\documentclass[reqno]{amsart}
\usepackage{hyperref}

\AtBeginDocument{{\noindent\small
\emph{Electronic Journal of Differential Equations},
Vol. 2016 (2016), No. 267, pp. 1--27.\newline
ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu}
\thanks{\copyright 2016 Texas State University.}
\vspace{7mm}}

\begin{document}
\title[\hfilneg EJDE-2016/267\hfil
 Methods in half-linear asymptotic theory]
{Methods in half-linear asymptotic theory}

\author[P. \v{R}eh\'ak \hfil EJDE-2016/267\hfilneg]
{Pavel \v{R}eh\'ak}

\address{Pavel \v{R}eh\'ak \newline
Institute of Mathematics,
Czech Academy of Sciences, 
\v{Z}i\v{z}kova 22, CZ-61662 Brno, Czech Republic}
\email{rehak@math.cas.cz}

\thanks{Submitted August 14, 2015. Published October 7, 2016.}
\subjclass[2010]{34C11, 34C41, 34E05, 26A12}
\keywords{Half-linear differential equation; nonoscillatory solution;
\hfill\break\indent regular variation; asymptotic formula}

\begin{abstract}
 We study the asymptotic behavior of eventually positive solutions of
 the second-order half-linear differential equation
 $$
 (r(t)|y'|^{\alpha-1}\operatorname{sgn} y')'=p(t)|y|^{\alpha-1}\operatorname{sgn} y,
 $$
 where $r(t)$ and $p(t)$ are positive continuous functions on
 $[a,\infty)$, $\alpha\in(1,\infty)$. The aim of this article is
 twofold. On the one hand, we show applications of a wide variety
 of tools, like the Karamata theory of regular variation, the de
 Haan theory, the Riccati technique, comparison theorems, the
 reciprocity principle, a certain transformation of dependent
 variable, and principal solutions. On the other hand, we solve
 open problems posed in the literature and generalize existing
 results. Most of our observations are new also in the linear
 case.
\end{abstract}

\maketitle
\numberwithin{equation}{section}
\newtheorem{theorem}{Theorem}[section]
\newtheorem{lemma}[theorem]{Lemma}
\newtheorem{proposition}[theorem]{Proposition}
\newtheorem{remark}[theorem]{Remark}
\newtheorem{corollary}[theorem]{Corollary}
\newtheorem{example}[theorem]{Example}
\allowdisplaybreaks

\section{Introduction}

We consider the second-order half-linear differential  equation
\begin{equation} \label{e}
(r(t)\Phi(y'))'=p(t)\Phi(y),
\end{equation}
where $r,p$ are positive continuous functions on $[a,\infty)$ and
$\Phi(u)=|u|^{\alpha-1}\operatorname{sgn} u$ with $\alpha>1$. Actually, the aim
of this paper is twofold. First, we complete somehow the study of
asymptotic properties of solutions to \eqref{e} given in \cite{pv}
and solve some open problems posed there; see also
\cite{geluk1990, geluk-maric-tomic, jar-kus-tan2003,
jar-kus-tan2006, kus-man, maric, maric-tomic1990, rehak-jmaa} for
closely related works. Second, we present applications of various
tools in the asymptotic theory of linear and half-linear
differential equations. In particular, we deal with the Riccati
technique, the Karamata theory of regular variation, the de Haan
theory, the reciprocity principle, comparison results, a certain
transformation of dependent variable, and principal solutions.

We give conditions guaranteeing regular variation of all positive
solutions of equation \eqref{e} and establish asymptotic formulas
for them. In several cases we offer more than one approach. Some
of the results (or at least the methods) appear to be new even in
the linear case. Our results can be understood as that they
provide a more precise description of behavior of solutions in
standard asymptotic classes. For the standard classification of
nonoscillatory solutions to \eqref{e} and basic existence theorems
see \cite{cdm2000,cdm2001,cdmv2006}, \cite[Chapter~4]{book}, and
\cite{mirzov}.

That the theory of regular variation is well suited for the study
of asymptotic behavior of differential equations was shown in
particular in the monograph \cite{maric} which summarizes the
research up to 2000. A survey of recent progress is made in
\cite{amathnet}. The already mentioned papers \cite{geluk1990,
geluk-maric-tomic, maric-tomic1990} present applications to linear
differential equations. Half-linear differential equations in the
framework of the Karamata theory and the de Haan theory are
treated in the works \cite{jar-kus-tan2003, jar-kus-tan2006,
patikova, rehak-jmaa, rehak-amc, pv}.


The article is organized as follows. In the next section we recall
some information on the Karamata theory of regularly varying
functions and on the de Haan theory. Basic classification of
nonoscillatory solutions to \eqref{e} is given in
Section~\ref{S:basic}. We will utilize results on slowly varying
solutions to \eqref{e} established in \cite{pv}; they are recalled
and bettered in Section~\ref{S:SV}. A theorem on non-slowly
varying solutions under the same setting as in Section~\ref{S:SV}
forms the main part of Section~\ref{S:nonSV}. We offer two
approaches. The first one is based on the result from
Section~\ref{S:SV}, the reciprocity principle, and the Karamata
theory. The second one uses the Riccati technique, the Karamata
theory, and the de Haan theory. We discuss regularly varying
solutions also under a different setting.
Section~\ref{S:sum} offers a summary, and incorporates the results
into a broader context, namely the standard classification of
nonoscillatory solutions. In Section~\ref{S:L} we discuss some
methods that are not fully available in the half-linear case. Some
directions for a future research are indicated in the last
section. Sections \ref{S:nonSV}--\ref{S:L} contain various
examples and further comments including a comparison with existing
results.


\section{Regular variation and de Haan class $\Pi$}

In this section we recall basic information on the Karamata theory
of regularly varying functions and the de Haan theory; for a
deeper study of this topic see the monographs
\cite{bgt,geluk,dehaan}.

A measurable function $f:[a,\infty)\to(0,\infty)$ is called
\emph{regularly varying (at infinity) of index}
$\vartheta$ if
\begin{equation} \label{D:RV}
\lim_{t\to\infty}\frac{f(\lambda t)}{f(t)}=\lambda^\vartheta
\quad \text{for every $\lambda>0$;}
\end{equation}
we write $f\in{\mathcal{RV}}(\vartheta)$. If $\vartheta=0$, then we speak about
\emph{slowly varying} functions;
we write $f\in{\mathcal{SV}}$, thus ${\mathcal{SV}}={\mathcal{RV}}(0)$.

The so-called Uniform Convergence Theorem (see e.g. \cite{bgt}) says that
if $f\in{\mathcal{RV}}(\vartheta)$, then relation \eqref{D:RV} holds uniformly
on each compact $\lambda$-set in $(0,\infty)$.

It follows that $ f \in {\mathcal{RV}}(\vartheta) $ if and only if there
exists a function $ L \in {\mathcal{SV}} $ such that
 $ f(t) = t^{\vartheta} L(t) $ for every $ t$.
 The slowly varying component of $f\in
{\mathcal{RV}}(\vartheta)$ will be denoted by $L_f$, i.e.,
$$
L_f(t):=\frac{f(t)}{t^{\vartheta}}.
$$

The Representation Theorem (see e.g. \cite{bgt}) says the following:

\begin{theorem} \label{T:repr}
$f\in {\mathcal{RV}}(\vartheta)$ if and only if
\begin{equation} \label{repr}
f(t)=\varphi(t)t^\vartheta\exp\Big\{\int_a^t\frac{\psi(s)}{s}\, \mathrm{d} s\Big\},
\end{equation}
$t\ge a$, for some $a>0$, where $\varphi, \psi$ are measurable with
$\lim_{t\to\infty}\varphi(t)=C\in(0,\infty)$ and $\lim_{t\to\infty}\psi(t)=0$.
\end{theorem}

A function $f\in {\mathcal{RV}}(\vartheta)$ can alternatively be represented as
\begin{equation} \label{repr2}
f(t)=\varphi(t)\exp\Big\{\int_a^t\frac{\omega(s)}{s}\, \mathrm{d} s\Big\},
\end{equation}
$t\ge a$, for some $a>0$, where $\varphi, \omega$ are measurable
with $\lim_{t\to\infty}\varphi(t)=C\in(0,\infty)$ and
$\lim_{t\to\infty}\omega(t)=\vartheta$.

 A regularly varying function $ f $ is said to be
\emph{normalized regularly varying}, we write $ f \in {\mathcal{NRV}}(\vartheta)$, if
$\varphi(t)\equiv C$ in
\eqref{repr} or in \eqref{repr2}. If \eqref{repr} holds with $ \vartheta = 0$
and $\varphi(t)\equiv C$, we say that $ f $ is \emph{normalized slowly varying},
we write $ f \in {\mathcal{NSV}}$. Clearly, if $ f $ is a $ C^1 $ function and
$ \lim_{t \to \infty} {tf'(t)}/{f(t)} = \vartheta$,
then $ f \in {\mathcal{NRV}} (\vartheta)$.
Conversely, if $f\in{\mathcal{NRV}}(\vartheta)\cap C^1$,
then $\lim_{t\to\infty}tf'(t)/f(t)=\vartheta$.

The following Karamata Integration Theorem (see e.g.
\cite{bgt,geluk})  will be very helpful in the sequel.  As usual,
the relation $f(t)\sim g(t)$ (as $t\to\infty$) means
$\lim_{t\to\infty}f(t)/g(t)=1$.

\begin{theorem} \label{T:karam}
If $ L \in {\mathcal{SV}},$ then
\begin{gather*}
\int_t^{\infty} s^{\vartheta}L(s)\, \mathrm{d} s  \sim \frac 1 {-\vartheta - 1}
  t^{\vartheta + 1} L(t) \quad \text { provided } \vartheta < -1, \\
\int_a^t s^{\vartheta}L(s)\,\mathrm{d} s  \sim \frac 1 {\vartheta + 1}
t^{\vartheta + 1} L(t) \quad \text { provided } \vartheta > -1
\end{gather*}
as $t\to\infty$. Moreover, if $ \int_a^{\infty} L(s)/s\, \mathrm{d} s $ converges,
then $ \tilde L(t) = \int_t^{\infty} L(s)/s\, \mathrm{d} s$ is a ${\mathcal{SV}}$ function;
if $ \int_a^{\infty} L(s)/s\, \mathrm{d} s $ diverges, then
 $ \tilde L(t) = \int_a^t L(s)/s\, \mathrm{d} s$ is a ${\mathcal{SV}}$ function;
in both cases, ${L(t)}/ {\tilde L(t)} \to 0$ as $t\to\infty$.
\end{theorem}

Here are further properties of ${\mathcal{RV}}$ functions that are useful in
our theory.

\begin{proposition}\label{P:RV} \quad
\begin{itemize}
\item[(i)]
If $f\in{\mathcal{RV}}(\vartheta)$, then $\ln f(t)/\ln t\to\vartheta$ as
$t\to\infty$. It then clearly implies that
$\lim_{t\to\infty}f(t)=0$ provided $\vartheta<0$, and
$\lim_{t\to\infty}f(t)=\infty$ provided $\vartheta>0$.

\item[(ii)]
If $f\in{\mathcal{RV}}(\vartheta)$, then $f^\alpha\in{\mathcal{RV}}(\alpha\vartheta)$ for every
$\alpha\in\mathbb{R}$.

\item[(iii)]
If $f_i\in{\mathcal{RV}}(\vartheta_i)$, $i=1,2$, $f_2(t)\to\infty$ as $t\to\infty$,
then $f_1\circ f_2\in{\mathcal{RV}}(\vartheta_1\vartheta_2)$.

\item[(iv)]
If $f_i\in{\mathcal{RV}}(\vartheta_i)$, $i=1,2$, then
$f_1+ f_2\in{\mathcal{RV}}(\max\{\vartheta_1, \vartheta_2\})$.

\item[(v)]
If $f_i\in{\mathcal{RV}}(\vartheta_i)$, $i=1,2$, then
$f_1 f_2\in{\mathcal{RV}}(\vartheta_1+\vartheta_2)$.

\item[(vi)]
If $f_1,\dots,f_n\in{\mathcal{RV}}$, $n\in\mathbb{N}$, and $R(x_1,\dots,x_n)$ is a rational
function with nonnegative  coefficients, then $R(f_1,\dots,f_n)\in{\mathcal{RV}}$.

\item[(vii)]
If $L\in{\mathcal{SV}}$ and $\vartheta>0$, then $t^\vartheta L(t)\to\infty$,
 $t^{-\vartheta}L(t)\to 0$ as $t\to\infty$.

\item[(viii)]
If $f\in{\mathcal{RV}}(\vartheta)$, $\vartheta\ne 0$, then there exists $g\in
C^1$ with $g(t)\sim f(t)$ as $t\to\infty$ and such that
$tg'(t)/g(t)\to\vartheta$, whence $g\in{\mathcal{NRV}}(\vartheta)$. Moreover,
$g$ can be taken such that $|g'|\in{\mathcal{NRV}}(\vartheta-1)$.

\item[(ix)] If $|f'|\in{\mathcal{RV}}(\vartheta)$, $\vartheta\ne-1$, with
$f'$ being eventually of one sign, then
$f\in{\mathcal{NRV}}(\vartheta+1)$.
\end{itemize}
\end{proposition}

\begin{proof}
The proofs of (i)--(viii) are either easy or can be found in
\cite{bgt,geluk}.

(ix) By the Karamata theorem, $f(t)=f(a)+\int_a^t f'(s)\,\mathrm{d}
s\sim \int_a^t f'(s)\,\mathrm{d} s\sim{t}f'(t)/(\vartheta+1)$ as
$t\to\infty$ when $\vartheta>-1$, resp. $f(t)=-\int_t^\infty
f'(s)\,\mathrm{d} s\sim{t}f'(t)/(\vartheta+1)$ as $t\to\infty$ when
$\vartheta<-1$. Hence, $\lim_{t\to\infty}tf'(t)/f(t)=\vartheta+1$.
\end{proof}

A measurable function $f:[a,\infty)\to\mathbb{R}$ is said to belong to the
class $\Pi$ if there exists a function $w:(0,\infty)\to(0,\infty)$
such that for $\lambda>0$
\begin{equation} \label{D:dehaan1}
\lim_{t\to\infty}\frac{f(\lambda t)-f(t)}{w(t)}=\ln \lambda;
\end{equation}
we write $f\in\Pi$ or $f\in\Pi(w)$. The function $w$ is called an
\emph{auxiliary function} for $f$. The class $\Pi$, after taking
absolute values, forms a proper subclass of ${\mathcal{SV}}$.

\begin{proposition}\label{P:Pi} \quad
\begin{itemize} 
\item[(i)]
If $f\in\Pi$, then for $0<c<d<\infty$ relation \eqref{D:dehaan1}
holds uniformly for $\lambda\in[c,d]$.

\item[(ii)]
Auxiliary function is unique up to asymptotic equivalence.

\item[(iii)]
If $f\in\Pi(v),$ then
\begin{equation} \label{fv}
v(t)\sim f(t)-\frac 1t\int_a^t f(s)\,\mathrm{d} s
\end{equation}
as $t\to\infty$.

\item[(iv)] If $f\in\Pi$, then $\lim_{t\to\infty}f(t)=:f(\infty)\le\infty$
exists. If the limit is infinite, then $f\in{\mathcal{SV}}$. If the limit is
finite, then $f(\infty)-f(t)\in{\mathcal{SV}}$.

\item[(v)] If $f'\in{\mathcal{RV}}(-1)$, then $f\in\Pi(tf'(t))$.
\end{itemize}
\end{proposition}


\begin{proof}
The proofs of (i)--(iv) can be found in \cite{geluk, dehaan}.

(v) For every $ \lambda > 0,$ we have
\begin{equation*} %\label{pi}
\frac {f(\lambda t) - f(t)} {tf'(t)} = \int_t^{\lambda t} \frac
{f'(u)}{tf'(t)}\, \mathrm{d} u = \int_1^{\lambda} \frac {f'(st)}
{f'(t)}\, \mathrm{d} s \to \int_1^{\lambda} \frac 1 s\, \mathrm{d} s = \ln
\lambda,
\end{equation*}
as $ t \to \infty,$  because $ {f'(st)}/ {f'(t)} \to 1/s $
uniformly as $t\to\infty$ in the interval $\big[\min\{1,\lambda\},
\max\{1,\lambda\}\big]$.
\end{proof}

We write $f\in\Pi{\mathcal{RV}}(\vartheta;w)$ if $t^{-\vartheta}f\in\Pi(w)$.
Then we speak about $\Pi$-regular variation; this concept was
introduced in \cite{geluk1981}.

\section{Basic information on nonoscillatory solutions}
\label{S:basic}

It is known (see \cite[Chapter 4]{book}) that \eqref{e} with
positive $r,p$ is nonoscillatory, i.e. all its solutions are
eventually of constant sign. Without loss of generality, we work
just with positive solutions, i.e. with the class
$$ \mathcal{S} = \{ y: y(t) \text{ is a positive solution of
\eqref{e} for large }t\}.
$$
Because of the sign conditions on the coefficients, all positive
solutions of \eqref{e} are eventually monotone, therefore they
belong to one of the following disjoint classes:
\begin{gather*}
{\mathcal{IS}} = \{ y \in \mathcal{S}: y'(t)>0 \text{ for large } t \}, \\
{\mathcal{DS}} = \{ y \in \mathcal{S}: y'(t)<0 \text{ for large } t \}.
\end{gather*}
It can be shown that both these classes are nonempty (see
\cite[Lemma 4.1.2]{book}). The classes ${\mathcal{IS}},{\mathcal{DS}}$ can be divided
into four mutually disjoint subclasses:
\begin{gather*}
{\mathcal{IS}}_{\infty} = \{ y \in {\mathcal{IS}}: \lim_{t \to \infty} y(t) = \infty \}, \quad
{\mathcal{IS}}_B = \{ y \in {\mathcal{IS}}: \lim_{t \to \infty} y(t) = b \in \mathbb R \}, \\
{\mathcal{DS}}_B = \{ y \in {\mathcal{DS}}: \lim_{t \to \infty} y(t) = b > 0 \}, \quad
{\mathcal{DS}}_0 = \{ y \in {\mathcal{DS}}: \lim_{t \to \infty} y(t) = 0 \}.
\end{gather*}
Define the so-called quasiderivative of $y\in\mathcal{S}$ by
$y^{[1]}=r\Phi(y')$.
We introduce the following convention
\begin{gather*}
{\mathcal{IS}}_{u,v}=\{ y \in {\mathcal{IS}}: \lim_{t \to \infty} y(t) =u,\;
\lim_{t\to\infty}y^{[1]}(t)=v \}\\
{\mathcal{DS}}_{u,v}=\{ y \in {\mathcal{DS}}: \lim_{t \to \infty} y(t) =u,\;
\lim_{t\to\infty}y^{[1]}(t)=v \}.
\end{gather*}
For subscripts of ${\mathcal{IS}}$ and ${\mathcal{DS}}$, by $u=B$ resp. $v=B$ we mean
that the value of $u$ resp. $v$ is a real nonzero number. Using
this convention we further distinguish the following types of
solutions which form subclasses in ${\mathcal{DS}}_0,{\mathcal{DS}}_B,{\mathcal{IS}}_B,$ and
${\mathcal{IS}}_\infty$:
\begin{equation} \label{sbc}
{\mathcal{DS}}_{0,0}, {\mathcal{DS}}_{0,B}, {\mathcal{DS}}_{B,0}, {\mathcal{DS}}_{B,B}, {\mathcal{IS}}_{B,B},
{\mathcal{IS}}_{B,\infty}, {\mathcal{IS}}_{\infty,B}, {\mathcal{IS}}_{\infty,\infty}.
\end{equation}
More information about (non)existence of solutions in these
subclasses  is recalled in Section~\ref{S:sum}, where we include
our results into the framework of the standard classification of
nonoscillatory solutions. We will also make a comparison with
general existence conditions. Basic classification of
nonoscillatory solutions and existence results can be found in
\cite{cdm2000,cdm2001,cdmv2006, mirzov}. For a partial survey see
\cite[Chapter~4]{book}. In some places we need to emphasize that
the classes of eventually positive increasing resp. decreasing
solutions resp. their subclasses are associated to a particular
equation, say $(\ast)$. Then we write ${\mathcal{IS}}^{(\ast)}$,
${\mathcal{DS}}^{(\ast)}$, ${\mathcal{IS}}^{(\ast)}_\infty$, etc.

No matter whether $p$ is positive, if \eqref{e} is nonoscillatory,
then there exists a nontrivial solution $y$ of \eqref{e} such that
for every nontrivial solution $u$ of \eqref{e} with $u\ne\lambda
y$, $\lambda\in\mathbb{R}$, we have $y'(t)/y(t)<u'(t)/u(t)$ for large $t$,
see \cite[Section~4.2]{book}. Such a solution is said to be a
principal solution. Solutions of \eqref{e} which are not
principal, are called nonprincipal solutions. Principal solutions
are unique up to a constant multiple.

 Let $ y\in{\mathcal{S}}$ and take $ f \in C^1 $ with $ f(t) \ne 0 $ for every
(large) $t$. Denoted $ w = fr \Phi( {y'}/ y)$, it satisfies the
generalized Riccati equation
\begin{equation} \label{w}
w' - \frac {f'} f w - fp + (\alpha - 1) \frac{r^{1
-\beta}}{\Phi^{-1}(f)} |w|^{\beta} = 0,
\end{equation}
where $\Phi^{-1}$ stands for the inverse of $\Phi$, i.e.,
$\Phi^{-1}(u)=|u|^{\beta-1}\operatorname{sgn} u$, and $ \beta $ denotes the
conjugate number of $ \alpha$, i.e. $1/\alpha+1/\beta=1$. If
$f(t)\equiv1$, then \eqref{w} reduces to the usual generalized
Riccati equation
\begin{equation} \label{riccati}
w'-p(t)+(\alpha-1)r^{1-\beta}(t)|w|^{\beta}=0.
\end{equation}
If $f(t)=t^{\alpha-1}/r(t),$ then \eqref{w} takes the form
\begin{equation} \label{tw}
tw'=\Big(\alpha-1-\frac{tr'(t)}{r(t)}\Big)w+\frac{t^\alpha
p(t)}{r(t)}-(\alpha-1)|w|^\beta;
\end{equation}
note that $w(t)=\Phi(ty'(t)/y(t)).$ A solution of the associated
generalized Riccati equation which is generated by a principal
solution is called an eventually minimal solution. According to
\cite[Theorem 4.2.2.]{book}, if $ P(t) \leq p(t) $ and
$0<R(t)\le r(t)$ for large $ t $, then the eventually minimal solutions
$w=r\Phi({y'}/ y) $ and $ z = R \Phi( {x'}/ x) $ of the generalized
Riccati equations respectively associated to \eqref{e} and
$(R(t)\Phi(x'))'=P(t)\Phi(x) $ satisfy
\begin{equation} \label{minim}
 w(t) \le z(t)
\end{equation}
 for large $t$.


\section{${\mathcal{SV}}$ solutions} \label{S:SV}

The following conditions appear frequently throughout this article:
\begin{gather} \label{pr}
p\in{\mathcal{RV}}(\delta),\quad  r\in{\mathcal{RV}}(\delta+\alpha), \\
\label{prL}
\frac{L_p(t)}{L_r(t)}\to 0\quad \text{as }t\to\infty.
\end{gather}
The relation between indices of regular variation of the
coefficients in \eqref{pr} appears to be quite natural when
dealing with ${\mathcal{SV}}$ solutions of \eqref{e}, see
\cite[Remark~11]{pv}. Set
$$
G(t)=\Big(\frac{tp(t)}{r(t)}\Big)^{\frac{1}{\alpha-1}}.
$$
If \eqref{pr} holds, then
$$
G(t)=\frac{1}{t}\Big(\frac{L_p(t)}{L_r(t)}\Big)^{\beta-1}.
$$
A substantial part of the following statement follows from \cite[Theorem~5,
Theorem~6]{pv}.

\begin{theorem} \label{T:SV}
Assume that \eqref{pr} and \eqref{prL} hold.
If $\delta<-1$, then ${\mathcal{DS}}\subset{\mathcal{NSV}}$ and $-y(t)\in\Pi(-ty'(t))$ for
any $y\in{\mathcal{DS}}$. If $\delta>-1$, then ${\mathcal{IS}}\subset{\mathcal{NSV}}$ and
$y(t)\in\Pi(ty'(t))$ for any $y\in{\mathcal{IS}}$. Moreover, for any
$y\in{\mathcal{DS}}$ when $\delta<-1$ and any $y\in{\mathcal{IS}}$ when $\delta>-1$ the
following hold:

(i) If $\int_a^\infty G(s)\,\mathrm{d} s=\infty$, then
\begin{equation} \label{a1}
y(t)=\exp\Big\{\int_a^t(1+o(1))
\frac{G(s)}{\Phi^{-1}(\delta+1)}\,\mathrm{d} s\Big\}
\end{equation}
as $t\to\infty$, with $y\in{\mathcal{DS}}_{0,0}$ provided $y\in{\mathcal{DS}}$ and
$\delta<-1$, while $y\in{\mathcal{IS}}_{\infty,\infty}$ provided $y\in{\mathcal{IS}}$
and $\delta>-1$.

(ii)  If $\int_a^\infty G(s)\,\mathrm{d} s<\infty$, then
\begin{equation} \label{a2}
y(t)=N\exp\Big\{-\int_t^\infty(1+o(1))
\frac{G(s)}{\Phi^{-1}(\delta+1)}\,\mathrm{d} s\Big\}
\end{equation}
as $t\to\infty$, where $N=\lim_{t\to\infty}y(t)\in(0,\infty)$,
with $y\in{\mathcal{DS}}_{B,0}$ provided $y\in{\mathcal{DS}}$ and $\delta<-1$, while
$y\in{\mathcal{IS}}_{B,\infty}$ provided $y\in{\mathcal{IS}}$ and $\delta>-1$. Moreover,
in any case, $|N-y|\in{\mathcal{SV}}$ and
\begin{equation} \label{hvezda}
\frac{L_p^{\beta-1}(t)}{L_r^{\beta-1}(t)(N-y(t))}=o(1)
\end{equation}
as $t\to\infty$.
\end{theorem}

\begin{proof}
We will prove only the last part of the theorem. The fact that
$|N-y|\in{\mathcal{SV}}$ follows from Proposition~\ref{P:Pi}-(iv), since
$y\in\Pi$. From the proofs of \cite[Theorem~5, Theorem~6]{pv}, we
have that
$$
y'(t)\sim\Phi^{-1}\Big(\frac{tp(t)}{(\delta+1)r(t)}\Big)y(t)
\sim\frac{N}{\Phi^{-1}(\delta+1)}\cdot\frac1t
\Big(\frac{L_p(t)}{L_r(t)}\Big)^{\beta-1}
$$
as $t\to\infty$. Integrating from $t$ to $\infty$, we obtain
$$
N-y(t)\sim\frac{N}{\Phi^{-1}(\delta+1)}\int_t^\infty\frac{1}{s}
\Big(\frac{L_p(s)}{L_r(s)}\Big)^{\beta-1}\mathrm{d} s
$$
as $t\to\infty$. Formula \eqref{hvezda} now follows from the
latter part of Theorem~\ref{T:karam}.
\end{proof}

Thanks to the next lemma, which follows from \cite[Remark~8, Remark~11]{pv},
we are dealing with all ${\mathcal{SV}}$ solutions of \eqref{e} in Theorem~\ref{T:SV}.

\begin{lemma} \label{L:allSV}
Assume that \eqref{pr} holds. If $\delta<-1$, then
${\mathcal{S}}\cap{\mathcal{SV}}\subseteq{\mathcal{DS}}$. If $\delta>-1$, then
${\mathcal{S}}\cap{\mathcal{SV}}\subseteq{\mathcal{IS}}$.
\end{lemma}

\section{Non-${\mathcal{SV}}$ solutions} \label{S:nonSV}

This section discusses the complementary case with respect to
Theorem~\ref{T:SV}; we study increasing solutions when $\delta<-1$
and decreasing solutions when $\delta>-1$. Under the same setting
(i.e., \eqref{pr} and
\eqref{prL}) we prove regular variation of these solutions where the
index is equal to
$$
\varrho:=\frac{-1-\delta}{\alpha-1}
$$
and derive asymptotic formulas. Note that if $\delta=-\alpha$
(which happens, for instance, when $r(t)\equiv 1$ under condition
\eqref{pr}), then $\varrho=1$. Set
$$
H(t)=\frac{t^{\alpha-1}p(t)}{r(t)}.
$$
If \eqref{pr} holds, then
$$
H(t)=\frac 1t\cdot\frac{L_p(t)}{L_r(t)}.
$$

\subsection{First approach}

In this subsection, we use the existing results (presented in
Section~\ref{S:SV}) in a combination with the reciprocity
principle and the Karamata theory to study non-${\mathcal{SV}}$ solutions.

The reciprocity principle is based on the following simple
relation.
 If $y$ is a
solution of \eqref{e}, then $u$ defined by $u=C r\Phi(y')$,
$C\in\mathbb{R}$, is a solution of the reciprocal equation
\begin{equation} \label{er}
(\widehat r(t)\widehat\Phi(u'))'=\widehat p(t)\widehat\Phi(u),
\end{equation}
where $\widehat r=p^{1-\beta}$, $\widehat p=r^{1-\beta}$, and
$\widehat\Phi(u)=|u|^{\widehat\alpha-1}\operatorname{sgn} u$ with
$\widehat\alpha=\beta$. Note that $\widehat\Phi=\Phi^{-1}$.

\begin{theorem} \label{T:1}
Assume that \eqref{pr} and \eqref{prL} hold.
If
$\delta<-1$, then ${\mathcal{IS}}\subset{\mathcal{NRV}}(\varrho)$. If $\delta>-1$, then
${\mathcal{DS}}\subset{\mathcal{NRV}}(\varrho)$. Moreover, one has
$y^{[1]}(t)\in\Pi(tp(t)\Phi(y(t)))$ for any
$y\in{\mathcal{S}}\cap{\mathcal{NRV}}(\varrho)$. For any $y\in{\mathcal{IS}}$ when $\delta<-1$ and
any $y\in{\mathcal{DS}}$ when $\delta>-1$ the following hold:

(i) If $\int_a^\infty H(s)\,\mathrm{d} s=\infty$, then
\begin{equation} \label{as1}
y(t)=A+\int_{a}^t\frac{1}{r^{\beta-1}(s)}\exp\Big\{\int_a^s(1+o(1))
\frac{\beta-1}{\varrho^{\alpha-1}}H(\tau)\,\mathrm{d}\tau\Big\}\,\mathrm{d}
s
\end{equation}
as $t\to\infty$, for some $A\in\mathbb{R}$, with $y\in{\mathcal{IS}}_{\infty,\infty}$
provided $y\in{\mathcal{IS}}$ and $\delta<-1$, while
\begin{equation} \label{as2}
y(t)=\int_{t}^\infty\frac{1}{r^{\beta-1}(s)}\exp\Big\{-\int_a^s(1+o(1))
\frac{\beta-1}{|\varrho|^{\alpha-1}}H(\tau)\,\mathrm{d}\tau\Big\}\,\mathrm{d}
s
\end{equation}
as $t\to\infty$, with $y\in{\mathcal{DS}}_{0,0}$ provided $y\in{\mathcal{DS}}$ and
$\delta>-1$.

(ii)  If $\int_a^\infty H(s)\,\mathrm{d} s<\infty$, then
\begin{equation} \label{as3}
y(t)=A+\int_{a}^t\frac{M^{\beta-1}}{r^{\beta-1}(s)}\exp\Big\{-\int_s^\infty(1+o(1))
\frac{\beta-1}{\varrho^{\alpha-1}}H(\tau)\,\mathrm{d}\tau\Big\}\,\mathrm{d}
s
\end{equation}
as $t\to\infty$, for some $A\in\mathbb{R}$, with $y\in{\mathcal{IS}}_{\infty,B}$
provided $y\in{\mathcal{IS}}$ and $\delta<-1$, while
\begin{equation} \label{as4}
y(t)=\int_{t}^\infty\frac{|M|^{\beta-1}}{r^{\beta-1}(s)}
\exp\Big\{\int_s^\infty(1+o(1))
\frac{\beta-1}{|\varrho|^{\alpha-1}}H(\tau)\,\mathrm{d}\tau\Big\}\,\mathrm{d}
s
\end{equation}
as $t\to\infty$, with $y\in{\mathcal{DS}}_{0,B}$ provided $y\in{\mathcal{DS}}$ and
$\delta>-1$, where
$M=\lim_{t\to\infty}y^{[1]}(t)$ in $\mathbb{R}\setminus\{0\}$. Moreover, in
any case, $M-y^{[1]}\in{\mathcal{SV}}$ and
\begin{equation} \label{dvehvezdy}
\frac{L_p(t)}{L_r(t)(M-y^{[1]}(t))}=o(1)
\end{equation}
as $t\to\infty$.
\end{theorem}

\begin{proof}
Let $\widehat {\mathcal{S}},\widehat {\mathcal{IS}},\widehat {\mathcal{DS}},
\widehat{\mathcal{IS}}_\infty,\widehat{\mathcal{IS}}_B,\widehat{\mathcal{DS}}_0,\widehat{\mathcal{DS}}_B$ have
the same meaning with respect to \eqref{er} as
${\mathcal{S}},{\mathcal{IS}},{\mathcal{DS}},{\mathcal{IS}}_\infty,{\mathcal{IS}}_B,{\mathcal{DS}}_0,{\mathcal{DS}}_B$, respectively, have
with respect to \eqref{e}. We have that $\widehat
p\in{\mathcal{RV}}(\widehat\delta)$ and $\widehat
r\in{\mathcal{RV}}(\widehat\delta+\widehat\alpha)$, where
$\widehat\delta:=\delta(1-\beta)-\beta$, thanks to \eqref{pr}.
Since $L_{\widehat p}/L_{\widehat
r}=L_r^{1-\beta}/L_p^{1-\beta}=(L_p/L_r)^{\beta-1}$ and
\eqref{prL} holds, we have $\lim_{t\to\infty}L_{\widehat
p}(t)/L_{\widehat r}(t)=0$.

Assume that $\delta<-1$ and take $y\in{\mathcal{IS}}$. Let $t_0\ge a$ be such
that $y(t)>0$, $y'(t)>0$ for $t\ge t_0$. Set $u=r\Phi(y')$. Then
$u\in\widehat{\mathcal{IS}}$ since $u'=p\Phi(y)$. We have
$\widehat\delta+\beta=-\delta(\beta-1)>\beta-1$, and so
$\widehat\delta>-1$. Note that $\widehat\delta+1=\varrho$. Now we
can apply Theorem~\ref{T:SV} to obtain $u\in{\mathcal{NSV}}$ and
$u\in\Pi(tu')$. Hence, $r\Phi(y')\in{\mathcal{NSV}}$, i.e.,
$\Phi(y')\in{\mathcal{RV}}(-\delta-\alpha)$, i.e., $y'\in{\mathcal{RV}}((-\delta-\alpha)
(\beta-1))$ with $(-\delta-\alpha)(\beta-1)>-1$. Thus,
$y\in{\mathcal{NRV}}(\varrho)$ by Proposition~\ref{P:RV}--(ix). Moreover,
$y^{[1]}=u\in\Pi(tu')=\Pi(tp\Phi(y))$ and $y\in{\mathcal{IS}}_\infty$ since
$\varrho>0$.
Next we derive an asymptotic formula for $y$. If
\begin{equation} \label{hatH}
\int_a^\infty\widehat G(s)\mathrm{d} s=\infty,\quad \text{where } \widehat
G(t)= \Big(\frac{t\widehat p(t)}{\widehat
r(t)}\Big)^{\frac{1}{\widehat\alpha-1}},
\end{equation}
then
\begin{equation} \label{u-podl}
u(t)=\exp\Big\{\int_a^t(1+o(1)) \widehat
G(s)(\widehat\delta+1)^{\frac{-1}{\widehat\alpha-1}}
\mathrm{d} s\Big\}
\end{equation}
as $t\to\infty$ and $u\in\widehat{\mathcal{IS}}_\infty$ for every
$u\in\widehat{\mathcal{IS}}$, thanks to Theorem~\ref{T:SV}. From
$u\in\widehat{\mathcal{IS}}_\infty$ and $y\in{\mathcal{IS}}_\infty$ we obtain
$y\in{\mathcal{IS}}_{\infty,\infty}$. Since
\begin{equation} \label{HH}
\widehat G(t)= \Big(\frac{t\widehat p(t)}{\widehat
r(t)}\Big)^{\frac{1}{\widehat\alpha-1}}
=\Big(\frac{tr^{1-\beta}(t)}{ p^{1-\beta}(t)}\Big)^{\alpha-1}
=\frac{t^{\alpha-1}p(t)}{r(t)}=H(t),
\end{equation}
$\widehat\delta+1=\varrho$, and $u=r(y')^{\alpha-1}$, from
\eqref{u-podl} we obtain
\begin{equation} \label{y-podl}
y'(t)=\frac{1}{r^{\beta-1}(t)}
\exp\Big\{\int_a^t(1+o(1))\frac{\beta-1}{\varrho^{\alpha-1}}H(s)\,\mathrm{d}
s\Big\}
\end{equation}
as $t\to\infty$. Note that thanks to \eqref{HH}, $\int_a^\infty
H(s)\,\mathrm{d} s=\infty$ is the same as \eqref{hatH}. Integrating
\eqref{y-podl} from $t_0$ to $t$ and realizing that $y(t_0)$ can
be replaced by some $A\in\mathbb{R}$ when $t_0$ is replaced by $a$,  we
obtain formula \eqref{as1}.

If the integral in \eqref{hatH} is convergent, i.e.,
$\int_a^\infty H(s)\,\mathrm{d} s<\infty$, then we again use Theorem~\ref{T:SV} to get
\begin{equation} \label{ur1}
r(t)\Phi(y'(t))=u(t)=M\exp\Big\{-\int_t^\infty(1+o(1))\frac{H(s)}
{\varrho^{\alpha-1}}\,\mathrm{d}
s\Big\}
\end{equation}
 as $\to\infty$, where
$M=\lim_{t\to\infty}u(t)=\lim_{t\to\infty}r(t)\Phi(y'(t))$. Since
$u\in\widehat{\mathcal{IS}}_B$ and $y\in{\mathcal{IS}}_\infty$, we have
$y\in{\mathcal{IS}}_{\infty,B}$. Formula \eqref{as3} follows from
\eqref{ur1}, where we first extract $y'$ and then integrate from
$t_0$ to $t$, with replacing $y(t_0)$ by $A$ and $t_0$ by $a$. The
fact that $M-y^{[1]}\in{\mathcal{SV}}$ follows from
Proposition~\ref{P:Pi}--(iv). Formula \eqref{dvehvezdy} is
obtained from \eqref{hvezda} applied to $u$, in view of
$u=y^{[1]}$, $(\alpha-1)(\beta-1)=1$, and $L_{\widehat
p}/L_{\widehat r}=(L_p/L_r)^{\beta-1}$.

Assume $\delta>-1$. Take $y\in{\mathcal{DS}}$. Now we set $u=-r\Phi(y')$.
Then $u\in\widehat{\mathcal{DS}}$. Since $\widehat\delta<-1$, we may apply
Theorem~\ref{T:SV} to equation \eqref{er}. We get that
$-y^{[1]}=u\in{\mathcal{NSV}}$ and $y^{[1]}=-u\in\Pi(-tu')=\Pi(tp\Phi(y))$.
Similarly as above, we have $y\in{\mathcal{NRV}}(\varrho)$ with
$\varrho=\widehat\delta+1<0$. If $\int_a^\infty H(s)\,\mathrm{d}
s=\infty$, then \eqref{hatH} holds and
\begin{equation} \label{ur2}
-r(t)\Phi(y'(t))=u(t)
=\exp\Big\{-\int_a^t(1+o(1))\frac{H(s)}{|\varrho|^{\alpha-1}}\,\mathrm{d}
s\Big\}
\end{equation}
as $t\to\infty$ for $u\in\widehat{\mathcal{DS}}$, by Theorem~\ref{T:SV}. The
fact that $y\in{\mathcal{DS}}_{0,0}$ is implied by $y\in{\mathcal{DS}}_0$ and
$u\in\widehat{\mathcal{DS}}_0$. Formula \eqref{as2} follows from \eqref{ur2},
where we first extract $y'$ and then integrate from $t$ to
$\infty$. If $\int_a^\infty H(s)\,\mathrm{d} s<\infty$, then the
integral in \eqref{hatH} is convergent and application of
Theorem~\ref{T:SV} yields
\begin{equation} \label{ur3}
-r(t)\Phi(y'(t))=u(t)=|M|
\exp\Big\{\int_t^\infty(1+o(1))\frac{H(s)}{|\varrho|^{\alpha-1}}\,\mathrm{d}
s\Big\}
\end{equation}
as $t\to\infty$, where
$M=\lim_{t\to\infty}-u(t)=\lim_{t\to\infty}r(t)\Phi(y'(t))$. From
$y\in{\mathcal{DS}}_0$ and $u\in\widehat{\mathcal{DS}}_B$, we obtain that $y\in{\mathcal{DS}}_{0,B}$.
Formula \eqref{as4} easily follows from \eqref{ur3}.
The fact that $y$ satisfies $M-y^{[1]}\in{\mathcal{SV}}$ and \eqref{dvehvezdy}
 can be proved similarly as in the case $\delta<-1$.
\end{proof}


\begin{remark}  \label{R:as} \rm
A closer examination  of the previous proof shows that the
expression $\exp\{\cdot\}$ in all formulae \eqref{as1} and
\eqref{as2} is slowly varying. Moreover,
$r^{1-\beta}\in{\mathcal{RV}}(\gamma)$,
$\gamma:=(1-\beta)(\delta+\alpha)=\varrho-1$, with $\gamma>-1$
when $\delta<-1$ resp. $\gamma<-1$ when $\delta>-1$. Hence, we can
apply the Karamata theorem to formula \eqref{as1} resp.
\eqref{as2} which in either case yields
$$
y(t)=(1+o(1))\frac{tr^{1-\beta}(t)}{|\gamma+1|}\exp
\Big\{\int_a^t(1+o(1))\frac{\beta-1}{\Phi(\varrho)}H(s)\,\mathrm{d} s\Big\}
$$
as $t\to\infty$.
Realizing that $(1+o(1))/|\gamma+1|=\exp\ln((1+o(1))/|\gamma+1|)$ and
$\int_a^\infty H(s)\,\mathrm{d} s$ diverges, we obtain
\begin{equation} \label{asform1}
y(t)=tr^{1-\beta}(t)\exp\Big\{\int_{a}^t(1+o(1))
\frac{\beta-1}{\Phi(\varrho)}H(s)\,\mathrm{d} s\Big\}
\end{equation}
as $t\to\infty$.
Alternatively, formula \eqref{asform1} can easily be obtained from
\eqref{y-podl} and \eqref{ur2}, if we realize that
$y\in{\mathcal{NRV}}(\varrho)$ implies that $y'(t)\sim\varrho y(t)/t$ as $t\to\infty$.

Assume -- under the conditions of Theorem~\ref{T:1} -- that $y$
is a solution such that
$\lim_{t\to\infty}y^{[1]}(t)=M\in\mathbb{R}\setminus\{0\}$. Integrating
the relation $y^{[1]}(t)\sim M$ and applying the Karamata
integration theorem (cf. \eqref{yM1}, \eqref{yM2} below), we obtain
the simple formula
\begin{equation} \label{asform2}
y(t)=(1+o(1))\frac{\Phi^{-1}(M)}{\varrho}tr^{1-\beta}(t)
\end{equation}
as $t\to\infty$.
\end{remark}

\begin{example} \rm
Let $p(t)=t^\delta L_p(t)$, $\delta\ne -1$, with
$L_p(t)=(\ln t)^{\nu_1}+g_1(t)$, and $r(t)=t^{\delta+\alpha}L_r(t)$ with
$L_r(t)=(\ln t)^{\nu_2}+g_2(t)$, where $|g_i(t)|=o((\ln
t)^{\nu_i})$ as $t\to\infty$, $i=1,2$, and $\nu_1<\nu_2$. Then
$L_p,L_r\in{\mathcal{SV}}$ and $\lim_{t\to\infty}L_p(t)/L_r(t)=0$. For
example, one can take $g_i(t)=\sin t$ or $g_i(t)=\ln(\ln t)$
provided $\nu_i>0$. We have
$$
H(t)=\frac{L_p(t)}{t
L_r(t)}\sim\frac{1}{t}\cdot\frac{1+g_1(t)/(\ln t)^{\nu_1}}{(\ln
t)^{\nu_2-\nu_1}(1+g_2(t)/(\ln t)^{\nu_2})}\sim\frac{1}{t}(\ln
t)^{\nu_1-\nu_2}
$$
as $t\to\infty$. Let $y$ be an eventually positive solution of \eqref{e}. If
$\nu_1-\nu_2=-1$, then $\int_a^t H(s)\,\mathrm{d} s\sim \ln(\ln t)$ and
$$
y(t)=t^\varrho(\ln t)^{\nu_2+(\beta-1)(1+o(1))/\Phi(\varrho)}
$$
as $t\to\infty$, in view of \eqref{asform1}. If $\nu_1-\nu_2>-1$,
then $$\int_a^t H(s)\,\mathrm{d} s\sim \frac{1}{\nu_1-\nu_2+1}(\ln
t)^{\nu_1-\nu_2+1}$$ and
$$
y(t)=t^\varrho(\ln
t)^{\nu_2}\exp\Big\{\frac{(\beta-1)(1+o(1))}{\Phi(\varrho)(\nu_1-\nu_2+1)}
(\ln t)^{\nu_1-\nu_2+1}\Big\}
$$
as $t\to\infty$, in view of \eqref{asform1}. If $\nu_1-\nu_2<-1$,
then $$\int_t^\infty H(s)\,\mathrm{d} s\sim \frac{1}{-\nu_1+\nu_2-1}(\ln
t)^{\nu_1-\nu_2+1}$$ and
$$
y(t)=(1+o(1))\frac{\Phi^{-1}(M)}{\varrho}t^\varrho(\ln t)^{\nu_2}
$$
as $t\to\infty$, in view of \eqref{asform2}, where
$M=\lim_{t\to\infty}r(t)\Phi(y'(t))\in\mathbb{R}\setminus\{0\}$.
\end{example}

\begin{remark} \rm
For decreasing solutions, if $\alpha=2$ and $r(t)=1$, then
Theorem~\ref{T:SV} reduces to \cite[Theorem~0.1-A]{geluk1990}.
In this case -- since we have a linear equation --
  we can obtain a linearly independent solution $x$
which satisfies $x(t)/t\in\Pi$ by the reduction of
order formula (see \cite[Remark~3]{geluk1990}),
thus $x\in{\mathcal{RV}}(1)$. A representation can also be given. This tool
however is not at disposal in the half-linear case; see also
Section~\ref{ss:7.3}.
The conclusion of Theorem~\ref{T:1} for $r(t)\not\equiv1$ is new in the
linear case. The both proofs (the above one as well as the one
in Subsection~\ref{SS:second}) are also new in the linear case.

Certain asymptotic formulae for regularly varying solutions of the
equation
\begin{equation} \label{e-kus-man}
(\Phi(y'))'+p(t)\Phi(y)=0
\end{equation}
with no sign condition on $p$ were established in very recent
paper \cite{kus-man}. The approach is quite different; a crucial
role there is played by the Banach fixed point theorem. Under
somewhat weaker assumptions than ours, the existence of a couple
of ${\mathcal{RV}}$ solutions is established and asymptotic formulae are
derived. On the other hand, in our paper we work with all positive
(eventually decreasing or increasing solutions). See also
Remark~\ref{R:RV}-(ii).
\end{remark}

\begin{remark} \label{R:3} \rm
From \cite[Remark 6]{pv}, we know that to show $\widehat
{\mathcal{DS}}\subset{\mathcal{NSV}}$ it is sufficient to assume weaker conditions,
namely $\int_a^\infty \widehat r^{1-\widehat\beta}(s)\,\mathrm{d}
s=\infty$, $\int_a^\infty \widehat p(s)\,\mathrm{d} s<\infty$, and
$\lim_{t\to\infty}\frac{t^{\widehat\alpha-1}}{\widehat
r(t)}\int_t^\infty\widehat p(s)\,\mathrm{d} s=0$. In terms of equation
\eqref{e} these conditions read as $\int_a^\infty p(s)\,\mathrm{d}
s=\infty$, $\int_a^\infty r^{1-\beta}(s)\,\mathrm{d} s<\infty$, and
\begin{equation} \label{tpr}
\lim_{t\to\infty}(tp(t))^{\beta-1}\int_t^\infty
r^{1-\beta}(s)\,\mathrm{d} s=0,
\end{equation}
respectively, and guarantee that $-r\Phi(y')\in{\mathcal{NSV}}$ for any
$y\in{\mathcal{DS}}$. If, moreover, $r\in{\mathcal{RV}}(\delta+\alpha)$ with
$\delta>-1$, then $y\in{\mathcal{NRV}}(\varrho)$; this follows from (ii),
(v), and (ix) of Proposition~\ref{P:RV}.  Note that condition
\eqref{tpr} can be written as
\begin{equation} \label{tpr1}
\lim_{t\to\infty}\frac{t^\alpha p(t)}{r(t)}=0
\end{equation}
provided $r\in{\mathcal{RV}}(\delta+\alpha)$, by the Karamata theorem. Similarly,
from \cite[Remark~9]{pv}, we obtain that the conditions
$\int_a^\infty r^{1-\beta}(s)\,\mathrm{d} s=\infty$ and
\begin{equation} \label{tpr2}
\lim_{t\to\infty}(tp(t))^{\beta-1}\int_a^t r^{1-\beta}(s)\,\mathrm{d}
s=0
\end{equation}
imply $r\Phi(y')\in {\mathcal{NSV}}$ for any $y\in{\mathcal{IS}}$. If, in addition,
$r\in{\mathcal{RV}}(\delta+\alpha)$ with $\delta<-1$, then
$y\in{\mathcal{NRV}}(\varrho)$, and \eqref{tpr2} can be written as
\eqref{tpr1}.
\end{remark}

\subsection{Necessity} \label{R:4}
Let \eqref{pr} hold. We claim that
condition \eqref{prL} is necessary for the existence of
$y\in{\mathcal{IS}}\cap{\mathcal{NRV}}(\varrho)$ (when $\delta<-1$) or
$y\in{\mathcal{DS}}\cap{\mathcal{NRV}}(\varrho)$ (when $\delta>-1$).

Indeed, assume first that $\delta<-1$ and that there exists
$y\in{\mathcal{IS}}\cap{\mathcal{NRV}}(\varrho)$. Set $w=r\Phi(y'/y)$.
Then $w$ satisfies \eqref{riccati} for large $t$, and
$0<t^{\alpha-1}w(t)/r(t)=(ty'(t)/y(t))^{\alpha-1}\to\varrho^{\alpha-1}$.
Hence, there exists $M_1>0$ such that
$w(t)\le M_1r(t)t^{1-\alpha}$ which belongs to ${\mathcal{RV}}(\delta+1)$,
and so $w(t)\to 0$ as
$t\to\infty$. Further, there exists $M_2>0$ such that
\[
r^{1-\beta}(t)w^\beta(t)=r(t)(y'(t)/y(t))^\alpha\le M_2
r(t)t^{-\alpha}\in{\mathcal{RV}}(\delta).
\]
 This implies $\int_a^\infty
r^{1-\beta}(s)w^\beta(s) \,\mathrm{d} s<\infty$. Integrating
\eqref{riccati} from $t$ to $\infty$ and multiplying by
$t^{\alpha-1}/r(t)$ we obtain
\begin{equation} \label{i-riccati}
\begin{gathered}
-\frac{t^{\alpha-1}}{r(t)}w(t)=\frac{t^{\alpha-1}}{r(t)}\int_t^\infty
p(s)\,\mathrm{d} s-(\alpha-1)z(t), \\
z(t):=\frac{t^{\alpha-1}}{r(t)}\int_t^\infty r^{1-\beta}(s)w^\beta
(s)\,\mathrm{d} s.
\end{gathered}
\end{equation}
We claim that $z(t)\to \varrho^{\alpha-1}/(\alpha-1)$ as
$t\to\infty$. Without loss of generality we may assume $r\in
{\mathcal{NRV}}(\delta+\alpha)\cap C^1$. Indeed, if $r$ is not normalized or
is not in $C^1$, then we can take $\widetilde r\in
{\mathcal{NRV}}(\delta+\alpha)\cap C^1$ with $\widetilde r(t)\sim r(t)$ when $ t
\to \infty $ (which is possible thanks to
Proposition~\ref{P:RV}--(viii)), and we have
$$
z(t)\sim\frac{t^{\alpha-1}}{\widetilde r(t)}\int_t^\infty \widetilde
r^{1-\beta}(s)\left(\widetilde
r(s)\Phi\left(\frac{y'(s)}{y(s)}\right)\right)^\beta\,\mathrm{d} s
$$
as $t\to\infty$. By the L'Hospital rule,
\begin{align*}
\lim_{t\to\infty}z(t)
&=\lim_{t\to\infty}\frac{-r^{1-\beta}(t)w^\beta(t)}{r'(t)t^{1-\alpha}
 +(1-\alpha)r(t)t^{-\alpha}}\\
&=\lim_{t\to\infty}\frac{(ty'(t)/y(t))^\alpha}{-tr'(t)/r(t)+\alpha-1}\\
&=\frac{\varrho^\alpha}{-\delta-\alpha+\alpha-1}=\frac{\varrho^{\alpha-1}}{\alpha-1}.
\end{align*}
From \eqref{i-riccati} we obtain
\begin{equation} \label{nec1}
\lim_{t\to\infty}\frac{t^{\alpha-1}}{r(t)}\int_t^\infty p(s)\,\mathrm{d} s=0,
\end{equation}
which, thanks to the Karamata theorem, yields \eqref{prL}

Similarly we proceed in the case $\delta>-1$. We assume that there
exists $y\in{\mathcal{DS}}\cap{\mathcal{NRV}}(\varrho)$ and again set $w=r\Phi(y'/y)$.
Instead of \eqref{i-riccati} we work with the Riccati type
integral equation of the form
$$
\frac{t^{\alpha-1}w(t)}{r(t)}-\frac{t^{\alpha-1}w(a)}{r(t)}
=\frac{t^{\alpha-1}}{r(t)}\int_a^t
p(s)\,\mathrm{d} s-\frac{t^{\alpha-1}}{r(t)}(\alpha-1)\int_a^t
r^{1-\beta}(s)|w(s)|^\beta \mathrm{d} s.
$$
Here, $t^{\alpha-1}/r(t)\to 0$ and $t^{\alpha-1}w(t)/r(t)\to
\Phi(\varrho)$ as $t\to 0$. We then get
\begin{equation} \label{nec2}
\lim_{t\to\infty}\frac{t^{\alpha-1}}{r(t)}\int_a^t p(s)\,\mathrm{d} s=0,
\end{equation}
which yields again \eqref{prL}, by the Karamata theorem. This
conclusion can be reached also in an alternative way, where we
apply \cite[Remark~6, Remark~9]{pv} and the reciprocity principle.

Observe that if we drop the condition $p\in{\mathcal{RV}}(\delta)$, then
necessary conditions read as \eqref{nec1} resp. \eqref{nec2}.

\subsection{Second approach} \label{SS:second}

Let us assume that the assumptions of Theorem~\ref{T:1} hold. Next we
present an alternative approach to the proof. The Riccati technique in
combination with the Karamata theory is directly used to show that
all increasing resp. decreasing solutions of \eqref{e} are in
${\mathcal{NRV}}(\varrho)$. Regular variation and the de Haan theory are then
utilized to obtain asymptotic formulas from Remark~\ref{R:as}.
In Section~\ref{S:L}, which is devoted to linear equations,
we offer another approaches to this problem.

\begin{proof}[Proof of ${\mathcal{IS}}\subset{\mathcal{NRV}}(\varrho)$]
Let $\delta<-1$. Take $y\in{\mathcal{IS}}$. We want to show that
$y\in{\mathcal{NRV}}(\varrho)$.

First assume that $r\in C^1\cap{\mathcal{NRV}}(\delta+\alpha)$.
Set $w(t)=\Phi(ty'(t)/y(t))$. Then $w$ is
positive and satisfies equation \eqref{tw} for large $t$, which
can be written as
\begin{equation} \label{tw+}
tw'=\frac{L_p(t)}{L_r(t)}
+w\Big(\alpha-1-\frac{tr'(t)}{r(t)}-(\alpha-1)w^{\beta-1}\Big).
\end{equation}
We claim that $\lim_{t\to\infty}w(t)=\varrho^{\alpha-1}$.
Let $w'(t)>0$
for large $t$. Then we obtain $\lim_{t\to\infty}w(t)=A\in(0,\infty]$. If
$A=\infty$, then the right-hand side of \eqref{tw+} tends to
$-\infty$, and so $\lim_{t\to\infty}tw'(t)=-\infty$, which
contradicts eventual positivity of $w'$. If
$A\in(0,\infty)\setminus\{\varrho^{\alpha-1}\}$, then $tw'(t)\sim
C:=A(-1-\delta-(\alpha-1)A^{\beta-1})\ne 0$ as $t\to\infty$. Thus,
$w(t)-w(a)\sim C\int_a^t 1/s\,\mathrm{d} s=C\ln (t/a)$ as $t\to\infty$,
which contradicts $A\in\mathbb{R}$. Now let $w'(t)<0$ for large $t$, say
$t\ge t_0$. Then $\lim_{t\to\infty}w(t)=B\in[0,\infty)$. If $B=0$,
then $\lim_{t\to\infty}ty'(t)/y(t)=0$, and so $y\in{\mathcal{NSV}}$. This
contradicts with the fact that ${\mathcal{SV}}$ solutions cannot increase
(see Lemma~\ref{L:allSV}). If
$B\in(0,\infty)\setminus\{\varrho^{\alpha-1}\}$, then similarly as
above we obtain a contradiction with $B\in\mathbb{R}.$ Finally, assume that
there exists a sequence $\{t_n\}_n$, with
$\lim_{n\to\infty}t_n=\infty$, such that $w'(t_n)=0$. We take here
zeroes of $w'$ being consecutive. From \eqref{tw+}, we have
\begin{equation} \label{hv1}
0=\frac{L_p(t_n)}{L_r(t_n)}+w(t_n)\Big(\alpha-1-\frac{t_n
r'(t_n)}{r(t_n)}-(\alpha-1)w^{\beta-1}(t_n)\Big).
\end{equation}
Hence, $w(t)$ hits the real roots of
\begin{equation} \label{Llambda}
0=\frac{L_p(t_n)}{L_r(t_n)}+\lambda\Big(\alpha-1-\frac{t_n
r'(t_n)}{r(t_n)}-(\alpha-1)\lambda^{\beta-1}\Big)
\end{equation}
at $t=t_n$. Observe that for large $n$, the roots are
(arbitrarily) close to the roots of
\begin{equation} \label{mu}
0=\mu(-1-\delta-(\alpha-1)\mu^{\beta-1}),
\end{equation}
i.e., $\mu=0$ and $\mu=\varrho^{\alpha-1}$. Hence, if $|\lambda|$,
$\lambda=\lambda(n)$ being the root of \eqref{Llambda}, is very
small (such root clearly corresponds to the root $\mu=0$ of
\eqref{mu}), then
$\alpha-1-t_nr'(t_n)/r(t_n)-(\alpha-1)|\lambda|^{\beta-1}>0$,
thanks to
$\alpha-1-t_nr'(t_n)/r(t_n)\to\alpha-1-\delta-\alpha=-1-\delta>0$
as $n\to\infty$. Because of positivity of $L_p/L_r$, we must then
have $\lambda<0$, which is impossible since $w(t)>0$. Hence,
$w(t)$ hits the positive roots of \eqref{Llambda} at $t=t_n$ which
tends to $\varrho^{\alpha-1}$ as $n\to\infty$. Consequently,
$\lim_{n\to\infty}w(t_n)=\varrho^{\alpha-1}$. The function $w$ is
monotone between zeroes of $w'$, thus
$\min\{w(t_n),w(t_{n+1})\}\le w(t)\le \max\{w(t_n),w(t_{n+1})\}$,
$t_n\le t\le t_{n+1}$. Hence,
$\lim_{t\to\infty}w(t)=\varrho^{\alpha-1}$ also in this case.

Altogether we have
$\lim_{t\to\infty}(ty'(t)/y(t))^{\alpha-1}=\lim_{t\to\infty}w(t)=\varrho^{\alpha-1}$,
which implies $y\in{\mathcal{NRV}}(\varrho)$.

Now we drop the assumption of continuous differentiability and
normality of regular variation of $r$. From
Proposition~\ref{P:RV}--(viii), there exists $\bar r$ such that
$\bar r(t)\sim r(t)$ as $t\to\infty$ and $\bar r \in
C^1\cap{\mathcal{NRV}}(\delta+\alpha)$. For every $\varepsilon\in(0,1)$ there
exists $t_\varepsilon$ such that $(1-\varepsilon)\bar r(t)\le
r(t)\le(1+\varepsilon)\bar r(t)$ for $t\ge t_\varepsilon$.
According to \cite[Lemma~4.1.2]{book}, there exist eventually
positive increasing solutions $u,v$, respectively, of the problems
\begin{equation} \label{ueps}
\big((1-\varepsilon)\bar r(t)\Phi(u')\big)'=p(t)\Phi(u), \ \
u(t_\varepsilon)=u_0,\ u'(t_\varepsilon)=u_1,
\end{equation}
and
\begin{equation} \label{veps}
\big((1+\varepsilon)\bar r(t)\Phi(v')\big)'=p(t)\Phi(v), \ \
v(t_\varepsilon)=v_0,\ v'(t_\varepsilon)=v_1,
\end{equation}
with $u_0,u_1,v_0,v_1$ positive and such that
$$
(1-\varepsilon)\bar
r(t_\varepsilon)\Big(\frac{u_1}{u_0}\Big)^{\alpha-1}\le
r(t_\varepsilon)\Big(\frac{y'(t_\varepsilon)}{y(t_\varepsilon)}\Big)^{\alpha-1}
\le (1+\varepsilon)\bar
r(t_\varepsilon)\Big(\frac{v_1}{v_0}\Big)^{\alpha-1}.
$$
Define $w_u=(1-\varepsilon)\bar r\Phi(u'/u)$, $w_y=r\Phi(y'/y)$,
and $w_v=(1+\varepsilon)\bar r\Phi(v'/v)$. These functions
satisfy respectively the generalized Riccati equations
$w'_u=p(t)-(\alpha-1)(1-\varepsilon)^{1-\beta}\bar
r^{1-\beta}(t)w_u^\beta$, $w'_y=p(t)-(\alpha-1)
r^{1-\beta}(t)w_y^\beta$, and
$w'_v=p(t)-(\alpha-1)(1+\varepsilon)^{1-\beta}\bar
r^{1-\beta}(t)w_v^\beta$. Since we actually have
$(1-\varepsilon)^{1-\beta}\bar
r^{1-\beta}\le-r^{1-\beta}\le(1+\varepsilon)^{1-\beta}\bar
r^{1-\beta}$ and $w_u(t_\varepsilon)\le w_y(t_\varepsilon)\le
w_v(t_\varepsilon)$, from the classical result on differential
inequalities (see \cite[Chapter~III, Section~4]{hartman}), we obtain
$w_u(t)\le w_y(t)\le w_v(t)$ for $t\ge t_\varepsilon$.
Consequently,
\begin{equation} \label{40,5}
(1-\varepsilon)\Big(\frac{tu'(t)}{u(t)}\Big)^{\alpha-1}\le\frac{r(t)}{\bar
r(t)}\Big(\frac{ty'(t)}{y(t)}\Big)^{\alpha-1}\le(1+\varepsilon)
\Big(\frac{tv'(t)}{v(t)}\Big)^{\alpha-1}
\end{equation}
for $t\ge t_\varepsilon$. From the previous part we
know that
$\lim_{t\to\infty}tu'(t)/u(t)=\varrho=\lim_{t\to\infty}tv'(t)/v(t)$.
Hence,
$$
(1-\varepsilon)^{\beta-1}\varrho\le\liminf_{t\to\infty}\frac{ty'(t)}{y(t)}
\le \limsup_{t\to\infty}\frac{ty'(t)}{y(t)}\le
(1+\varepsilon)\varrho.
$$
Since $\varepsilon\in(0,1)$ was arbitrary,
$\lim_{t\to\infty}ty'(t)/y(t)=\varrho$ and so $y\in{\mathcal{NRV}}(\varrho)$.
\end{proof}

\begin{proof}[Proof of asymptotic formula in the case $\delta<-1$]
Take $y\in{\mathcal{NRV}}(\varrho)\cap {\mathcal{IS}}$.
 Clearly, $y\in{\mathcal{IS}}_\infty$ since
$\varrho>0$. From \eqref{e},
$(r\Phi(y'))'=p\Phi(y)\in{\mathcal{RV}}(\delta+(\alpha-1)\varrho)={\mathcal{RV}}(-1)$.
Hence, $r\Phi(y')\in\Pi(t(r\Phi(y'))')=\Pi(tp\Phi(y))$, in view of
Proposition~\ref{P:Pi}--(v). Thanks to relation \eqref{fv}, we now
obtain
\begin{equation} \label{troj}
tp(t)\Phi(y(t))\sim r(t)\Phi(y'(t))-\frac{1}{t}\int_a^t
r(s)\Phi(y'(s))\,\mathrm{d} s
\end{equation}
as $t\to\infty$; without loss of generality, we may assume that $y(t)>0$
and $y'(t)>0$ for $t\ge a$. Since $r\Phi(y')\in{\mathcal{SV}}$, the Karamata integration
theorem yields
\[
\int_a^t r(s)\Phi(y'(s))\,\mathrm{d} s\sim tr(t)\Phi(y'(t))
\]
 as $t\to\infty$. Further, from
$y\in{\mathcal{NRV}}(\varrho)$, $y'(t)\sim\varrho y(t)/t$ as $t\to\infty$.
These two relations imply
\begin{equation} \label{troj2}
\int_a^t r(s)\Phi(y'(s))\,\mathrm{d} s\sim
t^{2-\alpha}r(t)\Phi(\varrho)y^{\alpha-1}(t)
\end{equation}
as $t\to\infty$. From \eqref{troj} and \eqref{troj2}, we obtain
\begin{equation} \label{troj3}
\frac{r(t)\Phi(y'(t))}{\int_a^t r(s)\Phi(y'(s))\,\mathrm{d}
s}-\frac1t\sim\frac{tp(t)y^{\alpha-1}(t)}{t^{2-\alpha}r(t)\varrho^{\alpha-1}y^{\alpha-1}(t)}=\frac{H(t)}{\varrho^{\alpha-1}}
\end{equation}
as $t\to\infty$. Relation \eqref{troj3} can be rewritten as
\begin{equation} \label{troj35}
\Big(\ln\frac{\int_a^t r(s)\Phi(y'(s))\,\mathrm{d}
s}{t}\Big)'=(1+o(1))\frac{H(t)}{\varrho^{\alpha-1}}
\end{equation}
as $t\to\infty$.
Integration from $t_0>a$ to $t$ yields
\begin{equation} \label{troj4}
\int_{t_0}^t(1+o(1))\frac{H(s)}{\Phi(\varrho)}\,\mathrm{d} s=
\ln\frac{\int_a^t r(s)\Phi(y'(s))\,\mathrm{d} s}{Dt},
\end{equation}
where $D=\frac{1}{t_0}\int_a^{t_0} r(s)\Phi(y'(s))\,\mathrm{d} s$.

Let $\int_a^\infty H(s)\,\mathrm{d} s=\infty$.
 Then $\lim_{t\to\infty}\frac1t\int_a^t
r(s)\Phi(y'(s))\,\mathrm{d} s=\infty$ and since $r\Phi(y')$ is positive
increasing, the L'Hospital rule implies that
$\lim_{t\to\infty}r(t)\Phi(y'(t))=\infty$ otherwise we would get a contradiction.
Hence, $y\in{\mathcal{IS}}_{\infty,\infty}$. Using \eqref{troj2}
in \eqref{troj4},
$$
Dt\exp\Big\{\int_{t_0}^t(1+o(1))\frac{H(s)}{\varrho^{\alpha-1}}\,\mathrm{d}
s\Big\}=(1+o(1))t^{2-\alpha}r(t)\varrho^{\alpha-1}y^{\alpha-1}(t)
$$
as $t\to\infty$. Realizing that $(1+o(1))D/\varrho^{\alpha-1}=\exp
\ln((1+o(1))D/\varrho^{\alpha-1})$ and $\int_a^\infty H(s)\,\mathrm{d} s$ diverges, we have
$$
y^{\alpha-1}(t)=\frac{t^{\alpha-1}}{r(t)}\exp\Big\{\int_{t_0}^t
(1+o(1))\frac{H(s)}{\varrho^{\alpha-1}}\,\mathrm{d} s\Big\}
$$
as $t\to\infty$. Raising by $\beta-1$ we obtain formula \eqref{asform1}.

Let $\int_a^\infty H(s)\,\mathrm{d} s<\infty$. Then, from \eqref{troj4},
$\lim_{t\to\infty}\frac1t\int_a^t r(s)\Phi(y'(s))\,\mathrm{d}
s=M\in(0,\infty)$. For the positive increasing $y^{[1]}=r\Phi(y')$ we must
then have $\lim_{t\to\infty}y^{[1]}(t)=M$, and so $y\in{\mathcal{IS}}_{\infty,B}$.
This immediately
implies $y'(t)\sim M^{\beta-1}r^{1-\beta}(t)$. Integrating this
relation and using the Karamata theorem,
\begin{equation} \label{yM1}
\begin{aligned}
y(t) &\sim y(t)-y(t_0)\sim M^{\beta-1}\int_{t_0}^t
r^{1-\beta}(s)\,\mathrm{d} s
\\ &
\sim
\frac{M^{\beta-1}}{(\delta+1)(1-\beta)}t^{(\delta+1)(1-\beta)}L_r^{1-\beta}(t)\\
& \sim \frac{M^{\beta-1}}{(\delta+1)(1-\beta)}tr^{1-\beta}(t)
\end{aligned}
\end{equation}
as $t\to\infty$. This implies \eqref{asform2}.
\end{proof}

\begin{proof}[Proof of ${\mathcal{DS}}\subset{\mathcal{NRV}}(\varrho)$]
Let $\delta>-1$. Assume first that $r\in C^1\cap{\mathcal{NRV}}(\delta+\alpha)$.
Take $y\in{\mathcal{DS}}$. We want to show that $y\in{\mathcal{NRV}}(\varrho)$. Set
again $w(t)=\Phi(ty'(t)/y(t))$. Then $w$ is negative and satisfies
equation \eqref{tw} for large $t$, which can be written as
$$
tw'=\frac{L_p(t)}{L_r(t)}+(-w)\Big(\frac{tr'(t)}{r(t)}
+1-\alpha-(\alpha-1)(-w)^{\beta-1}\Big).
$$
We claim that $\lim_{t\to\infty}w(t)=\Phi(\varrho)$. Some of the
arguments are similar to those in the case $\delta<-1$, but some
steps require a different approach. Indeed, if $w'(t)>0$ for large
$t$, then $\lim_{t\to\infty}w(t)=A^-\in(-\infty,0]$. The case
$A^-=0$ leads to $y\in {\mathcal{NSV}}$, which contradicts with the fact that
${\mathcal{SV}}$ solutions cannot decrease (see Lemma~\ref{L:allSV}). If
$A^-\in(-\infty,0)\setminus\{\Phi(\varrho)\}$, then we obtain a
contradiction with $A^-\in\mathbb{R}$ similarly as above. Let $w'(t)<0$
for large $t$. Then $\lim_{t\to\infty}w(t)=B^-\in[-\infty,0)$.
Assume that $B^-=-\infty$. This implies
$\lim_{t\to\infty}y(t)/(ty'(t))=0$. From \eqref{e}, we obtain
$r'\Phi(y')+(\alpha-1)r(-y')^{\alpha-2}y''=py^{\alpha-1}$. Hence,
\begin{equation} \label{yyy}
\begin{aligned}
\frac{y''(t)y(t)}{y'^2(t)}
&=\frac{p(t)y^\alpha(t)}{(\alpha-1)r(t)(-y'(t))^\alpha}
 -\frac{r'(t)y(t)}{(\alpha-1)r(t)y'(t)}\\
&=\frac{p(t)t^{\alpha}}{(\alpha-1)r(t)}
\Big(\frac{-y(t)}{ty'(t)}\Big)^\alpha
-\frac{tr'(t)}{(\alpha-1)r(t)}\cdot\frac{y(t)}{ty'(t)}
\to 0
\end{aligned}
\end{equation}
as $t\to\infty$. It follows that
$\big(\frac{y(t)}{y'(t)}\big)'=1-\frac{y''(t)y(t)}{y'^2(t)}\to
1$, hence $\frac{y(t)}{y'(t)}\to\infty$ as $t\to\infty$, which
implies $y'(t)>0$, contradiction with $y\in{\mathcal{DS}}$. If
$B^-\in(-\infty,0)\setminus\{\Phi(\varrho)\}$, then we obtain a
contradiction with $B^-\in\mathbb{R}$ similarly as above. The case when
$w'$ changes its sign and $w(t_n)=0$ can be treated using
arguments analogous to those from the proof of ${\mathcal{IS}}\subset{\mathcal{NRV}}(\varrho)$.

Now we drop the assumption of continuous differentiability and
normality of regular variation of $r$. We take $\bar r\in
C^1\cap{\mathcal{NRV}}(\delta+\alpha)$ such that $\bar r(t)\sim r(t)$ as
$t\to\infty$ and $(1-\varepsilon)\bar r(t)\le
r(t)\le(1+\varepsilon)\bar r(t)$ for large $t$. Because of a
certain uniqueness in the class ${\mathcal{DS}}$ (see
\cite[Section~4.1.3]{book}) we however cannot use the same
approach as above for increasing solutions. We utilize the concept
of principal solution. Along with \eqref{e}, let us consider the
equations $((1-\varepsilon)\bar r(t)\Phi(u'))'=p(t)\Phi(u)$ and
$((1+\varepsilon)\bar r(t)\Phi(v'))'=p(t)\Phi(v)$. Let
$w_u=(1-\varepsilon)\bar r\Phi(u'/u)$, $w_y=r\Phi(y'/y)$, and
$w_v=(1+\varepsilon)\bar r\Phi(v'/v)$, where $u,y,v$ are
eventually positive decreasing solutions of respective half-linear
equations. We have $\lim_{T\to\infty}\int_a^T
r^{1-\beta}(t)\left(\int_t^T p(s)\,\mathrm{d} s\right)^{\beta-1}\mathrm{d}
t=\infty$ since $\int_a^\infty p(s)\,\mathrm{d} s=\infty$. By
\eqref{princ}, the sets of all decreasing solutions of the
equations which are working with are in fact formed by principal
solutions. Consequently $w_u, w_y, w_v$ are eventually minimal
solutions of the associated generalized Riccati differential
equations.
Since
$(1-\varepsilon)\bar r(t)\le r(t)\le(1+\varepsilon)\bar r(t)$,
according to \eqref{minim} we obtain $w_u(t)\ge w_y(t)\ge w_v(t)$ for
large $t$. Consequently,
$-(1-\varepsilon)\Phi(tu'(t)/u(t))\le-r(t)/\bar
r(t)\Phi(ty'(y)/y(t))\le-(1+\varepsilon)\Phi(tv'(t)/v(t))$, and
the rest of the proof is similar to that after \eqref{40,5}.
\end{proof}

\begin{proof}[Proof of asymptotic formula in the case $\delta>-1$]
Take $y\in{\mathcal{NRV}}(\varrho)\cap {\mathcal{DS}}$. Clearly, $y\in{\mathcal{DS}}_0$ since
$\varrho<0$. From \eqref{e},
$(r\Phi(y'))'=p\Phi(y)\in{\mathcal{RV}}(\delta+(\alpha-1)\varrho)={\mathcal{RV}}(-1)$.
Hence, $r\Phi(y')\in\Pi(t(r\Phi(y'))')=\Pi(tp\Phi(y))$, in view of
Proposition~\ref{P:Pi}--(v).
Without loss of generality we may assume that $y(t)>0$ and $y'(t)<0$ for $t\ge a$.
Similarly as above -- we again use
\eqref{troj} (which is true thanks to
$r\Phi(y')\in\Pi(tp\Phi(y))$) and \eqref{troj2}
 -- we obtain
$$
(1+o(1))\frac{H(t)}{\Phi(\varrho)}=\Big(\ln\frac{-\int_a^t
r(s)\Phi(y'(s))\,\mathrm{d} s}{t}\Big)'
$$
as $t\to\infty$. Integrating from $t_0>a$ to $t$,
we obtain \eqref{troj4}
as $t\to\infty$.
Note that in this case $y^{[1]}$ and $D$ are negative.

Let $\int_a^\infty H(s)\,\mathrm{d} s=\infty$. Then $\int_a^t
y^{[1]}(s)\,\mathrm{d} s/t\to 0$ as $t\to\infty$ and since $-y^{[1]}$ is
positive decreasing, the L'Hospital rule gives $r(t)\Phi(y'(t))\to
0$ as $t\to\infty$. From \eqref{troj2} and \eqref{troj4} we obtain
$$
y^{\alpha-1}(t)=(1+o(1))\frac{|D|t^{\alpha-1}}{r(t)|\varrho|^{\alpha-1}}
\exp\Big\{\int_{t_0}^t (1+o(1))\frac{H(s)}{\Phi(\varrho)}\,\mathrm{d}
s\Big\}
$$
as $t\to\infty$, and formula \eqref{asform1} easily follows.


Let $\int_a^\infty H(s)\,\mathrm{d} s<\infty$.
Then $\lim_{t\to\infty}r(t)\Phi(y'(t))=M\in(-\infty,0)$, and so
$y\in{\mathcal{DS}}_{0,B}$. Consequently,
\begin{equation} \label{yM2}
y(t)\sim |M|^{\beta-1}\int_t^\infty r^{1-\beta}(s)\,\mathrm{d} s
\end{equation}
as $t\to\infty$. The Karamata integration theorem now yields
formula \eqref{asform2}.
\end{proof}

\begin{remark} \label{R:as2} \rm
A closer examination of the above observations
shows that -- under the assumptions of Theorem~\ref{T:1} --
asymptotic formulas for (non-${\mathcal{SV}}$) solutions of \eqref{e} can be
expressed in the following forms.
If $\int_a^\infty H(s)\,\mathrm{d} s=\infty$, then
\begin{equation} \label{asform3}
\big|\int_a^t y^{[1]}(s)\,\mathrm{d} s\big|
=t\exp\Big\{\int_{a}^t (1+o(1))\frac{H(s)}{\Phi(\varrho)}\,\mathrm{d}
s\Big\}
\end{equation}
as $t\to\infty$. This follows from \eqref{troj35} by taking $\exp$
and including $|D|$ and $\int_a^{t_0}$ into $(1+o(1))$ term. Note
that \eqref{asform1} can be obtained by using \eqref{troj2} in
\eqref{asform3}. If $\int_a^\infty H(s)\,\mathrm{d} s<\infty$, then
\begin{equation} \label{asform4}
\int_a^t y^{[1]}(s)\,\mathrm{d} s
=Mt\exp\Big\{-\int_t^\infty (1+o(1))\frac{H(s)}{\Phi(\varrho)}\,\mathrm{d}
s\Big\}
\end{equation}
as $t\to\infty$, where
$\lim_{t\to\infty}r(t)\Phi(y'(t))=M\in\mathbb{R}\setminus\{0\}$. This
follows from \eqref{troj35} by replacing $t_0$ by $t$ and $t$ by
$\infty$ and taking $\exp$.
\end{remark}


\subsection{${\mathcal{RV}}$ solutions when $t^\alpha p(t)/r(t)\to C> 0$}

Condition \eqref{prL} can be understood as
$\lim_{t\to\infty}t^\alpha p(t)/r(t)=0$. A logical step is to
assume that this limit is nonzero, i.e.,
\begin{equation} \label{cond-C1}
\lim_{t\to\infty}t^\alpha p(t)/r(t)=C>0.
\end{equation}
As we shall see, a modification of the approach from the previous
subsection leads to the claim that any solution of \eqref{e}
belongs to ${\mathcal{RV}}(\Phi^{-1}(\lambda))$, where $\lambda$ is a root of
\begin{equation} \label{algHL}
|\lambda|^\beta+\frac{\gamma+1-\alpha}{\alpha-1}\lambda-\frac{C}{\alpha-1}=0,
\end{equation}
$\gamma\in\mathbb{R}$ being the index of regular variation of $r$. More
precisely, we have the following statement, where
$\lambda_1,\lambda_2\in\mathbb{R}$, $\lambda_2<\lambda_1$, denote the
(real) roots of \eqref{algHL}. Imaging the graphs of
$\lambda\mapsto|\lambda|^\beta-\frac{C}{\alpha-1}$ and
$\lambda\mapsto\frac{\alpha-1-\gamma}{\alpha-1}\lambda$, it is
easy to see that $\lambda_2<0<\lambda_1$.

\begin{theorem} \label{T:RV}
Assume that $r\in{\mathcal{RV}}(\gamma)$ and condition \eqref{cond-C1} holds.
Then ${\mathcal{IS}}\subset{\mathcal{NRV}}(\Phi^{-1}(\lambda_1))$ and
${\mathcal{DS}}\subset{\mathcal{NRV}}(\Phi^{-1}(\lambda_2))$.
\end{theorem}

\begin{proof}
Assume first that $r\in{\mathcal{NRV}}(\gamma)\cap C^1$. Take $y\in{\mathcal{IS}}$ and
set $w(t)=\Phi(ty'(t)/y(t))$. Then $w$ satisfies
$$
tw'=\frac{t^\alpha
p(t)}{r(t)}+w\Big(\alpha-1-\frac{tr'(t)}{r(t)}-(\alpha-1)w^{\beta-1}\Big)
$$
for large $t$. Assume that $w'(t)>0$ for large $t$ and denote
$\lim_{t\to\infty} w(t)=:A\in(0,\infty]$. If $A=\infty$, then
$tw'(t)\to-\infty$ as $t\to\infty$, contradiction with $w'>0$. If
$\mathbb{R}\ni A\ne\lambda_1$, then $tw'(t)\sim D$ as $t\to\infty$ for
some $D\ne 0$, contradiction with $A\in\mathbb{R}$. Assume that $w'(t)<0$
for large $t$ and denote $\lim_{t\to\infty}w(t)=:B\in[0,\infty)$.
If $B=0$, then $tw'(t)\to C$ as $t\to\infty$, contradiction with
$B\in\mathbb{R}$. If $B\in\setminus\{\lambda_1\}$, then $tw'(t)\sim D$ as
$t\to\infty$ for some $D\ne 0$, contradiction with $B\in\mathbb{R}$. The
case when $w'(t_n)=0$ with $\{t_n\}$, $t_n\to\infty$ as
$n\to\infty$, can be managed similarly as under the assumption
$C=0$. Note only that instead of \eqref{mu}, we consider
$0=C+\mu(\alpha-1-\gamma-(\alpha-1)\mu^{\beta-1})$. Altogether we
obtain $\lim_{t\to\infty}w(t)=\lambda_1$, thus
$\lim_{t\to\infty}ty'(t)/y(t)=\Phi^{-1}(\lambda_1)$, i.e.,
$y\in{\mathcal{NRV}}(\Phi^{-1}(\lambda_1))$. If $r$ is not in $C^1$ or its
regular variation is not normalized, then we proceed similarly as
in the proof of ${\mathcal{IS}}\subset{\mathcal{NRV}}(\varrho)$ in the previous section.

Take $y\in{\mathcal{DS}}$.
Again, assume first that $r\in{\mathcal{NRV}}(\gamma)\cap C^1$ and set
$w(t)=\Phi(ty'(t)/y(t))$.
Then $w$ satisfies
$$
tw'=\frac{t^\alpha
p(t)}{r(t)}+(-w)\Big(\frac{tr'(t)}{r(t)}+1-\alpha-(\alpha-1)(-w)^{\beta-1}\Big)
$$
for large $t$. Assume that $w'(t)>0$ for large $t$ and denote
$\lim_{t\to\infty} w(t)=:A\in(-\infty,0]$. If $A=0$, then
$\lim_{t\to\infty}tw'(t)=C$, whence $w(t)\sim C\ln t$ as
$t\to\infty$, contradiction. The case
$A\in(-\infty,0)\setminus\{\lambda_2\}$ also leads to
contradiction. Assume that $w'(t)<0$ for large $t$ and denote
$\lim_{t\to\infty} w(t)=:B\in[-\infty,0)$. If $B=-\infty$, then
$\lim_{t\to\infty}y(t)/(ty'(t))=0$. From the identity in
\eqref{yyy} we obtain $(y(t)/y'(t))'=1-y''(t)y(t)/y'^2(t)\to 1$ as
$t\to\infty$, thus $y(t)/y'(t)\to\infty$ as $t\to\infty$,
contradiction with $y\in{\mathcal{DS}}$. If $\mathbb{R}\ni B\ne\lambda_2$, then
$tw'(t)\sim D$ as $t\to\infty$ for some $D\ne0$, contradiction
with $B\in\mathbb{R}$. The case when $w'$ changes its sign and $w'(t_n)=0$
can be treated similarly as when $y\in{\mathcal{IS}}$. Hence,
$\lim_{t\to\infty}w(t)=\lambda_2$. Consequently,
$y\in{\mathcal{NRV}}(\Phi^{-1}(\lambda_2))$.  If $r$ is not in $C^1$ or its
regular variation is not normalized, then we proceed similarly as
in the proof of ${\mathcal{DS}}\subset{\mathcal{NRV}}(\varrho)$ in the previous section.
Indeed, it is not difficult to see that $\lim_{T\to\infty}\int_a^T
r^{1-\beta}(t)\left(\int_t^\infty p(s)\,\mathrm{d}
s\right)^{\beta-1}\mathrm{d} t=\infty$. Consequently the solutions which
we are working with are all principal solutions, see
\eqref{princ}.
\end{proof}

\begin{remark} \label{R:RV} \rm
(i) A similar result as in Theorem~\ref{T:1} can be found in
\cite{pv}; the approach is however somewhat different.

(ii) A fixed point approach was used in \cite{jar-kus-tan2003,
jar-kus-tan2006} to derive conditions which guarantee the
existence of a couple of ${\mathcal{RV}}$ solutions (with different indices
which exactly correspond to the indices from Theorem~\ref{T:RV})
to equation \eqref{e}. For $r(t)\not\equiv1$, the concept of
generalized regular variation was used. Similarly, the conditions
for the existence of a ${\mathcal{SV}}$ solution and a non-${\mathcal{SV}}$ solution are
obtained in those works in the general case which can reduce to
condition \eqref{prL}, i.e., $C=0$. The conditions are in a more
general integral form than \eqref{cond-C1} (for instance, that
there exists the proper limit
$\lim_{t\to\infty}t^\alpha\int_t^\infty p(s)\,\mathrm{d} s$ when
$r(t)\equiv 1$) and are shown to be necessary, cf.
Remark~\ref{R:3} and Subsection~\ref{R:4}. On the other hand, here
we prove regular variation of all eventually positive solutions.

(iii) Another approach which is based on a transformation of
dependent variable -- and is at disposal in the linear case
-- is presented in the proof of Theorem~\ref{T:L}.

(iv) The extreme case where $C$ from \eqref{cond-C} is equal to
$\infty$ corresponds, in a certain sense, with the setting in
\cite{rehak-jmaa} and \cite[Section~3]{pv}. Solutions in the class
$\Gamma$, which forms a proper subset  of rapidly varying
functions, are studied there.

(v) A natural problem is to
establish asymptotic formula for solutions from Theorem~\ref{T:RV}.
This is done in Theorem~\ref{T:L} for linear equations.
\end{remark}

\section{Classification of nonoscillatory solutions in the framework
of regular variation}
\label{S:sum}


Denote
\begin{gather*}
{\mathcal{S}}_{{\mathcal{SV}}}={\mathcal{S}}\cap{\mathcal{SV}}, \quad
{\mathcal{S}}_{{\mathcal{RV}}}(\vartheta)={\mathcal{S}}\cap{\mathcal{RV}}(\vartheta),\\
{\mathcal{S}}_{{\mathcal{NSV}}}={\mathcal{S}}\cap{\mathcal{NSV}}, \quad
{\mathcal{S}}_{{\mathcal{NRV}}}(\vartheta)={\mathcal{S}}\cap{\mathcal{NRV}}(\vartheta).
\end{gather*}
If \eqref{pr} holds, we set
$$
J=\int_a^\infty\frac{1}{t}\Big(\frac{L_p(t)}{L_r(t)}\Big)^{\beta-1}\mathrm{d}
t\quad \text{and}\quad
R=\int_a^\infty\frac{1}{t}\cdot\frac{L_p(t)}{L_r(t)}\,\mathrm{d} t
$$
We actually have
$$
J=\int_a^\infty G(t)\,\mathrm{d} t\quad \text{and}\quad R=\int_a^\infty
H(t)\,\mathrm{d} t
$$
under condition \eqref{pr}. Further denote
$$
\mathfrak{P}=\{y\in{\mathcal{S}}: y \text{ is principal}\}.
$$

Theorem~\ref{T:SV}, Theorem~\ref{T:1}, Lemma~\ref{L:allSV},
Remark~\ref{R:as}, Remark~\ref{R:as2}, and
\cite[Theorem~B]{cdmv2006} (see also \eqref{princ} below) yield
the following corollary.


\begin{corollary} \label{C:sum}
Let \eqref{pr} and \eqref{prL} hold.


\noindent{\rm (i)} Assume that $\delta<-1$.
\begin{itemize}
\item[(i-a)]
If $J=\infty$, then
${\mathcal{S}}_{{\mathcal{NSV}}}={\mathcal{S}}_{{\mathcal{SV}}}={\mathcal{DS}}={\mathcal{DS}}_{0,0}=\mathfrak{P}$. For any
$y\in{\mathcal{DS}}$ formula \eqref{a1} holds.
\item[(i-b)]
If $J<\infty$, then
${\mathcal{S}}_{{\mathcal{NSV}}}={\mathcal{S}}_{{\mathcal{SV}}}={\mathcal{DS}}={\mathcal{DS}}_{B,0}=\mathfrak{P}$. For any
$y\in{\mathcal{DS}}$ formula \eqref{a2} holds.
\item[(i-c)]
If $R=\infty$, then
${\mathcal{S}}_{{\mathcal{NRV}}}(\varrho)={\mathcal{S}}_{{\mathcal{RV}}}(\varrho)={\mathcal{IS}}={\mathcal{IS}}_{\infty,\infty}$.
For any $y\in{\mathcal{IS}}$ formulae \eqref{as1}, \eqref{asform1},
\eqref{asform3} hold.
\item[(i-d)]
If $R<\infty$, then
${\mathcal{S}}_{{\mathcal{NRV}}}(\varrho)={\mathcal{S}}_{{\mathcal{RV}}}(\varrho)={\mathcal{IS}}={\mathcal{IS}}_{\infty,B}$. For
any $y\in{\mathcal{IS}}$ formulae \eqref{as3}, \eqref{asform2},
\eqref{asform4} hold.
\end{itemize}

\noindent{\rm (ii)} Assume that $\delta>-1$.
\begin{itemize}
\item[(ii-a)]
If $J=\infty$, then
${\mathcal{S}}_{{\mathcal{NSV}}}={\mathcal{S}}_{{\mathcal{SV}}}={\mathcal{IS}}={\mathcal{IS}}_{\infty,\infty}$. For any $y\in{\mathcal{IS}}$
formula \eqref{a1} holds.
\item[(ii-b)]
If $J<\infty$, then ${\mathcal{S}}_{{\mathcal{NSV}}}={\mathcal{S}}_{{\mathcal{SV}}}={\mathcal{IS}}={\mathcal{IS}}_{B,\infty}$. For
any $y\in{\mathcal{IS}}$ formula \eqref{a2} holds.
\item[(ii-c)]
If $R=\infty$, then
${\mathcal{S}}_{{\mathcal{NRV}}}(\varrho)={\mathcal{S}}_{{\mathcal{RV}}}(\varrho)={\mathcal{DS}}={\mathcal{DS}}_{0,0}=\mathfrak{P}$. For any
$y\in{\mathcal{DS}}$ formulae \eqref{as2}, \eqref{asform1}, \eqref{asform3}
hold.
\item[(ii-d)]
If $R<\infty$, then
${\mathcal{S}}_{{\mathcal{NRV}}}(\varrho)={\mathcal{S}}_{{\mathcal{RV}}}(\varrho)={\mathcal{DS}}={\mathcal{DS}}_{0,B}=\mathfrak{P}$. For any
$y\in{\mathcal{DS}}$ formulae \eqref{as4}, \eqref{asform2}, \eqref{asform4}
hold.
\end{itemize}
\end{corollary}

The following example shows that the case, when one of the
integrals $J,R$ is convergent while the other one is divergent,
may generally occur. Note that this is not possible in the linear
case (where we always have $J=R$ since $\beta=2$). Thus we see
that half-linear equations may exhibit more complex behavior than
linear ones.

\begin{example} \rm
Let $r,p$ be such that $L_p(t)/L_r(t)=\ln^\gamma t$ with
$\gamma\in(-\infty,0)$. Note that then \eqref{prL} is satisfied.
Let $a$ in $J,R$ be equal to 2. If $\alpha\in(1,2)$, then take
$\gamma$ such that $-1<\gamma<1-\alpha$, and we obtain
$$
R=\lim_{t\to\infty}\Big[\frac{\ln^{\gamma+1}s}{\gamma+1}\Big]_2^t=\infty,\quad
J=\lim_{t\to\infty}\Big[\frac{\ln^{\gamma(\beta-1)+1}s}{\gamma(\beta-1)+1}\Big]_2^t
<\infty.
$$
If $\alpha>2$, then take $\gamma$ such that $1-\alpha<\gamma<-1$,
and we obtain
$$
R<\infty, \ \ J=\infty.
$$
\end{example}

To include our results into a broader context, let us recall
several existence results concerning asymptotic classes defined in
Section~\ref{S:basic}. We already know that the classes ${\mathcal{DS}}$ and
${\mathcal{IS}}$ are nonempty. We set
\begin{gather*}
J_1 = \lim_{T \to \infty}\int_a^{T} r^{1 - \beta}(t)
\Big( \int_a^t p(s)\,\mathrm{d} s \Big)^{\beta -1} \mathrm{d} t,\\
J_2 = \lim_{T \to \infty} \int_a^{T} r^{1 - \beta}(t)
 \Big( \int_t^{T} p(s)\,\mathrm{d} s \Big)^{\beta -1} \mathrm{d} t.
\end{gather*}
The convergence or divergence of the above integrals fully characterize
the classes  ${\mathcal{DS}}_0,{\mathcal{DS}}_B,{\mathcal{IS}}_B,$ and ${\mathcal{IS}}_\infty$.
In particular, according to \cite[Theorems~4.1.1--4.1.3]{book}:
\begin{gather*}
{\mathcal{IS}}={\mathcal{IS}}_{\infty}\ \Leftrightarrow\ J_1 = \infty,\\
{\mathcal{IS}} = {\mathcal{IS}}_B\ \Leftrightarrow\  J_1 < \infty,\\
{\mathcal{DS}} = {\mathcal{DS}}_B\ \Leftrightarrow\ J_1 = \infty \text{ and } J_2 < \infty,\\
{\mathcal{DS}} = {\mathcal{DS}}_0\ \Leftrightarrow\ J_2 = \infty,\\
J_1 < \infty \text{ and }J_2 <
\infty\ \Rightarrow\ {\mathcal{DS}}_0 \ne \emptyset\ne {\mathcal{DS}}_B.
\end{gather*}
Denote
$$
J_r=\int_a^\infty r^{1-\beta}(s)\,\mathrm{d} s,\quad \text{and}\quad
J_p=\int_a^\infty p(s)\,\mathrm{d} s.
$$
It is useful to recall relations
between $J_1,J_2,J_r,J_p$ (\cite[Lemma~4.1.5]{book}): If
$J_1<\infty$, then $J_r<\infty$. If $J_2<\infty$, then
$J_p<\infty$. If $J_2=\infty$, then $J_r=\infty$ or $J_p=\infty$.
If $J_1=\infty$, then $J_r=\infty$ or $J_p=\infty$. It holds
$J_1<\infty$ and $J_2<\infty$ if and only if $J_r<\infty$ and
$J_p<\infty$.

Further we set
\begin{gather*}
R_1=\lim_{T\to\infty}\int_a^T p(t)\Big(\int_a^t
r^{1-\beta}(s)\,\mathrm{d} s\Big)^{\alpha-1}\,\mathrm{d} t,\\
R_2=\lim_{T\to\infty}\int_a^T p(t)\Big(\int_t^T
r^{1-\beta}(s)\,\mathrm{d} s\Big)^{\alpha-1}\,\mathrm{d} t.
\end{gather*}
Observe that the integral $J_r$ (resp. $J_p$) for \eqref{e} plays
the same role as $J_p$ (resp. $J_r$)
for the reciprocal equation \eqref{er}. Similarly, the integrals $J_1, J_2$
 become $R_1,R_2$, respectively,
for the reciprocal equation.

The integrals $J_1,J_2,R_1,R_2$ characterize the subclasses
defined in \eqref{sbc} in the following way (see
\cite[Theorem~1]{cdmv2006}):
\begin{equation} \label{gc}
\begin{aligned}
\text{(I)}&\ \ J_1=J_2=R_1=R_2=\infty\ \Rightarrow\
{\mathcal{IS}}={\mathcal{IS}}_{\infty,\infty},
{\mathcal{DS}}={\mathcal{DS}}_{0,0}\\
\text{(II)}&\ \ J_1=R_2=\infty, J_2<\infty, R_1<\infty\
\Rightarrow\ {\mathcal{IS}}={\mathcal{IS}}_{\infty,B},
{\mathcal{DS}}={\mathcal{DS}}_{B}\\
\text{(III)}&\ \ J_1<\infty, R_2<\infty, J_2=R_1=\infty\
\Rightarrow\ {\mathcal{IS}}={\mathcal{IS}}_{B},
{\mathcal{DS}}={\mathcal{DS}}_{0,B}\\
\text{(IV)}&\ \ J_1, J_2, R_1, R_2<\infty\ \Rightarrow\
{\mathcal{IS}}={\mathcal{IS}}_{B},
{\mathcal{DS}}_{0,0}=\emptyset,{\mathcal{DS}}_{0,B}\ne\emptyset\ne{\mathcal{DS}}_B\\
\text{(V)}&\ \ J_1=J_2=R_2=\infty, R_1<\infty\ \Rightarrow\
{\mathcal{IS}}={\mathcal{IS}}_{\infty,B},
{\mathcal{DS}}={\mathcal{DS}}_{0,0}\\
\text{(VI)}&\ \ J_1=J_2=R_1=\infty, R_2<\infty\ \Rightarrow\
{\mathcal{IS}}={\mathcal{IS}}_{\infty,\infty},
{\mathcal{DS}}={\mathcal{DS}}_{0,B}\\
\text{(VII)}&\ \ J_1=R_1=R_2=\infty, J_2<\infty\ \Rightarrow\
{\mathcal{IS}}={\mathcal{IS}}_{\infty,\infty},
{\mathcal{DS}}={\mathcal{DS}}_{B}\\
\text{(VIII)}&\ \ J_2=R_1=R_2=\infty, J_1<\infty\ \Rightarrow\
{\mathcal{IS}}={\mathcal{IS}}_{B},
{\mathcal{DS}}={\mathcal{DS}}_{0,0}.\\
\end{aligned}
\end{equation}
Necessary conditions for non-emptiness in the subclasses can be
found in \cite[Theorem~4.1.5]{book}. Note that the sufficient
conditions in cases (V), (VI) may occur only if $\alpha>2$, and
the sufficient conditions in cases (VII), (VIII) may occur only if
$\alpha<2$.

We have already applied the following characterization of
principal solutions (\cite[Theorem~B]{cdmv2006}) several times in
our paper:
\begin{equation} \label{princ}
\mathfrak{P}=
\begin{cases}
{\mathcal{DS}}_B & \text{if $J_1=\infty$ and $J_2<\infty$}\\
{\mathcal{DS}}_0 & \text{otherwise.}
\end{cases}
\end{equation}

Let us now discuss our results in the just described framework of
general existence conditions. Let us assume that \eqref{pr} holds.
First note that $J_p<\infty$ and $J_r=\infty$ when $\delta<-1$,
while $J_p=\infty$ and $J_r<\infty$ when $\delta>-1$. In view of
the Karamata theorem, $\int_t^\infty p(s)\,\mathrm{d} s\sim
tp(t)/(-\delta-1)$ as $t\to\infty$ and $\int_a^t
r^{1-\beta}(s)\,\mathrm{d} s \sim tr^{1-\beta}(t)/\varrho$ when
$\delta<-1$, while $\int_a^t p(s)\,\mathrm{d} s\sim tp(t)/(\delta+1)$ as
$t\to\infty$ and $\int_t^\infty r^{1-\beta}(s)\,\mathrm{d} s \sim
-tr^{1-\beta}(t)/\varrho$ when $\delta>-1$. Hence, if $\delta<-1$,
then
\[
J_1=\infty=R_2,\quad  J_2=\infty \Leftrightarrow J=\infty,\quad
R_1=\infty \Leftrightarrow R=\infty,
\]
while if $\delta>-1$, then
\[
J_2=\infty=R_1,\quad J_1=\infty \Leftrightarrow J=\infty,\quad
R_2=\infty \Leftrightarrow R=\infty.
\]

Now we can easily see how the conditions in Corollary~\ref{C:sum}
match the general existence conditions \eqref{gc}. More precisely,
the setting in (I) corresponds to (i-a), (ii-a), the setting in
(II) corresponds to (i-b), (i-d), the setting in (III) corresponds
to (ii-b), (ii-d), the setting in (V) corresponds to (i-a), (i-d),
the setting in (VI) corresponds to (ii-a), (ii-d), the setting in
(VII) corresponds to (i-b), (i-c), the setting in (VIII)
corresponds to (ii-b), (ii-c). It is worth mentioning that the
behavior of slowly varying components of $r,p$ appear to be
crucial. In view of relations among $J,J_1,J_2,R,R_1,R_2$, our
conditions must naturally guarantee non-emptiness in the
subclasses defined by \eqref{sbc} and yield the right-hand sides
of (I)--(III) and of (V)--(VIII); arguments are however completely
different from the general results in the previous literature. In
addition, we claim that these subclasses are formed by
(normalized) slowly varying functions or (normalized) regularly
varying functions of index $\varrho$, and all their elements
satisfy certain asymptotic formula. Note that the only case which
is not included in Corollary~\ref{C:sum} is (IV); the reason is
that $\delta<-1$ excludes $J_1<\infty$ while $\delta>-1$ excludes
$R_1<\infty$.


\section{Some methods that are not fully available in the half-linear
case} \label{S:L}

Consider the linear differential equation
\begin{equation} \label{le}
(r(t)y')'=p(t)y,
\end{equation}
where $r,p$ are positive continuous functions on $[a,\infty)$. If
$\alpha=2$, then \eqref{e} reduces to \eqref{le}. The main reasons
why the below discussed tools cannot be directly used in the
half-linear case are the lack of the additivity of the solution
space and the absence of a reasonable Wronskian identity for
\eqref{e}.

\subsection{Transformation of dependent variable: the choice
$h(t)=t^{\vartheta}$} \label{ss:7.1}

We use an argument based on transformation of dependent variable
where Theorems \ref{T:SV} and \ref{T:1} are applied to obtain
asymptotic formulae for solutions of \eqref{le} in new situations.


Let $h\ne0$ be a differentiable function such that $rh'$ is also
differentiable. Let us introduce a new independent variable
$y=hu$. Then we have the identity
$$
h[(ry')'-py]=(rh^2u')'-h[-(rh')'+ph]u.
$$
In particular, if $y$ is
a solution of \eqref{le}, then $u$ is a solution of the equation
\begin{equation} \label{le2}
(\widetilde r(t)u')'-\widetilde p u=0,
\end{equation}
where $\widetilde r=rh^2$ and $\widetilde p=h[-(rh')'+p]$.

Let $\vartheta_1,\vartheta_2$, $\vartheta_2<\vartheta_1$, denote
the (real) roots of the equation
\begin{equation} \label{algL}
\vartheta^2+\vartheta(\gamma-1)-C=0,
\end{equation}
where $C\in(0,\infty), \gamma\in\mathbb{R}$. Clearly,
$\vartheta_2<0<\vartheta_1$.


\begin{theorem} \label{T:L}
Assume that $r\in{\mathcal{NRV}}(\gamma)\cap C^1$, $\gamma\in\mathbb{R}$,
\begin{gather} \label{cond-C}
\lim_{t\to\infty}\frac{t^2p(t)}{r(t)}=C\in(0,\infty), \\
 \label{LL}
L_i(t):=\frac{t^2p(t)}{r(t)}-\vartheta_i\frac{tr'(t)}{r(t)}
-\vartheta_i(\vartheta_i-1)\in{\mathcal{SV}},
\end{gather}
$i=1,2$. Then ${\mathcal{IS}}^{\eqref{le}}\subset{\mathcal{NRV}}(\vartheta_1)$ and
${\mathcal{DS}}^{\eqref{le}}\subset{\mathcal{NRV}}(\vartheta_2)$. Moreover,
\begin{gather*}
y_1(t)\in\Pi{\mathcal{RV}}\left(\vartheta_1;t^{1-\vartheta_1}y_1'(t)-\vartheta_1
t^{-\vartheta_1}y_1(t)\right) \text{ for every }y_1\in{\mathcal{IS}}^{\eqref{le}},\\
-y_2(t)\in\Pi{\mathcal{RV}}\left(\vartheta_2;-t^{1-\vartheta_2}y_2'(t)+\vartheta_2
t^{-\vartheta_2}y_2(t)\right) \text{ for every
}y_2\in{\mathcal{DS}}^{\eqref{le}},
\end{gather*}
and

(i) if, for $i=1$ or $i=2$, $\int_a^\infty\frac{L_i(s)}{s}\,\mathrm{d}
s=\infty,$ then
\begin{equation} \label{f-i}
y_i(t)=t^{\vartheta_i}\exp\Big\{\int_a^t(1+o(1))\frac{L_i(s)}
{(\gamma+2\vartheta_1-1)s}\,\mathrm{d}
s\Big\},
\end{equation}
with $t^{-\vartheta_1}y_1(t)\nearrow\infty$ and
$t^{-\vartheta_2}y_2(t)\searrow 0$ as $t\to\infty$;


(ii) if, for $i=1$ or $i=2$, $\int_a^\infty\frac{L_i(s)}{s}\,\mathrm{d}
s<\infty,$ then
\begin{equation} \label{f-ii}
y_i(t)=D_it^{\vartheta_i}\exp\Big\{-\int_t^\infty(1+o(1))
\frac{L_i(s)}{(\gamma+2\vartheta_1-1)s}\,\mathrm{d}
s\Big\},
\end{equation}
with $t^{-\vartheta_1}y_1(t)\nearrow D_1=D_1(y_1)\in(0,\infty)$
and $t^{-\vartheta_2}y_2(t)\searrow D_2=D_2(y_2)\in(0,\infty)$ as
$t\to\infty$. Moreover, $|t^{\vartheta_i}y_i(t)-D_i|\in{\mathcal{SV}}$ and
\begin{equation} \label{tritecky}
\frac{L_i(t)}{D_i-t^{-\vartheta_i}y_i(t)}=o(1)
\end{equation}
as $t\to\infty$.
\end{theorem}

\begin{proof}
 Let $\widetilde
{\mathcal{S}},\widetilde {\mathcal{IS}},\widetilde {\mathcal{DS}}$ have the same meaning with
respect to \eqref{le2} as the classes
${\mathcal{S}}^{\eqref{le}},{\mathcal{IS}}^{\eqref{le}},{\mathcal{DS}}^{\eqref{le}}$,
respectively, have with respect to \eqref{le}. Set
$\delta=\gamma-2$, $h=t^{\vartheta_i}$, and
$\delta_i=\delta+2\vartheta_i$, $i=1,2$. Then $\widetilde r$
becomes $\widetilde
r(t)=r_i(t):=r(t)t^{2\vartheta_i}\in{\mathcal{RV}}(\delta_i+2)$ and
$\widetilde p(t)=p_i(t):=
\frac{r_i(t)}{t^2}L_i(t)\in{\mathcal{RV}}(\delta_i)$, $i=1,2$. We have
$\frac{L_{p_i}(t)}{L_{r_i}(t)}=\frac{t^2
p_i(t)}{r_i(t)}=L_i(t)\in{\mathcal{SV}}$ with $L_i(t)\to 0$ as $t\to\infty$,
$i=1,2,$ thanks to \eqref{cond-C}. Further, since
$\vartheta_{1,2}=\frac{1}{2}\left(-\delta-1\pm\sqrt{(\delta+1)^2+C}\right)$,
we obtain $\delta_1>-1$ and $\delta_2<-1$.

Take $y\in{\mathcal{IS}}^{\eqref{le}}$. Set $y=hu$ with
$h(t)=t^{\vartheta_1}$. Then $u$ solves \eqref{le2} with
$\widetilde p=p_1,\widetilde r=r_1$. Clearly, $u\in\widetilde
{\mathcal{S}}=\widetilde {\mathcal{IS}}\cup\widetilde {\mathcal{DS}}$. If $u\in\widetilde {\mathcal{IS}},$
then $u\in{\mathcal{NSV}}$ and $u\in\Pi(tu'(t))$ by Theorem~\ref{T:SV}.
Hence, $y\in{\mathcal{RV}}(\vartheta_1)$ and
$y\in\Pi(\vartheta_1;t^{1-\vartheta_1}y'(t)-\vartheta_1t^{-\vartheta_1}y(t))$.
Denote $g_i(t)=\frac{tp_i(t)}{|\delta_i+1|r_i(t)}$, $i=1,2$. By
Theorem~\ref{T:SV}, $u(t)=\exp\{\int_a^t(1+o(1))g_1(s)\,\mathrm{d}
s\}$ with $u(t)\to\infty$ as $t\to\infty$, provided
$\int_a^\infty g_1(s)\,\mathrm{d} s=\infty$. Formula \eqref{f-i} with
$i=1$ now easily follows if we realize that $y=t^{\vartheta_1}u$,
$\frac{tp_1}{r_1}=\frac{L_1}{t}$, and
$\delta_1=\delta+2\vartheta_1$. Similarly we obtain formula
\eqref{f-ii} with $i=1$, since if
$\int_a^\infty\frac{L_1(s)}{s}\,\mathrm{d} s<\infty,$ then
$u(t)=D_1\exp\left\{-\int_t^\infty(1+o(1))g_1(s)\,\mathrm{d} s\right\}$
as $t\to\infty$ with $\lim_{t\to\infty}u(t)=D_1\in(0,\infty).$ If
$u\in\widetilde {\mathcal{DS}}$, then $u\in{\mathcal{NRV}}(-\delta_1-1)$ by
Theorem~\ref{T:1}. Hence, recalling that
$\vartheta_1+\vartheta_2=-\delta-1$, $y\in{\mathcal{NRV}}(\vartheta_2)$ which
contradicts $y\in{\mathcal{IS}}^{\eqref{le}}$ since $\vartheta_2<0$.

Take $y\in{\mathcal{DS}}^{\eqref{le}}$. We proceed similarly as before. Now
we set $y=hu$ with $h(t)=t^{\vartheta_2}$. Consequently, $u$ is in
$\widetilde {\mathcal{S}}=\widetilde {\mathcal{IS}}\cup\widetilde {\mathcal{DS}}$ where
$\widetilde p=p_2\in{\mathcal{RV}}(\delta_2)$ and $\widetilde
r=r_2\in{\mathcal{RV}}(\delta_2+2)$ with $\delta_2<-1$. If
$u\in\widetilde{\mathcal{DS}}$, then we apply Theorem~\ref{T:SV} to obtain
$u\in{\mathcal{NSV}}$, $-u\in\Pi(-tu(t))$, and
$u(t)=\exp\{-\int_a^t(1+o(1))g_2(s)\,\mathrm{d} s\}$ as
$t\to\infty$ provided $\int_a^\infty g_2(s)\,\mathrm{d} s=\infty$ while
$u(t)=D_2\exp\{\int_t^\infty(1+o(1))g_2(s)\,\mathrm{d} s\}$
as $t\to\infty$ provided $\int_a^\infty g_2(s)\,\mathrm{d} s<\infty$,
where $\lim_{t\to\infty}u(t)=D_2\in(0,\infty).$ Asymptotic
formulae \eqref{f-i} with $i=2$ and \eqref{f-ii} with $i=2$ then
clearly follow. If $u\in\widetilde{\mathcal{IS}},$ then
$u\in{\mathcal{NRV}}(-\delta_2-1)$ by Theorem~\ref{T:1}. This implies
$y\in{\mathcal{NRV}}(\vartheta_1)$, which contradicts $y\in{\mathcal{DS}}^{\eqref{le}}$.

By \eqref{hvezda}, we have
$L_{p_i}(t)/(L_{r_i}(t)(D_i-u(t)))=o(1)$ as $t\to\infty$, and so
\eqref{tritecky} follows.
\end{proof}

\begin{remark} \rm
(i) If $r=1$, then formula \eqref{f-i} with $i=2$ (i.e., for
decreasing solutions) reduces to the former formula in
\cite[Theorem~0.2]{geluk1990}. The quoted result was however
proved by a quite different method. For increasing solutions and
with $r(t)\ne 1$, Theorem~\ref{T:L} is new.

(ii) Observe that -- for linear equations -- we have presented
another method of the proof of
 ${\mathcal{IS}}^{\eqref{le}}\subset{\mathcal{NRV}}(\vartheta_1)$ and
${\mathcal{DS}}^{\eqref{le}}\subset{\mathcal{NRV}}(\vartheta_2)$, see the proof of
Theorem~\ref{T:RV} and Remark~\ref{R:RV}.

(iii) Assuming $r\in{\mathcal{NRV}}(\gamma)\cap C^1$ and \eqref{cond-C}, if
$\vartheta_i tr'(t)/r(t)-t^2 p(t)/r(t)\in \Pi,$ then condition
\eqref{LL} is satisfied thanks to Proposition~\ref{P:Pi}--(iv).
\end{remark}

To obtain information about the behavior of solutions in
${\mathcal{DS}}^{\eqref{le}}$ and ${\mathcal{IS}}^{\eqref{le}}$, the previous theorem
requires both the functions $L_1$ and $L_2$ to be ${\mathcal{SV}}$ and so
they are necessarily positive. The next remark reveals that
asymptotic formulas for all solutions in ${\mathcal{S}}^{\eqref{le}}$ can be
obtained also in the case when one of these functions is not
positive. First however we give an example which discusses various
possibilities for behavior of the functions $L_1$ and $L_2$. Let
$\vartheta_i$, $i=1,2$, denote the roots of \eqref{algL}. The
functions $L_1,L_2$ can be written in the form
$$
L_i(t)=\vartheta_i\Big(\gamma-\frac{tr'(t)}{r(t)}\Big)-C+
\frac{t^2p(t)}{r(t)},
$$
 $i=1,2$. For $r\in{\mathcal{NRV}}(\gamma)\cap C^1$,
we have $tr'(t)/r(t)=\gamma+tL_r'(t)/L_r(t)$.

\begin{example} \label{E:L} \rm
(a) If $r(t)=t^{\gamma}$, then $L_1=-C+t^2p/t=L_2$, and so the
functions $L_1$ and $L_2$ coincide.

(b) Let $r\in{\mathcal{NRV}}(\gamma)\cap C^1$ and $p(t)=CL_r(t)t^{\gamma-2}$,
$C\in(0,\infty)$. Then $t^2p(t)/r(t)=C$, and so $L_i=-\vartheta_i
t L_r'(t)/L_r(t)$, $i=1,2$. If, in addition, $L_r'>0$, then
$L_1<0$ and $L_2>0$. Moreover, $L_r$ can be taken such that
$L_2\in{\mathcal{SV}}$. An example is $L_r(t)=\ln t$. Thus the situation
where \eqref{cond-C} is fulfilled and \eqref{LL} holds for only
one index can occur.

(c)
Let $ p(t)=\left(C\ln t+\vartheta_1+{C}/{\ln
t}\right)t^{\gamma-2},$ $C\in(0,\infty)$, and $r(t)=t^\gamma\ln
t$. Then $r\in{\mathcal{NRV}}(\gamma)\cap C^1$ and condition \eqref{cond-C}
is fulfilled. Further, $L_1(t)=C/\ln^2 t\in{\mathcal{SV}}$ and
$L_2(t)=(\vartheta_1-\vartheta_2)/\ln t+C/\ln^2t\in{\mathcal{SV}}$. Since
$(-1/\ln t)'=L_1(t)/(Ct)$, we obtain $\int_a^\infty L_1(t)/t\,\mathrm{d}
t<\infty$. On the other hand, we have
$(\vartheta_1-\vartheta_2)(\ln(\ln t))'<L_2(t)/t$, hence
$\int_a^\infty L_2(t)/t\,\mathrm{d} t=\infty$. Consequently, the case
when $\int_a^\infty L_i(t)/t\,\mathrm{d} t=\infty$ while $\int_a^\infty
L_{3-i}(t)/t\,\mathrm{d} t<\infty$ for one of $i\in\{1,2\}$ can
generally occur in Theorem~\ref{T:L}.
\end{example}

\begin{remark} \rm
(i) Assume that $L_2\in{\mathcal{SV}}$, $r\in{\mathcal{NRV}}(\gamma)\cap C^1$, and
\eqref{cond-C} holds. There is no assumption on $L_1$; in
particular, $L_1$ might not be positive. As we could see in
Example~\ref{E:L}-(b), such a case can occur. Take
$y\in{\mathcal{S}}^{\eqref{le}}$. Set $y=hu$, where $h(t)=t^{\vartheta_2}$.
Then $u\in\widetilde {\mathcal{S}}=\widetilde {\mathcal{IS}}\cup\widetilde {\mathcal{DS}}$ where
$\widetilde p=p_2\in{\mathcal{RV}}(\delta_2)$ and $\widetilde
r=r_2\in{\mathcal{RV}}(\delta_2+2)$ with $\delta_2<-1$. If $u\in\widetilde
{\mathcal{DS}}$, then -- as in the proof of the previous theorem -- we obtain
that $y$ is in ${\mathcal{NRV}}(\vartheta_2)$ (and so in ${\mathcal{DS}}$) and satisfies
formula \eqref{f-i} with $i=2$ or formula \eqref{f-ii} with $i=2$.
If $u\in\widetilde {\mathcal{IS}}$, then $u\in{\mathcal{NRV}}(-\delta_2-1)$ by
Theorem~\ref{T:1}, and so $y\in{\mathcal{NRV}}(\vartheta_1)$ (which yields
$y\in{\mathcal{IS}}^{\eqref{le}}$). To obtain an asymptotic formula, we use
Remark~\ref{R:as}. For instance, if
$\int_a^\infty\frac{L_2(s)}{s}\,\mathrm{d} s=\infty$, then
\begin{equation} \label{form-patek}
\begin{aligned}
y(t) &= t^{\vartheta_2}\frac{t}{r_2(t)}
\exp\Big\{\int_a^t(1+o(1))\frac{sp_2(s)}{(-1-\delta_2)r_2(s)}\,\mathrm{d}
s\Big\}\\
&=\frac{t^{\vartheta_1}}{L_{r_2}(t)}
\exp\Big\{\int_a^t(1+o(1))\frac{L_2(s)}{(1-\gamma-2\vartheta_2)s}\,\mathrm{d}
s\Big\}.
\end{aligned}
\end{equation}
Similarly we proceed if $\int_a^\infty\frac{L_2(s)}{s}\,\mathrm{d}
s<\infty$. The case when $L_1\in{\mathcal{SV}}$ (with $L_2$ not being
necessarily positive) can be treated analogously.

(ii) A closer examination of the previous observation shows that
the case may happen such that a formula for solutions of equation
\eqref{le2} where the coefficient $\widetilde p$ is not positive
is obtained. Indeed, assume, for instance, that $L_2\in{\mathcal{SV}}$ with
$\int_a^\infty\frac{L_2(s)}{s}\,\mathrm{d} s=\infty$, and
$L_1(t)\not>0$. We already know that $y\in{\mathcal{IS}}^{\eqref{le}}$ is in
${\mathcal{NRV}}(\vartheta_1)$ and satisfies formula \eqref{form-patek}. Take
this $y$ and set $y(t)=t^{\vartheta_1}v(t)$. Then $v$ satisfies
equation \eqref{le2} with $\widetilde r=r_1$ and $\widetilde
p=p_1=\frac{r_1}{t^2}L_1\not>0$. The formula for $v$ can easily be
obtained from $v=t^{-\vartheta_1}y$. Note that monotonicity for
$v$ is not guaranteed.
\end{remark}

\begin{remark} \rm
Similar arguments to those in the proof of Theorem~\ref{T:L} can
be used to obtain a variant of Theorem~\ref{T:1} in the linear
case. In fact, the following setting leads to $C=0$ and
$\gamma=\delta+2$. Thus, as for the roots of \eqref{algL}, we
obtain $\vartheta_1=-\delta-1$, $\vartheta_2=0$ when $\delta<-1$,
resp. $\vartheta_1=0$, $\vartheta_2=-\delta-1$ when $\delta>-1$.
Hence, in both cases we set $h(t)=t^{-\delta-1}$. Other details
are left to the reader. The statement reads as follows:

Let $p\in{\mathcal{RV}}(\delta)$, $r\in{\mathcal{NRV}}(\delta+2)\cap C^1$,
$\delta\ne-1$, and $\lim_{t\to\infty}t^2p(t)/r(t)=0$. Assume that
$L\in{\mathcal{SV}}$, where $$ %\begin{equation} \label{LLL}
L(t)=\frac{L_p(t)}{L_r(t)}+\Phi(\varrho)\Big(\delta+2-\frac{tr'(t)}{r(t)}\Big).
$$
If $\delta<-1$, then ${\mathcal{IS}}^{\eqref{le}}\subset{\mathcal{NRV}}(-1-\delta)$. If
$\delta>-1$, then ${\mathcal{DS}}^{\eqref{le}}\subset{\mathcal{NRV}}(-1-\delta)$.
Moreover, for any $y\in{\mathcal{IS}}^{\eqref{le}}$ when $\delta<-1$ and any
$y\in{\mathcal{DS}}^{\eqref{le}}$ when $\delta>-1$, the following hold:

(a) If $\int_a^\infty L(s)/s\,\mathrm{d} s=\infty$, then
$$
y(t)=t^{-\delta-1}\exp\Big\{\int_a^t
\frac{1+o(1)}{-\delta-1}\cdot\frac{L(s)}{s}\,\mathrm{d} s\Big\}
$$
with $y(t)t^{\delta+1}\nearrow\infty$ as $t\to\infty$ provided
$y\in{\mathcal{IS}}^{\eqref{le}}$ and $\delta<-1$, and
$y(t)t^{\delta+1}\searrow 0$ as $t\to\infty$ provided
$y\in{\mathcal{DS}}^{\eqref{le}}$ and $\delta>-1$.

(b) If $\int_a^\infty L(s)/s\,\mathrm{d} s<\infty$, then
$$
y(t)=Dt^{-\delta-1}\exp\Big\{-\int_t^\infty
\frac{1+o(1)}{-\delta-1}\cdot\frac{L(s)}{s}\,\mathrm{d} s\Big\}
$$
with $y(t)t^{\delta+1}\nearrow D=D(y)\in(0,\infty)$ as
$t\to\infty$ provided $y\in{\mathcal{IS}}^{\eqref{le}}$ and $\delta<-1$,
resp. $y(t)t^{\delta+1}\searrow D=D(y)\in(0,\infty)$ as
$t\to\infty$ provided $y\in{\mathcal{DS}}^{\eqref{le}}$ and $\delta>-1$.
Moreover, $|y(t)t^{\delta+1}-D|\in{\mathcal{SV}}$ and
\begin{equation*}
\frac{L(t)}{D-y(t)t^{\delta+1}}=o(1)
\end{equation*}
as $t\to\infty$.
\end{remark}

\subsection{Transformation of dependent variable: the choice
$h(t)=\int_t^\infty 1/r(s)\,\mathrm{d} s$
or $h(t)=\int_a^t 1/r(s)\,\mathrm{d} s$}
We have seen how the results of
Theorem~\ref{T:SV} and Theorem~\ref{T:1} can be related by the
reciprocity principle. In this subsection we show that for linear
equations the results in these theorems can be linked via other
tool, namely a suitable transformation of dependent variable. We
do not discuss all possibilities for the setting. Rather we
illustrate the method on one selected case. Assume that
$p\in{\mathcal{RV}}(\delta)$, $r\in{\mathcal{RV}}(\delta+2)$ with \eqref{prL}, and
$\delta>-1$. Take, for instance, $y\in{\mathcal{IS}}^{\eqref{le2}}$. Set
$y=hu$ where $h(t)=\int_t^\infty 1/r(s)\,\mathrm{d} s$; this integral
converges thanks to $\delta>-1$. Then $u$ solves \eqref{le}, where
$\widetilde r=rh^2\in{\mathcal{RV}}(\widetilde\delta+2)$ and $\widetilde
p=ph^2\in{\mathcal{RV}}(\widetilde\delta)$ with
$\widetilde\delta=-\delta-2<-1$. Moreover, $L_{\widetilde
p}(t)/L_{\widetilde
r}(t)=L_p(t)L_{h^2}(t)/(L_r(t)L_{h^2}(t))=L_p(t)/L_r(t)\to 0$ as
$t\to\infty$. Further, $\widetilde H(t):=t\widetilde
p(t)/\widetilde r(t)=tp(t)/r(t)$. Since $y\in{\mathcal{IS}}$ and $1/h$
increases, $u\in\widetilde{\mathcal{IS}}$. Application of Theorem~\ref{T:1}
yields $u\in{\mathcal{NRV}}(\varrho)$, where
$\varrho=-1-\widetilde\delta=\delta+1$. Hence,
$y/h\in{\mathcal{NRV}}(\varrho)$. Since $-h'=1/r\in{\mathcal{RV}}(-\delta-2)$ implies
$h\in{\mathcal{NRV}}(-\delta-1)$ by Proposition~\ref{P:RV}-(ix), we obtain
$y\in{\mathcal{NSV}}$. Assume, for instance, $\int_a^\infty tp(t)/r(t)\,\mathrm{d}
t=\infty$. The Karamata theorem yields $(\delta+1)h(t)\sim t/r(t)$
as $t\to\infty$. Hence, see \eqref{asform1},
\begin{align*}
y(t) &=\frac{th(t)}{\widetilde
r(t)}\exp\Big\{\int_a^t(1+o(1))\frac{\widetilde
H(s)}{\varrho}\,\mathrm{d} s\Big\}\\
& = \frac{th(t)}{r(t)h^2(t)}\exp\Big\{\int_a^t(1+o(1))\frac{
sp(s)}{(\delta+1)r(s)}\,\mathrm{d} s\Big\}\\
&=(1+o(1))(\delta+1)\exp\Big\{\int_a^t(1+o(1))\frac{
sp(s)}{(\delta+1)r(s)}\,\mathrm{d} s\Big\}\\
&= \exp\Big\{\int_a^t(1+o(1))\frac{ sp(s)}{(\delta+1)r(s)}\,\mathrm{d}
s\Big\}
\end{align*}
as $t\to\infty$, cf. \eqref{a1}. Similarly we treat other cases.

\subsection{Reduction of order formula} \label{ss:7.3}

Another tool which is not at disposal in the half-linear case is
the reduction of order formula.
If $y$ is a solution
of \eqref{le} such that $y(t)\ne 0$ on $[b,\infty)$, then any
other solution $x$ of \eqref{le} can be expressed as
$$
x(t)=c_1y(t)+c_2y(t)\int_b^t\frac{\mathrm{d} s}{r(s)y^2(s)},
$$
$c_1,c_2\in\mathbb{R}$. In particular, $u(t)=y(t)\int_b^t
1/(r(s)y^2(s))\,\mathrm{d} s$ is a linearly independent solution (w.r.t.
$y$). If $r\in{\mathcal{RV}}(\delta+2)$ and $y\in{\mathcal{SV}}$ resp.
$y\in{\mathcal{RV}}(-\delta-1)$, then $1/(ry^2)$ is ${\mathcal{RV}}$ of index different
form $-1$, and hence the Karamata theorem can be applied to get
$u\in{\mathcal{RV}}(-\delta-1)$ resp. $u\in{\mathcal{SV}}$ with
$$
u(t)\sim\frac{t}{|\delta+1|r(t)y(t)}
$$
as $t\to\infty$. Similarly, under the setting of
Theorem~\ref{T:L}, if $y\in{\mathcal{RV}}(\vartheta_i)$, then
$u\in{\mathcal{RV}}(\vartheta_{3-i})$ with
$$
u(t)\sim\frac{t}{|\gamma+2\vartheta_i+1|r(t)y(t)}
$$
as $t\to\infty$, $i=1,2$.

\section{Conclusion, further research}

We have presented several methods for the study of asymptotic
properties of linear and half-linear differential equations in the
framework of regular variation. We believe that these ideas and
their modifications will be useful also in other settings, for
example:
\begin{itemize}
\item
(half-)linear equation of the form \eqref{e} with $p(t)<0$ or with
$p(t)$ which may change its sign;
\item
nearly (half-)linear differential equations (i.e., the equations of the form \eqref{e} where $\Phi$ in both terms is replaced by
a regularly varying function at infinity or at zero of index $\alpha$);
\item
(half-)linear differential equations with deviated arguments;
\item
first order (half-)linear systems or higher order equations;
\item
(half-)linear difference equations;
\item (half-)linear dynamic equations on time scales.
\end{itemize}
Even though some results for linear or half-linear differential
equations can be established via more approaches, not all these
methods can be applicable in other settings. For instance, the
reciprocity principle cannot be used in dynamic equations on time
scales unless the graininess is constant; thus the approach from
Section~\ref{SS:second} or Section~\ref{ss:7.1} might be more
suitable for such an extension. Further, the facts like the
absence of a chain rule (and, consequently, a substitution in the
integral) in a discrete case or a time scale case might
substantially affect availableness of some approaches. For
half-linear differential equations with deviated argument, the
Riccati type substitution does not lead to a ``pure'' generalized
Riccati equation, which might be a serious problem in a delicate
asymptotic analysis.

 Of course, there is also some space for improving the presented
results. In particular:

$\bullet$ Establish a half-linear extension of Theorem~\ref{T:L} -- the
part concerning asymptotic formulas. One of the proper tools is
the transformation into a modified generalized Riccati
differential equation. This tool can somehow substitute the
transformation $y=hu$ used in Section~\ref{ss:7.1} and it actually
linearizes the problem, cf. \cite{rehak-amc}, where all positive
solutions of \eqref{e} are treated under this setting. A different
approach, based on the Banach fixed point theorem, is used in
\cite{kus-man} where the existence of regularly varying solutions
of \eqref{e-kus-man} along with asymptotic formulae is derived
under the condition $\lim_{t\to\infty}t^{\alpha-1}\int_t^\infty
p(s)\,\mathrm{d} s=C$ and some additional assumptions.

$\bullet$
 Examine whether some ``purely linear'' techniques
(e.g. the use of the Wronskian identity or the transformation
of dependent variable) can directly be applied to half-linear
equation at least in some ``asymptotic sense''.

$\bullet$
To obtain asymptotic formulae under relaxation of some conditions,
such as $\lim_{t\to\infty}t^\alpha p(t)/r(t)=C$, into an integral
form. See \cite{geluk-maric-tomic} for the linear case.

$\bullet$
Examine the borderline case $\delta=-1$. A suitable
transformation  of independent variable and utilization of
Theorems \ref{T:SV} and \ref{T:1} can quite satisfactorily solve
this problem, cf. \cite{rehak-amc}.

$\bullet$
Use the theory of regular variation and the de Haan theory to find
more precise asymptotic formulae for solutions of \eqref{e} (and
to find estimations for remainders), see e.g.
\cite[Theorem~0.1-B]{geluk} for the linear case.


\subsection*{Acknowledgments}
This research was supported by grant RVO 67985840.

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\end{document}
