\documentclass[reqno]{amsart}
\usepackage{hyperref}
\usepackage[compress]{cite}

\AtBeginDocument{{\noindent\small
\emph{Electronic Journal of Differential Equations},
Vol. 2015 (2015), No. 131, pp. 1--12.\newline
ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu
\newline ftp ejde.math.txstate.edu}
\thanks{\copyright 2015 Texas State University - San Marcos.}
\vspace{9mm}}

\begin{document}
\title[\hfilneg EJDE-2015/131\hfil Triple positive solutions]
{Triple positive solutions for $m$-point boundary-value problems of
dynamic equations  on time scales with $p$-Laplacian}

\author[A. Dogan \hfil EJDE-2015/131\hfilneg]
{Abdulkadir Dogan}

\address{Abdulkadir Dogan \newline
Department of Applied Mathematics,
Faculty of Computer Sciences, Abdullah Gul University,
Kayseri 38039, Turkey \newline
 Phone +90 352 224 88 00,  Fax +90 352 338 88 28}
\email{abdulkadir.dogan@agu.edu.tr}

\thanks{Submitted March 18, 2015. Published May 10, 2015.}
\subjclass[2010]{34B15, 34B16, 34B18, 39A10}
\keywords{Time scales; boundary value problem; $p$-Laplacian;
\hfill\break\indent positive solutions; five functionals fixed-point theorem}

\begin{abstract}
 In this article we study the existence of positive solutions for
 $m$-point dynamic equation on time scales with $p$-Laplacian.
 We prove that the boundary-value problem has at least three positive solutions
 by applying the five functionals fixed-point theorem.
 An example demonstrates the main results.
\end{abstract}

\maketitle
\numberwithin{equation}{section}
\newtheorem{theorem}{Theorem}[section]
\newtheorem{lemma}[theorem]{Lemma}
\newtheorem{definition}[theorem]{Definition}
\allowdisplaybreaks

\section{Introduction}

In recent years, dynamic equations on time scales have found a considerable
interest and attracted many researchers; see for example
\cite{RPAgarwal,Agarwal, APeterson, Avery, AGraef, AKong,Dogan,
ADogan,Liang,Peterson,Zhang}.
The reasons seem to be two-fold. Theoretically, dynamic equations on time
scales can not only unify differential and difference equations \cite{Hilger},
 but also have displayed much more complicated dynamics \cite{Bohner,Peter, Laks}.
Moreover, the study of time scales has led to several important applications
in the study of insect population models, neural networks, stock market,
 heat transfer, wound healing and epidemic models; see for example
 \cite{Jones,Sped,Thomas}.

In this paper, we study the existence of  positive solutions of $m$-point
 $p$-Laplacian equation on time scales
\begin{equation}
(\phi_p( u^\Delta(t)))^\nabla+g(t)f(u(t))=0,\quad  t\in[0,T]_{\mathbb{T} }, \label{e1.1}
\end{equation}
with the boundary conditions
\begin{equation}
u(0)=\sum_{i=1}^{m-2}a_i u(\xi_i), \quad  u^\Delta(T)=0,\label{e1.2}
\end{equation}
or
\begin{equation}
u^\Delta(0)=0,     \quad u(0)=\sum_{i=1}^{m-2}b_i u(\xi_i), \label{e1.3}
\end{equation}
where $\phi_p(s)$ is $p$-Laplacian operator; i.e.,
$\phi_p(s)=| s | ^{p-2} s$  for $p>1$, with
$(\phi_p)^{-1}=\phi_q \text{and} \frac{1}{p}+ \frac{1}{q}=1 $
 and $\xi_i \in (0,T)_{\mathbb{T}}  $ with
$  0<\xi_1<\xi_2<\dots<\xi_{m-2}< T$  and $a_i,b_i \in [0,\infty)$ satisfy
$1-\sum_{i=1}^{m-2}a_i \neq 0  $  and
 $ 1- \sum_{i=1}^{m-2}b_i  \neq 0 $   $ (i=1,2,\dots,m-2)$.
Some basic knowledge and definitions about time scales, which can be found
in \cite{Bohner,Peter}, will be used here. By using the five functionals
fixed-point theorem, we prove that the boundary-value problems
\eqref{e1.1} \eqref{e1.2}
and \eqref{e1.1} \eqref{e1.3} has  at least three positive solutions.

Throughout this paper, we assume that the following conditions are satisfied:
\begin{itemize}
\item[(H1)]  $f:\mathbb{R}\to  \mathbb{R}^{+}  $   is continuous, and
does not vanish identically on any closed subinterval of $[0,T]_{\mathbb{T}};$

\item[(H2)] $g:\mathbb{T} \to\mathbb{R}^{+} $  is left dense continuous ($ g \in C_{ld}(\mathbb{T},\mathbb{R}^{+})), $ and does not
 vanish identically on any closed
subinterval of   $[0,T]_{\mathbb{T}}$.

\end{itemize}

Recently, the boundary-value problems with $p$-Laplacian in the continuous
case have been studied extensively in the literature; see for example
\cite{ Bai,Feng,RLiang, Lu, YWang,WangGe,Zhao}.
However, to the best of our knowledge, there are not many results concerning
 $p$-Laplacian  dynamic equations on time scales, see \cite{ Avery,Su, DBWang}.

Zhao et al \cite{Zhao} studied the  existence of at least three positive
solutions to the following $p$-Laplacian  problem,
\begin{gather*}
(\phi_p(u'(t)))'+a(t)f(u,u')=0, \quad t\in[0,1], \\
 u'(0)=u(1)=0.
\end{gather*}
 To show their main results, they applied Leggett-Williams fixed-point theorem.

Anderson et al \cite{Avery} considered the following BVP on time scales:
\begin{gather*}
 [\phi_p(u^\Delta(t))]^\nabla   +c(t)f(u(t))=0,\quad  t\in (a,b)_{\mathbb{T}}, \\
 u(a)-B_0(u^{\Delta}(\upsilon))=0,  \quad  u^\Delta(b)=0,
\end{gather*}
where $\upsilon \in (a,b)_{\mathbb{T}}$,
$f\in C_{ld}([0,+\infty),[0,+\infty))$, $c\in C_{ld}([a,b],[0,+\infty))$,
and $K_m x \leq B_0 (x) \leq K_M x$ for some positive constants
$K_m, K_M$. By using a fixed-point theorem, they established the existence
result for at least one positive solution.

Wang \cite{DBWang} studied  existence criteria of three positive solutions
to the following boundary-value problems for $p$-Laplacian dynamic equations
on time scales
\begin{gather*}
 [\phi_p(u^\Delta(t))]^\nabla +a(t)f(u(t))=0,\quad  t\in[0,T]_{\mathbb{T}}, \\
 u^{\Delta}(0)=0,  \quad  u(T)+B_1(u^{\Delta}(\eta))=0,  \quad \text{or } \\
u(0)-B_0(u^{\Delta}(\eta))=0,  \quad  u^\Delta(T)=0.
\end{gather*}
The main tool used in \cite{DBWang} is the Leggett-Williams fixed-point theorem.

 Motivated by the results mentioned above, we consider the existence of solutions
to  \eqref{e1.1} \eqref{e1.2} and \eqref{e1.1} \eqref{e1.3}. Our main results
will depend on an application of the five functionals fixed-point theorem.

\section{Preliminaries}

In this section, we provide some background materials from theory of cones
in Banach spaces, and we then state the five functionals fixed-point
theorem for a cone preserving operator.

\begin{definition} \label{def2.1} \rm
 Let $E$  be a real Banach space. A nonempty, closed, convex set $P \subset E$
is said to be a cone provided the following conditions are satisfied:
\begin{itemize}
\item[(i)] If $u \in P$ and $\lambda \geq 0$, then   $\lambda u\in P$;
\item[(ii)] If $u \in P$  and $-u\in P$, then  $u=0$.
\end{itemize}
Every cone $P \subset E$ induces an ordering in $E$ given by
$x\leq y$ if and only if $y-x \in P$.
\end{definition}

\begin{definition} \label{def2.2} \rm
Given a cone $P$  in a real Banach space $E$, a functional
$\psi: P\to \mathbb{R}$ is  said to be increasing on $P$, provided
$\psi(x) \leq \psi(y)$ for all  $x,y \in P$ with $x\leq y$.
\end{definition}

\begin{definition} \label{def2.3} \rm
 A map $\alpha$  is said to be a nonnegative continuous concave functional on a cone
$P$ of a real Banach space $E$ if $\alpha: \to [0,\infty)$ is continuous and
$$
\alpha(tx+(1-t)y)\geq t\alpha(x)+(1-t)\alpha(y)
$$
 for all $x,y\in P$ and $0 \leq t \leq 1$.
Similarly, we say the map $\beta$ is a nonnegative continuous convex
functional on a cone $P$ of a real
Banach space $E$ if $\beta: P \to [0,\infty)$ is continuous and
$$
\beta (tx+(1-t)y) \leq t\beta(x)+(1-t)\beta(y)
$$
for all $x,y \in P$ and  $0 \leq t \leq 1$.
\end{definition}

Let $\gamma, \beta,\theta $ be  nonnegative continuous convex functionals
on $P$, and $\alpha,\psi$  be nonnegative
continuous concave functionals on  $P$. Then for nonnegative real numbers
$h,a,b,d$ and $c$, we define the following convex sets,
\begin{gather*}
P (\gamma,c) =  \{u\in P : \gamma(u)<c \},\\
P(\gamma,\alpha,a,c)  =  \{u\in P : a \leq \alpha(u), \gamma(u) \leq c \},\\
Q(\gamma,\beta,d,c)  =  \{u\in P : \beta(u) \leq d, \gamma(u) \leq c \},\\
P(\gamma,\theta,\alpha,a,b,c)  =  \{u\in P : a \leq \alpha(u), \theta(u) \leq b, 
\gamma(u) \leq c \},\\
Q(\gamma,\beta,\psi,h,d,c) =  \{u\in P : h \leq \psi(u),\beta(u) \leq d, 
\gamma(u) \leq c \}.
\end{gather*}

The following five functionals fixed-point theorem  will play an   
important role in the proof of our main results.

\begin{theorem}[\cite{RAvery}] \label{thm2.1}
 Let $P$ be a cone in a real  Banach space $E$. Suppose there exist positive 
numbers $c$ and $M$, nonnegative continuous concave functionals $\alpha$ 
and $\psi$ on $P$, and  nonnegative  continuous convex functionals $\gamma,\beta$  
and $\theta$ on $P$  with
$$
\alpha(u)\leq \beta(u),  \quad \|u \| \leq M \gamma(u)
$$
for all $u\in \overline{P(\gamma, c)}$. Suppose  that
$F:\overline{P(\gamma, c)}\to \overline{P(\gamma, c)}$ is  
a completely continuous operator and that there exist nonnegative numbers
 $h,a,k,b$, with  $0<a<b$ such that:
\begin{itemize}
\item [(i)] $\{ u \in P( \gamma,\theta,\alpha,b,k,c): 
\alpha(u)>b \}\ne \emptyset$ and $\alpha(Fu)>b$ for  \\
 $u\in P( \gamma,\theta,\alpha,b,k,c)$;

\item[(ii)] $\{ u\in Q( \gamma,\beta,\psi,h,a,c): 
 \beta(u)<a \}\ne \emptyset $ and $\beta(Fu)<a$ for \\
$u\in Q( \gamma,\beta,\psi,h,a,c)$;

\item[(iii)] $\alpha(Fu)>b$ for  $ u\in P( \gamma,\alpha,b,c)$ with 
$ \theta(Fu) >k$;

\item[(iv)] $\beta(Fu)< a$ for 
$u\in Q( \gamma,\beta,a,c)$ with $\psi(Fu) < h$.
\end{itemize}

Then  $F$  has at least three  fixed points  
$u_1,u_2, u_3 \in \overline{P(\gamma, c)}$ such that
$\beta(u_1) < a$,    $b<\alpha(u_2)$ and  $ a <\beta(u_3)$,   with
  $\alpha(u_3)<b$.
\end{theorem}

\section{Existence of three positive solutions}

In this section, by using the five functionals fixed-point theorem, 
we will find the existence of at least three positive solutions 
\eqref{e1.1} \eqref{e1.2}  and \eqref{e1.1}  \eqref{e1.3}.

Let the Banach space 
$E=C_{ld}([0,T]_{\mathbb{T}},\mathbb{R})$ with norm  
$ \|u\|=\sup_{t\in [0,T]_{\mathbb{T}}} |u(t)|$, and define the cone, 
$P\subset E$, by
$$
P=\{ u\in E: u^{\Delta}(T)=0,   u \text{ is concave and nonnegative on }   
[0,T]_{\mathbb{T}}\}. 
$$
Suppose that there exists $l\in \mathbb{T}$ such that $\xi_{m-2} < l < T$ and  
$\int_l^T g(r)\nabla r >0$ hold, then we will  use the following lemma.

\begin{lemma} \label{lem3.1}
If $u \in P$, then
\begin{itemize}
\item[(i)] $u(t)\geq\frac{t}{T} \|u\|$  for $t\in [0,T]_{\mathbb{T}}$;
\item[(ii)] $s u(t) \geq t u(s)$  for $ t,s \in [0,T]_{\mathbb{T}}$, with $t \leq s$.
\end{itemize}
\end{lemma}

\begin{proof}
(i) Since $u^{\Delta \nabla}(t)\leq 0$, it follows that $u^{\Delta}(t)$   
is nonincreasing.
Thus, for  $ 0< t < T$,
\begin{gather*}
u(t)-u(0)=\int_0^t u^{\Delta}(s) \Delta s\geq t u^{\Delta}(t),\\
u(T)-u(t)=\int_t^T u^{\Delta}(s) \Delta s\leq (T-t) u^{\Delta}(t)
\end{gather*}
from which we have
$$
u(t)\geq \frac{t u(T)+(T-t)u(0)}{T} \geq \frac{t}{T} u(T)
= \frac{t}{T}\|u\|. 
$$

(ii) If $t=s$, then the conclusion of (ii) holds. If 
$t<s$  with $t,s\in [0,T]_{\mathbb{T}}$,
setting $x(t)= u(t)-\frac{t}{s}u(s)$, for $u\in P$, we have
$$
x^{\Delta\nabla}(t)=u^{\Delta\nabla}(t)\leq 0,  x(0)=u(0)\geq 0,  x(s)=0. 
$$
Therefore, the concavity of $x$ implies that 
$x(t)\geq 0,   t\in [0,s)_{\mathbb{T}}$; i.e.,
$s u(t) > t u(s)$, for $t < s$ with  $t,s \in [0,T]_{\mathbb{T}}$.
This completes the proof.
\end{proof}

We define the nonnegative, continuous concave  functionals 
$\alpha,\psi$ and nonnegative continuous convex  functionals
$\beta,\theta,\gamma$  on  the cone $P$ by
\begin{gather*}
\gamma (u)=\theta(u):=\max_{t\in[0,\xi_{m-2}]_{\mathbb{T}} } u(t)=u(\xi_{m-2}),\\
\alpha (u):=\min_{t\in[l,T]_{\mathbb{T}} } u(t)=u(l),\\
\beta (u):=\max_{t\in[0,l]_{\mathbb{T}} } u(t)=u(l),\\
 \psi (u):=\min_{t\in[\xi_{m-2},T]_{\mathbb{T}} } u(t)=u(\xi_{m-2}).
\end{gather*}
We see that, for all $u \in P$,
$$
\alpha(u)=u(l)=\beta (u).
$$
For notational convenience, we define
\begin{gather*}
 M  =  \Big(\frac { \sum_{i=1}^{m-2} a_i \xi_i} {1-\sum_{i=1}^{m-2} a_i} 
+\xi_{m-2} \Big)
 \phi_q\Big( \int_{0}^T g(r) \nabla r \Big), \\
m  =  \Big(\frac { \sum_{i=1}^{m-2} a_i \xi_i} {1-\sum_{i=1}^{m-2} a_i} +l \Big)
 \phi_q\Big( \int_{l}^T g(r) \nabla r \Big), \\
 \lambda_l  =  \Big(\frac { \sum_{i=1}^{m-2} a_i \xi_i} {1-\sum_{i=1}^{m-2} a_i} 
+l \Big) \phi_q\Big( \int_{0}^T g(r) \nabla r \Big).
 \end{gather*}
We note that $u(t)$ is a solution of \eqref{e1.1}  and \eqref{e1.2},
if and only if
\begin{align*}
u(t)&=\frac {\sum_{i=1}^{m-2} a_i
\Big( \int_0^{\xi_i} \phi_q \Big( \int_s^T g(r) f(u(r)) \nabla r \Big) 
\Delta s \Big)} {1-\sum_{i=1}^{m-2} a_i} \\
&\quad  +\int_0^t \phi_q\Big( \int_s^T g(r) f(u(r) )\nabla r \Big)\Delta s, \quad
  t \in [0,T]_{\mathbb{T}}.
\end{align*}

\begin{theorem} \label{thm3.1}
 Let $0< a < lb/T <(l \xi_{m-2} c)/T^2$, $Mb <mc$,
 and suppose that $f$ satisfies the following conditions:
\begin{itemize}
\item[(C1)] $ f(w) < \phi_p (\frac{c}{M})$,   for all  
$0\leq w \leq Tc/\xi_{m-2}$;
\item[(C2)] $ f(w) > \phi_p (\frac{b}{m})$,   for all  
$b \leq w \leq T^2 b/\xi_{m-2}^2$;
\item[(C3)] $ f(w) < \phi_p (\frac{a}{\lambda_l})$,   for all
 $0 \leq w \leq Ta/l$.
\end{itemize}

Then, there exist  at least three positive solutions  
$u_1,u_2,  u_3$   of \eqref{e1.1} and \eqref{e1.2} such that
$$
\max_{t \in [0,l]_{\mathbb{T}}} u_1 (t) < a, \quad
b < \min_{t \in [l,T]_{\mathbb{T}}} u_2 (t)  \quad\text{and}\quad
a < \max_{t \in [0,l]_{\mathbb{T}}} u_3 (t)  \quad  \text{with } 
   \min_{t \in [l,T]_{\mathbb{T}}} u_3 (t)< b. 
 $$
\end{theorem}

\begin{proof}
 Defining a completely continuous integral operator
$F: P\to E$ by \begin{equation}
\begin{aligned}
(Fu)(t)&=\frac {\sum_{i=1}^{m-2} a_i
\big( \int_0^{\xi_i} \phi_q \big( \int_s^T g(r) f(u(r)) \nabla r \big) 
 \Delta s \big)} {1-\sum_{i=1}^{m-2} a_i} \\
&\quad +\int_0^t \phi_q\Big( \int_s^T g(r) f(u(r) )\nabla r \Big)\Delta s, \quad
 u\in P,
\end{aligned} \label{e3.1}
\end{equation}
for  $t\in [0,T]_{\mathbb{T}}$, we will search for fixed points of $F$ in the 
cone $P$. We note that, if
 $u\in P$, then $(Fu)(t)\geq 0$ for $t\in [0,T]_{\mathbb{T}}$, and
$$
(Fu)^{\Delta}(t)=\phi_q\Big( \int_t^T g(r) f(u(r) )\nabla r \Big),\quad 
u\in P,\; t\in [0,T]_{\mathbb{T^\kappa}}.
$$
We see that $(Fu)^{\Delta}(t)$ is continuous and nonincreasing on 
$[0,T]_{\mathbb{T^\kappa}}$
and,   $(Fu)^{\Delta\nabla}(t)\leq 0$  for  
$[0,T]_{\mathbb{T^\kappa}\cap \mathbb{T_\kappa}}$. In addition,
$(Fu)^{\Delta}(T)=0$. This implies that $Fu\in P$, and therefore $F:P\to P$.

If $u \in \overline{ P(\gamma,c)}$, then
$$
\gamma (u)=\max_{t \in[0,\xi_{m-2}]_{\mathbb{T}} } u(t)=u(\xi_{m-2})=c.  
$$
Consequently,
$0 \leq u(t) \leq c$ for  $t \in [0,\xi_{m-2}]_{\mathbb{T}}$.
By Lemma \ref{lem3.1}, we have
$$
 \| u \| \leq \frac{ T u(\xi_{m-2})} {\xi_{m-2}} \leq \frac{Tc}{\xi_{m-2}}.  
$$
This implies  $0\leq u(t) \leq \frac{Tc}{\xi_{m-2}}$   for   
$t \in[0,T]_{\mathbb{T}}$.

It follows from (C1) of Theorem \ref{thm3.1} that
 \begin{align*}
 \gamma(F(u)) & =  (Fu)(\xi_{m-2})\\
 & = \frac {\sum_{i=1}^{m-2} a_i \left(
\int_0^{\xi_i} \phi_q \left ( \int_s^T g(r) f(u(r) )\nabla  r \right)\Delta s\right)}
{1-\sum_{i=1}^{m-2} a_i}\\
&\quad + \int_0^{\xi_{m-2}} \phi_q\Big( \int_s^T g(r) f(u(r)) \nabla r \Big)\Delta s\\
& <  \frac {\sum_{i=1}^{m-2} a_i \left(
\int_0^{\xi_i} \phi_q \left ( \int_s^T g(r) f(u(r) )\nabla  r \right)\Delta s\right)}{1-\sum_{i=1}^{m-2} a_i}\\
 & \quad + \xi_{m-2} \phi_q\Big( \int_0^T g(r) f(u(r)) \nabla r \Big)\\
& <  \frac {\sum_{i=1}^{m-2} a_i \left(
\int_0^{\xi_i} \phi_q \left ( \int_0^T g(r) f(u(r) )\nabla  r \right)\Delta s\right)}{1-\sum_{i=1}^{m-2} a_i}\\
 &\quad + \xi_{m-2} \phi_q\Big( \int_0^T g(r) f(u(r)) \nabla r \Big)\\
& <   \frac{c}{M}\Big( \frac{\sum_{i=1}^{m-2} a_i\xi_i}{1-\sum_{i=1}^{m-2} a_i}
+\xi_{m-2} \Big)
\phi_q\Big( \int_0^T g(r) \nabla r \Big)=c.
\end{align*}
So  $F(u) \in \overline{ P(\gamma,c)}$.

By Lemma \ref{lem3.1}, we obtain $\gamma(u) =u(\xi_{m-2}) \geq \frac{\xi_{m-2}}{T} \| u \| $, hence
$$ \| u \| \leq \frac{ T u(\xi_{m-2})} {\xi_{m-2}} = \frac{T \gamma(u)}{\xi_{m-2}}  \text{for all }   u \in P.$$

Now we prove that (i)-(iv) of Theorem \ref{thm2.1} are satisfied.
Firstly, if $u\equiv \frac{Tb}{\xi_{m-2}}$, $k= \frac{Tb}{\xi_{m-2}}$, then
$$
\alpha(u)=u(l)= \frac{Tb}{\xi_{m-2}}>b, \quad
\theta(u)= u(\xi_{m-2})= \frac{Tb}{\xi_{m-2}}=k, \quad
\gamma(u)= \frac{Tb}{\xi_{m-2}}<c,  
$$
which show that
$$
\{ u \in P( \gamma,\theta,\alpha,b,k,c): \alpha(u)>b \}\ne \emptyset.
$$
For  $u \in P( \gamma,\theta,\alpha,b,\frac{Tb}{\xi_{m-2}},c)$, we obtain
$$
\theta(u)=\max_{t\in[0,\xi_{m-2}]_{\mathbb{T}} } u(t)=u(\xi_{m-2})\leq
\frac{Tb}{\xi_{m-2}} , \quad  
\alpha (u)=\min_{t\in[l,T]_{\mathbb{T}} } u(t)=u(l)\geq b,
$$
which imply
$$
0 \leq u(t) \leq    \frac{Tb}{\xi_{m-2}} \quad  \text{for all } 
  t\in[0,\xi_{m-2}]_{\mathbb{T}},  
$$
and
$b \leq u(t)$    for all  $t\in[l,T]_{\mathbb{T}}$.
By Lemma \ref{lem3.1}, we obtain
$$ 
\| u \| \leq \frac{ T u(\xi_{m-2})} {\xi_{m-2}} 
\leq \frac{ T^2 b} {\xi^2_{m-2}},
$$
as a result,
$$b \leq u(t) \leq \frac{ T^2 b} {\xi^2_{m-2}}  \quad  \text{for all } 
 t\in[l,T]_{\mathbb{T}}.  
$$
By (C2) of Theorem \ref{thm3.1}, we find
\begin{align*}
\alpha(F(u)) & =  (Fu)(l)\\
 & = \frac {\sum_{i=1}^{m-2} a_i \left(
\int_0^{\xi_i} \phi_q \left ( \int_s^T g(r) f(u(r) )\nabla  r \right)\Delta s\right)}{1-\sum_{i=1}^{m-2} a_i}\\
 & \quad  + \int_0^{l} \phi_q\Big( \int_s^T g(r) f(u(r)) \nabla r \Big)\Delta s\\
& >  \frac {\sum_{i=1}^{m-2} a_i \left(
\int_0^{\xi_i} \phi_q \left ( \int_l^T g(r) f(u(r) )\nabla  r \right)\Delta s\right)}{1-\sum_{i=1}^{m-2} a_i}\\
 & \quad + l \phi_q\Big( \int_l^T g(r) f(u(r)) \nabla r \Big)\\
& >   \frac{b}{m}\Big( \frac{\sum_{i=1}^{m-2} a_i\xi_i}{1-\sum_{i=1}^{m-2} a_i}
+l \Big)
\phi_q\Big( \int_l^T g(r)  \nabla r \Big)=b.
 \end{align*}
Therefore, (i) of Theorem \ref{thm2.1} is satisfied.

Secondly, we show that (ii) of Theorem \ref{thm2.1} is satisfied. Let
$ u= \frac{a \xi_{m-2}}{T}$ and 
$ h= \frac{a \xi_{m-2}}{T}$, then
\begin{gather*}
\gamma (u)= u(\xi_{m-2})=\frac{a \xi_{m-2}}{T}< c, \quad
\beta (u)=u(l)=\frac{a \xi_{m-2}}{T}< a,  \\
 \psi (u)= u(\xi_{m-2})= \frac{a \xi_{m-2}}{T}=h.
\end{gather*}
Thus
$$
\{ u\in Q( \gamma,\beta,\psi,h,a,c): \beta(u)<a \}\ne \emptyset.
$$
If $ u\in Q( \gamma,\beta,\psi,\frac{a \xi_{m-2}}{T},a,c), $ then
$$\beta (u):=\max_{t\in[0,l]_{\mathbb{T}} } u(t)=u(l)\leq a,$$
as a result
$0 \leq  u(t) \leq a$ for $ t\in[0,l]_{\mathbb{T}}$.
By Lemma \ref{lem3.1},
$$ 
\| u \| \leq \frac{ T u(l)} {l} \leq \frac{ T a} {l} \quad \text{for }
 t\in[0,T]_{\mathbb{T}},    
$$
hence
$ 0 \leq  u(t) \leq  T a/l$ for  $ t\in[0,T]_{\mathbb{T}}$. 
By (C3) of Theorem \ref{thm3.1}, we obtain
\begin{align*}
\beta(F(u)) & =  (Fu)(l)\\
 & = \frac {\sum_{i=1}^{m-2} a_i \left(
\int_0^{\xi_i} \phi_q \Big( \int_s^T g(r) f(u(r) )\nabla  r \Big)\Delta s\right)}{1-\sum_{i=1}^{m-2} a_i}\\
 & \quad + \int_0^{l} \phi_q\left ( \int_s^T g(r) f(u(r)) \nabla r \right)\Delta s\\
& <  \frac {\sum_{i=1}^{m-2} a_i \xi_i
 \phi_q \left ( \int_0^T g(r) f(u(r) )\nabla  r \right)}{1-\sum_{i=1}^{m-2} a_i}\\
 & \quad + l \phi_q\Big( \int_0^T g(r) f(u(r)) \nabla r \Big)\\
& <   \frac{a}{\lambda_l}
\Big( \frac{\sum_{i=1}^{m-2} a_i\xi_i}{1-\sum_{i=1}^{m-2} a_i}+l \Big)
\phi_q\Big( \int_0^T g(r)  \nabla r \Big)=a.
\end{align*}

Thirdly, we verify that (ii) of Theorem \ref{thm2.1} is satisfied. If
$$
u\in P( \gamma,\alpha,b,c)  \quad \text{and} \quad
  \theta(F(u)) =F( u(\xi_{m-2}) )> k= \frac{Tb}{\xi_{m-2}}, 
$$
then
$$\alpha(F(u))=(Fu)( l) \geq \frac{l}{T}F(u(l)) \geq \frac{l}{T}F( u(\xi_{m-2})  ) > \frac{lb}{\xi_{m-2}}>b. $$

Lastly, if
$$
u\in Q( \gamma,\beta,a,c)  \quad \text{and} \quad
  \psi(F(u))= F( u(\xi_{m-2}) )  < h=
 \frac{a \xi_{m-2}}{T},  
$$
then by Lemma \ref{lem3.1} we find
$$
\beta(F(u))=(Fu)( l) \leq \frac{T}{l}F(u(l)) 
\leq \frac{T}{\xi_{m-2}}F( u(\xi_{m-2})  ) < a
$$
which shows that  condition (iv) of Theorem \ref{thm2.1} is satisfied.

Hence, all the conditions in Theorem \ref{thm2.1} are fulfilled, 
therefore the boundary-value problems \eqref{e1.1} and \eqref{e1.2} 
 has at least three positive solutions
 $u_1,u_2,  u_3$    such that
$$
\max_{t \in [0,l]_{\mathbb{T}}} u_1 (t) < a, \quad
 b < \min_{t \in [l,T]_{\mathbb{T}}} u_2 (t) , \quad
a < \max_{t \in [0,l]_{\mathbb{T}}} u_3 (t)  \quad  \text{with }  
 \min_{t \in [l,T]_{\mathbb{T}}} u_3 (t)< b.  
$$
The proof of Theorem \ref{thm3.1} is complete.
\end{proof}

Now, we apply the five functionals fixed-point theorem to establish
 the existence of at least three positive solutions of  \eqref{e1.1} 
and  \eqref{e1.3}.

We define the cone, $P_1\subset E$, by
$$
P_1=\{ u\in E: u^{\Delta}(0)=0,   u \text{ is concave and nonnegative on } 
  [0,T]_{\mathbb{T}}\}. 
$$
Suppose that there exists $l_1\in \mathbb{T}$ such that $0 < l_1<\xi_1 < T$ 
and  $\int_0^{l_1} g(r)\nabla r >0$ hold.

\begin{lemma} \label{lem3.2}
If $u \in P_1$, then
\begin{itemize}
\item[(i)] $u(t)\geq\frac{T-t}{T} \|u\|$    for  $t\in [0,T]_{\mathbb{T}}$;
\item[(ii)] $(T-s) u(t) \geq(T-t) u(s)$  for $ t,s \in [0,T]_{\mathbb{T}}$,
 with $s \leq t$.
\end{itemize}
\end{lemma}

\begin{proof}
(i) Since $u^{\Delta \nabla}(t)\leq 0$, it follows that $u^{\Delta}(t)$ 
 is nonincreasing.
Thus, for  $ 0< t < T$,
\begin{gather*}
u(t)-u(0)=\int_0^t u^{\Delta}(s) \Delta s\geq t u^{\Delta}(t), \\
u(T)-u(t)=\int_t^T u^{\Delta}(s) \Delta s\leq (T-t) u^{\Delta}(t)
\end{gather*}
from which we have
$$
u(t)\geq \frac{t u(T)+(T-t)u(0)}{T} \geq \frac{T-t}{T} u(0)
= \frac{T-t}{T}\|u\|.  
  $$
(ii) If $t=s$, then the conclusion of (ii) holds. 
If $t>s$,  $t,s\in [0,T]_{\mathbb{T}}$,
setting $x(t)= u(t)-\frac{T-t}{T-s}u(s)$, for $u\in P_1$, we have
$$
x^{\Delta\nabla}(t)=u^{\Delta\nabla}(t)\leq 0,  x(T)=u(T)\geq 0,  x(s)=0. 
$$
Therefore, the concavity of $x$ implies that 
$x(t)\geq 0,   t\in (s,T]_{\mathbb{T}}$, i.e.,
$(T-s) u(t) > (T-t) u(s)$, for $t > s$,  $t,s \in [0,T]_{\mathbb{T}}$.
This completes the proof.
\end{proof}

We define the  nonnegative continuous concave  functionals 
 $\alpha_1,\psi_1$ and the  nonnegative continuous convex  functionals
$\gamma_1,\beta_1,\theta_1 $  on  the cone $P_1$ by
\begin{gather*}
\gamma_1 (u)=\theta_1 (u):=\max_{t\in[\xi_{1},T]_{\mathbb{T}} } u(t)=u(\xi_{1}),\\
\alpha_1 (u):=\min_{t\in[0,l_1]_{\mathbb{T}} } u(t)=u(l_1),\\
\beta_1 (u):=\max_{t\in[l_1,T]_{\mathbb{T}} } u(t)=u(l_1),\\
\psi_1 (u):=\min_{t\in[0,\xi_1]_{\mathbb{T}} } u(t)=u(\xi_{1}).
\end{gather*}
We see that, for all $u \in P_1$, $\alpha_1(u)=u(l_1)=\beta_1 (u)$.
\begin{gather*}
 M_1  =  \Big(\frac { \sum_{i=1}^{m-2} b_i(T- \xi_i)} 
{1-\sum_{i=1}^{m-2} b_i} + T-\xi_{1} \Big)
 \phi_q\Big( \int_{0}^T g(r) \nabla r \Big), \\
m_1 =  \Big(\frac { \sum_{i=1}^{m-2} b_i(T- \xi_i)} {1-\sum_{i=1}^{m-2} b_i} 
+T-l_1 \Big)
 \phi_q\Big( \int_{0}^{l_1} g(r) \nabla r \Big), \\
 \lambda_{l_1}  =  \Big(\frac { \sum_{i=1}^{m-2} b_i (T-\xi_i)} 
{1-\sum_{i=1}^{m-2} b_i} +T-l_1 \Big)
 \phi_q\Big( \int_{0}^T g(r) \nabla r \Big).
 \end{gather*}
We note that $u(t)$ is a solution of \eqref{e1.1}  and \eqref{e1.2},
if and only if
\begin{align*}
 u(t) &= \frac {\sum_{i=1}^{m-2} b_i
\left( \int_{\xi_i}^T \phi_q 
\big( \int_0^s g(r) f(u(r)) \nabla r \big) \Delta s \right)}
 {1-\sum_{i=1}^{m-2} b_i} 
\\
 &\quad + \int_t^T \phi_q\Big( \int_0^s g(r) f(u(r) )\nabla r \Big)\Delta s, \quad
  t\in[0,T]_{\mathbb{T}}.
\end{align*}

\begin{theorem} \label{thm3.2}
 Let $0< a < \frac{(T-l_1) b}{T} <\frac{(T-l_1)(T-\xi_{1}) c}{T^2}$,
 $M_1 b < m_1 c$, and assume that $f$ satisfies the following conditions:
\begin{itemize}
\item[(D1)] $ f(w) < \phi_p \big(\frac{c}{M_1}\big)$   for all  
$0\leq w \leq\frac{Tc}{T-\xi_{1}}$;
\item[(D2)] $ f(w) > \phi_p \big(\frac{b}{m_1}\big)$   for all   
$b \leq w \leq\frac{T^2 b}{(T-\xi_{1})^2}$;
\item[(D3)] $ f(w) < \phi_p \big(\frac{a}{\lambda_{l_1} }\big)$   for all
$0 \leq w \leq\frac{Ta}{T-l_1}$.
\end{itemize}

Then, there exist  at least three positive solutions  $u_1,u_2,  u_3$  
 of \eqref{e1.1}  and  \eqref{e1.3} such that
$$
\max_{t \in [l_1,T]_{\mathbb{T}}} u_1 (t) < a,  \quad
 b < \min_{t \in [0,l_1]_{\mathbb{T}}} u_2 (t) , \quad  
a < \max_{t \in [l_1,T]_{\mathbb{T}}} u_3 (t) \quad
   \text{with }    \min_{t \in [0,l_1]_{\mathbb{T}}} u_3 (t)< b.
  $$
\end{theorem}

\begin{proof}
 Defining a completely continuous integral operator
$F_1: P_1\to E$ by
\begin{equation}
\begin{aligned}
(F_1u)(t)
&=\frac {\sum_{i=1}^{m-2} b_i
\left( \int_{\xi_i}^T \phi_q \left ( \int_0^s g(r) f(u(r) ) \nabla r \right) 
\Delta s \right)} {1-\sum_{i=1}^{m-2} b_i} \\
&\quad  +\int_t^T \phi_q\Big( \int_0^s g(r) f(u(r) )\nabla r \Big)\Delta s,  
\quad u\in P_1,
\end{aligned} \label{e3.2}
\end{equation}
 for  $t\in [0,T]_{\mathbb{T}}$, each fixed point of $F_1$ in the cone $P_1$ 
is a positive solution of  \eqref{e1.1} and \eqref{e1.3}. 
We note that, if $u\in P_1$, then $(F_1u)(t)\geq 0$ for 
$t\in [0,T]_{\mathbb{T}}$, and
$$
(F_1u)^{\Delta}(t)=-\phi_q\Big( \int_0^t g(r) f(u(r) )\nabla r \Big),\quad
 u\in P_1,\; t\in [0,T]_{\mathbb{T^\kappa}}.
$$
Note that $(F_1u)^{\Delta}(t)$ is continuous and nonincreasing on 
$[0,T]_{\mathbb{T^\kappa}}$,
and   $(F_1u)^{\Delta\nabla}(t)\leq 0$  for  
$ t\in [0,T]_{\mathbb{T^\kappa}\cap \mathbb{T_\kappa}}$. In addition,
$(F_1u)^{\Delta}(0)=0$. This implies  $F_1u\in P_1$, and therefore $F:P_1\to P_1$.
In likeness to the proof of  Theorem \ref{thm3.1}, we arrive at the conclusion.
\end{proof}

\section{An example}

Let $\mathbb{T}=\{2-(\frac{1}{2})^{\mathbb{N}_0}  \}
\cup \{0,\frac{1}{8},\frac{1}{4},\frac{1}{3},\frac{1}{2},1,\frac{3}{2},2 \}
\cup[\frac{1}{10},\frac{1}{9}]$.
We consider the $p$-Laplacian dynamic equation with $k \in\mathbb{N}_0$,
\begin{equation}
(\phi_p( u^\Delta(t)))^\nabla+ \Big\{ \sum_{k=0}^6 t^k(\rho(t))^{6-k} \Big\} 
t^{\nabla} f(u(t))=0,\quad  t\in[0,2]_{\mathbb{T}}, \label{e4.1}
\end{equation}
satisfying the boundary conditions
\begin{equation}
u(0)=\frac{1}{2}u\Big (\frac{1}{4} \Big )+\frac{1}{6}u \Big (\frac{1}{2} \Big),\quad
  u^{\Delta}(2)=0, \label{e4.2}
\end{equation}
where $p=4/3$,  $\xi_1=1/4$,   $\xi_2=1/2$,  $a_1=1/2$, $a_2=1/6$, $T=2$  and
\[
 f(u)= \begin{cases}
1\times 10^{-7}, &    0\leq u \leq 4,\\
 p(u),    & 4\leq u \leq 10,\\
 7\times 10^{-6},    & 10\leq u \leq 800,\\
 s(u), & u \geq 800,
  \end{cases} 
\]
here $p(u)$ and $s(u)$ satisfy
$p(4)= 1\times 10^{-7}$,  $p(10)= 7\times 10^{-6}$, 
$s(800)= 7\times 10^{-6}$,
$(p^{\nabla}(u))^{\nabla}=0$ for $u\in (4,10)$,
and $s(u):\mathbb{R} \to \mathbb{R^{+} }$ is continuous.
If 
\[
g(t)= \Big\{ \sum_{k=0}^6 t^k(\rho(t))^{6-k} \Big\} t^{\nabla},
\]
then we obtain
$(t^7)^{\nabla}= \Big\{ \sum_{k=0}^6 t^k(\rho(t))^{6-k} \Big\} t^{\nabla}$.

Choose $a=2$,  $b=10$,  $c=200$,  $l=1$.  Then
\begin{gather*}
\begin{aligned}
 M & =  \Big(\frac { \sum_{i=1}^{m-2} a_i \xi_i} {1-\sum_{i=1}^{m-2} a_i} 
+\xi_{m-2} \Big)
 \phi_q\Big( \int_{0}^T g(r) \nabla r \Big)\\
& =  \big(\frac{5}{8} + \frac{1}{2}\big )
\Big(\int_0^2 \Big\{ \sum_{k=0}^6 t^k(\rho(t))^{6-k} \Big\} 
t^{\nabla}\nabla t \Big)^3\\
 &= \frac{9}{8}\times 2^{21}=2.3593\times10^6,
\end{aligned}\\
\begin{aligned}
m &=  \Big(\frac { \sum_{i=1}^{m-2} a_i \xi_i} {1-\sum_{i=1}^{m-2} a_i} +l \Big)
 \phi_q\Big( \int_{l}^T g(r) \nabla r \Big)\\
& =  \Big(\frac{5}{8} + 1 \Big )
\Big(\int_1^2 \Big\{ \sum_{k=0}^6 t^k(\rho(t))^{6-k} \Big\} t^{\nabla}\nabla t \Big)^3\\
& = \frac{13}{8}\times( 2^{7}-1)^3=3.3286\times10^6,
\end{aligned}\\
\begin{aligned}
 \lambda_l 
& =  \Big(\frac { \sum_{i=1}^{m-2} a_i \xi_i} {1-\sum_{i=1}^{m-2} a_i} +l \Big)
 \phi_q\Big( \int_{0}^T g(r) \nabla r \Big) \\
& = \frac{13}{8} \Big(\int_0^2 \Big\{ \sum_{k=0}^6 t^k(\rho(t))^{6-k} \Big\} 
t^{\nabla}\nabla t \Big)^3  \\
&= \frac{13}{8}\times 2^{21}=3.4079\times10^6.
\end{aligned}
 \end{gather*}
It is easy to see that
$$
0 < a < \frac{lb}{T}  <  \frac{\xi_{2} lc}{T^2} , \quad  Mb<mc
 $$
and $f$ satisfies 
\begin{gather*}
 f(w) <  \phi_p \left(\frac{a}{\lambda_l}\right)= 5.8687\times 10^{-7},\quad
\text{for } 0 \leq w \leq\frac{Ta}{l}=4,\\
 f(w) > \phi_p \left(\frac{b}{m}\right)=3.0043\times 10^{-6}, \quad
 \text{for }   10 \leq w \leq\frac{T^2 b}{\xi_{m-2}^2}=160,\\
 f(w) < \phi_p \left(\frac{c}{M}\right)= 8.4771\times 10^{-5},\quad
\text{for } 0\leq w \leq\frac{Tc}{\xi_{m-2}}=800.
\end{gather*}
So, all the conditions of Theorem \ref{thm3.1} are satisfied.
By Theorem  \ref{thm3.1},  the problem \eqref{e4.1},  \eqref{e4.2} has at 
least three positive solutions
$u_1$, $u_2$ and  $u_3$ satisfying
$$
\max_{t \in [0,1]_{\mathbb{T}}} u_1 (t) < 2, \quad
10 < \min_{t \in [1,2]_{\mathbb{T}}} u_2 (t) , \quad  
2 < \max_{t \in [0,1]_{\mathbb{T}}} u_3 (t) \quad   \text{with} 
   \min_{t \in [1,2]_{\mathbb{T}}} u_3 (t)< 10.  
$$

\subsection*{Acknowledgments}
The author would like to thank the anonymous referees and editor for their 
helpful comments and suggestions. The project is supported by Abdullah Gul 
University Foundation of Turkey.

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\end{document}
