\documentclass[reqno]{amsart}
\usepackage{hyperref}
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\AtBeginDocument{{\noindent\small
\emph{Electronic Journal of Differential Equations},
Vol. 2017 (2017), No. 166, pp. 1--18.\newline
ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu}
\thanks{\copyright 2017 Texas State University.}
\vspace{8mm}}

\begin{document}
\title[\hfilneg EJDE-2017/166\hfil Finite element method for fractional NLS]
{Finite element method for time-space-fractional Schr\"odinger equation}

\author[X. G. Zhu, Z. B. Yuan, J. G. Wang, Y. F. Nie, Z. Z. Yang 
 \hfil EJDE-2017/166\hfilneg]
{Xiaogang Zhu, Zhanbin Yuan, Jungang Wang, Yufeng Nie, Zongze Yang }

\address{Xiaogang Zhu  \newline
Department of Applied Mathematics,
Northwestern Polytechnical University, 
Xi'an 710129,  China}
\email{zhuxg590@yeah.net}

\address{Zhanbin Yuan  \newline
Department of Applied Mathematics,
Northwestern Polytechnical University,
Xi'an 710129, China}
\email{yzzzb@nwpu.edu.cn}

\address{Jungang Wang \newline
Department of Applied Mathematics,
Northwestern Polytechnical University,
Xi'an 710129,  China}
\email{wangjungang@nwpu.edu.cn}

\address{Yufeng Nie \newline
Department of Applied Mathematics,
Northwestern Polytechnical University, 
Xi'an 710129, China}
\email{yfnie@nwpu.edu.cn}

\address{Zongze Yang \newline
Department of Applied Mathematics,
Northwestern Polytechnical University, 
Xi'an 710129, China}
\email{yangzongze@gmail.com}

\dedicatory{Communicated by  Mokhtar Kirane}

\thanks{Submitted January 30, 2016. Published July 5, 2017.}
\subjclass[2010]{35R11, 65M60, 65M12}
\keywords{Time-space-fractional NLS; finite element method; convergence}

\begin{abstract}
 In this article, we develop a fully discrete finite element method for
 the nonlinear Schr\"odinger equation (NLS) with time- and space-fractional
 derivatives. The time-fractional derivative is described in Caputo's sense
 and the space-fractional derivative in Riesz's sense.
 Its stability is well derived; the convergent estimate is discussed by an
 orthogonal operator. We also extend the method to the two-dimensional
 time-space-fractional NLS and to avoid the iterative solvers at each time
 step, a linearized scheme is further conducted. Several numerical examples
 are implemented finally, which confirm the theoretical results as well as
 illustrate the accuracy of our methods.
\end{abstract}

\maketitle
\numberwithin{equation}{section}
\newtheorem{theorem}{Theorem}[section]
\newtheorem{lemma}[theorem]{Lemma}
\newtheorem{remark}[theorem]{Remark}
\newtheorem{definition}[theorem]{Definition}
\newtheorem{example}[theorem]{Example}
\allowdisplaybreaks




\section{Introduction}\label{intro}

The fractional calculus, as a generalization of classical integer calculus, 
possesses a long history and affluent connotation, which was discovered by 
mathematicians over three hundred years ago. Recently, due to their excellent 
properties to characterize the effects of memory and
long-range interaction, fractional partial differential equations (FPDEs) 
have aroused keen interests among academic circles and have also been applied broadly in various applications,
examples including complex network, stochastic interfaces, synoptic climatology, certain option
pricing mechanism, medical image processing, dielectric polarization, and the chaotic dynamics of
nonlinear systems, etc. In virtue of the singular integral form of fractional derivatives,
however, solving FPDEs suffers more obstacles than those associated with classical derivatives.
In many cases, as we all know, the analytic solutions are unattainable or even unrealistic for
most of the mathematical models, so resorting to the efficient numerical approaches to obtain
numerical solutions turns into a preferred option. In the past decades, much to our delight,
great efforts have been devoted to this area and  numerous commonly used methods have been developed,
such as finite difference method \cite{Ref004,Ref003,Ref001,Ref005}, finite element method
\cite{Ref009,Ref007}, spectral method \cite{Ref006}, adomian decomposition method \cite{Ref0012},
and variational iteration method \cite{Ref0013}. In general, finite difference method and finite
element method are the most accepted methods for solving FPDEs. 
It is noteworthy that, because of the universal mutuality of these models, 
considering the high-dimensional space-FPDEs efficiently
in the numerical aspect appears somewhat challenging 
\cite{Ref0017,Ref0015,Ref0042,Reh05,Ref0040}.



In this work, our aim is to propose a fully discrete finite element method for the one-
and two-dimensional  time-space-fractional NLS. Due to the similarity, 
we first focus on the following one-dimensional model
\begin{align}\label{eq001}
\mathrm{i}\frac{\partial^\alpha \psi}{\partial t^\alpha}
+\frac{\partial^{2\beta} \psi}{\partial|x|^{2\beta}}
  +\lambda f(|\psi|^2)\psi &=0,  \quad (x;t) \in\Omega\times(0,T],
\end{align}
with $\mathrm{i}^2=-1$, real parameters $\lambda$, $0<\alpha\leq 1$, 
$1/2<\beta\leq 1$, and the initial and boundary conditions given by
\begin{gather}
 \psi(x,0)=\varphi(x), \quad x\in \Omega\cup\partial\Omega,\label{e008}\\
 \psi(a,t)=0, \quad \psi(b,t)=0,\quad t \in(0,T], \label{e009}
\end{gather}
where $\Omega=(a,b)$, $f(s)$ is real on $\mathbb{R}$ and $\varphi(x)$ 
is a prescribed function.
In \eqref{eq001},  the time-fractional derivative is defined in Caputo 
sense as follow
\begin{equation} \label{yy02}
\frac{\partial^\alpha \psi(x,t)}{\partial t^\alpha}
= {^C_0}D^\alpha_t\psi(x,t)
=\frac{1}{\Gamma(1-\alpha)} \int^t_0\frac{\partial \psi(x,\xi)}
{\partial \xi}\frac{d\xi}{(t-\xi)^\alpha},
\end{equation}
and the Riesz space-fractional derivative is defined as
\begin{gather*}
\frac{\partial^{2\beta} \psi(x,t)}{\partial|x|^{2\beta}}=\frac{-1}{2\cos(\beta \pi)}
    \big(D^{2\beta}_L \psi(x,t)+D^{2\beta}_R \psi(x,t)\big),\\
D^{2\beta}_L \psi(x,t) = \frac{1}{\Gamma(2-{2\beta})}\frac{\partial^2}{\partial x^2}
    \int^x_a(x-\xi)^{1-{2\beta}}\psi(\xi,t)d\xi,\\
D^{2\beta}_R \psi(x,t) = \frac{1}{\Gamma(2-{2\beta})}\frac{\partial^2}{\partial x^2}
    \int^b_x(\xi-x)^{1-{2\beta}}\psi(\xi,t)d\xi.
\end{gather*}
In particular, we note \eqref{eq001} degenerates to the classical NLS,
while $\alpha,\beta=1$, which  has been the subject of intense research
in the  past few decades
\cite{Ref0019,Ref0021,Ref0023,Ref0022}.

The time-fractional NLS was generated by Naber \cite{Reh07}, where two kinds of different means
were utilized  to perform this generalization. The time-fractional NLS, also covering the mixed
time-space-fractional NLS, have been investigated by many authors \cite{Reh09,Reh15,Reh16}.
For the numerical algorithms to the pure time-fractional NLS, see \cite{Reh13,Reh12,Reh10} for
reference. The space-fractional NLS was first raised by Laskin 
\cite{Ref0024,Ref0025}, 
via extending the Feynman path integral over the Brownian paths 
to a new path integral over the L\'evy quantum mechanical paths.
Its local and global
well-posedness were studied in \cite{Ref0026,Ref0027}. In addition, numerous works are dedicated
to researching the theoretical properties for such equation in various regimes
\cite{Ref0043,Ref0038,Ref0028,Ref0037}. As to the numerical works for the space- and time-space-fractional
NLS in one-dimension, Amore et al. used an effective collocation method to solve the space-fractional
NLS \cite{Ref0029}. 
Herzallah and Gepreel advised an adomian decomposition method for the 
time-space-fractional NLS \cite{Ref0033}. 
The variable-order space-fractional NLS was considered in \cite{Ref0032}, 
using the Crank-Nicholson scheme. The ground state solutions of the semiclassical 
fractional NLS was investigated in \cite{Ref0046}
by a Fourier spectral method. Wang and Huang gave a second-order energy conservative finite difference method
for the space-fractional NLS \cite{Ref0035}. Wang et al. proposed two mass conservative difference methods
for the space-fractional coupled nonlinear Schr\"odinger equations (CNLS) \cite{Ref0031,Ref0098}. Liu et al.
presented the implicit and explicit-implicit finite difference methods for the time-space-fractional NLS
and an implicit method for the time-space-fractional CNLS \cite{Ref0096}. In two-dimensional case, Zhao et al.
derived a new fourth-order compact operator and applied it to construct a compact alternating direction
implicit method for the Riesz space-fractional NLS \cite{Ref0039}, which is
linearized and validated to be stable and well convergent.


In this context, inspired by these methods in existence, we tend to propose the finite
element method to solve the one- and two-dimensional time-space-fractional NLS, and as the
character of the space-fractional NLS, some necessary properties of fractional derivatives
will be introduced for auxiliary analysis. The layout of this article is organized as follows.
In Section \ref{Au},  we recall some fractional derivative spaces and basic properties for
the fractional derivatives. In Section \ref{VF}, the weak formulations are described. The fully
discrete finite element method is formulated in Section \ref{FD}, and its unconditional stability
is analyzed. The convergence of it is discussed in Section \ref{CA}. In Section \ref{NE},
we extend the method to the two-dimensional time-space-fractional NLS and carry out some
numerical tests in Section \ref{NY}.

\section{Preliminaries} \label{Au}

In this section, we present some  auxiliary results related to the Riemann-Liouville
fractional derivatives. Let $u$, $v$  be the real-valued functions. We employ
\[
\|u\|_{L^2(\mathbb{R})}=\langle u,u\rangle^{1/2}_{L^2(\mathbb{R})},
\quad \langle u,v\rangle_{L^2(\mathbb{R})}=\int_{\mathbb{R}}uv dx,
\]
and denote the norms $\|\cdot\|_{L^2(\Omega)}$ by $\|\cdot\|_0$, 
$\|\cdot\|_{H^c(\Omega)}$
by $\|\cdot\|_c$, and the inner products $\langle\cdot,\cdot\rangle_{L^2(\Omega)}$, 
$\langle\cdot,\cdot\rangle_{L^2(\mathbb{R})}$ by $\langle\cdot,\cdot\rangle$, 
with $c>0$ and a subinterval $\Omega\subset\mathbb{R}$. Referring to \cite{Ref007}, 
we define the following fractional derivative spaces by the above inner product.

\begin{definition}[Left fractional derivative space] \rm 
For $\mu>0$, we define the left semi-norm
\begin{equation*}
    |u|_{J^\mu_L(\mathbb{R})}=\|D^\mu_Lu\|_{L^2(\mathbb{R})},
\end{equation*}
and left norm
\begin{equation*}
\|u\|_{J^\mu_L(\mathbb{R})}= \big( \|u\|^2_{L^2(\mathbb{R})}
    +|u|^2_{J^\mu_L(\mathbb{R})} \big)^{1/2} ,
\end{equation*}
and let $J^\mu_L(\mathbb{R})$ be the closure of $C^\infty(\mathbb{R})$
with respect to $\|\cdot\|_{J^\mu_L(\mathbb{R})}$.
\end{definition}

\begin{definition}[Right fractional derivative space] \rm 
For $\mu>0$, we define the right semi-norm
\begin{equation*}
    |u|_{J^\mu_R(\mathbb{R})}=\|D^\mu_Ru\|_{L^2(\mathbb{R})},
\end{equation*}
and right norm
\begin{equation*}
\|u\|_{J^\mu_R(\mathbb{R})}=\big( \|u\|^2_{L^2(\mathbb{R})}
    +|u|^2_{J^\mu_R(\mathbb{R})} \big)^{1/2} ,
\end{equation*}
and let $J^\mu_R(\mathbb{R})$ be the closure of $C^\infty(\mathbb{R})$
with respect to $\|\cdot\|_{J^\mu_R(\mathbb{R})}$.
\end{definition}

\begin{definition}[Fractional Sobolev space] \label{le002} \rm 
Let $\mu>0$ and $\mathcal{F}(u)$ be the Fourier transform of a prescribed
$u(x)$ defined on $\mathbb{R}$, i.e., $\mathcal{F}(u)=\int_{\mathbb{R}}u(x)e^{-i\omega x}dx$,
with the variable $\omega$. Then, we can define the semi-norm
\begin{equation*}
|u|_{H^\mu(\mathbb{R})}=\|\,|\omega|^\mu \mathcal{F}(u)\|_{L^2(\mathbb{R}_\omega)},
\end{equation*}
and norm
\begin{equation*}
\|u\|_{H^\mu(\mathbb{R})}=\big(\|u\|^2_{L^2(\mathbb{R})}+|u|^2_{H^\mu(\mathbb{R})}\big)^{1/2},
\end{equation*}
and denote  the closure of $C^\infty(\mathbb{R})$ with respect to
$\|\cdot\|_{H^\mu(\mathbb{R})}$ by $H^\mu(\mathbb{R})$.
\end{definition}

\begin{lemma}[\cite{Ref007}]
For $\mu>0$, $J^\mu_L(\mathbb{R})$, $J^\mu_R(\mathbb{R})$, and $H^\mu(\mathbb{R})$
are equivalent with the equivalent semi-norms and norms.
\end{lemma}

\begin{lemma}[\cite{Ref007}]\label{le003}
For $\mu>0$, we have the property in $L^2$-sense
\begin{align}\label{s28}
\langle D{^{\mu}_L}u,D{^{\mu}_R}u\rangle=\cos(\mu\pi)\|D{^{\mu}_L}u\|^2_{L^2(\mathbb{R})}.
\end{align}
\end{lemma}

Let $J^\mu_{L,0}(\Omega)$, $J^\mu_{R,0}(\Omega)$, $H^\mu_0(\Omega)$
be the closures of $C^\infty_0(\Omega)$ with respect to 
$\|\cdot\|_{J^\mu_L(\Omega)}$,
$\|\cdot\|_{J^\mu_R(\Omega)}$, and $\|\cdot\|_{H^\mu(\Omega)}$, respectively.
Then, we have the following lemmas.

\begin{lemma}[\cite{Ref0010}] \label{le009}
If $0<\beta<1$, $u\in J^{2\beta}_{L,0}(\Omega)$, and 
$v\in J^{2\beta}_{R,0}(\Omega)$, then
\begin{equation}\label{s29}
\langle D{^{2\beta}_L}u,v\rangle=\langle D{^{\beta}_L}u,D{^{\beta}_R}v\rangle,
\quad \langle D{^{2\beta}_R}u,v\rangle=\langle D{^{\beta}_R}u,D{^{\beta}_L}v\rangle.
\end{equation}
\end{lemma}

\begin{lemma}[\cite{Ref007}]\label{le007}
Let $\mu > 0$, $\mu\neq n-1/2$, $n\in \mathbb{N}$. $J^\mu_{L,0}(\Omega)$, 
$J^\mu_{R,0}(\Omega)$, and $H^\mu_0(\Omega)$ are equivalent with the
 equivalent semi-norms and norms.
\end{lemma}

\begin{lemma}[\cite{Ref007}] \label{le006}
For $\mu>0$, $u\in J^\mu_{L,0}(\Omega)$, and $0< \gamma< \mu$, we have
\begin{equation}\label{s30}
\|u\|_0\leq C|u|_{J^\mu_{L}(\Omega)},\quad
\ |u|_{J^\gamma_{L}(\Omega)}\leq C|u|_{J^\mu_{L}(\Omega)},
\end{equation}
and for $u\in J^\mu_{R,0}(\Omega)$, $0<\gamma< \mu$, we have
\begin{equation}\label{s32}
\|u\|_0\leq C|u|_{J^\mu_{R}(\Omega)},\quad
\ |u|_{J^\gamma_{R}(\Omega)}\leq C|u|_{J^\mu_{R}(\Omega)}.
\end{equation}
If $u\in H^\mu_0(\Omega)$, $0<\gamma<\mu$, $\mu\neq n-1/2$, $n\in \mathbb{N}$,
the analogous result is obtained.
\end{lemma}

\begin{remark}\label{re002}
\rm In two-dimensions, the fractional derivative and Sobolev spaces can also be established
and \eqref{s28}-\eqref{s32} still work; see \cite{Ref0017,Reh02} for overall views.
\end{remark}


\section{Weak problem}\label{VF}

At first, decompose the unknown $\psi(x,t)$ into its real and imaginary parts by
\begin{equation*}
    \psi(x,t)=u(x,t)+\mathrm{i}v(x,t).
\end{equation*}
Inserting it into \eqref{eq001}-\eqref{e009}, the original problem
can be recast as a coupled system
\begin{gather*}
\frac{\partial^\alpha u}{\partial t^\alpha}+\frac{\partial^{2\beta} v}
{\partial|x|^{2\beta}}
    +\lambda f(u^2+v^2)v=0,\\
\frac{\partial^\alpha v}{\partial t^\alpha}-\frac{\partial^{2\beta} u}{\partial|x|^{2\beta}}
    -\lambda f(u^2+v^2)u=0, \ \ (x;t) \in\Omega\times(0,T],
\end{gather*}
with the initial and boundary values
\begin{align*}
& u(x,0)=\operatorname{Re}\varphi(x), \quad v(x,0)=\operatorname{Im}\varphi(x),
    \quad x\in \Omega\cup\partial\Omega,\\
& u(x,t)=0, \quad v(x,t)=0, \quad (x;t)\in\partial\Omega\times(0,T].
\end{align*}
where ``Re", ``Im" mean retaining the real and imaginary parts, respectively. 
Then, using Lemma \ref{le009}, we can derive the weak problem, i.e., 
seek $u(\cdot,t)$, $v(\cdot,t)\in H^{\beta}_0(\Omega)$, for any 
$\chi_1$, $\chi_2\in H^{\beta}_0(\Omega)$, to solve
\begin{gather}
\big\langle\frac{\partial^\alpha u}{\partial t^\alpha},\chi_1\big\rangle
-\Lambda(v,\chi_1)
    +\lambda\langle f(u^2+v^2)v,\chi_1\rangle=0, \label{s05} \\
\big\langle\frac{\partial^\alpha v}{\partial t^\alpha},\chi_2\big\rangle
+\Lambda(u,\chi_2)
    -\lambda\langle f(u^2+v^2)u,\chi_2\rangle=0, \label{s06}\\
u(x,0)=\operatorname{Re}\varphi(x), \quad v(x,0)=\operatorname{Im}\varphi(x), 
\label{s07}
\end{gather}
with zero boundary values, where $\Lambda(\cdot,\cdot)$ takes the form
\[
 \Lambda(u,v)=\frac{1}{2\cos(\beta\pi)}\langle D^{\beta}_L u,D^{\beta}_R v\rangle
    +\frac{1}{2\cos(\beta\pi)}\langle D^{\beta}_R u,D^{\beta}_L v\rangle,
\]
and $\varphi(x)$ denotes the same initial function prescribed before.

\begin{theorem}\label{Th3}
The bilinear form $\Lambda(\cdot, \cdot)$ is symmetric and enjoys the properties
$\Lambda(u,v)\leq C_1\|u\|_{\beta}\|v\|_{\beta}$, 
$\Lambda(u,u)\geq C_2\|u\|^2_{\beta}$,
where $C_1$, $C_2$ are positive constants.
\end{theorem}

The above theorem was proved in \cite{Ref0010}, by recalling 
Lemmas \ref{le003}, \ref{le007}, and \ref{le006}.

\section{Fully discrete finite element method}\label{FD}

Let $t_n=n \tau$, $n=0,1,\ldots,N$, and $T=\tau N $ with a constant 
$N\in\mathbb{Z}^+$; we discretize
the Caputo derivative by a difference approach as follows
\begin{align*}
{^C_0}D^\alpha_tw(x,t_{n})
&=\frac{1}{\Gamma(1-\alpha)}\sum^{n}_{j=1}\int^{t_{j}}_{t_{j-1}}
    \frac{\partial w(x,\xi)}{\partial \xi} \frac{d\xi}{(t_n-\xi)^\alpha} \\
&=\frac{1}{\Gamma(1-\alpha)}\sum^{n}_{j=1}\frac{\partial w(x,t_{j-1/2})}{\partial t}
    \int^{t_{j}}_{t_{j-1}}\frac{d\xi}{(t_n-\xi)^\alpha}+R^{1}_\tau\\
&=\frac{\tau^{1-\alpha}}{\Gamma(2-\alpha)}\sum^{n-1}_{j=0}b_j\frac{\partial
    w(x,t_{n-j-1/2})}{\partial t} +R^{1}_\tau \\
&=\frac{\tau^{-\alpha}}{\Gamma(2-\alpha)}\sum^{n-1}_{j=0}b_jd_tw(x,t_{n-j})
    +R^{1}_\tau + R^{2}_\tau,
\end{align*}
where $b_j=(j+1)^{1-\alpha}-j^{1-\alpha}$, $d_tw(x,t_{n-j})=w(x,t_{n-j})-w(x,t_{n-j-1})$,
and $j=0,1,\ldots,n-1$. Particularly, we assign $0^0=0$ when $\alpha=1$.
 According to \cite{Re01}, the truncated errors $R^{1}_\tau$, $R^{2}_\tau$ 
satisfy $R^{2}_\tau= O(\tau^2)$ and
\begin{align*}
|R^{1}_\tau|&= \Big|\frac{1}{\Gamma(1-\alpha)}\sum^{n}_{j=1}\int^{t_{j}}_{t_{j-1}}
 \Big\{\frac{\partial w(x,\xi)}
{\partial \xi}-\frac{\partial w(x,t_{j-1/2})}{\partial t}\Big\}
 \frac{d\xi}{(t_n-\xi)^\alpha}\Big| \\
&\leq C\tau^{2-\alpha}\max _{0\leq t\leq t_n}\Big|
 \frac{\partial^2w(x,t)}{\partial t^2}\Big|,
\end{align*}
with a bounded constant $C$ independent of $\tau$ for all $\alpha\in(0,1)$ 
and $n\geq 1$.
If we denote the discretized fractional operator by
\begin{equation*}
\mathcal{D}_t^\alpha w(x,t_n)=\frac{1}{\Gamma(2-\alpha)}\sum^{n-1}_{j=0}
b_j\frac{w(x,t_{n-j})-w(x,t_{n-j-1})}{\tau^{\alpha}},
\end{equation*}
then $\frac{\partial^\alpha w(x,t_n)}{\partial t^\alpha}$ can be approximated by
$\mathcal{D}_t^\alpha w(x,t_n)$, more precisely,
\begin{align}\label{eee028}
 \frac{\partial^\alpha w(x,t_n)}{\partial t^\alpha}
=\mathcal{D}_t^\alpha w(x,t_n) + R_\tau,
\end{align}
where $R_\tau=R^{1}_\tau+R^{2}_\tau$. Let $\Sigma_h$ be a family of subdivisions 
of $\Omega$, $h$ be their grid parameters, and $X_h\subset H^\beta_0(\Omega)$ 
be the finite element subspace, denoted as
\begin{equation*}
X_h=\{v_h\in H^\beta_0(\Omega)\cap C^0(\bar{\Omega}): 
 v_h|_D\in P_{r}(D), \; \forall D\in \Sigma_h \},
\end{equation*}
in which, $P_{r}(D)$ is the set of polynomials of degree at most $r$ on $D$. 
Discretizing the Caputo
derivative by \eqref{eee028} and applying finite element method in space, we obtain
\begin{gather}
\langle\mathcal{D}_{t}^\alpha U^n,\chi_1\rangle-\Lambda(V^n,\chi_1)+\lambda\langle
    f((U^n)^2+(V^n)^2)V^n,\chi_1\rangle=0, \label{s08} \\
\langle\mathcal{D}_{t}^\alpha V^n,\chi_2\rangle+\Lambda(U^n,\chi_2)-\lambda\langle
    f((U^n)^2+(V^n)^2)U^n,\chi_2\rangle=0,\label{s09}
\end{gather}
with any $\chi_1$, $\chi_2\in X_h$, $U^0=\operatorname{Re}\delta\varphi(x)$, 
$V^0=\operatorname{Im}\delta\varphi(x)$,
and $\mathcal{D}^\alpha_{t}w^n$, given by
\begin{equation*}
\mathcal{D}^\alpha_{t}w^n= \frac{1}{\Gamma(2-\alpha)}
\sum^{n-1}_{j=0}b_j\frac{w^{n-j}-w^{n-j-1}}{\tau^{\alpha}},
\end{equation*}
where $w^n=U^n$ or $V^n$, $\delta\varphi(x)$ is vital to the starter of 
\eqref{s08}-\eqref{s09} and thereby shall be properly chosen. Let us introduce 
the parameter $G_\alpha$:
\begin{equation*}
    G_\alpha:=\tau^\alpha\Gamma(2-\alpha).
\end{equation*}
Regroup $\mathcal{D}^\alpha_{t}w^n$ as follows
\begin{align*}
\mathcal{D}_{t}^\alpha w^n
&=\frac{\tau^{-\alpha} }{\Gamma(2-\alpha)}\sum^{n-1}_{j=0}b_j(w^{n-j}-w^{n-j-1})\\
&=G_\alpha^{-1}\Big(w^{n}-\sum^{n-1}_{j=1}(b_{j-1}-b_{j})w^{n-j}- b_{n-1}w^0\Big),
\end{align*}
then \eqref{s08}-\eqref{s09} can be recast, i.e., seek $U^{n}$, $V^{n}\in X_h$,
for $\chi_1$, $\chi_2\in X_h$, such that
\begin{gather}
\begin{aligned}
&\langle U^n, \chi_1\rangle-G_\alpha\Lambda(V^n,\chi_1) \\
&= \sum^{n-1}_{j=1} (b_{j-1}-b_{j})\langle U^{n-j},\chi_1\rangle 
+ b_{n-1}\langle U^0,\chi_1
    \rangle-\lambda G_\alpha\langle f((U^n)^2+(V^n)^2)V^{n},\chi_1\rangle,
\end{aligned}  \label{eh003} \\
\begin{aligned}
&\langle V^n, \chi_2\rangle+G_\alpha\Lambda(U^n,\chi_2) \\
&= \sum^{n-1}_{j=1} (b_{j-1}-b_{j})\langle V^{n-j},\chi_2\rangle
 + b_{n-1}\langle V^0,\chi_2
    \rangle+\lambda G_\alpha\langle f((U^n)^2+(V^n)^2)U^{n},\chi_2\rangle,
\end{aligned} \label{s10}
\end{gather}
with the initial conditions
\begin{equation}\label{e006}
U^0=\operatorname{Re}\delta\varphi(x),\quad V^0=\operatorname{Im}\delta\varphi(x),
\quad x\in \Omega\cup\partial\Omega,
\end{equation}
and boundary conditions
\begin{equation}\label{e007}
U^j=0, \quad V^j=0, \quad 1\leq j\leq N, \quad \text{on } \partial\Omega.
\end{equation}
In particular, as $n=1$, i.e., at the first step, \eqref{eh003}-\eqref{s10} 
simply become
\begin{gather}
\langle U^1, \chi_1\rangle-G_\alpha\Lambda(V^1,\chi_1)
= \langle U^0,\chi_1\rangle
 -\lambda G_\alpha\langle f((U^1)^2+(V^1)^2)V^{1},\chi_1\rangle,\label{e005}\\
\langle V^1, \chi_2\rangle+G_\alpha\Lambda(U^1,\chi_2)= \langle V^0,\chi_2\rangle
 +\lambda G_\alpha\langle f((U^1)^2+(V^1)^2)U^{1},\chi_2\rangle.\label{s12}
\end{gather}

Next, we proceed with the stability for \eqref{eh003}-\eqref{e007}.
To this end, we recall some requisite properties
for $b_j=(j+1)^{1-\alpha}-j^{1-\alpha}$, $j=0,1,\ldots,n$, which read
\begin{gather}
1=b_0>b_1>b_2> \cdots >b_n>0,\quad b_n\to 0,\quad \text{ as } n\to +\infty,\label{t01}\\
\sum^{n}_{j=1}(b_{j-1}-b_{j})+b_{n}=(1-b_1)+\sum^{n-1}_{j=2}(b_{j-1}-b_{j})+b_{n-1}
=1.\label{t02}
\end{gather}

\begin{theorem}\label{Th5}
The method \eqref{eh003}-\eqref{e007} is stable in the sense that
\begin{equation*}
\|U^{n}\|^2_{0}+\|V^{n}\|^2_{0}\leq \|U^{0}\|^2_{0}+\|V^{0}\|^2_{0},\quad 
n=1,2,\ldots,N.
\end{equation*}
\end{theorem}

\begin{proof}
Let $\chi_1=U^n$, $\chi_2=V^n$ in \eqref{eh003}-\eqref{s10}. It follows that
\begin{gather}
\begin{aligned}
\langle U^n, U^n\rangle-G_\alpha\Lambda(V^n,U^n) 
&= \sum^{n-1}_{j=1}(b_{j-1}-b_{j})
    \langle U^{n-j},U^n\rangle 
+ b_{n-1}\langle U^0,U^n\rangle\\
&\quad -\lambda G_\alpha
    \langle f((U^n)^2+(V^n)^2)V^{n},U^n\rangle,
\end{aligned} \label{s13} \\
\begin{aligned}
\langle V^n, V^n\rangle+G_\alpha\Lambda(U^n,V^n) 
&=\sum^{n-1}_{j=1}(b_{j-1}-b_{j})
    \langle V^{n-j},V^n\rangle 
 + b_{n-1}\langle V^0,V^n\rangle \\
&\quad +\lambda G_\alpha
    \langle f((U^n)^2+(V^n)^2)U^{n},V^n\rangle.
\end{aligned} \label{s15}
\end{gather}
The sum of \eqref{s13} and \eqref{s15} shows
\begin{align*}
&\|U^n\|_0^2 + \|V^n\|_0^2 \\
&=  \sum^{n-1}_{j=1}( b_{j-1} - b_{j})
(\langle U^{n-j}, U^n\rangle + \langle V^{n-j},V^n\rangle)
 +  b_{n-1}(\langle U^0, U^n\rangle + \langle V^0, V^n\rangle),
\end{align*}
since $\Lambda(U^n,V^n)=\Lambda(V^n,U^n)$.
We go on with the work by the method of induction. In the case of $n=1$,
using H\"older's and Young's inequalities, there holds
\begin{align*}
\|U^1\|_0^2+\|V^1\|_0^2
&=\langle U^0,U^1\rangle+\langle V^0,V^1\rangle \\
&\leq \frac{1}{2}(\|U^0\|_0^2+\|V^0\|_0^2)+\frac{1}{2}(\|U^1\|_0^2+\|V^1\|_0^2),
\end{align*}
which suggests the result at the first step, i.e.,
$\|U^1\|_0^2+\|V^1\|_0^2\leq\|U^0\|_0^2+\|V^0\|_0^2$.
We now preset the essential hypothesis
\begin{equation}\label{s16}
   \|U^n\|_0^2+\|V^n\|_0^2\leq\|U^0\|_0^2+\|V^0\|_0^2, \quad n=2,3,\ldots,p-1,
\end{equation}
and begin to consider the case of $n=p$. Using  \eqref{s16}, we obtain
\begin{align*}
\|U^p\|_0^2+\|V^p\|_0^2
&=\sum^{p-1}_{j=1}( b_{j-1}-b_{j})(\|U^{p-j}\|_0
    \|U^p\|_0+\|V^{p-j}\|_0\|V^p\|_0) \\
&\quad+b_{p-1}(\|U^0\|_0\|U^p\|_0+\|V^0\|_0\|V^p\|_0)\\
&\leq\frac{1}{2}\sum^{p-1}_{j=1}( b_{j-1} - b_{j})(\|U^{p-j}\|_0^2+\|V^{p-j}\|_0^2)
    +\frac{1}{2}b_{p-1}(\|U^0\|_0^2+\|V^0\|_0^2) \\
&\quad+\frac{1}{2}\sum^{p-1}_{j=1}( b_{j-1}-b_{j})(\|U^{p}\|_0^2+\|V^{p}\|_0^2)
    +\frac{1}{2}b_{p-1}(\|U^p\|_0^2+\|V^p\|_0^2).
\end{align*}
Then, via \eqref{t01}-\eqref{t02}, we easily see that
\begin{align*}
\|U^p\|_0^2+\|V^p\|_0^2
&\leq \sum^{p-1}_{j=1}( b_{j-1}-b_{j})(\|U^{p-j}\|_0^2
+\|V^{p-j}\|_0^2)    +b_{p-1}(\|U^0\|_0^2+\|V^0\|_0^2)\\
&\leq \Big((1-b_1) +\sum^{p-1}_{j=2}(b_{j-1}-b_{j})+b_{p-1}\Big)
(\|U^0\|_0^2+\|V^0\|_0^2)\\
&= \|U^0\|_0^2+\|V^0\|_0^2,
\end{align*}
and hence, the method is unconditionally stable, which proves the theorem.
\end{proof}

\section{Convergent analysis}\label{CA}

In this part, we describe the error estimate for \eqref{eh003}-\eqref{e007}. 
Define a Ritz projection $\Pi_h:H_0^\beta(\Omega)\mapsto X_h$, via 
the orthogonal relation
\begin{equation}\label{eq0068}
\Lambda(u-\Pi_hu,v_h)= 0, \quad \forall v_h\in X_h.
\end{equation}
Then, relying on \cite{Ref0018,Ref009}, for a $\epsilon\in(0,1/2)$, 
the following lemma is admitted.

\begin{lemma}\label{le008}
If $u\in H_0^\beta(\Omega)\cap H^{r+1}(\Omega)$ and $\epsilon\in(0,1/2)$, then
\[
    \|u-\Pi_h u\|_{0}\leq Ch^{\tilde{r}+1}\|u\|_{r+1},
\]
where if $\beta\neq3/4$, $\tilde{r}=r$ and if $\beta=3/4$,
$\tilde{r}=r-\epsilon$; $C$ is independent of $h$.
\end{lemma}

\begin{lemma}\label{le068}
Let $\varepsilon^j\geq0$, $R\geq0$, $j=0,1,\ldots,N$, and satisfy
\begin{equation*}\label{eee06}
    \varepsilon^n\leq \sum^{n-1}_{j=1}(b_{j-1}-b_j)\varepsilon^{n-j}+R.
\end{equation*}
Then, when $0<\alpha<1$, we have
\begin{equation}\label{eee01}
    \varepsilon^n\leq b^{-1}_{n-1} R\leq n^\alpha R/(1-\alpha),
\end{equation}
and when $\alpha$ closes to $1$, it turns to be
\begin{equation}\label{eee02}
     \varepsilon^n\leq nR.
\end{equation}
\end{lemma}

\begin{proof}
In fact, the lemma is implicitly involved in \cite{Ref009,Re01,Reh06};
here, we only underline the process to \eqref{eee02}, since it can not be directly
derived from \eqref{eee01} when $\alpha\to 1$. It holds trivially as $n=1$.
We now suppose that
\begin{equation*}
    \varepsilon^n\leq nR, \quad n=2,3,\ldots, p-1,
\end{equation*}
and show the result remains valid at $n=p$. By \eqref{t01}-\eqref{t02}, it is clear that
\begin{align*}
\varepsilon^p
&\leq\sum^{p-1}_{j=1}(b_{j-1}-b_j)\varepsilon^{p-j}
 +R\leq\sum^{p-1}_{j=1}(b_{j-1}-b_j)(p-j)R+R\\
& \leq \sum^{p-1}_{j=1}(b_{j-1}-b_j)(p-1)R+R  \leq pR,
\end{align*}
in which, $1+ \sum^{p-1}_{j=1}(b_{j-1}-b_{j})(p-1)\leq p$. 
As a result, \eqref{eee02} is concluded.
\end{proof}

In the sequel we use  the following notation:
\[
\partial_tu=\partial u/\partial t, \quad 
\partial^2_{t}u=\partial^2 u/\partial t^2,
\quad \partial^\alpha_{t}u={^C_0}D^\alpha_tu,
\]
and  as stressed before, we select $\delta \varphi(x)=\Pi_h \varphi(x)$ 
and $\operatorname{Re}\varphi(x)$,
$\operatorname{Im}\varphi(x)\in H^{r+1}(\Omega)$ so that the discrete system 
can be started; $C$ will be regarded as a general constant that may be 
different at different occasions. In the error analysis,
we let $\psi^n$ be the analytic solution to the  model \eqref{eq001}-\eqref{e009}
 at $t=t_n$ with its real
and imaginary parts $u^n$, $v^n$, and $\{U^{n}\}_{n=0}^{N}$, $\{V^{n}\}_{n=0}^{N}$ 
be the numerical solutions obtained by \eqref{eh003}-\eqref{e007}. 
Also, we define $\psi^n_h=U^n+\mathrm{i}V^n$ and the complex norm
\begin{equation}\label{s23}
    \|\psi^n-\psi^n_h\|_0=\big(\|u^n-U^n\|^2_0+\|v^n-V^n\|^2_0\big)^{1/2}, \quad
 n=0,1,\ldots,N.
\end{equation}
Then, with the help of mathematical induction, we state the convergent theorem.


\begin{theorem}\label{Th6}
Assume  $u, v$, $\partial^\alpha_t u, \partial^\alpha_t v$,
 $\partial_t u, \partial_t v$, $\partial^2_t u,
\partial^2_t v \in L^\infty(0,T;H^{r+1}(\Omega))$, and 
$U^0=\rm{Re}$$\Pi_h \varphi$, $V^0=\rm{Im}$$\Pi_h\varphi$.
Then, for $0<\alpha<1$, we have
\begin{equation}\label{e0010}
\|\psi^n-\psi^n_h\|_0\leq C(\alpha,u, v,T^\alpha)
(\tau^{2-\alpha}+h^{\tilde{r}+1}), \quad n=0,1,\ldots,N,
\end{equation}
and when $\alpha$ closes to $1$, the estimate becomes
\begin{equation}\label{e0012}
\|\psi^n-\psi^n_h\|_0\leq C(u,v,T)(\tau+h^{\tilde{r}+1}), \quad n=0,1,\ldots,N,
\end{equation}
where if $\beta\neq3/4$, $\tilde{r}=r$ and if $\beta=3/4$, 
$\tilde{r}=r-\epsilon$, $0<\epsilon<1/2$;
$C(\alpha,u, v,T^\alpha)$ is only related to $\alpha$, $u$, $v$, 
$T^\alpha$, and $C(u,v,T)$ is only
related to $u$, $v$, and $T$.
\end{theorem}

\begin{proof}
We consider the case of $\lambda=0$. From $U^0=\operatorname{Re}\Pi_h \varphi$ and
$V^0=\operatorname{Im}\Pi_h \varphi$, \eqref{e0010}, \eqref{e0012} are 
automatically fulfilled as $n=0$.
The claims to $n\geq 1$ will be showed next. It follows from
\eqref{s05}, \eqref{s06}, and \eqref{eee028} that
\begin{gather*}
\langle\mathcal{D}_{t}^\alpha u^n,\chi_1\rangle-\Lambda(v^n,\chi_1)
=-\langle    R_{u,\tau},\chi_1\rangle,\quad \forall \chi_1\in X_h,\\
\langle\mathcal{D}_{t}^\alpha v^n,\chi_2\rangle+\Lambda(u^n,\chi_2)
=-\langle    R_{v,\tau},\chi_2\rangle,\quad \forall \chi_2\in X_h,
\end{gather*}
where $R_{u,\tau}$, $R_{v,\tau}$ are the truncated errors in time.
 Let $\widetilde{U}^n=\Pi_hu^n$,
$\widetilde{V}^n=\Pi_hv^n$, $\varepsilon_u^n=u^n-\widetilde{U}^n$, and 
$\varepsilon_v^n=v^n-\widetilde{V}^n$.
Using \eqref{eq0068}, we obtain
\begin{gather*}
\langle\mathcal{D}_{t}^\alpha \widetilde{U}^n,\chi_1\rangle
-\Lambda(\widetilde{V}^n,\chi_1)
=-\langle \mathcal{D}_{t}^\alpha\varepsilon_u^n,\chi_1\rangle
 -\langle R_{u,\tau},\chi_1\rangle, \\
\langle\mathcal{D}_{t}^\alpha \widetilde{V}^n,\chi_2\rangle
 +\Lambda(\widetilde{U}^n,\chi_2)
=-\langle \mathcal{D}_{t}^\alpha\varepsilon_v^n,\chi_2\rangle
 -\langle R_{v,\tau},\chi_2\rangle,
\end{gather*}
i.e., there exist
\begin{gather}
\begin{aligned}
\langle\widetilde{U}^n,\chi_1\rangle-G_\alpha\Lambda(\widetilde{V}^n,\chi_1) 
&=(1-b_1)  \langle\widetilde{U}^{n-1},\chi_1\rangle
+\sum^{n-1}_{j=2}(b_{j-1}-b_{j})\langle\widetilde{U}^{n-j},
  \chi_1\rangle\\
&\quad + b_{n-1}\langle\widetilde{U}^{0},\chi_1\rangle
-G_\alpha\langle\gamma^n_u,\chi_1\rangle,
\end{aligned} \label{s19}\\
 \begin{aligned}
\langle\widetilde{V}^n,\chi_2\rangle+G_\alpha\Lambda(\widetilde{U}^n,\chi_2) 
&=(1-b_1)  \langle\widetilde{V}^{n-1},\chi_2\rangle 
 +\sum^{n-1}_{j=2}(b_{j-1}-b_{j})\langle\widetilde{V}^{n-j},\chi_2\rangle\\
 &\quad   +b_{n-1}\langle\widetilde{V}^{0},\chi_2\rangle
 -G_\alpha\langle\gamma^n_v,\chi_2\rangle,
\end{aligned} \label{s20}
\end{gather}
with terms $\gamma^n_u=\mathcal{D}_{t}^\alpha\varepsilon_u^n+R_{u,\tau}$, 
$\gamma^n_v=\mathcal{D}_{t}^\alpha \varepsilon_v^n+R_{v,\tau}$. 
Let $e^n_u=U^n-\widetilde{U}^n$, $e^n_v=V^n-\widetilde{V}^n$. Then, subtracting
\eqref{s19}-\eqref{s20} from \eqref{eh003}-\eqref{s10} declares the residual 
equations
\begin{gather}
\begin{aligned}
\langle e^n_u,\chi_1\rangle-G_\alpha\Lambda(e^n_v,\chi_1)
&=(1-b_1)\langle e^{n-1}_u,\chi_1\rangle
+\sum^{n-1}_{j=2}(b_{j-1}-b_{j})\langle e^{n-j}_u,\chi_1\rangle \\
&\quad +    b_{n-1}\langle e^0_u,\chi_1\rangle
 + G_\alpha\langle \gamma^n_u,\chi_1\rangle, 
\end{aligned} \label{s17}\\
\begin{aligned}
\langle e^n_v,\chi_2\rangle+G_\alpha\Lambda(e^n_u,\chi_2) 
&=(1-b_1)\langle e^{n-1}_v,\chi_2\rangle
+\sum^{n-1}_{j=2}(b_{j-1}-b_{j})\langle e^{n-j}_v,\chi_2\rangle \\
&\quad +    b_{n-1}\langle e^0_v,\chi_2\rangle + G_\alpha\langle\gamma^n_v,\chi_2\rangle,
\end{aligned} \label{s18}
\end{gather}
which yield, by setting $\chi_1=e^n_u$, $\chi_2=e^n_v$, and adding \eqref{s17}, \eqref{s18}, that
\begin{align*}
\|e^n_u\|^2_0+\|e^n_v\|^2_0
&=\sum^{n-1}_{j=1}(b_{j-1}-b_{j})(\langle e^{n-j}_u,e^n_u
    \rangle+\langle e^{n-j}_v,e^n_v\rangle)\\
&\quad +b_{n-1}(\langle e^0_u,e^n_u\rangle + \langle e^0_v,e^n_v\rangle)
    +G_\alpha(\langle\gamma^n_u,e^n_u\rangle+\langle\gamma^n_v,e^n_v\rangle),
\end{align*}
where Theorem \ref{Th3} is also applied. Handled by H\"older's inequality, i.e.,
for all $a_1,b_1,a_2,b_2 >0$:
\[
 a_1b_1+a_2b_2\leq(a^2_1+a^2_2)^{1/2}(b^2_1+b^2_2)^{1/2},
\]
it leads to
\begin{align*}
\|\boldsymbol{e}^n_h\|^2_0
&\leq\sum^{n-1}_{j=1}( b_{j-1}-b_{j})(\|e^{n-j}_u\|_0\|e^n_u\|_0
 +\|e^{n-j}_v\|_0\|e^n_v\|_0) \\
&\quad+b_{n-1}(\|e^0_u\|_0\|e^n_u\|_0+\|e^0_v\|_0\|e^n_v\|_0)
 +G_\alpha(\|\gamma^n_u\|_0\|e^n_u\|_0+\|\gamma^n_v\|_0\|e^n_v\|_0)\\
&\leq\sum^{n-1}_{j=1}( b_{j-1}-b_{j})\|\boldsymbol{e}^{n-j}_h
 \|_0\|\boldsymbol{e}^{n}_h\|_0+b_{n-1}\|\boldsymbol{e}^0_h\|_0
 \|\boldsymbol{e}^n_h\|_0+G_\alpha\|\boldsymbol{\gamma}^n_\tau\|_0
 \|\boldsymbol{e}^n_h\|_0,
\end{align*}
with norms
$\|\boldsymbol{e}^{n-j}_h\|^2_0=\|e^{n-j}_u\|^2_0+\|e^{n-j}_v\|^2_0$,
$\|\boldsymbol{\gamma}^{n}_\tau\|^2_0=\|\gamma^{n}_u\|^2_0
+\|\gamma^{n}_v\|^2_0$, $j=0,1,\ldots,n$.
This further implies the following result
\begin{align*}
\|\boldsymbol{e}^n_h\|_0\leq (1-b_1)\|\boldsymbol{e}^{n-1}_h\|_0
 +\sum^{n-1}_{j=2}(b_{j-1}-b_{j})
\|\boldsymbol{e}^{n-j}_h\|_0+ b_{n-1}\|\boldsymbol{e}^0_h\|_0
 +G_\alpha\|\boldsymbol{\gamma}^n_\tau\|_0.
\end{align*}
Also, it can be deduced that
\begin{align*}
\|\mathcal{D}_{t}^\alpha\varepsilon^n_u\|_0
&\leq \|\partial^\alpha_t\varepsilon_u^n\|_0
+C\tau^{2-\alpha}\max _{0\leq t\leq t_n}\|\partial^2_t\varepsilon_u\|_0 \\
&\leq C h^{\tilde{r}+1}\|\partial^\alpha_tu^n\|_{r+1} +C\tau^{2-\alpha}h^{\tilde{r}+1}
\max _{0\leq t\leq t_n}\|\partial^2_tu\|_{r+1},
\end{align*}
which gives
\begin{align*}
\|\gamma^n_u\|_0 
&\leq  C h^{\tilde{r}+1}\|\partial^\alpha_tu^n\|_{r+1} + C\tau^{2-\alpha}\max
 _{0\leq t\leq t_n}\|\partial^2_tu\|_{0}\\
&\quad + C\tau^{2-\alpha}h^{\tilde{r}+1}
 \max _{0\leq t\leq t_n}\|\partial^2_tu\|_{r+1}.
\end{align*}
Omitting  $C\tau^{2-\alpha}h^{\tilde{r}+1}
\max _{0\leq t\leq t_n}\|\partial^2_tu\|_{r+1}$, we thus obtain
\begin{align}\label{e0016}
\|\gamma^n_u\|_0\leq C\tau^{2-\alpha}\max _{0\leq t\leq t_n}\|\partial^2_tu\|_{0}
+C h^{\tilde{r}+1}\|\partial^\alpha_tu^n\|_{r+1},
\end{align}
and $\|\gamma^n_u\|_0\sim\|\gamma^n_v\|_0\sim\|\boldsymbol{\gamma}^n_\tau\|_0$. 
Now, on the foregoing
discussion, with Lemma \ref{le068}, \eqref{e0016}, and $\|\boldsymbol{e}^0_h\|_0=0$,
 we sum up the results
as \cite{Reh06}, i.e., for $n=1,2,\ldots,N$, and
 $\|\partial^\theta_t\psi\|^2_s=\|\partial^\theta_tu\|^2_s
+\|\partial^\theta_tv\|^2_s$, $\theta=2$ or $\alpha$, $s=0$ or $r+1$, 
when $0<\alpha<1$, one has
\begin{align*}
\|\boldsymbol{e}^n_h\|_0
&\leq b^{-1}_{n-1}G_\alpha\max _{0\leq j\leq n}\|\boldsymbol{\gamma}^j_\tau\|_{0}\\
&\leq \frac{ n^{\alpha}\tau^\alpha\Gamma(2-\alpha)}{1-\alpha}\max _{0\leq j\leq n}\|\boldsymbol{\gamma}^j_\tau\|_{0}\\
&\leq\frac{T^\alpha\Gamma(2-\alpha)}{1-\alpha}\Big(C\tau^{2-\alpha}\max _{0\leq t\leq t_n}\|\partial^2_t\psi\|_{0}
+C h^{\tilde{r}+1}\max _{0\leq j\leq n}\|\partial^\alpha_t\psi^j\|_{r+1}\Big)\\
&\leq C(\alpha,u,v,T^\alpha)(\tau^{2-\alpha}+h^{\tilde{r}+1}),
\end{align*}
and when $\alpha$ is very close to $1$, the estimate turns into
\begin{align*}
\|\boldsymbol{e}^n_h\|_0 
&\leq n\tau\max _{0\leq j\leq n}\|\boldsymbol{\gamma}^j_\tau\|_{0}\\
&\leq Cn\tau\big(\tau\max _{0\leq t\leq t_n}\|\partial^2_t\psi\|_{0}
  +h^{\tilde{r}+1}\max _{0\leq j\leq n}\|\partial_t\psi^j\|_{r+1}\big)\\
&\leq C(u,v,T)(\tau+h^{\tilde{r}+1}).
\end{align*}
Hence, with Lemma \ref{le008} and the triangle inequality
\begin{align*}
\|\psi^n-\psi^n_h\|_0
&\leq \|\psi^n_h-\widetilde{\psi}^n\|_0+\|\psi^n-\widetilde{\psi}^n\|_0\\
&\leq\|\boldsymbol{e}^n_h\|_0+\|u^n-\widetilde{U}^n\|_0+\|v^n-\widetilde{V}^n\|_0,
\end{align*}
\eqref{e0010}, \eqref{e0012} can be established. The proof is complete.
\end{proof}


\section{Extension to two-dimensional fractional NLS}\label{NE}

In this section, we extend the derived method to the two-dimensional 
time-space-fractional NLS, which has the following form
\begin{align}\label{kkh1}
\mathrm{i}\frac{\partial^{\alpha} \psi}{\partial t^{\alpha}}
 +\frac{\partial^{2\beta} \psi}
{\partial|x|^{2\beta}}+\frac{\partial^{2\beta} \psi}{\partial|y|^{2\beta}}
+\lambda f(|\psi|^2)\psi &=0,  \quad (x,y;t) \in\Omega\times(0,T],
\end{align}
with the real factors in \eqref{eq001}-\eqref{e009} and the initial and 
boundary conditions
\begin{gather}
   \psi(x,y,0)=\varphi(x,y), \quad (x,y)\in \Omega\cup\partial\Omega, \label{kk008}\\
   \psi(x,y,t)=0,  \quad (x,y;t) \in\partial\Omega\times(0,T], \label{kk009}
\end{gather}
where $\Omega=(a,b)\times(c,d)$, 
$\frac{\partial^{\alpha} \psi}{\partial t^{\alpha}}$ is
defined as \eqref{yy02}, and Riesz derivative is defined by
\begin{gather*}
\frac{\partial^{2\beta} \psi(x,y,t)}{\partial|x|^{2\beta}}
 =\frac{-1}{2\cos(\beta \pi)}
    \big({_X}D^{2\beta}_L \psi(x,y,t)+{_X}D^{2\beta}_R \psi(x,y,t)\big),\\
{_X}D^{2\beta}_L \psi(x,y,t) = \frac{1}{\Gamma(2-{2\beta})}
\frac{\partial^2}{\partial x^2}
    \int^x_a(x-\xi)^{1-{2\beta}}\psi(\xi,y,t)d\xi, \\
{_X}D^{2\beta}_R \psi(x,y,t) = \frac{1}{\Gamma(2-{2\beta})}
\frac{\partial^2}{\partial x^2}
    \int^b_x(\xi-x)^{1-{2\beta}}\psi(\xi,y,t)d\xi.
\end{gather*}
$\frac{\partial^{2\beta}\psi}{\partial|y|^{2\beta}}$ is similar to 
$\frac{\partial^{2\beta}\psi}{\partial|x|^{2\beta}}$.
Decompose $\psi(x,y,t)$ into its real and imaginary parts by 
$\psi(x,y,t)=u(x,y,t)+iv(x,y,t)$,
whence, \eqref{kkh1} can be rewritten, i.e.,
\begin{gather*}
\frac{\partial^\alpha u}{\partial t^\alpha}
+\frac{\partial^{2\beta} v}{\partial|x|^{2\beta}}
+\frac{\partial^{2\beta} v}{\partial|y|^{2\beta}}+\lambda f(u^2+v^2)v=0,\\
\frac{\partial^\alpha v}{\partial t^\alpha}
-\frac{\partial^{2\beta}u}{\partial|x|^{2\beta}}
-\frac{\partial^{2\beta}u}{\partial|y|^{2\beta}}-\lambda f(u^2+v^2)u=0,
\end{gather*}
so are the initial and boundary values. 
Let $\Sigma_h$ be a quasi-uniform family of subdivisions of $\Omega$ and the finite
element subspace $X_h$ belong to $\mathcal{H}^\beta_0(\Omega)$, denoted as
\begin{equation*}
X_h=\{v_h\in \mathcal{H}^\beta_0(\Omega)\cap C^0(\bar{\Omega}): v_h|_D\in P_{r}(D),
 \quad \forall D\in \Sigma_h \},
\end{equation*}
where $\mathcal{H}^\beta_0(\Omega)$ is the fractional Sobolev space. 
Then, the schemes for \eqref{kkh1}-\eqref{kk009}
are constructed, which read: seek $U^n$, $V^n\in X_h$, for any $\chi_1$, 
$\chi_2\in X_h$, to satisfy
\begin{gather}
\begin{aligned}
\langle U^n, \chi_1\rangle-G_\alpha\mathbf{\Lambda}(V^n,\chi_1)
&= \sum^{n-1}_{j=1}   (b_{j-1}-b_{j})\langle U^{n-j},\chi_1\rangle
 + b_{n-1}\langle U^0,\chi_1\rangle \\
&\quad -\lambda G_\alpha
    \langle f((U^n)^2+(V^n)^2)V^{n},\chi_1\rangle,
\end{aligned} \label{s21} \\
\begin{aligned}
\langle V^n, \chi_2\rangle+G_\alpha\mathbf{\Lambda}(U^n,\chi_2) 
&=\sum^{n-1}_{j=1}    (b_{j-1}-b_{j})\langle V^{n-j},\chi_2\rangle 
+ b_{n-1}\langle V^0,\chi_2\rangle \\
 &\quad   +\lambda G_\alpha\langle f((U^n)^2+(V^n)^2)U^{n},\chi_2\rangle,
\end{aligned} \label{s22}
\end{gather}
subjected to the initial conditions
\begin{equation}\label{s26}
U^0=\operatorname{Re}\mathbf{\Pi}_h\varphi(x,y),\quad
V^0=\operatorname{Im}\mathbf{\Pi}_h\varphi(x,y),\quad
 (x,y)\in\Omega\cup\partial\Omega,
\end{equation}
and zero boundary conditions
\begin{equation}\label{s27}
  U^j = 0, \quad V^j=0, \quad 1\leq j\leq N, \quad \text{on }\partial\Omega,
\end{equation}
where $\mathbf{\Pi}_h$ is an operator like $\Pi_h$, and 
$\mathbf{\Lambda}(\cdot,\cdot)$ in \eqref{s21}-\eqref{s22} takes the form
\begin{align*}
\mathbf{\Lambda}(u,v)
&=\frac{1}{2\cos(\beta\pi)}\Big\{\langle{_X}D^{\beta}_L u,{_X}D^{\beta}_R v\rangle
    +\langle{_X}D^{\beta}_R u,{_X}D^{\beta}_L v\rangle\Big\} \\
&\quad +\frac{1}{2\cos(\beta\pi)}\Big\{\langle{_Y}D^{\beta}_L u,{_Y}
 D^{\beta}_R v\rangle
    +\langle{_Y}D^{\beta}_R u,{_Y}D^{\beta}_L v\rangle\Big\}.
\end{align*}

\begin{theorem}[\cite{Ref0017}] \label{Th7}
The bilinear form $\mathbf{\Lambda}(\cdot,\cdot)$ preserves the symmetric, 
continuous, and coercive properties, but with the  energy norm
\begin{align*}
\|u\|_{E}=\big(\|u\|^2_{0}+|({_X}D^{\beta}_L u, {_X}D^{\beta}_R u)|
    +|({_Y}D^{\beta}_L u, {_Y}D^{\beta}_R u)|\big)^{1/2}.
\end{align*}
\end{theorem}

\begin{theorem}
The method \eqref{s21}-\eqref{s27} is stable in sense that, for 
$n=1,2,\ldots,N$, there exists 
$\|U^{n}\|^2_{0}+\|V^{n}\|^2_{0}\leq \|U^{0}\|^2_{0}+\|V^{0}\|^2_{0}$.
\end{theorem}

The above theorem follows from  Theorem \ref{Th7} and the proof of Theorem \ref{Th5}.

\begin{remark}\label{re003}
\rm Solving \eqref{kkh1}-\eqref{kk009} by \eqref{s21}-\eqref{s27}, 
we confront severe challenge and computing burden; to cut the costs as 
much as possible, a feasible linearized strategy is
needed to treat the nonlinear part, where, for $n\geq2$, we employ
\begin{equation*}
f(|\psi^n|^2)\psi^n=f(|\widehat{\psi}^n|^2)\widehat{\psi}^n
    +O(\tau^2),\quad\widehat{\psi}^n=2\psi^{n-1}-\psi^{n-2}.
\end{equation*}
Decompose $\psi^n$ and inserting it into \eqref{s21}-\eqref{s27}, 
we obtain explicit-implicit schemes
\begin{gather}
\langle\mathcal{D}_{t}^\alpha U^n,\chi_1\rangle
 -\mathbf{\Lambda}(V^n,\chi_1)+\lambda\langle f((\widehat{U}^n)^2
    +(\widehat{V}^n)^2)\widehat{V}^n,\chi_1\rangle =0, \label{s24}\\
\langle\mathcal{D}_{t}^\alpha V^n,\chi_2\rangle+\mathbf{\Lambda}(U^n,\chi_2)
-\lambda\langle f((\widehat{U}^n)^2
    +(\widehat{V}^n)^2)\widehat{U}^n,\chi_2\rangle=0. \label{s25}
\end{gather}
The first step ought to be remained as itself, because available $U^1,V^1$ 
are required  to start \eqref{s24}-\eqref{s25}.
 Moreover, if the solution $\psi(x,y,t)$ to \eqref{kkh1}-\eqref{kk009}
is sufficiently regular, \eqref{s21}-\eqref{s27} and \eqref{s24}-\eqref{s25} 
maintain the optimal accuracy $O(\tau^{2-\alpha}+h^{r+1})$ in $L^2$-sense.
The convergence will be confirmed in the subsequent experiments.
\end{remark}

\section{Numerical experiments}\label{NY}

In this part, several numerical examples are performed to gauge the practical 
performance of \eqref{eh003}-\eqref{e007} and \eqref{s21}-\eqref{s27}, 
which also suffice to exhibit the accuracy of those methods. 
We use the algorithm as in \cite{Ref0099} with structured triangular meshes to
assemble the stiffness matrix  for the second method. In all the tests, 
$X_h$ is chosen to be piecewise
linear; the nonlinear system of equations is solved by iteration with 
tolerant error 1.0e-012
and the convergent orders are computed as follows
\begin{align*}
\text{C. Order}=\begin{cases}
\frac{\log\{e(\tau_1)/e(\tau_{2})\}}{\log\{\tau_1/\tau_{2}\}} &\text{in time},\\[4pt]
\frac{\log\{e(h_1)/e(h_{2})\}}{\log\{h_1/h_{2}\}} &\text{in space},
\end{cases}
\end{align*}
where $e(\tau_1)$, $e(\tau_2)$, $e(h_1)$, $e(h_2)$ are the global $L^2$-norm 
errors (abbreviated as ``L. Error'')
at stepsizes $\tau_1$, $\tau_2$, $h_1$, $h_2$, and $\tau_1\neq\tau_2$, $h_1\neq h_2$.
To obtain more insights, we discuss the convergence separately by the real and 
imaginary parts. In accord with Theorem \ref{Th6} and Remark \ref{re003}, 
$O(\tau^{2-\alpha}+h^2)$ are anticipated
in the sequel.

\begin{example} \label{examp6.1} \rm
Consider the one-dimensional Schr\"odinger type equation
\begin{equation*}
\mathrm{i}\frac{\partial^{\alpha}\psi}{\partial t^{\alpha}}
+\frac{\partial^{2\beta}\psi}{\partial|x|^{2\beta}}+|\psi|^2\psi=g(x,t),
\end{equation*}
on the interval $(0,1)$, $0<t\leq 0.5$ with the initial condition
\begin{align*}
    \psi(x,0)=10x^2(1-x)^2.
\end{align*}
The right-hand $g(x,t)$ is selected as
\begin{align*}
g(x,t)&=\mathrm{i}\frac{ 20 t^{2-\alpha}}{\Gamma(3-\alpha)}x^2(1-x)^2
  +1.0\times 10^3\cdot(1+t^2)^3x^6(1-x)^6\\
&\quad -\frac{10(1+t^2)x^{2-2\beta}}{\cos(\beta\pi)\Gamma(3-2\beta)} 
 \Big(1-\frac{6x}{3-2\beta}
    +\frac{12x^2}{(3-2\beta)(4-2\beta)}\Big) \\
&\quad -\frac{10(1+t^2)(1-x)^{2-2\beta}}{\cos(\beta\pi)\Gamma(3-2\beta)}
 \Big(1-\frac{6(1-x)}{3-2\beta}
    +\frac{12(1-x)^2}{(3-2\beta)(4-2\beta)}\Big),
\end{align*}
to enforce the exact solution 
$$
\psi(x,t)=10(1+t^2)x^2(1-x)^2.
$$
Table \ref{tab01} shows the convergent  results at $t=0.5$ in space
with $\alpha=0.3$, $\beta=0.6$, and $\tau=1.0\times10^{-5}$, whereas 
Table \ref{tab02} reports the numerical results at $t=0.5$ in time with 
$h=1.0\times10^{-3}$, where the predicted
convergent orders are observed.
\end{example}

\setlength{\abovecaptionskip}{0pt}
\setlength{\belowcaptionskip}{5pt}
\begin{table}[htb]
\small
%\footnotesize
\caption{The spatial numerical results at $t=0.5$ for Example \ref{examp6.1}.} 
\label{tab01}
\begin{tabular}{lp{2.3cm}lp{2.3cm}lll}
\hline\hline
\multicolumn{1}{l}{\multirow{2}{1.2cm}{h}}
&\multicolumn{2}{l}{Real part}
&\multicolumn{2}{l}{Imaginary part}\\
\cline{2-5}&L. Error &C. Order\ \ \ \ &L. Error &C. Order\\
\hline  1/8     &1.457861e-002  &-         &    5.242450e-003  &-  \\
        1/16    &3.809748e-003  &1.936086  &    1.309208e-003  &2.001547 \\
        1/32    &9.557528e-004  &1.994986  &    3.117938e-004  &2.070030 \\
        1/64    &2.361702e-004  &2.016811  &    7.234288e-005  &2.107669 \\
        1/128   &5.790022e-005  &2.028186  &    1.649549e-005  &2.132780 \\
\hline\hline
\end{tabular}
\end{table}


\setlength{\abovecaptionskip}{0pt}
\setlength{\belowcaptionskip}{5pt}
\begin{table}[htb]
\small
\caption{The temporal numerical results at $t=0.5$ for Example \ref{examp6.1}.} \label{tab02}
\begin{tabular}{lp{2.3cm}lp{2.3cm}lll}
\hline\hline
\multicolumn{1}{l}{\multirow{2}{1.2cm}{$\tau$}}
&\multicolumn{2}{l}{Real part}
&\multicolumn{2}{l}{Imaginary part}\\
\cline{2-5}&L. Error &C. Order\ \ \ \ &L. Error &C. Order\\
\hline  1/8     &5.088096e-004  &-         &    8.277816e-004  &-     \\
        1/16    &1.634896e-004  &1.637928  &    2.747536e-004  &1.591112     \\
        1/32    &5.253915e-005  &1.637734  &    8.933547e-005  &1.620833     \\
        1/64    &1.700971e-005  &1.627034  &    2.858752e-005  &1.643848     \\
        1/128   &5.726426e-006  &1.570652  &    8.980920e-006  &1.670450     \\
\hline\hline
\end{tabular}
\end{table}


\begin{example} \label{examp6.2} \rm
Consider the two-dimensional Schr\"odinger type  equation
\begin{equation*}
\mathrm{i}\frac{\partial^{\alpha}\psi}{\partial t^{\alpha}} 
+\frac{\partial^{2\beta}\psi} {\partial|x|^{2\beta}}
+\frac{\partial^{2\beta}\psi}{\partial|y|^{2\beta}}+|\psi|^2\psi=g(x,y,t),
\end{equation*}
on domain $(0,1)\times(0,1)$, $0<t\leq1$ with the initial condition
\begin{align*}
    \psi(x,y,0)=15\mathrm{i}x^2(1-x)^2y^2(1-y)^2,
\end{align*}
and the forcing term
\begin{align*}
g(x,y,t)&=\Big(\mathrm{i}\frac{15 t^{1-\alpha}}{\Gamma(2-\alpha)}
 -\frac{ 30 t^{1-\alpha}}{\Gamma(2-\alpha)}
    -\frac{ 30 t^{2-\alpha}}{\Gamma(3-\alpha)}\Big)x^2(1-x)^2y^2(1-y)^2\\
 &\quad + 3.375\times 10^3\cdot(t^2+(1+t)^4)(t+\mathrm{i}(1+t)^2)
 x^6(1-x)^6y^6(1-y)^6  \\
 &\quad -\frac{15(t+\mathrm{i}(1+t)^2)y^2(1-y)^2}{\cos(\beta\pi)}
 \Big(\mathcal{P}(x,\beta)+\mathcal{Q}(x,\beta)\Big)\\
 &\quad -\frac{15(t+\mathrm{i}(1+t)^2)x^2(1-x)^2}{\cos(\beta\pi)}
 \Big(\mathcal{P}(y,\beta)+\mathcal{Q}(y,\beta)\Big),
\end{align*}
where $\mathcal{P}(\cdot,\cdot)$, $\mathcal{Q}(\cdot,\cdot)$ are as follows
\begin{gather*}
\mathcal{P}(s,z)=\frac{s^{2-2z}}{\Gamma(3-2z)}
 \Big(1-\frac{6s}{3-2z}+\frac{12s^2}{(3-2z)(4-2z)}\Big),\\
\mathcal{Q}(s,z)=\frac{(1-s)^{2-2z}}{\Gamma(3-2z)}
 \Big(1-\frac{6(1-s)}{3-2z}+\frac{12(1-s)^2}{(3-2z)(4-2z)}\Big).
\end{gather*}
It is verified that the solution is
\begin{equation*}
\psi(x,y,t)=15(t+\mathrm{i}(1+t)^2)x^2(1-x)^2y^2(1-y)^2.
\end{equation*}
In this example, we reset $\alpha=0.7$, $\beta=0.9$ to test the convergent behaviors
with $\tau\approx h^{1.5385}$ in space and $h\approx\tau^{0.65}$ in time. Table \ref{tab3} and Table \ref{tab4}
elaborately demonstrate the decay of the spatial and temporal global errors as the function of stepsizes
$\tau$ and $h$, respectively, where good convergence is admitted.
\end{example}

\setlength{\abovecaptionskip}{0pt}
\setlength{\belowcaptionskip}{5pt}
\begin{table}[htb]
\small
\caption{The spatial numerical results at $t=1$ for Example \ref{examp6.2}.} \label{tab3}
\begin{tabular}{lp{2.3cm}lp{2.3cm}lll}
\hline\hline
\multicolumn{1}{l}{\multirow{2}{1.2cm}{h}}
&\multicolumn{2}{l}{Real part}
&\multicolumn{2}{l}{Imaginary part} \\
\cline{2-5}&L. Error &C. Order\ \ \ \ &L. Error &C. Order\\
\hline  1/2     &5.010280e-003  &-         &    2.344960e-002  &-     \\
        1/4     &3.663048e-003  &0.451846  &    1.574488e-002  &0.574680     \\
        1/8     &1.019908e-003  &1.844606  &    4.378051e-003  &1.846522     \\
        1/16    &2.457387e-004  &2.053242  &    1.048135e-003  &2.062464     \\
        1/24    &1.045048e-004  &2.108777  &    4.442889e-004  &2.116811     \\
\hline\hline
\end{tabular}
\end{table}


\setlength{\abovecaptionskip}{0pt}
\setlength{\belowcaptionskip}{5pt}
\begin{table}[!htb]
\small
\caption{The temporal numerical results at $t=1$ for Example \ref{examp6.2}.} \label{tab4}
\begin{tabular}{lp{2.3cm}lp{2.3cm}lll}
\hline\hline
\multicolumn{1}{l}{\multirow{2}{1.2cm}{$\tau$}}
&\multicolumn{2}{l}{Real part}
&\multicolumn{2}{l}{Imaginary part} \\
\cline{2-5}&L. Error &C. Order\ \ \ \ &L. Error &C. Order\\
\hline  1/36     &6.585969e-004  &-         &    2.820447e-003  &-     \\
        1/64     &3.263319e-004  &1.220439  &    1.392862e-003  &1.226241     \\
        1/100    &1.718398e-004  &1.437085  &    7.315002e-004  &1.443058     \\
        1/144    &9.658020e-005  &1.580145  &    4.103992e-004  &1.585021     \\
        1/196    &6.595577e-005  &1.237067  &    2.799499e-004  &1.240734     \\
\hline\hline
\end{tabular}
\end{table}


\begin{example} \label{examp6.3} \rm
The last example is devoted to examine the stability and convergent accuracy of
\eqref{s24}-\eqref{s25}.  The first step, i.e., $n=1$, does not need to be 
changed since suitable $U^1$, $V^1$ with optimal truncated errors ought 
to be contained to start this system.
To make this simpler, the model utilized in the second example is focused on. 
We present the global errors and convergent orders when $\alpha=0.6$, $\beta=0.8$ 
in space and time,
respectively, in Table \ref{tab5} and Table \ref{tab6}.  
The starting step is tackled
by a fixed-point iteration terminated by reaching a solution with error 1.0e-012.
\end{example}

\setlength{\abovecaptionskip}{0pt}
\setlength{\belowcaptionskip}{5pt}
\begin{table}[htb]
\centering
\small
\caption{The spatial numerical results at $t=1$ for Example \ref{examp6.3}.} \label{tab5}
\begin{tabular}{lp{2.3cm}lp{2.3cm}lll}
\hline\hline
\multicolumn{1}{l}{\multirow{2}{1.2cm}{h}}
&\multicolumn{2}{l}{Real part}
&\multicolumn{2}{l}{Imaginary part}\\
\cline{2-5}&L. Error &C. Order\ \ \ \ &L. Error &C. Order\\
\hline     1/2     &5.110917e-003  &-         &    2.399465e-002  &-     \\
           1/4     &3.462901e-003  &0.561601  &    1.470962e-002  &0.705953     \\
           1/8     &8.711763e-004  &1.990945  &    3.696989e-003  &1.992337     \\
           1/16    &2.003108e-004  &2.120724  &    8.469123e-004  &2.126066     \\
           1/24    &8.481370e-005  &2.119574  &    3.587811e-004  &2.118271     \\
\hline\hline
\end{tabular}
\end{table}

\setlength{\abovecaptionskip}{0pt}
\setlength{\belowcaptionskip}{5pt}
\begin{table}[htb]
\centering
\small
\caption{The temporal numerical results at $t=1$ for Example \ref{examp6.3}.} \label{tab6}
\begin{tabular}{lp{2.3cm}lp{2.3cm}lll}
\hline\hline
\multicolumn{1}{l}{\multirow{2}{1.2cm}{$\tau$}}
&\multicolumn{2}{l}{Real part}
&\multicolumn{2}{l}{Imaginary part} \\
\cline{2-5}&L. Error &C. Order\ \ \ \ &L. Error &C. Order\\
\hline      1/36     &3.750427e-004  &-         &    1.587011e-003  &-     \\
            1/64     &1.572838e-004  &1.510327  &    6.647428e-004  &1.512447     \\
            1/100    &7.842176e-005  &1.559423  &    3.317944e-004  &1.557035     \\
            1/144    &4.684757e-005  &1.412895  &    1.987468e-004  &1.405439     \\
            1/196    &2.962318e-005  &1.486669  &    1.263056e-004  &1.470402     \\
\hline\hline
\end{tabular}
\end{table}


\subsection*{Conclusion}
In the present research, we have investigated the finite element approximation 
to the Caputo-Riesz time-space-fractional NLS in one- and two-di\-mensions. 
The stability is conducted and the convergent estimate is analyzed. 
To avoid the iterative loop, we sequentially construct a linearized scheme,
 which is validated to be stable and convergent. A series of
computed tests are implemented and  the numerical results are showed to 
be in agreement with the theoretical assertion.



\subsection*{Acknowledgements}
This research was supported by National Natural Science Foundations of 
China (No.11471262 and 11501450).


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