\documentclass[reqno]{amsart}
\usepackage{hyperref}

\AtBeginDocument{{\noindent\small
\emph{Electronic Journal of Differential Equations},
Vol. 2016 (2016), No. 252, pp. 1--9.\newline
ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu}
\thanks{\copyright 2016 Texas State University.}
\vspace{8mm}}

\begin{document}
\title[\hfilneg EJDE-2016/252\hfil 
 A method for solving ill-posed Robin-Cauchy problems]
{A method for solving ill-posed Robin-Cauchy problems for
second-order elliptic equations in  multi-dimensional cylindrical
domains}

\author[B. T. Torebek \hfil EJDE-2016/252\hfilneg]
{Berikbol T. Torebek}

\dedicatory{Dedicated to Professor Tynysbek Kalmenov on his 70th birthday}

\address{Berikbol T. Torebek \newline
Department of Differential Equations,
Department of Fundamental Mathematics,
Institute of Mathematics and Mathematical Modeling,
125 Pushkin str., 050010 Almaty, Kazakhistan}
\email{torebek@math.kz}

\thanks{Submitted Submitted May 5, 2016. Published September 20, 2016.}
\subjclass[2010]{31A30, 31B30, 35J40}
\keywords{Elliptic equation; Robin-Cauchy problem;
 self-adjoint operator; \hfill\break\indent ill-posedness}

\begin{abstract}
 In this article we consider the Robin-Cauchy problem for multidimensional
 elliptic equations in a cylindrical domain. The method of spectral
 expansion in eigenfunctions of the Robin-Cauchy problem for equations
 with deviating argument establishes a criterion of the strong solvability
 of the considered Robin-Cauchy problem. It is shown that the ill-posedness
 of the Robin-Cauchy problem is equivalent to the existence of an isolated
 point of the continuous spectrum for a self-adjoint operator with the
 deviating argument.
\end{abstract}

\maketitle
\numberwithin{equation}{section}
\newtheorem{theorem}{Theorem}[section]
\newtheorem{lemma}[theorem]{Lemma}
\newtheorem{definition}[theorem]{Definition}
\allowdisplaybreaks


\section{Introduction}

 As it is known, the solution of the Cauchy problem for the Laplace equation
 is unique but unstable. First of all it should be noted that the existence
 and uniqueness of its solution is essentially guaranteed by the universal
 Cauchy-Kovalevskaja theorem, which holds for elliptic problems.
 However, the existence of the solution is guaranteed only in a small data.
 Traditionally the ill-posedness of the elliptic Cauchy problem is determined
 in relation to its equivalence to Fredholm integral equations of the first kind.
 The problem of solving the operator equation of the first kind can not be correct,
 since the operator which is inverse to completely continuous operator is not
 continuous.

The Cauchy problem for the Laplace equation is one of the main examples 
of ill-posed problems. One can pick up the harmonic functions with arbitrarily 
small Cauchy data on a piece of the domain boundary, which will be arbitrarily
 large in the domain (the famous example of Hadamard) \cite{1}. 
For the formulation of the problem to be correct, it is necessary to restrict 
the class of solutions. The stability of a two dimensional problem in the class 
of bounded solutions firstly was proved by Carleman \cite{2}.

From Carleman's results immediately follow estimations characterizing this stability.
 In the mentioned work Carleman established a formula for determining an complex 
variable analytic function from the data only on part of the arc. 
However, this formula is unstable and therefore can not be directly used as 
an efficient method. The first results related to the construction of an 
efficient algorithm for solving the problem, best to our knowledge, 
are published simultaneously in works  Pucci \cite{3} and  Lavrent'ev \cite{4}. 
Estimates characterizing the stability of a spatial problem in the class of 
bounded solutions, were first obtained by M.M. Lavrent'ev \cite{4} for harmonic 
functions, given in a straight cylinder and vanishing on the generators. 
The Cauchy data were given on the base of the cylinder. Just after, 
similar estimates were obtained by  Mergelyan \cite{5} for the functions 
within a sphere and by  Lavrent'ev \cite{6} for an arbitrary spatial domain 
with sufficiently smooth boundary. Around the same time,  Landis \cite{7} 
obtained estimates characterizing the stability of spatial problem for an 
arbitrary elliptic equation.

The above results laid the foundation for the theory of ill-posed Cauchy 
problems for elliptic equations. By now this theory has deep development 
both in the plane, and for the spatial cases, and also for general elliptic 
equations of high order, etc. Methods of regularization and solutions of 
ill-posed problems have been proposed in 
\cite{12,10,11,9,13,8}. In these works the concept of conditional correctness 
of such problems is introduced and algorithms for constructing their 
solutions are proposed.

In contrast to the presented results, in this paper a new criterion 
of well-posedness (ill-posedness) of initial boundary value problem for a 
general second order elliptic equation is proved. The principal 
difference of our work from the work of other authors is the application 
of spectral problems for equations with deviating argument in the study 
of ill posed boundary value problems. The present work is an extension 
of results \cite{14}-\cite{16} on the case of more general elliptic 
operators in a multidimensional cylindrical domain.

\section{Formulation of the problem and main results}

Let $D = \Omega  \times ({0,1})$ be a cylinder and $\Omega  \subset \mathbb{R}^n $ 
be a bounded domain with smooth boundary $S$. 
In $D$ we consider a mixed Robin-Cauchy problem for elliptic equations
\begin{equation}\label{1}
\begin{aligned}
Lu &\equiv u_{yy} ({x,t}) + \sum_{i,j = 1}^n
{\frac{\partial }{{\partial x_i }}
\Big({a_{ij} (x)\frac{{\partial u}}{{\partial x_j }}}\Big)({x,y})}  
 + a(x)u({x,y}) \\
&= f({x,y}), \quad ({x,y}) \in D,
\end{aligned}
\end{equation}
with the Robin condition
\begin{equation}\label{2}
\sum_{i,j = 1}^n \nu_i{\frac{\partial }{{\partial x_i }}
\Big({a_{ij} (x)\frac{{\partial u}}{{\partial x_j }}}\Big)({x,y})}+b(x)u(x,y) 
 = 0, \quad x \in S,\; y \in [{0,1}],
\end{equation}
and Cauchy conditions
\begin{equation}\label{3}
u({0,x}) = u_y ({0,x}) = 0, \quad x \in \Omega  \cup S.
\end{equation}
Here $a_{ij} (x), a(x)$ and $b(x)$ are given bounded measurable functions 
satisfying the following conditions:
\begin{equation}\label{3*}
\begin{gathered}
\sum_{i,j = 1}^n {a_{ij} (x)\xi _i \xi _j }  
\ge c\sum_{i = 1}^n {\xi _i^2 } ,\quad \text{$c$ is a positive constant}\\ 
a_{ij} (x) = a_{ji} (x),\quad  a(x), b(x) \ge 0,
\end{gathered}
\end{equation} 
and $\nu=(\nu_1,\dots,\nu_n)$  denotes the outer unit normal on the boundary $S$.

\begin{definition} \label{def2.1} \rm 
The function $u \in L^2 (D)$  will be called a strong solution of the
 Robin-Cauchy problem \eqref{1}-\eqref{3}, if  there exists a sequence 
of functions $u_n  \in C^2 ({\bar D})$ satisfying conditions \eqref{2} 
and \eqref{3}, such that $u_n $ and $Lu_n $ converge in the norm  $L^2 (D)$ 
respectively to $u$ and $f$.
\end{definition}

In the future, the following eigenvalue problem for an elliptic equation 
with deviating argument will play an important role.
Find numerical values of $\lambda $ (eigenvalues), under which the problem 
for a differential equation with deviating argument
\begin{equation}\label{4}
\begin{aligned}
Lu &\equiv u_{yy} ({x,y}) + \sum_{i,j = 1}^n {\frac{\partial }{{\partial x_i }}
\Big({a_{ij} (x)\frac{{\partial u}}{{\partial x_j }}}\Big)({x,y})} + a(x)u({x,y}) \\
& = \lambda u({x,1 - y}),\quad ({x,y}) \in D,
\end{aligned}
\end{equation} 
has nonzero solutions (eigenfunctions) satisfying conditions \eqref{2} and \eqref{3}.
Obviously, the equivalent representation of equation \eqref{4} 
has the form 
\[
LPu(x,y) = \lambda u(x,y), \quad\text{in } D,
\]
 where $Pu({x,y}) = u({x,1 - y})$ is a unitary operator.

We consider the  spectral problem
\begin{gather}\label{5} 
- \sum_{i,j = 1}^n {\frac{\partial }{{\partial x_i }}\Big({a_{ij} (x)
\frac{{\partial u_k }}{{\partial x_j }}}\Big)} (x) + a(x)u_k (x) 
= \mu _k u_k (x), \quad x \in \Omega,\\
\label{6}
\sum_{i,j = 1}^n \nu_i{\frac{\partial }{{\partial x_i }}
\Big({a_{ij} (x)\frac{{\partial u_k}}{{\partial x_j }}}\Big)({x})}+b(x)u_k(x)  
= 0, \quad x \in S.
\end{gather}
It is known \cite{17}, that problem \eqref{5}--\eqref{6} with the condition 
\eqref{3*} is self-adjoint and non-negative definite operator in 
$L^2 (\Omega)$ and it has a discrete spectrum. 
All eigenvalues of the problem \eqref{5}--\eqref{6} are discrete and non-negative, 
and the system of eigenfunctions form a complete orthonormal system 
in $L^2 (\Omega)$.

By $\mu _k $ we denote all eigenvalues (numbered in decreasing order) and 
by $u_k (x),k \in \mathbb{N}$ denote a complete system of all orthonormal 
eigenfunctions of the problem \eqref{5}-\eqref{6} in $L^2(\Omega)$.

\begin{theorem}\label{t1.1} 
The spectral Robin-Cauchy problem \eqref{4}, \eqref{2}, \eqref{3} has a 
complete orthonormal system of eigenfunctions
\begin{equation}\label{7}
u_{km} (x,y) = u_k (x) \cdot v_{km} (y),
\end{equation}
where  $k,m \in N$, $v_{km} (y)$ are non-zero solutions of the problem
\begin{gather}\label{8}
v''_{km} (y) - \mu _k v_{km} (y) 
= \lambda _{km} v_{km} ({1 - y}),\quad 0 < y < 1, \\
\label{8*}
v_{km} (0) = v'_{km} (0) = 0,
\end{gather}
and $\lambda _{km} $ are eigenvalues of problem 
\eqref{4}, \eqref{2}, \eqref{3}. In addition for large $k$ the smallest eigenvalue $\lambda _{k1} $ 
has the asymptotic behavior
\begin{equation}\label{9}
\lambda _{k1}  = 4\mu _k \exp( - \sqrt {\mu _k } ) ({1 + o(1)})\,.
\end{equation}
\end{theorem}

\begin{theorem}\label{t1.2} 
A strong solution of the Robin-Cauchy problem \eqref{1}--\eqref{3} 
exists if and only if  $f({x,\,y})$ satisfies the inequality
\begin{equation}\label{10}
\sum_{k = 1}^\infty  \big| {\frac{{\tilde f_{k1} }}{{\lambda _{k1} }}} \big| ^2 
 < \infty ,
\end{equation}
where $\tilde f_{km}  = ({f(x,1 -y),u_{km} (x,y)})$.

If condition \eqref{10} holds, then a solution of  \eqref{1}--\eqref{3} can be 
written as
\begin{equation}\label{11}
u({x,y}) = \sum_{k = 1}^\infty  {\frac{{\tilde f_{k1} }}{{\lambda _{k1} }}u_{k1}
 ({x,\,y})}  + \sum_{k = 1}^\infty  
{\sum_{m = 2}^\infty  {\frac{{\tilde f_{km} }}{{\lambda _{km} }}u_{km} } } ({x,y}).
\end{equation}
\end{theorem}

By $\tilde L^2 (D)$ we denote a subspace of $L^2 (D)$, spanned by the eigenvectors 
$$
\{ {u_{k1} ({x,y})}\}_{k = p + 1}^\infty ,
$$ 
$p \in \mathbb{N}$ and by $\hat L^2 (D)$ we denote its orthogonal complement 
\begin{align*}
L^2 (D) = \tilde L^2 (D) \oplus \hat L^2 (D).
\end{align*}

\begin{theorem}\label{t1.3} 
For any $f \in \hat L^2 (D)$ a solution of the problem \eqref{1}--\eqref{3} 
exists, is unique and belongs to $\hat L^2 (D)$. This solution is stable 
and has the form
\begin{equation}\label{12}
u({x,y}) = \sum_{k = 1}^p {\frac{{\tilde f_{k1} }}{{\lambda _{k1} }}u_{k1} ({x,\,y})}
  + \sum_{k = 1}^\infty  {\sum_{m = 2}^\infty 
 {\frac{{\tilde f_{km} }}{{\lambda _{km} }}u_{km} } } ({x,y}).
\end{equation}
\end{theorem}

\section{Auxiliary statements}

In this section we present some auxiliary results to prove the main results.

\begin{lemma}\label{l1.1} 
For each fixed value of the index $k$ the spectral problem \eqref{8}-\eqref{8*} 
has a complete orthonormal in $L^2 ({0,1})$ system of eigenfunctions 
$v_{km} (y),\quad m \in \mathbb{N}$, corresponding to the eigenvalues 
$\lambda _{km}$. These eigenvalues $\lambda _{km} $ are roots of the equation
\begin{equation}\label{13}
\begin{aligned}
&\sqrt {\mu _k  - \lambda } \cosh\frac{{\sqrt {\mu _k  
+ \lambda } }}{2}\cosh\frac{{\sqrt {\mu _k  - \lambda } }}{2}\\
& - \sqrt {\mu _k  + \lambda } \sinh\frac{{\sqrt {\mu _k  + \lambda } }}{2}
\sinh\frac{{\sqrt {\mu _k  - \lambda } }}{2} = 0.
\end{aligned}
\end{equation}
\end{lemma}

\begin{proof}
 Indeed, applying an inverse operator $L_C^{ - 1} $ to the Cauchy eigenvalue 
problem \eqref{8}--\eqref{8*} we arrive at the operator equation 
$$
v_{km} (y) = \lambda L_C^{ - 1} Pv_{km} (y),
$$ 
where $Pf(y) = f({1 - y})$, and a function $\phi (y) = L_C^{ - 1} f(y)$ 
is the solution of the Cauchy problem 
$$
\phi ''(y) - \mu _k \phi (y) = f(y),\,\,\phi (0) = \phi '(0) = 0,\quad
\forall f \in L^2 ({0,1}).
$$
Then for the operator $L_C^{ - 1} $ we have the representation 
\begin{equation}\label{14}
L_C^{ - 1} f(y) = \frac{1}{{\sqrt {\mu _k } }}\int_0^y {f(\xi)\sinh
\sqrt {\mu _k } ({y - \xi })d\xi },\quad \forall f \in L^2 ({0,1}).
\end{equation}
Therefore, the adjoint to $L_C^{ - 1} $ operator has the form
\begin{equation}\label{15}
({L_C^{ - 1} })^ *  f(y) = \frac{1}{{\sqrt {\mu _k } }}
\int_y^1 {f(\xi)\sinh\sqrt {\mu _k } ({\xi  - y})d\xi } ,\quad \forall 
 f \in L^2 ({0,1}).
\end{equation}
Taking into account representation \eqref{14} and \eqref{15}, it is easy 
to make sure that 
$$
L_C^{ - 1} Pf = P({L_C^{ - 1} })^ *  f.
$$ 
Then the chain of equalities 
$$
L_C^{ - 1} Pf = P({L_C^{ - 1} })^ *  f = P^ *  ({L_C^{ - 1} })^ *  f 
= ({L_C^{ - 1} P})^ *  f,\,\,\forall \quad f \in L^2 ({0,1}),
$$ 
allows us to conclude that the operator $L_C^{ - 1} P$ is completely 
continuous self-adjoint Hilbert-Schmidt operator \cite{18}. 
Therefore for each $k \in \mathbb{N}$, the spectral problem \eqref{8}--\eqref{8*} 
has a complete orthonormal system of functions $v_{km} (y)$, $m \in \mathbb{N}$ 
in $L^2 ({0,1})$.

We are looking for eigenfunctions of problem \eqref{4}, \eqref{2}, \eqref{3} 
by means of the Fourier method of separation of variables in the form 
$$
u_k ({x,y}) = u_k (x)v(y),
$$ where $k \in \mathbb{N}$.
Therefore, to determine the unknown function $v(y)$ we get the spectral 
problem \eqref{8}, \eqref{8*}.
It is easy to show that the general solution of equation \eqref{8} has 
the form 
$$
v(y) = c_1 \quad \cosh\sqrt {\mu _k  + \lambda } 
\big({y - \frac{1}{2}}\big) + c_2 \quad 
\sinh\sqrt {\mu _k  - \lambda } \big({y - \frac{1}{2}}\big),
$$ 
where  $c_1 $ and $c_2 $ are some constants.
Using the initial conditions \eqref{8}, we arrive at the system of linear 
homogeneous equations concerning these constants.  As we know, this system 
has a nontrivial solution if the determinant of the system 
$$
\Delta (\lambda ) = \det\begin{pmatrix}
  {\cosh\frac{{\sqrt {\mu _k  + \lambda } }}{2}} 
& {\sinh\frac{{\sqrt {\mu _k  - \lambda } }}{2}}  \\  
 {\sqrt {\mu _k  + \lambda } \sinh\frac{{\sqrt {\mu _k  + \lambda } }}{2}} 
& {\sqrt {\mu _k  - \lambda } \cosh\frac{{\sqrt {\mu _k  - \lambda } }}{2}}  
\end{pmatrix}
$$
 is zero.
Thus, for determining the parameter $\lambda $ we get \eqref{13}. 
The proof  is complete.
\end{proof}

Let
\begin{equation}\label{16}
\varpi _k (\lambda) = \ln\Big({\coth\frac{{\sqrt {\mu _k  + \lambda } }}{2}}\Big)
 + \ln \Big({\coth\frac{{\sqrt {\mu _k  - \lambda } }}{2}}\Big)
- \frac{1}{2}\ln \Big({\frac{{\mu _k  + \lambda }}{{\mu _k  - \lambda }}}\Big).
\end{equation}

\begin{lemma}\label{l1.2} 
There exists a number $\lambda _0 $ such that for all 
$$
0 < \lambda  < \lambda _0  < \frac{{\mu _k }}{{4\mu _k  + \theta }},\quad
k \in \mathbb{N},\;\theta  \in ({0,\,1})\,,
$$ 
the following statements are true:
\begin{itemize}
\item[(1)] the function $\varpi '_k (\lambda)$ is of a fixed sign;
\item[(2)] for the function $\varpi ''_k (\lambda)$ , 
$$
\| {\lambda \mu _k \varpi ''_k (\lambda)} |<1,\quad k >1.
$$
\end{itemize}
\end{lemma}

\begin{proof} By  Lemma \ref{l1.1} we have the real eigenvalues of
 \eqref{8}-\eqref{8*}, that is, real roots $\lambda _{km} $ of equation \eqref{13}. 
It is easy to verify that $\lambda _{km}  > 0$.

Indeed, let us write the asymptotic behavior of the smallest eigenvalues 
$\lambda _{km} $ at $k \to \infty $. After a nontrivial transformation of 
equation \eqref{13}, we have 
\begin{equation}\label{17}
\frac{{\sqrt {\mu _k  + \lambda } }}{{\sqrt {\mu _k  - \lambda } }} 
= \coth\frac{{\sqrt {\mu _k  + \lambda } }}{2}
\coth\frac{{\sqrt {\mu _k  - \lambda } }}{2}.
\end{equation}
Assuming  $| \lambda| < 1$ and taking the logarithm of both sides 
of  \eqref{17}, we obtain \eqref{16}. By calculating the derivative 
$\varpi _k (\lambda)$, we get 
$$
\varpi '_k (0) =  - \frac{1}{{\mu _k }}.
$$

Then the required boundary of monotonicity of $\varpi _k (\lambda )$ 
can be determined from the relation 
$$
\varpi '_k (\lambda _0 ) = \varpi '_k (0) + \varpi ''_k ({\theta \lambda _0 })
\lambda _0  < 0.$$ Here  $0 < \lambda _0  < 1$ and 
$\theta  \in {\rm{(0}}{\rm{, 1)}}$ are arbitrary numbers. 
Thus, for determining $\lambda _0 $ we have the condition
\begin{equation}\label{18}
\lambda _0 \mu _k \varpi ''_k ({\theta \lambda _0 }) < 1.
\end{equation}
We write explicitly the second derivative of $\varpi _k (\lambda )$:
\begin{align*}
\varpi ''_k (\lambda ) 
&= \frac{{\cosh\sqrt {\mu _k  + \lambda } }}{{4({\mu _k  + \lambda })
 \sinh^2 \sqrt {\mu _k  + \lambda } }} 
 + \frac{{\cosh\sqrt {\mu _k  - \lambda } }}{{4({\mu _k  - \lambda })
 \sinh^2 \sqrt {\mu _k  - \lambda } }} \\
&\quad + \frac{1}{{4\sqrt {({\mu _k  + \lambda })^3 } 
\sinh\sqrt {\mu _k  + \lambda } }} 
 + \frac{1}{{4\sqrt {({\mu _k  - \lambda })^3 } 
 \sinh\sqrt {\mu _k  - \lambda } }}\\
&\quad  - \frac{{2\lambda \mu _k }}{{({\mu _k^2  - \lambda ^2 })^2 }}.
\end{align*}
As 
$$
\frac{{2\lambda _0 \theta \mu _k }}{{({\mu _k^2  
- ({\lambda _0 \theta })^2 })^2 }} \ge  - \frac{1}{{({\mu _k^{} 
 + \lambda _0 \theta })^2 }}
$$
 and 
$$
\frac{{\cosh\sqrt {\mu _k  \pm \lambda _0 \theta } }}{{\sinh^2 
\sqrt {\mu _k  \pm \lambda _0 \theta } }} 
\le \frac{1}{{\cosh\sqrt {\mu _k  \pm \lambda _0 \theta }  - 1}},
$$
the inequality
$$
\varpi ''_k (\lambda _0 \theta ) \le \frac{1}{{({\mu _k 
 - \lambda _0 \theta })}}\frac{{2 + ({1 - \
exp{({ - \sqrt {\mu _k  - \lambda _0 \theta } })}})^2 }}
{{({1 - \exp{(- \sqrt {\mu _k  - \lambda _0 \theta })} })^2 }}
$$ 
is true. Hence
\begin{equation}\label{19}
\varpi ''_k ({\lambda _0 \theta }) 
< \frac{1}{{({\mu _k  - \lambda _0 \theta })}}
\frac{{3 - 2\exp{(- \sqrt {\mu _k  - \lambda _0 \theta })}  
+ \exp{(- 2\sqrt {\mu _k  - \lambda _0 \theta })} }}
{{({1 - \exp{(- \sqrt {\mu _k  - \lambda _0 \theta })} })^2 }}.
\end{equation}
Further, for large values $k$, from \eqref{19} we obtain the validity of 
the inequality 
$$
\varpi ''_k ({\lambda _0 \theta }) \le \frac{4}{{\mu _k  - \lambda _0 \theta }}.
$$
Applying the condition \eqref{18} to the last inequality, we obtain the 
desired estimate for $\lambda _0$:
 $$
\lambda _0  < \frac{{\mu _k }}{{4\mu _k  + \theta }},\quad
\mu _k  > 1,\; 0 < \theta  < 1.
$$
The proof is complete.
\end{proof}

Consider now the question of an asymptotic behavior of the eigenvalues of
 problem \eqref{8}--\eqref{8*} for large $k$.

\begin{lemma}\label{l1.3} 
An asymptotic behavior of eigenvalues of the problem \eqref{8}-\eqref{8*}, 
not exceeding $\lambda _0 $, for the large values of $k$ has the form \eqref{9}.
\end{lemma}

\begin{proof} 
According to Lemma \ref{l1.2} the monotonic function 
$\varpi _k (\lambda)$ in the interval $({0,\,\lambda _0 })$ can have only 
one zero. By the Taylor formula we have 
$$
\varpi _k (\lambda) = \varpi _k (0) + \frac{{\varpi '_k (0)}}{{1!}}\lambda 
 + \frac{{\varpi ''_k (\theta \lambda )}}{{2!}}\lambda ^2  < 0\,,\,0 < \theta  < 1.
$$
Substituting the calculated values of the function $\varpi _k $ and its derivative 
$\varpi '_k $, we get 
$$
\varpi _k (\lambda) = 2\ln \Big({\coth\frac{{\sqrt {\mu _k } }}{2}}\Big)
 - \frac{\lambda }{{\mu _k }} + \varpi ''_k ({\theta \lambda })
\frac{{\lambda ^2 }}{2}.
$$
Then the zero of the linear part of the function 
$$
\mu _k \varpi _k (\lambda) = 2\mu _k \ln \Big({\coth\frac{{\sqrt {\mu _k } }}{2}}\Big)
 - \lambda  + \frac{{\mu _k \lambda ^2 }}{2}\varpi ''_k ({\theta \lambda })
$$
will be 
$$
\lambda _{k1}  = 2\mu _k 
\ln \Big({\frac{{1 + \exp{(- \sqrt {\mu _k }) } }}
{{1 - \exp{(- \sqrt {\mu _k })} }}}\Big).
$$

For sufficiently large values $k \in \mathbb{N}$, considering the asymptotic 
formulas, $\lambda _{k1} $ can be written as 
$$
\lambda _{k1}  = 4\mu _k \exp{(- \sqrt {\mu _k }) } ({1 + o(1)}).
$$
Taking into account the result of Lemma \ref{l1.2} on a circle 
$| \lambda | = 4\mu _k \exp{(- \sqrt {\mu _k }) } ({1 + \varepsilon })$,
 where $\varepsilon $ is a greatly small positive number, 
for sufficiently large $k \ge k_0 (\varepsilon )$ it is easy to check 
the validity of the inequality 
\begin{align*}
&\Big| {\varpi ''_k ({\theta \lambda })\mu _k \lambda ^2 } 
\Big|_{| \lambda  | = 4\mu _k \exp{(- \sqrt {\mu _k }) } 
({1 + \varepsilon })\,} \\ 
&\le C\Big| {2\mu _k \ln ({\frac{{1 + \exp{(- \sqrt {\mu _k }) } }}
{{1 - \exp{(- \sqrt {\mu _k })} }}}) - \lambda } \Big|
_{| \lambda  | = 4\mu _k \exp{(- \sqrt {\mu _k })} ({1 + \varepsilon })}.
\end{align*}
Then, by Rouche's theorem \cite{19}, we have that the quantity of
 zeros of $\mu _k \varpi _k (\lambda)$ and its linear part coincide and 
are inside the circle 
$| \lambda  | = 4\mu _k \exp{(- \sqrt {\mu _k }) } ({1 + \varepsilon })$. 
Consequently, the function 
$\mu _k \varpi _k (\lambda)$ for $0 < \lambda  < \lambda _0 $ has one zero, 
the asymptotic behavior is given by formula \eqref{9}. 
the proof is complete.
\end{proof}

\section{Proof  the main results}

\begin{proof}[Theorem \ref{t1.1}] 
By $u_k (x),k \in \mathbb{N}$ we denote a complete system of orthonormal 
eigenfunctions of the problem \eqref{5}-\eqref{6} in $L^2(\Omega)$.
 By Lemma \ref{l1.1}, for each fixed value of the $k$ the spectral problem 
\eqref{8}--\eqref{8*} has complete orthonormal system of eigenfunctions 
$v_{km} (t),\quad m = 1,2,..$. in $L^2 ({0,1})$. Then the system \eqref{7} 
forms a complete orthogonal system in $L^2 (D)$. Consequently, 
problem \eqref{4}, \eqref{3} does not have other eigenvalues and eigenfunctions. 
the proof is complte.
\end{proof}

\begin{proof}[Theorem \ref{t1.2}]
 Let $u \in C^2 (D)$ be a solution of problem \eqref{1}--\eqref{3}. 
Then, by  the completeness and orthonormality of eigenfunctions 
$u_{km} (x,t)$ of problem \eqref{4}, \eqref{2}, \eqref{3}, the function 
$u(x,t)$ in $L^2 (D)$ can be expanded in a series \cite{20} 
\begin{equation}\label{20}
u(x,t) = \sum_{k = 1}^\infty  {\sum_{m = 1}^\infty  {a_{km} u_{km} } } (x,t),
\end{equation} 
where $a_{km} $ are the Fourier coefficients of the system. 
Rewriting equation \eqref{1} in the form
\begin{equation}\label{21}
\begin{aligned}
LPu &= P({u_{yy} ({x,y}) + \sum_{i,j = 1}^n {\frac{\partial }{{\partial x_i }}
({a_{ij} (x)\frac{{\partial u}}{{\partial x_j }}})({x,y})}  + a(x)u({x,y})})\\
&= Pf(x,y),
\end{aligned}
\end{equation} 
and substituting the solution of form \eqref{20} in equation \eqref{21} 
according to representation 
\[
P({\frac{{\partial ^2 u_{km} }}{{\partial y^2 }}({x,y})
 + \sum_{i,j = 1}^n {\frac{\partial }{{\partial x_i }}({a_{ij} (x)
\frac{{\partial u}}{{\partial x_j }}})({x,y})}  + a(x)u({x,y})})
 = \lambda _{km} u_{km} (x,y),
\] 
we have 
$$
a_{km}  = \frac{{\tilde f_{km} }}{{\lambda _{km} }},
$$ 
where $\tilde f_{km}  = ({f(x,\,1 - y), u_{km} (x,\,y)})$.

Thus for solutions $u(x,y)$ we obtain the following explicit representation 
\begin{equation}\label{22}
u(x,y) = \sum_{k = 1}^\infty  {\sum_{m = 1}^\infty  
{\frac{{\tilde f_{km} }}{{\lambda _{km} }}u_{km} } } (x,y).
\end{equation}
Note that the representation \eqref{22} remains true for any strong 
solution of problem \eqref{1}-\eqref{3}. We have obtained this representation 
under the assumption that the solution of the Robin-Cauchy 
problem \eqref{1}-\eqref{3} exists.

The question naturally arises, for what subset of the functions 
$f \in L^2 (D)$ there exists a strong solution?

To answer this question, we represent the formula \eqref{22} 
in the form \eqref{11} from which, by Parseval's equality, it follows
\begin{equation}\label{23}
\| {\rm{u}} \|^2  = \sum_{k = 1}^\infty  {| {\frac{{\tilde f_{k1} }}
{{\lambda _{k1} }}} |} ^2  + \sum_{k = 1}^\infty  {\sum_{m = 2}^\infty 
 {| {\frac{{\tilde f_{km} }}{{\lambda _{km} }}} |^2 } }.
\end{equation}
By Lemma \ref{l1.3} we have $\lambda _{km}  \ge \frac{1}{4}$, $m > 1$. 
Therefore, the right-hand side of equality \eqref{23} is bounded only for 
those $f({x,\,y})$ for which the weighted norm \eqref{10} is bounded.
 This fact completes the proof.
\end{proof}

\begin{proof}[Theorem \ref{t1.3}]
 Obviously the operator $L$ is invariant in $\hat L^2 (D)$.
 By Theorem \ref{t1.2}, for any $f \in \hat L^2 (D)$ there exists a 
unique solution of problem \eqref{1}--\eqref{3} and it can be represented 
in the form \eqref{12}. Therefore, determined infinite-dimensional 
space $\hat L^2 (D)$ is the space of correctness of the Robin-Cauchy 
problem \eqref{1}-\eqref{3}. The proof is complete.
\end{proof}


\subsection*{Acknowledgements} 
The Authors are Grateful to Professor T. Sh. Kal'menov and to Professor 
M. A. Sadybekov for valuable advice during discussions of the results 
of the present work. This research is financially supported by a grant 
from the Ministry of Science and Education of the Republic of
Kazakhstan (Grant No. 0820/GF4).


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