\documentclass[reqno]{amsart}
\usepackage{hyperref}

\AtBeginDocument{{\noindent\small
\emph{Electronic Journal of Differential Equations},
Vol. 2016 (2016), No. 70, pp. 1--13.\newline
ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu
\newline ftp ejde.math.txstate.edu}
\thanks{\copyright 2016 Texas State University.}
\vspace{9mm}}

\begin{document}
\title[\hfilneg EJDE-2016/70\hfil Elliptic systems at resonance]
{Elliptic systems at resonance for jumping non-linearities}

\author[H. Lakeha, B. Khodja \hfil EJDE-2016/70\hfilneg]
{Hakim Lakhal, Brahim Khodja}

\address{Hakim Lakhal \newline
Universit\'e de Skikda, B.P. 26 route d'El-Hadaiek, 21000, Alg\'erie}
\email{H.lakhal@univ-skikda.dz}

\address{Brahim Khodja (corresponding author) \newline
Badji Mokhtar University P.O. 12 Annaba, Algeria}
\email{brahim.khodja@univ-annaba.org}

\thanks{Submitted July 26, 2015. Published March 15, 2016.}
\subjclass[2010]{35Q30, 65N12, 65N30, 76M25}
\keywords{Topological degree; elliptic systems; homotopy}

\begin{abstract}
 In this article, we study the existence of nontrivial solutions for the problem
 \begin{gather*}
 -\Delta u=\alpha _1u^{+}-\beta _1u^{-}+f(x,u,v)+h_1( x)
 \quad \text{in }\Omega, \\
 -\Delta v=\alpha _2v^{+}-\beta _2v^{-}+g(x,u,v)+h_2( x)
 \quad \text{in }\Omega, \\
 u=v=0\quad \text{on }\partial \Omega,
 \end{gather*}
 where $\Omega $ is a bounded domain in $\mathbb{R}^{N}$, and
 $h_1,h_2\in L^2( \Omega)$. Here
 $[ \alpha_j,\beta _j] \cap \sigma(-\Delta)={\lambda}$, where
 $\sigma(\cdot)$ is the spectrum.
 We use the  Leray-Schauder degree theory.
\end{abstract}

\maketitle
\numberwithin{equation}{section}
\newtheorem{theorem}{Theorem}[section]
\newtheorem{lemma}[theorem]{Lemma}
\newtheorem{proposition}[theorem]{Proposition}
\allowdisplaybreaks

\section{Introduction and statement of results}

This article is devoted to the study of nonlinear elliptic systems at resonance.
The study of resonant problems started with the seminal work of Landesman
and Lazer (1969/1970), who produced sufficient conditions (which in certain
circumstances are also necessary) for the existence of solutions for some
smooth  semilinear  Dirichlet problems. The corresponding scalar case considered
in \cite{TK2} has shown the existence of solutions to the problem
$ Au=\alpha u^{+}-\beta u^{-}+f(x,u)+h  $, where $A$ is a self-adjoint
operator with compact resolvent in $ L^2( \Omega)$, $f(\cdot,\cdot)$  maps
$\Omega\times\mathbb{R}$ into $\mathbb{R}$, such that
$\lim_{s\to\infty} \frac{f(x,s)}{s}=0$ and
$[ \alpha,\beta] \cap \sigma(A)={\lambda}$, ($\lambda $ a simple eigenvalue of $A $).
The study of nonlinear elliptic systems at resonance has been extensively
studied during recent years (see \cite{HB,MK}). In this work we establish
the existence of weak solutions of the  problem
\begin{equation}\label{e1.1}
\begin{gathered}
-\Delta u=\alpha _1u^{+}-\beta _1u^{-}+f(x,u,v)+h_1( x)
\quad\text{in }\Omega, \\
-\Delta v=\alpha _2v^{+}-\beta _2v^{-}+g(x,u,v)+h_2( x)
\quad \text{in }\Omega, \\
u=v=0\quad \text{on } \partial \Omega,
\end{gathered}
\end{equation}
Where $\Omega $ is a bounded domain in $\mathbb{R}^{N}$
$(N\geq 2)$ with smooth boundary $\partial \Omega $ and
$h=( h_1,h_2)$ is an $ (L^2( \Omega)) ^2$ function.
Let $\overline{\lambda }$ and $\underline{\lambda }$ be defined
as follows
\begin{gather*}
\underline{\lambda }=\sup \{ \lambda _{k}:\lambda _{k}<\lambda,
k\in \mathbb{N}^{\ast }\} , \\
\overline{\lambda }=\inf \{ \lambda _{k}:\lambda _{k}>\lambda,
k\in \mathbb{N}^{\ast }\}.
\end{gather*}
For the rest of this article, we suppose that
 $\alpha _j, \beta _j\in ] \underline{
\lambda }, \overline{\lambda }[=I_\lambda $ satisfy
\begin{equation*}
[ \alpha _j, \beta _j] \cap \sigma(A) ={ \lambda}, j=1,2
\end{equation*}
we denote by $\sigma(A)$ the spectrum of $A$. For $u\in D(A)$, we define the
real function $C(.,.)$ on the square $ I_\lambda\times I_\lambda $
satisfying
\[
 Au=\alpha u^{+}-\beta u^{-}+C(\alpha,\beta)\varphi,\\
 \int_{\Omega} u\varphi=1,
\]
where $\varphi$ is a normalized eigenfunction corresponding to $\lambda$,
$$
 Au=\lambda u, \quad \| u \|_{L^2(\Omega)}=1.
$$
 The function  $C(.,.)$ is continuous on $ I_\lambda\times I_\lambda $ and
strictly decreasing with respect to each variable. Moreover, the curve
 \begin{equation*}
\Sigma= \{(\alpha,\beta)\in I_\lambda\times I_\lambda, C(\alpha,\beta)= \{0\}\}
\end{equation*}
is continuous, passing through the point $(\lambda,\lambda)$ of
$I_\lambda\times I_\lambda $. Let
$$
C^{+,j}=C(\alpha_j,\beta_j), \quad C^{-,j}=C(\beta_j,\alpha_j), j=1,2.
$$
The main idea in \cite{MK} is to present a priori bounds for the solutions
of \eqref{e1.1} where $ C^{+,j}\cdot C^{-,j}\neq 0, j=1,2$.
Always in the system case, the interested reader may refer to \cite{A,D,DR}
and \cite{DY}.
In the present paper we study the case where
$ C^{+,j}\cdot C^{-,j}= 0, (j=1,2)$. Let
\begin{equation*}
N(\alpha, \beta )=\{ u\in D(A),Au=\alpha u^{+}-\beta u^{-}\},
\end{equation*}
then $ N(\alpha, \beta )=\{0\} $ if and only if
$C(\alpha,\beta)\cdot C(\beta,\alpha)\neq {0} $  note that
 $ N(\lambda,\lambda )=N_{\lambda}=\ker(A-\lambda I)$.
The equation of existence of solution for \eqref{e1.1} when
$ N(\alpha, \beta )=\{0\} $ has been studied in \cite{MK}.
The main idea of the paper is to prove the existence of solutions
of semilinear elliptic system of the form \eqref{e1.1} in the case where
$ N(\alpha, \beta )\neq \{0\} $.
There are two cases:
\begin{itemize}
\item If $ C(\beta,\alpha)=C(\alpha,\beta)={0}$, we have (resonance),

\item If $C(\alpha,\beta)={0}\neq C(\beta,\alpha),
\text{ or }C(\beta,\alpha)={0}\neq C(\alpha,\beta) $, we have (semi resonance).
\end{itemize}
We assume that $f,g: \Omega \times\mathbb{R}\times
\mathbb{R}\to \mathbb{R}$ are continuous functions satisfying the condition below:
\begin{equation}\label{cr}
\begin{gathered}
 |f(x,s,t)|\leq c_1( 1+|s|+|t|), \\
 |g(x,s,t)|\leq c_2( 1+ |s|+ |t|),
\end{gathered}
\end{equation}
where $c_1,c_2$ are real positive constants.
\begin{equation}\label{lim}
\begin{gathered}
 \lim_{s,|t|\to\infty}f(.,t,s)=\gamma _1^{+}, \quad
\lim_{-s,|t|\to\infty}f(.,t,s)=\gamma_1^{-},\\
\gamma_1^{-},\gamma_1^{+} \in L^2( \Omega), \quad
\gamma _1^{-}\leq f(x,t,s)\leq \gamma _1^{+},
\end{gathered}
\end{equation}
and
\begin{equation}\label{bo}
\begin{gathered}
 \lim_{t,|s|\to\infty}g(.,t,s)=\gamma _2^{+}, \quad
\lim_{-t,|s|\to\infty}g(.,t,s)=\gamma_2^{-},\\
\gamma_2^{-},\gamma_2^{+} \in L^2( \Omega), \quad
\gamma _2^{-}\leq g(x,t,s)\leq \gamma _2^{+}.
\end{gathered}
\end{equation}
 Let $\theta _1=(\mu _{3},\mu _4)$ and
$\theta _2=(\mu _1,\mu _2)$ be defined as follows
\begin{equation}\label{h}
\begin{gathered}
-\Delta \mu _j=\alpha _j\mu _j^{+}-\beta _j\mu _j^{-},\quad
 \int_{\Omega}\mu _j\varphi =-1\\
 \text{when }C( \beta _j,\alpha _j) =0,\;( j=1,2),\\
-\Delta \mu _{j+2}=\alpha _j\mu _{j+2}^{+}-\beta _j\mu _{j+2}^{-},\quad
\int_{\Omega}\mu _{j+2}\varphi =1\\
\text{when  }C( \alpha_j,\beta _j) =0,\;( j=1,2).
\end{gathered}
\end{equation}
Our main theorem read as follows:

\begin{theorem}\label{thm1}
Assume that \eqref{cr}, \eqref{lim}, \eqref{bo} and \eqref{h} are fulfilled.
For each $( h_1,h_2) \in ( L^2( \Omega))^2 $. We define
\[
H_{i}( h_j) =\int_{\Omega}
h_j\mu _{i}dx+\int_{\Omega}
\gamma _j^{+}\mu _{i}^{+}dx-
\int_{\Omega}\gamma _j^{-}\mu _{i}^{-}dx, \quad i\in\{1,2,3,4\},\; j=1,2.
\]
\begin{itemize}
\item[(i)] If $C^{+,j} =C^{-,j} =0$, \eqref{e1.1} has at least one solution.
For every $h_j\in L^2(\Omega)$ such that $H_j( h_j).H_{j+2}(h_j)>0$,
$ j=1,2$.

\item[(ii)] If $C^{+,j} =0\neq C^{-,j}$ (resp $C^{-,j} =0\neq C^{+,j}$),
\eqref{e1.1} has at least one solution. For every $h_j\in L^2(\Omega)$ such that
$C^{-,j}H_{j+2}( h_j)<0$ (resp $C^{+,j}.H_j( h_j)<0$), $ j=1,2$.
\end{itemize}
\end{theorem}

In the case $\alpha_j=\beta_j\neq\lambda$, $j=1,2$ see \cite{MK}
(resp $\alpha_j=\beta_j=\lambda, j=1,2$ see \cite{HB}), we obtain the
result of solutions existence.

\section{Preliminaries}

Let us consider the space
$$
U=H_0^1(\Omega )\times H_0^1(\Omega ),
$$
which is a Banach space endowed with the norm
$$
\|(u,v)\|_{U}^2=\| u \|_{H_0^1(\Omega )}^2
+\| v\| _{H_0^1(\Omega )}^2,
$$
and let us take $ V=L^2(\Omega )\times L^2(\Omega )$. In the sequel,
$\|\cdot\| _{L^2(\Omega )}$ and $\|\cdot\|_{H_0^1(\Omega )}$
will denote the usual norms on $L^2(\Omega )$ and $H_0^1(\Omega )$
respectively. Recalling that the operator $A$, given by
\begin{gather*}
Au=-\Delta u\\
D(A)=\{ u\in H_0^1(\Omega ),\Delta u\in L^2(\Omega )\},
\end{gather*}
defines an inverse compact on $L^2(\Omega )$ and his spectrum is formed
by the sequence $(\lambda _{k}) _{k\in\mathbb{N}^{\ast }}$
such that $|\lambda _{k}| \to +\infty $
and $\lambda _1$ the first eigenvalue is positive. Throughout this paper,
we denote by $\lambda $ a simple eigenvalue of $A$, $\varphi $ is an
eigenfunction associated to $\lambda $ normalized in $L^2(\Omega )$,
$ \Pr $ designates the orthogonal projection of $ V $ on $( \varphi^{\bot })^2$
 $( \varphi^{\bot }$ is the orthogonal of $\varphi$ in $L^2(\Omega))$.
We recall the following proposition proved by Gallouet and Kavian (see \cite{TK1}).

\begin{proposition} \label{prop2.1}
For all $\alpha ,\beta \in ] \underline{\lambda },\overline{\lambda }
[$, there exist a unique $C( \alpha ,\beta) \in\mathbb{R}$, and a unique $u\in D(A)$,
such that
\begin{gather*}
-\Delta u=\alpha u^{+}-\beta u^{-}+C( \alpha ,\beta) \varphi ,\\
\int_{\Omega}u\varphi =1.
\end{gather*}
\end{proposition}

The next result is given in a general framework.

\begin{proposition} \label{prop2.2}
Let $Q(x,s):\Omega\times\mathbb{R}\to\mathbb{R}$, measurable on
$x\in \Omega $ and continuous on $s\in \mathbb{R}$, function verifying
\begin{itemize}
\item[(i)] There exists $\alpha ,\beta \in\mathbb{R}$ such that
$ \underline{\lambda }<\alpha \leq \frac{Q(x,s)-Q(x,t)}{s-t}
 \leq \beta <\overline{\lambda }$ for all $s,t\in \mathbb{R}$, a.e. in $\Omega$,

\item[(ii)]
$\lim_{| s| \to +\infty } \frac{Q(x,s)}{s}=l$  a.e. in $\Omega$,

\item[(iii)]  $Q(x,0)=0$ a.e. in $\Omega$. Then
for all $s\in \mathbb{R}$ and all $Q_0\in \varphi ^{\bot }$, there exists a unique
$v\in  D(A)\cap  \varphi^{\bot }$
such that
$$
Av=\Pr Q(. ,v+s\varphi )+ Q_0.
$$
\end{itemize}
\end{proposition}

The proof of the above proposition can be found also in \cite{TK1}.
For $t\in[ 0,1] $ and $( u,v)\in( L^2(\Omega)) ^2$ we define
\begin{equation*}
H(t,u,v)=
\begin{pmatrix}
A^{-1} &  \\
& A^{-1}
\end{pmatrix})
\begin{pmatrix}
 \alpha _1u^{+}-\beta _1u^{-}+tf(x,u,v)+(1-t)( \beta_1-\alpha _1) u^{-} \\
 \alpha _2v^{+}-\beta _2v^{-}+tg(x,u,v)+(1-t)( \beta_2-\alpha _2) v^{-}
\end{pmatrix}
\end{equation*}
The following two problems are equivalent:
\begin{gather*}
-\Delta u= \alpha _1u^{+}-\beta _1u^{-}+tf(x,u,v)+(1-t)(
\beta _1-\alpha _1) u^{-}+h_1( x), \\
-\Delta v= \alpha _2v^{+}-\beta _2v^{-}+tg(x,u,v)+(1-t)(\beta _2-\alpha _2)
 v^{-}+h_2( x), \\
( u,v) \in (D(A))^2,
\end{gather*}
and
\begin{gather*}
(u,v)=H(t,u,v)+(A^{-1}h_1,A^{-1}h_2),\\
( u,v) \in (D(A))^2,h\in(L^2(\Omega )) ^2,
\end{gather*}
$H(t,u,v):[ 0,1] \times V\to V $ is compact.

\section{A priori bounds for solutions of \eqref{e1.1}}

\begin{lemma} \label{lem3.1}
Under the assumptions of theorem \ref{thm1}, and assuming that
  $H_j(h_j) <0$, and  $H_{j+2}( h_j)<0,$ with $\alpha _j< \beta _j, j=1,2$.
There exist $R>0$ such that
for all $t\in[ 0,1]$ and all $( u,v) \in U$,
\[
(u,v) -H(t,u,v)=0\Longrightarrow \|(u,v)\|_{U}<R.
\]
\end{lemma}

\begin{proof}
To prove this lemma we assume by contradiction, that for all $ R >0$ there exists
 $( t,u,v) \in [ 0,1] \times U $ such that
\begin{equation*}
( u,v) -H(t,u,v)=0\quad\text{and}\quad \|( u,v)\| _{U}>R,
\end{equation*}
In other words, we can find a sequence $(t_n,u_n,v_n)
\in [ 0,1] \times U$ such that
\begin{equation} \label{e3.1}
( u_n,v_n) -H(t_n,u_n,v_n)=0\quad\text{and}\quad
b_n=\|( u_n,v_n) \| _{U}>n.
\end{equation}
Taking
\begin{equation*}
w_n=( w_{n,1},w_{n,2}) =\Big( \frac{u_n}{\|(
u_n,v_n) \| _{U}},\frac{v_n}{\|(
u_n,v_n) \| _{U}}\Big),
\end{equation*}
then it follows with this choice of $w_n$ that
\begin{equation*}
w_n=( w_{n,1},w_{n,2}) \in ( D(A))^2\quad\text{and}\quad \| w_n\| _{U}=1.
\end{equation*}
Indeed, it is easy to see that $\| w_n\| _{U}=1$. Let us show that
$w_n\in ( D(A)) ^2$. We have
\begin{gather}
\begin{aligned}
&-\Delta w_{n,1} \\
&=\frac{1}{b_n}[ \alpha _1u_n^{+}-\beta
_1u_n^{-}+t_nf(x,u_n,v_n)+(1-t_n)( \beta _1-\alpha_1) u_n^{-}+h_1( x)],
\end{aligned} \label{e3.2}\\
\begin{aligned}
&-\Delta w_{n,2} \\
&=\frac{1}{b_n}[ \alpha _2v_n^{+}-\beta
_2v_n^{-}+t_ng(x,u_n,v_n)+(1-t_n)( \beta _2-\alpha_2) v_n^{-}+h_2( x)].
\end{aligned} \label{e3.3}
\end{gather}
From \eqref{cr} and noticing that $( a+b)^2\leq2( a^2+b^2)$, we obtain
the following estimate
\begin{align*}
\int_{\Omega }| f(x,u_n,v_n)| ^2dx
&\leq\int_{\Omega }c_1^2( 1+| u_n| +| v_n|) ^2dx \\
&\leq 2c_1^2\int_{\Omega }( ( 1+| u_n|) ^2+| v_n| ^2) dx
\leq c'( 1+\| u_n\|_{H_0^1}^2+\| v_n\|_{H_0^1}^2),
\end{align*}
where $c'$ is a positive constant. Therefore,
$$
\int_{\Omega }\frac{| f(x,u_n,v_n)| ^2}{\|
( u_n,v_n)\|_{U}^2}dx
\leq c'(  \frac{1}{\|( u_n,v_n) \|_{U}^2}+\frac{\| u_n\| ^2}{\|(u_n,v_n)\|_{U}^2}
+\frac{\| v_n\| ^2}{\|( u_n,v_n) \| _{U}^2}).
$$
Then
$$
\int_{\Omega}
\frac{| f(x,u_n,v_n)| ^2}{\|
( u_n,v_n)\|_{U}^2}dx \leq c'( \frac{1}{n^2}+1) \leq 2c';
$$
that is, $\frac{f(x,u_n,v_n)}{\| ( u_n,v_n)\| _{U}}$
is bounded in $L^2(\Omega ).$ Similarly, the function $
\frac{g(x,u_n,v_n)}{\| ( u_n,v_n) \| _{U}}$ is bounded in
$L^2(\Omega )$. Moreover, by \eqref{e3.1} we have
\begin{gather*}
\frac{\| h_1\| _{L^2(\Omega )}}{\| (u_n,v_n)\|_{U}}\leq \frac{\| h_1\|
_{L^2(\Omega )}}{n}\leq \| h_1\| _{L^2(\Omega )},
\\
\frac{\| h_2\| _{L^2(\Omega )}}{\| (u_n,v_n)\|_{U}}\leq \frac{\| h_2\|
_{L^2(\Omega )}}{n}\leq\| h_2\|_{L^2(\Omega )},
\end{gather*}
then the right hand side of \eqref{e3.2} is bounded in $L^2(\Omega)$ for all $n$,
thus
$$
\frac{1}{b_n}[ \alpha _1u_n^{+}-\beta
_1u_n^{-}+t_nf(x,u_n,v_n)+(1-t_n)( \beta _1-\alpha_1) u_n^{-}+h_1( x) ] \in L^2(\Omega).
$$
Similarly we have
$$
\frac{1}{b_n}[ \alpha _2v_n^{+}-\beta
_2v_n^{-}+t_ng(x,u_n,v_n)+(1-t_n)( \beta _2-\alpha_2) v_n^{-}+h_2( x) ] \in L^2(\Omega).
$$
Since $( w_{n,1},w_{n,2})\in ({H_0^1(\Omega)})^2 $ and the embedding
$(  H_0^1(\Omega)\hookrightarrow L^2(\Omega))$ is compact, we can extract a
subsequence $(t_n,w_{n,1},w_{n,2})  $, still denoted by $(  t_n,w_{n,1},w_{n,2})$,
which converges in $[  0,1]\times V$. Let
$(t,w_1,w_2)$ be the limit of $(t_n,w_{n,1},w_{n,2})$ in $[0,1]\times V$.
From the hypothesis \eqref{lim} and \eqref{bo} it follows that
\begin{align*}
\frac{f(x,u_n,v_n)}{\| (  u_n,v_n)\|_{U}}
&=\frac{u_n}{\| (u_n,v_n)  \| _{U}}\frac{f(x,u_n,v_n)}{u_n}\\
&=w_{n,1}\frac{f(x,w_{n,1}\| (u_n,v_n,)
 \| _{U},v_n)}{w_{n,1}\| (u_n,v_n)  \|_{U}}\text{}\underset{n\to\infty
}{\to0}\quad \text{a.e. in }\Omega,\\
\frac{g(x,u_n,v_n)}{\| (  u_n,v_n)\| _{U}}
&=\frac{v_n}{\| (  u_n,v_n)\| _{U}}\frac{g(x,u_n,v_n)}{v_n}\\
&=w_{n,2}\frac{g(x,u_n,w_{n,2}\| (u_n,v_n)\| _{U})}{w_{n,2}\|(u_n
,v_n)\| _{U}}\text{}\underset{n\to\infty}{\to0}\quad \text{a.e. in }\Omega,
\end{align*}
and since the sequences $w_{n,1}$, $w_{n,2}$ are bounded in $L^2(\Omega)$, we get
\begin{gather*}
\frac{f(x,u_n,v_n)}{\| (  u_n,v_n)\| _{U}}
\leq c_1(  1+| w_{n,1}| +  | w_{n,2}| )\leq c'\quad \text{a.e. in }\Omega,\\
\frac{g(x,u_n,v_n)}{\| (  u_n,v_n)\| _{U}
}\leq c_2(1+| w_{n,1}| +| w_{n,2}|)  \leq
c''\quad \text{a.e. in }\Omega,
\end{gather*}
where $c',c''$ are real positive constants.
  Thanks to Lebesgue's convergence theorem, we deduce that
\begin{gather*}
\frac{f(x,u_{u},v_n)}{\|( u_n,v_n)\|_{U}}\to 0 \quad\text{in }L^2( \Omega),n\to \infty,
\\
\frac{g(x,u_n,v_n)}{\|( u_n,v_n)\|_{U}}\to 0 \quad \text{in }L^2( \Omega),n\to \infty,
\end{gather*}
and consequently
\begin{gather*}
-\Delta w_{n,1}\to [ \alpha _1w_1^{+}-\beta
_1w_1^{-}+(1-t)( \beta _1-\alpha _1) w_1^{-}], \\
-\Delta w_{n,2}\to [ \alpha _2w_2^{+}-\beta
_2w_2^{-}+(1-t)( \beta _2-\alpha _2) w_2^{-}], \\
\|( w_{1,n},w_{2,n})\|_{U}=1.
\end{gather*}
Then
\begin{gather*}
-\Delta w_1=\alpha _1w_1^{+}-\beta _1w_1^{-}+(1-t)( \beta
_1-\alpha _1) w_1^{-}, \\
-\Delta w_2=\alpha _2w_2^{+}-\beta _2w_2^{-}+(1-t)( \beta
_2-\alpha _2) w_2^{-}.
\end{gather*}

\subsection*{Case I: $\int_{\Omega }w_1\varphi =\int_{\Omega }w_2\varphi =0$}
Then projecting on $\varphi ^{\perp }$ we have
\begin{gather*}
-\Delta w_1=\Pr[ \alpha _1w_1^{+}-\beta
_1w_1^{-}+(1-t)( \beta _1-\alpha _1) w_1^{-}], \\
-\Delta w_2=\Pr[ \alpha _2w_2^{+}-\beta
_2w_2^{-}+(1-t)( \beta _2-\alpha _2) w_2^{-}].
\end{gather*}
Using proposition \ref{prop2.2}, $( s=0,Q_0=0) $ we see that $%
w_1=w_2=0$, this is contradiction with $\| w\|_{U}=1$. Hence
$\int_{\Omega }w\varphi \neq 0$.

\subsection*{Case II: $\int_{\Omega }w_1\varphi\neq 0$}
If $\int_{\Omega }w_1\varphi =\theta >0$, then $\mu =\frac{w_1}{\theta }$ verifies
$$
A\mu = \alpha _1\mu ^{+}-( \beta _1+(1-t)( \alpha_1-\beta _1)) \mu ^{-}  ,
\quad \int_{\Omega }\mu \varphi =1,
$$
 from proposition \ref{prop2.1}, we deduce that
\[
C( \alpha _1,\beta _1+(1-t)( \alpha _1-\beta _1)) =0.
\]
The function $C(\cdot,\cdot)$ is strictly decreasing with respect to each
 variable, with  $ \beta _1>\alpha _1$ and $ t<1 $,  we have
\[
C( \alpha _1,\beta _1+(1-t)( \alpha _1-\beta _1)) >C( \alpha _1,\beta _1)=0 ,
\]
which is a contradiction.
If $\int_{\Omega }w_1\varphi =\theta <0$, $\mu =\frac{w_1}{\theta }$,
we obtain a contradiction as a similar argument with the above step.

\subsection*{Case  III: $\int_{\Omega }w_2\varphi\neq 0$}
A similar argument can be made when $\int_{\Omega}w_2\varphi\neq 0 $.
Let us assume $t=1$ i.e $t_n\to1$. Now, however, we have no contradiction
since $(w_1,w_2)\in N(\alpha _j,\beta _j)$ and
\begin{equation}
\begin{gathered}
Aw_1=\alpha_1 w_1^{+}-\beta_1 w_1^{-},\quad (w_1,w_2)\in N(\alpha _1,\beta _1), \\
Aw_2=\alpha_2 w_2^{+}-\beta_2 w_2^{-},\quad (w_1,w_2)\in N(\alpha _2,\beta _2),
\end{gathered}
\end{equation}
we can write
\begin{gather*}
w_j=a_j\mu _{j+2}\text{ if  }a_j=\int_{\Omega }w_j\varphi dx>0,\quad j=1,2, \\
w_j=a_j\mu _j\text{ if }-a_j=\int_{\Omega }w_j\varphi dx<0,\quad j=1,2,
\end{gather*}
defining
\begin{equation*}
a_{n,j}\in \mathbb{R}, \quad
z_{n,j}\in D(A),\quad
a_{n,j}=-\int_{\Omega }w_{n,j}\varphi dx,z_{n,j}=w_{n,j}-a_{n,j}\mu _j,
\end{equation*}
in such a way that
\begin{equation*}
w_{n,j}=z_{n,j}+a_{n,j}\mu _j, \quad a_{n,j}\to a_j, \quad
\| z_{n,j}\|_{D(A)}\to 0,\quad z_{n,j}\in \varphi ^{\perp },
\end{equation*}
if $a_j\neq 0$ we claim that
\begin{equation} \label{e3.5}
\exists M>0\text{ such that  }\forall n\geq 1,\quad
b_n\| z_{n,j}\| _{D(A)}\leq M, \quad j=1,2.
\end{equation}

When $\int_{\Omega }w_1\varphi dx<0$,
if \eqref{e3.5} is established,  multiplying  \eqref{e3.2}
on both sides by $\mu _1 $ gives
\begin{align*}
 b_n\int_{\Omega }-\Delta w_{n,1}\mu _1dx
&=b_n\int_{\Omega }( \alpha _1w_{n,1}^{+}-\beta
_1w_{n,1}^{-}) \mu _1dx+(1-t_n)( \beta _1-\alpha
_1) w_{n,1}^{-}\mu _1dx, \\
&\quad +\int_{\Omega }t_nf(x,b_nw_{n,1},v_n)\mu _1dx+h_1( x)\mu _1dx\,.
\end{align*}
For $n$ large enough,  $\int_{\Omega }w_{n,1}^{-}\mu _1\leq0$, because
$w_{n,1}^{-}\to a_1\mu _1^{-}$ in $L^2,a_1>0$, hence
\begin{equation} \label{e3.6}
\begin{aligned}
&t_n\int_{\Omega }f(x,b_nw_{n,1},v_n)\mu _1dx+h_1( x) \mu _1dx\\
&\geq b_n\int_{\Omega }-\Delta w_{n,1}\mu _1dx-b_n\int_{\Omega
}( \alpha_1w_{n,1}^{+}-\beta_1w_{n,1}^{-}) \mu _1dx,
\end{aligned}
\end{equation}
noticing that
$$
E_{n,1}=\int_{\Omega }-\Delta w_{n,1}\mu _1dx-\int_{\Omega }(
\alpha _1w_{n,1}^{+}-\beta _1w_{n,1}^{-}) \mu _1dx,
$$
because $( A=A^{\ast }) $;
$$
E_{n,1}=\int_{\Omega }w_{n,1}( -\Delta \mu _1)
dx-\int_{\Omega }( \alpha _1w_{n,1}^{+}-\beta _1w_{n,1}^{-})
\mu _1dx,
$$
then
$$
E_{n,1}=\int_{\Omega }w_{n,1}( \alpha _1\mu _1^{+}-\beta _1\mu
_1^{-}) dx-\int_{\Omega }( \alpha _1w_{n,1}^{+}-\beta
_1w_{n,1}^{-}) \mu _1dx,
$$
that is
$$
E_{n,1}=\alpha _1\int_{\Omega }( w_{n,1}^{+}\mu _1^{-} -w_{n,1}^{-}\mu
_1^{+}) -\beta _1\int_{\Omega }( w_{n,1}^{+}\mu
_1^{-}-w_{n,1}^{-}\mu _1^{+}) dx,
$$
hence
\begin{equation} \label{e3.7}
| E_{n,1}| \leq | \beta _1-\alpha_1|
\Big( \int_{\Omega }w_{n,1}^{+}\mu _1^{-}+\int_{\Omega}w_{n,1}^{-}\mu _1^{+}\Big) .
\end{equation}
If $x\in \Omega $ is such that
$\mu _1(x)\geq 0$ and $w_{n,1}( x) =z_{n,1}( x)
+a_{n,1}\mu _1( x) \leq 0$,
then
$$
z_{n,1}( x) \leq 0\quad\text{and}\quad
0\leq \mu _1(x)=\frac{w_{n,1}( x) -z_{n,1}( x) }{a_{n,1}}
\leq \frac{| z_{n,1}( x)| }{a_{n,1}},
$$
we obtain
$$
w_{n,1}^{-}( x) \mu _1^{+}( x) \leq \frac{|
z_{n,1}( x)| ^2}{a_{n,1}}\quad \text{a.e. in }\Omega,
$$
using the same arguments, one can see that
$$
w_{n,1}^{+}( x) \mu _1^{-}( x) \leq \frac{|
z_{n,1}( x)| ^2}{a_{n,1}}\quad\text{a.e. in }\Omega,
$$
From these inequalities and \eqref{e3.7},  we deduce
$$
| E_{n,1}| \leq 2| \beta _1-\alpha
_1| \frac{\| z_{n,1}\| _{L^2(\Omega) }^2}{a_{n,1}};
$$
hence, \eqref{e3.5} implies that
$$
b_n| E_{n,1}| \leq 2M| \beta _1-\alpha
_1| \frac{\| z_{n,1}\|_{D(A)}}{a_{n,1}},
$$
and $\lim_{n\to \infty } b_n| E_{n,1}| =0$.
Now coming back to formula \eqref{e3.6},
\begin{align*}
J_{n,1}&=t_n\int_{\Omega }f(x,b_nw_{n,1},v_n)\mu _1dx+h_1(x) \mu _1dx \\
&\geq b_n\int_{\Omega }-\Delta w_{n,1}\mu _1dx
-b_n\int_{\Omega}( \alpha _1w_{n,1}^{+}-\beta _1w_{n,1}^{-}) \mu _1dx.
\end{align*}
From the hypothesis \eqref{lim},
\begin{equation*}
\gamma _1^{-}\leq f(x,s,t)\leq \gamma _1^{+},
\end{equation*}
we have
\[
J_{n,1}=t_n\int_{\Omega }f(x,u_n,v_n)\mu _1dx+h_1( x)
\mu _1dx\leq t_n\int_{\Omega }\gamma _1^{+}\mu _1^{+}-\gamma
_1^{-}\mu _1^{-}dx+h_1( x) \mu _1dx,
\]
which gives
\[
b_nE_{n,1}\leq t_n\int_{\Omega }\gamma _1^{+}\mu _1^{+}-\gamma
_1^{-}\mu _1^{-}dx+h_1( x) \mu _1dx.
\]
Passing to the limit we obtain
\begin{equation*}
0\leq \int_{\Omega }\gamma _1^{+}\mu _1^{+}-\gamma _1^{-}\mu
_1^{-}dx+h_1( x) \mu _1dx=H_1(h_1),
\end{equation*}
which contradicts $H_1( h_1) <0$.

When $\int_{\Omega }w_2\varphi dx<0$, we multiply \eqref{e3.3} on
both sides by $\mu _2 $,
\begin{align*}
& b_n\int_{\Omega }-\Delta w_{n,2}\mu _2dx\\
&= b_n\int_{\Omega }( \alpha _2w_{n,2}^{+}-\beta
_2w_{n,2}^{-}) \mu _2dx+(1-t_n)( \beta _2-\alpha
_2) w_{n,2}^{-}\mu _2dx \\
&\quad +\int_{\Omega }t_ng(x,u_n,b_nw_{n,2})\mu _2dx+h_2( x)\mu _2dx\,.
\end{align*}
By the same arguments used in the precedent step with
\begin{equation*}
\gamma _2^{-}\leq g(x,s,t)\leq \gamma _2^{+},
\end{equation*}
we have
\begin{equation*}
J_{n,2}=t_n\int_{\Omega }g(x,u_n,v_n)\mu _2dx+h_2( x)
\mu _2dx\leq t_n\int_{\Omega }\gamma _2^{+}\mu _2^{+}-\gamma
_2^{-}\mu _2^{-}dx+h_2( x) \mu _2dx\,.
\end{equation*}
This gives a contradiction with $H_2( h_2) <0$.

When $\int_{\Omega }w_1\varphi dx>0$
defining
\begin{equation*}
a_{n,j}\in \mathbb{R}, \quad
z_{n,j}\in D(A),\quad
a_{n,j}=\int_{\Omega }w_{n,j}\varphi dx,\quad
z_{n,j}=w_{n,j}-a_{n,j}\mu _{j+2},
\end{equation*}
in such a way that
\begin{equation*}
w_{n,j}=z_{n,j}+a_{n,j}\mu _{j+2},\quad
a_{n,j}\to a_j,\quad
\| z_{n,j}\|_{D(A)}\to 0, \quad
z_{n,j}\in \varphi ^{\perp },
\end{equation*}
we multiply \eqref{e3.2} on both sides by $\mu _{3} $,
\begin{align*}
b_n\int_{\Omega }-\Delta w_{n,1}\mu _{3}dx
&= b_n\int_{\Omega }( \alpha _1w_{n,1}^{+}-\beta
_1w_{n,1}^{-}) \mu _{3}dx+(1-t_n)( \beta _1-\alpha
_1) w_{n,1}^{-}\mu _{3}dx \\
&\quad +\int_{\Omega }t_nf(x,b_nu_n,w_{n,2})\mu _{3}dx+h_2( x)\mu _{3}dx\,.
\end{align*}
By the same arguments used in the precedent step with
$\gamma _1^{-}\leq f(x,s,t)\leq \gamma _1^{+}$,
we have
\begin{equation*}
J_{n,1}=t_n\int_{\Omega }f(x,u_n,v_n)\mu _{3}dx+h_2( x)
\mu _{3}dx\leq t_n\int_{\Omega }\gamma _1^{+}\mu _{3}^{+}-\gamma
_1^{-}\mu _{3}^{-}dx+h_2( x) \mu _{3}dx,
\end{equation*}
gives a contradiction to $H_{3}( h_2) <0$.

When $\int_{\Omega }w_2\varphi dx>0$
Multiply \eqref{e3.3} on both sides by $\mu _4 $,
\begin{align*}
b_n\int_{\Omega }-\Delta w_{n,2}\mu _4dx
&= b_n\int_{\Omega }( \alpha _2w_{n,2}^{+}-\beta
_2w_{n,2}^{-}) \mu _4dx+(1-t_n)( \beta _2-\alpha
_2) w_{n,2}^{-}\mu _4dx \\
&\quad +\int_{\Omega }t_ng(x,u_n,b_nw_{n,2})\mu _4dx+h_2( x)\mu _4dx,.
\end{align*}
By the same arguments used in the precedent step, with
$\gamma _2^{-}\leq g(x,s,t)\leq \gamma _2^{+}$,
we have
\begin{equation*}
J_{n,2}=t_n\int_{\Omega }f(x,u_n,v_n)\mu _4dx+h_2( x) \mu _4dx
\leq t_n\int_{\Omega }\gamma _2^{+}\mu _4^{+}-\gamma
_2^{-}\mu _4^{-}dx+h_2( x) \mu _4dx,
\end{equation*}
give a contradiction with $H_4( h_2) <0$.

Now, if \eqref{e3.5} does not hold, there exists a subsequence
denoted by $b_n\| z_n\| _{( D(A)) ^2}$,
such that $\lim_{n\to \infty } b_n\| z_n\| _{( D(A)) ^2}\to \infty$. Let
\begin{gather*}
c_n=\| z_n\|_{( D( A))^2},\\
y_n=( y_{n,1},y_{n,2})
=\Big(\frac{z_{n,1}}{\| z_n\|_{( D(A))^2}},\frac{z_{n,2}}{\| z_n\|_{( D(A))^2}}\Big)
=\frac{z_n}{c_n},
\end{gather*}
$y_n\in ( D(A))^2$, $\| y_n\|_{(D(A))^2}=1$. The inclusion 
$D(A)\hookrightarrow L^2(\Omega )$ being compact there is a subsequence
(still denoted by) $ y_n=( y_{n,1},y_{n,2})$ such that
\begin{equation}
\begin{gathered}
( y_{n,1},y_{n,2}) \to ( y_1,y_2)\text{ in }V, \quad
 A(y_n)\to A(y)\text{ in }V\text{ weak }y\in( \varphi^{\bot })^2 ,\\
 y_n(x) \to y(x) \quad \text{ a.e. in }\Omega.
\end{gathered}
\end{equation}
There exists $( k_1,k_2) \in V$ , such that
\[
| y_{n,1}(x)| \leq k_1(x) \text{ a.e}, \quad
| y_{n,2}(x)| \leq k_2( x) \text{ a.e}.
\]
On the other hand $w_{n,j}=z_{n,j}+a_{n,j}\mu _j, j=1,2$ satisfies
\begin{gather*}
-\Delta w_{n,1}
= \alpha_1 w_{n,1}^{+}-\beta_1 w_{n,1}^{-}
 +t_n\frac{f(.,b_nw_{n,1},v_n)}{b_n}
 +(1-t_n)(\beta _1-\alpha _1) w_{n,1}^{-}+\frac{h_1}{b_n},  \\
-\Delta w_{n,2} = \alpha_2 w_{n,2}^{+}-\beta_2 w_{n,2}^{-}
 +t_n\frac{g(.,u_n,b_nw_{n,2})}{b_n}\\
 +(1-t_n)( \beta _2-\alpha _2) w_{n,2}^{-}+\frac{h_2}{b_n}.
\end{gather*}
Multiplying the first equation by $ \mu _1/c_n$, and the second
equation by $\mu _2/c_n$, we have
\begin{gather*}
\begin{aligned}
\frac{1}{c_n}\int_{\Omega }-\Delta w_{n,1}\mu _1
&=\frac{1}{c_n}\int_{\Omega }( \alpha _1w_{n,1}^{+}-\beta _1w_{n,1}^{-})
\mu _1+t_n\int_{\Omega }( \frac{f(.,b_nw_{n,1},v_n)}{b_nc_n%
}) \mu _1 \\
&\quad +\frac{1}{c_n}\int_{\Omega }(1-t_n)( \beta _1-\alpha _1)
w_{n,1}^{-}\mu _1+\int_{\Omega }\frac{h_1}{b_nc_n}\mu _1,
\end{aligned}\\
\frac{1}{c_n}\int_{\Omega }-\Delta w_{n,2}\mu _2
=\frac{1}{c_n}\int_{\Omega }( \alpha _2w_{n,2}^{+}-\beta _2w_{n,2}^{-})
\mu _2+t_n\int_{\Omega }\frac{g(.,u_n,b_nw_{n,2})}{b_nc_n}\mu_2
\\
\frac{1}{c_n}\int_{\Omega }(1-t_n)( \beta _2-\alpha _2)
w_{n,2}^{-}\mu _2+\int_{\Omega }\frac{h_2}{b_nc_n}\mu _2\,.
\end{gather*}
$A=A^{\ast }$ gives
\begin{align*}
\frac{1}{c_n}\int_{\Omega }w_{n,1}(-\Delta \mu _1)
&=\frac{1}{c_n}
\int_{\Omega }( \alpha _1w_{n,1}^{+}-\beta _1w_{n,1}^{-})
\mu _1+t_n\int_{\Omega }( \frac{f(.,b_nw_{n,1},v_n)}{
b_nc_n}) \mu _1 \\
&\quad +\frac{1}{c_n}\int_{\Omega }(1-t_n)( \beta _1-\alpha _1)
w_{n,1}^{-}\mu _1+\int_{\Omega }\frac{h_1}{b_nc_n}\mu _1,
\\
\frac{1}{c_n}\int_{\Omega }w_{n,2}( -\Delta \mu _2)
&=\frac{1}{c_n}\int_{\Omega }( \alpha _2w_{n,2}^{+}
 -\beta_2w_{n,2}^{-}) \mu _2+t_n\int_{\Omega }\frac{
g(.,u_n,b_nw_{n,2})}{b_nc_n}\mu _2
\\
&\quad +\frac{1}{c_n}\int_{\Omega }(1-t_n)( \beta _2-\alpha _2)
w_{n,2}^{-}\mu _2+\int_{\Omega }\frac{h_2}{b_nc_n}\mu _2\,.
\end{align*}
Then
\begin{gather*}
\frac{1}{c_n}E_{n,1}-t_n\int_{\Omega }( \frac{f(.,b_nw_{n,1},v_n)}{b_nc_n})
\mu _1=\frac{1}{c_n}\int_{\Omega }(1-t_n)( \beta _1-\alpha _1) w_{n,1}^{-}\mu
_1+\int_{\Omega }\frac{h_1}{b_nc_n}\mu _1 ,
\\
\frac{1}{c_n}E_{n,2}-t_n\int_{\Omega }\frac{g(.,u_n,b_nw_{n,2})}{
b_nc_n}\mu _2=\frac{1}{c_n}\int_{\Omega }(1-t_n)( \beta
_2-\alpha _2) w_{n,2}^{-}\mu _2+\int_{\Omega }
\frac{h_2}{b_nc_n}\mu _2,
\end{gather*}
or equivalently,
\begin{gather*}
\frac{(1-t_n)( \beta _1-\alpha _1) }{c_n}\int_{\Omega}w_{n,1}^{-}\mu _1
=\frac{1}{c_n}E_{n,1}-t_n\int_{\Omega }( \frac{
f(.,b_nw_{n,1},v_n)}{b_nc_n}) \mu _1-\int_{\Omega }\frac{
h_1}{b_nc_n}\mu _1, \\
\frac{(1-t_n)( \beta _2-\alpha _2) }{c_n}\int_{\Omega
}w_{n,2}^{-}\mu _2=\frac{1}{c_n}E_{n,2}-t_n\int_{\Omega }\frac{
g(.,u_n,b_nw_{n,2})}{b_nc_n}\mu _2-\int_{\Omega }\frac{h_2}{
b_nc_n}\mu _2\,.
\end{gather*}
From \eqref{lim}, \eqref{cr} we can write
$$
( \beta _j-\alpha _j) \lim_{n\to \infty }
\frac{(1-t_n)}{c_n}\int_{\Omega }w_{n,j}^{-}\mu _j=0, \quad j=1,2,
$$
such that
$$
\lim_{n\to \infty } \int_{\Omega }w_{n,j}^{-}\mu_{J}
 =-a_j\int_{\Omega }| \mu _j^{-}| ^2dx\neq 0\,.
$$
If $\mu _j$ satisfies \eqref{h} and $\alpha _j\notin \sigma(A)$, then
$\mu _j^{-}\neq 0$. For this index $j$,  $\beta _j-\alpha _j\neq 0$, we find that
\begin{equation}
\underset{n\to \infty }{\lim }\frac{(1-t_n)}{c_n}=0.
\end{equation}%
From \eqref{h} $,(3.3),(3.4)$ and
$$
w_{n,j}=z_{n,j}+a_{n,j}\mu _j=y_{n,j}c_n+a_{n,j}\mu _j,j=1,2$$
we obtain
\begin{align*}
-\Delta( y_{n,1}c_n+a_{n,1}\mu _1)
&=\alpha _1(
y_{n,1}c_n+a_{n,1}\mu _1)^{+}-\beta _1(
y_{n,1}c_n+a_{n,1}\mu _1)^{-} \\
&\quad +t_n\frac{f(.,b_nw_{n,1},v_n)}{b_n}+(1-t_n)( \beta_1-\alpha _1)
 ( w_{1,n})^{-}+\frac{h_1}{b_n}, \\
-\Delta ( y_{n,2}c_n+a_{n,2}\mu _2)
&=\alpha _2(y_{n,2}c_n+a_{n,2}\mu _2)^{+}-\beta _2(
y_{n,2}c_n+a_{n,2}\mu _2)^{-} \\
&\quad +t_n\frac{g(.,u_n,b_nw_{n,2})}{b_n}+(1-t_n)( \beta_2-\alpha _2)( w_{2,n}) ^{-}
+\frac{h_2}{b_n}\,.
\end{align*}
From system \eqref{h} we deduce
\begin{equation}
\begin{aligned}
-\Delta y_{n,1}
&=\alpha _1( ( y_{n,1}+\frac{a_{n,1}}{c_n}\mu
_1) ^{+}-\frac{a_{n,1}}{c_n}\mu _1^{+})
 -\beta _1(( y_{n,1}+\frac{a_{n,1}}{c_n}\mu _1)^{-}-\frac{a_{n,1}}{c_n}\mu _1^{-})\\
&\quad +t_n\frac{f(.,b_nw_{n1},v_n)}{c_nb_n}+\frac{(1-t_n)( \beta
_1-\alpha _1) }{c_n}( w_{1,n})^{-}+\frac{h_1}{%
c_nb_n},
\\
-\Delta y_{n,2}
&=\alpha _2(( y_{n,2}+\frac{a_{n,2}}{c_n}\mu
_2) ^{+}-\frac{a_{n,2}}{c_n}\mu _2^{+})
-\beta _2(( y_{n,2}+\frac{a_{n,2}}{c_n}\mu _2) ^{-}-\frac{a_{n,2}}{c_n}\mu _2^{-}) \\
&\quad +t_n\frac{g(.,u_n,b_nw_{n2})}{c_nb_n}+\frac{(1-t_n)( \beta
_2-\alpha _2) }{c_n}( w_{2,n}) ^{-}+\frac{h_2}{c_nb_n},
\end{aligned} \label{e3.10}
\end{equation}
when $n\to \infty, c_n b_n\to \infty$ and the last three terms of the two equations
above converge to zero in $L^2(\Omega)$. The
following inequalities hold
\begin{equation} \label{e3.11}
\begin{gathered}
| ( y_{n,j}+\frac{a_{n,j}}{c_n}\mu _j) ^{+}-\frac{a_{n,j}}{c_n}\mu _j^{+}|
\leq | y_{n,j}| \leq k_j \quad\text{a.e.}
\\
| ( y_{n,j}+\frac{a_{n,j}}{c_n}\mu _j) ^{-}-\frac{a_{n,j}}{c_n}\mu _j^{-}|
\leq | y_{n,j}| \leq k_j\quad \text{a.e.}
\end{gathered}
\end{equation}
Extracting a subsequence, we may assume that the last three terms of each
equation of \eqref{e3.10} approach zero a.e in $\Omega$, and there exists
$( k_1',k_2') \in L^2(\Omega )\times L^2(\Omega )$ such that
\begin{gather*}
| t_n\frac{f(x,b_nw_{n,1},v_n)}{c_nb_n}+\frac{%
(1-t_n)( \beta _1-\alpha _1) }{c_n}( w_{1,n})
^{-}+\frac{h_1( x) }{c_nb_n}| \leq
k_1'\quad \text{a.e. in }\Omega,
\\
| t_n\frac{g(x,u_n,b_nw_{n,2})}{c_nb_n}+\frac{%
(1-t_n)( \beta _2-\alpha _2) }{c_n}( w_{2,n})
^{-}+\frac{h_2( x) }{c_nb_n}| \leq
k_2'\quad \text{a.e. in  }\Omega.
\end{gather*}
From \eqref{e3.10}, \eqref{e3.11},  and the above inequality, we have
\begin{equation} \label{e3.12}
\begin{gathered}
| -\Delta y_{n,1}( x)| \leq 2\max (| \alpha _1| ,| \beta _1|)
k_1(x) +k_1^{\prime }( x) ,\\
| -\Delta y_{n,2}( x)| \leq 2\max (| \alpha _2| ,| \beta _2| )
k_2(x)+k_2^{\prime }( x).
\end{gathered}
\end{equation} 
Let $\rho ( x) $ be defined a.e in $\Omega $ as follows
\[ % 3.13
\rho( x) = \begin{cases}
\alpha _j &\text{if $\mu _j( x) >0$ or if $\mu _j( x) =0$ and $y_j\geq 0$},
\\
\beta _j &\text{if $\mu _j( x) <0$ or if $\mu _j( x) =0$ and $y_j<0$},
\end{cases}
\] 
from \eqref{e3.10} and the fact that $c_n\to 0$ one can see that
\begin{gather*}
-\Delta y_{n,1}( x) \to \rho ( x) y_1(
x) \quad \text{a.e. in }\Omega ,\\
-\Delta y_{n,2}( x) \to \rho( x) y_2(
x) \quad \text{ a.e. in }\Omega\,.
\end{gather*}
From  \eqref{e3.12} and Lebesgue's convergence theorem we conclude that
\begin{gather*}
-\Delta y_{n,1}\overset{L^2(\Omega )}{\to }\rho y_1, \quad
-\Delta y_{n,2}\overset{L^2(\Omega )}{\to }\rho y_2\,.
\end{gather*}
Then
\[
-\Delta y_n\overset{( L^2(A)) ^2}{\to }\rho y, \quad
y_n\overset{( L^2(A)) ^2}{\to }y.
\]
The operator $A$ being closed, we have
\[
-\Delta y=\rho y,\quad y\in \varphi ^{\perp },\quad \| y\|_{( D(A) )^2}=1.
\]
Since $\rho $ satisfies: $\overline{\lambda }<\alpha _j\leq \rho \leq
\beta _j<\underline{\lambda }$ by \cite[Proposition 2.2]{TK1}, we conclude that
$y=0$. This contradicts $\| y\| _{( D(\Omega )) ^2}=1$ and hence \eqref{e3.5}
is established.
\end{proof}

Using a similar argument to that given above, we obtain
the following results:
\begin{itemize}
\item
When  $\alpha_j=\beta_j=\lambda$ for $j=1,2$,
We assume that \eqref{lim} and \eqref{bo} are fulfilled.
Let $(\theta_1,\theta_2)  \in N_{\lambda}\times N_{\mu}$. 
Then the problem \eqref{e1.1} has at least one weak solution if and only if
$$
\int_{\Omega}
\gamma_{i}^{+}\theta_{i}^{+}(  x)  dx-
\int_{\Omega}
\gamma_{i}^{-}\theta_{i}^{-}(  x)  (  x)  dx+
\int_{\Omega}
h_{i}(  x)  \theta_{i}(  x)  dx\geq0, \quad i\in1,2
$$.

\item A similar argument can be made when
    $\alpha_j>\beta_j$ and $H_j(h_j),H_{j+2}( h_j) >0$, $j=1,2$.
\end{itemize}

Now, we give the proof of our main result.

\begin{proof}[Proof of Theorem \eqref{thm1}]
 Let
\begin{equation*}
B( 0,R) =\{ ( u,v) \in U,\| (u,v) \| _{U}<R\}.
\end{equation*}
By invariance of the topological degree,
for  $t\in [ 0,1]$, $\deg (H(t,\cdot,\cdot),B( 0,R) ,0)$
is constant. In particular if $t=0$, we have
\[
H(0,u,v)=\begin{pmatrix}
-\Delta ^{-1} &  \\
& -\Delta ^{-1}
\end{pmatrix}
\begin{pmatrix}
 \alpha _1u^{+}-\alpha _1u^{-} \\
 \alpha _2v^{+}-\alpha _2v^{-}
\end{pmatrix},
\]
on the other hand, for $t=0$ the linear problem
\begin{gather*}
-\Delta u=\alpha _1u+h_1\text{ in }\Omega, \\
-\Delta v=\alpha _2v+h_2\text{ in }\Omega, \\
u=v=0\text{ on }\partial \Omega.
\end{gather*}
possesses a unique solution $(u,v)\in U.$\\
By the homotopy invariance property,  we have
\begin{align*}
&\deg (I-H(0,\cdot,\cdot),B( 0,R) ,( -\Delta ) ^{-1}h)\\
&=\deg (I-H(1,\cdot,\cdot),B( 0,R) ,( -\Delta ) ^{-1}h)=\pm 1,
\end{align*}
this completes the proof.
\end{proof}


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\end{document}
