\documentclass[reqno]{amsart}
\usepackage{hyperref}

\AtBeginDocument{{\noindent\small
\emph{Electronic Journal of Differential Equations},
Vol. 2009(2009), No. 124, pp. 1--18.\newline
ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu
\newline ftp ejde.math.txstate.edu}
\thanks{\copyright 2009 Texas State University - San Marcos.}
\vspace{9mm}}

\begin{document}
\title[\hfilneg EJDE-2009/124\hfil Infinite multiplicity]
{Infinite multiplicity of positive solutions for singular
nonlinear elliptic equations with convection term and
related supercritical problems}

\author[C. C. Aranda \hfil EJDE-2009/124\hfilneg]
{Carlos C. Aranda}  % in alphabetical order

\address{Carlos C. Aranda \newline
Laboratorio de modelizaci\'on, c\'alculo num\'erico y
diseno experimental\\
Facultad de Recursos Naturales, Universidad Nacional de Formosa,
Argentina}
\email{carloscesar.aranda@gmail.com}


\thanks{Submitted August 24, 2009. Published October 1, 2009.}
\thanks{Supported  by  Secretar\'{i}a de
 Ciencia y Tecnolog\'{i}a, UNaF}
\subjclass[2000]{35J25, 35J60}
\keywords{Bifurcation; degree theory, nonlinear eigenvalues
and eigenfunctions}

\begin{abstract}
 In this article, we consider the singular nonlinear elliptic problem
 \begin{gather*}
 -\Delta u  =  g(u)+h(\nabla u)+f(u)  \quad\text{in }\Omega, \\
        u  =  0   \quad\text{on }\partial\Omega.
 \end{gather*}
 Under suitable assumptions on $g$ , $h$, $f$ and $\Omega$
 that allow a singularity of $g$ at the origin, we obtain
 infinite multiplicity results.  Moreover, we state infinite
 multiplicity results for related boundary blow up supercritical
 problems and for supercritical elliptic problems
 with Dirichlet boundary condition.
\end{abstract}

\maketitle
\numberwithin{equation}{section}
\newtheorem{theorem}{Theorem}[section]
\newtheorem{lemma}[theorem]{Lemma}
\newtheorem{remark}[theorem]{Remark}

%\usepackage{amssymb,latexsym}


\section{Introduction and statement of main results}

In 1869,  Lane  \cite{l} introduced the equation
\begin{equation}\label{lane}
    -\Delta u=u^p
\end{equation}
for $p$ a nonnegative real number and $u>0$  in a Ball of radius
$R$ in $\mathbb{R}^3$, with Dirichlet boundary conditions. Lane
was interested in computing both the temperature and the density
of mass on the surface of the sun. Today the problem (\ref{lane})
is named Lane-Emden-Fowler equation \cite{e,f}. Singular
Lane-Emden-Fowler equations ($p<0$) has been considered in a
remarkable pioneering paper  by Fulks and Maybe \cite{fm}.
Nonlinear singular elliptic equations arise in applications, for
example in glacial advance \cite{w}, ecology \cite{gl}, in
transport of coal slurries down conveyor belts \cite{c},
micro-electromechanical system device \cite{egg} etc.

Nonlinear singular elliptic equations have been studied
intensively during the last 40 years, for a detailed review out of
our scope in  this article, see Hern\'andez and Mancebo \cite{hm},
and the recent book by Ghergu and  R\u adulescu \cite{gr2}.
Multiplicity is a question with few results. Apparently, the first
multiplicity result for the problem
\begin{equation}\label{queso}
\begin{gathered}
-\Delta u  =  K(x)u^{-p}+u^q     \quad\text{in }  \Omega, \\
        u  =  0    \quad\text{on }  \partial\Omega,
\end{gathered}
\end{equation}
where $\Omega$ is smooth bounded domain and
\[
0<p<1<q\leq\frac{N+2}{N-2},
\]
was  obtained by Yijing et al. \cite{ysy} using variational methods.
Similar results concerning the existence of at least two solutions
$K(x)\equiv\lambda$, it can be encountered in \cite{h,hss,z}
with similar restrictions on $p,q$. A related multiplicity result
is stated by Adimurthi and Giacomoni \cite{ag1} for singular critical
problems in domains of $\mathbb{R}^2$, allowing $0<p<3$.
In dimension $N=1$ results on multiplicity can be found, for example,
in  Agarwal and  O'Reagan \cite{ao}. For strong singularities,
 Aranda and Godoy \cite{ag} stated the following theorem.

\begin{theorem}[{\cite{ag}}]
Let $\Omega$ be a smooth bounded domain in $\mathbb{R}^N$, $N\geq
3$. Suppose the following conditions hold:
\begin{enumerate}
\item $g:(0,\infty) \to(0,\infty)$ is non increasing
locally H\"{o}lder continuous function (that may be
singular at the origin) ;
\item  $f$ is locally H\"{o}lder continuous,  $\inf_{s>0}f(s)  /s>0$ and
$\lim_{s\to\infty}f(s)  /s^{p}<\infty$ for some
$p\in(1,\frac{N}{N-2}]$;
\item $\Omega$ is a strictly convex domain in $\mathbb{R}^{N}$.
\end{enumerate}
 Then the problem
\begin{gather*}
-\Delta u  =  g(u)+\lambda f(u)  \quad\text{in }\Omega,\\
u    =  0  \text{ on }\partial\Omega,
\end{gather*}
has at least two positive solutions for $\lambda$ positive
and small enough and that $\lambda=0$ is a bifurcation point
from infinity for this problem.
\end{theorem}

Our first result in this article is as follows.

\begin{theorem}\label{11}
Let $\Omega$ be a smooth bounded domain in $\mathbb{R}^N$, $N\geq 3$.
Suppose the following conditions hold:
\begin{enumerate}
\item  $g:(0,\infty) \to(0,\infty)$ is non increasing
 locally H\"{o}lder continuous function (that may be singular
  at the origin);
\item  $f$ is continuous, nonnegative and non decreasing
  function with $f(0)=0$;
\item  $f(\xi_{i})\geq \beta\xi_{i}$, $f(\eta_{i})\leq \alpha\eta_{i}$
 with
\[
\xi_{1}<\eta_{1}<\dots<\xi_{i}<\eta_{i}<\xi_{i+1}<\dots<\xi_{m},
\quad m\leq\infty ;
\]

\item $ \beta C(\Omega)(\int_{K}\varphi_{1})\varphi_{1}\geq 1 $, on
 $K\subset\Omega$ compact where $\varphi_1$, $\lambda_1$ are
 the principal eigenfunction an principal eigenvalue of the operator
$-\Delta$ ($-\Delta\varphi_1=\lambda_1\varphi_1$) with
Dirichlet boundary conditions;

\item $v+\alpha\eta_{i}e\leq\eta_{i}$, where
\begin{gather*}
-\Delta v  =  g(v)  \quad\text{in }\Omega, \\
        v  =  0   \quad\text{on }\partial\Omega,
\end{gather*}
and
\begin{gather*}
-\Delta e  =  1  \quad\text{in }\Omega, \\
        e  =  0  \quad\text{on }\partial\Omega.
\end{gather*}

\end{enumerate}
Then the problem
\begin{equation}\label{1}
\begin{gathered}
-\Delta u  =  g(u)+f(u)  \quad\text{in }\Omega, \\
        u  =  0   \quad\text{on }\partial\Omega,
\end{gathered}
\end{equation}
has $m\leq\infty$ nonnegative  classical solutions.
Moreover the problem
\begin{equation}\label{sumo1}
\begin{gathered}
-\Delta u  =  g(u)+f(u)  \quad\text{in }\Omega, \\
        u  =  \epsilon   \quad\text{on }\partial\Omega,
\end{gathered}
\end{equation}
has $2m-1\leq\infty$ nonnegative  classical solutions for
all $\epsilon >0$.
\end{theorem}

The behavior of the function $f$ in Theorem \ref{11} is closely
related to a similar nonlinearity studied by Kielh\"ofer and Maier
in \cite{km}. Under our best knowledge this is the first result
on infinite multiplicity for nonlinear singular equations.
Hern\'andez, Mancebo and Vega obtained the following theorem.

\begin{theorem}[\cite{hmv}]
Let $\Omega$ be a smooth bounded domain in $\mathbb{R}^N$, $N\geq 3$.
 Suppose the following conditions hold: $-1<q<1$,
$p<q$ and $\lambda >0$.
Then the problem
\begin{equation}\label{e5}
\begin{gathered}
-\Delta u  =  \lambda u^{-q}-u^{-p}  \quad\text{in }\Omega, \\
        u  =  0   \quad\text{on }\partial\Omega,
\end{gathered}
\end{equation}
 has a unique nonnegative classical solution.
\end{theorem}

Our second Theorem is related to multiplicity of a nonlinear
eigenvalue problem.

\begin{theorem}\label{drno5}
Let $\Omega$ be a smooth bounded domain in $\mathbb{R}^N$, $N\geq 3$.
Suppose the following conditions hold:
\begin{enumerate}
\item  $0<p<q$;
\item  $f$ is continuous, nonnegative and non decreasing function
 with $f(0)=0$;
\item $f(\xi_{i})\geq \beta\xi_{i}$, $f(\eta_{i})\leq \alpha\eta_{i}$
 with
\[
\xi_{1}<\eta_{1}<\dots<\xi_{i}<\eta_{i}<\xi_{i+1}<\dots<\xi_{m}
\leq\big(\frac{q\lambda}{p}\big)^{\frac{1}{q-p}}
\]

\item $ \beta C(\Omega)(\int_{K}\varphi_{1})\varphi_{1}\geq 1 $, on
$K\subset\Omega$ compact;

\item $\lambda^{\frac{1}{q+1}}v+\alpha\eta_ie\leq\eta_i$, where
\begin{gather*}
-\Delta v  =  v^{-q}  \quad\text{in }\Omega, \\
        v  =  0   \quad\text{on }\partial\Omega,
\end{gather*}
and
\begin{gather*}
-\Delta e  =  1  \quad\text{in }\Omega, \\
        e  =  0   \quad\text{on }\partial\Omega.
\end{gather*}

\item $\lambda^{\frac{1}{1+q}}\| v\|_\infty
\leq \big(\frac{q\lambda}{p}\big)^{\frac{1}{q-p}}$.

\end{enumerate}
Then the problem
\begin{equation}\label{e6}
\begin{gathered}
-\Delta u  =  \lambda u^{-q}-u^{-p}+f(u)  \quad\text{in }\Omega, \\
        u  =  0   \quad\text{on }\partial\Omega,
\end{gathered}
\end{equation}
has $m$ nonnegative  classical solutions. Moreover the problem
\begin{equation}\label{e7}
\begin{gathered}
-\Delta u  =  \lambda u^{-q}-u^{-p}+f(u)  \quad\text{in }\Omega, \\
        u  =  \epsilon   \quad\text{on }\partial\Omega,
\end{gathered}
\end{equation}
has $2m-1$ nonnegative  classical solutions for all $\epsilon >0$
small enough.
\end{theorem}

Existence and nonexistence results for singular nonlinear elliptic
equations with convection term have been stated by
Zhang \cite{z1}, Zhang  and Yu \cite{zy}, Ghergu and
R\u adulescu \cite{gr,gr1}. Multiplicity for singular
Lane-Emden-Fowler equation with convection term is a topic
essentially open.  A result was stated by Aranda and
Lami Dozo in \cite{al}:

\begin{theorem}[\cite{al}]\label{williams}
Let $\Omega$ be a smooth bounded domain in $\mathbb{R}^N$, $N\geq 3$.
Suppose the following conditions hold:
\begin{enumerate}
\item $0<p<\frac{1}{N}$, $1<q<\frac{N+1}{N-1}$  and $0<s<\frac{2}{N}$;
\item $w\in L^\infty(\Omega)$, $w>0$;
\item $ 0\leq\nu<C\big\{ \frac{\int_\Omega
w\varphi_1dx\int_\Omega\varphi_1^2dx}{\int_\Omega\varphi_1dx}
\big\}^{p-1}$
where $\varphi_1$, $\lambda_1$ are the principal
eigenfunction an principal eigenvalue of the
operator $-\Delta$
($-\Delta\varphi_1=\lambda_1\varphi_1$) with
Dirichlet boundary conditions and $C$ is a
constant depending only in $\Omega$, $q$,
$\lambda_1$.
\end{enumerate}
 Then there exist $0<\lambda^{**}\leq \lambda^*<\infty$ such that
for all  $\lambda\in (0,\lambda^{**})$, the
problem
\begin{gather*}
-\Delta u  =  u^{-p}+\lambda(u^q+\nu|\nabla u|^s)+w(x) \quad
\text{in }\Omega,\\
        u  =  0 \quad \text{on }\partial\Omega,
\end{gather*}
admits at least two solutions and no solutions for
 $\lambda>\lambda^*$. Furthermore there is bifurcation at infinity at
$\lambda=0$.
\end{theorem}

Our third result in this article, it is concerned with infinite
multiplicity for nonlinear elliptic equations with strong
singularity and convection term.

\begin{theorem}\label{122}
Let $\Omega$ be a smooth bounded domain in $\mathbb{R}^N$, $N\geq 3$.
Suppose the following conditions hold:
\begin{enumerate}
\item $g$ and $f$ satisfies conditions (1)--(4)  of Theorem \ref{11};
\item $h$ is a locally H\"older continuous function on $\mathbb{R}^N$
and $0\leq h( \nabla u )\leq   b_{1} | \nabla u |^{s}+b_{0}$, $ 0<s<1 $;
\item $ \eta_{i}  \geq   b_{1} \big(\eta_{i}\| \nabla e
\|_{L^{\infty}(\Omega)} \big)^{s}
 +b_{0}+g(\epsilon)+\alpha\eta_{i}$ for all $i$, where
\begin{gather*}
-\Delta e  =  1  \quad\text{in }\Omega, \\
        e  =  \epsilon   \quad\text{on }\partial\Omega.
\end{gather*}

\item $\epsilon + \exp(d(\Omega))\leq 2$ where $d(\Omega)$
is the distance between two parallel planes containing $\Omega$.
\end{enumerate}
Then the problem
\begin{equation}\label{a}
\begin{gathered}
-\Delta u  =  g(u)+h(\nabla u)+f(u)  \quad\text{in }\Omega, \\
        u  =  0   \quad\text{on }\partial\Omega,
\end{gathered}
\end{equation}
 has $m\leq\infty$ nonnegative  classical solutions.
\end{theorem}

\begin{remark} \label{rmk1} \rm
Condition (4) indicates a deep relation between the domain,
the convection term and multiplicity.
\end{remark}

\begin{figure}[ht]
\begin{center}
\setlength{\unitlength}{0.3mm}
\begin{picture}(270,210)(-40,-5)
\put(-60,5){\vector(1,0){300}}
\put(-60,5){\vector(0,1){200}}
\put(-60,5){\line(4,1){300}}
\put(-60,5){\line(2,1){300}}
\put(225,-8){$u$}
\put(18,-8){$\xi_1$}
\put(185,-8){$\eta_1$}
\put(70,25){$\alpha u$}
\put(200,150){$\beta u$}
\put(100,63){$f(u)$}
\thicklines{\qbezier(-60,5)(5,60)(230,70)}
\end{picture}
\end{center}
\caption{Double resonance of $f$}
\end{figure}

The existence of at least three solutions, for singular nonlinear
elliptic problems, using variational methods is a difficult task.
 Next, we apply a classical compensated compactness  technique
from the calculus of variations, for derive our fourth Theorem.

\begin{theorem}\label{inner}
Let $\Omega$ be a smooth bounded domain in $\mathbb{R}^N$, $N\geq 3$
and $0<p<1$. Suppose the following conditions hold:
\begin{enumerate}
\item $f$ is continuous, nonnegative and non decreasing function
 with $f(0)=0$;
\item $f(\xi_{i})\geq \beta\xi_{i}$, $f(\eta_{i})\leq \alpha\eta_{i}$
with
\[
\xi_{1}<\eta_{1}<\dots<\xi_{i}<\eta_{i}<\xi_{i+1}<\dots<\xi_{m};
\]
\item With $\kappa$, we denote the indicator function of a compact
set $K\subset\Omega$. We assume that the problem
\begin{gather*}
-\Delta\mathfrak{u} +\mathfrak{u}|\nabla\mathfrak{u}|^2
 =  \beta \xi_{i}\kappa  \quad\text{in }\Omega, \\
        \mathfrak{u}  =  0   \quad\text{on }\partial\Omega,
\end{gather*}
has at least a solution $\mathfrak{u}\in \mathcal{W}^{2,r}(\Omega)$,
$r>N$ with $\mathfrak{u}\geq \xi_i\kappa$;

\item $v(x)+\alpha\eta_{i}e(x)<\eta_{i}$ for all $x\in\overline{\Omega}$,
where
\begin{gather*}
-\Delta v  =  v^{-p}  \quad\text{in }\Omega, \\
        v  =  0   \quad\text{on }\partial\Omega,
\end{gather*}
and
\begin{gather*}
-\Delta e  =  1  \quad\text{in }\Omega, \\
        e  =  0   \quad\text{on }\partial\Omega.
\end{gather*}
\end{enumerate}
Then the problem
\begin{equation}\label{alice}
\begin{gathered}
-\Delta u +u|\nabla u|^2 =  u^{-p}+f(u)    \quad\text{in }  \Omega, \\
        u  =  0    \quad\text{on }  \partial\Omega,
\end{gathered}
\end{equation}
has $m$ solutions in $H^{1,2}_0(\Omega)$.
\end{theorem}

\begin{remark} \label{rmk2} \rm
Condition (3) indicates again a complex relation between domain,
convection term and multiplicity.
\end{remark}

For large solutions Ghergu et al. stated the following result.

\begin{theorem}[\cite{gnr}]
Let $\Omega$ be a smooth bounded domain in $\mathbb{R}^N$, $N\geq 3$.
Suppose the following conditions hold:
\begin{enumerate}
\item $f\in C^1[0,\infty)$, $f'\geq 0$, $f(0)=0$ and $f>0$ on
$(0,\infty)$;
\item $\int_1^\infty\left[F(t)\right]^{-2/a}dt<\infty$, where
\item $\frac{F(t)}{f^{2/a}}\to 0$ as $t \to 0$;
\item $\mathfrak{p}$, $\mathfrak{q}\in C^{0,\gamma}(\overline\Omega)$
are nonnegative functions such
that for every $x_0\in\Omega$ with $\mathfrak{p}(x_0)=0$,
there exists a domain $\Omega_0\ni x_0$ such that
$\overline\Omega_0\subset\Omega$ and $\mathfrak{p}>0$ on
$\partial\Omega_0$;
\item $0<a<2$.
\end{enumerate}
Then the problem
\begin{equation}
\begin{gathered}
\Delta u +\mathfrak{q}(x)|\nabla u|^a =  \mathfrak{p}(x)f(u)
 \quad\text{in }  \Omega, \\
        u  =  \infty   \quad\text{on }  \partial\Omega,
\end{gathered}
\end{equation}
has a nonnegative solution.
\end{theorem}

Related to the above Theorem, we have our  fifth result:

\begin{theorem}\label{blowup}
Let $\Omega$ be a smooth bounded domain in $\mathbb{R}^N$, $N\geq 3$.
Suppose: $f(s)=s^2\tilde{f}(\frac{1}{s})$, satisfies
{\rm (2)--(5)} of  Theorem \ref{11} with $g(u)=u^{2-p}$, $p>2$.
Then the problem
\begin{equation} \label{e11}
\begin{gathered}
\Delta v =  \frac{2}{v}|\nabla v|^2+v^p+\tilde{f}(u)
 \quad\text{in }\Omega, \\
       u =  \infty   \quad\text{on }\partial\Omega,
\end{gathered}
\end{equation}
 has $m\leq\infty$ nonnegative  classical solutions.
Moreover the problem
\begin{equation} \label{e12}
\begin{gathered}
\Delta v  =  \frac{2}{v}|\nabla v|^2+v^p+\tilde{f}(u)
 \quad\text{in }\Omega, \\
    u  =  M  \quad\text{on }\partial\Omega,
\end{gathered}
\end{equation}
has $2m-1\leq\infty$ nonnegative  classical solutions for all
$M >0$ big enough.
\end{theorem}

\begin{theorem}\label{supercritico}
Let $\Omega$ be a smooth bounded domain in $\mathbb{R}^N$, $N\geq 3$.
Suppose the following conditions hold:
\begin{enumerate}
\item $f(s)=s^2\tilde{f}(\frac{1}{s})$ satisfies
{\rm (2)--(4)} of Theorem \ref{11};
\item $2<q<p$;
\item $0<\epsilon\leq \big(\frac{q-2}{p-2}\big)^{\frac{1}{p-q}}$;
\item $v+\alpha\eta_ie\leq\eta_i$, where
\begin{gather*}
-\Delta e  =  1  \quad\text{in }\Omega, \\
        e  =  \frac{1}{\epsilon}   \quad\text{on }\partial\Omega,
\end{gather*}
and
\begin{gather*}
-\Delta v  =  v^{2-q}-v^{2-p}  \quad\text{in }\Omega, \\
        v  =  \frac{1}{\epsilon}   \quad\text{on }\partial\Omega.
\end{gather*}
\end{enumerate}
Then the problem
\begin{equation} \label{e13}
\begin{gathered}
-\Delta z +\frac{2}{z}|\nabla z|^2+\tilde{f}(z)+z^q
  =   z^p  \quad\text{in }\Omega, \\
z =  \epsilon   \quad\text{on }\partial\Omega,
\end{gathered}
\end{equation}
 has $2m-1\leq\infty$ nonnegative classical solutions.
\end{theorem}

\section{Preliminaries}

It is our purpose in this section to prove some preliminary results.
Let us start with some known facts about the Laplacian operator and
solution properties of nonlinear singular elliptic equations.


\begin{lemma}[{\cite[Uniform Hopf maximum principle.]{dmo,bc}}]
\label{hopf}
Let $\Omega$ be a smooth and bounded domain in $\mathbb{R}^N$, $N\geq 3$.
Suppose that
\begin{gather*}
-\Delta u  =  h  \quad\text{on }\Omega, \\
        u  =  0  \quad\text{in }\partial\Omega,
\end{gather*}
with $u\in\mathcal{W}^{1,1}_{0}(\Omega)$ and
$h\geq 0$, $h\in L^{1}(\Omega)$.
Then
\[
u\geq C\Big(\int_{\Omega}h\varphi_{1}\Big)\varphi_{1},
\]
where $C=C(\Omega)$ depends only on $\Omega$ and
\begin{gather*}
-\Delta\varphi_{1} =  \lambda_{1}\varphi_{1}  \quad\text{in }\Omega,\\
\varphi_{1}  >  0 \quad\text{in } \Omega,\\
\varphi_{1}  =  0  \quad\text{on } \partial\Omega.
\end{gather*}
\end{lemma}

\begin{remark} \label{rmk3} \rm
The proof of Lemma \ref{hopf} given by  Brezis and  Cabre in \cite{bc}
relies on the superharmonicity of the laplacian operator.
\end{remark}

\begin{theorem}[\cite{ag}]\label{H}
Let $P$ be the positive cone in $L^\infty(\Omega)$.
Let $S_{\epsilon}:P\to P$ be the solution operator
for the problem
\begin{gather*}
-\Delta u  =  g(u)+w  \quad\text{in }\Omega, \\
        u  =  \epsilon   \quad\text{on }\partial\Omega,
\end{gather*}
gives $S_{\epsilon}(w)=u$ where $\epsilon\geq 0$ and
$g:(0,\infty) \to(0,\infty)$ is nonincreasing
locally H\"{o}lder continuous function (that may be singular
at the origin). Then $S_{\epsilon}:P\to P$ is a continuous,
non decreasing and compact map with
$S_{\epsilon_0}(w)\leq S_{\epsilon_1}(w)$ for $\epsilon_0<\epsilon_1$.
\end{theorem}

\begin{lemma}\label{comparacion}
Let $\Omega$ be a smooth bounded domain in $\mathbb{R}^N$, $N\geq 3$.
Let $u,v\in C^{2}(\Omega)\cap C(\overline{\Omega})$
 be solutions of the problem
\begin{gather*}
-\Delta u -g(u)-h(\nabla u) \geq  -\Delta v -g(v)-h(\nabla v)
 \quad\text{in }\Omega, \\
        u  \geq  v\geq 0   \quad\text{on }\partial\Omega.
\end{gather*}
Then $u  \geq  v $ on $\Omega$.
\end{lemma}

\begin{proof}
 Indeed suppose $v>u$ somewhere and consider the non empty open set
\[
\Omega_{\delta}=\{x\in\Omega |v(x)>u(x)+\delta, \; \delta >0\}.
\]
Since $u,v\in C^{2}(\Omega)$, we have
\begin{align*}
-\Delta (u+\delta) -h(\nabla (u+\delta))
& =   g(u)+q\\
& \geq   g(v)+r  \\
& =  -\Delta v -h(\nabla v)  \quad\text{on }\Omega_{\delta},
\end{align*}
with $q,r\in C(\overline{\Omega_{\delta}})$
and $\overline{\Omega_{\delta}}\subset\Omega$.
Also $u+\delta=v $ on $\partial\Omega_{\delta}$ and
so the comparison Theorem 10.1 \cite{gt} implies
$u+\delta\geq v $ on $\Omega_{\delta}$.
It follows  $\Omega_{\delta}=\emptyset$ a contradiction.
\end{proof}

\begin{lemma}\label{m29}
Let $\Omega$ be a smooth bounded domain in $\mathbb{R}^N$, $N\geq 3$.
Suppose the following conditions hold:
\begin{enumerate}
\item $g:(0,\infty) \to(0,\infty)$ is non increasing
 locally H\"{o}lder continuous function (that may be singular
at the origin);
\item $h$ is locally H\"older continuous function on $\mathbb{R}^N$
with $0\leq h( \nabla u )\leq   b_{1} | \nabla u |^{s}+b_{0}$,
$ 0<s<1 $;
\item $w$ is a nonnegative locally H\"older continuous function
on $\overline\Omega$.
\end{enumerate}
Then the problem
\begin{equation}\label{100}
\begin{gathered}
-\Delta u  =  g(u)+h(\nabla u)+w(x)  \quad\text{in }\Omega, \\
        u  =  \epsilon\geq 0   \quad\text{on }\partial\Omega,
\end{gathered}
\end{equation}
has a unique solution $u\in C^{2}(\Omega)\cap C(\overline{\Omega})$.
\end{lemma}

\begin{proof}
 Let $g_{j}:\mathbb{R}\to \mathbb{R}$ be a non increasing and
locally H\"older continuous  function defined by
\[
g_{j}(s) = \begin{cases}
g(s) &\text{if } s\geq\frac{1}{j}\,,\\
C_{j}    &\text{if } s\leq \frac{1}{j+1}.
\end{cases}
\]
Using \cite[Theorem 15.11]{gt}, the problem
\begin{gather*}
-\Delta u  =  g_{j}(u)+h(\nabla u)+w(x)   \quad\text{on }\Omega, \\
        u  =  \epsilon>0   \quad\text{in }\partial\Omega,
\end{gather*}
has a classical solution. From
\begin{align*}
\Delta u_{j-1} + g_{j}(u_{j-1})+h(\nabla u_{j-1})+w(x)
& \geq  \Delta u_{j-1} + g_{j-1}(u_{j-1})+h(\nabla u_{j-1})+w(x)  \\
& =  0 \\
& =  \Delta u_{j} + g_{j}(u_{j})+h(\nabla u_{j})+w(x)
\quad\text{in }\Omega,
\end{align*}
$u_{j-1}=u_{j}=\epsilon $ on $\partial\Omega$,
using \cite[Theorem 10.1]{gt}, we infer $u_{j-1}\leq u_{j} $ in
$\Omega$. Therefore for $j$ big enough there exists an unique
$u_{\epsilon}=u_{j}$ solution of
\begin{gather*}
-\Delta u_{\epsilon}
= g(u_{\epsilon})+h(\nabla u_{\epsilon})+w(x) \quad\text{in }\Omega ,  \\
 u_{\epsilon}  =  \epsilon   \quad\text{on }\partial\Omega.
 \end{gather*}
If $\epsilon_{0}<\epsilon_{1}$, for $j$ big enough, we have
\[
\Delta u_{\epsilon_{0}} + g_{j}(u_{\epsilon_{0}})
+h(\nabla u_{\epsilon_{0}})+w(x)
=  \Delta u_{\epsilon_{1}} + g_{j}(u_{\epsilon_{1}})
+h(\nabla u_{\epsilon_{1}})+w(x),
\]
on $\Omega$,  $u_{\epsilon_{0}}<u_{\epsilon_{1}}$  in
$\partial\Omega$, using Theorem 10.1 \cite{gt},
we deduce $u_{\epsilon_{0}}<u_{\epsilon_{1}}$  on $\Omega$.
 From the inequalities
\begin{gather*}
\begin{aligned}
-\Delta u_{\epsilon}
& =  g(u_{\epsilon})+h(\nabla u_{\epsilon})+w(x) \\
& \geq  g(u_{1}) \\
& = -\Delta \mathcal{M} \quad\text{in }\Omega,
\end{aligned} \\
 u_{\epsilon}  =  \epsilon>0=\mathcal{M} \quad\text{on }\partial\Omega,
\end{gather*}
we obtain $u_{\epsilon}>r$ on $\Omega$. \cite[Theorem 15.8]{gt} implies
\[
-\Delta u_{\epsilon} =   g(u_{\epsilon})+h(\nabla u_{\epsilon})+w(x) \\
                \leq  g(\mathcal{M})+C,
\]
on $\overline{\Omega'}\subset\Omega$. Using \cite[Theorem  9.11]{gt},
 we have
\[
\| u_{\epsilon} \|_{\mathcal{W}^{2,r}(\Omega')}
  \leq  C(\| u_{\epsilon} \|_{L^{r}(\Omega')} +C)
 \leq  C(\| u_{1} \|_{L^{r}(\Omega')} +C),
\]
with $r>N$. By the Sobolev imbedding \cite[Theorem 7.26]{gt}
$u_{\epsilon}\to u$, in $C^{1,\gamma}(\Omega')$. A standard bootstrap
argument implies that $u\in C^{2}(\Omega)\cap C(\overline{\Omega})$
is a classical solution of problem
(\ref{100}). The unicity follows from Lemma \ref{comparacion}.
\end{proof}

\begin{lemma}\label{car}
Let $\Omega$ be a smooth bounded domain in $\mathbb{R}^N$, $N\geq 3$.
Suppose the following conditions hold:
\begin{enumerate}
\item $g:(0,\infty) \to(0,\infty)$ is non increasing locally
H\"{o}lder continuous function (that may be singular at the origin);
\item $h$ is locally H\"older continuous function on $\mathbb{R}^N$
with $0\leq h( \nabla u )\leq   b_{1} | \nabla u |^{s}+b_{0}$,
 $ 0<s<1 $;
\item $w$ is a nonnegative locally H\"older continuous function on
$\Omega$ and continuous on $\overline\Omega$.
\end{enumerate}
Then the problem
\begin{equation}\label{carry}
\begin{gathered}
-\Delta u  =  g(u)+h(\nabla u)+w(x)  \quad\text{in }\Omega, \\
        u  =  \epsilon\geq 0   \quad\text{on }\partial\Omega,
\end{gathered}
\end{equation}
has a unique solution
$u_{\epsilon}\in C^{2}(\Omega)\cap C(\overline{\Omega})$.
Moreover if $0<\epsilon$ then $u_{0}<u_{\epsilon}$.
\end{lemma}

\begin{proof}
Let $w_{\vartheta}:\Omega\to\mathbb{R}^+$ be a nonnegative
locally H\"older continuous function on $\overline\Omega$ defined by
\[
w_{\vartheta}(x) =
\begin{cases}
w(x) & \text{if } d(x,\partial\Omega)\geq\vartheta,\\
0    & \text{if } d(x,\partial\Omega)\leq \frac{\vartheta}{2}.
\end{cases}
\]
Let us consider the problems
\begin{gather*}
-\Delta u_{\vartheta}  =  g(u_{\vartheta})+h(\nabla u_{\vartheta})
 +w_{\vartheta}(x)  \quad\text{in }\Omega,\\
        u_{\vartheta}  =  0   \quad\text{on }\partial\Omega,
\end{gather*}
and
\begin{gather*}
-\Delta u_{\epsilon,\vartheta}
 =  g(u_{\vartheta})+h(\nabla u_{\vartheta})+w_{\vartheta}(x)
  \quad\text{in }\Omega, \\
        u_{\epsilon,\vartheta}  =  \epsilon
\quad\text{on }\partial\Omega.
\end{gather*}
Let us suppose that $w_{\vartheta_{1}}<w_{\vartheta_{0}}$ if
$\vartheta_{0}<\vartheta_{1}$. Using Lemma \ref{comparacion},
 we obtain  $u_{\epsilon,\vartheta_{1}}<u_{\epsilon,\vartheta_{0}}$
and $u_{\vartheta_{1}}<u_{\vartheta_{0}}$ on $\Omega$.
By  construction, we know that
$ u_{\vartheta}\leq  u_{\epsilon,\vartheta}$. By Lemma \ref{m29},
the problem
\begin{gather*}
-\Delta v_{\epsilon}  =  g(v_\epsilon)+h(\nabla v_{\epsilon})
+\| w \|_{L^{\infty}(\Omega)}  \quad\text{on }\Omega, \\
        v_{\epsilon}  =  \epsilon   \quad\text{in }\partial\Omega,
\end{gather*}
has a unique classical solution $v_\epsilon$. Using the comparison
\cite[Theorem 10.1]{gt}, we conclude that
$u_{\epsilon,\vartheta}\leq v_{\epsilon}$. It follows that
$u_{\vartheta}(x)\nearrow u_{0}(x)\leq v_{\epsilon}(x)$
for all $x\in\Omega$ and for $\vartheta\searrow 0$.

 Using \cite[Theorem 15.8]{gt}, the standard bootstrap
argument and Lemma \ref{comparacion}, we infer that the
problem (\ref{carry}) with $\epsilon = 0$  has a unique
solution $u_{0}\in C^{2}(\Omega)\cap C(\overline{\Omega})$.

 Similar arguments also yield
$u_{\epsilon,\vartheta}(x)\nearrow u_{\epsilon}(x)\leq v_{\epsilon}(x)$,
for all $x\in\Omega$ and for $\vartheta\searrow 0$.
Therefore, we get that the problem (\ref{carry}) has a unique
solution $u_{\epsilon}\in C^{2}(\Omega)\cap  C(\overline{\Omega})$,
for $\epsilon>0$.
\end{proof}

\begin{lemma}\label{adel}
Let $\Omega$ be a smooth bounded domain in $\mathbb{R}^N$, $N\geq 3$.
Suppose that $0<p<1$, $0<\delta$ and $0\leq w(x)\in L^\infty(\Omega)$.
Then the problem
\begin{equation}\label{poison}
\begin{gathered}
-\Delta u_{\epsilon,\delta} +\frac{u_{\epsilon,\delta}|\nabla u_{j,
\epsilon,\delta}|^2 }{1+\delta u_{\epsilon,\delta}| u_{\epsilon,
\delta}|^2} =  u_{\epsilon,\delta}^{-p}+w(x)  \quad\text{in }  \Omega, \\
        u_{\epsilon,\delta}  =  \epsilon   \quad\text{on }
 \partial\Omega,
\end{gathered}
\end{equation}
has a unique solution
$u_{\epsilon,\delta}\in\mathcal{W}^{2,r}(\Omega)\cap C(\overline\Omega)$
for all $r>1$, satisfying:
\begin{itemize}
\item[(a)] Let $P$ be the positive cone in $L^\infty(\Omega)$.
Let $\mathcal{S}_{\epsilon,\delta} :P\to P$ be the solution operator
for the problem (\ref{poison}), gives
$\mathcal{S}_{\epsilon,\delta}(w)=u_{\epsilon,\delta}$.
Then $\mathcal{S}_{\epsilon,\delta} :P\to P$ is continuous,
 compact and non decreasing map.

\item[(b)] If $\epsilon_0<\epsilon_1$, then
$\mathcal{S}_{\epsilon_0,\delta}(w)\leq \mathcal{S}_{\epsilon_1,
\delta}(w)$.

\item[(c)] If $\delta_0<\delta_1$, then
$\mathcal{S}_{\epsilon,\delta_0}(w)\leq \mathcal{S}_{\epsilon,
\delta_1}(w)$.

\item[(d)] $\inf_{\Omega'}u_{\epsilon,\delta}\geq C$,
$\overline\Omega'\subset\Omega$, where
$C=C(p,\Omega',w(x))$ is a constant independent of $\epsilon$,
$\delta$  and $C(\alpha,\Omega',0)>0$.

\item[(e)] For $0<\epsilon,\delta<1$, we have
$\| u_{\epsilon,\delta} -\epsilon\|_{H^{1,2}_0(\Omega)}\leq C$,
where $C$ is a constant independent of $\epsilon$ and $\delta$.
\end{itemize}
\end{lemma}

\begin{remark} \label{rmk46} \rm
Items (a)--(c) contain the monotone and compactness properties
of approximate solutions.
Item (d) is a uniform Harnack inequality.
Item (e) contains a uniform bound necessary for the compensated
compactness technique.
\end{remark}

\begin{proof}[Proof of Lemma \ref{adel}]
Let $g_{j}:\mathbb{R}\to\mathbb{R}$ be a non increasing and
locally H\"older continuous  function defined by
\[
g_{j}(s) = \begin{cases}
s^{-p} & \text{if } s\geq\frac{1}{j},\\
C_{j}  & \text{if } s\leq \frac{1}{j+1}.
\end{cases}
\]
Using a standard argument involving $L^r$ estimates
\cite[Theorem 9.10]{gt},
Sobolev imbedding \cite[Theorem 7.26]{gt}, \cite[Theorem 10.1]{gt}
and the Schauder fixed point Theorem, we deduce that the problem
\begin{gather*}
-\Delta u_{j,\epsilon,\delta} +\frac{u_{j,\epsilon,
\delta}|\nabla u_{j,\epsilon,\delta}|^2 }{1+\delta u_{j,\epsilon,\delta}|
\nabla u_{j,\epsilon,\delta}|^2}
=  g_j(u_{j,\epsilon,\delta})+w(x)  \quad\text{in }  \Omega, \\
u_{j,\epsilon,\delta}  =  \epsilon    \quad\text{on }  \partial\Omega,
\end{gather*}
has a unique solution
$u_{j,\epsilon,\delta}\in\mathcal{W}^{2,r}(\Omega)\cap C(\overline\Omega)$
for all $r>1$. If $w\in L^r(\Omega)$, $r>N$, then by
\cite[Theorem 7.26]{gt},
$u_{j,\epsilon,\delta}\in\mathcal{W}^{2,r}(\Omega)
\hookrightarrow C^{1,\gamma}(\overline\Omega)$ for some $\gamma>0$.
Calling
\[
b_\delta(u,\nabla u)=\frac{u|\nabla u|^2}{1+\delta u|\nabla u|^2},
\]
we deduce
\begin{align*}
&-\Delta u_{j,\epsilon,\delta}+b_\delta(u_{j,\epsilon,\delta},
 \nabla u_{j,\epsilon,\delta})-g_{j+1}(u_{j,\epsilon,\delta})   \\
&\leq -\Delta u_{j,\epsilon,\delta}+b_\delta(u_{j,\epsilon,\delta},
\nabla u_{j,\epsilon,\delta})-g_{j}(u_{j,\epsilon,\delta})      \\
&= w(x)\\
&= -\Delta u_{j+1,\epsilon,\delta}+b_\delta(u_{j+1,\epsilon,\delta},
\nabla u_{j+1,\epsilon,\delta})-g_{j+1}(u_{j+1,\epsilon,\delta})
\end{align*}
in $\Omega$ and $u_{j+1,\epsilon,\delta}=u_{j,\epsilon,\delta}=\epsilon$
on $\partial\Omega$. Using Theorem 10.1 \cite{gt}, we obtain that
$u_{j+1,\epsilon,\delta}>u_{j,\epsilon,\delta}$ in $\Omega$.
Moreover from
\[
-\Delta u_{j,\epsilon,\delta} +b_\delta (u_{j+1,\epsilon,\delta},
\nabla u_{j+1,\epsilon,\delta})
=  g_j(u_{j,\epsilon,\delta})+w(x)
\geq  -\Delta\epsilon+b_\delta(\epsilon,\nabla\epsilon)\quad
\text{in }\Omega,
\]
and $u_{j,\epsilon,\delta}=\epsilon$ on $\partial\Omega$, using
again \cite[Theorem 10.1]{gt}, we conclude
$u_{j,\epsilon,\delta}>\epsilon$ on $\Omega$. Letting
$u_{\epsilon,\delta}=\lim_{j\to\infty}u_{j,\epsilon,\delta}$, we have
\begin{gather*}
-\Delta u_{\epsilon,\delta} +b_\delta(u_{\epsilon,\delta},
\nabla u_{\epsilon,\delta}) =
 u_{\epsilon,\delta}^{-p}+w(x)   \quad\text{in }  \Omega, \\
 u_{\epsilon,\delta} =  \epsilon   \quad\text{on }  \partial\Omega.
\end{gather*}
Using standard Nemytskii mappings properties and Sobolev Imbedding
Theorems, we demonstrate the continuity and compacity  of the map
$\mathcal{S}_{\delta,\epsilon}$. This states ($\mathfrak{a}$).

Comparison \cite[Theorem 10.1]{gt} implies if
$\epsilon_0<\epsilon_1$ then
$\mathcal{S}_{\epsilon_0,\delta}(w)=u_{\epsilon_0,
\delta}<u_{\epsilon_1,\delta}=\mathcal{S}_{\epsilon_1,\delta}(w)$
 in $\Omega$. This establishes (b).

We demonstrate now (c). We suppose that the set
\[
\widehat{\Omega}=\{x\in\Omega :\mathcal{S}_{\epsilon,\delta_1}(w(x))
<\mathcal{S}_{\epsilon,\delta_0}(w(x))\},
\]
is nonempty for $\delta_1>\delta_0>0$. It follows that
\begin{align*}
&-\Delta \mathcal{S}_{\epsilon,\delta_1}(w)
+\frac{\mathcal{S}_{\epsilon,\delta_1}(w)|\nabla
\mathcal{S}_{\epsilon,\delta_1}(w)|^2}{1+\delta_0
\mathcal{S}_{\epsilon,\delta_1}(w)|\nabla
\mathcal{S}_{\epsilon,\delta_1}(w)|^2}\\
& \geq    -\Delta \mathcal{S}_{\epsilon,\delta_1}(w)
 +\frac{\mathcal{S}_{\epsilon,\delta_1}(w)|\nabla
  \mathcal{S}_{\epsilon,\delta_1}(w)|^2}
 {1+\delta_1\mathcal{S}_{\epsilon,\delta_1}(w)|
 \nabla \mathcal{S}_{\epsilon,\delta_1}(w)|^2} \\
& = (\mathcal{S}_{\epsilon,\delta_1}(w))^{-p}+w(x) \\
& \geq  (\mathcal{S}_{\epsilon,\delta_0}(w))^{-p}+w(x)\\
& =   -\Delta \mathcal{S}_{\epsilon,\delta_0}(w)
+\frac{\mathcal{S}_{\epsilon,\delta_0}(w)|\nabla
 \mathcal{S}_{\epsilon,\delta_0}(w)|^2}
{1+\delta_0\mathcal{S}_{\epsilon,\delta_0}(w)|\nabla
\mathcal{S}_{\epsilon,\delta_0}(w)|^2}\quad\text{on }\widehat{\Omega},
\end{align*}
and $\mathcal{S}_{\epsilon,\delta_1}(w(x))
=\mathcal{S}_{\epsilon,\delta_0}(w(x))$ on $\partial\widehat{\Omega}$.
Using Theorem 10.1 \cite{gt}, we infer
$\mathcal{S}_{\epsilon,\delta_1}(w)>\mathcal{S}_{\epsilon,\delta_0}(w)$
on $\widehat{\Omega}$. This contradiction
implies
$\mathcal{S}_{\epsilon,\delta_1}(w)\leq\mathcal{S}_{\epsilon,\delta_0}(w)$.
We also have
\begin{align*}
-\Delta u_{\epsilon,\delta} +b_\delta (u_{\epsilon,\delta},
\nabla u_{\epsilon,\delta})
& \geq  -\Delta u_{\epsilon,\delta} +b_\delta (u_{\epsilon,\delta},\nabla u_{\epsilon,\delta})-w(x)\\
& =  u_{\epsilon,\delta}^{-p}\\
& \geq  u_{1,\delta}^{-p}\\
& = -\Delta \omega_\delta +b_\delta(\omega_\delta,
\nabla\omega_\delta)\quad\text{in }\Omega,
\end{align*}
and $u_{\epsilon,\delta}=\epsilon>0=\omega_\delta$ on
$\partial\Omega$. Therefore $u_{\epsilon,\delta}>\omega_\delta$ on
$\Omega$. By definition
\begin{gather*}
-\Delta u_{1,\delta} +b_\delta(u_{1,\delta},\nabla u_{1,\delta})
=  u_{1,\delta}^{-p}+w(x)   \quad\text{in }  \Omega \\
        u_{1,\delta} =  1   \quad\text{on }  \partial\Omega.
\end{gather*}
So, we have
\begin{gather*}
-\Delta u_{1,\delta} -u_{1,\delta}^{-p}\leq w(x)
= -\Delta u_1-u_1^{-p}    \quad\text{in }  \Omega \\
  u_{1,\delta} = 1  =u_1   \quad\text{on }  \partial\Omega.
\end{gather*}
Therefore,  $u_{1,\delta}\leq u_1$ in $\Omega$. Similarly
\begin{align*}
-\Delta\omega_\delta +b_\delta (\omega_{\delta},\nabla \omega_{\delta})
& =  u_{1,\delta}^{-p} \\
& \geq  u_1^{-p}\\
& = -\Delta \mathcal{O}_\delta +b_\delta( \mathcal{O}_\delta,
\nabla\mathcal{O}_\delta)\quad\text{in }\Omega,
\end{align*}
and $\omega_\delta\geq\mathcal{O}_\delta$ in $\partial\Omega$.
Then, we obtain $\omega_\delta\geq\mathcal{O}_\delta$.
For $a\in\Omega$, we define
\[
\mathcal{V}(x)=C(C-| x-a|^2).
\]
It follows that, for $C$ small enough
\begin{align*}
-\Delta \mathcal{O}_\delta +b_\delta ( \mathcal{O}_\delta,\nabla
\mathcal{O}_\delta)
& =  g(u_1) \\
& \geq  C_1 \\
& \geq  -\Delta \mathcal{V}+ \mathcal{V}|\nabla\mathcal{V}|^2\\
& \geq  -\Delta \mathcal{V}+ \frac{\mathcal{V}|\nabla\mathcal{V}
|^2}{1+\delta\mathcal{V}|\nabla\mathcal{V}|^2}\\
& =  -\Delta\mathcal{V}+b_\delta(\mathcal{V},\nabla\mathcal{V})
\quad\text{in }B_{\sqrt{C}}(a)\subset\Omega,
\end{align*}
and $\mathcal{O}_\delta\geq 0=\mathcal{V}$ on
$\partial B_{\sqrt{C}}(a)$. Therefore, we deduce
$\mathcal{O}_\delta\geq\mathcal{V}$ in $B_{\sqrt{C}}(a)$.
 We conclude
\[
u_{\epsilon,\delta}\geq\omega_\delta\geq\mathcal{O}_\delta
\geq\mathcal{V} \quad\text{in }B_{\sqrt{C}}(a)\subset\Omega.
\]
This states (d).

Now we consider (e):
\begin{align*}
\| u_{\epsilon,\delta}-\epsilon\|_{H_0^{1,2}}^2
 & = \int_{\Omega}|\nabla (u_{\epsilon,\delta}-\epsilon)|^2dx\\
 & \leq \int_{\Omega}u_{\epsilon,\delta}^{-p}(u_{\epsilon,\delta}
 -\epsilon)dx+\int_{\Omega}w(u_{\epsilon,\delta}-\epsilon)dx \\
 & \leq \int_{\Omega}(u_{\epsilon,\delta}-\epsilon)^{-p}
 (u_{\epsilon,\delta}-\epsilon)dx+\| w\|_{H^{-1}}\| u_{\epsilon,\delta}
 -\epsilon\|_{H^{1,2}_0}\\
 &\leq \int_{\Omega}(\mathcal{S}_{1,1}(w) -\epsilon)^{1-p}dx
 +\| w\|_{H^{-1}}\| u_{\epsilon,\delta}-\epsilon\|_{H^{1,2}_0}.
\end{align*}
This states (e).
\end{proof}

\section{Proofs of mains results}

\begin{proof}[Proof of Theorem \ref{11}]
Let $P$ be the positive cone in $L^\infty(\Omega)$. Let $A:P\to P$
be the solution operator for the problem
\begin{gather*}
-\Delta z  =  g(z)+f(u) \quad\text{in }\Omega ,\\
        z  =  0   \quad\text{on }\partial\Omega,
\end{gather*}
gives $A(u)=z$. Using Theorem \ref{H}, we infer that $A:P\to P$
is a well defined, continuous, non decreasing and compact map.
Let us to denote with $\kappa$  the indicator function of the set $K$.
Using hypothesis $(3^\circ)$, we get
\[
-\Delta A(\xi_i\kappa)  =  g(A(\xi_i\kappa))+f(\xi_i\kappa)
                        \geq  \beta\xi_i\kappa.
\]
We will denote by $u=(-\Delta)^{-1}h$ the solution operator of
the problem $-\Delta u=h$ in $\Omega$ and $u=0$ on $\partial\Omega$.
It follows that
\begin{gather*}
-\Delta ( A(\xi_i\kappa) -(-\Delta)^{-1}\beta\xi_i\kappa  )  \geq
 0   \quad\text{in }\Omega, \\
 A(\xi_i\kappa) -(-\Delta)^{-1}\beta\xi_i\kappa    =   0
 \quad\text{on }\partial\Omega.
\end{gather*}
 From the maximum principle,  Lemma \ref{hopf} and (4), we infer
\[
A(\xi_i\kappa)
\geq   (-\Delta)^{-1}\beta\xi_i\kappa
\geq   \beta\xi_i C(\Omega)\Big(\int_{\Omega}\kappa\varphi_{1}\Big)\varphi_{1}
\geq   \xi_i\kappa.
\]
Now $A(0)<A(\eta_{i})$ and so, simple calculation yields
\begin{align*}
-\Delta A(\eta_{i})
& =   g(A(\eta_{i})) +f(\eta_{i}) \\
& \leq  g(A(0))+\alpha\eta_{i}\\
& \leq  -\Delta( A(0) +\alpha\eta_{i}(-\Delta)^{-1}1).
\end{align*}
It now follows from maximum principle that
\[
A(\eta_{i})\leq A(0) +\alpha\eta_{i}(-\Delta)^{-1}1,
\]
so that from hypothesis (5),
  $A(0) +\alpha\eta_{i}(-\Delta)^{-1}1\leq \eta_{i}$.
Then $A(\eta_{i})\leq \eta_{i}$, and hence
$A[\xi_i\kappa,\eta_{i}]\subset[\xi_i\kappa,\eta_{i}]$.
Thus, there are a solution $u_{i}\in [\xi_i\kappa,\eta_{i}]$ of
the fixed point equation $A(u_{i})=u_{i}$.
Now by Amann's ``three solution Theorem'' \cite{a},
problem (\ref{sumo1}) has $2m-1$ solutions.
\end{proof}


\begin{proof}[Proof of Theorem \ref{drno5}]
Let us to define the function
\[
g_0(s) =  \begin{cases}
\lambda s^{-q}-s^{-p} & \text{if }
s<(\frac{q \lambda}{p})^{\frac{1}{q-p}}\\
\lambda(\frac{q\lambda}{p})^{\frac{-q}{q-p}}
-(\frac{q}{p})^{\frac{-p}{q-p}} & \text{if }
s\geq(\frac{q\lambda}{p})^{\frac{1}{q-p}}.
\end{cases}
\]
If $v$ is a solution of
\begin{gather*}
-\Delta v  =  v^{-q}  \quad\text{in }\Omega,\\
        v  =  0  \quad\text{on }\partial\Omega.
\end{gather*}
Then $z=\lambda^{\frac{1}{1+q}}v$, solves
\begin{gather*}
-\Delta z  =  \lambda z^{-q}  \quad\text{in }\Omega,\\
        z  =  0  \quad\text{on }\partial\Omega.
\end{gather*}
 From $\lambda^{\frac{1}{1+q}}\| v\|_\infty
\leq (\frac{q\lambda}{p})^{\frac{1}{q-p}}$, it follows that
\begin{gather*}
-\Delta z -\lambda z^{-q}+z^{-p}
 \geq 0 = -\Delta u_0-g_0(u_0)  \quad\text{in }\Omega, \\
        z  =  0 =u_0  \quad\text{in }\partial\Omega;
\end{gather*}
therefore, $z\geq u_0$ on $\Omega$. Observe that,
we can apply Theorem \ref{11} for
\begin{gather*}
-\Delta u   =  g_0(u)+f(u) \quad\text{in }\Omega, \\
        u  = 0  \quad\text{in }\partial\Omega,
\end{gather*}
\end{proof}


\begin{proof}[Proof of Theorem \ref{122}]
 Let $P$ the positive cone in the space
$C^\gamma_{loc}(\Omega)\cap C(\overline\Omega)$.
Let  $H_{\epsilon}:P\to P$ be solution operator of the problem
\begin{gather*}
-\Delta z  =  g(z)+h(\nabla z)+f(u)  \quad\text{in }\Omega, \\
        z  =  \epsilon   \quad\text{on }\partial\Omega,
\end{gather*}
gives $H_\epsilon(u)=z$. Now we use the operator $A$ introduced
in the proof of Theorem \ref{11}. By Lemma \ref{car},
$A^{2}(\xi_{i}\kappa)$  belongs to the domain of $H_{0}$. Moreover
\begin{align*}
-\Delta H_{0}(A^{2}(\xi_{i}\kappa))
- g(H_{0}(A^{2}(\xi_{i}\kappa)))
& =  h(\nabla H_{0}(A^{2}(\xi_{i}\kappa)))+ f(A^{2}(\xi_{i}\kappa)) \\
& \geq  f(A(\xi_{i}\kappa)) \\
& =   -\Delta A^{2}(\xi_{i}\kappa)- g(A^{2}(\xi_{i}\kappa)),
\end{align*}
 in $\Omega$ and
$H_{0}(A^{2}(\xi_{i}\kappa))=A^{2}(\xi_{i}\kappa)=0$ on
 $\partial\Omega$. It follows from Lemma \ref{comparacion}
with $h\equiv 0$,
\[
 H_{0}(A^{2}(\xi_{i}\kappa))\geq A^{2}(\xi_{i}\kappa).
\]
In particular, Lemma \ref{car} implies
$H_{0}(\eta_{i})\leq H_{\epsilon}(\eta_{i})$.
Then by hypothesis (1) we have
\begin{align*}
-\Delta H_{\epsilon}(\eta_{i})-h(\nabla H_{\epsilon}(\eta_{i}))
& =  g(H_{\epsilon}(\eta_{i}))+ f(\eta_{i}) \\
& \leq   g(\epsilon) +\alpha\eta_{i}  \\
& =   -\Delta v_{\epsilon}- h(\nabla v_{\epsilon} )
\quad\text{in $\Omega$},
\end{align*}
and $H_{\epsilon}(\eta_{i})=v_{\epsilon}=\epsilon$ on $\partial\Omega$.
Using the  \cite[Theorem 10.1]{gt}, we obtain
\[
 H_{\epsilon}(\eta_{i})\leq v_{\epsilon} \quad\text{on } \Omega .
\]
Consider the auxiliary problem
\begin{gather*}
-\Delta e  =  1   \quad\text{in }  \Omega, \\
        e  =   \epsilon    \quad\text{on }  \partial\Omega.
\end{gather*}
Moreover, by hypothesis (3),
\begin{align*}
-\Delta \eta_{i} e & =  \eta_{i} \\
& \geq   b_{1} (\eta_{i}\| \nabla e \|_{L^{\infty}(\Omega)} )^{s}
  +b_{0}+g(\epsilon)+\alpha\eta_{i}  \\
& \geq    h( \eta_i\nabla e )
  +g(\epsilon)+\alpha\eta_{i}\quad\text{on $\Omega$},
\end{align*}
and so, one obtains
\begin{gather*}
-\Delta v_{\epsilon}- h(\nabla v_{\epsilon})
 \leq  -\Delta \eta_i e -h(\eta_i\nabla e)  \quad\text{in }  \Omega, \\
 v_\epsilon  \leq  \eta_ie   \quad\text{on }  \partial\Omega.
\end{gather*}
Using again \cite[Theorem 10.1]{gt}, we get
$v_{\epsilon}\leq \eta_{i}e$. From \cite[Theorem 3.7]{gt} and
 hypothesis (4) it follows that
\[
\sup_{\Omega} e\leq \epsilon + \exp(d(\Omega))-1\leq 1.
\]
Then we obtain
\[
H_{0}(\eta_{i})\leq H_{\epsilon}(\eta_{i})\leq v_{\epsilon}
\leq \eta_{i}e\leq\eta_{i}.
\]
Now we consider the non decreasing sequence
$\{u_k\}\subset C^{2,\gamma}_{loc}(\Omega)\cap C(\overline\Omega)$,
defined by $u_{k} = H^{k}_{0}(A^{2}(\xi_{i}\kappa))$. We deduce
\begin{equation}\label{tu}
A^{2}(\xi_{i}\kappa)\leq H^{k}_{0}(A^{2}(\xi_{i}\kappa))\leq H_{0}(\eta_{i}),
\end{equation}
and by definition
\begin{gather*}
-\Delta u_k  =  g(u_k)+h(\nabla u_k)+f(u_{k-1}) \quad \text{in }\Omega ,\\
        u_k  =  0 \quad \text{on }\partial\Omega.
\end{gather*}
On the other hand, by (\ref{tu}) there holds
\[
\| u_k\|_{L^\infty(\Omega')}\leq C,\quad
\| g(u_k)\|_{L^\infty(\Omega')}\leq C,
\]
where $\overline\Omega'\subset\Omega$ and $C$ is a constant
independent of $k$. \cite[Theorem 15.8]{gt} implies
\[
\| \nabla u_k\|_{L^\infty(\Omega')}\leq C.
\]
where $C$ is a constant independent of $k$.
By \cite[Theorem 9.11]{gt},
\[
\|  u_k\|_{\mathcal{W}^{2,r}(\Omega')}
\leq C(\| u_k\|_{L^r(\Omega')}+C)\leq C,
\]
with $r>N$. By the Sobolev imbedding \cite[Theorem 7.26]{gt},
$u_k\to u$ in $C^{1,\gamma}(\Omega')$. A standard bootstrap
argument implies that $u\in C^2(\Omega)\cap C(\overline\Omega)$
is a classical solution of problem (\ref{a}) in the interval
$[A^{2}(\xi_{i}\kappa),\eta_{i}]$.
\end{proof}

\begin{proof}[Proof of Theorem \ref{inner}]
Let $P$ the positive cone in the space $L^\infty(\Omega)$.
Let $\mathcal{H}_\epsilon:P\to P$ be the solution operator
of the problem
\begin{gather*}
-\Delta z  =  z^{-p}+f(u)  \quad\text{in }\Omega,\\
        z  =  \epsilon  \quad\text{on }\partial\Omega,
\end{gather*}
gives  $\mathcal{H}_\epsilon(u)=z$. Using Theorem \ref{H},
we deduce that $\mathcal{H}_\epsilon:P\to P$ is a well defined,
continuous, non increasing and compact map with
$\mathcal{H}_{\epsilon_0}(u)\leq\mathcal{H}_{\epsilon_1}(u)$
for $\epsilon_0<\epsilon_1$.

Let $\mathcal{T}_\epsilon:P\to P$ be the solution operator
of the problem
\begin{gather*}
-\Delta z +\frac{z|\nabla z|^2}{1+\epsilon z|\nabla z|^2}
 =  z^{-p}+f(u)  \quad\text{in }\Omega,\\
        z  =  \epsilon  \quad\text{on }\partial\Omega,
\end{gather*}
gives  $\mathcal{T}_\epsilon(u)=z$. By Lemma \ref{adel}, we infer
that $\mathcal{T}_\epsilon:P\to P$  is a well defined,
continuous, non increasing and compact map with
$\mathcal{T}_{\epsilon_0}(u)\leq\mathcal{T}_{\epsilon_1}(u)$
for $\epsilon_0<\epsilon_1$. From
\begin{align*}
-\Delta \mathcal{T}_{\epsilon}(u)
& \leq  -\Delta \mathcal{T}{_\epsilon(u)}+\frac{\mathcal{T}_\epsilon(u)|\nabla \mathcal{T}_\epsilon(u)|^2}{1+\epsilon \mathcal{T}_\epsilon(u)|\nabla \mathcal{T}_\epsilon(u)|^2} \\
& =  u^{-p}+f(u)\\
& =  -\Delta\mathcal{H}_\epsilon (u)\quad\text{in }\Omega ,
\end{align*}
and $\mathcal{T}_{\epsilon}(u)=\mathcal{H}_\epsilon (u)$ on
$\partial\Omega$ implies
$\mathcal{T}_{\epsilon}(u)\leq\mathcal{H}_\epsilon (u)$ in $P$.
\begin{align*}
-\Delta (\mathcal{H}_\epsilon (\eta_i))
& =  (\mathcal{H}_\epsilon (\eta_i))^{-p}+f(\eta_i) \\
& \leq   (\mathcal{H}_\epsilon (0))^{-p}+\alpha\eta_i \\
& =  -\Delta( \mathcal{H}_\epsilon (0)+\alpha\eta_i(-\Delta)^{-1}1)
\quad\text{in }\Omega.
\end{align*}
 From $-\Delta(-\Delta)^{-1}1=1$ in $\Omega$ and
$(-\Delta)^{-1}1=0$ on $\partial\Omega$, we implies
$\mathcal{H}_\epsilon (\eta_i)=\mathcal{H}_\epsilon (0)
+\alpha\eta_i(-\Delta)^{-1}1$ on $\partial\Omega$.
Therefore,
$\mathcal{H}_\epsilon (\eta_i)\leq \mathcal{H}_\epsilon (0)
+\alpha\eta_i(-\Delta)^{-1}1$ in $\Omega$. By condition
(4), for $\epsilon$ small enough
\begin{equation}
\mathcal{H}_\epsilon (\eta_i)<\eta_i
\end{equation}
By hypothesis (3), we have
\begin{align*}
-\Delta \mathfrak{u} +\mathfrak{u}|\nabla \mathfrak{u}|^2
& =  \beta\xi_i\kappa\\
& =  -\Delta \mathfrak{v}+ \frac{\mathfrak{v}|\nabla\mathfrak{v}|^2}
 {1+\epsilon\mathfrak{v}|\nabla\mathfrak{ v}|^2}\\
& \leq  -\Delta \mathfrak{v}+\mathfrak{v}|\nabla\mathfrak{v}|^2
\quad\text{in }\Omega,
\end{align*}
and  $\mathfrak{u}=0<\epsilon=\mathfrak{v}$ on
$\partial\Omega$. Therefore \cite[Theorem 10.1]{gt} implies
$\mathfrak{v}\geq\mathfrak{u}\geq \xi_i\kappa$. From
\begin{align*}
-\Delta\mathcal{T}_\epsilon(\xi_i\kappa)
+ \frac{\mathcal{T}_\epsilon(\xi_i\kappa)|
\nabla\mathcal{T}_\epsilon(\xi_i\kappa)|^2}
{1+\epsilon\mathcal{T}_\epsilon(\xi_i\kappa)
|\nabla\mathcal{T}_\epsilon(\xi_i\kappa)|^2 }
&= (\mathcal{T}_\epsilon(\xi_i\kappa))^{-p} +f(\xi_i\kappa)\\
& \geq  \beta\xi_i\kappa \\
& =  -\Delta\mathfrak{v}+ \frac{\mathfrak{v}|\nabla
\mathfrak{v}|^2}{1+\epsilon\mathfrak{v}|\nabla \mathfrak{v}|^2}
\quad\text{in }\Omega,
\end{align*}
and $\mathcal{T}_\epsilon(\xi_i\kappa)=\epsilon=\mathfrak{v}$
on $\partial\Omega$ implies
$\mathcal{T}_\epsilon(\xi_i\kappa)\geq \mathfrak{v}\geq \mathfrak{u}
\geq \xi_i\kappa$. It follows that
$\mathcal{T}_\epsilon[\xi_i\kappa,\eta_i]\subset
[\xi_i\kappa,\eta_i]$, and so there exists a fixed
point $u_{i,\epsilon}$ of $\mathcal{T}_\epsilon$ in
$[\xi_i\kappa,\eta_i]$ for $\epsilon$ small enough.
By a compensated compactness method, the ``Murat's lemma'',
the ``Fatou lemma technique'' of Freshe (see \cite[Theorem 3.4]{s})
 and Lemma \ref{adel}, letting
$u_i=\lim_{\epsilon\searrow 0}u_{i,\epsilon}$, we have
$u_i\in[\xi_i\kappa,\eta_i]$ belongs  to $H^{1,2}_0(\Omega)$.
Moreover, $u_i$ solves problem ($\ref{alice}$).
\end{proof}

\begin{proof}[Proof of Theorem \ref{blowup}]
Using the identity
\[
\Delta (\frac{1}{u})=\frac{2}{u^3}|\nabla u|^2-\frac{1}{u^2}\Delta u
\]
If $u$ solves the equation
\begin{gather*}
-\Delta u  =  u^{2-p}+f(u)    \quad\text{in }\Omega, \\
        u  =  0  \quad\text{on }  \partial\Omega.
\end{gather*}
Then
\[
\Delta(\frac{1}{u})=u\frac{2}{u^4}|\nabla u|^2+u^{-p}+\frac{1}{u^2}f(u)
\]
Calling $z=\frac{1}{u}$, we conclude
\begin{gather*}
-\Delta z  =  \frac{2}{z}|\nabla z|^2+z^p+z^2f(\frac{1}{z})
  \quad\text{in }\Omega, \\
        z  =  \infty    \quad\text{on }  \partial\Omega.
\end{gather*}
Using the hypothesis of Theorem \ref{11}, we conclude the proof.
\end{proof}


\begin{proof}[Proof of Theorem \ref{supercritico}]
Let us to define the function
\[
g_0(s) =  \begin{cases}
s^{2-q}-s^{2-p} & \text{if }s>(\frac{q-2}{p-2})^{\frac{1}{q-p}}\\
\big(\frac{q-2}{p-2}\big)^{2-q}-\big(\frac{q-2}{p-2}\big)^{2-p}
& \text{if } s\leq(\frac{q-2}{p-2})^{\frac{1}{q-p}}
\end{cases}
\]
Using Lemma \ref{H} with $g(u)=g_0(u+\frac{1}{\epsilon})$,
we can define the solution operator $z=H_{1/\epsilon}(h)$
of the problem
\begin{gather*}
-\Delta z  =  g_0(z)+h     \quad\text{in }\Omega, \\
        z  =  \frac{1}{\epsilon}    \quad\text{on }\partial\Omega.
\end{gather*}
Moreover, this operator is well defined
$H_{1/\epsilon}:\{h\in L^\infty(\Omega)| h\geq0\}\to\{z\in
C(\overline{\Omega})| z\geq 0\}$, it is continuous,
non decreasing and compact. Therefore, we can define
$z=A_{1/\epsilon}(u):\{u\in L^\infty(\Omega)| h\geq0\}
\to\{z\in C(\overline{\Omega})| z\geq0\}$, the continuous,
increasing and compact solution operator of the problem
\begin{gather*}
-\Delta z  =  g_0(z)+f(u)   \quad\text{in }\Omega \\
        z  =  \frac{1}{\epsilon}   \quad\text{on }\partial\Omega.
\end{gather*}
If $\kappa$ is the indicator function of the set $K$, as in the
proof of Theorem \ref{11}, we deduce
\[
A_{1/\epsilon}(\xi_i\kappa)\geq\xi_i\kappa\,.
\]
 From $A_{1/\epsilon}(0)<A_{1/\epsilon}(\eta_i)$, we get
$g(A_{1/\epsilon}(\eta_i))<g(A_{1/\epsilon}(0))$. Therefore,
\begin{align*}
-\Delta A_{1/\epsilon}(\eta_i)
& =  g\big(A_{1/\epsilon}(\eta_i)\big)+f(\eta_i)  \\
& \leq  g\big(A_{1/\epsilon}(0)\big)+\alpha\eta_i  \\
& =  -\Delta\big(A_{1/\epsilon}(0)+\alpha\eta_ie\big)
\end{align*}
Where
\begin{align*}
-\Delta e & =  1     \quad\text{in }\Omega, \\
        z & =  \frac{1}{\epsilon}    \quad\text{on }\partial\Omega.
\end{align*}
The maximum principle implies
\[
A_{1/\epsilon}(\eta_i)\leq A_{1/\epsilon}(0)+\alpha\eta_ie
\]
By condition (4), it holds $A_{1/\epsilon}(0)+\alpha\eta_ie\leq\eta_i$.
Therefore $A_{1/\epsilon} [\xi_i\kappa,\eta_i] \subset
[  \xi_i\kappa,\eta_i ]$. By construction
$A_{1/\epsilon}:P\to P$ where $P$ is the positive cone
in $L^\infty(\Omega)$. The interior of $P$ is nonempty, so we
deduce the existence of $2m-1$ different solutions of the equation
\begin{equation}\label{fix}
A_{1/\epsilon}(u)=u
\end{equation}
If $\frac{1}{\epsilon}\geq(\frac{q-2}{p-2})^{\frac{1}{q-p}}$,
then a solution of equation (\ref{fix}), solves the problem
\begin{gather*}
-\Delta u  =  u^{2-q}-u^{2-p}+f(u)   \quad\text{in }\Omega, \\
        u  =  \frac{1}{\epsilon}  \quad\text{on }  \partial\Omega.
\end{gather*}
From
\[
\Delta (\frac{1}{u})  =
 \frac{2}{u^3}|\nabla u|^2-\frac{1}{u^2}\Delta u ,
\]
We infer
\[
\Delta (\frac{1}{u}) = u\frac{2}{u^4}|\nabla u|^2+u^{-q}-u^{-p}
+\frac{1}{u^2}f(u) .
\]
If we define $z=\frac{1}{u}$, we have
\begin{gather*}
\Delta z =  \frac{2}{z}|\nabla z|^2+z^{q}-z^{p}+z^2f(\frac{1}{z})
 \quad\text{in }\Omega, \\
z  =  \epsilon   \quad\text{on }  \partial\Omega,
\end{gather*}
and we complete the proof
\end{proof}

\subsection*{Acknowledgments}
The  author would like  to express  gratitude with
the French Oil Institut at Rueil Malmaison.


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