\documentclass[reqno]{amsart}
\usepackage{hyperref}

\AtBeginDocument{{\noindent\small
\emph{Electronic Journal of Differential Equations},
Vol. 2017 (2017), No. 27, pp. 1--18.\newline
ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu}
\thanks{\copyright 2017 Texas State University.}
\vspace{8mm}}

\begin{document}
\title[\hfilneg EJDE-2017/27\hfil Fourth-order critical growth problem]
{Multiple solutions of a fourth-order nonhomogeneous equation
with \\ critical growth in $\mathbb{R}^4$}

\author[A. Sarkar \hfil EJDE-2017/27\hfilneg]
{Abhishek Sarkar}

\address{Abhishek Sarkar \newline
NTIS, University of West Bohemia,
Technick\'a 8, 306 14 Plze\v{n}, Czech Republic}
\email{sarkara@ntis.zcu.cz}

\dedicatory{Communicated by Mitsuharu Otani}

\thanks{Submitted September 12, 2016. Published January 24, 2017.}
\subjclass[2010]{35J30, 35J40, 35J60}
\keywords{Biharmonic; critical exponent; multiple solutions}

\begin{abstract}
 In this article we study the existence of at least two positive weak solutions
 of an nonhomogeneous fourth-order Navier boundary-value problem involving
 critical exponential growth on a bounded domain in $\mathbb{R}^4$,
 with a parameter $\lambda >0$. We establish upper and lower bounds for
 $\lambda$, which determine multiplicity and non-existence of solutions.
\end{abstract}

\maketitle
\numberwithin{equation}{section}
\newtheorem{theorem}{Theorem}[section]
\newtheorem{lemma}[theorem]{Lemma}
\newtheorem{proposition}[theorem]{Proposition}
\newtheorem{remark}[theorem]{Remark}
\newtheorem{definition}[theorem]{Definition}
\newtheorem{corollary}[theorem]{Corollary}
\allowdisplaybreaks


\section{Introduction}

Let $\Omega \subset \mathbb{R}^{4}$ be a bounded domain with the boundary
$\partial \Omega \in C^{2,\sigma}$ for some $0 < \sigma <1$.
In this context, we study the existence of multiple solutions in
$W^{2,2}_{\mathcal{N}}(\Omega) = \{u \in W^{2,2}(\Omega): u = 0 \text{ on }
\partial \Omega\}$, for the following fourth-order Navier boundary value problem
\begin{equation} \label{eP}
\begin{gathered}
\Delta^2 u = \mu u |u|^pe^{u^2} + \lambda h(x) \quad \text{in } \Omega,\\
 u,-\Delta u > 0 \quad \text{in } \Omega, \\
u=\Delta u=0 \quad \text{on } \partial \Omega,
 \end{gathered}
\end{equation}
where $h \geq 0$ in $\Omega$, $\|h\|_{L^2(\Omega)} = 1$,
$ \lambda >0$, $\mu =1$ if $p>0$ and $\mu \in (0,\lambda_1(\Omega))$ if $p=0$.
Where $\lambda_1(\Omega)$ and $\phi_1$ denote the first eigenvalue and the
 corresponding eigenfunction of $\Delta^2 $ on $W^{2,2}_{\mathcal{N}}(\Omega)$
respectively with respect to the Navier boundary condition. We note that
$\lambda_1 >0$ and $\phi_1$ is strictly positive (see \cite{Drabek}).
The existence of multiple solutions for analogous problems in higher
dimensions with critical exponent, have been studied in \cite{Peral,Lu}
for the Dirichlet boundary condition, and in \cite{Zhang} for Navier boundary
condition. The existence of multiple solutions for the fourth-order
nonhomogeneous quasilinear equation has been studied in \cite{Santos}.
The corresponding problem for second order elliptic equations have been
studied in \cite{Prashanth} for dimension two and in \cite{Tarantello}
for higher dimensions. We note that, the critical growth for the fourth-order
equations is $u \mapsto |u|^{8/(N-4)}u$ for $N \geq 5$, from the
point of view of the Sobolev imbedding theorem in $\mathbb{R}^n$.
In 1971, Moser \cite{Moser} proved the following theorem.

 \begin{theorem} \label{Moser_Thm}
 Let $\Omega \subset \mathbb{R}^N$, $N \geq 2$ be a bounded domain.
There exists a constant $C_N >0$ such that for any $u \in W^{1,N}_0(\Omega)$,
$N\geq 2$ with $\|\nabla u\|_{L^N(\Omega)} \leq 1$, then
 \begin{equation}
 \int_{\Omega} e^{\alpha |u|^p}\,\mathrm{d} x \leq C_N|\Omega|, \quad
\forall\alpha \leq \alpha_N, \label{Moser_Sharp}
 \end{equation}
where
$$
p = \frac{N}{N-1}, \quad \alpha_N:= N w^{\frac{1}{N-1}}_{N-1},
$$
and $w_{N-1}$ is the surface measure of the unit sphere
$\mathbb{S}^{N-1} \subset \mathbb{R}^N$. Furthermore, the integral on the
left hand side can be made arbitrarily large if $\alpha > \alpha_N$ by
appropriate choice of $u$ with $\|\nabla u\|_{L^N(\Omega)} \leq 1$.
The embedding
$$
W^{1,N}_0(\Omega) \ni u \mapsto e^{\alpha |u|^{\frac{N}{N-1}}} \in L^1(\Omega),
$$
is compact for $\alpha < \alpha_N$ and it is not compact for $\alpha = \alpha_N$.
\end{theorem}

In 1988, Adams \cite{Adams} extended the above result of Moser to higher
order Sobolev spaces. To state the main theorem by Adams, we denote the
$m$-th order derivatives of $u \in C^m(\Omega)$, by
\[
\nabla^m u = \begin{cases}
 \Delta ^{m/2} u , &\text{for $m$ even},\\
 \nabla \Delta^{(m-1)/2} u, &\text{for $m$ odd}.
 \end{cases}
\]
 Now denote by $W^{m,\frac{N}{m}}_0(\Omega)$ the completion of
 $C^{\infty}_0(\Omega)$, under the Sobolev norm
 \begin{equation}
 \|u\|_{W^{m,\frac{N}{m}}(\Omega)}
= \Big( \|u\|^{N/m}_{N/m}
 + \sum_{|\alpha|=1}^m \|D^{\alpha} u\|^{N/m}_{N/m}\Big)^{m/N}. \label{full-norm}
 \end{equation}
Adams proved the following embedding.

 \begin{theorem}\label{Adams_Thm}
 Let $\Omega \subset \mathbb{R}^N$ be a bounded domain. 
If $m$ is a positive integer and $m \leq N$, then there exists a constant 
$C_0=C_0(N,m)>0$, such that for any $u \in W^{m,\frac{N}{m}}_0(\Omega)$ with 
$\| \nabla^m u\|_{L^{N/m}(\Omega)} \leq 1$, then
 \begin{equation}
 \frac{1}{|\Omega|} \int_{\Omega} \exp\Big(\beta |u(x)|^{N/(N-m)}\Big)
\,\mathrm{d} x \leq C_0, \label{Adams_Sharp}
 \end{equation}
 for all $\beta \leq \beta_{N,m}$, where
 \[
\beta_{N,m}=\begin{cases}
\frac{N}{w_{N-1}}
 \big[\frac{\pi ^{\frac{N}{2}}2^m \Gamma(\frac{m+1}{2})}
 {\Gamma(\frac{N-m+1}{2})}\big]^{N/(N-m)}, & \text{when $m$  is odd,}\\[4pt]
\frac{N}{w_{N-1}}\big[\frac{\pi ^{\frac{N}{2}}2^m \Gamma(\frac{m}{2})}
{\Gamma(\frac{N-m}{2})}\big]^{N/(N-m)} , & \text{when $m$ is even}.
\end{cases}
\]
Furthermore, for any $\beta > \beta_{N,m}$, the integral can be made 
as large as possible by appropriate choice of $u$ with 
$\|\nabla ^m u\|_{L^{N/m}(\Omega)} \leq 1$.
\end{theorem}

Now we define a subspace of $W^{m,\frac{N}{m}}(\Omega)$, by
$$
W^{m,\frac{N}{m}}_{\mathcal{N}}(\Omega) := 
\big\{u \in W^{m,\frac{N}{m}}(\Omega): \Delta^j u|_{\partial \Omega} =0 
\text{ for } 0 \leq j\leq \big[\frac{m-1}{2}\big]\big\}.
$$
 Note that, $W_0^{m,\frac{N}{m}}(\Omega)$ is strictly contained in 
$W^{m,\frac{N}{m}}_{\mathcal{N}}(\Omega)$.
Therefore, one has
 \begin{align*}
&\sup_{u \in W^{m,\frac{N}{m}}_0(\Omega), 
\|\nabla^m u\|_{L^{N/m}(\Omega)} \leq 1} 
 \int_{\Omega} e^{\beta_{N,m} |u|^{N/(N-m)}}\,\mathrm{d} x \\
&\leq \sup_{u \in W^{m,\frac{N}{m}}_{\mathcal{N}}(\Omega), 
\|\nabla^m u\|_{L^{N/m}(\Omega)} \leq 1} \int_{\Omega} 
e^{\beta_{N,m} |u|^{N/(N-m)}}\,\mathrm{d} x.
 \end{align*}

In 2012, Tarsi \cite{Tarsi} established that the Adams' inequality is also 
valid for the larger space $W^{m,\frac{N}{m}}_{\mathcal{N}}(\Omega)$. 
The key idea was to embed $W^{m,\frac{N}{m}}_{\mathcal{N}}(\Omega)$ into a 
Zygmund space. We state her embedding theorem below.

 \begin{theorem}\label{Tarsi_Thm}
 Let $N >2$, $m <N$ and $\Omega \subset \mathbb{R}^N$ be a bounded domain. 
Then, there is a constant $C'_N >0$, such that for all 
$u \in W^{m,\frac{N}{m}}_{\mathcal{N}}(\Omega)$ with 
$\|\nabla^m u \|_{L^{N/m}(\Omega)} \leq 1$, we have
 \begin{equation}
 \int_{\Omega} e^{\beta |u|^{N/(N-m)}}\,\mathrm{d} x <C'_N |\Omega|, \quad
\forall \beta \leq \beta_{N,m} , \label{Tarsi}
 \end{equation}
 and the constant $\beta_{N,m}$ appearing in \eqref{Tarsi} is sharp and
 $\beta_{N,m}$ is same as in Theorem \ref{Adams_Thm}.
 \end{theorem}

 \begin{remark} \rm
 When $N=4=2m$, we have $\beta_{4,2} = 32 \pi^2$.
 \end{remark}

 \begin{remark} \rm
 We note that the bilinear form
 \begin{equation}
 (u,v) \mapsto \int_{\Omega}\nabla^m u \cdot \nabla^m v
= \begin{cases}
 \int_{\Omega} \Delta^k u \Delta^k v, & \text{if } m =2k,\\
 \int_{\Omega} \nabla(\Delta^k u) \cdot \nabla (\Delta^k v), &
 \text{if } m=2k+1,
\end{cases} \label{poly-norm}
\end{equation}
defines a scalar product on both spaces $W^{m,2}_0(\Omega)$ and
$W^{m,2}_{\mathcal{N}}(\Omega)$.
Furthermore, if $\Omega$ is bounded, this scalar product induces a norm
 equivalent to \eqref{full-norm}.
 \end{remark}

Therefore, the above results imply that the nonlinearity of the problem \eqref{eP}
 is of critical type. Now we state our main theorem regarding multiple solutions 
in this non-compact situation, given by problem \eqref{eP}.

\begin{theorem} \label{Multiplicity}
There exist positive real numbers $\lambda_* \leq \lambda^*$, with 
$\lambda_*$ independent of $h$, such that the problem \eqref{eP} has at 
least two positive solutions for all $ \lambda \in (0, \lambda_*)$ 
and no solution for all $\lambda > \lambda^*$.
\end{theorem}

Though the Palais-Smale condition fails due to the presence of critical exponent, 
first we adapt the method of Tarantello (cf. \cite{Tarantello}) 
to prove the existence of a first solution by a decomposition of 
Nehari manifold into three parts. Then, for the existence of second solution, 
we rely on a refined version of the Mountain-Pass Lemma, which was introduced 
by Ghoussoub and Preiss in \cite{Preiss}.


\section{Decomposition of the Nehari Manifold}

Let $f(u) = \mu |u|^pue^{u^2}$. 
The corresponding energy functional associated with problem \eqref{eP}, is 
\begin{equation}
J(u)= \frac{1}{2} \int_{\Omega}|\Delta u|^2- \int_{\Omega} F(u) 
- \lambda \int_{\Omega} hu , \label{energy}
\end{equation}
where $F(u) = \int_0^u f(s)ds$. As the energy functional is not bounded 
from below on $W^{2,2}_{\mathcal{N}}(\Omega)$, we need to study $J$ on the
 Nehari manifold
 \begin{equation}
 \mathcal{M}:= \{u \in W^{2,2}_{\mathcal{N}}(\Omega): \langle J'(u),u \rangle =0\},
 \end{equation}
where $J'(u)$ denotes the Fr\'{e}chet derivative of $J$ at $u$ and 
$\langle \cdot,\cdot \rangle$ is the inner product. Here we note that, 
$\mathcal{M}$ contains every solution of the problem \eqref{eP}.
For any $u \in W^{2,2}_{\mathcal{N}}(\Omega)$, we note that
\begin{gather*}
\langle J'(u),u \rangle = \int_{\Omega} |\Delta u|^2 - \int_{\Omega} f(u)u 
 - \lambda \int_{\Omega} hu, \\
\langle J''(u)u,u \rangle = \int_{\Omega}|\Delta u|^2 - \int_{\Omega} f'(u)u^2.
\end{gather*}
Similar to the method used by Tarantello \cite{Tarantello}, we split 
$\mathcal{M}$ into three parts
\begin{gather*}
\mathcal{M}^0 = \{u \in \mathcal{M}: \langle J''(u)u,u \rangle = 0\},\\
\mathcal{M}^+ = \{u \in \mathcal{M}: \langle J''(u)u,u \rangle > 0\},\\
\mathcal{M}^- = \{u \in \mathcal{M}: \langle J''(u)u,u \rangle < 0\}.
\end{gather*}

\section{Topological Properties of  $\mathcal{M}^0,\mathcal{M}^+, \mathcal{M}^-$}

Our first aim is to show, $\mathcal{M}^0 = \{0\}$ for some small $\lambda$. 
For this, let $\zeta >0$ if $p>0$ and $\zeta < \frac{\lambda_1-\mu}{\mu}$ if $p=0$. 
Define, $ \Lambda := \{u \in W^{2,2}_{\mathcal{N}}(\Omega): 
\int_{\Omega} |\Delta u|^2 \leq (1+\zeta)\int_{\Omega} f'(u)u^2\}$.
Then, Lemma \ref{nonempty} implies that $\Lambda \neq \{0\}$. We now assume 
the following important hypotheses
\begin{gather}
 \lambda >0, \quad \|h\|_{L^2(\Omega)} = 1 , \nonumber \\
\inf_{u \in \Lambda \setminus \{0\}}\Big(\mu \int_{\Omega}(p+2u^2)|u|^{p+2}e^{u^2}
 - \lambda \int_{\Omega}hu\Big)>0. \label{Nehari1}
\end{gather} 
Condition \eqref{Nehari1} forces $\lambda$ to be suitably small. 
Indeed, we can prove the following result.

\begin{proposition} \label{lambdastar}
Let
\begin{equation}
\lambda < \mu C_0^{\frac{p+3}{p+4}}|\Omega|^{-(\frac{p+2}{2p+8})}, \label{lambda}
\end{equation}
 where $C_0 = \inf_{u \in \Lambda \setminus \{0\}}
 \int_{\Omega}(p+2u^2)|u|^{p+2}e^{u^2} >0$. Then \eqref{Nehari1} holds.
\end{proposition}

\begin{proof}
\textbf{Step 1:} $\inf_{ u \in \Lambda \setminus \{0\}} 
\|u\|_{W^{2,2}_{\mathcal{N}}(\Omega)} >0$. 
Toward a contradiction, suppose that, there exists a sequence 
$\{u_n\} \subset \Lambda \setminus \{0\}$, with 
$\|u_n\|_{W^{2,2}_{\mathcal{N}}(\Omega)} \to 0$ as $n \to \infty$. 
Let $v_n = \frac{u_n}{\|u_n\|_{W^{2,2}_{\mathcal{N}}(\Omega)}}$. 
Then $\|v_n\|_{W^{2,2}_{\mathcal{N}}(\Omega)} =1$ and $v_n$ satisfies
\begin{equation}
1 \leq (1+\zeta) \int_{\Omega} f'(u_n) v_n^2, \quad \forall n. \label{lambda1}
\end{equation}
Since $u_n \to 0$ in $W^{2,2}_{\mathcal{N}}(\Omega)$, by Adams' inequality 
for the higher order derivative in Theorem \ref{Tarsi_Thm}, we obtain
 $f'(u_n) \to f'(0)$ in $L^r(\Omega)$ for all $r \geq 1$. Since $v_n$ is 
bounded in $W^{2,2}_{\mathcal{N}}(\Omega)$, $v_n$ has a weak limit say $v$ 
in $W^{2,2}_{\mathcal{N}}(\Omega)$. Certainly 
$\|v\|_{W^{2,2}_{\mathcal{N}}(\Omega)} \leq 1$ and up to a subsequence which 
we still denote by $v_n$ which converges strongly to $v$ in $L^r(\Omega)$ 
for all $r \geq 1$. Hence from \eqref{lambda1}, we obtain
\begin{equation}
\int_{\Omega} |\Delta v|^2 \leq 1 \leq (1+\zeta) f'(0) \int_{\Omega} v^2. \label{lambda2}
\end{equation}
This gives a contradiction for the case $p>0$ since $f'(0)= 0$ in this case. 
For the case $p=0$, by the assumption
$$
\int_{\Omega} |\Delta v|^2 \geq \lambda_1 \int_{\Omega} v^2 
> (1+\zeta) \mu \int_{\Omega}v^2,
$$ 
which gives a contradiction to \eqref{lambda1} since $f'(0)= \mu$. 
This completes Step 1.
Since $\inf_{ u \in \Lambda \setminus \{0\}} 
\|u\|_{W^{2,2}_{\mathcal{N}}(\Omega)} >0$, from the definition of 
$\Lambda$, we obtain
\begin{equation}
0< \inf_{u \in \Lambda \setminus \{0\}} \int_{\Omega}f'(u)u^2
=\inf_{u \in \Lambda \setminus \{0\}}\mu 
\int_{\Omega}(p+1+2u^2)e^{u^2}|u|^{p+2}. \label{Nehari123} 
\end{equation}
Using \eqref{Nehari123}, we can easily check that
\begin{equation}
 C_0=\inf_{u \in \Lambda \setminus \{0\}}\int_{\Omega}(p+2u^2)|u|^{p+2}e^{u^2} >0. \label{lambda-inf}
\end{equation}
\smallskip

\noindent\textbf{Step 2:} Finally, we have
\begin{align*}
 \lambda \big|\int_{\Omega} hu\big| 
&\leq \lambda \|u\|_{L^2(\Omega)} 
\leq \lambda |\Omega|^{\frac{p+2}{2p+8}}
 \Big(\int_{\Omega} |u|^{p+4} \Big)^{1/(p+4)}\\
&\leq \frac{\lambda |\Omega|^{\frac{p+2}{2p+8}}}
 {(\mu \int_{\Omega}(p+2u^2)|u|^{p+2}e^{u^2})^{\frac{p+3}{p+4}}} 
\Big(\mu \int_{\Omega} (p+2u^2)|u|^{p+2}e^{u^2}\Big)\\
&\leq \Big(\frac{\lambda |\Omega|^{\frac{p+2}{2p+8}}}{\mu C_0^{\frac{p+3}{p+4}}}\Big) 
\Big(\mu \int_{\Omega}(p+2u^2)|u|^{p+2}e^{u^2}\Big).
\end{align*}
Hence, from the above inequality together with \eqref{lambda} and \eqref{lambda-inf}, 
we can complete the proof.
\end{proof}

\begin{lemma} \label{Null Set}
Suppose $\lambda >0$ be such that \eqref{Nehari1} holds. Then 
$\mathcal{M}^0 = \{0\}$.
\end{lemma}

\begin{proof}
For the sake of contradiction, suppose there exists $u \in \mathcal{M}^0$ and 
$u \not\equiv 0$. Then, we have
\begin{gather}
\int_{\Omega}|\Delta u|^2 = \int_{\Omega} f(u) u + \lambda \int_{\Omega}hu, \label{Nehari2}\\
\int_{\Omega}|\Delta u|^2 = \int_{\Omega} f'(u)u^2. \label{Nehari3}
\end{gather}
It follows from \eqref{Nehari3}, that 
$$
\int_{\Omega}|\Delta u|^2 = \int_{\Omega} f'(u)u^2 < (1+\zeta) 
\int_{\Omega} f'(u)u^2,
$$ 
therefore, $ u \in \Lambda \setminus \{0\}$. 
From \eqref{Nehari2} and \eqref{Nehari3}, we obtain
$$
\lambda \int_{\Omega} hu = \int_{\Omega}(f'(u)u-f(u))u 
= \mu \int_{\Omega}(p+2u^2)|u|^{p+2}e^{u^2},
$$
which violates the condition \eqref{Nehari1}. Therefore, $\mathcal{M}^0 = \{0\}$.
\end{proof}

Now we discuss the topological properties of $\mathcal{M}^+$ and $\mathcal{M}^-$. 
The study of Nehari manifold is closely related to the behaviour of the map 
$s \mapsto J(su)$. This technique was first introduced in \cite{Dra-Poh} 
by Dr\'{a}bek and Pohozaev. Given 
$u \in {W^{2,2}_{\mathcal{N}}(\Omega)} \setminus \{0\}$, we define a map,
 $\xi_u: \mathbb{R}^+ \to \mathbb{R}$ by
\begin{equation}
\xi_u(s) = s \int_{\Omega} |\Delta u|^2 - \int_{\Omega} f(su)u. \label{xi}
\end{equation}
The choice of the above function is a consequence of the following expression
\begin{equation*}
\langle J'(su), su \rangle 
= s \Big(s \int_{\Omega} |\Delta u|^2 - \int_{\Omega} f(su)u 
- \lambda \int_{\Omega}hu \Big).
\end{equation*}
So, $\xi_u(s)=\lambda \int_{\Omega}hu$ if and only if 
$su \in \mathcal{M}$ for $s >0$.

Now we are ready to prove the following lemma.

\begin{lemma} \label{nonempty}
For every $u \in W^{2,2}_{\mathcal{N}}(\Omega) \setminus \{0\}$, 
there exists unique $s_* =s_*(u) >0$, such that $\xi_u(\cdot)$ has
its maximum at $s_*$ with $\xi_u(s_*)>0$. 
Also there holds, $s_*u \in \Lambda \setminus \{0\}$.
\end{lemma}

\begin{proof}
Differentiating \eqref{xi}, we have
\begin{equation}
\xi'_u(s) = \int_{\Omega} |\Delta u|^2- \int_{\Omega} f'(su)u^2. \label{xi1}
\end{equation}
Therefore,
\begin{equation}
s^2 \xi'_u(s)
= \int_{\Omega}|\Delta (su)|^2 - \int_{\Omega}f'(su)(su)^2 
= \langle J''(su)su,su \rangle. \label{xi2}
\end{equation}
Now we observe that, $\xi_u(\cdot)$ is a concave function on $\mathbb{R}^+$ since
\begin{equation}
\xi''_u(s)=-\int_{\Omega}f''(su)u^3 < 0. \label{xi3}
\end{equation}
Also from the range of $\mu$, we obtain
\[
\lim_{s \to 0+} \xi'_u(s) >0 , \quad
\lim_{s \to \infty} \xi_u(s) = -\infty.
\]
Hence there exists a unique $s_*=s_*(u)>0$, such that $\xi_u$ is
increasing on $(0,s_*)$, decreasing on $(s_*,\infty)$ and
 $\xi'_u(s_*)=0$. Now using \eqref{xi1} and $\xi'_u(s_*)=0$, we deduce
\begin{equation}
\begin{aligned}
 \xi_u(s_*)
&= s_* \int_{\Omega} f'(s_*u) u^2 - \int_{\Omega} f(s_*u)u   \\
 &= \frac{1}{s_*} \int_{\Omega} (f'(s_*u)s_*u - f(s_*u))s_*u  \\
 &=\frac{\mu}{s_*} \int_{\Omega} (p+2(s_*u)^2)|s_*u|^{p+2}e^{(s_*u)^2} > 0.
\end{aligned} \label{xi4}
\end{equation}
Here we note that, $f'(s)s-f(s) =\mu(p+2s^2)|s|^p s e^{s^2}$. Finally
$$
s_* \xi'_u(s_*) = \int_{\Omega} |\Delta(s_*u)|^2 - \int_{\Omega}f'(s_*u)(s_*u)^2 =0,
$$
which implies, $s_*u \in \Lambda \setminus \{0\}$.
\end{proof}

\begin{lemma} \label{min-thm}
Let $\lambda$ be such that \eqref{Nehari1} holds. Then, for every 
$u \in W^{2,2}_{\mathcal{N}}(\Omega) \setminus \{0\}$, there exists a unique 
$s_- = s_-(u)>0$ such that $s_-u \in \mathcal{M}^-$, $s_- > s_*$ and 
$J(s_-u) = \max_{s \geq s_*} J(su) \hspace{2mm}\forall s \in [s_*, \infty)$. 
Furthermore, if $\int_{\Omega} hu >0$, then there exists a unique $s_+=s_+(u) >0$ 
such that $s_+u \in \mathcal{M}^+$. In particular, $ s_+ <s_*$ and 
\begin{equation}
J(s_+u) \leq J(su)\quad\text{for all }s \in [0, s_-]. \label{maxima-minima}
\end{equation}
\end{lemma}

\begin{proof}
Define the functional, $\rho_u :[0, \infty) \to \mathbb{R}$ by $\rho_u(s) = J(su)$.
 Then it is easy to verify that 
$\rho_u \in C^2((0,\infty),\mathbb{R}) \cap C([0,\infty),\mathbb{R})$. 
Now we have 
$$
\rho'_u(s) = \xi_u(s)-\lambda \int_{\Omega} hu, \quad 
\rho''_u(s)= \xi'_u(s), \quad \forall s >0.
$$
Next from \eqref{Nehari1} and \eqref{xi4}, we obtain
\[
\xi_u(s_*) - \lambda \int_{\Omega} hu
 = \frac{1}{s_*}\biggl\{ \mu \int_{\Omega} (p+2(s_*u)^2)|s_*u|^{p+2}e^{(s_*u)^2} 
 - \lambda \int _{\Omega} h(s_*u)\biggr\} >0.
\]
Since $\xi_u(\cdot)$ is strictly decreasing in $(s_*,\infty)$ and 
$\lim_{s \to \infty} \xi_u(s) = -\infty$, there exists a unique 
$s_- = s_-(u) > s_*$, such that $\xi_u(s_-) = \lambda \int_{\Omega} hu$. 
That is $s_-u \in \mathcal{M}$. One has $s_- > s_*$ and $\rho_u'(s_) <0$, 
we obtain $s_-u \in \mathcal{M^-}$.

On the other hand, when $\int_{\Omega} hu >0$, we have $\lim_{s \to 0+} \xi_u(s) <0$, 
which implies, $\xi_u(s)- \lambda \int_{\Omega} hu <0$ for $s$ near $0$. 
Hence there exists a unique $s_+$, such that $\xi_u(s_+) = \lambda \int_{\Omega} hu$ 
which implies $s_+u \in \mathcal{M}$. From the graph, we see that $\xi_u(\cdot)$ 
is strictly increasing in $(0,s_*)$. Hence we have, $s_+u \in \mathcal{M}^+$.

And the remaining properties of $s_-, s_+$ can be proved by analyzing the 
identity $\rho_u(s) = \xi_u(s) - \lambda \int_{\Omega}hu$.
\end{proof}

\begin{remark} \rm
If we define the positive cone 
$\mathcal{P}=\{ u \in W^{2,2}_{\mathcal{N}}(\Omega): \int_{\Omega}hu >0\}$ 
in $W^{2,2}_{\mathcal{N}}(\Omega)$. Then, we obtain 
$\mathcal{M^+} \subset \mathcal{P}$.
\end{remark}

The next corollary shows some topological properties of 
$\mathcal{M}^+, \mathcal{M}^-$.

\begin{corollary} \label{coro3.5}
Let $S_{W^{2,2}_{\mathcal{N}}(\Omega)} 
= \{u \in W^{2,2}_{\mathcal{N}}(\Omega): \|u\|_{W^{m,2}_{\mathcal{N}}(\Omega)} = 1\}$.
 Then there exists a homeomorphism 
$S_-: S_{W^{2,2}_{\mathcal{N}}(\Omega)} \to \mathcal{M}^-$ defined by 
$S_-(u) = s_-(u)u$. Also $\mathcal{M}^+$ is homeomorphic to 
$S_{W^{2,2}_{\mathcal{N}}(\Omega)} \cap \mathcal{P}$.
\end{corollary}

\begin{proof}
The function $S_-$ is continuous, because $s_-$ is continuous as an application 
of implicit function theorem applied to the map, 
$(s,u) \mapsto \xi_u(s) - \lambda \int_{\Omega}hu$. Also we deduce the continuity 
of $(S_-)^{-1}$ by the fact that $(S_-)^{-1}(w) = w/\|w\|$. 
In a similar manner, we can prove that $ \mathcal{M}^+$ is homeomorphic to 
$S_{W^{m,2}_{\mathcal{N}}(\Omega)} \cap \mathcal{P}$.
\end{proof}

We set, $\theta_0 = \inf\{J(u) : u \in \mathcal{M}\}$. 
Relying on the embedding of $W^{2,2}_{\mathcal{N}}
(\Omega) \hookrightarrow L^q(\Omega)$ for all $1 \leq q <\infty$ 
and using the estimate, $F(s) \leq \frac{\mu|s|^p}{2}(e^{s^2}-1)$ for all 
$s \in \mathbb{R}$, we have the following two lemmas on the lower bound and 
upper bound of $\theta_0$ in terms of $\lambda$, $\mu$.

\begin{lemma} \label{upper bound}
There exists $C_1=C_1(p)>0$, such that 
$$ 
\theta_0 \geq -C_1 \lambda^{\frac{p+4}{p+3}}.
$$
\end{lemma}

\begin{proof}
Let $u \in \mathcal{M}$. Then
\begin{align*}
 J(u)&=\frac{1}{2} \int_{\Omega} |\Delta u|^2 -\int_{\Omega}F(u) 
 -\lambda \int_{\Omega}hu\\
 &=\int_{\Omega} \big[ \frac{1}{2}f(u)u-F(u)\big] 
 -\frac{\lambda}{2} \int_{\Omega}hu.
\end{align*}
We note that a simple calculation gives
\begin{equation}
 F(s) \leq \frac{\mu |s|^p}{2}(e^{s^2}-1), \quad \forall s \in \mathbb{R}. 
\label{F-estimate}
\end{equation}
Using \eqref{F-estimate}, we deduce
\begin{equation}
\begin{aligned}
 J(u)
&\geq \frac{\mu}{2} \int_{\Omega} ((u^2-1)e^{u^2}+1)|u|^p
 - \frac{\lambda}{2} \int_{\Omega}hu  \\
&\geq \frac{c\mu}{2} \int_{\Omega} |u|^{p+4}
-\frac{\lambda}{2}\int_{\Omega} hu,
\end{aligned} \label{lower-bound-lemma}
\end{equation}
since $(s^2-1)e^{s^2}+1 \geq cs^4$ for some $c>0$ and for all $s \in \mathbb{R}$.
By applying H\"{o}lder inequality, we obtain
\begin{equation}
 \int_{\Omega} hu \leq |\Omega|^{\frac{p+2}{2(p+4)}} \|u\|_{L^{p+4}(\Omega)}.
\label{lower-bound-holder}
\end{equation}
From \eqref{lower-bound-lemma} and \eqref{lower-bound-holder}, we obtain
\begin{equation}
 J(u) \geq \frac{c \mu}{2} \|u\|^{p+4}_{L^{p+4}(\Omega)}
- \Big(\frac{\lambda |\Omega|^{\frac{p+2}{2(p+4)}}}{2}\Big)
 \|u\|_{L^{p+4}(\Omega)}. \label{lower-bound}
\end{equation}
By considering the global minimum of the function
\[
\omega(x)= (\frac{c \mu}{2}) x^{p+4}
- \Big( \frac{\lambda |\Omega|^{\frac{p+2}{2(p+4)}}}{2}\Big) x,
\]
we deduce $\theta_0 \geq -C_1 \lambda^{\frac{p+4}{p+3}}$.
\end{proof}

\begin{lemma}\label{uppbdd}
There exists $C_2 >0$, such that 
$$ 
\theta_0 \leq - \frac{\mu (p+1)p}{2(p+2)}C_2.
$$
\end{lemma}

\begin{proof}
Choose $v \in W^{2,2}_{\mathcal{N}}(\Omega) \setminus \{0\}$, such that 
$\int_{\Omega} hv >0$. Therefore, by Lemma \ref{min-thm}, there exists 
$s_+=s_+(v)>0$, such that $s_+v \in \mathcal{M}^+$. 
Hence
\begin{equation}
\begin{aligned}
J(s_+v)
&= -\frac{s_+^2}{2} \int_{\Omega} |\Delta u|^2 
+ \int_{\Omega}[ f(s_+v)s_+v - F(s_+v)] \\
& \leq \int_{\Omega}\Big[ f(s_+v)s_+v -F(s_+v) - \frac{1}{2}f'(s_+v)(s_+v)^2\Big],
\end{aligned}\label{upp}
\end{equation}
since $s_+v \in \mathcal{M}$.
Now we consider the function
$$
\gamma(s) = f(s)s - F(s) - \frac{1}{2} f'(s) s^2.
$$
We note that $\gamma'(s)= -\frac{1}{2} f''(s)s^2$.
Since $\gamma(0)=0$, it follows that $\gamma(s) \leq 0$ for all
$s \in \mathbb{R}$. Also we can verify the following limits
\begin{gather*} %(i)
\lim_{s \to 0} \frac{\gamma(s)}{|s|^{p+2}} = -\frac{\mu p (p+1)}{2(p+2)} \quad
\text{if }p >0, \\
 \lim_{s \to 0} \frac{\gamma(s)}{s^4} = -\frac{3}{4}\mu \quad \text{if } p=0, \\
\lim_{s \to \infty} \frac{\gamma(s)}{|s|^{p+4}e^{s^2}}
= -\mu \quad \forall p \geq 0.
\end{gather*}
From these two estimates, we obtain
\begin{equation}
\gamma(s) \leq -\frac{\mu p(p+1)}{(p+2)}(p+2s^2)|s|^{2(p+2)}e^{s^2} ,\quad
\forall s \in \mathbb{R}. \label{upp1}
\end{equation}
Therefore, using \eqref{upp} and \eqref{upp1} we obtain
\begin{equation}
\begin{aligned}
J(s_+v)
&\leq -\frac{\mu p(p+1)}{2(p+2)} \int_{\Omega} (p+2|s_+v|^2)
 |s_+v|^{p+2} e^{|s_+v|^2}  \\ 
&\leq -\frac{\mu p(p+1)}{2(p+2)} \int_{\Omega} |s_+v|^{p+4}.
\end{aligned}
\end{equation}
Hence
\[
\theta_0 \leq -\frac{\mu p(p+1)}{2(p+2)} C_2,\quad \text{where }
 C_2 = \int_{\Omega} |s_+v|^{p+4}.
\]
\end{proof}

As a consequence of Lemma \ref{Null Set}, we have the following lemma.

\begin{lemma} \label{Implicit-Inner}
Let $\lambda$ and $h$ satisfy \eqref{Nehari1}. Given 
$u \in \mathcal{M} \setminus \{0\}$, there exists $\delta >0$ and a 
differentiable function 
$s:\{w \in W^{2,2}_{\mathcal{N}}(\Omega): \|w\|_{W^{2,2}_{\mathcal{N}}(\Omega)} 
< \delta \}\to \mathbb{R}$, with 
$$
s(0)=1,\quad s(w)(u-w) \in \mathcal{M}, \quad \forall 
\|w\|_{W^{2,2}_{\mathcal{N}}(\Omega)} < \delta
$$ 
and
\begin{equation}
\langle s'(0), v \rangle= \frac{2 \int_{\Omega} \Delta u \Delta v 
- \int_{\Omega} (f'(u)u+f(u))v - \lambda \int_{\Omega}hv}
{\int_{\Omega} |\Delta u |^2 - \int_{\Omega}f'(u)u^2} . \label{Nehari4}
\end{equation}
\end{lemma}

\begin{proof}
Define a function $G: \mathbb{R} \times W^{2,2}_{\mathcal{N}}(\Omega) \to \mathbb{R}$
 by
$$
G(s,w) = s \int_{\Omega} |\Delta (u-w)|^2 - \int_{\Omega} f(s(u-w))(u-w) 
- \lambda \int_{\Omega} h(u-w).
$$
Then $ G \in C^1( \mathbb{R} \times W^{2,2}_{\mathcal{N}}(\Omega); \mathbb{R})$ 
and since $u \in \mathcal{M}$ it implies 
$$
G(1,0)= \int_{\Omega} |\Delta u|^2 - \int_{\Omega}f(u)u - \lambda \int_{\Omega} hu 
= 0.
$$ 
Also $G_s(1,0) \neq 0$, indeed 
$$
G_s(1,0)= \int_{\Omega} |\Delta u|^2 - \int_{\Omega} f'(u)u^2 \neq 0,
$$
thanks to Lemma \ref{Null Set}.
 Then by the Implicit Function Theorem, there exists $\delta >0$ and a map 
$s:\{w \in W^{2,2}_{\mathcal{N}}(\Omega): \|w\| < \delta\} \to \mathbb{R}$ 
of class $C^1$ that satisfies
\begin{gather*}
G(s(w),w)= 0, \quad \text{if } \|w\|_{W^{2,2}_{\mathcal{N}}(\Omega)} < \delta,\\
s(0) = 1.
\end{gather*}
Then
\begin{align*}
0 &= s(w)G(s(w),w)\\
 &= \int_{\Omega} (s(w) |\Delta (u-w)|)^2 - \int_{\Omega}f(s(w)(u-w))s(w)(u-w) \\
 &\quad -\lambda \int_{\Omega}hs(w)(u-w),
\end{align*}
that is $s(w)(u-w) \in \mathcal{M}$ for all $w \in W^{2,2}_{\mathcal{N}}(\Omega)$ 
with $\|w\| < \delta$.
Now if we differentiate the identity $G(s(w),w)=0$ with respect to $w$, we obtain
\[ 
0 = \langle G_s(s(w),w)s'(w) + G_w(s(w),w), v \rangle, \quad \forall 
v \in W^{2,2}_{\mathcal{N}}(\Omega).
 \]
Put $w=0$ in the above identity and we obtain
\[
 0 = \langle G_s(1,0) s'(0) + G_w(1,0), v \rangle 
= G_s(1,0) \langle s'(0), v \rangle + \langle G_w(1,0), v \rangle.
 \] 
Therefore,
\[
\langle s'(0), v \rangle 
= -\frac{\langle G_w(1,0),v \rangle}{G_s(1,0)}
= \frac{2 \int_{\Omega} \Delta u \Delta v - \int_{\Omega} (f'(u)u+f(u))v 
- \lambda \int_{\Omega}hv}{\int_{\Omega} |\Delta u|^2 - \int_{\Omega}f'(u)u^2}.
\]
\end{proof}


\section{Local minimum of $J$  in  $W^{2,2}_{\mathcal{N}}(\Omega)$}

We are now in a position to prove the existence of a local minimizer for $J$,
which ensures the existence of a first solution.
Note that, $\mathcal{M} \subset W^{2,2}_{\mathcal{N}}(\Omega)$ is closed, 
hence a complete metric space. Now $J$ is bounded below on $\mathcal{M}$. 
By the Ekeland's Variational Principle, there exists a sequence 
$\{u_n\} \subset \mathcal{M} \setminus \{0\}$, satisfying
\begin{equation}
J(u_n) < \theta_0 + \frac{1}{n}, \quad
J(v) \geq J(u_n)- \frac{1}{n}\|v-u_n\|_{W^{2,2}_{\mathcal{N}}(\Omega)}, \quad 
\forall v \in \mathcal{M} . \label{Ekeland}
\end{equation}

\begin{proposition} \label{norm-dual}
Let $\lambda$ and $h$ satisfy \eqref{Nehari1}. Then, we have
 $$
\lim _{n \to \infty}\|J'(u_n)\|_{(W^{2,2}_{\mathcal{N}}(\Omega))^{-1}} = 0.
$$
\end{proposition}

\begin{proof}
We proceed in three steps.
\smallskip

\noindent\textbf{Claim 1:} 
$\liminf_{n \to \infty}\|u_n\|_{W^{2,2}_{\mathcal{N}}(\Omega)}>0$.
Suppose this claim is false. Then, there exists a subsequence of 
$\{u_n\}$, which we still denote by $\{u_n\}$, such that 
$\|u_n\|_{W^{2,2}_{\mathcal{N}}(\Omega)} \to 0$ as $n \to \infty$. 
Therefore, $J(u_n) \to 0$ as $n \to \infty$ by continuity of the functional $J$. 
Which contradicts Lemma \ref{uppbdd}.
\smallskip

\noindent\textbf{Claim 2:} 
$\liminf_{n \to \infty} \int_{\Omega} (p+2u_n^2)|u_n|^{p+2}e^{u_n^2} >0$.
We argue by contradiction. Assume there exists a subsequence of $\{u_n\}$, 
which is still denoted by $\{u_n\}$, satisfying
\begin{equation}
 \lim_{n \to \infty} \int_{\Omega}(p+2u_n^2)|u_n|^{p+2}e^{u_n^2} \to 0 \quad
\text{as } n \to \infty . \label{lim-dual}
\end{equation}
Here we note that, $u_n \to 0$ in $L^q(\Omega)$ for all $q \in [1,\infty)$, 
by using \eqref{lim-dual}, and for the case $p>0$, we obtain
\[
\int_{\Omega} f(u_n)u_n = \mu \int_{\Omega} |u_n|^{p+2} e^{u_n^2} \to 0 \quad
\text{ as } n \to \infty.
\]
Therefore, we have $\int_{\Omega}f(u_n)u_n \to 0$ and $\int_{\Omega} hu_n \to 0$ 
as $n \to \infty$. Since $\{u_n\} \subset \mathcal{M}$, we deduce 
$\|u_n\|_{W^{2,2}_{\mathcal{N}}} \to 0$ as $n \to \infty$, hence a contradiction 
to  Claim 1. Similar argument also holds for $p=0$.
\smallskip

\noindent\textbf{Claim 3:} $\liminf_{n \to \infty} 
| \int_{\Omega}|\Delta u_n|^2 - \int_{\Omega} f'(u_n)u_n^2| >0$.
Suppose the claim does not hold. Then for a subsequence $\{u_n\}$, we have
\begin{equation}
 \int_{\Omega} |\Delta u_n|^2 - \int_{\Omega} f'(u_n)u_n^2 = o_n(1). 
\label{Nehari1234}
 \end{equation}
From \eqref{Nehari1234} and using Claim 1,
we infer that
\[
\liminf_{n \to \infty}f'(u_n)u_n^2 >0.
\]
Therefore, we have $u_n \in \Lambda \setminus \{0\}$ for large $n$. 
Since $\{u_n\} \subset \mathcal{M}$, we obtain
\begin{align*}
 o_n(1) 
&= \lambda \int_{\Omega} hu_n + \int_{\Omega} (f(u_n)-f'(u_n)u_n)u_n\\
&= -\mu \int_{\Omega} (p+2u_n^2)|u_n|^{p+2}e^{u_n^2} 
+ \lambda \int_{\Omega} hu_n,
\end{align*}
which contradicts \eqref{Nehari1}. This completes the proof of the claim.

Now we complete the proof of the proposition.
 Suppose the statement of the proposition is false, i.e., 
$\|J'(u_n)\|_{(W^{2,2}_{\mathcal{N}}(\Omega))^{-1}} >0$, for all large $n$ 
(otherwise obvious). Now we set, $u=u_n \in \mathcal{M}$ and 
$w=\delta \frac{J'(u_n)}{\|J'(u_n)\|}$ for $\delta >0$ small 
(by Riesz representation theorem, we identify $J'(u_n)$ as an element in 
$W^{2,2}_{\mathcal{N}}(\Omega)$). Applying Lemma \ref{Implicit-Inner}, we obtain 
$s_n(\delta):= s[ \delta \frac{J'(u_n)}{\|J'(u_n)\|}] >0$, 
such that 
\[ 
w_{\delta}= s_n(\delta) \big[ u_n - \delta \frac{J'(u_n)}{\|J'(u_n)\|}\big] 
\in \mathcal{M}.
\]
Now from \eqref{Ekeland} and with the help of Taylor expansion, we have
\begin{align*}
 \frac{1}{n} \|w_{\delta} - u_n\| 
&\geq J(u_n) - J(w_{\delta})\\
&=(1-s_n(\delta)) \langle J'(w_{\delta}),u_n \rangle + \delta s_n(\delta) 
\big\langle J'(w_{\delta}), \frac{J'(u_n)}{\|J'(u_n)\|} \big\rangle
+ o(\delta).
\end{align*}
Dividing by $\delta>0$ and taking limit as $\delta \to 0$, we obtain
\[
\frac{1}{n}(1+|s_n'(0)| \|u_n\|) \geq -s'_n(0) \langle J'(u_n),u_n\rangle +\|J'(u_n)\|
=\|J'(u_n)\|.
\]
Hence
\[ 
\|J'(u_n)\| \leq \frac{1}{n}(1+|s_n'(0)|\|u_n\|).
\]
We complete the proof by noticing that, $|s_n'(0)|$ is uniformly bounded
 on $n$ by \eqref{Nehari4} and using the Claim 2.
\end{proof}

\begin{theorem}
Let $\lambda$ and $h$ satisfy \eqref{Nehari1}. Then there exists a 
nonnegative function $ u_0 \in \mathcal{M}^+$, such that 
$J(u_0)= \inf_{u \in \mathcal{M}\setminus \{0\}} J(u)$. 
Moreover, $u_0$ is a local minimum for $J$ in $W^{2,2}_{\mathcal{N}}(\Omega)$. 
\label{1st solution}
\end{theorem}

\begin{proof}
Let $\{u_n\}$ be a sequence which minimizes $J$ on $\mathcal{M} \setminus \{0\}$ 
as in \eqref{Ekeland}. 
\smallskip

\noindent\textbf{Step 1:}  $\liminf_{n \to \infty} \int_{\Omega} hu_n >0$ and hence 
$u_n \in \mathcal{M}^+$.
 Indeed, $u_n \in \mathcal{M}$ and by using Lemma \ref{uppbdd}, there exists $C>0$, 
such that
 \begin{equation}
\begin{aligned}
J(u_n) &= \frac{p}{2(p+2)} \int_{\Omega} |\Delta u_n|^2
+ \int_{\Omega} ( \frac{1}{p+2} f(u_n)u_n - F(u_n)) \\
 & \quad -\lambda \frac{p+1}{p+2} \int_{\Omega} hu_n < -C . 
\end{aligned} \label{liminf}
\end{equation}
Now we note that, $F(s) < \frac{1}{p+2}f(s)s$ for all $ s \in \mathbb{R}$.
Using \eqref{liminf}, we conclude
\[
 \liminf _{n \to \infty} \int_{\Omega}hu_n >0.
\]

\noindent\textbf{Step 2:} 
$ \limsup _{n \to \infty} \|u\|_{W^{2,2}_{\mathcal{N}}(\Omega)} < \infty$. 
\\
\textit{Case 1.} If $p>0$, then by using \eqref{liminf}, we obtain directly
$$ 
\int_{\Omega}|\Delta u_n|^2 \leq \lambda \int_{\Omega} hu_n,
$$ 
and then with the help of Sobolev embedding we derive $\{u_n\}$ is bounded 
in $W^{2,2}_{\mathcal{N}}(\Omega)$.
\\
\textit{Case 2.} If $p=0$, by using the fact that 
$\frac{1}{2}f(s)s - F(s) \geq Cs^4$ for all $s \in \mathbb{R}$ and for 
some $C>0$, we deduce that $\{u_n\}$ is a bounded sequence in $L^2(\Omega)$. 
It implies that $\{F(u_n)\}$ is a bounded sequence in $L^1(\Omega)$ 
using \eqref{liminf} and hence $\{u_n\}$ is a bounded sequence in 
$W^{2,2}_{\mathcal{N}}(\Omega)$.
\smallskip

\noindent\textbf{Step 3:}  Existence of $u_0 \in \mathcal{M}^+$.
From the previous step up to a subsequence, $u_n \rightharpoonup u_0$ weakly 
in $W^{2,2}_{\mathcal{N}}(\Omega)$. Now from the Proposition \ref{norm-dual},
 we note that $\{f(u_n)u_n\}$ is a bounded sequence in $L^1(\Omega)$. 
Therefore, by recalling Vitali convergence theorem 
(for details see Lemma \ref{mountain}), we obtain
$$
\int_{\Omega}f(u_n) \phi \to \int_{\Omega}f(u_0)\phi, \quad \text{for all } 
\phi \in W^{2,2}_{\mathcal{N}}(\Omega).
$$
Hence, $u_0$ will solve \eqref{eP}.
It is obvious that $u_0 \neq 0$ as $h \neq 0$, that is $u_0 \in \mathcal{M}$. 
We see that $ \theta_0 \leq J(u_0)$. From \eqref{Ekeland} we obtain 
by using Fatou's Lemma that $\theta_0 = \liminf_{n \to \infty} J(u_n) \geq J(u_0)$. 
Therefore, $u_0$ minimizes $J$ on $\mathcal{M} \setminus \{0\}$. 
Now we have to show $u_0 \in \mathcal{M}^+$.
Since $u_0$ satisfies $\int_{\Omega} hu_0>0$, by Lemma \ref{maxima-minima}, 
there exists $s_+(u_0)$ such that $s_+(u_0) u_0 \in \mathcal{M}^+$. 
We claim $s_+(u_0)=1$. Suppose $s_+(u_0) <1$, then $s_-(u_0)=1$ and hence 
$u_0 \in \mathcal{M}^-$. By using Lemma \ref{maxima-minima}, we obtain 
$$
J(s_+(u_0)u_0) < J(u_0) = \theta_0,
$$ 
which is impossible since $s_+(u_0)u_0 \in \mathcal{M}\setminus\{0\}$. 
\smallskip

\noindent\textbf{Step 4:}  $u_0$ is a local minimum for for $J$ in 
$W^{2,2}_{\mathcal{N}}(\Omega)$. 
 We see that $s_+(u_0) =1$, since $u_0 \in \mathcal{M}^+$ (from Step 3). 
Also from \eqref{maxima-minima}, we have
\begin{equation*}
s_+(u_0)=1 <s_*(u_0).
\end{equation*}
Now by the continuity of $s_*(u_0)$, for sufficiently small $\delta>0$, we have
\begin{equation}
1 < s_*(u_0-w), \quad \forall \|w\|_{W^{2,2}_{\mathcal{N}}(\Omega)} 
< \delta. \label{minimizer}
\end{equation}
 By Lemma \ref{Implicit-Inner}, for $\delta>0$ small enough if necessary, 
there exists $s: \{w \in W^{2,2}_{\mathcal{N}}(\Omega):
 \|w\| < \delta\} \to \mathbb{R}$, such that 
$s(w)(u_0-w) \in \mathcal{M}$ and $s(0)=1$.
 Whenever $s(w) \to 1 $ as $\|w\| \to 0$, we have
\[ 
s(w) < s_*(u_0-w), \hspace{1.5mm} \forall w \in W^{2,2}_{\mathcal{N}}(\Omega) \quad
\text{with } \|w\| < \delta.
\] 
Hence, we obtain $s(w)(u_0-w) \in \mathcal{M}^+$, using the above inequality 
and Lemma \ref{maxima-minima}. Again by using the Lemma \ref{maxima-minima}, 
we see that
\[
J(u_0-w) \geq J(s(w)(u_0-w)) \geq J(u_0), \quad \forall s \in [0,s_*(u_0-w)].
\] 
Therefore, from \eqref{minimizer}, we observe that $J(u_0-w) \geq J(u_0)$ for every 
$\|w\|_{W^{2,2}_{\mathcal{N}}(\Omega)} <\delta$. 
Consequently, $u_0$ is a local minimizer. 
\smallskip

\noindent\textbf{Step 5:}  A positive local minimum for $J$.
 When $u_0, -\Delta u_0 > 0$, we are done. Otherwise, we obtain positive 
solution by the following procedure (cf. \cite{Santos}).
 Since $-\Delta u_0 \in L^2(\Omega)$ (also we note that $-\Delta u_0 \not\equiv 0$,
 as $u_0 \in \mathcal{M}^+$), by standard elliptic PDE theory 
(see e.g \cite[Theorem 9.1.4]{Wu}), the  boundary-value problem 
\[
\begin{gathered}
-\Delta v = |-\Delta u_0| \quad \text{in } \Omega,\\
v =0 \quad \text{on } \partial \Omega,
\end{gathered}
\]
has a strong solution in $W^{2,2}_{\mathcal{N}}(\Omega)$. 
Note that, $\|v\|_{W^{2,2}_{\mathcal{N}}} = \|u_0\|_{W^{2,2}_{\mathcal{N}}}$ 
and also by maximum principle, we obtain $ v > |u_0|$ in $\Omega$. 
Hence, we obtain
\begin{equation}
\|v\| = \|u_0\|,\quad  |v|_{p+1} \geq |u_0|_{p+1}, \quad
\int_{\Omega} h v >0. \label{hv}
\end{equation}
 From \eqref{hv}, we have
\begin{equation*}
1 = s_+(u_0) \leq s_+(v) \leq s_-(v) \leq s_-(u_0).
\end{equation*}
Then Lemma \ref{min-thm} implies
\begin{equation}
 J(s_+(v)v) =\min_{s \in [0,s_-(v)]} J(sv) \leq J(v) \leq J(u_0), \label{min1}
\end{equation} 
where the first inequality is not strict if and only if $s_+(v)=1$.

 Since $J(s_+(v)v) \geq \theta_0$ and $J(u_0) =\theta_0$, we obtain 
$s_+(v)=1$ from \eqref{min1}, which implies $v \in \mathcal{M}^+$ and 
$J(v)=J(u_0)=\theta_0$. Then $v$ is also a local minimum for $J$.
 When $u_0$ does not satisfy $u_0, -\Delta u_0 > 0$ a.e in $\Omega$, 
we replace $u_0$ by $v$.
\end{proof}

\section{Existence of a second solution}

The existence of a second solution for \eqref{eP}, depends on whether we can 
apply some version of Mountain Pass Lemma. We wish to look for a solution of 
the form $u_1 = v + u_0$, where $u_0$ is the local minimum for the functional
 \eqref{energy}. Then, we see that $u_1$ will solve \eqref{eP}, whenever $v$ 
solves the  equation
\begin{equation} \label{eP1}
\begin{gathered}
\Delta^2 v = f(v+u_0)-f(u_0)\quad  \text{in }\Omega,\\
v, -\Delta v > 0 \quad  \text{in }\Omega, \\
v = \Delta v = 0\quad \text{on } \partial \Omega.
 \end{gathered}
\end{equation}
We can write the above problem as
\begin{equation} \label{ePtilde}
\begin{gathered}
\Delta^2 v = \tilde{f}(x,v) \quad \text{in }\Omega,\\
v, -\Delta v > 0 \quad \text{in }\Omega, \\
v = \Delta v = 0 \quad \text{on } \partial \Omega,
 \end{gathered}
\end{equation}
when we define the map $\tilde{f}: \Omega \times \mathbb{R} \to \mathbb{R}$ by
\[
\tilde{f}(x,s) = \begin{cases}
f(s+u_0(x))-f(u_0(x)) &\text{if } s \geq 0, \\
0 &\text{if }s<0.
\end{cases}
\]
The energy functional corresponding to \eqref{ePtilde} is
$J_{u_0}: {W^{2,2}_{\mathcal{N}}(\Omega)} \to \mathbb{R}$, defined by
\[
J_ {u_0}(v) = \frac{1}{2}\int_{\Omega}|\Delta v|^2
- \int_{\Omega} \tilde{F}(x,v),
\]
where $\tilde{F}(x,s) = \int_0^s \tilde{f}(x,t)dt$.
Now onwards, we denote $J_{u_0}$ by $J_0$. These type of functionals were
studied in many articles, for example see \cite{Zhao-Chang,Peral}.
We now state the Generalized Mountain Pass Lemma that was introduced
 by Ghoussoub and Preiss \cite{Preiss}.

\begin{definition} \rm
Let $H$ be a closed subset of the Banach Space $W^{2,2}_{\mathcal{N}}(\Omega)$. 
We say that a sequence $\{v_n\} \subset W^{2,2}_{\mathcal{N}}(\Omega)$ is a 
Palais-Smale sequence for $J_0$ at the level $c$ around $H$, if
\begin{itemize}
\item[(i)] $\lim_{n \to \infty} \operatorname{dist}(v_n,H) =0$,
\item[(ii)] $\lim_{n \to \infty} J_0(v_n) = c$,
\item[(iii)] $\lim_{n \to \infty} \|J_0'(v_n)\|_{(W^{2,2}_{\mathcal{N}}(\Omega))^{-1}} = 0$.
\end{itemize}
In short, we say such a sequence is a $(PS)_{H,c}$ sequence.
\end{definition}

\begin{remark} \rm
In case $H =W^{2,2}_{\mathcal{N}}(\Omega)$, the above definition coincides
 with the usual Palais-Smale sequence at the level $c$.
\end{remark}

\begin{lemma} \label{mountain}
Let $H \subset W^{2,2}_{\mathcal{N}}(\Omega)$ be a closed set, 
$c \in \mathbb{R}$. Assume, $\{v_n\} \subset W^{2,2}_{\mathcal{N}}(\Omega)$ 
be a $(PS)_{H,c}$ sequence. Then (up to a subsequence), 
$v_n \rightharpoonup v_0$ weakly in $W^{2,2}_{\mathcal{N}}(\Omega)$, and
\begin{equation}
\lim _{n \to \infty} \int_{\Omega} \tilde{f}(x,v_n) 
= \int_{\Omega} \tilde{f}(x,v_0), \quad 
\lim_{n \to \infty} \int_{\Omega} \tilde{F}(x,v_n) 
= \int_{\Omega} \tilde{F}(x,v_0). \label{Vitali}
\end{equation}
\end{lemma}

\begin{proof}
From the fact that $\{v_n\}$ is a $(PS)_{H,c}$ sequence, we have
\begin{gather}
\frac{1}{2}\int_{\Omega} |\Delta v_n|^2 
 - \int_{\Omega} \tilde{F}(x,v_n) 
= c+ o_n(1), \label{GPS1}\\
\big|\int_{\Omega} \Delta v_n \Delta \phi 
 - \int_{\Omega}\tilde{f}(x,v_n) \phi \big| 
\leq o_n(1) \|\phi\|_{W^{2,2}_{\mathcal{N}}(\Omega)}, \quad 
\forall \phi \in W^{2,2}_{\mathcal{N}}(\Omega). \label{GPS2}
\end{gather}
Now we make the following claim.
\smallskip

\noindent\textbf{Claim:} $\sup_n \|v_n\|_{W^{2,2}_{\mathcal{N}}(\Omega)} < \infty$ 
and $\sup_n \int_{\Omega} \tilde{f}(x,v_n) < \infty$.

Given any $\epsilon >0$, there exists $s_{\epsilon} >0$, such that
\begin{equation}
\int_{\Omega} \tilde{F}(x,s) \leq \epsilon \int_{\Omega}s \tilde{f}(x,s), \quad 
\forall |s| \geq s_{\epsilon}. \label{GPS3}
\end{equation}
Using \eqref{GPS1} and \eqref{GPS3}, we have
\begin{equation}
\begin{aligned}
\frac{1}{2}\int_{\Omega} |\Delta v_n|^2
&\leq \int_{\Omega \cap \{|v_n| \leq s_{\epsilon}\}} \tilde{F}(x,v_n)
 + \int_{\Omega \cap \{|v_n| \geq s_{\epsilon}\}} \tilde{F}(x,v_n) +c+o_n(1)  \\
&\leq \int_{\Omega \cap \{|v_n| \leq s_{\epsilon}\}}\tilde{F}(x,v_n)
  + \epsilon \int_{\Omega} \tilde{f}(x,v_n)v_n +c+o_n(1)  \\
&\leq C_{\epsilon} + \epsilon \int_{\Omega} \tilde{f}(x,v_n)v_n.
\end{aligned} \label{GPS4}
\end{equation}
Now from \eqref{GPS4} and by substituting $\phi = v_n$ in \eqref{GPS2}, we obtain
\begin{align*}
\int_{\Omega}\tilde{f}(x,v_n)v_n
&\leq \int_{\Omega}|\Delta v_n|^2 + o_n(1) \|v_n\|_{W^{2,2}_{\mathcal{N}}(\Omega)}\\
&\leq 2 C_{\epsilon} + 2\epsilon \int_{\Omega} \tilde{f}(x,v_n)v_n
+o_n(1)\|v_n\|_{W^{2,2}_{\mathcal{N}}(\Omega)},
\end{align*}
Hence, by choosing $\epsilon$ small enough if needed, we obtain
\begin{equation}
 \int_{\Omega} \tilde{f}(x,v_n)v_n \leq \frac{2C_{\epsilon}}{1-2\epsilon}
 + o_n(1)\|v_n\|_{W^{2,2}_{\mathcal{N}}(\Omega)}. \label{GPS5}
\end{equation}
We conclude the claim by using \eqref{GPS2} and \eqref{GPS5}.
Also note that, $\sup_n\int_{\Omega}\tilde{f}(x,v_n)v_n <\infty$.
Since $\{v_n\} \subset W^{2,2}_{\mathcal{N}}(\Omega)$ is bounded, up to
a subsequence $v_n \rightharpoonup v_0$ weakly in $W^{2,2}_{\mathcal{N}}(\Omega)$,
for some $v_0 \in W^{2,2}_{\mathcal{N}}(\Omega)$.

Let $|A|$ denote the Lebesgue measure of $A \subset \mathbb{R}^{4}$.
 Now we set 
\[
C:=\sup_n \int_{\Omega}|\tilde{f}(x,v_n)v_n|,
\]
 and notice that 
$C<\infty$, from the above claim. Given $\epsilon >0$, we define
\[
\mu_{\epsilon}= \max_{x \in \bar{\Omega}, |s|\leq \frac{2C}{\epsilon}} 
|\tilde{f}(x,s)|.
\] 
Then, for any $A \subset \Omega$ with $|A| \leq \frac{\epsilon}{2\mu_{\epsilon}}$, 
we have
\begin{align*}
 \int_{A} |\tilde{f}(x,v_n)| 
&\leq \int_{A \cap \{|v_n| \geq \frac{2C}{\epsilon}\}} 
 \frac{|\tilde{f}(x,v_n)v_n|}{|v_n|} 
 + \int_{A \cap \{|v_n| \leq \frac{2C}{\epsilon}\}} |\tilde{f}(x,v_n)|\\
&\leq \frac{\epsilon}{2} + \mu_{\epsilon}|A| \leq \epsilon.
\end{align*}
Therefore, $\{\tilde{f}(x,v_n)\}$ is an equi-integrable family in 
$L^1(\Omega)$ and so is $\{\tilde{F}(x,v_n)\}$ (we note that, 
$|\tilde{F}(x,t)| \leq C_1 |t||\tilde{f}(x,t)|$ for all 
$(x,t) \in \bar{\Omega} \times \mathbb{R}$ and for some $C_1>0$). 
By applying the Vitali convergence theorem, we complete the proof.
 \end{proof}

Certainly, $J_0(0)=0$ and $v=0$ is a local minimum for $J_0$. 
Also, we have 
$$ 
\lim_{s \to \infty}J_0(sv) = -\infty, \quad 
\forall v \in W^{2,2}_{\mathcal{N}}(\Omega)\setminus \{0\}.
$$ 
Hence, we can fix $e \in W^{2,2}_{\mathcal{N}}(\Omega)\setminus \{0\}$, such that 
$J_0(e) <0$. Now, we define the mountain pass level 
$$ 
c_0 = \inf_{\gamma \in \Gamma} \sup_{s \in [0,1]} J_0(\gamma(s)),
$$
where $\Gamma = \{ \gamma \in C([0,1],W^{2,2}_{\mathcal{N}}(\Omega)): 
\gamma(0)=0, \gamma(1) = e\}$. Note that, from the definition, we have 
$c_0 \geq 0$. Define, $R_0 =\|e\|_{W^{2,2}_{\mathcal{N}}(\Omega)}$. 
We note that, $\inf\{J_0(v):\|v\|_{W^{2,2}_{\mathcal{N}}(\Omega)}=R\} = 0$ 
for all $R \in (0,R_0)$. We consider, $H = W^{2,2}_{\mathcal{N}}(\Omega)$ if 
$c_0 >0$ and $H=\{\|v\|_{W^{2,2}_{\mathcal{N}}(\Omega)} =\frac{R_0}{2}\}$ if 
$c_0=0$. We now present an upper bound for $c_0$.

\begin{lemma}\label{MPLev}
The upper bound $c_0$ for the Mountain Pass level satisfies 
\begin{equation}
c_0 < 16 \pi^2. \label{MPL1}
\end{equation}
\end{lemma}

\begin{proof}
Without loss of generality, we can assume that the unit ball 
$B_0(1) \subset \Omega$. For any $\epsilon >0$, we define
\begin{equation}
\tilde{\tau}_n(x) := \begin{cases}
\sqrt{\frac{1}{16 \pi^2}\log n}+\frac{1}{\sqrt{16 \pi^2 \log n}} (1-n|x|^2),
&\text{if } |x| \in [0, \frac{1}{\sqrt{n}}),\\[4pt]
-\sqrt{\frac{1}{4\pi^2 \log n}} \log |x|, 
&\text{if } |x| \in [\frac{1}{\sqrt{n}},1),\\[4pt]
\chi_n(x), & \text{if } |x| \in [1,\infty),
\end{cases}
\end{equation}
where
\[
 \chi_n \in \mathcal{C}^{\infty}_0(\Omega), \quad
 \chi_n\big|_{\partial B_1(0)}= \chi_n|_{\partial \Omega} =0.
\]
Furthermore,
 $\Delta \chi_n|_{\partial \Omega} = 0$
and $ \chi_n, |\nabla \chi_n|, \Delta \chi_n$ are  of $O(\frac{1}{\sqrt{2 \log n}})$
 as $n \to \infty$.
Then, $\tilde{\tau}_n \in W^{2,2}_{\mathcal{N}}(\Omega)$.
Now we normalize $\tilde{\tau}_n$, by setting
$$
{\tau}_n := \frac{\tilde{\tau}_n}{\|\tilde{\tau}_n\|_{W^{2,2}_{\mathcal{N}}
(\Omega)}} \in W^{2,2}_{\mathcal{N}}(\Omega).
$$
Suppose \eqref{MPL1} is not true. This implies for all $n$, there is $s_n>0$
(see \cite{Lam-Lu}), such that
\[
J_0(s_n \tau_n)= \sup_{s>0}J_0(s \tau_n) \geq 16 \pi^2, \quad \forall n.
\]
Hence
\begin{equation}
 \frac{s_n^2}{2} - \int_{\Omega} \tilde{F}(x,s_n \tau_n) \geq 16 \pi^2,
\quad \forall n. \label{MPL201}
\end{equation}
In particular
\begin{equation}
s_n^2 \geq 32 \pi^2, \quad \forall n. \label{MPL2}
\end{equation}
 It follows that, $\frac{d}{ds}J_0(s \tau_n)=0$ at the point of maximum
$s=s_n$ for $J_0$, we obtain
\begin{equation}
s_n^2 = \int_{\Omega} \tilde{f}(x,s_n \tau_n)(s_n \tau_n). \label{MPL3}
\end{equation}
 Now, from the definition of $\tilde{f}$, we have
$\inf_{x \in \bar{\Omega}} \tilde{f}(x,s) \geq e^{s^2}$ for $|s|$ large.
Then, from \eqref{MPL2} for sufficiently large $n$, we obtain
\begin{equation}
\begin{aligned}
 s_n^2
&\geq \int_{\{|x| \leq \frac{1}{\sqrt{n}}\}} \tilde{f}(x,s_n \tau_n)(s_n \tau_n) \\
&\geq \int_{\{|x| \leq \frac{1}{\sqrt{n}}\}} e^{s_n^2 \tau_n ^2}(s_n \tau_n)  \\
&\geq e^{{s_n^2} \frac{\log n}{16 \pi^2}} \frac{s_n}{\sqrt{16 \pi^2}}
  \sqrt{\log n} \frac{\pi^2}{2} \frac{1}{n^2} \\
&=\frac{\pi}{8} e^{(\frac{s_n^2}{16\pi^2}-2)\log n} s_n (\log n)^{\frac{1}{2}}.
\end{aligned} \label{MPL4}
\end{equation}
 Using \eqref{MPL2} and \eqref{MPL4}, it follows that $s_n$ is bounded and also
$s_n^2 \to 32 \pi^2$. Also from \eqref{MPL4}, we have
$s_n \geq \frac{\pi}{8} (\log n)^{\frac{1}{2}}$ for all large $n$, which
gives a contradiction.
\end{proof}

We now prove the theorem regarding the existence of a second solution.

\begin{theorem} \label{2nd solution}
Given a local minimum $u_0$ of $J$ in $W^{2,2}_{\mathcal{N}}(\Omega)$, 
there exists an element $v_0 \in W^{2,2}_{\mathcal{N}}(\Omega)$ with 
$v_0 > 0$ in $\Omega$, such that $J_0'(v_0)=0$.
\end{theorem}

\begin{proof}
From Lemma \ref{MPLev}, we have $c_0 \in [0, 16 \pi^2)$. 
Consider $\{v_n\}$ be a Palais-Smale sequence for $J_0$ at the level $c_0$ 
around $H$ (such a $(PS)_{H,c_0}$ sequence exists \cite{Preiss}). 
Then, up to a subsequence, $v_n \rightharpoonup v_0$ weakly in 
$W^{2,2}_{\mathcal{N}}(\Omega)$ for some $v_0 \in W^{2,2}_{\mathcal{N}}(\Omega)$ 
by Lemma \ref{mountain} and \eqref{Vitali} holds. We can easily check that,
 $v_0$ is a solution of \eqref{ePtilde} and therefore a critical point of $J_0$. 
It remains to show that $v_0$ is not a trivial solution. 
We prove this by contradiction. 
\smallskip

\noindent\textbf{Case I.} $c_0 = 0$, $ v_0 = 0$. We note that,
 $H= \{\|v\|_{W^{2,2}_{\mathcal{N}}(\Omega)} = \frac{R_0}{2}\}$ 
in this case. Also,
\[ 
o_n(1)=J_0(v_n)=\frac{1}{2} \int_{\Omega}|\Delta v_n|^2 
- \int_{\Omega}\tilde{F}(x,v_n) 
=\frac{1}{2} \int_{\Omega}|\Delta v_n|^2 +o_n(1), 
\]
which contradicts  that $\operatorname{dist}(v_n,H) \to 0$ as $n \to \infty$.
\smallskip

\noindent\textbf{Case II.} $c_0 \in (0,16 \pi^2)$, $v_0=0$.
 Using the fact that $J_0(v_n) \to c_0$, we see that for given any $\epsilon > 0$, 
$\|v_n\|^2_{W^{2,2}_{\mathcal{N}}(\Omega)} \leq 32 \pi^2 -\epsilon$ for all large $n$.
 Let, $0 < \delta < \frac{\epsilon}{32 \pi^2}$ and 
$q = \frac{32 \pi^2}{(1+\delta)(32 \pi^2 -\epsilon)} >1$. We have
$$
\int_{\Omega} |\tilde{f}(x,v_n)v_n|^q 
\leq C \int_{\Omega} e^{((1+\delta)q\|v_n\|^2)(\frac{v_n^2}{\|v_n\|^2})^2},
$$
since, $\sup_{x \in \bar{\Omega}}|\tilde{f}(x,s)s| \leq C e^{(1+\delta)s^2}$ 
for all $ s \in \mathbb{R}$ and for some $C>0$. Now using Tarsi's embedding 
\eqref{Tarsi}, we obtain 
$\sup_{x \in \bar{\Omega}} \int_{\Omega} |\tilde{f}(x,v_n)v_n|^q < \infty$ 
since $(1+\delta)q\|v_n\|^2 \leq 32 \pi^2$. Since $v_n \to 0$ pointwise 
almost everywhere in $\Omega$, by recalling Vitali convergence theorem, 
one obtains $\int_{\Omega} \tilde{f}(x,v_n)v_n \to 0$ as $n \to \infty$. Therefore,
\begin{align*}
 o_n(1) \|v_n\|_{W^{2,2}_{\mathcal{N}}(\Omega)} 
&= \langle J_0'(v_n),v_n \rangle = \frac{1}{2} \int_{\Omega}|\Delta v_n|^2 
 - \int_{\Omega} \tilde{f}(x,v_n)v_n\\
&= \frac{1}{2} \int_{\Omega} |\Delta v_n|^2+ o_n(1),
 \end{align*}
which contradicts, $\frac{1}{2} \int_{\Omega} |\Delta v_n|^2 \to c_0$ as 
$n \to \infty$.

Therefore, $v_0 \not\equiv 0$ in $\Omega$ and the positivity of $v_0$ and 
$-\Delta v_0$ follows from the fact that, $\tilde{f}(x,s) \geq 0$ for all 
$(x,s) \in \Omega \times \mathbb{R}$ and using the maximum principle.
\end{proof}

\section{Proof of Theorem \ref{Multiplicity}}

Define, $\lambda_* := \mu C_0^{\frac{p+3}{p+4}}|\Omega|^{-\frac{p+2}{2p+8}}$ 
where $C_0$ is same as in the Proposition \eqref{lambdastar}. 
Then, condition \eqref{Nehari1} is true whenever $0<\lambda < \lambda_*$. 
From the Theorem \ref{1st solution} and \ref{2nd solution}, we show the 
existence of at least two positive solutions for \eqref{eP}. 
Also, we define
$$
\lambda^* := p \mu^{-1/p} \Big( \frac{\lambda_1}{p+1}\Big)^{\frac{p+1}{p}}
\Big( \frac{\int_{\Omega}\phi_1}{\int_{\Omega}h \phi_1}\Big).
$$
 We prove, there is no solution of \eqref{eP} when $\lambda > \lambda^*$.
 Assume, $u_{\lambda}$ be a solution of \eqref{eP}. Now multiply \eqref{eP} 
by $\phi_1$ and then integrating by parts over $\Omega$, we obtain
\begin{align*}
\int_{\Omega} \phi_1( \Delta^2 u_{\lambda} )
= \int_{\Omega}f(u_{\lambda})\phi_1 + \lambda \int_{\Omega}h \phi_1,
\end{align*}
which implies
\begin{equation}
\lambda \int_{\Omega} h \phi_1
 = \int_{\Omega}(\lambda_1u_{\lambda}-f(u_{\lambda}))\phi_1 . \label{lambdaupper}
\end{equation}
We see that, $\lambda_1t-f(t) \leq \lambda_1t-\mu t^{p+1}=\Theta(t)$ for all $t >0$. 
The global maximum for the function $\Theta$ is 
$p \mu^{-1/p} (\frac{\lambda_1}{p+1} )^{\frac{p+1}{p}}$ on $(0,\infty)$.
Then, from \eqref{lambdaupper} and the definition of $\lambda^*$, we obtain 
$\lambda \leq \lambda^*$. This completes the proof of Theorem \ref{Multiplicity}.

\subsection*{Acknowledgements} 
This research was supported by the project LO1506 of the Czech Ministry of Education, 
Youth and Sports. The author wishes to express his sincere thanks to 
 Prof. Prashanth K. Srinivasan for suggesting the problem and for various 
suggestions along the way.

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\end{document}
