\documentclass[reqno]{amsart}
\usepackage{hyperref}

\AtBeginDocument{{\noindent\small
\emph{Electronic Journal of Differential Equations},
Vol. 2016 (2016), No. 338, pp. 1--12.\newline
ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu}
\thanks{\copyright 2016 Texas State University.}
\vspace{8mm}}

\begin{document}
\title[\hfilneg EJDE-2016/338\hfil Critical exponent for the heat equation]
{Critical exponent for the heat equation in $\alpha$-modulation spaces}

\author[W. Zheng, H. Qiang, B. Rui \hfil EJDE-2016/338\hfilneg]
{Wang Zheng, Huang Qiang, Bu Rui}

\address{Wang Zheng \newline
School of Mathematical Sciences,
Zhejiang University,
Hangzhou 310027,  China}
\email{wangzheng10.17@163.com}

\address{Huang Qiang (corresponding author)\newline
School of Mathematical Sciences,
Zhejiang University,
Hangzhou 310027,  China}
\email{huangqiang0704@163.com}

\address{Bu Rui \newline
Department of Mathematics,
Qingdao University of Science and Technology,
 Qingdao 266061, China}
\email{burui0@163.com}

\thanks{Submitted January 27, 2016. Published December 30, 2016.}
\subjclass[2010]{35A01, 35A02, 42B37}
\keywords{$\alpha$-modulation space; heat equation; critical exponent}

\begin{abstract}
 In this article, we propose a method for finding the critical exponent for heat
 equations in $\alpha$-modulation space $M_{p,q}^{s,\alpha}$.
 We define an index $\sigma (s,p,q)$, and use it to determine the critical
 exponent of the heat equation.
 Then we use this exponent to describe well and ill-posedness of the heat
 equation in $L^{\infty}([0,T];M_{p,q}^{s,\alpha})$.
 In some special case our conclusions are sharp. Furthermore, our method may
 be applied to other evolution equations.
\end{abstract}

\maketitle
\numberwithin{equation}{section}
\newtheorem{theorem}{Theorem}[section]
\newtheorem{lemma}[theorem]{Lemma}
\newtheorem{proposition}[theorem]{Proposition}
\newtheorem{remark}[theorem]{Remark}
\newtheorem{definition}[theorem]{Definition}
\newtheorem{corollary}[theorem]{Corollary}
\allowdisplaybreaks

\section{Introduction and statement of main results}

 It is well known that many dispersive equations have their critical
exponents in either Sobolev spaces or Besov spaces, or both.
For  instance, the critical exponent of nonlinear Schr\"{o}dinger (NLS) equation  is
$\frac{n}{2}-\frac{2}{k-1}$ when the nonlinear term is  $|u|^{k-1}u$
in Sobolev spaces.
Cazenave and Weissler \cite{CZ}
showed that NLS is local well-posedness in $C([-T,T];\dot{H}^{s})$ when
$s\geq 0$ and $s> \frac{n}{2}-\frac{2}{k-1}$.  Christ, Colliander
and Tao \cite{CCT} proved that when $s<\max \{0,\frac{n}{2}-\frac{2}{k-1}\}$,
 NLS is ill-posed in $C([-T,T];\dot{H}^{s})$ for any fixed $T>0$.
We can see that the domain of well and ill-posedness is completely described
by their critical exponents. Furthermore, the methods in
\cite{CZ} and \cite{CCT} relay heavily  on the scaling invariance of the
work spaces. In recent years, modulation space emerges and plays a significant
 role in the study of certain nonlinear dispersive equations.
(We will describe more details of the modulation space and $\alpha$-modulation
space in the following contents.)
Although modulation space lacks the scaling property, in our previous work\cite{HFC},
we found the critical exponents for some dispersive equations in modulation
space by different methods.
Particularly, we found critical exponents for fractional heat equation
in the modulation space without the scaling property.
This exponent also could describe well and ill posedness
in modulation space completely. That description is quite similar
to above conclusions in \cite{CZ} and \cite{CCT}.

Modulation space was introduced by Feichtinger in \cite{F} to measure
smoothness of a function or distribution in a way different from $L^{p}$
space, and they are now recognized as a powerful tool for studying
wavelet and pseudo-differential operators
 (see \cite{B,CFS,G1,G2,M,S,Tj,G3}). The original definition of the modulation
space is based on the short-time Fourier transform and window function.
Wang and Hudizk \cite{WHH} gave an equivalent definition of the discrete
version on modulation
space by the frequency-uniform-decomposition. With this discrete version,
they were able to find global solutions for nonlinear Schr\"{o}dinger
equation and nonlinear Klein-Gordon equation in lower regularity space.
After then, there have been many studies on nonlinear PDEs in modulation
space. So far, people have found that modulation has many advantages
in study of PDE's problems.

The $\alpha$-modulation space $M_{p,q}^{s,\alpha}$ was first introduced by
 G\"obner in his unpublished thesis \cite{G}.
Later, the definition was refined by Han and Wang in \cite{HW}.
They used the $\alpha$-covering and a
corresponding bounded admissible partition of unity of order $p$ (BAPU)
to define $\alpha$-modulation space.
The parameter $\alpha\in[0,1]$ determines a segmentation of the frequency spaces.
When $\alpha=0$, $M_{p,q}^{s,0}$
is equivalent to the classical modulation space; When $\alpha=1$,
$M_{p,q}^{s,1}$ is equivalent to the classical Besov space.
Obviously, it is proposed to be an intermediate function space between
Besov space and modulation space. Hence, it is very important to study
some analysis and PDE's problems in $\alpha$-modulation space.
So far, there are many good results on this topic. Below we list some of them,
among many others.  Guo and Chen \cite{GC} proved the
Stricharz estimates on $M_{p,q}^{s,\alpha}$. For Cauchy problem in
$\alpha$-modulation space,  Han and Wang studied the derivative nonlinear
 Schr\"{o}dinger equation in \cite{HW1}; Chen and Huang studied
dispersive equations with noninteger term  in \cite{HC}.
For the boundness of operators, Wu and Chen \cite{WC} obtained the sharp
conditions for the boundness of
fractional integral operators and bilinear fractional integral operators
in $M_{p,q}^{s,\alpha}$; Feichtinger, Huang and Wang \cite{FHW} studied
 trace operators  in $M_{p,q}^{s,\alpha}$.


In this article, we find the critical exponents for heat equation in
 $M_{p,q}^{s,\alpha}$.
Moreover, we use this exponent to describe well and ill-posedness for heat equation,
and get sharp results in some special cases.
First, we recall some important properties of Besov space \cite{T} and
modulation space \cite{WHH}. The
first one is Sobolev-type embedding that says
$B_{p_1,q}^{s_1}\subset B_{p_2,q}^{s_2}$ if and only if
\[
s_2\leq s_1  \quad\text{and}\quad  s_1-\frac{n}{p_1}\geq s_2-\frac{n}{p_2}.
\]
$M_{p,q_1}^{s_1}\subset
M_{p,q_2}^{s_2}$ if and only if
\[
s_2\leq s_1 \quad\text{and}\quad s_1-\frac{n}{q_1'}\geq s_2-\frac{n}{q_2'}.
\]
The second one is algebra property that says  $B_{p,q}^{s}$  forms a
multiplication algebra if $s-\frac{n}{p}>0$, and  $M_{p,q}^{s}$  forms a
multiplication algebra if $s-\frac{n}{q'}>0$. By comparing these properties
to embedding in $M_{p,q}^{s,\alpha}$ (see proposition \ref{prop2})
and algebra property of $M_{p,q}^{s,\alpha}$ (\cite[Theorem 5.1]{HW}),
we observe that the index $s-\alpha\frac{n}{p}-(1-\alpha)\frac{n}{q'}$
in the $\alpha$-modulation space
is an analog of the index $s-\frac{n}{p}$ in the Besov space or
$s-\frac{n}{q'}$ in the modulation space. Motivated by such an
observation, heuristically, we may use the index
$s-\alpha\frac{n}{p}-(1-\alpha)\frac{n}{q'}$ to
describe the critical exponent for heat equation in $M_{p,q}^{s,\alpha}$.
Of course, this heuristic idea will be technically supported in our
following discussion.
For convenience in the discussion, we denote
$\sigma (s,p,q)=s-\alpha\frac{n}{p}-(1-\alpha)\frac{n}{q'}$,
and $\sigma_{i}:=\sigma (s_{i},p_{i},q_{i})
=s_{i}-\alpha\frac{n}{p_{i}}-(1-\alpha)\frac{n}{q_{i}'}$, we use the inequality
\[
A(u,v,w\dots )\preceq B(u,v,w\dots )
\]
to mean that there is a positive number $C$ independent of all main
variables $u,v,w\dots $, for which $A(u,v,w\dots )\leq CB(u,v,w\dots )$.


Now we state main results in our paper. We only consider the case:
$\mathfrak{D}=\{(p,q)\in\mathbb{R}^2:1\leq p\leq\infty,
1\leq q\leq\infty,q\geq p\}$ for the technical problem. Now we use the index
$\sigma(s,p,q)$ to describe well and ill-posedness for
following heat equation
\begin{equation}
u_{t}+\Delta u=u^2,  \quad     u(0)=u_0  \label{e1.1}
\end{equation}
in $M_{p,q}^{s,\alpha}$. Following theorems are our main results in this paper:

\begin{theorem} \label{thm1}
Let $(p,q)\in \mathfrak{D}$ and $\sigma (s,p,q)>-\frac{2\alpha}{2-\alpha}$.
There exists a $\ T>0$ \ such that equation \eqref{e1.1} is local well-posedness
in $L^{\infty}([0,T];M_{p,q}^{s,\alpha})$. Precisely, for every inial data
$u_0\in M_{p,q}^{s,\alpha}$, there exists $T>0$ such that
heat equation \eqref{e1.1} has a unique solution in
$L^{\infty}([0,T];M_{p,q}^{s,\alpha})$.
\end{theorem}

\begin{theorem} \label{thm2}
Let $s\in\mathbb{R}$,$1\leq p,q\leq\infty$, when $\sigma (s,2,q)<-\frac{2}{k-1}$
or $s-\frac{n}{2}<-\frac{2}{k-1}$ for any $q\in [1,\infty)$, then
equation \eqref{e1.1} is ill-posed in $L^{\infty}([0,T];M_{p,q}^{s,\alpha})$
for any fixed $T>0$.
\end{theorem}



\begin{remark} \label{rmk1} \rm
Equation \eqref{e1.1} is a special case of heat equations. For general case,
if we replace the nonlinear term $u^2$ by $u^{k}$ for $k\in\mathbb{Z}^{+}$
or replace Laplacian $\Delta$ by fractional Laplacian $\Delta^{\frac{\beta}{2}}$,
 we can also obtain similar results by the same method.
\end{remark}

\begin{remark} \label{rmk2} \rm
When $\alpha=1$, we can see the results are sharp and same as that in Besov space.
But for the case $\alpha\in(0,1)$, our results are
not sharp for technical problem. Essentially, this difficulty is due to the shape
of $\alpha$-covering when we prove the algebra property of
$M_{p,q}^{s,\alpha}$ (see Lemma \ref{lem2}).
In the proof of Lemma \ref{lem2}, when $(p,q)=(1,1)$
 we encounter to this difficulty. But for the case $1\leq p\leq\infty$,
$q=\infty$, we can obtain perfect conclusions. So, when $(p,q)=(2,\infty)$,
our results are sharp for any $\alpha\in[0,1]$. Specifically, we have
following corollary.
\end{remark}

\begin{corollary} \label{coro1}
When $\sigma(s,2,\infty)>-2$, heat equation \eqref{e1.1} is locally
well-posedness in $L^{\infty}([0,T];M_{p,q}^{s,\alpha})$; when
$\sigma(s,2,\infty)<-2$, heat equation \eqref{e1.1} is ill-posed
in $L^{\infty}([0,T];M_{p,q}^{s,\alpha})$ for any fix $T>0$.
\end{corollary}

This article is organized as follows.
 In Section 2, we will introduce some basic
knowledge on $\alpha$-modulation space, as well as some useful
 propositions that will be used in our proofs. All proofs of main
theorems will be presented in Section 3.

\section{Preliminaries}

 In this section, we give the definition and discuss some basic
properties of $\alpha$-modulation space. Before giving the definition of
$M_{p,q}^{s,\alpha}$, we
introduce some notation frequently used in this paper.
Let $\mathcal{S}=\mathcal{S}(\mathbb{R}^n)$ be
the Schwartz function. Its dual is $\mathcal{S}'=\mathcal{S}'(\mathbb{R}^n)$,
the set of all tempered distribution
on $\mathbb{R}^n$. For any $p\in[1,\infty)$, $p'$ will stand for the dual
index of $p$, i.e., $\frac{1}{p}+\frac{1}{p'}=1$
We write $L^{p}$ for $L^{p}(\mathbb{R}^n)$ and $l^{p}$ the sequence Lebesgue space.
 For a vector $k=(k_1,k_2,\dots ,k_{n})\in\mathbb{Z}^n$,
we denote $|k|=(k_1^2+k_2^2+\dots +k^2_{n})^{\frac{1}{2}}$,
$|k|_{\infty}=\max_{i=1,\dots ,n}|k_{i}|$,
$\langle k\rangle=(1+|k|^2)^{\frac{1}{2}}$. Now, we briefly introduce
the definition of $\alpha$-modulation. More details can be found in \cite{HW}.

\begin{definition} \label{def1} \rm
 Let $\rho$ be a nonnegative smooth radial bump
function supported in $B(0,2)$, satisfying $\rho(\xi)=1$ for
$|\xi|<1$ and $\rho(\xi)=0$ for $|\xi|\geq2$. For any
$k=(k_1,k_2,\dots ,k_{n})\in\mathbb{Z}^n$, we set
\begin{gather*}
\rho_k^{\alpha}(\xi)=\rho\Big(\frac{\xi-\langle k
 \rangle^{\frac{\alpha}{1-\alpha}}k}{r\langle k
 \rangle^{\frac{\alpha}{1-\alpha}}}\Big), \\
\varphi_k^{\alpha}=\rho_k^{\alpha}(\xi)
\Big( \sum_{l\in\mathbb{Z}^n}\rho_{l}^{\alpha}(\xi)\Big)
\end{gather*}
We define the ball
$$
B_k^r:=\{\xi\in\mathbb{R}^n:|\xi-\langle k
\rangle^{\frac{\alpha}{1-\alpha}}k|<r\langle k\rangle^{\frac{\alpha}{1-\alpha}}\}
$$
It is easy to check that $\{\varphi_k^{\alpha}\}_{k\in\mathbb{Z}^n}$ satisfy
\begin{gather*}
\operatorname{supp} \varphi_k^{\alpha}\subset B_k^{2r}, \\
\varphi_k^{\alpha}(\xi)=c,\quad \forall \xi\in B_k^r,\\
\sum_{k\in\mathbb{Z}^n}\varphi_k^{\alpha}(\xi)\equiv1,\quad \xi\in\mathbb{R}^n, \\
\|\mathcal{F}^{-1}\varphi_k^{\alpha}\|_{L^1}\prec 1
\end{gather*}
Corresponding to the above sequence $\{\varphi_k^{\alpha}\}_{k\in\mathbb{Z}^n}$,
 we can construct an operator sequence $\{\Box_k^{\alpha}\}_{k\in\mathbb{Z}^n}$ by
$$
\Box_k^{\alpha}=\mathcal{F}^{-1}\varphi_k^{\alpha}\mathcal{F}
$$
where $\mathcal{F}$ and $\mathcal{F}^{-1}$ donate the standard Fourier transform
and inverse Fourier transform respectively.
For $\alpha\in[0,1),0\leq p,q\leq\infty,s\in\mathbb{R}$, using this decomposition,
 we define $\alpha$-modulation space as
$$
M_{p,q}^{s,\alpha}=\{f\in\mathcal{S}':\|f\|_{M_{p,q}^{s,\alpha}}<\infty\}
$$
where
$$
\|f\|_{M_{p,q}^{s,\alpha}}
=\Big(\sum_{k\in\mathbb{Z}^n}\langle k\rangle^{\frac{sq}{1-\alpha}}\|
\Box_k^{\alpha}f\|^q_{L^{p}}\Big)^{1/q}
$$
\end{definition}


\begin{proposition}[Isomorphism \cite{HW}] \label{prop1}
 Let $0<p,q\leq \infty ,s,\sigma \in R$. $J_{\sigma
}=(I-\triangle )^{\sigma/2}:M_{p,q}^{s,\alpha}\to M_{p,q}^{s-\sigma,\alpha}$
is an isomorphic mapping, where  $I$  is the identity
mapping and  $\Delta $  is the Laplacian.
\end{proposition}

\begin{proposition}[Embedding \cite{HW}] \label{prop2}
Suppose $0<p_1\leq p_2\leq\infty$, $0<q_1,q_2\leq\infty$, we have
\begin{itemize}
\item[(i)] if $q_1\leq q_2$ and $s_1\geq s_2+n\alpha(\frac{1}{p_1}-\frac{1}{p_2})$,
 then
\begin{equation}
M_{p_1,q_1}^{s_1,\alpha}\subset M_{p_2,q_2}^{s_2,\alpha}\label{e2.1}
\end{equation}

\item[(ii)] if $q_1> q_2$ and $s_1-\alpha\frac{n}{p_1}
 -(1-\alpha)\frac{n}{q_1'}>s_2-\alpha\frac{n}{p_2}-(1-\alpha)\frac{n}{q_2'}$,
then
\begin{equation}
M_{p_1,q_1}^{s_1,\alpha}\subset M_{p_2,q_2}^{s_2,\alpha}\label{e2.2}
\end{equation}
\end{itemize}
\end{proposition}


\section{Proof of  main results}

Before proving Theorem \ref{thm1}, we state some key lemmas.

\begin{lemma} \label{lem1}
Let $1\leq p_1\leq p_2\leq\infty$, $1\leq q_1\leq q_2\leq\infty$, $s_2\leq s_1$.
When $\sigma_1-\sigma_2>R$,
heat semigroup $e^{t\Delta}:=\mathcal{F}^{-1}e^{-t|\xi|^2}\mathcal{F}$
satisfy  estimate
$$
\|e^{t\Delta}f\|_{M_{p_2,q_2}^{s_2,\alpha}}\preceq
(1+t^{-\frac{R}{2}})\|f\|_{M_{p_1,q_1}^{s_1,\alpha}}
$$
\end{lemma}

\begin{proof}
We first consider the case $p=p_1=p_2$, $q=q_1=q_2$. For the low frequency part
$|k|\leq 100\sqrt{n}$, by the multiplier estimate of $e^{t\Delta}$, we have
\[
\sum_{|k|\leq 100\sqrt{n}} \langle k\rangle^{\frac{s_1q}{1-\alpha}}
\| \Box^{\alpha}_ke^{t\Delta}f\| _{L^{p}}^q
\preceq \sum_{|k|\leq 100\sqrt{n}}\langle k\rangle^{\frac{s_2q}{1-\alpha}}
 \| \Box^{\alpha}_kf\|_{L^{p}}^q\preceq \| f\| _{M_{p,q}^{s_2}}^q.
\]
For the high frequency part, note that the operator
 $\Box^{\alpha}_ke^{t\Delta}$  can be written as
\[
\Box^{\alpha}_ke^{t\Delta}=\sum_{| \ell
| \leq 1}\Box^{\alpha}_{k+\ell }e^{t\Delta}\Box^{\alpha}_k
\]%
and  $\Box^{\alpha}_{k+\ell }e^{t\Delta}$ are convolution
operators with the kernels
\[
\Omega _{k+\ell }(y)=e^{i\langle k+\ell ,y\rangle}
\int_{\mathbb{R}^n}e^{-t| \xi +k+\ell | ^{\frac{2}{1-\alpha}}}e^{i<y,\xi >}\varphi
(\xi )d\xi .
\]
Hence, when $|k|\geq 100\sqrt{n}$  it is easy to prove that
\[
\| \Box^{\alpha}_ke^{t\Delta}f\| _{L^{p}}\preceq
e^{-\frac{t}{2}|k|^{\frac{2}{1-\alpha}}}\| \Box^{\alpha}_kf\| _{L^{p}}.
\]
Now, we have
\begin{align*}
\langle k\rangle^{\frac{s_1}{1-\alpha}}\| \Box _k
 e^{t\Delta}f\|_{L^{p}}
&\preceq \langle k\rangle^{\frac{s_1-s_2}{1-\alpha}}
 e^{-\frac{t}{2}|k|^{\frac{2}{1-\alpha}}}
\langle k\rangle^{\frac{s_2}{1-\alpha}}\| \Box^{\alpha}_kf\| _{L^{p}} \\
&\preceq t^{-\frac{1}{2}(s_1-s_2)}\langle k\rangle^{\frac{s_2}{1-\alpha}}\|
 \Box^{\alpha}_kf\| _{L^{p}}.
\end{align*}
Taking the $l^q$ norm in both sides, we obtain
\begin{equation}
\|e^{t\Delta}f\|_{M_{p,q}^{s_2,\alpha}}
\preceq(1+t^{-\frac{1}{2}(s_1-s_2)})\|f\|_{M_{p,q}^{s_1,\alpha}}\label{e3.1}
\end{equation}
Next, we estimate the case $1\leq p_1<p_2$,$1\leq q_1<q_2$ and $s_1\geq s_2$.
By \eqref{e2.2} and \eqref{e3.1}, we have
\[
\| e^{t\Delta}f\| _{M_{p_1,q_1}^{s_1,\alpha}}
\preceq \| e^{t\Delta}f\|_{M_{p_2,q_2}^{s_2-R,\alpha}}
\preceq (1+t^{-\frac{R}{2}})\| f\| _{M_{p_2,q_2}^{s_2,\alpha}}\,.
\]
\end{proof}

\begin{lemma} \label{lem2}
Let $(p,q)\in\mathfrak{D}$, $s_0>0$. When
$\sigma(s,p,q)>-\frac{s_0\alpha}{2-\alpha}$, we have following estimate:
$$
\|u^2\|_{M_{p,q}^{s-s_0,\alpha}}\preceq\|u\|^2_{M_{p,q}^{s,\alpha}}\,.
$$
\end{lemma}

\begin{proof}
We start with some notation and basic conclusions which were obtained in \cite{HW}.
For every $(k_1,k_2)\in\mathbb{Z}^{2n}$, we
introduce
$$
\Lambda(k_1,k_2)=\{k\in\mathbb{Z}^n:\Box_k^{\alpha}(\Box_{k_1}^{\alpha}
u\Box_{k_2}^{\alpha}u)\neq0\}
$$
We write
\begin{gather*}
K_j(k_1,k_2)=\langle k_1\rangle^{\frac{\alpha}{1-\alpha}}k_{1j}
 +\langle k_2\rangle^{\frac{\alpha}{1-\alpha}}k_{2j}, \\
K(k_1,k_2)=\max_{1\leq j\leq n}|K_j(k_1,k_2)|
\end{gather*}
To obtain a more precise estimate, we divide $\mathbb{Z}^{2n}$ of all $(k_1,k_2)$
in to the sets
\begin{gather*}
\Omega_0=\{(k_1,k_2\in\mathbb{Z}^{2n}):\langle k_1\rangle\sim\langle k_2\rangle\},\\
\Omega_1=\{(k_1,k_2\in\mathbb{Z}^{2n}):\langle k_1\rangle\gg\langle k_2\rangle\},\\
\Omega_2=\{(k_1,k_2\in\mathbb{Z}^{2n}):\langle k_1\rangle\ll\langle k_2\rangle\}
\end{gather*}
and separate $\Omega_0$ into the sets
\begin{gather*}
\Omega_{0,1}=\{(k_1,k_2\in\Omega_0:K(k_1,k_2)
 \preceq\langle k_1\rangle^{\frac{\alpha}{1-\alpha}}\}, \\
\Omega_{0,2}=\{(k_1,k_2\in\Omega_0:K(k_1,k_2)\gg\langle k_1
\rangle^{\frac{\alpha}{1-\alpha}}\}.
\end{gather*}
In \cite{HW}, it had been proved that when $(k_1,k_2)\in\Omega_{0,1}$,
we have $\langle k\rangle\preceq\langle k_1\rangle^{\alpha}$; when
$(k_1,k_2)\in\Omega_{0,2}$, we have $\langle k\rangle\preceq\langle k_1\rangle^{y}$
for some $y:=y(k_1,k_2)\in(\alpha,1]$.

First, we consider the case $(p,q)=(1,1)$, by the triangle inequality, we have
\begin{align*}
\|u^2\|_{M_{p,q}^{s-s_0,\alpha}}
&= \sum_{k\in\mathbb{Z}^n}\langle k\rangle^{\frac{s-s_0}{1-\alpha}}\|\Box_k^{\alpha}u^2\|_{L^1}\\
&\leq \sum_k\langle k\rangle^{\frac{s-s_0}{1-\alpha}}
\Big(\sum_{k_1,k_2}\|\Box_k^{\alpha}(\Box_{k_1}^{\alpha}u
\Box_{k_2}^{\alpha}u)\|_{L^1}\Big)\\
&= \sum_{l=0}^2\sum_{(k_1,k_2)\in\Omega_{l}}
 \sum_{k\in\Lambda(k_1,k_2)}\langle k\rangle^{\frac{s-s_0}{1-\alpha}}
\|\Box_k^{\alpha}(\Box_{k_1}^{\alpha}u\Box_{k_2}^{\alpha}u)\|_{L^1}
\end{align*}
By the multiplier estimate and H\"older's inequality, we have
$$
\|\Box_k^{\alpha}(\Box_{k_1}^{\alpha}u\Box_{k_2}^{\alpha}u)\|_{L^1}
\preceq\|\Box_{k_1}^{\alpha}u\Box_{k_2}^{\alpha}u\|_{L^1}
\preceq\|\Box_{k_1}^{\alpha}u\|_{L^1}\|\Box_{k_2}^{\alpha}u\|_{L^{\infty}}
$$
For $(k_1,k_2)\in\Omega_{0,1}$, choose $b=\sigma(s,1,1)-\varepsilon$, we have
\begin{align*}
&\sum_{(k_1,k_2)\in\Omega_{01}}\sum_{k\in\Lambda(k_1,k_2)}
 \langle k\rangle^{\frac{s-s_0}{1-\alpha}}
\|\Box_k^{\alpha}(\Box_{k_1}^{\alpha}u\Box_{k_2}^{\alpha}u)\|_{L^1}\\
&\preceq \sum_{(k_1,k_2)}\langle k_1\rangle^{\frac{(s-s_0)\alpha}{1-\alpha}
+n\alpha-\frac{b}{1-\alpha}}\|\Box_{k_1}^{\alpha}u\|_{L^1}
\langle k_2\rangle^{\frac{b}{1-\alpha}}\|\Box_{k_2}^{\alpha}u\|_{L^{\infty}}\\
&\leq \|u\|_{M_{1,1}^{(s-s_0)\alpha+n\alpha(1-\alpha)-b,\alpha}}
\|u\|_{M_{\infty,1}^{b,\alpha}}
\end{align*}
Choosing $\varepsilon\to 0^{+}$, the domain of $\sigma(s,1,1)$ guarantees that
$(s-s_0)\alpha+n\alpha(1-\alpha)-b<s$. Hence, by \eqref{e2.2} we have
$$
\|u^2\|_{M_{1,1}^{s-s_0,\alpha}}\preceq\|u\|^2_{M_{1,1}^{s,\alpha}}
$$

For $(k_1,k_2)\in\Omega_{0,2}$, we have
\begin{align*}
&\sum_{(k_1,k_2)\in\Omega_{02}}\sum_{k\in\Lambda(k_1,k_2)}
 \langle k\rangle^{\frac{s-s_0}{1-\alpha}}
\|\Box_k^{\alpha}(\Box_{k_1}^{\alpha}u\Box_{k_2}^{\alpha}u)\|_{L^1}\\
&\preceq \sum_{(k_1,k_2)}\langle k_1\rangle^{\frac{(s-s_0)y}{1-\alpha}
 +\frac{n\alpha}{1-\alpha}(1-y)-\frac{b}{1-\alpha}}\|\Box_{k_1}^{\alpha}u\|_{L^1}
\langle k_2\rangle^{\frac{b}{1-\alpha}}\|\Box_{k_2}^{\alpha}u\|_{L^{\infty}}\\
&\leq \|u\|_{M_{1,1}^{(s-s_0)y+n\alpha(1-y)-b,\alpha}}\|u\|_{M_{\infty,1}^{b,\alpha}}
\end{align*}
Similarly, Choosing $\varepsilon\to 0^{+}$, the domain of $\sigma(s,1,1)$ and
$y\in[\alpha,1)$ also guarantees that $(s-s_0)y+n\alpha(1-y)-b<s$. So we also have
$$
\|u^2\|_{M_{1,1}^{s-s_0,\alpha}}\preceq\|u\|^2_{M_{1,1}^{s,\alpha}}
$$

For $(k_1,k_2)\in\Omega_1$, we recall the refined H\"odler inequality:
$$
\|fg\|_{L^{p}}\preceq\|J_{a}f\|_{L^{p_1}}\|J_{b}g\|_{L^{p_2}},
$$
where $\frac{1}{p}=\frac{1}{p_1}+\frac{1}{p_2}$, $J_{a}$ and $J_{b}$ are
Bessel potentials which satisfy $a+b>0$. Also, it had been
proved that $\sharp\Lambda(k_1,k_2)\sim1$ in \cite[5.17]{HW}.
By this conclusion and the above H\"odler inequality, choosing
$b=\sigma(s,1,1)-\varepsilon$, $a=2\varepsilon-\sigma(s,1,1)$, and
$\varepsilon\to 0^{+}$ we have
\begin{align*}
&\sum_{(k_1,k_2)\in\Omega_1}\sum_{k\in\Lambda(k_1,k_2)}
 \langle k\rangle^{\frac{s-s_0}{1-\alpha}}
\|\Box_k^{\alpha}(\Box_{k_1}^{\alpha}u\Box_{k_2}^{\alpha}u)\|_{L^1}\\
&\preceq \sum_{k_1\in\mathbb{Z}^n}\langle k_1\rangle^{\frac{(s-s_0)}{1-\alpha}}
\|\Box_{k_1}^{\alpha}J_{a}u\|_{L^1}
\sum_{k_2\in\mathbb{Z}^n}\|\Box_{k_2}^{\alpha}J_{b}u\|_{L^{\infty}}\\
&\leq \|u\|_{M_{1,1}^{s-s_0+a,\alpha}}\|u\|_{M_{\infty,1}^{b,\alpha}}\\
&\leq \|u\|_{M_{1,1}^{s,\alpha}}^2
\end{align*}
For $(k_1,k_2)\in\Omega_2$, we can get the same estimate by using the
 method above.

Next, we consider the case $1\leq p \leq\infty$, $q=\infty$.
We also choose $b=\sigma(s,p,\infty)-\varepsilon$,
$a=2\varepsilon-\sigma(s,p,\infty)$, and let $\varepsilon\to 0^{+}$.
By the triangle inequality,
\begin{align*}
\|u^2\|_{M_{p,q}^{s-s_0,\alpha}}
&= \sup_{k\in\mathbb{Z}^n}\langle k\rangle^{\frac{s-s_0}{1-\alpha}}\|
 \Box_k^{\alpha}u^2\|_{L^{p}}\\
&\leq \sup_{k\in\mathbb{Z}^n}\langle k\rangle^{\frac{s-s_0}{1-\alpha}}
 \sum_{k_1,k_2\in\Lambda(k)}\|\Box_k^{\alpha}(\Box_{k_1}^{\alpha}u\Box_{k_2}^{\alpha}u)\|_{L^{p}}\\
&= \sup_{k\in\mathbb{Z}^n}\sum_{l=0}^2
 \sum_{(k_1,k_2)\in\Lambda(k)\cap\Omega_{l}}
 \langle k\rangle^{\frac{s-s_0}{1-\alpha}}\|\Box_k^{\alpha}
 (\Box_{k_1}^{\alpha}u\Box_{k_2}^{\alpha}u)\|_{L^{p}}
\end{align*}
For a $\Phi\subset\mathbb{Z}^{2n}$, we denote
\begin{gather*}
\Phi_1^{*}=\{k_1\in\mathbb{Z}^n:\exists k_2\in\mathbb{Z}^n \text{ s.t. }
(k_1,k_2)\in\Phi\}, \\
\Phi_2^{*}=\{k_2\in\mathbb{Z}^n:\exists k_1\in\mathbb{Z}^n \text{ s.t. }
 (k_1,k_2)\in\Phi\}\,.
\end{gather*}
It had been proved that $\sharp\Lambda(-k_2,k)\preceq1$ in \cite{HW}. Then for any
$k_2\in\{\{\Omega_0\cup\Omega_1\}\cap\Lambda(k)\}_2^{*}$ with every fixed k,
 we have
\begin{align*}
&\sum_{(k_1,k_2)\in\{\Omega_0\cup\Omega_1\}\cap\Lambda(k)}
 \langle k\rangle^{\frac{s-s_0}{1-\alpha}}\|
 \Box_k^{\alpha}(\Box_{k_1}^{\alpha}u\Box_{k_2}^{\alpha}u)\|_{L^{p}}\\
&\preceq \sup_{k_1\in\{\{\Omega_0\cup\Omega_1\}\cap\Lambda(k)\}_1^{*}}
 \langle k\rangle^{\frac{s-s_0}{1-\alpha}}
\|\Box_{k_1}^{\alpha}J_{a}u\|_{L^{p}}\sum_{k_1\in\{\{\Omega_0\cup\Omega_1\}
 \cap\Lambda(k)\}_1^{*}}
\sum_{k_2\in\Lambda(-k_1,k)}\|\Box_{k_2}^{\alpha}J_{b}u\|_{L^{\infty}}\\
&\preceq \sup_{k_1\in\mathbb{Z}^n}\langle k_1\rangle\frac{s-s_0}{1-\alpha}\|\Box_{k_1}^{\alpha}J_{a}f\|_{L^{p}}
\sum_{k_2\in\{\{\Omega_0\cup\Omega_1\}\cap\Lambda(k)\}_2^{*}}
\sum_{k_1\in\Lambda(-k_2,k)}\|\Box_{k_2}^{\alpha}J_{b}u\|_{L^{\infty}}\\
&\preceq \|u\|_{M_{p,\infty}^{s-s_0+a,\alpha}}\|u\|_{M_{\infty,1}^{b,\alpha}}
\preceq \|u\|_{M_{p,q}^{s,\alpha}}^2
\end{align*}
For $k_2\in\{\{\Omega_0\cup\Omega_1\}\cap\Lambda(k)\}_2^{*}$ with every fixed $k$,
 symmetrically, we have
\begin{align*}
&\sum_{(k_1,k_2)\in\Omega_2\cap\Lambda(k)}\langle k
 \rangle^{\frac{s-s_0}{1-\alpha}}\|\Box_k^{\alpha}
 (\Box_{k_1}^{\alpha}u\Box_{k_2}^{\alpha}u)\|_{L^{p}}\\
&\preceq \sup_{k_2\in\mathbb{Z}^n}\langle k_2\rangle^{\frac{s-s_0}{1-\alpha}}
\|\Box_{k_2}^{\alpha}J_{a}u\|_{L^{p}}\sum_{k_1\in\{\Omega_2\cap\Lambda(k)\}_1^{*}}
\sum_{k_2\in\Lambda(-k_1,k)}\|\Box_{k_1}^{\alpha}J_{b}u\|_{L^{\infty}}\\
&\preceq \|u\|_{M_{p,\infty}^{s-s_0+a,\alpha}}\|u\|_{M_{\infty,1}^{b,\alpha}}
\preceq \|u\|_{M_{p,q}^{s,\alpha}}^2
\end{align*}
Finally, using the complex interpolation (see \cite[Theorem 2.2]{HW}) and
combining above estimates, we  obtain the desire conclusion.
\end{proof}

Based on the above lemmas, now we can prove Theorem \ref{thm1}.

\begin{proof}[Proof of Theorem \ref{thm1}]
It is well known that heat equation \eqref{e1.1} is equivalent to the
integral equation
$$
u=\Phi(u):=e^{t\Delta}u_0+\int_0^{t}e^{(t-\tau)\Delta}u^2d\tau\,.
$$
To prove that the above equation is local well-posed in $M_{p,q}^{s,\alpha}$,
we  use the standard contraction method. To this end,
we define the space
$$
X=\{u:\|u\|_{L^{\infty}([0,T];M_{p,q}^{s,\alpha})}\leq C_0\}
$$
with the metric
$$
d(u,v)=\|u-v\|_{L^{\infty}([0,T];M_{p,q}^{s,\alpha})}\,,
$$
where the positive numbers $C_0$ and $T$ will be chosen later when we invoke the
contraction. Choosing $\varepsilon>0$ small enough to ensure that
$\sigma(s,p,q)>-\frac{(2-\varepsilon)\alpha}{1-\alpha}$, by \eqref{e3.1} and
Lemma \ref{lem2}, we have
\begin{align*}
\|\Phi(u)\|_{X}
&\preceq \|u_0\|_{M_{p,q}^{s,\alpha}}+\|\int_0^{t}e^{(t-\tau)\Delta}u^2d\tau\|_{X}\\
&\preceq \|u_0\|_{M_{p,q}^{s,\alpha}}+\sup_{t\in(0,T]}\int_0^{t}(t-\tau)
^{-\frac{2-\varepsilon}{2}}\|u^2\|_{M_{p,q}^{s-2+\varepsilon,\alpha}}d\tau\\
&\preceq \|u_0\|_{M_{p,q}^{s,\alpha}}+\sup_{t\in(0,T]}\int_0^{t}(t-\tau)
^{-\frac{2-\varepsilon}{2}}d\tau\|u\|^2_{M_{p,q}^{s-2+\varepsilon,\alpha}}d\tau\\
&\preceq \|u_0\|_{M_{p,q}^{s,\alpha}}+T^{\frac{\varepsilon}{2}}\|u\|_{X}^2\,.
\end{align*}
By the contraction mapping argument, we obtain the conclusion of Theorem \ref{thm1}
after choosing $T$ such that  $T^{\varepsilon/2}<1/2$,
and $C_0=2\|u_0\|_{M_{p,q}^{s,\alpha}}$.
\end{proof}

\begin{proof}[Proof of Theorem \ref{thm2}]
 Before the proof, we recall a crucial conclusion which was obtained by
Bejenaru and Tao \cite{IT}. They consider equation
$$
u=L(u_0)+N_k(u,\dots, u)
$$
where $L$ is a linear operator, $u_0$ is the initial data, $N_k(u,\dots, u)$
is a $k$-linear operator. Also we define
$A_1(u_0):=L(u_0)$,
$$
A_{n}(u_0):=\sum_{n_1,\dots ,n_k\geq1;n_1+\dots +n_k=n}N_k(A_{n_1(u_0)},\dots ,
A_{n_k(u_0)}) for n\in\mathbb{Z}^{+}
$$
They proved that if above equation is well posed from space $X$ to $Y$,
then for each $i\in\mathbb{Z}^{+}$, $A_{i}$ is continuous from $X$ to $Y$
 (see \cite[Proposition 1]{IT}). So, if we want to prove ill-posedness
of equation \eqref{e1.1}, we only need to choose a special $i\in\mathbb{Z^{+}}$
and prove $A_{i}$ is discontinuous. Here, we choose $i=2$.
So, it suffices to show that the map from $M_{p,q}^{s,\alpha}$ to
$L^{\infty}([0,T];M_{p,q}^{s,\alpha})$ defined by
\begin{equation}
u_0\to \int_0^{t}e^{(t-\tau )\Delta} (e^{\tau \Delta}u_0)^2d\tau. \label{e3.2}
\end{equation}
is discontinuous in our domain of $s,p,q$. Actually, if the map is
continuous, we will have
\begin{equation}
\sup_{t\in [0,T]}\big\|\int_0^{t}e^{(t-\tau )\Delta}(e^{\tau\Delta}u_0)^2d\tau
\big\|_{M_{p,q}^{s,\alpha}}\preceq \| u_0\|_{M_{p,q}^{s,\alpha}}^2.\label{e3.3}
\end{equation}
So, we only need to find a $u_0$ such that \eqref{e3.3} fails.

First, we consider the case $\sigma (s,p,q)<-\frac{2}{k-1}$. We choose
\[
\widehat{u_0}(\xi)=\chi_{[N^{1/(1-\alpha)},3N^{1/(1-\alpha)}]^n}(\xi),
\]
where $N\gg1$. Obviously, the number of $j\in\mathbb{Z}^n$ that satisfy
$$
\operatorname{supp}\varphi_j^{\alpha}\cap[N^{1/(1-\alpha)},
3N^{1/(1-\alpha)}]^n\neq\emptyset
$$
is $CN^n$.
 By the definition of $M_{p,q}^{s,\alpha}$, we have
\begin{align*}
\|u_0\|_{M_{p,q}^{s,\alpha}}
&= \Big(\sum_{j\in\mathbb{Z}^n}\langle j\rangle^{\frac{sq}{1-\alpha}}\|\Box^{\alpha}_ju_0\|_{L^2}^q
\Big)^{1/q}\\
&\preceq \Big(\sum_{j\in\mathbb{Z}^n}\langle N\rangle^{\frac{sq}{1-\alpha}}
 \|\varphi^{\alpha}_j\widehat{u_0}\|_{L^2}^q\Big)^{1/q}\\
&\preceq N^{\frac{s}{1-\alpha}+\frac{\alpha}{1-\alpha}\frac{n}{2}+\frac{n}{q}}
\end{align*}
Now, we estimate
$\big\|\int_0^{t}e^{(t-\tau )\Delta}(e^{\tau\Delta}u_0)^2d\tau\big
\|_{M_{p,q}^{s,\alpha}}$.
It is easy to obtain
$$
(\widehat{u_0}*\widehat{u_0})(\eta)
=\begin{cases}
\prod_{i=1}^n6N^{\frac{1}{1-\alpha}}-\eta_{i},
& \eta\in[4N^{\frac{1}{1-\alpha}},6N^{\frac{1}{1-\alpha}}]^n\\
\prod_{i=1}^n\eta_{i}-2N^{\frac{1}{1-\alpha}},
& \eta\in[2N^{\frac{1}{1-\alpha}},4N^{\frac{1}{1-\alpha}}]^n\\
 0,& \text{otherwise}\,.
\end{cases}
$$
Then by taking $t=N^{-\frac{2}{1-\alpha}}$, we obtain
\begin{align*}
& \|\int_0^{N^{-\frac{2}{1-\alpha}}}e^{-(N^{-\frac{2}{1-\alpha}}-\tau
)\Delta}(e^{\tau\Delta}u_0)^2d\tau\|_{_{M_{2,q}^{s,\alpha}}}^q \\
&=\sum_{j\in\mathbb{Z}
^n}\langle j\rangle^{\frac{sq}{1-\alpha}}\|\Box^{\alpha}_j
 \int_0^{N^{-\frac{2}{1-\alpha}}}
e^{(N^{-\frac{2}{1-\alpha}}-\tau)\Delta}(e^{\tau\Delta}u_0)^2d\tau\|_{L^2}^q
\end{align*}
It is easy to see that
\[
e^{-\tau |\xi |^2}\geq C>0
\]
for $\tau \in [ 0,N^{-\frac{2}{1-\alpha}}]$ and
$\xi \in \operatorname{supp}\widehat{u_0}(\xi)$, and
that
\[
e^{-(\frac{1}{N^{\alpha }}-\tau )|\eta |^{2 }}\geq C>0
\]
for $\tau \in [ 0,N^{-\frac{2}{1-\alpha}}]$ and
$\eta \in \operatorname{supp}(\widehat{u_0}*\widehat{u_0})(\eta)$.

We denote
\[
E_{N}=[(\frac{5}{2})N^{\frac{1}{1-\alpha}},(\frac{7}{2})N^{\frac{1}{1-\alpha}}]^n
\cup[(\frac{9}{2})N^{\frac{1}{1-\alpha}},(\frac{11}{2})N^{\frac{1}{1-\alpha}}]^n.
\]
Also, the number of $j\in\mathbb{Z}^n$ which satisfy
$\operatorname{supp} \varphi_j^{\alpha}\cap E_{N}\neq\emptyset$ is $CN^n$.
By the Plancharel theorem, for such set of $j$, we have
\begin{align*}
&\sum_{j\in\mathbb{Z}^n}\langle j\rangle^{\frac{sq}{1-\alpha}}
\|\int_0^{N^{-\frac{2}{1-\alpha}}}e^{-(N^{-\frac{2}{1-\alpha}}-\tau
)\Delta}(e^{\tau\Delta}u_0)^2d\tau\|_{_{M_{2,q}^{s,\alpha}}}^q\\
&\geq \sum_{j\in\mathbb{Z}^n}\langle j\rangle^{\frac{sq}{1-\alpha}}\|\Box^{\alpha}_j
\int_0^{N^{-\frac{2}{1-\alpha}}}e^{(N^{-\frac{2}{1-\alpha}}-\tau)\Delta}
(e^{\tau\Delta}u_0)^2d\tau \|_{L^2}^q \\
&= \sum_{j\in\mathbb{Z}^n}\langle j\rangle^{\frac{sq}{1-\alpha}}
 \|\varphi^{\alpha}_j(\xi)\int_0^{N^{-\frac{2}{1-\alpha}}}
 e^{-(N^{-\frac{2}{1-\alpha}}-\tau)|\xi |^2}
\left\{ (e^{\tau|\cdot|^2}\widehat{u_0})*(e^{\tau|\cdot|^2}\widehat{u_0})
 \right\}d\tau\|^q_{L^2}\\
&\succeq \sum_{j\in\mathbb{Z} ^n}\langle j\rangle^{\frac{sq}{1-\alpha}}
\Big(\int_0^{N^{-\frac{2}{1-\alpha}}}\| \widehat{u_0}*\widehat{u_0}
 \| _{L^2(E_{N}\cap \operatorname{supp}\varphi^{\alpha}_j)}d\tau\Big)^q\\
&\succeq  N^{n+\frac{sq}{1-\alpha}-\frac{2q}{1-\alpha}
 +\frac{\alpha}{1-\alpha}\frac{qn}{2}+\frac{qn}{1-\alpha}}
\end{align*}
So, one has
$$
\|\int_0^{N^{-\frac{2}{1-\alpha}}}e^{-(N^{-\frac{2}{1-\alpha}}-\tau
)\Delta}(e^{\tau\Delta}u_0)^2d\tau\|_{_{M_{2,q}^{s,\alpha}}}
\succeq N^{\frac{s}{1-\alpha}+\frac{n}{2}\frac{\alpha}{1-\alpha}
+\frac{n}{1-\alpha}+\frac{n}{q}-\frac{2}{1-\alpha}}.
$$
Hence, when $\sigma(s,2,q)<-2$, map \eqref{e3.3} fails to be continuous;
this leads to the heat equation \eqref{e1.1} being ill-posed.
\end{proof}

Next, we consider the case $s<-2$. Here we choose
$$
\widehat{u_0}(\xi)=\chi_{[N^{\frac{1}{1-\alpha}}-N^{\frac{\alpha}{1-\alpha}},
N^{\frac{1}{1-\alpha}}+N^{\frac{\alpha}{1-\alpha}}]^n}(\xi)\,.
$$
Similarly, by the almost orthogonal property of
$\{\varphi_j^{\alpha}\}$(see \cite{HW}), the number of $j\in\mathbb{Z}^n$
satisfying $\operatorname{supp} \varphi_j^{\alpha}\cap
\operatorname{supp} \widehat{u_0}\neq\emptyset$ is a constant. Hence, we have
\begin{align*}
\|u_0\|_{M_{p,q}^{s,\alpha}}
&= \Big(\sum_{j\in\mathbb{Z}^n}\langle j\rangle^{\frac{sq}{1-\alpha}}
 \|\Box^{\alpha}_ju_0\|_{L^2}^q\Big)^{1/q}\\
&\preceq \Big(\sum_{j\in\mathbb{Z}^n}\langle N\rangle^{\frac{sq}{1-\alpha}}
 \|\varphi^{\alpha}_j\widehat{u_0}\|_{L^2}^q\Big)^{1/q}\\
&\preceq N^{\frac{s}{1-\alpha}+\frac{\alpha}{1-\alpha}\frac{n}{2}}
\end{align*}
Also, by simple calculations, we have
$$
(\widehat{u_0}*\widehat{u_0})(\eta)
=\begin{cases}
\prod_{i=1}^n(2N^{\frac{1}{1-\alpha}}+2N^{\frac{\alpha}{1-\alpha}}-\eta_{i}),
& \eta\in[2N^{\frac{1}{1-\alpha}}-2N^{\frac{\alpha}{1-\alpha}},
 2N^{\frac{1}{1-\alpha}}]^n,\\
\prod_{i=1}^n(\eta_{i}-2N^{\frac{1}{1-\alpha}}+2N^{\frac{\alpha}{1-\alpha}}),
& \eta\in[2N^{\frac{1}{1-\alpha}},2N^{\frac{1}{1-\alpha}}
 +2N^{\frac{\alpha}{1-\alpha}}]^n,\\
0 & \text{otherwise}.
\end{cases}
$$
Note that $\alpha\in[0,1)$, when choose $t=N^{-\frac{2}{1-\alpha}}$, we also have
\[
e^{-\tau |\xi |^{2 }}\geq C>0
\]
for $\tau \in [ 0,N^{-\frac{2}{1-\alpha}}]$ and
$\xi \in \operatorname{supp}\widehat{u_0}(\xi)$,  and that
\[
e^{-(\frac{1}{N^{\alpha }}-\tau )|\eta |^{2 }}\geq C>0
\]
for $\tau \in [ 0,N^{-\frac{2}{1-\alpha}}]$ and
$\eta \in supp(\widehat{u_0}*\widehat{u_0})(\eta)$.
Fixed $j_0\in\mathbb{Z}^n$ such that
$\operatorname{supp}\varphi_{j_0}^{\alpha}\cap
\operatorname{supp}(\widehat{u_0}*\widehat{u_0})(\eta)\neq\emptyset$,
we have
\begin{align*}
&\sum_{j\in\mathbb{Z}^n}\langle j\rangle^{\frac{sq}{1-\alpha}}\|
 \int_0^{N^{-\frac{2}{1-\alpha}}}e^{-(N^{-\frac{2}{1-\alpha}}-\tau
)\Delta}(e^{\tau\Delta}u_0)^2d\tau\|_{_{M_{2,q}^{s,\alpha}}}^q\\
&\geq \langle j_0\rangle^{\frac{sq}{1-\alpha}}\|\Box^{\alpha}_{j_0}
 \int_0^{N^{-\frac{2}{1-\alpha}}}e^{(N^{-\frac{2}{1-\alpha}}-\tau)\Delta}
(e^{\tau\Delta}u_0)^2d\tau \| _{L^2}^q \\
&= \langle j_0\rangle^{\frac{sq}{1-\alpha}}\| \varphi^{\alpha}_{j_0}(\xi)
 \int_0^{N^{-\frac{2}{1-\alpha}}}e^{-(N^{-\frac{2}{1-\alpha}}-\tau)|\xi |^2}
\left\{ (e^{\tau|\cdot|^2}\widehat{u_0})*(e^{\tau|\cdot|^2}\widehat{u_0})\right\}
 d\tau\|^q_{L^2}\\
&\succeq \langle j_0\rangle^{\frac{sq}{1-\alpha}}
 \Big(\int_0^{N^{-\frac{2}{1-\alpha}}}\| \widehat{u_0}*\widehat{u_0}
 \| _{L^2(\operatorname{supp}\varphi^{\alpha}_{j_0})}d\tau\Big)^q\\
&\succeq N^{\frac{sq}{1-\alpha}-\frac{2q}{1-\alpha}+\frac{\alpha}{1-\alpha}
 \frac{qn}{2}+\frac{q\alpha n}{1-\alpha}}
\end{align*}
So, we have
 $$
\|\int_0^{N^{-\frac{2}{1-\alpha}}}e^{-(N^{-\frac{2}{1-\alpha}}-\tau
)\Delta}(e^{\tau\Delta}u_0)^2d\tau\|_{_{M_{2,q}^{s,\alpha}}}
\succeq
N^{\frac{s}{1-\alpha}+\frac{n}{2}\frac{\alpha}{1-\alpha}
+\frac{\alpha n}{1-\alpha}-\frac{2}{1-\alpha}}.
$$
Hence, when $s-\frac{n}{2}\alpha<-2$, map \eqref{e3.3} fail to be continuous;
this lead the heat equation \eqref{e1.1}  being ill-posed in
$L^{\infty}([0,T];M_{2,q}^{s,\alpha})$ for any fixed $T>0$.

\subsection{Acknowledgments}
This work is supported by the NSF of China (Grants  11271330 and 11471288)


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\end{document}


