\documentclass[reqno]{amsart}
\usepackage{hyperref}

\AtBeginDocument{{\noindent\small
\emph{Electronic Journal of Differential Equations},
Vol. 2011 (2011), No. 91, pp. 1--11.\newline
ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu
\newline ftp ejde.math.txstate.edu}
\thanks{\copyright 2011 Texas State University - San Marcos.}
\vspace{9mm}}

\begin{document}
\title[\hfilneg EJDE-2011/91\hfil Existence of three solutions]
{Existence of three solutions for a Kirchhoff-type
boundary-value problem}

\author[S. Heidarkhani, G. A. Afrouzi,  D. O'Regan \hfil EJDE-2011/91\hfilneg]
{Shapour Heidarkhani, Ghasem Alizadeh Afrouzi, Donal  O'Regan}  % in alphabetical order

\address{Shapour Heidarkhani \newline
Department of Mathematics,
Faculty of Sciences, Razi University,
67149 Kermanshah, Iran}
\email{s.heidarkhani@razi.ac.ir}

\address{Ghasem Alizadeh Afrouzi \newline
Department of Mathematics, Faculty of Basic Sciences,
University of Mazandaran, 47416-1467 Babolsar, Iran}
\email{afrouzi@umz.ac.ir}

\address{Donal O'Regan \newline
Department of Mathematics, National University of Ireland,
Galway, Ireland}
\email{donal.oregan@nuigalway.ie}

\thanks{Submitted April 26, 2011. Published July 6, 2011.}
\subjclass[2000]{35J20, 35J25, 35J60}
\keywords{Kirchhoff-type problem; multiple solutions; critical point}

\begin{abstract}
 In this note, we establish the existence of two intervals of
 positive real parameters $\lambda$ for which the boundary-value
 problem of Kirchhoff-type
 \begin{gather*}
 -K\big(\int_{a}^b |u'(x)|^2dx\big)u''=\lambda f(x,u),\\
 u(a)=u(b)=0
 \end{gather*}
 admits three weak solutions whose norms are
 uniformly bounded with respect to $\lambda$ belonging to one of the
 two intervals. Our main tool is a three critical point theorem by
 Bonanno.
\end{abstract}

\maketitle
\numberwithin{equation}{section}
\newtheorem{theorem}{Theorem}[section]
\newtheorem{corollary}[theorem]{Corollary}
\newtheorem{example}[theorem]{Example}
\allowdisplaybreaks

\section{Introduction}

 In the literature many results focus on the
existence of multiple solutions to boundary-value problems.  For
example, certain chemical reactions in tubular reactors can be
mathematically described by a nonlinear two-point boundary-value
problem and one is interested if multiple steady-states exist.
For a recent treatment of chemical reactor theory
and multiple solutions see \cite[section 7]{ATT} and the
references therein.

 Bonanno in \cite{B} established the existence of two intervals of
positive real parameters $\lambda$ for which the functional
$\Phi-\lambda \Psi$ has three critical points whose norms are
uniformly bounded in respect to $\lambda$ belonging to one of the
two intervals and he obtained multiplicity results for a two point
boundary-value problem. In the present paper as an
application, we shall illustrate these results for a Kirchhoff-type
problem.

Problems of Kirchhoff-type have been widely investigated. We refer
the reader to the papers \cite{ACM,CL,HZ,M,MZ,PZ,ZP} and the
references therein.
Ricceri \cite{R2} established  the existence of at least three weak
solutions to a class of Kirchhoff-type doubly eigenvalue boundary
value problem using \cite[Theorem 2]{R1}.

Consider the Kirchhoff-type problem
\begin{equation} \label{e1}
\begin{gathered}
-K\big(\int_{a}^b |u'(x)|^2dx\big)u''=\lambda f(x,u),\\
u(a)=u(b)=0
\end{gathered}
\end{equation}
where $K:[0,+\infty[\to \mathbb{R}$ is a continuous function,
$f :[a,b]\times \mathbb{R}\to \mathbb{R}$ is a
Carath\'eodory function and $\lambda>0$.

 In the present paper, our approach is based on a three critical points
theorem proved in \cite{B}, which is recalled in the next section
for the reader's convenience (Theorem \ref{thmA}). Our main result is
Theorem \ref{thm1} which, under suitable assumptions, ensures the existence
of two intervals $\Lambda_1$ and $\Lambda_2$ such that, for each
$\lambda\in \Lambda_1\cup \Lambda_2$, the problem \eqref{e1} admits at
least three classical solutions whose norms are uniformly bounded
in respect to $\lambda\in \Lambda_2$.

 Let $X$  the the Sobolev space
$H^{1}_{0}([a,b])$ with the  norm
$$
\| u\|
=\Big(\int_{a}^b (|u'(x)|^2)dx \Big)^{1/2}.
$$
We say that $u$ is a weak solution to \eqref{e1} if $u\in
X$ and
$$
K\big(\int_{a}^b |u'(x)|^2dx\big)\int_{a}^b
u'(x) v'(x)dx-\lambda\int_{a}^b f(x,u(x))v(x)dx=0
$$
for every $v\in X$.

For other basic notations and definitions, we refer the reader to
 \cite{BMV,GR,KRV,Z}.

\section{Results}

For the reader's convenience, dirst we here recall
\cite[Theorem 2.1]{B}.

\begin{theorem} \label{thmA}
 Let $X$ be a separable and reflexive real
Banach space, $ \Phi:X \to \mathbb{R}$ a nonnegative
continuously G\^{a}teaux differentiable and sequentially weakly
lower semicontinuous functional whose G\^{a}teaux derivative
admits a continuous inverse on $X^{*}$, $J:X\to \mathbb{R}$
a continuously  G\^{a}teaux differentiable functional whose
 G\^{a}teaux derivative is compact. Assume that there
 exists $x_{0}\in X$ such that $\Phi(x_{0})=J(x_{0})=0$ and that
$$
\lim_{\|x\| \to +\infty} (\Phi(x)-\lambda J(x))=+\infty \quad
\text{for all }  \lambda\in[0,+\infty[.
$$
Further, assume that there are $r>0$, $x_1\in X$ such
that $ r <\Phi(x_1)$ and
$$
\sup\nolimits_{x\in\overline{\Phi^{-1}(]-\infty,r[)}^{w}}J(x) <
\frac{r}{r+\Phi(x_1)}J(x_1);
$$
here $\overline{\Phi^{-1}(]-\infty,r[)}^{w}$
denotes the closure of
$\Phi^{-1}(]-\infty,r[)$ in the weak topology (in particular
note $J(x_1) \geq 0$ since
$x_0 \in \overline{\Phi^{-1}(]-\infty,r[)}^{w}$
(note $J(x_0)=0$) so
$\sup_{x\in\overline{\Phi^{-1}(]-\infty,r[)}^{w}}J(x) \geq 0$).
Then, for each
$$
\lambda\in \Lambda_1=
]\frac{\Phi(x_1)}{J(x_1)-\sup_{x\in\overline{\Phi^{-1}
(]-\infty,r[)}^{w}}J(x)},
\frac{r}{\sup_{x\in\overline{\Phi^{-1}(]-\infty,r[)}^{w}}J(x)}[,
$$
the equation
\begin{equation} \label{e2}
\Phi'(u)+\lambda J'(u)=0
\end{equation}
has at least three solutions in $X$ and, moreover, for each $\eta>1$,
there exist an open interval
$$
\Lambda_2\subseteq[ 0,\frac{\eta r}{r
\frac{J(x_1)}{\Phi(x_1)}-
\sup_{x\in\overline{\Phi^{-1}(-\infty,r[)}^{w}}J(x)}]
$$
and a positive real number $\sigma$ such that, for each
$\lambda\in\Lambda_2$, the equation \eqref{e3} has at least three
solutions in $X$ whose norms are less than $\sigma$.
\end{theorem}

 Let $K:[0,+\infty[\to \mathbb{R}$ be a continuous function such
that there exists a positive number $m$ with $K(t)\geq m$
for all $t\geq 0$,
and let $f:[a,b]\times \mathbb{R}\to \mathbb{R}$ be a
Carath\'eodory function such that
 $\sup_{|\xi|\leq s}|f(.,\xi)|\in L^{1}(a,b)$ for all $s>0$.
Corresponding to $K$ and $f$ we introduce the functions
$\tilde{K}:[0,+\infty[\to \mathbb{R}$ and
$F:[a,b]\times \mathbb{R}\to \mathbb{R}$, respectively as
follows
\begin{equation} \label{e3}
\tilde{K}(t)=\int_{0}^{t}K(s)ds\quad
\text{for all }  t\geq 0
\end{equation}
and
\begin{equation} \label{e4}
F(x,t)=\int_{0}^{t}f(x,s)ds\quad  \text{for all }
 (x,t)\in [a,b]\times \mathbb{R}.
\end{equation}
 Now, we state our main result.

\begin{theorem} \label{thm1}
Assume that there exist positive constants $r$ and $\theta$,
and a function $w\in X$ such that:
\begin{itemize}
\item[(i)]
$\tilde{K}(\|w\|^2)>2r$,
\item[(ii)]
$$
\int_{a}^b \sup\nolimits_{t\in[-\sqrt{\frac{r(b-a)}{2m}},
\sqrt{\frac{r(b-a)}{2m}}]}F(x,t)dx
< r\frac{\int_a^b F(x,w(x))dx}{r+ \frac{1}{2}\,
\tilde{K}(\|w\|^2)},
$$
\item[(iii)]
 $\frac{(b-a)^2}{2m}\limsup_{|t|\to
+\infty}\frac{F(x,t)}{t^2}<\frac{1}{\theta}$ uniformly with
respect to $x\in [a,b]$.
\end{itemize}
Further, assume that there exists a continuous function
$h:[0,+\infty[\to \mathbb{R}$ such that
$h(tK(t^2))=t$ for all $t\geq 0$. Then, for each
$\lambda$ in the interval
\begin{align*}
\Lambda_1&=]
\frac{\frac{1}{2}\tilde{K}(\|w\|^2)}{\int_a^b F(x,w(x))dx-\int_{a}^b
\sup_{t\in[-\sqrt{\frac{r(b-a)}{2m}},
\sqrt{\frac{r(b-a)}{2m}}]}F(x,t)dx}, \\
&\quad \frac{r}{\int_{a}^b
\sup_{t\in[-\sqrt{\frac{r(b-a)}{2m}},\sqrt{\frac{r(b-a)}{2m}}]}F(x,t)dx
}[,
\end{align*}
problem \eqref{e1} admits at least three weak solutions in $X$
and, moreover, for each $\eta>1$, there exist an open interval
$$
\Lambda_2\subseteq[ 0,\frac{\eta r }{2r\frac{\int_a^b F(x,w(x))dx}{\tilde{K}(\|w\|^2)}-
\int_{a}^b \sup_{t\in[-\sqrt{\frac{r(b-a)}{2m}},
\sqrt{\frac{r(b-a)}{2m}}]}F(x,t)dx}]
$$
and a positive real number $\sigma$ such that, for each
$\lambda\in\Lambda_2$,  problem \eqref{e1} admits at least three
weak solutions in $X$ whose
norms are less than $\sigma$.
\end{theorem}

 Let us first give a particular consequence of Theorem \ref{thm1}
for a fixed test function  $w$.

 \begin{corollary} \label{coro1}
Assume that there exist positive constants $c$, $d$, $\alpha$, $\beta$
 and  $\theta$ with $\beta-\alpha<b-a$ such that
Assumption (ii) in Theorem \ref{thm1} holds, and
\begin{itemize}
\item[(i)] $\tilde{K}(d^2(\frac{\alpha+\beta}{\alpha\beta}))
>\frac{4mc^2}{b-a}$,
\item[(ii)] $ F(x,t) \geq0$ for each
$(x,t)\in ([a, a+\alpha]\cup [b-\beta,b])\times [0,d]$,

\item[(iii)] $\int_{a}^b \sup_{t\in[-c,c]}F(x,t)dx<
\frac{2mc^2}{b-a}\frac{\int_{ a+\alpha}^{b-\beta}F(x,d)dx}
{\frac{2mc^2}{b-a}+\frac{1}{2}\tilde{K}(d^2
(\frac{\alpha+\beta}{\alpha\beta}))}$.
\end{itemize}
Further, assume that there exists a continuous function
$h:[0,+\infty[\to \mathbb{R}$ such that
$h(tK(t^2))=t$ for all $t\geq 0$. Then, for each
$$
\lambda\in \Lambda'_1
=]\frac{\frac{1}{2}\tilde{K}(d^2
 (\frac{\alpha+\beta}{\alpha\beta}))}{\int_{
a+\alpha}^{b-\beta}F(x,d)dx-\int_{a}^b  \sup_{t\in[-c,c]}F(x,t)dx
},\frac{\frac{2mc^2}{b-a}}{\int_{a}^b
\sup_{t\in[-c,c]}F(x,t)dx }[,
$$
problem \eqref{e1} admits at least
three weak solutions in $X$ and, moreover, for each $\eta>1$,
there exist an open interval
\begin{align*}
\Lambda_2
&\subseteq[ 0,\big(\frac{2\eta mc^2}{b-a}\big)\\
&\quad \div
\Big(\frac{4mc^2}{b-a}\frac{\int_{a}^{
a+\alpha}F(x,\frac{d}{\alpha}(x-a))dx
+\int_{a+\alpha}^{b-\beta}F(x,d)dx
+\int_{b-\beta}^b F(x,\frac{d}{\beta}(b-x))dx}{\tilde{K}
(d^2(\frac{\alpha+\beta}{\alpha\beta}))}\\
&\quad -\int_{a}^b \sup_{t\in[-c,c]}F(x,t)dx\Big)]
\end{align*}
and a positive real number $\sigma$ such that, for each
$\lambda\in\Lambda_2$,
problem \eqref{e1} admits at least three weak solutions in $X$ whose
norms are less than $\sigma$.
\end{corollary}

\begin{proof}
We claim that the all the assumptions of Theorem \ref{thm1} are
fulfilled with
\begin{equation} \label{e5}
w(x)= \begin{cases}
\frac{d}{\alpha}(x-a)&\text{if } a\leq x< a+\alpha, \\
d &\text{if } a+\alpha\leq x \leq b-\beta,\\
\frac{d}{\beta}(b-x) &\text{if }  b-\beta<x\leq b
\end{cases}
\end{equation}
and $r=2mc^2/(b-a)$ where constants $c$, $d$, $\alpha$ and
$\beta$ are given in the statement of the theorem.

It is clear from \eqref{e5} that $w\in X$ and, in particular, one has
\begin{equation} \label{e6}
\|w\|^2=d^2(\frac{\alpha+\beta}{\alpha\beta}).
\end{equation}
Moreover with this choice of $w$ and taking into account
\eqref{e6}, from (i) we get (i) of Theorem \ref{thm1}.
Since $0\leq w(x)\leq d$ for each $x\in [a,b]$, condition (ii)
ensures that
$$
\int_{a}^{a+\alpha} F(x,w(x))dx+\int_{b-\beta}^b F(x,w(x))dx
\geq 0,
$$
 so from (iii) we have
\begin{align*}
\int_{a}^b \sup_{t\in[-c,c]}F(x,t)dx
&< \frac{2mc^2}{b-a}\frac{\int_{
a+\alpha}^{b-\beta}F(x,d)dx}{\frac{2mc^2}{b-a}
 +\frac{1}{2}\tilde{K}(d^2(\frac{\alpha+\beta}{\alpha\beta}))}\\
&\leq \frac{2mc^2}{b-a}\frac{\int_{a}^b
 F(x,w(x))dx}{\frac{2mc^2}{b-a}+\frac{1}{2}\tilde{K}(\|w\|^2)}\\
&= r\frac{\int_{a}^b F(x,w(x))dx}{r+\frac{1}{2}\tilde{K}(\|w\|^2)},
\end{align*}
so (ii) of Theorem \ref{thm1} holds
(note $c^2=\frac{r(b-a)}{2m}$). Next
notice that
\begin{align*}
&\frac{\frac{1}{2}\tilde{K}(\|w\|^2)}{\int_{a}^b F(x,w(x))dx
-\int_{a}^b  \sup_{t\in[-\sqrt{\frac{r(b-a)}{2m}},
 \sqrt{\frac{r(b-a)}{2m}}]}F(x,t)dx }\\
&\leq \frac{\frac{1}{2}\tilde{K}(d^2
 (\frac{\alpha+\beta}{\alpha\beta}))}{\int_{a+\alpha}^{b-\beta}
 F(x,d)dx-\int_{a}^b  \sup_{t\in[-c,c]}F(x,t)dx}
\end{align*}
and
$$
\frac{r}{\int_{a}^b
\sup_{t\in[-\sqrt{\frac{r(b-a)}{2m}},\sqrt{\frac{r(b-a)}{2m}}]}
F(x,t)dx}
=\frac{\frac{2mc^2}{b-a}}{\int_{a}^b  \sup_{t\in[-c,c]}F(x,t)dx}.
$$
In addition note that
\begin{align*}
&\frac{\frac{1}{2}\tilde{K}(d^2(\frac{\alpha+\beta}{\alpha\beta}))}
{\int_{a+\alpha}^{b-\beta}F(x,d)dx
-\int_{a}^b  \sup_{t\in[-c,c]}F(x,t)dx }
\\
& <  \frac{\frac{1}{2}\tilde{K}(d^2
(\frac{\alpha+\beta}{\alpha\beta}))}{
\big(   \frac { \frac{2mc^2}{b-a}+
\frac{1}{2}\tilde{K}(d^2(\frac{\alpha+\beta}{\alpha\beta}))   }{
\frac{2mc^2}{b-a} } -1 \big)
\int_{a}^b  \sup_{t\in[-c,c]}F(x,t)dx } \\
&  =  \frac{\frac{2mc^2}{b-a}}{\int_{a}^b
\sup_{t\in[-c,c]}F(x,t)dx }.
\end{align*}
Finally note that
\begin{align*}
&\frac{hr }{2r\frac{\int_a^b F(x,w(x))dx}{\tilde{K}(\|w\|^2)}-
\int_{a}^b \sup_{t\in[-\sqrt{\frac{r(b-a)}{2m}},
\sqrt{\frac{r(b-a)}{2m}}]}F(x,t)dx}\\
&= \big(\frac{2hmc^2}{b-a}\big)\\
&\quad \div \Big(\frac{4mc^2}{b-a}\frac{\int_{a}^{
a+\alpha}F(x,\frac{d}{\alpha}(x-a))dx
+\int_{a+\alpha}^{b-\beta}F(x,d)dx+\int_{b-\beta}^b
F(x,\frac{d}{\beta}(b-x))dx}{\tilde{K}(d^2
(\frac{\alpha+\beta}{\alpha\beta}))}\\
&\quad -
\int_{a}^b \sup_{t\in[-c,c]}F(x,t)dx\Big),
\end{align*}
and taking into account that $\Lambda'_1\subseteq \Lambda_1$
we have the desired conclusion
directly from Theorem \ref{thm1}.
\end{proof}

 It is of interest to list some special cases of Corollary \ref{coro1}.

 \begin{corollary} \label{coro2}
 Assume that there exist positive constants
$c$, $d$, $p_1$, $p_2$, $\alpha$, $\beta$ and $\theta$ with
$\beta-\alpha<b-a$ such that Assumption (ii) of Corollary \ref{coro1}
holds, and
\begin{itemize}
\item[(i)] $ p_1d^2(\frac{\alpha+\beta}{\alpha\beta})
+\frac{p_2}{2}d^{4}(\frac{\alpha+\beta}{\alpha\beta})^2
>\frac{4p_1c^2}{b-a}$,

\item[(ii)]
$$
\int_{a}^b \sup_{t\in[-c,c]}F(x,t)dx<
\frac{2p_1c^2}{b-a}\frac{\int_{
a+\alpha}^{b-\beta}F(x,d)dx}{\frac{2p_1c^2}{b-a}
+\frac{p_1}{2}d^2(\frac{\alpha+\beta}{\alpha\beta})
+\frac{p_2}{4}d^{4}(\frac{\alpha+\beta}{\alpha\beta})^2},
$$

\item[(iii)] $\frac{(b-a)^2}{2p_1}\limsup_{|t|\to
+\infty}\frac{F(x,t)}{t^2}<\frac{1}{\theta}$ uniformly with
respect to $x\in [a,b]$.
\end{itemize}
Then, for each
$$
\lambda\in \Lambda''_1
=]\frac{
\frac{p_1}{2}d^2(\frac{\alpha+\beta}{\alpha\beta})
 +\frac{p_2}{4}d^{4}(\frac{\alpha+\beta}{\alpha\beta})^2}{\int_{
a+\alpha}^{b-\beta}F(x,d)dx-\int_{a}^b  \sup_{t\in[-c,c]}F(x,t)dx},
\frac{\frac{2p_1c^2}{b-a}}{\int_{a}^b
\sup_{t\in[-c,c]}F(x,t)dx }[,
$$
the problem
\begin{equation} \label{e7}
\begin{gathered}
-(p_1+p_2\int_{a}^b |u'(x)|^2dx)u''=\lambda f(x,u),\\
u(a)=u(b)=0
\end{gathered}
\end{equation} admits at least
three weak solutions in $X$ and, moreover, for each $\eta>1$,
there exist an open interval
\begin{align*}
\Lambda_2&\subseteq
[0,\big(\frac{2\eta p_1c^2}{b-a}\big)\\
&\quad \div\Big(\frac{4p_1c^2}{b-a}\frac{\int_{a}^{
a+\alpha}F(x,\frac{d}{\alpha}(x-a))dx+\int_{
a+\alpha}^{b-\beta}F(x,d)dx+\int_{b-\beta}^b F(x,
\frac{d}{\beta}(b-x))dx}{p_1d^2
(\frac{\alpha+\beta}{\alpha\beta})
+\frac{p_2}{2}d^{4}(\frac{\alpha+\beta}{\alpha\beta})^2}\\
&\quad -\int_{a}^b \sup_{t\in[-c,c]}F(x,t)dx\Big)]
\end{align*}
and a positive real number $\sigma$ such that, for each
$\lambda\in\Lambda_2$, problem \eqref{e7}
 admits at least three weak solutions in $X$ whose
norms are less than $\sigma$.
\end{corollary}

\begin{proof}
For fixed $p_1, p_2>0$, set $K(t)=p_1+p_2t$
 for all $t\geq 0$. Bearing in mind that $m=p_1$, from
 (i)--(iii), we see that (i)--(iii) of Corollary \ref{coro2}
hold respectively. Also we note that there exists a continuous
function  $h:[0,+\infty[\to \mathbb{R}$ such that
$h(tK(t^2))=t$ for all $t\geq 0$ because the function $K$
is nondecreasing in $[0,+\infty[$ with $K(0)>0$ and
$t\to tK(t^2)\ (t\geq 0)$ is increasing and
onto $[0,+\infty[$. Hence, Corollary \ref{coro1} yields the conclusion.
\end{proof}


\begin{corollary} \label{coro3}
Assume that there exist positive constants $c$, $d$, $\alpha$,
$\beta$ and $\theta$ with
$\beta-\alpha<b-a$ such that Assumption (ii) in
Corollary \ref{coro1} holds, and
\begin{itemize}
\item[(i)] $d^2(\frac{\alpha+\beta}{\alpha\beta})>\frac{4c^2}{b-a}$,

\item[(ii)]
$$
\int_{a}^b \sup_{t\in[-c,c]}F(x,t)dx<
\frac{2c^2}{b-a}\frac{\int_{
a+\alpha}^{b-\beta}F(x,d)dx}{\frac{2c^2}{b-a}
+\frac{d^2}{2}(\frac{\alpha+\beta}{\alpha\beta})},
$$

\item[(iii)] $\frac{(b-a)^2}{2}\limsup_{|t|\to
+\infty}\frac{F(x,t)}{t^2}<\frac{1}{\theta}$ uniformly with
respect to $x\in [a,b]$.
\end{itemize}
Then, for each
$$
\lambda\in \Lambda'''_1=]
\frac{ \frac{d^2}{2}(\frac{\alpha+\beta}{\alpha\beta})}{\int_{
a+\alpha}^{b-\beta}F(x,d)dx-\int_{a}^b  \sup_{t\in[-c,c]}F(x,t)dx
},\frac{\frac{2c^2}{b-a}}{\int_{a}^b
\sup_{t\in[-c,c]}F(x,t)dx }[,
$$
the problem
\begin{equation} \label{e8}
\begin{gathered}
-u''=\lambda f(x,u),\\
u(a)=u(b)=0
\end{gathered}
\end{equation}
admits at least three weak solutions in $X$ and, moreover,
for each $\eta>1$, there exist an open interval
\begin{align*}
\Lambda_2
&\subseteq[
0,\big(\frac{2\eta c^2}{b-a}\big)\\
&\quad\div\Big(\frac{4c^2}{b-a}\frac{\int_{a}^{
a+\alpha}F(x,\frac{d}{\alpha}(x-a))dx
+\int_{ a+\alpha}^{b-\beta}F(x,d)dx+\int_{b-\beta}^b F(x,
\frac{d}{\beta}(b-x))dx}{
d^2(\frac{\alpha+\beta}{\alpha\beta})}\\
&\quad - \int_{a}^b \sup_{t\in[-c,c]}F(x,t)dx\Big)]
\end{align*}
and a positive real
number $\sigma$ such that, for each $\lambda\in\Lambda_2$, the
problem \eqref{e8} admits at least three weak solutions in $X$ whose
norms are less than $\sigma$.
\end{corollary}

 We conclude this section by giving an example to
illustrate our results applying by Corollary \ref{coro2}.

\begin{example} \label{examp1} \rm
Consider the problem
\begin{equation} \label{e9}
\begin{gathered}
-(\frac{1}{128}+\frac{1}{64}\int_{0}^{1}|u'(x)|^2dx)u''
=\lambda (e^{-u}u^{11}(12-u)),\\
u(0)=u(1)=0
\end{gathered}
\end{equation}
where $\lambda>0$.
 Set $p_1=\frac{1}{128},\ p_2=\frac{1}{64}$ and
$f(x,t)=e^{-t}t^{11}(12-t)$ for all $(x,t)\in
[0,1]\times \mathbb{R}$. A direct calculation yields
$F(x,t)=e^{-t}t^{12}$ for all $(x,t)\in [0,1]\times \mathbb{R}$.
Assumptions (i) and (ii) of Corollary \ref{coro2} are satisfied by
choosing, for example $d=2$, $c=1$, $[a,b]=[0,1]$ and
$\alpha=\beta=1/4$. Also, since $\limsup_{|t|\to
+\infty}\frac{F(x,t)}{t^2}=0$, Assumption (iii) of Corollary \ref{coro2}
is fulfilled. Now we can apply Corollary \ref{coro2}. Then, for each
$$
\lambda\in \Lambda''_1=] \frac{
33}{2^{14}e^{-2}-8e },\frac{1}{64 e }[
$$
problem \eqref{e9} admits at
least three weak solutions in $H^{1}_{0}([0,1])$ and, moreover,
for each $\eta>1$, there exist an open interval
$$
\Lambda_2\subseteq[ 0,\frac{\eta
}{\frac{8}{33}\left(8^{12}\int_{0}^{\frac{1}{4}}e^{-8t}t^{12}dt+2^{11}e^{-2}+
8^{12}\int_{\frac{3}{4}}^{1}e^{-8(1-t)}(1-t)^{12}dt\right)-64e}]
$$
and a positive real number $\sigma$ such that, for each
$\lambda\in\Lambda_2$, problem \eqref{e9} admits at least three weak
solutions in $H^{1}_{0}([0,1])$ whose norms are less than
$\sigma$.
\end{example}

\section{Proof of Theorem \ref{thm1}}

  We begin by setting
\begin{gather} \label{e10}
\Phi(u)=\frac{1}{2}\tilde{K}(\|u\|^2),\\
\label{e11}
J(u)=\int_{a}^b F(x,u(x))dx
\end{gather}
for each $u \in X$, where $\tilde{K}$ and $F$ are
given in \eqref{e3} and \eqref{e4}, respectively.
It is well known that $J$ is a
G\^{a}teaux differentiable functional whose G\^{a}teaux derivative
at the point $u\in X$ is the functional $J'(u)\in X^{*}$,
given by
$$
J'(u)v=\int_{a}^b f(x,u(x))v(x)dx
$$
for every $v\in X$, and that $J':X \to X^{*}$
is a continuous and compact operator. Moreover, $\Phi$ is a
continuously G\^{a}teaux differentiable and sequentially weakly
lower semi continuous functional whose G\^{a}teaux derivative at
the point $u\in X$ is the functional $\Phi'(u)\in X^{*}$, given
by
$$
\Phi'(u)v=K(\int_{a}^b | u'(x)|^2dx)\int_{a}^b u'(x)
v'(x)dx
$$
for every $v\in X$. We claim that $\Phi'$ admits a
continuous inverse on $X$ (we identity $X$ with $X^{*}$). To prove
this fact, arguing as in \cite{R2} we need to find a continuous
operator $T:X\to X$ such that $T(\Phi'(u))=u$ for all $u\in X$.
Let $T:X\to X$ be the operator defined
by
$$
T(v)=\begin{cases}
\frac{h(\|v\|)}{\|v\|}v & \text{if }  v\neq 0\\
0 &\text{if } v= 0,
\end{cases}
$$
where $h$ is defined in the statement of Theorem \ref{thm1}.
Since, $h$ is continuous and $h(0)=0$, we have that the operator
$T$ is continuous in $X$. For every $u\in X$, taking into account
that $\inf_{t\geq0}K(t)\geq m>0$, we have since $h(t\,K(t^2))=t$
for all $t\geq 0$ that
\begin{align*}
T(\Phi'(u))&=T(K(\|u\|^2)u)\\
&=\frac{h(K(\|u\|^2)\|u\|)}{K(\|u\|^2)\|u\|}K(\|u\|^2)u\\
&=\frac{\|u\|}{K(\|u\|^2)\|u\|}K(\|u\|^2)u=u,
\end{align*}
so our claim is true. Moreover, since $m\leq K(s)$
for all $s\in [0,+\infty[$,
from \eqref{e10} we have
\begin{equation} \label{e12}
\Phi(u)\geq \frac{m}{2}\|u\|^2\quad
\text{for all } u\in X.
\end{equation}
Furthermore from (iii),
there exist two constants $\gamma, \tau\in \mathbb{R}$ with
$0<\gamma<1/\theta$ such that
$$
\frac{(b-a)^2}{2m}F(x,t)\leq \gamma t^2+\tau \quad
\text{for all }  x\in (a,b) \text{ and all } t\in \mathbb{R}.
$$
Fix $u\in X$. Then
\begin{equation} \label{e13}
F(x,u(x))\leq \frac{2m}{(b-a)^2}(\gamma |u(x)|^2+\tau)\quad
\text{for all }x\in (a,b).
\end{equation}
Fix $\lambda \in ]0,+\infty[$. Then
there exists $\theta>0$ with $\lambda \in ]0, \theta]$. Now since
\begin{equation} \label{e14}
\max_{x\in [a,b]}|u(x)|\leq
\frac{(b-a)^{1/2}}{2}\|u\|,
\end{equation}
from \eqref{e12}, \eqref{e13} and \eqref{e14}, we have
\begin{align*}
\Phi(u)-\lambda J(u)
&= \frac{1}{2}\tilde{K}(\|u\|^2)-\lambda\int^b _{a}F(x,u(x))dx\\
&\geq \frac{m}{2}\|u\|^2- \frac{2\theta m}{(b-a)^2}
\Big(\gamma \int^b _{a}|u(x)|^2+\tau(b-a)\Big)\\
&\geq \frac{m}{2}\|u\|^2-\frac{2\theta
m}{(b-a)^2}\Big(\gamma \frac{(b-a)^2}{4}\|u\|^2+\tau(b-a)\Big)\\
&= \frac{m}{2}(1-\gamma\theta)\|u\|^2-\frac{2\theta
\tau m}{b-a},
\end{align*}
 and so
$$
\lim_{\| u\|\rightarrow+\infty}
(\Phi(u)-\lambda J(u))=+\infty.
$$
Also from \eqref{e10} and (i) we have
$\Phi(w)>r$. Using \eqref{e12} and \eqref{e14}, we obtain
\begin{align*}
\Phi^{-1}(]-\infty,r[)
&=\big\{ u\in X; \Phi(u)< r\big\}\\
&\subseteq \big\{ u\in X; \|u\|< \sqrt{2r/m}\big\}\\
&\subseteq \big\{ u\in X; |u(x)|\leq
\sqrt{r(b-a)/(2m)},  \text{ for all }\ x\in
[a,b]\big\},
\end{align*}
so, we have
$$
\sup\nolimits_{\overline{u\in\Phi^{-1}(]-\infty,r[)}^{w}}J(u)
\leq \int_{a}^b
\sup\nolimits_{t\in[-\sqrt{\frac{r(b-a)}{2m}},
\sqrt{\frac{r(b-a)}{2m}}]}F(x,t)dx.
$$
Therefore, from (ii), we have
\begin{align*}
\sup\nolimits_{\overline{u\in\Phi^{-1}(]-\infty,r[)}^{w}}J(u)
&\leq   \int_{a}^b
\sup\nolimits_{t\in[-\sqrt{\frac{r(b-a)}{2m}},\sqrt{\frac{r(b-a)}{2m}}]}F(x,t)
dx\\
&< \frac{r}{r+
\frac{1}{2}\tilde{K}(\|w\|^2)}\int_{a}^b F(x,w(x))dx
\\
&= \frac{r}{r+\Phi(w)}J(w).
\end{align*}
 Now, we can apply
Theorem \ref{thmA}. Note for each $x\in [a,b]$,
$$
\frac{r}{\sup_{u\in\overline{\Phi^{-1}(]-\infty,r[)}^{w}}J(u)}\geq
\frac{r}{\int_{a}^b
\sup_{t\in[-\sqrt{\frac{r(b-a)}{2m}},\sqrt{\frac{r(b-a)}{2m}}]}F(x,t)dx
}$$
and
\begin{align*}
&\frac{\Phi(w)}{J(w)-\sup_{u\in\overline{\Phi^{-1}
(]-\infty,r[)}^{w}}J(u)}\\
&\leq \frac{\frac{1}{2}\tilde{K}(\|w\|^2)}{\int_a^b F(x,w(x))dx-\int_{a}^b
\sup_{t\in[-\sqrt{\frac{r(b-a)}{2m}},
\sqrt{\frac{r(b-a)}{2m}}]}F(x,t)dx}.
\end{align*}
Note also that (ii) immediately implies
\begin{align*}
&\frac{\frac{1}{2}\tilde{K}(\|w\|^2)}{\int_a^b F(x,w(x))dx-\int_{a}^b
\sup_{t\in[-\sqrt{\frac{r(b-a)}{2m}},
\sqrt{\frac{r(b-a)}{2m}}]}F(x,t)dx}\\
&< \frac{\frac{1}{2}\tilde{K}(\|w\|^2)}{ \big( \frac{r+
\frac{1}{2}\tilde{K}(\|w\|^2)}{r} \,-\,1 \big) \int_{a}^b
\sup_{t\in[-\sqrt{\frac{r(b-a)}{2m}},
\sqrt{\frac{r(b-a)}{2m}}]}F(x,t)dx}
\\
& = \frac{r}{\int_{a}^b \sup_{t\in[-\sqrt{\frac{r(b-a)}{2m}},
\sqrt{\frac{r(b-a)}{2m}}]}F(x,t)dx}.
\end{align*}
Also
\begin{align*}
&\frac{\eta r}{r\frac{J(w)}{\Phi(w)}-
\sup_{u\in\overline{\Phi^{-1}(-\infty,r[)}^{w}}J(u)}\\
&\leq\frac{\eta r }{2r\frac{\int_a^b F(x,w(x))dx}
 {\tilde{K}(\|w\|^2)}- \int_{a}^b
 \sup_{t\in[-\sqrt{\frac{r(b-a)}{2m}},
\sqrt{\frac{r(b-a)}{2m}}]}F(x,t)dx}=\rho.
\end{align*}
 Note from (ii) that
\begin{align*}
& 2r\frac{\int_a^b F(x,w(x))dx}{\tilde{K}(\|w\|^2)}-
\int_{a}^b \sup_{t\in[-\sqrt{\frac{r(b-a)}{2m}},
\sqrt{\frac{r(b-a)}{2m}}]}F(x,t)dx \\
& > \Big( \frac{2r}{\tilde{K}(\|w\|^2)} - \frac{r}{
r+ \frac{1}{2}\tilde{K}(\|w\|^2)} \Big)
\int_{a}^b F(x,w(x))dx \\
& \geq \Big( \frac{2r}{\tilde{K}(\|w\|^2)} -
\frac{2r}{ \tilde{K}(\|w\|^2)} \Big) \int_a^b F(x,w(x))dx=0
\end{align*}
since $\int_a^b F(x,w(x))dx \geq 0$ (note $F(x,0)=0$ so
$$
\int_{a}^b \sup\nolimits _{t\in[-\sqrt{\frac{r(b-a)}{2m}},
\sqrt{\frac{r(b-a)}{2m}}]}F(x,t)dx \geq 0
$$
and now apply (ii).
 Now with $x_{0}=0$, $x_1=w$ from Theorem \ref{thmA} (note
$J(0)=0$ from \eqref{e4}) it follows that, for each $\lambda\in
\Lambda_1$, the problem \eqref{e1} admits at least three weak solutions
and there exist an open interval $\Lambda_2\subseteq[0,\rho]$ and
a real positive number $\sigma$ such that, for each $\lambda\in
\Lambda_2$, the problem \eqref{e1} admits at least three weak solutions
that whose norms in $X$ are less than $\sigma$.

\begin{thebibliography}{00}
\bibitem{ATT}R. P. Agarwal, H. B. Thompson and C.C. Tisdell;
 \emph{On the existence of multiple solutions to boundary value problems for second order, ordinary differential equations. }
Dynam. Systems Appl. 16 (2007) 595-609.

\bibitem{ACM} C. O. Alves, F. S. J. A. Corr\^ea and T. F. Ma;
 \emph{Positive solutions for a quasilinear
elliptic equations of Kirchhoff type,} Comput. Math. Appl., 49
(2005), 85-93.

\bibitem{B} G. Bonanno;
 \emph{A critical points theorem and nonlinear differential problems,} J. Global Optimization, 28 (2004) 249-258.

\bibitem{BMV} G. Bonanno, G. Molica Bisci and V. R\u{a}dulescu;
\emph{Infinitely many solutions for a class of nonlinear eigenvalue
problem in Orlicz-Sobolev spaces,} C. R. Acad. Sci. Paris, Ser. I 349 (2011)
263-268.

\bibitem{CL} M. Chipot and B. Lovat;
 \emph{Some remarks on non local elliptic and parabolic
problems,} Nonlinear Anal., 30 (1997), 4619-4627.

\bibitem{GR} M. Ghergu and V. R\u{a}dulescu;
 \emph{Singular Elliptic Problems.
Bifurcation and Asymptotic Analysis,} Oxford Lecture Series in
Mathematics and Its Applications, vol. 37, Oxford University
Press, 2008.

\bibitem{HZ} X. He and W. Zou;
 \emph{Infinitely many positive solutions for Kirchhoff-type
problems,} Nonlinear Anal. 70 (2009) 1407-1414.

\bibitem{KRV} A. Krist\'aly, V. R\u{a}dulescu and C. Varga;
 \emph{Variational Principles in Mathematical Physics, Geometry, and Economics:
Qualitative Analysis of Nonlinear Equations and Unilateral
Problems,} Encyclopedia of Mathematics and its Applications, No.
136, Cambridge University Press, Cambridge, 2010.

\bibitem{M} T. F. Ma;
 \emph{Remarks on an elliptic equation of Kirchhoff type,} Nonlinear Anal., 63
(2005), e1957-e1977.

\bibitem{MZ} A. Mao and Z. Zhang;
\emph{Sign-changing and multiple solutions of Kirchhoff type
problems without the P. S. condition,}
Nonlinear Anal. 70 (2009) 1275-1287.

\bibitem{PZ} K. Perera and Z. T. Zhang;
\emph{Nontrivial solutions of Kirchhoff-type problems via
the Yang index,} J. Differential Equations, 221 (2006), 246-255.

\bibitem{R1} B. Ricceri;
\emph{A further three critical points theorem,}
Nonlinear Anal. 71 (2009) 4151-4157.

\bibitem{R2} B. Ricceri;
\emph{On an elliptic Kirchhoff-type problem depending on two
parameters,} J. Global Optimization 46 (2010) 543-549.

\bibitem{Z} E. Zeidler;
\emph{Nonlinear functional analysis and its applications,}
Vol. II, III. Berlin-Heidelberg-New York 1985.

\bibitem{ZP} Z. T. Zhang and K. Perera;
\emph{Sign changing solutions of Kirchhoff type problems
via invariant sets of descent flow,} J. Math. Anal. Appl., 317
(2006) 456-463.

\end{thebibliography}


\end{document}
