\documentclass[reqno]{amsart}
\usepackage{hyperref}

\AtBeginDocument{{\noindent\small
\emph{Electronic Journal of Differential Equations},
Vol. 2016 (2016), No. 88, pp. 1--15.\newline
ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu
\newline ftp ejde.math.txstate.edu}
\thanks{\copyright 2016 Texas State University.}
\vspace{9mm}}

\begin{document}
\title[\hfilneg EJDE-2016/88\hfil Fractional Schr\"odinger equations]
{Infinitely many solutions for fractional Schr\"odinger equations in
$\mathbb{R}^N$}

\author[C. Chen \hfil EJDE-2016/88\hfilneg]
{Caisheng Chen}

\address{Caisheng Chen \newline
College of Science, Hohai University,
Nanjing 210098, China}
\email{cshengchen@hhu.edu.cn}

\thanks{Submitted January 31, 2016. Published March 30, 2016.}
\subjclass[2010]{35R11, 35A15, 35J60, 47G20}
\keywords{ Fractional Schr\"odinger equation;  variational methods;
\hfill\break\indent   (PS) condition;  (C)$_c$ condition}

\begin{abstract}
 Using  variational methods we  prove the existence of infinitely
 many solutions to the fractional Schr\"odinger equation
 \[
 (-\Delta)^su+V(x)u=f(x,u), \quad  x\in\mathbb{R}^N,
 \]
 where $N\ge 2, s\in (0,1)$. $(-\Delta)^s$ stands for the fractional
 Laplacian. The potential function satisfies  $V(x)\ge V_0>0$.
 The nonlinearity $f(x,u)$ is superlinear, has subcritical
 growth in $u$, and may or may not satisfy the (AR) condition.
\end{abstract}

\maketitle
\numberwithin{equation}{section}
\newtheorem{theorem}{Theorem}[section]
\newtheorem{lemma}[theorem]{Lemma}
\newtheorem{remark}[theorem]{Remark}
\newtheorem{definition}[theorem]{Definition}
\allowdisplaybreaks

\section{Introduction and statement of main results}

In this article, we investigate the existence  of infinitely many
solutions to the fractional Schr\"odinger equation
\begin{equation}\label{1.1}
(-\Delta)^su+V(x)u=f(x,u), \quad  x\in\mathbb{R}^N,
 \end{equation}
where $N\ge 2$, $s\in (0,1)$. $(-\Delta)^s$ stands for the fractional
Laplacian. The function $f(x,u)$ is odd, sublinear or suplinear and
subcritical in $u$, $V(x)$ is positive and bounded below in
$\mathbb{R}^N$.

Equation \eqref{1.1} arises in the study of the fractional Schr\"odinger
equation
\begin{equation}\label{1.2}
i\frac{\partial \psi}{\partial
t}+(-\Delta)^s\psi+V(x)\psi=f(x,\psi), \quad
x\in\mathbb{R}^N,\;t>0,
 \end{equation}
 when looking for standing waves, that
is, solutions with the form $\psi(x,t)=e^{i\omega t}u(x),$ where
$\omega$ is a constant. This equation was introduced by Laskin
 \cite{F15,F16}
 and comes from an expansion of the Feynman path integral and
from Brownian-like to L\'{e}vy-like quantum mechanical paths.


This equation is of particular interest in fractional quantum
mechanics for the study of particles on stochastic fields modelled
by L\'{e}vy processes, which occur widely in physics, chemistry and
biology. The stable L\'{e}vy processes that gives rise to equations
with the fractional Laplacian have recently attracted much research
interest. For more details, we can see \cite{F5}.

Nonlinear equations like \eqref{1.1} have recently been studied by
Cabr\'e and Roquejoffre \cite{F3}, Cabr\'e and Tan \cite{F4}, Sire
and Valdinoci \cite{F23}, Iannizzotto et al. \cite{F13}, Hua and Yu
 \cite{F12}.
 A one-dimensional version of \eqref{1.1} has been studied in the
context of solitary waves by Weinstein \cite{F28}.

 Equations of the form \eqref{1.1} in the
whole space $\mathbb{R}^N$ were studied by a number of authors; see for
instance \cite{F6,F9,F20,F21,F22} and the references therein.
Felmer et al. \cite{F9}  considered the existence and regularity of
positive solution of \eqref{1.1} with $V(x)=1$ and $s\in(0,1)$ when
$f$ has subcritical growth and satisfies the
Ambrosetti-Rabinowitz ((AR) for short) condition. Secchi \cite{F20}
 obtained the existence of ground state solutions of
 \eqref{1.1} for  $s\in(0,1)$ when $V(x)\to \infty$ as
$|x|\to \infty$ and (AR) condition holds.  In \cite{F8}, the
authors proved  the existence of infinitely many weak solutions for
\eqref{1.1} by variant fountain theorem under the assumption
\begin{equation}\label{1.3}
0<\inf_{x\in\mathbb{R}^N}V(x)<\liminf_{|x|\to\infty}V(x)=V_{\infty}<\infty.
\end{equation}
Tang \cite{F26} studied \eqref{1.1} with a potential $V(x)$
satisfying
\begin{equation}\label{1.4}
0<\inf_{x\in\mathbb{R}^N}V(x),\quad \operatorname{meas}(\{x\in \mathbb{R}^N
|V(x)\le d\})<\infty,\quad \forall d>0.
\end{equation}
Similar assumptions can be found in \cite{F10,F22,F24,F29}.  Each of
these conditions ensures that the embedding
$W^{s,2}(\mathbb{R}^N)\hookrightarrow L^q(\mathbb{R}^N)$ is compact
for $2\le q<2_s^*=\frac{2N}{N-2s}$. On the other hand, Gou and
Sun \cite{F11}, Chang and Wang \cite{F7} investigated the existence
of radial solutions for \eqref{1.1}.

 In this article, we are interest in  the
existence of infinitely many solutions for \eqref{1.1} under the
assumptions (A3)--(A7) below.  Our assumptions on $f(x,u)$ are
different from that in the above papers. The weighted functions
$h_1(x),h_2(x)$ and $h_3(x)$ depend on the potential function $V(x)$
and the nonlinear function $f(x,u)$ either  satisfies (AR)
condition or does not. Moreover, two cases that $f(x,u)$ is bounded
and  unbounded in $x\in\mathbb{R}^N$ are considered. We note that,
in \cite{F18,F24,F27}, $f(x,u)$ is assumed to bounded in $x\in\mathbb{R}^N$

  To state  our main results, we recall some fractional Sobolev spaces and
norms \cite{F17}. Let $V(x)$ satisfy (A1) below and
\begin{equation}\label{1.5}
E=\Big\{u\in W^{s,2}(\mathbb{R}^N):
\int_{\mathbb{R}^N} |\xi|^{2s}|
\hat{u}|^2d\xi+\int_{\mathbb{R}^N}  V(x)|u|^2dx<\infty\Big\}
\end{equation}
endowed with the norm
\begin{equation}\label{1.6}
\|u\|_{E}=\Big(\int_{\mathbb{R}^N}  |\xi|^{2s}|
\hat{u}|^2d\xi+\|u\|_{2,V}^2\Big)^{1/2},
\end{equation}
 where and in the sequel, $\|u\|_{2,V}^2=\int_{\mathbb{R}^N}  V(x)|u|^2dx$ and
$\hat{\omega}=\hat{\omega}(\xi)$  is the Fourier
transform of $\omega(x)$; that is,
\begin{equation}\label{1.7}
\begin{gathered}
\hat{\omega}=\mathcal{F}[\omega(x)]
=\frac{1}{(2\pi)^{N/2}}\int_{\mathbb{R}^N}\omega(x)e^{-i\xi\cdot x}dx,\\
\omega(x)=\mathcal{F}^{-1}[\hat{\omega}]
=\frac{1}{(2\pi)^{N/2}}\int_{\mathbb{R}^N}  \hat{\omega}(\xi)e^{i\xi\cdot
x}d\xi.
\end{gathered}
\end{equation}
 In \cite{F17}, the author shows that
\begin{gather}\label{1.8}
((-\Delta)^su)(x)=\mathcal{F}^{-1}[|\xi|^2\hat{u}],\quad \forall x\in\mathbb{R}^N,  \\
\label{1.9}
[u]^2_{E}=\frac{2}{C(N,s)}\int_{\mathbb{R}^N}  |\xi|^2|\hat{u}|^2d\xi,
\end{gather}
where
\begin{equation}\label{1.10}
[u]_{E}=\Big(\iint_{\mathbb{R}^{2N}} \frac{|u(x)-u(y)|^2}{|x-y|^{N+2s}}\,dx\,dy
\Big)^{1/2}
\end{equation}
 is called the Gagliardo norm, and the constant $C(N,s)$ depends only on
the space dimensional $N$ and  the order $s$, and it is explicitly given by
the integral
\begin{equation}\label{1.11}
\frac{1}{C(N,s)}=\int_{\mathbb{R}^N}\frac{1-\cos(\zeta_1)}{|\zeta|^{N+2s}}d\zeta,
\quad \zeta=(\zeta_1,\zeta_2,\dots,\zeta_N)\in\mathbb{R}^N.
\end{equation}
Moreover, by the Plancherel formula in Fourier analysis, we
have
\begin{equation}\label{1.12}
[u]^2_{E}=\frac{2}{C(N,s)}\|(-\Delta)^{s/2}u\|_2^2.
\end{equation}
Then, from \eqref{1.8}-\eqref{1.12}, we obtain that the norm
$\|\cdot\|_E$ is equivalent to the  norms
\begin{equation}\label{1.13}
\begin{gathered}
\|u\|_{1}=\Big(\int_{\mathbb{R}^N}  V(x)|u|^2dx
+\iint_{\mathbb{R}^{2N}}  \frac{|u(x)-u(y)|^2}{|x-y|^{N+2s}}\,dx\,dy\Big)^{1/2},
\\
\|u\|_{2}=\Big(\int_{\mathbb{R}^N}  V(x)|u|^2dx+\|(-\Delta)^{s/2}u\|^2_2\Big)^{1/2}.
\end{gathered}
\end{equation}

In general, we define the fractional Sobolev space
$W^{s,p}(\mathbb{R}^N)(0<s<1<p, sp<N)$ as follows
\begin{equation}\label{1.14}
W^{s,p}(\mathbb{R}^N)=\Big\{u\in L^p(\mathbb{R}^N):
\frac{|u(x)-u(y)|}{|x-y|^{\frac{N}{p}+s}} \in L^p(\mathbb{R}^{2N})\Big\}.
\end{equation}
This space is endowed with the natural norm
\begin{equation}\label{1.15}
\|u\|_{W^{s,p}}=\Big(\int_{\mathbb{R}^N}  |u|^pdx+\iint_{\mathbb{R}^{2N}}\frac{|u(x)
-u(y)|^p}{|x-y|^{N+ps}}\,dx\,dy\Big)^{1/p},
\end{equation}
 while
\begin{equation}\label{1.16}
[u]_{W^{s,p}}=\Big(\iint_{\mathbb{R}^{2N}}
\frac{|u(x)-u(y)|^p}{|x-y|^{N+ps}}\,dx\,dy\Big)^{1/p}
\end{equation}
  is called the Gagliardo norm.
For the reader's convenience, we recall the main embedding
results for $W^{s,p}(\mathbb{R}^N)$.

 \begin{lemma}[\cite{F17}] \label{lem1.1}
 Let $s\in(0,1)$ and $p\ge 1$ such that $sp<N$. Then there exists a positive constant
 $S_0=S_0(N,p,s)$ such that, for any measurable and compactly supported
function $u: \mathbb{R}^N\to \mathbb{R}$,  we have
\begin{equation}\label{1.17}
\|u\|_{p^*_s}\le S_0[u]_{W^{s,p}},
\end{equation}
where $p_s^*=pN/(N-ps)$ is the fractional critical exponent.
Consequently, the space $W^{s,p}(\mathbb{R}^N)$ is continuously embedded in
$L^q(\mathbb{R}^N)$ for any $q\in [p,p_s^*]$. Moreover, the embedding
 $W^{s,p}(\mathbb{R}^N)\hookrightarrow L^q(\mathbb{R}^N)$ is locally compact whenever
$1<q<p_s^*$.
\end{lemma}

\begin{remark} \label{rmk1.2} \rm
By the density of the compactly supported functions in
$W^{s,p}(\mathbb{R}^N)$, we know that \eqref{1.17} holds for any $u\in
W^{s,p}(\mathbb{R}^N)$.
\end{remark}

From the H\"older inequality and Lemma \ref{lem1.1}, we obtain the following lemma.

 \begin{lemma} \label{lem1.3}
Let $s\in(0,1)$, $sp<N$ and $p\le q\le p_s^*$.  Then for any $u\in
X=W^{s,p}(\mathbb{R}^N)$,
\begin{equation}\label{1.18}
\|u\|_{q}\le S_q\|u\|_X
\end{equation}
 where $S_q$ is a constant depending on $s,q,p,N$. In particular, we denote
$S_{p_s^*}$ by $S_0$. The inequality \eqref{1.18} shows that  the
 embedding $X\hookrightarrow L^q(\mathbb{R}^N)$ is continuous.
\end{lemma}

\begin{proof}
When $q=p$,  inequality \eqref{1.18} is obvious. For $q=p_s^*$,
\eqref{1.18} can be obtained from \eqref{1.17}. Let $p<q<p_s^*$.
Then there exists $t\in (0,1)$ such that $q=pt+p_s^*(1-t)$. It
follows from the H\"older inequality and \eqref{1.17} that
\begin{equation}\label{1.19}
\begin{split}
\int_{\mathbb{R}^N}  |u|^qdx
&=\int_{\mathbb{R}^N}  |u|^{p_s^*(1-t)}|u|^{pt}dx
\le \Big(\int_{\mathbb{R}^N}  |u|^{p_s^*}dx\Big)^{(1-t)}
 \Big(\int_{\mathbb{R}^N}  |u|^{p}dx\Big)^{t} \\
&\le S_0^{1-t}[u]_X^{p_s^*(1-t)}\|u\|_p^{pt}
\le S_q^q\|u\|_X^{p_s^*(1-t)}\|u\|_X^{pt}=S_q^q\|u\|_X^q,
\end{split}
\end{equation}
where $S_q^q=S_0^{1-t}$. This implies  \eqref{1.18}.
\end{proof}

Similarly, for the Sobolev space $E$ defined by \eqref{1.5}, we have
the following result.

\begin{lemma} \label{lem1.4}
Let $s\in(0,1), 2s<N$ and $2\le q\le 2_s^*$.
Assume $V(x)\ge V_0>0$ in $\mathbb{R}^N$. Then, for any $u\in E$,
\begin{equation}\label{1.20}
\|u\|_{q}\le S_q\|u\|_E
\end{equation}
 where $S_q$ is a constant depending on $s,q,p,N$ and $V_0$.
In particular, we denote $S_{2_s^*}$ by $S_0$.
\end{lemma}

\begin{definition} \label{def1.1} \rm 
A function $u\in E$ is said to be a (weak) solution of
\eqref{1.1} if for any $\varphi \in E$, we have
\begin{equation}\label{1.21}
\int_{\mathbb{R}^N}  |\xi|^{2s}\hat{u}\hat{\varphi}
d\xi+\int_{\mathbb{R}^N}  V(x)u\varphi dx
= \int_{\mathbb{R}^N}  f(x,u)\varphi dx.
\end{equation}
\end{definition}

Let $J(u):E\to \mathbb{R} $ be the energy functional
associated with \eqref{1.1} defined by
\begin{equation}\label{1.22}
J(u)=\frac{1}{2}\int_{\mathbb{R}^N}  |\xi|^{2s}|\hat{u}|^2 d\xi
+\frac{1}{2}\int_{\mathbb{R}^N}  V(x)|u|^2dx
 -\int_{\mathbb{R}^N}  F(x,u)dx,
\end{equation}
where $F(x,u)=\int_0^u f(x,t)dt$.

Using  \eqref{1.18} and  assumptions (A3)--(A7) below,  we see that
  the functional
$J$ is well defined and $J\in C^1(E,\mathbb{R})$ with
\begin{equation}\label{1.23}
J'(u)\varphi =\int_{\mathbb{R}^N}  |\xi|^{2}\hat{u}\hat{\varphi}
d\xi+\int_{\mathbb{R}^N}  V(x)u\varphi dx
-\int_{\mathbb{R}^N}  f(x,u)\varphi dx, \quad  \forall \varphi\in
E.
\end{equation}

Throughout this article,  the function $f(x,u)\in
C(\mathbb{R}^N \times\mathbb{R})$  is odd in $u$.
In addition, we  use the following assumptions.
\begin{itemize}
\item[(A1)] The function $V(x)\in C(\mathbb{R}^N)$ satisfies
 $\inf_{x\in\mathbb{R}^N}V(x)\ge V_0>0$, where $V_0$ is a constant.

\item[(A2)] There exists $a>0$ such that 
$\lim_{|y|\to\infty}\operatorname{meas}(\{x\in B_a(y):V(x)\le d\})=0$ for any
$d>0$, where ``meas" denotes the Lebesgue measure on $\mathbb{R}^N$ and
$B_r(x)$ denotes any open ball of $\mathbb{R}^N$ centered at $x$ and of
radius $r>0$, while we simply write $B_r$ when $x=0$.

\item[(A3)]  There exist $2<\alpha<\beta<2_s^*$  such that
\begin{equation}\label{1.24}
|f(x,u)|\le h_1(x)|u|^{\alpha-1}+h_2(x)|u|^{\beta-1},\forall
(x,u)\in \mathbb{R}^N \times\mathbb{R},
\end{equation}
where $h_1(x), h_2(x)\in C(\mathbb{R}^N)$ and
\begin{equation}\label{1.25}
\lim_{r\to\infty}\sup_{x\in
B_r^c}\frac{h_1(x)}{V^{t_1}(x)}=0,\quad
\lim_{r\to\infty}\sup_{x\in B_r^c} \frac{h_2(x)}{V^{t_2}(x)}=0
  \end{equation}
with $t_1=(2_s^*-\alpha)/(2_s^*-2),\; t_2=(2_s^*-\beta)/(2_s^*-2)$ and
$B_r^c=\mathbb{R}^N\setminus\overline{B}_r=\{x\in \mathbb{R}^N: |x|>r\}$.

\item[(A4)]  There exists $\mu>2$ such that
\begin{equation}\label{1.26}
tf(x,t)-\mu F(x,t)\ge 0,\quad \forall (x,t )\in \mathbb{R}^N\times \mathbb{R}.
\end{equation}

\item[(A5)]
 $\lim_{|t|\to\infty}(F(x,t)t^{-2})=\infty$  for any $x\in \mathbb{R}^N$.


\item[(A6)] There exist
$k>\frac{N}{2s}$ and $2<\alpha<\beta\le\frac{2k}{k-1}$
  such that \eqref{1.24} and \eqref{1.25}  hold. Furthermore,
there exist $b, c_1\ge 1$  such that for $x\in\mathbb{R}^N$ and $|u|\ge b$,
\begin{equation}\label{1.27}
\begin{gathered}
F(x,u)\ge 0,\quad
G(x,u) = \frac{1}{2}uf(x,u) - F(x,u)\ge 0,\\
|F(x,u)|^{k}\le  c_1^k|u|^{2k}|h_3(x)|^{2k}G(x,u),
\end{gathered}
\end{equation}
where  $h_3(x)\in C(\mathbb{R}^N)$ satisfies
\begin{equation}\label{1.28}
\lim_{r\to\infty}\sup_{x\in B_r^c}\frac{|h_3(x)|^{2k'}}{V^{t_3}(x)}=0,
\quad\text{with }
k'=\frac{k}{k-1},\; t_3=\frac{2_s^*-2k'}{2_s^*-2}.
\end{equation}

\item[(A7)] There exist a constant $C_0>0$ and $2<\alpha<\beta<2_s^*$,
  such that
\begin{equation}\label{1.29}
|f(x,u)|\le C_0(|u|^{\alpha-1}+|u|^{\beta-1}),\quad 
\forall (x,u)\in \mathbb{R}^N \times\mathbb{R}.
\end{equation}
\end{itemize}

\begin{remark} \label{rmk1.5} \rm
Condition (A2), which is weaker than the coercivity assumption
$V(x)\to\infty$ as $|x|\to\infty$, was originally introduced by
Bartsch and Wang in \cite{F1} to overcome the lack of compactness.
Clearly, if $V(x)\to\infty$ as $|x|\to\infty$, it is possible that
the functions $h_1(x),h_2(x)$ and $h_3(x)$  in $(A3)$ and (A6)
are unbounded on $\mathbb{R}^N$. So, it is necessary to consider the
condition (A7).
\end{remark}

 Our main results in this paper are as follows.

\begin{theorem} \label{thm1.6}  
 Let $s\in(0,1), 2s<N$. Assume {\rm (A1), (A2)} and {\rm (A5)} hold. In addition, 
suppose that either   {\rm(A3), (A4)} or 
(A6)  are satisfied.
 Then   \eqref{1.1} admits infinitely many  solutions $u_n\in E$ such that
$J(u_n)\to \infty$ as $n\to \infty$.
\end{theorem}

\begin{theorem} \label{thm1.7}   
Let $s\in(0,1), 2s<N$. Assume {\rm(A1)--(A3)} and {\rm (A7)} hold. 
In addition, suppose that either  (A4) or \eqref{1.27} is satisfied
with $h_3(x)\equiv 1$.
 Then   \eqref{1.1} admits infinitely many solutions $u_n\in E$ such that
$J(u_n)\to \infty$ as $n\to \infty$.
\end{theorem}

\begin{remark} \label{rmk1.8} \rm 
Assumption \eqref{1.25} implies that the functions
 $(h_1V^{-1})$, $(h_2V^{-1})$, $(h_1V^{-t_1})$, 
$(h_2V^{-t_2})$ belong to $L^{\infty}(\mathbb{R}^N)$ and 
\[
\lim_{r\to\infty}\sup_{x\in B_r^c}[h_1(x)V^{-1}(x)]
=\lim_{r\to\infty}\sup_{x\in B_r^c}[h_2(x)V^{-1}(x)]=0.
\] 
Moreover, the condition $k>\frac{N}{2s}$ in
(A7) implies that $\frac{2k}{k-1}<2_s^*$.
\end{remark}

\begin{remark} \label{rmk1.9} \rm 
Assumption (A4) is called the (AR) condition.
Obviously, the power functions in $u$ like
$f(x,u)=\sum_{i=1}^nh_i(x)|u|^{\beta_i-2}u$ with $2<\beta_i<2_s^*$
satisfy (A3) and (A4) for  appropriate functions 
$h_i\in C(\mathbb{R}^N)$. The functions like $f(x,u)=h(x)u\log(1+|u|)$ fails to
satisfy  condition (A4), but  it satisfies  (A6).
 \end{remark}

Teng  \cite{F27} considered  problem \eqref{1.1} under assumption
(A4) with $h_1(x), h_2(x)\in L^{\infty}(\mathbb{R}^N)$. Obviously, our
assumptions on $h,h_1$ and $h_2$ are  weaker than that in \cite{F27}.
Without loss of  generality, we let $V_0=1$ in (A1).

\section{Proof of main results}

To prove the  main results,  we recall some useful concepts
and results.

\begin{definition} \label{def2.1} \rm 
Let $E$  be a real Banach space and the functional  
$J\in C^1(E,\mathbb{R})$.  We say that $J$ satisfies the $(C)_c$ condition if any
$(C)_c$ sequence $\{u_n\}\subset E$:
\begin{equation}\label{2.1}
J(u_n)\to c,\quad (1+\|u_n\|_E)\|J'(u_n)\|_{E^*}\to 0  \quad
\text{as } n\to \infty
\end{equation}
has a convergent subsequence in $E$.
\end{definition}

\begin{lemma}[\cite{F19,F25}] \label{lem2.1} 
 Let $E$ be an infinite dimensional real Banach
space, the functional $J\in C^1(E,\mathbb{R})$ be even and satisfy
the $(C)_c$ condition  for all $c>0$ and $J(0)=0$. In addition,
assume  $E=Y\oplus Z$, in which $Y$ is finite dimensional, and $J$
satisfies
\begin{itemize}
\item[(A8)] there exist constants $\rho, \alpha_0>0$ such that $J(z)\ge
\alpha_0$ on $\partial B_{\rho}\cap Z$;

\item[(A9)] for each finite dimensional subspace $E_0\subset E$, there
is an $R=R(E_0)$ such that $J(z)\le 0$ on $E_0\setminus
\overline{B}_{R}$, where $B_R=\{z\in E: \|z\|_E<R\}, \partial
B_R=\{z\in E: \|z\|_E=R\}$.
\end{itemize}
 Then, $J$ possesses an unbounded sequence of critical values, i.e. there
exists a sequence $\{u_n\}\subset E$  such that $J'(u_n)=0$ and
$J(u_n)\to \infty$ as $n\to \infty$.
\end{lemma}

In the proof of our  results, we  use the following lemma.

\begin{lemma}[\cite{F18}] \label{lem2.2} 
 Let $s\in (0,1), 2s<N$ and $2\le q<2_s^*=\frac{2N}{N-2s}$. 
Assume {\rm (A1)} and {\rm (A2)}. Then the embedding 
$E\hookrightarrow L^q(\mathbb{R}^N)$ is compact.
\end{lemma}

For the prove Theorems \ref{thm1.6} and \ref{thm1.7}, we  need the following lemmas.

\begin{lemma} \label{lem2.3}  
Assume {\rm (A1)} and {\rm (A2)}. 
If  {\rm (A4)} is satisfied, then any  $(C)_c$ sequence
$\{u_n\}$   is bounded in $E$.
\end{lemma}

\begin{proof} 
 Let the sequence $\{u_n\}$ satisfy \eqref{2.1} and $\mu>2$. Then
 for large $n$,  we have
\begin{equation}\label{2.2}
\begin{aligned}
c+1+\|u_n\|_E 
&\ge J(u_n) - \frac{1}{\mu}J'(u_n)u_n\\
&=(\frac{1}{2}-\frac{1}{\mu})\|u_n\|_E^2+\frac{1}{\mu}\int_{\mathbb{R}^N}f(x,u_n)u_n
-\mu F(x,u_n))dx.
\end{aligned}
\end{equation}
Then (A4) implies that  $\{u_n\}$ is bounded in $E$. The proof
is complete.
\end{proof}


\begin{lemma} \label{lem2.4}  
 Assume {\rm (A1), (A2), (A5), (A6)} hold. Then any $(C)_c$   sequence
$\{u_n\}$  is bounded in $E$.
\end{lemma}

\begin{proof} 
To prove the boundedness of $\{u_n\}$, arguing
contradiction, we suppose that $\|u_n\|_E\to \infty$ as
$n\to\infty$. Let $v_n(x)=\frac{u_n(x)}{\|u_n\|_E}$. Then
$\|v_n\|_E=1$ for all $n\ge 1$. By Lemma \ref{lem2.2},
 there exists a subsequence of $\{v_n\}$, still
denoted by $\{v_n\}$, and  $v\in E$ such that $\|v\|_E\le 1$ and
\begin{equation}\label{2.3}
\begin{gathered}
 v_n \rightharpoonup v \text{ weakly in }E; \quad
v_n\to v\text{ in } L^q(\mathbb{R}^N)\; (2\le q<2_s^*);\\
 v_n(x)\to v(x) \text{ a.e. in } \mathbb{R}^N.
\end{gathered}
\end{equation}

Clearly, it follows from \eqref{2.3} that there exists
 $\omega(x)\in L^q(\mathbb{R}^N)(2\le q<2_s^*)$ such that 
$|v_n(x)|\le \omega(x)$ a.e. in $\mathbb{R}^N$ for all $n\ge 1$.

From \eqref{1.22}, \eqref{1.23} and \eqref{2.1}, it
follows that for,  $n$ large,
\begin{equation}\label{2.4}
c+ 1 \ge J(u_n) - \frac{1}{2}J'(u_n)u_n
 = \int_{\mathbb{R}^N}  G(x,u_n)dx,
\end{equation}
 where $ G(x,u)=\frac{1}{2}uf(x,u)-F(x,u)$,
and
\begin{equation}\label{2.5}
\begin{aligned}
\frac{1}{2}
&\leq \limsup_{n\to\infty}\int_{\mathbb{R}^N}  \frac{|F(x,u_n)|}{\|u_n\|_E^{2}}dx\\
&\leq \limsup_{n\to\infty}\int_{B_r}
\frac{|F(x,u_n)|}{|u_n|^{2}}|v_n|^{2}dx
+\limsup_{n\to\infty}\int_{B_r^c}
\frac{|F(x,u_n)|}{|u_n|^{2}}|v_n|^{2}dx,
\end{aligned}
\end{equation}
for any $r>0$. By (A6), we obtain, for any $\varepsilon>0$, there
exists $\delta>0$ such that 
$\frac{|F(x,t)|}{|t|^{2}}\le \varepsilon(h_1(x)+h_2(x))$ for all 
$0<|t|\le\delta$ and all $x\in\mathbb{R}^N$.
 Denote $X_n= \{x\in\mathbb{R}^N:|u_n(x)|\le \delta\}$, 
$Y_n= \{x\in\mathbb{R}^N:\delta<|u_n(x)|\le b\}, Z_n
=\{x\in\mathbb{R}^N:|u_n(x)|\ge b\}$,
where the  constant $b$ is given in (A6). Obviously,
$\mathbb{R}^N=X_n\cup Y_n \cup Z_n$ and 
$B_r^c=B_r^c\cap( X_n\cup Y_n \cup Z_n)$.  Then
\begin{equation}\label{2.6}
\begin{split}
\int_{B_r^c\cap X_n}\frac{|F(x,u_n)|}{|u_n|^{2}}|v_n|^{2}dx
&\le \varepsilon \int_{B_r^c\cap X_n} (h_1(x)+h_2(x))|v_n|^{2}dx
\\
&\le \varepsilon (\|h_1V^{-1}\|_{\infty}+\|h_2V^{-1}\|_{\infty})
\int_{\mathbb{R}^N}  V|v_n|^{2}dx \\
&\le 2\varepsilon M_1\|v_n\|_E^2=2\varepsilon M_1,
\end{split}
\end{equation}
where $M_1=\max\{\|h_1V^{-1}\|_{\infty},\|h_2V^{-1}\|_{\infty}\}$.
Furthermore, by \eqref{1.24} and \eqref{1.25}, one sees that
 \begin{equation}\label{2.7}
 \begin{split}
&\int_{B_{r}^c\cap Y_n}  \frac{|F(x,u_n)|}{|u_n|^2}|v_n|^2 \,dx\\
&\le b^{\beta-2}\int_{B_{r}^c\cap Y_n}  (h_1(x)+h_2(x))|v_n(x)|^2 \,dx
\\
&\le   b^{\beta-2}\Big(\sup_{x\in B_r^c}\frac{h_1(x)}{V(x)}+\sup_{x\in
  B_r^c}\frac{h_2(x)}{V(x)}  \Big)\int_{B_r^c}V(x)|v_n|^2dx
 \\
&\le b^{\beta-2}\Big(\sup_{x\in B_r^c}\frac{h_1(x)}{V(x)}+\sup_{x\in
  B_r^c}\frac{h_2(x)}{V(x)}
 \Big)\to 0 \quad  \text{as } r=|x|\to \infty.
\end{split}
\end{equation}

 On the other hand,  from \eqref{1.27} and \eqref{2.4} it follows that
\begin{equation}\label{2.8}
\begin{split}
&\int_{B_r^c\cap Z_n}  \frac{|F(x,u_n)|}{|u_n|^2}|v_n|^2dx\\
&\le\Big(\int_{B_r^c\cap Z_n}  \Big(\frac{|F(x,u_n)|}{h_3^2|u_n|^2}\Big)^{k}
dx\Big)^{1/k}\Big(\int_{B_r^c\cap Z_n}  |h_3v_n|^{2k'}dx\Big)^{1/k'} \\
&\le c_1\Big(\int_{\mathbb{R}^N}  G(x,u_n)dx\Big)^{1/k}\Big(\int_{B_r^c\cap
Z_n}  |h_3v_n|^{2k'}dx\Big)^{1/k'}\\
&\le c_1(c+1)^{1/k}\Big(\int_{B_r^c}  |h_3v_n|^{2k'}dx\Big)^{1/k'}.
 \end{split} 
\end{equation}

Note that  $2<2k'<2_s^*$. Let $t_3=(2_s^*-2k')/(2_s^*-2)$. By the
H\"older inequality and \eqref{1.20}, we obtain
\begin{equation}\label{2.9}
\begin{aligned}
\int_{B_r^c}  |h_3v_n|^{2k'}dx
&\le \sup_{x\in B_r^c}\frac{|h_3(x)|^{2k'}}{V^{t_3}(x)}
\Big(\int_{B_r^c}  Vv_n^2dx\Big)^{t_3}
\Big(\int_{B_r^c}  |v_n|^{2_s^*}dx\Big)^{1-t_3}
\\
&\le S_0\|v_n\|_E^{2k'}\sup_{x\in
B_r^c}\frac{|h_3(x)|^{2k'}}{V^{t_3}(x)} \le S_0\sup_{x\in
B_r^c}\frac{|h_3(x)|^{2k'}}{V^{t_3}(x)}\to 0
\end{aligned}
\end{equation}
as $r=|x|\to\infty$, where $S_0=S_{2_s^*}$ is the constant in \eqref{1.20}.
Then, and application of \eqref{2.6}-\eqref{2.9}  implies that for any
$\varepsilon>0$, there exist $n_0, r_0\ge 1$, such that $n\ge n_0$,
$r\ge r_0$,
\begin{equation}\label{2.10}
\int_{B_r^c}  \frac{|F(x,u_n)|}{|u_n|^2}|v_n|^2dx\le
\varepsilon(2M_1+1).
\end{equation}
 Set $T_n=X_n\cup Y_n$. Notice that for all
$x\in B_{r_0}\cap T_n$,
\begin{equation}\label{2.11}
\begin{aligned}
\frac{|F(x,u_n)|}{|u_n|^{2}}|v_n|^{2}
& \le b^{\beta-2}(h_1(x)+h_2(x))|v_n(x)|^2\\
&\le b^{\beta-2}M_2|\omega(x)|^2\equiv d(x)\in L^1(B_{r_0}),
\end{aligned}
\end{equation}
where
\begin{equation}\label{2.12}
M_2=\sup_{x\in B_{r_0}}(h_1(x)+h_2(x)).
\end{equation}

If $v(x)=0$ in $B_{r_0}$, it follows from Fatou's lemma that
\begin{equation}\label{2.13}
\begin{aligned}
\limsup_{n\to\infty}\int_{B_{r_0}\cap T_n}
\frac{|F(x,u_n)|}{|u_n|^{2}}|v_n|^{2}dx
&\le M_2b^{\beta-2} \int_{B_{r_0}}   \limsup_{n\to\infty}|v_n|^{2}dx\\
&=M_2b^{\beta-2}    \int_{B_{r_0}}   |v|^{2}dx=0.
\end{aligned}
\end{equation}

Arguing as in \eqref{2.8} and \eqref{2.9}, we obtain
\begin{equation}\label{2.14}
\int_{B_{r_0}\cap Z_n}  \frac{|F(x,u_n)|}{|u_n|^2}|v_n|^2dx
\le C_1\sup_{x\in
B_{r_0}}|h_3(x)|^2\Big(\int_{B_{r_0}}  |v_n|^{2k'}dx\Big)^{1/k'}
 \end{equation}
with $C_1=c_1(c+1)^{1/k}$.
Similarly, since $|v_n(x)|^{2k'}\le |\omega(x)|^{2k'}$ a.e. in
$\mathbb{R}^N$ and $|\omega(x)|^{2k'} \in L^1(\mathbb{R}^N)$, we obtain
\begin{equation*}
\limsup_{n\to\infty}\int_{B_{r_0}}  |v_n|^{2k'}dx\le
\int_{B_{r_0}}  \limsup_{n\to\infty}|v_n|^{2k'}dx=\int_{B_{r_0}}  |v|^{2k'}dx=0.
 \end{equation*}
Hence,
\begin{equation}\label{2.15}
\limsup_{n\to\infty}\int_{B_{r_0}}  \frac{|F(x,u_n)|}{|u_n|^2}|v_n|^2dx=0.
 \end{equation}
So, an application of \eqref{2.10} and  \eqref{2.15} contradicts
\eqref{2.5} and then meas$(A)>0$, where  $A=\{x\in\mathbb{R}^N:v(x)\neq 0\}$.
Obviously, for a.e. $x\in A$, we have $\lim_{n\to\infty}|u_n(x)|=\infty$.
Hence, $A\subset Z_n$ for large $n$.  Moreover, one sees that
\begin{equation}\label{2.16}
\begin{split}
&\int_{T_n}  \frac{|F(x,u_n)|}{|u_n|^2}|v_n|^2dx\le
b^{\beta-2}\int_{\mathbb{R}^N}(h_1(x)+h_2(x))|v_n|^2dx
\\
&\le
b^{\beta-2}(\|h_1V^{-1}\|_{\infty}+\|h_2V^{-1}\|_{\infty})
\int_{\mathbb{R}^N}  V|v_n|^2dx\\
&\le 2b^{\beta-2}M_1\|v_n\|_E^2=2b^{\beta-2}M_1.
 \end{split}
\end{equation}
Moreover, using assumption (A5) and Fatou's lemma, it follows
from $J(u_n)\to c$ that
\begin{equation}\label{2.17}
\begin{split}
 0&=\lim_{n\to\infty}\frac{c+o(1)}{\|u_n\|_E^{2}}=\lim_{n\to\infty}\frac{J(u_n)}{\|u_n\|_E^{2}}\le
\lim_{n\to\infty}\Big[\frac{1}{2}-\int_{\mathbb{R}^N}  \frac{F(x,u_n)}{|u_n|^{2}}|v_n|^{2}dx\Big]
\\
&\le
\frac{1}{2}+2b^{\beta-2}M_1-\liminf_{n\to\infty}\int_{Z_n}  \frac{F(x,u_n)}{|u_n|^2}|v_n|^2dx
\\
&\le
\frac{1}{2}+2b^{\beta-2}M_1-\int_{\mathbb{R}^N}  \liminf_{n\to\infty}\frac{F(x,u_n)}{|u_n|^{2}}\chi_{Z_n}(x)|v_n|^{2}dx
=-\infty,
\end{split}
\end{equation}
where $\chi_I$ denotes the characteristic function associated to the
mensurable subset $I\subset \mathbb{R}^N$. Clearly, \eqref{2.17} is
impossible.  Thus $\{u_n\}$ is bounded in $E$ and the proof of Lemma
\ref{lem2.4} is finished.
\end{proof}

\begin{lemma} \label{lem2.5}  
Assume {\rm (A1), (A2), (A5), (A7)}. In addition, suppose that
 \eqref{1.27} is satisfied  with $h_3(x)\equiv 1$.  
Then any $(C)_c$  sequence $\{u_n\}$  is bounded in $E$.
\end{lemma}

\begin{proof}
Arguing as the proof of Lemma \ref{lem2.4}, we suppose that 
$\|u_n\|_E\to \infty$ as $n\to\infty$. Let $v_n(x)=\frac{u_n(x)}{\|u_n\|_E}$. 
Then $\{v_n\}$ satisfies \eqref{2.3}. For any $\varepsilon>0$, we choose
$r_1>0$ such that $\int_{B_{r}^c}|v(x)|^2dx<\varepsilon$ when 
$r\ge r_1$. Since $v_n(x)\to v(x)$ in $L^2(\mathbb{R}^N)$, we obtain
\begin{equation}\label{2.18}
 \limsup_{n\to\infty}\int_{B_r^c}|v_n(x)|^2dx\le
 \int_{B_r^c}\limsup_{n\to\infty}|v_n(x)|^2dx
\le\int_{B_{r}^c}|v(x)|^2dx<\varepsilon.
\end{equation}
 Then
\begin{equation}\label{2.19}
\begin{aligned}
\limsup_{n\to\infty}\int_{B_r^c\cap T_n}
\frac{|F(x,u_n)|}{|u_n|^{2}}|v_n|^{2}dx
&\le 2b^{\beta-2}C_0 \limsup_{n\to\infty}\int_{B_r^c} |v_n|^{2}dx\\
&\le C_2 \int_{B_r^c} |\omega(x)|^{2}dx\le C_2\varepsilon,
\end{aligned}
\end{equation}
where $C_2=2b^{\beta-2}C_0$, $b$ is the constant in (A6) and
$C_0$ is given in \eqref{1.29}.

 On the other hand,  from \eqref{1.27} with $h_3(x)=1$ and \eqref{2.4} 
it follows that
\begin{equation}\label{2.20}
\begin{split}
&\int_{B_r^c\cap Z_n}  \frac{|F(x,u_n)|}{|u_n|^2}|v_n|^2dx \\
& \le\Big(\int_{B_r^c\cap Z_n}  \Big(\frac{|F(x,u_n)|}{|u_n|^2}\Big)^{k}dx\Big)^{1/k}
 \Big(\int_{B_r^c\cap Z_n}  |v_n|^{2k'}dx\Big)^{1/k'} \\
&\le c_1\Big(\int_{\mathbb{R}^N}  G(x,u_n)dx\Big)^{1/k}\Big(\int_{B_r^c\cap
Z_n}  |v_n|^{2k'}dx\Big)^{1/k'}\\
&\le c_1(c+1)^{1/k}\Big(\int_{B_r^c}  |v_n|^{2k'}dx\Big)^{1/k'}.
 \end{split} 
\end{equation}

 From \eqref{2.9} and \eqref{2.18}, for large $n$,  we obtain 
\begin{equation}\label{2.21}
\int_{B_r^c}  |v_n|^{2k'}dx\le
\|v_n\|_{L^2(B_r^c)}^{2t_3}\|v_n\|_{L^{2_s^*}(B_r^c)}^{(1-t_3)2^*_s}\le
S_0\|v_n\|_{L^2(B_r^c)}^{2t_3}\le S_0\varepsilon.
\end{equation}
 Then, an application of \eqref{2.19}-\eqref{2.21} gives that for any 
$\varepsilon>0$ there exist $n_0, r_0\ge 1$ such that $n\ge n_0, r\ge r_0$,
\begin{equation}\label{2.22}
\int_{B_r^c}  \frac{|F(x,u_n)|}{|u_n|^2}|v_n|^2dx\le
\varepsilon(C_2+S_0C_1).
\end{equation}
Similar to \eqref{2.11}, for a.e.  $x\in B_{r_0}\cap T_n $ and $n\ge
1$, we obtain
\begin{equation}\label{2.23}
\frac{|F(x,u_n)|}{|u_n|^{2}}|v_n|^{2}\le C_2|v_n(x)|^2\le
C_2|\omega(x)|^2\equiv d(x)\in L^1(B_{r_0}).
\end{equation}
 By Fatou's lemma,
\begin{equation}\label{2.24}
\begin{aligned}
\limsup_{n\to\infty}\int_{B_{r_0}\cap
T_n}  \frac{|F(x,u_n)|}{|u_n|^{2}}|v_n|^{2}
& \le C_2 \int_{B_{r_0}}\limsup_{n\to\infty}|v_n(x)|^2\\
&= C_2\int_{B_{r_0}}|v(x)|^2dx.
\end{aligned}
\end{equation}
Similar to \eqref{2.20}, we derive
\begin{equation}\label{2.25}
\limsup_{n\to\infty}\int_{B_{r_0}\cap
Z_n}  \frac{|F(x,u_n)|}{|u_n|^{2}}|v_n|^{2}\le
C_1\Big(\int_{B_{r_0}}  |v(x)|^{2k'}dx\Big)^{1/k'}.
\end{equation}
If $v(x)=0$ in $B_{r_0}$, an application of \eqref{2.24} and
\eqref{2.25} gives that
\begin{equation}\label{2.26}
\limsup_{n\to\infty}\int_{B_{r_0}}  \frac{|F(x,u_n)|}{|u_n|^{2}}|v_n|^{2}=0.
\end{equation}
Combining \eqref{2.22} with \eqref{2.26}  contradicts \eqref{2.5}.
So, $\operatorname{meas}(A)>0$, where $A=\{x\in\mathbb{R}^N:v(x)\not=0\}$ and for a.e.
$x\in A$, we have $\lim_{n\to\infty}|u_n(x)|=\infty$. Hence,
$A\subset Z_n$ for large $n$. Moreover, one sees that
\begin{equation}\label{2.27}
\int_{T_n}  \frac{|F(x,u_n)|}{|u_n|^2}|v_n|^2dx\le C_1
\int_{\mathbb{R}^N}|v_n|^2dx\le C_1\int_{\mathbb{R}^N}  V|v_n|^2dx\le
C_1\|v_n\|_E^2=C_1.
 \end{equation}
Moreover, using assumption (A5) and Fatou's lemma, 
from $J(u_n)\to c$ it follows that
\begin{equation}\label{2.28}
\begin{split}
 0&=\lim_{n\to\infty}\frac{c+o(1)}{\|u_n\|_E^{2}}
 =\lim_{n\to\infty}\frac{J(u_n)}{\|u_n\|_E^{2}}\le
\lim_{n\to\infty}\Big[\frac{1}{2}-\int_{\mathbb{R}^N}  
 \frac{F(x,u_n)}{|u_n|^{2}}|v_n|^{2}dx\Big]
\\
&\le \frac{1}{2}+C_1-\liminf_{n\to\infty}\int_{Z_n}  
 \frac{F(x,u_n)}{|u_n|^2}|v_n|^2dx
\\
&\le \frac{1}{2}+C_1-\int_{\mathbb{R}^N}  \liminf_{n\to\infty}
 \frac{F(x,u_n)}{|u_n|^{2}}\chi_{Z_n}(x)|v_n|^{2}dx
=-\infty.
\end{split}
\end{equation}
Clearly, the limit \eqref{2.28} is impossible.  Thus $\{u_n\}$ is
bounded in $E$ and the proof  is complete.
\end{proof}

 From Lemmas \ref{lem2.3}--\ref{lem2.5}, we know that any $(PS)_c$ sequence
and $(C)_c$ sequence $\{u_n\}$ of the functional $J$ are bounded in
$E$. Therefore,  by Lemma \ref{lem2.2}, there exists a subsequence of
$\{u_n\}$, still denoted by $\{u_n\}$, and  $u\in E$ such that
$\|u_n\|_E+\|u\|_E\le M(\forall n\ge 1)$ and
\begin{equation}\label{2.29}
\begin{gathered}
 u_n \rightharpoonup u \text{ weakly\ in } E, \quad
 u_n\to u\text{ in }  L^q(\mathbb{R}^N)\; (2\le q<2_s^*),\\
 u_n(x)\to u(x) \text{ a.e. in } \mathbb{R}^N
\end{gathered}
\end{equation}
with some constant $M>0$.

\begin{lemma} \label{lem2.6} 
Assume {\rm (A1)--(A6)} hold. If the sequence $\{u_n\}$ satisfies 
\eqref{2.29}, then
\begin{gather}\label{2.30}
\lim_{n\to\infty}\int_{\mathbb{R}^N} h_1(|u_n|^{\alpha}-|u|^{\alpha})dx=0,\quad
\lim_{n\to\infty}\int_{\mathbb{R}^N} h_2(|u_n|^{\beta}-|u|^{\beta})dx=0,\\\
\label{2.31}
\lim_{n\to\infty}\int_{\mathbb{R}^N} f(x,u_n)(u_n-u)dx=0,\quad
\lim_{n\to\infty}\int_{\mathbb{R}^N} f(x,u)(u_n-u)dx=0, \\
\label{2.32}
\lim_{n\to\infty}\int_{\mathbb{R}^N} F(x,u_n)dx=\int_{\mathbb{R}^N} F(x,u)dx.
\end{gather}
\end{lemma}

\begin{proof}
 First, we assume {(A3), (A4)}.  From \eqref{2.29}, we obtain 
\begin{equation}\label{2.33}
\lim_{n\to\infty}\int_{B_r}  h_1(|u_n|^{\alpha}-|u|^{\alpha})dx=0,\quad
\lim_{n\to\infty}\int_{B_r}  h_2(|u_n|^{\beta}-|u|^{\beta})dx=0
\end{equation}
for any $r>0$. On the other hand, we see from the H\"older
inequality and (A3) that
\begin{equation}\label{2.34}
\begin{split}
\int_{B^c_{r}}  h_1|u_n|^{\alpha}dx
&\le \sup_{x\in B_r^c}\frac{h_1(x)}{V^{t_1}(x)}
 \Big(\int_{B^c_{r}}  V|u_n|^2dx\Big)^{t_1}
 \Big(\int_{B_r^c}  |u_n|^{2_s^*}dx\Big)^{1-t_1}
\\
&\le S_0\sup_{x\in
B_r^c}\frac{h_1(x)}{V^{t_1}(x)}\|u_n\|_E^{2t_1}\|u_n\|_E^{(1-t_1)2_s^*} \\
&\le S_0 M^{\alpha} \sup_{x\in B_r^c}\frac{h_1(x)}{V^{t_1}(x)} \to
0, \quad \text{as } r\to\infty,
\end{split}
\end{equation}
 where
$t_1=(2_s^*-\alpha)/(2_s^*-2), S_0=S_{2_s^*}$. Similarly, as $ r\to \infty$,
\begin{equation}\label{2.35}
\begin{aligned}
\int_{B^c_{r}}  h_2|u_n|^{\beta}dx
&\le S_0\sup_{x\in B_r^c}\frac{h_2(x)}{V^{t_2}(x)}
 \|u_n\|_E^{2t_2}\|u_n\|_E^{(1-t_2)2_s^*} \\
&\le S_0 M^{\beta} \sup_{x\in B_r^c}\frac{h_2(x)}{V^{t_2}(x)} \to 0,
\end{aligned}
\end{equation} 
where $t_2=(2_s^*-\beta)/(2_s^*-2)$. Then an application of 
\eqref{2.33}, \eqref{2.34} and \eqref{2.35} gives
\eqref{2.30}. Moreover, the limit \eqref{2.30} and Brezis-Lieb lemma \cite{F2}
give that
\begin{equation}\label{2.36}
\lim_{n\to\infty}\int_{\mathbb{R}^N} h_1|u_n-u|^{\alpha}dx=0,\quad  
\lim_{n\to\infty}\int_{\mathbb{R}^N} h_2|u_n-u|^{\beta}dx=0.
\end{equation}
Thus, from \eqref{2.36}, it follows that
\begin{equation}\label{2.37}
\begin{split}
&\int_{\mathbb{R}^N}  h_1|u_n|^{\alpha-1}|u_n-u|dx\le
\Big(\int_{\mathbb{R}^N}  h_1|u_n|^{\alpha}dx\Big)^{(\alpha-1)/\alpha}
\Big(\int_{\mathbb{R}^N}  h_1|u_n-u|^{\alpha}dx\Big)^{1/\alpha}
\\
&\le (S_0M^{\alpha}\|h_1V^{-t_1}\|_{\infty})^{(\alpha-1)/\alpha}
\Big(\int_{\mathbb{R}^N}  h_1|u_n-u|^{\alpha}dx\Big)^{1/\alpha}\to
0,\quad \text{as } n\to\infty
\end{split}
\end{equation}
and
\begin{equation}\label{2.38}
\begin{split}
&\int_{\mathbb{R}^N}  h_2|u_n|^{\beta-1}|u_n-u|dx \\
&\le \Big(\int_{\mathbb{R}^N}  h_2|u_n|^{\beta}dx\Big)^{1-1/\beta}
 \Big(\int_{\mathbb{R}^N}  h_2|u_n-u|^{\beta}dx\Big)^{1/\beta}
\\
&\le (S_0M^{\beta}\|h_2V^{-t_2}\|_{\infty})^{1-1/\beta}
\Big(\int_{\mathbb{R}^N} h_2|u_n-u|^{\beta}dx\Big)^{1/\beta}\to 0,
\quad \text{as } n\to\infty.
\end{split}
\end{equation}
Hence,
\begin{equation}\label{2.39}
\int_{\mathbb{R}^N} |f(x,u_n)(u_n-u)|dx\le
\int_{\mathbb{R}^N} (h_1|u_n|^{\alpha-1}+h_2|u_n|^{\beta-1})|u_n-u|dx
\to 0,
\end{equation}
as $n\to\infty$.
This proves the first limit of \eqref{2.31}. The second limit of
\eqref{2.31} can be obtained in a similar way.

To prove the limit \eqref{2.32}, we use  \eqref{1.24} and derive
that
\begin{equation}\label{2.40}
\begin{aligned}
&|F(x,u_n)-F(x,v)|\\
&\le C\Big[h_1(x)(|u_n|^{\alpha-1}+|u|^{\alpha-1})
+h_2(x)(|u_n|^{\beta-1}+|u|^{\beta-1})\Big]|u_n-u|.
\end{aligned}
\end{equation}
Then an application of \eqref{2.37} and \eqref{2.38} yields that
the limit \eqref{2.32}. The  proof  is complete.
\end{proof}

\begin{lemma} \label{lem2.7} 
Let the assumptions in Theorem \ref{thm1.7} hold.  If the sequence $\{u_n\}$ 
satisfies \eqref{2.29},
then the limits \eqref{2.31} and \eqref{2.32} hold.
\end{lemma}

\begin{proof}
Choose $\psi\in C_0^{\infty}(\mathbb{R})$ such that $supp\psi\subset [-2,2]$
and $\psi(t)=1$ on $[-1,1]$. Denote $g(x,t)=\psi(t)f(x,t)$,
 $ H(x,t)=(1-\psi(t))f(x,t)$. Then $f(x,t)=g(x,t)+H(x,t)$. Furthermore,
from \eqref{1.29}, there  exist the constants $a_1,b_1>0$ such that
\begin{equation}\label{2.41}
|g(x,t)|\le a_1|t|^{\alpha-1},\quad 
|H(x,t)|\le b_1|t|^{\beta-1},\quad \forall (x,t)\in\mathbb{R}^N\times\mathbb{R}.
\end{equation}
Denote
\begin{equation}\label{2.42}
A_n=\int_{\mathbb{R}^N} |g(x,u_n)-g(x,u)|^{\alpha'}dx,\quad
D_n=\int_{\mathbb{R}^N} |H(x,u_n)-H(x,u)|^{\beta'}dx,
\end{equation}
where $t'=t/(t-1)$. By \eqref{2.29},  there exist $\omega_1(x)\in
L^{\alpha}(\mathbb{R}^N)$ and $\omega_2(x) \in L^{\beta}(\mathbb{R}^N)$ such that
$|u_n(x)|\le \omega_1(x)$ and $|u_n(x)|\le \omega_2(x)$ a.e. in
$\mathbb{R}^N$ for all $n\ge 1$. Note that
\begin{equation}\label{2.43}
\begin{aligned}
|g(x,u_n)-g(x,u)|^{\alpha'}
& \le C_3(|u_n(x)|^{\alpha}+|u(x)|^{\alpha})\\
&\le C_3(|\omega_1(x)|^{\alpha}+|u(x)|^{\alpha})\equiv d_1(x)\in
L^{1}(\mathbb{R}^N)
\end{aligned}
\end{equation}
and
\begin{equation}\label{2.44}
\begin{aligned}
|H(x,u_n)-H(x,u)|^{\beta'}
&\le C_3(|u_n(x)|^{\beta}+|u(x)|^{\beta})\\
&\le C_3(|\omega_2(x)|^{\beta}+|u(x)|^{\beta})\equiv d_2(x)\in
L^{1}(\mathbb{R}^N),
\end{aligned}
\end{equation}
where $C_3$ is a constant independent of $n$. 
By the Lebesgue dominated
convergence theorem and \eqref{2.29}, we have
\begin{equation}\label{2.45}
\begin{gathered}
\lim_{n\to \infty}A_n = \int_{\mathbb{R}^N} \lim_{n\to
\infty}|g(x,u_n) - g(x,u)|^{\alpha'}dx = 0,\\
 \lim_{n\to \infty}D_n = \int_{\mathbb{R}^N} \lim_{n\to
\infty}|H(x,u_n) - H(x,u)|^{\beta'}dx=0.
\end{gathered}
\end{equation}
Therefore, by the H\"older inequality,
\begin{equation}\label{2.46}
\begin{split}
&\int_{\mathbb{R}^N} |f(x,u_n) - f(x,u)||u_n - u|dx \\
&\le \int_{\mathbb{R}^N}  (|g(x,u_n) - g(x,u)|+|H(x,u_n) - H(x,u)|)|u_n - u|dx
\\
&\le A_n^{1/\alpha'}\|u_n-u\|_{\alpha}+D_n^{1/\beta'}\|u_n-u\|_{\beta} \\
&\le (A_n^{1/\alpha'}+D_n^{1/\beta'})\|u_n-u\|_E
 \le M(A_n^{1/\alpha'}+D_n^{1/\beta'}).
\end{split}
\end{equation}
An application of \eqref{2.45} and \eqref{2.46} gives 
\begin{equation}\label{2.47}
\lim_{n\to \infty}\int_{\mathbb{R}^N} f(x,u_n)(u_n-u)dx
=\lim_{n\to\infty}\int_{\mathbb{R}^N} f(x,u)(u_n-u)dx.
\end{equation}
Similarly, from \eqref{2.41}, \eqref{2.43} and \eqref{2.44}, we can
derive  that
\begin{equation}\label{2.48}
\lim_{n\to \infty}\int_{\mathbb{R}^N} f(x,u)(u_n-u)dx
=\int_{\mathbb{R}^N} \lim_{n\to\infty}f(x,u)(u_n-u)dx=0.
\end{equation}
Consequently, the limit  \eqref{2.31} is given. Similarly,
\eqref{2.32} can be proved and the proof is complete.
\end{proof}

\begin{lemma} \label{lem2.8}  
Let  the assumptions in Theorems \ref{thm1.6} and \ref{thm1.7}  hold. 
 Let $\{u_n\}$  be the sequence in Lemmas \ref{lem2.3}--\ref{lem2.5} satisfying \eqref{2.29}.
 Then  $u$ is a critical point of the  functional
$J$ and  $u_n\to u$ in $E$.
\end{lemma}

\begin{proof}
First, we show that  $J'(u)=0$ in $E^*$.
By Lemmas \ref{lem2.3}--\ref{lem2.5},  the sequence $\{u_n\}$ is bounded in $E$. So,  
there exists a subsequence, still denoted by $\{u_n\}$, such that
  $\{u_n\}$ satisfies \eqref{2.29}. Moreover, one sees that for all 
$\varphi \in   C_0^{\infty}(\mathbb{R}^N)$,
 \begin{equation}\label{2.49}
 \lim_{n\to\infty}\Big(\int_{\mathbb{R}^N}  |\xi|^2(\hat{u_n}-\hat{u })\hat{\varphi}
dx +\int_{\mathbb{R}^N}  V(x)(u_n-u)\varphi dx\Big)=0.
\end{equation}

Under  assumptions  (A3)--(A7), we obtain
\begin{equation}\label{2.50}
\lim_{n\to\infty}\int_{\mathbb{R}^N}  (f(x,u_n)-f(x,u))\varphi dx=0.
\end{equation}
 Furthermore, from \eqref{2.49}, \eqref{2.50} and the assumption  
$J'(u_n)\to 0$ in  $E^*$, we have
\begin{equation}\label{2.51}
0=\lim_{n\to\infty}J'(u_n)\varphi=J'(u)\varphi, \quad \forall
\varphi \in C_0^{\infty}(\mathbb{R}^N).
\end{equation}
By the denseness of $C_0^{\infty}(\mathbb{R}^N)$ in $E$, it follows that
$J'(u)\varphi=0, \forall\varphi\in E$. Hence, $u$ is a critical
point of $J$ in $E$. On the other hand,   from
\eqref{2.29} it follows that
 \begin{equation}\label{2.52}
R_{n}=\int_{\mathbb{R}^N}  |\xi|^{2}\hat{u}(\hat{u}_n-\hat{u})d\xi
+\int_{\mathbb{R}^N}  V(x)u(u_n-u)dx\to 0,\;\;{\rm as}\quad n\to\infty.
\end{equation}
Set
\begin{equation}\label{2.53}
W_{n}:=\int_{\mathbb{R}^N}  f(x,u_n)(u_n-u)dx,\quad
S_{n}:=\int_{\mathbb{R}^N}  f(x,u)(u_n-u)dx,\quad
\forall n\in \mathbb{N}.
\end{equation}
From \eqref{2.31}, it follows that $W_n, S_n\to 0$ as $n\to \infty$
and so
  \begin{equation}\label{2.54}
 J'(u)(u_n-u)=R_{n}-S_n\to 0.
\end{equation}

Similarly, we set
\begin{equation}\label{2.55}
Q_{n}:=(J'(u_n)-J'(u))(u_n-u)=\|u_n-u\|_E^2-W_n+S_n,\quad
\forall n\in \mathbb{N}.
\end{equation}
Obviously, relation \eqref{2.55}  can be reduced to the form
\begin{equation}\label{2.56}
\|u_n-u\|_E^2=W_{n}+Q_{n}-S_{n},\quad \forall n\in \mathbb{N}.
\end{equation}
From  \eqref{2.53}, \eqref{2.54} and $J'(u_n)\to 0$, we
find $Q_{n}\to 0$ and  $\|u_n-u\|_E \to 0$ as $n\to \infty$.
Thus   $u_n\to u$ in $E$  as $n\to\infty$ under assumptions
(A3)--(A7). Therefore, $J$ satisfies the $(C)_c$ condition in $E$
 and the proof  is complete.
\end{proof}

\begin{proof}[Proof of Theorem \ref{thm1.6}]
 Clearly, the functional $J$ defined by \eqref{1.22} is
even. By Lemma \ref{lem2.8}, the functional $J$ satisfies the $(C)_c$
condition. Next, we prove that $J$ satisfies (A8) and (A9) in
Lemma \ref{lem2.1}.
From  (A3), we have
\begin{equation}\label{2.57}
J(u)=\frac{1}{2}\|u\|_E^2-\int_{\mathbb{R}^N}  F(x,u)dx\ge
\frac{1}{2}\|u\|_E^2-\int_{\mathbb{R}^N}(h_1|u|^{\alpha}+h_2|u|^{\beta})dx.
\end{equation}
Arguing as in the proof of \eqref{2.34} and \eqref{2.35}, we obtain
\begin{equation}\label{2.58}
J(u)\ge\frac{1}{2}\|u\|_E^2-S_0M_3(\|u\|_E^{\alpha}+\|u\|_E^{\beta})
\ge\rho^2(\frac{1}{2}-2S_0M_3\rho^{\alpha-2})\ge
\frac{\rho^2}{4}\equiv \alpha_0>0,
\end{equation}
where $M_3=\max\{\|h_1V^{-t_1}\|_{\infty},
\|h_2V^{-t_2}\|_{\infty}\}$  and
$\|u\|_E=\rho=\min\{1,(8S_0M_3)^{\frac{1}{2-\alpha}}\}$.  Thus, by
\eqref{2.58}, condition (A8) is satisfied. We now satisfy
condition (A9). For any finite dimensional subspace $E_0\subset
E$, we assert that there holds $J(u_n)\to -\infty$ when $u_n\in E_0$
and $\|u_n\|_E\to \infty$. Arguing by contradiction, suppose that
for some sequence $\{u_n\}\subset E_0$ with $\|u_n\|_E\to \infty$,
there is $M_4>0$ such that $J(u_n)\ge -M_4$, for all $n\geq 1$. Set
$v_n(x)=\frac{u_n(x)}{\|u_n\|_E}$, then $\|v_n\|_E=1$. Passing to a
subsequence, we may assume that $v_n\rightharpoonup v$ in $E$,
$v_n(x)\to v(x)$ a.e on $\mathbb{R}^N$. Since $E_0$ is finite dimensional,
then $v_n\to v$ in $E_0$ and so $v\not=0$ a.e.in $\mathbb{R}^N$.  Set
$\Omega=\{x\in\mathbb{R}^N:v(x)\not=0\}$, then meas$(\Omega)>0$. For
$x\in\Omega$, we have $\lim_{n\to\infty}|u_n(x)|=\infty$.

 Then,  from (A5) it follows that
\begin{equation}\label{2.59}
\begin{split}
 0&=\limsup_{n\to\infty}\frac{-M}{\|u_n\|_E^{2}}
 \le \limsup_{n\to\infty}\frac{J(u_n)}{\|u_n\|_E^{2}}
 = \limsup_{n\to\infty}\Big[\frac{1}{2}
 -\int_{\mathbb{R}^N}  \frac{F(x,u_n)}{|u_n|^{2}}|v_n|^{2}dx\Big]
\\
&\le \frac{1}{2}-\int_{\mathbb{R}^N}  \liminf_{n\to\infty}
 \frac{F(x,u_n)}{|u_n|^{2}}\chi_{\Omega}(x)|v_n|^{2}dx
=-\infty,
\end{split}
\end{equation}
and  we have a contradiction. So, there exists $R=R(E_0)>0$ such
that $J(u)<0$ for $u\in E_0$ and $\|u\|_E\ge R$.
 Therefore, condition (A9) is satisfied. 
Then an application of Lemma \ref{lem2.1} shows that
\eqref{1.1} admits infinitely many solutions $u_n\in E$ with
$J(u_n)\to \infty$ as $n\to \infty$. 
This completes the proof.
\end{proof}

\begin{proof}[Proof of Theorem \ref{thm1.7}]
 Clearly, the functional $J$ defined by \eqref{1.22} is even.
 By Lemma \ref{lem2.8}, the functional $J$ satisfies the $(C)_c$
condition. Next, we prove that $J$ satisfies (A8) and (A9) in
Lemma \ref{lem2.1}.
From  (A7), we have
\begin{equation}\label{2.60}
J(u)=\frac{1}{2}\|u\|_E^2-\int_{\mathbb{R}^N}  F(x,u)dx\ge
\frac{1}{2}\|u\|_E^2-C_0\int_{\mathbb{R}^N}(|u|^{\alpha}+|u|^{\beta})dx.
\end{equation}
Furthermore,  from \eqref{1.20} it follows that
\begin{equation}\label{2.61}
J(u)\ge\frac{1}{2}\|u\|_E^2-C_4(\|u\|_E^{\alpha}+\|u\|_E^{\beta})
\ge\rho^2(\frac{1}{2}-C_4\rho^{\alpha-2})\ge \frac{\rho^2}{4}\equiv
\alpha_1>0,
\end{equation}
with  $\|u\|_E=\rho=\min\{1,(4C_4)^{\frac{1}{2-\alpha}}\}$ and
$C_4=\max\{S_{\alpha}^{\alpha},S_{\beta}^{\beta}\}$. Thus, by
\eqref{2.61},  condition (A8) is satisfied. Similarly, we can
derive \eqref{2.59} and the verification of condition (A9) is
finished. Again, using Lemma \ref{lem2.1}, we complete the proof of Theorem
\ref{thm1.7}.
\end{proof}

\subsection*{Acknowledgments}
This work is supported by the Fundamental Research Funds for the
Central Universities of China (2015B31014) and  by the National
Natural Science Foundation of China (No.11571092).

The author would like to express his
sincere gratitude to the  reviewers for their valuable comments and
suggestions.


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\end{document}
