\documentclass[reqno]{amsart}
\usepackage{hyperref}

\AtBeginDocument{{\noindent\small
\emph{Electronic Journal of Differential Equations},
Vol. 2011 (2011), No. 144, pp. 1--7.\newline
ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu
\newline ftp ejde.math.txstate.edu}
\thanks{\copyright 2011 Texas State University - San Marcos.}
\vspace{7mm}}

\begin{document}
\title[\hfilneg EJDE-2011/144\hfil Existence of three positive solutions]
{Existence of three positive solutions for a system of nonlinear
third-order ordinary differential equations}

\author[N. Nyamoradi\hfil EJDE-2011/144\hfilneg]
{Nemat Nyamoradi}

\address{Nemat Nyamoradi \newline
Department of Mathematics, Faculty of Sciences\\
Razi University, 67149 Kermanshah, Iran}
\email{nyamoradi@razi.ac.ir}

\thanks{Submitted September 11, 2010. Published November 1, 2011.}
\thanks{Supported the Razi University}
\subjclass[2000]{34L30, 34B18, 34B27}
\keywords{Positive solution; boundary value problem;
fixed point theorem}

\begin{abstract}
 In this work, we use the Leggett-Williams fixed point
 theorem, we prove the existence of at least three positive
 solutions of a boundary-value problem for system of third-order
 ordinary differential equations.
\end{abstract}

\maketitle
\numberwithin{equation}{section}
\newtheorem{theorem}{Theorem}[section]
\newtheorem{lemma}[theorem]{Lemma}
\allowdisplaybreaks

\section{Introduction}

 Third-order differential equations arise in a
variety of different areas of applied mathematics and physics. In
recent years, boundary-value problems (BVPs for short) have
included, as special cases, multi-point BVPs considered by many
authors (see \cite{Anderson1,Anderson2,Guo2,Sun,Yao1,Yu}
and references therein). Naturally, further study in
this specific field is on BVPs for systems of ordinary
differential equations. However, to our knowledge, various results
for systems of second and third order differential equations have
been established (see \cite{Hu,Li,Wei} and references
therein). Guo et al. \cite{Guo2} obtained some
existence results for positive solutions for the BVP
\begin{gather*}
u'''(t)+a(t)f(u(t))=0 \quad 0<t<1\\
 u(0)= u'(0)=0, \quad  u'(1)=\alpha u'(\eta),
\end{gather*}
by using the well-know Guo-Krasnoselshkii and Leggett-Williiams
fixed point theorems \cite{Guo,Krasnoselskii,Leggett}
when $f$ is superlinear or sublinear.
Hu et al. \cite{Hu} established some results on the existence and
multiplicity of positive solution for the  BVP
\begin{gather*}
-u''(t) = f(x,v)\\
-v''(t) = g(x,u),\\
\alpha u(0) - \beta u'(0)=0,
 \gamma u(1)+ \sigma u'(1)=0,\\
\alpha v(0) - \beta v'(0)=0,\quad
 \gamma v(1)+ \sigma v'(1)=0.
\end{gather*}
  Li et al. \cite{Li}, considered the
existence of positive solutions for the  boundary-value problem
\begin{gather*}
 -u'''(t) = a(t)f(t,v(t))\\
-v'''(t) = b(t)h(t,u(t)),\\
u(0) = u'(0)=0,\quad  u'(1)= \alpha u'(\eta),\\
v(0) = v'(0)=0,\quad  v'(1)= \alpha v'(\eta)=0.
\end{gather*}
Motivated by the above-mentioned works, in this
article, we prove the existence of at least three positive
solutions for the  boundary-value problem
\begin{equation} \label{e1}
 \begin{gathered}
u'''(t) + a(t)f(t,u(t),v(t))=0,\quad  0< t < 1,\\
v'''(t) + b(t)h(t,u(t), v(t)), \quad   0< t < 1,\\
u(0) = u'(0)=0, \quad u'(1)= \beta u'(\eta),\\
v(0) = v'(0)=0,\quad   v'(1)= \beta v'(\eta),
\end{gathered}
\end{equation}
where $f,h:[0,1] \times [0, \infty) \times [0, \infty) \to
[0,\infty)$ are continuous and $0 < \eta < 1$,
$1 < \beta < 1/\eta$,  $a(t),b(t) \in C([0,1], [0, \infty))$
and are not identically zero on $[\eta/\beta,\eta]$.

A pair of functions $(u,v) \in C^3((0,1), \mathbb{R}^{+}) \times
C^3((0,1), \mathbb{R}^{+})$ is said to be a positive solution of
 \eqref{e1} if  $(u, v)$ satisfies  \eqref{e1}
and $u(t) \geq 0$, $v(t) > 0$, or $u(t) > 0$, $v(t) \geq 0$, for all
$t \in (0,1)$.

 For the convenience  of the reader, we present here
the Leggett-Williams fixed point theorem.

Given a cone $K$ in a real Banach space $E$, a map $\alpha$ is
said to be a nonnegative continuous concave (resp. convex)
functional on $K$ provided that
 $\alpha : K \to [0,+ \infty)$ is continuous and
\begin{gather*}
\alpha (tx + (1-t)y) \geq t \alpha (x) + (1-t) \alpha
(y),  \\
\text{(resp. } \alpha (tx + (1-t)y) \leq t \alpha (x) +
(1-t) \alpha (y)),
\end{gather*}
for all $x,y \in K$ and $t \in [0,1]$.
Let $0 < a < b$ be given and let $\alpha$ be a nonnegative
continuous concave functional on $K$. Define the convex sets $P_r$
and $P(\alpha, a, b)$ by
\[
P_r = \{ x \in K | \|x\| < r\}, \quad
P(\alpha, a, b) = \{ x \in K |a \leq \alpha (x), \|x\| \leq b\}.
\]
\begin{theorem}[Leggett-Williams fixed point theorem] \label{thm1}
Let $A : \overline{P_c} \to \overline{P_c}$ be a completely
continuous operator and let $\alpha$ be a nonnegative continuous
concave functional on $K$ such that $\alpha (x) \leq \|x\|$ for
all $x \in \overline{P_c}$. Suppose there exist $0 < a
< b < d \leq c$ such that
\begin{itemize}
\item[(A1)] $ \{x \in P(\alpha, b, d) :\alpha(x) > b\} \neq \emptyset $,
 and $\alpha (Ax) > b $ for $x \in P(\alpha, b, d)$;

\item[(A2)]  $\| Ax \| < a $ for $\| x \| \leq a$; and

\item[(A3)] $\alpha (Ax) > b $ for $x \in P(\alpha, b, c)$ with
$\| Ax \| > d$.
\end{itemize}
Then $A$ has at least three fixed points $x_1$, $x_2$ and $x_3$
and such that $\|x_1\| < a$, $b < \alpha (x_2)$ and $\|x_3\| > a$,
with $\alpha (x_3) < b$.
\end{theorem}

Inspired and motivated by the works mentioned above, in this work
we  consider the existence of  positive solutions to
\eqref{e1}. We shall first give a new form of the solution, and then
determine the properties of the Green's function for associated
linear boundary-value problems; finally, by employing the
Leggett-Williams fixed point theorem, some sufficient conditions
guaranteeing the existence of a positive solution. The rest of the
article is organized as follows: in Section 2, we present some
preliminaries that will be used in Section 3. The main results and
proofs will be given in Section 3. Finally, in Section 4, we shall
give an example to illustrate our main result.

\section{Preliminaries}

 In this section, we present some notations and preliminary lemmas
that will be used in the proof of the main result.
Obviously, $(u(t),v(t)) \in C^3([0,1], (0,+ \infty)) \times
C^3([0,1], (0,+ \infty))$ is a solution of \eqref{e1} if and only if
$(u(t),v(t))$ is a solution of the system of integral equations
\begin{gather}
u(t)= \int_0^1 G(t,s)a(s)f(s, u(s),v(s))ds , \label{e2}\\
v(t)= \int_0^1 G(t,s)b(s)h(s,u(s), v(s))ds , \label{e3}
\end{gather}
where $G(t,s)$ is the Green's function \cite{Guo} defined as
follows:
\[
G(t,s)= \frac{1}{2(1- \beta \eta)}\begin{cases}
(2ts-s^2)(1- \beta \eta) + t^2s(\beta -1), &
s \leq \min \{\eta,t \} \\
 t^2(1- \beta \eta) + t^2s(\beta -1), & t \leq s \leq \eta\\
 (2ts-s^2)(1- \beta \eta) + t^2(\beta \eta - s), &
\eta \leq s \leq t, \\
t^2 (1-s), & \max \{\eta,t \} \leq s\,.
\end{cases}
\]
 We need some properties of function $G(t,s)$  in
order to discuss the existence of positive solutions. For
convenience, we define
\begin{eqnarray}
g(s)= \frac{1 + \alpha}{1 - \beta \eta} s(1- s) \quad s \in
[0,1].
\end{eqnarray}
For the Green's function $G(t,s)$, we have the following two
lemmas \cite{Guo}.

\begin{lemma} \label{lem1}
Let $0 < \eta < 1$ and $1 < \beta < 1/\eta$.
Then for any $(t,s) \in [0,1]\times [0,1] $, we have
$0\leq G(t,s)\leq g(s)$.
\end{lemma}

\begin{lemma} \label{lem2}
Let $0 < \eta < 1$ and $1 < \beta < 1/\eta$. Then for any
$(t,s) \in [\eta/\beta,\eta] \times [0,1] $, we have
$$
\lambda g(s)\leq G(t,s),
$$
where $0 < \lambda = \eta^2 \min
\{\beta -1, 1\} /(2\beta^2 (1 + \beta))< 1$.
\end{lemma}

In this article, we  assume that the following
conditions are satisfied
\begin{equation} \label{e5}
0 < \int_0^1 g(s) a(s) ds < + \infty, \quad
0 < \int_0^1 g(s) b(s) ds < + \infty.
\end{equation}
 Also, we use the following notation
\begin{gather*}
M_1 = \max_{0 \leq t \leq 1} \int_0^1 G(t,s) a(s) ds , \quad
M_2 = \max_{0 \leq t \leq 1} \int_0^1 G(t,s) b(s) ds,\\
m_1 = \min_{\eta/\beta  \leq t \leq \eta}
\int_{\eta/\beta }^\eta G(t,s) a(s) ds ,  \quad
 m_2 = \min_{\eta/\beta  \leq t \leq \eta}
\int_{\eta/\beta }^\eta G(t,s) b(s)ds.
\end{gather*}
Clearly, we see that $0 < m_i < M_i$; for $i= 1,2$.

 Let $E = C([0,1], \mathbb{R}) \times C([0,1],
\mathbb{R})$ endowed with the norm
$\|(u,v)\|:= \|u\| + \|v\|$,
where $\|u\| =  \max_{0 \leq t \leq 1} |u(t)|$, $\|v\| =  \max_{0
\leq t \leq 1} |v(t)|$,
and define
\[ %\label{e6}
K=\{(u,v) \in E; u(t) \geq 0, v(t) \geq 0, t \in [0,1],
\min_{\eta/\beta  \leq t \leq \eta}( u(t) + v(t))  \geq
\gamma \|(u,v)\|\}.
\]
It is obvious that $E$ is a Banach space and $K$ is a cone in $E$.
Define  operator $T : E \to E$ as
\begin{equation} \label{e7}
T (u , v)(t) = (A(u , v)(t), B(u , v)(t)), \quad  \forall t \in (0,1),
\end{equation}
where
\begin{gather}
A(u , v)(t)=\int_0^1 G(t,s)a(s)f(s, u(s),v(s))ds, \label{e8}\\
B(u , v)(t)= \int_0^1 G(t,s)b(s)f(s, u(s),v(s))ds. \label{e9}
\end{gather}

\begin{lemma} \label{lem3}
 For $T$ and $K$ as above, $T (K) \subset K$.
\end{lemma}

\begin{proof}
For any $(u , v) \in K$,  from properties of
$G(t,s)$, $A(u , v)(t) \geq 0, B(u , v)(t) \geq 0, t \in [0,1]$,
and it follows from \eqref{e8}, \eqref{e9} and
Lemma \ref{lem1} that
\begin{equation} \label{e10}
\begin{gathered}
\|A(u , v)\|\leq \int_0^1 g(s)a(s)f(s, u(s),v(s))ds,\\
\|B(u , v)\|\leq \int_0^1 g(s)b(s)f(s, u(s),v(s))ds,
\end{gathered}
\end{equation}
Thus, for any $(u , v) \in K$, by Lemma \ref{lem2} and the above inequality,
\begin{align*}
\min_{\eta/\beta \leq t \leq \eta}A(u , v)(t)
&=  \min_{\eta/\beta \leq t \leq \eta}
 \int_0^1 G(t,s)a(s)f(s, u(s),v(s))ds,\\
&\geq  \lambda  \int_0^1 g(s)a(s)f(s, u(s),v(s))ds \\
&\geq  \lambda \|A(u , v)\|.
\end{align*}
In the same way, for any $(u , v) \in K$, we have
\[
\min_{\eta/\beta \leq t \leq \eta}B(u , v)(t)
\geq \lambda \|B(u,v)\|.
\]
Therefore,
\begin{align*}
&\min_{\eta/\beta  \leq t \leq \eta}(A(u , v)(t) + B(u ,
v)(t) \geq  \lambda \|A(u , v)\| + \lambda \|B(u,v)\|) \\
&= \lambda \|(A(u , v) , B(u,v))\|.
\end{align*}
From the above, we conclude that $T(u,v) = (A(u , v) , B(u , v))
\in K$, that is, $T (K) \subset K$. The proof is complete.
\end{proof}

It is clear that the existence of a positive solution for
 \eqref{e1} is equivalent to the existence of a nontrivial fixed
point of $T$ in $K$.

 \section{Main results}

 In this section, we discuss the existence of a
positive solution  \eqref{e1}. We define the nonnegative continuous
concave functional on $K$ by
\[
\alpha(u,v)= \min_{\eta/\beta \leq t \leq \eta}(u(t) ,v(t)).
\]
It is obvious that, for each $(u , v) \in K, \alpha(u,v) \leq
\|(u,v)\|$.
In this section, we assume
that $p_i, i= 1, 2$, are two positive numbers satisfying
$\frac{1}{p_1} + \frac{1}{p_2} \leq 1$.
Also, we use the following assumptions:
There exist nonnegative
numbers $a, b, c$ such that $0 < a < b \leq \min \{\lambda,
\frac{m_1}{p_1 M_1}, \frac{m_2}{p_2 M_2}\}c$, and $f(t, u, v)$,
$h(t, u, v)$ satisfy the following conditions:
\begin{itemize}

\item[(H1)] $f(t, u, v) < \frac{1}{p_1} \cdot \frac{c}{M_1}$,
$h(t, u, v) < \frac{1}{p_2} \cdot \frac{c}{M_2}$, for all
$t \in [0,1]$, $u+ v\in [0,c]$;

\item[(H2)] $f(t, u, v) < \frac{1}{p_1} \cdot \frac{a}{M_1}$,
$h(t, u, v) < \frac{1}{p_2} \cdot \frac{a}{M_2}$, for all
$t \in [0,1]$, $u+ v\in [0,a]$;

\item[(H3)] $f(t, u, v) > b/m_1$ or
 $h(t, u, v) > b/m_2 $, for all $t \in [0,1]$,
$u + v \in [b, b/\lambda]$.
\end{itemize}


\begin{theorem} \label{thm2}
Assume \eqref{e5} and {\rm (H1)--(H3)}.
Then \eqref{e1} has at least three positive solutions
$(u_1,v_1), (u_2, v_2), (u_3, v_3)$ such that
$\|(u_1, v_1)\| < a$,
$b < \min_{[\eta/\beta,\eta]}(u_2(t) + v_2(t))$, and
$\|(u_3,v_3)\| > a$, with
$\min_{\eta/\beta  \leq t \leq \eta}(u_3(t) + v_3(t)) < b$.
\end{theorem}

\begin{proof}
First, we show that $T : \overline{P_c} \to \overline{P_c}$
is a completely continuous operator. If $(u,v) \in
\overline{P_c}$, by condition (H1), we have
 \begin{align*}
 \|T(u,y)\|&=  \max_{0 \leq t \leq 1} |A(u,v)(t)| + \max_{0 \leq t \leq 1}
 |B(u,v)(t)|\\
&=  \max_{0 \leq t \leq 1}\int_0^1 G(t,s)a(s)f(s,u(s),v(s))ds \\
&\quad +\max_{0 \leq t \leq 1}\int_0^1 G(t,s)b(s)h(s,u(s),v(s))ds\\
&\leq  \frac{1}{p_1} \cdot \frac{c}{M_1} \max_{0 \leq t \leq
1}\int_0^1 G(t,s)a(s)ds + \frac{1}{p_2} \cdot \frac{c}{M_2}
\max_{0 \leq t \leq 1}\int_0^1 G(t,s)b(s)ds
\\
&\leq  \frac{1}{p_1} \cdot \frac{c}{M_1} \cdot M_1 + \frac{1}{p_2}
\cdot \frac{c}{M_2} \cdot M_2 \leq c.
\end{align*}
Therefore, $\|T(u,y)\| \leq c$, that is, $T : \overline{P_c}
\to \overline{P_c}$. The operator $T$ is completely
continuous by an application of the Ascoli-Arzela theorem.

In the same way, the condition (H2) implies that the condition
(A2) of Theorem \ref{thm1} is satisfied. We now show that condition (A1) of
Theorem \ref{thm1} is satisfied. Clearly,
$\{(u,v) \in P(\alpha, b,b/\lambda) | \alpha(u,v) > b\}
\neq \emptyset$.
If $(u,v) \in P(\alpha, b, b/\lambda)$, then
$b \leq u(s) + v(s) \leq \frac{b}{\lambda}, s
\in [\eta/\beta,\eta]$.

By condition (H3), we obtain
\begin{align*}
 \alpha (T(u,v)(t))
&=  \min_{\eta/\beta  \leq t \leq \eta} (A(u,v)(t) + B(u,v)(t))\\
&\geq  \min_{\eta/\beta  \leq t \leq \eta}
\int_{\eta/\beta }^\eta G(t,s)a(s)f(s,u(s),v(s))ds\\
&\quad +\min_{\eta/\beta  \leq t \leq
\eta} \int_{\eta/\beta }^\eta G(t,s)b(s)h(s,u(s),v(s))ds \\
&\geq  \frac{b}{m_1} \min_{\eta/\beta  \leq t \leq \eta}
\int_{\eta/\beta }^\eta G(t,s)a(s)ds = \frac{b}{m_1} \cdot
m_1 = b.
\end{align*}
Therefore, condition (A3) of Theorem \ref{thm1} is satisfied.

Finally, we show that the condition (A3) of Theorem \ref{thm1} is
satisfied.
If $(u,v) \in P(\alpha, b,c)$, and $\|T(u,v)\| >
\frac{b}{\lambda}$, then
\[
 \alpha (T(u,v)(t))=  \min_{\eta/\beta  \leq t \leq \eta}
 (A(u,v)(t) + B(u,v)(t)) \geq \lambda \|T(u,v)\| > b.
\]
Therefore, the condition (A3) of Theorem \ref{thm1} is also satisfied. By
Theorem \ref{thm1}, there exist three positive solutions $(u_1, v_1), (u_2,
v_2), (u_3, v_3)$ such that $\|(u_1, v_1)\| < a, b <
\min_{\eta/\beta  \leq t \leq \eta}(u_2(t) + v_2(t))$, and
$\|(u_3, v_3)\| > a$, with $\min_{\eta/\beta  \leq t \leq
\eta}(u_3(t) + v_3(t)) < b$.
\end{proof}

\section{Application}

 Consider the  system of
nonlinear third-order ordinary differential equations
\begin{equation} \label{e11}
\begin{gathered}
 u'''(t) + f(t,u(t),v(t))=0   0< t < 1,\\
v'''(t) + h(t,u(t), v(t)),   0< t < 1,\\
u(0)  = u'(0)=0, \quad u'(1)= \frac{3}{2} u'(\frac{1}{2}),\\
v(0)  = v'(0)=0,\quad   v'(1)= \frac{3}{2} v'(\frac{1}{2}),
\end{gathered}
\end{equation}
where
\begin{align*}
&f(t, u, v) = h(t, u, v) \\
&= \begin{cases}
\frac{t}{100} + \frac{1}{200} (u + v)^2,
&   t \in [0, 1],\; 0 \leq u + v \leq 1,\\
\frac{t}{100} + 240 [(u + v)^2 - (u + v)] + \frac{1}{200},
&  t \in [0, 1],  \;  1 <  u + v  < 2,\\
\frac{t}{100} + 30 [10 \log_2{(u + v)} + 3(u + v)] +
\frac{1}{200},
& t \in [0, 1], \;   2 \leq u + v \leq 4\\
\frac{t}{100} + \frac{\sqrt{u + v}}{2} + \frac{191801}{200},
 & t \in [0, 1], \;  4 < u + v  < + \infty.
\end{cases}
\end{align*}

 It is easy to check that $g(s) = 10 s (1 - s)$, for all
$s \in [0,1]$, $0 < \int_0^1 g(s) a(s) ds < + \infty, 0 < \int_0^1
g(s) b(s) ds < + \infty$ hold. Choose $p_1 = p_2 = 2$. Then by
direct calculations, we can obtain that
$M_1 = M_2 = 5/3$,
$m_1 = m_2 = 13/2916$.
So we choose $a = 1$, $b = 2$, $c = 3500$. It is easy to check that
$f, h$ satisfy the conditions (H1)--(H3).
 So system \eqref{e11} has at least three positive solutions
$(u_1, v_1), (u_2, v_2), (u_3,v_3)$ such that
$\|(u_1, v_1)\| < 1, 2 < \min_{\frac{1}{3} \leq t \leq
\frac{1}{2}}(u_2(t) + v_2(t))$, and
$\|(u_3, v_3)\| > 1$, with
$\min_{\frac{1}{3} \leq t \leq \frac{1}{2}}(u_3(t) + v_3(t)) <2$.


\subsection*{Acknowledgments}
The author would like to thank the anonymous referee for his/her
valuable suggestions and comments.

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\end{document}
