\documentclass[reqno]{amsart}
\usepackage{hyperref}

\AtBeginDocument{{\noindent\small
\emph{Electronic Journal of Differential Equations},
Vol. 2016 (2016), No. 251, pp. 1--17.\newline
ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu}
\thanks{\copyright 2016 Texas State University.}
\vspace{8mm}}

\begin{document}
\title[\hfilneg EJDE-2016/251\hfil 
Second-order $\Phi$-Laplacian equtions with  nonlocal BC]
{Positive solutions for a second-order $\Phi$-Laplacian equations 
with limiting nonlocal boundary conditions}

\author[G. L. Karakostas, K. G. Palaska, P. Ch. Tsamatos \hfil EJDE-2016/251\hfilneg]
{George L. Karakostas, Konstantina G. Palaska, \\ Panagiotis Ch. Tsamatos}

\address{George L. Karakostas \newline
 Department of Mathematics, University of Ioannina,
 451 10 Ioannina, Greece}
\email{gkarako@uoi.gr, gkarako@hotmail.com}

\address{Konstantina G. Palaska \newline
 Department of Mathematics, University of Ioannina,
 451 10 Ioannina, Greece}
\email{cpalaska@cc.uoi.gr}

\address{Panagiotis Ch. Tsamatos \newline
 Department of Mathematics, University of Ioannina,
 451 10 Ioannina, Greece}
\email{ptsamato@cc.uoi.gr}

\thanks{Submitted April 19, 2016. Published September 20, 2016.}
\subjclass[2010]{34B18, 34B10}
\keywords{Positive solution; Sturm-Liouville equation;
$\Phi$-Laplacian; \hfill\break\indent
Schauder's fixed point theorem}

\begin{abstract}
 Motivated, mainly, by the works of Fewster-Young and  Tisdell \cite{YT, YT1}
 and  Orpel \cite{oa}, as well as the papers by  Karakostas \cite{ka, ka1, k2},
 we give sufficient conditions to guarantee the existence of (nontrivial)
 solutions of the second-order $\Phi$-Laplacian  equation
 $$
\frac{1}{p(t)}\frac{d}{dt}[p(t)\Phi(u'(t))]+(Fu)(t)=0,\quad\text{a.e. }
  t\in[0,1]=:I,
 $$
 which satisfy the nonlocal  boundary value conditions of the
 limiting Sturm-Liouville form
 $$
 \lim_{t\to 0}[p(t)\Phi(u'(t))]=\int_0^1u(s)d\eta(s),\quad
 \lim_{t\to 1}[p(t)\Phi(u'(t))]=-\int_0^1u(s)d\zeta(s).
 $$
 Here  $\Phi$ is an increasing homeomorphism of the real line onto itself
 and $F$ is an operator acting on the function $u$ and on its first
 derivative with the characteristic property that $u\to p(Fu)$ is a
 $C^0$-type, or $C^1$-type Caratheodory operator, a meaning introduced here.
 Examples are given to illustrate both cases.
\end{abstract}

\maketitle
\numberwithin{equation}{section}
\newtheorem{theorem}{Theorem}[section]
\newtheorem{lemma}[theorem]{Lemma}
\newtheorem{definition}[theorem]{Definition}
\allowdisplaybreaks

\section{Introduction}

We study  the existence of positive solutions of the  second-order
$\Phi$-Laplacian equation
 \begin{equation}\label{e1}
\frac{1}{p(t)}\frac{d}{dt}[p(t)\Phi(u'(t))]+(Fu)(t)=0,\quad\text{a.e. }
  t\in[0,1]=:I,
\end{equation}
associated with the nonlocal limiting boundary value conditions of the
Sturm-Liouville form
\begin{equation}\label{e2}
\lim_{t\to 0}[p(t)\Phi(u'(t))]=\int_0^1u(s)d\eta(s),\quad
\lim_{t\to 1}[p(t)\Phi(u'(t))]=-\int_0^1u(s)d\zeta(s),
\end{equation}
 where  $\Phi$ is an increasing homeomorphism, while, conditions for $p$,
$\eta$ and $\zeta$ will be given in the text.  If $p(t)=1$ and $\Phi$
is the identity, then the boundary value conditions  \eqref{e2}
take a form related to that one considered in   \cite{Inf1} and \cite{Inf2}.

In the sequel  we shall use the Banach space $C^0:=C^0(I,\mathbb{R})$
of continuous functions $u:I\to\mathbb{R}$ endowed with the sup-norm
 $\|\cdot\|_0$ and the Banach space $C^1:=C^1(I,\mathbb{R})$
(of all differentiable functions $u:I\to\mathbb{R}$ having derivative
$u'\in C^0(I,\mathbb{R})$)  endowed with the norm
$\|u\|_1:=\max\{\|u\|_0, \|u'\|_0\}$.  Notice that the natural imbedding
$C^1\hookrightarrow C^0$ furnishes the space $C^1$ with both norms,
$\|\cdot\|_0$ and $\|\cdot\|_1$. 
Then, given a set $A\subseteq C^1$, we let $cl_0 A$ and $cl_1 A$ be the closures
of $A$ with respect to the norms $\|\cdot\|_0$ and $\|\cdot\|_1$, respectively.
We shall denote by $C^0_+$ the set of
all nonnegative functions of $C^0$. Also,  let $\mathcal{M}$ be the linear
space of all Lebesgue measurable functions $u:I\to\mathbb{R}$ and
$\mathcal{L}^1$ the Banach space of all Lebesgue integrable functions
$u\in \mathcal{M}$ with norm $\|u\|_{\mathcal{L}^1}$.

 In the sequel, given two topological  spaces $X_1, X_2$,
to emphasize that an operator $V:X_1\to X_2$ is continuous, we shall say
that $V$ is $(X_1, X_2)$-continuous.
We introduce the following definition.

 \begin{definition}\label{d1} \rm
Let $i=0,1$. An operator  $G:C^i\to \mathcal{M}$   will be said to be a
$C^i$-type Caratheodory operator, if it is $(\|\cdot\|_i,\mathcal{L}^1)$-continuous,
and for each  $c>0$, there is a  function $m_c\in \mathcal{L}^1$,
such that
$$
\|u\|_i\leq c\implies|(Gu)(t)|\leq m_c(t), \quad \text{for a.a. }  t\in I
$$
and  $u\in C^i$.
 \end{definition}

Hence, if $f(t,x,y)$ is a  Caratheodory function (in the usual sense) with
respect to the pair-variable $(x,y)$, then the types
\begin{gather*}
(F_1u)(t):=f(t,u(t), u(\frac{t}{2})), \\
(F_2u)(t):=f(t, u(t), \int_0^1a(s)u^2(s)ds),\quad (a\in\mathcal{L}^1), \\
(F_3u)(t):=f(t, u(t),  u'(\frac{t}{3}))
\end{gather*}
define, respectively,  $C^0, C^0, C^1$-type Caratheodory operators.

Because of  a great number of physical applications, the study of $\phi$-Laplacian
differential equations of second order of the form
$$
(a(t)\Phi(u'(t)))'+b(t)f (t, u(t))=0,\quad  t\in(0, 1),
$$
associated with various boundary value conditions have received the  attention
of many authors; see, e.g.,
\cite{BF}-\cite{bdm1}, \cite{dfg}, \cite{gmz}-\cite{ ggm}, \cite{k2},
\cite{lz}-\cite{ l1}, \cite{ zlm}, and the references therein.
In  most of these papers the response function  is continuous in its arguments,
thus it is a Caratheodory function.  Also, many two- (or multi)-point boundary
value problems involving  the well-known $p$-Laplacian equation
 $$
(\phi_p(u'(t)))' = f(t, u(t), u'(t)), \quad t\in [0, 1],
$$
where $\phi_p(s):= |s|^{p-2}s$, \quad $(p>1)$,  have received a lot of attention,
see for instance, \cite{bdgk, gm,  hm, pem} and the references therein.
The key condition in these works is a growth restriction imposed on the response
$f$.

 When seeking a positive solution of the problem and the positivity of the
 nonlinearity is guaranteed, most of the authors mentioned above, are frequently
led to use the Krasnoselskii's fixed point theorem applying to a completely
continuous operator $T$ which is defined on an appropriate cone in some
Banach space.  A type of a barrier strip on the function $f$ is used elsewhere
(see, e.g., \cite{k, kt, zlm} and the references therein) and then  apply
 the Topological Transversality Theorem. The disadvantage in the latter
situations is that no sign of the solutions is known.

 The presence of a generally nonlinear operator $\Phi$ was introduced
in \cite{ka, ka1}, which  was assumed to be  a sup-multiplicative-like
function in the following sense:  $\Phi$ is a \emph{sup-multiplicative-like}
function, if it is an odd homeomorphism of the real line $\mathbb{R}$
onto itself, for which there exists a homeomorphism $\phi$ of $[0, +\infty)$
onto itself, that \emph{supports} $\Phi$, in the sense that, for all
$v_1, v_2\geq 0$, it holds $\phi(v_1)\Phi(v_2)\leq\Phi(v_1v_2)$.
For instance, a function of the form
$\Phi(v):=\sum_0^kc_j |v|^jv$, $v\in\mathbb{R}$ is sup-multiplicative-like,
provided that $c_j\geq 0$ and $\sum c_j>0$. Here a supporting function is
defined by $\phi(u):=\min\{u^{k+1},u\}$, $u\geq 0$.
A good use of sup-multiplicative-like functions is made elsewhere, see,
 e.g., \cite{bdm, bdm2}.

The motivation of considering limiting boundary conditions  comes, mainly,
from the works of \cite{YT, YT1, oa}, which refer to $\mathbb{R}$, or to
 $\mathbb{R}^n$ and are of the form
$$
-\frac{1}{p(t)}(p(t)y'(t))'=q(t)f(t,y(t)), \quad 0<t<T,
$$
with boundary conditions,
$$
-\alpha y(0)+\beta\lim_{t\to 0^+}p(t)y'(t)=c, \quad
\gamma y(T)+\delta\lim_{t\to T^-}p(t)y'(t)=d,
$$
where $\alpha, \beta, \gamma, \delta$ are nonnegative real numbers.
In these problems the moment-function $p$ is positive on $(0,1)$ and
$$
\int_0^1\frac{ds}{p(s)}<+\infty,
$$
as well as either it is a $C^1$ function, or such that $\min_{t\in I}p(t)>0$.
The latter is not required in our first main result.

In this work we give two existence results covering the case where the operator
$F$  is a  $C^0$- or a $C^1$-type operator.
To prove our main theorems we shall apply the following well known
Schauder-Tychonoff Fixed Point Theorem (see, e.g., \cite{m}
and \cite[p. 26]{Br}).

\begin{theorem}\label{thm1}
Let $\mathbf{C}$ be a closed convex subset of a normed linear space and
let $f:\mathbf{C}\to \mathbf{C}$ be a compact map (i.e. it is continuous
and $f(\mathbf{C})$ is relatively compact), then $f$ has a fixed point.
\end{theorem}

We shall apply twice Theorem \ref{thm1}. First in the linear space
$C^1(I,\mathbb{R})$, when it is furnished with the norm $\|\cdot\|_0$
and second in the same space, endowed with its natural norm $\|\cdot\|_1$.
 Notice that with respect to the first norm the space $C^1$ is not complete. \par

\section{Some auxiliary facts}

In the sequel we assume the following:
\begin{itemize}
\item[(H1)]  The function $\Phi$ is an increasing homeomorphism of
$\mathbb{R}$ onto $\mathbb{R}$,  with $\Phi(0)=0$.
Let $\Psi$ be the inverse of $\Phi$.

\item[(H2)] The function $p:I\to(0,+\infty)$ is measurable, and the function
$\Psi(\frac{k}{p})$ is Lebesgue integrable on I, for all $k\in\mathbb{R}$.

\item[(H3)] The measure-functions $\eta, \zeta:[0,1]\to[0,+\infty)$ are
nondecreasing and non constants on $I$, and, moreover, satisfy the
conditions
$$
\eta(0)=\zeta(0)=0,\quad \eta(1)\zeta(t)\leq\zeta(1)\eta(t),\quad
\text{for all}\quad t\in I.
$$

\item[(H4)] The quantity $(F0)(t)$ is not identically equal to zero for a.a.
$t\in I$. (Obviously, the latter implies that the problem does not admit
the zero solution.)
\end{itemize}

\begin{lemma}\label{lemm}
Under the conditions {\rm (H1)--(H4)} the problem does not have a
nonnegative solution $u$ with $(Fu)(t)=0$, a.e. on $I$.
\end{lemma}

\begin{proof}
Indeed, if such a solution $u$ exists, it satisfies $p(t)\Phi(u'(t))=c$,
a.e. on $I$, for some $c$. From \eqref{e2} we obtain both $c\geq 0$ and $c\leq 0$.
Thus $c=0$ and so $\Phi(u'(t))=0$, a.e. on $I$, which means that $u$
is a constant, $v$, say. Again, from  the first of \eqref{e2}
we obtain $v\eta(1)=0$, and so $v=0$. Thus we have $(F0)(t)=0$,
 a.a $t\in I$, which contradicts to (H4).
\end{proof}

Next, for $i=0, 1$ we consider the condition:
\begin{itemize}
\item[(H5)$_i$] The operator $F$ has the following properties:\par
\begin{itemize}
\item[(i)]   It holds $(Fu)(t)\geq 0$, $t\in I$, for all $u\in C^i$,
with $u(t)\geq 0$.
\item[(ii)] The operator $u\to p(Fu)=:Gu$ maps the set $C^i$ into
$\mathcal{L}^1$ and it is a $C^i$-type Caratheodory operator.
Recall that, by definition, the latter condition ensures  that,
for each $c>0$, there is some $m_c\in\mathcal{L}^1$, satisfying the
condition  $0\leq p(t)(Fu)(t)\leq m_c(t)$, for a.a. $t\in I$ and
$u\in C^i$ with $0\leq \|u\|_i\leq c$ and $0\leq u(t)$, $t\in I$.
\end{itemize}
\end{itemize}
 In  the sequel, the most important role in our discussion will be played by
 the quantity
$$
D(x,\phi):=\eta(1)(x-\phi(1))+\zeta(1)x+\int_0^1(\zeta(1)\eta(t)
-\eta(1)\zeta(t))\Psi\big(\frac{1}{p(t)}[x-\phi(t)]\big)dt,
$$
 which is defined for each real number $x$ and any continuous function
$\phi:[0,1]\to \mathbb{R}$. This functional has the following properties:

\begin{lemma}\label{l1}
Given any  nondecreasing continuous function $\phi:[0,1]\to\mathbb{R}^+$,
there exists a unique  real number $\mathcal{X}\big(\phi)\in[0,\phi(1)\big]$,
satisfying the equation
$$
D(\mathcal{X}(\phi),\phi)=0.
$$
If  $\phi(0)=0<\phi(1)$, then $\mathcal{X}\big(\phi)\in(0,\phi(1)\big)$.
Moreover the operator $\phi\to \mathcal{X}(\phi)$ is
$(C^0,\mathbb{R})$-continuous.
\end{lemma}

\begin{proof} It is obvious that if $\phi(1)=0$ then $D(x,\phi)=0$, if and only
if $x=0$. Assume that it holds  $\phi(1)>0$. Then the  existence of such
a real number follows from the continuity of $D(\cdot,\phi)$ and the fact
that the value
$$
D(0,\phi)=-\eta(1)\phi(1)+\int_0^1(\zeta(1)\eta(t)-\eta(1)\zeta(t))
\Psi\big(\frac{1}{p(t)}[-\phi(t)]\big)dt,
$$
is negative, while, for any fixed $v\geq\phi(1)$, the value
\begin{equation}
\begin{aligned}
D(v,\phi)&=\eta(1)(v-\phi(1))+\zeta(1)v\\
&\quad +\int_0^1(\zeta(1)\eta(t)-\eta(1)\zeta(t))\Psi\big(\frac{1}{p(t)}
[v-\phi(t)]\big)dt,
\end{aligned}
\end{equation}
is positive.
The uniqueness is implied from the monotonicity of $D(x,\phi)$
with respect to $x$.

 Finally, let $(\phi_n)$ be a sequence of nonnegative continuous
functions defined on $I$. Assume that $(\phi_n)$  converges, in the
sense of $\|\cdot\|_0$-norm, to a function $\phi$. (By the uniform
converge of bounded functions, it follows that there is a common upper
bound $B$ of all functions $\phi_n$, $n=1, 2, \dots$.
Hence, by the first part of the lemma, we conclude that the quantities
$(\mathcal{X}(\phi_{n}))$ belong to $[0,B]$, for all $n=1, 2,\dots$).
  If there are subsequences $(\mathcal{X}(\phi_{k_n}))$ and
 $(\mathcal{X}(\phi_{l_n}))$ converging to $v_1$ and $v_2$ respectively,
we must have
$$
D(\mathcal{X}(\phi_{k_n}),\phi_{k_n})=0
=D(\mathcal{X}(\phi_{l_n}),\phi_{l_n}).
$$
Then, by the continuity of $\Psi$, we obtain
$$
D(v_1,\phi)=0=D(v_2,\phi),
$$
which, by the uniqueness, implies that $v_1=\mathcal{X}(\phi)=v_2$.
This shows the continuity of $\mathcal{X}$.
\end{proof}
Next  assume that $F$ satisfies condition (H5)$_i$. Then  the operator
$P$ defined by
\begin{equation}\label{b1}
P(u)(t):=\int_{0}^tp(s)(Fu)(s)ds, \quad u\in C^0_+\cap C^i,
\end{equation}
is $(C^i,C^0)$-continuous and  the function  $P(u)$ is nonnegative
and non-decreasing, with $P(u)(0)=0<P(u)(1)$. Therefore, by  Lemma \ref{l1},
the operator $u\to\mathcal{X}(P(u))$ is $(C^i,\mathbb{R})$-continuous
on the set $C^0_+\cap C^i$. Moreover, the previous arguments ensure that the
quantity $\mathcal{X}(P(u))$ satisfies the relation
\begin{equation} \label{v1}
\begin{aligned}
\mathcal{X}(P(u))
&=\frac{\eta(1)}{\eta(1)+\zeta(1)}\Big[P(u)(1)\\
&\quad -\int_0^1\int_0^t\Psi
  \big(\frac{1}{p(s)}[\mathcal{X}(P(u))-P(u)(s)]\big)dsd(\zeta+\eta)(t)\Big]\\
&\quad+\int_0^1\int_0^t\Psi\big(\frac{1}{p(s)}[\mathcal{X}(P(u))-P(u)(s)]
\big)dsd\eta(t).
 \end{aligned}
\end{equation}

\section{Reformulation of the Problem}

By a positive solution of the problem \eqref{e1}-\eqref{e2} we mean a function
$u\in C^1\cap C^0_+$,  satisfying the conditions  \eqref{e2}, and being such
that the function $t\rightarrow p(t)\Phi(u'(t))$ is absolutely continuous on
the interval $I$  and the relation   \eqref{e1} is satisfied almost everywhere
on the  interval $I$.

To set the problem \eqref{e1}-\eqref{e2} in a form of seeking a fixed point
of an appropriate functional operator, we shall reformulate it to an integral
equation.
To this end, assume that $u(t), \quad t\in I$, is a nonnegative solution.
Then, for all $\tau, t\in [0,1]$, we have
\begin{equation}\label{q1}
p(t)\Phi(u'(t))=p(\tau)\Phi(u'(\tau))-\int_{\tau}^tp(s)(Fu)(s)ds.
\end{equation}
By using the boundary conditions \eqref{e2} we obtain
\begin{equation}\label{e4}
p(t)\Phi(u'(t))=\int_0^1u(s)d\eta(s)-\int_{0}^tp(s)(Fu)(s)ds,
\end{equation}
as well as
\begin{equation}\label{e5}
-\int_0^1u(s)d\zeta(s)=\int_0^1u(s)d\eta(s)-\int_0^1p(s)(Fu)(s)ds.
\end{equation}
From relation \eqref{e4} it follows that
$$
\Phi(u'(t))=\frac{1}{p(t)}[k_u-P(u)(t)],
$$
 where $k_u$ is the non-negative real number
$$
k_u:=\int_0^1u(s)d\eta(s)
$$
and $P(u)$  is the function defined by \eqref{b1}.
From Lemma \ref{lemm} we have $P(u)(1)>0$. Also, it is clear that it holds
\begin{equation}\label{eqw1}
P(u)(t)\leq \int_0^1m_c(s)ds=:B_c
\end{equation}
where $c:=\|u\|_0$. Moreover we have
\begin{equation}\label{a1}
u'(t)=\Psi\big(\frac{1}{p(t)}[k_u-P(u)(t)]\big).
\end{equation}
Thus the solution $u$ satisfies the integral equation
\begin{equation}\label{e6}
u(t)=u(0)+\int_0^t\Psi\big(\frac{1}{p(s)}[k_u-P(u)(s)]\big)ds.
\end{equation}

The value of the function $u$ at 0, is not known, so we shall express it
 by using the boundary values \eqref{e2}. In order to do it, we observe  that,
 on one hand, we have
$$
\int_0^1u(s)d\zeta(s)=u(0)\zeta(1)
+\int_0^1\int_0^t\Psi\big(\frac{1}{p(s)}[k_u-P(u)(s)]\big)dsd\zeta(t),
$$
and, on the other hand
$$
\int_0^1u(s)d\eta(s)=u(0)\eta(1)+\int_0^1\int_0^t\Psi\big(\frac{1}{p(s)}
[k_u-P(u)(s)]\big)dsd\eta(t),
$$
Then, by using relation \eqref{e5} we obtain
$$
u(0)=\frac{1}{\eta(1)+\zeta(1)}
\Big[P(u)(1)-\int_0^1\int_0^t\Psi
\big(\frac{1}{p(s)}[k_u-P(u)(s)]\big)dsd(\zeta+\eta)(t)\Big].
$$
 Replacing this value of $u(0)$ in equation \eqref{e6} we obtain that
 \begin{equation} \label{e7}
\begin{aligned}
u(t)
&=\frac{1}{\eta(1)+\zeta(1)}
 \Big[P(u)(1)-\int_0^1\int_0^t\Psi\big(\frac{1}{p(s)}
[k_u-P(u)(s)]\big)dsd(\zeta+\eta)(t)\Big]\\
 &\quad +\int_0^t\Psi\big(\frac{1}{p(s)}[k_u-P(u)(s)]\big)ds.
 \end{aligned}
\end{equation}
The latter equation gives a useful expression of the quantity $k_u$, as follows:
  \begin{equation} \label{e81}
\begin{aligned}
k_u&=\int_0^1u(s)d\eta(s)\\
  &=\frac{\eta(1)}{\eta(1)+\zeta(1)}\Big[P(u)(1)-\int_0^1\int_0^t\Psi
  \big(\frac{1}{p(s)}[k_u-P(u)(s)]\big)dsd(\zeta+\eta)(t)\Big]\\
 &\quad +\int_0^1\int_0^t\Psi\big(\frac{1}{p(s)}[k_u-P(u)(s)]\big)dsd\eta(t),
 \end{aligned}
\end{equation}
which, after some obvious manipulations, becomes
\begin{align*}
k_u&=\frac{1}{\eta(1)+\zeta(1)}\Big[\eta(1)P(u)(1)\\
 &\quad +\int_0^1\int_0^t\Psi
  \big(\frac{1}{p(s)}[k_u-P(u)(s)]ds\big)d[\zeta(1)\eta(t)-\eta(1)\zeta(t)]\Big]\\
  &=\frac{1}{\eta(1)+\zeta(1)}\Big[\eta(1)P(u)(1)
-\int_0^1(\zeta(1)\eta(t)-\eta(1)\zeta(t))\Psi
\big(\frac{1}{p(t)}[k_u-P(u)(t)]\big)dt\Big].
 \end{align*}
This relation means  that the quantity $k_u=:x$  satisfies the equation
 $$
D(x,P(u))=0.
$$
Then, by Lemma \ref{l1}, we conclude that $k_u$ is the unique quantity
which satisfies \eqref{e81} and it is such that
 \begin{equation}\label{e9}
k_u=\mathcal{X}(P(u))=\mathcal{X}\big(\int_0^{\cdot}p(s)(Fu)(s)ds\big)
\in(0,B_{c}).
\end{equation}

\begin{lemma}  \label{lem3.1}
A function $u\in C^0_+$ solves the problem \eqref{e1}-\eqref{e2},
if and only if it satisfies the integral equation
\begin{equation} \label{r7}
\begin{aligned}
u(t)&=\frac{1}{\eta(1)+\zeta(1)}
 \Big[P(u)(1)-\int_0^1\int_0^t\Psi\big(\frac{1}{p(s)}
 [\mathcal{X}(P(u))-P(u)(s)]\big)dsd(\zeta+\eta)(t)\Big]\\
 &\quad  +\int_0^t\Psi\big(\frac{1}{p(s)}[\mathcal{X}(P(u))-P(u)(s)]\big)ds,
 \end{aligned}
\end{equation}
 where $P(u)$ is defined by \eqref{b1}.
\end{lemma}

\begin{proof}
If $u$ is such a solution, then, by using \eqref{e9} and \eqref{e7}
we obtain the ``if'' part.
To  prove the ``only if'' part,  assume that a nonnegative function $u$
satisfies \eqref{r7}. Clearly, $u$ is differentiable and its derivative
satisfies  \eqref{e1}. We shall show that   \eqref{e2} is satisfied,
too. To do it,  observe that
\begin{align*}
\int_0^1u(s)d\eta(s)&=\frac{\eta(1)}{\eta(1)+\zeta(1)}
 \Big[P(u)(1) \\
&\quad-\int_0^1\int_0^t\Psi\big(\frac{1}{p(s)}[\mathcal{X}(P(u))-P(u)(s)]
\big)dsd(\zeta+\eta)(t)\Big]\\
&\quad +\int_0^1\int_0^t\Psi\big(\frac{1}{p(s)}
[\mathcal{X}(P(u))-P(u)(s)]\big)dsd\eta(t).
\end{align*}
which, by \eqref{v1}, shows that the quantity $\int_0^1u(s)d\eta(s)$
is equal to $\mathcal{X}(P(u))$, namely we have
 $$
\mathcal{X}(P(u))=\int_0^1u(s)d\eta(s)=k_u.
$$
Also, we have
\begin{align*}
\int_0^1u(s)d\zeta(s)
&=\frac{\zeta(1)}{\eta(1)+\zeta(1)}
 \Big[P(u)(1) \\
&\quad -\int_0^1\int_0^t\Psi\big(\frac{1}{p(s)}[k_u-P(u)(s)]\big)
dsd(\zeta+\eta)(t)\Big]\\
&\quad +\int_0^1\int_0^t\Psi\big(\frac{1}{p(s)}[k_u-P(u)(s)]
\big)dsd\zeta(t)
\end{align*} and therefore
 \begin{equation}\begin{aligned}
&\int_0^1u(s)d(\zeta(s)+\eta(s))\\
 &=\frac{\zeta(1)+\eta(1)}{\zeta(1)+\eta(1)} \Big[P(u)(1)
 -\int_0^1\int_0^t\Psi\big(\frac{1}{p(s)}[k_u-P(u)(s)]\big)dsd(\zeta+\eta)(t)\Big]\\
 &\quad +\int_0^1\int_0^t\Psi\big(\frac{1}{p(s)}[k_u-P(u)(s)]\big)
 dsd(\zeta(t)+\eta(t)),
\end{aligned}
\end{equation}
from which it follows that
 \begin{equation}\label{e8}
-\int_0^1u(s)d\zeta(s)=k_u-P(u)(1)=k_u-\int_0^1p(s)(Fu)(s)ds.
\end{equation}
 On the other hand we observe that
 $$
p(t)\Phi(u'(t))=k_u-\int_0^tp(s)(Fu)(s)ds
$$
and hence the function $t\to p(t)\Phi(u'(t))$ is absolutely continuous
in the interval $I$. Moreover, from this relation and \eqref{e8}
we conclude that conditions \eqref{e2} are satisfied.
\end{proof}

\section{Main results}
By the results of the previous section, the problem of existence
of solutions of the problem \eqref{e1}-\eqref{e2} is equivalent
to the problem of existence of a fixed point of the operator defined by
 \begin{equation} \label{e71}
\begin{aligned}
(\mathcal{T}u)(t):&=\frac{1}{\eta(1)+\zeta(1)}  \Big[\int_0^1p(s)(Fu)(s)ds\\
 &\quad -\int_0^1\int_0^{\theta}\Psi\big(\frac{1}{p(s)}
 [\mathcal{X}(P(u))-\int_0^sp(r)(Fu)(r)dr]\big)dsd(\zeta+\eta)(\theta)\Big]\\
&\quad +\int_0^t\Psi\big(\frac{1}{p(s)}[\mathcal{X}(P(u))
 -\int_0^sp(r)(Fu)(r)dr]\big)ds,
\end{aligned}
\end{equation}
where $P(u)$ is defined by \eqref{b1}. Recall that $\mathcal{X}(P(u))$ is
an element of the interval $[0,B_c]$, where $c:=\|u\|_0$.

\begin{lemma}\label{l3}
Assume that  conditions {\rm (H1)--(H4)} and {\rm (H5)$_0$}
 are satisfied. Then the  operator $\mathcal{T}$ is $(C^0,C^0)$-continuous
on $C^0_+$.
\end{lemma}

 \begin{proof}
Let $(u_n)$ be a sequence of functions in $C^0_+$ converging to a certain
$u_0\in C^0_+$ in the $\|\cdot\|_0$-sense. It is clear that there is some
$b>0$ satisfying $0\leq u_n(t)\leq b$, for all $t\in I$ and $n=1, 2, \dots$.
 Hence all points $\mathcal{X}(P(u_n))$ exist in $[0,B_b]$ and it holds
 \begin{equation}\label{e72}
|g_n(s)|\leq \max\{-\Psi(\frac{-B_b}{p(s)}),\Psi(\frac{B_b}{p(s)})\}, \quad
n=1, 2,\dots
\end{equation}
where
$$
g_n(s):=\Psi\big(\frac{1}{p(s)}[\mathcal{X}(P(u_n))
- \int_0^sp(r)(Fu_n)(r)dr]\big), \quad n=0, 1, 2, \dots.
$$
Notice that the right side of \eqref{e72} defines an integrable function and,
 moreover, due to (H5)$_0$ (ii), it holds
$$
\lim g_n(s)=g_0(s), \quad s\in I.
$$
Finally observe that $ (\mathcal{T}u)$ takes the form
\begin{align*}
 (\mathcal{T}u_n)(t)
&=\frac{1}{\eta(1)+\zeta(1)} \Big[\int_0^1p(s)(Fu_n)(s)ds\\
&\quad -\int_0^1(\eta(1)+\zeta(1)-\eta(s)-\zeta(s))g_n(s)ds
+\int_0^tg_n(s)ds\Big]
\end{align*}
Now, we apply the Lebesgue Dominated Convergence Theorem and
get the desired result.
\end{proof}

 \begin{lemma}\label{l31}
Assume that  conditions {\rm (H1), (H3)} and {\rm (H5)$_1$}  are satisfied.
Then the operator $\mathcal{T}$ is $(C^0,C^1)$-continuous, provided that the
following condition holds:
\begin{equation}\label{eC} 
p:I\to(0,+\infty)\text{ is continuous}.
\end{equation}
\end{lemma}

 \begin{proof}
Condition \eqref{eC} implies that there is some $\rho>0$ such that
$p(t)\geq\rho$, for $t\in I$.
As in previous lemma,
let $(u_n)$ be a sequence of functions in $C^0_+$ converging to a certain
$u\in C^0_+$ in the $\|\cdot\|_0$-sense.  Since, obviously, condition
 \eqref{eC} implies condition (H2), from the previous lemma we know that  
the sequence  $(\mathcal{T}u_n)$ converges to $\mathcal{T}u$ in the 
$\|\cdot\|_0$-sense. 

Notice, also, that    the function 
$$
u\to\mathcal{X}(P(u))- \int_0^{\cdot}p(r)(Fu)(r)dr
$$ 
is $(C^0,C^0)$-continuous. 
  From the form of the operator $\mathcal{T}$ we see that
it holds 
$$
\frac{d}{dt}(\mathcal{T}u)(t)=\Psi(w(t;u)),
$$ 
where 
$$
w(t;u):=\frac{1}{p(t)}[\mathcal{X}(P(u))-\int_0^tp(r)(Fu)(r)dr].
$$ 
 To proceed, consider any $\epsilon>0$. By the uniform continuity of the 
function $\Psi$ on the interval $[-\frac{B_b}{\rho}, \frac{B_b}{\rho}]$, 
there is a $\delta_0>0$ such that for all 
$v_1, v_2\in[-\frac{B_b}{\rho}, \frac{B_b}{\rho}]$, it holds  
$$
|v_1-v_2|<\delta_0\implies |\Psi(v_1)-\Psi(v_2)|< \epsilon.
$$ 
 Fix any $\delta\in(0,\delta_0\rho)$. By the previous argument it follows that 
there is some $n_0$ such that 
$$
|[\mathcal{X}(P(u_n))- \int_0^{t}p(r)(Fu_n)(r)dr]-[\mathcal{X}(P(u))
- \int_0^{t}p(r)(Fu)(r)dr]|\leq\delta,
$$ 
for all $t\in I$ and $n\geq n_0$. This and the assumption that 
$p(t)\geq \rho$, for all $t\in I$, imply that
$$
|w(t;u_n)-w(t;u)|\leq\frac{\delta}{\rho}< \delta_0,
$$ 
for all $t\in I$ and $n\geq n_0$. We conclude that  
$$
|\Psi(w(t,u_n))-\Psi(w(t;u))|\leq \epsilon,
$$ 
for all $t\in I$ and $n\geq n_0$. The proof is complete.
\end{proof}

 \subsection{Existence in the $C^0$ case}
 Our first main result is  the following.

 \begin{theorem}\label{t1} 
Let the conditions {\rm(H1)--(H4)} and {\rm (H5)$_0$} be satisfied. 
Also,  assume that there is a $c>0$ such that 
\begin{itemize}
\item[(H6)] 
$$
\frac{B_{c}}{\eta(1)}+\int_0^1\frac{\eta(s)}{\eta(1)}
\Psi\big(\frac{B_{c}}{p(s)}\big)ds
-\int_{0}^1\Psi\big(\frac{-B_{c}}{p(s)}\big)ds\leq c,
$$ 
where $B_c$ is defined by \eqref{eqw1},  and

\item[(H7)]  for all $\lambda \in [0,B_{c}]$, it holds
$$
\lambda\geq\max\Big\{\int_0^{1}[\zeta(1)-\zeta(t)+\eta(1)
-\eta(t)]\Psi\big(\frac{\lambda}{p(t)}\big)dt,\quad 
-\int_0^1[\zeta(t)+\eta(t)]\Psi\big(\frac{-\lambda}{p(t)}\big)dt\Big\}.
$$
\end{itemize}
Then the operator $\mathcal{T}$ admits a fixed point in the set 
$$
S_{c}:=\{u\in C^0_+: 0<\|u\|_0\leq c\}.
$$
\end{theorem}

\begin{proof} 
Because of (H5)$_0$,  to prove the result it is sufficient to show that  
the Schauder's fixed point theorem is applicable on the $\|\cdot\|_0$-closure 
$cl_0S_c$ of the set ${S_c}$. 

 We shall  show that the operator $\mathcal{T}$ maps the set $\overline{S_c}$ 
into itself.
Fix any  $u\in cl_0S_c$ and consider the quantity  $P(u)$ defined 
in \eqref{b1}. Then, from the relation
\begin{equation}\begin{aligned}
0&=(\eta(1)+\zeta(1))\mathcal{X}(P(u))-\eta(1)P(u)(1)\\
&\quad +\int_0^1(\zeta(1)\eta(t)-\eta(1)\zeta(t))
 \Psi\big(\frac{1}{p(t)}[\mathcal{X}(P(u))-P(u)(t)]\big)dt\\
&=\eta(1)(\mathcal{X}(P(u))-P(u)(1))+\zeta(1)\mathcal{X}(P(u))\\
&\quad +\int_0^1(\zeta(1)\eta(t)-\eta(1)\zeta(t))
 \Psi\big(\frac{1}{p(t)}[\mathcal{X}(P(u))-P(u)(t)]\big)dt,
\end{aligned}
\end{equation} 
it follows that we must have $\mathcal{X}(P(u))-P(u)(1)<0$.
 Thus  
$$
0\leq \mathcal{X}(P(u))\leq P(u)(1)\leq B_c.
$$ 
Also, by using the non-negativity of $F$, on the set $C^0_+$, we have 
$$
0\leq P(u)(t)\leq P(u)(1).
$$ 
These facts imply that there is a certain point $\xi\in(0,1)$ such that   
$$
(\xi-t)[\mathcal{X}(P(u))-P(u)(t)]\geq 0,\quad t\in(0,1).
$$ 
 Now, from the form of the operator $\mathcal{T}$, we observe that it holds 
$$
\frac{d}{dt}(\mathcal{T}u)(t)=\Psi\big(\frac{1}{p(t)}[\mathcal{X}(P(u))
-\int_0^tp(r)(Fu)(r)dr]\big)
$$
and so we conclude  that  at the point $\xi$ the function $\mathcal{T}u$ 
admits a maximum, it is increasing for $t\leq \xi$ and decreasing for
 $t\geq \xi$.

From these remarks it follows that  to show that  
$0\leq(\mathcal{T}u)(t)\leq c$, for all $t\in I$, it is sufficient
 to show that  the following two inequalities hold:
\begin{gather}\label{a}
(\mathcal{T}u)(\xi)\leq c, \\
\label{b} \min\{ (\mathcal{T}u)(0), (\mathcal{T}u)(1)\}\geq 0.
\end{gather} 
To show \eqref{a}, we use relation  \eqref{v1}. We have
\begin{align*}
(\mathcal{T}u)(\xi)
&=\frac{1}{\eta(1)}\Big[\mathcal{X}(P(u))
 -\int_0^1\int_0^{t}\Psi\big(\frac{1}{p(s)}
 [\mathcal{X}(P(u))-P(u)(s)]\big)dsd\eta(t)\Big]\\
&\quad +\int_0^{\xi}\Psi\big(\frac{1}{p(s)}[\mathcal{X}(P(u))-P(u)(s)]\big)ds\\
&=\frac{\mathcal{X}(P(u))}{\eta(1)}+\int_0^1\frac{\eta(s)}{\eta(1)}
 \Psi\big(\frac{1}{p(s)}[\mathcal{X}(P(u))-P(u)(s)]\big)ds\\
&\quad -\int_{\xi}^1\Psi\big(\frac{1}{p(s)}[\mathcal{X}(P(u))-P(u)(s)]\big)ds\\
&\leq \frac{\mathcal{X}(P(u))}{\eta(1)}+\int_0^1\frac{\eta(s)}{\eta(1)}
 \Psi\big(\frac{1}{p(s)}[\mathcal{X}(P(u))]\big)ds
 -\int_{0}^1\Psi\big(\frac{1}{p(s)}[-P(u)(s)]\big)ds\\
&\leq \frac{B_{c}}{\eta(1)}+\int_0^1\frac{\eta(s)}{\eta(1)}
 \Psi\big(\frac{B_{c}}{p(s)}\big)ds
 -\int_{0}^1\Psi\big(\frac{-B_{c}}{p(s)}\big)ds.
\end{align*}
Because of (H6), the latter quantity is less than or equal to $c$.

To show \eqref{b}, by the contrary,  we assume that $(\mathcal{T}u)(0)<0$. 
Then from \eqref{e71} we must have
\begin{align*}
 P(u)(1)&<\int_0^1\int_0^{t}\Psi\big(\frac{1}{p(s)}
[\mathcal{X}(P(u))-P(u)(s)]\big)dsd(\zeta(t)+\eta(t))\\
&=\int_0^1[\zeta(1)-\zeta(t)+\eta(1)-\eta(t)]
 \Psi\big(\frac{1}{p(t)}[\mathcal{X}(P(u))-P(u)(t)]\big)dt\\
&\leq \int_0^{1}[\zeta(1)-\zeta(t)+\eta(1)-\eta(t)]
 \Psi\big(\frac{1}{p(t)}[\mathcal{X}(P(u))]\big)dt
\end{align*}
and so
$$
\mathcal{X}(P(u))\leq P(u)(1)<\int_0^{1}
[\zeta(1)-\zeta(t)+\eta(1)-\eta(t)]\Psi\big(\frac{1}{p(t)}
[\mathcal{X}(P(u))]\big)dt,
$$
which is impossible because of (H7).

Next,  assuming that $(\mathcal{T}u)(1)<0$, we obtain
\begin{align*}
 P(u)(1)
&<-\int_0^1[\zeta(t)+\eta(t)]\Psi\big(\frac{1}{p(t)}
 [\mathcal{X}(P(u))-P(u)(t)]\big)dt\\
&\leq -\int_0^1[\zeta(t)+\eta(t)]\Psi\big(\frac{1}{p(t)}
 [-P(u)(1)]\big)dt.
\end{align*}
This is impossible, too, because of (H7) and the fact that 
$0\leq P(u)(1)\leq B_c$.

Now we recall Lemma \ref{l3} which says that  the operator $\mathcal{T}$ 
is $(C^0,C^0)$-continuous on $C^0_+$.  Also, as we have shown above,  
the set $cl_0S_c$  has a bounded image. 
The fact that  the family $\{\mathcal{T}u: u\in cl_0S_c\}$ 
is equicontinuous, follows easily from the relation
$$
|(\mathcal{T}u)(t)-(\mathcal{T}u)(\tau)|
\leq\Big|\int_{\tau}^t\Psi\big(\frac{1}{p(s)}
[\mathcal{X}(P(u))-P(u)(s)]\big)ds\Big|\leq\int_{\tau}^tY(s)ds,
$$ 
for all $\tau, t\in I$, with $\tau\leq t$, where 
$$
Y(s):=\max\{\Psi\big(\frac{B_c}{p(s)}\big),-\Psi\big(\frac{-B_c}{p(s)}\big)\}.
$$  
Hence, by Arzel\'{a} Ascoli' s Theorem, we conclude that the set 
$\mathcal{T}cl_0S_c$ is relatively $\|\cdot\|_0$-compact.
 Now, the desired result follows by applying Schauder's Fixed Point 
Theorem \ref{thm1}.
\end{proof} 

 \subsection{Existence in the $C^1$ case}
Our next result is the following.

\begin{theorem}\label{t2} 
Assume that conditions {\rm (H1), (H3), (H5)$_1$}  and  \eqref{eC} 
are satisfied. Also, assume that there is some $c>0$, satisfying the conditions  
{\rm (H6)} and {\rm(H7)}, as well as 
\begin{itemize}
\item[(H8)]
 $$
\max\{\Psi(\frac{B_c}{\rho}),-\Psi(-\frac{B_c}{\rho})\}\leq c,
$$
 where $\rho:=\min_{t\in I}p(t)$.
\end{itemize}
  Then the operator $\mathcal{T}$ defined by \eqref{e71}
admits a fixed point in the set 
$$
R_{c}:=\{u\in C^1(I,[0,+\infty)), \quad 0<\|u\|_1\leq c \}.
$$ 
\end{theorem}

\begin{proof}
First we notice that $R_c\subseteq S_c$ and $cl_1R_c=R_c\cup\{0\}$. 
Then, by the first part of  the proof 
of Theorem \ref{t1}, we conclude that the operator $\mathcal{T}$ maps the 
set $R_c$ into $S_c$, namely, for any $u\in R_c$
it holds
\begin{equation}\label{r1}
0\leq (\mathcal{T}u)(t)\leq c,\quad t\in I.
\end{equation}
Also we have $\mathcal{T}_0\in \mathcal{T}(cl_0S_c)\subseteq cl_0Sc$
and, so, $0\leq (\mathcal{T}0)(t)\leq c$, $t\in I$.
This and \eqref{r1} imply that
$0\leq(\mathcal{T}u)(t) \leq c$, $t \in I$, $u\in cl_1R_c$.


Consider a function $u\in cl_1 R_c$.
At first we observe that the function
$$(\mathcal{T}u)'(t)=\Psi\big(\frac{1}{p(t)}[\mathcal{X}(P(u))
-\int_0^tp(r)(Fu)(r)dr]\big), \quad t\in I
$$ 
is continuous. Also, since, $0\leq\|u\|_0\leq\|u\|_1\leq c$, 
it holds 
$$
-B_c\leq \mathcal{X}(P(u))-\int_0^tp(r)(Fu)(r)dr\leq B_c,\quad t\in I
$$ 
and so condition  (H8) gives 
$$
|(\mathcal{T}u)'(t)|\leq \max\{\Psi(\frac{B_c}{\rho}),
-\Psi(-\frac{B_c}{\rho})\}\leq c,\quad t\in I.
$$ 
This and \eqref{r1} imply that   $\|\mathcal{T}u\|_1\leq c$, hence 
$\mathcal{T}$ maps $cl_1 R_c$ into itself. 

 Now,  by (H5)$_1$, to complete the proof of the theorem, 
it is sufficient to show that  the Schauder's fixed point theorem 
is applicable on the set $cl_1R_c$, namely on  $\overline{R_c}=\{0\}\cup R_c$. 
This is a $\|\cdot\|_1$-closed, bounded, convex subset of the space $C^1$. 
It remains to prove that $\mathcal{T}cl_1 R_c$ is a relatively compact 
subset of $C^1$. 

 We shall show that  the operator $\mathcal{T}$ 
is compact, namely it is continuous and  the set $\mathcal{T}cl_1R_c$ 
is a (relatively) compact subset of $C^1$. 

First we notice that,  
by  Lemma \ref{l31}, the operator $\mathcal{T}$ is $(C^1,C^1)$-continuous.  
 Then taking into account, also, that the set $R_c$ is a subset of $S_c$, 
we have 
$\mathcal{T}cl_1 R_c\subseteq cl_1 \mathcal{T}R_c$.
 Therefore it is enough to show that $\mathcal{T}{S_c}$ is a (relatively) 
$\|\cdot\|_1$-compact subset of $C^1$. \par To do that consider a sequence 
$(U_n)$ in $\mathcal{T}S_c$. Then there is a sequence $u_n\in S_c$ such that 
$U_n=\mathcal{T}u_n$. As we proved previously,  it holds
$$
\|\mathcal{T}u_n\|_0\leq \|\mathcal{T}u_n\|_1\leq c,\quad n=1, 2, \dots
$$  
and, moreover, it satisfies
\begin{equation}
\begin{aligned}
|U_n(t)-U_n(\tau)|
&=\Big|\int_{\tau}^t\Psi\big(\frac{1}{p(s)}
 [\mathcal{X}(P(u))-\int_0^sp(r)(Fu_n)(r)dr]\big)ds\Big|\\
&\leq\max\{\Psi(\frac{B_c}{\rho}),-\Psi(-\frac{B_c}{\rho})\} 
|t-\tau|\\
&\leq c|t-\tau|.
\end{aligned}\end{equation}
The latter says that the sequence $(U_n)$  is equicontinuous.  
By Arzel\'{a}-Ascoli Theorem it follows that a subsequence 
$(U_{k_n})=(\mathcal{T}u_{k_n})$ exists, which converges in the 
$\|\cdot\|_0$-norm to a function $y\in C^0(I,\mathbb{R})$. 

 Next, we take any $\epsilon>0$. By the uniform continuity of the function 
$\Psi$ on the interval $[-B_c/\rho, B_c/\rho]$,
 there is a $\delta_1>0$ such that, 
for all $v_1, v_2\in [-B_c/\rho, B_c/\rho]$,
it holds  
\begin{equation}\label{r2}
|v_1-v_2|<\delta_1\implies |\Psi(v_1)-\Psi(v_2)|< \epsilon.
\end{equation} 
It is clear  that  the sequence of functions defined by 
$$
z_n(t):=\frac{1}{p(t)}[\mathcal{X}(P(u_{k_n}))-\int_0^tp(s)(Fu_{k_n})(s)ds], 
\quad t\in I
$$ 
is 
$\|\cdot\|_0$-bounded\footnote{with a bound $\frac{B_c}{\rho}$} and, 
for all $\tau, t\in I$, it satisfies
\begin{align*}
|z_n(t)-z_n(\tau)|
&= \Big|\Big(\frac{1}{p(t)}-\frac{1}{p(\tau)}\Big)\mathcal{X}(P(u_{k_n}))\\
&\quad -\frac{1}{p(t)}\int_{0}^tp(s)(Fu_{k_n})(s)ds
+\frac{1}{p(\tau)}\int_{0}^{\tau}p(s)(Fu_{k_n})(s)ds\Big|
\\
&\leq \frac{1}{p(t)}\Big|\int_{\tau}^tp(s)(Fu_{k_n})(s)ds\Big|\\
&\quad +\Big|\frac{1}{p(t)}-\frac{1}{p(\tau)}\Big| \Big|\mathcal{X}(P(u_{k_n}))
-\int_0^{\tau}p(s)(Fu_{k_n})(s)ds\Big|\\
&\leq\frac{1}{p(t)} \Big|\int_{\tau}^tm_c(s)ds\Big|
 +\Big|\frac{1}{p(t)}-\frac{1}{p(\tau)}\Big|B_c.
\end{align*}
 Therefore, the sequence $(z_n)$ is equicontinuous and so it has a subsequence  
$(z_{l_n})$, which converges to a function $z\in C^0$ in the sense of 
$\|\cdot\|_0$-norm. Equivalently, the sequence 
$(\Phi\big((\mathcal{T}u_{k_{l_n}})'(\cdot)\big))$ converges to the function 
$z(\cdot)$ in the $\|\cdot\|_0$-norm and hence it is a 
$\|\cdot\|_0$-Cauchy sequence. Therefore, given any $\delta>0$ with 
$\delta\leq\delta_1$,   there is some index $k_0$ such that
$$
| \Phi\big((\mathcal{T}u_{k_{l_n}})'(t)\big)
-\Phi\big((\mathcal{T}u_{k_{l_m}})'(t)\big)|<\delta,
\quad t\in I,
$$ 
for all $m, n\geq k_0$. Thus, from \ref{r2}, we obtain
$$
|(\mathcal{T}u_{k_{l_n}})'(t)-(\mathcal{T}u_{k_{l_m}})'(t)|<\epsilon,\quad t\in I,
$$ 
for all $m, n\geq k_0$. This proposition says that the  sequence 
$((\mathcal{T}u_{k_{l_n}})'(\cdot))$ is a Cauchy sequence and so 
it converges to the function $\Psi(z)$ in the $\|\cdot\|_0$-norm. 
 By a standard criterion of the uniform converge of sequences of 
differentiable functions, we conclude that $y'$ exists, it is equal to 
$\Psi(z)$ and, moreover  it satisfies the limiting relation 
$$
\lim \|\mathcal{T}u_{k_{l_n}}-y\|_1=0.
$$ 
These arguments and the continuity of $\mathcal{T}$ imply the  relative 
$\|\cdot\|_1$-compactness of the set ${\mathcal{T}{S_c}}$. 
This implies that the set  $\mathcal{T}cl_1R_c$ is relatively
 $\|\cdot\|_1$-compact.  Now, the Schauder's Fixed Point Theorem \ref{thm1} 
completes the proof.
\end{proof}

\section{An application of Theorem \ref{t1}}

We consider the equation
$$
t^{1/6}\big[t^{-1/6}\Phi(u'(t))\big]'
+\beta_0t+\beta_1u^2(t)+\beta_2u^3(\gamma t)\|u\|_0
+\beta_3\int_0^1u(s)ds=0,\quad t\in (0,1],
$$ 
with $\gamma\in (0,1)$ and $\beta_0>0$, $\beta_1, \beta_2, \beta_3\geq 0$,
associated with the boundary conditions
\begin{gather*}
\lim_{t\to0}t^{-1/6}\Phi(u'(t))=a_0u(0), \\
\lim_{t\to1}t^{-1/6}\Phi(u'(t))=-a_1u(0)-b_1u(\frac{1}{3}),
\end{gather*}
with $ a_0>0$, $a_1, b_1\geq 0$, where
$\Phi$ is the inverse of the function $$\Psi(v):=v+v^3,$$ namely,
$$
\Phi(w):=\Big(\frac{w-(w^2+\frac{4}{27})^{1/2}}{2}\Big)^{1/3}
-\frac{1}{3}\Big(\frac{w-(w^2+\frac{4}{27})^{1/2}}{2}\Big)^{-1/3}.
$$
This is of the form  \eqref{e1}-\eqref{e2}, with 
\begin{gather*}
p(t):=t^{-1/6},\quad t\in (0,1], \\
\eta:=a_0\chi_{(0,1]},\quad \zeta:=a_1\chi_{(0,\frac{1}{3}]}
+(a_1+b_1)\chi_{(\frac{1}{3},1]}.
\end{gather*}
We take $c=1$ and define 
\begin{gather*}
m(t):=\beta_0t^{5/6}+(\beta_1+\beta_2+\beta_3)t^{-1/6}, \quad t\in (0,1], \\
B:=\frac{6}{11}\beta_0+\frac{6}{5}(\beta_1+\beta_2+\beta_3).
\end{gather*}

 We can assume that the coefficients of the problem satisfy the following 
conditions (which are easily computable):
 \begin{gather*}
B(\frac{1}{a_0}+\frac{12}{7})+\frac{4B^3}{3}\leq 1,\\
(a_0+a_1)(\frac{3}{7}+\frac{B^2}{3})
 +b_1\frac{3}{7}\Big(1-\frac{1}{3^{7/6}}\Big)+b_1\frac{B^2}{3}
\Big(1-\frac{1}{3^{3/2}}\Big)\leq \frac{1}{2}.
\end{gather*}
 One can see that, in case $c=1$, these conditions show,  respectively, 
that (H6) and (H7) are satisfied.
 Hence,  Theorem \ref{t1} guarantees the existence of a solution $u\in C^0$ 
such that $0<\|u\|_0\leq 1$.

\section{An application of Theorem \ref{t2}}
 
We consider the equation
$$
\frac{d}{dt}\Phi(u'(t))+\alpha+\frac{\beta_1}{1+|u(\frac{t}{2})|}
+\frac{\beta_2}{1+(u'(t))^2}=0,\quad t\in I,
$$
 with  $\alpha, \beta_1, \beta_2\geq 0$, and $\alpha+\beta_1+ \beta_2>0$,
associated with the boundary conditions
$$
\lim_{t\to0}\Phi(u'(t))=au(\frac{1}{2}), \quad 
\lim_{t\to1}\Phi(u'(t))=-bu(1),
$$
($a, b>0$) where  $\Phi$ is the function  defined by
$\Phi(v):=\ln(1+|v|)sign(v)$.
This problem is of the form  \eqref{e1}-\eqref{e2}, with 
\begin{gather*}
p(t):=1,\quad t\in I, \\
\eta:=a\chi_{[\frac{1}{2},1]},\quad \zeta:=b\chi_{\{1\}}.
\end{gather*}
Assuming that the  condition
\begin{equation}\label{ex1}
b+\frac{a}{2}\leq \frac {\alpha+\beta_1+\beta_2}{e^{\alpha+\beta_1+\beta_2}-1}
\end{equation} 
is satisfied, we shall show that the problem admits a  solution $u$ with 
$$
0<\|u\|_1\leq \frac{2(\alpha+\beta_1+\beta_2)}{a}+3(e^{\alpha+\beta_1+\beta_2}-1).
$$
To do that it is sufficient to prove that the conditions of Theorem \ref{t2} 
are satisfied with 
$$
c:=\frac{\alpha+\beta_1+\beta_2}{a}+\frac{3}{2}(e^{\alpha+\beta_1+\beta_2}-1).
$$ 
Indeed, first of all observe that the inverse  of $\Phi$ is the  
function $\Psi(v):=(e^{|v|}-1)\operatorname{sign}(v)$. 
 We set $m:=\alpha+\beta_1+\beta_2$ and observe that $m_c(t):=m=B_c$. 
Then conditions (H6) and (H8) become
  $$
\frac{m}{a}+\frac{3}{2}(e^m-1)\leq c, \quad e^m-1\leq c.
$$ 
Clearly, this is true because of the choice of $c$. 
 Condition (H7) becomes
  $$
\lambda\geq (b+\frac{a}{2})(e^{\lambda}-1), \quad 
\lambda\geq \frac{a}{2}(e^{\lambda}-1).
$$ 
Both relations are satisfied if we have
  $$
b+\frac{a}{2}\leq \frac{\lambda}{e^{\lambda}-1},
$$ 
for all $\lambda\in [0,m]$. Since the right side of this inequality 
decreases with $\lambda$, the condition is satisfied, provided 
that it holds for the value $\lambda=m$. But the latter is true because 
of \eqref{ex1}. Thus, Theorem \ref{t2} applies and the result follows.

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\end{document}
