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\AtBeginDocument{{\noindent\small
\emph{Electronic Journal of Differential Equations},
Vol. 2014 (2014), No. 141, pp. 1--27.\newline
ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu
\newline ftp ejde.math.txstate.edu}
\thanks{\copyright 2014 Texas State University - San Marcos.}
\vspace{9mm}}

\begin{document}
\title[\hfilneg EJDE-2014/141\hfil One-dimensional Gross-Pitaevskii equation]
{Hydrodynamical form for the one-dimensional Gross-Pitaevskii equation}

\author[H. Mohamad \hfil EJDE-2014/141\hfilneg]
{Haidar Mohamad} 

\address{Haidar Mohamad \newline
Laboratoire Jacques-Louis Lions, Universit\'e Pierre et Marie
Curie, Bo\^ite Courrier 187,
75252 Paris Cedex 05, France}
\email{tartousi@ann.jussieu.fr}


\thanks{Submitted February 17, 2014. Published June 18, 2014.}
\thanks{This article is part of the PhD thesis at the univesity of
Pierre et Marie Curie (UPMC), Paris.}
\subjclass[2000]{35C07, 35C08}
\keywords{Non-linear Schr\"odinger equation; Gross-Pitaevskii equation}

\begin{abstract}
 We establish a well-posedness result for the hydrodynamical form (HGP)
 of the one dimensional Gross-Pitaevskii equation (GP) via the
 classical form of this equation. The result established in this way
 proves that (HGP) is locally well-posed since the solution of (GP)
 can  vanished at some $t\neq 0$.
\end{abstract}

\maketitle
\numberwithin{equation}{section}
\newtheorem{theorem}{Theorem}[section]
\newtheorem{lemma}[theorem]{Lemma}
\newtheorem{proposition}[theorem]{Proposition}
\newtheorem{corollary}[theorem]{Corollary}
\allowdisplaybreaks

\section{Introduction}

In this article, we focus on the equation
\begin{equation}\label{HGP}
 \begin{gathered}
         \partial_t\eta = 2\partial_x((1-\eta)v), \\
          \partial_tv = \partial_x\Big(\eta - v^2 -\frac{\partial_x\eta}{2(1-\eta)}
+ \frac{(\partial_x\eta)^2}{4(1-\eta)^2}\Big),
        \end{gathered}
\end{equation}
where $(\eta,v): (I\subset \mathbb{R})\times\mathbb{R}\to \mathbb{R}^2$,
with the condition
\begin{equation}\label{con_HGP}
 \max_{x\in \mathbb{R}}\eta(t,x)< 1, \quad \forall t\in I.
\end{equation}
This equation forms some variant of the one-dimensional Gross-Pitaevskii equation
\begin{equation}\label{GP}
 i\partial_t\Psi +\partial_x^2\Psi + (1-|\Psi|^2)\Psi = 0.
\end{equation}
Indeed, any non-vanishing solution $\Psi$ to \eqref{GP}, can be written, 
at least formally, as
 $$
\Psi = |\Psi|\exp(i\varphi).
$$
Then the two functions $\eta = 1-|\Psi|^2$ and $v= \partial_x \varphi$  
are solutions to \eqref{HGP}.
Our goal is to establish non-formal links
between these two formulations.

We begin by defining the spaces of resolution for \eqref{GP} and  \eqref{HGP}, 
and by establishing a link between these two spaces.
Let $k\in \mathbb{N}$. We define the space  $E^k$ by
$$
E^k =\big\{u \in L^{\infty}(\mathbb{R},\mathbb{C}),\quad 
\text{such that $1-|u|^2 \in L^2(\mathbb{R})$ and }
u'\in H^k(\mathbb{R}) \big\}.
$$
We endow the space $E^k$ with two distances
\begin{gather*}
d^k(u_1,u_2)= \|u_1-u_2\|_{L^\infty(\mathbb{R})}
+\||u_1|^2-|u_2|^2\|_{L^2(\mathbb{R})} 
+ \sum_{j=1}^{k+1}\|(u_1-u_2)^{(j)}\|_{L^2(\mathbb{R})},\\
d^k_{\rm loc}(u_1,u_2)= \|u_1-u_2\|_{L^\infty(-1,1)}+\||u_1|^2
 -|u_2|^2\|_{L^2(\mathbb{R})} 
 + \sum_{j=1}^{k+1}\|(u_1-u_2)^{(j)}\|_{L^2(\mathbb{R})}.
\end{gather*}
We also define the space 
$X^k(\mathbb{R}) = H^{k+1}(\mathbb{R})\times H^k(\mathbb{R})$,
equipped with the norm 
$$
\|(\eta,v)\|^2_{X^k} = \|\eta\|_{H^{k+1}}^2+\|v\|_{H^k}^2.
$$
Consider the subsets
\begin{gather*}
\mathcal{NV}^k(\mathbb{R}) = \{(\eta,v)\in X^k(\mathbb{R}),\quad 
 \max_{x\in \mathbb{R}}\eta(x)< 1 \}\subset X^k(\mathbb{R}),\\
A^k := \{ u \in E^k  : u(x) \neq 0\; 
\forall x \in \mathbb{R}\} \subset E^k.
\end{gather*}
Then we establish the following result

\begin{proposition}\label{esp_gp_hgp}
The application
$$
\begin{array}{llcl}
\varPhi : &\mathcal{NV}^k(\mathbb{R}) \times \mathbb{R}/(2\pi\mathbb{Z}) &\longrightarrow &A^k\\
          & ((\eta,v),\theta) & \longmapsto &u(x):=\sqrt{1-\eta(x)}\exp\big(i(\theta + \int_0^x v(s)\,ds)\big)
\end{array}
$$
is a bijection whose inverse is given by
$$
\begin{array}{llcl}
\varPhi^{-1} : & A^k & \longrightarrow &\mathcal{NV}^k(\mathbb{R}) \times \mathbb{R}/(2\pi\mathbb{Z})\\
          & u & \longmapsto & ((\eta(x),v(x)),\theta) := ((1-|u(x)|^2,\langle \frac{i}{\bar{u}(x)},u'(x)\rangle_\mathbb{C}),\arg(u(0))).
\end{array}
$$
The application $\varPhi$ is continuous if we provide $A^k$ with the metric 
$d^k_{\rm loc}$, but it is not
 continuous if we provide $A^k$ with the metric $d^k$. The application
$\varPhi^{-1}$ is  locally Lipschitz-continuous
if we provide $A^k$ with the metric $d^k$, but it is not so if we provide  
$A^k$ with the metric $d^k_{\rm loc}$. 
\end{proposition}

We define the  Ginzburg-Landau energy for  \eqref{HGP}  by
$$
H(\eta,v) = \frac{1}{8}\int_{\mathbb{R}}\frac{(\partial_x\eta)^2}{1-\eta}
+\frac{1}{2}\int_{\mathbb{R}}(1-\eta)v^2+\frac{1}{4}\int_{\mathbb{R}}\eta^2,
$$
and the momentum
$$
P(\eta, v)= \frac{1}{2}\int_{\mathbb{R}}\eta v.
$$
These two quantities are well defined on $\mathcal{NV}^0(\mathbb{R})$.
Our main result is the next theorem.

\begin{theorem}\label{Cauchy_HGP}
Let $k\in \mathbb{N}$ and $(\eta_0,v_0)\in \mathcal{NV}^k(\mathbb{R})$. 
There exist maximal $T_\ast, T^\ast >0$ and a unique solution
 $(\eta,v)\in \mathcal{C}(-T_\ast, T^\ast, \mathcal{NV}^k)$ 
to equation \eqref{HGP} such that $(\eta(0,.),v(0,.)) = (\eta_0,v_0)$.
Moreover, $T_\ast, T^\ast$ are characterized by
\begin{gather*}
\lim_{t\to T^\ast}\max_{x\in \mathbb{R}}\eta(t,x)=1,\quad 
 \text{when } T^\ast < +\infty,\\
\lim_{t\to -T_\ast}\max_{x\in \mathbb{R}}\eta(t,x)=1,\quad 
 \text{when } -T_\ast > -\infty .
\end{gather*}
For all  $t\in ]T_\ast, T^\ast[$, the application
 $(\eta_0,v_0)\mapsto (\eta(t,.),v(t,.))$ is continuous from 
$\mathcal{NV}^0(\mathbb{R})$ to itself.
The energy $H$ and the momentum $P$ are constant along the flow.
\end{theorem}

\subsection{Motivation}

A stability result, in the energy space, for sums of solitons of 
equation \eqref{GP} was established in \cite{Bet_Gr_Smt} when their
speeds are mutually distinct and distinct from zero. 
A soliton of speed $c$ is a solution to \eqref{GP} of the form
$$
\Psi(t,x)= U_c(x-ct),
$$
where $U_c$ is the solution to the ordinary differential equation
\begin{equation}\label{edo_GP}
 -icU_c' + U_c'' + U_c (1-|U_c|^2)= 0.
\end{equation}
The finite energy solutions of \eqref{edo_GP} can be explicitly calculated.
If $|c|\geq \sqrt{2}$, all of them are identically constant. 
If $|c|< \sqrt{2}$, there exists a family of non-constant solutions
with finite energy. Such solutions are given by the expression
$$
U_c(x)= \sqrt{\frac{2-c^2}{2}}\tanh\Big(\frac{2-c^2}{2}x\Big) 
+ i\frac{c}{\sqrt{2}}.
$$
Notice that for $c\neq 0$, $U_c$ does not vanish on $\mathbb{R}$, 
which is important since the
stability analysis established in \cite{Bet_Gr_Smt} 
requires such solutions.
In fact, we need in what follows a reformulation of \eqref{GP}
 which only makes sense for such solutions.

\subsection{Strategy of proof}

Let $k\in \mathbb{N}$. We define the space $E^k$ by
$$
E^k =\big\{u \in L^{\infty}(\mathbb{R},\mathbb{C}),:  1-|u|^2 \in L^2(\mathbb{R}),\;
u'\in H^k(\mathbb{R}) \big\}.
$$
We provide  two distances  on the space $E^k$,  namely:
\begin{gather*}
d^k(u_1,u_2)= \|u_1-u_2\|_{L^\infty(\mathbb{R})}
+\||u_1|^2-|u_2|^2\|_{L^2(\mathbb{R})} 
+ \sum_{j=1}^{k+1}\|(u_1-u_2)^{(j)}\|_{L^2(\mathbb{R})},\\
d^k_{\rm loc}(u_1,u_2)= \|u_1-u_2\|_{L^\infty(-1,1)}+\||u_1|^2
-|u_2|^2\|_{L^2(\mathbb{R})} 
+ \sum_{j=1}^{k+1}\|(u_1-u_2)^{(j)}\|_{L^2(\mathbb{R})}.
\end{gather*}
The space $E^k$ equipped with the distance  $d^k$ is a complete space.
The strategy of proof consists of proving certain equivalence between 
\eqref{GP} and \eqref{HGP} which takes into account the
spaces of resolution $\mathcal{C}(I,E^k)$ and 
$\mathcal{C}(I,\mathcal{NV}^k(\mathbb{R}))$, respectively. 
For that purpose, it will be required
to show that the Cauchy problem for \eqref{GP} is well posed in $E^k$. 
Given any initial data $(\eta_0,v_0) \in \mathcal{NV}^k(\mathbb{R})$ of
\eqref{HGP}, we construct $\Psi_0 \in E^k$ from $(\eta_0,v_0)$. 
Considering the solution  $\Psi$ of \eqref{GP} whose initial data
is $\Psi_0$, we construct a solution 
$(\eta,v) \in \mathcal{C}(I,\mathcal{NV}^k(\mathbb{R}))$ for \eqref{HGP} with
$(\eta(0,.),v(0,.))= (\eta_0,v_0)$, and we define the time interval 
$ I = [T_1,T_2]$ in such a way that 
$\inf_{(t,x)\in I\times \mathbb{R}}|\Psi(t,x)| >0$.
This gives the existence in the space 
$\mathcal{C}(I,\mathcal{NV}^k(\mathbb{R}))$. 
To prove the uniqueness, we show that every solution
$(\eta,v)\in \mathcal{C}(I,\mathcal{NV}^k(\mathbb{R}))$  of \eqref{HGP} allows 
us to construct a solution $\Psi \in \mathcal{C}(I,E^k)$ of \eqref{GP}; hence
the uniqueness of such solution yields that of $(\eta,v)$. 
The repetition of this procedure prove the existence of $T_\ast , T^\ast$ 
mentioned in Theorem \ref{Cauchy_HGP}. The continuity property will be 
proved according to the following diagram
$$
\xymatrix{\ar @{} [dr] |{}
            (\eta_0,v_0) \ar[d] \ar[r]^-1 & \Psi_0\ar[d]^-2 \\
            (\eta(t,.),v(t,.))        & \Psi(t,.)\ar[l]^-3
}$$
where arrow (1) represents the continuity of the application 
$(\eta_0, v_0)\mapsto \Psi_0 = \sqrt{1-\eta_0}\exp(i\int_0^xv_0)$ 
from $(\mathcal{NV}^k,\|\cdot\|_{X^k})$ to $(E^k, d_{\rm loc}^k)$, 
arrow (2) represents the continuity of $\Psi(t,.)$ with respect to 
the initial data $\Psi_0$ in $(E^k, d_{\rm loc}^k)$ for all 
$t\in ]-T_\ast,T^\ast[$ and arrow (3) represents the continuity of
 the application $\Psi\mapsto (\eta , v)$.
Concerning the equation \eqref{GP}, we will show the following result.

\begin{theorem}\label{thm:cauchyGP}
Let $k\in \mathbb{N}$. For all $R>0$, there exists $T= T(k,R)>0$ such that 
if $\Psi_0 \in E^k$ satisfies
$$
\sum_{j=1}^{k+1}\|\Psi^{(j)}_0\|_{L^2} + \|1-|\Psi_0|^2\|_{L^2}   \leq R,
$$
then there exists a unique solution $\Psi\in \mathcal{C}([-T,T], (E^k,d^k))$ 
to the Cauchy problem
 \begin{gather*}
	i\partial_t\Psi+\partial_{xx} \Psi+(|\Psi|^2-1)\Psi=0 \quad \text{on } 
(-T,T)\times \mathbb{R},\\
        \Psi(0,\cdot) = \Psi_0. 
\end{gather*}
Moreover, the energy
$$
\Sigma(\Psi(t)) := \frac12 \int_\mathbb{R} |\Psi'|^2(t,x)\, dx 
+ \frac 14 \int_\mathbb{R} (1-|\Psi(t,x)|^2)^2\, dx
$$
is constant on $[-T,T]$.

If $\tilde{\Psi}_0\in E^k$ satisfies the same bounds as $\Psi_0$ and 
if $\tilde \Psi$ denotes the corresponding solution
of the Cauchy problem, then we have the continuity estimate
$$
\sup_{|t|\leq T}d^k(\Psi(t),\tilde{\Psi}(t))\leq C(R,T)d^k(\Psi_0,\tilde{\Psi}_0)
$$
where the constant $C(R,T)>0$ depends only on $R$ and $T$. 
Finally, this unique solution is globally defined ($T=+\infty$).
\end{theorem}

We will complete the result of the previous theorem by establishing the 
continuity of the flow at a fixed time $t$ with respect to the
 metric $d^0_{\rm loc}$:

\begin{proposition}\label{propo:cont}
Let $(\Psi^n_0)_{n\in \mathbb{N}}$ be some sequence in $E^0$ such that 
$\Psi_0^n \to \Psi_0$ in $(E^0,d^0_{\rm loc})$ when $n \to +\infty$. 
Then for all $t \in \mathbb{R}$,
$\Psi^n(t,\cdot) \to \Psi(t,\cdot)$ in $(E^0,d^0_{\rm loc})$, where
 $\Psi^n$ and $\Psi$ denote the global solutions of the corresponding 
Cauchy problems.
\end{proposition}

\section{Cauchy problem for GP and continuity  properties}

The main purpose of this section is to present the proofs of 
Theorem \ref{thm:cauchyGP} and Proposition \ref{propo:cont}.  
In \cite{Zhidkov}, we find many existence results of solutions to the nonlinear 
Schr\"{o}dinger equation
\begin{equation*}
 i\partial_tu + \Delta u + f(|u|^2)u = 0,
\end{equation*}
where $u: \mathbb{R}\times\mathbb{R}^N\to\mathbb{C}$ and 
$f: \mathbb{R}^+ \to \mathbb{R}$ is some smooth function.
These results are established in dimension $N =1$ of space and for 
non-vanishing solutions when $|x| \to +\infty$ with regularity
$Z^k(\mathbb{R})$, $k\in \mathbb{N}$, in space, where
$$
Z^k(\mathbb{R})= \{u \in L^{\infty}(\mathbb{R}):  u'\in H^{k-1}(\mathbb{R})\}
$$
is equipped with the norm 
$$
\|u\|_{Z^k} = \|u\|_{L^\infty(\mathbb{R})}
+\sum_{j=1}^{k}\|u^{(j)}\|_{L^2(\mathbb{R})},\quad \forall u \in Z^k(\mathbb{R}).
$$
Equation \eqref{GP} corresponds to the choice $f(s) = 1-s$, but the topology 
of space $Z^k(\mathbb{R})$ is too weak  for our needs.
In 2006, Gerard \cite{P_Ger} established a well-posedness result for  \eqref{GP}
in dimension $N=2,3$ in the space $\mathcal{C}(\mathbb{R}, E)$ with
$$
E =\{u \in H^1_{\rm loc}(\mathbb{R}^N) : \nabla u \in L^2(\mathbb{R}^N) ,\;
 1-|u|^2 \in L^2(\mathbb{R}^N)\},
$$
equipped with the distance  
$$
d(u,\tilde{u}) = \|u-\tilde{u}\|_{Z^1+H^1}+ \||u|^2-|\tilde{u}|^2\|_{L^2}.
$$
Recall that for two Banach spaces $X$ and $Y$, if we endow the space $X+Y$ 
with the norm
$$
\|v\|_{X+Y} = \inf\{\|v_1\|_X+ \|v_2\|_Y : v= v_1+v_2,\; (v_1,v_2)\in X\times Y\},
$$
then the space $(X\times Y, \|\cdot\|_{X+Y})$ is also a Banach space. 
We will follow a plan similar to the one adopted in
\cite{P_Ger}. Remark first that for  $N=1$, we have $E^0 = E$, but $d^0 \geq d$. 
In fact, for some $k$, it is possible to endow the space
$E^k$ with the distance
$$
d_k(u,\tilde{u}) = \|u-\tilde{u}\|_{Z^{k+1}+H^{k+1}}
+ \||u|^2-|\tilde{u}|^2\|_{L^2},
$$
which generalizes the distance $d$, but our choice for the distance 
$d^k$ or even $d^k_{\rm loc}$
seems more adapted to describe the link with the solutions of \eqref{HGP}. 
This specificity creates additional difficulties related to
possible slow windings of phase at infinity, By contrast, working 
in dimension one in space simplifies  greatly the treatment of
the nonlinearity through the Sobolev embeddings.

Now we prove  some important properties of   
$(E^k,d^k)$ and the Schr\"{o}dinger operator $S_t=e^{it\Delta}, t\in \mathbb{R}$.
We start by a property of $S_t$ on the Zhidkov space $Z^k(\mathbb{R})$.

\begin{lemma}\label{zhidkov}
\begin{itemize}
\item[(i)] Let $k\in \mathbb{N}$. There exists $C>0$ such that, for all  $f\in Z^k(\mathbb{R})$ and $t\in \mathbb{R}$, we have $S_tf-f\in H^k(\mathbb{R})$  and
$$\|S_tf-f\|_{H^k}\leq C(1+|t|)^{1/2}\|f\|_{Z^k}.$$
Furthermore, $$\lim_{t\to 0}\|S_tf-f\|_{H^k} = 0.$$
\item[(ii)] There exists $C>0$ such that, for all $f\in E^0$, we have
\begin{equation}\label{zhidkov_2}
 \|f\|_{L^\infty(\mathbb{R})}\leq C(1+\sqrt{\Sigma(f)}).
\end{equation}
\end{itemize}
\end{lemma}

\begin{proof}
The operator $S_t: Z^k\to Z^k$  is defined as the integral operator
\begin{equation}\label{op_schrodinger}
 \begin{gathered}
         S_t\phi = \int_{\mathbb{R}}K(t,x-y)\phi(y)dy, t\neq 0,\\
         S_0\phi = \phi ,
        \end{gathered}
\end{equation}
with $K(t,x)=\frac{\exp(\frac{ix^2}{4t})}{\sqrt{4\pi it}}$.
Here $K(t,x)$ is the fundamental solution for the operator 
$L= i\partial_t+\partial^2_x$.
We also have, for $t\neq 0$,
$$
S_t\phi =  K(t,.)\star\phi,
$$
where $\star$ is the convolution product. 
Let $\mathcal{F}$ denote the Fourier transform. We have
$$
\mathcal{F}S_t\phi = (\mathcal{F}K(t,.)).(\mathcal{F}\phi),
$$
and, for almost every $\xi \in \mathbb{R}$, we also have
\begin{align*}
 \mathcal{F}K(t,.)(\xi) 
&= \frac{1}{\sqrt{4\pi it}}\int_{\mathbb{R}}\exp
\Big(\frac{i}{4t}(x^2-4t\xi x)\Big)dx \\
&= \frac{\exp(-it\xi^2)}{\sqrt{4\pi it}}\int_{\mathbb{R}}\exp
\Big(\frac{i}{4t}(x-2t\xi)^2\Big)dx \\
&= \exp(-it\xi^2).
\end{align*}
Now let $\chi \in \mathcal{D}(\mathbb{R})$ be such that $\chi(x)=1$ when 
$|x|\leq 1$. Since
\begin{equation}
\exp(-it\xi^2)-1 = g(t,\xi)\xi,
\end{equation}
with 
\[
g(t,\xi) = -it\chi(t\xi^2)\xi\int_0^1e^{-its\xi^2}ds 
+ \frac{\exp(-it\xi^2)-1}{\xi}(1-\chi(t\xi^2)),
\]
 for all $f\in Z^k(\mathbb{R})$,  we have
\begin{align*}
 S_tf-f &= \mathcal{F}^{-1}\mathcal{F}( S_tf-f)\\
&= \mathcal{F}^{-1}((e^{-it\xi^2}-1)\mathcal{F}f)\\
&= \mathcal{F}^{-1}(g(t,\xi)\xi\mathcal{F}f)\\
&=  (\mathcal{F}^{-1}g(t,\xi))\star \partial_xf \quad \in L^2(\mathbb{R}).
\end{align*}
If $1\leq j\leq k$, we have 
$\partial_x^{(j)}(S_tf-f)= (S_t-1)\partial_x^{(j)}f \in L^2(\mathbb{R})$, 
so that $S_tf-f \in H^k(\mathbb{R})$.
To prove the inequality 
$\|S_tf-f\|_{H^k}\leq C(1+|t|)^{1/2}\|f\|_{Z^k}$,
notice  that we have on the one hand
\begin{equation}\label{schrod_ineg1}
 \|S_tf-f\|_{L^2}= \|\mathcal{F}(S_tf-f)\|_{L^2}
\leq \|g(t,.)\|_{L^\infty}\|\partial_xf\|_{L^2}.
\end{equation}
On the other hand,\footnote{See the variations of the real function 
$\xi \mapsto |\frac{\exp(-it\xi^2)-1}{\xi}|$.}
there exists $C_1>0$ such that $\|g(t,.)\|_{L^\infty}\leq C_1\sqrt{|t|}$, and, 
if  $1\leq j\leq k$, we have
$$
\|\partial_x^{(j)}(S_tf-f)\|_{L^2}
= \|\mathcal{F}\partial_x^{(j)}(S_tf-f)\|_{L^2}
\leq 2\|\mathcal{F}\partial^{(j)}_xf\|_{L^2}= 2\|\partial^{(j)}_xf\|_{L^2}.
$$
This proves the existence of $C>0$ such that 
$$
\|S_tf-f\|_{H^k} \leq C(1+|t|)^{1/2}\|f\|_{Z^k}.
$$
The fact that $\lim_{t\to 0}\|S_tf-f\|_{H^k} =0$ follows 
from \eqref{schrod_ineg1} and from the continuity of the application\\
$t\mapsto S_t\partial_x^{(j)}f: \mathbb{R}\to L^2(\mathbb{R})$ when $j \geq 1$.

To prove the inequality \eqref{zhidkov_2}, let 
$\chi \in \mathcal{D}(\mathbb{C},\mathbb{R})$ be such that 
$0\leq \chi \leq 1$, $\chi(z) = 1$
when $|z|\leq 1$ and $\chi(z) =0$ when $|z|\geq 3$. We set 
$$
f= f_1 + f_2,
$$
with $f_1 = \chi(f)f$ and $f_2 = (1-\chi(f))f$. Clearly, we have
$$
\|f\|_{L^\infty(\mathbb{R})}\leq \|f_1\|_{L^\infty(\mathbb{R})}
+\|f_2\|_{L^\infty(\mathbb{R})}.
$$
We also have
\begin{equation}\label{major_7}
 \|f_1\|_{L^\infty(\mathbb{R})} \leq 3.
\end{equation}
 Let us now show that $f_2 \in H^1(\mathbb{R})$. since
$$
f_2  = (1-\chi(f))f \mathbf{1}_{\{x,\quad|f(x)|\geq 2\}},
$$  
we have   
$$
|f_2| \leq |f|(1- \chi(f))\leq (1+|f|)(|f|-1)= |f|^2-1 \in L^2(\mathbb{R}).
$$
On the other hand, we also have
$$
f'_2 = (1-\chi(f)-\partial_f\chi(f))f'\in L^2(\mathbb{R}).$$
Hence, $f'_2 \in H^1(\mathbb{R})$ and there exists $C_1 >0$ and 
$C_2 = C_2(\chi) >0$ such that
\begin{equation}\label{major_6}
\|f_2\|_{L^\infty(\mathbb{R})} \leq C_1\|f_2\|_{H^1(\mathbb{R})}\quad \text{and} 
\quad \|f_2\|_{H^1(\mathbb{R})} \leq C_2\sqrt{\Sigma(f)}.
\end{equation}
Combining \eqref{major_7} and \eqref{major_6}, we deduce that there exists 
$C>0$ such that
$$
\|f\|_{L^\infty(\mathbb{R})} \leq C(1+\sqrt{\Sigma(f)}).
$$
\end{proof}

\begin{lemma}\label{inclusion}
 For every $k\in \mathbb{N}$, we have
\begin{equation}\label{inc}
 E^k + H^{k+1}(\mathbb{R})\subset E^k.
\end{equation}
Moreover, there exists $C_1, C_2 >0$ such that, for every  
$(v,w), (\tilde{v}, \tilde{w}) \in E^k\times H^{k+1}(\mathbb{R})$, we have
\begin{gather} \label{injec_1_bis}
\begin{aligned}
 d^k(v+w, \tilde{v}+\tilde{w}) 
&\leq C_1\left(k+\|v\|_{L^\infty}+\|\tilde{v}\|_{L^\infty}+\|w\|_{L^2}
+\|\tilde{w}\|_{L^2}+\right)\|w-\tilde{w}\|_{H^{k+1}} \\
&\quad + (1+\|\tilde{w}\|_{L^2}+\|w\|_{L^2})d^k(v,\tilde{v}),
\end{aligned} \\
\label{injec_1} 
\begin{aligned}
 d^k(v+w, \tilde{v}+\tilde{w}) 
&\leq C_2\left(k+1+\|w\|_{L^2}+\|\tilde{w}\|_{L^2}+\sqrt{\Sigma(v)}
 +\sqrt{\Sigma(\tilde{v})}\right)\|w-\tilde{w}\|_{H^{k+1}} \\
&\quad  + (1+\|\tilde{w}\|_{L^2}+\|w\|_{L^2})d^k(v,\tilde{v}).
\end{aligned}
\end{gather}
\end{lemma}

\begin{proof}
Let $(v,w) \in E^k\times H^{k+1}$. Since
$$
|v+w|^2-1= |v|^2-1+2\operatorname{Re}(w\bar{v})+|w|^2,
$$
and since $(v,w)\in L^\infty(\mathbb{R})\times H^{1}(\mathbb{R})$, 
we have $\operatorname{Re}(w\bar{v}), |w|^2 \in L^2(\mathbb{R})$. 
This proves \eqref{inc}.
Let now $(v,w), (\tilde{v}, \tilde{w}) \in E^k\times H^{k+1}(\mathbb{R})$. 
There exists $C>0$ such that
\begin{equation} \label{major_1}
\begin{aligned}
d^k(v+w,\tilde{v}+\tilde{w})
&\leq \|v-\tilde{v}\|_{L^\infty}+C\|w-\tilde{w}\|_{H^{k+1}}
 +\||v+w|^2-|\tilde{v}+\tilde{w}|^2\|_{L^2}\notag \\
&\quad +\sum_{j=1}^{k+1}\|(v-\tilde{v})^{(j)}\|_{L^2}
 + \sum_{j=1}^{k+1}\|(w-\tilde{w})^{(j)}\|_{L^2}.
\end{aligned}
\end{equation}
Using the identity
$$
|v+w|^2-|\tilde{v}+\tilde{w}|^2
= |v|^2-|\tilde{v}|^2+2\operatorname{Re}(w\bar{v}
-\tilde{w}\bar{\tilde{v}})+|w|^2-|\tilde{w}|^2,
$$
and the relations
\begin{gather*}
        w\bar{v}-\tilde{w}\bar{\tilde{v}}
= (w-\tilde{w})\bar{v}+\tilde{w}\overline{(v-\tilde{v})},\\
        w\bar{v}-\tilde{w}\bar{\tilde{v}}
= (w-\tilde{w})\bar{\tilde{v}}+w\overline{(v-\tilde{v})},\\
        |w|^2-|\tilde{w}|^2 = (|w|+|\tilde{w}|)(|w|-|\tilde{w}|),
       \end{gather*}
we obtain
\begin{align*}
 \||v+w|^2-|\tilde{v}+\tilde{w}|^2\|_{L^2}
&\leq \||v|^2-|\tilde{v}|^2\|_{L^2}+(\|w\|_{L^2}
 +\|\tilde{w}\|_{L^2}+\|v\|_{L^\infty} \\
&\quad  +\|\tilde{v}\|_{L^\infty})\|w-\tilde{w}\|_{L^2}
 +(\|w\|_{L^2}+ \|\tilde{w}\|_{L^2})\|v-\tilde{v}\|_{L^\infty}.
\end{align*}
The conclusion follows by combining this inequality with \eqref{major_1}.
\end{proof}

The previous lemmas allow us to deduce that $E^k$ is kept invariant by $S_t$. 
Moreover, we have the following two continuity properties.

\begin{lemma}\label{cont}
 Let $t\in \mathbb{R}$ and $k\in \mathbb{N}$. Then $S_t(E^k)\subset E^k$ and, 
for each $\Psi_0\in E^k$, the application
$$
t\in \mathbb{R}\mapsto S_t\Psi_0 \in (E^k,d^k),
$$
is continuous. Moreover, for each $(\Psi_0,\tilde{\Psi}_0)\in (E^k)^2$, 
there exists 
\[
C=C\Big(k,|t|,\sqrt{\Sigma(\Psi_0)},\sqrt{\Sigma(\tilde{\Psi}_0)}\Big)
\] 
such that
\begin{equation}\label{Scrodinger_lip}
d^k(S_t\Psi_0,S_t\tilde{\Psi}_0)\leq Cd^k(\Psi_0,\tilde{\Psi}_0).
\end{equation}
\end{lemma}

\begin{proof}
Let $t\in \mathbb{R}, k\in \mathbb{N}$, and $\Psi_0\in E^k\subset Z^{k+1}$. 
Writing  $S_t\Psi_0 = \Psi_0+S_t\Psi_0 -\Psi_0$ and using
Lemmas \ref{zhidkov} and \ref{inclusion}, we find that $S_t\Psi_0\in E^k$.
 To show the continuity of the application
$t\in \mathbb{R}\mapsto S_t\Psi_0 \in (E^k,d^k)$, we just need to show that
$$
\lim_{t \to 0}d^k(S_t\Psi_0,\Psi_0)=0.
$$
For this aim, we use Lemma \ref{inclusion} and deduce  that
\begin{align*}
 d^k(S_t\Psi_0,\Psi_0)
&= d^k(\Psi_0+ S_t\Psi_0-\Psi_0,\Psi_0)\\
&\leq C\Big( k+1+\|S_t\Psi_0-\Psi_0\|_{L^2}+2\sqrt{\Sigma(\Psi_0)}\Big)
\|S_t\Psi_0-\Psi_0\|_{H^{k+1}};
\end{align*}
hence we conclude by using Lemma \ref{zhidkov}.

Now let  $(\Psi_0,\tilde{\Psi}_0)\in (E^k)^2 \subset (Z^{k+1})^2$. 
In view of Lemma \ref{zhidkov}, we have
$(S_t\Psi_0 -\Psi_0,S_t\tilde{\Psi}_0-\tilde{\Psi}_0)\in (H^{k+1})^2$. 
Using Lemma \ref{inclusion}, we can write
\begin{align*}
&d^k(S_t\Psi_0,S_t\tilde{\Psi}_0)\\
&= d^k(\Psi_0+S_t\Psi_0-\Psi_0,\tilde{\Psi}_0+S_t\tilde{\Psi}_0-\tilde{\Psi}_0)\\
&\leq \Big(1+\|S_t\tilde{\Psi}_0-\tilde{\Psi}_0\|_{L^2}+\|S_t\Psi_0-\Psi_0\|_{L^2}
\Big)d^k(\Psi_0,\tilde{\Psi}_0)\\
&\quad + C\Big(k+1+\|S_t\tilde{\Psi}_0-\tilde{\Psi}_0\|_{L^2}
+\|S_t\Psi_0-\Psi_0\|_{L^2}+\sqrt{\Sigma(\Psi_0)}
+\sqrt{\Sigma(\tilde{\Psi}_0)}\Big)\\
&\quad\times \|(S_t-1)(\Psi_0-\tilde{\Psi}_0)\|_{H^{k+1}}.
\end{align*}
Furthermore, in view of Lemma \ref{zhidkov}, there exists $C_1>0$ such that
\begin{align*}
&d^k(S_t\Psi_0,S_t\tilde{\Psi}_0)\\
&\leq \Big(1+C_1(1+|t|)^{1/2}(\|\tilde{\Psi}_0\|_{Z^1}+\|\Psi_0\|_{Z^1})
 \Big)d^k(\Psi_0,\tilde{\Psi}_0)\\
&\quad + CC_1(1+|t|)^{1/2}
 \Big(k+1+C_1(1+|t|)^{1/2}(\|\tilde{\Psi}_0\|_{Z^1}
 +\|\Psi_0\|_{Z^1})+\sqrt{\Sigma(\Psi_0)}\\
&\quad  +\sqrt{\Sigma(\tilde{\Psi}_0)}\Big)
 \|\Psi_0-\tilde{\Psi}_0\|_{Z^{k+1}}.
\end{align*}
 Thus we conclude by using the inequality 
$\|\Psi_0-\tilde{\Psi}_0\|_{Z^{k+1}} \leq d^k(\Psi_0,\tilde{\Psi}_0)$.
\end{proof}

Let $\Psi_0 \in E^k$. The Duhamel formula for \eqref{GP} reads
$$
\Psi(t) = S_t\Psi_0 + i\int_0^tS_{t-\tau}[(1-|\Psi|^2)\Psi(\tau)]d\tau.
$$
Thus it will be useful to study the application 
$$
\Psi\mapsto \int_0^tS_{t-\tau}[(1-|\Psi|^2)\Psi(\tau)]d\tau, \quad
\forall \Psi \in \mathcal{C}([-T,T],E^k),
$$
with $T>0$ and $k\in \mathbb{N}$.

\begin{lemma}\label{cont_1}
Let $k\in \mathbb{N}$ and $T>0$. Then the application 
$$
\Psi\mapsto G(\Psi)=\int_0^tS_{t-\tau}[(1-|\Psi|^2)\Psi(\tau)]d\tau
$$
is defined from $\mathcal{C}([-T,T],E^k)$ to 
$\mathcal{C}([-T,T],H^{k+1})$. Moreover, for every $R> 0$ there exists 
$C= C(k,R)$ such that, for all
 $(\Psi,\tilde{\Psi}) \in \left(\mathcal{C}([-T,T],E^k)\right)^2$ 
with
$$
\sup_{|t|\leq T}\left(\|\partial_x\Psi(t)\|_{H^{k}}+\sqrt{\Sigma(\Psi(t))} \right)
\leq R,\quad 
\sup_{|t|\leq T}\left(\|\partial_x\tilde{\Psi}(t)\|_{H^k}
+ \sqrt{\Sigma(\tilde{\Psi}(t))}\right) \leq R,
$$
we have
\begin{equation}\label{Schrodinger_lip1}
 \sup_{|t|\leq T}\|G(\Psi)-G(\tilde{\Psi})\|_{H^{k+1}}
\leq TC(k,R)\sup_{|t|\leq T}d^k(\Psi(t),\tilde{\Psi}(t)).
\end{equation}
\end{lemma}

\begin{proof}
Let $k\in \mathbb{N}$. Let us first show that the application 
$\Psi \mapsto \Gamma(\Psi)= (1-|\Psi|^2)\Psi$ is locally Lipschitz-continuous 
from $(E^k,d^k)$ to $H^{k+1}$.
Let $(\Psi_1,\Psi_2) \in (E^k)^2$ and $j\leq k+1$. We have
\begin{equation}\label{deriv_4}
\begin{aligned}
&(\Gamma(\Psi_1)- \Gamma(\Psi_2))^{(j)} \\
&= \sum_{l=0}^{j}C_l^j(|\Psi_1|^2-|\Psi_2|^2)^{(l)}\Psi_1^{(j-l)}
+ \sum_{l=0}^{j}C_l^j(\Psi_1-\Psi_2)^{(j-l)}(|\Psi_2|^2-1)^{(l)}.
\end{aligned}
\end{equation}
We now find an upper bound for the $L^2$-norm of the first term of
the right-hand of \eqref{deriv_4}.
 If $(j\neq 0)\wedge(l\neq 0)$, we have
\begin{align*}
&(|\Psi_1|^2-|\Psi_2|^2)^{(l)}\Psi_1^{(j-l)} \\
&=  \sum_{s=0}^lC_s^l\langle\Psi_1^{(l-s)},
 (\Psi_1-\Psi_2)^{(s)}\rangle_{\mathbb{C}}\Psi_1^{(j-l)} 
 + \sum_{s=0}^lC_s^l\langle\Psi_2^{(l-s)},(\Psi_1-\Psi_2)^{(s)}
\rangle_{\mathbb{C}}\Psi_1^{(j-l)}.
\end{align*}
Hence there exists $C>0$ such that
$$
\|\langle\Psi_1^{(l-s)},(\Psi_1-\Psi_2)^{(s)}
\rangle_{\mathbb{C}}\Psi_1^{(j-l)}\|_{L^2} 
\leq C\|\Psi'_1\|^2_{H^{j-1}}d^k(\Psi_1,\Psi_2),
$$
which implies that
$$
\|(|\Psi_1|^2-|\Psi_2|^2)^{(l)}\Psi_1^{(j-l)}\|_{L^2} 
\leq C2^l\|\Psi'_1\|_{H^{j-1}}(\|\Psi'_1\|_{H^{j-1}}
+\|\Psi'_2\|_{H^{j-1}})d^k(\Psi_1,\Psi_2).
$$
If $(j\neq 0)\wedge(l = 0)$, we have
$$
\|(|\Psi_1|^2-|\Psi_2|^2)\Psi_1^{(j)}\|_{L^2} 
\leq (\|\Psi_1\|_{L^\infty}+\|\Psi_2\|_{L^\infty})\|\Psi'_1\|_{H^{j-1}}d^k
(\Psi_1,\Psi_2).
$$
If $(j= 0)\wedge(l = 0)$, we have
$$
\|(|\Psi_1|^2-|\Psi_2|^2)\Psi_1\|_{L^2} 
\leq \|\Psi_1\|_{L^\infty}d^k(\Psi_1,\Psi_2).
$$
Thus, using \eqref{zhidkov_2} to estimate  $\|\Psi_1\|_{L^\infty}$  and 
$\|\Psi_2\|_{L^\infty}$, we find that there exists 
\[
C_1=C_1\left(j,\|\Psi'_1\|_{H^{j}},\|\Psi'_2\|_{H^j},
\sqrt{\Sigma(\Psi_1)},\sqrt{\Sigma(\Psi_2)}\right)
\]
such that
$$
\|\sum_{l=0}^{j}C_l^j(|\Psi_1|^2-|\Psi_2|^2)^{(l)}\Psi_1^{(j-l)}\|_{L^2} 
\leq C_1d^k(\Psi_1,\Psi_2).
$$
A similar argument allows us to obtain the same estimate for the $L^2$-norm 
of the second term of the right-hand side of \eqref{deriv_4}. This
allows to prove the existence of
\[
C= C\left(k,\|\Psi'_1\|_{H^{k}},\|\Psi'_2\|_{H^k},
\sqrt{\Sigma(\Psi_1)},\sqrt{\Sigma(\Psi_2)}\right)
\]
 such that
$$
\|\Gamma(\Psi_1)- \Gamma(\Psi_2)\|_{H^{k+1}} \leq Cd^k(\Psi_1,\Psi_2).
$$
It follows that for all $R>0$, there exists $C(k,R)>0$ such that, 
for every $(\Psi_1, \Psi_2) \in (E^k)^2$ with
$$
\|\Psi'_1\|_{H^{k}} +\sqrt{\Sigma(\Psi_1)} \leq R,\quad \text{and}\quad 
\|\Psi'_2\|_{H^{k}} +\sqrt{\Sigma(\Psi_2)} \leq R,
$$  
we have
$$
\|\Gamma(\Psi_1)- \Gamma(\Psi_2)\|_{H^{k+1}} \leq C(k,R)d^k(\Psi_1,\Psi_2),
$$ 
and the application $\Gamma$ is locally Lipschitz.
Thus the inequality \eqref{Schrodinger_lip1} is a consequence of 
$G(\Psi) = \int_{0}^{t}S_{t-\tau}\Gamma (\Psi(\tau))d\tau$ and of
$$ 
\partial^{(j)}_xG(\Psi)= \int_{0}^{t}S_{t-\tau}\partial^{(j)}_x
\Gamma (\Psi(\tau))d\tau \quad \forall j\leq k+1.
$$
\end{proof}

\subsection{Proof of Theorem \ref{thm:cauchyGP}}

Let $T>0$. We define the set $E_T$ by
$$
E_T= \big\{\Psi \in \mathcal{C}([-T,T], E^k):
 \sup_{|t|\leq T}\Big(\sum_{j=2}^{k+1}\|\partial^{(j)}_x\Psi\|_{L^2} 
+ \sqrt{\Sigma(\Psi)}\Big)\leq 2R \big\}.
$$
In what follows, we prove that for $T$ small enough, the function
$$
\Psi \mapsto F(\Psi)= S_t\Psi_0 + iG(\Psi),
$$
is a contraction on $E_T$. Let $\Psi \in \mathcal{C}([-T,T], E^k)$. 
Lemmas \ref{cont_1} and \ref{inclusion}  imply  that
$G(\Psi)\in \mathcal{C}([-T,T], H^{k+1})$ and 
$F(\Psi)= S_t\Psi_0 + iG(\Psi) \in \mathcal{C}([-T,T], E^k)$. 
On the other hand, for $\Phi= F(\Psi)$ with
 $\Psi \in E_T$, and $t\in [-T,T]$, we have
\begin{align*}
&d^k(\Phi, \Psi_0) \\
&= d^k(S_t\Psi_0 + iG(\Psi), \Psi_0)\\
&\leq (1+ \|G(\Psi)\|_{L^2})d^k(S_t\Psi_0,\Psi_0) + C\left(k+\|S_t\Psi_0\|_{L^\infty}+\|G(\Psi)\|_{L^2}\right)\|G(\Psi)\|_{H^{k+1}}\\
&\leq C_1(R)d^k(S_t\Psi_0,\Psi_0) + TC_2(k,R),
\end{align*}
hence 
$$
\sup_{|t|\leq T}d^k(\Phi, \Psi_0)\leq C_1(R)
\sup_{|t|\leq T}d^k(S_t\Psi_0,\Psi_0)+TC_2(k,R).
$$
In view of  Lemma \ref{cont}, we have $\lim_{t\to 0}d^k(S_t\Psi_0,\Psi_0) = 0$. 
Hence there exists $T_1 >0$ such that
$$
\sup_{|t|\leq T_1}d^k(\Phi, \Psi_0)\leq (2-\sqrt{2})R,
$$  
so that
\begin{align*}
 \sup_{|t|\leq T_1}\Big(\sum_{j=2}^{k+1}\|\partial^{(j)}_x\Phi\|_{L^2} 
+ \sqrt{\Sigma(\Phi)}\Big) 
&\leq \sup_{|t|\leq T_1}d^k(\Phi, \Psi_0) 
+ \sum_{j=2}^{k+1}\|\Psi^{(j)}_0\|_{L^2} + \sqrt{2\Sigma(\Psi_0)}\\
&\leq 2R,
\end{align*}
and $F(M_{T_1}) \subset M_{T_1}$. In view of Lemmas \ref{cont_1} 
and \ref{inclusion}, there exists $C>0$ such that, 
for  $\Psi, \tilde{\Psi} \in M_T$, we have
\begin{align*}
&d^k(F(\Psi),F(\tilde{\Psi})) \\
&= d^k(S_t\Psi_0 + iG(\Psi), S_t\Psi_0 + iG(\tilde{\Psi}))\\
&\quad + C\Big(k+ 2\|S_t\Psi_0\|_{L^\infty}+\|G(\Psi)\|_{L^2}
 +\|G(\tilde{\Psi})\|_{L^2}\Big)\|G(\Psi)-G(\tilde{\Psi})\|_{H^{k+1}}\\
&\leq TC_1(k,R)\sup_{|t|\leq T}d^k(\Psi,\tilde{\Psi}).
\end{align*}
Thus proves the existence of $T= T(k,R)$ with $T_1>T>0$ such that $F$ is 
contraction on $M_T$. Thus $F$ has a unique  fixed point
$\Psi \in \mathcal{C}([-T,T],E^k,)$ which is the unique solution of \eqref{GP}. 
The proof of the Lipschitz estimate is similar.

Equation \eqref{GP} is invariant with respect to the change of variable 
$t\mapsto t+c$ ($c$ is some constant). Then a similar result to that of Theorem
\ref{thm:cauchyGP} can be  proved if we replace the initial condition at 
$t_0 =0$ by an initial condition at
$t_0 \neq 0$. This proves the existence of maximal $T^\star, T_\star >0$ 
such that the solution can be continued on the interval $]-T_\star, T^\star[$.

\subsubsection{Global well-posedness and conservation of energy in  $E^k$, $k\geq 1$}

We start with the case $k=1$. We already proved that \eqref{GP} had a maximal 
solution in the space   $\mathcal{C}(]-T_\star, T^\star[,E^1)$.
In what follows, we will show that  $]-T_\star, T^\star[ = \mathbb{R}$. 
Since $\partial_t\Psi \in L^\infty(]-T_\star, T^\star[,L^2(\mathbb{R}))$, we can write
\begin{equation}\label{cons_energie}
 \frac{d}{dt}\Sigma(\Psi(t))
= \int_{\mathbb{R}}\left(\langle\partial_x\Psi,
 \partial_x\partial_t\Psi\rangle_{\mathbb{C}}
+(|\Psi|^2-1)\langle\Psi,\partial_t\Psi\rangle_{\mathbb{C}}\right)dx = 0.
\end{equation}
Thus, we have $\Sigma(\Psi(t)) = \Sigma(\Psi_0)$ on $]-T_\star, T^\star[$.
Next we prove the existence of  $T_1>0$, depending only on $\Sigma(\Psi_0)$, 
such that
$[-T_1,T_1]\subset ]-T_\star, T^\star[$ and that $\partial^2_x\Psi(t,.)$ 
stays bounded in $L^2(\mathbb{R})$ for $|t|\leq T_1$.
For all $t\in  ]-T_\star, T^\star[$, we have
$$
|\partial^2_x((|\Psi|^2-1)\Psi)| \leq (3|\Psi|^2+1)|\partial^2_x\Psi|
+ 2|\Psi||\partial_x\Psi|^2,
$$
which next implies that
$$
\|\partial^2_x((|\Psi|^2-1)\Psi)\|_{L^2}
\leq (3\|\Psi\|^2_{L^\infty}+1)\|\partial^2_x\Psi\|_{L^2}
+ 2\|\Psi\|_{L^\infty}\|\partial_x\Psi\|^2_{L^4}.
$$
On  the other hand, using Lemma \ref{zhidkov} and Gagliardo-Nirenberg 
inequality \cite{G_Nbrg}, we find that there exist $C_1, C_2$ such that
\begin{gather*}
          \|\Psi\|_{L^\infty} \leq C_1(1+ \sqrt{\Sigma(\Psi)}),\\
          \|\partial_x\Psi\|_{L^4} 
\leq C_2  \|\partial_x\Psi\|^{3/4}_{L^2} 
\|\partial^2_x\Psi\|^{1/4}_{L^2}.
\end{gather*}
Then there exist $D_1, D_2 >0$ depending on $\Sigma(\Psi_0)$  
such that for all $T'>0$ with $[-T',T']\subset ]-T_\star, T^\star[$, we have
$$
\|\partial^2_x((|\Psi|^2-1)\Psi)\|_{L^\infty([-T',T'],L^2)}
\leq D_1\|\partial^2_x\Psi\|_{L^\infty([-T',T'],L^2)} + D_2.
$$
Combined with Duhamel formula
 \begin{equation}\label{Duhamel_1}
\Psi(t) = S_t\Psi_0-i\int_0^tS_{t-\tau}((|\Psi|^2-1)\Psi(\tau))d\tau,
\end{equation}
this shows that
$$
\|\partial^2_x\Psi\|_{L^\infty([-T',T'],L^2)} 
\leq \|\partial_x^2\Psi_0\|_{L^2} 
+ 2T'\left(D_1\|\partial^2_x\Psi\|_{L^\infty([-T',T'],L^2)} + D_2\right).
$$
This proves the existence of $T_1=T_1(\Sigma(\Psi_0))$ such that 
$[-T_1,T_1]\subset ]-T_\star, T^\star[$ and that $\partial^2_x\Psi(t,.)$ 
stays bounded in $L^2(\mathbb{R})$ for $|t|\leq T_1$.
By iterating this argument, we find that $\Psi$ can be extended into a 
global solution with $\Psi \in \mathcal{C}(\mathbb{R},E^1)$ and 
$\Sigma(\Psi(t)) = \Sigma(\Psi_0)$ for all $t\in \mathbb{R}$.

The general case $k\geq 1$ can be  treated as above.
 Indeed, for $2\leq j\leq k+1$, we have
\begin{equation}\label{deriv_j}
 ((|\Psi|^2-1)\Psi)^{(j)} 
= \sum_{l=1}^j \sum_{s=0}^l C_l^jC_s^l\langle\Psi^{(s)}, 
\Psi^{(l-s)}\rangle_{\mathbb{C}}\Psi^{(j-l)} +(|\Psi|^2-1)\Psi^{(j)},
\end{equation}
from which we obtain
$$
\|((|\Psi|^2-1)\Psi)^{(j)}\|_{L^2}\leq \sum_{l=1}^j 
\sum_{s=0}^l C_l^jC_s^l\|\Psi^{(s)} \Psi^{(l-s)}\Psi^{(j-l)}\|_{L^2}
+ (\|\Psi\|^2_{L^\infty}+1)\|\Psi^{(j)}\|_{L^2}.
$$
Thus to upper-bound the term $\|\Psi^{(s)} \Psi^{(l-s)}\Psi^{(j-l)}\|_{L^2}$, 
we discuss essentially the following two cases:
\begin{enumerate}
 \item The three indexes $s, l-s, j-l$ are mutually distinct. 
In this case we denote $l_3 = \max(s, l-s, j-l)$ and  $l_1, l_2$ 
the others two.
Then $\max(l_1,l_2)<l_3 < j$ and we have
\begin{align*}
 \|\Psi^{(s)} \Psi^{(l-s)}\Psi^{(j-l)}\|_{L^2} 
&\leq \|\Psi^{(l_1)} \Psi^{(l_2)}\|_{L^\infty}\|\Psi^{(l_3)}\|_{L^2}\\
&\leq C\|\Psi^{(l_1)} \Psi^{(l_2)}\|_{H^1}\|\Psi^{(l_3)}\|_{L^2}
\end{align*}

\item There are  two indexes $l_1 = l_2$. Let $l_3$ be the other one, then
\begin{enumerate}
 \item Either $l_1 = l_2= 0$, then $l_3= j$ and we have
$$
\|\Psi^{(s)} \Psi^{(l-s)}\Psi^{(j-l)}\|_{L^2} 
\leq \|\Psi\|^2_{L^\infty}\|\Psi^{(j)}\|_{L^2}.
$$

\item Or  $l_1 = l_2\neq 0$, then by using Gagliardo-Nirenberg  
inequality \cite{G_Nbrg}, there exists $C_1$ such that
\begin{align*}
 \|\Psi^{(s)} \Psi^{(l-s)}\Psi^{(j-l)}\|_{L^2} 
&\leq \|\Psi^{(l_3)}\|_{L^\infty} \|\Psi^{(l_1)}\|^2_{L^4}\\
&\leq C_1\|\Psi^{(l_3)}\|_{L^\infty} \|\Psi^{(l_1)}\|^{3/2}_{L^2} 
 \|\Psi^{(l_1+1)}\|^{1/2}_{L^2}\\
&\leq \frac{C_1}{2}\|\Psi^{(l_3)}\|_{L^\infty}
\left(\|\Psi^{(l_1)}\|^3_{L^2}+ \|\Psi^{(l_1+1)}\|_{L^2}\right).
\end{align*}
\end{enumerate}
\end{enumerate}
Thus, there exist $D_1, D_2 >0$ depending on $\|\Psi\|_{L^\infty}$ 
and the $L^2$-norm of the derivatives of $\Psi$ of order less than $j$,
such that
$$
\|((|\Psi|^2-1)\Psi)^{(j)}\|_{L^2}\leq D_1\|\Psi^{(j)}\|_{L^2} + D_2 .
$$
Then for every $T'>0$ such that $[-T',T']\subset ]-T_\star, T^\star[$,
 we find  using \eqref{Duhamel_1} that there exist
$E_1, E_2 >0$ depending on  $\|\Psi\|_{L^\infty}$ and the $L^2$-norm 
of the derivatives of $\Psi$ of order $<j$ such that
$$
\|\Psi^{(j)}\|_{L^\infty([-T',T'],L^2)} \leq \|\Psi_0^{(j)}\|_{L^2} 
+ 2T'\left(E_1\|\Psi^{(j)}\|_{L^\infty([-T',T'],L^2)} + E_2\right).
$$
This allows, by induction on $j$, to prove the existence of $T_j >0$ 
depending only on $\Sigma(\Psi_0)$ such that  
$[-T_j,T_j]\subset ]-T_\star, T^\star[$ and
 $\Psi^{(j)}(t,.)$ stays bounded in $L^2(\mathbb{R})$ for $|t|\leq T_j$. 
It follows that the quantity
 $\sum_{j=1}^{k+1}\|\Psi^{(j)}(t,.)\|_{L^2} + \|1-|\Psi(t,.)|^2\|_{L^2}$ 
is bounded in $[-T_{k+1},T_{k+1}]$ and, by iterating the previous argument,
it can not blow up on $]-T_\star, T^\star[$.

\subsubsection{Global well-posedness and conservation of energy in  $E^0$}

The idea is to use the energy conservation to move from local to global. 
To establish the latter, in view of \eqref{cons_energie},
we proceed  by regularizing the initial datum so that it belongs to $E^1$.
More specifically, we approximate $\Psi_0$ in the sense of the distance $d^0$ 
by a sequence $\Psi^\epsilon_0$ of elements from $E^1$.
By Proposition \ref{thm:cauchyGP}, we have
$$
\sup_{|t|\leq T}d^0(\Psi^\epsilon(t),\Psi(t))\to 0,
$$
when $\epsilon \to 0$, where $\Psi^\epsilon$ is the solution 
of \eqref{GP} with initial datum $\Psi_0^\epsilon$. Then for all $t$,
we have
$$
\Sigma(\Psi^\epsilon(t))\to \Sigma(\Psi(t)),
$$
when $\epsilon \to 0$. Hence the energy conservation of
 $\Psi^\epsilon$ implies that of $\Psi$.

\subsection{Proof of Proposition \ref{propo:cont}}

We start by a weak convergence result preoved in \cite{Bet_Gr_Smt}
for which the Gross-Pitaevskii flow is continuous.

\begin{proposition}\label{cont_4}
Let $(\Psi_{n,0})_{n\in \mathbb{N}} \in (E^0)^{\mathbb{N}}$ and 
$\Psi_0 \in E^0$ such that
\begin{equation}\label{conv_faible1}
\begin{gathered}
        \Psi'_{n,0} \rightharpoonup \Psi'_0 \quad \text{in }  L^2(\mathbb{R}),\\
       1- |\Psi_{n,0}|^2  \rightharpoonup 1-|\Psi_0|^2 
\quad \text{in }  L^2(\mathbb{R}),
       \end{gathered}
\end{equation}
and, for all compact set $K \subset \mathbb{R}$,
\begin{equation}\label{conv_faible2}
 \Psi_{n,0} \to \Psi_0 \quad \text{in } L^\infty(K).
\end{equation}
We denote by $\Psi_n$ and $\Psi$ the global solutions for \eqref{GP} 
corresponding to initial datum $\Psi_{n,0}$ and $\Psi_0$, respectively. Then
for all $t\in \mathbb{R}$ and for all compact set $K\subset \mathbb{R}$, we have
\begin{equation}\label{conv_faible3}
 \begin{gathered}
        \partial_x\Psi_n(t,.) \rightharpoonup \partial_x\Psi(t,.) 
\quad \text{in } L^2(\mathbb{R}),\\
       1- |\Psi_n(t,.)|^2  \rightharpoonup 1-|\Psi(t,.)|^2 
\quad \text{in } L^2(\mathbb{R}),\\
       \Psi_n(t,.)\to  \Psi(t,.) \quad \text{in } L^\infty(K).
       \end{gathered}
\end{equation}
\end{proposition}

\begin{proof}
We denote $\eta_n = 1-|\Psi_n|^2$. The weak convergence in \eqref{conv_faible1} 
implies the existence of a constant
 $M>0$ such that 
$$
\Sigma(\Psi_{n,0}) \leq M^2\quad \forall n\in \mathbb{N}.
$$
Since the energy $\Sigma$ is conserved along the flow, we also have
\begin{equation}\label{major_2}
 \|\partial_x\Psi_n(t,.)\|_{L^2(\mathbb{R})} \leq \sqrt{2}M \quad \text{and} \quad 
\|\eta_n(t,.)\|_{L^2(\mathbb{R})}\leq 2M,
\end{equation}
for every $n\in \mathbb{N}$ and $t\in \mathbb{R}$. 
Then Lemma \ref{zhidkov} implies the existence of a constant $C> 0$ such that
$\|\Psi_n(t,.)\|_{L^\infty(\mathbb{R})} \leq C(1+\sqrt{\Sigma(\Psi_n(t,.))})$ 
for all $t\in \mathbb{R}$.  Since
$\|\partial_x\eta_n(t,.)\|_{L^2(\mathbb{R})} 
\leq 2\|\Psi_n(t,.)\|_{L^\infty(\mathbb{R})}
\|\partial_x\Psi_n(t,.)\|_{L^2(\mathbb{R})}$, there exists
two constants $K_M, L_M >0$ depending on $M$, such that
\begin{equation}\label{major_3}
 \|\partial_x\eta_n(t,.)\|_{L^2(\mathbb{R})} \leq K_M \quad \text{and} \quad 
\|\Psi_n(t,.)\|_{L^\infty(\mathbb{R})} \leq L_M,
\end{equation}
for all $t\in \mathbb{R}$. In particular, for some $T>0$, we deduce that
\begin{equation}\label{major_4}
 \int_0^T\int_{\mathbb{R}}|\partial_x\Psi_n(t,x)|^2dxdt \leq M^2T \quad \text{and} 
\quad \int_0^T\int_{\mathbb{R}}\eta_n^2(t,x)^2dxdt \leq M^2T.
\end{equation}
Inequalities \eqref{major_3} and \eqref{major_4} will allow us to construct weak 
limits for $\partial_x\Psi_n$ and $\eta_n$. In view of \eqref{major_4},
there exist two functions $\Phi_1\in L^2([0,T]\times\mathbb{R})$ and  
$N\in L^2([0,T]\times\mathbb{R})$ such that up to a further subsequence,
\begin{equation}\label{lim_faible}
 \partial_x\Psi_n\rightharpoonup \Phi_1 \quad \text{in } 
 L^2([0,T]\times\mathbb{R})\quad \text{and} \quad
\eta_n\rightharpoonup N \quad \text{in } L^2([0,T]\times\mathbb{R}),
\end{equation}
when $n\to +\infty$. Similarly, \eqref{major_3} proves the existence 
of $\Phi \in L^\infty([0,T]\times\mathbb{R})$ such that,
up to a further subsequence,
\begin{equation}\label{lim_faible1}
 \Psi_n\stackrel{\ast}{\rightharpoonup} \Phi \quad \text{in } 
 L^\infty([0,T]\times\mathbb{R}),
\end{equation}
when $n\to +\infty$. Combined with \eqref{lim_faible}, 
this shows that  $\Phi_1 = \partial_x\Phi$ in the sense of distributions.
Our goal now is to check that the function $\Phi$ is a solution to \eqref{GP}. 
This requires to improve
the convergence in \eqref{lim_faible} and \eqref{lim_faible1}. 
With this goal in mind, we define the function $\chi_p = \chi(./p)$ when
$p\in \mathbb{N}$ and $\chi \in \mathcal{D}(\mathbb{R})$ with $\chi\equiv 1$ on
$[-1,1]$ and $\chi \equiv 0$ on $]-\infty,2]\cup[2,+\infty[$. 
Inequalities \eqref{major_3} and \eqref{major_4} prove that the sequence
$(\chi_p \Psi_n)_{n\in \mathbb{N}}$ is bounded in 
$\mathcal{C}([0,T], H^1(\mathbb{R}))$. By the Rellich-Kondrachov theorem, 
the sets
$\{\chi_p\Psi_n(t,.), n\in \mathbb{N}\}$ are relatively compact 
in $H^{-1}(\mathbb{R})$ for any fixed $t\in [0,T]$. 
On the other hand, the function
$\Psi_n$ is solution to \eqref{GP}, so that 
$\partial_t \Psi_n\in \mathcal{C}([0,T], H^{-1}(\mathbb{R}))$, and we also have
\begin{align*}
\|\partial_t\Psi_n(t,.)\|_{H^{-1}(\mathbb{R})} 
&\leq \|\partial_x\Psi_n(t,.)\|_{L^2(\mathbb{R})}
 +\|\Psi_n(t,.)\|_{L^\infty(\mathbb{R})}\|\eta_n(t,.)\|_{L^2(\mathbb{R})} \\
&\leq M(\sqrt{2}+2L_M).
\end{align*}
As a consequence, the functions $\chi_p\Psi_n$ are equicontinuous 
in $\mathcal{C}([0,T], H^{-1}(\mathbb{R}))$. Applying the
Arzela-Ascoli theorem and using the Cantor diagonal argument, 
we can find a further sub-sequence (independent of $p$) such that for 
any $p\in \mathbb{N}^\ast$
\begin{equation}\label{conv_forte2}
 \chi_p\Psi_n \to \chi_p\Phi \quad \text{in }
 \mathcal{C}([0,T],H^{-1}(\mathbb{R})),
\end{equation}
when $n\to +\infty$.
Recalling that the functions $\chi_p\Psi_n$ are uniformly bounded in 
$\mathcal{C}([0,T],H^1(\mathbb{R}))$, we deduce that the convergence 
in \eqref{conv_faible2}
also holds in the spaces $\mathcal{C}([0,T],H^s(\mathbb{R}))$ for any $s<1$. 
In particular, by the Sobolev embedding theorem, we obtain
 \begin{equation}\label{conv_forte2bis}
 \chi_p\Psi_n \to \chi_p\Phi \quad \text{in } \mathcal{C}([0,T],
\mathcal{C}(\mathbb{R})).
\end{equation}
Such convergences are sufficient to establish that $\Phi$ is solution to \eqref{GP}.
Let $h\in \mathcal{D}(\mathbb{R})$. Since the functions $\chi_p\Psi_n$ are 
uniformly bounded in $\mathcal{C}([0,T],\mathcal{C}(\mathbb{R}))$,
for $p\in \mathbb{N}$ such that $supp(h) \subset [-p,p]$, we get
\begin{equation}\label{conv_forte3}
 h\eta_n(t,.) = h(1-\chi_p^2|\Psi_n(t,.))|^2)\to h(1-\chi_p^2|\Phi(t,.))|^2)
 = h(1-|\Phi(t,.))|^2) \quad \text{in } \mathcal{C}(\mathbb{R}),
\end{equation}
when $n\to +\infty$. Since this convergence is uniform with respect to 
$t\in [0,T]$, \eqref{lim_faible} implies that $N = 1- |\Phi|^2$.
Similarly,
\begin{equation}\label{conv_forte3bis}
 h\Psi_n(t,.)= h\chi_p\Psi_n(t,.) \to h\chi_p\Phi(t,.) 
= h\Phi(t,.) \quad \text{in } \mathcal{C}(\mathbb{R}).
\end{equation}
In view of $\eqref{lim_faible}$, we deduce that
$$
h\eta_n\Psi_n \to h(1-|\Phi|^2)\Phi \quad \text{in } L^2([0,T]\times\mathbb{R}).
$$
Going back to \eqref{lim_faible} and \eqref{lim_faible1}, we recall that
$$
i\partial_t\Psi_n \to i\partial_t\Phi \quad \text{in }
 \mathcal{D}'([0,T]\times\mathbb{R})\quad \text{and}
\quad \partial_x^2\Psi_n \to \partial_x^2\Phi \quad \text{in }
 \mathcal{D}'([0,T]\times\mathbb{R}) ,
$$
when $n\to +\infty$, so that it remains to take the limit, when 
$n\to +\infty$ in the expression
$$
\langle i\partial_t\Psi_n + \partial_x^2\Psi_n
+ \eta_n\Psi_n, h\rangle_{\mathcal{D}'\times\mathcal{D}},
$$
where $h\in \mathcal{D}([0,T]\times\mathbb{R})$, to deduce that $\Phi$ 
is a solution to \eqref{GP} in the sense of distributions.
Moreover, we infer from the convergence in any compact set 
$K\subset \mathbb{R}$ and from relation \eqref{conv_forte3bis} that 
$\Phi(0,.) = \Psi_0$.
We now prove that $\Phi \in \mathcal{C}([0,T],Z^s(\mathbb{R}))$ for any 
$\frac{1}{2}< s<1$, with
$$
Z^s = \{u \in L^\infty(\mathbb{R}), u' \in H^{s-1}(\mathbb{R})\}.
$$
Let $t\in [0,T]$. Up to a subsequence (depending on $t$), we deduce 
from \eqref{major_2}, \eqref{conv_faible2} and \eqref{conv_forte3bis} that
\begin{equation}\label{lim_faible2}
 \partial_x\Psi_n(t,.)\rightharpoonup \partial_x\Phi(t,.) \quad 
\text{in } L^2(\mathbb{R})\quad \text{and} \quad
\eta_n(t,.) \rightharpoonup 1-|\Phi(t,.)|^2\quad \text{in } L^2(\mathbb{R}),
\end{equation}
 when $n\to +\infty$. On the other hand, we know that
\begin{equation}\label{major_5}
 \int_{\mathbb{R}}|\partial_x\Phi(t,.)|^2 \leq M^2\quad \text{and} \quad 
\int_{\mathbb{R}}(1-|\Phi(t,.)|^2)^2 \leq M^2.
\end{equation}
Arguing as in the proof of \eqref{major_4}, we find that $\Phi(t,x)$ 
is uniformly bounded with respect to $x\in \mathbb{R}$ and $t\in [0,T]$. 
In particular,
$\partial_x \Phi\in L^\infty([0,T], L^2(\mathbb{R}))$ and
 $1-|\Phi|^2\in L^\infty([0,T],H^1(\mathbb{R}))$. Since
$$
i\partial_t(\partial_x \Phi)= -\partial_x^3\Phi-\partial_x(\eta \Phi),
$$
we have $\partial_x\Phi \in W^{1,\infty}([0,T],H^{-2}(\mathbb{R}))
\subset \mathcal{C}([0,T],H^{-2}(\mathbb{R}))$. 
Hence, $\partial_x\Phi$ is continuous with values
into $H^s(\mathbb{R})$ for any $-2<s<0$. Similarly, $\eta_n$ is a solution 
to the equation
\begin{equation}\label{eq_1}
 \partial_t\eta_n=2\partial_x(\langle i\partial_x\Psi_n, 
\Psi_n\rangle_{\mathbb{C}}).
\end{equation}
In view of the convergence established in \eqref{conv_forte3bis} and 
\eqref{lim_faible}, we have
$$
h\langle i\partial_x\Psi_n, \Psi_n\rangle_{\mathbb{C}} 
\to h\langle i\partial_x\Phi, \Phi\rangle_{\mathbb{C}} \quad \text{in } 
 L^2([0,T]\times\mathbb{R}),
$$
for any $h\in \mathcal{D}(\mathbb{R})$. Using \eqref{conv_forte3} and taking 
the limit when $n\to +\infty$ in \eqref{eq_1}, we find that
$$
\partial_t(1-|\Phi|^2) = 2\partial_x(\langle i\partial_x\Phi, 
\Phi\rangle_{\mathbb{C}}),
$$
in the sense of distributions. 

We deduce as above that 
$1-|\Phi|^2\in W^{1,\infty}([0,T],H^{-1}(\mathbb{R}))\subset 
\mathcal{C}([0,T],H^{-1}(\mathbb{R}))$. Moreover,
$1-|\Phi|^2$ is continuous from $[0,T]$ into $H^s(\mathbb{R})$ for all 
$-1\leq s<1$. It remains to apply the Sobolev embedding theorem to
guarantee that $\Phi \in \mathcal{C}([0,T],L^\infty(\mathbb{R}))$, so that 
$\Phi \in \mathcal{C}([0,T],Z^s(\mathbb{R}))$ for $\frac{1}{2}<s<1$. 
The two functions
$\Phi$ and $\Psi$ are two solutions to \eqref{GP} in 
$\mathcal{C}([0,T],Z^s(\mathbb{R}))$ with the same initial data $\Psi_0$.
To conclude, we need the following result of Cauchy problem for \eqref{GP} 
in the space $Z^s(\mathbb{R})\supsetneqq E^0$, equipped with the norm
$$
\|\psi\|_{Z^s} = \|\psi\|_{L^\infty(\mathbb{R})}+ \|\psi\|_{H^{s-1}(\mathbb{R})},
$$
with $1/2<s<1$.

\begin{proposition}\label{Cauchy_Gp_Zs}
 Let $1/2<s<1$ et $\psi_0 \in Z^s(\mathbb{R})$. 
There exists a unique maximal solution 
$\psi\in \mathcal{C}(]T_{\rm min},T_{\rm max}[,Z^s(\mathbb{R}))$ to
\eqref{GP} with $\psi(0,.) = \psi_0$.
\end{proposition}

For a proof of the above proposition, we refer the reader to \cite{Bet_Gr_Smt}.
In view of Proposition \ref{Cauchy_Gp_Zs}, the two solutions
$\Phi$ and $\Psi$ are equal. We have just proved that for any $t\in [0,T]$ 
and up to a subsequence (independent of $t$),
\begin{equation}\label{lim_faible3}
 \partial_x\Psi_n(t,.) \rightharpoonup \partial_x\Psi(t,.) \quad \text{and} \quad 
\eta_n(t,.) \rightharpoonup 1-|\Psi(t,.)|^2 \quad \text{in } L^2(\mathbb{R}),
\end{equation}
and that for any compact set $K\subset \mathbb{R}$,
$$
\Psi_n(t,.) \to \Psi(t,.) \quad \text{in } L^\infty(K),
$$
when $n\to +\infty$. To complete the proof, we  argue by contradiction. 
Assume that there exists $T>0, h\in L^2(\mathbb{R})$, and $\delta >0$, such that
for a further subsequence $(\Psi_{\phi(n)})_{n\in \mathbb{N}}$,
$$
|\int_{\mathbb{R}}(\partial_x\Psi_{\phi(n)}(T,x)-\partial_x\Psi(T,x))\bar{h}(x)dx |
>\delta.
$$
Up to the choice of a further subsequence (possibly depending
on $T$),this is in contradiction with \eqref{lim_faible3}. 
A similar argument proves the weak convergence of 
$\{\eta_n\}_{n\in \mathbb{N}}$ and the uniform convergence
of $(\Psi_n)_{n\in \mathbb{N}}$ on any compact set $K\subset \mathbb{R}$. 
Since the proof extends with no change to the case
where $T$ is negative, this concludes the proof.
\end{proof}

Proposition \ref{cont_4} together with the conservation of the energy 
$\Sigma$ along the flow $\Psi(t,.)$ yield the following result of 
strong convergence
\begin{corollary}\label{cont_forte}
Let the sequence $(\Psi_{n,0})_{n\in \mathbb{N}} \in (E^0)^{\mathbb{N}}$ and 
$\Psi_0 \in E^0$ satisfy
\begin{equation}\label{conv_forte1}
 \lim_{n\to \infty}d^0_{\rm loc}(\Psi_{n,0},\Psi_0) =0.
\end{equation}
Then the solutions $\Psi_n$ and $\Psi$ of \eqref{GP} with initial data  
$\Psi_{n,0}$ and $\Psi_0$, respectively, satisfy
$$
\lim_{n\to \infty}d^0_{\rm loc}(\Psi_n(t,.),\Psi(t,.)) =0\quad 
\forall t\in \mathbb{R}.
$$
\end{corollary}

\begin{proof}
 The condition \eqref{conv_forte1} implies \eqref{conv_faible1} and 
\eqref{conv_faible2}. Indeed, if $K\subset \mathbb{R}$ is a compact set, 
for any $x\in K$ we have 
$$
\Psi_{n,0}(x)-\Psi_0(x) = \Psi_{n,0}(0)-\Psi_0(0)
+ \int_0^x(\Psi'_{n,0}(z)-\Psi'_0(z))dz,
$$ 
which implies in turn that
$$
\|\Psi_{n,0}-\Psi_0\|_{L^\infty(K)} 
\leq \|\Psi_{n,0}-\Psi_0\|_{L^\infty(-1,1)}
+ \sqrt{|K|+dist(0,K)}\|\Psi'_{n,0}-\Psi'_0\|_{L^2(\mathbb{R})}.
$$
In view of Proposition \ref{cont_4}, the weak convergence in $L^2(\mathbb{R})$ 
to $\partial_x\Psi(t,.)$ and  of $(\partial_x\Psi_n(t,.))_{n\in \mathbb{N}}$
to $1-|\Psi(t,.)|^2$ hold. Moreover,  $(\Psi_n(t,.))_{n\in \mathbb{N}}$ 
tends to $\Psi(t,.)$ in
$L^\infty(-1,1)$ for any $t\in \mathbb{R}$. Thus for any $t\in \mathbb{R}$, we have
\begin{gather*}
  \liminf_{n\to \infty} \|\partial_x\Psi_n(t,.)\|_{L^2} 
 \geq \|\partial_x\Psi(t,.)\|_{L^2} ,\\
  \liminf_{n\to \infty} \| 1- |\Psi_n(t,.)|^2\|_{L^2}  
\geq \|1-|\Psi(t,.)|^2\|_{L^2} .
\end{gather*}
Furthermore, since
$$
\lim_{n\to \infty}\Sigma(\Psi_n(t,.)) 
= \lim_{n\to \infty}\Sigma(\Psi_{n,0})=\Sigma(\Psi_0)=\Sigma(\Psi(t,.)),
$$
we have
\begin{align*}
&\frac{1}{2}\limsup_{n\to \infty} \|\partial_x\Psi_n\|^2_{L^2} 
+ \frac{1}{4}\liminf_{n\to \infty} \| 1- |\Psi_n|^2\|^2_{L^2} \\
&\leq \limsup_{n\to \infty}\Sigma(\Psi_n)\\
&=  \lim_{n\to \infty}\Sigma(\Psi_n) \\
&=  \frac{1}{2}\|\partial_x\Psi\|^2_{L^2} + \frac{1}{4}\| 1- |\Psi|^2\|^2_{L^2} \\
&\leq  \frac{1}{2}\liminf_{n\to \infty} \|\partial_x\Psi_n\|^2_{L^2} 
+ \frac{1}{4}\liminf_{n\to \infty} \| 1- |\Psi_n|^2\|^2_{L^2}.
\end{align*}
Thus, for  $t\in \mathbb{R}$, the two sequences 
$(\|\partial_x\Psi_n(t,.)\|_{L^2})_{n\in \mathbb{N}}$ and
$(\|1-|\Psi_n(t,.)|^2\|_{L^2})_{n\in \mathbb{N}}$  converge to 
$\|\partial_x\Psi(t,.)\|_{L^2}$ and $\|1-|\Psi(t,.)|^2\|_{L^2}$,
respectively. The weak convergence together with the convergence of the 
$L^2(\mathbb{R})$-norm  yield the strong convergence. This completes the proof.
\end{proof}


\section{From the classical formulation to  the hydrodynamical one}

The main purpose of this section is to present the proofs of 
Proposition \ref{esp_gp_hgp} and Theorem \ref{Cauchy_HGP}.

\subsection{Proof of Proposition \ref{esp_gp_hgp}}

Let $k\in \mathbb{N}$. We define the application $\varPhi_1$ by
$$
\begin{array}{llcl}
\varPhi_1 : & A^k & \longrightarrow &\mathcal{NV}^k(\mathbb{R}) \times \mathbb{R}/(2\pi\mathbb{Z})\\
          & u & \longmapsto & ((\eta(x),v(x)),\theta) := ((1-|u(x)|^2,\langle \frac{i}{\bar{u}(x)},u'(x)\rangle_\mathbb{C}),\arg(u(0))).
\end{array}
$$
Let $((\eta, v),\theta)\in \mathcal{NV}^k(\mathbb{R})\times \mathbb{R}/(2\pi\mathbb{Z})$. 
Clearly, we have
$$
\varPhi_1(\varPhi(((\eta, v),\theta))) = ((\eta, v),\theta).
$$
Let $\Psi \in A^k$ and let $\omega = |\Psi|^{-1}\Psi$. 
Then $\omega \in E^0$ and we have
\begin{equation}\label{bij_dem}
 \omega ' - i\langle \frac{i}{\bar{\Psi}},\Psi'\rangle_{\mathbb{C}} \omega =0\quad
 \text{almost everywhere.}
\end{equation}
This yields
$$
\omega =\omega(0)\exp\Big(i\int_0^x \langle \frac{i}{\bar{\Psi}},
\Psi'\rangle_{\mathbb{C}}\Big)= |\Psi|^{-1} \varPhi (\varPhi_1(\Psi)).
$$
It follows that
$\varPhi (\varPhi_1(\Psi)) = \Psi$,
so that $\varPhi$ is a bijection whose inverse is $\varPhi^{-1} = \varPhi_1$. 
To establish the continuity properties, We begin by proving the following lemmas.

\begin{lemma}\label{convergence}
 Let $(g_n)_{n\in \mathbb{N}}$ and $(f_n)_{n\in \mathbb{N}}$ be two sequences 
with elements in $L^\infty(\mathbb{R})$ and $L^2(\mathbb{R})$ respectively,
the sequence $(g_n)_{n\in \mathbb{N}}$ being in addition bounded in 
$L^\infty(\mathbb{R})$. Assume that there exists
$(g,f) \in L^\infty(\mathbb{R})\times L^2(\mathbb{R})$ such that, for any 
compact set $K \subset \mathbb{R}$,
the sequence $(g_n)_{n\in \mathbb{N}}$ converges to $g$ in $L^\infty(K)$ and 
the sequence $(f_n)_{n\in \mathbb{N}}$
converges to $f$ in $L^2(\mathbb{R})$. Then the sequence 
$(f_ng_n)_{n\in \mathbb{N}}$ converges to $fg$ in $L^2(\mathbb{R})$.
\end{lemma}

\begin{proof}
We can easily see that for any compact set $K \subset \mathbb{R}$, the sequence 
$(f_ng_n)_{n\in \mathbb{N}}$ converges to $fg$ in $L^2(K)$.
There exists $M >0$ such that for every $n\in \mathbb{N}$ we have 
$\|g_n\|_{L^\infty(\mathbb{R})} \leq M$. Let $\epsilon >0$. 
There exists $x_0 >0$ and
$(n_0, n_1) \in (\mathbb{N})^2$ (depending on $x_0$) such that
\begin{gather*}
 \int_{\mathbb{R}\setminus [-x_0,x_0]}|f|^2 
 \leq \frac{\epsilon^2}{6(M+\|g\|_{L^\infty(\mathbb{R})})^2},\\
 \int_{\mathbb{R}\setminus [-x_0,x_0]}|f_n-f|^2
 \leq \frac{\epsilon^2}{6M^2}\quad \forall n\geq n_0, \\
\int_{-x_0}^{x_0}|f_ng_n-fg|^2 \leq \frac{\epsilon^2}{3} \quad \forall n\geq n_1.
\end{gather*}
 Then for every $n\geq \max(n_0,n_1)$, we have
\begin{align*}
 \int_{\mathbb{R}}|f_ng_n-fg|^2 
&=  \int_{-x_0}^{x_0}|f_ng_n-fg|^2 + \int_{\mathbb{R}\setminus [-x_0,x_0]}|(f_n-f)g_n+ (g_n-g)f|^2 \\
&\leq \int_{-x_0}^{x_0}|f_ng_n-fg|^2 + 2M^2\int_{\mathbb{R}\setminus [-x_0,x_0]}|f_n-f|^2\\
 &\quad + 2(M+\|g\|_{L^\infty(\mathbb{R})} )^2\int_{\mathbb{R}\setminus [-x_0,x_0]}|f|^2 \\
&\leq \epsilon^2,
\end{align*}
which completes the proof.
\end{proof}

\begin{lemma}\label{cont_2}
Let $k\in \mathbb{N}$ and $\Psi \in A^k$.
We set $\eta = 1-|\Psi|^2$ and 
$v = \langle \frac{i}{\bar{\Psi}}, \Psi'\rangle_{\mathbb{C}}$. 
Then the application $\Psi\mapsto ((\eta,v),\arg(\Psi(0)))$ is continuous from 
$(A^k,d^k_{\rm loc})$ into 
$(\mathcal{NV}^k(\mathbb{R})\times \mathbb{R}/(2\pi\mathbb{Z}), \|\cdot\|_{X^k}
+|\cdot|_{\mathbb{R}/(2\pi\mathbb{Z})})$ and
Lipschitz-continuous from $(A^k,d^k)$ into 
$(\mathcal{NV}^k(\mathbb{R})\times \mathbb{R}/(2\pi\mathbb{Z}), \|.\|_{X^k}+|.|_{\mathbb{R}/(2\pi\mathbb{Z})})$.
 \end{lemma}

\begin{proof}
Let $\Psi \in A^k$ and let $(\Psi_n)_{n\in \mathbb{N}}$ be a sequence in 
$A^k$ such that $d^k_{\rm loc}(\Psi_n, \Psi) \to 0$ when $n\to 0$. 
We first prove that the sequence $((\eta_n, v_n))_{n\in \mathbb{N}}$ 
converges to $(\eta,v)$ in $X^k(\mathbb{R})$. Let $j\leq k$. We have
$$ 
v_n^{(j)} =(\langle \frac{i}{\bar{\Psi}_n}, \Psi_n'\rangle_{\mathbb{C}})^{(j)}
 =\sum_{l=0}^jC_l^j\big\langle i\big(\frac{1}{\bar{\Psi}_n}\big)^{(l)},
 \Psi_n^{(j-l+1)}\big\rangle_{\mathbb{C}}.
$$
Using the Fa  di Bruno formula for the derivative of two composite functions, 
we obtain
$$
\big(\frac{1}{\Psi_n}\big)^{(l)} 
= \sum_{\pi \in \Gamma_l}(-1)^{|\pi|}|\pi|!\Psi_n^{-(|\pi|+1)}
\prod_{B\in \pi}\Psi_n^{(|B|)},\quad l\geq 1,
$$
where $\Gamma_l$ is the set of partitions of $\{1,\dots ,l\}$. Then
\begin{equation} \label{deriv_3}
\begin{aligned}
&(\langle \frac{i}{\bar{\Psi}_n}, \Psi_n'\rangle_{\mathbb{C}})^{(j)} \\
&= \sum_{l=1}^j\sum_{\pi \in \Gamma_l}C_l^j(-1)^{|\pi|}|\pi|!
\big\langle i\bar{\Psi}_n^{-(|\pi|+1)}\prod_{B\in \pi}\bar{\Psi}_n^{(|B|)},
 \Psi_n^{(j-l+1)}\big\rangle_{\mathbb{C}}
+  \big\langle \frac{i}{\bar{\Psi}_n}, \Psi_n^{(j+1)}\big\rangle_{\mathbb{C}}.
\end{aligned}
\end{equation}
Since $d^k_{\rm loc}(\Psi_n, \Psi) \to 0$  and $\Psi\in A^k$, for any compact
set $K \subset \mathbb{R}$, there exists an integer $N_K\in\mathbb{N}$
such that the sequence $\big(\frac{1}{\Psi_n}\big)_{n\geq N_K}$
converges to $\frac{1}{\Psi}$ in $L^\infty(K)$. Moreover, there exists an
integer $n_0 \geq N_K$ and $M>0$ such that, for any $n\geq n_0$, we have
$\|\frac{1}{\Psi_n}\|_{L^\infty(\mathbb{R})} \leq M$.
For every $1\leq j\leq k$, the sequence
$\big(\prod_{B\in \pi}\bar{\Psi}_n^{(|B|)}\big)_{n\in \mathbb{N}}$ converges to
$\prod_{B\in \pi}\bar{\Psi}^{(|B|)}$  in $L^2(\mathbb{R})$,  and
the sequence $\big(\Psi_n^{(j-l+1)}\big)_{n\in \mathbb{N}}$ converges to
$\Psi^{(j-l+1)}$ in $L^\infty(\mathbb{R})$, since
$\big(\Psi'_n\big)_{n\in \mathbb{N}}$ converges to
$\Psi'$ in $H^k(\mathbb{R})$ and $\sum_{B\in \pi}|B|=l$.
In view of Lemma \ref{convergence}, the two sequences
$\big(\langle \frac{i}{\bar{\Psi}_n}, \Psi_n^{(j+1)}\rangle_{\mathbb{C}}
\big)_{n\in \mathbb{N}}$ and
$\big(\bar{\Psi}_n^{-(|\pi|+1)}\prod_{B\in \pi}\bar{\Psi}_n^{(|B|)}
\big)_{n\in \mathbb{N}}$ converge in $L^2(\mathbb{R})$ to
$\langle \frac{i}{\bar{\Psi}}, \Psi^{(j+1)}\rangle_{\mathbb{C}}$ and
$\bar{\Psi}^{-(|\pi|+1)}\prod_{B\in \pi}\bar{\Psi}^{(|B|)}$, respectively.
This proves the convergence of $(v_n^{(j)})_{n\in \mathbb{N}}$ to $v^{(j)}$
in $L^2(\mathbb{R})$.
On the other hand, for $1\leq j\leq k+1$, we have
\begin{equation} \label{deriv03}
\begin{aligned}
 \eta_n^{(j)} &= -2\sum_{l=0}^jC_l^j\langle\Psi_n^{(l)},\Psi_n^{(j-l)}
\rangle_{\mathbb{C}} \\
&= -2\sum_{l=1}^{j-1}C_l^j\langle\Psi_n^{(l)},\Psi_n^{(j-l)}
\rangle_{\mathbb{C}} -2\langle\Psi_n,\Psi_n^{(j)}\rangle_{\mathbb{C}}.
\end{aligned}
\end{equation}
The sequence $\big(\langle\Psi_n^{(l)},\Psi_n^{(j-l)}
\rangle_{\mathbb{C}}\big)_{n\in \mathbb{N}}$ converges to
$\langle\Psi^{(l)},\Psi^{(j-l)}\rangle_{\mathbb{C}}$ in $L^2(\mathbb{R})$.
In view of Lemma \ref{zhidkov}, there exists $C>0$ such that
$\|\Psi_n\|_{L^\infty(\mathbb{R})}\leq C(1+\sqrt{\Sigma(\Psi_n)})$.
Then the sequence $(\Psi_n)_{n\in \mathbb{N}}$
is bounded from above in $L^\infty(\mathbb{R})$ and Lemma \ref{convergence}
implies the convergence of the sequence
$\big(\langle\Psi_n,\Psi_n^{(j)}\rangle_{\mathbb{C}}\big)_{n\in \mathbb{N}}$
to $\langle\Psi,\Psi^{(j)}\rangle_{\mathbb{C}}$ in $L^2(\mathbb{R})$,
which proves the convergence of $\big(\eta_n^{(j)}\big)_{n\in \mathbb{N}}$ to
$\eta^{(j)}$ in $L^2(\mathbb{R})$.

Let $\Psi_0 , \Psi \in A^k$. The local Lipschitz continuity is obtained by 
applying formulas \eqref{deriv_3} and \eqref{deriv03} on $\Psi_0$ t $\Psi$, 
by taking the difference,
and by estimating the  $L^2(\mathbb{R})$-norms  of 
$\Psi^m\Psi^{(K)}-\Psi_0^m\Psi_0^{(K)}$ with $(m,K) \in \mathbb{Z}^*\times\mathbb{N}$. 
In the case where $m$ is negative, we just
note that
\begin{align*}
&\|\Psi^m\Psi^{(K)}-\Psi_0^m\Psi_0^{(K)}\|_{L^2(\mathbb{R})} \\
&\leq  \frac{\|\Psi_0^{(K)}\|_{L^2(\mathbb{R})}}{\inf_x|\Psi^{-m}(x)\Psi_0^{-m}(x)|}
 \|\Psi^{-m}-\Psi_0^{-m}\|_{L^\infty(\mathbb{R})}
 + \frac{1}{\inf_x|\Psi^{-m}(x)|} \|\Psi^{(K)}\!-\Psi_0^{(K)}\|_{L^2(\mathbb{R})}\\
&\leq  \|\Psi\Psi_0\|^m_{L^\infty(\mathbb{R})} 
 \|\Psi_0^{(K)}\|_{L^2(\mathbb{R})}\|\Psi^{-m}-\Psi_0^{-m}
 \|_{L^\infty(\mathbb{R})}
 + \|\Psi\|^m_{L^\infty(\mathbb{R})} \|\Psi^{(K)}
 -\Psi_0^{(K)}\|_{L^2(\mathbb{R})}.
\end{align*}
Besides, the function $\arg: \mathbb{C}^*\to \mathbb{R}/(2\pi Z)$ is of class 
$\mathcal{C}^\infty$ (hence locally continuous Lipschitz).
Then, by fixing  $\Psi_0 \in A^k$, we find that there exist two strictly 
nonnegative constants $C$ and
$\delta$ depending on $\Psi_0$ such that, for all $\Psi\in A^k$ with 
$d^k(\Psi_0,\Psi) \leq \delta$, we have
$$
\|(\eta_0-\eta, v_0-v)\|_{X^k}+ |\arg(\Psi_0(0))
-\arg(\Psi(0))|_{\mathbb{R}/(2\pi Z)} \leq Cd^k(\Psi_0,\Psi),
$$
with $\eta = 1-|\Psi|^2$, $\eta_0 = 1-|\Psi_0|^2$, 
$v = \langle \frac{i}{\bar{\Psi}}, \Psi'\rangle_{\mathbb{C}}$ and 
$v_0 = \langle \frac{i}{\bar{\Psi}_0}, \Psi_0'\rangle_{\mathbb{C}}$.
\end{proof}

The following lemma proves the converse result to that of previous lemma.

\begin{lemma}\label{cont_3} 
Let $k\in \mathbb{N}$ and 
$((\eta, v),\theta)\in \mathcal{NV}^k(\mathbb{R})\times \mathbb{R}/(2\pi\mathbb{Z})$. 
We set $\Psi = \sqrt{1-\eta}u$ with
$u = \exp\left(i(\theta+\int_0^xv(z)dz\right))$. 
Then $\Psi \in A^k$ and the application $((\eta, v),\theta)\mapsto \Psi$ is 
continuous from
$(\mathcal{NV}^k(\mathbb{R})\times \mathbb{R}/(2\pi\mathbb{Z}))$ to  $(A^k,d^k_{\rm loc})$.
\end{lemma}

\begin{proof}
Let $((\eta, v),\theta) \in \mathcal{NV}^k(\mathbb{R})\times \mathbb{R}/(2\pi\mathbb{Z})$ 
and let $((\eta_n,v_n),\theta_n)_{n\in \mathbb{N}}$  be a sequence of elements in
$\mathcal{NV}^k(\mathbb{R})\times \mathbb{R}/(2\pi\mathbb{Z})$ such that
\begin{equation}\label{suit_cv}
\|(\eta_n-\eta, v_n-v)\|_{X^k} +|\theta_n-\theta|_{ \mathbb{R}/(2\pi\mathbb{Z})}\to 0\quad 
\text{as }  n\to 0.
\end{equation}
We will show that $(\Psi_n= \sqrt{1-\eta_n}u_n )_{n\in \mathbb{N}}$ converges
to $\Psi = \sqrt{1-\eta}u$ in $(E^k,d^k_{\rm loc})$. 
First, we clearly have $\|\Psi_n - \Psi\|_{L^\infty(-1,1)} \to 0$ and
$\||\Psi_n|^2 - |\Psi|^2\|_{L^2} \to 0$ when $n\to 0$. Let $1 \leq j\leq k+1$. 
We have
\begin{gather*}
 \Psi_n^{(j)} =(\sqrt{1-\eta_n}u_n)^{(j)} 
=\sum_{l=0}^jC_l^j(\sqrt{1-\eta_n})^{(l)}u_n^{(j-l)},\\
u_n^{(l)} = \sum_{\gamma \in \Gamma_{j-l}}i^{|\gamma|}u_n
\prod_{D\in \gamma}v_n^{(|D|-1)},\quad j-l\geq 1,
\end{gather*}
and, by using the Fa di Bruno formula, we obtain
$$
(\sqrt{1-\eta_n})^{(l)} = \sum_{\pi \in \Gamma_l}C(|\pi|)
(1-\eta_n)^{\frac{1}{2}-|\pi|}\prod_{B\in \pi}\eta_n^{(|B|)},\quad l\geq 1,
$$
where $\Gamma_l$ is the set of partitions for $\{1,\dots ,l\} $ and 
$C(|\pi|)=(-1)^{|\pi|}\prod_{s=0}^{|\pi|-1}(\frac{1}{2}-s)$.
In the first sum, we have $\sum_{B\in \pi}|B| = l$ and
 $\sum_{D\in \gamma}|D| = j-l$, hence the sequence 
$\big(\prod_{D\in \gamma, B\in \pi}v_n^{(|D|-1)}\eta_n^{(|B|)}\big)_{n\in \mathbb{N}}$
converges to $\prod_{D\in \gamma, B\in \pi}v^{(|D|-1)}\eta^{(|B|)}$ in 
$L^2(\mathbb{R})$. Since  $\|(\eta_n-\eta, v_n-v)\|_{X^k}\to 0$ when $n\to 0$,
then for any compact set $K \subset \mathbb{R}$, the sequence 
$(u_n(1-\eta_n)^{\frac{1}{2}-|\pi|})_{n\in \mathbb{N}}$ converges to 
$u(1-\eta)^{\frac{1}{2}-|\pi|}$ in $L^\infty(K)$.
Moreover, there exists $n_0 \in \mathbb{N}$ and $M>0$ such that, for every 
$n\geq n_0$, we have 
$\|u_n(1-\eta_n)^{\frac{1}{2}-|\pi|}\|_{L^\infty(\mathbb{R})} \leq M$.
In view of Lemma \ref{convergence}, it follows that the sequence 
$(\Psi^{(j)})_{n\in \mathbb{N}}$ converges to $\Psi^{(j)}$ in $L^2(\mathbb{R})$
for any $1\leq j\leq k+1$, which finally proves that
 $d^k_{\rm loc}(\Psi_n, \Psi) \to 0$ and $n\to 0$.
\end{proof}

Conversely, the following result provide a counterexample to the continuity 
or the Lipschitz-continuity, which shows the
importance of our choice for the topology $d^k$ or $d^k_{\rm loc}$.

\begin{lemma} \label{lem3.4}
 The application $((\eta,v),\theta)\mapsto \Psi$  is not continuous from  
$(\mathcal{NV}^k(\mathbb{R})\times \mathbb{R}/(2\pi\mathbb{Z}))$ in  $(A^k,d^k)$ and
the application $\Psi\mapsto ((\eta,v),\arg(\Psi(0)))$ is not locally 
continuous Lipschitz from $(A^k,d^k_{\rm loc})$ in
 $(\mathcal{NV}^k(\mathbb{R})\times \mathbb{R}/(2\pi\mathbb{Z}))$.
\end{lemma}

\begin{proof}
We provide a counterexample in each of the two cases when $k=0$; 
these counterexamples can readily be adapted to the general cases.
We define the sequence $((\eta_n,v_n))_{n\in\mathbb{N}^\ast}$ 
with elements in $\mathcal{NV}^0(\mathbb{R})$ by
$$
((\eta_n(x),v_n(x)),\theta_n) 
= \Big(\Big(0,\frac{1}{n(1+|x|)}\Big),0\Big).
$$
We remark that
$$
\lim_{n\to +\infty}\|(\eta_n,v_n)\|_{X^0} =0.
$$
We set 
$$
\Psi_n(x) = \exp\Big(\frac{i}{n}\int_0^x\frac{dz}{(1+|z|)}\Big)
=\exp\Big(\frac{i}{n}\delta(x)\ln(1+|x|)\Big),
$$
with 
$$
\delta(x) = \begin{cases}
 1,& x>0,\\
 -1,& x<0.
\end{cases}
$$
Then
\begin{align*}
 d^0(\Psi_n,1)
&=  \|\exp\big(\frac{i}{n}\delta\ln(1+|.|)\big)-1\|_{L^\infty(\mathbb{R})}
  + \|v_n\|_{L^2(\mathbb{R})}\\
&= \|\exp\big(\frac{i}{n}\ln(1+|e^{n\pi}-1|)\big)-1\|_{L^\infty(\mathbb{R})} 
+ \|v_n\|_{L^2(\mathbb{R})}
\geq 2.
\end{align*}
Hence $d^0(\Psi_n,1)\nrightarrow 0$ and the application $(\eta,v)\mapsto \Psi$ 
is not continuous.
The second counterexample is as follows. Let $\epsilon >0$ and let 
$(\Psi, \tilde{\Psi})\in (E^0)^2$ be defined by
\begin{gather*}
          \tilde{\Psi}(x) = \Psi(x)=1,\quad x\in ]-\infty,0[,\\
          \Psi(x) = 1\quad \text{and } \tilde{\Psi}(x)=\exp(i\pi\epsilon x), \quad
  x\in [0,\frac{1}{ \epsilon}[,\\
          \Psi'(x) = \tilde{\Psi}'(x),\quad x\in [\frac{1}{ \epsilon},+\infty[.
\end{gather*}
Notice that $\Psi$ and $\tilde{\Psi}$ depend on $\epsilon$ and that
 $|\Psi|=|\tilde{\Psi}|$. We set
\begin{gather*}
(\eta,v)= \left(1-|\Psi|^2, \langle\frac{i}{\bar{\Psi}},
 \Psi'\rangle_{\mathbb{C}}\right), \\
(\tilde{\eta},\tilde{v})
= \big(1-|\tilde{\Psi}|^2, \langle\frac{i}{\bar{\tilde{\Psi}}},
\tilde{\Psi}'\rangle_{\mathbb{C}}\big).
         \end{gather*}
Then in view of the equality $|\Psi|= |\tilde{\Psi}|$, we have on the one hand,
\begin{gather*}
v+ \tilde{v} = \frac{1}{|\Psi|^2}\langle i(\Psi+\tilde{\Psi}),
 \Psi'\rangle_{\mathbb{C}} = 0,\\
\|(\tilde{\eta},\tilde{v}) - (\eta,v)\|^2_{X^0} 
= \pi^2\epsilon +4\int_{\frac{1}{ \epsilon}}^\infty v^2.
\end{gather*}
On the other hand, for $\epsilon <1$, we have
\begin{align*}
d_{\rm loc}^0(\Psi,\tilde{\Psi}) 
&= \|1-\exp(i\pi\epsilon.)\|_{L^\infty(0,1)}+\pi\sqrt{\epsilon} \\
&= |1-\exp(i\pi\epsilon)| +\pi\sqrt{\epsilon} \\
&= \frac{\sin(\pi \epsilon)}{\sin(\frac{1}{2}\pi(1-\epsilon))} + \pi\sqrt{\epsilon}.
\end{align*}
Assume now that there exists $0< C= C(\Psi, \tilde{\Psi}) \leq M$  
($M$ is independent of $\epsilon$) such that, for any 
$(\Psi, \tilde{\Psi}) \in A^0$, we have
\begin{equation*}
 \|(\tilde{\eta},\tilde{v}) - (\eta,v)\|_{X^0}
\leq C d_{\rm loc}^0(\Psi, \tilde{\Psi}).
\end{equation*}
Then
\[
\int_{\frac{1}{ \epsilon}}^\infty v^2 \leq \frac{1}{4}
\Big(M\Big(\frac{\sin(\pi \epsilon)}{\sin(\frac{1}{2}\pi(1-\epsilon))} 
+ \pi\sqrt{\epsilon}\Big)-\pi^2\epsilon \Big),
\]
and
\begin{equation}\label{con_ex}
 \lim_{\epsilon \to 0}\Big(\int_{\frac{1}{ \epsilon}}^\infty v^2\Big) = 0 .
\end{equation}
Take for instance
\begin{gather*}
          \Psi(x) = 1 + i(x-\epsilon^{-1})e^{-(x-\epsilon^{-1})}, \\
          \tilde{\Psi}(x) = -1 + i(x-\epsilon^{-1})e^{-(x-\epsilon^{-1})}
         \end{gather*}
when $x\in [\frac{1}{ \epsilon},+\infty[$. Then we easily verify that
$$
\int_{\frac{1}{ \epsilon}}^\infty v^2 
= \int_{1/\epsilon}^\infty \langle\frac{i}{\bar{\Psi}},\Psi'\rangle_{\mathbb{C}} =
\int_{0}^\infty\frac{(x-1)^2}{(1+x^2e^{-2x})^2e^{2x}}dx, $$
which is in contraction with \eqref{con_ex}.
\end{proof}

\subsection{Proof of Theorem \ref{Cauchy_HGP}} 

We start by defining the function $\Psi_0$ by
$$
\Psi_0 = \sqrt{1- \eta_0}\exp\Big(i\Big(\int_0^xv_0(z)dz\Big)\Big).
$$
Clearly $\Psi_0 \in E^k$. Then, in view of the study of the Cauchy problem 
for \eqref{GP} which we have done, there exists 
$\Psi \in \mathcal{C}(\mathbb{R}, E^k)$
satisfying \eqref{GP} with $\Psi(0,.) = \Psi_0$. 
The function $\Psi_0$ does not vanish and satisfies the property
$$
\lim_{|x|\to +\infty} |\Psi_0(x)| = 1.
$$
Then there exists $\delta$ and $T_1,T_2 >0$ such that
$$
\inf_{t\in [-T_1,T_2],x\in \mathbb{R}}|\Psi(t,x)| > \delta.
$$

\begin{proposition}\label{exis_HGP}
Let
\begin{gather*}
  \eta(t,.) = 1-|\Psi(t,.)|^2,\\
 v(t,.) = \langle \frac{i}{\bar{\Psi}(t,.)},\partial_x\Psi(t,.)\rangle_{\mathbb{C}},
 \quad t\in [-T_1,T_2].
\end{gather*}
Then the function $(\eta,v)\in \mathcal{C}([-T_1,T_2], \mathcal{NV}^k)$ 
is solution to \eqref{HGP} with $(\eta,v)(0,.) = (\eta_0,v_0)$.
\end{proposition}

\begin{proof}
We treat the more difficult case ($k=0$). We will show that $(\eta,v)$ 
satisfies \eqref{HGP} in the sense of distributions on 
$[-T_1,T_2]\times \mathbb{R}$. To this end,
we use the following regularization argument: 
Let $\rho \in \mathcal{D}(\mathbb{R})$ with $\int_{\mathbb{R}}\rho = 1$ 
and let $\epsilon >0$. We set
$\rho_\epsilon(x) = \frac{1}{\epsilon}\rho(x/\epsilon)$ and 
$\Psi_\epsilon^0 = \Psi_0\star \rho_\epsilon$. Let $\Psi_\epsilon$ 
be the solution of \eqref{GP} such that
$\Psi_\epsilon(0,.) = \Psi_\epsilon^0$. In view of Theorem  \eqref{thm:cauchyGP},  
we have
\begin{equation}\label{reg_conv}
 \sup_{t\in[-T_1, T_2]}d^0(\Psi_\epsilon(t,.),\Psi(t,.)) \to 0,
\end{equation}
as $\epsilon \to 0$. Let $\xi \in \mathcal{D}([-T_1,T_2]\times\mathbb{R})$. Then
$$
\langle \eta, \partial_t\xi\rangle_{\mathcal{D}\times\mathcal{D}'} 
= \langle |\Psi_\epsilon|^2-|\Psi|^2, \partial_t\xi\rangle_{\mathcal{D}
\times\mathcal{D}'}
 +2\langle \langle \partial_t\Psi_\epsilon,\Psi_\epsilon\rangle_{\mathbb{C}}, 
\xi\rangle_{\mathcal{D}\times\mathcal{D}'} ,
$$
and
\begin{align*}
\langle i(\partial_x^2\Psi_\epsilon 
+ (1-|\Psi_\epsilon|^2)\Psi_\epsilon),\Psi_\epsilon\rangle_{\mathbb{C}} 
&= \langle i\partial_x^2\Psi_\epsilon ,\Psi_\epsilon\rangle_{\mathbb{C}} \\
&= \partial_x\langle i\partial_x\Psi_\epsilon ,\Psi_\epsilon\rangle_{\mathbb{C}}\\
&= -\partial_x\langle i\Psi_\epsilon,\partial_x\Psi_\epsilon \rangle_{\mathbb{C}}.
\end{align*}
Relation \eqref{reg_conv} shows that
\begin{gather*}
 |\Psi_\epsilon|^2-|\Psi|^2 \to 0 \quad \text{in }
 \mathcal{C}([-T_1,T_2],L^2(\mathbb{R})),\\
 \langle i\Psi_\epsilon,\partial_x\Psi_\epsilon \rangle_{\mathbb{C}} 
\to \langle i\Psi,\partial_x\Psi \rangle_{\mathbb{C}} = (1-\eta)v \quad
         \text{in }  \mathcal{C}([-T_1,T_2],L^2(\mathbb{R})),
\end{gather*}
as $\epsilon \to 0$, which means that
$$
\partial_t\eta = 2\partial_x((1-\eta)v) \quad \text{in }
 \mathcal{D}'([-T_1,T_2]\times\mathbb{R}).
$$
We treat similarly the equation in $\partial_tv$. First, we set
$v_\epsilon = \langle \frac{i}{\bar{\Psi}_\epsilon},
\partial_x\Psi_\epsilon\rangle_{\mathbb{C}}$, 
$\eta_\epsilon = 1-|\Psi_\epsilon|^2$ and
$\gamma_\epsilon = \eta_\epsilon - v^2_\epsilon 
-\frac{\partial_x\eta_\epsilon}{2(1-\eta_\epsilon)}
+ \frac{(\partial_x\eta_\epsilon)^2}{4(1-\eta_\epsilon)^2}$.

In what follows we use the identity 
$\langle a,b\rangle_{\mathbb{C}}= \langle 1,\bar{a}b\rangle_{\mathbb{C}}$
for any  $(a,b)\in \mathbb{C}^2$.
Then we obtain
\begin{align*}
 \partial_t\langle \frac{i}{\bar{\Psi}_\epsilon},
\partial_x\Psi_\epsilon\rangle_{\mathbb{C}} 
&= \langle\partial_t( \frac{i}{\bar{\Psi}_\epsilon}),
\partial_x\Psi_\epsilon\rangle_{\mathbb{C}}
+ \langle \frac{i}{\bar{\Psi}_\epsilon},
\partial_x\partial_t\Psi_\epsilon\rangle_{\mathbb{C}}\\
&= \langle -\frac{\partial^2_x\bar{\Psi} 
+ \eta_\epsilon \bar{\Psi}}{(\bar{\Psi}_\epsilon)^2},
\partial_x\Psi_\epsilon\rangle_{\mathbb{C}}
+ \langle \frac{i}{\bar{\Psi}_\epsilon},
i\partial_x(\partial_x^2\Psi_\epsilon
+\eta_\epsilon\Psi_\epsilon)\rangle_{\mathbb{C}}\\
&= \langle -\frac{\partial_x\bar{\Psi}_\epsilon}{(\bar{\Psi}_\epsilon)^2},
\partial^2_x\Psi + \eta_\epsilon \Psi\rangle_{\mathbb{C}}
+ \langle \frac{1}{\bar{\Psi}_\epsilon},\partial_x(\partial_x^2\Psi_\epsilon
+\eta_\epsilon\Psi_\epsilon)\rangle_{\mathbb{C}}\\
&= \partial_x\langle \frac{1}{\bar{\Psi}_\epsilon},\partial_x^2\Psi_\epsilon
+\eta_\epsilon\Psi_\epsilon\rangle_{\mathbb{C}}.
\end{align*}
On the other hand, we have 
$\frac{\partial_x\eta_\epsilon}{2(1-\eta_\epsilon)} 
=-\langle \frac{1}{\bar{\Psi}_\epsilon},
\partial_x\Psi_\epsilon\rangle_{\mathbb{C}}$.
Hence
\begin{align*}
 \frac{(\partial_x\eta_\epsilon)^2}{4(1-\eta_\epsilon)^2} - v^2_\epsilon 
&=
\Big(\frac{\partial_x\eta_\epsilon}{2(1-\eta_\epsilon)}-v_\epsilon\Big)
\Big(\frac{\partial_x\eta_\epsilon}{2(1-\eta_\epsilon)}+ v_\epsilon\Big)\\
&= -\langle \frac{i-1}{\bar{\Psi}_\epsilon},\partial_x\Psi_\epsilon
 \rangle_{\mathbb{C}}\langle \frac{1+i}{\bar{\Psi}_\epsilon},
 \partial_x\Psi_\epsilon\rangle_{\mathbb{C}}\\
&= -\langle \partial_x(\frac{1}{\bar{\Psi}_\epsilon}),
 \partial_x\Psi_\epsilon\rangle_{\mathbb{C}}.
\end{align*}
Thus we obtain
\begin{align*}
 \gamma_\epsilon 
&= \langle\frac{1}{\bar{\Psi}_\epsilon},\eta_\epsilon 
 \Psi_\epsilon\rangle_{\mathbb{C}}
-\langle \partial_x(\frac{1}{\bar{\Psi}_\epsilon}),
 \partial_x\Psi_\epsilon\rangle_{\mathbb{C}} + \partial_x \langle
  \frac{1}{\bar{\Psi}_\epsilon},\partial_x\Psi_\epsilon\rangle_{\mathbb{C}}\\
&= \langle \frac{1}{\bar{\Psi}_\epsilon},\partial_x^2\Psi_\epsilon
+\eta_\epsilon\Psi_\epsilon\rangle_{\mathbb{C}},
\end{align*}
and $\partial_tv_\epsilon = \partial_x\gamma_\epsilon$.

Let now $\xi \in \mathcal{D}([-T_1,T_2]\times\mathbb{R})$.
 We have  on the one hand,
$$
\langle v_\epsilon , \partial_t\xi\rangle_{\mathcal{D}\times\mathcal{D}'}
 = \langle v-v_\epsilon, \partial_t\xi\rangle_{\mathcal{D}\times\mathcal{D}'}
 -\langle \partial_x\gamma_\epsilon , \xi\rangle_{\mathcal{D}\times\mathcal{D}'}.
$$
On the other hand, it follows from \eqref{reg_conv} that
\begin{gather*}
 \eta_\epsilon \to \eta  \quad \text{in }
 \mathcal{C}([-T_1,T_2],H^1(\mathbb{R})),\\
 v_\epsilon \to v \quad \text{in } \mathcal{C}([-T_1,T_2],L^2(\mathbb{R})),\\
\frac{1}{1-\eta_\epsilon} \to \frac{1}{1-\eta} \quad \text{in } 
\mathcal{C}([-T_1,T_2],L^\infty(\mathbb{R})),
\end{gather*}
as $\epsilon \to 0$. Then
\begin{gather*}
 v^2_\epsilon \to v^2 \quad \text{in } 
 \mathcal{C}([-T_1,T_2],L^1(\mathbb{R})),\\
\frac{(\partial_x\eta_\epsilon)^2}{(1-\eta_\epsilon)^2} 
 \to \frac{(\partial_x\eta)^2}{(1-\eta)^2}\quad \text{in }
 \mathcal{C}([-T_1,T_2],L^1(\mathbb{R})), 
\end{gather*}
as $\epsilon \to 0$. Finally, we deduce that
$$
\partial_x\gamma_\epsilon \to \eta - v^2 
-\frac{\partial_x\eta}{2(1-\eta)}+ \frac{(\partial_x\eta)^2}{4(1-\eta)^2}
\quad \text{in }  \mathcal{C}([-T_1,T_2],H^{-2}(\mathbb{R})),
$$
as $\epsilon \to 0$, and
$$
\partial_t v = \partial_x\Big(\eta - v^2 -\frac{\partial_x\eta}{2(1-\eta)}
+ \frac{(\partial_x\eta)^2}{4(1-\eta)^2}\Big)
\quad \text{in } \mathcal{D}'([-T_1,T_2]\times\mathbb{R}).
$$
\end{proof}

Now let $(\eta, v)\in \mathcal{C}(I,\mathcal{NV}^k)$ be a solution of 
\eqref{HGP}. We will show in the following proposition
that we can reconstruct a solution $\Psi$ of \eqref{GP} from $(\eta, v)$. 
Such solution will be given by
$$
\Psi(t,x) = \sqrt{1-\eta(t,x)}\exp(i\varphi(t,x)),
$$
where $\varphi$ is defined up to a constant $c=c(t)$ by 
$\partial_x\varphi = v$. It remains to determine $c$.
More specifically, we show that there exists a function 
$c: I\to \mathbb{R}$ (depending on $(\eta,v)$) such that
the function $\varphi$ defined by
$$
\varphi = \int_0^xv + c,$$ allows to reconstruct $\Psi$. 
The function $c$ represents the temporal evolution of the phase of 
$\Psi(t,0)$ and satisfies,  for $(\eta,v)$ smooth enough,
$$
c(t) = \int_0^t\partial_t\varphi(\tau,x)d\tau + \int_0^x(v(0,z)-v(t,z))dz.
$$
In this case $\Psi$ will be solution of \eqref{GP} if
$\partial_t\varphi = S$,
with 
$$
S = \eta - v^2-\partial_x\Big(\frac{\partial_x\eta}{2(1-\eta)}\Big)
+\frac{(\partial_x\eta)^2}{4(1-\eta)^2}.$$
This gives us the idea of the choice of $c$ in the following proposition.

\begin{proposition}\label{unic_HGP}
 Let $  I=[-T_1,T_2]$, with $T_1,T_2>0$, let $k\in \mathbb{N}$ and 
let $(\eta, v)\in \mathcal{C}(I,\mathcal{NV}^k)$ be a solution of \eqref{HGP}. 
 We set
$\varphi_v(t,x)= \int_0^xv(t,z)dz$. There exists a unique function  
$c\in \mathcal{C}^1(I,\mathbb{R})$ satisfying $c(0)=0$ such that the function
$\Psi \in \mathcal{C}(I,E^k)$, defined by
$$
\Psi(t,x) = \sqrt{1- \eta(t,x)}\exp\left(i(\varphi_v(t,x) + c(t))\right),
$$
is a solution of \eqref{GP}.
\end{proposition}

\begin{proof}
Note that $\Psi \in \mathcal{C}(I,E^k)$ for all $k\in \mathbb{N}$. 
To show that the function $\Psi$ defined above is solution to
\eqref{GP}, we detail the more difficult case ($k=0$).
We define $a, S\in \mathcal{D}'(I\times\mathbb{R},\mathbb{R})$ by
\begin{gather*}
S(t,x)= \Big(\eta - v^2-\partial_x\Big(\frac{\partial_x\eta}{2(1-\eta)}
\Big)+\frac{(\partial_x\eta)^2}{4(1-\eta)^2}\Big)(t,x),\\
a(t,x) = \int_0^x(v(0,z)-v(t,z))dz+\int_0^tS(\tau,x)d\tau.
\end{gather*}
Then
\begin{equation}\label{deriv_1}
 \partial_ta=S-\partial_t\varphi_v \quad \text{in } 
 \mathcal{D}'(I\times\mathbb{R},\mathbb{R}).
\end{equation}
Let $\chi \in \mathcal{D}(\mathbb{R}, \mathbb{R})$ be such that 
$\int_{\mathbb{R}}\chi(z)dz=1$. We set
$$
c(t) = \langle a(t,.),\chi\rangle_{\mathcal{D}'(\mathbb{R})
\times\mathcal{D}(\mathbb{R})}.
$$
By construction, we have $c(0) = 0$ and, since 
$(\eta, v)\in \mathcal{C}(I,\mathcal{NV}^0)$, we also have 
$c\in \mathcal{C}^1(I, \mathbb{R})$.
On the other hand, since $(\eta,v)$ is solution to \eqref{HGP}, we have
\[
 \partial_x(\partial_ta)= -\partial_tv+ \partial_x S = 0.
\]
Let $\xi \in \mathcal{D}(I\times\mathbb{R},\mathbb{R})$. We set
$$
\alpha(t) = \int_{\mathbb{R}}\xi(t,z)dz \in \mathcal{D}(I).
$$
Then
\begin{equation} \label{deriv_2}
\begin{aligned}
 \langle\varphi_v+c,\partial_t\xi\rangle_{\mathcal{D}'\times\mathcal{D}}
&=  -\langle\partial_t\varphi_v,\xi\rangle_{\mathcal{D}'\times\mathcal{D}}
 +\langle c,\partial_t\xi\rangle_{\mathcal{D}'\times\mathcal{D}}  \\
&=  -\langle S,\xi\rangle_{\mathcal{D}'\times\mathcal{D}} +\langle\partial_t a,\xi\rangle_{\mathcal{D}'\times\mathcal{D}} +
\langle c,\partial_t\xi\rangle_{\mathcal{D}'\times\mathcal{D}} \\
&=  -\langle S,\xi\rangle_{\mathcal{D}'\times\mathcal{D}} +\langle\partial_t a,\alpha\rangle_{\mathcal{D}'(I)\times\mathcal{D}(I)}
+\langle c,\partial_t\alpha\rangle_{\mathcal{D}'(I)\times\mathcal{D}(I)} \\
&=  -\langle S,\xi\rangle_{\mathcal{D}'\times\mathcal{D}},
\end{aligned}
\end{equation}
which means that $\partial_t(\varphi_v+c)= S$ in
$\mathcal{D}'(I\times\mathbb{R},\mathbb{R})$.
We shall prove that the function $\Psi$, defined by
$$
\Psi(t,x) = \sqrt{1- \eta(t,x)}\exp\left(i(\varphi_v(t,x) + c(t))\right),
$$
is solution to \eqref{GP} on $I\times\mathbb{R}$. To this end,
we need to compute the two derivatives $\partial_t\Psi$ and $\partial^2_x\Psi$
in the sense of distributions.
We use a regularization argument, where  $(\eta_{\epsilon}, v_{\epsilon})$
is defined for each $\epsilon >0$ by
\begin{gather*}
         \eta_\epsilon(t,.)= \eta(t,.)\star \rho_\epsilon, \\
         v_\epsilon(t,.) = v(t,.)\star \rho_\epsilon \quad t\in I,\\
\end{gather*}
with $\rho_\epsilon(x)= \frac{1}{\epsilon}\rho(\frac{x}{\epsilon})$,
$\rho \in \mathcal{D}(\mathbb{R})$, and $\int_{\mathbb{R}}\rho = 1$.
We denote
   $$
\Psi_{\epsilon} = \sqrt{1- \eta_{\epsilon}}
\exp\Big(i\Big((\int_0^xv_{\epsilon} + c\Big)\Big).
$$
The fact that $\|(\eta_\epsilon-\eta,v_\epsilon-v)(t,.)\|_{X^0}\to 0$ when
$\epsilon \to 0$, together with Lemma  \ref{cont_3},
yield $d^0_{\rm loc}(\Psi_\epsilon(t,.),\Psi(t,.)) \to 0$ as $\epsilon \to 0$.
Let now  $\xi \in \mathcal{D}(I\times\mathbb{R},\mathbb{C})$. Then
\begin{equation}\label{dervi_distr}
\begin{aligned}
 \langle\Psi,\partial_t\xi\rangle_{\mathcal{D}'\times\mathcal{D}}
&=  \langle\Psi-\Psi_{\epsilon},\partial_t\xi\rangle_{\mathcal{D}'\times\mathcal{D}}
-\langle\partial_t\Psi_{\epsilon},\xi\rangle_{\mathcal{D}'\times\mathcal{D}} \\
&=  \langle\Psi-\Psi_{\epsilon},\partial_t\xi\rangle_{\mathcal{D}'\times\mathcal{D}}
-\Big\langle\Big(\frac{\partial_t\eta_{\epsilon}}{2(1-\eta_{\epsilon})}
+i\partial_t\big(\int_0^xv_{\epsilon} + c\big)\Big)\Psi_{\epsilon},
\xi\Big\rangle_{\mathcal{D}'\times\mathcal{D}}.
\end{aligned}
\end{equation}
 Since $\Psi_{\epsilon} \to \Psi$ in $\mathcal{D}'(I\times\mathbb{R},\mathbb{C})$
 when $\epsilon \to 0$,
the first term of the right hand side of \eqref{dervi_distr} converges to zero.
 For the second term, we have
 $\frac{\partial_t\eta}{1-\eta}\Psi \in \mathcal{C}(I, H^{-1}(\mathbb{R}))$,
hence
$$
\frac{\partial_t\eta_{\epsilon}}{2(1-\eta_{\epsilon})}\Psi_{\epsilon}
\to \frac{\partial_t\eta}{1-\eta}\Psi \quad \text{in }
\mathcal{D}'(I\times\mathbb{R},\mathbb{C}),
$$
as $\epsilon \to 0$.
A similar argument shows that
$\partial_t(\int_0^xv_{\epsilon} + c)\Psi_{\epsilon}
\to \partial_t (\varphi_v+c)\Psi$ in $\mathcal{D}'(I\times \mathbb{R},\mathbb{C})$.
We already found that $\partial_t(\varphi_v+c)
= S\in \mathcal{C}(I, H^{-1}(\mathbb{R}))$.

We have just shown that, in the sense of distributions,
\begin{equation}\label{deriv_t}
i\partial_t\Psi = -\Big(i\frac{\partial_t\eta}{2(1-\eta)}+\partial_t(\varphi_v+c)\Big)\Psi.
\end{equation}
Similarly, we prove that, in the sense of distributions, we also have
\begin{equation}\label{deriv_xx}
 \partial^2_x\Psi= \Big( S-\eta +i\frac{\partial_x((1-\eta)v)}{1-\eta}\Big)\Psi.
\end{equation}
Thus combining \eqref{deriv_t} and \eqref{deriv_xx}, we find that, 
in the sense of distributions,
$$
i\partial_t\Psi+\partial^2_{x}\Psi+ \Psi(1-|\Psi|^2) = 0,
$$
since $\partial_t(\varphi_v+c)=S$ in $\mathcal{D}'(I\times\mathbb{R},\mathbb{R})$ 
and $(\eta,v)$ is solution to \eqref{HGP}. Since the derivative of the continuous
function $c$ in the sense of distributions is completely determined by  
$S$ and $\partial_t\varphi_v$, and since $c(0)=0$, the uniqueness of $c$ follows.
\end{proof}

Proposition \ref{unic_HGP} proves that the solution of \eqref{HGP} constructed 
by Proposition \ref{exis_HGP} is unique in the space
$\mathcal{C}([-T_1,T_2],\mathcal{NV}^k(\mathbb{R}))$. Indeed, let
$(\eta_1,v_1), (\eta_2, v_2) \in \mathcal{C}([-T_1,T_2],\mathcal{NV}^k(\mathbb{R}))$ 
denote two solutions to the equation \eqref{HGP} that satisfy
$$
(\eta_1(0,.), v_1(0,.))=(\eta_2(0,.), v_2(0,.)) 
= (\eta_0,v_0) \in \mathcal{NV}^k(\mathbb{R}).
$$
Then, in view of Proposition \ref{unic_HGP}, there exist
 $c_1, c_2 \in \mathcal{C}^1([-T_1,T_2],\mathbb{R})$ such that the two functions
$$
\Psi_1 = \sqrt{1-\eta_1}\exp(i(\int_0^xv_1 + c_1))\quad \text{and} \quad 
\Psi_2 = \sqrt{1-\eta_2}\exp(i(\int_0^xv_2 + c_2)),
$$
are  solutions to \eqref{GP} in the space $\mathcal{C}([-T_1,T_2], E^k)$ satisfying
$$
\Psi_1(0,.) = \Psi_2(0,.) = \sqrt{1-\eta_0}\exp\Big(i\Big(\int_0^xv_0\Big)\Big).
$$
Since the Cauchy problem for \eqref{GP} is well-posed in the space 
$\mathcal{C}([-T_1,T_2], E^k)$, we have in view of Proposition 
\eqref{esp_gp_hgp} that
$$
\varPhi^{-1}(\Psi_1(t,.))= \varPhi^{-1}(\Psi_2(t,.)) \quad \forall 
t\in [-T_1,T_2].
$$
Consequently, we obtain that
$\eta_1 = \eta_2$ and $v_1 = v_2$.
This proves the well-posedness in 
$\mathcal{C}([-T_1,T_2], \mathcal{NV}^k(\mathbb{R})$ 
of the Cauchy problem of \eqref{HGP}.

Equation \eqref{HGP} is invariant with respect to the change of variable 
$t\to t+c$. Then a similar result to that of
Proposition \ref{exis_HGP} can be proved for an initial data at time 
$t= t_0 \neq 0$. By using iteratively
the two Propositions \ref{exis_HGP} and \ref{unic_HGP}, this allows 
to prove the existence of maximal $T_\ast, T^\ast >0$ such that the 
solution $(\eta,v)$
can be extended to the interval $]-T_\ast, T^\ast[$, with
\begin{gather*}
\lim_{t\to T^\ast}\max_{x\in \mathbb{R}}\eta(t,x)=1,\quad \text{when }
 T^\ast < +\infty,\\
\lim_{t\to -T_\ast}\max_{x\in \mathbb{R}}\eta(t,x)=1,\quad \text{when } 
 -T_\ast > -\infty .
\end{gather*}

\subsubsection{Conservation of the quantities $H$ and $P$}

We show in this section that the energy
$$
H(\eta,v) = \frac{1}{8}\int_{\mathbb{R}}
\frac{(\partial_x\eta)^2}{1-\eta}+\frac{1}{2}
\int_{\mathbb{R}}(1-\eta)v^2+\frac{1}{4}\int_{\mathbb{R}}\eta^2
$$
is conserved along $(\eta(t,.), v(t,.))$ when
 $ (\eta,v) \in \mathcal{C}(]-T_\ast,T^\ast[, \mathcal{NV}^k)$. 
In view of Proposition \ref{unic_HGP}, for any
$[-T_1,T_2]\subset ]-T_\ast,T^\ast[$, there exists 
$c\in \mathcal{C}^1([-T_1,T_2])$ such that the function
$$
\Psi = \sqrt{1-\eta}\exp(i(\int_0^xv + c))
$$
is a solution to \eqref{GP} on $[-T_1,T_2]\times \mathbb{R}$. 
We have shown that the Ginzburg-Landau energy
$$
\Sigma(\Psi) = \frac{1}{2}\int_{\mathbb{R}}|\partial_x\Psi|^2 
+ \int_{\mathbb{R}}(1-|\Psi|^2)^2
$$
is conserved along the flow $\Psi(t,.)$. Moreover, we have
$$
H(\eta(t,.),v(t,.)) = \Sigma(\Psi(t,.))\quad\forall t\in [-T_1,T_2].
$$
Thus $H(\eta(t,.),v(t,.))$ is constant on $[-T_1,T_2]$.

We now prove the conservation of the momentum $P$ defined by
$$
P(\eta,v) = \frac{1}{2}\int_{\mathbb{R}}\eta v.
$$
In the case where $k\geq 1$, it suffices to note that if 
$(\eta,v) \in \mathcal{C}(]-T_\ast,T^\ast[,\mathcal{NV}^k)$, then
$$
\frac{d}{dt}\int_{\mathbb{R}}\eta v= \int_{\mathbb{R}}\partial_t\eta v
+\int_{\mathbb{R}}\eta\partial_tv.
$$
Replacing $\partial_t\eta$ and $\partial_t v$ by the right-hand side 
member of \eqref{HGP} gives the desired result. The case $k=0$ is more difficult. 
To treat this case, it
is useful to show that the application  $(\eta_0,v_0)\mapsto (\eta(t,.),v(t,.))$ 
is continuous from $\mathcal{NV}^0$ to $\mathcal{NV}^0$ in the following sense: 
For every sequence $((\eta_{0,n},v_{0,n}))_{n\in \mathbb{N}}$ with elements 
in $\mathcal{NV}^0$ that converges to $(\eta_0,v_0)$ in 
$(\mathcal{NV}^0,\|.\|_{X^0})$,
the sequence $((\eta_n,v_n))_{n\in \mathbb{N}}$ of the solution of \eqref{HGP}
 with initial data $(\eta_{0,n},v_{0,n})$ satisfies, for each 
$t\in ]-T_\ast, T^\ast[$,
$$
\lim_{n\to +\infty}\|(\eta_n(t,.),v_n(t,.))-(\eta(t,.),v(t,.))\|_{X^0(\mathbb{R})} 
= 0.
$$
This result is a consequence of Lemmas \ref{cont_2} and \ref{cont_3}, 
and of Corollary \ref{cont_forte}, via the diagram
$$
\xymatrix{\ar @{} [dr] |{}
            (\eta_0,v_0) \ar[d] \ar[r]^-{\ref{cont_3}} & \Psi_0\ar[d]^-{\ref{cont_forte}} \\
            (\eta(t,.),v(t,.))        & \Psi(t,.)\ar[l]^-{\ref{cont_2}}
}$$
where $\Psi_0 = \sqrt{1-\eta_0}\exp(i(\int_0^xv_0))$ and $\Psi$ 
is the solution of \eqref{HGP} with initial data $\Psi_0$. Now, 
to prove the  conservation of the momentum $P$, we use the following regularization 
argument: Let $\rho_\epsilon = \frac{1}{\epsilon}\rho(./\epsilon)$ with
$\rho \in \mathcal{D}(\mathbb{R})$ and $\epsilon >0$ and let
\begin{gather*}
          \eta^0_\epsilon = \eta_0 \star\rho_\epsilon, \\
          v^0_\epsilon = v_0\star \rho_\epsilon .
         \end{gather*}
Let $(\eta_\epsilon,v_\epsilon)$ be the solution of \eqref{GP} with initial 
data $( \eta^0_\epsilon, v^0_\epsilon)$. Noting that
$$
\|( \eta^0_\epsilon, v^0_\epsilon)-(\eta_0,v_0)\|_{X^0(\mathbb{R})}\to 0,
$$
when $\epsilon \to 0$, the above continuity property shows that, for any 
$t\in ]-T_\ast,T^\ast[$,
$$
\lim_{\epsilon \to 0}\|( \eta_\epsilon(t,.), v_\epsilon(t,.))
-(\eta(t,.),v(t,.))\|_{X^0(\mathbb{R})} = 0.
$$
Thus, for any $t\in ]-T_\ast,T^\ast[$, we have
$$
\lim_{\epsilon \to 0}P(\eta_\epsilon(t,.),v_\epsilon(t,.)) = P(\eta(t,.),v(t,.)).
$$ 
It remains to show that
$$
\frac{d}{dt}P(\eta_\epsilon(t,.),v_\epsilon(t,.)) =0.
$$
This follows from
\begin{align*}
 \int_{\mathbb{R}}\partial_tv_\epsilon\eta_\epsilon 
&= -\int_{\mathbb{R}}\Big(\eta_\epsilon -v_\epsilon^2
-\partial_x\Big(\frac{\partial_x\eta_\epsilon}{2(1-\eta_\epsilon)}\Big)
 +\frac{(\partial_x\eta_\epsilon)^2}{4(1-\eta_\epsilon)^2}\Big)
\partial_x\eta_\epsilon \\
&=  -\frac{1}{2}\int_{\mathbb{R}}\partial_x(\eta_\epsilon^2)+\int_{\mathbb{R}}\partial_x\eta_\epsilon v_\epsilon^2
- \frac{1}{4}\int_{\mathbb{R}}\frac{\partial_x(\partial_x\eta_\epsilon)^2(1-\eta_\epsilon)+(\partial_x\eta_\epsilon)^3}{(1-\eta_\epsilon)^2} \\
&=  \int_{\mathbb{R}}\partial_x\eta_\epsilon v_\epsilon^2
- \frac{1}{4}\int_{\mathbb{R}}\partial_x
\Big(\frac{(\partial_x\eta_\epsilon)^2}{1-\eta_\epsilon}\Big) .
\end{align*}
and
\[
 \int_{\mathbb{R}}\partial_t\eta_\epsilon v_\epsilon 
=  2\int_{\mathbb{R}}\partial_x((1-\eta_\epsilon)v_\epsilon)v_\epsilon \\
=  - \int_{\mathbb{R}}\partial_x \eta_\epsilon v_\epsilon^2 \\
=  -\int_{\mathbb{R}}\partial_tv_\epsilon\eta_\epsilon.
\]

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