v \mapsto \delta v
\end{gather*}
are continuous. The statements in this remark follow from the theory of
interpolation of Hilbert spaces, see Lions-Magenes \cite{L-M}.
\end{remark}

Next, we state our main result.

\begin{theorem}\label{teo2.1}
Assume that hypotheses {\rm (H1)--(H4)} are satisfied. Consider
 $\{u^0,u^1\}$ in $V \cap H^2(\Omega) \times V$
satisfying the compatibility condition
 \begin{equation}\label{2.1}
\frac{\partial u^0}{\partial \nu} + \delta h(u^1)=0,
\end{equation}
and the norm condition
\begin{equation}\label{q16}
\|u^0\| < \lambda^{*}:=\Big(\frac{m_0}{3k_0^{\rho+1}} \Big)^{\frac{1}{\rho-1}},
\end{equation}
where $k_0$ is the immersion constant of $V$ in $L^{\rho +1}(\Omega)$, and
\begin{equation}\label{q15}
f\in L^1(0, T; L^2(\Omega)), \quad
f'\in L^1(0, T; L^2(\Omega))\,.
\end{equation}
Then there exist a real number $0< T_0 \leq T$, and a unique function
$u$ with
\begin{equation}\label{2.2}
\begin{gathered}
 {u} \in L^{\infty}(0,T_0; V \cap H^2(\Omega) ), \\
 {u'} \in L^{\infty}(0,T_0; V ), \\
 u'' \in L^{\infty}(0,T_0; L^2(\Omega)) \cap L^2(0, T_0; L^2(\Gamma_1)),
\end{gathered}
\end{equation}
such that $u$ satisfies
\begin{equation}\label{2.3}
 u''-M(\cdot,\|u\|^{2})\Delta u + |u|^\rho=f \quad\text{in }
L^{\infty}(0,T_0; L^2(\Omega)),
\end{equation}
\begin{equation} \label{2.4}
\begin{gathered}
 \frac{\partial u}{\partial\nu} + \delta h(u')=0 \quad\text{in }
L^{2}(0,T_0; H^{1/2}(\Gamma_1)), \\
 \frac{\partial u'}{\partial\nu} + \delta h'(u')u''=0 \quad\text{in }
L^{2}(0,T_0; L^{2}(\Gamma_1)),
\end{gathered}
\end{equation}
 and
\begin{equation}\label{2.5}
 u(0)=u^0,\quad u'(0)=u^1,
\end{equation}
\end{theorem}

\begin{remark}\label{obs2.4} \rm
By Remarks \ref{obs2.1} and \ref{obs2.3}, the function $\delta h(u^1)$ belongs to
$H^{1/2}(\Gamma_1)$. Then condition \eqref{2.1} makes sense.
\end{remark}

\section{Existence of Solutions}

To apply Banach Fixed-Point Theorem in the proof of our result,
 we introduce an auxiliary problem related to \eqref{I1.4}.

\subsection{Auxiliary Problem}
Consider the problem
\begin{equation}\label{3.1}
\begin{gathered}
 u'' - \mu \Delta u + |u|^\rho=f \quad\text{in }\Omega \times (0, \infty ), \\
 u=0 \quad\text{on }\Gamma_0 \times (0, \infty), \\
 \frac{\partial u}{\partial \nu} + \delta h(u')=0 \quad\text{on }
\Gamma_1 \times (0, \infty), \\
 u(0)=u^0,\quad u'(0)=u^1\quad\text{in }\Omega.
 \end{gathered}
\end{equation}
Where $\mu(t), h(s)$ and $\delta $ are real functions defined in $[0, \infty )$,
 $\mathbb{R}$ and $\Gamma_1$, respectively.

The existence of solutions of \eqref{3.1} is derived by applying the Galerkin
method with a special basis of $V \cap H^2(\Omega)$ and a modification of the
Tartar method. To obtain this basis we introduce some results.

\begin{lemma}\label{lema1}
Let $m$ and $n$ be functions in $L^1(0,T)$ with $m(t)\geq 0$
and $n(t)\geq 0$ a.e. $t $ in $(0,T)$ and let $a\geq 0$ be a constant.
Consider $\varphi: [0,T] \to \mathbb{R}$ continuous, $\varphi(t)\geq0$,
for all $t \in [0,T]$, and satisfying
$$
\frac{1}{2}\varphi^2(t) \leq \frac{1}{2}a^2 + \int_0^t m(\tau)\varphi(\tau) d\tau
+ \int_0^t n(\tau) \varphi^2(\tau) d\tau,\quad \forall t \in [0,T].
$$
Then
$$
\varphi(t) \leq \Big( a + \int_0^T m(\tau)d \tau \Big)
\exp\Big( \int_0^t n(\tau)d \tau \Big), \quad
\forall t \in [0,T].
$$
\end{lemma}

The above result is a consequence of a lemma provided in Brezis
\cite[p. 157]{Brezis}.
Milla Miranda and Medeiros \cite{mm-lam} showed the
following three results:

\begin{proposition}\label{pr3.1}
Let us consider $f \in L^2(\Omega)$ and $g \in H^{1/2}(\Gamma_1)$. Then,
the solution $u$ of the problem
\begin{equation}\label{3.2}
\begin{gathered}
 -\Delta u=f \quad \text{in }\Omega, \\
 u=0 \quad \text{on } \Gamma_0, \\
\frac{\partial u}{\partial \nu}=g
\quad \text{on } \Gamma_1,
\end{gathered}
\end{equation}
belongs to $V \cap H^2(\Omega)$ and satisfies
$$
\|u\|^2_{H^2(\Omega)}\leq c\big[|f|^2 + \|g\|^2_{H^{1/2}(\Gamma_1)}\big],
$$
where the constant $c>0$ is independent of $u, f$ and $g$.
\end{proposition}

\begin{proposition}\label{pr3.2}
In $V \cap H^2(\Omega)$ the norms $H^2(\Omega)$ and
$$
\Big[ |\Delta u|^2 + \|\frac{\partial u}{\partial \nu}\|_{H^{1/2}(\Gamma_1)}^2
 \Big]^{1/2},
$$
are equivalent.
\end{proposition}

We equipp $V \cap H^2(\Omega)$ with the preceding norm.

\begin{remark}\label{obs3.1} \rm
The space $V \cap H^2(\Omega)$ is dense in $V$.
In fact, we consider the operator $A=-\Delta$ defined by the triplet
$\{V, L^2(\Omega), ((u,v))\}$. Then its domain
$D(-\Delta)$ is
$$
D(-\Delta)=\big\{v \in V \cap H^2(\Omega); \frac{\partial v}{\partial
\nu}=0  \text{ on }  \Gamma_1 \big\},
$$
is dense in $V$ (see \cite{Lions1}). As $D(-\Delta)$ is contained in
$V \cap H^2(\Omega)$, the conclusion follows.
\end{remark}

\begin{lemma}\label{pr3.3} \rm
Consider a function $\delta$ satisfying hypothesis (H3), and a Lipschitz continuous
function $h(s)$, $s \in \mathbb{R}$, with $h(0)=0$.
Take  $u^0 \in V \cap H^2(\Omega)$ and $u^1 \in V$
satisfying the condition
\begin{equation}\label{3.3}
\frac{\partial u^0}{\partial \nu} + \delta h(u^1)=0 \quad
\text{on }\Gamma_1.
\end{equation}
Then, for each $\varepsilon >0$, there exist $w$ and $z$ in
$V \cap H^2(\Omega)$ such that
\begin{gather*}
\|w-u^0\|_{V \cap H^2(\Omega)}< \varepsilon,\quad \|z-u^1\|<\varepsilon, \\
\frac{\partial w}{\partial \nu} + \delta h(z)=0 \quad \text{on }\Gamma_1.
\end{gather*}
\end{lemma}

With respect to the function $\mu$ we make the following assumptions:
\begin{equation}\label{q4}
 \mu \in W^{1,1}_{\rm loc}(0, \infty), \quad
 0< \mu_0 \leq \mu(t) \leq \mu_1,\quad \forall t \geq 0,\quad
 \mu'\in L^1(0,\infty)
\end{equation}
for some constants $\mu_0$, $\mu_1$.

Consider the real number $\rho$ satisfying the restrictions (H4). Then
\begin{equation}\label{q8}
V \hookrightarrow L^{p^{*}}(\Omega) \hookrightarrow L^{2\rho}(\Omega)
\hookrightarrow L^{\rho+1}(\Omega)\hookrightarrow
L^{\rho}(\Omega)
\end{equation}
where $p^{*}=\frac{2n}{n-2}$, $n \geq 3$. In what follows
 $X \hookrightarrow Y$ denotes that injection of the space $X$
 into the space $Y$ is continuous.
Note that when $p>1$ and $n=1$ or $n=2$, the continuous injections \eqref{q8}
without $L^{{p^{*}}}(\Omega)$ is true.

With respect to the above injections, we introduce the following notation:
\begin{equation}\label{q12}
\begin{gathered}
 \|v\|_{L^{\rho+1}(\Omega)} \leq k_0 \|v\|,\quad
 \|v\|_{L^{\rho}(\Omega)} \leq k_1 \|v\|, \\
 \|v\|_{L^{2\rho}(\Omega)} \leq k_2 \|v\|,\quad
\|v\|_{L^{(\rho-1)n}(\Omega)} \leq k_3 \|v\|, \\
 \|v\|_{L^{p^{*}}(\Omega)} \leq k_4 \|v\|
\end{gathered}
\end{equation}
for all $v \in V$.

Consider
\begin{gather}\label{00q16}
\|u^0\| < \lambda^{*}_1:=\Big(\frac{\mu_0}{3k_0^{\rho+1}} \Big)^{\frac{1}{\rho-1}},\\
\label{q06}
G(s)=\frac{1}{\rho+1}|s|^\rho s.
\end{gather}
Recall that $G(s)=\int_0^s |\tau|^\rho d \tau$.
With the above assumptions, we have the following result.

\begin{theorem}\label{teorema1}
Assume hypotheses {\rm (H1), (H3), (H4)} and \eqref{q4}. Consider
\begin{equation}\label{q15b}
u^0 \in V \cap H^2(\Omega),\quad u^1 \in V, f\in L^1(0, \infty; L^2(\Omega)),
\quad f'\in L^1_{\rm loc}(0, \infty; L^2(\Omega))
\end{equation}
satisfying \eqref{2.1} and
\begin{equation}\label{0q16}
\begin{gathered}
\|u^0\| < \lambda^{*}_1,\\
 \big(\frac{2}{\mu_0} \big)^{1/2}\Big[ (2N)^{1/2} +
\int_0^{\infty}|f(t)|dt \Big]\exp\Big( \frac{2}{\mu_0}\int_0^{\infty}|\mu'(t)|dt
\Big) < \lambda_1^{*},
\end{gathered}
\end{equation}
where
\begin{equation}\label{q17}
N=\frac{1}{2}|u^1|^2 + \frac{1}{2}\mu(0)\|u^0\|^2
+ \frac{k_0^{\rho+1}}{\rho+1}\|u^0\|^{\rho +1}.
\end{equation}
and the real number $\lambda^{*}_1$ defined in \eqref{00q16}.
Then there exists a function $u$ with
\begin{equation}\label{q18}
\begin{gathered}
u\in L^{\infty}(0, \infty; V),\quad
u'\in L^{\infty}(0, \infty; L^2(\Omega))\cap L^{\infty}_{\rm loc}(0, \infty; V)
\\
u'' \in L^{\infty}_{\rm loc}(0, \infty; L^2(\Omega)),\quad
u'\in L^{\infty}(0, \infty; L^2(\Gamma_1)); \\
u''\in L^{\infty}_{\rm loc}(0, \infty; L^2(\Gamma_1))
\end{gathered}
\end{equation}
satisfying
\begin{gather}\label{q19}
u'' - \mu \Delta u + |u|^\rho= f\quad\text{in }
L^2_{\rm loc}(0, \infty; L^2(\Omega)),\\
\label{q20}
 \frac{\partial u}{\partial \nu} + \delta h(u')=0\quad\text{in }
L^{2}_{\rm loc}(0, \infty; H^{1/2}(\Gamma_1)), \\
\label{0q20}
 \frac{\partial u'}{\partial \nu} + \delta h'(u')u''=0\quad\text{in }
L^2_{\rm loc}(0, \infty; L^2(\Gamma_1)), \\
\label{q21}
u(0)=u^0,\quad u'(0)=u^1.
\end{gather}
\end{theorem}

\subsection*{Proof of Theorem \ref{teorema1}}
By Lemma \ref{pr3.3}, we obtain sequences
$(u_l^0), (u_l^1)$ of vectors of $V \cap H^2(\Omega) $
satisfying
\begin{equation}\label{equacao3.9}
\begin{gathered}
 \lim_{l \to \infty}u_l^0=u^0 \quad \text{in }  V\cap H^2(\Omega)  \\
 \lim_{l \to \infty}u_l^1=u^1 \quad \text{in }  V  \\
 \frac{\partial u_l^0}{\partial \nu} + \delta h(u_l^1)=0 \quad \text{on }
\Gamma_1,\; \forall l \in \mathbb{N}.
 \end{gathered}
\end{equation}
We construct a special basis of $V \cap H^2(\Omega)$ as follows:
Fix $l \in \mathbb{N}$. Consider the basis
$$
\{w_1^l, w_2^l, \dots , w_j^l,\dots \} ,
$$
of $V \cap H^2(\Omega)$ satisfying $u^0, u^1 \in [w_1^l, w_2^l]$,
where $[w_1^l, w_2^l]$ denotes the subspace generated by $w_1^l, w_2^l$.
With this basis determine approximate solutions $u_{lm}(t)$ of Problem
\eqref{3.1}, that is,
\begin{equation}\label{equacao3.10}
\begin{gathered}
u_{lm}(t)=\sum_{j=1}^mg_{jlm}(t)w_j^l,  \\
\begin{aligned}
&(u''_{lm}(t), v) + \mu(t)((u_{lm}(t), v)) + (|u_{lm}(t)|^\rho, v) \\
&+  \mu(t)\int_{\Gamma_1}\delta h(u'_{lm}(t))v d\Gamma
 =(f(t),v), \quad \forall v \in V_m^l,
\end{aligned}  \\
 u_{lm}(0)=u_l^0, \quad u'_{lm}(0)=u_l^1,
 \end{gathered}
\end{equation}
where $V_m^l$ is the subspace generated by $w_1^l, w_2^l, \dots, w_m^l$.

The above finite-dimensional system has a solution $u_{lm}$ defined in
$[0, t_{lm})$.
The following estimates allow us to extend this solution to the interval
$[0, \infty)$


\subsection*{First Estimate}
 Set $v=u'_{lm}$ in \eqref{equacao3.10}$_1$. We have
\begin{align*}
&\frac{1}{2}\frac{d}{dt}|u_{lm}'(t)|^2 + \frac{1}{2}\frac{d}{dt}
\big[ \mu(t) \|u_{lm}'(t)\|^2\big]
+\frac{d}{dt}\int_{\Omega} G(u_{lm}(t))dx \\
&+ \mu(t) \int_{\Gamma_1}\delta h(u'_{lm}(t))u'_{lm}(t) d\Gamma \\
&=(f(t), u'_{lm}(t)) + \frac{1}{2}\mu'(t) \|u'_{lm}(t)\|^2.
\end{align*}
Integrating on $[0,t]$, $0< t < t_{lm}$, we obtain
\begin{equation}\label{q3.4}
\begin{aligned}
&\frac{1}{2}|u_{lm}'(t)|^2 + \frac{\mu(t)}{2}\|u_{lm}'(t)\|^2
+\int_{\Omega} G(u_{lm}(t))dt \\
&+ \int_0^t \int_{\Gamma_1}\mu(t)h(u'_{lm}(\tau))u'_{lm}(\tau) d\Gamma d\tau  \\
&=\int_0^t (f(\tau), u'_{lm}(\tau))d\tau
 + \frac{1}{2}\int_0^t\mu'(\tau) \|u'_{lm}(\tau)\|^2d \tau \\
&\quad + \frac{1}{2}|u_l^1|^2 +
\frac{\mu(0)}{2}\|u^0_l\|^2 + \int_{\Omega}G(u^0_l)dx.
\end{aligned}
\end{equation}
Using \eqref{q06}, it follows that
\begin{gather*}
 \big| \int_{\Omega}G(u_{lm}(t))dx \big|
 \leq \frac{1}{\rho+1}k_0^{\rho+1}\|u_{lm}(t)\|^{\rho+1}, \\
\big| \int_{\Omega}G(u^0_l)dx \big|\leq \frac{1}{\rho+1}k_0^{\rho+1}
 \|u^0_l\|^{\rho+1}.
\end{gather*}
Taking into account the last two inequalities in \eqref{q3.4}, and using hypotheses
\eqref{q4}$_2$ and the fact $h_l(s)s \geq d_0$, we find
\begin{equation}\label{q3.5}
\begin{aligned}
&\frac{1}{2}|u_{lm}'(t)|^2 + \frac{\mu_0}{2}\|u_{lm}(t)\|^2-
\frac{1}{\rho+1}k_0^{\rho+1}\|u_{lm}(t)\|^{\rho+1} \\
& \leq \frac{1}{2}|u_{lm}'(t)|^2 + \frac{\mu(t)}{2}\|u_{lm}(t)\|^2 +
\int_{\Omega} G(u_{lm}(t))dx  \\
&\quad + \mu_0d_0 \int_0^t \int_{\Gamma_1}[u'_{lm}(\tau)]^2 d\Gamma d\tau \\
&\leq \int_0^t |f(\tau)| |u'_{lm}(\tau)|d\tau +
\frac{1}{2}\int_0^t|\mu'(\tau)| \|u'_{lm}(\tau)\|^2d \tau + N_{1l}
\end{aligned}
\end{equation}
 where
\begin{equation}\label{q3.6}
 N_{l}= \frac{1}{2}|u_l^1|^2 +\frac{\mu(0)}{2}\|u^0\|^2
+\frac{1}{\rho+1}k_0^{\rho +1}\|u^0\|^{\rho +1}.
\end{equation}
Motivated by the expression
$$
 \frac{\mu_0}{2}\|u_{lm}(t)\|^2-\frac{1}{\rho+1}k_0^{\rho+1}\|u_{lm}(t)\|^{\rho+1}
$$
we introduce the function
\begin{equation}\label{q3.7}
 J(\lambda)= \frac{1}{4}\mu_0\lambda^2
- \frac{3}{2}\frac{k_0^{\rho +1}}{\rho+1}\lambda^{\rho +1},\quad \lambda \geq 0.
\end{equation}
That is,
$$
J'(\lambda)=\frac{1}{2}\mu_0\lambda -\frac{3}{2}k_0^{\rho +1}\lambda^{\rho}.
$$
We are interested in $\lambda \geq 0$ such that $J'(\lambda)\geq 0$, that is,
\begin{equation}\label{q3.9}
\frac{3}{2}k_0^{\rho +1}\lambda^{\rho-1} \leq \frac{1}{2}\mu_0
\end{equation}
or
\begin{equation}\label{q3.10}
0 \leq \lambda^{\rho-1} \leq \frac{\mu_0}{3k_0^{\rho+1}}.
\end{equation}
This inequality  is equivalent to $0\leq \lambda \leq \lambda^{*}_1$,
where $\lambda_1^{*}$ was defined in \eqref{q16}. Thus
\begin{equation}\label{q3.11}
J(\lambda) \geq 0\quad \text{for }\lambda \in [0, \lambda_1^{*}].
\end{equation}
As consequence of \eqref{q3.11} and hypothesis \eqref{q16}$_1$, we obtain
\begin{equation}\label{q3.12}
 \frac{\mu_0}{4}\|u_{lm}(t)\|^2-
\frac{3}{2}\frac{k_0^{\rho+1}}{\rho+1}\|u_{lm}(t)\|^{\rho+1} \geq 0,
\end{equation}
for $\|u_{lm}(t)\|<\lambda_1^{*},~t\in [0, t_{lm})$.
Inequality \eqref{q3.12} implies
\begin{equation*} %\label{q3.13}
 \frac{1}{4}\mu_0\|u_{lm}(t)\|^2+
\frac{1}{2}\frac{k_0^{\rho+1}}{\rho+1}\|u_{lm}(t)\|^{\rho+1}
\leq \frac{1}{2}\mu_0\|u_{lm}(t)\|^2-
\frac{k_0^{\rho+1}}{\rho+1}\|u_{lm}(t)\|^{\rho+1}.
\end{equation*}
Taking into account this inequality and \eqref{q3.12}, we have
\begin{equation}\label{q3.14}
\begin{aligned}
&\frac{1}{2}|u'_{lm}(t)|^2 + \frac{1}{4}\mu_0\|u_{lm}(t)\|^2+
\frac{1}{2}\frac{k_0^{\rho+1}}{\rho+1}\|u_{lm}(t)\|^{\rho+1}  \\
&\leq \frac{1}{2}|u'_{lm}(t)|^2 + \frac{\mu(t)}{2}\|u_{lm}(t)\|^2
+ \int_{\Omega} G(u_{lm}(t))dx \\
&\quad + \mu_0d_0 \int_0^t \int_{\Gamma_1}[u'_{lm}(\tau)]^2 d\Gamma d\tau \\
&\leq \int_0^t |f(\tau)||u'_{lm}(\tau)|d\tau
+ \frac{1}{2}\int_0^t |\mu'(\tau)|\|u_{lm}(\tau)\|^2d\tau + N_{l}.
\end{aligned}
\end{equation}
Note that
\begin{equation}\label{q3.15}
N_{l} < N \quad \text{for all } l\geq l_0
\end{equation}
where $N$ was introduced in \eqref{q17}.

We set
$$
 \varphi(t)=|u'_{lm}(t)|^2 + \frac{1}{2}\mu_0\|u_{lm}(t)\|^2+
\frac{k_0^{\rho+1}}{\rho+1}\|u_{lm}(t)\|^{\rho+1}.
$$
Then taking into account \eqref{q3.15} in \eqref{q3.14} and noting that
$\frac{1}{\mu_1} \leq \frac{1}{\mu_0}$, we obtain
$$
\varphi^2(t) \leq \frac{[(2N)^{1/2}]^2}{2} + \int_0^t |f(\tau)||\varphi(\tau)|d\tau +
\int_0^t 2\frac{|\mu'(\tau)|}{\mu_0}\varphi^2(\tau)d\tau.
$$
Then by Lemma \ref{lema1}, we obtain
\begin{equation}\label{q3.16}
\varphi(t) \leq \Big[ (2N)^{1/2}+ \int_0^{\infty} |f(t)|dt \Big]
\exp\Big( \frac{2}{\mu_0}\int_0^{\infty}|\mu'(t)|dt \Big)=P.
\end{equation}
So
\begin{equation}\label{q3.17}
 |u'_{lm}(t)| \leq P\quad \text{and}\quad
\|u_{lm}(t)\|\leq \big( \frac{2}{\mu_0} \big)^{1/2}P
\end{equation}
for each $t\in [0, t_{lm})$ and  $\|u_{lm}(t)\|<\lambda_1^{*}$.
The following result ensures that inequalities \eqref{q3.17} hold
 for all $t\in [0, \infty)$.

\begin{lemma}\label{lema3}
Let $[0, t_{lm})$ be an interval of existence of the solution $u_{lm}(t)$
of \eqref{equacao3.10}. Then
$$
\|u_{lm}(t)\|<\lambda_1^{*},\quad \forall t\in [0, \infty),\;
\forall l \geq l_0,\; \forall m.
$$
\end{lemma}

\begin{proof}
First, we note that by hypothesis \eqref{q16}, we have
$$
\|u_{lm}(0)\|=\|u^0_l\|< \lambda_1^{*},\quad \forall l \geq l_0,\; \forall m.
$$
Reasoning by contradiction, we assume that there exists $t_1 \in (0, t_{lm})$
such that $\|u_{lm}(t_1)\|=\lambda_1^{*}$. Let 
$$
t^{*}=\inf\{t_1 \in (0, t_{lm}): \|u_{lm}(t_1)\|=\lambda_1^{*}\}.
$$
By the continuity of $\|u_{lm}(t)\|$, we obtain $\|u_{lm}(t^{*})\|=\lambda_1^{*}$.
Note that $0< t^{*} < t_{lm}$. Consider $t\in [0, t^{*})$. Then
$\|u_{lm}(t)\|<\lambda_1^{*}$. So inequality \eqref{q3.17} provides
$$
\|u_{lm}(t)\| \leq \Big( \frac{2}{\mu_0} \Big)^{1/2}P,~\forall t \in [0,t^{*})
$$
that implies
$$
\lambda_1^{*} = \|u_{lm}(t^{*})\|\leq \Big( \frac{2}{\mu_0} \Big)^{1/2}P
$$
But this is a contradiction because by hypothesis \eqref{q16}$_2$,
$\big( \frac{2}{\mu_0} \big)^{1/2}P< \lambda_1^{*}$. This concludes the proof.
\end{proof}

Lemma \ref{lema3} provides the estimates

\begin{equation}\label{q3.18}
 |u'_{lm}(t)| \leq P,\quad 
\|u_{lm}(t)\|\leq \Big( \frac{2}{\mu_0} \Big)^{1/2}P, \quad
\forall t \in [0,\infty),\; \forall l \geq l_0,\; \forall m.
\end{equation}
Also inequalities \eqref{q3.16}, \eqref{q3.18} and \eqref{q3.5} gives us
\begin{equation}\label{q3.19}
 \int_0^{\infty}\|u'_{lm}(t)\|_{L^2(\Gamma_1)}dt\leq K, \quad
\forall t \in [0,\infty),\;  \forall l \geq l_0, \; \forall m.
\end{equation}


\subsection*{Second Estimate.}
In this part,  to facilitate the notation we do not write the variable $t$
and the subscripts $l$ and $m$.
Differentiating with respect to $t$ equation \eqref{equacao3.10}$_1$ 
and then setting $w=u''$,
we obtain
\begin{align*}
&\frac{1}{2}\frac{d}{dt}|u''|^2 
 + \frac{1}{2}\frac{d}{dt}[ \mu\|u'\|^2] 
+ \mu'((u,u'')) + (\rho |u|^{\rho-2} uu',u'' ) \\
& + \mu \int_{\Gamma_1}\delta h'(u')[u'']^2d\Gamma 
 + \mu' \int_{\Gamma_1}h(u')u''d\Gamma \\
&= (f', u'') + \frac{1}{2}\mu'\|u'\|^2.
\end{align*}
Considering $w=\frac{\mu'}{\mu}u''$ in approximate equation \eqref{equacao3.10}$_1$,
we find
$$
 \mu'((u,u'') + \mu' \int_{\Gamma_1}h(u')u''d\Gamma =
\big(f', \frac{\mu'}{\mu}u'' \big) -\big(u'',\frac{\mu'}{\mu}u'' \big)
-\big(|u|^\rho,\frac{\mu'}{\mu}u'' \big).
$$
Combining the last two equalities, we have
\begin{equation}\label{q3.20}
\begin{aligned}
&\frac{1}{2}\frac{d}{dt}|u''|^2 + \frac{1}{2}\frac{d}{dt}\left[ \mu\|u'\|^2 \right]
 + \mu \int_{\Gamma_1}\delta h'(u)[u'']^2d\Gamma \\
&= (f', u'')+\frac{1}{2}\mu'\|u\|^2 -\big(f,\frac{\mu'}{\mu}u'' \big)
 + \big(u'',\frac{\mu'}{\mu}u'' \big) \\
&\quad + \big(|u|^{\rho},\frac{\mu'}{\mu}u'' \big) 
 -(\rho |u|^{\rho-2} uu',u'').
\end{aligned}
\end{equation}
Fix a real number $T>0$. We bound the last terms of the second member 
of \eqref{q3.20}.
By $C=C(T)>0$ is denoted a generic constant which is independent of $l$ and $m$.
By \eqref{q06}, \eqref{q12}$_1$ and estimate \eqref{q3.20}, we obtain
\[
 \big| \big(|u|^{\rho},\frac{\mu'}{\mu}u'' \big) \big|
\leq k_2^{\rho}\|u\|^{\rho}\frac{|\mu'|}{\mu_0}|u''|
  \leq C\frac{|\mu'|}{\mu_0}|u''|.
\]
By \eqref{q12}$_2$, \eqref{q12}$_3$, estimates \eqref{q3.18} and noting that
$\frac{1}{n} + \frac{1}{p^{*}}+ \frac{1}{2}=1$ ($p^{*}$ 
introduced in \eqref{q8}), we find
\[
| (\rho |u|^{\rho-2} u u',u'' ) |
\leq \rho k_3^{\rho-1}k_4\|u'\||u''|
 \leq C\|u'\||u''|
\leq \frac{C}{2}\|u'\|^2 + \frac{C}{2}|u''|^2.
\]

Taking into account the last two inequalities \eqref{q3.20} and 
integrating on $[0,t]$, we obtain
\begin{equation}\label{q3.21}
\begin{aligned}
&\frac{1}{2}|u_{lm}''(t)|^2 + \frac{1}{2} \mu(t)\|u_{lm}'(t)\|^2
 + {\mu_0d_0} \int_0^t \int_{\Gamma_1}[u_{lm}''(\tau)]^2d\Gamma d\tau  \\
&\leq \int_0^t\left[|f'(\tau)|+ \frac{|\mu'(\tau)|}{\mu_0}|f(\tau)| 
 + \frac{C|\mu'(\tau)|}{\mu_0} \right]|u_{lm}''(\tau)| d\tau  \\
&\quad + \int_0^t \frac{C}{2}|u_{lm}''(\tau)|^2d\tau 
 + \int_0^t \frac{C}{2}\|u_{lm}'(\tau)\|^2d\tau \\
&\quad + \frac{1}{2}\int_0^t \frac{|\mu'(\tau)|}{\mu_0} \mu(\tau) \|u(\tau)\|^2d\tau
 + \frac{1}{2}|u''_{lm}(0)|^2 + \frac{\mu(0)}{2}\|u_l^1\|^2.
\end{aligned}
\end{equation}
For this inequality provides an estimate, we need to bound $|u''_{lm}(0)|$.
This is possible thanks to the choice of the special basis of 
$V \cap H^2(\Omega)$ and \eqref{equacao3.9}$_3$.

We bound $|u''_{lm}(0)|$. Set $t=0$ in approximate equation \eqref{equacao3.10}$_1$
and then take $v=u''_{lm}(0)$. The Gauss theorem and \eqref{equacao3.9}$_3$ 
gives us
$$
|u''_{lm}(0)|^2 + \mu(0)(-\Delta u^0_l, u''_{lm}(0)) + (|u^0_l|^\rho, u''_{lm}(0))=
(f(0), u''_{lm}(0)).
$$
This equality and \eqref{equacao3.9} gives us
$$
|u''_{lm}(0)|^2 \leq K_1.
$$
Taking into account this inequality in \eqref{q3.21} and using 
Lemma \ref{lema3}, follows that
\begin{equation}\label{q3.22}
\begin{gathered}
 \|u_{lm}'(t)\| \leq C,\quad \forall t \in [0,T],\; \forall l \geq l_0,\;\forall m \\
 |u_{lm}''(t)| \leq C,\quad \forall t \in [0,T],\; \forall l \geq l_0,\; \forall m \\
 \int_0^{t}\|u_{lm}''(t)\|_{L^2(\Gamma_1)} \leq C,\quad \forall t \in [0,T],\; 
\forall l \geq l_0,\; \forall m
\end{gathered}
\end{equation}

\subsection*{Passage to the Limit in $m$.}
Estimates \eqref{q3.18}, \eqref{q3.19}, \eqref{q3.22} and diagonal process 
allows to find a function
$u_k$ and a subsequence of $(u_{lm})$, still denoted by $(u_{lm})$, such that
\begin{equation}\label{q3.23}
\begin{gathered}
 u_{lm} \to u_l \quad\text{weak star in }L^{\infty}(0, \infty, V); \\
 u'_{lm} \to u_l' \quad\text{weak star in }L^{\infty}(0, \infty, L^2(\Omega)) \cap L^{\infty}_{\rm loc}(0, \infty, V); \\
 u''_{lm} \to u_l''\quad\text{weak star in }L^{\infty}_{\rm loc}(0, \infty, L^2(\Omega)); \\
 u'_{lm} \to u_l' \quad\text{weak star in }L^{\infty}(0, \infty, L^2(\Gamma_1)); \\
 u''_{lm} \to u_l''\quad\text{weak star in }L^{\infty}_{\rm loc}(0, \infty, L^2(\Gamma_1)). \\
\end{gathered}
\end{equation}
Estimates \eqref{q3.23}$_1$, \eqref{q3.23}$_2$ and Aubin-Lions Theorem provides us
$$
u_{lm}(x,t) \to u_l(x,t)\quad\text{a.e. in } Q=\Omega \times (0,T).
$$
Then
\begin{equation}\label{q3.24}
|u_{lm}(x,t)|^\rho \to |u_{l}(x,t)|^\rho\quad\text{a.e. in }
 Q=\Omega \times (0,T).
\end{equation}
By \eqref{q06}, \eqref{q12}$_2$ and \eqref{q3.18}, we find
\begin{equation}\label{q3.25}
 \int_{\Omega}|u_{lm}|^{2\rho} dx \leq k_2^{2\rho}\|u_{lm}\|^{2\rho} \leq C.
\end{equation}
Expressions \eqref{q3.24}, \eqref{q3.25}, Lions Lema \cite{Lions} and diagonal process
provide
\begin{equation}\label{q3.26}
|u_{lm}|^\rho~\to |u_{l}|^\rho \quad \text{weak star in } 
L^{\infty}_{\rm loc}(0, \infty; L^2(\Omega)).
\end{equation}
Estimate \eqref{q3.23}$_3$ yields 
$$
u'_{lm}\to u'_{l} \quad \text{weak star in }L^{\infty}(0, \infty; H^{1/2}(\Gamma_1)).
$$
This, convergence \eqref{q3.23}$_5$ and Aubin-Lions Theorem and fact 
$h$ Lipchitizian function gives us
$$
h(u'_{lm}(x,t))\to h(u'_{l}(x,t)) \quad\text{a.e. in }Q
$$
and by trace theorem and \eqref{q3.23}, we obtain
\[
(h(u'_{lm})) ~\text{bounded in}~L^{\infty}_{\rm loc}(0, \infty; H^{1/2}(\Gamma_1)).
\]
Therefore, by Lions Lemma, we conclude that
\begin{equation}\label{q3.27}
h(u'_{lm})\to h(u'_{l}) ~~\text{weak star in}~L^{\infty}_{\rm loc}
(0, \infty; H^{1/2}(\Gamma_1)).
\end{equation}
Convergences \eqref{q3.23}, \eqref{q3.26}-\eqref{q3.27} allows us to pass to
the limit in approximate equation \eqref{equacao3.10}$_1$. Then by density
 of $V\cap H^2(\Omega) $ in $V$, we obtain
\begin{equation}\label{q3.29}
\begin{aligned}
&\int_0^{\infty}(u_{l}''(t), v)\theta(t)dt 
 + \mu \int_0^{\infty}((u_{l}(t), v))\theta(t)dt
 +\int_0^{\infty}(|u_{l}(t)|^\rho, v )\theta(t)dt  \\
&+ \int_0^{\infty}\int_{\Gamma_1} \mu(t)\delta h(u'_{l}(t))v\theta(t) d\Gamma dt\\
& =\int_0^{\infty}(f(t), v)\theta(t)dt, \quad
v \in V,\; \forall \theta \in C_0^{\infty}(\Omega). 
\end{aligned}
\end{equation}
Taking $v \in {\mathcal{D}}(\Omega)$ in \eqref{q3.29}, and observing 
the regularities of $u_{l}'', |u_{l}|^\rho$ and $f$, follows that
\begin{equation}\label{q3.30}
u_{l}''- \mu \Delta u_{l} + |u_{l}|^\rho=f\quad
\text{in }L^2_{\rm loc}(0, \infty; L^2(\Omega)).
\end{equation}
This equation provides $\Delta u_{l} \in L^{\infty}(0, \infty; L^2(\Omega))$ and
\eqref{q3.23}$_1$, $u_{l} \in L^{\infty}(0, \infty; V)$. Then
\begin{equation}\label{q3.31}
\frac{\partial u_{l}}{\partial \nu} \in L^{\infty}_{\rm loc}
(0, \infty; H^{1/2}(\Gamma_1)).
\end{equation}
Multiply both sides of \eqref{q3.30} by $v \theta, v\in V$ and 
$\theta \in C_0^{\infty}(0,\infty)$,
and integrate on $\Omega \times (0, \infty)$. Using regularity \eqref{q3.31} 
of $\frac{\partial u}{\partial \nu}$, we conclude
\begin{align*}
&\int_0^{\infty}(u_{l}''(t), v)\theta(t)dt 
 + \mu \int_0^{\infty}((u_{l}(t), v))\theta(t)dt
 -\int_0^{\infty}\mu(t)\langle \frac{\partial u_{l}}{\partial \nu}, v \rangle
  \theta(t)dt  \\
&+ \int_0^{\infty}(|u_{l}(t)|^\rho, v )\theta(t)dt \\
&=\int_0^{\infty}(f(t), v)\theta(t)dt, \quad v \in V,\; 
\forall \theta \in C_0^{\infty}(\Omega).
\end{align*}
where $\langle \cdot, \cdot \rangle$ denotes the duality paring between 
$H^{-\frac{1}{2}}(\Gamma_1)$ and $H^{1/2}(\Gamma_1)$. 
Comparing this equality with \eqref{q3.29} and observing the regularity 
of $h(u'_l)$, we find (see \cite{milla02})
\begin{equation}\label{q3.32}
\frac{\partial u_{l}}{\partial \nu} +\delta h(u'_{l})=0 \quad\text{in }
L^{2}_{\rm loc}(0, \infty; H^{1/2}(\Gamma_1)).
\end{equation}


\subsection*{Passage to the Limit in $l$}
Estimates \eqref{q3.18}, \eqref{q3.19}, \eqref{q3.22} and convergence \eqref{q3.23}
provide
\begin{equation}\label{q3.33}
\begin{gathered}
 |u_{l}'(t)| \leq P,\|u_{l}(t)\|\leq \Big( \frac{2}{\mu_0} \Big)^{1/2} \quad
 \forall t \in [0,\infty),\; \forall l \geq l_0, \\
 \int_0^{\infty}\|u_{l}''(t)\|_{L^2(\Gamma_1)}^2dt \leq C,\quad 
\forall t \in [0,\infty),\; \forall l \geq l_0; \\
 \|u_{l}'(t)\| \leq C,\quad |u_{l}''(t)| \leq C\quad 
\forall t \in [0,T],]; \forall l \geq l_0, \\
 \int_0^{t}\|u_{l}''(\tau)\|_{L^2(\Gamma_1)}^2d\tau \leq C,\quad
\forall t \in [0,T],\; \forall l \geq l_0.
\end{gathered}
\end{equation}
These estimates allows to obtain similar convergence to those obtained 
in \eqref{q3.23}. So there exists a function
$u$ and subsequence of $(u_{l})$, still denoted by $(u_{l})$, such that
\begin{equation}\label{q3.34}
\begin{gathered}
 u_{l} \to u \quad\text{weak star in }L^{\infty}(0, \infty, V); \\
 u'_{l} \to u' \quad\text{weak star in }L^{\infty}(0, \infty, L^2(\Omega))
\cap L_{\rm loc}^{\infty}(0, \infty; V); \\
 u''_{l} \to u'' \quad\text{weak star in }L^{\infty}_{\rm loc}(0, \infty, L^2(\Omega)); \\
 u'_{l} \to u' \quad\text{weak in } L^{2}(0, \infty, L^2(\Gamma_1)); \\
 u''_{l} \to u'' \quad\text{weak in } L^{2}_{\rm loc}(0, \infty, L^2(\Gamma_1)).
\end{gathered}
\end{equation}
By arguments similar to those used for \eqref{q3.26}, we find
\begin{equation} \label{0q3.34}
|u_{l}|^{\rho} \to |u|^{\rho} \quad \text{weak in } 
 L^2_{\rm loc}(0, \infty; L^2(\Omega)).
\end{equation}
This convergence, \eqref{q3.34}$_3$ and \eqref{q3.30} provide
\begin{equation}\label{q3.35}
\Delta u_{l} \to \Delta u\quad \text{weak in } L^2_{\rm loc}(0, \infty; L^2(\Omega))
\end{equation}
and therefore
\begin{equation}\label{q3.36}
u'' -\mu\Delta u + |u|^{\rho}=f\quad  \text{in } L^2_{\rm loc}
(0, \infty; L^2(\Omega)).
\end{equation}
Also convergences \eqref{q3.34}$_1$ and \eqref{q3.35} provide us with
\begin{equation}\label{q3.37}
\frac{\partial u_{l}}{\partial \nu}\to \frac{\partial u}{\partial \nu}\quad
 \text{weak in } L^2_{\rm loc}(0, \infty; H^{-\frac{1}{2}}(\Gamma_1)).
\end{equation}
As done in \eqref{q3.27}, we find
\begin{equation}\label{0q3.27}
\delta h(u'_{l})\to \delta h(u') \quad\text{weak star in }
 L^{\infty}_{\rm loc}(0, \infty; H^{1/2}(\Gamma_1)).
\end{equation}
So these two convergences and \eqref{q3.32}, we met
\begin{equation}\label{0q3.32}
\frac{\partial u}{\partial \nu} + \delta h(u')=0 \quad\text{in }
L^{2}_{\rm loc}(0, \infty; H^{1/2}(\Gamma_1)).
\end{equation}

From the regularity 
$$
u \in L_{\rm loc}^{\infty}(0, \infty; V),\quad
\Delta u \in L_{\rm loc}^{\infty}(0, \infty; L^2(\Omega)), \quad
\frac{\partial u}{\partial \nu} \in L_{\rm loc}^{\infty}
(0, \infty; H^{1/2}(\Gamma_1))
$$
and by Proposition \ref{pr3.1}, we obtain
\begin{equation}\label{equacao3.29}
u \in L^{\infty}_{\rm loc}(0,\infty; V \cap H^{2}(\Omega)).
\end{equation}

Also, by estimate \eqref{q3.34}$_4$ and noting that $h$ is a Lipschitz 
continuous function we find
\begin{equation}\label{equacao3.300}
\frac{\partial u'}{\partial \nu}+ \delta h'(u')u''=0 \quad \text{in }
 L^{2}_{\rm loc}(0,\infty; L^{2}(\Gamma_1)).
\end{equation}

The verification of initial conditions follows in the usual way.

In what follows, we prove the uniqueness of solutions. 
Let $u$ and $v$ two functions in class \eqref{q18}
which satisfy equations \eqref{q19}, \eqref{q20} and initial conditions \eqref{q21}. 
Consider $w=u-v$. Then
\begin{equation}\label{E3.28}
\begin{gathered}
 w'' -\mu \Delta w + |u|^\rho-|v|^\rho= 0\quad 
\text{in } L^{\infty}(0,T; L^2(\Omega)),  \\
 \frac{\partial w}{\partial \nu} + \delta [h(u')-h(v')]=0  \quad
\text{in } L^{\infty}(0,T; H^{1/2}(\Gamma_1)),   \\
 w(0)=0,\quad w'(0)=0  
 \end{gathered}
\end{equation}
Multiplying both sides of \eqref{E3.28}$_1$ by $w'$ integrating on $\Omega$ 
and using Gauss Theorem, we obtain
\begin{equation}\label{E3.29}
\begin{aligned}
&\frac{1}{2}\frac{d}{dt}|w'(t)|^2+ \frac{1}{2}\|w(t)\|^2 
+ \int_{\Gamma_1}\delta[h(u'(t))-h(v'(t))]d\Gamma \\
&= -(|u(t)|^\rho- |v(t)|^\rho,w'(t)).
\end{aligned}
\end{equation}
We have
$$
|u(x,t)|^\rho -|v(x,t)|^\rho =\rho|\xi|^{\rho-2}\xi w(x,t)
$$
where $\xi$ is between $u(x,t)$ and $v(x,t)$. Then
$$
||u(x,t)|^\rho -|v(x,t)|^\rho| = \rho |\xi|^{\rho-1}| w(x,t)|
$$
that provides
\begin{equation}\label{E3.30}
\begin{aligned}
||u(t)|^\rho- |v(t)|^\rho| 
&\leq \rho [|u(x,t)| + |v(x,t)|]^{\rho-1}|w(x,t)|  \\
&\leq C(\rho)[|u(x,t)|^{\rho-1}|w(x,t)| + |v(x,t)|^{\rho-1}|w(x,t)|].
\end{aligned}
\end{equation}
We obtain
\begin{align*}
\int_{\Omega}|u(x,t)|^{\rho-1}|w(x,t)||w'(x,t)|dx 
&\leq \|u(t)\|_{L^{(\rho-1)n}(\Omega)}^{\rho-1}\|w(t)\|_{L^{p^{*}}(\Omega)}|w'(t)| \\
&\leq k_3k_4\|u(t)\|^{\rho-1}\|w(t)\||w'(t)|.
\end{align*}
Thus
$$
|(|u(t)|^\rho- |v(t)|^\rho, w'(t))| 
\leq C\|w(t)\||w'(t)|
\leq \frac{C}{2}\|w(t)\|^2 + \frac{C}{2}|w'(t)|^2.
$$
This inequality, \eqref{E3.29} and property of monotony of $h$, imply
$$
\frac{1}{2}\frac{d}{dt}|w'(t)|^2 + \frac{1}{2}\frac{d}{dt}\|w(t)\|^2
 + \delta_0d_0\int_{\Gamma_1}w'(t)^2d\Gamma 
\leq \frac{C}{2}\|w(t)\|^2 + \frac{C}{2}|w'(t)|.
$$
Then the Gronwall inequality provides $w'(t)=0$ and $w(t)=0$. 
This concludes the proof of Theorem \ref{teorema1}.


\subsection{Proof of Theorem \ref{teo2.1}}

We introduce some notation to apply the Banach Fixed-Point Theorem. 
Consider a real number $R>0$ such that
\begin{equation}\label{3.30}
R> M_0
\end{equation}
where $M_0=\max\{M_1,M_2\}$ is defined in \eqref{local5}, $M_1$, 
$M_2$ are defined by \eqref{local1} and \eqref{local3} respectively.
Let 
\begin{gather}
R_1^2=N_1^2 =|u^1|^2+ M(0,\|u^0\|^{2})\|u^0\|^2 
+ \frac{1}{\rho+1}k_0\|u_0\|^{\rho +1}, \label{3.31} \\
R_2^2=M(0,\|u^0\|^{2})\|u^1\|^2 + M(0,\|u^0\|^{2})|\Delta u^0| +|u^0|^\rho + |f(0)|.
\label{3.32}
\end{gather}
We define $B_{R,T_0}$ as the set of vectors
\begin{align*}
B_{R,T_0}=\Big\{& {u}: {u} \in L^{\infty}(0, T_0; V), \;
{u'} \in L^{\infty}(0, T_0; V)\cap  C^0([0, T_0]; L^2(\Omega)), \\
 &\|u\|_{L^{\infty}(0, T_0; V)}+ \|u'\|_{L^{\infty}(0, T_0; V)}\leq R, \\
 &u(0)=u^0,\; u'(0)=u^1.\Big\}
\end{align*}
The real number $T_0$ with $0< T_0 \leq 1$ will be determined later. 
We equipped $B_{R,T_0} $ with the metric
$$
d(u,v)=\|u-v\|_{L^{\infty}(0,T_0;V)}+\|u'-v'\|_{C^{0}([0,T_0]; L^2(\Omega))}
$$
where $u$ and $v$ belong to $B_{R,T_0}$. In \cite{Jutuca} is proved that
$(B_{R,T_0}, d(u,v))$ is a complete metric space.

Consider the map $S: B_{R,T_0}\to {\mathcal{H}},z\mapsto S(z)=\varphi$, where
$\mathcal{H}$ denotes the set of solutions $\varphi$, of the problem
\begin{equation}\label{3.34}
 \begin{gathered}
 \varphi'' - M(\cdot,\|z\|^{2})\Delta \varphi + |\varphi|^\rho=f
\quad \text{in }\Omega \times (0, T_0)  \\
 \varphi=0 \quad \text{on }  \Gamma_0 \times (0, T_0)  \\
 \frac{\partial \varphi}{\partial \nu} + \delta h(\varphi')=0 \quad \text{on } 
 \Gamma_1 \times (0, T_0) \\
 \varphi(0)=u^0,\quad \varphi'(0)=u^1 \quad \text{in }  \Omega 
 \end{gathered}
\end{equation}
We prove that the map $S$ is well defined.
Set
\begin{equation}\label{3.35}
K=\max\Big\{\big|\frac{\partial M}{\partial t}(t,
\lambda) \big|,\big|\frac{\partial M}{\partial
\lambda}(t, \lambda) \big|; t \in[0,1],\;
\lambda \in [0,R^2]\Big\}.
\end{equation}
Consider
\begin{equation}\label{3.36}
\mu(t)=M(t, \|z(t)\|^2),\quad t \in [0, T_0].
\end{equation}
We have that $\mu \in W^{1,\infty}(0,T_0)$.
In fact,
\[
 \mu'(t)=\frac{\partial M}{\partial t}(t,\|z(t)\|^{2})
+ \frac{\partial M}{\partial\lambda}(t,\|z(t)\|^{2})\frac{d}{dt}\|z(t)\|^2.
\]
As $z\in B_{R,T_0}$, we find that
\begin{equation}\label{3.37}
|\mu'(t)|\leq K(1 + 4R^{2}),\quad\text{a.e. }t \in ]0,T_0[.
\end{equation}
Thus, $\mu \in W^{1,\infty}(0,T_0)$ with $\mu_0 =m_0$. Theorem \ref{teorema1} 
says  that there exists a unique
solution ${\varphi}$ of system \eqref{3.34} and this solution has the 
regularity of the vectors of $B_{R, T_0}$.

Our objective now is to show that $S(B_{R,T_0})$ is contained $B_{R,T_0}$ and
that $S$ is a strict contraction.

Let ${\varphi}$ be a solution of the problem \eqref{3.34} given by
the Theorem \ref{teorema1} with $\mu(t)$ defined in \eqref{3.36}. 
Let $\varphi_{lm}$  be the approximate solution given in the proof of
 Theorem \ref{teorema1}.
 Then by first a priori estimate given the proof of Theorem \ref{teorema1}, 
we obtain
$$
 \|\varphi_{lm}(t)\|^2\leq
M_1\exp\Big( \frac{2}{m_0}\int_0^t|\mu'(\tau)|d\tau \Big),\quad 
0\leq t \leq T_0, 
$$
where
\begin{equation}\label{local1}
M_1=(2R_1)^{1/2} + \int_0^{T_0}|f(t)|dt.
\end{equation}
This and \eqref{3.37} gives
\begin{equation}\label{3.38}
 \|\varphi_{lm}(t)\|\leq
M_1 \exp({\mathcal{K}}_1T_0),\quad 0\leq t \leq T_0, \text{ for } m \geq 2 
\text{ and } l\geq l_0(1).
\end{equation}
where
\begin{equation}\label{local2}
\mathcal{K}_1=\frac{2K(1+ R^2)}{m_0}.
\end{equation}
The second priori estimates Theorem \ref{teo2.1} gives us
\begin{equation}\label{3.40}
\|\varphi'_{lm}(t)\|\leq
M_2\exp\left({\mathcal{K}}_2T_0 \right),\quad 
0\leq t \leq T_0,\text{ for } m \geq 2 \text{ and } l \geq l_0(1).
\end{equation}
where
\begin{equation}\label{local3}
\begin{aligned}
 M_2&=2R_2^{1/2} + \int_0^{T_0}\left[|f'(t)| 
 + \frac{|\mu'(t)|}{m_0}|f(t)| + \frac{C}{m_0}|\mu'(t)|\right]dt  \\
 &\leq 2R_2^{1/2} + \int_0^{T_0}\big[|f'(t)| + \frac{K(1 + 4R^{2})}{m_0}|f(t)| 
+ \frac{C}{m_0}K(1 + 4R^{2})\big]dt
\end{aligned}
\end{equation}
and
\begin{equation}\label{local4}
\mathcal{K}_2=\frac{(2+m_0)K(1 + 4R^{2})}{2m_0} + \frac{3C}{2}.
\end{equation}
Consider
\begin{equation}\label{local5}
M_0=\max\{M_1, M_2\}, \quad \mathcal{K}=\max\{\mathcal{K}_1, \mathcal{K}_2\}.
\end{equation}
From \eqref{3.38}, \eqref{3.40} and \eqref{local5} and
taking the maximum on $[0,T_0]$ of both of members the
\eqref{3.38} and \eqref{3.40} and then the limit inferior, first with respect 
to $m $ and later with respect to $l$, we obtain
\begin{equation}\label{3.41}
 \begin{array}{l}
 \|\varphi\|_{L^{\infty}(0,T_0; V)}+ \|\varphi'\|_{L^{\infty}(0,T_0; V)}
 \leq M_0exp({\mathcal{K}}T_0).
 \end{array}
\end{equation}

We will choose $T_0>0$ so that the second member of the preceding inequality
 be less than or equal to $R$. In fact, set
$$
q(t)=M_0e^{{\mathcal{K}}t}, \quad t\geq 0.
$$
Then $q$ is continuous, increasing, $q(t) \to \infty$
when $t\to \infty$ and
$q(0)=M_0<R$ (see \eqref{3.30}). 
Then by the Intermediate Value Theorem there exists $T_1^{*}>0$ such
that $q(T_1^{*})=R$, that is,
\begin{equation}\label{3.42}
T_1^{*}=\frac{1}{\mathcal{{K}}}\ln\Big(\frac{R}{M_0} \Big).
\end{equation}
We choose
\begin{equation}\label{3.43}
0< T_0 \leq \min\{1, T_1^{*} \}.
\end{equation}
Then expression \eqref{3.41} with $T_0$ given by \eqref{3.43} satisfies
$$
\|\varphi\|_{L^{\infty}(0,T_0; V)}+
\|\varphi'\|_{L^{\infty}(0,T_0; V)} \leq R.
$$
Therefore $\varphi$ belongs to $B_{R,T_0}$. Thus $S(B_{R,T_0})$ is 
contained in $ B_{R,T_0}$.

In the sequel we prove that $S$ is a strict contraction. 
Set $r_1,y_1\in B_{R,T_0}$ and
$S(r_1)=r$, $S(y_1)={y}$.
Introduce the notation
\begin{equation}\label{3.44}
\varphi = r-y.
\end{equation}
We have
\begin{equation}\label{3.45}
\begin{gathered}
 \varphi''-M(\cdot,\|r_1\|^2) \Delta r +
 M(\cdot,\|y_1 \|^2)\Delta y + |r|^\rho-|y|^\rho=0 \quad\text{in }
 \Omega \times ]0,T_0[,  \\
 \varphi=0, \quad  \psi =0\quad \text{on } \Gamma_0 \times ]0, T_0[,  \\
 \frac{\partial \varphi}{\partial \nu} + \delta [h(r')-h(y')]=0 
\quad \text{on }\Gamma_1 \times ]0, T_0[,  \\
 \varphi(0)=0,\quad \varphi'(0)=0 \quad \text{in }\Omega.
\end{gathered}
\end{equation}
Taking the scalar product in $L^2(\Omega)$ of \eqref{3.45}$_1$ with $\varphi'(t)$ 
we obtain
\begin{equation}\label{3.46}
\begin{aligned}
&\frac{1}{2}\frac{d}{d}|\varphi'(t)|^2-M(t,\|r_1(t)\|^2)(\Delta r(t),\varphi'(t))\\
& + M(t,\|y_1(t)\|^2)(\Delta y(t),\varphi'(t)) + (|r|^\rho-|y|^\rho,\varphi'(t))=0.  
\end{aligned}
\end{equation}
We modify \eqref{3.46}, to obtain
\begin{align*}
&\frac{1}{2}\frac{d}{d}|\varphi'(t)|^2-M(t,\|r_1(t)\|^2)
 (\Delta \varphi(t),\varphi'(t)) \\
&= [ M(t,\|r_1(t)\|^2)-M(t,\|y_1(t)\|^2 )](\Delta y(t),\varphi'(t)) 
- (|y|^\rho-|r|^\rho, \varphi'(t)). 
\end{align*}
We abbreviate the notation and write this expression in the form
\begin{equation}\label{3.47}
\frac{1}{2}\frac{d}{dt}|\varphi'(t)|^2 + A(t)=B(t).
\end{equation}
\smallskip

\noindent$\bullet$ Analysis of $A(t)$.
Using the Green's Theorem and the boundary condition in
\eqref{3.45}$_3$, we find that
\begin{align*}
 A(t)&=M(t,\|r_1(t)\|^2)\frac{1}{2}\frac{d}{dt}\|\varphi(t)\|^2  \\
 &\quad + M(t,\|r_1(t)\|^2)\int_{\Gamma_1} \delta [h(r'(t))-h(y'(t))]
 \varphi'(t)d\Gamma.
\end{align*}
Note that, $\delta(x)\geq \delta_0>0$ and $\varphi'(t)=r'(t)-y'(t)$ 
then by the strong monotonicity of $h$, follows that
$$
\int_{\Gamma_1} \delta [h(r'(t))-h(y'(t))]\varphi'(t)d\Gamma \geq 0.
$$
Combining the last two expressions we conclude that
\begin{equation}\label{3.48}
 A(t)\geq M(t,\|r_1(t)\|^2)\frac{1}{2}\frac{d}{dt}\|\varphi(t)\|^2~a.e.~t \in ]0, T_0[. \\
\end{equation}
\smallskip

\noindent$\bullet$ Analysis of $B(t)$.
To facilitate the notation in this part we do not write the variable $t$. 
We have
\begin{equation}\label{3.49}
 B= \left[ M(\cdot,\|r_1\|^2)-( M(\cdot ,\|y_1\|^2)\right]
(\Delta y(t),\varphi'(t))-(|y|^\rho-|r|^\rho, \varphi'(t)).
\end{equation}
\begin{itemize}
\item As $M \in C^1$ we have
$$
\big|M(\cdot, \|r_1\|^2)-M(\cdot, \|y_1\|^2)\big|\leq 2{K}M_0\|r_1-y_1\| ,
$$
where ${K}$ and $M_0$ were defined in \eqref{3.35} and \eqref{local5}, respectively.

\item Analysis of $(|y(t)|^\rho-|r(t)|^\rho, \varphi'(t))$.
We have
$$
|y(x,t)|^\rho -|r(x,t)|^\rho =\rho|\xi|^{\rho-2}\xi \varphi(x,t)
$$
where $\xi$ is between $y(x,t)$ and $r(x,t)$. Then
$$
||y(x,t)|^\rho -|r(x,t)|^\rho| \leq \rho |\xi|^{\rho-1}| \varphi(x,t)|
$$
which implies
$$
||y(x,t)|^\rho-|r(x,t)|^\rho|\leq C [|y(x,t)|^{\rho-1}+ |r(x,t)|^{\rho-1}]|\varphi(x,t)|.
$$
Thus
$$
 | (|y(t)|^\rho -|r(t)|^\rho,\varphi'(t)) |\leq
C \|y(t)\|_{L^{(\rho-1)n}(\Omega)}^{\rho-1}\|\varphi(t)\|_{L^{p^{*}}(\Omega)}
|\varphi'(t)|.
$$
By \eqref{q12}, we find that
\begin{gather*}
\|y(t)\|_{L^{(\rho-1)n}(\Omega)}^{\rho-1} 
\leq k_3^{\rho-1} \|y(t)\|^{\rho-1}\leq C,\quad \forall t \in [0,T_0],\\
\|r(t)\|_{L^{(\rho-1)n}(\Omega)}^{\rho-1} \leq C,~\forall t \in [0,T_0].
\end{gather*}
Combining the last tree inequalities, we obtain
$$
|(|y(t)|^\rho- |r(t)|^\rho, \varphi'(t))| 
\leq C\|\varphi(t)\||\varphi'(t)|\leq \frac{C}{2}\|\varphi(t)\|^2 
+ \frac{C}{2}|\varphi'(t)|^2.
$$
\end{itemize}
Taking into account the last two inequalities in \eqref{3.49}, we obtain
\begin{equation}\label{3.50}
 |B(t)| \leq C|\Delta y(t)| |\varphi'(t)|d(r_1,y_1)
 + \frac{C}{2}\|\varphi(t)\|^2 + \frac{C}{2}|\varphi'(t)|^2.
\end{equation}
Next we find a bound for $|\Delta y(t)|$. We have 
$$
\varphi'' - M(\cdot, \|z\|^2)\Delta \varphi + |\varphi|^\rho=f
\quad \text{in } L^{\infty}(0, T_0; L^2(\Omega)).
$$
By estimates \eqref{3.38}, \eqref{3.40} and following the same reasoning
 used for \eqref{3.40}, we obtain
\begin{equation}\label{03.50}
|y''(t)|\leq M_0\exp({{\mathcal{K}}}T_0)\quad \text{a.e. }t \in ]0, T_0[.
\end{equation}
Hence,
\begin{equation}\label{local6}
\begin{aligned}
|M(t,\|z(t))\|| |\Delta \varphi (t)| 
&\leq |f(t)| + |u(t)|^\rho + |\varphi'(t)| \\
&\leq \Big(\frac{C_1 + C_2}{m_0} \Big) + \frac{M_0}{m_0}\exp(\mathcal{K}T_0).
\end{aligned}
\end{equation}
These last two expressions give
\begin{equation}\label{3.51}
 |\Delta y(t)| \leq M_3+ M_3exp({{\mathcal{K}}}T_0)\quad \text{a.e. }t \in 
]0, T_0[,
\end{equation}
where
$$
M_3=\max\big\{\frac{C_1 + C_2}{m_0}, \frac{M_0}{m_0} \big\}.
$$
Note that $e^{\mathcal{K}T_0}>1$, therefore $M_3 \leq M_3e^{\mathcal{K}T_0}$.
Hence
Combining \eqref{3.50}$ and \eqref{3.51}$ we derive
\begin{equation}\label{3.52}
|B(t)|\leq P_0[exp({\mathcal{K}}T_0)]|\varphi'(t)|d(r_1,y_1)
\quad \text{a.e. }t \in ]0, T_0[
\end{equation}
where
\begin{equation}\label{3.54}
P_0=4 {K} M_0 M_3.
\end{equation}
Combining \eqref{3.48} and \eqref{3.52} with \eqref{3.47}, we obtain
\begin{equation}\label{3.53}
\begin{aligned}
&\frac{1}{2}\frac{d}{dt}|\varphi'(t)|^2 
 + M(t, \|r_1(t)\|^2) \frac{1}{2}\frac{d}{dt}\|\varphi(t)\|^2   \\
&\leq P_0 [exp({{\mathcal{K}}}T_0)]^2d^2(r_1,y_1) 
 + |\varphi'(t)|^2 \quad \text{a.e } t \in ]0, T_0[.
\end{aligned}
\end{equation}
We have
\begin{align*}
&M(\cdot ,\|r_1\|^2)\frac{1}{2}\frac{d}{dt}\|\varphi\|^2
&=\frac{1}{2}\frac{d}{dt} [M(\cdot ,\|r_1\|^2)\|\varphi(t)\|^2 ] \\
&\quad -\frac{1}{2} \Big[\frac{\partial M}{\partial
t}(\cdot ,\|r_1\|^2) + \frac{\partial M}{\partial
\lambda}(\cdot ,\|r_1\|^2)\frac{d}{dt}\|r_1\|^{2}\Big]\|\varphi\|^2.
\end{align*}
Substituting this equality in \eqref{3.53}, and using boundedness \eqref{3.35} and
\eqref{3.32}, we find
\begin{align*}
&\frac{1}{2}\frac{d}{d}\left[|\varphi'(t)|^2 + M(t,\|r_1(t)\|^2)
\|\varphi(t)\|^2 \right] \\
&\leq \frac{{K}(1+2R^2)}{2}\|\varphi(t)\|^2 
 + P_0^2[\exp({{\mathcal{K}}}T_0)]^2 d^2(r_1,y_1)
 + |\varphi'(t)|^2 \quad\text{a.e. }t \in ]0, T_0[.
\end{align*}
Integrating on $[0, t]$, $0<t \leq T_0$, and noting that 
$M(t, \lambda )\geq m_0$
and $\varphi(0)=\varphi'(0)=0$, we obtain
\begin{equation}\label{3.55}
\begin{aligned}
&\frac{1}{2}[|\varphi'(t)|^2 + m_0 \|\varphi(t)\|^2] \\
&\leq P_1 \int_0^t \|\varphi(s)\|^2ds 
 + T_0P_0^2[exp({{\mathcal{K}}}T_0)]^2 d^2(r_1,y_1)
 + \int_0^t |\varphi'(s)|^2ds,
\end{aligned}
\end{equation}
where
\begin{equation}\label{3.56}
P_1=\frac{{K}(1 + 2R^2)}{2}.
\end{equation}
Considering
\begin{equation}\label{3.58}
b_1^2=\frac{P_0 [exp ({\mathcal{K}}T_0)]^2}{\min\{\frac{1}{2},\frac{m_0}{2}\}},\quad
b_2=\frac{\max\{P_1,1\}}{\min\{\frac{1}{2},\frac{m_0}{2}\}},
\end{equation}
where $P_0$ was defined in \eqref{3.54}, we have
$$
 \|\varphi(t)\|^2 + |\varphi'(t)|^2 \leq b_1^2 T_0 d^2(r_1,y_1) +
 b_2\int_0^t[\|\varphi(s)\|^2 + |\varphi'(s)|^2]ds.
$$
Then  Gronwall's lemma gives
$$
 \|\varphi(t)\|^2 + |\varphi'(t)|^2 \leq 4b_1^2 T_0 d^2(r_1,y_1)\exp(b_2T_0),
$$
which implies
$$
 \|\varphi(t)\| + |\varphi'(t)| \leq 2b_1T_0^{1/2} d(r_1,y_1)\exp(b_2T_0),
$$
Recalling that
$S(r_1)=r$, $S(y_1)=y$ and $\varphi=r-y$,
from the above inequality it follows that
\begin{equation}\label{3.59}
 d(S(r_1),S(y_1)) \leq [2b_1T_0^{1/2}\exp(b_2T_0)]d((r_1,y_1).
\end{equation}

Note that ${K}$ given in \eqref{3.35} is independent of $T_0$, therefore 
${\mathcal{K}}$, $P_0$ and $P_1$ defined in \eqref{local5}, \eqref{3.54} and 
\eqref{3.56} respectively, are independent of $T_0$.
Thus the constants $b_1$ and $b_2$ given in \eqref{3.58} are also independent 
of $T_0$.

Consider $\psi(t)=2b_1t\exp(b_2t)$, $t \geq 0$. Then $\psi$ is continuous, 
increasing and $\psi(0)=0$. So there exists
$T_2^{*}>0$ such that $\psi(T_2^{*})<1$. Take
$$
T_0=\min\{1, T_1^{*}, T_2^{*}\}>0,
$$
where $T_1^{*}$ was defined in \eqref{3.42}. Then $T_0$ satisfies \eqref{3.43} and
$$
2b_1T_0\exp(b_2 T_0)=\alpha_0<1.
$$
Substituting this constant in \eqref{3.59}, we conclude that
$$
 d(S(r_1),S(y_1)) \leq \alpha_0 d(r_1,y_1),\quad \forall r_1, y_1 \in B_{R, T_0}.
$$
Thus $d$ is a strict contraction. By the Banach Fixed-Point Theorem 
there exists a unique point $u\in B_{R, T_0}$
such that $S(u)=u$. This fixed point satisfies all conditions required 
in the theorem.

The uniqueness of solutions follows as in \cite{Jutuca}.


The existence of global solutions to problem \eqref{2.3}
and their asymptotic behavior  with small data will be published in 
a future article.

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