\documentclass[reqno]{amsart}
\usepackage{hyperref}

\AtBeginDocument{{\noindent\small
\emph{Electronic Journal of Differential Equations},
Vol. 2012 (2012), No. 117, pp. 1--14.\newline
ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu
\newline ftp ejde.math.txstate.edu}
\thanks{\copyright 2012 Texas State University - San Marcos.}
\vspace{9mm}}

\begin{document}
\title[\hfilneg EJDE-2012/117\hfil Solutions to systems of PDEs]
{Solutions to systems of partial differential equations with weighted
 self-reference and heredity}

\author[P. K. Anh, N. T. T. Lan, N. M. Tuan\hfil EJDE-2012/117\hfilneg]
{Pham Ky Anh, Nguyen Thi Thanh Lan, Nguyen Minh Tuan}  % in alphabetical order

\address{Pham Ky Anh \newline
Department of Mathematics, 
School of Science, Vietnam National University,
334 Nguyen Trai Str., Hanoi, Vietnam}
\email{anhpk@vnu.edu.vn, anhpk2009@gmail.com}

\address{Nguyen Thi Thanh Lan \newline
Faculty of Mathematics and Applications, 
Saigon University, 
273 An Duong Vuong str., w. 3, dist. 5, Ho Chi Minh
City, Vietnam}
\email{nguyenttlan@gmail.com}

\address{Nguyen Minh Tuan \newline
Department of Mathematics, University of Education, 
Vietnam  National University,
G7 Build., 144 Xuan Thuy Rd., Cau Giay
 Dist., Hanoi, Vietnam}
\email{tuannm@hus.edu.vn}

\thanks{Submitted June 18, 2012. Published July 14, 2012.}
\subjclass[2000]{35F25, 45G15, 47J35, 47N60, 92D15}
\keywords{Hereditary; self-referred; non-linear integro-differential equations;
\hfill\break\indent  recursive scheme}

\begin{abstract}
 This article studies the existence of solutions to systems of nonlinear 
 integro-differential  self-referred and heredity equations.
 We show the existence of a global solution and the uniqueness of a local
 solution to a system of integro-differential equations with given
 initial conditions.
\end{abstract}

\maketitle
\numberwithin{equation}{section}
\newtheorem{theorem}{Theorem}[section]
\newtheorem{lemma}[theorem]{Lemma}
\newtheorem{remark}[theorem]{Remark}
\newtheorem{proposition}[theorem]{Proposition}
\allowdisplaybreaks

\newcommand{\ep}{\varepsilon}
\newcommand{\eps}[1]{{#1}_{\varepsilon}}

\section{Introduction}\label{intro}

Self-referred and hereditary phenomena play an important role in applied sciences,
especially that in studying evolution processes of biology. Mathematically,
these phenomena can be described by the following model: let $A: X\to\mathbb{R}$ and
$B: X\to\mathbb{R}$ be two functionals defined on a function space $X$.
Consider the equation
\begin{equation}\label{I1}
Au(x,t)=u(Bu(x,t),t),
\end{equation}
where $u=u(x,t)$, $(x,t)\in\mathbb{R}\times[0,+\infty)$ is an
unknown function satisfying some initial data at $t=0$, $A$ and $B$
are differential or/and integral operators. For example, if
\begin{equation}\label{I2}
Bu(x,t)=\int_0^tu(x,\tau)d\tau,
\end{equation}
then $B$ is called a {\it hereditary} operator. As the unknown
function $u$ in the right-hand side of the equation \eqref{I1}
depends on itself, equation \eqref{I1} may be called a
self-reference equation.

Some special cases of \eqref{I1} were originally studied by Volterra in the
20 century (see \cite{MMEP2,EP1} and references therein). It is noticeable
to say that some authors considered the variable $t$ as the complex one. In the
simple case when $B$ is an identity operator, Eder \cite{Eder} obtained the
existence, uniqueness, analyticity of solutions, and the analytic dependence
of solutions of the real-variable equation
\begin{equation*} %\label{I3}
u'(t)=u(u(t)).
\end{equation*}
Si and Cheng \cite{Si1} investigated a more general functional-differential equation
\begin{equation}\label{I4}
u'(t)=u(at+bu(t)),
\end{equation}
where $a\neq 1$ and $b\neq 0$ are complex numbers, and $u:\mathbb{C}\to \mathbb{C}$
is the unknown complex-variable function. In particular, by constructing a
convergent power series solution $v(t)$ of a companion equation of the form
$$
\beta v'(\beta t)=v'(t)[v(\beta^2 t)-a v(\beta t)+a],
$$
the authors \cite{Si1} obtained the analytic solution of \eqref{I4} which is
of the form
\[
\frac{v(\beta v^{-1}(t)) -at}{b}.
\]
As a development of \eqref{I4}, Cheng, Si, and Wang \cite{Si2} studied the equation
$$
\alpha t+\beta u'(t)=u\big(at+bu'(t)\big),
$$
where $\alpha$ and $\beta$ are complex numbers. The main results of \cite{Si2}
are the existence theorems for the analytic solutions, and an explicit solution
 via symmetric methods.

Equations of the form \eqref{I1} attract attention of many authors.
 More investigations can be found in
\cite{Stanek95,Stanek97,Stanek98,Stanek00,Stanek00.1,Stanek01,Wan-Tong02,Domoshnitsky02,Hartung05,MMEP1,Domoshnitsky06,MMEP2,EP1,pascali_ut,UL,Stanek09,TL,Bernat}, and references therein.

In recent years,  Pascali and Miranda obtained many 
results concerning the self-referred functional-differential equations
\cite{MMEP1,MMEP2,EP1,pascali_ut}. For instance, the authors in \cite{MMEP2}
studied the initial-value problem
\begin{equation}\label{I5}
\begin{gathered}
\frac{\partial}{\partial t}u(x,t)=u(\frac{1}{t}\int_0^tu(x,s)ds,t),\quad
x\in\mathbb{R},\; t\in [0,T],\\
u(x,0)=u_0(x),\quad x\in\mathbb{R}.
\end{gathered}
\end{equation}
The authors claimed that under some suitable conditions problem \eqref{I5}
has a unique bounded and continuous solution. Observe that the unknown $u$ in
the right-hand side of \eqref{I5} contains a weighted hereditary operator
$$
(Bu)(t):=\frac{1}{t}\int_0^tu(x,s)ds.
$$
Motivated by the long list of works on self-referred functional-differential
equations as mentioned above, we study the following system of two
partial-differential equations with self-reference and weighted heredity
\begin{equation}\label{I6}
\begin{gathered}
\frac{\partial}{\partial t}u(x,t)=u\Big(f\big(u(x,t)\big)
+v\big(\frac{1}{t}\int_0^tu(x,s)ds
+\varphi(u(x,t)),t\big),t\Big)
\\
\frac{\partial}{\partial t}v(x,t)
=v\Big(g\big(v(x,t)\big)+u\big(\frac{1}{t}\int_0^tv(x,s)ds+\psi(v(x,t)),t\big),t\Big),
\end{gathered}
\end{equation}
associated with the initial conditions
\begin{equation}\label{I7}
u(x, 0)=u_0(x),\quad v(x, 0)=v_0(x),
\end{equation}
where $f, g, \varphi, \psi, u_0$ and $v_0$ are given functions
satisfying some suitable conditions. This work is devoted to the uniqueness
of local solution, and the existence of a global solution of this problem.

\section{Preliminaries}

To study problem \eqref{I6}-\eqref{I7},  we reduce it to the following
system of two integral equations
\begin{equation}
\begin{gathered}\label{II.1}
u(x,t)=u_0(x)+\int_0^tu\Big(f\Big(u(x,s)\Big)
+v\Big(\frac{1}{s}\int_0^su(x,\tau)d\tau+\varphi(u(x,s)),s\Big),s\Big)ds,\\
v(x,t)=v_0(x)+\int_0^tv\Big(g\Big(v(x,s)\Big)
+u\Big(\frac{1}{s}\int_0^sv(x,\tau)d\tau+\psi(v(x,s)),s\Big),s\Big)ds.
\end{gathered}
\end{equation}

\begin{proposition}\label{prop2.1}
If problem \eqref{II.1} has a solution $(u, v)$, then the pair of functions
$(u, v)$ solves problem \eqref{I6}-\eqref{I7}.
\end{proposition}

We omit the proof of this proposition, as it is quite simple.
Therefore, we shall investigate problem \eqref{II.1} hereafter.
We now define the sequences of real
functions $\{u_n\}_{n\ge 1},\,
\{v_n\}_{n\ge 1}$ as follows:
\begin{equation} \label{II.2}
\begin{gathered}
 u_1(x,t)=u_0(x)+\int_0^tu_0\Big(f\Big(u_0(x)\Big)+v_0\Big(u_0(x)
+\varphi\big(u_0(x)\big)\Big)\Big)ds,
\\
v_1(x,t)=v_0(x)+\int_0^tv_0\Big(g\Big(v_0(x)\Big)+u_0\Big(v_0(x)
 +\psi\big(v_0(x)\big)\Big)\Big)ds,
\\
\begin{aligned}
u_{n+1}(x,t)
&=u_0(x)+\int_0^tu_n\Big(f\Big(u_n(x,s)\Big) \\
&\quad +v_n\Big(\frac{1}{s}\int_0^su_n(x,\tau)d\tau
+\varphi\big(u_n(x,s)\big),s\Big),s\Big)ds,
\end{aligned}\\
\begin{aligned}
v_{n+1}(x,t)&=v_0(x)+\int_0^tv_n\Big(g\Big(v_n(x,s)\Big) \\
&\quad +u_n\Big(\frac{1}{s}\int_0^sv_n(x,\tau)d\tau+\psi\big(v_n(x,s)\big),
 s\Big),s\Big)ds,
\end{aligned}
\end{gathered}
\end{equation}
for $x\in\mathbb{R}$ and $t> 0$.

We  should give the following additional conditions on the functions $u_0, v_0$ and
$f, g, \varphi, \psi$:
\begin{itemize}
\item[(A1)] $u_0$ and $v_0$ are bounded and Lipschitz continuous on $\mathbb{R}$.
\item[(A2)] $f, g, \varphi$ and $\psi$ are Lipschitz continuous on $\mathbb{R}$.
\end{itemize}
The functional inequalities in the next lemma are useful for proving the
main results.

\begin{lemma}\label{lemma1}
Assume that the functions $u_0, v_0$ and $ f, g, \varphi$, and $\psi$
satisfy conditions as in {\rm(A1)--(A2)}.
 For any $n\ge 1$ there exist two continuous, non-negative functions
defined on $\mathbb{R}^+$, say $M_n(t)$ and $N_n(t)$, such that the following
two inequalities hold:
\begin{gather*}
|u_{n+1}(x, t)-u_{n+1}(y, t)|\leq M_{n+1}(t)|x-y|,\quad
 n\in\mathbb{N},\; x, y\in\mathbb{R}\\
|v_{n+1}(x, t)-v_{n+1}(y, t)|\leq N_{n+1}(t)|x-y|, \quad n\in\mathbb{N},\;
x, y\in\mathbb{R}.
\end{gather*}
Moreover, there is a positive constant $T_1$ such that the non-negative function
sequences $\{M_n(t)\}_{n\ge 1}$, $\{N_n(t)\}_{n\ge 1}$ are uniformly bounded
on the interval $(0, T_1]$; i.e., there
exists a constant $G_0>0$ such that $0<M_n(t), N_n(t)\le G_0$ for every
 $t\in (0, T_1]$, and for any $n\ge 1$.
\end{lemma}

\begin{proof}
For $n=0$, we have
\begin{equation*}
|u_0(x)-u_0(y)|\leq M_0|x-y|,\quad
|v_0(x)-v_0(y)|\leq N_0|x-y|
\end{equation*}
for any $x, y\in\mathbb{R}$ and for some $M_0>0, N_0>0$.
Let $P, Q, \varpi, \sigma>0$ such that
\begin{equation}\label{II.3}
\begin{gathered}
|f(\alpha_1)-f(\alpha_2)|\leq P|\alpha_1-\alpha_2|,\quad
\alpha_1, \alpha_2\in\mathbb{R}\\
%
|g(\beta_1)-g(\beta_2)|\leq Q|\beta_1-\beta_2|,\quad \beta_1, \beta_2\in\mathbb{R}\\
%
|\varphi(\gamma_1)-\varphi(\gamma_2)|\leq \varpi |\gamma_1-\gamma_2|,\quad
 \gamma_1, \gamma_2\in\mathbb{R}\\
%
|\psi(\eta_1)-\psi(\eta_2)|\leq \sigma |\eta_1-\eta_2|, \quad
 \eta_1, \eta_2\in\mathbb{R}.
\end{gathered}
\end{equation}
For $n=1$ we have
 $$
|u_1(x,t)-u_1(y,t)|\leq M_1(t)|x-y|,
$$
where
\[
M_1(t)=M_0+t(M_0^2P+M_0^2N_0+M_0^2N_0\varpi),
\]
and
 $$|v_1(x,t)-v_1(y,t)|\leq N_1(t)|x-y|,$$ where
\[N_1(t)=N_0+t(N_0^2Q+M_0N_0^2+M_0N_0^2\sigma).\]

\noindent For $n=2$, we derive
 $$
|u_2(x,t)-u_2(y,t)|\leq M_2(t)|x-y|,
$$
where
\[
M_2(t)=M_0+\int_0^t\Big(M_1^2(s)P+N_1(s)\frac{1}{2s}\frac{d}{ds}
\Big(\int_0^sM_1(\tau)d\tau\Big)^2
+M_1^2(s)N_1(s)\varpi\Big)ds,
\]
and
 $$
|v_2(x,t)-v_2(y,t)|\leq N_2(t)|x-y|,
$$
where
\[
N_2(t)=N_0+
\int_0^t\Big(N_1^2(s)Q+M_1(s)\frac{1}{2s}\frac{d}{ds}
\Big(\int_0^sN_1(\tau)d\tau\Big)^2
+M_1(s)N_1^2(s)\sigma\Big)ds.
\]
 We can inductively prove that
\begin{equation}\label{II.4}
|u_{n+1}(x,t)-u_{n+1}(y,t)|\leq M_{n+1}(t)|x-y|,
\end{equation}
where
\[
M_{n+1}(t)=M_0+\int_0^t\Big(M_n^2(s)P+N_n(s)\frac{1}{2s}
\frac{d}{ds}\Big(\int_0^sM_n(\tau)d\tau\Big)^2\\
+M_n^2(s)N_n(s)\varpi\Big)ds,
\]
and
\begin{equation}\label{II.5}
|v_{n+1}(x,t)-v_{n+1}(y,t)|\leq N_{n+1}(t)|x-y|,
\end{equation}
where
\begin{align*}
N_{n+1}(t)=N_0+\int_0^t\Big(N_n^2(s)Q+M_n(s)\frac{1}{2s}
\frac{d}{ds}\Big(\int_0^sN_n(\tau)d\tau \Big)^2
+M_n(s)N_n^2(s)\sigma\Big)ds.
\end{align*}
Clearly, the functions $M_{n+1}(t)$ and $N_{n+1}(t)$ are
non-negative and continuous on $\mathbb{R}$. We shall prove that
each one of the function sequences $\{M_{n+1}\}_{n\ge 1}(t)$ and
$\{N_{n+1}\}_{n\ge 1}(t)$ is uniformly bounded on some $(0, T_1]$.
Indeed, by choosing constants $K_0, H_0$, and $I_0>0$ fulfilling the
following conditions
$$
N_0+K_0\leq H_0 \quad M_0+K_0\leq I_0
\quad G_0=\max\{H_0, I_0\},
$$
there exists a number $T_1>0$ such that
\begin{equation}\label{II.6}
\begin{gathered}
(M_0^2P+M_0^2N_0+M_0^2N_0\varpi)t\leq K_0,\quad \forall t\in(0,T_1]\\
(N_0^2Q+M_0N_0^2+M_0N_0^2\sigma)t\leq K_0,\quad \forall t\in(0,T_1]\\
(G_0^2P+G_0^3+G_0^3\varpi)t\leq K_0,\\
(G_0^2Q+G_0^3+G_0^3\sigma)t\leq K_0.
\end{gathered}
\end{equation}
Then
\begin{equation}\label{II.7}
\begin{gathered}
0\leq M_1(t)-M_0=(M_0^2P+M_0^2N_0+M_0^2N_0\varpi)t\leq K_0,\\
0\leq N_1(t)-N_0=(N_0^2Q+M_0N_0^2+M_0N_0^2\sigma)t\leq K_0.
\end{gathered}
\end{equation}
It follows that
\begin{equation}\label{II.8}
\begin{gathered}
0\leq M_1(t)\leq K_0+M_0\leq I_0\leq G_0,\\
0\leq N_1(t)\leq K_0+N_0\leq H_0\leq G_0.
\end{gathered}
\end{equation}
Similarly,
\begin{equation} \label{II.9}
\begin{aligned}
0\leq M_2(t)-M_0
\leq\int_0^t(G_0^2P+G_0^3+G_0^3\varpi)ds=(G_0^2P+G_0^3+G_0^3\varpi)t \leq K_0,\\
0\leq N_2(t)-N_0
\leq\int_0^t(G_0^2Q+G_0^3+G_0^3\sigma)ds=(G_0^2Q+G_0^3+G_0^3\sigma)t
\leq K_0.
\end{aligned}
\end{equation}
From these inequalities,  we have
\begin{equation}\label{II.10}
\begin{gathered}
0\leq M_2(t)\leq M_0+K_0\leq I_0\leq G_0,\\
0\leq N_2(t)\leq N_0+K_0\leq H_0\leq G_0.
\end{gathered}
\end{equation}
By induction on $n$ we obtain
\begin{equation}\label{II.11}
\begin{gathered}
0\leq M_{n+1}(t)\leq M_0+K_0\leq G_0,\\
0\leq N_{n+1}(t)\leq N_0+K_0\leq G_0,
\end{gathered}
\end{equation}
for every $t\in (0,T_1]$, $T_1>0$. The lemma is proved.
\end{proof}

We can see that Lemma \ref{lemma1} concerns the properties of the
functions $\{u_{n}(x,t)\}$ and $\{v_{n}(x,t)\}$, while 
Lemma \ref{lemma2} concerns the recursive sequences
$\{u_{n+1}(x,t)-u_n(x,t)\}$ and
$\{v_{n+1}(x,t)-v_n(x,t)\}$.

\begin{lemma}\label{lemma2}
Assume that the functions $u_0, v_0$ and $ f, g, \varphi$, and $\psi$
satisfy conditions as in {\rm(A1)--(A2)}. For any $n\ge 1$
there exist two nonnegative, continuous functions, say $A_n(t)$ and $B_n(t)$,
satisfying the following two inequalities:
\begin{gather*}
|u_{n+1}(x,t)-u_n(x,t)|\leq A_{n+1}(t),\quad x\in\mathbb{R},\; t\in\mathbb{R}^+,\\
|v_{n+1}(x,t)-v_n(x,t)|\leq B_{n+1}(t),\quad x\in\mathbb{R},\; t\in\mathbb{R}^+.
\end{gather*}
Moreover, there is a positive constant $T_2$ such that the both series with
general terms $A_n(t)$, and $B_n (t)$ are uniformly convergent on $(0, T_2]$.
\end{lemma}

\begin{proof}
We have
\begin{gather*}
|u_1(x,t)-u_0(x)|\leq t\|u_0\|_{L^\infty}:=A_1(t),\\
|v_1(x,t)-v_0(x)|\leq t\|v_0\|_{L^\infty}:=B_1(t).
\end{gather*}
Similarly,
\begin{align*}
|u_2(x,t)-u_1(x,t)|
&\leq\int_0^t\Big(A_1(s)\Big(1+M_0P+M_0N_0\varpi\Big)+M_0B_1(s)\\
&\quad +M_0N_0\frac{1}{s}\int_0^sA_1(\tau)d\tau\Big)ds:=A_2(t),
\end{align*}
and
\begin{align*}
|v_2(x,t)-v_1(x,t)|
&\leq\int_0^t\Big(B_1(s)\Big(1+N_0Q+M_0N_0\sigma\Big)+N_0A_1(s)\\
&\quad +M_0N_0\frac{1}{s}\int_0^sB_1(\tau)d\tau\Big)ds:=B_2(t).
\end{align*}
By induction on $n$, we conclude that
\begin{equation}\label{II.12}
|u_{n+1}(x,t)-u_n(x,t)|\leq A_{n+1}(t),
\end{equation}
where
\begin{align*}
A_{n+1}(t)&=\int_0^t\Big(A_n(s)\Big(1+M_{n-1}(s)P+M_{n-1}(s)N_{n-1}(s)\varpi\Big) \\
&\quad +B_n(s)M_{n-1}(s)
+M_{n-1}(s)N_{n-1}(s)\frac{1}{s}\int_0^sA_n(\tau)d\tau\Big)ds;
\end{align*}
and
\begin{equation}\label{II.13}
|v_{n+1}(x,t)-v_n(x,t)|\leq B_{n+1}(t),
\end{equation}
where
\begin{align*}
B_{n+1}(t)&=\int_0^t\Big(B_n(s)\Big(1+N_{n-1}(s)Q+M_{n-1}(s)N_{n-1}(s)\sigma\Big) \\
&\quad +A_n(s)N_{n-1}(s)
+M_{n-1}(s)N_{n-1}(s)\frac{1}{s}\int_0^sB_n(\tau)d\tau\Big)ds.
\end{align*}
For a number $h\in (0, 1/2)$, we can choose $T_2>0$ such that the following two
inequalities hold for any $t\in(0, T_2]$,
\begin{equation}\label{II.14}
\begin{gathered}
(1+G_0P+G_0+G_0^2\varpi+G_0^2)t\leq h<\frac{1}{2},\\
(1+G_0Q+G_0+G_0^2\sigma+G_0^2)t\leq h<\frac{1}{2},
\end{gathered}
\end{equation}
By \eqref{II.14} and Lemma \ref{lemma1},
\begin{equation} \label{II.15}
\begin{aligned}
0\leq A_{n+1}(t)
&\leq(1+G_0P+G_0^2\varpi+G_0^2)t\|A_n\|_{L^\infty}+G_0t\|B_n\|_{L^\infty} \\
&\leq h(\|A_n\|_{L^\infty}+\|B_n\|_{L^\infty}),
\end{aligned}
\end{equation}
and
\begin{equation} \label{II.16}
\begin{aligned}
0\leq B_{n+1}(t)
&\leq(1+G_0Q+G_0^2\sigma+G_0^2)t\|B_n\|_{L^\infty}+G_0t\|A_n\|_{L^\infty} \\
&\leq h(\|A_n\|_{L^\infty}+\|B_n\|_{L^\infty}).
\end{aligned}
\end{equation}
By induction on $n$, we obtain
\[
0\leq A_{n+1}(t), B_{n+1}(t)\leq
h^n\Big(\|A_1\|_\infty+\|B_1\|_\infty\Big),
\]
for $t\in(0, T_2]$.
Therefore, the series with general terms $A_n(.)$ and $B_n(.)$ uniformly
converge on the interval $(0, T_2]$. Lemma \ref{lemma2} is proved.
\end{proof}

\begin{remark} \label{rmk2.4} \rm
It is easy to prove inductively that
\[
|u_{n+1}(x,t)|\le e^t\|u_0\|_{\infty},\quad |v_{n+1}(x,t)|\le e^t\|v_0\|_{\infty}.
\]
If we consider $T$ such that $0<T\leq\min\{T_1, T_2\}$, the
functions $u_{n}(x, t),\; v_n(x, t)$ are bounded uniformly with
respect to variable $x\in\mathbb{R}$, for $t\in (0,T]$. On the other
hand, due to \eqref{II.8} and Lemma \ref{lemma1}, the functions
$u_{n}(x, t),\; v_n(x, t)$ are uniformly Lipschitz continuous with
respect to each of the variables $x\in\mathbb{R}$ and
 $t\in (0, T]$.
\end{remark}

For serving the existence of a global solution to problem \eqref{II.1},
we propose some assumptions on the functions $u_0, v_0$ and $f, g, \varphi, \psi$,
that are different from (A1)--(A2) in Lemma \ref{lemma2}.
Namely, assume that
\begin{itemize}
\item[(B1)] $u_0$ and $v_0$ are non-negative, non-decreasing, bounded and
 lower semi-con\-tinuous on $\mathbb{R}$.
\item[(B2)] $f, g, \varphi$ and $\psi$ are non-decreasing and lower
 semi-continuous.
\end{itemize}

\begin{lemma}\label{lemma4}
Suppose that the functions $u_0, v_0$ and $f, g, \varphi$ and $\psi$
fulfill the conditions as in {\rm (B1)--(B2)}. Then the functions
$\{u_n(x,t)\}_{n\geq 1}$ and $\{v_n(x,t)\}_{n\geq 1}$ possess the
following properties:
\begin{itemize}
\item[(C1)] $u_n$ and $v_n$ are non-negative.

\item[(C2)] $u_n $ and $v_n $ are non-decreasing with
respect to each one of variables $x\in\mathbb{R},\, t\in (0,T];$
more precisely $u_{n+1}\geq u_n, v_{n+1}\geq v_n$.

\item[(C3)] $u_n $ and $v_n $ are lower
semi-continuous with respect to $x$, for every $t\in(0,+\infty)$.

\item[(C4)] $u_n$ and $v_n$ are Lipschitz continuous with respect to
$t$, uniformly bounded with respect to $x\in\mathbb{R}$.
\end{itemize}
\end{lemma}

\begin{proof}
We have
\begin{equation}\label{III.1}
\begin{gathered}
u_1(x,t)\geq u_0(x)\geq 0,\quad \forall x\in\mathbb{R},\, t\in (0,+\infty),\\
v_1(x,t)\geq v_0(x)\geq 0,\quad \forall x\in\mathbb{R},\, t\in (0,+\infty).
\end{gathered}
\end{equation}
For $t_1, t_2\in (0,+\infty)$, $t_1<t_2$, and for $x\in\mathbb{R}$, we have
\begin{equation} \label{III.2}
\begin{aligned}
u_1(x,t_2)
&=u_0(x)+\int_0^{t_2}u_0\Big(f\Big(u_0(x)\Big)
 +v_0\Big(u_0(x)+\varphi\Big(u_0(x)\Big)\Big)ds\\
&\geq u_0(x)+\int_0^{t_1}u_0\Big(f\Big(u_0(x)\Big)
+v_0\Big(u_0(x)+\varphi\Big(u_0(x)\Big)\Big)\Big)ds\\
&=u_1(x,t_1),
\end{aligned}
\end{equation}
\begin{equation} \label{III.2a}
\begin{aligned}
v_1(x,t_2)
&=v_0(x)+\int_0^{t_2}v_0\Big(g\Big(v_0(x)\Big)+u_0\Big(v_0(x)
+\psi\Big(v_0(x)\Big)\Big)\Big)ds\\
&\geq v_0(x)+\int_0^{t_1}v_0\Big(g\Big(v_0(x)\Big)+u_0\Big(v_0(x)
+\psi\Big(v_0(x)\Big)\Big)\Big)ds\\
&=v_1(x,t_1).
\end{aligned}
\end{equation}
Similarly, for all $x_1, x_2\in\mathbb{R}$, $x_1<x_2$, for all
$t\in(0,+\infty)$, we derive
\begin{equation}
\begin{aligned}
u_1(x_1,t)
&=u_0(x_1)+\int_0^tu_0\Big(f\big(u_0(x_1)\big)+v_0\big(u_0(x_1)
+\varphi\big(u_0(x_1)\big)\big)\Big)ds \\
&\leq u_0(x_2)+\int_0^tu_0\Big(f\big(u_0(x_2)\big)
 +v_0\big(u_0(x_2)+\varphi\big(u_0(x_2)\big)\big)\Big)ds\\
&=u_1(x_2,t),
\end{aligned}\label{III.3}
\end{equation}
\begin{equation}
\begin{aligned}\
v_1(x_1,t)&=v_0(x_1)+\int_0^tv_0\Big(g\big(v_0(x_1)\big)
+u_0\big(v_0(x_1)+\psi\big(v_0(x_1)\big)\big)\Big)ds \\
&\leq v_0(x_2)+\int_0^tv_0\Big(g\big(v_0(x_2)\big)
+u_0\big(v_0(x_2)+\psi\big(v_0(x_2)\big)\big)\Big)ds\\
&=v_1(x_2,t).
\end{aligned} \label{III.3a}
\end{equation}

Using \eqref{III.2}--\eqref{III.3a}, we can prove inductively that
\begin{equation}\label{III.4}
\begin{gathered}
u_n(x,t_2)\geq u_n(x,t_1),\quad\forall x\in\mathbb{R},\;t_2>t_1,\\
u_n(x_2,t)\geq u_n(x_1,t),\quad \forall t\in(0,+\infty),\;x_2>x_1,\\
v_n(x,t_2)\geq v_n(x,t_1),\quad \forall x\in\mathbb{R},\; t_2>t_1,\\
v_n(x_2,t)\geq v_n(x_1,t),\quad \forall t\in(0,+\infty),\;x_2>x_1.
\end{gathered}
\end{equation}
Also, we can prove that (see also remark \ref{rmk2.4})
\begin{equation} \label{III.5}
\begin{aligned}
0\leq u_n(x,t)\leq u_{n+1}(x,t)\leq e^T\|u_0\|_{L^\infty}, \\
0\leq v_n(x,t)\leq v_{n+1}(x,t)\leq e^T\|v_0\|_{L^\infty},
\end{aligned}
\end{equation}
for all $x\in\mathbb{R}$, $t\in(0,T]$ and $n\in \mathbb{N}$.
On the other hand,
\begin{gather}
|u_{n+1}(x,t_1)-u_{n+1}(x,t_2) \leq
\big|\int_{t_1}^{t_2}\|u_0\|_{L^\infty}e^Tds \big|
\leq \|u_0\|_{L^\infty}e^T|t_2-t_1|,\label{III.6}\\
|v_{n+1}(x,t_1)-v_{n+1}(x,t_2)|
\leq \big|\int_{t_1}^{t_2}\|v_0\|_{L^\infty}e^Tds\big|
\leq\|v_0\|_{L^\infty}e^T|t_2-t_1|.\label{III.7}
\end{gather}
Relations \eqref{III.6} and \eqref{III.7} ensure that $u_n$ and
$v_n$ satisfy $(C_4)$. Since the sequences $(u_n)$ and $(v_n)$ are
non decreasing, above and upper bounded, there exist the limits
\begin{equation} \label{III.8}
u_\infty(x,t)=\lim_nu_n(x,t), \quad
v_\infty(x,t)=\lim_nv_n(x,t).
\end{equation}
Since  $u_0, v_0, f, g, \varphi$ and $\psi$ are lower
semi-continuous and non-decreasing, the functions
$f(u_0), g(v_0),
v_0\big(u_0+\varphi(u_0)\big)$, and
$u_0\big(v_0+\psi(v_0)\big)$ are lower semi-continuous and
non-decreasing (see \cite[Lemma 3]{TL}). Hence, 
$u_0\big(f(u_0)+v_0\big(u_0 +\varphi(u_0)\big)\big)$, and
$v_0\big(g(v_0)+u_0\big(v_0 +\psi(v_0)\big)\big)$ are lower semi-continuous and
non-decreasing, too. Thus, the lower semi-continuity and the decrease of $u_1(x, t)$ 
and $v_1(x,t)$ are established. By induction on $n$,
we can conclude that $u_n(x,t)$ and $v_n(x,t)$ are lower semi-continuous and
non-decreasing. Lemma \ref{lemma4} is proved.
\end{proof}

\section{Main results}

\begin{theorem}[Uniqueness of local solutions]\label{theorem1}
Assume that the functions $f$, $g$, $\varphi$, $\psi$, $u_0$, and $v_0$ satisfy
{\rm (A1)--(A2)}. Then there exists a positive constant $T_\star$ such
that  \eqref{II.1} has a unique solution on $R \times (0, T_*]$ denoted
 by $\{u_*, v_*\}$. Moreover, the functions
$u_\infty,\, v_\infty$ are Lipschitz continuous and bounded with
respect to each of the variables $x\in\mathbb{R}$, and $ t\in(0, T_\star]$.
\end{theorem}

\begin{theorem}[Existence of global solutions]\label{theorem2}
Assume that $f$, $g$, $\varphi$, $\psi$, $u_0$ and $v_0$ satisfy
{\rm (B1)--(B2)}. There exist two functions $u_\infty, v_\infty:
\mathbb{R}\times (0, +\infty)\to\mathbb{R}$ satisfying
\eqref{II.1} for $t\in(0, +\infty)$. Moreover, these solutions have
the properties similar to those of $\{u_n(x,t)\}_{n\geq 1}$
and $\{v_n(x,t)\}_{n\geq 1}$ as in Lemma \ref{lemma4}; namely,
 the functions $u_\infty, v_\infty$ possess the properties
 {\rm (C1)--(C4)}.
\end{theorem}

\begin{proof}[Proof of Theorem \ref{theorem1}]
Write $T_*:=\min\{T_1, T_2\}$. By Lemmas \ref{lemma1}, and
\ref{lemma2}, the limits $u_{\infty}(x, t)$, $v_{\infty}(x, t)$ of the
sequences $\{u_n(x,t)\}_{n\ge 1}$, $\{v_n(x, t)\}_{n\ge 1}$ are bounded on
$\mathbb{R}\times (0,T_*]$, Lipschitz continuous with respect to
each of variables, and satisfy problem \eqref{II.1}.

Now, suppose that $(u_\star,v_\star)$ is another solution of \eqref{II.1} on
$\mathbb{R}\times (0,T_*]$ with the same given data. We have
% \label{III.9}
\begin{align*}
&\Big|u_\star\Big(f(u_\star(x,t))+v_\star\Big(\frac{1}{t}\int_0^tu_\star(x,s)ds
 +\varphi(u_\star(x,t)),t\Big),t\Big) \\
&-u_\infty\Big(f(u_\infty(x,t))+v_\infty\Big(\frac{1}{t}\int_0^tu_\infty(x,s)ds
 +\varphi(u_\infty(x,t)),t\Big),t\Big)\Big|  \\
&\leq\|u_\star-u_\infty\|_{L^\infty}+\Big|u_\infty\Big(f(u_\star(x,t))
+v_\star\Big(\frac{1}{t}\int_0^tu_\star(x,s)ds
+\varphi(u_\star(x,t)),t\Big),t\Big) \\
&\quad-u_\infty\Big(f(u_\infty(x,t))+v_\infty\Big(\frac{1}{t}\int_0^tu_\infty(x,s)ds
+\varphi(u_\infty(x,t)),t\Big),t\Big)\Big|
 \\&\leq(1+M_\infty(t)P+M_\infty(t)N_\infty(t)
+M_\infty(t)N_\infty(t)\varpi)\|u_\star-u_\infty\|_{L^\infty} \\
&\quad+M_\infty(t)\|v_\star-v_\infty\|_{L^\infty}.
\end{align*}
From the above inequality and Lemma \eqref{lemma1} we obtain
\begin{equation} \label{III.10}
\begin{split}
&|u_\star(x,t)-u_\infty(x,t)|  \\
&\leq \Big(1+G_0P+G_0^2+G_0^2\varpi\Big)t\|u_\star
 -u_\infty\|_{L^\infty}+G_0t\|v_\star-v_\infty\|_{L^\infty}.
\end{split}
\end{equation}
In addition, we have
\begin{equation} \label{III.11}
\begin{aligned}
&\Big|v_\star\Big(g(u_\star,v_\star)+u_\star\Big(\frac{1}{t}\int_0^tv_\star(x,s)ds
 +\psi(v_\star(x,t)),t\Big),t\Big)\\
&- v_\infty\Big(g(u_\infty,v_\infty)+u_\infty\Big(\frac{1}{t}\int_0^tv_\infty(x,s)ds
 +\psi(v_\infty(x,t)),t\Big),t\Big)\Big| \\
&\leq\Big(1+N_\infty(t)Q+M_\infty(t)N_\infty(t)\sigma\Big)\|v_\star
-v_\infty\|_{L^\infty}
+N_\infty(t)\|u_\star-u_\infty\|_{L^\infty}.
\end{aligned}
\end{equation}
By \eqref{III.11} and Lemma \eqref{lemma1}, we find
\begin{equation} \label{III.12}
\begin{aligned}
&|v_\star(x,t)-v_\infty(x,t)| \\
&\leq\Big(1+G_0Q+G_0^2+G_0^2\sigma\Big)t\|v_\star-v_\infty\|_{L^\infty}
+G_0t\|u_\star-u_\infty\|_{L^\infty}.
\end{aligned}
\end{equation}
Combining \eqref{III.10} and \eqref{III.12}, we obtain
\begin{equation}\label{III.13}
\begin{aligned}
&|u_\star(x,t)-u_\infty(x,t)|\\
&\leq\Big(1+G_0P+G_0+G_0^2+G_0^2\varpi\Big)t
\max\{\|u_\star-u_\infty\|_{L^\infty},\|v_\star-v_\infty\|_{L^\infty}\},
\end{aligned}
\end{equation}
and
\begin{equation} \label{III.14}
\begin{aligned}
&|v_\star(x,t)-v_\infty(x,t)|\\
&\leq\Big(1+G_0Q+G_0+G_0^2+G_0^2\sigma\Big)t
\max\{\|u_\star-u_\infty\|_{L^\infty},\|v_\star-v_\infty\|_{L^\infty}\}.
\end{aligned}
\end{equation}
Taking account of \eqref{II.14}, \eqref{III.13} and \eqref{III.14}, we have
\begin{equation} \label{III.15}
\begin{gathered}
|u_\star(x,t)-u_\infty(x,t)|\leq h\max\{\|u_\star
 -u_\infty\|_{L^\infty},\|v_\star-v_\infty\|_{L^\infty}\}, \\
|v_\star(x,t)-v_\infty(x,t)|\leq
h\max\{\|u_\star-u_\infty\|_{L^\infty},\|v_\star-v_\infty\|_{L^\infty}\},
\end{gathered}
\end{equation}
for all $t\in(0,T_0]$, $x\in\mathbb{R}$. Finally, we conclude that
\begin{equation*}
\max\{\|u_\star-u_\infty\|_{L^\infty},\|v_\star-v_\infty\|_{L^\infty}\}\leq
h\max\{\|u_\star-u_\infty\|_{L^\infty},\|v_\star-v_\infty\|_{L^\infty}\}.
\end{equation*}
The last inequality  ensures the uniqueness of the solution. Theorem
\ref{theorem1} is proved.
\end{proof}

\begin{proof}[Proof of Theorem \ref{theorem2}]
Thanks to \eqref{III.4} and \eqref{III.5}, the following two limits exit:
\begin{equation} \label{III.17}
u_\infty(x,t)=\sup_nu_n(x,t), \quad
v_\infty(x,t)=\sup_nv_n(x,t).
\end{equation}
We shall prove that $u_\infty(x,t), v_\infty(x,t)$ satisfy
 \eqref{II.1}. From \eqref{III.17} we have
\begin{equation} \label{III.18}
\begin{aligned}
&u_{n+1}(x,t)-u_0(x) \\
&=\int_0^tu_n\Big(f\Big(u_n(x,s)\Big)+v_n
\Big(\frac{1}{s}\int_0^su_n(x,\tau)d\tau+\varphi\big(u_n(x,s)\big),s\Big),s\Big)ds \\
&\leq\int_0^tu_\infty\Big(f\Big(u_\infty(x,s)\Big)+v_\infty\Big(\frac{1}{s}\int_0^su_\infty(x,\tau)d\tau+\varphi\big(u_\infty(x,s)\big),s\Big),s\Big)ds,
\end{aligned}
\end{equation}
and
\begin{equation} \label{III.19}
\begin{aligned}
&v_{n+1}(x,t)-v_0(x) \\
&=\int_0^tv_n\Big(g\Big(v_n(x,s)\Big)+v_n
\Big(\frac{1}{s}\int_0^sv_n(x,\tau)d\tau+\psi\big(v_n(x,s)\big),s\Big),s\Big)ds \\
&\leq\int_0^tv_\infty\Big(g\Big(v_\infty(x,s)\Big)+u_\infty\Big(\frac{1}{s}\int_0^sv_\infty(x,\tau)d\tau+\psi\big(v_\infty(x,s)\big),s\Big),s\Big)ds.
\end{aligned}
\end{equation}
As ${u_n(x,t)}$, and ${v_n(x,t)}$ are non-decreasing, we have
\begin{align}\label{III.20}
&u_{n+p}\Big(f\Big(u_{n+p}(x,t)\Big)+v_{n+p}\Big(\frac{1}{t}\int_0^tu_{n+p}(x,s)ds+\varphi\big(u_{n+p}(x,t)\big),t\Big),t\Big) \\
&\geq
u_{n}\Big(f\Big(u_{n+p}(x,t)\Big)+v_{n+p}\Big(\frac{1}{t}\int_0^tu_{n+p}(x,s)ds+\varphi\big(u_{n+p}(x,t)\big),t\Big),t\Big),
\end{align}
and
\begin{equation} \label{III.21}
\begin{aligned}
&v_{n+p}\Big(g\Big(v_{n+p}(x,t)\Big)+u_{n+p}\Big(\frac{1}{t}\int_0^tv_{n+p}(x,s)ds
 +\psi\big(v_{n+p}(x,t)\big),t\Big),t\Big) \\
&\geq v_{n}\Big(g\Big(v_{n+p}(x,t)\Big)+u_{n+p}\Big(\frac{1}{t}
\int_0^tv_{n+p}(x,s)ds+\psi\big(v_{n+p}(x,t)\big),t\Big),t\Big).
\end{aligned}
\end{equation}
From \eqref{III.20} and \eqref{III.21} we deduce
\begin{equation} \label{III.22}
\begin{aligned}
&\lim_{p\to\infty}\int_0^tu_{n+p}\Big(f\Big(u_{n+p}(x, s)\Big)\\
&\quad +v_{n+p}\Big(\frac{1}{s}\int_0^su_{n+p}(x,\tau)d\tau 
+\varphi\big(u_{n+p}(x,s)\big),s\Big),s\Big)ds \\
&\geq\int_0^tu_n\Big(f\Big(u_\infty(x,s)\Big)
+v_\infty\Big(\frac{1}{s}\int_0^su_\infty(x,\tau)d\tau
+\varphi\big(u_\infty(x,s)\big),s\Big),s\Big)ds,
\end{aligned}
\end{equation}
and
\begin{equation} \label{III.23}
\begin{aligned}
&\lim_{p\to\infty}\int_0^tv_{n+p}\Big(g\Big(v_{n+p}(x,s)\Big)\\
&\quad +u_{n+p}\Big(\frac{1}{s}\int_0^sv_{n+p}(x,\tau)d\tau 
 +\psi\big(v_{n+p}(x,s)\big),s\Big),s\Big)ds \\
&\geq\int_0^tv_n\Big(g\Big(v_\infty(x,s)\Big)+u_\infty\Big(\frac{1}{s}
\int_0^sv_\infty(x,\tau)d\tau+\psi\big(v_\infty(x,s)\big),s\Big),s\Big)ds.
\end{aligned}
\end{equation}
Hence,
\begin{equation} \label{III.24}
\begin{aligned}
&\lim_p[u_{n+p+1}(x,t)-u_0(x)]\\
&=\lim_p\int_0^tu_{n+p}\Big(f\Big(u_{n+p}(x, s)\Big) \\
&\quad +v_{n+p}\Big(\frac{1}{s}\int_0^su_{n+p}(x,\tau)d\tau
 +\varphi\big(u_{n+p}(x,s)\big),s\Big),s\Big)ds \\
&\geq\int_0^tu_n\Big(f\Big(u_\infty(x,s)\Big)
+v_\infty\Big(\frac{1}{s}\int_0^su_\infty(x,\tau)d\tau
 +\varphi\big(u_\infty(x,s)\big),s\Big),s\Big)ds,
\end{aligned}
\end{equation}
and
\begin{equation}  \label{III.25}
\begin{aligned}
&\lim_p[v_{n+p+1}(x,t)-v_0(x)]\\
&=\lim_p\int_0^tv_{n+p}\Big(g\Big(v_{n+p}(x,s)\Big) \\
&\quad +u_{n+p}\Big(\frac{1}{s}\int_0^sv_{n+p}(x,\tau)d\tau
 +\psi\big(v_{n+p}(x,s)\big),s\Big),s\Big)ds \\
&\geq\int_0^tv_n\Big(g\Big(v_\infty(x,s)\Big)
+u_\infty\Big(\frac{1}{s}\int_0^sv_\infty(x,\tau)d\tau
+\psi\big(v_\infty(x,s)\big),s\Big),s\Big)ds.
\end{aligned}
\end{equation}
By \eqref{III.24}-\eqref{III.25} we find that
\begin{equation} \label{III.26}
\begin{aligned}
&u_\infty(x,t)-u_0(x)\geq\int_0^tu_\infty\Big(f\Big(u_\infty(x,s)\Big) \\
&\quad +v_\infty\Big(\frac{1}{s}\int_0^su_\infty(x,\tau)d\tau
+\varphi\big(u_\infty(x,s)\big),s\Big),s\Big)ds,
\end{aligned}
\end{equation}
and
\begin{equation} \label{III.27}
\begin{aligned}
&v_\infty(x,t)-v_0(x)\geq\int_0^tv_\infty\Big(g\Big(v_\infty(x,s)\Big) \\
&\quad +u_\infty\Big(\frac{1}{s}\int_0^sv_\infty(x,\tau)d\tau
 +\psi\big(v_\infty(x,s)\big),s\Big),s\Big)ds.
\end{aligned}
\end{equation}
Combining \eqref{III.18}-\eqref{III.19} and
\eqref{III.26}-\eqref{III.27} we obtain
\begin{equation} \label{III.28}
\begin{aligned}
u_\infty(x,t)-u_0(x)
&=\int_0^tu_\infty\Big(f\Big(u_\infty(x,s)\Big) \\
&\quad +v_\infty\Big(\frac{1}{s}\int_0^su_\infty(x,\tau)d\tau
 +\varphi\big(u_\infty(x,s)\big),s\Big),s\Big)ds,
\end{aligned}
\end{equation}
and
\begin{equation} \label{III.29}
\begin{aligned}
v_\infty(x,t)-v_0(x)
&=\int_0^tv_\infty\Big(v_\infty(x,s)\Big) \\
&\quad +u_\infty\Big(\frac{1}{s}\int_0^sv_\infty(x,\tau)d\tau
+\psi\big(v_\infty(x,s)\big),s\Big),s\Big)ds.
\end{aligned}
\end{equation}
The above equalities imply that $(u_\infty, v_\infty)$ is a solution of
\eqref{II.1}.

On the other hand, it is easily seen that $u_\infty, v_\infty$ are
Lipschitz continuous in $t$ on $(0,+\infty)$. The proof  is complete.
\end{proof}

\section{Illustrative Example}

Consider the initial-value problem for a system of
integro-differential equations \eqref{I6}-\eqref{I7} with the
following data:
\begin{gather*}
u_0(x) =\begin{cases}
 1 - |x| &\text{if }  |x|\leq 1 \\
0 &\text{otherwise}
\end{cases}\\
v_0(x)=1 \quad\text{for all } x\in\mathbb{R},\\
f(u)=u,\quad  g(v)=v, \quad \varphi(u)=\psi(v)=0.
\end{gather*}
We compute the successive approximations as follows:
\begin{equation}\label{IV.1}
\begin{gathered}
\begin{aligned}
u_1(x,t)&=u_0(x)+\int_0^tu_0\Big(f(u_0(x))+v_0(u_0(x)+\varphi(u_0(x)))\Big)ds\\
&=u_0(x)+\int_0^tu_0(u_0(x)+1)ds
=u_0(x)+\int_0^t0ds=u_0(x), 
\end{aligned}
\\
\begin{aligned}
v_1(x,t)&=v_0(x)+\int_0^tv_0\Big(g(v_0(x))+u_0(v_0(x)+\psi(v_0(x)))\Big)ds\\
&=1+\int_0^t1ds=1+t.
\end{aligned}
\end{gathered}
\end{equation}
Similarly,
$u_2(x,t)=u_0(x)$, $v_2(x,t)=1+t+(t^2/2)$.
Suppose that
\begin{equation}\label{IV.4}
u_n(x,t)=u_0(x),\quad v_n(x,t)=\sum_{i=0}^n\frac{t^i}{i!}.
\end{equation}
We can prove inductively that
\[
u_{n+1}(x,t)=u_0(x),\quad v_{n+1}(x,t)=\sum_{i=0}^{n+1}\frac{t^i}{i!}.
\]
Tending $n$ to infinity we obtain
\begin{equation}\label{IV.7}
u_\star(x,t)=u_0(x),\quad v_\star(x,t)=e^t.
\end{equation}
In fact, we can choose $u_0(x)$ as a nonnegative, Lipschitz
continuous function having a compact support, and $v_0(x) =c $\ as a
constant function. Due to the symmetry of the system, the functions
$u_0$ and $v_0$ are interchangeable.


\subsection*{Concluding remarks}
 Mathematically, one can provide acceptable assumptions on equations, and add suitable
restrictions on initial data of problems so that the solution exists uniquely.
 Therefore, both the existence and uniqueness of solutions of
self-referred and heredity problems, in general, remain considerable
challenges to attempts at generalization, namely (see also
\cite{Eder,MMEP1,MMEP2,EP1,pascali_ut}),
\begin{enumerate}
\item The uniqueness/non-uniqueness of global solutions, with also
relaxed condition on data.
\item Structure of the solution set.
\item Numerical solution for the above mentioned system.
\end{enumerate}


\subsection*{Acknowledgements} This work is partially supported by the
Vietnam National Foundation for Science and Technology Development
(NAFOSTED).

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\end{thebibliography}

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