\documentclass[reqno]{amsart}
\usepackage{hyperref}


\AtBeginDocument{{\noindent\small
\emph{Electronic Journal of Differential Equations},
Vol. 2014 (2014), No. 266, pp. 1--19.\newline
ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu
\newline ftp ejde.math.txstate.edu}
\thanks{\copyright 2014 Texas State University - San Marcos.}
\vspace{9mm}}

\begin{document}
\title[\hfilneg EJDE-2014/266\hfil Limit of minimax values]
{Limit of minimax values under $\Gamma$-convergence}

\author[M. Degiovanni, M. Marzocchi \hfil EJDE-2014/266\hfilneg]
{Marco Degiovanni, Marco Marzocchi}  % in alphabetical order

\address{Marco Degiovanni \newline
 Dipartimento di Matematica e Fisica\\
 Universit\`a Cattolica del Sacro Cuore\\
 Via dei Musei 41\\
 25121 Brescia, Italy}
\email{marco.degiovanni@unicatt.it}

\address{Marco Marzocchi \newline
 Dipartimento di Matematica e Fisica\\
 Universit\`a Cattolica del Sacro Cuore\\
 Via dei Musei 41\\
 25121 Brescia, Italy}
\email{marco.marzocchi@unicatt.it}

\thanks{Submitted November 15, 2014. Published December 25, 2014.}
\subjclass[2000]{35P30, 49R05, 58E05}
\keywords{Nonlinear eigenvalues; variational convergence;
$p$-Laplace operator; \hfill\break\indent total variation}

\begin{abstract}
 We consider a sequence of minimax values related to a class
 of even functionals. We show the continuous dependence of these
 values under the $\Gamma$-convergence of the functionals.
\end{abstract}

\maketitle
\numberwithin{equation}{section}
\newtheorem{theorem}{Theorem}[section]
\newtheorem{lemma}[theorem]{Lemma}
\newtheorem{proposition}[theorem]{Proposition}
\newtheorem{definition}[theorem]{Definition}
\newtheorem{corollary}[theorem]{Corollary}
\allowdisplaybreaks

\section{Introduction}

Let $X$ be a Banach space and $f,g:X\to\mathbb{R}$ two functions
of class $C^1$.
Assume also that $f$ and $g$ are even and positively homogeneous
of the same degree.

Several results of critical point theory
(see \cite{bartsch1993, krasnoselskii1964,rabinowitz1986, willem1996})
are based on the
construction of a sequence of minimax values $(c_m)$ given by
\[
c_m = \inf_{K\in \mathcal{K}_s^{(m)}}\, \max_{u\in K} f(u)\,,
\]
where $\mathcal{K}_s^{(m)}$ is the family of compact and symmetric
subsets $K$ of
\[
\{u\in X:g(u)=1\}
\]
such that $\operatorname{i}(K)\geq m$ and $\operatorname{i}$ is a topological index
which takes into account the symmetry of $f$ and $g$.
Typical examples are the Krasnosel'ski\u{\i} genus
(see e.g.~\cite{krasnoselskii1964, rabinowitz1986, willem1996})
and the $\mathbb{Z}_2$-cohomological index
(see~\cite{fadell_rabinowitz1977, fadell_rabinowitz1978}).
More general examples are contained in \cite{bartsch1993}.

A natural question concerns the behavior of the minimax
values $c_m$ when $f$ and $g$ are substituted by two sequences
$(f_h)$ and $(g_h)$ converging in a suitable sense.
This problem has been recently treated
(see \cite{champion_depascale2007, littig_schuricht2014,
parini2011} and references therein) in the setting of
homogenization problems and limit behavior of the
$p$-Laplace operator.

As pointed out in \cite{champion_depascale2007}, one has
\[
c_m = \inf_{K\in\mathcal{K}} \mathcal{F}^{(m)}(K)\,,
\]
where $\mathcal{K}$ is the family of nonempty compact subsets
$K$ of $X$ and $\mathcal{F}^{(m)}:\mathcal{K}\to\overline{\mathbb{R}}$ is defined as
\[
\mathcal{F}^{(m)}(K) =
\begin{cases}
\max_{u\in K} f(u)
&\text{if } K\in \mathcal{K}_s^{(m)}\,,\\
+\infty
&\text{otherwise}\,.
\end{cases}
\]
In this way the behavior of minimax values of $f$ is reduced to
that of infimum values for the related functionals $\mathcal{F}^{(m)}$ and
the convergence of infima has been extensively studied in the
setting of $\Gamma$-convergence of functionals
(see e.g.~\cite{attouch1984, dalmaso1993}).

Let us mention that the behavior of critical values under
$\Gamma$-convergence has been already studied also
in \cite{ambrosetti_sbordone1976, degiovanni_eisner2000,
groli2003, jerrard_sternberg2009}.

A goal of this article is to answer a question raised
in \cite[Remark~5.2]{champion_depascale2007}, concerning
the relation between the $\Gamma$-convergence of the functionals
$(f_h)$ and that of the related functionals $(\mathcal{F}_h^{(m)})$
(see the next Corollaries~\ref{cor:limval} and \ref{cor:limconcr}).
By the way, \cite[Remark~5.2]{champion_depascale2007} seemed to
suggest a negative answer, while we will show that it is
affirmative.

In particular, our results allow to treat the convergence of the
minimax eigenvalues $\lambda$ associated to nonlinear problems of
the form
\begin{gather*}
- \Delta_p u= \lambda V_p |u|^{p-2}u \quad\text{in $\Omega$}\,,\\
u=0 \quad\text{on $\partial\Omega$}\,,
\end{gather*}
where $\Omega$ is a (possibly unbounded) open subset on $\mathbb{R}^N$,
$1\leq p<N$ and the weight $V_p$ is possibly indefinite.
As usual, in the case $p=1$ a suitable relaxed interpretation
of the problem has to be introduced.
For $1<p<N$ fixed, eigenvalue problems of this kind have been
treated in \cite{lucia_schuricht2013, szulkin_willem1999}.
For $p=1$ with $\Omega$ bounded and $V_1(x)=1$,
we refer the reader
to \cite{chang2009, degiovanni_magrone2009, milbers_schuricht2010,
milbers_schuricht2011, milbers_schuricht2013}.

In Theorem~\ref{thm:convlambda} we will show the right continuity with
respect to $p$ of the minimax eigenvalues.
When $\Omega$ is bounded and $V_p(x)=1$,
the problem has been already treated
in \cite{champion_depascale2007, littig_schuricht2014,parini2011}.

A related question concerns, for $f$ and $g$ fixed, the
dependence of the minimax values on the topology of the space.
Actually, in the setting of classical critical point theory
the topology is chosen so that $f$ and $g$ are of class $C^1$,
while minimization methods and $\Gamma$-convergence
techniques prefer weaker topologies in which the sets
\[
\{u\in X:f(u)\leq b\,,\,g(u)=1\}
\]
are compact, but then $f$ cannot be continuous.

In Corollary \ref{cor:norm} we prove, under quite general
assumptions, that the minimax values are not affected by a
change of topology.
Then in Theorem~\ref{thm:change} we show an application in the
setting of functionals of the Calculus of variations.

\section{Review on variational convergence}
\label{sect:rec}

Throughout this section, $X$ will denote a metrizable topological
space.

\begin{definition} \rm
Let $(f_h)$ be a sequence of functions from $X$ to $\overline{\mathbb{R}}$.
According to \cite[Definition~4.1]{dalmaso1993}, we define
two functions
\[
\Big(\Gamma-\liminf_{h\to\infty} f_h\Big):
X\to\overline{\mathbb{R}}\,,\quad
\Big(\Gamma-\limsup_{h\to\infty} f_h\Big): X\to\overline{\mathbb{R}}\,,
\]
as
\begin{gather*}
\Big(\Gamma-\liminf_{h\to\infty} f_h\Big)(u)
= \sup_{U\in \mathcal{N}(u)}
\Big[\liminf_{h\to\infty}
\bigl(\inf\{f_h(v):v\in U\}
\bigr)\Big]\,,\\
\Big(\Gamma-\limsup_{h\to\infty} f_h\Big)(u)
=\sup_{U\in \mathcal{N}(u)}
\Big[\limsup_{h\to\infty}
\bigl(\inf\{f_h(v):v\in U\}\bigr)\Big]\,,
\end{gather*}
where $\mathcal{N}(u)$ denotes the family of neighborhoods
of $u$.
\end{definition}

If at some $u\in X$ we have
\[
\Big(\Gamma-\liminf_{h\to\infty} f_h\Big)(u)
= \Big(\Gamma-\limsup_{h\to\infty} f_h\Big)(u) \,,
\]
we simply write
\[
\Big(\Gamma-\lim_{h\to\infty} f_h\Big)(u)\,.
\]
Let us also recall \cite[Propositions 8.1 and 7.1]{dalmaso1993}.

\begin{proposition}
\label{prop:gammaseq}
The following facts hold:
\begin{itemize}
\item[(a)]
for every $u\in X$ and every sequence $(u_h)$ converging to
$u$ in $X$, it holds
\[
\Big(\Gamma-\liminf_{h\to\infty} f_h\Big)(u) \leq
\liminf_{h\to\infty} f_h(u_h)\,;
\]
\item[(b)]
for every $u\in X$ there exists a sequence $(u_h)$
converging to $u$ in $X$ such that
\[
\Big(\Gamma-\liminf_{h\to\infty} f_h\Big)(u) =
\liminf_{h\to\infty} f_h(u_h)\,;
\]
\item[(c)]
for every $u\in X$ and every sequence $(u_h)$ converging to
$u$ in $X$, it holds
\[
\Big(\Gamma-\limsup_{h\to\infty} f_h\Big)(u) \leq
\limsup_{h\to\infty} f_h(u_h)\,;
\]
\item[(d)]
for every $u\in X$ there exists a sequence $(u_h)$
converging to $u$ in $X$ such that
\[
\Big(\Gamma-\limsup_{h\to\infty} f_h\Big)(u) =
\limsup_{h\to\infty} f_h(u_h)\,;
\]
\item[(e)]
we have
\[
\inf_{X}\,
\Big(\Gamma-\limsup_{h\to\infty} f_h\Big)
\geq \limsup_{h\to\infty} \Big(\inf_{X} f_h\Big)\,.
\]
\end{itemize}
\end{proposition}

Now let us recall from \cite[Definition~5.2]{degiovanni1990-ampa}
a variant of the notion of equicoercivity.

\begin{definition} \rm
A sequence $(f_h)$ of functions from $X$ to $\overline{\mathbb{R}}$
is said to be \emph{asymptotically equicoercive} if,
for every strictly increasing sequence $(h_n)$ in $\mathbb{N}$
and every sequence $(u_n)$ in $X$ satisfying
\[
\sup_{n\in\mathbb{N}} f_{h_n}(u_n) < +\infty\,,
\]
there exists a subsequence $(u_{n_j})$ converging in $X$.
\end{definition}

The next result is a simple variant
of \cite[Proposition~7.2]{dalmaso1993}.
We prove it for reader's convenience.

\begin{proposition} \label{prop:liminfinf}
If $(f_h)$ is asymptotically equicoercive, we have
\[
\inf_{X}\,
\Big(\Gamma-\liminf_{h\to\infty} f_h\Big)
\leq \liminf_{h\to\infty} \Big(\inf_{X} f_h\Big)\,.
\]
\end{proposition}

\begin{proof}
Without loss of generality, we may assume that
\[
\liminf_{h\to\infty}
\Big(\inf_{X} f_h\Big) < +\infty\,.
\]
Let
\[
b > \liminf_{h\to\infty}
\Big(\inf_{X} f_h\Big)
\]
and let $(f_{h_n})$ be a subsequence such that
\[
\sup_{n\in\mathbb{N}}
\Big(\inf_{X} f_{h_n}\Big) < b\,.
\]
Let $u_n\in X$ be such that
\[
f_{h_n}(u_n) < b\,.
\]
Then a subsequence $(u_{n_j})$ is convergent to some $u$ in $X$.
We infer that
\[
\inf_X \Big(\Gamma-\liminf_{h\to\infty} f_h\Big)
\leq \Big(\Gamma-\liminf_{h\to\infty} f_h\Big)(u) \leq
\liminf_{j\to\infty} f_{h_{n_j}}(u_{n_j}) \leq b
\]
and the assertion follows by the arbitrariness of $b$.
\end{proof}

In the following, we  denote by $\mathcal{K}$ be the family
of nonempty compact subsets of $X$.
If $d$ is a compatible distance on $X$, the associated
\emph{Hausdorff distance} $d_{\mathcal{H}}$ is defined on $\mathcal{K}$ as
\[
d_{\mathcal{H}}(K_1,K_2) = \max\Big\{
\max_{u\in K_1}\,d(u,K_2)\,,\,
\max_{v\in K_2}\,d(v,K_1)\Big\}\,.
\]
The \emph{$\mathcal{H}$-topology} is the topology on $\mathcal{K}$
induced by $d_{\mathcal{H}}$.
Recall that the $\mathcal{H}$-topology just depends on the
topology of $X$, not on the distance $d$.
Therefore~$\mathcal{K}$ has an intrinsic structure of metrizable
topological space.

\begin{proposition} \label{prop:coerchausd}
Let $(f_h)$ be a sequence of functions from $X$ to $\overline{\mathbb{R}}$
and define $\mathcal{F}_h:\mathcal{K}\to\overline{\mathbb{R}}$ as
\[
\mathcal{F}_h(K) = \sup_K f_h\,.
\]
Then $(f_h)$ is asymptotically equicoercive if and only if
$(\mathcal{F}_h)$ is asymptotically equicoercive with respect to the
$\mathcal{H}$-topology.
\end{proposition}

\begin{proof}
Assume that $(f_h)$ is asymptotically equicoercive and
let $(h_n)$ be a strictly increasing sequence in $\mathbb{N}$
and $(K_n)$ a sequence in $\mathcal{K}$ such that
\[
\sup_{n\in\mathbb{N}} \mathcal{F}_{h_n}(K_n) < +\infty\,.
\]
We claim that
$\overline{\cup_{n\in\mathbb{N}} K_n}$ is compact.

Actually, given a compatible distance $d$ on $X$,
let $(u_j)$ be a sequence in this set and let
$v_j\in K_{n_j}$ be such that $d(v_j,u_j)\to 0$.
Up to a subsequence, either $(n_j)$ is constant or
$(n_j)$ is strictly increasing.
In the former case it is obvious that $(v_j)$ admits a
convergent subsequence, while in the latter case this is due
to the asymptotic equicoercivity of $(f_h)$.
In any case, $(u_j)$ also admits a convergent subsequence.

By Blaschke's theorem (see e.g.~\cite[Theorem~4.4.15]{ambrosio_tilli2004})
we infer that the image of the sequence $(K_n)$ is included in a
compact subset of $\mathcal{K}$ and the assertion follows.

Conversely, assume that $(\mathcal{F}_h)$ is asymptotically
equicoercive and let $(h_n)$ and $(u_n)$ be such that
\[
\sup_{n\in\mathbb{N}} f_{h_n}(u_n) < +\infty\,.
\]
If we set $K_n=\{u_n\}$, then $(K_n)$ is a sequence in
$\mathcal{K}$ with
\[
\sup_{n\in\mathbb{N}} \mathcal{F}_{h_n}(K_n) < +\infty\,.
\]
If $(K_{n_j})$ is convergent in $\mathcal{K}$, then
$(u_{n_j})$ is convergent in $X$.
\end{proof}

\section{Index theory and minimax values}
\label{sect:minimax}

In this article, we  consider an index $\operatorname{i}$ with the
following properties:
\begin{itemize}
\item[(i)]
$\operatorname{i}(K)$ is an integer greater or equal than $1$ and is defined
whenever $K$ is a nonempty, compact and symmetric subset of a
topological vector space such that $0\not\in K$;

\item[(ii)]
if $X$ is a topological vector space and
$K\subseteq X\setminus\{0\}$ is compact, symmetric and nonempty,
then there exists an open subset $U$ of $X\setminus\{0\}$
such that $K\subseteq U$ and
\[
\operatorname{i}(\widehat{K}) \leq \operatorname{i}(K)
\text{ for any compact, symmetric and nonempty $\widehat{K}\subseteq U$}\,;
\]

\item[(iii)]
if $X, Y$ are two topological vector spaces,
$K\subseteq X\setminus\{0\}$ is compact, symmetric and nonempty
and $\pi:K\to Y\setminus\{0\}$ is continuous and
odd, we have
\[
\operatorname{i}(\pi(K)) \geq \operatorname{i}(K)\,.
\]
\end{itemize}
Well known examples are the Krasnosel'ski\u{\i} genus
(see e.g.~\cite{krasnoselskii1964, rabinowitz1986})
and the $\mathbb{Z}_2$-cohomo\-logical index
(see \cite{fadell_rabinowitz1977, fadell_rabinowitz1978}).
More general examples are contained in \cite{bartsch1993}.

In the following, if $X$ is a topological vector space we
will denote by $\mathcal{K}_s$ the family of nonempty, compact and
symmetric subsets of $X\setminus\{0\}$.

If $X$ is just a vector space, we denote by $\mathcal{K}_{s,F}$
the family of nonempty, compact and symmetric subsets $K$
of some finite dimensional subspace of $X$ such that $0\not\in K$.
Of course, we mean that the subspace is endowed with the
unique topology which makes it a topological vector space.

Let us point out a situation in which the behavior of
$\operatorname{i}$ on $\mathcal{K}_s$ is completely determined by that
on $\mathcal{K}_{s,F}$.

\begin{proposition} \label{prop:iusc}
If $X$ is a metrizable and locally convex topological vector
space, the following facts hold:
\begin{itemize}
\item[(a)]
for every $K\in \mathcal{K}_s$ and every sequence $(K_h)$ in $\mathcal{K}_s$
converging to $K$ with respect to the $\mathcal{H}$-topology,
it holds
\[
\operatorname{i}(K) \geq \limsup_{h\to\infty} \operatorname{i}(K_h)\,;
\]
\item[(b)]
for every $K\in \mathcal{K}_s$ there exists a sequence $(K_h)$ in
$\mathcal{K}_{s,F}$ converging to $K$ with respect to the
$\mathcal{H}$-topology such that
\[
\operatorname{i}(K) = \lim_{h\to\infty} \operatorname{i}(K_h)\,.
\]
\end{itemize}
\end{proposition}

\begin{proof}
Assertion (a) easily follows from  property (ii) of
the index $\operatorname{i}$.
To prove (b), consider a compatible distance $d$ on $X$
such that
$d(-u,-v) = d(u,v)$
and such that $B_r(u)$ is convex for any
$u\in X$ and $r>0$ (see e.g.~\cite{rudin1991}).

Given $K\in\mathcal{K}_s$, let $r>0$ with $K\cap B_r(0)=\emptyset$
and let $F\subseteq K$ be a finite set such that
\[
K\subseteq \cup_{v\in F} B_r(v)\,.
\]
By substituting $F$ with $F\cup(-F)$, we may assume
that $F$ is symmetric.
For every $v\in F$, let $\vartheta_v:X\to [0,1]$
be a continuous function such that
\begin{gather*}
\vartheta_v(u)=0 \quad\text{whenever $u\not\in B_r(v)$}\,,\\
\sum_{v\in F} \vartheta_v(u) = 1\quad\text{for all $u\in K$}\,,\\
\sum_{v\in F}\, \vartheta_v(u) \leq 1 \quad\text{for all $u\in X$}\,,\\
\vartheta_{-v}(u) = \vartheta_v(-u)
\quad\text{for all $v\in F$ and $u \in X$}\,.
\end{gather*}
Since $0\in\operatorname{conv}(F)$, we can define an odd and continuous map
$\pi:X\to \operatorname{conv}(F)$ as
\[
\pi(u)=\sum_{v\in F}\,\vartheta_v(u)\, v \,.
\]
For every $u\in K$ and $v\in F$, we have
either $\vartheta_v(u)=0$ or $d(v,u)<r$, whence
\[
\pi(u)\in \operatorname{conv}(\{v\in F:d(v,u)<r\})
\quad\text{for all $u\in K$}\,,
\]
which implies
\[
d(\pi(u),u)<r \quad\text{for all $u\in K$}\,.
\]
In particular, we have $0\not\in \pi(K)$,
$\pi(K)\in\mathcal{K}_{s,F}$, $d_{\mathcal{H}}(\pi(K),K)<r$ and
\[
\operatorname{i}(\pi(K)) \geq \operatorname{i}(K)
\]
by  property (iii) of the index $\operatorname{i}$.
Then assertion (b) follows.
\end{proof}

In an equivalent way, one can say that
$\operatorname{i}:\mathcal{K}_s\to[1,+\infty[$ is the upper semicontinuous
envelope of its restriction to $\mathcal{K}_{s,F}$.

Now let $X$ be a metrizable and locally convex topological
vector space and let $f:X\to[0,+\infty]$ and
$g:X\setminus\{0\}\to \mathbb{R}$ be two functions
such that:
\begin{itemize}
\item[(a)]
$f$ and $g$ are even and positively homogeneous of degree $1$;
\item[(b)]
$f$ is convex;
\item[(c)]
for every $b\in \mathbb{R}$, the restriction of $g$ to
$\{u\in X\setminus\{0\}:f(u) \leq b\}$
is continuous.
\end{itemize}
For every $m\geq 1$, one can define a minimax value $c_m$ as
\[
c_m = \inf_{K\in\mathcal{K}_s^{(m)}}\,\sup_K f \,,
\]
where $\mathcal{K}_s^{(m)}$ is the family $K$'s in $\mathcal{K}_s$ such that
\[
K\subseteq \left\{u\in X\setminus\{0\}:g(u)=1\right\}
\,,\quad \operatorname{i}(K)\geq m\,,
\]
with the convention
\[
\inf_{K\in\mathcal{K}_s^{(m)}}\,\sup_K f = +\infty\quad
\text{if }\mathcal{K}_s^{(m)}=\emptyset.
\]

One can also consider
\[
\inf_{K\in\mathcal{K}_{s,F}^{(m)}}\,\sup_K f \,,
\]
where $\mathcal{K}_{s,F}^{(m)}$ is the family $K$'s in $\mathcal{K}_{s,F}$ such that
\[
K\subseteq \left\{u\in X\setminus\{0\}:g(u)=1\right\}
\,,\quad \operatorname{i}(K)\geq m\,,
\]
with analogous convention if
$\mathcal{K}_{s,F}^{(m)}=\emptyset$.

We aim to show that the two values agree, so that the topology
of $X$ plays a role just in assumption~$(c)$.
%
\begin{theorem} \label{thm:minimaxfin}
For every integer $m\geq 1$ we have
\[
\inf_{K\in\mathcal{K}_s^{(m)}}\,\sup_K f =
\inf_{K\in\mathcal{K}_{s,F}^{(m)}}\,\sup_K f \,.
\]
\end{theorem}

\begin{proof}
Of course, we have
\[
\inf_{K\in\mathcal{K}_s^{(m)}}\,\sup_K f \leq
\inf_{K\in\mathcal{K}_{s,F}^{(m)}}\,\sup_K f \,.
\]
To prove the converse, let $K\in\mathcal{K}_s^{(m)}$ with
\[
\sup_K f <+\infty
\]
and let $b\in \mathbb{R}$ with
\[
b > \sup_K f \,.
\]
Consider a compatible distance $d$ on $X$ as in the
proof of Proposition~\ref{prop:iusc}.
By assumption~$(c)$ we can find $r>0$ such that
$K\cap B_r(0)=\emptyset$ and
\begin{equation}\label{eq:minimaxfin}
\begin{aligned}
&g(w)>0\,,\quad \sup_K f < b\,g(w) \\
&\text{whenever $w\in X$ with $d(w,K)<r$ and $f(w) < b$}\,.
\end{aligned}
\end{equation}
Now let $F$, $\vartheta_v$ and $\pi$ be as in the
proof of Proposition~\ref{prop:iusc}, so that
$\pi(K)\in \mathcal{K}_{s,F}$ with $\operatorname{i}(\pi(K))\geq \operatorname{i}(K)\geq m$
and $d(\pi(u),u)<r$ with
\[
\pi(u)\in \operatorname{conv}(\{v\in F:d(v,u)<r\})
\quad\text{for all $u\in K$}\,.
\]
Since $f$ is convex, for every $u\in K$
there exists $v\in F$ such that $d(v,u)<r$ and
$f(\pi(u))\leq f(v)<b$, whence $g(\pi(u))>0$ and
\[
\frac{f(\pi(u))}{g(\pi(u))} \leq
\frac{f(v)}{g(\pi(u))} < b
\]
by \eqref{eq:minimaxfin}.
Since $g$ is even and continuous on $\pi(K)$ by
assumption~(c), if we set
\[
\widehat{K} = \big\{\frac{\,\pi(u)}{g(\pi(u))}: u\in K\big\}\,,
\]
we have $\widehat{K}\in\mathcal{K}_{s,F}^{(m)}$ with
\[
\sup_{\widehat{K}} f \leq b
\]
and the assertion follows by the arbitrariness of $b$.
\end{proof}

\begin{corollary}\label{cor:norm}
Under the assumptions of Theorem~\ref{thm:minimaxfin},
let $Y$ be a vector subspace of $X$ such that
\[
\left\{u\in X\setminus\{0\}:
\text{$g(u)>0$ and $f(u)<+\infty$}\right\} \subseteq Y
\]
and let $\tau_Y$ be any topology on $Y$ which makes $Y$
a metrizable and locally convex topological vector space
such that, for every $b\in \mathbb{R}$, the restriction of $g$ to
\[
\{u\in Y\setminus\{0\}:f(u)\leq b\}
\]
is $\tau_Y$-continuous.

Then the minimax values defined in the space $Y$ agree with
those defined in the originary space $X$.
\end{corollary}

\begin{proof}
First of all, there is no change if $X$ is substituted by $Y$
endowed with the topology of~$X$.
By Theorem~\ref{thm:minimaxfin} it is equivalent to consider
the classes $\mathcal{K}_{s,F}^{(m)}$ which do not change, when
passing from the topology of $X$ to $\tau_Y$.
\end{proof}


\section{Variational convergence of functions and sup-functions}
\label{sect:est}

Let $X$ be a metrizable and locally convex topological vector
space and, for every $h\in \mathbb{N}$, let $f_h:X\to[0,+\infty]$
and $g_h:X\setminus\{0\}\to \mathbb{R}$ be two functions such that:
\begin{itemize}
\item[(a)]
$f_h$ and $g_h$ are both even and positively homogeneous of
degree $1$;
\item[(b)]
$f_h$ is convex;
\item[(c)]
for every $b\in \mathbb{R}$, the restriction of $g_h$ to
$\left\{u\in X\setminus\{0\}:f_h(u) \leq b\right\}$
is continuous.
\end{itemize}
For any integer $m\geq 1$, denote by $\mathcal{K}_{s,h}^{(m)}$
the family of nonempty, compact and symmetric subsets~$K$ of
\[
\left\{u\in X\setminus\{0\}:g_h(u)=1\right\}
\]
such that $\operatorname{i}(K)\geq m$ and define
$\mathcal{F}_h^{(m)}:\mathcal{K}\to[0,+\infty]$ as
\[
\mathcal{F}_h^{(m)}(K) =\begin{cases}
\sup_K f_h
&\text{if $K\in \mathcal{K}_{s,h}^{(m)}$}\,,\\
+\infty
&\text{otherwise}\,.
\end{cases}
\]
The set $\mathcal{K}$ will be endowed with the $\mathcal{H}$-topology.

Let also $f:X\to[0,+\infty]$ and
$g:X\to \mathbb{R}$ be two
even functions such that $g(0)=0$
and define $\mathcal{K}_s^{(m)}\subseteq\mathcal{K}$ and
$\mathcal{F}^{(m)}:\mathcal{K}\to[0,+\infty]$ in an analogous way.

\begin{theorem} \label{thm:limsup}
Assume that
\[
f(u) \geq \Big(\Gamma-\limsup_{h\to\infty} f_h\Big)(u)
\quad\text{for all $u\in X$}
\]
and that, for every strictly increasing sequence
$(h_n)$ in $\mathbb{N}$ and every sequence $(u_n)$ in $X\setminus\{0\}$
converging to $u\neq 0$ such that
\[
\sup_{n\in\mathbb{N}} f_{h_n}(u_n) < +\infty\,,
\]
it holds
\[
g(u) = \lim_{n\to\infty} g_{h_n}(u_n) \,.
\]
Then, for every $m\geq 1$, we have
\begin{gather*}
\mathcal{F}^{(m)}(K)\geq \Big(\Gamma-\limsup_{h\to\infty} \mathcal{F}_h^{(m)}\Big)(K)
\quad\text{for all $K\in\mathcal{K}$}\,,\\
\inf_{K\in\mathcal{K}} \mathcal{F}^{(m)}(K) \geq \limsup_{h\to\infty}
\Big( \inf_{K\in \mathcal{K}} \mathcal{F}_h^{(m)}(K)\Big)\,,\\
\inf_{K\in\mathcal{K}_s^{(m)}} \sup_K f
\geq \limsup_{h\to\infty} \Big(\inf_{K\in\mathcal{K}_{s,h}^{(m)}} \sup_K f_h\Big)\,.
\end{gather*}
\end{theorem}

\begin{proof}
Let $m\geq 1$ and let $K\in\mathcal{K}$ with $\mathcal{F}^{(m)}(K)<+\infty$.
Then $K$ is a nonempty, compact and symmetric subset of
$\{u\in X\setminus\{0\}:g(u)=1\}$
with $\operatorname{i}(K)\geq m$.
Consider a compatible distance $d$ on $X$ as in the
proof of Proposition~\ref{prop:iusc}.

Now, let $b\in \mathbb{R}$ with
\[
b > \mathcal{F}^{(m)}(K) = \sup_K f
\]
and let $\delta>0$.
Let $\sigma\in]0,1[$ be such that
\begin{gather} \label{eq:e1}
\sup_K f+\sigma < bs\quad\text{whenever $|s-1|<\sigma$}\,,\\
\label{eq:e2}
d\big(s^{-1}\,w,u\big) < \delta
\quad\text{whenever $u\in K$, $w\in X$
 with $d(w,u)<\sigma$ and $|s-1|<\sigma$}\,.
\end{gather}
Then let $\overline{h}\in\mathbb{N}$ and $r\in]0,\sigma/2]$ be such that
$K\cap B_{2r}(0)=\emptyset$ and
\begin{equation} \label{eq:r}
|g_h(w) - 1| < \sigma
\end{equation}
for any $h\geq\overline{h}$ and any $w\in X$
with $d(w,K)<2r$ and $f_h(w) < b+\sigma$.

Again, let $F$ and $\vartheta_v$ be as in the proof
of Proposition~\ref{prop:iusc}.
Since $F$ is a finite set, by (d) of
Proposition~\ref{prop:gammaseq} we can define,
for every $h\in\mathbb{N}$,
an odd map $\psi_h:F\to X$ such that
\begin{gather*}
\lim_{h\to\infty} \psi_h(v) = v
\quad\text{for all $v \in F$}\,,\\
f(v) \geq \limsup_{h\to\infty} f_h(\psi_h(v))
\quad\text{for all $v \in F$}\,.
\end{gather*}
Without loss of generality, we assume that
\[
\text{$d(\psi_h(v),v)<r$ and $f_h(\psi_h(v))<f(v)+\sigma$
for any
$h\geq\overline{h}$ and $v\in F$}\,.
\]
Then define an odd and continuous map
$\pi_h:X\to \operatorname{conv}(\psi_h(F))$ as
\[
\pi_h(u)=\sum_{v\in F}\,\vartheta_v(u)\, \psi_h(v) \,.
\]
For every $u\in K$ and $v\in F$, we have
either $\vartheta_v(u)=0$ or $d(v,u)<r$,
hence $d(\psi_h(v),u)<2r$.
Therefore,
\[
\pi_h(u) \in \operatorname{conv}\big(
\{\psi_h(v):v\in F\,,\,\,d(\psi_h(v),u)<2r\}\big)
\quad\text{for all $u\in K$}\,,
\]
whence
\[
d(\pi_h(u),u)<2r\leq\sigma
\quad\text{for all $h\geq\overline{h}$ and $u\in K$}\,.
\]
Moreover, since $f_h$ is convex, for every $u\in K$
there exists $v\in F$ such that $d(\psi_h(v),u)<2r$ and
$f_h(\pi_h(u))\leq f_h(\psi_h(v))< f(v) + \sigma $, whence
\[
f_h(\pi_h(u)) < b+\sigma
\quad\text{for all $h\geq\overline{h}$ and $u\in K$}\,.
\]
From \eqref{eq:r}, it follows
\[
\text{$\pi_h(u)\neq 0$ and $|g_h(\pi_h(u))-1|<\sigma$}
\quad\text{for all $h\geq\overline{h}$ and $u\in K$}
\]
and $\pi_h(K)$ is a compact and symmetric subset
of $X\setminus\{0\}$ with
\[
\operatorname{i}(\pi_h(K)) \geq \operatorname{i}(K) \geq m\,.
\]
Moreover,
\[
\frac{f_h(\pi_h(u))}{g_h(\pi_h(u))} <
\frac{f(v)+\sigma}{g_h(\pi_h(u))} < b
\]
by \eqref{eq:e1} and $g_h$ is continuous and even on $\pi_h(K)$.
If we set
\[
K_h = \big\{\frac{\,\pi_h(u)}{g_h(\pi_h(u))}:
u\in K\big\}\,,
\]
we have $K_h\in\mathcal{K}_{s,h}^{(m)}$ and
\[
f_h(w) < b
\quad\text{for all $h\geq\overline{h}$ and $w\in K_h$}\,,
\]
whence
\[
\mathcal{F}_h^{(m)}(K_h) \leq b
\quad\text{for all $h\geq\overline{h}$}\,.
\]
Moreover, we have
\[
d\left(\frac{\pi_h(u)}{g_h(\pi_h(u))},u\right)
< \delta
\quad\text{for all $h\geq\overline{h}$ and $u\in K$}
\]
by \eqref{eq:e2} and \eqref{eq:r}, whence
\[
d_{\mathcal{H}}\left(K_h,K\right) < \delta
\quad\text{for all $h\geq\overline{h}$}\,.
\]
It follows
\[
\limsup_{h\to\infty}\,\Big(\inf\left\{\mathcal{F}_h^{(m)}(\widehat{K}):
d_{\mathcal{H}}\left(\widehat{K},K\right)<\delta\right\}\Big) \leq b\,,
\]
hence
\[
\Big(\Gamma-\limsup_{h\to\infty} \mathcal{F}_h^{(m)}\Big)(K)\leq b
\]
by the arbitrariness of $\delta$.
We conclude that
\[
\mathcal{F}^{(m)}(K) \geq
\Big(\Gamma-\limsup_{h\to\infty} \mathcal{F}_h^{(m)}\Big)(K)
\]
by the arbitrariness of $b$.

From (e) of Proposition~\ref{prop:gammaseq} we infer that
\[
\inf_{K\in\mathcal{K}} \mathcal{F}^{(m)}(K) \geq
\limsup_{h\to\infty} \Big(
\inf_{K\in \mathcal{K}} \mathcal{F}_h^{(m)}(K)\Big)
\]
and the last assertion is just a reformulation of this fact.
\end{proof}

\begin{theorem}\label{thm:liminf}
Assume that
\[
f(u) \leq \Big(\Gamma-\liminf_{h\to\infty} f_h\Big)(u)
\quad\text{for all $u\in X$}
\]
and that, for every strictly increasing sequence $(h_n)$ in $\mathbb{N}$
and every sequence $(u_n)$ in $X\setminus\{0\}$ such that
\[
\sup_{n\in\mathbb{N}} f_{h_n}(u_n) < +\infty\,,\quad
\lim_{n\to\infty} (u_n,g_{h_n}(u_n)) = (u,c)
\quad\text{with $c>0$}\,,
\]
it holds
\[
\text{$u\neq 0$ and $g(u)=c$}\,.
\]
Then, for every $m\geq 1$, we have
\[
\mathcal{F}^{(m)}(K) \leq
\Big(\Gamma-\liminf_{h\to\infty} \mathcal{F}_h^{(m)}\Big)(K)
\quad\text{for all $K\in\mathcal{K}$}\,.
\]
\end{theorem}

\begin{proof}
Let $m\geq 1$, let $K\in\mathcal{K}$ and let $(K_h)$ be a sequence
converging to $K$ in $\mathcal{K}$ such that
\[
\Big(\Gamma-\liminf_{h\to\infty} \mathcal{F}_h^{(m)}\Big)(K) =
\liminf_{h\to\infty} \mathcal{F}_h^{(m)}(K_h) \,.
\]
Without loss of generality, we may assume that this value
is not $+\infty$.
Let $b\in \mathbb{R}$ with
\[
b > \liminf_{h\to\infty} \mathcal{F}_h^{(m)}(K_h)\,.
\]
Then there exists a subsequence $(K_{h_n})$ such that
\[
\sup_{n\in\mathbb{N}} \,\sup_{K_{h_n}} \,f_{h_n} =
\sup_{n\in \mathbb{N}}\,\mathcal{F}_{h_n}^{(m)}(K_{h_n}) < b \,.
\]
In particular, $K_{h_n}\in\mathcal{K}_{s,h_n}^{(m)}$ so that
$K$ also is symmetric.

On the other hand, for every $u\in K$, there exists $u_h\in K_h$
with $u_h\to u$.
Since $f_{h_n}(u_{h_n})<b$ and $g_{h_n}(u_{h_n})=1$,
it follows that
\begin{gather*}
f(u) \leq \liminf_{h\to\infty} f_h(u_h) \leq
\liminf_{n\to\infty} f_{h_n}(u_{h_n}) \leq b
\quad\text{for all $u\in K$}, \\
K \subseteq \{u\in X\setminus\{0\}:g(u)=1\}\,.
\end{gather*}
Let $U$ be an open subset of $X\setminus\{0\}$ such that
$K\subseteq U$ and
\[
\operatorname{i}(\widehat{K}) \leq \operatorname{i}(K)
\]
for any nonempty, compact and symmetric subset $\widehat{K}$ of $U$.
Since $K_{h_n}\subseteq U$ eventually as $n\to\infty$,
we have $\operatorname{i}(K_{h_n})\leq \operatorname{i}(K)$ eventually as $n\to\infty$,
whence $\operatorname{i}(K)\geq m$.
Therefore,
\[
\mathcal{F}^{(m)}(K) = \sup_K f \leq b\,.
\]
By the arbitrariness of $b$, the assertion follows.
\end{proof}

\begin{corollary} \label{cor:liminfval}
Assume that
\[
f(u) \leq \Big(\Gamma-\liminf_{h\to\infty} f_h\Big)(u)
\quad\text{for all $u\in X$}
\]
and that for every strictly increasing sequence $(h_n)$ in $\mathbb{N}$
and every sequence $(u_n)$ in $X\setminus\{0\}$ such that
\[
\sup_{n\in\mathbb{N}} f_{h_n}(u_n) < +\infty\,,\quad
\lim_{n\to\infty} g_{h_n}(u_n) = c
\quad\text{with $c>0$}\,,
\]
there exists a subsequence $(u_{n_j})$ such that
\[
\lim_{j\to\infty} u_{n_j} = u\quad\text{with $u\neq 0$
and $g(u)=c$}\,.
\]
Then, for every $m\geq 1$, the sequence
$(\mathcal{F}_h^{(m)})$ is asymptotically equicoercive and
\begin{gather*}
\mathcal{F}^{(m)}(K)\leq
\Big(\Gamma-\liminf_{h\to\infty} \mathcal{F}_h^{(m)}\Big)(K)
\quad\text{for all $K\in\mathcal{K}$}\,,\\
\inf_{K\in\mathcal{K}} \mathcal{F}^{(m)}(K) \leq
\liminf_{h\to\infty} \Big(\inf_{K\in \mathcal{K}} \mathcal{F}_h^{(m)}(K)\Big)\,,\\
\inf_{K\in\mathcal{K}_s^{(m)}} \sup_K f \leq
\liminf_{h\to\infty} \Big(
\inf_{K\in\mathcal{K}_{s,h}^{(m)}} \sup_K f_h\Big)\,.
\end{gather*}
\end{corollary}

\begin{proof}
If we define $\tilde{f}_h:X\to[0,+\infty]$
and $\widetilde{\mathcal{F}}_h:\mathcal{K}\to[0,+\infty]$ as
\begin{gather*}
\tilde{f}_h(u) = \begin{cases}
f_h(u) &\text{if $g_h(u)=1$}\,,\\
+\infty &\text{otherwise}\,,
\end{cases} \\
\widetilde{\mathcal{F}}_h(K)= \sup_K \tilde{f}_h\,,
\end{gather*}
it is easily seen that $(\tilde{f}_h)$ is asymptotically
equicoercive.
By Proposition~\ref{prop:coerchausd}
$(\widetilde{\mathcal{F}}_h)$ also is asymptotically equicoercive.
In turn, from $\mathcal{F}_h^{(m)}\geq \widetilde{\mathcal{F}}_h$ it follows
that $(\mathcal{F}_h^{(m)})$ is asymptotically equicoercive.

From Theorem~\ref{thm:liminf} we infer that
\[
\mathcal{F}^{(m)}(K) \leq
\Big(\Gamma-\liminf_{h\to\infty} \mathcal{F}_h^{(m)}\Big)(K)
\quad\text{for all $K\in\mathcal{K}$}
\]
and the other assertions follow from
Proposition~\ref{prop:liminfinf}.
\end{proof}

\begin{corollary} \label{cor:limval}
Assume that
\[
f(u) = \Big(\Gamma-\lim_{h\to\infty} f_h\Big)(u)
\quad\text{for all $u\in X$}
\]
and that, for every strictly increasing sequence $(h_n)$ in $\mathbb{N}$
and every sequence $(u_n)$ in $X\setminus\{0\}$ such that
\[
\sup_{n\in\mathbb{N}} f_{h_n}(u_n) < +\infty\,,
\]
there exists a subsequence $(u_{n_j})$ converging to some
$u$ in $X$ with
\[
\lim_{j\to\infty} g_{h_{n_j}}(u_{n_j}) = g(u)\,.
\]
Then, for every $m\geq 1$, the sequence
$(\mathcal{F}_h^{(m)})$ is asymptotically equicoercive and
\begin{gather*}
\mathcal{F}^{(m)}(K)=
\Big(\Gamma-\lim_{h\to\infty} \mathcal{F}_h^{(m)}\Big)(K)
\quad\text{for all $K\in\mathcal{K}$}\,,\\
\inf_{K\in\mathcal{K}} \mathcal{F}^{(m)}(K) = \lim_{h\to\infty}
\Big(\inf_{K\in \mathcal{K}} \mathcal{F}_h^{(m)}(K)\Big)\,,\\
\inf_{K\in\mathcal{K}_s^{(m)}} \sup_K f =
\lim_{h\to\infty} \Big(\inf_{K\in\mathcal{K}_{s,h}^{(m)}} \sup_K f_h\Big)\,.
\end{gather*}
\end{corollary}

\begin{proof}
Since $g(0)=0$, if $(u_{n_j})$ is convergent to some $u$ in $X$ with
\[
\sup_{n\in\mathbb{N}} f_{h_n}(u_n) < +\infty\,,\quad
\lim_{n\to\infty} g_{h_n}(u_n) = c >0\,,
\]
it follows that $u\neq 0$ and $g(u)=c$.
Then the assertion is just a combination of
Theorem~\ref{thm:limsup} and Corollary~\ref{cor:liminfval}.
\end{proof}


\section{Minimax values and functionals of calculus of variations}
\label{sect:calcvar}

Throughout this section, $\Omega$  denotes an open subset
of $\mathbb{R}^N$ with $N\geq 2$ and, for any $q\in[1,\infty]$,
$\|\cdot\|_q$ the usual norm in $L^q$.
Since $\Omega$ is allowed to be unbounded, for any $p\in]1,N[$
we will consider the Banach space $D^{1,p}_0(\Omega)$
(see e.g.~\cite{lucia_schuricht2013})
endowed with the norm
\[
\|u\| = \|\nabla u\|_p =
\Big(\int_\Omega |\nabla u|^p\,dx\Big)^{1/p}\,.
\]
Recall that $D^{1,p}_0(\Omega)$ is continuously
embedded in $L^{p^*}(\Omega)$, where $p^*=Np/(N-p)$,
and contains $C^{\infty}_c(\Omega)$ as a dense vector subspace.
For any $p\in]1,N[$, define
$\mathcal{E}_p:L^1_{\rm loc}(\Omega)\to[0,+\infty]$ as
\[
\mathcal{E}_p(u) =\begin{cases}
\|\nabla u\|_p
&\text{if $u\in D^{1,p}_0(\Omega)$}\,,\\
+\infty
&\text{otherwise}\,.
\end{cases}
\]
In the case $p=1$, define first
$\widehat{\mathcal{E}}_1:
L^1_{\rm loc}(\Omega)\to[0,+\infty]$ as
\[
\widehat{\mathcal{E}}_1(u) =\begin{cases}
\int_\Omega |\nabla u|\,dx
&\text{if $u\in C^1_c(\Omega)$}\,,\\
+\infty &\text{otherwise}\,,
\end{cases}
\]
then denote by
$\mathcal{E}_1:L^1_{\rm loc}(\Omega)\to[0,+\infty]$
the lower semicontinuous envelope of
$\widehat{\mathcal{E}}_1$
with respect to the $L^1_{\rm loc}(\Omega)$-topology.
If $\Omega$ is bounded and has Lipschitz boundary,
then $\mathcal{E}_1$ has a well known integral
representation (see
e.g.~\cite[Example~3.14]{dalmaso1993}).

In any case, $\mathcal{E}_1$ is convex, even and positively
homogeneous of degree $1$.
Moreover,
\[
X_1 = \{u\in L^1_{\rm loc}(\Omega):
\mathcal{E}_1(u)<+\infty\}
\]
is a vector subspace of $L^1_{\rm loc}(\Omega)$ and
$\mathcal{E}_1$ is a norm on $X_1$ which makes $X_1$ a normed
space continuously embedded in
$L^{1^*}(\Omega)=L^{\frac{N}{N-1}}(\Omega)$.

More precisely, if we set
\[
S(N,p) = \inf\Big\{
\frac{{\int_{\mathbb{R}^N} |\nabla u|^p\,dx}}{
{\big(\int_{\mathbb{R}^N}
|u|^{p^*}\,dx\big)^{p/p^*}}}:
u\in C^1_c(\mathbb{R}^N)\setminus\{0\}\Big\}
\quad\text{whenever $1\leq p<N$}\,,
\]
then we have
\begin{gather*}
\inf_{1\leq p \leq q} S(N,p) > 0 \quad\text{for all $q\in]1,N[$}\,,\\
S(N,p)^{1/p}\,\|u\|_{p^*} \leq\mathcal{E}_p(u)
\quad\text{whenever $1\leq p<N$ and
$\mathcal{E}_p(u)<+\infty$}\,.
\end{gather*}
It follows easily  that, for every $q\in]1,N[$ and $b\in \mathbb{R}$, the set
\[
\cup_{1\leq p\leq q} \left\{u\in L^1_{\rm loc}(\Omega):
\mathcal{E}_p(u) \leq b\right\}
\]
has compact closure in $L^1_{\rm loc}(\Omega)$.

Now, given $p\in[1,N[$, consider $V_p\in L^{N/p}(\Omega)$.
Let $\varrho_p:\mathbb{R}\to \mathbb{R}$ be the odd function
such that
\[
\varrho_p(s) = s^{1/p}
\quad\text{for all $s\geq 0$}
\]
and define $g_p:L^1_{\rm loc}(\Omega)\to \mathbb{R}$ as
\begin{equation}
\label{eq:gV}
g_p(u) =\begin{cases}
\varrho_{p}\Big(\int_\Omega V_p\,|u|^p\,dx\Big)
&\text{if $u\in L^{p^*}(\Omega)$}\,,\\
0 &\text{otherwise}\,.
\end{cases}
\end{equation}

\begin{proposition}\label{prop:gV}
The following facts hold:
\begin{itemize}
\item[(a)] $g_p$ is even and positively homogeneous of degree $1$;
\item[(b)] for every $b\in \mathbb{R}$, the restriction of $g_p$ to
$\left\{u\in L^1_{\rm loc}(\Omega):\mathcal{E}_p(u)\leq b\right\}$
is continuous.
\end{itemize}
\end{proposition}

\begin{proof}
Assertion (a) is obvious.
If $(u_n)$ is convergent to $u$ in $L^1_{\rm loc}(\Omega)$
with $\mathcal{E}_p(u_n)\leq b$, then $(u_n)$ is bounded
in $L^{p^*}(\Omega)$ and assertion~$(b)$ also follows
(see also \cite[Lemma~2.13]{willem1996}).
\end{proof}

We aim to compare the minimax values with respect to the
$L^1_{\rm loc}(\Omega)$-topology with those with respect to
a stronger topology.
As before, denote by $\mathcal{K}_{s,p}^{(m)}$ the family of compact
and symmetric subsets $K$ of
\[
\{u\in L^1_{\rm loc}(\Omega):g_p(u) = 1\}
\]
such that $\operatorname{i}(K)\geq m$, with respect to the topology
of $L^1_{\rm loc}(\Omega)$.

If $1<p<N$, denote also by $\mathcal{V}_p^{(m)}$ the family of
compact and symmetric subsets $K$ of
\[
\big\{u\in D^{1,p}_0(\Omega):
\int_\Omega V_p\,|u|^p\,dx = 1\big\}
\]
such that $\operatorname{i}(K)\geq m$, with respect to the norm
topology of $D^{1,p}_0(\Omega)$.

If $p=1$, denote by $\mathcal{V}_1^{(m)}$ the family of compact
and symmetric subsets $K$ of
\[
\big\{u\in L^{\frac{N}{N-1}}(\Omega):
\int_\Omega V_1\,|u|\,dx = 1\big\}
\]
such that $\operatorname{i}(K)\geq m$, with respect to the norm
topology of $L^{\frac{N}{N-1}}(\Omega)$.

\begin{theorem}\label{thm:change}
Let $f_p:L^1_{\rm loc}(\Omega)\to[0,+\infty]$
be convex, even and positively homogeneous of degree $1$.
Moreover, suppose there exists $\nu>0$ such that
\[
f_p(u) \geq \nu \,\mathcal{E}_p(u)
\quad\text{for all $u\in L^1_{\rm loc}(\Omega)$}\,.
\]
Then, for every $m\geq 1$, we have
\[
\inf_{K\in\mathcal{K}_{s,p}^{(m)}} \sup_K f_p =
\inf_{K\in\mathcal{V}_p^{(m)}} \sup_K f_p\,.
\]
\end{theorem}

\begin{proof}
From Proposition \ref{prop:gV} and
the lower estimate on $f_p$ we infer that, for every $b\in \mathbb{R}$,
the restriction of $g_p$ to
$\{u\in L^1_{\rm loc}(\Omega):f_p(u)\leq b\}$
is $L^1_{\rm loc}(\Omega)$-continuous.
Of course, the same is true if we consider a stronger topology.
Then the assertion follows from Corollary~\ref{cor:norm}.
\end{proof}

Now, in view of the convergence results of the next section,
let us prove some further basic facts concerning
$\mathcal{E}_p$ and $g_p$. 
The authors want to thank Lorenzo Brasco for pointing out 
that a previous version of this theorem was incorrect.

\begin{theorem}\label{thm:gammaE}
For every sequence $(p_h)$ decreasing to $p$
in $[1,N[$, we have
\[
\mathcal{E}_p(u) =
\Big(\Gamma-\lim_{h\to\infty} \mathcal{E}_{p_h}\Big)(u)
\quad\text{for all $u\in L^1_{\rm loc}(\Omega)$}\,.
\]
\end{theorem}

\begin{proof}
Let us prove only the case $p=1<p_h$.
The other cases are similar and even simpler.
Let $d$ be a compatible distance on $L^1_{\rm loc}(\Omega)$
and let $u\in L^1_{\rm loc}(\Omega)$.
Let $b\in \mathbb{R}$ with
\[
b>\Big(\Gamma-\liminf_{h\to\infty} \mathcal{E}_{p_h}\Big)(u)
\]
and let $(u_h)$ be a sequence converging to $u$ in $L^1_{\rm loc}(\Omega)$
such that
\[
\Big(\Gamma-\liminf_{h\to\infty} \mathcal{E}_{p_h}\Big)(u)
= \liminf_{h\to\infty} \mathcal{E}_{p_h}(u_h)\,.
\]
Let $(\mathcal{E}_{p_{h_n}})$ be such that
\[
\sup_{n\in\mathbb{N}}\,\mathcal{E}_{p_{h_n}}(u_{h_n}) <b\,.
\]
First of all,
\[
\sup_{n\in\mathbb{N}}\,\int_\Omega |u_{h_n}|^{p_{h_n}^*}\,dx < +\infty\,,
\]
so that $u\in L^{\frac{N}{N-1}}(\Omega)$.
Let $v_n\in C^1_c(\Omega)$ be such that
\[
d(v_n,u_{h_n})<\frac{1}{n}\,,\quad
\mathcal{E}_{p_{h_n}}(v_n) < b\,.
\]
Then $(v_n)$ also  converges to $u$ in $L^1_{\rm loc}(\Omega)$
and is bounded in $L^{\frac{N}{N-1}}_{\rm loc}(\Omega)$.
For every $\vartheta\in C^1_c(\mathbb{R}^N)$ with $0\leq \vartheta\leq 1$,
we have
\begin{align*}
b &> \|\nabla v_n\|_{p_{h_n}}
 \geq \|\vartheta\nabla v_n\|_{p_{h_n}}\\
& \geq \|\nabla(\vartheta v_n)\|_{p_{h_n}} - \|v_n \nabla\vartheta\|_{p_{h_n}} \\
& \geq \mathcal{L}^n(\operatorname{supp}(\vartheta))^{\frac{1-p_{h_n}}{p_{h_n}}}
\,\|\nabla(\vartheta v_n)\|_1 - \|v_n \nabla\vartheta\|_{p_{h_n}} \\
&\geq \mathcal{L}^n(\operatorname{supp}(\vartheta))^{\frac{1-p_{h_n}}{p_{h_n}}}
\,\mathcal{E}_1(\vartheta v_n) - \|v_n \nabla\vartheta\|_{p_{h_n}}\,,
\end{align*}
where $\mathcal{L}^n$ denotes the Lebesgue measure.
Passing to the lower limit as $n\to\infty$, we obtain
\[
b\geq \mathcal{E}_1(\vartheta u) - \|u \nabla\vartheta\|_1\,.
\]
Let $\vartheta:\mathbb{R}^N\to[0,1]$ be a $C^1$-function such that
$\vartheta(x)=1$ if $|x|\leq 1$ and
$\vartheta(x)=0$ if $|x|\geq 2$ and let
$\vartheta_k(x) = \vartheta(x/k)$.
Then
\[
b\geq
\mathcal{E}_1(\vartheta_k u) -
\int_\Omega |u|\,|\nabla\vartheta_k|\,dx\,.
\]
It is easily seen that $(\vartheta_k u)$ is convergent to $u$
in $L^1_{\rm loc}(\Omega)$, while $(|\nabla\vartheta_k|)$ is bounded
in $L^N(\Omega)$ and convergent to $0$ a.e. in $\Omega$.
Passing to the lower limit as $k\to\infty$, we obtain
$b\geq \mathcal{E}_1(u)$,
hence
\[
\mathcal{E}_1(u) \leq
\Big(\Gamma-\liminf_{h\to\infty} \mathcal{E}_{p_h}\Big)(u)
\]
by the arbitrariness of $b$.

Now let $u\in L^1_{\rm loc}(\Omega)$, let
$b\in \mathbb{R}$ with $b>\mathcal{E}_1(u)$ and let $\delta>0$.
Let $w\in C^1_c(\Omega)$ with $d(w,u)<\delta$ and
$\|\nabla w\|_1<b$.
Then
\[
b > \lim_{h\to\infty} \mathcal{E}_{p_h}(w)\,,
\]
whence
\[
b> \limsup_{h\to\infty}\bigl(
\inf\{\mathcal{E}_{p_h}(v):d(v,u)<\delta\}\bigr)\,.
\]
By the arbitrariness of $\delta$, it follows that
\[
 b\geq
\Big(\Gamma-\limsup_{h\to\infty} \mathcal{E}_{p_h}\Big)(u)\,,
\]
hence
\[
\mathcal{E}_1(u) \geq
\Big(\Gamma-\limsup_{h\to\infty} \mathcal{E}_{p_h}\Big)(u)
\]
by the arbitrariness of $b$.
\end{proof}

\begin{theorem}\label{thm:convg}
Let $(p_h)$ be a sequence converging to $p$ in $[1,N[$ and let
$V_h\in L^{N/p_h}(\Omega)$ and $V\in L^{N/p}(\Omega)$
be such that
\begin{gather*}
\lim_{h\to\infty} V_h(x) = V(x)
\quad\text{for a.e. $x\in\Omega$}\,,\\
\lim_{h\to\infty} \|V_h\|_{N/p_h} = \|V\|_{N/p}\,.
\end{gather*}
Define $g_h, g:L^1_{\rm loc}(\Omega)\to \mathbb{R}$
according to \eqref{eq:gV}.
Then, for every strictly increasing sequence $(h_n)$ in $\mathbb{N}$ and
$(u_n)$ in $L^1_{\rm loc}(\Omega)$ such that
\[
\sup_{n\in\mathbb{N}} \mathcal{E}_{p_{h_n}}(u_n) <+\infty\,,
\]
there exists a subsequence $(u_{n_j})$ such that
\begin{gather*}
\lim_{j\to\infty} u_{n_j} = u
\quad\text{in $L^1_{\rm loc}(\Omega)$}\,,\\
\lim_{j\to\infty} g_{h_{n_j}}(u_{n_j}) = g(u)\,.
\end{gather*}
\end{theorem}

\begin{proof}
Up to a subsequence, $(u_n)$ is convergent to some $u$ in
$L^1_{\rm loc}(\Omega)$ and a.e. in $\Omega$.
Moreover, for every $\varepsilon>0$ there exists
$C_\varepsilon>0$ independent of $n$ such that
\[
\big|V_{h_n}\,|u_n|^{p_{h_n}} - V\,|u|^p\big|
\leq C_\varepsilon |V_{h_n}|^{N/p_{h_n}} +
\varepsilon |u_n|^{p_{h_n}^*} + |V|\,|u|^p\,,
\]
whence
\[
C_\varepsilon |V_{h_n}|^{N/p_{h_n}} +
\varepsilon |u_n|^{p_{h_n}^*} -
\big|V_{h_n}\,|u_n|^{p_{h_n}} - V\,|u|^p\big|
\geq - |V|\,|u|^p\,.
\]
From Fatou's lemma it follows that
\begin{align*}
& C_\varepsilon \int_\Omega |V|^{N/p}\,dx \\
& \leq C_\varepsilon \int_\Omega |V|^{N/p}\,dx
+ \varepsilon
\Big(\sup_{n\in\mathbb{N}}\|u_n\|_{p_{h_n}^*}^{p_{h_n}^*}\Big)
- \limsup_{n\to\infty} \int_\Omega
\big|V_{h_n}\,|u_n|^{p_{h_n}} - V\,|u|^p\big|\,dx\,,
\end{align*}
whence
\[
\limsup_{n\to\infty}\int_\Omega
\big|V_{h_n}\,|u_n|^{p_{h_n}} - V\,|u|^p\big|\,dx
\leq
\varepsilon \Big(\sup_{n\in\mathbb{N}}\|u_n\|_{p_{h_n}^*}^{p_{h_n}^*}\Big)\,.
\]
Since $(\mathcal{E}_{p_{h_n}}(u_n))$ is bounded, we infer that
\[
\sup_{n\in\mathbb{N}}\|u_n\|_{p_{h_n}^*}^{p_{h_n}^*}< +\infty
\]
and the assertion follows by the arbitrariness
of $\varepsilon$.
\end{proof}


\section{Convergence of minimax values for functionals of
calculus of variations}
\label{sect:convcalcvar}

In this section, $\Omega$  still denotes an open subset
of $\mathbb{R}^N$ with $N\geq 2$ and, for any $p\in[1,N[$,
$\mathcal{E}_p:L^1_{\rm loc}(\Omega)\to[0,+\infty]$
the functional introduced in the previous section.

Assume that $(p_h)$ is a sequence converging to $p$
in $[1,N[$, $f:L^1_{\rm loc}(\Omega)\to[0,+\infty]$
is a functional,
$(f_h)$ is a sequence of functionals from
$L^1_{\rm loc}(\Omega)$ to $[0,+\infty]$,
$V\in L^{N/p}(\Omega)$ and $(V_h)$ is a sequence with
$V_h\in L^{N/p_h}(\Omega)$.
Also suppose that:
\begin{itemize}
\item[(H1)] $f$ is even;

\item[(H2)] each $f_h$ is convex, even and positively homogeneous of
degree $1$; moreover, there exists $\nu>0$ such that
\[
f_h(u) \geq \nu \mathcal{E}_{p_h}(u)
\quad\text{for all $h\in\mathbb{N}$ and $u\in L^1_{\rm loc}(\Omega)$}\,;
\]

\item[(H3)] we have
\begin{gather*}
\lim_{h\to\infty} V_h(x) = V(x) \quad\text{for a.e. $x\in\Omega$}\,,\\
\lim_{h\to\infty} \|V_h\|_{N/p_h} = \|V\|_{N/p}\,.
\end{gather*}
\end{itemize}

Let $\mathcal{K}$ be the family of nonempty compact subsets of $L^1_{\rm loc}(\Omega)$
endowed with the $\mathcal{H}$-topology and
define $g_h, g:L^1_{\rm loc}(\Omega)\to \mathbb{R}$
according to \eqref{eq:gV}.
Then define
$\mathcal{K}_{s,h}^{(m)}, \mathcal{K}_s^{(m)} \subseteq\mathcal{K}$ and
$\mathcal{F}_h^{(m)}, \mathcal{F}^{(m)}:\mathcal{K}\to[0,+\infty]$
as in Section~\ref{sect:est}.

\begin{theorem} \label{thm:limsupconcr}
Assume that
\[
f(u) \geq \Big(\Gamma-\limsup_{h\to\infty} f_h\Big)(u)
\quad\text{for all $u\in L^1_{\rm loc}(\Omega)$}\,.
\]
Then, for every $m\geq 1$, we have
\begin{gather*}
\mathcal{F}^{(m)}(K) \geq
\Big(\Gamma-\limsup_{h\to\infty} \mathcal{F}_h^{(m)}\Big)(K)
\quad\text{for all $K\in\mathcal{K}$}\,,\\
\inf_{K\in\mathcal{K}} \mathcal{F}^{(m)}(K)\geq \limsup_{h\to\infty}
\Big(\inf_{K\in \mathcal{K}} \mathcal{F}_h^{(m)}(K)\Big)\,,\\
\inf_{K\in\mathcal{K}_s^{(m)}} \sup_K f
\geq \limsup_{h\to\infty}
\Big(\inf_{K\in\mathcal{K}_{s,h}^{(m)}} \sup_K f_h\Big)\,.
\end{gather*}
\end{theorem}

The proof of the above theorem follows from Theorem~\ref{thm:limsup},
Proposition~\ref{prop:gV} and Theorem~\ref{thm:convg}.

\begin{theorem} \label{thm:liminfconcr}
Assume that
\[
f(u) \leq \Big(\Gamma-\liminf_{h\to\infty} f_h\Big)(u)
\quad\text{for all $u\in L^1_{\rm loc}(\Omega)$}\,.
\]
Then, for every $m\geq 1$, the sequence
$(\mathcal{F}_h^{(m)})$ is asymptotically equicoercive and we have
\begin{gather*}
\mathcal{F}^{(m)}(K)
\leq \Big(\Gamma-\liminf_{h\to\infty} \mathcal{F}_h^{(m)}\Big)(K)
\quad\text{for all $K\in\mathcal{K}$}\,,\\
\inf_{K\in\mathcal{K}} \mathcal{F}^{(m)}(K)
\leq \liminf_{h\to\infty}
\Big(\inf_{K\in \mathcal{K}} \mathcal{F}_h^{(m)}(K)\Big)\,,\\
\inf_{K\in\mathcal{K}_s^{(m)}} \sup_K f
\leq \liminf_{h\to\infty} \Big(\inf_{K\in\mathcal{K}_{s,h}^{(m)}} \sup_K f_h\Big)\,.
\end{gather*}
\end{theorem}

The proof of the above theorem follows from Corollary~\ref{cor:liminfval},
Proposition~\ref{prop:gV} and Theorem~\ref{thm:convg}.

\begin{corollary} \label{cor:limconcr}
Assume that
\[
f(u) = \Big(\Gamma-\lim_{h\to\infty} f_h\Big)(u)
\quad\text{for all $u\in L^1_{\rm loc}(\Omega)$}\,.
\]
Then, for every $m\geq 1$, the sequence
$(\mathcal{F}_h^{(m)})$ is asymptotically equicoercive and we have
\begin{gather*}
\mathcal{F}^{(m)}(K) = \Big(\Gamma-\lim_{h\to\infty} \mathcal{F}_h^{(m)}\Big)(K)
\quad\text{for all $K\in\mathcal{K}$}\,,\\
\inf_{K\in\mathcal{K}} \mathcal{F}^{(m)}(K)
= \lim_{h\to\infty} \Big(\inf_{K\in \mathcal{K}} \mathcal{F}_h^{(m)}(K)\Big)\,,\\
\inf_{K\in\mathcal{K}_s^{(m)}} \sup_K f
=\lim_{h\to\infty} \Big(\inf_{K\in\mathcal{K}_{s,h}^{(m)}} \sup_K f_h\Big)\,.
\end{gather*}
\end{corollary}

The proof of the above corollary follows from Corollary~\ref{cor:limval},
Proposition~\ref{prop:gV} and Theorem~\ref{thm:convg}.


As an example, whenever $1\leq p <N$ and $m\geq 1$, consider again
$V_p\in L^{N/p}(\Omega)$ and the families $\mathcal{V}_p^{(m)}$
already defined in Section~\ref{sect:calcvar}.
Define
\[
\lambda_p^{(m)} =
\inf_{K\in \mathcal{V}_p^{(m)}} \sup_{u\in K} \big(\mathcal{E}_p(u)\big)^p\,.
\]
In particular, if $1<p<N$ we have
\[
\lambda_p^{(m)} = \inf_{K\in \mathcal{V}_p^{(m)}} \sup_{u\in K}
\int_\Omega |\nabla u|^p\,dx\,.
\]

\begin{theorem} \label{thm:convlambda}
Let $(p_h)$ be a sequence decreasing to $p$ in
$[1,N[$ and assume that
\begin{gather*}
\lim_{h\to\infty} V_{p_h}(x) = V_p(x)
\quad\text{for a.e. $x\in\Omega$}\,,\\
\lim_{h\to\infty} \|V_{p_h}\|_{N/p_h} = \|V_p\|_{N/p}\,.
\end{gather*}
Then, for every $m\geq 1$, we have
$\lim_{h\to\infty} \lambda_{p_h}^{(m)} =
\lambda_p^{(m)}$.
\end{theorem}

\begin{proof}
Of course, it is equivalent to show that
\[
\lim_{h\to\infty} \left(\lambda_{p_h}^{(m)}\right)^{1/p_h}
= \left(\lambda_p^{(m)}\right)^{1/p}\,.
\]
By Theorem~\ref{thm:change} we get the same values
$\lambda_p^{(m)}$ using the $L^1_{\rm loc}(\Omega)$-topology.
Then the assertion follows from Corollary~\ref{cor:limconcr}
and Theorem~\ref{thm:gammaE}.
\end{proof}

\subsection*{Acknowledgments}
This research  was partially supported by
 Gruppo Nazionale per l'Analisi Matematica,
 la Probabilit\`a e le loro Applicazioni (INdAM)

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\end{document}
