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\AtBeginDocument{{\noindent\small
\emph{Electronic Journal of Differential Equations},
Vol. 2014 (2014), No. 148, pp. 1--15.\newline
ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu
\newline ftp ejde.math.txstate.edu}
\thanks{\copyright 2014 Texas State University - San Marcos.}
\vspace{9mm}}

\begin{document}
\title[\hfilneg EJDE-2014/148\hfil Two-component Camassa-Holm system]
{Initial data problems for the two-component Camassa-Holm system}

\author[X. Wang \hfil EJDE-2014/148\hfilneg]
{Xiaohuan Wang}  % in alphabetical order

\address{Xiaohuan Wang \newline
 College of Mathematics and Information Science, Henan University,
 Kaifeng 475001,  China}
\email{xhwangmaths@163.com, Phone 86+15226038672}

\thanks{Submitted June 4, 2014. Published June 24, 2014.}
\thanks{This work was supported by PRC Grant NSFC 11301146.}
\subjclass[2000]{35G25, 35B30, 35L05}
\keywords{Non-uniform dependence; Camassa-Holm system; well-posedness;
\hfill\break\indent energy estimates; initial value problem}

\begin{abstract}
 This article concerns the study of some properties of the two-component
 Camassa-Holm system. By constructing two sequences of solutions of
 the two-component Camassa-Holm system, we prove that the solution map
 of the Cauchy problem of the two-component Camassa-Holm system is not
 uniformly continuous in $H^s(\mathbb{R})$, $s>5/2$.
\end{abstract}

\maketitle
\numberwithin{equation}{section}
\newtheorem{theorem}{Theorem}[section]
\newtheorem{lemma}[theorem]{Lemma}
\newtheorem{remark}[theorem]{Remark}
\allowdisplaybreaks

\section{Introduction}

 Many authors have studied shallow water equations, of which
a typical example is Camassa-Holm (CH) equation. This equation
has been extended to a two-component integrable system (CH2) by
combining its integrability property with compressibility,
or free-surface elevation dynamics in its shallow-water interpretation
\cite{CI,HNT}:
\begin{equation}  \label{1.1}
 \begin{gathered}
 m_t+um_x+2m u_x+\sigma\rho\rho_x=0,\quad  t>0,\; x\in\mathbb{R},\\
 \rho_t+(\rho u)_x=0, \quad t>0,\; x\in\mathbb{R},
 \end{gathered}
\end{equation}
where $m=u-u_{xx}$ and $\sigma=\pm1$. We remark that $\sigma=1$ is the
hydrodynamically relevant choice, see the discussion in \cite{CI}.
Local well-posedness of  \eqref{1.1} with $\sigma=1$ was obtained by
\cite{CI,ELY}. The precise blow-up scenarios and blow-up
phenomena of strong solution for  \eqref{1.1} was
established by \cite{CI,ELY,FQ,GY,GZ,GL1}. Guan-Yin obtained the
existence of global weak solution to \eqref{1.1}. Just recently, Gui
and Liu \cite{GL2} studied  \eqref{1.1} with $\sigma=1$
in Besov space and they obtained the local well-posedness.  In
this paper, we consider the Cauchy problem of
\eqref{1.1} and study the some properties of it.


If $\rho\equiv0$, then  \eqref{1.1} becomes the
well-known Camassa-Holm equation \cite{CH}. In the past decade,
the Camassa-Holm equation has attracted much attention because
of its integrability and the existence of multi-peakon
solutions, see \cite{BC1}-\cite{CE4} and \cite{YLF}-\cite{ZC}
for the details. The Cauchy problem and initial boundary value
problem of the Camassa-Holm equation have been studied
extensively \cite{CE1,EY1}. It has been shown that the
Camassa-Holm equation is locally well-posedness \cite{CE1} for
initial data $u_0\in H^s(\mathbb{R})$, $s>3/2$. Moreover, it
has global strong solutions \cite{CE1} and finite time blow-up
solutions \cite{CE1,CE2,CE3}. On the other hand, it has global
weak solution in $H^1(\mathbb{R})$ \cite{BC1,BC2,CH,CE4}. The
advantage of the Camassa-Holm equation in comparison with the
KdV equation lies in the fact that the Camassa-Holm equation
has peaked solutions and models wave breaking (i.e. the
solution remains bounded while its slope becomes unbounded in
finite time \cite{CH,CE1,CE2,TSD}). Here peaked solutions are actually
peaked traveling waves, similar to the waves of greatest height encountered
in classical hydrodynamics, see the discussion in the papers
\cite{C2006,CE2007,T1996}.
Moreover, there is a rich geometric structure underlying
the Camassa-Holm equation, see the discussion in the papers \cite{K2007,K2008}.


Recently, some properties of solutions to the Camassa-Holm
equation have been studied by many authors. Himonas et al.
\cite{HMPZ} studied the persistence properties and unique
continuation of solutions of the Camassa-Holm equation. They
showed that a strong solution of the Camassa-Holm equation,
initially decaying exponentially together with its spacial
derivative, must be identically equal to zero if it also decays
exponentially at a later time, see \cite{ZC,FL} for the similar
properties of solutions to other shallow water equation. Just
recently, Himonas-Kenig \cite{HK} and Himonas et al. \cite{HKM}
considered the non-uniform dependence on initial data for the
Camassa-Holm equation on the line and on the circle,
respectively. Lv et al. \cite{LPW} obtained the non-uniform
dependence on initial data for $\mu$-$b$ equation. Lv-Wang
\cite{LWjmp} considered the  \eqref{1.1} with
$\rho=\gamma-\gamma_{xx}$ and obtained the non-uniform
dependence on initial data. Wang \cite{Wxh} obtained the
non-uniform dependence on initial data of periodic Camassa-Holm
system. Tang-Wang \cite{TW} obtained the H\"{o}lder continuous of
Camassa-Holm system.

In this paper, we  consider the non-uniform dependence on
initial data for \eqref{1.1}. We remark that there is
significant difference between  \eqref{1.1} and
\eqref{1.1} with $\rho=\gamma-\gamma_{xx}$. It is easy to see
that when $\rho=\gamma-\gamma_{xx}$, there are some similar
properties between the two equations in  \eqref{1.1}.
Thus the proof of non-uniform dependence on initial data to
 \eqref{1.1} with $\rho=\gamma-\gamma_{xx}$ is similar to
the single equation, for example, Camassa-Holm equation. But in
 \eqref{1.1}, $\rho$ and $u$ have different properties,
see Theorem \ref{t2.1}. This needs construct different
asymptotic solution, see section 3. Besides, the results in this
paper are different from those in \cite{LPW} because of the difference
of the two operators $1-\partial_{xx}$ and $\mu-\partial_{xx}$.

This article is organized as follows. In section 2, we recall the
well-posedness result of Constantin-Ivanov \cite{CI} and Escher
et al. \cite{ELY} and use it to prove the basic energy estimate
from which we derive a lower bound for the lifespan of the
solution as well as an estimate of the $H^s(\mathbb{R})\times
H^{s-1}(\mathbb{R})$ norm of the solution $(u(t,x),\rho(t,x))$
in terms of $H^s(\mathbb{R})\times H^{s-1}(\mathbb{R})$ norm of
the initial data $(u_0,\rho_0)$. In section 3, we construct
approximate solutions, compute the error and estimate the
$H^1$-norm of this error. In section 4, we estimate the
difference between approximate and actual solutions, where the
exact solution is a solution to  \eqref{1.1} with initial
data given by the approximate solutions evaluated at time zero.
The non-uniform dependence on initial data for
\eqref{1.1} is established in section 5 by constructing two
sequences of solutions to  \eqref{1.1} in a bounded
subset of the Sobolev space $H^s(\mathbb{R})$, whose distance
at the initial time is converging to zero while at any later
time it is bounded below by a positive constant.

\textbf{Notation.} In the following, we denote by $\ast$ the
spatial convolution. Given a Banach space $Z$, we denote its
norm by $\|\cdot\|_Z$. Since all space of functions are over
$\mathbb{R}$, for simplicity, we drop $\mathbb{R}$ in our
notations of function spaces if there is no ambiguity. Let
$[A,B]=AB-BA$ denotes the commutator of linear operator $A$ and
$B$. Set $\|z\|_{H^s\times
H^{s-1}}^2=\|u\|_{H^s}^2+\|\rho\|_{H^{s-1}}^2$, where
$z=(u,\rho)$.

\section{Local well-posedness}

In this section we first recall the known results of
Constantin-Ivanov \cite{CI} and Escher et al. \cite{ELY} and
give a new estimate of the solution to \eqref{1.1}.

Let $\Lambda=(1-\partial^2_x)^{1/2}$. Then the operator
$\Lambda^{-2}$ acting on $L^2(\mathbb{R})$ can be expressed by
its associated Green's function $G(x)=\frac{1}{2}e^{-|x|}$ as
\[
\Lambda^{-2}f(x)=(G\ast f)(x)=\frac{1}{2}\int_{-\infty}^\infty
e^{-|x-y|} f(y){\rm d}y, \quad f\in L^2(\mathbb{R}).
\]
Hence \eqref{1.1} is equivalent to the system
  \begin{equation} \label{2.1}
\begin{gathered}
 u_t+uu_x=-\partial_x\Lambda^{-2}\big(u^2+\frac{1}{2}u^2_x+\frac{1}{2}\rho^2
\big),\quad  t>0,\; x\in\mathbb{R},\\
 \rho_t+u\rho_x=-u_x\rho,\quad t>0, \; x\in\mathbb{R},
 \end{gathered}
 \end{equation}
with initial data
   \begin{equation}
 u(0,x)=u_0(x),\quad \rho(0,x)=\rho_0(x), \quad  x\in\mathbb{R}.
   \label{2.1a}
   \end{equation}
The following result is given by Constantin-Ivanov \cite{CI}
and Escher et al. \cite{ELY}.

\begin{theorem}\label{t2.1}
Given $z_0=(u_0,\rho_0)\in H^s\times H^{s-1}$,
$s\geq2$. Then there exists a maximal existence time
$T=T(\|z_0\|_{H^s\times H^{s-1}})>0$ and a unique solution
$z=(u,\rho)$ to  \eqref{2.1} with \eqref{2.1a}
such that
\[
z=z(\cdot,z_0)\in C([0,T);H^s\times H^{s-1})\cap
C^1([0,T);H^{s-1}\times H^{s-2}).
\]
Moreover, the solution depends continuously on the initial
data, i.e. the mapping
\[
z_0\mapsto z(\cdot,z_0): H^s\times H^{s-1}\to
C([0,T);H^s\times H^{s-1})\cap C^1([0,T);H^{s-1}\times H^{s-2})
\]
is continuous.
 \end{theorem}


Next, we will give an explicit estimate for the maximal
existence time $T$. Also, we will show that at any time $t$ in
the time interval $[0,T_0]$ the $H^s$-norm of the solution
$z(t,x)$ is dominated by the $H^s$-norm of the initial data
$z_0(x)$. In order to do this, we need the following lemmas.


\begin{lemma}[\cite{IM}] \label{l2.3}
 If $r>0$, then
\[
\|[\Lambda^r, f]g\|_2\leq
C(\|f_x\|_\infty\|\Lambda^{r-1}g\|_2+\|\Lambda^rf\|_2\|g\|_\infty),
\]
where $C$ is a positive constant depending only on $r$.
\end{lemma}

\begin{theorem}\label{t2.2}
Let $s>5/2$. If $z=(u,\rho)$ is a
solution of  {\rm\eqref{2.1}} with initial data $z_0$
described in Theorem \ref{t2.1}, then the maximal
existence time $T$ satisfies
\begin{equation}
T\geq T_0:=\frac{1}{2C_s\|z_0\|_{H^s\times H^{s-1}}}, \label{2.2}
\end{equation}
where $C_s$ is a constant depending only on $s$. Also, we have
 \begin{equation}
\|z(t)\|_{H^s\times H^{s-1}}\leq 2\|z_0\|_{H^s\times H^{s-1}},
\quad 0\leq t\leq T_0.  \label{2.3}
\end{equation}
 \end{theorem}

\begin{proof}
  The derivation of the lower bound for the maximal
existence time \eqref{2.2} and the solution size estimate
\eqref{2.3} is based on the following differential inequality
for the solution $z$:
  \begin{equation}
\frac{1}{2}\frac{d}{dt}\|z(t)\|_{H^s\times H^{s-1}}^2\leq
C_s\|z(t)\|_{H^s\times H^{s-1}}^3, \quad  0\leq t<T.
 \label{2.4}
\end{equation}
Suppose that \eqref{2.4} holds. Then, integrating \eqref{2.4}
from $0$ to $t$, we have
 \[
\|z(t)\|_{H^s\times H^{s-1}} \leq\frac{\|z_0\|_{H^s\times
H^{s-1}}}{1-C_s\|z_0\|_{H^s\times H^{s-1}}t}.
 \]
From this inequality it  follows that
$\|z(t)\|_{H^s\times H^{s-1}}$ is finite if
$C_s\|z_0\|_{H^s\times H^{s-1}}t<1$. Let
$T_0=\frac{1}{2C_s\|z_0\|_{H^s\times H^{s-1}}}$, then, for
$0\leq t\leq T_0$, we have
 \[
\|z(t)\|_{H^s\times H^{s-1}} \leq\frac{\|z_0\|_{H^s\times
H^{s-1}}}{1-C_s\|z_0\|_{H^s\times
H^{s-1}}T_0}=2\|z_0\|_{H^s\times H^{s-1}}.
\]

Now we prove the inequality \eqref{2.4}. Note that the products
$u u_x$ and $u\rho_x$ are only in $H^{s-1}$ if $u,\rho\in H^s$.
To deal with this problem, we will consider the following
modified system
  \begin{equation}
\begin{gathered}
 (J_\varepsilon u)_t+J_\varepsilon(u u_x)=-
 \partial_x\Lambda^{-2}\Big(J_\varepsilon u^2+\frac{1}{2}J_\varepsilon u_x^2
 +\frac{1}{2}J_\varepsilon\rho^2\Big),\quad  t>0,\; x\in\mathbb{R},
 \\
 (J_\varepsilon\rho)_t+J_\varepsilon(u\rho_x)=-
J_\varepsilon(u_x\rho),\quad
 t>0,\; x\in\mathbb{R},
 \end{gathered} \label{2.5}
 \end{equation}
where for each $\varepsilon\in(0,1]$ the operator
$J_\varepsilon$ is the Friedrichs mollifier defined by
 \[
J_\varepsilon f(x)=J_\varepsilon(f)(x)=j_\varepsilon\ast f.
  \]
Here $j_\varepsilon(x)=\frac{1}{\varepsilon}j(\frac{x}{\varepsilon})$,
and $j(x)$ is a $C^\infty$ function supported in the interval
$[-1,1]$ such that $j(x)\geq0,\,\int_\mathbb{R}j(x){\rm d}x=1$.
 Applying the operator $\Lambda^s$ and $\Lambda^{s-1}$ to the first
and second equations
of \eqref{2.5} respectively, then multiplying the resulting
equations by $\Lambda^sJ_\varepsilon u$ and
$\Lambda^{s-1}J_\varepsilon\rho$, respectively, and integrating
them with respect to $x\in\mathbb{R}$, we obtain
\begin{gather}
\begin{aligned}
\frac{1}{2}\frac{d}{dt}\|J_\varepsilon u\|^2_{H^s}
&= -\int_\mathbb{R}\Lambda^sJ_\varepsilon (u
u_x)\Lambda^sJ_\varepsilon u{\rm
d}x \\
&\quad -\int_\mathbb{R}\partial_x\Lambda^{s-2}\partial_x\Lambda^{-2}
\Big(J_\varepsilon u^2+\frac{1}{2}J_\varepsilon u_x^2
 +\frac{1}{2}J_\varepsilon\rho^2\Big)\Lambda^sJ_\varepsilon u{\rm
d}x, \end{aligned} \label{2.6}
\\
\frac{1}{2}\frac{d}{dt}\|J_\varepsilon\rho\|^2_{H^{s-1}}
=-\int_\mathbb{R}\Lambda^{s-1}J_\varepsilon
(u\rho_x)\Lambda^{s-1}J_\varepsilon \rho{\rm
d}x-\int_\mathbb{R}\Lambda^{s-1}J_\varepsilon(u_x\rho)
\Lambda^{s-1}J_\varepsilon \rho{\rm d}x. \label{2.7}
\end{gather}
Similar to \cite{Wxh}, we can estimate  the right-hand sides of
\eqref{2.6} and \eqref{2.7}.
We obtain
\begin{gather*}
\frac{1}{2}\frac{d}{dt}\|J_\varepsilon u\|^2_{H^s}
\leq C_s(\|u\|_\infty+\|\rho\|_\infty+\|
u_x\|_\infty +\|\rho_x\|_\infty)(\|u\|^2_{H^s}
+\|\rho\|^2_{H^{s-1}}),
\\
\frac{1}{2}\frac{d}{dt}\|J_\varepsilon
\rho\|^2_{H^{s-1}}
\leq C_s(\|u\|_\infty+\|\rho\|_\infty+\|
u_x\|_\infty +\|\rho_x\|_\infty)(\|u\|^2_{H^s}
+\|\rho\|^2_{H^{s-1}}).
\end{gather*}
Consequently,
 \begin{align*}
&\frac{1}{2}\frac{d}{dt}\left(\|J_\varepsilon
u\|^2_{H^s}+\|J_\varepsilon \rho\|^2_{H^{s-1}}\right)\\
& \leq C_s(\|u\|_\infty+\|\rho\|_\infty+\| u_x\|_\infty
+\|\rho_x\|_\infty)(\|u\|^2_{H^s}
+\|\rho\|^2_{H^{s-1}}).
\end{align*}
Then, letting $\varepsilon$ aproach $0$, we have
 \[
\frac{1}{2}\frac{d}{dt}\left(\|u\|^2_{H^s}+\|
\rho\|^2_{H^{s-1}}\right)\leq
C_s(\|u\|_\infty+\|\rho\|_\infty+\| u_x\|_\infty
+\|\rho_x\|_\infty)(\|u\|^2_{H^s}
+\|\rho\|^2_{H^{s-1}}),
  \]
or
 \begin{equation}
\frac{1}{2}\frac{d}{dt}\|z(t)\|^2_{H^s\times H^{s-1}}\leq
C_s(\|u(t)\|_{C^1}+\|\rho\|_{C^1})\|z(t)\|^2_{H^s\times
H^{s-1}}. \label{2.19}
\end{equation}
Since $s>5/2$, using Sobolev's inequality we have that
 \[
\|u(t)\|_{C^1}\leq C_s\|u(t)\|_{H^s},\quad
\|\rho(t)\|_{C^1}\leq C_s\|\rho(t)\|_{H^{s-1}}.
 \]
From \eqref{2.19} we obtain the desired inequality \eqref{2.4}.
This completes the proof of Theorem \ref{t2.2}.
\end{proof}

Recall that $\|z(t)\|_{H^s\times
H^{s-1}}^2=\|u(t)\|_{H^s}^2+\|\rho(t)\|_{H^{s-1}}^2$, where
$z(t)=(u(t),\rho(t))$. It follows from Theorem \ref{t2.2} that
 \begin{equation}
\|u(t)\|_{H^s},\,\|\rho(t)\|_{H^{s-1}}\leq\|z(t)\|_{H^s\times
H^{s-1}}\leq2\|z_0\|_{H^s\times H^{s-1}},\quad  0\leq t\leq T_0.
 \label{2.20}
\end{equation}

 \begin{remark}\label{r2.1} \rm
Comparing Theorem \ref{t2.2} with that in
\cite{LWjmp}, we will see that there exists a significant different
between \eqref{1.1} and \eqref{1.1} with $\rho=\gamma-\gamma_{xx}$.
In the other words, we require $s>5/2$ because of the Sobolev embedding Theorem.
But in paper \cite{LWjmp}, since $u$ and $\gamma$ have the same property, we
assume that $s>3/2$.
 \end{remark}

\section{Approximate solutions}

In this section we  first construct a two-parameter family of
approximate solutions by using a similar method to \cite{HK},
then compute the error and last estimate the $H^1$-norm of the
error.

Following \cite{HK}, our approximate solutions
$u^{\omega,\lambda}=u^{\omega,\lambda}(t,x)$ and
$\rho^{\omega,\lambda}=\rho^{\omega,\lambda}(t,x)$ to
\eqref{2.1} will consist of a low frequency and a high
frequency part, i.e.
 \[
u^{\omega,\lambda}=u_l+u^h,\quad
\rho^{\omega,\lambda}=\rho_l+\rho^h,
 \]
where $\omega$ is in a bounded set of $\mathbb{R}$ and
$\lambda>0$. The high frequency part is given by
 \begin{equation} \label{3.1}
\begin{gathered}
u^h=u^{h,\omega,\lambda}(t,x)=\lambda^{-\frac{1}{2}\delta-s}
\phi\big(\frac{x}{\lambda^\delta}\big)
\cos(\lambda x-\omega t),\\
\rho^h=\rho^{h,\omega,\lambda}(t,x)=\lambda^{-\frac{1}{2}\delta-s+1}
\psi\big(\frac{x}{\lambda^\delta}\big)\cos(\lambda x-\omega t),
\end{gathered}
\end{equation}
where $\phi$ and $\psi$ are $C^\infty$ cut-off functions such
that
 \[
\phi(x)=\begin{cases}
 1 & \text{if } |x|<1,\\
 0 & \text{if } |x|\geq2,
 \end{cases}\quad
\psi(x)=\begin{cases}
 1  &\text{if } |x|<1,\\
 0  &\text{if } |x|\geq2.
 \end{cases}
\]
 The low frequency part
 $(u_l,\rho_l)=(u_{l,\omega,\lambda}(t,x),\rho_{l,\omega,\lambda}(t,x))$
 is the solution to \eqref{2.1} with initial data
\begin{equation}
 u_l(0,x)=\omega\lambda^{-1}\tilde\phi\big(\frac{x}{\lambda^\delta}\big), \quad
 \rho_l(0,x)=\omega\lambda^{-1}\tilde\psi\big(\frac{x}{\lambda^\delta}\big),
\quad x\in\mathbb{R},   \label{3.2}
\end{equation}
where $\tilde\phi$ and $\tilde\psi$ are
$C_0^\infty(\mathbb{R})$ functions such that
 \[
\tilde\phi(x)=1 \quad\text{if } x\in \operatorname{supp}\phi\cup
\operatorname{supp}\psi.
\]
We first study the properties of $(u_l,\rho_l)$ and
$(u^h,\rho^h)$. The high frequency part $(u^h,\rho^h)$ defined
by \eqref{3.1} satisfies
   \[
\|u^h(t)\|_{H^s}\approx O(1), \quad
\|\rho^h(t)\|_{H^{s-1}}\approx O(1) \quad\text{for }\lambda\gg1
 \]
because of the following result.

\begin{lemma}[\cite{HK}] \label{l3.1}
 Let $\psi\in \mathcal{S}(\mathbb{R})$, $1<\delta<2$ and $\alpha\in\mathbb{R}$.
Then for any $s\geq0$ we have that
 \begin{equation}
\lim _{\lambda\to\infty}\lambda^{-\frac{1}{2}\delta-s}\|\psi
\big(\frac{x}{\lambda^\delta}\big)\cos(\lambda
x-\alpha)\|_{H^s}=\frac{1}{\sqrt{2}}\|\psi\|_2. \label{3.3}
\end{equation}
Relation \eqref{3.3} is also true if $\cos$ is replaced by
$\sin$.
\end{lemma}

For the low frequency part $(u_l,\rho_l)$, we have the
following result.

\begin{lemma}\label{l3.2}
Let $\omega$ belong to a bounded set of $\mathbb{R}$, $1<\delta<2$ and
$\lambda\gg1$. Then the initial-value problem \eqref{2.1}-\eqref{3.2}
has a unique solution $(u_l,\rho_l)\in C([0,T);H^s)\times
C([0,T);H^{s-1})$, for all $s>5/2$, satisfying the
estimates
 \[
\|u_l(t)\|_{H^s}\leq C_s\lambda^{-1+\frac{1}{2}\delta}, \quad
\|\rho_l(t)\|_{H^{s-1}}\leq C_{s-1}\lambda^{-1+\frac{1}{2}\delta}.
 \]
\end{lemma}

\begin{proof}
The existence and uniqueness of local a solution can
be derived from Theorem \ref{t2.1} for $s>5/2$.

It follows from \cite[Lemma 5]{HK} that
  \[
\|\psi\big(\frac{x}{\lambda^\delta}\big)\|_{H^s}
\leq\lambda^{\delta/2}\|\psi\|_{H^s},
 \]
where $s\geq0$ and $\psi\in \mathcal {S}(\mathbb{R})$. Using
the above inequality, we have that the initial data
$(u_l(0,x),\rho_l(0,x))$ satisfies the estimate
 \[
\|u_l(0)\|_{H^s}\leq|\omega|\lambda^{-1+\frac{1}{2}\delta}\|\tilde\phi\|_{H^s},\quad
\|\rho_l(0)\|_{H^{s-1}}\leq|\omega|\lambda^{-1+\frac{1}{2}\delta}
\|\tilde\psi\|_{H^{s-1}},
 \]
which decay if $\delta<2$ and $\omega$ is in a bounded set of
$\mathbb{R}$. Recall that $\|z_l(t)\|_{H^s\times
H^{s-1}}^2=\|u_l(t)\|_{H^s}^2+\|\rho_l(t)\|_{H^{s-1}}^2$, we
obtain
\[
\|z_l(0)\|_{H^s\times
H^{s-1}}=(\|u_l(0)\|_{H^s}^2+\|\rho_l(0)\|_{H^{s-1}}^2)^{1/2}\leq
|\omega|\lambda^{-1+\frac{1}{2}\delta}
(\|\tilde\phi\|^2_{H^s}+\|\tilde\psi\|^2_{H^{s-1}})^{1/2}.
 \]

It follows from \eqref{3.2} that $z_l(0)\in H^s\times H^{s-1}$
for all $s>5/2$. If $s>5/2$, then from estimate \eqref{2.2} of
Theorem \ref{t2.2}, we have
\begin{gather*}
\|u_l(t)\|_{H^s}\leq
C_s\|u_l(0)\|_{H^{s}}\leq C_s\lambda^{-1+\frac{1}{2}\delta},\\
\|\rho_l(t)\|_{H^{s-1}}\leq C_s\|\rho_l(0)\|_{H^{s-1}}\leq
C_{s-1}\lambda^{-1+\frac{1}{2}\delta}.
\end{gather*}
The proof is complete.
\end{proof}

Now we compute the error. Substituting the approximate solution
$(u^{\omega,\lambda},\rho^{\omega,\lambda})$ into the first and
second equation of \eqref{2.1}, we obtain the  error
\begin{gather*}
\begin{aligned}
 E&=u^h_t+u_lu^h_x+u^h u_{lx}+u^hu^h_x
 +\partial_x\Lambda^{-2}\Big((u^h)^2+k_1u_lu^h\\
&\quad +\frac{1}{2}(u^h_x)^2
 +u_{lx}u^h_x+\frac{1}{2}(\rho^h)^2+\rho_l\rho^h\Big),
\end{aligned}\\
F=\rho^h_t+u_l\rho^h_x+u^h\rho_{lx} +u^h\rho^h_x
+\rho^h u_{lx}+\rho_lu^h_x+\rho^hu^h_x,
\end{gather*}
where we have used that $(u_l,\rho_l)$ solves \eqref{3.2}.

Direct calculation shows that
\begin{gather*}
 u^h_t(t,x)=\omega\lambda^{-\frac{1}{2}\delta-s}
\phi\big(\frac{x}{\lambda^\delta}\big)\sin(\lambda x-\omega t),\\
\rho^h_t(t,x)=\omega \lambda^{-\frac{1}{2}\delta-s+1}
\psi\big(\frac{x}{\lambda^\delta}\big)\sin(\lambda x-\omega t).
\end{gather*}
Since $\tilde\phi=1$ if $x\in\operatorname{supp}\phi\cup\operatorname{supp}\psi$,
we can write $ u^h_t$ and $\rho^h_t$ in the form
\begin{equation}
\begin{aligned}
 u^h_t(t,x)
&= \omega\tilde\phi\big(\frac{x}{\lambda^\delta}\big)
\lambda^{-\frac{1}{2}\delta-s}\phi\big(\frac{x}{\lambda^\delta}\big)
\sin(\lambda x-\omega t)  \\
&= \lambda
u_l(0,x)\lambda^{-\frac{1}{2}\delta-s}\phi\big(\frac{x}{\lambda^\delta}\big)
\sin(\lambda x-\omega t),
\\
\rho^h_t(t,x)&= \omega \tilde\phi\big(\frac{x}{\lambda^\delta}\big)
\lambda^{-\frac{1}{2}\delta-s+1}\psi\big(\frac{x}{\lambda^\delta}\big)
\sin(\lambda x-\omega t) \\
 &= \lambda u_l(0,x)\lambda^{-\frac{1}{2}\delta-s+1}\psi\big(\frac{x}{\lambda^\delta}\big)
\sin(\lambda x-\omega t).
\end{aligned}\label{3.4}
\end{equation}
Computing the spacial derivatives of $u^h$ and $\rho^h$, we
have
\begin{equation}
\begin{aligned}
u^h_x(t,x)
&= -\lambda\lambda^{-\frac{1}{2}\delta-s}\phi\big(\frac{x}{\lambda^\delta}\big)
\sin(\lambda x-\omega
t)+\lambda^{-\frac{3}{2}\delta-s}\phi'\big(\frac{x}{\lambda^\delta}\big)
\cos(\lambda x-\omega t), \\
\rho^h_x(t,x)
&= -\lambda\lambda^{-\frac{1}{2}\delta-s+1}\psi\big(\frac{x}{\lambda^\delta}\big)
\sin(\lambda x-\omega
t)+\lambda^{-\frac{3}{2}\delta-s+1}\psi'\big(\frac{x}{\lambda^\delta}\big)
\cos(\lambda x-\omega t).
\end{aligned}\label{3.5}
\end{equation}
Combining \eqref{3.4} with \eqref{3.5}, we obtain
\begin{align*}
  u^h_t(t,x)+u_lu^h_x(t,x)
&= \lambda
 [u_l(0,x)-u_l(t,x)]\lambda^{-\frac{1}{2}\delta-s}\phi\left(\frac{x}{\lambda^\delta}
 \right)\sin(\lambda x-\omega t)\\
 &\quad +u_l(t,x)\lambda^{-\frac{3}{2}\delta-s}\phi'
 \big(\frac{x}{\lambda^\delta}\big)\cos(\lambda x-\omega t),
\\
 \rho^h_t(t,x)+u_l\rho^h_x(t,x)
&= \lambda  [u_l(0,x)-u_l(t,x)]\lambda^{-\frac{1}{2}\delta-s+1}
 \psi\big(\frac{x}{\lambda^\delta}\big)
 \sin(\lambda x-\omega t)\\
 &\quad +u_l(t,x)\lambda^{-\frac{3}{2}\delta-s+1}\psi'
\left (\frac{x}{\lambda^\delta}\right)\cos(\lambda x-\omega t).
\end{align*}
Therefore, we can rewrite the error $E$ and $F$ as
  \[
E=E_1+E_2+\dots+E_8,\quad  F=F_1+F_2+\dots+F_6,
   \]
where
\begin{gather*}
E_1 = -\lambda[u_l(0,x)-u_l(t,x)]\lambda^{-\frac{1}{2}\delta-s}
 \phi\big(\frac{x}{\lambda^\delta}\big)\sin(\lambda x+\omega t),\\
E_2 = u_l(t,x)\lambda^{-\frac{3}{2}\delta-s}\phi'\big(\frac{x}{\lambda^\delta}\big)
 \cos(\lambda x+\omega t),\\
E_3 = -u^h u_{lx},\quad
E_4 =-u^hu^h_x,\\
E_5 = -\partial_x \Lambda^{-2}\Big(\frac{k_1}{2}(u^h)^2
+\frac{k_2}{2}(\rho^h)^2\Big),\quad
 E_6 =-\partial_x \Lambda^{-2}
 \left(k_1u_lu^h+k_2\rho_l\rho^h\right), \\
E_7 = -(3-k_1)\partial_x \Lambda^{-2} (u_{lx}u^h_x) ,\ \
E_8 =\frac{3-k_1}{2}\partial_x \Lambda^{-2}\left((u^h_x)^2\right),\\
F_1 = -k_3\lambda[u_l(0,x)-u_l(t,x)]\lambda^{-\frac{1}{2}\delta-s+1}
 \psi\big(\frac{x}{\lambda^\delta}\big)\sin(\lambda x+\omega t),\\
F_2 = k_3u_l(t,x)\lambda^{-\frac{3}{2}\delta-s+1}
\psi'\big(\frac{x}{\lambda^\delta}\big)\cos(\lambda x+\omega t),\\
F_3 = -k_3u^h\rho_{lx},\ \ F_4=-k_3u^h\rho^h_x,\\
F_5 = -k_3\left(\rho^h u_{lx}+\rho_lu^h_x
 +\rho^hu^h_x\right).
\end{gather*}

Now we are ready to estimate the $H^1$-norm of each error $E_i$
and the $L^2$-norm of each error $F_j$
$(i=1,\dots,8,j=1,\dots,6)$. Let $C$ be a generic positive
constant. For any positive quantities $P$ and $Q$, we write
$P\lesssim Q$ $(P\gtrsim Q)$ means that $P\leq CQ$  $(P\geq CQ)$
in the following.

\textbf{Estimates of $\|E_1\|_{H^1}$ and $\|F_1\|_{L^2}$.} Note
that
 \[
\|fg\|_{H^1}\leq\sqrt{2}\|f\|_{C^1}\|g\|_{H^1}, \quad \forall
f\in C^1,\; g\in H^1,
\]
and $\|\phi\big(\frac{x}{\lambda^\delta}\big)\sin(\lambda
x-\omega t)\|_{C^1}=\lambda\|\phi\|_\infty$, we have
\begin{equation}
\begin{aligned}
 \|E_1\|_{H^1}
&= \lambda^{1-\frac{1}{2}\delta-s}\|\phi\left(\frac{x}
 {\lambda^\delta}\right)\sin(\lambda x-\omega t)
 [u_l(0,x)-u_l(t,x)]\|_{H^1} \\
&\lesssim \lambda^{1-\frac{1}{2}\delta-s}\|\phi\left(\frac{x}{\lambda^\delta}
  \right)\sin(\lambda x-\omega t)\|_{C^1}\|u_l(0,x)-u_l(t,x)\|_{H^1} \\
&\lesssim \lambda^{2-\frac{1}{2}\delta-s}\|u_l(0,x)-u_l(t,x)\|_{H^1}.
\end{aligned} \label{3.6}
\end{equation}
To estimate the $H^1$-norm of the difference
$u_l(0,x)-u_l(t,x)$, we apply the fundamental theorem of
calculus in time variable to obtain
\[
\|u_l(0,x)-u_l(t,x)\|_{H^1}=\int_0^t\| u_{lt}(\tau)\|_{H^1}{\rm d}\tau.
 \]
It follows from the first equation of \eqref{3.2} that
 \begin{equation}
\begin{aligned}
\| u_{lt}(t)\|_{H^1}
&\leq \|u_l u_{lx}\|_{H^1}+
 \|\partial_x\Lambda^{-2}\big(u_l^2+\frac{1}{2}u^2_{lx}+\frac{1}{2}\rho_l^2
\big)\|_{H^1} \\
&\leq \|u_l\|_{H^1}\|u_l\|_{H^2}+\|u_l^2+\frac{1}{2}u^2_{lx}+\frac{1}{2}\rho_l^2\|_2 \\
&\lesssim \|u_l\|_{H^2}^2+\|u_l\|_\infty\|u_l\|_2+ \|
u_{lx}\|_\infty\|u_l\|_{H^1}+
\|\rho_l\|_\infty\|\rho_l\|_2 \\
&\lesssim \|u_l\|_{H^2}^2+\|u_l\|_{H^1}^2+\|\rho_l\|_{H^2}^2 \\
&\lesssim \|u_l\|_{H^3}^2+\|\rho_l\|_{H^3}^2 \\
&\lesssim \lambda^{-2+\delta},\quad \lambda\gg 1,
\end{aligned} \label{3.7}
\end{equation}
where we have used Lemma \ref{l3.2} and the Sobolev embedding
Theorem $H^s\hookrightarrow L^\infty$ for $s>3/2$.

Combining \eqref{3.6} and \eqref{3.7}, we obtain
 \[
\|E_1\|_{H^1}\lesssim\lambda^{-s+\frac{1}{2}\delta}, \quad \lambda\gg1.
 \]
Similarly,
  \[
\|F_1\|_{L^2}\lesssim\lambda^{-s+\frac{1}{2}\delta}, \quad \lambda\gg1.
 \]

\textbf{Estimates of $\|E_i\|_{H^1}$ and $\|F_j\|_{H^1}$, $i=2,\dots,8,j=2,3$.}
In  \cite{LWjmp}, the authors obtained the following estimates
\begin{gather*}
\|E_2\|_{H^1}
 \lesssim \lambda^{-s-\delta},\\
\|E_3\|_{H^1},\,\|E_6\|_{H^1},\,\|E_7\|_{H^1}
 \lesssim \lambda^{-\frac{1}{2}\delta-s+1}\lambda^{-1+\frac{1}{2}\delta},
\\
\|E_4\|_{H^1},\,\|E_5\|_{H^1},\,\|E_8\|_{H^1}
\lesssim \lambda^{-\frac{1}{2} \delta-2s+2}
\end{gather*}
Similar to the estimate of $\|E_2\|_{H^1}$, we have
 \[
\|F_2\|_{L^2}\lesssim\lambda^{-s-\delta},\quad  \lambda\gg 1.
 \]
Direct calculation shows that
 \[
\|F_3\|_{L^2}=\|u^h\rho_{lx}\|_{L^2}\lesssim\|u^h\|_{L^\infty}\|\rho_{lx}\|_{H^1}
\lesssim\lambda^{-\frac{1}{2}\delta-s}\lambda^{-1+\frac{1}{2}\delta},\quad
\lambda\gg 1.
 \]


\textbf{Estimates of $\|F_4\|_{L^2}$.}  It
follows from \eqref{3.1} that
 \begin{equation}
\|u^h_x(t)\|_\infty\lesssim\lambda^{-\frac{1}{2} \delta-s+1},\quad
\|\rho^h_x(t)\|_\infty\lesssim\lambda^{-\frac{1}{2}
\delta-s+2},\quad \lambda\gg 1. \label{3.8}
\end{equation}
By using Lemma \ref{l3.1}, we have
  \begin{equation}
\begin{aligned}
 \|u^h(t)\|_{H^k}
&= \lambda^{-\frac{1}{2}\delta-s}\|\phi
 \big(\frac{x}{\lambda^\delta}\big)\cos(\lambda x-\omega t)
 \|_{H^k} \\
&= \lambda^{-s+k}\lambda^{-\frac{1}{2}\delta-k}\|\phi
 \big(\frac{x}{\lambda^\delta}\big)\cos(\lambda x-\omega t)\|_{H^k} \\
&\lesssim \lambda^{-s+k},\quad \lambda\gg 1.
\end{aligned} \label{3.9}
\end{equation}
The above inequality also holds for $\rho^h(t)$. Combining
\eqref{3.8} and \eqref{3.9}, we
obtain that, for $\lambda\gg1$,
  \[
\|F_4\|_{L^2}=\|u^h\rho^h_x\|_{L^2} \lesssim
\|u^h\|_\infty\|\rho^h\|_{H^1}\lesssim\lambda^{-\frac{1}{2} \delta-s}
 \lambda^{-s+2}\lesssim\lambda^{-\frac{1}{2} \delta-2s+2}.
\]



\textbf{Estimate of $\|F_5\|_{L^2}$.}
It follows from \eqref{3.8} and \eqref{3.9} that
\begin{align*}
\|F_5\|_{L^2}
&= \|\left(\rho^h u_{lx}+\rho_lu^h_x  +\rho^hu^h_x\right)\|_{L^2}\\
&\leq \left(\|\rho^h\|_\infty\|
u_{lx}\|_{H^1}+\|u^h_x\|_\infty\|\rho_l\|_{H^1}+
\|\rho^h\|_\infty\|u^h_x\|_{L^2}\right)\\
&\lesssim \|\rho^h\|_\infty\|u_l\|_{H^2}+\|u^h_x\|_\infty\|\rho_l\|_{H^2}+
\|\rho^h\|_\infty\|u^h_x\|_{H^1}\\
&\lesssim \lambda^{-\frac{1}{2}
\delta-s}\lambda^{-1+\frac{1}{2}\delta}+
\lambda^{-\frac{1}{2}\delta-s+1}\lambda^{-1+\frac{1}{2}\delta}
+\lambda^{-\frac{1}{2} \delta-s+1}\lambda^{-s+1},
\end{align*}
which gives
$\|F_5\|_{H^1}\lesssim\lambda^{-\frac{1}{2}\delta-2s+2}$,
$\lambda\gg 1$.

Collecting all error estimates together, we have the following
theorem.

\begin{theorem}\label{t3.1}
Let $s>5/2$ and $1<\delta<2$. When $\omega$ is in a
bounded set of $\mathbb{R}$ and $\lambda\gg1$, we have that
  \begin{equation}
\|E\|_{H^1}\lesssim\lambda^{-r_s},\quad
\|F\|_{L^2}\lesssim\lambda^{-r_s},\quad \text{for } \lambda\gg1,\; 0<t<T,
 \label{3.10}
\end{equation}
where $r_s=s-\frac{1}{2}\delta>0$.
\end{theorem}


\section{Difference between approximate and actual solutions}

In this section, we estimate the difference between the
approximate and actual solutions.
Let $(u_{\omega,\lambda}(t,x),\rho_{\omega,\lambda}(t,x))$ be
the solution to  \eqref{2.1} with initial data the value
of the approximate solution
$(u^{\omega,\lambda}(t,x),\rho^{\omega,\lambda}(t,x))$ at time
zero, that is,
$(u_{\omega,\lambda}(t,x),\rho_{\omega,\lambda}(t,x))$
satisfies
\begin{equation}
\begin{gathered}
 \partial_tu_{\omega,\lambda}-u_{\omega,\lambda}\partial_xu_{\omega,\lambda}
 -\partial_x\Lambda^{-2}
 (u_{\omega,\lambda}^2+\frac{1}{2}(\partial_xu_{\omega,\lambda})^2
 +\frac{1}{2}\rho_{\omega,\lambda}^2
 )=0,\quad t>0,\; x\in\mathbb{R},\\
 \partial_t\rho_{\omega,\lambda}-u_{\omega,\lambda}\partial_x\rho_{\omega,\lambda}-
 (\partial_xu_{\omega,\lambda}\rho_{\omega,\lambda}
 +\partial_x\rho_{\omega,\lambda}u_{\omega,\lambda})=0,\quad t>0,\;
 x\in\mathbb{R},\\
 u_{\omega,\lambda}(0,x)=u^{\omega,\lambda}(0,x)
=\omega\lambda^{-1}\tilde\phi\big(\frac{x}{\lambda^\delta}\big)+
 \lambda^{-\frac{1}{2}\delta-s}\phi\big(\frac{x}{\lambda^\delta}\big)\cos(\lambda x),
 \quad  x\in\mathbb{R},\\
  \rho_{\omega,\lambda}(0,x)=\rho^{\omega,\lambda}(0,x)=\omega\lambda^{-1}
  \tilde\psi\big(\frac{x}{\lambda^\delta}\big)+
 \lambda^{-\frac{1}{2}\delta-s+1}\psi
\big(\frac{x}{\lambda^\delta}\big)\cos(\lambda x), \quad
 x\in\mathbb{R}.
 \end{gathered} \label{4.1}
\end{equation}
Note that
$(u_{\omega,\lambda}(0,x),\rho_{\omega,\lambda}(0,x))\in
H^s\times H^{s-1}$, $s\geq2$, it follows from Lemma \ref{l3.2}
and \eqref{3.9} that
\begin{gather*}
\|u_{\omega,\lambda}(0,x)\|_{H^s}
 \leq \|u_l(0)\|_{H^s}+\|u^h(0)\|_{H^s}\lesssim\lambda^{-1+\frac{1}{2}\delta}+1,
 \quad \lambda\gg1,\\
\|\rho_{\omega,\lambda}(0,x)\|_{H^{s-1}}
\leq \|\rho_l(0)\|_{H^{s-1}}+\|\rho^h(0)\|_{H^{s-1}}
 \lesssim\lambda^{-1+\frac{1}{2}\delta}+1,\quad
\lambda\gg1.
 \end{gather*}
Therefore, if $s>5/2$, by using Theorem \ref{t2.1} and
\ref{t2.2}, we have that for any $\omega$ in a bounded set and
$\lambda\gg1$, problem \eqref{4.1} has a unique solution
$z_{\omega,\lambda}\in C([0,T];H^s)\times C([0,T];H^{s-1})$
with
 \begin{equation}
T\gtrsim \frac{1}{\|z_{\omega,\lambda}(0)\|_{H^s\times
H^{s-1}}}\gtrsim\frac{1}{1+\lambda^{-1+\frac{1}{2}\delta}}\gtrsim1.
 \label{a.1}
\end{equation}
To estimate the difference between the approximate and actual
solutions, we let
\[
v=u^{\omega,\lambda}-u_{\omega,\lambda},\quad
\sigma=\rho^{\omega,\lambda}-\rho_{\omega,\lambda}.
 \]
Then $(v,\sigma)$ satisfies
  \begin{equation}
\begin{gathered}
\begin{aligned}
&v_t-v v_x+u^{\omega,\lambda} v_x+v u^{\omega,\lambda}_x-
 \partial_x\Lambda^{-2}\Big[v^2 +\frac{1}{2}v_x^2\\
&+\frac{1}{2}\sigma^2
 -2u^{\omega,\lambda}v- u^{\omega,\lambda}_x v_x-\rho^{\omega,\lambda}\sigma
\Big]=\tilde E,\quad t>0,\;  x\in\mathbb{R},
\end{aligned}\\
 \sigma_t-v\sigma_x+u^{\omega,\lambda}\sigma_x+v\rho^{\omega,\lambda}_x-
\big(\sigma v_x- u^{\omega,\lambda}\sigma-
 \rho^{\omega,\lambda} v_x\big)=\tilde F,
 \quad t>0,\; x\in\mathbb{R},\\
v(0,x)=\sigma(0,x)=0,\quad  x\in\mathbb{R},
 \end{gathered} \label{4.2}
 \end{equation}
where
\begin{gather*}
 \tilde E= u_t^{\omega,\lambda}+u^{\omega,\lambda}
u^{\omega,\lambda}_x+\partial_x\Lambda^{-2}
\Big((u^{\omega,\lambda})^2+ \frac{1}{2}(
u^{\omega,\lambda}_x)^2+\frac{1}{2}(\rho^{\omega,\lambda})^2
\Big),\\
\tilde  F= \rho_t^{\omega,\lambda}+u^{\omega,\lambda}\rho^{\omega,\lambda}_x+
 +\rho^{\omega,\lambda} u^{\omega,\lambda}_x,
 \end{gather*}
Similar to the prove of Theorem \ref{t3.1}, $\tilde E$ and
$\tilde F$ satisfy the $H^1$-norm estimation \eqref{3.10}. Now
we prove that the $H^1$-norm of difference decays.

\begin{theorem}\label{t4.1}
Let $1<\delta<2$ and $s>5/2$, then
  \[
 \|v(t)\|_{H^1}\lesssim\lambda^{-r_s},\quad
\|\sigma(t)\|_{L^2}\lesssim\lambda^{-r_s}, \quad
 0\leq t\leq T, \; \lambda\gg 1,
 \]
where $r_s=s-\frac{1}{2}\delta>0$.
\end{theorem}

\begin{proof}  Note that
\begin{gather}
\frac{1}{2}\frac{d}{dt}\|v(t)\|^2_{H^1}
= \int_\mathbb{R}(vv_t+ v_x v_{xt}){\rm d}x,\label{4.3}\\
\frac{1}{2}\frac{d}{dt}\|\sigma(t)\|^2_{L^2}
= \int_\mathbb{R} \sigma\sigma_t{\rm d}x.  \label{4.4}
\end{gather}
Applying the operator $1-\partial_x^2=\Lambda^2$  to both sides
of the first equations of  \eqref{4.2}, we have
 \begin{gather}
\begin{aligned}
 v_t&= \Lambda^2\tilde E-\Lambda^2(u^{\omega,\lambda} v_x-
 v u^{\omega,\lambda}_x)-(2u^{\omega,\lambda}v+ u^{\omega,\lambda}_x v_x
+\rho^{\omega,\lambda}\sigma)_x \\
&\quad +\frac{1}{2}  (\sigma^2)_x+3v v_x-
 2v_x v_{xx}-v v_{xxx}+v_{xxt},
\end{aligned} \label{4.5}\\
 \sigma_t= \tilde F-(u^{\omega,\lambda}\sigma_x
+ v\rho^{\omega,\lambda}_x)-(u_x^{\omega,\lambda}\sigma+
 \rho^{\omega,\lambda} v_x)+(v\sigma)_x.
 \label{4.6}
\end{gather}
Substituting \eqref{4.5} and \eqref{4.6} into \eqref{4.3} and
\eqref{4.4}, respectively, we obtain
 \begin{gather}
\begin{aligned}
 \frac{1}{2}\frac{d}{dt}\|v(t)\|^2_{H^1}
&= \int_\mathbb{R}v\Lambda^2\tilde E{\rm d}x
-\int_\mathbb{R}v\Lambda^2(u^{\omega,\lambda} v_x+
 v u^{\omega,\lambda}_x){\rm d}x \\
&\quad -\int_\mathbb{R}v(2u^{\omega,\lambda}v+
  u^{\omega,\lambda}_x v_x+\rho^{\omega,\lambda}\sigma)_x{\rm d}x
 +\frac{1}{2}\int_\mathbb{R}v(\sigma^2 )_x{\rm d}x \\
&\quad +\int_\mathbb{R}(v(3v v_x-2 v_x v_{xx}-v v_{xxx}
 +v_{xxt})+ v_x v_{xt}) {\rm d}x,
\end{aligned}\label{4.7}\\
\begin{aligned}
\frac{1}{2}\frac{d}{dt}\|\sigma(t)\|^2_{L^2}
&= \int_\mathbb{R}\sigma\tilde
F{\rm d}x-\int_\mathbb{R} \sigma(u^{\omega,\lambda}\sigma_x+
 v\rho^{\omega,\lambda}_x){\rm d}x \\
&\quad  -\int_\mathbb{R}\sigma(\rho^{\omega,\lambda} v_x
 +\sigma u^{\omega,\lambda}_x){\rm d}x+
 \int_\mathbb{R}\sigma(v\sigma)_x {\rm d}x.
\end{aligned} \label{4.8}
\end{gather}
A direct calculation yields
 \begin{align*}
&\int_\mathbb{R}(v(3v v_x-2 v_x v_{xx}-v v_{xxx}
 +v_{xxt})+ v_x v_{xt}) {\rm d}x\\
&=\int_\mathbb{R}[(v^3)_x-(v^2 v_{xx})_x+(v
v_{xt})_x] {\rm d}x=0.
\end{align*}
Substituting the above equalities in \eqref{4.7}, and adding
the resulting equations, we obtain
\begin{align*}
&\frac{1}{2}\frac{d}{dt}\left(\|v(t)\|^2_{H^1}+\|\sigma(t)\|^2_{L^2}\right)\\
&= \int_\mathbb{R}v\Lambda^2 \tilde E{\rm
d}x+\int_\mathbb{R}\sigma\tilde F{\rm d}x-\int_\mathbb{R}
v\Lambda^2(u^{\omega,\lambda} v_x+
 v u^{\omega,\lambda}_x){\rm d}x\\
&\quad -\int_\mathbb{R} \sigma(u^{\omega,\lambda}\sigma_x+
 v\rho^{\omega,\lambda}_x){\rm d}x-\int_\mathbb{R}v
 (2u^{\omega,\lambda}v+ u^{\omega,\lambda}_x v_x
 +\rho^{\omega,\lambda}\sigma)_x{\rm d}x
 \\
 &\quad -\int_\mathbb{R}
 \sigma(\rho^{\omega,\lambda} v_x
+\sigma u^{\omega,\lambda}_x) {\rm d}x+\int_\mathbb{R}
\big[\frac{1}{2}v(\sigma^2)_x+ \sigma( v\sigma)_x\big]{\rm d}x\\
&:= I_1+I_2+\dots+I_7.
 \end{align*}
We first look at the last term $I_7$. Integrating by parts
gives
 \[
I_7=\int_\mathbb{R} \big[\frac{1}{2}v(\sigma^2)_x+ \sigma(
v\sigma)_x\big]{\rm d}x=0.
   \]

\textbf{Estimates of integrals $I_1$ and $I_2$.}  Integrating by
parts and applying the Cauchy-Schwarz inequality, we have
\begin{gather*}
\Big|\int_\mathbb{R}v\Lambda^2 \tilde E{\rm
d}x\Big|=\Big|\int_\mathbb{R}(v\tilde E- v_x\tilde E_x){\rm
d}x\Big|\leq\|\tilde E\|_{H^1}\|v(t)\|_{H^1},\\
\Big|\int_\mathbb{R}\sigma\tilde F{\rm d}x\Big|\leq\|\tilde
F\|_{L^2}\|\sigma(t)\|_{L^2}.
\end{gather*}

\textbf{Estimates of integrals $I_3$-$I_6$.}
Similar to that in \cite{LWjmp}, we obtain
\begin{align*}
\sum_{i=3}^6I_i
 &\lesssim (\|u^{\omega,\lambda}(t)\|_\infty
 +\| u^{\omega,\lambda}_x(t)\|_\infty+\| u^{\omega,\lambda}_{xx}(t)\|_\infty+
 \|\rho^{\omega,\lambda}(t)\|_\infty)\\
&\quad \times  (\|v(t)\|^2_{H^1}+\|\sigma(t)\|^2_{L^2}).
\end{align*}

Combining the estimations for $I_1$--$I_7$, we have
\begin{equation}
\begin{aligned}
&\frac{1}{2}\frac{d}{dt}(\|v(t)\|^2_{H^1}+\|\sigma(t)\|^2_{L^2}) \\
&\lesssim (\|\tilde E\|_{H^1}+\|\tilde F\|_{H^1})(\|v(t)\|_{H^1}
 +\|\sigma(t)\|_{L^2}) \\
&\quad +(\|u^{\omega,\lambda}(t)\|_\infty+\| u^{\omega,\lambda}_x(t)
 \|_\infty+\|u^{\omega,\lambda}_{xx}(t)\|_\infty
 +\|\rho^{\omega,\lambda}(t)\|_\infty+\|\rho_x^{\omega,\lambda}(t)\|_\infty
 )\\
&\quad \times (\|v(t)\|^2_{H^1}+\|\sigma(t)\|^2_{H^1}).
\end{aligned} \label{4.9}
\end{equation}
It follows from \eqref{3.1} that
\begin{gather*}
 u^h_x= -\lambda^{-\frac
 32\delta-s}\phi'\left(\frac x{\lambda^\delta}\right)\cos(\lambda
 x-\omega t)-\lambda^{-\frac\delta 2-s+1}\phi\left(\frac
 x{\lambda^\delta}\right)\sin(\lambda x-\omega t),\\
\begin{aligned}
  u^h_{xx}&= \lambda^{-\frac{5}{2}\delta-s}\phi''
 \big(\frac{x}{\lambda^\delta}\big)\cos(\lambda x-\omega t)
 -2\lambda^{-\frac{3}{2}\delta-s+1}\phi'\big(\frac{x}{\lambda^\delta}\big)
 \sin(\lambda x-\omega t)\\
 &\quad -2\lambda^{-\frac{1}{2}\delta-s+2}\phi\big(\frac{x}{\lambda^\delta}\big)
 \cos(\lambda x-\omega t).
\end{aligned}
\end{gather*}
Hence
 \[
\|u^h(t)\|_\infty+\|u^h_x(t)\|_\infty+\| u^h_{xx}(t)\|_\infty
\lesssim\lambda^{-(\frac{1}{2}\delta+s-2)}, \quad \lambda\gg1.
 \]
By using Lemma \ref{l3.2}, we have
 \[
\|u_l(t)\|_\infty+\| u_{lx}(t)\|_\infty+\|u_{lxx}(t)\|_\infty
\lesssim\lambda^{-(1-\frac{1}{2}\delta)}, \quad \lambda\gg1.
 \]
Therefore,
 \begin{equation}
\|u^{\omega,\lambda}(t)\|_\infty+\|
u_x^{\omega,\lambda}(t)\|_\infty
+\|u^{\omega,\lambda}_{xx}(t)\|_\infty
\lesssim\lambda^{-\rho_s}, \quad \lambda\gg1,  \label{4.10}
\end{equation}
where
$\rho_s=\min\{\frac{1}{2}\delta+s-2,1-\frac{1}{2}\delta\}>0$
for any $s>1$ if $\delta$ is chosen appropriately in the
interval $(1,2)$. Similarly, we can prove that
 \begin{equation}
\|\rho^{\omega,\lambda}(t)\|_\infty \lesssim\lambda^{-s},\ \
\|\rho_x^{\omega,\lambda}(t)\|_\infty \lesssim\lambda^{-\rho_s}
\ \ \lambda\gg1.
 \label{4.11}
\end{equation}
Let $\tilde z(t,x)=(v(t,x),\sigma(t,x))$ and
$\|\tilde z(t)\|_{H^1\times
L^2}^2=\|v(t)\|_{H^1}^2+\|\sigma(t)\|_{L^2}^2$, then by
\eqref{4.9}-\eqref{4.11}, we obtain that
\begin{align*}
\frac{1}{2}\frac{d}{dt}\|\tilde z(t)\|_{H^1\times
L^2}^2
&\lesssim (\|\tilde E\|_{H^1}+\|\tilde
F\|_{L^2})\|\tilde z(t)\|_{H^1\times
L^2}+\lambda^{-\rho_s}\|\tilde z(t)\|_{H^1}^2\\
&\lesssim \lambda^{-r_s}\|\tilde z(t)\|_{H^1\times
L^2}+\lambda^{-\rho_s}
 \|\tilde z(t)\|_{H^1\times L^2}^2, \quad \lambda\gg1,
\end{align*}
where we have used Theorem \ref{t3.1}. Consequently,
 \begin{equation}
\frac{d}{dt}\|\tilde z(t)\|_{H^1\times
L^2}\lesssim\lambda^{-\rho_s} \|\tilde z(t)\|_{H^1\times
L^2}+\lambda^{-r_s}, \quad \lambda\gg1.  \label{4.12}
\end{equation}
Since $\|\tilde z(0)\|_{H^1\times
L^2}=(\|v(0)\|_{H^1}^2+\|\sigma(0)\|_{L^2}^2)^{1/2}=0$ and for
$s>1$, we can choose $\delta\in(1,2)$ such that $\rho_s\geq0$,
by \eqref{4.12} and Gronwall's inequality, we obtain
 \[
\|\tilde z(t)\|_{H^1\times L^2}\lesssim\lambda^{-r_s},\quad
0\leq t\leq T, \quad \lambda\gg1.
 \]
Note that
 \[
\|v(t)\|_{H^1},\,\,\|\sigma(t)\|_{L^2}\leq\|\tilde
z(t)\|_{H^1\times L^2},
 \]
we see that
 \[
\|v(t)\|_{H^1},\; \|\sigma(t)\|_{L^2}\lesssim\lambda^{-r_s},\quad
0\leq t\leq T, \; \lambda\gg1.
\]
This completes the proof.
\end{proof}

\section{Non-uniform dependence}

In this section, we  prove non-uniform dependence for
 \eqref{2.1} by taking advantage of the information
provided by Theorem \ref{t2.1}-\ref{t2.2}, Theorem \ref{t3.1}
and Theorem \ref{t4.1}. Our main result is the following.

\begin{theorem}\label{t5.1} 
If $s>5/2$, then the data-to-solution $z(0)\to z(t)$ for  \eqref{2.1}
is not uniformly continuous from any bounded subset of
$H^s\times H^{s-1}$ into $C([-T,T];H^s)\times
C([-T,T];H^{s-1})$, where $z(0)=(u_0(x),\rho_0(x))$ and
$z(t)=(u(t,x),\rho(t,x))$. More precisely, there exist two
sequences of solutions $(u_\lambda(t),\rho_\lambda(t))$ and
$(\tilde u_\lambda(t),\tilde\rho_\lambda(t))$ to the
differential equations of {\rm\eqref{2.1}} in
$C([-T,T];H^s)\times C([-T,T];H^{s-1})$ such that
\begin{gather}
\|u_\lambda(t)\|_{H^s}+\|\tilde u_\lambda(t)\|_{H^s}
 +\|\rho_\lambda(t)\|_{H^{s-1}}+\|\tilde\rho_\lambda(t)\|_{H^{s-1}}\lesssim1,  \\
\lim _{\lambda\to\infty}\|u_\lambda(0)-\tilde
u_\lambda(0)\|_{H^s}=\lim _{\lambda\to\infty}\|\rho_\lambda(0)
-\tilde\rho_\lambda(0)\|_{H^{s-1}}=0, \label{5.2} \\
\liminf_{\lambda\to\infty}\left(\|u_\lambda(t)-\tilde
u_\lambda(t)\|_{H^s}+\|\rho_\lambda(t)-\tilde
\rho_\lambda(t)\|_{H^{s-1}}\right)\gtrsim\sin t,\quad |t|<T\leq1. \label{5.3}
\end{gather}
\end{theorem}

\begin{proof}  
Let 
$(u_\lambda(t),\rho_\lambda(t))=(u_{1,\lambda}(t,x),\rho_{1,\lambda}(t,x))$
and let $(\tilde u_\lambda(t),\tilde\rho_\lambda(t)) = \\ (u_{-1,\lambda}(t,x),\rho_{-1,\lambda}(t,x))$,
where $(u_{1,\lambda}(t,x),\rho_{1,\lambda}(t,x))$ and
$(u_{-1,\lambda}(t,x),\rho_{-1,\lambda}(t,x))$ be the unique
solution to problem \eqref{4.1} with initial data
$(u^{1,\lambda}(0,x),\rho^{1,\lambda}(0,x))$ and
$(u^{-1,\lambda}(0,x),\rho^{-1,\lambda}(0,x))$, respectively.
From Theorem \ref{t2.1} these solutions belong
to $C([0,T];H^s)\times C([0,T];H^{s-1})$. By \eqref{a.1} and
the assumptions after Theorem \ref{t2.1}, we see that $T$ is
independent of $\lambda\gg1$. Letting $k=[s]+2$ and using
estimate \eqref{2.20}, we have
\begin{equation}
\|u_{\pm1,\lambda}(t)\|_{H^k},\|\rho_{\pm1,\lambda}(t)\|_{H^{k-1}}
\lesssim\|z^{\pm1,\lambda}(0)\|_{H^k\times H^{k-1}},
 \label{5.4}
\end{equation}
where
$z^{\pm1,\lambda}(0)=(u^{\pm1,\lambda}(0),\rho^{\pm1,\lambda}(0))$
and $\|z^{\pm1,\lambda}(0)\|_{H^k\times
H^{k-1}}^2=\|u^{\pm1,\lambda}(0)\|_{H^k}^2+\|\rho^{\pm1,\lambda}(0)\|_{H^{k-1}}^2$.
If $\lambda$ is large enough, then from Lemma \ref{l3.1} we
have
\begin{align*}
\|u^{\pm1,\lambda}(t)\|_{H^k}
&\leq \|u_{\pm 1,\lambda}(t) \|_{H^k}+\lambda^{-\frac{1}{2}\delta-s}
 \|\phi\big(\frac{x}{\lambda^\delta}\big)
 \cos(\lambda x-\omega t)\|_{H^k}\\
&\lesssim \lambda^{-1+\frac{1}{2}\delta}+\lambda^{k-s}\|\phi\|_2,
\end{align*}
which gives
\begin{equation}
\|u^{\pm1,\lambda}(t)\|_{H^k}\lesssim\lambda^{k-s}. \label{5.5}
\end{equation}
Combining \eqref{5.4} with \eqref{5.5}, we obtain
\begin{equation}
\|u_{\pm1,\lambda}(t)\|_{H^k} \lesssim\lambda^{k-s}, \quad \lambda\gg1.
 \label{5.6}
\end{equation}
Estimates \eqref{5.5} and \eqref{5.6} yield
\begin{equation}
\|u^{\pm1,\lambda}(t)-u_{\pm1,\lambda}(t)\|_{H^k}\lesssim\lambda^{k-s},
\quad \lambda\gg1.  \label{5.7}
\end{equation}
Theorem \ref{t4.1} implies
\begin{equation}
\|u^{\pm1,\lambda}(t)-u_{\pm1,\lambda}(t)\|_{H^1}\lesssim
\lambda^{-r_s}, \quad \lambda\gg1.  \label{5.8}
\end{equation}
Now, applying the interpolation inequality
 \[
\|\varphi\|_{H^s}\leq\|\varphi\|^{(s_2-s)/(s_2-s_1)}_{H^{s_1}}
\|\varphi\|^{(s-s_1)/(s_2-s_1)}_{H^{s_2}}
 \]
with $s_1=1$ and $s_2=[s]+2=k$, and using estimates \eqref{5.7}
and \eqref{5.8}, we obtain
\begin{align*}
&\|u^{\pm1,\lambda}(t)-u_{\pm1,\lambda}(t)\|_{H^s}\\
&\leq \|u^{\pm1,\lambda}(t)-u_{\pm1,\lambda}(t)\|^{(k-s)/(k-1)}_{H^1}
\|u^{\pm1,\lambda}(t)-u_{\pm1,\lambda}(t)\|^{(s-1)/(k-1)}_{H^k}\\
&\lesssim \lambda^{-r_s(k-s)/(k-1)}\lambda^{(k-s)(s-1)/(k-1)}\\
&\lesssim \lambda^{-(r_s-s+1)(k-s)/(k-1)}, \quad \lambda\gg1.
\end{align*}
Hence
\begin{equation}
\|u^{\pm1,\lambda}(t)-u_{\pm1,\lambda}(t)\|_{H^s}
\lesssim\lambda^{-\varepsilon_s}, \quad \lambda\gg1,  \label{5.9}
\end{equation}
where $\varepsilon_s=(1-\frac{1}{2}\delta)/(s+2)$.

Next, we prove \eqref{5.2} and \eqref{5.3}. Note that
$0<\delta<2$, we have
\begin{gather*}
 \|u_{1,\lambda}(0)-u_{-1,\lambda}(0)\|_{H^s}
= 2\lambda^{-1}  \|\tilde\phi\big(\frac{x}{\lambda^\delta}\big)\|_{H^s}
 \leq 2\lambda^{-1+\frac{1}{2}\delta}\|\tilde\phi\|_{H^s}\to 0,\\
\|\rho_{1,\lambda}(0)-\rho_{-1,\lambda}(0)\|_{H^{s-1}}
= 2\lambda^{-1}  \|\tilde\psi\big(\frac{x}{\lambda^\delta}\big)\|_{H^{s-1}}
 \leq 2\lambda^{-1+\frac{1}{2}\delta}\|\tilde\psi\|_{H^{s-1}}\to0
\end{gather*}
as $\lambda\to\infty$, which implies that \eqref{5.2} holds. Now, we prove
\eqref{5.3}. It is easy to see that
   \[
\liminf_{\lambda\to\infty}\left(\|u_\lambda(t)-\tilde
u_\lambda(t)\|_{H^s}+\|\rho_\lambda(t)-\tilde
\rho_\lambda(t)\|_{H^{s-1}}\right)\geq
\liminf_{\lambda\to\infty}\|u_\lambda(t)-\tilde
u_\lambda(t)\|_{H^s}.
   \]
Thus we only prove that
 \[
\liminf_{\lambda\to\infty}\|u_\lambda(t)-\tilde
u_\lambda(t)\|_{H^s}\gtrsim\sin t,\quad |t|<T\leq1.
  \]
Obviously,
\begin{align*}
&\|u_{1,\lambda}(t)-u_{-1,\lambda}(t)\|_{H^s}\\
&\geq\|u^{1,\lambda}(t)-u^{-1,\lambda}(t)\|_{H^s}-
\|u^{1,\lambda}(t)-u_{1,\lambda}(t)\|_{H^s}-\|u^{-1,\lambda}(t)
 -u_{-1,\lambda}(t)\|_{H^s}.
\end{align*}
It follows from \eqref{5.9} that
\[
\|u_{1,\lambda}(t)-u_{-1,\lambda}(t)\|_{H^s}\geq
\|u^{1,\lambda}(t)-u^{-1,\lambda}(t)\|_{H^s}-c\lambda^{-\varepsilon_s},
\quad \lambda\gg1,
\]
which implies that
 \begin{equation}
\liminf_{\lambda\to\infty}\|u_{1,\lambda}(t)-u_{-1,\lambda}(t)\|_{H^s}\geq
\liminf_{\lambda\to\infty}\|u^{1,\lambda}(t)-u^{-1,\lambda}(t)\|_{H^s}.
 \label{5.10}
\end{equation}
The identity
$\cos\alpha-\cos\beta=-2\sin\frac{\alpha+\beta}{2}\sin\frac{\alpha-\beta}{2}$
gives
\[
u^{1,\lambda}(t)-u^{-1,\lambda}(t)=u_{l,1,\lambda}(t)-u_{l,-1,\lambda}(t)
+2\lambda^{-\frac{1}{2}\delta-s}\phi\big(\frac{x}{\lambda^\delta}\big)\sin\lambda
x\sin t.
 \]
Thus,
 \begin{align*}
&\|u^{1,\lambda}(t)-u^{-1,\lambda}(t)\|_{H^s}\\
&\geq 2\lambda^{-\frac{1}{2}\delta-s}
 \|\phi\big(\frac{x}{\lambda^\delta}\big)\sin\lambda
 x\|_{H^s}|\sin t|-\|u_{l,1,\lambda}(t)\|_{H^s}-
 \|u_{l,-1,\lambda}(t)\|_{H^s}\\
 &\gtrsim \lambda^{-\frac{1}{2}\delta-s}
 \|\phi\big(\frac{x}{\lambda^\delta}\big)\sin\lambda
 x\|_{H^s}|\sin t|-\lambda^{-1+\frac{1}{2}\delta}, \ \ \lambda\gg1.
 \end{align*}
Letting $\lambda\to\infty$ in the above inequality, we
have
 \begin{equation}
\liminf_{\lambda\to\infty}\|u^{1,\lambda}(t)-u^{-1,\lambda}(t)\|_{H^s}\gtrsim
|\sin t|.  \label{5.11}
\end{equation}
Summing inequalities \eqref{5.10} and \eqref{5.11} up, it
yields inequality \eqref{5.3}. This completes the proof.
\end{proof}

\subsection*{Acknowledgments}
The author is grateful to the anonymous referees for their valuable 
suggestions and comments on the original manuscript.

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\end{document}
