\documentclass[reqno]{amsart}
\usepackage{hyperref}

\AtBeginDocument{{\noindent\small
\emph{Electronic Journal of Differential Equations},
Vol. 2016 (2016), No. 144, pp. 1--15.\newline
ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu}
\thanks{\copyright 2016 Texas State University.}
\vspace{8mm}}

\begin{document}
\title[\hfilneg EJDE-2016/144\hfil Systems of Monge-Amp\'ere equations]
{Nontrivial convex solutions for systems of Monge-Amp\'ere
equations via global bifurcation}

\author[Z. Qi \hfil EJDE-2016/144\hfilneg]
{Zexin Qi}

\address{Zexin Qi \newline
School of Mathematics and Information Sciences,
Henan Normal University, Xinxiang 453007, China}
\email{qizedong@126.com}

\thanks{Submitted December 21, 2015. Published June 14, 2016.}
\subjclass[2010]{35J47, 35J96, 35B32}
\keywords{Monge-Amp\'ere equations; elliptic system; global bifurcation}

\begin{abstract}
 We obtain existence results for some systems of Monge-Amp\'ere equations,
 using bifurcation theorems of Krasnosell'ski-Rabinowitz type.
\end{abstract}

\maketitle
\numberwithin{equation}{section}
\newtheorem{theorem}{Theorem}[section]
\newtheorem{lemma}[theorem]{Lemma}
\newtheorem{remark}[theorem]{Remark}
\allowdisplaybreaks

\section{Introduction}

We study the system of coupled Monge-Amp\'ere equations,
\begin{equation}\label{1.1}
\begin{gathered}
 \det D^2u=f(u,v), \quad x\in \Omega, \\
 \det D^2v=g(u,v), \quad x\in \Omega, \\
 u=v=0, \quad x\in\partial \Omega,
\end{gathered}
\end{equation}
where $\Omega$ is a bounded, smooth and strictly convex domain in
 $\mathbb{R}^n$, and $\det D^2u$ stands for the determinant of
Hessian matrix of $u$. We will restrict system \eqref{1.1} to be
elliptic and search for nontrivial convex solutions, thus we suppose
the functions $f$ and $g$ to be nonnegative.

Monge-Amp\'ere equations have received considerable attention in the previous decades,
because of their important applications in geometry and other
scientific fields. However, systems coupled by Monge-Amp\'ere equations
have only been considered in recent years, see for example \cite{m1,w1,z1}.
Wang \cite{w1} studied the system
\begin{equation}\label{1.2}
 \begin{gathered}
 \det D^2u_1={f(-u_2)}, \quad \text{in } B,\\
 \det D^2u_2={g(-u_1)}, \quad \text{in } B, \\
 u_1=u_2=0, \quad \text{on } \partial B,
 \end{gathered}
\end{equation}
with $B:=\{x\in\mathbb{R}^n: |x|<1\}$. Under suitable assumptions on
$f$ and $g$, the author found nontrivial radial convex solutions for
 \eqref{1.2}, using ODE techniques together with fixed point theorems in a cone.
More precisely, he obtained

\begin{theorem}[{\cite[Theorem 1.1]{w1}}] \label{thmA}
Suppose $f,g:[0,\infty)\to [0,\infty)$ are continuous.
\begin{itemize}
\item[(a)] If $f_0=g_0=0$ and $f_{\infty}=g_{\infty}=\infty$, then
\eqref{1.2} has at least one nontrivial radial convex solution.

\item[(b)] If $f_0=g_0=\infty$ and $f_{\infty}=g_{\infty}=0$, then
\eqref{1.2} has at least one nontrivial radial convex solution.
 \end{itemize}
where
\[
f_0:=\lim _{x\to0^{+}}\frac{f(x)}{x^n},   \quad
f_{\infty}:=\lim _{x\to\infty}\frac{f(x)}{x^n}.
\]
\end{theorem}

The above theorem implies the existence of a radial convex solution for the
system
\begin{equation}\label{1.3}
\begin{gathered}
 \det D^2u_1={(-u_2)}^\alpha, \quad \text{in } B, \\
 \det D^2u_2={(-u_1)}^\beta, \quad \text{in } B \\
 u_1<0,\quad u_2<0,\quad \text{in } B,\\
 u_1=u_2=0, \quad \text{on }\partial B
 \end{gathered}
\end{equation}
if one of the following two conditions holds:
(1) $\alpha > n, \beta > n $,
(2) $\alpha < n, \beta < n $.

Theorem \ref{thmA} was improved later in \cite{z1} by a decoupling method.
For example, for system \eqref{1.3}, the authors in \cite{z1} proved that
it has a radial convex solution if and only if $\alpha>0, \beta>0$
and $\alpha\beta\neq n^2$. Moreover, as $\alpha\beta= n^2$, for the
eigenvalue problem
\begin{equation}\label{1.4}
\begin{gathered}
 \det D^2u_1=\lambda{(-u_2)}^\alpha, \quad \text{in } \Omega, \\
 \det D^2u_2=\mu{(-u_1)}^\beta, \quad \text{in } \Omega, \\
 u_1<0, u_2<0, \quad \text{in } \Omega,\\
 u_1=u_2=0, \quad \text{on } \partial \Omega,
\end{gathered}
\end{equation}
with positive parameters $\lambda$ and $\mu$.
They used a nonlinear version of Krein-Rutman theorem developed in \cite{j1}
to obtain the following result.

\begin{theorem}[{\cite[Theorem 1.4]{z1}}]  \label{thmB}
Suppose $\Omega\subset\mathbb{R}^n$ is a bounded, smooth and strictly
convex domain. If $\alpha>0, \beta>0$ and $\alpha\beta=n^2$, then system
\eqref{1.4} admits a convex solution if and only if
$\lambda\mu^\frac{\alpha}{n}=C$, where $C$ is a positive constant depending
on $n$, $\alpha$ and $\Omega$.
\end{theorem}

The motivation of this article come from a corollary of Theorem \ref{thmB}
(see Lemma \ref{lem2.1} below), as well as the work in  \cite{j1}, where Jacobsen
investigated global bifurcation problems for a class of fully nonlinear
elliptic equations, including the Monge-Amp\'ere equation.
As byproducts, Jacobsen obtaied some interesting existence results.
We will show that, under suitable assumptions on the functions $f$ and $g$,
 one can generalize part of the work in \cite{j1} to get new existence
results for problem \eqref{1.1}, see Theorem \ref{thm3.8} and \ref{thm4.6} below.

This article is organized as follows.
In Section 2, we give some preliminaries.
In Section 3 and 4, we study two bifurcation problems,
where we obtain the main results in this paper.

\section{Preliminaries}

Unless otherwise stated $\Omega$ is supposed to be a bounded, smooth
and strictly convex domain in $\mathbb{R}^n$.
Let us recall the Monge-Amp\'ere operator
$\mathcal{M}: C^2(\Omega)\to C(\Omega)$, $\mathcal{M}[u]=\det D^2u$.
Since it is $n$-homogeneous, the eigenvalue problem for a single
 Monge-Amp\'ere equation with Dirichlet boundary condition is described as
\begin{gather*}
 \det D^2u =| \lambda u|^n, \quad x \in\Omega, \\
 u =0, \quad x \in\partial \Omega.
 \end{gather*}
It is known that there exists a unique positive $\lambda=\lambda_0(\Omega)$
such that the above problem admits nonzero convex solutions.
In the literature, $\lambda_0(\Omega)$ is called the first eigenvalue,
or the principal eigenvalue, of the Monge-Amp\'ere operator corresponding
to $\Omega$, see references \cite{j1,l1,t2}.
As for systems, we have the following lemma.

\begin{lemma}[{\cite[Corollary 1.5]{z1}}]  \label{lem2.1}
 The eigenvalue problem
\begin{equation}\label{eigenvalue problem}
\begin{gathered}
 \det D^2u={|\lambda v|}^n, \quad x\in \Omega, \\
 \det D^2v={|\lambda u|}^n, \quad x\in\Omega, \\
 u = v = 0, \quad x\in\partial \Omega
 \end{gathered}
\end{equation}
admits nonzero convex solutions if and only if $|\lambda|=\lambda_0(\Omega)$.
\end{lemma}

Thanks to Lemma \ref{lem2.1}, we are able to study global bifurcation problems
for some systems of Monge-Amp\'ere equations. Before we do this in the next
sections, let us make some preparations first. We begin with some notations
and terminologies that will be used later.

As in reference \cite{j1}, we will use the following terminologies.
Let $Z$ be a real Banach space with a cone $P\subset Z$. The cone $P$
induces a partial order via $u\preceq v \Leftrightarrow v-u \in P$.
Let $A_0: Z \to Z$.
\begin{itemize}
 \item $A_0$ is called homogeneous if it is positively homogeneous with degree 1.
 \item $A_0$ is monotone if it satisfies $x\preceq y\Rightarrow
A_0(x)\preceq A_0(y)$.
 \end{itemize}

Now we recall a result due to Trudinger. 
As a special case of Trudinger \cite[Theorem 1.1]{t1},
in the second paragraph on p. 1253, we have

\begin{lemma} \label{lem2.2}
Let $\Omega$ be a strictly convex bounded domain in
$\mathbb{R}^n$, $\psi \in C(\overline\Omega)$ with $\psi\geq 0$,
$\phi \in C(\overline{\Omega})$. Then there exists a unique
admissible weak solution $u \in C^{1}(\Omega)\cap C(\overline\Omega)$ of the
equation
 \begin{gather*}
\det D^2u = \psi, \quad   x \in\Omega, \\
 u = \phi, \quad x \in \partial \Omega.
 \end{gather*}
\end{lemma}

\begin{remark} \label{rmk2.3} \rm
The definition of admissible weak solution coincides with the Aleksandrov
 sense weak solution (please see \cite[page 1252-1253]{t1}),
thus the admissible weak solutions occurred in the rest of the paper
 are also Aleksandrov solutions. For the notion of Aleksandrov solution,
see \cite[Definition 1.1.1, Theorem 1.1.13 and Definition 1.2.1]{g1}.
\end{remark}

By Lemma \ref{lem2.2}, we can define a solution operator as follows.
 Denote $C(\overline{\Omega})$ to be the usual Banach space of continuous
functions with sup-norm. Define a cone
$$
K_0:=\{u\in C(\overline{\Omega}):u(x)\leq 0,\forall x \in \Omega\},
$$
 and an operator
$$
T:C(\overline{\Omega})\to C(\overline{\Omega}), \quad   T(f)=u,
$$
where
$u$ is the unique admissible weak solution of
 \begin{equation}\label{definition of solution operator}
\begin{gathered}
 \det D^2u =|f(x)|, \quad x \in\Omega, \\
 u = 0, \quad  x \in\partial \Omega.
 \end{gathered}
 \end{equation}
Note the Monge-Amp\'ere operator is $n$-hessian (see \cite{c1}),
so the solution operator defined by \eqref{definition of solution operator}
 coincides with $T_{n}$, where $T_k(k=1,2,\cdots,n)$ are solution
operators for $k$-hessian equations defined in Section 3.1 in \cite{j1}.
By \cite[Proposition 3.2]{j1}, $T: C(\overline{\Omega}) \to C(\overline{\Omega})$
is completely continuous.

Let us define another operator. Take the Banach space
$E:=C(\overline{\Omega})\times C(\overline{\Omega})$,
 with norm $\|(u,v)\|:=\|u\|_{\infty}+\|v\|_{\infty}$. Define a cone
$$
K=\{(u,v)\in E:u(x)\leq 0,\;v(x)\leq 0,\;\forall x \in \Omega\}.
$$
We remark that we don't distinguish the writing of norms in $E$ and
$C(\overline{\Omega})$, and both are denoted by $\|\cdot\|$ in the paper.
Define
$$
A:E\to E,\;   A(u,v)=(w,z),
$$
where $(w,z)$ is the unique admissible weak solution pair of
\begin{equation}\label{solution operator A}
\begin{gathered}
 \det D^2w={|v|}^n, \quad x\in \Omega, \\
 \det D^2z={|u|}^n, \quad x\in\Omega, \\
 w = z = 0, \quad  x\in\partial \Omega.
 \end{gathered}
\end{equation}
By the completely continuity of $T$ it is easy to see $A$ is also
completely continuous from $E$ to $E$. Now $E$ is a real Banach space,
and the cone $K$ induced a partial order on $E$ via
$(u_1,v_1)\preceq (u_2,v_2)\Leftrightarrow(u_2-u_1,v_2-v_1)\in K$.
It is readily checked that $A$ is homogeneous; by
\cite[Lemma 1.4.6]{g1}, the comparison principle, we see $T$ is monotone,
so is $A$, i.e.,
$(u_1,v_1)\preceq (u_2,v_2)\Rightarrow A(u_1,v_1)\preceq A(u_2,v_2)$.

Properties of the operators $T$ and $A$ can be summarized as follows.

 \begin{lemma} \label{lem2.4}
 $T: C(\overline{\Omega})\to C(\overline{\Omega})$ is a completely continuous,
monotone operator. $A: E\to E$ is a completely continuous, monotone operator;
 moreover, it is homogeneous.
\end{lemma}

In this article, we take $b_0$ a fixed number such that
$b_0>\lambda_0$. We have the following crucial result essentially given
 by Jacobsen\cite{j1}, and give a proof for completeness.

\begin{lemma}\label{lem2.5}
For Leray-Schauder degree, we have
\begin{equation}\label{critical degree}
 \deg(\operatorname{id}-b_0A(\cdot,\cdot),B_{r}(0,0),0)=0,  \quad  \forall r>0.
\end{equation}
\end{lemma}

\begin{proof}
First we note, by Lemma \ref{lem2.1}, that the degree in \eqref{critical degree}
is well defined for any $r>0$, and it is independent with the value of $r$.

We argue by contradiction. Let $(u_0,v_0)$ be a nonzero solution
pair of \eqref{eigenvalue problem} corresponding to $\lambda_0$,
then we have
\begin{equation}\label{15}
 \lambda_0A(u_0,v_0)=(u_0,v_0).
\end{equation}
Fix $\overline{r}>0$. By the continuity of Leray-Schauder degree, we
can choose $\epsilon>0$ small, such that
$$
\deg(\operatorname{id}-b_0A(\cdot,\cdot),B_{\overline{r}}(0,0),0)
=\deg(\operatorname{id}-b_0A((\cdot,\cdot)+\epsilon(u_0,v_0)),B_{\overline{r}}(0,0),0).
$$
When \eqref{critical degree} not true, we obtain
\[
\deg(\operatorname{id}-b_0A((\cdot,\cdot)+\epsilon(u_0,v_0)),
B_{\overline{r}}(0,0),0)\neq0,
\]
which implies the existence of $(\overline{u},\overline{v})\in B_{\overline{r}}(0,0)$
such that
\begin{equation}\label{17}
 (\overline{u},\overline{v})=b_0A((\overline{u},\overline{v})
+\epsilon(u_0,v_0)).
\end{equation}
Recall the partial order induced by $K$ in $E$, we have
$(\overline{u},\overline{v})\preceq(\overline{u},\overline{v})+\epsilon(u_0,v_0)$.
Since $A$ is monotone, we obtain
\begin{equation}\label{18}
 A(\overline{u},\overline{v})\preceq A((\overline{u},\overline{v})
+\epsilon(u_0,v_0)).
\end{equation}
Equations \eqref{17} and \eqref{18} give us
\begin{equation}\label{19}
 A(\overline{u},\overline{v})\preceq\frac{(\overline{u},\overline{v})}{b_0}.
\end{equation}
On the other hand, from
$\epsilon(u_0,v_0)\preceq(\overline{u},\overline{v})+\epsilon(u_0,v_0)$,
we have
$$
A(\epsilon(u_0,v_0))\preceq A((\overline{u},\overline{v})+\epsilon(u_0,v_0));
$$
using \eqref{17} again, we reach
\begin{equation}\label{21}
b_0 A(\epsilon(u_0,v_0))\preceq (\overline{u},\overline{v}).
\end{equation}
By \eqref{15}, \eqref{21} and the homogeneity of $A$,
\begin{equation}\label{first operation}
 \frac{b_0 \epsilon (u_0,v_0)}{\lambda_0}\preceq (\overline{u},\overline{v}).
\end{equation}
Now operate $A$ on both sides of \eqref{first operation}, we have
\begin{equation}\label{22}
\frac{b_0 \epsilon A(u_0,v_0)}{\lambda_0}\preceq A(\overline{u},\overline{v}).
\end{equation}
Combining \eqref{22} with \eqref{15} and \eqref{19}, we deduce
\begin{equation}\label{second operation}
 \frac{b_0^2 \epsilon (u_0,v_0)}{\lambda_0^2}\preceq (\overline{u},\overline{v}).
\end{equation}
Noticing \eqref{first operation} and \eqref{second operation},
one can prove by induction that
\[
\frac{b_0^n \epsilon (u_0,v_0)}{\lambda_0^n}\preceq(\overline{u},\overline{v}),
\quad\forall n\in \mathbb{N}.
\]
So
\[
(u_0,v_0)\preceq \Big(\frac{\lambda_0}{b_0}\Big)^n\cdot\frac{(\overline{u},
\overline{v})}{\epsilon},\quad \forall n\in \mathbb{N}.
\]
Letting $n\to\infty$, from $b_0>\lambda_0>0$ we obtain $(u_0,v_0)\preceq (0,0)$.
Thus $-(u_0,v_0)\in K$, giving $(u_0,v_0)\in K\cap(-K)= \{(0,0)\}$,
a contradiction with $(u_0,v_0)\neq (0,0)$. This finishes the proof of the lemma.
\end{proof}

\section{Global bifurcation}

Our basic assumption on $f$ and $g$ is
\begin{itemize}
 \item[(A1)] $f,g:\mathbb{R}\times\mathbb{R}\to\mathbb{R}_{+}:=[0,+\infty)$
are continuous.
\end{itemize}
We seek nontrivial solutions to \eqref{1.1}. The approach used is motivated
by \cite{j1}. More precisely, we embed \eqref{1.1} into the one-parameter
family of problems
\begin{equation}\label{bifurcation problem}
\begin{gathered}
 \det D^2u={|\lambda v|}^n+f(u,v), \quad x\in \Omega, \\
 \det D^2v={|\lambda u|}^n+g(u,v), \quad x\in\Omega, \\
 u = v = 0, \quad  x\in\partial \Omega,
 \end{gathered}
\end{equation}
and consider the behavior of global bifurcation or global asymptotic
 bifurcation continuum. By continuum we shall mean a closed connected set.

We associated to \eqref{bifurcation problem} the solution operator
$H:\mathbb{R}\times E\to E, H(\lambda,(u,v))=(w,z)$,
where $(w,z)$ is the unique solution pair of
\begin{equation}\label{solution operator H}
\begin{gathered}
 \det D^2w={|\lambda v|}^n+f(u,v), \quad x\in \Omega, \\
 \det D^2z={|\lambda u|}^n+g(u,v), \quad  x\in\Omega, \\
 w = z = 0, \quad   x\in\partial \Omega.
 \end{gathered}
 \end{equation}
Using the operator $T$ defined in Section 2, we can write $H=(H_1,H_2)$, where
$H_1(\lambda,(u,v))=T({|\lambda v|}^n+f(u,v))$,
$H_2(\lambda,(u,v))=T({|\lambda u|}^n+g(u,v))$.
By assumption (A1) and the completely continuity of $T$ (see Lemma \ref{lem2.4}),
it is easy to check $H_1$ and $H_2$ are both completely continuous.
 So $H$ is completely continuous.
Define $h:\mathbb{R}\times E\to E, h(\lambda ,(u,v))=(u,v)-H(\lambda ,(u,v))$
and consider the equation
\begin{equation}\label{bifurcation equation}
 h(\lambda ,(u,v))=0.
\end{equation}
We see that $\lambda$, $u$ and $v$ satisfy \eqref{bifurcation problem}
if and only if $(\lambda,(u,v))$ is a solution of \eqref{bifurcation equation}.

Note that \eqref{bifurcation problem} can be seen as a perturbation of
the eigenvalue problem \eqref{eigenvalue problem}.
For our purpose in this section, the perturbation terms also need to satisfy:
\begin{itemize}
 \item[(A2)] $f(s,t)=o({(|s|+|t|)}^n), g(s,t)=o({(|s|+|t|)}^n)$, as
$|s|+|t|\to0$;
 \item[(A3)] either $\frac{f(s,t)}{{(|s|+|t|)}^n}\to\infty$ or
$\frac{g(s,t)}{{(|s|+|t|)}^n}\to\infty$, as $|s|+|t|\to\infty$.
\end{itemize}

Under  assumptions of (A1) and (A2), one has $f(0,0)=g(0,0)=0$,
thus \eqref{bifurcation equation} admits trivial solution branch
$\mathbb{R}\times (0,0)$. In order to obtain a nontrivial branch
of solutions to \eqref{bifurcation equation}, we need the following bifurcation
theorem of Krasnosell'ski-Rabinowitz type.

\begin{theorem}[global bifurcation, \cite{s1}] \label{thm3.1}
Let $Y$ be a Banach space, let $F:\mathbb{R}\times Y\to Y$ be completely continuous,
such that $F(\lambda,0)=0$, for all $\lambda\in\mathbb{R}$. Suppose there exist
constants $a,b\in\mathbb{R}$, with $a<b$, such that $(a,0),(b,0)$ are not
bifurcation points for the equation
\[
y-F(\lambda,y)=0.
\]
Furthermore, assume for Leray-Schauder degree that
\[
\deg(\operatorname{id}-F(a,\cdot),B_{r}(0),0)\neq \deg(\operatorname{id}-F(b,\cdot),B_{r}(0),0),
\]
where $B_{r}(0)=\{y\in E: \|y\|< r\}$ is an isolating neighborhood
of the trivial solution for both constants $a$ and $b$. Let
\[
 \mathcal{S}=\overline{\{(\lambda,y):y-F(\lambda,y)=0,y\neq0\}}\cup([a,b]\times\{0\}),
\]
and let $\mathcal{C}$ be the component of $\mathcal{S}$ containing
$[a,b]\times\{0\}$. Then either
\begin{enumerate}
 \item $\mathcal{C}$ is unbounded in $\mathbb{R}\times Y$, or
 \item $\mathcal{C}\cap [(\mathbb{R}\backslash[a,b])\times\{0\}]\neq\emptyset$.
\end{enumerate}
\end{theorem}

We shall apply Theorem \ref{thm3.1} to the Banach space $E$ and the operator
$H$ after we collect some lemmas.

\begin{lemma} \label{lem3.2}
Assuming {\rm (A1)} and {\rm (A2)}, a necessary condition
for $(\mu,(0,0))$ to be a bifurcation point of \eqref{bifurcation equation}
 is that $|\mu|=\lambda_0$.
\end{lemma}

\begin{proof}
 Suppose $(\mu,(0,0))$ is a bifurcation point for \eqref{bifurcation equation}.
Then there exists a sequence $(\lambda_k,(u_k,v_k))\to(\mu,(0,0))$
such that $\|u_k\|+\|v_k\|\neq0$ for all $k$, and
$h(\lambda_k,(u_k,v_k))=0$, i.e.,
\begin{equation}\label{8}
\begin{gathered}
 \det D^2u_k={|\lambda_k v_k|}^n+f(u_k,v_k), \quad x\in \Omega, \\
 \det D^2v_k={|\lambda_k u_k|}^n+g(u_k,v_k), \quad  x\in\Omega, \\
 u_k = v_k = 0, \quad  x\in\partial \Omega.
 \end{gathered}
\end{equation}
Divide each equation in \eqref{8} by $(\|u_k\|+\|v_k\|)^n$, and denote
\begin{gather*}
\widetilde{u}_k=\frac{u_k}{\|u_k\|+\|v_k\|}, \quad
\widetilde{v}_k= \frac{v_k}{\|u_k\|+\|v_k\|},\\
\widetilde{f}_k=\frac{f(u_k,v_k)}{(\|u_k\|+\|v_k\|)^n}, \quad
\widetilde{g}_k=\frac{g(u_k,v_k)}{(\|u_k\|+\|v_k\|)^n},
\end{gather*}
we obtain
\begin{equation}\label{9}
\begin{gathered}
 \det D^2\widetilde{u}_k=|\lambda_k\widetilde{v}_k|^n+\widetilde{f}_k,
\quad x\in \Omega, \\
 \det D^2\widetilde{v}_k=|\lambda_k\widetilde{u}_k|^n+\widetilde{g}_k,
\quad x\in \Omega, \\
 \widetilde{u}_k = \widetilde{v}_k = 0, \quad  x\in\partial \Omega.
 \end{gathered}
\end{equation}
This system can be rewritten as
\begin{equation}\label{10}
\begin{gathered}
 \widetilde{u}_k=T(|\lambda_k\widetilde{v}_k|^n+\widetilde{f}_k), \\
 \widetilde{v}_k=T(|\lambda_k\widetilde{u}_k|^n+\widetilde{g}_k).
 \end{gathered}
\end{equation}
Note $\|u_k\|+\|v_k\|\neq0$, and $u_k$, $v_k$ are both convex functions
with zero boundary data, we have $|u_k(x)|+|v_k(x)|\neq0$ for any
$x\in\Omega$. Thus, for $x\in\Omega$,
\[
 0\leq\widetilde{f}_k=\frac{f(u_k,v_k)}{(|u_k|+|v_k|)^n}\cdot
\Big(\frac{|u_k|+|v_k|}{\|u_k\|+\|v_k\|}\Big)^n
\leq\frac{f(u_k,v_k)}{(|u_k|+|v_k|)^n}.
\]
Noticing $(u_k,v_k)\to(0,0)$ in $C(\overline{\Omega})\times C(\overline{\Omega})$,
we deduce from the above inequalities and (A2) that
$\widetilde{f}_k(x)\to0$, uniformly for $x\in\Omega$, as $k\to\infty$.
Combining this with the facts $ \|\widetilde{v}_k\|\leq1$ and
$\lambda_k\to\mu$, we see
$\{|\lambda_k\widetilde{v}_k|^n+\widetilde{f}_k\}$ is bounded in
$C(\overline{\Omega})$. Hence, by \eqref{10} and the compactness of $T$,
 we obtain a sub-sequence of $\{\widetilde{u}_k\}$, still denoted
$\{\widetilde{u}_k\}$, such that $\widetilde{u}_k\to u_{\ast}$ for some
$u_{\ast}\in C(\overline{\Omega})$. Similarly, one can prove
$\widetilde{g}_k(x)\to0$, uniformly for $x\in\Omega$, as $k\to\infty$,
and there exists a sub-sequence of $\{\widetilde{v}_k\}$,
still denoted $\{\widetilde{v}_k\}$, such that
$ \widetilde{v}_k\to v_{\ast}$ for some $v_{\ast}\in C(\overline{\Omega})$.
By the continuity of $T$, we infer from \eqref{10}
\begin{equation}\label{11}
\begin{gathered}
 u_{\ast}=T(|\mu v_{\ast}|^n), \\
 v_{\ast}=T(|\mu u_{\ast}|^n).
 \end{gathered}
\end{equation}
We claim $(u_{\ast},v_{\ast})\neq(0,0)$. Indeed,
\[
\|u_{\ast}\|=\lim_{k\to\infty}\frac{\|u_k\|}{\|u_k\|+\|v_k\|}, \quad
\|v_{\ast}\|=\lim_{k\to\infty}\frac{\|v_k\|}{\|u_k\|+\|v_k\|},
\]
which yield
\[
 \|u_{\ast}\|+\|v_{\ast}\|=\lim_{k\to\infty}\frac{\|u_k\|+\|v_k\|}{\|u_k\|+\|v_k\|}=1.
\]
Now, by \eqref{11} and Lemma \ref{lem2.1}, we reach the conclusion $|\mu|=\lambda_0$.
\end{proof}

\begin{lemma} \label{lem3.3}
 Assume {\rm (A1)} and {\rm (A2)} hold, then there exists $r>0$,
sufficiently small, such that
\begin{itemize}
\item[(1)] $\deg(\operatorname{id}-H(0,(\cdot,\cdot)),B_{r}(0,0),0)=1$,
\item[(2)]  $\deg(\operatorname{id}-H(b_0,(\cdot,\cdot)),B_{r}(0,0),0)=0$.
\end{itemize}
\end{lemma}

\begin{proof}
 First of all, by Lemma \ref{lem3.2}, $(0,(0,0))$ and $(b_0,(0,0))$ are not bifurcation
points for \eqref{bifurcation equation}, so one can take $r>0$ sufficiently
small, such that the degrees in assertions (1) and (2) are well defined.

Let $\tilde{b}\in \{0,b_0\}$. Define a homotopic mapping 
$F_{\tilde{b}}:[0,1]\times E\to E, F_{\tilde{b}}(t,(u,v))=(w,z)$,
 where $(w,z)$ is the unique solution pair of
\begin{gather*}
 \det D^2w={|\tilde{b}v|}^n+tf(u,v), \quad x\in\Omega,\\
 \det D^2z={|\tilde{b}u|}^n+tg(u,v), \quad x\in\Omega, \\
 w = z = 0, \quad   x\in\partial \Omega.
 \end{gather*}
By the complete continuity of $T$, 
$F_{\tilde{b}}:[0,1]\times E\to E$ is completely continuous.
 We claim when $r>0$ is sufficiently small,
$\deg(\operatorname{id}-F_{\tilde{b}}(t,(\cdot,\cdot)),B_{r}(0,0),0)$
is well defined for all $t\in[0,1]$. If this were not true, then there exist
$\{t_m\}\subset[0,1]$ with $t_m\to t_0\in[0,1]$, and
$\{(u_m,v_m)\}\subset E$ with $\|(u_m,v_m)\|=r_m>0$, $r_m\to0$,
such that $(u_m,v_m)=F_{\tilde{b}}(t_m,(u_m,v_m))$, i.e.,
 \begin{gather*}
\det D^2u_m={|\tilde{b}v_m|}^n+t_mf(u_m,v_m), \quad x\in\Omega, \\
\det D^2v_m={|\tilde{b}u_m|}^n+t_mg(u_m,v_m), \quad x\in\Omega,\\
 u_m = v_m = 0, \quad x\in\partial \Omega.
 \end{gather*}
By mimicking the rest proof after \eqref{8} in Lemma \ref{lem3.2}, one
reaches again $|\tilde{b}|=\lambda_0$, a contradiction with
 $\tilde{b}\in \{0,b_0\}$. So for $r>0$ sufficiently small we have
\[
 (u,v)\neq F_{\tilde{b}}(t,(u,v)),\quad
 \forall(u,v)\in \partial B_{r}(0,0),\;\forall t\in [0,1].
\]
This implies $F_{\tilde{b}}$ is a degree-preserving homotopic mapping.
We distinguish the following two cases.
\smallskip

\noindent\textbf{Case $\tilde{b}=0$.}
 For $r>0$ small, we have
 \begin{align*}
 \deg(\operatorname{id}-F_0(1,(\cdot,\cdot)),B_{r}(0,0),0)
&=\deg(\operatorname{id}-F_0(0,(\cdot,\cdot)),B_{r}(0,0),0)\\
&=\deg(\operatorname{id},B_{r}(0,0),0)=1.
\end{align*}
Since $F_0(1,(\cdot,\cdot))=H(0,(\cdot,\cdot))$, assertion (1) is valid.
\smallskip

\noindent\textbf{Case $\tilde{b}=b_0$.}
 For $r>0$ small, we have
\begin{equation}
\begin{aligned}
 \deg(\operatorname{id}-H(b_0,(\cdot,\cdot)),B_{r}(0,0),0)
&=\deg(\operatorname{id}-F_{b_0}(1,(\cdot,\cdot)),B_{r}(0,0),0)\\
 &=\deg(\operatorname{id}-F_{b_0}(0,(\cdot,\cdot)),B_{r}(0,0),0)\\
 &=\deg(\operatorname{id}-A(b_0(\cdot,\cdot)),B_{r}(0,0),0)\\
 &=\deg(\operatorname{id}-b_0A(\cdot,\cdot),B_{r}(0,0),0).
\end{aligned} \label{13}
\end{equation}
By Lemma \ref{lem2.5} and \eqref{13}, we see assertion (2) is also valid.
\end{proof}

Now let us recall a known blow-up result. Since the Monge-Amp\'ere operator
is $n$-hessian, we have a special case of Jacobsen \cite[Lemma 5.1]{j1}.

\begin{lemma} \label{lem3.4}
 Let $\{v_m\}\subset C(\overline{\Omega})$ be a collection of admissible
 weak solutions to the Dirichlet problem
\begin{gather*}
 \det D^2v_m =g_m, \quad x \in\Omega, \\
 v_m = 0,\quad  x \in\partial \Omega,
 \end{gather*}
where $g_m:\Omega\to\mathbb{R}$ form a collection of nonnegative continuous
functions. If $g_m(x)\to\infty$, uniformly on some compact sub-domain
of $\Omega$, then $\|v_m\|\to\infty$.
\end{lemma}

Using this lemma, we can establish some priori bounds concerning solutions
of \eqref{bifurcation equation}.

\begin{lemma} \label{lem3.5}
Under  assumption {\rm (A1)}, there exists $M_1>0$, such that any solution
 $(\lambda,(u,v))$ of \eqref{bifurcation equation} with
$(u,v)\neq (0,0)$ must satisfy $|\lambda|\leq M_1$.
\end{lemma}

\begin{proof}
We argue by contradiction. If the conclusion of Lemma \ref{lem3.5} is false,
then there exists $\{(\lambda_k,(u_k,v_k))\}$, solving
\eqref{bifurcation equation} for each $k$, such that
$\|u_k\|+\|v_k\|>0$, and $|\lambda_k|\to\infty$ as $k\to\infty$.
Let
\[
\widetilde{u}_k:=\frac{u_k}{\|u_k\|+\|v_k\|},  \quad
\widetilde{v}_k:= \frac{v_k}{\|u_k\|+\|v_k\|},
\]
and let $\Omega'$ be a compact sub-domain of $\Omega$.
Since $\|\widetilde{u}_k\|+\|\widetilde{v}_k\|=1$, we may assume,
without loss of generality, that there exists a $\gamma>0$ such that
\begin{equation}\label{positive lower bound of vk}
 \|\widetilde{v}_k\|\geq\gamma.
\end{equation}
Moreover, by \cite[Lemma 5.10]{j1}, there exists $\eta>0$ such that
\begin{equation}\label{another lower bound}
 |\widetilde{v}_k(x)|\geq\eta\|\widetilde{v}_k\|,  \quad \forall x \in\Omega'.
\end{equation}
As $(\lambda_k,(u_k,v_k))$ solves \eqref{bifurcation equation}, we have
\begin{gather*}
\det D^2u_k={|\lambda_k v_k|}^n+f(u_k,v_k),\quad x\in\Omega,\\
 u_k= 0,\quad  x\in\partial \Omega.
 \end{gather*}
Dividing the above equation by $(\|u_k\|+\|v_k\|)^n$, we obtain
\begin{equation}\label{divided equation}
\begin{gathered}
 \det D^2\widetilde{u}_k=\psi_k, \quad x\in \Omega, \\
 \widetilde{u}_k = 0, \quad  x\in\partial \Omega,
 \end{gathered}
\end{equation}
where
\begin{equation}\label{definition of psi}
 \psi_k:={|\lambda_k \widetilde{v}_k|}^n
+\frac{f(u_k,v_k)}{(\|u_k\|+\|v_k\|)^n}.
\end{equation}
Equations \eqref{definition of psi}, \eqref{positive lower bound of vk}
and \eqref{another lower bound} yield that, for $x\in\Omega'$,
\begin{equation}\label{blow up of psi}
 \psi_k(x)\geq{|\lambda_k \widetilde{v}_k|}^n
\geq{|\lambda_k\eta\gamma|}^n\to\infty,     k\to\infty.
\end{equation}
By Lemma \ref{lem3.4}, we deduce from \eqref{divided equation} and \eqref{blow up of psi} that
$\|\widetilde{u}_k\|\to\infty$ as $k\to\infty$, a
contradiction with $\|\widetilde{u}_k\|\leq 1$.
\end{proof}

\begin{lemma}\label{lem3.6}
Under  assumptions {\rm (A1)} and {\rm (A3)}, there exists $M_2>0$, such
that a solution $(\lambda,(u,v))$ of \eqref{bifurcation equation} must
satisfy $\|u\|+\|v\|\leq M_2$.
\end{lemma}


\begin{proof}
Without loss of generality, we assume the first alternative of (A3) holds, i.e.,
\begin{equation}\label{first alternative of A3}
 \frac{f(s,t)}{{(|s|+|t|)}^n}\to\infty, \quad\text{as } |s|+|t|\to\infty.
\end{equation}
We argue by contradiction. If the conclusion of Lemma \ref{lem3.6} is false,
then there exists
$\{(\lambda_k,(u_k,v_k))\}$, solving \eqref{bifurcation equation}
for each $k$, such that $\|u_k\|+\|v_k\|>0$, $\|u_k\|+\|v_k\|\to\infty$ as
$k\to\infty$. Now we have
\begin{gather*}
\det D^2u_k={|\lambda_k v_k|}^n+f(u_k,v_k),\quad x\in\Omega,\\
 u_k= 0,\quad x\in\partial \Omega.
 \end{gather*}
Divide the above equation by $(\|u_k\|+\|v_k\|)^n$, and denote
\[
\varphi_k(x):=\frac{{|\lambda_k v_k(x)|}^n+f(u_k(x),v_k(x))}{(\|u_k\|+\|v_k\|)^n},
\]
we reach
\begin{equation}\label{5}
 \begin{gathered}
 \det D^2\Big(\frac{u_k}{\|u_k\|+\|v_k\|}\Big)=\varphi_k,
\quad x \in \Omega, \\
 \frac{u_k}{\|u_k\|+\|v_k\|} = 0, \quad x \in\partial \Omega.
 \end{gathered}
\end{equation}
Note that
\begin{equation}\label{6}
 \varphi_k(x)\geq \frac{f(u_k,v_k)}{(|u_k|+|v_k|)^n}
\Big(\frac{|u_k|+|v_k|}{\|u_k\|+\|v_k\|}\Big)^n,  \forall x \in \Omega.
\end{equation}
Let $\Omega'$ be a compact sub-domain of $\Omega$.
By \cite[Lemma 5.10]{j1}, there exists $\delta>0$, such that
$|u_k(x)|\geq\delta\|u_k\|$ and $|v_k(x)|\geq\delta\|v_k\|$ for any
$x \in\Omega'$. Thus
$|u_k(x)|+|v_k(x)|\geq\delta(\|u_k\|+\|v_k\|)$ for any $x \in\Omega'$.
Since $\|u_k\|+\|v_k\|\to\infty$, we see it holds uniformly for
 $x \in\Omega'$ that $|u_k(x)|+|v_k(x)|\to\infty$.
Using these facts and \eqref{first alternative of A3}, we deduce
from \eqref{6} that for $x \in\Omega'$, it holds uniformly
 \begin{equation}\label{7}
 \varphi_k(x)\to\infty ,   \quad\text{as } k\to\infty.
 \end{equation}
By \eqref{5} and \eqref{7}, we infer from Lemma \ref{lem3.4} that
\[
\frac{\|u_k\|}{\|u_k\|+\|v_k\|}\to\infty ,\quad \text{as } k\to\infty,
\]
which contradicts
\[
\frac{\|u_k\|}{\|u_k\|+\|v_k\|}\leq1,  \quad  \forall k\in\mathbb{N}.
\]
\end{proof}


We are in a position to give the main results in this section.
Recall that, by continuum we mean a closed connected set.

\begin{theorem} \label{thm3.7}
 Under assumptions  {\rm (A1)--(A3)}, there exists a bounded continuum
of solutions to \eqref{bifurcation equation} bifurcating from
$(\lambda_0,(0,0))$ in $\mathbb{R}\times E$. This continuum connects
$(\lambda_0,(0,0))$ to $(-\lambda_0,(0,0))$. It is nontrivial in the sense
that it intersects the trivial solution branch of
\eqref{bifurcation equation} only at $(\pm\lambda_0,(0,0))$.
\end{theorem}

\begin{proof}
 Let us apply Theorem \ref{thm3.1} to the Banach space $E$ and the operator $H$.
By Lemmas \ref{lem3.2} and \ref{lem3.3}, we infer from Theorem \ref{thm3.1} that there exists a
nontrivial branch of solutions to \eqref{bifurcation equation},
say $\overline{\mathcal{C}}$, bifurcating from $(\lambda_0,(0,0))$, and
it holds $([0,b_0]\times(0,0))\cap\overline{\mathcal{C}}=(\lambda_0,(0,0))$.
Furthermore, either
\begin{enumerate}
 \item $\overline{\mathcal{C}}$ is unbounded in $\mathbb{R}\times E$, or
 \item $\overline{\mathcal{C}}\cap [(\mathbb{R}\backslash[0,b_0])\times(0,0)]\neq\emptyset$.
\end{enumerate}
By Lemmas \ref{lem3.5} and \ref{lem3.6}, $\overline{\mathcal{C}}$ must be bounded
in $\mathbb{R}\times E$, so $\overline{\mathcal{C}}$ must connect
to another bifurcation point. By Lemma \ref{lem3.2}, $\overline{\mathcal{C}}$
connects $(\lambda_0,(0,0))$ to $(-\lambda_0,(0,0))$, and it cannot
intersect the trivial solution branch of \eqref{bifurcation equation}
at points other than $(\pm\lambda_0,(0,0))$.
\end{proof}

\begin{theorem} \label{thm3.8}
 Assume the functions $f$ and $g$ satisfy {\rm (A1)--(A3)}, then
\eqref{bifurcation problem} admits at least a nontrivial convex
solution for all $\lambda\in (-\lambda_0,\lambda_0)$. In particular,
\eqref{1.1} admits at least a nontrivial convex solution.
\end{theorem}

\begin{proof}
 By Theorem \ref{thm3.7}, there exists a bounded continuum of solutions to
\eqref{bifurcation equation} that is nontrivial, and it connects
$(-\lambda_0,(0,0))$ to $(\lambda_0,(0,0))$ in $\mathbb{R}\times E$.
Since it is connected, for arbitrarily fixed
$\widehat{\lambda}\in (-\lambda_0,\lambda_0)$, the continuum must
cross $\lambda=\widehat{\lambda}$ at a point, say $(\widehat{\lambda},(u,v))$.
By Lemma \ref{lem3.2}, $\widehat{\lambda}$ is not a bifurcation value,
thus $(u,v)\neq(0,0)$, and it is a nontrivial convex solution
for \eqref{bifurcation problem} with $\lambda=\widehat{\lambda}$.
\end{proof}

\section{Global asymptotic bifurcation}

Besides (A1), we also need the following assumptions on $f$ and $g$:
\begin{itemize}
 \item[(A4)] either $\frac{f(s,t)}{{(|s|+|t|)}^n}\to\infty$,
or $\frac{g(s,t)}{{(|s|+|t|)}^n}\to\infty$, as $|s|+|t|\to0$;
 \item[(A5)] $\frac{f(s,t)}{{(|s|+|t|)}^n}\to0$, and
$\frac{g(s,t)}{{(|s|+|t|)}^n}\to0$, as $|s|+|t|\to\infty$.
\end{itemize}
In this section, we  study global asymptotic bifurcation problems
for \eqref{bifurcation equation}.
Our analysis is based on the theorem below.

\begin{theorem}[Global asymptotic bifurcation, \cite{s1}] \label{thm4.1}
Let $Y$ be a Banach space, let $F:\mathbb{R}\times Y\to Y$ be completely
continuous. Suppose there exist constants $a,b\in \mathbb{R}$, with $a<b$,
such that solutions of
\begin{equation}\label{23}
 y-F(\lambda,y)=0
\end{equation}
 are a priori bounded in $Y$ for $\lambda =a$ and $\lambda =b$; i.e.,
 there exists a constant $M>0$ such that
\[
F(a,y)\neq y \neq F(b,y),
\]
for all $y\in Y$ with $\|y\|\geq M$. Furthermore, assume that
\[
 \deg(\operatorname{id}-F(a,\cdot),B_{R}(0),0)
\neq \deg(\operatorname{id}-F(b,\cdot),B_{R}(0),0),
\]
for $R>M$. Then there exists at least one continuum $\mathcal{C}$ of
solutions to \emph{\eqref{23}} that is unbounded in $[a,b]\times Y$ and either
\begin{enumerate}
 \item $\mathcal{C}$ in unbounded in the $\lambda$ direction, or else,
 \item there exists an interval $[c,d]$ such that $(a,b)\cap (c,d)=\emptyset$,
and $\mathcal{C}$ bifurcates from infinity in $[c,d]\times Y$.
\end{enumerate}
\end{theorem}

In Theorem \ref{thm4.1}, to say $\mathcal{C}$ bifurcates from infinity in
$[c,d]\times Y$, we mean there exist $\nu\in[c,d]$ and a sequence
$\{(\lambda_k,y_k)\}\subseteq\mathcal{C}$, such that $\lambda_k\to\nu$
and $\|y_k\|_{Y}\to\infty$ as $ k\to\infty$. We shall apply Theorem \ref{thm4.1}
to the Banach space $E$ and the operator $H$ after we collect some lemmas.

\begin{lemma} \label{lem4.2}
 Under  assumptions {\rm (A1)} and {\rm (A5)}, a necessary condition
for $\mu$ to be an asymptotic bifurcation value of \eqref{bifurcation equation}
is $|\mu|=\lambda_0$.
\end{lemma}

\begin{proof}
 Suppose $\mu$ is an asymptotic bifurcation value for \eqref{bifurcation equation},
i.e., there exists a sequence $\{(\lambda_k,(u_k,v_k))\}$ such that
$\|u_k\|+\|v_k\|\to\infty, \lambda_k\to\mu$ as $ k\to\infty$, and it
satisfies $h(\lambda_k,(u_k,v_k))=0, \forall k\in\mathbb{N}$. Thus we have
\begin{equation}\label{24}
\begin{gathered}
 \det D^2u_k={|\lambda_k v_k|}^n+f(u_k,v_k), \quad x\in \Omega, \\
 \det D^2v_k={|\lambda_k u_k|}^n+g(u_k,v_k), \quad x\in\Omega, \\
 u_k = v_k = 0, \quad  x\in\partial \Omega.
 \end{gathered}
\end{equation}
Divide \eqref{24} by $(\|u_k\|+\|v_k\|)^n$, and denote
\begin{gather*}
\overline{u}_k=\frac{u_k}{\|u_k\|+\|v_k\|},   \quad
\overline{v}_k= \frac{v_k}{\|u_k\|+\|v_k\|}, \\
\overline{f}_k=\frac{f(u_k,v_k)}{(\|u_k\|+\|v_k\|)^n}, \quad
\overline{g}_k=\frac{g(u_k,v_k)}{(\|u_k\|+\|v_k\|)^n},
\end{gather*}
we obtain
\begin{equation}\label{25}
 \begin{gathered}
 \det D^2\overline{u}_k=|\lambda_k\overline{v}_k|^n+\overline{f}_k,
\quad x\in \Omega,  \\
 \det D^2\overline{v}_k=|\lambda_k\overline{u}_k|^n+\overline{g}_k,
\quad x\in \Omega, \\
 \overline{u}_k = \overline{v}_k = 0, \quad x\in\partial \Omega.
 \end{gathered}
\end{equation}
This system can be rewritten as
\begin{equation}\label{26}
\begin{gathered}
 \overline{u}_k=T(|\lambda_k\overline{v}_k|^n+\overline{f}_k), \\
 \overline{v}_k=T(|\lambda_k\overline{u}_k|^n+\overline{g}_k).
 \end{gathered}
\end{equation}

We claim that $\overline{f}_k(x)\to0$, uniformly for $x\in\Omega$,
as $k\to\infty$. Indeed, by (A5), for each $\epsilon>0$, there exists $M_0>0$,
such that if $|(s,t)|:=|s|+|t|>M_0$, then
\begin{equation}\label{1002}
 \frac{f(s,t)}{(|s|+|t|)^n}<\epsilon.
\end{equation}
For this $M_0>0$, denote $f_0:=\max_{|(s,t)|\leq M_0}f(s,t)$,
then for large $k$,
\begin{equation}\label{1003}
 \frac{f_0}{(\|u_k\|+\|v_k\|)^n}<\epsilon.
\end{equation}
By \eqref{1002}, \eqref{1003} and (A1), we deduce that for $k$ sufficiently large,
$$
0\leq\overline{f}_k(x)<\epsilon, \quad  \forall x\in\Omega.
$$
So our claim holds.

Similarly, $\overline{g}_k(x)\to0$, uniformly for $x\in\Omega$,
as $k\to\infty$. By mimicking the counterpart in the proof of Lemma \ref{lem3.2},
one is ready to reach $|\mu|=\lambda_0$. We omit the details.
\end{proof}

Recall $b_0$ is a fixed number such that $b_0>\lambda_0$.

\begin{lemma} \label{lem4.3}
 Assume {\rm (A1)} and {\rm (A5)}. Then there exists $M>0$, such that for $R>M$,
\begin{itemize}
\item[(1)]  $\deg(\operatorname{id}-H(0,(\cdot,\cdot)),B_{R}(0,0),0)=1$;
\item[(2)]  $\deg(\operatorname{id}-H(b_0,(\cdot,\cdot)),B_{R}(0,0),0)=0$.
\end{itemize}
\end{lemma}

\begin{proof}
 By Lemma \ref{lem4.2}, there exists $M>0$ such that for all $(u,v)\in E$ with
$\|(u,v)\|\geq M$,
$$
H(0,(u,v))\neq (u,v) \neq H(b_0,(u,v)).
$$
So when $R>M$, the degrees in the assertions are well defined and independent
of $R$.

Let $\tilde{b}\in \{0,b_0\}$. Define a homotopic mapping
$F_{\tilde{b}}:[0,1]\times E\to E$, be defined by
$F_{\tilde{b}}(t,(u,v))=(w,z)$,
 where $(w,z)$ is the unique solution pair of
\begin{gather*}
 \det D^2w={|\tilde{b}v|}^n+tf(u,v), \quad x\in\Omega, \\
 \det D^2z={|\tilde{b}u|}^n+tg(u,v), \quad x\in\Omega, \\
 w = z = 0, \quad  x\in\partial \Omega.
 \end{gather*}
By the complete continuity of $T$, one verifies
$F_{\tilde{b}}:[0,1]\times E\to E$ is completely continuous. We point
 out that when $R>M$ is sufficient large, the function
$\deg(\operatorname{id}-F_{\tilde{b}}(t,(\cdot,\cdot)),B_{R}(0,0),0)$
is well defined for all $t\in[0,1]$. If this were not true, then
 there exist
 $\{t_m\}\subset[0,1]$ with $t_m\to t_0\in[0,1]$, and
$\{(u_m,v_m)\}\subset E$ with $\|(u_m,v_m)\|=R_m\to+\infty$, such that
$(u_m,v_m)=F_{\tilde{b}}(t_m,(u_m,v_m))$, i.e.,
\begin{gather*}
 \det D^2u_m={|\tilde{b}v_m|}^n+t_mf(u_m,v_m), \quad x\in\Omega, \\
 \det D^2v_m={|\tilde{b}u_m|}^n+t_mg(u_m,v_m), \quad x\in\Omega, \\
 u_m = v_m = 0, \quad   x\in\partial \Omega.
 \end{gather*}
Divide the above system by $(\|u_m\|+\|v_m\|)^n$, and then follow the
arguments used in the proof of Lemma \ref{lem4.2}, one reaches again
$|\tilde{b}|=\lambda_0$, a contradiction with $\tilde{b}\in \{0,b_0\}$.
So when $R>M$ is sufficiently large,
\[
 (u,v)\neq F_{\tilde{b}}(t,(u,v)),\quad \forall(u,v)\in \partial
B_{R}(0,0),\quad \forall t\in [0,1].
\]
This implies $F_{\tilde{b}}$ is a degree-preserving homotopic mapping.
We distinguish the following two cases.
\smallskip

\noindent\textbf{Case $\tilde{b}=0$.}
 For $R>M$ large, we have
 \begin{align*}
 \deg(\operatorname{id}-F_0(1,(\cdot,\cdot)),B_{R}(0,0),0)
&=\deg(\operatorname{id}-F_0(0,(\cdot,\cdot)),B_{R}(0,0),0)\\
&=\deg(\operatorname{id},B_{R}(0,0),0)
 =1.
\end{align*}
Since $F_0(1,(\cdot,\cdot))=H(0,(\cdot,\cdot))$, assertion (1) is valid.
\smallskip

\noindent\textbf{Case $\tilde{b}=b_0$.}
 For $R>M$ large, we have
\begin{align*}
 \deg(\operatorname{id}-H(b_0,(\cdot,\cdot)),B_{R}(0,0),0)
 &=\deg(\operatorname{id}-F_{b_0}(1,(\cdot,\cdot)),B_{R}(0,0),0)\\
 &=\deg(\operatorname{id}-F_{b_0}(0,(\cdot,\cdot)),B_{R}(0,0),0)\\
 &=\deg(\operatorname{id}-A(b_0(\cdot,\cdot)),B_{R}(0,0),0)\\
 &=\deg(\operatorname{id}-b_0A(\cdot,\cdot),B_{R}(0,0),0).
\end{align*}
By this equality and  Lemma \ref{lem2.5}, we see assertion (2) is also valid.
\end{proof}

\begin{lemma} \label{lem4.4}
 Assume {\rm (A1)} and {\rm (A4)}. Then there exists $\varepsilon>0$,
such that any solution $(\lambda,(u,v))$ of \eqref{bifurcation equation}
 with $(u,v)\neq(0,0)$ must satisfy $\|(u,v)\|\geq\varepsilon$.
\end{lemma}

\begin{proof}
 Without loss of generality, we assume the first alternative of (A4) holds,
i.e.,
\begin{equation}\label{first alternative of A4}
 \frac{f(s,t)}{{(|s|+|t|)}^n}\to\infty,\quad\text{as } |s|+|t|\to 0.
\end{equation}
 We argue by contradiction. If the conclusion of Lemma \ref{lem4.4} is false,
then there exists
$\{(\lambda_k,(u_k,v_k))\}$, solving \eqref{bifurcation equation}
for each $k$, such that $(u_k,v_k)\neq(0,0)$, $(u_k,v_k)\to(0,0)$ as
$k \to \infty$. Now we have
 \begin{gather*}
 \det D^2u_k={|\lambda_k v_k|}^n+f(u_k,v_k),\quad x\in\Omega,\\
 u_k= 0,\quad  x\in\partial \Omega.
 \end{gather*}
Divide the above equation by $(\|u_k\|+\|v_k\|)^n$, and denote
\begin{gather*}
\zeta_k(x):=\frac{{|\lambda_k v_k(x)|}^n+f(u_k(x),v_k(x))}{(\|u_k\|+\|v_k\|)^n},
\end{gather*}
we reach
\begin{equation}\label{31}
 \begin{gathered}
 \det D^2\Big(\frac{u_k}{\|u_k\|+\|v_k\|}\Big)=\zeta_k,\quad x \in \Omega, \\
 \frac{u_k}{\|u_k\|+\|v_k\|} = 0,\quad x \in\partial \Omega.
 \end{gathered}
\end{equation}
Note that
\begin{equation}\label{32}
 \zeta_k(x)\geq \frac{f(u_k,v_k)}{(|u_k|+|v_k|)^n}
\Big(\frac{|u_k|+|v_k|}{\|u_k\|+\|v_k\|}\Big)^n,  \forall x \in \Omega.
\end{equation}
Let $\Omega'$ be a compact sub-domain of $\Omega$.
By \cite[Lemma 5.10]{j1}, there exists $\widetilde{\delta}>0$, such that
$|u_k(x)|\geq\widetilde{\delta}\|u_k\|$ and
$|v_k(x)|\geq\widetilde{\delta}\|v_k\|$, for any $x \in\Omega'$.
Thus
\begin{equation}\label{1005}
 |u_k(x)|+|v_k(x)|\geq\widetilde{\delta}(\|u_k\|+\|v_k\|),\quad
\forall x \in\Omega'.
\end{equation}
Note $(u_k,v_k)\to(0,0)$ in $E$, so for $x \in\Omega'$, it holds uniformly
\begin{equation}\label{1006}
 |u_k(x)|+|v_k(x)|\to 0,\quad k\to\infty.
\end{equation}
By \eqref{first alternative of A4}, \eqref{1005} and \eqref{1006},
it is easy to deduce from \eqref{32} that for $x \in\Omega'$,
it holds uniformly
 \begin{equation}\label{33}
 \zeta_k(x)\to\infty ,\quad k\to\infty.
 \end{equation}
By \eqref{31} and \eqref{33}, we infer from Lemma \ref{lem3.4} that
\[
 \frac{\|u_k\|}{\|u_k\|+\|v_k\|}\to\infty ,\quad k\to\infty,
\]
which contradicts
$\frac{\|u_k\|}{\|u_k\|+\|v_k\|}\leq1$ for all $k\in \mathbb{N}$.
\end{proof}

Now we can give the main results of this section.

\begin{theorem} \label{thm4.5}
Assume {\rm (A1), (A4)} and {\rm (A5)}. Then there exists an unbounded
continuum of nontrivial solutions to \eqref{bifurcation equation}
 in $\mathbb{R}\times E$. The continuum bifurcates from infinity at
 $\mu=\pm\lambda_0$, and it is bounded in the $\lambda$ direction.
\end{theorem}

\begin{proof}
Let us apply Theorem \ref{thm4.1} to the Banach space $E$ and the operator $H$.
By Lemma \ref{lem4.2}, there exists $M>0$ such that for $(u,v)\in E$ with
 $\|(u,v)\|\geq M$, it holds
$H(0,(u,v))\neq (u,v) \neq H(b_0,(u,v))$.
By Lemma \ref{lem4.3}, we can choose $M>0$ large, so that
\[
 \deg(\operatorname{id}-H(0,\cdot),B_{R}(0),0)\neq
\deg(\operatorname{id}-H(b_0,\cdot),B_{R}(0),0)
\]
for $R>M$.
We infer from Theorem \ref{thm4.1} that there exists a continuum of solutions
to \eqref{bifurcation equation}, say $\widetilde{\mathcal{C}}$,
that is unbounded in $[0,b_0]\times E$, which forces $\lambda_0$
to be an asymptotic bifurcation value by Lemma \ref{lem4.2}. Furthermore, either
\begin{enumerate}
 \item $\widetilde{\mathcal{C}}$ is unbounded in the $\lambda$ direction, or
 \item there exist an interval $[c,d]$ such that $(0,b_0)\cap (c,d)=\emptyset$,
and $\widetilde{\mathcal{C}}$ bifurcates from infinity in $[c,d]\times E$.
\end{enumerate}
By Lemma \ref{lem3.5}, $\widetilde{\mathcal{C}}$ is bounded in the $\lambda$ direction,
so it must bifurcate from infinity at $-\lambda_0$ by
Lemma \ref{lem4.2}. Since $\widetilde{\mathcal{C}}$ is connected and unbounded,
we infer from Lemma \ref{lem4.4} that
\begin{equation}\label{last}
 (u,v)\neq(0,0),  \quad \forall (\lambda,(u,v))\in\widetilde{\mathcal{C}}.
\end{equation}
\end{proof}

\begin{theorem} \label{thm4.6}
 Assume {\rm (A1), (A4)} and {\rm (A5)}. Then
\eqref{bifurcation problem} has a nontrivial convex solution for all
$\lambda\in (-\lambda_0,\lambda_0)$. In particular, \eqref{1.1} admits
a nontrivial convex solution.
\end{theorem}

\begin{proof}
 Note that the continuum $\widetilde{\mathcal{C}}$ obtained in the proof of
Theorem \ref{thm4.5} bifurcates from infinity at $\mu=\pm\lambda_0$.
So by connectedness and \eqref{last}, we see \eqref{bifurcation problem}
has a nontrivial convex solution for all $\lambda\in (-\lambda_0,\lambda_0)$.
\end{proof}

\begin{remark}\label{rmk4.8} \rm
We say that a solution $(u,v)$ of \eqref{bifurcation problem} is a vector
solution if $u\neq0$ and $v\neq0$. When $0<|\lambda|<\lambda_0$,
the solutions for \eqref{bifurcation problem} obtained in
 Theorem \ref{thm3.8} and \ref{thm4.6} are vector solutions, which can be inferred from
system \eqref{bifurcation problem} itself and the assumption (A1).
Similarly, if $f$ and $g$ are such that
$$
f(s,t)>0, \quad g(s,t)>0, \quad \forall (s,t)\neq(0,0),
$$
then solutions for \eqref{1.1} obtained in Theorem \ref{thm3.8} and
 Theorem \ref{thm4.6}
are also vector solutions.
\end{remark}

To illustrate our results for problem \eqref{1.1},
We present the following example:
Let $\Omega$ be a bounded, smooth, and strictly convex domain in $\mathbb{R}^n$.
If $0<p_1,p_2<n$ or $p_1,p_2>n$, then the system
\begin{gather*}
 \det D^2u_1=\lambda (-u_1-u_2)^{p_1}, \quad x\in \Omega, \\
 \det D^2u_2=\lambda (-u_1-u_2)^{p_2}, \quad x\in \Omega, \\
 u_1=u_2=0, \quad x\in\partial \Omega
 \end{gather*}
admits at least a nontrivial convex solution for any $\lambda>0$.

\subsection*{Acknowledgements}
 This work was supported by Doctoral Starting up Foundation of Henan
 Normal university (Grant No. 5101019170149).

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\end{document}
