\documentclass[reqno]{amsart}
\usepackage{hyperref}

\AtBeginDocument{{\noindent\small
\emph{Electronic Journal of Differential Equations},
Vol. 2017 (2017), No. 02, pp. 1--10.\newline
ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu}
\thanks{\copyright 2017 Texas State University.}
\vspace{8mm}}

\begin{document}
\title[\hfilneg EJDE-2017/02\hfil Positive almost periodic solutions]
{Positive almost periodic solutions to integral equations with
superlinear perturbations via a new fixed point theorem in cones}

\author[J.-Y. Zhao, H.-S. Ding,  G. M. N'Gu\'er\'ekata \hfil EJDE-2017/02\hfilneg]
{Jing-Yun Zhao, Hui-Sheng Ding,  Gaston M. N'Gu\'er\'ekata}

\address{Jing-Yun Zhao \newline
College of Mathematics and Information Science,
Jiangxi Normal University,
Nanchang, Jiangxi 330022, china}
\email{1475551804@qq.com}

\address{Hui-Sheng Ding (corresponding author)\newline
College of Mathematics and Information Science,
Jiangxi Normal University,
Nanchang, Jiangxi 330022, china}
\email{dinghs@mail.ustc.edu.cn}

\address{ Gaston M. N'Gu\'er\'ekata \newline
Department of Mathematics,
Morgan State University,
1700 E. Cold Spring Lane,
Baltimore, MD 21251, USA}
\email{Gaston.N'Guerekata@morgan.edu, nguerekata@aol.com}

\thanks{Submitted June 7, 2016. Published January 4, 2017.}
\subjclass[2010]{45G10, 34K14}
\keywords{Almost periodic; delay integral equation; positive solution;
\hfill\break\indent superlinear perturbation}

\begin{abstract}
 In this article, we  establish a new fixed point theorem for nonlinear
 operators with superlinear perturbations in partially ordered Banach spaces,
 Then we use the fixed point theorem to prove the existence of positive
 almost periodic solutions to some integral equations with superlinear
 perturbations. Also, a concrete example is given to illustrate our results.

\end{abstract}

\maketitle
\numberwithin{equation}{section}
\newtheorem{theorem}{Theorem}[section]
\newtheorem{lemma}[theorem]{Lemma}
\newtheorem{definition}[theorem]{Definition}
\newtheorem{example}[theorem]{Example}
\allowdisplaybreaks

\section{Introduction}

Cooke and Kaplan \cite{cooke} initiated the study on the nonlinear delay
integral equation
\begin{equation}\label{1.1}
x(t)=\int_{t-\tau}^{t}f(s, x(s))ds,
\end{equation}
which is a model for the spread of some infectious diseases.
Afterwards, Fink and Gatica \cite{fink} firstly studied the existence of
positive almost periodic solution to equation \eqref{1.1}. Since the work
of Fink and Gatica, there has been of great interest for many mathematicians
to study the existence of positive almost periodic type solutions to \eqref{1.1}.
There is a large body of literature on this topic
(see, e.g., \cite{dad1997,dad2000,dad2008,dad2009,dad2015,ding2011,ezzinbi,long,
torre,ding2016} and references therein).

Among the above references on almost periodic type solutions to  \eqref{1.1},
there are several interesting works on generalized variants of equation \eqref{1.1}.
For example, Ait Dads and Ezzinbi \cite{dad1997} considered the
 neutral integral equation
\begin{equation}\label{1.2}
x(t)=\gamma x(t-\tau)+(1-\gamma)\int_{t-\tau}^{t}f(s, x(s))ds,
\end{equation}
Ait Dads and Ezzinbi \cite{dad2000} studied the  infinite delay integral equation
\begin{equation}\label{1.3}
x(t)=\int_{-\infty}^{t}a(t-s)f(s, x(s))ds,
\end{equation}
and Ait Dads et al \cite{dad2009} generalized equation \eqref{1.3}, i.e.,
they discussed the more general infinite delay integral equation
\begin{equation}\label{1.4}
x(t)=\int_{-\infty}^{t}a(t, t-s)f(s, x(s))ds.
\end{equation}
In fact,  \eqref{1.1} is also a special case of equation \eqref{1.4}.
This is so because  if
$$
a(t,s)=\begin{cases}
 1 & s\in [0,\tau],\; t\in\mathbb{R},\\
0 & s>\tau,\; t\in\mathbb{R},
\end{cases}
$$
then \eqref{1.4} becomes \eqref{1.1}.

Motivated by the ideas in \cite{dad1997} and \cite{dad2009}, Ding, Chen,
and N'Gu\'{e}r\'{e}kata \cite{ding2011} studied the  integral equation
\begin{equation}\label{1.5}
x(t)=\alpha(t)x(t-\beta)+\int_{-\infty}^{t}a(t, t-s)f(s, x(s))ds+h(t, x(t)),
\end{equation}
which unifies  \eqref{1.1}-\eqref{1.4}. Recently, Bellour and Ait Dads
\cite{dad2015} studied the  nonlinear integro-differential equation with neutral
delay
\begin{equation}\label{eq3-1}
x(t)=\gamma x(t-\sigma(t))+(1-\gamma)\int^{t}_{t-\sigma(t)}f(s,x(s),x'(s))ds.
\end{equation}
As noted in \cite{dad2009} and \cite{dad2015}, the above variants of  \eqref{1.1}
include many important integral and functional equations that arise in
 biomathematics.

Very recently,  the authors of this paper \cite{ding2016} studied the
existence of $S$-asymptotically periodic solutions for the  delay
integral equation with superlinear perturbations
\begin{equation}\label{ding2016-eq}
x(t)=\alpha(t)x^n(t-\beta)+\int^t_{t-\tau(t)}f(s,x(s))ds,
\end{equation}
where $n\geq 1$. We aim is to make further study on this direction,
i.e., we aim to investigate the existence of positive almost periodic solution
to the  integral equations with superlinear perturbations,
\begin{equation}\label{1.6}
x(t)=\alpha(t)x^n(t-\beta)+\int_{-\infty}^{t}a(t, t-s)f(s, x(s))ds+h(t, x(t)),
\end{equation}
where $n\geq 1$. We will use a different method from \cite{ding2016}.
In fact, we will first establish a new fixed point theorem for nonlinear
operators with superlinear perturbations in partially ordered Banach spaces,
and then apply the obtained fixed point theorem to equation \eqref{1.6}.


\section{Preliminaries}

Throughout the rest of this paper, we denote by $\mathbb{N}$ the set of positive
integers, by $\mathbb{R}$ the set of all real numbers, by $\mathbb{R^+}$ the
set of nonnegative real numbers, by $X$ a real Banach space with the norm
$\|\cdot\|$, by $\Omega$ a subset of $X$, by $L^{1}(\mathbb{R^+})$ the
set of all Lebesgue measurable functions $f:\mathbb{R}\to \mathbb{R}^+$ with
$\int_{\mathbb{R}} |f(t)| dt<+\infty$ and denote
 $$
\|f\|_{L^1(\mathbb{R^+})}=\int_{\mathbb{R}} |f(t)| dt.
$$
 Next, let us recall some definitions, notation and basic results about
almost periodic functions. For more details, we refer the reader
to \cite{fink-book,zhang-book}.

\begin{definition}\label{2.1} \rm
A continuous function $f:\mathbb{R} \to X$  is called almost periodic if
for every $\varepsilon >0$ there exists $ l(\varepsilon)>0$ such that every
interval $I$ of length $l(\varepsilon)$ contains a number $\tau$ with the
property that
$$
\sup_{t\in\mathbb{R}}\|f(t+\tau)-f(t)\|<\varepsilon.
$$
We denote by $AP(X)$ the set of all such functions.
\end{definition}

\begin{definition}\label{2.2} \rm
A continuous function $f:\mathbb{R} \times \Omega \to X$ is called almost
periodic in $t$ uniformly for $ x \in\Omega $ if for every $\varepsilon >0$
and for every compact subset $ K \subset \Omega$ there exists
$ l(\varepsilon,K)>0$ such that every interval $I$ of length
$l(\varepsilon,K)$ contains a number $\tau$ with the property that
$$
\sup_{t\in\mathbb{R},x\in K}\|f(t+\tau, x)-f(t, x)\|<\varepsilon.
$$
We denote by $AP(\mathbb{R}\times\Omega, X)$ the set of all such functions.
\end{definition}


\begin{lemma}[\cite{zhang-book}] \label{ap-basic}
The following assertions hold:
\begin{itemize}
\item[(a)] AP($X$) is a Banach space equipped with the supremum norm.

\item[(b)] $f,g\in AP(\mathbb{R})$ implies that $f\cdot g\in AP(\mathbb{R})$ .

\item[(c)] $f\in AP(X)$ implies that $f(\cdot -c)\in AP(X)$ for every
$c\in \mathbb{R}$.
\end{itemize}
\end{lemma}


\begin{lemma}[\cite{zhang-book}] \label{ap-compostion}
Let $f\in AP(\mathbb{R}\times\Omega, X)$, $g\in AP(X)$ and
$\overline{g(\mathbb{R})}\subset \Omega$. Then $f(\cdot,g(\cdot))\in AP(X)$.
\end{lemma}

\begin{lemma}[\cite{dad2009}] \label{ap-integral}
Let $f\in AP(\mathbb{R})$ and $a:\mathbb{R}\times\mathbb {R^+}\to \mathbb{R^+}$
satisfying $t\mapsto a(t, \cdot)$ being in $AP(L^{1}(\mathbb {R^+}))$.
Then, $F\in AP(\mathbb{R})$, where $F(t)=\int_{-\infty}^{t}\:a(t, t-s)f(s)ds$
for all $t\in\mathbb{R}$.
\end{lemma}

We also need to recall some basic notation about cones (for more details,
 we refer the reader to \cite{deimling-book}).
Let $X$ be a real Banach space, and $\theta$ be the zero element in $X$.
A closed and convex set $K$ in $X$ is called a cone if the following two
conditions are satisfied:
\begin{itemize}
\item[(i)] if $x\in K$, then $\lambda x\in K$ for every $\lambda\geq0$;

\item[(ii)] if $x\in K$ and $-x\in K$, then $x=\theta$.
\end{itemize}
A cone $K$ induces a partial ordering $\leq$ in $X$ by
$$
x\leq y \quad \text{if and only if} \quad y-x\in K.
$$
For any given $u,v\in K$ with $u\leq v$,
$$
[u,v]:=\{x\in X|u\leq x\leq v\}.
$$
A cone $K$ is called normal if there exists a constant $k>0$ such that
$$
\theta\leq x\leq y \quad\text{implies}\quad \|x\|\leq k\|y\|.
$$
We denote by $ K^o $ the interior of $K$. A cone $K$ is called a solid cone if $K^o\not =\emptyset$.

An operator $T: K \to K $ is called increasing if
$\theta\leq x\leq y$ implies $Tx\leq Ty$, and is called decreasing
if $\theta\leq x\leq y$ implies $Tx\geq Ty$.


\section{Main results}

The following theorem is a generalization of \cite[Theorem 3.1]{ding2011}
and \cite[Theorem 2.1]{ding-fp}. As one will see, although the organization
of the proof is more or less similar to that of \cite[Theorem 3.1]{ding2011},
the proof is more tricky and more delicate.

\begin{theorem}\label{important theorem}
Let $n\geq 1$ be a constant, $K$ be a normal solid cone in a real Banach
space $X$, and $A$ be an operator defined on $K\times K\times K$ by
$$
A(x, y, z)=B(x, y, z)+D(x),\quad x,y,z\in K,
$$
where $B:K\times K\times K\to K$ and $D:K\to K$.
Assume that the following conditions hold:
\begin{itemize}
\item[(H1)] For every $x,y,z\in K^o$, $B(\cdot, y, z)$ is increasing in
$K^o$, $B(x, \cdot, z)$ is decreasing in $K^o$, and $B(x, y, \cdot)$ is
decreasing in $K^o$. Moreover, $D:K^o\to K^o$ is an increasing operator
and $D(tx)=t^n D(x)$ for every $x\in K^o$ and $t>0$.

\item[(H2)] There exist $x_0,y_0\in K^o$ with $x_0\leq y_0$, $A(x_0, y_0,
 x_0)\geq x_0$ and $A(y_0, x_0, y_0)\leq y_0$.

\item[(H3)] For every $x,y,z\in [t_0x_0,t_0^{-1}y_0]$, $B(x,y,z)\in K^o$, where
$t_0=\sup\{t>0: x_0\geq t y_0\}$.

\item[(H4)]  There exists a function $\varphi:(0, 1)\times K^o\times K^o
\to(0, +\infty)$ such that for every $t\in(0, 1)$ and $x,y,z\in[t_0x_0,t_0^{-1}y_0]$,
$$
B(tx, t^{-1}y, z)\geq\varphi(t, x, y)B(x, y, z) \quad \text{and} \quad
\varphi(t, x, y)> \varepsilon_{t_0}(t-t^n)+t,
$$
where $\varepsilon_{\lambda}=\inf\{t>0 : D(\lambda^{-1}y_0)\leq
t B(\lambda x_0, \lambda ^{-1}y_0, \lambda ^{-1}y_0)\}$
for every $\lambda \in[t_0, 1]$.
Moreover, it holds
 \begin{equation}\label{infinimum}
\inf_{x, y \in[x_0, y_0]}\varphi(t, x, y)> \varepsilon_{t_0}(t-t^n)+t,
\quad t\in(0, 1).
\end{equation}

\item[(H5)] There exists a constant $L>0$ such that for all $x,y,z_{1},z_{2}\in K^o$
with $z_{1}\geq z_{2}$,
\begin{equation}\label{Lipschitz}
B(x, y, z_{1})-B(x, y, z_{2})\geq-L(z_{1}-z_{2}).
\end{equation}
\end{itemize}
Then $A$ has a unique fixed point $x^*$ in $[x_0, y_0]$, i.e.,
$A(x^*, x^*, x^*)=x^*$.
\end{theorem}

\begin{proof}
It is easy to see that for every $x,y,z\in K^o$, $A(\cdot, y, z)$
is increasing in $K^o$, $A(x, \cdot, z)$ is decreasing in $K^o$, and
$A(x, y, \cdot)$ is decreasing in $K^o$. Note that
$$
\varepsilon_{\lambda}=\inf\{t>0 : D(\lambda^{-1}y_0)
\leq t B(\lambda x_0, \lambda ^{-1}y_0, \lambda ^{-1}y_0)\},\quad
\lambda \in[t_0, 1],
$$
it is easy to see that
$$
D(\lambda^{-1}y_0)\leq \varepsilon_{\lambda}B(\lambda x_0,
\lambda ^{-1}y_0, \lambda ^{-1}y_0).
$$
Then, for every $x,y,z\in[\lambda x_0, \lambda^{-1}y_0]$, we have
$$
D(x)\leq D(\lambda^{-1}y_0)\leq \varepsilon_{\lambda}B(\lambda x_0,
\lambda ^{-1}y_0, \lambda ^{-1}y_0)\leq \varepsilon_{\lambda}B(x, y, z),
$$
Thus, it holds
 $$
A(x,y,z)\leq (1+\varepsilon_{\lambda})B(x, y, z)
$$
i.e.,
$$
B(x, y, z)\geq \frac{1}{1+\varepsilon_{\lambda}}A(x,y,z),\quad
\lambda \in[t_0, 1],\; x,y,z\in[\lambda x_0, \lambda^{-1}y_0].
$$
In addition, it follows from the definition of $\varepsilon_{\lambda}$
that $\varepsilon_{\lambda}$ is decreasing in $\lambda$.
We divide the remaining proof by three steps.
\smallskip

\noindent\textbf{Step 1.}
 In view of the above observations and (H4), for every $\lambda \in[t_0, 1]$,
$x,y,z\in[\lambda x_0, \lambda^{-1}y_0]$ and $t\in(0, 1)$, we have
\begin{equation}\label{use for step5}
\begin{aligned}
A(tx, t^{-1}y, z) &=  B(tx, t^{-1}y, z)+D(tx) \\
&\geq  \varphi(t, x, y)B(x, y, z)+t^nD(x) \\
&= t A(x, y, z)+[\varphi(t, x, y)-t]B(x, y, z)+(t^n-t)D(x) \\
&\geq  t A(x, y, z)+[\varphi(t, x, y)-t]B(x, y, z)
 -\varepsilon_{\lambda}(t-t^n)B(x, y, z) \\
&= t A(x, y, z)+\left[\varphi(t, x, y)-t-\varepsilon_{\lambda}(t-t^n)
 \right]B(x, y, z) \\
&\geq  t A(x, y, z)+\frac{\varphi(t, x, y)-t
 -\varepsilon_{\lambda}(t-t^n)}{1+\varepsilon_{\lambda}}A(x, y, z) \\
&= \phi_{\lambda}(t, x, y)A(x, y, z),
\end{aligned}
\end{equation}
where for every $\lambda \in[t_0, 1]$, $\phi_{\lambda}$ is defined by
$$
\phi_{\lambda}(t, x, y)=t+\frac{\varphi(t, x, y)-t
-\varepsilon_{\lambda}(t-t^n)}{1+\varepsilon_{\lambda}},
\quad t\in(0, 1),\ x,y\in[\lambda x_0, \lambda^{-1}y_0].
$$
By (H4), for every $\lambda \in[t_0, 1]$,
$x,y\in[\lambda x_0, \lambda^{-1}y_0]$ and $t\in(0, 1)$, it holds
$$
\varphi(t, x, y)> \varepsilon_{t_0}(t-t^n)
+t\geq \varepsilon_{\lambda}(t-t^n)+t,
$$
which means that
\begin{equation}\label{great than t}
\phi_{\lambda}(t, x, y)>t.
\end{equation}
Moreover, by \eqref{infinimum},
\begin{equation}\label{key}
\inf_{x, y\in[x_0, y_0]}\phi_{1}(t, x, y)>t, \quad t\in(0, 1).
\end{equation}
\smallskip

\noindent\textbf{Step 2.} By using (H5) and a similar proof to
\cite[Theorem 2.1]{ding-fp}, one can show that for every
$x,y\in [t_0x_0, t_0^{-1}y_0]$, there exists a unique point in
$[t_0x_0, t_0^{-1}y_0]$, which we denote by $\Psi(x,y)$, such that
$$
A(x,y,\Psi(x,y))=\Psi(x,y).
$$
Also, $\Psi(\cdot, y)$ is increasing, and $\Psi(x, \cdot)$ is decreasing.
Moreover, for every $\lambda \in[t_0, 1]$ and $x,y\in
[\lambda x_0,\lambda^{-1}y_0]$, it holds
$$
\Psi(x,y)\in [\lambda x_0,\lambda^{-1}y_0].
$$
Then, combining \eqref{use for step5} with the fact that $A$ is decreasing
for the third argument, for every $\lambda\in(t_0, 1]$, it holds
\begin{equation}\label{step5}
\begin{aligned}
\Psi(tx, t^{-1}y)
&= A(tx, t^{-1}y, \Psi(tx, t^{-1}y)) \\
&\geq  A(tx, t^{-1}y, \Psi(x, y)) \\
&\geq  \phi_{\lambda}(t, x, y)A(x, y, \Psi(x, y)) \\
&=  \phi_{\lambda}(t, x, y)\Psi(x, y),
\end{aligned}
\end{equation}
for all $t\in[\frac{t_0}{\lambda}, 1)$ and
$x,y\in [\lambda x_0, \lambda^{-1}y_0]$. Moreover, denoting
$\phi_{t_0}(1, x, y)=1$, \eqref{step5} holds for $\lambda\in[t_0, 1]$,
$t\in[\frac{t_0}{\lambda}, 1]$ and $x,y\in [\lambda x_0, \lambda^{-1}y_0]$.
\smallskip

\noindent\textbf{Step 3.}
 Let $u_0=x_0$, $v_0=y_0$ and
$$
u_n=\Psi(u_{n-1}, v_{n-1}),\; v_n=\Psi(v_{n-1}, u_{n-1}),\; n\in\mathbb{N}.
$$
It follows from Step 2 that
\[ %\label{3.8}
u_0\leq u_{1}\leq\dots\leq u_n\leq\dots\leq v_n\leq\dots\leq v_{1}\leq v_0.
\]
Let $t_n=\sup\{t>0:u_n\geq tv_n\},\; n\in\mathbb{N}$. Then,
$u_n\geq t_nv_n,\; n\in\mathbb{N}$, and
$$
0<t_0\leq t_{1}\leq\dots\leq t_n\leq\dots\leq1.
$$
Let $\xi=\lim_{n\to\infty} t_n$. Next, we prove $\xi=1$ by contradiction,
i.e., we assume that $\xi\in (0,1)$. Noting that $\xi\geq t_0$,
$\xi v_n,\frac{u_n}{\xi}\in[\xi x_0, \xi^{-1}y_0]$ and
$\frac{t_n}{\xi}\in [\frac{t_0}{\xi},1]$, by using \eqref{step5}, we obtain
\begin{align*}
u_{n+1}
&=  \Psi(u_n, v_n)\\
&\geq  \Psi(t_nv_n, t_n^{-1}u_n)\\
&\geq  \Psi\big(\frac{t_n}{\xi}\cdot\xi v_n, \frac{\xi}{t_n}\cdot
 \frac{u_n}{\xi}\big)\\
&\geq  \phi_{\xi}\big(\frac{t_n}{\xi}, \xi v_n, \frac{u_n}{\xi}\big)
 \Psi\big(\xi v_n, \frac{u_n}{\xi}\big)\\
&\geq  \frac{t_n}{\xi}\Psi\big(\xi v_n, \frac{u_n}{\xi}\big).
\end{align*}
Again by using \eqref{step5}, we have
\[
\Psi(\xi v_n, \xi^{-1}u_n)
\geq \phi_{1}(\xi, v_n, u_n)\Psi(v_n, u_n)
= \phi_{1}(\xi, v_n, u_n)v_{n+1}.
\]
Then, we have $u_{n+1}\geq \frac{t_n}{\xi}\phi_{1}(\xi, v_n, u_n)v_{n+1}$, and thus
$$
t_{n+1}\geq \frac{\phi_{1}(\xi, v_n, u_n)}{\xi} t_n
\geq \frac{\inf_{x, y\in[x_0, y_0]}\phi_{1}(\xi, x, y)}{\xi} t_n,
$$
which contradicts with $\lim_{n\to\infty} t_n=\xi$ since
 $\frac{\inf_{x, y\in[x_0, y_0]}\phi_{1}(\xi, x, y)}{\xi}>1$ by \eqref{key}.

In view of
$$
0\leq u_{n+p}-u_n\leq v_n-u_n\leq v_n-t_nv_n\leq(1-t_n)v_0,\quad n,p\in\mathbb{N},
$$
we conclude that $u_n$ is convergent in $X$, and we denote
$\lim_{n\to\infty}u_n=x^{*}$. In addition, noting that $u_n\leq x^*$ for all
$n\in\mathbb{N}$, we have
$$
0\leq v_n-x^*\leq v_n-u_n\leq(1-t_n)v_0,\quad n\in\mathbb{N},
$$
which means that $\lim_{n\to\infty}v_n=x^{*}$. Moreover, by the monotonicity
of $\Psi$, it is not difficult to show that $\Psi(x^{*}, x^{*})=x^{*}$,
and $x^{*}$ is a unique fixed point of $\Psi$ in $[x_0, y_0]$.


Combining Step 2 and Step 3, one obtains
$$
x^{*}=\Psi(x^{*}, x^{*})=A(x^{*}, x^{*}, \Psi(x^{*}, x^{*}))=A(x^{*}, x^{*}, x^{*}).
$$
Also, $x^{*}$ is the unique fixed point of $A$ in $[x_0, y_0]$.
\end{proof}

Now, we are ready to establish our existence result for equation \eqref{1.6}, i.e.,
$$
x(t)=\alpha(t) x^n(t-\beta))+\int_{-\infty}^{t} a(t, t-s)f(s, x(s))ds
+h(t, x(t)),\quad t\in\mathbb{R}.
$$
For convenience, we denote by $AP(\mathbb{R}\times\mathbb {R^+}, \mathbb{R^+})$
the set of all nonnegative functions in
$ AP(\mathbb{R}\times\mathbb{R^+},\mathbb{R})$.

\begin{theorem}\label{th-ie}
Assume that the function $f$ in \eqref{1.6} admits the decomposition:
$$
f(t, x)=\sum_{i=1}^{p}f_i(t, x)g_i(t, x),\quad t\in\mathbb{R},\; x\in\mathbb{R^+}
$$
for some $p\in\mathbb{N}$. Moreover, the following conditions hold:
\begin{itemize}
\item[(H6)] $\alpha\in AP(\mathbb{R})$ with positive infimum.
$f_i,\;g_i,\;h\in AP(\mathbb{R}\times\mathbb {R^+}, \mathbb{R^+})$
$(i=1, 2,\dots, p)$ satisfy that for every $t\in\mathbb{R}$ and
$i\in\{1, 2,\dots, p\}$, $f_i(t,\cdot)$ is increasing in
$\mathbb {R^+}$, $g_i(t, \cdot)$ is decreasing in $\mathbb {R^+}$, and
$h(t, \cdot)$ is decreasing in $\mathbb {R^+}$. In addition, there exists
 a constant $L>0$ such that
$$
h(t, z_{1})-h(t, z_{2})\geq-L(z_{1}-z_{2}),\quad \forall t\in\mathbb {R},\;
\forall z_{1}\geq z_{2}\geq0.
$$

\item[(H7)] $a$ is a function from $\mathbb{R}\times\mathbb {R^+}$ to
$\mathbb{R^+}$ and the function $t\mapsto a(t, \cdot)$ is in
$AP(L^{1}(\mathbb {R^+}))$.

\item[(H8)] There exist two constants $d_0> c_0>0$ such that
\begin{gather*}
\inf_{t\in\mathbb{R}}\int_{-\infty}^{t}a(t, t-s)\sum_{i=1}^{p}f_i(s, c_0)
g_i(s, d_0)ds\geq c_0, \\
\|\alpha\| d_0^n+\sup_{t\in\mathbb{R}}
\Big[\int_{-\infty}^{t} a(t, t-s)\sum_{i=1}^{p}f_i(s, d_0)g_i
(s,c_0)ds+h(t, d_0)\Big]\leq d_0.
\end{gather*}

\item[(H9)] There exist $\varphi_i, \; \psi_i:(0, 1)\times(0,+\infty)\to(0, 1]$
such that
$$
f_i(t, \lambda x)\geq\varphi_i(\lambda, x)f_i(t, x),\quad \text{and}\quad
g_i(t, \lambda^{-1}y)\geq\psi_i(\lambda, y)g_i(t, y),
$$
for all $x,y>0$, $\lambda\in(0, 1)$, $t\in\mathbb{R}$ and
$i\in\{1,2,\dots,p\}$. Moreover,
$$
\inf_{x, y\in [\frac{c_0^2}{d_0},\frac{d_0^2}{c_0}]}
\varphi_i(\lambda, x)\psi_i(\lambda, y)>\gamma(\lambda-\lambda^n)+\lambda,
\quad \lambda\in (0,1),\ i=1,2,\ldots,p,
$$
where
$$
\gamma=\frac{\|\alpha\|(\frac{d_0^{2}}{c_0})^n}
{\inf_{t\in\mathbb{R}}\big[\int_{-\infty}^{t} a(t, t-s)\sum_{i=1}^{p}f_i
\big(s, \frac{c_0^{2}}{d_0}\big)g_i\big(s, \frac{d_0^{2}}{c_0}\big)ds
+h\big(t, \frac{d_0^{2}}{c_0}\big)\big]}.
$$
\end{itemize}
Then \eqref{1.6} has an almost periodic solution with positive infinimum.
\end{theorem}

\begin{proof}
Let $K=\{x\in AP(\mathbb{R}):\inf_{t\in\mathbb{R}}x(t)\geq 0\}$. 
It is easy to verify that $K$ is a normal and solid cone in $AP(\mathbb{R})$, and
$K^{o}=\{x\in AP(\mathbb{R}):\inf_{t\in\mathbb{R}}x(t)>0\}$. 
For  $x,y,z\in K^{o}$ and $t\in\mathbb{R}$, define
$D(x)(t)=\alpha(t)x^n(t-\beta)$, 
\[
B(x, y, z)(t)
=\int_{-\infty}^{t}a(t, t-s)\sum_{i=1}^{p}f_i(s, x(s))g_i(s, y(s))ds+h(t, z(t)),
\] 
and $A(x, y, z)=B(x, y, z)+D(x)$.

Next, we verify all the assumptions of Theorem \ref{important theorem}. 
By (H6), (H7), Lemmas \ref{ap-basic}--\ref{ap-integral}, it is not difficult
to show that $B$ is an operator from $K\times K\times K$ to $K$ and $D$ 
is an operator from $K$ to $K$. Also, it follows directly from (H6) that 
assumptions (H1) and (H5)  hold. 
In addition, taking $x_0(t)\equiv c_0$ and $y_0(t)\equiv d_0$, assumption 
(H2) follows from (H8).

Let us verify (H3). It is easy to see $t_0=\frac{c_0}{d_0}$. 
For every $x,y,z\in [t_0 x_0,t_0^{-1}y_0]$, we have
\begin{align*}
B(x,y,z)(t)
&\geq \int_{-\infty}^{t}a(t, t-s)\sum_{i=1}^{p}f_i(s, t_0 x_0)g_i(s, t_0^{-1}y_0)ds\\
&=   \int_{-\infty}^{t}a(t, t-s)\sum_{i=1}^{p}f_i(s, t_0 c_0)g_i(s, t_0^{-1}d_0)ds\\
&\geq   \int_{-\infty}^{t}a(t, t-s)\sum_{i=1}^{p}\varphi_i(t_0,c_0)\psi_i(t_0,d_0)f_i(s,  c_0)g_i(s,d_0)ds\\
&\geq   t_0\int_{-\infty}^{t}a(t, t-s)\sum_{i=1}^{p}f_i(s,  c_0)g_i(s,d_0)ds\\
&\geq  t_0c_0>0,\quad t\in\mathbb{R},
\end{align*}
which means that $B(x,y,z)\in K^o$. Thus,  assumption (H3) holds.

It remains to show that (H4) holds. For  $x,y\in K^{o}$, we denote
$$
(x, y)^-=\min\{\inf_{t\in\mathbb{R}}x(t), \inf_{t\in\mathbb{R}}y(t)\},\quad 
(x, y)^+=\max\{\sup_{t\in\mathbb{R}}x(t),\sup_{t\in\mathbb{R}}y(t)\}. 
$$
Then, by (H9), for all $x,y>0$, $\lambda\in(0, 1)$, $t\in\mathbb{R}$ and 
$i\in\{1,2,\dots,p\}$,
$$
f_i(t, \lambda x)\geq\varphi_i(\lambda, x)f_i(t, x),\quad \text{and}\quad 
g_i(t, \lambda^{-1}y)\geq\psi_i(\lambda, y)g_i(t, y),
$$
which yields that for every $t\in\mathbb{R}$, $\lambda\in (0,1)$ and $x,y,z\in K^o$,
\begin{align*}
B(\lambda x, \lambda^{-1}y, z)(t)
&=  \int_{-\infty}^{t}a(t, t-s)\sum_{i=1}^{p}f_i(s, \lambda x(s))
g_i(s, \lambda^{-1}y(s))ds+h(t, z(t))\\
&\geq  \phi(\lambda, x, y)B(x, y, z)(t),
\end{align*}
where
$$
\phi(\lambda, x, y):=\min_{1\leq i\leq p}
\Big(\inf_{u, v\in[(x, y)^-, (x, y)^+]}\varphi_i(\lambda, u)\psi_i(\lambda, v)\Big).
$$
By the definition of $\gamma$, for every $t\in\mathbb{R}$, we have
\begin{align*}
D(t_0^{-1}y_0)(t)
&=  D\Big(\frac{d_0^2}{c_0}\Big)(t)\\
&\leq \|\alpha\|\Big(\frac{d_0^{2}}{c_0}\Big)^n\\
&\leq  \gamma\inf_{t\in\mathbb{R}}\Big[\int_{-\infty}^{t} a(t, t-s)
\sum_{i=1}^{p}f_i\Big(s, \frac{c_0^{2}}{d_0}\Big)g_i
\Big(s, \frac{d_0^{2}}{c_0}\Big)ds+h\Big(t, \frac{d_0^{2}}{c_0}\Big)\Big]\\
&\leq   \gamma B\Big(\frac{c_0^2}{d_0},\frac{d_0^2}{c_0},\frac{d_0^2}{c_0}\Big)(t)
=\gamma B(t_0x_0,t_0^{-1}y_0,t_0^{-1} y_0)(t),
\end{align*}
which means that $\gamma\geq \varepsilon_{t_0}$. Then, by (H9),
 for every $\lambda\in (0,1)$ and 
$x,y\in [t_0x_0,t_0^{-1}y_0]=[\frac{c_0^2}{d_0},\frac{d_0^2}{c_0}]$, it holds
\begin{align*}
\phi(\lambda, x, y)
&= \min_{1\leq i\leq p}
 \Big(\inf_{u, v\in[(x, y)^-, (x, y)^+]}\varphi_i(\lambda, u)\psi_i(\lambda, v)\Big)\\
&\geq  \min_{1\leq i\leq p}\Big(\inf_{u, v\in[\frac{c_0^2}{d_0},
\frac{d_0^2}{c_0}]}\varphi_i(\lambda, u)\psi_i(\lambda, v)\Big)\\
&> \gamma(\lambda-\lambda^n)+\lambda\\
&\geq  \varepsilon_{t_0}(\lambda-\lambda^n)+\lambda.
\end{align*}
Similarly, one can show that
$$
\inf_{x,y\in [x_0,y_0]}\phi(\lambda, x, y)>\varepsilon_{t_0}(\lambda-\lambda^n)
+\lambda,\quad \lambda\in (0,1).
$$
Thus, (H4) holds.

Now, Theorem \ref{important theorem} gives that $A$ has a unique fixed point 
in $[c_0, d_0]$, and thus \eqref{1.6} has an almost periodic solution with
 positive infinimum.
\end{proof}


Next, we give a simple example to show that our assumptions on  \eqref{1.6} 
can be satisfied.

\begin{example}\rm
Let $\alpha(t)\equiv 1/20$, $n=4/3$, $\beta=1$, $a(t,s)=\exp(-s^2)$, 
$p=1$,
$$
f_1(t,x)=(1+\frac{|\sin t+\sin \pi t|}{{30}})\sqrt[3]{x^2+x},\quad 
g_1(t,x)\equiv 1,\quad
h(t,x)=\frac{\sin^2 t+\sin^2 \sqrt{2}t}{20(1+x)}.
$$
It is easy to see that (H6) and (H7) hold. Let $c_0=1$ and $d_0=2$. We have
$$
\inf_{t\in\mathbb{R}}\int_{-\infty}^{t}a(t, t-s)\sum_{i=1}^{p}
f_i(s, c_0)g_i(s, d_0)ds\geq \frac{\sqrt{\pi}}{2} \sqrt[3]{2}\geq 1=c_0,
$$
and
\begin{align*}
&\|\alpha\| d_0^n+\sup_{t\in\mathbb{R}}\Big[\int_{-\infty}^{t} a(t, t-s)
 \sum_{i=1}^{p}f_i(s, d_0)g_i(s,c_0)ds+h(t, d_0)\Big] \\
&\leq \frac{2^{4/3}}{20} + \frac{1+16\sqrt{\pi}\sqrt[3]{6}}{30}\leq 2=d_0,
\end{align*}
which means that (H8) holds. Moreover, noting that
\begin{align*}
\gamma
&= \frac{\|\alpha\|\big(\frac{d_0^{2}}{c_0}\big)^n}
{\inf_{t\in\mathbb{R}}\big[\int_{-\infty}^{t} a(t, t-s)\sum_{i=1}^{p}f_i
\big(s, \frac{c_0^{2}}{d_0}\big)g_i\big(s, \frac{d_0^{2}}{c_0}\big)ds
+h\big(t, \frac{d_0^{2}}{c_0}\big)\big]}\\
&\leq \frac{\frac{4^{4/3}}{20}}{\frac{\sqrt{\pi}}{2}
\sqrt[3]{\frac{1}{4}+\frac{1}{2}}}<\frac{1}{2},
\end{align*}
and for every $\lambda\in(0,1)$, $x>0$, and $t\in\mathbb{R}$,
$$
\frac{f_1(t,\lambda x)}{f_1(t,x)}\geq \lambda^{2/3},\quad  
\lambda^{2/3}>(\lambda- \lambda^{4/3})+\lambda ,
$$
we conclude that (H9)  holds with $\varphi_1(\lambda,x)\equiv \lambda^{2/3}$ 
and $\psi_1(\lambda,x)\equiv 1$.
\end{example}


\subsection*{Acknowledgements}
The work was partially supported by NSFC (11461034), the Program for Cultivating 
Young Scientist of Jiangxi Province
(20133BCB23009), the NSF of Jiangxi Province (20143ACB21001), and 
the Foundation of Jiangxi Provincial Education
Department (GJJ150342).



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\end{document}
