\documentclass[reqno]{amsart}
\usepackage{hyperref}
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\AtBeginDocument{{\noindent\small
\emph{Electronic Journal of Differential Equations},
Vol. 2015 (2015), No. 127, pp. 1--11.\newline
ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu
\newline ftp ejde.math.txstate.edu}
\thanks{\copyright 2015 Texas State University - San Marcos.}
\vspace{9mm}}

\begin{document}
\title[\hfilneg EJDE-2015/127\hfil Super-quadratic conditions]
{Super-quadratic conditions for periodic elliptic system on $\mathbb{R}^N$}

\author[F. Liao, X. Tang, J. Zhang, D. Qin \hfil EJDE-2015/127\hfilneg]
{Fangfang Liao, Xianhua Tang, Jian Zhang, Dongdong Qin}

\address{Fangfang Liao \newline
School of Mathematics and Statistics,
Central South University,
Changsha, 41008, 3 Hunan, China. \newline
School of Mathematics and Finance,
Xiangnan University,
Chenzhou, 423000, Hunan, China}
\email{liaofangfang1981@126.com}

\address{Xianhua Tang (corresponding author) \newline
School of Mathematics and Statistics,
Central South University,
Changsha, 41008, 3 Hunan, China}
\email{tangxh@mail.csu.edu.cn}

\address{Jian Zhang \newline
School of Mathematics and Statistics,
Central South University,
Changsha, 41008, 3 Hunan, China}
\email{zhangjian433130@163.com}

\address{Dongdong Qin \newline
School of Mathematics and Statistics,
Central South University,
Changsha, 41008, 3 Hunan, China}
\email{qindd132@163.com}

\thanks{Submitted January 31, 2015. Published May 6, 2015.}
\subjclass[2010]{35J10, 35J20}
\keywords{Elliptic system; super-quadratic; nontrivial solution; 
\hfill\break\indent strongly indefinite functionals}

\begin{abstract}
 This article concerns the  elliptic system
   \begin{gather*}
    -\Delta u+V(x)u=W_{v}(x, u, v), \quad  x\in \mathbb{R}^{N},\\
    -\Delta v+V(x)v=W_{u}(x, u, v), \quad  x\in \mathbb{R}^{N},\\
    u, v\in H^{1}(\mathbb{R}^{N}),
   \end{gather*}
 where  $V $ and $W$ are periodic in $x$, and $W(x, z)$ is super-linear
 in $z=(u, v)$.  We use a new technique to show that the above system has
 a nontrivial solution under concise super-quadratic conditions.
 These conditions show that the existence of a nontrivial solution
 depends mainly on the behavior of $W(x, u, v)$
 as $|u+v| \to 0$ and $|au+bv| \to \infty$ for some positive constants $a, b$.
\end{abstract}

\maketitle
\numberwithin{equation}{section}
\newtheorem{theorem}{Theorem}[section]
\newtheorem{lemma}[theorem]{Lemma}
\newtheorem{remark}[theorem]{Remark}
\newtheorem{example}[theorem]{Example}
\allowdisplaybreaks

\section{Introduction}

   In this article, we study the elliptic system
 \begin{equation} \label{hs}
 \begin{gathered}
    -\Delta u+V(x)u=W_{v}(x, u, v), \quad x\in \mathbb{R}^{N},\\
    -\Delta v+V(x)v=W_{u}(x, u, v), \quad x\in \mathbb{R}^{N},\\
    u, v\in H^{1}(\mathbb{R}^{N}),
   \end{gathered}
 \end{equation}
 where  $z:=(u, v) \in \mathbb{R}^2$, $V : \mathbb{R}^{N} \to {\mathbb{R}}$ and
$W: \mathbb{R}^N\times \mathbb{R}^2 \to {\mathbb{R}}$.

 Systems similar to \eqref{hs} have been considered recently;
see for instance
\cite{ACM,AY,AY2,BF,DL,FYD,LTZ,LY,PR,S,SS,WXZ1,WXZ2,YCD,ZCZ,ZD,ZTZ,ZTZ1,
ZQZ,ZZ,ZZD1,ZZD2,ZZD3,ZZD4} and references therein.
 For the superquadratic case, it always assumed that $W$ satisfies the
 Ambrosetti-Rabinowitz condition
 \begin{itemize}
 \item[(AR)] there is a $\mu>2$ such that
 \begin{equation}\label{AR1}
   0< \mu W(x, z)\le W_z(x, z)\cdot z, \quad \forall
(x, z)\in \mathbb{R}^{N}\times \mathbb{R}^2, \; z\ne 0\,.
 \end{equation}
 \end{itemize}
 We use the assumption that there exist $c>0$ and
$\nu\in (2N/(N+2), 2)$ such that
 \begin{equation}\label{AR2}
   |W_z(x, z)|^{\nu}
\le c[1+W_z(x, z)\cdot z], \quad \forall
 (x, z)\in \mathbb{R}^{N}\times \mathbb{R}^2\,,
 \end{equation}
 or the super-quadratic condition
 \begin{equation}\label{AR3}
   \lim_{|z|\to \infty}\frac{|W(x, z)|}{|z|^2}=\infty, \quad
\text{uniformly in }x\in \mathbb{R}^N,
 \end{equation}
and a condition of the Ding-Lee type,
 \begin{itemize}
 \item[(DL)] $\widetilde{W}(x, z):=\frac{1}{2}W_z(x, z)\cdot z-W(x, z)> 0$
for $z\ne 0$ and there  exist  $\hat{c}>0$ and $\kappa>\max\{1, N/2\}$ such that
 \begin{equation}\label{AR4}
   |W_z(x, z)|^{\kappa}\le \hat{c}|z|^{\kappa}\widetilde{W}(x, z), \quad
\text{for large } |z|.
 \end{equation}
 \end{itemize}


 Observe that conditions \eqref{AR3} and $W(x, z)>0, \forall z\ne 0$ in (AR)
or $\widetilde{W}(x, z)>0, \forall\ z\ne 0$
 in (DL) play an important role for showing that any Palais-Smale sequence
or Cerami sequence is bounded in the aforementioned works.
 However, there are many functions that do not satisfy these conditions, for example,
 $$
  W(x, u, v)=(u^2+uv+v^2)\ln(1+u^2),
 $$
 or
 $$
 W(x, u, v)=(u+2v)^2\sqrt{u^2+v^2}.
 $$


  In a recent paper  Liao, Tang and Zhang \cite{LTZ} studied the existence
of solutions for system \eqref{hs} under the following assumptions on $V$ and $W$:
\begin{itemize}
\item[(V1)]  $V\in C(\mathbb{R}^N, \mathbb{R})$, $V(x)$ is 1-periodic in each of
$x_1, x_2, \dots, x_N$, and $\min_{\mathbb{R}^N}V \geq \beta_0>0$;

\item[(W1)] $W\in C(\mathbb{R}^N\times \mathbb{R}^2, \mathbb{R}^+)$,
$W(x, z)$ is 1-periodic in each of $x_1, x_2, \dots, x_N$, continuously
differentiable on $z \in \mathbb{R}^2$ for every
$x \in \mathbb{R}^N$, and there exist constants $p\in (2, 2^*)$ and $C_0>0$
 such that
 $$
   |W_z(x, z)|\le C_0\left(1+|z|^{p-1}\right), \quad
\forall (x, z)\in \mathbb{R}^N\times \mathbb{R}^2;
 $$

\item[(W2)] $|W_z(x,z)|=o(|z|)$, as $|z|\to 0$, uniformly in
$x \in \mathbb{R}^N$;

\item[(W3)]
$\lim_{|u+v|\to \infty}\frac{|W(x, u, v)|}{|u+v|^2}=\infty$,   a.e.
$x\in \mathbb{R}^N$;

\item[(W4)]  $\widetilde{W}(x, z) \ge 0$ for all
 $(x, z) \in \mathbb{R}^{N}\times \mathbb{R}^2$, and there  exist
$c_0, R_0>0$ and $\kappa>\max\{1, N/2\}$
 such that
 $$
   |W_{u}(x, u, v)+W_{v}(x, u, v)|\le \frac{2\beta_0}{3}\sqrt{u^2+v^2},
       \quad  u^2+v^2\le R_0^2
 $$
 and
 $$
   |W_{u}(x, u, v)+W_{v}(x, u, v)|^{\kappa}\le c_0\left(u^2+v^2\right)^{\kappa/2}\widetilde{W}(x, u, v),
   \quad \ u^2+v^2\ge R_0^2.
 $$
\end{itemize}

 Specifically, Liao, Tang and Zhang \cite{LTZ} established the following theorem.


 \begin{theorem}[{\cite[Theorem1.2]{LTZ}}] \label{thm1.1}
 Assume that {\rm (V1), (W1)--(W4)} are satisfied.
Then \eqref{hs} has a nontrivial solution.
\end{theorem}

 As shown in \cite{LTZ}, (W3) is different from usual superquadratic conditions
(AR) and \eqref{AR3}, and is weaker than \eqref{AR3}.
Clearly, (W4) is significantly weaker than (DL).
By a variable substitution, instead of (W3) and (W4),
  the following more general conditions were used:
\begin{itemize}
 \item[(W3')]  there exist $a, b>0$ such that
\[
\lim_{|au+bv|\to \infty}\frac{|W(x, u, v)|}{|au+bv|^2}=\infty,
\quad\text{a.e. }x\in \mathbb{R}^N;
\]

\item[(W4')] $\widetilde{W}(x, z)\ge 0$ for all
$(x, z)\in \mathbb{R}^{N}\times \mathbb{R}^2$, and there  exist
 $c_1, R_1>0$ and $\kappa>\max\{1, N/2\}$ such that
\begin{gather*}
 |bW_{u}(x, u, v)+aW_{v}(x, u, v)|\le \frac{2\beta_0}{3}\sqrt{u^2+v^2},
  \quad \ a^2u^2+b^2v^2\le R_1^2, \\
 |bW_{u}(x, u, v)+aW_{v}(x, u, v)|^{\kappa}
\le c_1\left(a^2u^2+b^2v^2\right)^{\kappa/2}\widetilde{W}(x, u, v),\\
 a^2u^2+b^2v^2\ge R_1^2.
\end{gather*}

\end{itemize}
 Motivated by  \cite{LTZ},  we obtain a  super-quadratic condition  more
concise  than (W4'):
\begin{itemize}
\item[(W5)] $\widetilde{W}(x, z)\ge 0$ for all
$(x, z)\in \mathbb{R}^{N}\times \mathbb{R}^2 $, and there exist
$\theta \in (0, 1)$, $\alpha_0 > 0$, and
 $\kappa>\max\{1, N/2\}$ such that
\begin{align*}
&\frac{|bW_u(x, z)+aW_v(x, z)|}{|z|} \geq \theta \beta_0 \min\{a, b\}\\
& \Rightarrow   \Big(\frac{|bW_u(x, z)+aW_v(x, z)|}{|z|}\Big)^\kappa
\le \alpha_0 \widetilde{W}(x, z).
\end{align*}
\end{itemize}
 By introducing new techniques, under (W3') and (W5), we  obtain the linking
structure and the boundedness of a Cerami sequence of the
 energy functional associated with \eqref{hs}. Specifically, we obtain the
following theorem.


 \begin{theorem} \label{thm1.2}
 Assume that{\rm  (V1), (W1), (W2), (W3'), (W5)} hold.
 Then \eqref{hs} has a nontrivial solution.
\end{theorem}


 \begin{remark} \label{rmk1.3}\rm
Note that  (W5) is weaker than (DL) and than (AR).
Since
\[
|bW_{u}+aW_{v}|\le \sqrt{a^2+b^2}|W_{z}(x, z)|,
\]
in view of (W2),  it is clear that (DL) implies (W5).
If $W(x, z)$ satisfies \eqref{AR1}, then there exist $c_1, R_1>0$ such that
 \begin{gather}\label{Re1}
   W_z(x, z)\cdot z\ge \mu W(x, z)\ge c_1|z|^{\mu}, \quad |z|\ge R_1,\\
\label{Re2}
   \widetilde{W}(x, z)\ge \frac{\mu-2}{2}W_z(x, z)\cdot z>0, \quad \forall
z\in \mathbb{R}^2\setminus \{0\}.
 \end{gather}
Let $\kappa=\nu/(2-\nu)$. Then $\kappa>\max\{1, N/2\}$. Hence, it follows
from \eqref{AR2}, \eqref{Re1} and \eqref{Re2} that
 \begin{equation} \label{Re3}
\begin{aligned}
   |W_z(x, z)|^{\kappa}
&\leq  c_2|W_z(x, z)|^{\kappa-\nu}W_z(x, z)\cdot z \\
&\leq  c_3|z|^{(\kappa-\nu)/(\nu-1)}\widetilde{W}(x, z) \\
&=  c_3|z|^{\kappa}\widetilde{W}(x, z),  \quad |z|\ge R_1.
\end{aligned}
\end{equation}
 This shows that (DL) holds, and so (W5) holds.
\end{remark}

 Before proceeding with the proof of Theorem \ref{thm1.2}, we give a nonlinear
example to illustrate the assumptions.


 \begin{example} \label{examp1.4}\rm
$W(x, u, v)=h(x)(u+2v)^2\sqrt{u^2+v^2}$,  where
$h\in C(\mathbb{R}^N, (0, \infty))$  is 1-periodic in each of the variables
 $x_1, x_2, \ldots, x_N$.
  Then
\[
  \widetilde{W}(x, u, v)=\frac{1}{2}h(x)(u+2v)^2\sqrt{u^2+v^2},
\quad u, \, v\in \mathbb{R}.
\]
 Therefore all conditions (W1), (W2), (W3'), (W5)  are satisfied with
$a=1, b=2$ and $\kappa\le 3$.
 Note that $W(x, u, v)=\widetilde{W}(x, u, v)=0$ for $u=-2v$, $v\in \mathbb{R}$, thus
$W$ does not satisfy (AR) and (DL).
\end{example}

The rest of this article is organized as below.
In Section 2, we provide a variational setting.
The proofs of our main results are given in the last section.


\section{Variational setting}

 Under assumption (V1), we can define the  Hilbert space
 $$
E_V=\big\{u \in H^1(\mathbb{R}^N): \int_{\mathbb{R}^N}
(|\nabla u|^2+V(x)u^2)\,\mathrm{d}x < +\infty \big\}
$$
equipped with the inner product
 $$
   (u, v)_{E_V}=\int_{\mathbb{R}^N} [\nabla{u}\cdot \nabla{v} +V(x)uv]\,\mathrm{d}x,
\quad \forall u, v\in E_V,
 $$
 and the corresponding norm
 \begin{equation}\label{2.1-}
   \|u\|_{E_V}=\Big(\int_{\mathbb{R}^N} [|\nabla{u}|^2+V(x)u^2]\,\mathrm{d}x\Big)
^{1/2}, \quad \forall u\in E_V.
 \end{equation}
By  the Sobolev embedding theorem, there exists constant $\gamma_s>0$ such that
 \begin{equation}\label{2.1}
   \|u\|_{s}\le \gamma_s\|u\|_{E_V},
      \quad \forall u\in H^1(\mathbb{R}^N), \; 2\le s \le 2^*,
 \end{equation}
 here and in the sequel, by $\|\cdot\|_s$ we denote the usual norm
in space $L^s(\mathbb{R}^N)$.

 Let $E =E_V\times E_V $ with the inner product
\[
(z_1,z_2)=((u_1, v_1), (u_2, v_2)) = (u_1, u_2)_{E_V} + (v_1, v_2)_{E_V},
\]
for $z_i=(u_i, v_i)\in E$, $i=1, 2$,
and the corresponding norm $\|\cdot\|$.
Then there hold
 \begin{equation}\label{2.2}
   \|z\|^2=\|u\|_{{E_V}}^2+\|v\|_{{E_V}}^2,  \quad \forall z=(u, v)\in E
 \end{equation}
 and
 \begin{equation} \label{2.3}
\begin{aligned}
   \|z\|_s^s
    &=  \int_{\mathbb{R}^N}(u^2+v^2)^{s/2}\,\mathrm{d}x
\le 2^{(s-2)/2}(\|u\|_s^s+\|v\|_s^s) \\
&\leq  2^{(s-2)/2}\gamma_s^{s}\left(\|u\|_{E_V}^s+\|v\|_{E_V}^s\right)\\
&\le 2^{(s-2)/2}\gamma_s^{s}\left(\|u\|_{E_V}^2+\|v\|_{E_V}^2\right)^{s/2} \\
&=  2^{(s-2)/2}\gamma_s^{s}\|z\|^s,  \quad
\forall s\in [2, 2^*], \;  z=(u, v)\in E.
 \end{aligned}
\end{equation}

 Now we define a functional $\Phi$ on $E$ by
 \begin{equation}\label{2.4}
   \Phi(z)=\int_{\mathbb{R}^N}\left(\nabla u\cdot\nabla v+V(x)uv\right)
\,\mathrm{d}x
 -\int_{\mathbb{R}^N}W(x, u, v)\,\mathrm{d}x, \quad \forall z=(u, v)\in E.
 \end{equation}
Consequently, under assumptions (V1), (V2), (W1), (W2), (W3'), it is well
known that $\Phi$ is $C^1(E, \mathbb{R})$, and
 \begin{equation}\label{2.5}
\begin{aligned}
   \langle \Phi'(z), \zeta \rangle
    &=  \int_{\mathbb{R}^N}\left[\nabla u\cdot\nabla \psi
+\nabla v\cdot\nabla \varphi+V(x)(u\psi+v\varphi)\right]\,\mathrm{d}x \\
 & \quad -\int_{\mathbb{R}^N}[W_{u}(x, u, v)\varphi
 +W_{v}(x, u, v)\psi]\,\mathrm{d}x,
\end{aligned}
\end{equation}
 for all $z=(u, v)$, $\zeta=(\varphi, \psi)\in E$.
  Let
 $$
   E^{-}=\{(u, -u) : u\in H^1(\mathbb{R}^N)\}, \quad
E^{+}=\{(u, u) : u\in H^1(\mathbb{R}^N)\}.
 $$
 For any $z=(u, v)\in E$, set
 \begin{equation}\label{2.6}
   z^{-}=\Big(\frac{u-v}{2}, \frac{v-u}{2}\Big), \quad
   z^{+}=\Big(\frac{u+v}{2}, \frac{u+v}{2}\Big).
  \end{equation}
 It is obvious that $z=z^{-}+z^{+}$, $z^{-}$ and $z^{+}$ are orthogonal
with respect to the inner products
 $(\cdot, \cdot)_{L^2}$ and $(\cdot, \cdot)$. Thus we have
$E=E^{-}\oplus E^{+}$. By a simple calculation,
 one can get that
 $$
   \frac{1}{2}\left(\|z^{+}\|^2-\|z^{-}\|^2\right)
     =\int_{\mathbb{R}^N}\left[\nabla u\cdot \nabla v+V(x)uv\right]\,\mathrm{d}x.
 $$
 Therefore, the functional $\Phi$ defined in \eqref{2.4} can be rewritten
in a standard way
 \begin{equation}\label{2.7}
   \Phi(z)=\frac{1}{2}\left(\|z^{+}\|^2-\|z^{-}\|^2\right)
     -\int_{\mathbb{R}^N}W(x, z)\,\mathrm{d}x, \quad \forall z=(u, v)\in E.
 \end{equation}
 Moreover
 \begin{equation}\label{2.8}
   \langle \Phi'(z), z \rangle
=  \|z^{+}\|^2-\|z^{-}\|^2 -\int_{\mathbb{R}^N}[W_{u}(x, u, v)u
+W_{v}(x, u, v)v]\,\mathrm{d}x,
\end{equation}
 for all $z=(u, v)\in E$.


\section{Proofs of main resutls}

 To give the proofs of our results, we set
 \begin{equation}\label{3.1}
 \Psi(z) = \int_{\mathbb{R}^N} W(x, z) \,\mathrm{d}x, \quad \forall z \in E.
 \end{equation}


 \begin{lemma} \label{lem3.1}
Suppose that {\rm (W1), (W2)}  are satisfied. Then  $\Psi$
is nonnegative, weakly sequentially lower semi-continuous, and  $\Psi'$
is weakly sequentially continuous.
\end{lemma}

 Using the Sobolev's imbedding theorem, one can easily check the above lemma,
so we omit the proof.

\begin{lemma} \label{lem3.2}
 Suppose that {\rm (V1), (W1), (W2), (W3')}  are satisfied.
Then there is a $\rho>0$  such that $\kappa_1:=\inf\Phi(S_{\rho}^{+})>0$,
where $S_{\rho}^{+}=\partial B_{\rho}\cap E^{+}$.
\end{lemma}

The above lemma can be proved in standard way; we omit its proof.

 \begin{lemma} \label{lem3.3}
 Suppose that {\rm (V1), (W1), (W2), (W3')}  are satisfied.
Let $e=(e_0, e_0)$ belong to $E^{+}$ with $\|e\|=1$. Then there is a constant
$r>0$ such that $\sup \Phi(\partial Q)\le 0$, where
 \begin{equation}\label{3.2}
   Q=\big\{\zeta+se : \zeta=(w, -w)\in E^{-},\, s\ge 0,\, \|\zeta+se\|\le r\big\}.
 \end{equation}
\end{lemma}

\begin{proof}  By (W1) and \eqref{2.7}, $\Phi(z)\le 0$ for $z\in E^{-}$.
 Next, it is sufficient to show that $\Phi(z)\to -\infty$ as
$z\in E^{-}\oplus \mathbb{R} e$ for $\|z\|\to \infty$.
 Arguing indirectly, assume that for some sequence
$\{\zeta_n+s_ne\}\subset E^{-}\oplus \mathbb{R} e$ with $\|\zeta_n+s_ne\|\to \infty$,
there is $M>0$ such that $\Phi(\zeta_n+s_ne)\ge -M$ for all $n\in \mathbb{N}$.
 Set $\zeta_n=(w_n, -w_n)$,
$\xi_n=(\zeta_n+s_ne)/\|\zeta_n+s_ne\| =\xi_n^{-}+t_ne$, then
$\|\xi_n^{-}+t_ne\|=1$.
Passing to a subsequence, we may assume that $t_n \to \bar{t}$ and
$\xi_n\rightharpoonup \xi$ in $E$,
then $\xi_n\to \xi$ a.e. on $\mathbb{R}^N$,
$\xi_n^{-}\rightharpoonup \xi^{-}$ in $E$,
$\xi_n^-:=(\tilde{w_n}, -\tilde{w_n})\rightharpoonup \xi^-:=(\tilde{w}, -\tilde{w})$,
and
 \begin{equation}\label{3.3}
\begin{aligned}
   -\frac{M}{\|\zeta_n+s_ne\|^2}
&\le \frac{\Phi(\zeta_n+s_ne)}{\|\zeta_n+s_ne\|^2}\\
&=\frac{t_n^2}{2}-\frac{1}{2}\|\xi_n^{-}\|^2
     -\int_{\mathbb{R}^N}
\frac{W(x, w_n+s_ne_0, -w_n+s_ne_0)}{\|\zeta_n+s_ne\|^2}\,\mathrm{d}x.
\end{aligned}
\end{equation}

 If $\bar{t}=0$, then it follows from \eqref{3.3} that
 $$
   0\le \frac{1}{2}\|\xi_n^{-}\|^2+\int_{\mathbb{R}^N}
\frac{W(x,  w_n+s_ne_0, -w_n+s_ne_0)}{\|\zeta_n+s_ne\|^2}\,\mathrm{d}x
 \le \frac{t_n^2}{2}+\frac{M}{\|\zeta_n+s_ne\|^2}\to 0,
 $$
 which yields $\|\xi_n^{-}\|\to 0$, and so $1=\|\xi_n\|\to 0$, 
a contradiction.

If $\bar{t}\ne 0$, then
 \begin{equation}\label{3.4}
 (a-b)\tilde{w}+(a+b)\bar{t} e_0 \neq 0.
 \end{equation}
Arguing indirectly, assume that $(a-b)\tilde{w}+(a+b)\bar{t} e_0 =0$, 
then $a \neq b$ and
 \begin{align*}
 \bar{t}^2
&=  \lim_{n \to \infty} t_n^2 \\
&\geq \lim_{n \to \infty}\inf
\Big( -\frac{2M}{\|\zeta_n+s_ne\|^2}+\|\xi_n^-\|^2 \Big)\\
& \geq  \|\xi^-\|^2\\
&= \int_{\mathbb{R}^N} [|\nabla \xi^-|^2+V(x)|\xi^-|^2 ]\,\mathrm{d}x\\
&=  \frac{(a+b)^2}{(b-a)^2}\bar{t}^2 \int_{\mathbb{R}^N}\left[|\nabla e|^2+V(x)|e|^2 \right]\,\mathrm{d}x\\
& >   \bar{t}^2 \int_{\mathbb{R}^N} [|\nabla e|^2+V(x)|e|^2 ]\,\mathrm{d}x
= \bar{t}^2,
 \end{align*}
which is a contradiction.

Let $\Omega := \{x \in \mathbb{R}^N:
 (a-b)\tilde{w}(x)+(a+b)\bar{t}e_0(x)\neq 0\}$. 
Then \eqref{3.4} shows that $|\Omega|>0$.
 Since $\|\zeta_n+s_ne\| \to \infty$,
 for any $x \in \Omega$, one has
\begin{align*}
  & |a(w_n(x)+s_ne_0(x))+b(-w_n(x)+s_ne_0(x))|\\
  &= \|\zeta_n+s_ne\||(a-b)\tilde{w}_n(x)+(a+b)t_ne_0(x)|\to \infty.
\end{align*}
 Let $\eta_n := a(\tilde{w}_n+t_ne_0)+b(-\tilde{w}_n+t_ne_0)$.
 It follows from \eqref{3.3}, \eqref{3.4}, (W3') and Fatou's lemma that
\begin{align*}
  0 
&\leq \limsup_{n\to\infty}
\Big[\frac{t_n^2}{2}-\frac{1}{2}\|\xi_n^{-}\|^2
              -\int_{\mathbb{R}^N}\frac{W(x,  w_n+s_ne_0, -w_n+s_ne_0)}
{\|\zeta_n+s_ne\|^2}\,\mathrm{d}x\Big]\\
&=  \limsup_{n\to\infty}\Big[\frac{t_n^2}{2}-\frac{1}{2}\|\xi_n^{-}\|^2
                 -\int_{\mathbb{R}^N}\frac{W(x,  w_n+s_ne_0, 
-w_n+s_ne_0)}{|a(w_n+s_ne_0)+b(-w_n+s_ne_0)|^2}|\eta_n|^2\,\mathrm{d}x\Big]\\
&\leq  \frac{1}{2}\lim_{n\to\infty}t_n^2-\liminf_{n\to\infty}
             \int_{\mathbb{R}^N}\frac{W(x,  w_n+s_ne_0, -w_n+s_ne_0)}
{|a(w_n+s_ne_0)+b(-w_n+s_ne_0)|^2}|\eta_n|^2\,\mathrm{d}x\\
&\leq  \frac{\bar{t}^2}{2}-\int_{\mathbb{R}^N}
\liminf_{n\to\infty} \frac{W(x,  w_n+s_ne_0, -w_n+s_ne_0)}
   {|a(w_n+s_ne_0)+b(-w_n+s_ne_0)|^2}|\eta_n|^2\,\mathrm{d}x\\
 &=  -\infty,
 \end{align*}
 a contradiction.
 \end{proof}

 Applying the generalized linking theorem \cite{KS, LS}
and standard arguments, we can prove the following lemma.

 \begin{lemma} \label{lem3.4}
 Suppose that {\rm (V1), (W1), (W2), (W3')} are satisfied.
 Then there exist a constant $c_*\in [\kappa_0, \sup \Phi(Q)]$ and a 
sequence $\{z_n\}=\{(u_n, v_n)\} \subset E$ satisfying
 \begin{equation}\label{3.5}
   \Phi(z_n)\to c_*, \quad \|\Phi'(z_n)\|(1+\|z_n\|)\to 0.
 \end{equation}
 where $Q$ is defined by \eqref{3.2}.
\end{lemma}
 
 \begin{lemma} \label{lem3.5}
 Suppose that {\rm (V1), (W1), (W2), (W3'), (W5)}  are satisfied.
Then any sequence  $\{z_n\}=\{(u_n, v_n)\} \subset E$ satisfying \eqref{3.5} 
is bounded in $E$.
\end{lemma}

 
\begin{proof} 
To prove the boundedness of $\{z_n\}$, arguing by contradiction, suppose 
that $\|z_n\| \to \infty$.
 Let 
\begin{gather*}
 \xi_n=\frac{z_n}{\|z_n\|}=(\varphi_n, \psi_n), \quad
 \hat{z}_n=(\hat{u}_n, \hat{v}_n)
:= \Big(\frac{au_n+bv_n}{2a}, \frac{au_n+bv_n}{2b} \Big), \\
 \hat{\xi}_n=(\hat{\varphi}_n, \hat{\psi}_n)
:=\frac{\hat{z}_n}{\|z_n\|}
=\Big(\frac{a\varphi_n+b\psi_n}{2a}, \frac{a\varphi_n+b\psi_n}{2b}\Big).
\end{gather*}
  By  (W1), \eqref{2.2}, \eqref{2.4}, \eqref{2.7}, \eqref{2.8} and \eqref{3.5}, 
one obtains
 \begin{gather}\label{3.6}
    2c_*+o(1)  =  \|z_n^{+}\|^2-\|z_n^{-}\|^2-2\int_{\mathbb{R}^N}W(x, z_n)
\,\mathrm{d}x\le\|z_n^{+}\|^2-\|z_n^{-}\|^2, \\
\label{3.7}
     c_*+o(1)   =  \int_{\mathbb{R}^N}\widetilde{W}(x, z_n)\,\mathrm{d}x, 
\end{gather}
and
\begin{align*}
\|\hat{z}_n\|^2  
&=  \frac{a^2+b^2}{4a^2b^2}\|au_n+bv_n\|_{E_V}^2 \\
&=  \frac{a^2+b^2}{4a^2b^2}\Big[a^2\|u_n\|_{E_V}^2+b^2\|v_n\|_{E_V}^2
+2ab \int_{\mathbb{R}^N}(\nabla u_n\nabla v_n+V(x)u_nv_n)\Big] \\
 &=  \frac{a^2+b^2}{4a^2b^2}\Big[a^2\|u_n\|_{E_V}^2+b^2\|v_n\|_{E_V}^2
+2ab\Big(\Phi(z_n)+\int_{\mathbb{R}^N}W(x, u_n, v_n)\,\mathrm{d}x\Big)\Big] \\
& \geq   \frac{a^2+b^2}{4a^2b^2}
[\min\{a^2, b^2\}\|z_n\|^2+2ab(c_*+o(1))],
 \end{align*}
 which implies 
 \begin{equation}\label{3.8}
  \|z_n\| \leq \frac{2ab}{\sqrt{a^2+b^2}\min\{a,b\}}\|\hat{z}_n\|, \quad a, b>0.
 \end{equation}
 Note that
 \begin{equation}\label{b4}
\begin{aligned}
  \|\hat{\xi}_n\|^2
&=  \frac{a^2+b^2}{4a^2b^2}\|a\varphi_n+b\psi_n\|_{E_V}^2 \\
& \leq \frac{a^2+b^2}{4a^2b^2}
 \left(a\|\varphi_n\|_{E_V}+b\|\psi_n\|_{E_V}\right)^2 \\
& \leq \frac{a^2+b^2}{2a^2b^2}
 \left(a^2\|\varphi_n\|_{E_V}^2+b^2\|\psi_n\|_{E_V}^2\right) \\
& \leq  \frac{(a^2+b^2)^2}{2a^2b^2}
 \left(\|\varphi_n\|_{E_V}^2+\|\psi_n\|_{E_V}^2\right) \\ 
&=    \frac{(a^2+b^2)^2}{2a^2b^2}\|\xi_n\|^2=\frac{(a^2+b^2)^2}{2a^2b^2},
 \end{aligned}
\end{equation}
 which implies that $\{\hat{\xi}_n\}$ is bounded.
 If $\delta:= \lim\sup_{n \to \infty} \sup_{y \in \mathbb{R}^N}
\int_{B(y,1)}|\hat{\xi_n}|^2\,\mathrm{d}x=0$,
 then by Lions's concentration compactness principle \cite[Lemma 1.21]{Wi},
$a\varphi_n + b\psi_n \to 0$ in $L^s(\mathbb{R}^N)$ for $2<s<2^*$.
 Set $\kappa' = \kappa / (\kappa-1)$ and
$$
\Omega_n := \big\{x \in \mathbb{R}^N : \frac{|bW_u(x, u_n, v_n)
+aW_v(x, u_n, v_n)|}{|z_n|}
 \leq \theta \beta_0 \min\{a, b\} \big\},
$$
 then $2<2\kappa'<2^*$.
 Hence, by (W1), (W2), (W3'), it follows from \eqref{2.1-}, \eqref{2.2},
\eqref{3.8} and H\"older inequality that
 \begin{equation}\label{3.9}
\begin{aligned}
     & \int_{\Omega_n}|bW_{u}(x, u_n, v_n)+aW_{v}(x, u_n, v_n)|
|au_n+bv_n|\,\mathrm{d}x \\
     &\leq  \int_{\Omega_n}\frac{|bW_{u}(x, u_n, v_n)
+aW_{v}(x, u_n, v_n)|}{|z_n|}|z_n||au_n+bv_n|\,\mathrm{d}x \\
     &\leq  \theta \beta_0 \min\{a, b\}
\int_{\Omega_n}|z_n||au_n+bv_n|\,\mathrm{d}x \\
     &\leq  \theta \beta_0 \min\{a, b\}
\Big(\int_{\mathbb{R}^N}|z_n|^2\,\mathrm{d}x\Big)^{1/2}
 \Big(\int_{\mathbb{R}^N}|au_n+bv_n|^2\,\mathrm{d}x\Big)^{1/2} \\
     &\leq  \theta \min\{a, b\}\|z_n\|\|au_n+bv_n\|_{E_V} \\
     &=  \theta \min\{a, b\}\|z_n\|\frac{2ab}{\sqrt{a^2+b^2}}\|\hat{z}_n\| \\
     &\leq  \theta \frac{2ab \min\{a, b\}}{\sqrt{a^2+b^2}}
\times \frac{2ab}{\sqrt{a^2+b^2}\min\{a, b\}}\|\hat{z}_n \|^2  \\
     &=  \theta \frac{4a^2b^2}{a^2+b^2}\|\hat{z}_n\|^2.
\end{aligned}
 \end{equation}
 On the other hand, by (W5), \eqref{2.3}, \eqref{3.7}, \eqref{3.8}
and H\"older inequality, one obtains that
 \begin{equation}\label{3.10}
\begin{aligned}
   &   \int_{\mathbb{R}^N \setminus \Omega_n}\frac{|bW_{u}(x, u_n, v_n)
+aW_{v}(x, u_n, v_n)||au_n+bv_n|}{\|z_n\|^2}\,\mathrm{d}x \\
   &=   \int_{\mathbb{R}^N \setminus  \Omega_n}\frac{|bW_{u}(x, u_n, v_n)
+aW_{v}(x, u_n, v_n)||\xi_n||a\varphi_n+b\psi_n|}{|z_n|}\,\mathrm{d}x \\
   & \leq  \Big[\int_{\mathbb{R}^N \setminus  \Omega_n}
\Big(\frac{|aW_{u}(x, u_n, v_n)+bW_v(x, u_n, v_n)|}{|z_n|}\Big)^{\kappa}
\,\mathrm{d}x\Big]^{1/\kappa}
              \\
 &\quad\times \Big(\int_{\mathbb{R}^N \setminus
\Omega_n}|\xi_n|^{2\kappa'}\,\mathrm{d}x\Big)^{1/2\kappa'}
\Big(\int_{\mathbb{R}^N \setminus  \Omega_n}|a\varphi_n+b\psi_n|^{2\kappa'}\,
\mathrm{d}x\Big)^{1/2\kappa'}  \\
 &\leq  \Big(\int_{\mathbb{R}^N \setminus  \Omega_n}\alpha_0\widetilde{W}(x, z_n)
\,\mathrm{d}x\Big)^{1/\kappa}
             \|\xi_n\|_{2\kappa'}\|a\varphi_n+b\psi_n\|_{2\kappa'} \\
   &\leq   (c_*\alpha_0+o(1))^{1/\kappa}\left\|\xi_n\right\|_{2\kappa'}
\|a\varphi_n+b\psi_n\|_{2\kappa'} \\
   &\leq   (c_*\alpha_0+o(1))^{1/\kappa}2^{(\kappa'-1)/{2\kappa'}}
\gamma_{_{2\kappa'}}\left\|\xi_n\right\|\|a\varphi_n+b\psi_n\|_{2\kappa'} \\
   &=   o(1).
\end{aligned}
\end{equation}
 Combining \eqref{3.9} with \eqref{3.10} and using \eqref{2.5}, and \eqref{3.8},
we have
 \begin{align}
&\frac{4a^2b^2}{a^2+b^2}+o(1) \nonumber \\
     &=  \frac{4a^2b^2}{a^2+b^2} -2ab\frac{ \langle\Phi'(z_n),
\hat{z}_n\rangle}{\|\hat{z}_n\|^2}  \nonumber \\
     &=  \frac{1}{{\|\hat{z}_n\|^2}}\int_{\mathbb{R}^N}{\left[bW_{u}
(x, u_n, v_n)+aW_{v}(x, u_n, v_n)\right](au_n+bv_n)}\,\mathrm{d}x \nonumber\\
     &=  \frac{1}{{\|\hat{z}_n\|^2}}\int_{\Omega_n}\left[bW_{u}(x, u_n, v_n)
+aW_{v}(x, u_n, v_n)\right](au_n+bv_n)\,\mathrm{d}x \nonumber\\
     &\quad +\frac{1}{{\|\hat{z}_n\|^2}}\int_{\mathbb{R}^N \setminus \Omega_n}
\left[bW_{u}(x, u_n, v_n)+aW_{v}(x, u_n, v_n)\right](au_n+bv_n)\,\mathrm{d}x \nonumber\\
     &\leq  \theta\frac{4a^2b^2}{a^2+b^2}+o(1). \label{3.11}
\end{align}
This contradiction shows that $\delta \neq 0$.

If necessary going to a subsequence, we may assume the existence of 
$k_n\in \mathbb{Z}^N$ such that
 $\int_{B_{1+\sqrt{N}}(k_n)}|\hat{\xi}_n|^2dx > \frac{\delta}{2}$.
 Since $|\hat{\xi}_n|^2=\frac{a^2+b^2}{4a^2b^2}|a\varphi_n+b\psi_n|^2$, 
one can get that
 $$
\int_{B_{1+\sqrt{N}}(k_n)}|a\varphi_n+b\psi_n|^2dx > \frac{2a^2b^2}{a^2+b^2}\delta.
$$
 Let us define $\tilde{\varphi}_n(x)=\varphi_n(x+k_n)$, 
$\tilde{\psi}_n(x)=\psi_n(x+k_n)$ so that
 \begin{equation}\label{3.12}
   \int_{B_{1+\sqrt{N}}(0)}|a\tilde{\varphi}_n+b\tilde{\psi}_n|^2dx 
> \frac{2a^2b^2}{a^2+b^2}\delta.
 \end{equation}
 Now we define $\tilde{u}_n(x)=u_n(x+k_n)$, $\tilde{v}_n(x)=v_n(x+k_n)$,
 then $\tilde{\varphi}_n=\tilde{u}_n/\|z_n\|$, $\tilde{\psi}_n=\tilde{v}_n/\|z_n\|$.
 Passing to a subsequence, we have
 $a\tilde{\varphi}_n(x)+b\tilde{\psi}_n(x) 
\rightharpoonup a\tilde{\varphi}(x)+b\tilde{\psi}(x)$ in $E_{V}$,
 $a\tilde{\varphi}_n(x)+b\tilde{\psi}_n(x) 
\to a\tilde{\varphi}(x)+b\tilde{\psi}(x)$ in
 $L^{s}_{\rm loc}(\mathbb{R}^{N})$, $2\le s<2^*$
 and
 $a\tilde{\varphi}_n(x)+b\tilde{\psi}_n(x) \to a\tilde{\varphi}(x)+b\tilde{\psi}(x)$ 
a.e. on $\mathbb{R}^{N}$.
 Obviously, \eqref{3.12} implies that $a\tilde{\varphi}(x)+b\tilde{\psi}(x) \ne 0$.
 Since $\|z_n\|\to \infty$, for a.e. 
$x\in \{y\in \mathbb{R}^N : a\tilde{\varphi}(y)+b\tilde{\psi}(y)\ne 0\}:=\Omega$, 
we have
 $$
 \lim_{n\to\infty}|a\tilde{u}_n(x)+b\tilde{v}_n(x)|
=\lim_{n\to\infty}\|z_n\||a\tilde{\varphi}_n(x)+b\tilde{\psi}_n(x)|= +\infty.
 $$
 By (W3'), \eqref{3.6} and Fatou's lemma, we have
 \begin{align*}
  0 &=  \lim_{n\to\infty}\frac{c_*+o(1)}{\|z_n\|^2} 
= \lim_{n\to\infty}\frac{\Phi(z_n)}{\|z_n\|^2}
\\
&=  \lim_{n\to\infty}\left[\frac{1}{2}\|\xi_n^+\|^2
-\frac{1}{2}\|\xi_n^-\|^2
-\int_{\mathbb{R}^N}\frac{W(x, z_n)}{\|z_n\|^2}\,\mathrm{d}x\right]
\\
&\leq   \lim_{n\to\infty}
\left[\frac{1}{2}\|\xi_n^+\|^2
-\frac{1}{2}\|\xi_n^-\|^2
             -\int_{\mathbb{R}^N}\frac{W(x, z_n)}{|au_n+bv_n|^2}|a\varphi_n
+b\psi_n|^2\,\mathrm{d}x\right]\\
    &=  \lim_{n\to\infty}\left[\frac{1}{2}\|\xi_n\|^2
             -\int_{\mathbb{R}^N}\frac{W(x+k_n, \tilde{z}_n)}{|a\tilde{u}_n
+b\tilde{v}_n|^2}|a\tilde{\varphi}_n+b\tilde{\psi}_n|^2\,\mathrm{d}x\right]\\
    &\leq  \frac{1}{2}-\int_{\Omega}\liminf_{n\to\infty}
\Big[\frac{W(x, \tilde{u}_n, \tilde{v}_n)}
             {|a\tilde{u}_n+b\tilde{v}_n|^2}|a\tilde{\varphi}_n
+b\tilde{\psi}_n|^2\Big]\,\mathrm{d}x =-\infty,
 \end{align*}
 which is a contradiction. Thus $\{z_n\}$ is bounded in $E$.
\end{proof}

\begin{proof}[Proof of Theorem \ref{thm1.2}]
 Applying Lemmas \ref{lem3.4} and \ref{lem3.5}, 
we deduce that there exists a bounded 
sequence $\{z_n\}=\{(u_n, v_n)\}\subset E$ satisfying \eqref{3.5}.
 Thus there exists a constant $C_2>0$ such that $\|z_n\|_2\le C_2$.
 By the Lion's concentration compactness principle 
(\cite{PL} or \cite [Lemma 1.21]{Wi}), one can rule out the case of vanishing.
 So nonvanishing occurs. Using a standard translation argument, 
we can obtain a nontrivial solution of \eqref{hs}.
\end{proof}

\subsection*{Acknowledgments}
This work is partially supported by the NNSF of China  (No. 11171351),
by the Construct Program of the Key Discipline in Hunan Province, and
by the Hunan Provincial Innovation Foundation for Postgraduates.


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\end{document}
