\documentclass[reqno]{amsart}
\usepackage{hyperref}

\AtBeginDocument{{\noindent\small
\emph{Electronic Journal of Differential Equations},
Vol. 2014 (2014), No. 255, pp. 1--8.\newline
ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu
\newline ftp ejde.math.txstate.edu}
\thanks{\copyright 2014 Texas State University - San Marcos.}
\vspace{9mm}}

\begin{document}
\title[\hfilneg EJDE-2014/255\hfil Distribution of the Pr\"ufer angle]
{Distribution of the Pr\"ufer angle in $p$-Laplacian eigenvalue problems}

\author[Y.-H. Cheng, C.-K. Law, Y.-C. Luo \hfil EJDE-2014/255\hfilneg]
{Yan-Hsiou Cheng, Chun-Kong Law, Yu-Chen Luo}  % in alphabetical order

\address{Yan-Hsiou Cheng \newline
Department of Mathematics and Information Education,
National Taipei University of Education, Taipei 106, Taiwan}
\email{yhcheng@tea.ntue.edu.tw}

\address{Chun-Kong Law \newline
Department of Applied Mathematics,
National Sun Yat-sen University,
Kaohsiung 80424, Taiwan}
\email{law@math.nsysu.edu.tw}

\address{Yu-Chen Luo \newline
Department of Applied Mathematics,
National Sun Yat-sen University,
Kaohsiung 80424, Taiwan}
\email{leoredro@gmail.com}

\thanks{Submitted November 11, 2014. Published December 4, 2014.}
\subjclass[2000]{34B24, 37A30}
\keywords{$p$-Laplacian eigenvalue problem; Pr\"{u}fer angle;
 equidistribution; \hfill\break\indent uniform distribution}

\begin{abstract}
 The Pr\"ufer angle is an effective tool for studying Sturm-Liouville problems
 and $p$-Laplacian eigenvalue problems.
 In this article, we show that for the $p$-Laplacian eigenvalue problem, when
 $x$ is irrational in $(0,1)$, a sequence of modified
 Pr\"ufer angles  (after modulo $\pi_p$) is equidistributed
 in $(0,\pi_p)$. As a function of $x$, $\psi_n$ is also asymptotic to
 the uniform distribution on $(0,\pi_p)$.
\end{abstract}

\maketitle
\numberwithin{equation}{section}
\newtheorem{theorem}{Theorem}[section]
\newtheorem{lemma}[theorem]{Lemma}
\newtheorem{corollary}[theorem]{Corollary}
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 \section{Introduction}

 It is well known that when a real number $x$ is irrational, the
 sequence $\{ x_n=\bl nx\br\}$ is dense in $(0,1)$. Here for any
$t\in \mathbb{R}$, the fractional part of $t$ is denoted by $\bl t\br:=t-[t]$.
It is equivalent to saying that $\{\xi_n=\sin(n\pi x)\}$ is dense in $[-1,1]$.
Furthermore, the above sequence $\{ x_n\}$ is equidistributed in
 $(0,1)$ in the sense below (\cite[p.105]{SS}).

\noindent\textbf{Definition.}
 A sequence $\{{x}_n\}\subset (0,1)$ is said to be
 equidistributed in $(0,1)$ if for any subinterval $(a,b)\subset (0,1)$,
 $$
 \lim_{N\to\infty} \frac{1}{N} \sum_{n=1}^N \Bigchi_{(a,b)}(x_n)=b-a.
 $$

The above property is a basic one in ergodic theory. It tells us
 that the sequence spreads evenly in the interval $(0,1)$. In
fact, this equidistribution theorem is equivalent to the property that for
 any $f\in L^1(0,1)$,
 $$
 \int_0^1 f(x)\, dx=\lim_{N\to\infty}\frac{1}{N} \sum_{n=1}^N f(x_n),
 $$
 which in term is equivalent to saying that the transformation
$T(\th)=\langle \th+x\rangle$
 is ergodic \cite{SS,BS}.

 Consider the Sturm-Liouville problem
 \begin{equation}
 -u''+q(x)u=\la u \label{eq1.1}
 \end{equation}
 subject to boundary conditions
 \begin{equation}
 \begin{gathered}
 u(0)\cos\al + u'(0)\sin\al = 0\\
 u(1)\cos\be + u'(1)\sin\be = 0
 \end{gathered}
 \label{eq1.2}
 \end{equation}
 where $\al, \be\in[0, \pi)$, and $q\in L^{1}(0,1)$. We call
 $\al,\be$ the boundary phases.

 The Pr\"ufer substitution
 \begin{equation}
 u=r(x)\sin\th(x),\quad u'=r(x)\cos\th(x)\label{eq1.25}
 \end{equation}
is a useful method to study the
 Sturm-Liouville problem, such as the existence of countably many
 simple eigenvalues, oscillations of the $n$th {eigenfunction}, the
 asymptotics of the eigenvalues and eigenfunctions \cite{BR}. In
 \cite{a64}, Atkinson showed that the Sturm-Liouville properties are also valid
 when the coefficient function $q$ is $L^1$.
 His method is also this Pr\"ufer substitution in spirit.
Furthermore, Binding and Volkmer
 \cite{BV12} (see also \cite{BV13}) showed that one can use the Pr\"ufer
substitution method to show the distribution of
 periodic and anti-periodic eigenvalues for periodic Sturm-Liouville problems.
(Traditionally the Hill discriminant function is used to prove this distribution.)
Thus the Pr\"ufer angle is an effective tool for the Sturm-Liouville theory.
 It would be interesting to explore further properties of this Pr\"ufer angle.
 In this paper, we shall study the equidistribution property.

 In recent years, the Pr\"ufer angle has been used to show that another
class of degenerate boundary value problems, the $p$-Laplacian eigenvalue problem,
observes the Sturm-Liouville properties, as shown by Binding and
Drabek \cite{BD03} (see also \cite{bd06}).
Let $(\lambda_n,y_n)$ be the $n$th eigenpair of the
 boundary value problem
 \begin{equation}
 \begin{gathered}
 -(|y'|^{p-2}y')'=(p-1)(\lambda-q(x))|y|^{p-2}y,\\
 y(0)S'_p(\alpha) + y'(0)S_p(\alpha) = 0,\\
 y(1)S'_p(\beta) + y'(1)S_p(\beta) = 0.
 \end{gathered} \label{eq1.3}
 \end{equation}
 Here, $S_p$ is called the generalized sine function and defined as the solution
 of the initial value problem
 \begin{gather*}
 (|S_p'(x)|^{p-2}S_{p}'(x))'+(p-1)|S_p(x)|^{p-2}S_{p}(x) = 0,\\
 S_p(0)=S_p'(0)-1= 0.
 \end{gather*}
 It is known that the function $S_p$ is $2\pi_p$-periodic on
 $\mathbb{R}$, where
 $$
 \pi_p\equiv 2\int_0^1 (1-t^p)^{-1/p} dt,
 $$
 and for all $x\in \mathbb{R}$, the following identity holds:
 $$
 |S_p(x)|^p+|S_p'(x)|^p=1.
 $$
 Note that $\pi_p$ is strictly decreasing in $p$ \cite{bd06}.
When $p=2$, we have $\pi_2=\pi$ and $S_p(x)=\sin x$.
 Moreover, for $q=0$ and $p=2$, the Dirichlet eigenvalues and
eigenfunctions are $\la_n=(n\pi)^2$ and $y_n=\sin(n\pi x)$.

 For $a>0$, let us define the fractional part of
$ \bl t\br_a$ $(t \pmod a)$ by
 $$
\bl t\br_a:= t-a\cdot\left[t/a\right].
$$
When $a=1$, we denote this fractional part simply by $ \bl t\br$.
 As discussed above, when $x$ is irrational, the sequence
$\{ \bl n\pi x\br_\pi\}$ is equidistributed in $(0,\pi)$.
We shall see that a sequence of modified
 Pr\"ufer angles $\{\bl \psi_n(x)\br_{\pi_p}\}$ also observe this
ergodic behavior.
 Consider the modified Pr\"ufer substitution
 \begin{equation}
 y(x)=R(x)S_p(\psi(x)),\quad
 y'(x)=\lambda^{1/p}R(x)S'_p(\psi(x)).\label{eq1.35}
 \end{equation}
We call $\psi(x)$ the modified Pr\"ufer angle at $x$ of the problem
 \eqref{eq1.3}. It becomes $\psi_n(x)$ when associated with the
 $n$th eigenpair $(\la_n,y_n)$.
We note that in literature $\psi(x)$ can also help to
 give estimates for the eigenvalues and nodal points. See \cite{CCL}.


 \begin{theorem} \label{thm1.1}
 Fix any irrational number $x\in (0,1)$.
 For any boundary phases $\al$ and $\be$, the sequence
 $ \{\bl \psi_n(x)\br_{\pi_p}\}$ is equidistributed in $(0,\pi_p)$.
 \end{theorem}

 We remark that $\psi_n(x)$ can be viewed as the
 phase of the eigenfunction $y_n$ at $x$, analogous to the argument
 of the function $\sin(n\pi x)$. Moreover $\psi_n(x)$ demonstrates another property
 of uniform distribution, just like $\bl n\pi x\br_\pi$.

 \begin{theorem} \label{thm1.2}
 For $q\in L^{1}(0, 1)$, the distribution of the modifed Pr\"ufer angle
$\psi_{n}$ defined in \eqref{eq1.35}
 is asymptotic to the uniform distribution on $(0, \pi_p)$. That is, for
 all $t\in(0,\pi_p)$,
 $$
P_{n}(t):=\mu\{x\in(0, 1):
 \bl\psi_{n}(x)\br_{\pi_p} < t\}\to\frac{t}{\pi_p}\quad \text{as }
 n\to\infty\, .
$$
Here $\mu$ denotes the Lebesgue measure on $\mathbb{R}$.
 \end{theorem}

The above two theorems are the main results of this paper. To prove
them, we need to use the following lemma. Define $CT_{p} (x) \equiv
 S'_{p}(x)/S_{p}(x)$ and let $CT^{-1}_{p} (x)$
 be the inverse function of $CT_{p} (x)$ taking value in $(0,\pi_p)$.

 \begin{lemma} \label{lem1.3}
 The modified Pr\"{u}fer angle $\psi_n(x)$, defined in \eqref{eq1.35}
 for the $p$-Lapla\-cian eigenvalue problem
 \eqref{eq1.3}, has the asymptotic formula
 \begin{equation}
 \psi_n(x)=\lambda_n^{1/p}x+\psi_n(0)+O(\frac 1{\lambda_{n}^{1-1/p}}),
 \label{eq1.4}
 \end{equation}
 where
 $$
 \psi_n(0)=\begin{cases}
 0, & \text{if } \alpha=0,\\
 CT_p^{-1}(-\frac{CT_p(\alpha)}{\lambda_n^{1/p}}),& \text{if }\al>0.
 \end{cases}
 $$
 \end{lemma}

 \begin{proof}
Since $\frac{y'(x)}{\lambda^{1/p}y(x)}=\frac{S'_p(\psi(x))}{S_p(\psi(x))}$,
 differentiating both sides with respect to $x$, we have
 \begin{equation}
 \psi'(x)=\lambda^{1/p}-\frac{q(x)}{\lambda^{1-1/p}}|S_p(\psi(x))|^p
=\lambda^{1/p}+O(\frac 1 {\lambda^{1-1/p}}).
 \label{eq1.5}
 \end{equation}
 Integrating \eqref{eq1.5} with respect to the $n$th eigenfunction from $0$
to $x$ and we have
 \begin{equation}
 \psi_n(x)=\lambda_n^{1/p}x+\psi_n(0)+O(\frac 1
 {\lambda_{n}^{1-1/p}}).
 \label{eq1.6}
 \end{equation}
This completes the proof.
 \end{proof}

 \noindent\textbf{Remark.}
If the eigenvalues $\la_n\to\infty$, then
 when $\al>0$,
 \begin{equation}
 \lim_{n\to\infty} \psi_n(0)=\frac{\pi_p}{2}.\label{eq1.8}
 \end{equation}

 In section 2, we shall prove Theorem \ref{thm1.2}. The proof of
 Theorem~\ref{thm1.1}, using Weyl's criterion, will be given in section 3.
 In section 4, we shall see that
 the classical Pr\"ufer angle {$\theta_n(x)$ after modulo $\pi_p$ is not
 equidistributed in $(0,\pi_p)$. Nor is the sequence asymptotic to
 the uniform distribution.}

 The question that whether the classical Pr\"ufer angle is
 dense in $(0,\pi_p)$ or not is still open.
 The problem seems to be related to continued fractions with bounded
and unbounded elements. It would be interesting to study this question.

 As discussed above, the eigenvalues and eigenfunctions of the
 Sturm-Liouville operators $H_q$ behaves like $H_0$, the case when
the potential function $q=0$.
 Say, with Dirichlet boundary conditions
 has the asymptotics $y_n\sim A\sin(n\pi x)$ and the nodal points
 $ x^{(n)}_k\sim \frac{k}{n}$. For these asymptotic results, the use of
 another modified Pru\"fer angle $\phi_n=\psi_n/\sqrt{\la_n}$ so that
 $$\phi_n'=1-\frac{q}{\la_n}\sin^2(\sqrt{\la_n}\phi_{n}(x)),
 $$
 gives the simplest proof. The situation with the $p$-Laplacian
 operator is analogous. This paper establishes another analogy of
 equidistribution between $\bl\psi_n(x) \br_\pi$, and
$\bl n\pi x\br_\pi$ which is associated with $q=0$. It supports the fact that
 $\psi_n/\sqrt{\la_n}$ was a better choice.

 \section{Proof of Theorem \ref{thm1.2}}

 \begin{lemma}\label{lem2.1}
For any $t\in(0,\pi_p)$, $a>0$, $b\in\mathbb{R}$, we have
 \begin{itemize}
 \item[(a)] $ \mu\{x\in(0,\pi_p):\bl x+b\br_{\pi_p}<t\}=t$.
 \item[(b)] $ \mu\{x\in(0,\pi_p):\bl
 ax\br_{\pi_p}<t\}=\frac{t[a]}{a}+\min\left\{\frac{t}{a},
\pi_p\left(1-\frac{[a]}{a}\right)\right\}.$
 \end{itemize}
 \end{lemma}

 \begin{proof}
 (a) Without loss of generality, we assume that $b\in(0, \pi_p)$.
The statement is trivial when $t\geq b$.
 If $t<b$, it is easy to see that the measure is still $t$.

 (b) First, it is clearly that if $k\pi_p\leq ax<k\pi_p+t$ for
 $k\in\mathbb{N}\cup \{ 0\}$, then $\bl ax\br_{\pi_p}<t$. This
 means that for $k=0,\dots, [a]-1$,
 $$
 \frac{k\pi_p}{a}\leq x<\frac t a+\frac{k\pi_p}{a}\,.
 $$
 When $k=[a]$, the contribution is either $\frac{t}{a}$ or
 $ \pi_p(1-\frac{|a|}{a})$.
 We conclude that (b) is also valid.
\end{proof}

 \begin{corollary} \label{coro2.2}
 Let $t\in (0,\pi_p)$ and $n\in \mathbb{N}$. As
 $n\to\infty$,
 \begin{align*}
 \mu\{x\in(0,\pi_p):\bl nx+o(1)\br_{\pi_p}<t\}
&= \mu\{x\in(0,\pi_p):\bl nx\br_{\pi_p}<t\}+o(1)\\
&= t+o(1).
 \end{align*}
 \end{corollary}

\begin{proof}
 From Lemma \ref{lem2.1}(b)$,
 \mu\{x\in(0,\pi_p):\bl nx\br_{\pi_p}<t\} =t$.
 It is clear that if $k\pi_p\leq nx+o(1)<k\pi_p+t$ for
 $k\in\mathbb{N}\cup \{ 0\}$, then $\bl nx+o(1)\br_{\pi_p}<t$.
This means that for $k=0,\dots, n-1$,
 $$
 \frac{k\pi_p}{n}+o(\frac 1n)\leq x<\frac{k\pi_p}{n}+\frac t n+o(\frac 1 n).
 $$
 The case $k=n$ only contributes $ o(\frac 1n)$.
 We conclude that the formula is valid.
 \end{proof}

 We also need an eigenvalue asymptotic result proved in \cite{CLLW}.

 \begin{lemma} \label{lem2.3}
 The eigenvalues $\la_n$ in the $p$-Laplacian eigenvalue problem
 \eqref{eq1.3} has the following asymptotic formula
\begin{equation}
\begin{aligned}
 \lambda_n^{1/p}
&= n_{\alpha\beta}\pi_p+\frac{\widetilde{CT_p}(\beta)^{(p-1)}
 - \widetilde{CT_p}(\alpha)^{(p-1)}}{(n_{\alpha\beta}\pi_p)^{p-1}}
 +\frac{1}{p(n_{\alpha\beta}\pi_p)^{p-1}}\int^1_0q+o(\frac{1}{n^{p-1}})\\
&= n_{\al\be}\pi_p +o(1).
\end{aligned}\label{eq2.1}
\end{equation}
where
 $$
 n_{\alpha\beta}=\begin{cases}
 n,&\text{if } \alpha=\beta=0\\
 n-\frac{1}{2},&\text{if } \alpha=0<\beta\text{ or } \alpha>0=\beta\\
 n-1,&\text{if } \alpha,; \beta>0\,,
 \end{cases}
 $$
 and, for any $\gamma\in[0, \pi_p)$,
 $$
 \widetilde{CT_p}(\ga)^{(p-1)}=\begin{cases}
 0 & \text{if }\gamma=0\\
 |CT_p(\ga)|^{p-2}CT_p(\ga) & \text{if }\gamma>0\,.
 \end{cases}
 $$
 \end{lemma}

 \begin{proof}[Proof of Theorem \ref{thm1.2}]
 From \eqref{eq1.6} and \eqref{eq2.1},
 $$
 \psi_n(x )= \lambda_n^{1/p}x+\psi_n(0)+o(1)
=n_{\alpha\beta}\pi_{p}x+\psi_{{n}}(0)+o(1).
 $$
 Hence by Lemma \ref{lem2.1},
 \begin{align*}
 P_n(t)&:={\mu}\{x\in(0,1):\bl\psi_n(x)\br_{\pi_p}<t\}\\
 &= \mu\{x\in(0,1):\bl n_{\alpha\beta}\pi_px+\psi_{{n}}(0)+o(1)\br_{\pi_p}<t\}\\
 &= \frac{1}{\pi_p}\mu\{x\in(0,\pi_p):\bl n_{\alpha\beta}x\br_{\pi_p}<t\}+o(1)\\
 &= \frac{t[n_{\alpha\beta}]}{\pi_p n_{\alpha\beta}} 
+ {\min\big\{\frac{t}{n_{\alpha\beta}},\pi_{p}
 \big(1- \frac{[n_{\alpha\beta}]}{n_{\alpha\beta}}\big)\big\}}+o(1).
 \end{align*}
 By the definition of $n_{\alpha\beta}$, we conclude that 
$ P_n(t) \to\frac{t}{\pi_p}$ as $n\to\infty$.
\end{proof}

\section{Proof of Theorem \ref{thm1.1}}


We shall make use of Weyl criterion,
 a Fourier analytic equivalent condition for a equidistributed
 sequence. The criterion was given by Weyl in 1916 and has proved to
 be very useful. The interested reader may refer to
 \cite[p. 115-123]{SS} for a clear and interesting exposition.

 \begin{theorem} \label{th3.1}
 A sequence $\{ x_n\}$ is equidistributed in $(0,\pi_p)$ if and
 only if for any $k\in \mathbb{Z}\setminus\! \{0\}$,
 $$
 \lim_{N\to\infty} \sum_{n=1}^N \exp(\frac{2i k\pi x_n}{\pi_p})=0
 $$
 \end{theorem}

 \noindent\textbf{Remark.}
 When $x_n=\bl nx\br$ in the interval $(0,1)$
 with $x$ irrational, then by a scaling, the Weyl criterion is
 \begin{equation}
 \lim_{N\to\infty} \sum_{n=1}^N \exp(2\pi i k nx)=0. \label{eq1.9}
 \end{equation}
 It means that along the unit circle on the complex plane, as we
 move by an argument of $2\pi k x$ each time, the points do not
 overlap, but are so evenly distributed on the unit circle that
 their average tends to $0$.

 \begin{lemma} \label{lem3.2}
 Let $\{ b_n\}$ be a sequence in $\mathbb{R}$ such that $
 \lim_{N\to\infty} \frac{1}{N}\sum_{n=1}^N b_n = b$.
 Let the sequence $\{ a_n\}$  satisfy
 $a_n=b_n+o(1)$ as $n\to\infty$. Then 
$ \lim_{N\to\infty} \frac{1}{N}\sum_{n=1}^N a_n = b$.
 \end{lemma}

\begin{proof}
Since $\lim_{N\to\infty}\frac 1 N  \sum^N_{n=1}b_n=b$, we find that, for 
 $\varepsilon>0$, there exists a $N_1\in\mathbb{N}$ such that for all 
$N\geq  N_1$,
\[
\big|\frac 1 N\sum^{N}_{n=1}b_n-b\big|\leq\frac\varepsilon 3.
\]
On the other hand,
 $a_n=b_n+o(1)$ as $n\to\infty$. Given $\varepsilon>0$, there exists a 
$N_2\in\mathbb{N}$
 such that for all $n\geq N_2$, $|a_n-b_n|\leq\frac\varepsilon 3$.
 Now let
\[
 M=\sum^{N_2-1}_{n=1}|a_n-b_n|.
\]
 Let
$N_0\in\mathbb{N}$ be such that $N_{0}\geq \max\{N_1, N_2, \frac{3M}{\varepsilon}\}$. 
Then for all $N\geq N_0$,
 \begin{align*}
 \big|\frac 1 N\sum^N_{n=1}a_n-b\big|
&\leq \big|\frac 1 N\sum^N_{n=1}(a_n-b_n)\big|
+\big|\frac{1}{N}\sum^N_{n=1}b_n-b\big|\\
&< \frac{M+(N-N_2+1)\cdot\varepsilon/3}{N}+\frac{\varepsilon}{3}
< \varepsilon\,.
 \end{align*}
This completes the proof.
 \end{proof}

 \begin{proof}[Proof of Theorem \ref{thm1.1}]
 By Theorem \ref{th3.1}, it suffices to show that
 $$
 \lim_{N\to\infty} \sum_{n=1}^N \exp\Big(\frac{2i k\pi\psi_n(x)}{\pi_p}\Big)=0.
 $$
Fixed $x\in\mathbb{R}$, from \eqref{eq1.6} and
 \eqref{eq2.1},
 $$
\psi_n(x)=\lambda_n^{1/p}x+\psi_n(0)+o(1)=n_{\alpha\beta}\pi_px+\psi_n(0)+o(1).
 $$
If $\al=\be=0$, then $\psi_n(0)=0$ and $n_{\al\be}=n$. Hence
 $$
 \psi_n(x)=n\pi_p x+o(1).
 $$
 Since $\{ \bl n\pi_p x\br_{\pi_p}\}$ is equidistributed in
 $(0,\pi_p)$, by Lemma \ref{lem3.2}, {$\{ \bl \psi_n(x)\br_{\pi_p}\}$} is
 also equidistributed.

 If $\al>0=\be$, then by \eqref{eq1.8},
$\psi_n(0)=\frac{\pi_p}{2}+o(1)$, and $ n_{\al\be}=n-\frac{1}{2}$.
 Thus
 $$
 \psi(x)=(n-\frac{1}{2})\pi_p x+\frac{\pi_p}{2}+o(1).
 $$
 So when $x\in (0,1)$ is irrational, by taking any
 $k\in\mathbb{Z}\setminus \{ 0\}$,
 $$
 \frac{1}{N} \sum_{n=1}^N \exp\Big(2\pi i k(n-\frac{1}{2}){x}+\pi i k\Big)
 =\rme^{\pi ik(1-x)}\cdot \frac{1}{N}\sum_{n=1}^N\exp(2\pi ikn x),
 $$
 which converges to $0$ as $N\to\infty$. By Weyl's criterion, 
$\{\bl\psi_n(x)\br\}_{\pi_p}$ is  also equidistributed.

 The other cases $\al=0<\be$ and $\al,\be>0$ are similar.
 \end{proof}

 \section{Classical Pr\"ufer angle}
 
 The classical Pr\"ufer angle $\th(x)$ is defined through
 $$
 y=R(x)S_p(\th(x)),\quad y'=R(x)S_p'(\th(x)),
 $$
 and the Pr\"ufer angle $\th_{n}(x)$ associated with the $n$th eigenpair satisfies
 \begin{equation}
 CT_p(\th_n(x))= \la_n^{\frac{1}{p}} \,
 CT_p(\psi_n(x)). \label{eq4.10}
 \end{equation}
 We denote
 $$
 b_n:= \bl\th_n(x)\br_{\pi_p} =CT_p^{-1}
\Big( \la_n^{\frac{1}{p}} CT_p({n_{\alpha\beta}\pi_p
 x+\psi_n(0)+o(1)})\Big),
 $$
 taking value of the inverse function $CT_p^{-1}$ in $(0,\pi_p)$.

 \begin{theorem} \label{thm4.1}
 For $x\in(0,1)$, the sequence of classical Pr\"ufer angle 
$ \{ \bl\th_n(x)\br_{\pi_p}\}$
 is NOT equidistributed in $(0,\pi_p)$. Nor  asymptotic to
 the uniform distribution.
 \end{theorem}

 \begin{proof}
 Let $I$ be the subinterval $ ( CT_p^{-1}(1), \pi_{p}/2)\subset
 (0,\pi_p/2)$. We shall see that for any $x\in (0,1)$,
 \begin{equation}
 \lim_{N\to\infty}\sum_{n=1}^N \Bigchi_I(b_n) \neq
 {\frac{1}{2}-\frac{CT_p^{-1}(1)}{\pi_p}}.\label{eq4.1}
 \end{equation}
 Observe that
\begin{equation}
 \begin{aligned}
 \Bigchi_I(b_n)=1
&\Leftrightarrow  CT_p^{-1}\left( \la_n^{1/p} CT_p(\psi_n(x)) \right)\in
I = \left(CT_p^{-1}(1),\frac{\pi_{p}}{2}\right)\\
 &\Leftrightarrow  \lambda_n^{1/p} CT_p(\psi_n(x))\in
 \left(0,1\right)\\
 &\Leftrightarrow  \bl n_{\al\be}\pi_p x{+\psi_n(0)}+o(1)\br_{\pi_p} \in
 \big( CT_p^{-1}( \la_n^{-1/p}),\frac{\pi_{p}}{2} \big)
\end{aligned}\label{eq4.2}
 \end{equation}

 If $\al=\be=0$, then $n_{\al\be}=n$ and $\psi_n(0)=0$. Hence
 $\Bigchi_I(b_n)=1$ if and only if
 $$
 {\langle\psi_n(x)\rangle_{\pi_p}= \bl n\pi_p x+o(1)\br_{\pi_p}\in J_n:=}\left( CT_p^{-1}\left( \la_n^{-1/p} \right),\frac{\pi_{p}}{2} \right).
 $$
 Since $ \lim_{n\to\infty}CT_p^{-1}( \la_n^{-1/p}) = \frac{\pi_p}{2}$, the
 probability of $b_n$ in $I$ tends to $0$ as
 $n\to\infty$. Therefore.
 $$
 \lim_{N\to\infty} \frac{1}{N} \sum_{n=1}^N \Bigchi_I(b_n)
 {=\lim_{N\to\infty}\frac{1}{N}\sum_{n=1}^N\Bigchi_{J_n}(\langle\psi_n(x)\rangle_{\pi_p})=0<
 \frac{1}{2}-\frac{CT_p^{-1}(1)}{\pi_p},}
 $$
because $|J_n|\to 0$ as $n\to\infty$.

 In case $\al>0=\be$, by \eqref{eq4.2},
 \begin{eqnarray*}
 \Bigchi_I(b_n)=1 
&\Leftrightarrow \bl (n-\frac{1}{2})\pi_p x+\frac{\pi_p}{2}+o(1)\br_{\pi_p} \in
 \left( CT_p^{-1}\left( \la_n^{-1/p} \right),\frac{\pi_{p}}{2} \right)\\
&\Leftrightarrow \bl (n-\frac{1}{2})\pi_p x+o(1)\br_{\pi_p} \in
 \left(\frac{\pi_{p}}{2}+CT_p^{-1}(\la_n^{-1/p}) ,\pi_p\right),
 \end{eqnarray*}
 by Lemma \ref{lem2.1}(a).
 Therefore by a similar argument as above,
 $$
 \lim_{N\to\infty}\frac{1}{N}\sum_{n=1}^N
 \Bigchi_I(b_n)=0<{\frac{1}{2}- \frac{CT_p^{-1}(1)}{\pi_p}} .
 $$
 Therefore, \eqref{eq4.1} is also valid. The other cases are
 similar.
 
 On the other hand, from \eqref{eq4.10},
 \begin{align*}
 \bl\th_n(x)\br_{\pi_p}<t 
&\Leftrightarrow  CT_p^{-1}(\la_n^{\frac{1}{p}} CT_p(\psi_n(x)))<t\\
 &\Leftrightarrow \bl\psi_n(x)\br_{\pi_p}<CT_p^{-1}(\la_n^{\frac{-1}{p}}
 CT_p(t)).
 \end{align*}
 Now for any $t\in (0,\pi_p)$, 
$ CT_p^{-1}(\la_n^{\frac{-1}{p}}\, CT_p(t))\to \frac{\pi_p}{2}$. Hence
 $$
 \mu\{ x\in(0,1):\ \bl \th_n(x)\br_{\pi_p}<t\} =
 {P_n(\frac{\pi_p}{2}+o(1))}
 \to \frac{1}{2},
 $$
 as $n\to\infty$, by Theorem \ref{thm1.2}.
 \end{proof}
 
\subsection*{Acknowledgements}
The authors were partially supported by Ministry of Science and Technology, 
Taiwan (formerly National Science Council).
We would also like to thank Prof. Jhishen Tsay for ther helpful discussions.

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