\documentclass[reqno]{amsart}
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\AtBeginDocument{{\noindent\small
\emph{Electronic Journal of Differential Equations},
Vol. 2012 (2012), No. 168, pp. 1--6.\newline
ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu
\newline ftp ejde.math.txstate.edu}
\thanks{\copyright 2012 Texas State University - San Marcos.}
\vspace{9mm}}

\begin{document}
\title[\hfilneg EJDE-2012/168\hfil Existence of solutions]
{Existence of solutions for  convex  sweeping processes in
 $p$-uniformly smooth and $q$-uniformly convex Banach spaces}

\author[M. Bounkhel \hfil EJDE-2012/168\hfilneg]
{Messaoud Bounkhel}

\address{Messaoud Bounkhel \newline
King Saud University, Department of Mathematics, P.O. Box 2455,
Riyadh 11451, Riyadh, Saudi-Arabia}
\email{bounkhel@ksu.edu.sa, bounkhel\_messaoud@yahoo.fr}

\thanks{Submitted February 14, 2012. Published October 4, 2012.}
\subjclass[2000]{34A60, 49J53}
\keywords{Uniformly smooth and uniformly convex  Banach spaces;
\hfill\break\indent state dependent sweeping process;
generalized projection; duality mapping}

\begin{abstract}
 We show the existence of at least one Lipschitz solution 
 for extensions of convex sweeping processes  in reflexive smooth
 Banach spaces.  Our result is proved under a weaker
 assumption on the moving set than those in \cite{bounkhel_rabab},
 and using a different discretization.
\end{abstract}

\maketitle
\numberwithin{equation}{section}
\newtheorem{theorem}{Theorem}[section]
\newtheorem{lemma}[theorem]{Lemma}
\newtheorem{proposition}[theorem]{Proposition}
\newtheorem{definition}[theorem]{Definition}
\allowdisplaybreaks

\section{Main result}

Bounkhel and Al-yusof  \cite{bounkhel_rabab}  studied the
following extension of the convex sweeping processes from Hilbert spaces $H$
to reflexive smooth Banach spaces $X$:
\begin{itemize}
 \item[(SP)]
Find $u:[0,T]\to X$ such that $u(t)=u_0+\int_0^t \dot u(s) ds$,
$$
 -\frac{d}{dt}(J(u(t))) \in N(C(t);u(t)) \text{ a.e. in } [0,T] \text{ and } u(t)\in
C(t), \forall t\in [0,T],
$$
\end{itemize}
where $J:X\to X^*$ is the duality mapping defined from $X$ into $X^*$
(see Section 2 for the definition).

Clearly,  (SP)   coincides with the well known convex sweeping process introduced
and studied in \cite{moreau}  in the Hilbert space setting in which $J$
is the identity mapping.
The authors in \cite{bounkhel_rabab} proved the following theorem.

\begin{theorem} \label{thm2.1}
Let $p,q >1$, $X$ be a $p$-uniformly convex and $q$-uniformly smooth Banach space,
 $T>0$, $I=[0,T]$ and
$C:I\rightrightarrows X$ be a set-valued mapping closed convex values
satisfying for any $t, t' \in I$ and any $x\in X$
\begin{equation}\label{dVcond}
|(d^V_{C(t')})^{1/q'}(\psi)-(d^V_{C(t)})^{1/q'}(\phi)|\le \lambda|t'-t|+
\gamma \|\psi-\phi\|,
\end{equation}
where $\lambda, \gamma>0$, and $q'=\frac{q}{q-1}$. Assume that
\begin{equation}\label{compac_cond}
J(C(t))\subset K,  \forall t\in I \text{ for some convex
compact set }  K \text{ in } X^*.
\end{equation}
Then {\rm (SP)} has at least one Lipschitz solution
\end{theorem}

They proved the existence of solutions under the Lipschitz continuity
of the function $(t,\psi)\mapsto (d^V_{C(t)})^{1/q'}(\psi)$ defined on
$I\times X^*$, and under the compactness assumption \eqref{compac_cond}.
Using a different discretization we prove the previous theorem under the
boundedness of $C$ and the compactness of their values
which is clearly weaker than the compactness assumption \eqref{compac_cond},
and under the Lipschitz continuity
of the usual distance function $t\mapsto (d_{C(t)})^{1/q'}(u)$, for all $u\in X$,
defined on
$I$ which is easier to handle with, than the function used in \eqref{dVcond}.
Although, both Lipschitz assumptions coincide in the Hilbert space setting, in the case
of Banach spaces the Lipschitz continuity of the distance function is easier to be checked
than \eqref{dVcond}.

Before proving our main result in Theorem \ref{th2}, we recall
from \cite{bounkhel_rabab}
some needed concepts and results and for more details we refer
the reader to \cite{bounkhel_rabab} and the references therein.

\section{Preliminaries}

Let  $X$ be a Banach space with topological dual space
$X^*$. We denote by $d_S$ the usual distance function to $S$;
i.e., $d_S(x):=\inf_{u\in S}\|x-u\|$. Let $S$ be a
nonempty closed convex set of $X$ and  $\bar x$ be a point in $S$.
The convex normal cone of $S$ at $\bar x$ is defined by (see for
instance \cite{clarke1})
\begin{equation}\label{eq2.1}
N(S;\bar x)=\{\varphi\in X^*: \langle \varphi, x-\bar x\rangle \le
0\text{ for all } x\in S\}.
\end{equation}
The normalized duality mapping $J:X\rightrightarrows X^*$ is defined by
$$
J(x)=\{j(x)\in X^*:\langle j(x),x\rangle =\|x\|^2=\|j(x)\|^2\}.
$$
Many properties of the normalized duality mapping $J$ have been studied.
For the details, one may see the books \cite{yakov,takahashi,Vainberg}.
Let $V:X^*\times X \to \mathbb{R}$ be defined by
$$
V(\varphi,x)=\|\varphi\|^2-2\langle\varphi,x\rangle+\|x\|^2,
\text{ for any } \varphi \in X^* \text{ and } x\in X.
$$
Based on the functional $V$, a set $\pi_S(\varphi)$ of generalized
projections of $\varphi\in X^*$ onto $S$ is defined as follows
(see \cite{alber1}).

\begin{definition} \label{def0.2.1} \rm
Let $S$ be a nonempty subset of $X$ and $\varphi \in X^*$.
If there exists a point $\bar x \in S$ satisfying
$$
V(\varphi,\bar x)=\inf_{ x\in S} V(\varphi,x),
$$
then $\bar x$ is called a generalized projection of $\varphi $
onto $S$. The set of all such points is denoted by
$\pi_S(\varphi)$. When the space $X$ is not reflexive
$\pi_S(\varphi)$ may be empty for some elements $\varphi\in X^*$
even when $S$ is closed and convex (see \cite[Example 1.4]{Li}).
\end{definition}

The  two following propositions are needed in the proof of the main theorem.
 For their proofs we refer the reader
to \cite{bounkhelthibault,penot} respectively.

\begin{proposition}\label{prop2}
Let $S$ be a nonempty closed convex subset of $X$ and $x\in S$. Then
$$
\partial d_S(x)=N_S(x)\cap \mathbf{B}.
$$
\end{proposition}

\begin{proposition}\label{prop1}
For a nonempty closed convex subset $S$ of a reflexive
smooth Banach space $X$ and $u\in S$, the following assertions are
equivalent:
\begin{itemize}
\item[(i)] $\bar x\in S$ is a projection of $u$ onto $S$, that is
$\bar x\in P_S(u)$;
\item[(ii)] $\langle J(u-\bar x),x-\bar
x\rangle\le 0$ for all $x\in S$;
\item[(iii)] $J(u-\bar x)\in N(S;\bar x)$.
\end{itemize}
\end{proposition}

Assume now that $X$ is $p$-uniformly convex and $q$-uniformly smooth
Banach space and let $S$ be closed nonempty set in $X$.
Recall the definition of the function
$d^V_S: X^* \to [0,\infty[ $,  given by $d^V_S(\varphi)=\inf_{x\in S}V(\varphi,x)$.
Clearly, in Hilbert spaces, $d^V_S$ coincides with $d_S^2$.
We need the two following lemmas proved in
\cite{bounkhel_rabab}.

\begin{lemma} \label{lem5.1}
Let $p,q>1$, $X$ be a $p$-uniformly convex and $q$-uniformly
smooth Banach space, and let $S$ be a bounded set. Then there
exist two constants $\alpha >0$ and $\beta >0$ so that
$\alpha\|x-y\|^p \le V(J(x),y)\le \beta \|x-y\|^q, \text{ for all }
x,y \in S$.
\end{lemma}

\begin{proposition}\label{propo5.0}
If $S$ is a bounded set in $X$, then
$d^V_S(\varphi)\le \beta (d_S(J^*(\varphi)))^q$,
where $\beta$ depends on the bound of $S$ and on $\varphi$.
As a consequence, for  sets $S_1$ and $S_2$ in $X$ and $X^*$ bounded by $l_1$
and $l_2$ respectively, we have $d^V_S(\varphi)\le \beta (d_S(J^*(\varphi)))^q,
\text{ for all } \varphi \in S_2$, where $\beta$ depends on $l_1$ and $l_2$.
\end{proposition}

The following proposition is taken from \cite{yakov}.

\begin{proposition}\label{prop5.2}
Let $p\ge 2$ and let $X$ be a $p$-uniformly convex and $q$-uniformly smooth Banach
space. The duality mapping $J:X\to X^*$ is Lipschitz on bounded sets; that is,
$$
\|J(x)-J(y)\|\le C(R)\|x-y\|, \text{ for all } \|x\\\le R, \|y\|\le R.
$$
Here $C(R):=32Lc_2^2(q-1)^{-1}$ and $c_2=\max\{1,R\}$ and $1<L<1.7$.
The Lipschitz continuity on bounded sets of the duality mapping $J_*$
on $X^*$, follows from the fact that $X^*$ is  $p'$-uniformly convex and
$q'$-uniformly smooth Banach
space with $p'$ and $q'$ are the conjugate numbers of $p$ and $q$ respectively;
 i.e., $p'=\frac{p}{p-1}$, $q'=\frac{q}{q-1}$.
\end{proposition}

The following proposition summarizes some results proved in
\cite{bounkhel_rabab2,Li}.

\begin{proposition}\label{prop0.0.6}
Let  $X$ be a  reflexive Banach space with dual space $X^*$ and
$S$ be a nonempty, closed and convex subset of $X$. The following
properties hold:
\begin{itemize}
\item[($\pi1$)] $\pi_S(\varphi)\not=\emptyset$,
for any $\varphi\in X^*$;

\item[($\pi2$)] If $X$ is also smooth,
then   $\varphi\in N(S,\bar x)$, if and only if,
there exists $\alpha>0$  such that
 $\bar x\in \pi_S(J(\bar x)+\alpha\varphi)$.
\end{itemize}
\end{proposition}

\section{Main result}

Now, we are ready to prove our main result in the following theorem.

\begin{theorem}\label{th2}
Instead of \eqref{dVcond} and \eqref{compac_cond} in Theorem \ref{thm2.1},
assume that $C$ is bounded with compact values and that
\begin{equation}\label{distcond}
|(d_{C(t')})^{p/q}(u)-(d_{C(t)})^{p/q}(u)|\le \lambda|t'-t|.
\end{equation}
Then {\rm (SP)} has at least one Lipschitz solution.
\end{theorem}

\begin{proof}
Assume that $T=1$. Consider $\forall n\in N$ the following partition of $I$
$$
I_{n,i}=(t_{n,i},t_{n,i+1}], \quad t_{n,i}=\frac{i}{n}, \quad
0\leq i\leq n-1,\quad I_{n,0}=\{0\}.
$$
Put $\mu_n=1/n$. Fix $n\ge 2$. Define by induction
\begin{gather*}
u_{n,0}= {u_0}\in C(0); \\
{u_{n,{i+1}}} \in
\pi(C(t_{n,{i+1}});u_{n,i}), \quad\text{for } 0\leq i\leq n-1,
\end{gather*}
and
\begin{gather*}
u_n(t):= J^*(u^*_n(t))\\
u^*_n(t):= J(u_{n,i})+\frac{(t-t_{n,i})}{\mu_{n}}(J(u_{n,i+1})-J(u_{n,i})),
 \quad\text{for all } t\in I_{n,i}
\end{gather*}
and $u^*_n(0)=J(u_0)$.
The construction is well defined since the generalized projection $\pi$ exits
 by Proposition  \ref{prop0.0.6}. Clearly $u^*_n$ and $u_n$ are continuous
 on all $I$ and $u^*_n$ is  differentiable on $I\setminus \{t_{n,i}\}$ and
 $\dot u^*_n(t)=\frac{J(u_{n,i+1})-J(u_{n,i})} {\mu_{n}}$, for all
 $t\in I\setminus \{t_{n,i}\}$.

 Let us find an upper bound estimate for the expression $\|J(u_{n,i+1})-J(u_{n,i})\|$.
First, we have to point out that the sequence $u_i^n$ is bounded by some $l$ because
 the set-valued mapping $C$ is  bounded.
Now, since $X$ is $q$-uniformly smooth and $p$-uniformly convex and the sequence
$u_i^n$ is bounded by $l$, there exist some constants $\alpha$ and $\beta$
depending on $l$ such that
 \[
\alpha\|u_{n,i+1}-u_{n,i}\|^p \le V(J(u_{n,i}),u_{n,i+1})
\le \beta\|u_{n,i+1}-u_{n,i}\|^q,
\]
  and so by the construction of the sequence $u_i^n$ and
Proposition \ref{propo5.0} we obtain
\[
\alpha\|u_{n,i+1})-u_{n,i}\|^p \le d^V_{C(t_{n,i+1})}(J(u_{n,i})) \le \beta
d^q_{C(t_{n,i+1})}(u_{n,i})
\]
 and so by the Lipschitz continuity in \eqref{distcond} we obtain
  \begin{align*}
(\frac{\alpha}{\beta})^{\frac{1}{p}}\|u_{n,i+1})-u_{n,i}\|
&\le d^{q/p}_{C(t_{n,i+1})}(u_{n,i})-
d^{q/p}_{C(t_{n,i})}(u_{n,i})\\
&\leq \lambda|t_{n,i+1}-t_{n,i}|=\lambda \mu_n,
\end{align*}
 and so
\[
\|u_{n,i+1})-u_{n,i}\| \le  \bar{\lambda}\mu_n,
\]
where $ \bar{\lambda}=  (\frac{\beta}{\alpha})^{\frac{1}{p}}\lambda$.
Using now the Lipschitz property of the duality mapping $J$ in
 Proposition \ref{prop5.2}, we can write
$$
\|J(u_{n,i+1})-J(u_{n,i})\|\le C(l)\|u_{n,i+1}-u_{n,i}\|\le C(l)\bar{\lambda}\mu_n.
$$
This inequality ensures the Lipschitz continuity of $u^*_n$ on all $I$ with ratio
$\delta:=C(l)\bar{\lambda}$.
Using the characterization of the normal cone, in terms of the generalized projection
 $\pi$ projection operator stated in Proposition \ref{prop0.0.6},
we can write for a.e.   $t\in I$
\[
J(u_{n,i+1})-J(u_{n,i})\in -N (C(t_{n,i+1});u_{n,i+1}),
\]
which ensures together with Proposition \ref{prop2} that
\[
-\frac{J(u_{n,i+1})-J(u_{n,i})}{\mu_n} \in
\delta \partial d_{C(t_{n,i+1})}(u_{n,i+1}).
\]
Define now on $I_{n,i}$ the functions  $\theta_n :I\rightarrow I$ by
 $\theta_n(0)=0$, and
$$
\theta_n(t)=t_{n,i+1}, \quad \text{for all } t \in I_{n,i}.
$$
Then the above inclusion becomes
\begin{eqnarray}\label{eqn;2biss}
-\dot u^*_n(t) \in \delta \partial d_{C(\theta_n(t))}(u_n(\theta_n(t))).
\end{eqnarray}
Now, let us prove that the sequence $(u_n)$ has a convergent subsequence. Clearly,
we have $B=\{u_n; n\ge 2\}$ is equi-Lipschitz and bounded.
So it remains to prove that $B(t)=\{u_n(t); n\ge 2\}$ is relatively compact in $X$,
for all $t\in I$.
By construction we have
\begin{equation} \label{eqn:3}
u_n(\theta_n(t))\in C(\theta_n(t)), \quad \forall t\in I \text{ and all }n\ge 2,
\end{equation}
and hence by the Lipschitz property of $d^{p/q}_C$ and the
equi-Lipschitz property of $u_n$ we can write
\begin{align*}
d^{p/q}_{C(t)}(u_n(t))
&= d^{p/q}_{C(t)}(u_n(t))-d^{p/q}_{C(\theta_n(t))}(
u_n(\theta_n(t))\le \lambda\mu_n+\|u_n(\theta_n(t))-u_n(t)\| \\
&\leq  (\lambda+\delta)\mu_n.
\end{align*}
Assume by contradiction that $B(t_0)$ is not relatively compact in $X$ for
some $t_0\in I$. So,
$\gamma (B(t_0))\ge 2\bar \delta >0$, for some $\bar\delta\in(0,1]$.
Fix now $n_0\in \mathbb{N}$ such that $\mu_n \le \mu_{n_0} <
\frac{(\frac{\bar\delta}{2})^{p/q}}{\lambda+\delta}$, for all
$n\ge n_0$.
So
\[
u_n(t)\in C(t)+ (\lambda+\delta)^{q/p}\mu_{n_0}^{q/p}
\mathbb{B}, \quad \text{for all } n\ge n_0 \text{ and all } t\in I,
\]
which implies
\[
B(t) \subset C(t)+ (\lambda+\delta)^{q/p}\mu_{n_0}^{q/p}
\mathbb{B}, \quad \text{ for all } t\in I.
\]
Then the properties of $\gamma$ and the compactness of the values of $C$ imply
\begin{align*}
\gamma(B(t_0))
&= \gamma(\{u_n(t_0):n\ge n_0\})\le \gamma((C(t_0))
+\gamma((\lambda+\delta)^{q/p}\mu_{n_0}^{q/p}\mathbb{B}) \\
&\leq  2(\lambda+\delta)^{q/p}\mu_{n_0}^{q/p}
< \bar\delta,
\end{align*}
which is a contradiction. Therefore, the set $B(t)$ is relatively compact
in $X$ for any $t\in I$. Thus, Arzela-Ascoli theorem concludes that $(u_n)$
has a subsequence (still denoted $u_n$) converging uniformly to some $u$.
Since $\lim_n \theta_n(t)=t$, we can write
$\lim_n u_n(\theta_n(t)) =\lim_n u_n(t)=u(t)$ uniformly on $I$.
So the   sequence $u^*_n=J(u_n)$ will converge uniformly to $u^*=J(u)$ on $I$,
since $J$ is uniformly continuous on bounded sets. We also have $(\dot u ^*_n)$
 converges weakly star in $L^\infty(I,X^*)$ to some $w$. So, by the reflexivity
and the separability of the space $X$, we can write
$$
u^*(t)=J(u(t))=\lim_n u^*_n(t)
=\lim_n\left(u^*_n(0)+\int^t_0 \dot u^*_n(s) ds\right)
= u_0+\int^t_0 w(s) ds.
$$
Hence $\dot u^*(t)=\frac{d}{dt}J(u(t))=w(t)$ a.e. on $I$.
 Let us prove that $u$ is the solution of our problem. First, we have to prove that
 $u(t)\in C(t)$, for all $t\in I$. Using now the Lipschitz property of the function
$t\mapsto d^{q/p}_{C(t)}$
  to write for all $t\in I$
\begin{align*}
d^{q/p}_{C(t)}(u_n(\theta_n(t))
&= d^{q/p}_{C(t)}(u_n(\theta_n(t))-
d^{q/p}_{C(\theta_n(t))}(u_n(\theta_n(t))\\
&\leq \lambda|\theta_n(t)-t|
\le \lambda\mu_n,
\end{align*}
 and so
 \begin{align*}
d_{C(t)}(u(t))
&= d_{C(t)}(u_n(\theta_n(t))+\|u_n(\theta_n(t)-u(t)\| \\
&\leq (\lambda\mu_n)^{p/q}+\|u_n(\theta_n(t))-u(t)\|  \to 0,
\end{align*}
as $n\to \infty$, by the fact that $\lim_n u_n(\theta_n(t))=u(t)$ uniformly on $I$.
So the closedness of the set $C(t)$ ensures $u(t)\in C(t)$, for all $t\in I$.
 Going back to \eqref{eqn;2biss} we have
\[
-\dot u^*_n(t)) \in N(C(\theta_n(t));u_n(\theta_n(t))), \quad \text{a.e. on } I.
\]
So, Proposition \ref{prop2} ensures for a.e. $t\in I$,
\begin{equation} \label{eqn:5bis}
\langle -\dot u^*_n(t));x-u_n(\theta_n(t))\rangle \le 0, \quad
\forall x\in C(\theta_n(t)).
\end{equation}
Using the fact that $\dot u^*_n$  converges
to $\frac{d}{dt}J(u(\cdot))$ in the weak star topology of $L^\infty(I,X^*)$,
 we can pass to the limit in \eqref{eqn:5bis} to obtain
\begin{equation} \label{eqn:6}
\langle -\frac{d}{dt}J(u(t));x-u(t)\rangle \le 0, \quad
\forall x\in C(t), \text{ a.e. on } I.
\end{equation}
Indeed, fix $t\in I$, for which $\dot u^*_n(t)$ exists  and
converges weakly  to $\frac{d}{dt}J(u(t))$, and let $x$ be any element in $C(t)$.
Then, we have
$$
x\in C(\theta_n(t))+(\lambda \mu_n)^{q/p} \mathbb{B};
$$
that is,
$x=y_n(t)+(\lambda \mu_n)^{q/p}b_n$,
 with $b_n\in \mathbb{B}$ and $y_n(t)\in C(\theta_n(t))$.
 Hence \eqref{eqn:5bis} yields
\begin{align*}
&\langle -\frac{d}{dt}J(u(t)),x-u(t)\rangle \\
&=  \langle -\frac{d}{dt}J(u(t))+\dot u^*_n(t)),x-u(t)\rangle+
\langle -\dot u^*_n(t)),x-u(t)\rangle \\
&= \langle -\frac{d}{dt}J(u(t))+\dot u^*_n(t)),x-u(t)\rangle+\langle -\dot u^*_n(t)),
u_n(\theta_n(t))-u(t)\rangle\\
&\quad + \langle -\dot u^*_n(t),y_n(t)-u_n(\theta_n(t))\rangle+
\langle -\dot u^*_n(t)), (\lambda \mu_n)^{q/p}b_n\rangle \\
&\leq \langle \dot u^*_n(t))-\frac{d}{dt}J(u(t)),x-u(t)\rangle+
\lambda(\lambda \mu_n)^{q/p}  
+ \lambda\| u_n\big(\theta_n(t)-u(t)\big)\|
\to 0
\end{align*}
as $n\to \infty$. So,
\begin{eqnarray}
\langle -\frac{d}{dt}J(u(t)),x-u(t)\rangle \le 0, \quad \text{for all } x\in C(t),
\end{eqnarray}
which by Proposition \ref{prop2}  gives
 \begin{equation} \label{eqn:7ter}
 -\frac{d}{dt}J(u(t))\in N(C(t);u(t)), \quad \text{ a.e. on  }  I
 \end{equation}
and hence the proof is complete.
\end{proof}

\subsection*{Acknowledgments}
 The author extends his appreciation to the Deanship of Scientific Research 
at King Saud University for funding the work through the research group 
project  No. RGP-VPP-024.


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\end{document}
