\documentclass[reqno]{amsart}
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\AtBeginDocument{{\noindent\small
\emph{Electronic Journal of Differential Equations},
Vol. 2019 (2019), No. 10, pp. 1--27.\newline
ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu}
\thanks{\copyright 2019 Texas State University.}
\vspace{8mm}}

\begin{document}
\title[\hfilneg EJDE-2019/10\hfil Doubly nonlocal Fisher-KPP equations]
{Existence and properties of traveling waves for doubly
 nonlocal Fisher-KPP equations}

\author[D. Finkelshtein, Y. Kondratiev, P. Tkachov \hfil EJDE-2019/10\hfilneg]
{Dmitri Finkelshtein, Yuri Kondratiev, Pasha Tkachov}

\address{Dmitri Finkelshtein \newline
Department of Mathematics,
Swansea University, Bay Campus,
 Fabian Way, Swansea SA1 8EN, UK}
\email{d.l.finkelshtein@swansea.ac.uk}

\address{Yuri Kondratiev \newline
Fakult\"{a}t f\"{u}r Mathematik,
Universit\"{a}t Bielefeld, Postfach 110 131,
33501 Bielefeld, Germany}
\email{kondrat@math.uni-bielefeld.de}

\address{Pasha Tkachov \newline
Gran Sasso Science Institute,
Viale Francesco Crispi, 7,
67100 L'Aquila AQ, Italy}
\email{pasha.tkachov@gssi.it}


\thanks{Submitted July 2, 2018. Published Janaury 22, 2019.}
\subjclass[2010]{35C07, 35K57, 45G10}
\keywords{Nonlocal diffusion; reaction-diffusion equation; Fisher-KPP equation; 
\hfill\break\indent traveling waves; nonlocal nonlinearity;
 anisotropic kernels; integral equation}

\begin{abstract}
 We consider a reaction-diffusion equation with nonlocal anisotropic
 diffusion and a linear combination of local and nonlocal monostable-type
 reactions in a space of bounded functions on $\mathbb{R}^d$.
 Using the properties of the corresponding semiflow, we prove the existence
 of monotone traveling waves along those directions where the diffusion
 kernel is exponentially integrable. Among other properties,
 we prove continuity, strict monotonicity and exponential integrability
 of the traveling wave profiles.
\end{abstract}

\maketitle
\numberwithin{equation}{section}
\newtheorem{theorem}{Theorem}[section]
\newtheorem{lemma}[theorem]{Lemma}
\newtheorem{corollary}[theorem]{Corollary}
\newtheorem{definition}[theorem]{Definition}
\newtheorem{proposition}[theorem]{Proposition}
\newtheorem{remark}[theorem]{Remark}
\allowdisplaybreaks

\section{Introduction}

\subsection{Description of equation}
We  study the initial value problem
\begin{equation}
 \begin{gathered}
 \frac{\partial u}{\partial t}(x,t)
=\kappa^+(a^{+}*u)(x,t)-m u(x,t)-u(x,t) (Gu)(x,t),\quad t>0,\\
 u(x,0)=u_0(x),
 \end{gathered} \label{eq:basic}
\end{equation}
where
\begin{equation}\label{eq:defofG}
 (Gu)(x,t):=\kappa_{\ell} u(x,t) + \kappa_{n\ell} ( a^-*u )(x,t),
\end{equation}
which generates a semi-flow $u(\cdot,0)\mapsto u(\cdot,t)$, $t>0$, 
in a class of bounded nonnegative functions on ${\mathbb{R}^d}$, $d\geq1$. Here
$\kappa^+, m>0$ and $\kappa_{\ell}, \kappa_{n\ell}\geq0$ are constants, such that
\begin{equation}\label{eq:kaminusissum}
 \kappa^- := \kappa_{\ell}+\kappa_{n\ell} > 0;
\end{equation}
and the functions $0\leq a^\pm \in L^{1}({\mathbb{R}^d})$ are probability densities, i.e.
\begin{equation}\label{normed}
 \int_{{\mathbb{R}^d} }a^+(y)dy=\int_{{\mathbb{R}^d} }a^-(y)dy=1.
\end{equation}
The symbol $*$ denotes the convolution with respect to the space variable, i.e.
\[
(a^\pm*u)(x,t):=\int_{{\mathbb{R}^d} }a^\pm(x-y)u(y,t)dy.
\]

The solution $u=u(x,t)$ describes the local density of a species at the point 
$x\in{\mathbb{R}^d}$ at the moment of time $t\geq0$. The individuals of the species spread 
over the space ${\mathbb{R}^d}$ according to the dispersion kernel $a^+$ and the fecundity 
rate $\kappa^+$. The individuals may die according to both constant mortality 
rate $m$ and density dependent competition, described by the rate $\kappa^-$. 
The competition may be \emph{local}, when the density $u(x,t)$ at a point $x$ 
is influenced by itself only, with the rate $\kappa_{\ell}$, or \emph{nonlocal}, 
when the density $u(x,t)$ is influenced by all values $u(y,t)$, $y\in{\mathbb{R}^d}$, 
averaged over ${\mathbb{R}^d}$ according to the competition kernel $a^-$ with the rate $\kappa_{n\ell}$.

For the case $\beta:=\kappa^+ -m>0$,  equation \eqref{eq:basic} can be rewritten 
in the reaction-diffusion form
\begin{equation}\label{eq:RDform}
\begin{aligned}
 \frac{\partial u}{\partial t}(x,t)
&=\kappa^+ \int_{\mathbb{R}^d} a^+(x-y)\bigl(u(y,t)-u(x,t)\bigr)\,dy\\
&\quad +u(x,t)\bigl(\beta - (Gu)(x,t)\bigr).
\end{aligned}
\end{equation}
The first summand here describes a non-local diffusion generator, 
see e.g.\ \cite{AMRT2010} (also known as the generator of a continuous time random 
walk in ${\mathbb{R}^d}$ or of a compound Poisson process on ${\mathbb{R}^d}$).
 As a result, the solution $u$ to \eqref{eq:RDform} may be interpreted 
as a density of a species which invades according to a nonlocal diffusion 
within the space ${\mathbb{R}^d}$ meeting a reaction $Fu:=u(\beta -Gu)$; 
see e.g.\ \cite{Fif1979,Mur2003,SK1997}.

The non-local diffusion in reaction-diffusion equations first appeared 
(for the case $d=1$) in the seminal paper \cite{KPP1937} by Kolmogorov, Petrovsky 
and Piskunov, to~describe a dynamics where individuals move during the 
time between birth and reproduction meeting a local reaction $Fu=f(u)=u(1-u)^2$.
 Using a diffusive scaling, the equation in \cite{KPP1937} was informally 
transformed to
\begin{equation}\label{kpp}
 \frac{\partial u}{\partial t}(x,t)=\alpha \Delta u(x,t)+f\bigl(u(x,t)\bigr),
\end{equation}
where $\Delta$ denotes the Laplace operator, $\alpha>0$. The choice of the 
local reaction $f(u)=u(1-u)^2$ was motivated by a discrete genetic model. 
Equation \eqref{kpp} was studied in \cite{KPP1937}, for a class of 
reactions which includes also, in particular,
\[
 f(u)=u(1-u)
\]
that corresponds to $\kappa_{n\ell}=0$, $\kappa_{\ell}=1$, $\beta=1$ in \eqref{eq:defofG} 
and \eqref{eq:RDform}. The latter reaction was early considered by 
Fisher in \cite{Fis1937} for another genetic model. 
The Fisher-KPP equation \eqref{kpp} has been actively studied and 
generalized since then, see e.g. \cite{AW1978,HR2016,Saa2003} 
and references therein.

Later,  equation \eqref{eq:RDform} with local $G$, i.e.\ 
with $\kappa_{n\ell}=0$ in \eqref{eq:defofG}, was considered in \cite{Sch1980} 
(motivated by an analogy to Kendall's epidemic model) and has been actively 
studied in the last decade, see e.g.\
 \cite{AGT2012,CY2017,CDM2008a,  CD2007, Gar2011,LSW2010,SLW2011,Yag2009} 
for $d=1$ and \cite{CDM2008,SZ2010} for $d\geq1$.

Equation \eqref{eq:RDform} with pure nonlocal $G$, i.e.\
with $\kappa_{\ell}=0$, $\kappa^- =\kappa_{n\ell}$ in \eqref{eq:defofG}, first appeared, 
for the case $\kappa^+ a^+=\kappa^- a^-$, $m=0$, in \cite{Mol1972a,Mol1972}. 
Next, it was derived from a lattice `crabgrass model', for the 
case $\kappa^+ a^+=\kappa^- a^-$, $m>0$ in \cite{Dur1988} and latter considered 
in \cite{PS2005}.

Note also that, in the pure nonlocal case $\kappa_{\ell}=0$, the microscopic 
(individual-based) model of spatial ecology corresponding to  
equation \eqref{eq:basic} was proposed by Bolker and Pacala in \cite{BP1997}. 
In this case,  equation \eqref{eq:basic} can be rigorously derived 
in a proper scaling limit of the corresponding multi-particle evolution; 
see \cite{FM2004} for integrable species densities and \cite{FKKozK2014,FKK2011a} 
for bounded ones.

In this article, we consider a unified approach to both local and nonlocal 
competition terms in \eqref{eq:basic}.

\subsection{Description of results}
 Clearly, $u\equiv0$ is a constant stationary solution to \eqref{eq:basic}.
We will assume in the sequel that
\begin{equation}\label{as:chiplus_gr_m}
 \kappa^+ >m.
\end{equation}
Then  equation \eqref{eq:basic} has the unique positive constant 
stationary solution $u\equiv\theta$, where
\begin{equation}\label{theta_def}
 \theta:=\frac{\kappa^+ -m}{\kappa^- }>0.
\end{equation}

Our primary object of investigation are monotone traveling waves, 
which connect $0$ and $\theta$. Let $\mathcal{M}_\theta(\mathbb{R})$ denote the set of all decreasing 
and right-continuous functions $f:\mathbb{R}\to[0,\theta]$. By a (monotone) traveling 
wave solution to \eqref{eq:basic} in a direction $\xi\in S^{d-1}$ 
(the unit sphere in ${\mathbb{R}^d}$), we will understand a solution of the form
\begin{equation}\label{eq:deftrw}
 \begin{gathered}
 u(x,t)=\psi(x\cdot\xi-ct), \quad t\geq0, \quad \text{a.a. } x\in{\mathbb{R}^d}, \\
 \psi(-\infty)=\theta, \quad \psi(+\infty)=0,
 \end{gathered}
\end{equation}
where $c\in\mathbb{R}$ is called the speed of the wave and the function $\psi\in\mathcal{M}_\theta(\mathbb{R})$
is called the profile of the wave.
Here and below $x\cdot \xi$ denotes the scalar product in ${\mathbb{R}^d}$. 
Such solutions are also called in literature as traveling planes, 
see e.g.\ \cite{Eva2010}.

Define the function
\begin{equation}\label{diffofkernels}
 J_\theta(x):=\kappa^+ a^+(x)-\kappa_{n\ell} \theta a^-(x),\quad x\in{\mathbb{R}^d}.
\end{equation}
For a fixed $\xi\in S^{d-1} $, we introduce the following assumptions:
\begin{equation}\label{as:aplus_gr_aminus-intro}
 \int_{\{x\cdot\xi=s\}} J_\theta(x)\,dx\geq0 \quad \text{for a.a. } s\in\mathbb{R},
\end{equation}
cf. \eqref{apm1dim}, \eqref{acheckpos} below, and
\begin{equation}\label{aplusexpint1}
 \text{there exists $\mu=\mu(\xi)>0$ such that }
 \int_{\mathbb{R}^d} a^+(x) e^{\mu \, x\cdot \xi}\,dx<\infty.
\end{equation}
Stress that assumption \eqref{as:aplus_gr_aminus-intro} is redundant
for the case of the local $G$, when $\kappa_{n\ell}=0$, i.e.\
 for the case of the local reaction $Fu=f(u)=u(\beta -\kappa_{\ell} u)$.

We will also use the following counterpart of \eqref{as:aplus_gr_aminus-intro}: 
there exist $\rho,\delta>0$ (depending on $\xi$), such that
 \begin{equation}\label{as:aplus-aminus-is-pos1d}
 \int_{\{x\cdot\xi=s\}} J_\theta(x)\,dx \geq\rho \quad \text{for a.a. }
 |s|\leq \delta.
\end{equation}
The following theorem is the main result of this article.

\begin{theorem}\label{thm:trwexist}
Let $\xi\in S^{d-1} $ be fixed, and suppose that 
\eqref{as:chiplus_gr_m}, \eqref{as:aplus_gr_aminus-intro}, \eqref{aplusexpint1} hold.
Then there exists $c_*(\xi)\in\mathbb{R}$, such that for any $c<c_*(\xi)$, 
a traveling wave solution to \eqref{eq:basic} of the 
form \eqref{eq:deftrw} with $\psi\in\mathcal{M}_\theta(\mathbb{R})$ does not exist; whereas, 
for any $c\geq c_*(\xi)$,
\begin{enumerate}
 \item there exists a traveling wave solution to \eqref{eq:basic} 
with the speed $c$ and a profile $\psi\in\mathcal{M}_\theta(\mathbb{R})$ such that \eqref{eq:deftrw} holds;

 \item if $c\neq0$, then the profile $\psi\in C_b^\infty(\mathbb{R})$ 
(the class of infinitely many times differentiable functions on $\mathbb{R}$ 
with bounded derivatives); if $c=0$ (in the case $c_*(\xi)\leq 0$),
 then $\psi\in C(\mathbb{R})$;

 \item there exists $\mu=\mu( c, a^+, \kappa^-, \theta)>0$ such that
 \begin{equation}\label{eq:trwexpint}
 \int_\mathbb{R}\psi(s)e^{\mu s}\,ds<\infty;
 \end{equation}

\item let \eqref{as:aplus-aminus-is-pos1d} hold, then the profile $\psi$ 
is a strictly decreasing function on $\mathbb{R}$;

 \item let \eqref{as:aplus-aminus-is-pos1d} hold, then, for any $c\neq0$, 
there exists $\nu>0$, such that $\psi(t)e^{\nu t}$ is a strictly increasing 
function.
\end{enumerate}
\end{theorem}

\begin{remark} \rm
The last two items of Theorem~\ref{thm:trwexist} will be proven in 
Propositions~\ref{prop:psidecaysstrictly} and \ref{prop:trw_willbe_incr}
 below under assumptions weaker than \eqref{as:aplus-aminus-is-pos1d}.
\end{remark}

\begin{remark} \rm
The results of \cite{FKT100-3, FT2017c} show that the assumption 
\eqref{aplusexpint1} is `almost' necessary to have traveling wave solutions 
in equation \eqref{eq:basic}.
\end{remark}

By a solution to \eqref{eq:basic} on $[0,T)$, $T\leq \infty$, we will understand 
the so-called classical solution, that is a mapping from $[0,T)$ to a 
Banach space $E$ of bounded functions on ${\mathbb{R}^d}$ which is continuous in $t\in[0,T)$, 
continuously differentiable (in the sense of the norm in $E$) in $t\in(0,T)$, 
and satisfies \eqref{eq:basic}. The space $E$ is either the space $L^{\infty}({\mathbb{R}^d})$
of essentially bounded (with respect to the Lebesgue measure) functions on 
${\mathbb{R}^d}$ with $\operatorname{ess\,sup}$-norm, or its Banach subspaces $C_b({\mathbb{R}^d})$ or $ C_{ub}(\mathbb{R}^d)$
of bounded continuous or, respectively, bounded uniformly continuous 
functions on ${\mathbb{R}^d}$ with $\sup$-norm.

According to \eqref{eq:defofG}, we consider the mapping
\begin{equation}\label{eq:defofmapG}
 Gu:=\kappa_{\ell} u+ \kappa_{n\ell} a^-*u, \quad u\in E.
\end{equation}
Clearly, $G$ maps $E$ to $E$ and preserves the cone $\{0\leq u\in E\}$.
Here and below, all point-wise inequalities for functions from $E$ we 
 consider, for the case $E=L^\infty({\mathbb{R}^d})$, almost everywhere only. 
Moreover, the mapping $G$ is globally Lipschitz on~$E$. 
In particular, it satisfies the conditions of \cite[Theorem 2.2]{FT2017a} 
that can be read, in our case, as follows.

 \begin{theorem}[{\cite[Theorems 2.2, 3.3]{FT2017a}}]\label{thm:existuniq}
Let $0\leq a^\pm\in L^1({\mathbb{R}^d})$, $m>0$, $\kappa_{\ell},\kappa_{n\ell}\geq0$ be such that 
\eqref{eq:kaminusissum} and \eqref{normed} hold.
Then, for any $0\leq u_0\in E$ and for any $T>0$, there exists a 
unique classical solution $u$ to \eqref{eq:basic} on $[0,T)$. 
In particular, $u$ is a unique classical solution to \eqref{eq:basic} 
on $[0,\infty)$.
\end{theorem}

For any $t\geq0$ and $0\leq f\in L^\infty({\mathbb{R}^d})$, we define
\begin{equation}
 (Q_{t}f)(x):=u(x,t),\quad \text{a.a. } x\in{\mathbb{R}^d},\label{def:Q_T}
\end{equation}
where $u(x,t)$ is the solution to \eqref{eq:basic} with the initial 
condition $u(x,0)=f(x)$.
From the uniqueness arguments and the proof of \cite[Theorems~2.2, 3.3]{FT2017a}, 
we immediately get that $(Q_t)_{t\geq0}$ constitutes a continuous semi-flow 
on the cone $\{0\leq f\in L^\infty({\mathbb{R}^d})\}$, i.e. $Q_t$ is continuous 
at $t=0$ and
\[
 Q_{t+s}f=Q_t(Q_s f), \quad t,s\geq0,
\]
for each $0\leq f\in L^\infty({\mathbb{R}^d})$.

It can be checked (see Proposition~\ref{prop:statsol} below) that 
$u\equiv 0$ is an unstable solution to \eqref{eq:basic} and that the 
following reinforced version of \eqref{as:aplus_gr_aminus-intro},
\begin{equation}\label{as:aplus_gr_aminus}%\tag{\ref{as:aplus_gr_aminus-intro}${}'$}
 J_\theta(x)\geq 0,\quad \text{a.a.}\ x\in{\mathbb{R}^d},
\end{equation}
is a sufficient condition to that $u\equiv\theta$ is a uniformly and 
asymptotically stable solution, in the sense of Lyapunov.

Similarly to above, the assumption \eqref{as:aplus_gr_aminus} is 
redundant for the case of the local $G$, when $\kappa_{n\ell}=0$, 
$Fu=f(u)=u(\beta -\kappa_{\ell} u)$.


In \cite[Proposition 5.4]{FT2017a}, we considered properties of the 
semi-flow $Q_t$ generated by  equation \eqref{eq:basic}, cf.~\eqref{def:Q_T}, 
with a general $G$ which satisfies a list of conditions. We will show in 
Subsection~\ref{subsec:checkQ1-Q5} below, that $G$ given by \eqref{eq:defofmapG} 
fulfills these conditions, that will imply the items 
\ref{eq:QBtheta_subset_Btheta}--\ref{prop:Q_cont} of the following statement. 
We define the tube
\begin{equation}\label{eq:tube}
 E^+_\theta:=\{u\in E\mid 0\leq u\leq\theta\}.
\end{equation}
For the case $d=1$, we recall also that $\mathcal{M}_\theta(\mathbb{R})$ denotes the set of all decreasing 
and right-continuous functions $f:\mathbb{R}\to[0,\theta]$, cf.~Remark~\ref{rem:inclus} 
below.

\begin{theorem}[{\cite[Proposition 5.4]{FT2017a}}]\label{thm:Qholds}
Let \eqref{as:chiplus_gr_m} and \eqref{as:aplus_gr_aminus} hold. 
Let $E=L^\infty({\mathbb{R}^d})$ and $(Q_t)_{t\geq0}$ be the semi-flow \eqref{def:Q_T} 
on the cone $\{0\leq f\in L^\infty({\mathbb{R}^d})\}$. Then, for each $t>0$, 
$Q=Q_t$ satisfies the following properties:
\begin{enumerate}[label=\textnormal{(Q\arabic*)}]
 \item $Q$ maps each of sets $E^+_\theta$, $E^+_\theta\cap C_b({\mathbb{R}^d})$, 
$E^+_\theta\cap C_{ub}(\mathbb{R}^d)$ into itself; \label{eq:QBtheta_subset_Btheta}

 \item let $T_y$, $y\in{\mathbb{R}^d}$, be a translation operator, given 
by \label{prop:QTy=TyQ}
 \begin{equation}\label{shiftoper}
 (T_y f)(x)=f(x-y), \quad x\in{\mathbb{R}^d},
 \end{equation}
 then
 \begin{equation}
 (Q T_{y}f)(x)=(T_{y}Qf)(x), \quad x,y\in{\mathbb{R}^d},\ f\in E^+_\theta;\label{eq:QTy=TyQ}
 \end{equation}

 \item $Q0=0$, $Q\theta=\theta$, and $Q r>r$, for any constant 
$r\in(0,\theta)$; \label{prop:Ql_gr_l}

 \item if $f,g\in E^+_\theta$, $f \leq g $, then $Qf \leq Qg$; 
\label{prop:Q_preserves_order}
 \item if $f_n,f\in E^+_\theta$, $f_{n}\xRightarrow{\rm loc} f$, then
 $(Qf_{n})(x)\to (Qf)(x)$ for (a.a.) $x\in{\mathbb{R}^d}$; \label{prop:Q_cont}

 \item if $d=1$, then $Q:\mathcal{M}_\theta(\mathbb{R})\to\mathcal{M}_\theta(\mathbb{R})$.\label{prop:Q_Mtheta}
 \end{enumerate}
\end{theorem}

 Here and below $\xRightarrow{\rm loc}$ denotes the locally uniform convergence of functions 
on ${\mathbb{R}^d}$ (in other words, $f_n 1\!\!1_\Lambda$ converge to $f 1\!\!1_\Lambda$ in $E$, for 
each compact $\Lambda\subset{\mathbb{R}^d}$).

The property \ref{eq:QBtheta_subset_Btheta} states that the solution 
$u(\cdot,t)$ remains in the tube $E_\theta^+$ for all $t>0$ if only 
$u(\cdot,0)$ is in this tube. In Remark~\ref{rem:necineq} below, we will 
show that, under \eqref{as:chiplus_gr_m}, the assumption 
\eqref{as:aplus_gr_aminus} is necessary to the fact that the set $E_\theta^+$ 
is invariant for $Q_t$, $t>0$.

The property \ref{prop:Q_preserves_order} means that the comparison principle 
holds for the solutions to \eqref{eq:basic}. Namely, if $u_1,u_2$ are 
classical solutions to \eqref{eq:basic} on $\mathbb{R}_+$ and 
$0\leq u_{1}(x,0)\leq u_{2}(x,0)\leq \theta$, $x\in{\mathbb{R}^d}$, then, for all 
$t\in\mathbb{R}_+$, (a.a.) $x\in{\mathbb{R}^d}$,
 \begin{equation}\label{eq:comparineq}
 0\leq u_{1}(x,t)\leq u_{2}(x,t) \leq \theta.
 \end{equation}
 See also Proposition~\ref{prop:fullcomp} below.

Our proof for the first part of Theorem~\ref{thm:trwexist} is based on an 
abstract result, for the case $d=1$, by Yagisita \cite{Yag2009} for a 
continuous semi-flow which satisfies \ref{prop:QTy=TyQ}--\ref{prop:Q_Mtheta} 
on $\mathcal{M}_\theta(\mathbb{R})$ and has an appropriate super-solution (see Proposition~\ref{prop:trwexists} 
below for details). As an application, Yagisita considered a generalization 
of  equation \eqref{eq:basic} with a local $G$ in \eqref{eq:defofG}, 
i.e.\ with $\kappa_{n\ell}=0$ (and for $d=1$).

Early, in \cite{CDM2008}, it was shown how to reduce the study of traveling 
waves of the form \eqref{eq:deftrw} for the case $d>1$ to the study of the 
case $d=1$, cf. Proposition~\ref{prop:monot_sol} below; and, for a continuous 
anisotropic kernel $a^+$ and for also a generalization of a local $G$ 
in \eqref{eq:defofG}, the traveling waves for \eqref{eq:basic} were 
studied using the technique of sub- and super-solutions; see also \cite{SLW2011}. 
For generalizations in the case of local reaction depending on space variable 
(i.e.\ $\kappa_{n\ell}=0$ and $\kappa_{\ell}, m$ depend on $x$), see e.g. \cite{LZ2016,S-S2016}

The case of a nonlocal $G$ in \eqref{eq:basic}--\eqref{eq:defofG} appeared more 
difficult for analysis. The only known results for the case $\kappa_{n\ell}\neq 0$ in 
\eqref{eq:defofG} were obtained in \cite{YY2013,WZ2006} for the case of 
a symmetric quickly decaying kernel $a^+$, the latter mean that the integral 
in \eqref{aplusexpint1} is finite \emph{for all} $\mu>0$.

In this paper, we find an upper estimate for $c_*(\xi)$, see 
\eqref{cstarestimate} and \eqref{aplusexpla} below.
Note that the present and forthcoming papers \cite{FKT100-2,FKT100-3} 
are based on our unpublished preprint \cite{FKT2015} and thesis \cite{Tka2017}. 
In particular, in \cite{FKT100-2}, we will prove that the 
estimate \eqref{cstarestimate} is, as a matter of fact, equality, namely,
\[
 c_*(\xi)=\min_{\lambda>0} \frac{1}{\lambda}\Big(\kappa^+ \int_{\mathbb{R}^d} a^+(x) e^{\lambda x\cdot \xi}\,dx 
-m \Big).
\]
(that coincides with the result in \cite{CDM2008} for $\kappa_{n\ell}=0$).
We will find also in \cite{FKT100-2} the exact asymptotic of the profile
 $\psi$ at $\infty$, that implies, in particular, \eqref{eq:trwexpint}. 
Note that, the quite technical result \eqref{eq:trwexpint} is crucial for 
the analysis of traveling waves used in \cite{FKT100-2} which is based on 
the usage of the Laplace transform.

It is worth noting also that, in \cite{Wei1982a}, Weinberger considered 
spreading speeds of a discrete-time dynamical system $u_{n}=Qu_{n-1}$ 
constructed by a mapping $Q$ on $E=C_b({\mathbb{R}^d})$ which satisfies the 
properties \ref{eq:QBtheta_subset_Btheta}--\ref{prop:Q_cont}. 
He has also obtained results about a traveling wave solution (in discrete time), 
however, under an additional assumption that $Q$ is a compact mapping on 
$E=C_b({\mathbb{R}^d})$ in the topology of the locally uniform convergence. 
The traveling wave appeared the limit of a subsequence of appropriately 
chosen sequence $(u_n)_{n\in\mathbb{N}}$. However, for equation \eqref{eq:basic},
 it is unclear how to check whether the operator $Q=Q_t$, given by 
\eqref{def:Q_T}, is compact on $E=C_b({\mathbb{R}^d})$ even for the local $G$ in 
\eqref{eq:defofG} ($\kappa_{n\ell}=0$); and hence we can't apply Weinberger's results. 
On the other hand, Yagisita in \cite{Yag2009} has pointed out that, 
considering traveling waves \eqref{eq:deftrw} with monotone profiles $\psi$, 
the existence of the limit above follows from Helly's theorem, 
which implies that $Q$ is compact on $\mathcal{M}_\theta(\mathbb{R})$ in the topology of the locally 
uniform convergence. Note also that a modification of Weinberger's results 
about spreading speeds for continuous time for  equation \eqref{eq:basic} 
with an arbitrary $u_0\in E_\theta^+$ will be considered in \cite{FKT100-3}.


This paper is organized as follows. In Section~\ref{sec:semiflow}, we 
check properties \ref{eq:QBtheta_subset_Btheta}--\ref{prop:Q_cont} 
of Theorem~\ref{thm:Qholds}, and prove the strong maximum principle for 
the case $E= C_{ub}(\mathbb{R}^d)$ (see Theorem~\ref{thm:strongmaxprinciple}, cf. 
e.g.\ \cite{CDM2008} for $\kappa_{n\ell}=0$).
In Section~\ref{sec:tr-waves}, we prove \ref{prop:Q_Mtheta} 
(see Proposition~\ref{prop:Qtilde}) and Theorem~\ref{thm:trwexist}.

\section{Properties of semi-flow}\label{sec:semiflow}

\subsection{Verification of properties 
\ref{eq:QBtheta_subset_Btheta}--\ref{prop:Q_cont}}\label{subsec:checkQ1-Q5}
to this end we to use \cite[Proposition 5.4]{FT2017a}, and  
check the assumptions of the latter statement. 
Let the mapping $G$ be given by \eqref{eq:defofmapG}. Then,
 under \eqref{as:chiplus_gr_m},  by \eqref{theta_def}, we have
\begin{equation}\label{eq:oldA2}
 0=G0\leq Gv \leq G\theta=\kappa^+ -m, \quad v\in E_\theta^+,
\end{equation}
cf. \eqref{eq:tube}. Moreover, it is easy to see that
\begin{equation}\label{eq:oldA8}
 Gr<\kappa^+ -m, \quad r\in(0,\theta).
\end{equation}
Note also, that, for $T_y$, $t\in{\mathbb{R}^d}$ given by \eqref{shiftoper}, we evidently have
\begin{equation}\label{eq:oldA7}
 (T_yGv)(x)=(GT_yv)(x), \quad x\in{\mathbb{R}^d}, \ v\in E_\theta^+.
\end{equation}

We denote also by
\begin{equation}\label{eq:defH}
 Hu:=\kappa^+ a^+*u-mu-u Gu
\end{equation}
the right-hand side of  \eqref{eq:basic}.

Let \eqref{as:aplus_gr_aminus} hold.
Then, for $u,v\in E_\theta^+$ with $u\leq v$, we have,
 by \eqref{theta_def}, \eqref{eq:defofmapG}, that $0\leq Gv\leq \kappa^+ -m$ 
and $Gv-Gu=\kappa_{\ell}(v-u)+\kappa_{n\ell} a^-*(v-u)$, and hence
\begin{align*}
Hv-Hu&=\kappa^+ a^+*(v-u)-m(v-u)-(v -u)Gv-u(Gv-Gu) \\
&\geq J_\theta*(v-u)-(\kappa^+ +\theta \kappa_{\ell})(v -u).
\end{align*}
Therefore, there exists $p=\kappa^+ +\theta \kappa_{\ell}>0$, such that the operator $H$ 
is quasi-monotone on $E^+_\theta$, namely,
\begin{equation}\label{eq:HisQuasiMon}
 Hu+pu\leq Hv+pv, \quad u,v\in E_\theta^+, \ u\leq v.
\end{equation}
We will use also the following simple lemmas in the sequel.

\begin{lemma}\label{le:simple}
 Let $a\in L^1({\mathbb{R}^d})$, $f\in E$. Then $a*f\in C_{ub}(\mathbb{R}^d)$.
 Moreover, if $v\in C_b(I\to E)$, $I\subset\mathbb{R}_+$, then
 $a*v\in C_b(I\to  C_{ub}(\mathbb{R}^d))$.
\end{lemma}

\begin{proof}
 The convolution is a bounded function, as
 \begin{equation}\label{convbdd}
 |(a*f)(x)|\leq \|f\|_E \,\|a\|_{L^1({\mathbb{R}^d})}, \quad a\in L^1({\mathbb{R}^d}), f\in E.
 \end{equation}
 Next, let $a_n\in C_0({\mathbb{R}^d})$, $n\in\mathbb{N}$, be such that $\|a-a_n\|_{L^1({\mathbb{R}^d})}\to0$, 
$n\to\infty$. For any $n\geq1$, the proof of that $a_n*f\in C_{ub}(\mathbb{R}^d)$ is 
straightforward. Next, by \eqref{convbdd}, $\|a*f-a_n*f\|_E\to0$, $n\to\infty$.
 Hence $a*u$ is a uniform limit of uniformly continuous functions that 
fulfills the proof of the first statement. The second statement is followed 
from the first one and the inequality \eqref{convbdd}.
\end{proof}

 \begin{lemma}\label{convluc}
Let $a\in L^1({\mathbb{R}^d})$, $\{f_n,f\}\subset L^\infty({\mathbb{R}^d})$, $\|f_n\|\leq C$, 
for some $C>0$, and $f_n\xRightarrow{\rm loc} f$.
Then $a*f_n \xRightarrow{\rm loc} a*f$.
\end{lemma}

\begin{proof}
 Let $\{a_m\}\subset C_0({\mathbb{R}^d})$ be such that $\|a_m-a\|_{L^1({\mathbb{R}^d})}\to0$, 
$m\to\infty$, and denote $A_m:=\mathrm{supp}\, a_m$. Note that, there exists 
$D>0$, such that $\|a_m\|_{L^1({\mathbb{R}^d})}\leq D$, $m\in\mathbb{N}$. Next, for any compact 
$\Lambda\subset{\mathbb{R}^d}$,
 \begin{align}
 | 1\!\!1_\Lambda (x) (a_m*(f_n-f))(x)|&\leq \int_{\mathbb{R}^d}  1\!\!1_{A_m}(y) 
 1\!\!1_\Lambda (x) |a_m(y)| |f_n(x-y)-f(x-y)|\,dy\notag\\
 &\leq \|a_m\|_{L^1({\mathbb{R}^d})} \| 1\!\!1_{\Lambda_m}(f_n-f)\|\to0, n\to\infty, 
\label{eq:justappeared}
 \end{align}
for some compact $\Lambda_m\subset{\mathbb{R}^d}$. Next,
 \begin{align*}
 \| 1\!\!1_\Lambda (a*(f_n-f))\|
&\leq\| 1\!\!1_\Lambda (a_m*(f_n-f))\|+\| 1\!\!1_\Lambda ((a-a_m)*(f_n-f))\| \\
&\leq D\| 1\!\!1_{\Lambda_m}(f_n-f)\|+(C+\|f\|)\|a-a_m\|_{L^1({\mathbb{R}^d})},
 \end{align*}
 and the second term may be arbitrary small by a choice of $m$.
\end{proof}

\begin{remark}\label{rem:contofconvaa} \rm
By the first inequality in \eqref{eq:justappeared} and the dominated 
convergence theorem, we can conclude that $f_n(x)\to f(x)$ a.e.\
 implies that $(a*f_n)(x)\to (a*f)(x)$ a.e.
\end{remark}

By Lemma~\ref{convluc}, both operators $Av=\kappa^+ a^+*v $ and 
$Gv=\kappa_{\ell} v+\kappa_{n\ell} a^-*v$ are continuous in the topology of the locally 
uniformly convergence.

Because of \eqref{eq:oldA2}, \eqref{eq:oldA8}, \eqref{eq:oldA7}, 
\eqref{eq:HisQuasiMon}, and the continuity of $G$ in both uniform and 
locally uniform convergences inside the tube $E_\theta^+$, one 
can apply \cite[Proposition 5.4]{FT2017a} to get the 
properties \ref{eq:QBtheta_subset_Btheta}--\ref{prop:Q_cont} 
of Theorem~\ref{thm:Qholds}.

\begin{remark} \rm
We assumed in \cite{FT2017a} also that the condition \eqref{as:a+nodeg} 
below holds, however, it is straightforward to check that this was not 
used to prove \cite[Proposition 5.4]{FT2017a}.
\end{remark}

\subsection{The comparison principle}
For each $0\leq T_1<T_2<\infty$, let $\mathcal{X}_{T_1,T_2}$ denote the Banach 
space of all continuous mappings from $[T_1,T_2]$ to $E$ with the norm
\[
 \|u\|_{T_1,T_2}:=\sup_{t\in[T_1,T_2]}\|u(\cdot,t)\|_E.
\]
For any $T>0$, we set also $\mathcal{X}_T:=\mathcal{X}_{0,T}$ and consider the subset 
$\mathcal{U}_T\subset\mathcal{X}_T$ of all mappings which are continuously differentiable on 
$(0,T]$. Here and below, we consider the left derivative at $t=T$ only. 
We consider also the vector space $\mathcal{X}_\infty$ of all continuous mappings 
from $\mathbb{R}_+$ to $E$.

Note that, by \eqref{eq:HisQuasiMon}, we can apply \cite[Theorem~2.3]{FT2017a} 
to get the following statement, which is nothing but the combination 
of \ref{eq:QBtheta_subset_Btheta} and \ref{prop:Q_preserves_order}.

\begin{proposition}\label{prop:compar}
Let \eqref{as:chiplus_gr_m} and \eqref{as:aplus_gr_aminus} hold. 
Let functions $u_1,u_2$ be classical solutions to \eqref{eq:basic} on 
$\mathbb{R}_+$ with the corresponding initial conditions which satisfy 
$0\leq u_{1}(x,0)\leq u_{2}(x,0)\leq \theta$ for (a.a.) $x\in{\mathbb{R}^d}$. 
Then \eqref{eq:comparineq} holds. In particular, $0\leq u(\cdot,0)\leq \theta$ 
for (a.a.) $x\in{\mathbb{R}^d}$ implies that $0\leq u(x,t)\leq\theta$ for $t>0$ and 
(a.a.) $x\in{\mathbb{R}^d}$.
\end{proposition}

\begin{remark}\label{rem:necineq} \rm
Condition \eqref{as:aplus_gr_aminus} is a necessary one for 
Proposition~\ref{prop:compar}. Indeed, let  condition \eqref{as:aplus_gr_aminus} 
fail in a ball $B_{r}(y_0)$ only, ${r}>0$, $y_0\in{\mathbb{R}^d}$, i.e.\ $J_\theta(x)<0$, 
for a.a.\ $x\in B_{r}(y_0)$, where $J_\theta$ is given by \eqref{diffofkernels}. 
Take any $y\in B_{r}(y_0)$ with $\frac{{r}}{4}<|y-y_0|<\frac{3{r}}{4}$, 
then $y_0\notin B_{\frac{{r}}{4}}(y)$ whereas 
$B_{\frac{{r}}{4}}(y)\subset B_{r}(y_0)$.
Take $u_0\in C_{ub}(\mathbb{R}^d)$ such that $u_0(x)=\theta$, 
$x\in {\mathbb{R}^d}\setminus B_{\frac{{r}}{4}}(y_0-y)$, and $u_0(x)< \theta$, 
$x\in B_{\frac{{r}}{4}}(y_0-y)$. Since 
$\int_{\mathbb{R}^d} J_\theta(x)\,dx=\kappa^+ -\kappa_{n\ell}\theta=m+\kappa_{\ell}\theta$, one has
\begin{align*}
\frac{\partial u}{\partial t}(y_0,0)
&=-(m+\kappa_{\ell}\theta)\theta+\kappa^+ (a^+*u)(y_0,0)-\kappa_{n\ell}\theta (a^-*u)(y_0,0) \\
&=(J_\theta*u)(y_0,0)-(\kappa^+ -\kappa_{n\ell}\theta)\theta=(J_\theta*(u_0-\theta))(y_0)\\
&=\int_{B_{\frac{{r}}{4}}(y)} J_\theta(x)(u_0(y_0-x)-\theta)\,dx>0, 
\end{align*}
Therefore, $u(y_0,t)>u(y_0,0)=\theta$, for small enough $t>0$, and hence, 
the statement of Proposition~\ref{prop:compar} does not hold in this case.
\end{remark}

As a simple corollary of \ref{eq:QBtheta_subset_Btheta}--\ref{prop:Q_cont}, 
we will show that the semi-flow $(Q_t)_{t\geq0}$ preserves functions 
which are monotone along a given direction. More precisely,
a function $f\in L^\infty({\mathbb{R}^d})$ is said to be increasing 
(decreasing, constant) along the vector $\xi\in S^{d-1} $ (recall that 
$ S^{d-1} $ denotes a unit sphere in ${\mathbb{R}^d}$ centered at the origin) if, 
for a.a.\ $x\in{\mathbb{R}^d} $, the function
$f(x+s\xi)=(T_{-s\xi}f)(x)$ is increasing (decreasing, constant) in 
$s\in\mathbb{R}$, respectively.

\begin{proposition}\label{prop:monot_along_vector_sol}
Let \eqref{as:chiplus_gr_m} and \eqref{as:aplus_gr_aminus} hold. 
Let $u_0\in E^+_\theta$ be the initial condition for equation \eqref{eq:basic}
 which is increasing (decreasing, constant) along a vector 
$\xi\in S^{d-1} $; and $u(\cdot,t)\in E^+_\theta$, $t\geq0$, be the 
corresponding solution (cf. Proposition~\ref{prop:compar}). 
Then, for any $t>0$, $u(\cdot,t)$ is increasing (decreasing, constant, respectively)
 along the $\xi$.
\end{proposition}

\begin{proof}
Let $u_0$ be decreasing along a $\xi\in S^{d-1} $. Take any $s_1\leq s_2$ 
and consider two initial conditions to \eqref{eq:basic}: 
$u_0^i(x)=u_0(x+s_i\xi)=(T_{-s_i\xi}u_0)(x)$, $i=1,2$. 
Since $u_0$ is decreasing, $u_0^1(x)\geq u_0^2(x)$, $x\in{\mathbb{R}^d}$. 
Then, by Theorem~\ref{thm:Qholds},
\[
T_{-s_1\xi}Q_tu_0=Q_tT_{-s_1\xi}u_0=Q_t u_0^1\geq Q_tu_0^2=Q_tT_{-s_2\xi}u_0=
T_{-s_2\xi}Q_tu_0,
\]
that proves the statement. The cases of a increasing $u_0$ can be 
considered in the same way. The constant function along a vector is 
increasing and decreasing simultaneously.
\end{proof}

For each $T>0$ and $u\in\mathcal{U}_T$, one can define
\begin{equation}\label{Foper}
 (\mathcal{F}u)(x,t):=\frac{\partial u}{\partial t}(x,t)
-\kappa^+ (a^{+}*u)(x,t)+mu(x,t)+u(x,t) \bigl( Gu \bigl)(x,t)
\end{equation}
for all $t\in(0,T]$ and $x\in{\mathbb{R}^d}$ (a.a.\ $x\in{\mathbb{R}^d}$ in the case $E=L^\infty({\mathbb{R}^d})$).

By \cite[Theorem~2.3]{FT2017a}, we will also get the following counterpart 
of Proposition~\ref{prop:compar}.

 \begin{proposition}\label{prop:fullcomp}
 Let \eqref{as:chiplus_gr_m} and \eqref{as:aplus_gr_aminus} hold. 
Let $T>0$ be fixed and $u_1,u_2\in\mathcal{U}_T$ be such that, for all $t\in(0,T]$, $x\in{\mathbb{R}^d}$,
 \begin{gather}
 (\mathcal{F}u_1)(x,t)\leq (\mathcal{F}u_2)(x,t),\label{eq:max_pr_BUC:ineq}\\
 0 \leq u_1(x,t)\leq\theta, \quad 0 \leq u_2(x,t)\leq \theta,\notag\\
 0\leq u_{1}(x,0)\leq u_{2}(x,0)\leq \theta.\notag
 \end{gather}
Then \eqref{eq:comparineq} holds for all $t\in[0,T]$, $x\in{\mathbb{R}^d}$.
 \end{proposition}

Below, for technical reasons, we will need to extend the result of 
Proposition~\ref{prop:fullcomp} to a wider class of functions in the 
case $E= C_{ub}(\mathbb{R}^d)$. Namely, the expression \eqref{Foper} is well-defined for
 a.a.\ $t$ if the function $u$ is absolutely continuous in $t$ only.
 In view of this, for any $T\in(0,\infty]$, we define the set 
$\mathscr{D}_T$ of all functions $u:{\mathbb{R}^d}\times\mathbb{R}_+\to\mathbb{R}$, such that, for all 
$t\in[0,T)$, $u(\cdot,t)\in  C_{ub}(\mathbb{R}^d)$, and, for all $x\in{\mathbb{R}^d}$, the function 
$f(x,t)$ is absolutely continuous in $t$ on $[0,T)$. Then, for any 
$u\in\mathscr{D}_T$, one can define the function \eqref{Foper}, for all 
$x\in{\mathbb{R}^d}$ and a.a.\ $t\in[0,T)$.

\begin{proposition}\label{compprabscont}
The statement of Proposition~\ref{prop:fullcomp} remains true, if we 
assume that $u_1,u_2\in\mathscr{D}_T$ and, for any $x\in{\mathbb{R}^d}$, the 
inequality \eqref{eq:max_pr_BUC:ineq} holds for a.a.\ $t\in(0,T)$ only.
\end{proposition}

\begin{proof}
 One can literally follow the proof of \cite[Theorem~4.2]{FT2017a}:
 the auxiliary function $v(x,t):=e^{Kt}(u_{2}(x,t)-u_{1}(x,t))$ with 
large enough $K>0$ will satisfy a proper differential equation
 $\frac{d}{dt}v(x,t)=\Theta(t,v(x,t))$, see \cite[(4.12)]{FT2017a}, 
for a.a.\ $t\in[0,T]$. However, the corresponding integral equation 
$v(x,t)=v(x,0)+\int_0^t \Theta(s,v(x,s))\,ds$ holds still for all 
$t\in[0,T]$, since $v$ is continuous in $t$. Hence, the rest of the 
proof remains the same.
\end{proof}

We are going to show now that any solution to \eqref{eq:basic} is bounded 
from below by a solution to the corresponding equation with `truncated' 
kernels~$a^\pm$.
Namely, suppose that the conditions \eqref{as:chiplus_gr_m}, 
\eqref{as:aplus_gr_aminus} hold. Consider a family of Borel sets 
$\{\Delta_R\mid R>0\}$, such that $\Delta_R\nearrow{\mathbb{R}^d}$, $R\to\infty$. 
Define, for any $R>0$, the following kernels:
\begin{equation}\label{trkern}
 a_R^{\pm}(x)= 1\!\!1_{\Delta_R}(x)a^{\pm}(x),\quad x\in{\mathbb{R}^d},
\end{equation}
and the corresponding `truncated' equation, cf.\ \eqref{eq:basic},
\begin{equation}
 \begin{gathered}
 \begin{aligned}
 \frac{\partial w}{\partial t}(x,t)
&= \kappa^+ (a_R^+*w)(x,t)-mw(x,t) - \kappa_{\ell} w^2(x,t) \\
 &\quad -\kappa_{n\ell} w(x,t)(a_R^-*w)(x,t), \quad x\in{\mathbb{R}^d},\; t>0,
 \end{aligned}\\
 w(x,0)=w_{0}(x), \quad  x\in{\mathbb{R}^d}.
 \end{gathered}\label{eq:basic_R}
\end{equation}
We set
\begin{equation}\label{ARdef}
 A_R^\pm:=\int_{\Delta_R}a^\pm(x)\,dx \nearrow 1, \quad R\to\infty,
\end{equation}
by \eqref{normed}. Then the non-zero constant solution to \eqref{eq:basic_R} 
is equal to
\begin{equation}\label{defofthetaR}
 \theta_R=\frac{\kappa^+ A_R^+-m}{\kappa_{n\ell} A_R^- + \kappa_{\ell}}\to \theta, \quad R\to\infty,
\end{equation}
however, the convergence $\theta_R$ to $\theta$ is, in general, not monotonic. 
Clearly, by~\eqref{as:chiplus_gr_m}, $\theta_R>0$ if only
\begin{equation}\label{bigR}
 A_R^+>\frac{m}{\kappa^+ }\in(0,1).
\end{equation}

\begin{proposition}\label{lowestsuppCub}
Let \eqref{as:chiplus_gr_m} and \eqref{as:aplus_gr_aminus} hold, and
 let $R>0$ be such that \eqref{bigR} holds, cf.~\eqref{ARdef}. 
Let $w_0\in E$ be such that $0\leq w_0\leq \theta_R,\ x\in{\mathbb{R}^d}$. 
Then there exists the unique solution $w\in\mathcal{X}_{\infty}$ to \eqref{eq:basic_R}, such that
\begin{equation}\label{wlessthetaR}
0\leq w(x,t)\leq\theta_R, \quad x\in{\mathbb{R}^d},\ t>0.
\end{equation}
Let $u_0\in E_\theta^+$ and $u\in\mathcal{X}_{\infty}$ be the corresponding solution 
to \eqref{eq:basic}. If $w_0(x)\leq u_0(x), x\in {\mathbb{R}^d}$, then
\begin{equation}\label{ineqtrunc}
w(x,t)\leq u(x,t),\quad x\in{\mathbb{R}^d}, \; t>0.
\end{equation}
\end{proposition}

\begin{proof}
Denote $\Delta_R^c:={\mathbb{R}^d}\setminus \Delta_R$. We have
\begin{align*}
 \theta-\theta_R &= \frac{\kappa_{n\ell} \theta A^-_R + \kappa_{\ell} \theta
 - \kappa^+ A^+_R+m}{\kappa^- (\kappa_{n\ell} A^-_R+\kappa_{\ell})}
 =\frac{\kappa^+ (1-A^+_R)-\kappa_{n\ell} \theta (1-A^-_R)}{\kappa^- (\kappa_{n\ell} A^-_R+\kappa_{\ell})}\\
 &=\frac{1}{\kappa^- (\kappa_{n\ell} A^-_R + \kappa_{\ell})}\int_{\Delta_R^c}\bigl( \kappa^+ a^+(x)
-\kappa_{n\ell} \theta a^-(x)\bigr)\,dx\geq0,
\end{align*}
by \eqref{as:aplus_gr_aminus}. Therefore,
\begin{equation}\label{thetaRlesstheta}
 0<\theta_R\leq\theta.
\end{equation}
Clearly, \eqref{as:aplus_gr_aminus} and \eqref{thetaRlesstheta} yield
\begin{equation}\label{as:aplus_geq_aminus_R}
\kappa^+ a_R^+(x)\geq \theta_R\kappa^- a_R^-(x),\quad x\in{\mathbb{R}^d}.
\end{equation}
Thus one can apply Proposition~\ref{prop:compar} to \eqref{eq:basic_R} 
using trivial equalities $a^\pm_R(x)=A_R^\pm \tilde{a}^\pm_R(x)$,
 where the kernels $\tilde{a}^\pm_R(x)=(A_R^\pm)^{-1}a^\pm_R(x)$ are normalized, 
cf. \eqref{normed}; and the inequality \eqref{as:aplus_geq_aminus_R} 
is the corresponding analog of \eqref{as:aplus_gr_aminus}, 
according to \eqref{defofthetaR}. This proves the existence and uniqueness
 of the solution to \eqref{eq:basic_R} and the bound \eqref{wlessthetaR}.

Next, for $\mathcal{F}$ given by \eqref{Foper}, one gets from \eqref{trkern}
and \eqref{eq:basic_R}, that the solution $w$ to \eqref{eq:basic_R} satisfies 
the  equality
\begin{equation}
\begin{aligned}
 (\mathcal{F}w)(x,t)=&-\kappa^+ \int_{\Delta_R^c} a^+(y) w(x-y,t)\,dy\\
&+\kappa_{n\ell} w(x,t)\int_{\Delta_R^c} a^-(y)w(x-y,t)\,dy.\label{dopR}
\end{aligned}
\end{equation}
By \eqref{wlessthetaR}, \eqref{thetaRlesstheta}, \eqref{as:aplus_gr_aminus},
one gets from \eqref{dopR} that
\begin{align*}
(\mathcal{F}w)(x,t)
&\leq-\kappa^+ \int_{\Delta_R^c} a^+(y) w(x-y,t)\,dy
 + \kappa_{n\ell}\theta\int_{\Delta_R^c} a^-(y)w(x-y,t)\,dy \\
&\leq 0=(\mathcal{F}u)(x,t),
\end{align*}
 where $u$ is the solution to \eqref{eq:basic}. Therefore, we may apply
Proposition~\ref{prop:fullcomp} to get the statement.
\end{proof}

In the following two propositions we consider results about stability 
of stationary solutions to \eqref{eq:basic}.

According to the proof of \cite[Theorems 2.2, 3.4]{FT2017a}, which 
implies Theorem~\ref{thm:existuniq}, the solution $u(x,t)$ to \eqref{eq:basic} 
may be obtained on an arbitrary time interval $[0,T]$ as follows. 
There exist $m\in\mathbb{N}$ and $0=:\tau_0<\tau_1<\dots<\tau_m$ with $\tau_m\geq T$,
such that for each $[\tau, \widehat{\tau}]:=[\tau_{k-1},\tau_k]$, $1\leq k\leq m$, 
there exists $r_k>0$, such that, for any $v\in \mathcal{X}_{\tau,\widehat{\tau}}$ 
with $0\leq v\leq r_k$, $u=\lim_{n\to\infty}\Phi_\tau ^n v$ in
$\mathcal{X}_{\tau,\widehat{\tau}}$, where
\begin{gather}
(\Phi_\tau v)(x,t)
 :=(Bv)(x,\tau,t)u_\tau(x) +\int_\tau^t(Bv)(x,s,t)\kappa^+ (a^{+}*v)(x,s)\,ds,
\label{eq:exist_uniq_BUC:Phi_v} \\
(Bv)(x,s,t):=\exp\Big(-\int _{s}^t\bigl(m+(Gv)(x,p)\bigr)\,dp\Big),
\label{eq:exist_uniq_BUC:B}
\end{gather}
for $x\in{\mathbb{R}^d}$, $t,s\in[\tau,T]$, and $G$ is given by \eqref{eq:defofG}.
By the uniqueness arguments, we will immediately get the following proposition.

\begin{proposition}\label{prop:startwithconst}
 Let $t_0\geq0$ be such that the solution $u$ to \eqref{eq:basic} is a constant 
in space at the moment of time $t_0$, namely, $u(x,t_0)\equiv u(t_0)\geq0$, 
$x\in{\mathbb{R}^d}$. Then  this solution will be a constant in space for all further moments 
of time. In particular, if \eqref{as:chiplus_gr_m} holds 
(and hence $\beta=\kappa^+ -m>0$), then
\begin{equation}\label{homogensol}
 u(x,t)= u(t)
=\frac{\theta u(t_0)}{u(t_0) (1-e^{-\beta t}) +\theta e^{-\beta t}}\geq0, 
\quad x\in{\mathbb{R}^d}, \ t\geq t_0,
\end{equation}
and $u(t)\to \theta$, $t\to\infty$.
\end{proposition}

\begin{remark} \rm
 Note that \eqref{homogensol} solves the classical logistic equation
 \begin{equation}\label{eq:homogen}
 \frac{d}{dt} u(t)=\kappa^- u(t) (\theta - u(t)), \quad t>t_0,\quad u(t_0)\geq0.
 \end{equation}
\end{remark}

We are going to study stability of constant stationary solutions to \eqref{eq:basic}.

\begin{proposition}\label{prop:statsol}
Let \eqref{as:chiplus_gr_m} and \eqref{as:aplus_gr_aminus} hold. 
Then $u^*\equiv \theta$ is a uniformly and asymptoticaly stable solution 
to \eqref{eq:basic}, whereas $u_*\equiv 0$ is an unstable solution 
to~\eqref{eq:basic}.
\end{proposition}

\begin{proof}
Let $H$ and $J_\theta$ be given by \eqref{eq:defH} and \eqref{diffofkernels}, 
correspondingly. Find the linear operator $H'(u)$ on $E$: namely, for $v\in E$,
\begin{equation}\label{derofG}
 H'(u)v=\kappa^+ (a^+*v)-mv-\kappa_{n\ell} v(a^-*u)-\kappa_{n\ell} u(a^-*v)-2\kappa_{\ell} uv.
\end{equation}
Therefore, by \eqref{diffofkernels},
\[
 H'(\theta)v =J_\theta*v-(\kappa^+ +\kappa_{\ell}\theta) v.
\]
By \eqref{diffofkernels}, $\int_{\mathbb{R}^d} J_\theta(x)\,dx = \kappa^+{-}\kappa_{n\ell}\theta$, 
thus, the spectrum $\sigma(A)$ of the operator $Av:=J_\theta *v$ on $ C_{ub}(\mathbb{R}^d)$ 
is a subset of $\{|z|\leq \kappa^+{-}\kappa_{n\ell}\theta\}\subset \mathbb{C}$. Therefore,
\[
 \sigma(H'(\theta)) \subset \bigl\{z\in\mathbb{C}: 
 |z+\kappa^+ +\kappa_{\ell}\theta|\leq \kappa^+{-}\kappa_{n\ell}\theta\bigr\}.
\]
Therefore, $\sigma(H'(\theta)) \subset \{z\in\mathbb{C}\mid \mathrm{Re}\, z<0\}$.
 Hence, by e.g.\ \cite[Chapter VII]{DK1974}, $u^*\equiv\theta$ is uniformly 
and asymptotically stable solution in the sense of Lyapunov.

Next, by \eqref{derofG},
$H'(0)v=\kappa^+ (a^+*v)-mv$. If \eqref{as:chiplus_gr_m} holds, then the 
operator $H'(0)$ has an eigenvalue $\kappa^+ -m>0$ whose corresponding 
eigenfunctions will be constants on ${\mathbb{R}^d}$. Therefore $\sigma(H'(0))$ has 
points in the right half-plane and since $H''(0)$ exists, one has, again 
by \cite[Chapter VII]{DK1974}, that $u_*\equiv0$ is unstable.
\end{proof}

\subsection{Strong maximum principle}
Now we are going to study the maximum principle for solutions to \eqref{eq:basic} 
in the space $E= C_{ub}(\mathbb{R}^d)$.
For this case, we denote $ U_\theta:=E_\theta^+$.

We introduce also the following assumption:
there exist $\rho,\delta>0$ such that, cf. \eqref{diffofkernels},
\begin{equation}\label{as:aplus-aminus-is-pos}
%\tag{\ref{as:aplus-aminus-is-pos1d}${}'$}
 J_\theta(x)=\kappa^+ a^{+}(x)-\kappa_{n\ell} \theta a^{-}(x)\geq\rho \quad \text{for a.a. } 
|x|\leq\delta.
\end{equation}
Clearly, \eqref{as:aplus-aminus-is-pos} implies \eqref{as:aplus-aminus-is-pos1d} 
and implies also that the following condition holds: 
there exist $\rho,\delta>0$, such that
\begin{equation}\label{as:a+nodeg}\tag{\ref{as:a+nodeg1d}${}'$}
a^{+}(x)\geq\rho \text{ \ for a.a. } |x|\leq \delta.
\end{equation}

It is straightforward to check that, under assumptions 
\eqref{as:chiplus_gr_m}, \eqref{as:aplus_gr_aminus}, \eqref{as:a+nodeg}, 
one can apply \cite[Proposition 5.2]{FT2017a}, that yields the following 
statement about strict positivity of solutions to \eqref{eq:basic}.
\begin{proposition}\label{prop:u_gr_0}
Let $E= C_{ub}(\mathbb{R}^d)$ and \eqref{as:chiplus_gr_m}, \eqref{as:aplus_gr_aminus}, 
\eqref{as:a+nodeg}
hold. Let $u_0\in  U_\theta$, $u_0\not\equiv0$, $u_0\not\equiv\theta$, 
be the initial condition to \eqref{eq:basic}, and $u\in\mathcal{X}_{\infty}$ be the 
corresponding solution. Then
\[
u(x,t)>\inf_{\substack{y\in{\mathbb{R}^d} \\ s>0}}u(y,s)\geq0, \quad x\in{\mathbb{R}^d}, t>0.
\]
\end{proposition}

In contrast to the case of the infimum, the solution to \eqref{eq:basic} 
may attain its supremum but not the value $\theta$. As a matter of fact,
 under \eqref{as:aplus-aminus-is-pos}, a much stronger statement than 
unattainability of $\theta$ does hold.

\begin{theorem}\label{thm:strongmaxprinciple}
Let $E= C_{ub}(\mathbb{R}^d)$ and \eqref{as:chiplus_gr_m}, \eqref{as:aplus_gr_aminus}, 
\eqref{as:aplus-aminus-is-pos} hold. Let $u_1,u_2\in\mathcal{X}_{\infty}$ be two solutions 
to \eqref{eq:basic}, such that $0\leq u_1(x,t)\leq u_2(x,t)\leq\theta$, 
$x\in{\mathbb{R}^d}$, $t\geq0$. Then either $u_1(x,t)= u_2(x,t)$, $x\in{\mathbb{R}^d}$, $t\geq0$ or
$u_1(x,t)< u_2(x,t)$, $x\in{\mathbb{R}^d}$, $t>0$.
\end{theorem}

\begin{proof}
Let $u_1(x,t)\leq u_2(x,t)$, $x\in{\mathbb{R}^d}$, $t\geq0$, and suppose that there exist 
$t_0>0$, $x_0\in{\mathbb{R}^d} $, such that $u_1(x_0,t_0)=u_2(x_0,t_0)$. 
Define $w:=u_2-u_1\in\mathcal{X}_{\infty}$. Then $w(x,t)\geq0$ and $w(x_0,t_0)=0$, 
hence $\frac{\partial}{\partial t}w(x_0,t_0)=0$. Since both $u_1$ and $u_2$ 
solve \eqref{eq:basic}, one easily gets that $w$ satisfies the following 
linear equation
\begin{equation}\label{lineareqw}
\begin{aligned}
 \frac{\partial}{\partial t}w(x,t)
&= (J_\theta* w)(x,t) + \kappa_{n\ell}(\theta-u_1(x,t))(a^-*w)(x,t)\\
&\quad  -w(x,t)\bigl(\kappa_{\ell} \bigl(u_2(x,t)+u_1(x,t)\bigl)
 + \kappa_{n\ell}(a^-*u_2)(x,t) +m \bigr);
\end{aligned}
\end{equation}
or, at the point $(x_0,t_0)$, we will have
\begin{equation}\label{atx0t0}
 0 = (J_\theta* w)(x_0,t_0) + \kappa_{n\ell}(\theta-u_1(x_0,t_0))(a^-*w)(x_0,t_0).
\end{equation}
Since the both summands in \eqref{atx0t0} are nonnegative, one has
$(J_\theta* w)(x_0,t_0)=0$. Then, by \eqref{as:aplus-aminus-is-pos},
 we have that $w(x,t_0)=0$, for all $x\in B_\delta (x_0)$.
Using the same arguments as in the proof of \cite[Proposition 5.2]{FT2017a},
one gets that $w(x,t_0)=0$, $x\in{\mathbb{R}^d}$.
Then, by Proposition~\ref{prop:startwithconst}, $w(x,t)=0$, $x\in{\mathbb{R}^d}$, $t\geq t_0$.
Finally, one can reverse the time in the linear equation \eqref{lineareqw}
(cf.\ the proof of \cite[Proposition 5.2]{FT2017a}), and the uniqueness
arguments imply that $w\equiv 0$, i.e. $u_1(x,t)= u_2(x,t)$, $x\in{\mathbb{R}^d}$, $t\geq0$.
The statement is proved.
\end{proof}

By choosing $u_2\equiv\theta$ in Theorem~\ref{thm:strongmaxprinciple}, 
we immediately get the following result.

\begin{corollary}\label{cor:lesstheta}
Let $E= C_{ub}(\mathbb{R}^d)$ and \eqref{as:chiplus_gr_m}, \eqref{as:aplus_gr_aminus}, 
\eqref{as:aplus-aminus-is-pos} hold. Let $u_0\in  U_\theta$, $u_0\not\equiv\theta$, 
be the initial condition to \eqref{eq:basic}, and $u\in\mathcal{X}_{\infty}$ be the corresponding 
solution. Then $u(x,t)<\theta$, $x\in{\mathbb{R}^d}$, $t>0$.
\end{corollary}

\section{Traveling waves}\label{sec:tr-waves}

Through this section, $E=L^\infty({\mathbb{R}^d})$. Similarly to the above, we denote 
by $\mathcal{U}_\infty$ the subset of $\mathcal{X}_\infty$ of all continuously differentiable 
mappings from $(0,\infty)$ to $E$.
Recall that $\mathcal{M}_\theta(\mathbb{R})$ denotes the set of all decreasing and right-continuous 
functions $f:\mathbb{R}\to[0,\theta]$.

\begin{remark}\label{rem:inclus} \rm
 There is a natural embedding of $\mathcal{M}_\theta(\mathbb{R})$ into $L^\infty(\mathbb{R})$. 
According to this, for a function $f\in L^\infty(\mathbb{R})$, the inclusion $f\in\mathcal{M}_\theta(\mathbb{R})$ 
means that there exists $g\in\mathcal{M}_\theta(\mathbb{R})$, such that $f=g$ a.s.\ on $\mathbb{R}$.
\end{remark}

Recall also the definition of a traveling wave solution.

\begin{definition}\label{def:trw}
A function $u\in \mathcal{U}_\infty$ is said to be a traveling
wave solution to \eqref{eq:basic} with
a speed $c\in\mathbb{R}$ and in a direction $\xi\in S^{d-1} $ if there
exists a profile $\psi\in\mathcal{M}_\theta(\mathbb{R})$, such that \eqref{eq:deftrw} holds.
\end{definition}

We will use some ideas and results from \cite{Yag2009}.
To study traveling wave solutions to \eqref{eq:basic}, it is natural to consider
the corresponding initial conditions of the form
 \begin{equation}\label{trwvincond}
u_0(x)=\psi(x\cdot\xi),
\end{equation}
for some $\xi\in S^{d-1} $, $\psi\in\mathcal{M}_\theta(\mathbb{R})$. Then the solutions will have a 
special form as well, namely, the following proposition holds.

\begin{proposition}\label{prop:monot_sol}
Let $\xi\in S^{d-1} $, $\psi\in\mathcal{M}_\theta(\mathbb{R})$, and an initial condition to 
\eqref{eq:basic} be given by
$u_0(x)=\psi(x\cdot\xi)$, a.a.\ $x\in{\mathbb{R}^d}$; let also $u\in\mathcal{X}_\infty$ 
be the corresponding solution. Then there exist a function 
$\phi:\mathbb{R}\times\mathbb{R}_+\to[0,\theta]$, such that $\phi(\cdot,t)\in\mathcal{M}_\theta(\mathbb{R})$, for any
 $t\geq0$, and
\begin{equation}\label{repres}
 u(x,t)=\phi(x\cdot\xi,t),\quad t\geq0,\ \text{a.a. }x\in{\mathbb{R}^d}.
\end{equation}
Moreover, there exist functions $\check{a}^\pm$ (depending on $\xi$)
on $\mathbb{R}$ with
$0\leq \check{a}^\pm\in L^1(\mathbb{R})$, $\int_\mathbb{R} \check{a}^\pm(s)\,ds=1$,
such that $\phi$ is a solution to the following one-dimensional version 
of \eqref{eq:basic}:
\begin{equation}
 \begin{gathered}
 \begin{aligned}
 \frac{\partial \phi}{\partial t}(s,t)
&=\kappa^+ (\check{a}^{+}*\phi)(s,t)-m\phi(s,t) -\kappa_{\ell} \phi^2(s,t) \\
&\quad  -\kappa_{n\ell}\phi(s,t)(\check{a}^{-}*\phi)(s,t), \quad t>0, \; \text{a.a. }
  s\in\mathbb{R},
 \end{aligned}\\
 \phi(s,0)=\psi(s),\quad \text{a.a. }s\in\mathbb{R}.
 \end{gathered}\label{eq:basic_one_dim}
\end{equation}
\end{proposition}

\begin{proof}
Choose any $\eta\in S^{d-1} $ which is orthogonal to the $\xi$. 
Then the initial condition $u_0$ is constant along $\eta$, indeed, 
for any $s\in\mathbb{R}$,
\[
 u_0(x+s\eta)=\psi((x+s\eta)\cdot\xi)=\psi(x\cdot\xi)=u_0(x),\quad 
\text{a.a. }x\in{\mathbb{R}^d}.
\]
Then, by Proposition~\ref{prop:monot_along_vector_sol}, for any fixed $t>0$, 
the solution $u(\cdot,t)$ is constant along $\eta$ as well. 
Next, for any $\tau\in\mathbb{R}$, there exists $x\in{\mathbb{R}^d}$ such that $x\cdot\xi=\tau$; 
and, clearly, if $y\cdot\xi=\tau$ then $y=x+s\eta$, for some $s\in\mathbb{R}$ and 
some $\eta$ as above. Therefore, if we just set, for a.a.\
 $x\in{\mathbb{R}^d}$, $\phi(\tau,t):=u(x,t)$, $t\geq0$, this definition will be correct 
a.e.\ in $\tau\in\mathbb{R}$; and it will give \eqref{repres}. Next, for a.a.\
 fixed $x\in{\mathbb{R}^d}$, $u_0(x+s\xi)=\psi(x\cdot\xi+s)$ is decreasing in $s$, therefore, $u_0$ is decreasing along the $\xi$, and by Proposition~\ref{prop:monot_along_vector_sol},
$u(\cdot,t)$, $t\geq0$, will be decreasing along the $\xi$ as well. 
The latter means that, for any $s_1\leq s_2$, we have, by \eqref{repres},
\[
 \phi(x\cdot\xi+s_1,t)=u(x+s_1\xi,t)\geq u(x+s_2\xi,t)=\phi(x\cdot\xi+s_2,t),
\]
and one can choose in the previous any $x$ which is orthogonal to $\xi$ 
to prove that $\phi$ is decreasing in the first coordinate.

To prove the second statement, for $d\geq2$, choose any 
$\{\eta_{1},\ \eta_{2},\dots, \eta_{d-1}\}\subset S^{d-1} $ 
which form a complement of $\xi\in S^{d-1} $ to an orthonormal basis in ${\mathbb{R}^d} $.
Then, for a.a.\ $x\in{\mathbb{R}^d}$, with $x=\sum_{j=1}^{d-1}\tau_j\eta_j+s\xi$, 
$\tau_1,\dots,\tau_{d-1},s\in\mathbb{R}$, we have (using an analogous expansion of
$y$ inside the integral below an taking into account that any linear 
transformation of orthonormal bases preserves volumes)
\begin{align}
& (a^\pm*u)(x,t)\\
&=\int_{\mathbb{R}^d} a^\pm(y)u(x-y,t)dy\notag\\
&=\int_{\mathbb{R}^d} a^\pm\Big(\sum_{j=1}^{d-1}\tau_j'\eta_j+s'\xi\Big)\,
 u\Big(\sum_{j=1}^{d-1}(\tau_j-\tau_j')\eta_j+(s-s')\xi,t\Big)
 \,d\tau_{1}'\dots d\tau_{d-1}'ds'\notag\\
&=\int_\mathbb{R}\Bigl(\int_{\mathbb{R}^{d-1}}a^\pm\Big(\sum_{j=1}^{d-1}\tau_j'\eta_j+s'\xi\Big)\,
d\tau_1'\dots d\tau_{d-1}'\Bigr)u\bigl((s-s')\xi,t\bigr)\,ds',\label{reducingto1dim}
\end{align}
where we used again Proposition~\ref{prop:monot_along_vector_sol} to show that 
$u$ is constant along the vector $\eta=\sum_{j=1}^{d-1}(\tau_j-\tau_j')\eta_j$ 
which is orthogonal to the $\xi$.

Therefore, one can set
\begin{equation}\label{apm1dim}
\check{a}^\pm(s):=\begin{cases}
 \int_{\mathbb{R}^{d-1}} a^\pm(\tau_1\eta_1+\dots+\tau_{d-1}\eta_{d-1}
 +s\xi)\,d\tau_1\dots d\tau_{d-1}, & d\geq2,\\
a^\pm(s\xi), & d=1.
\end{cases}
\end{equation}
It is easily seen that $\check{a}^\pm=\check{a}^\pm_\xi$
does not depend on the choice of $\eta_1,\dots,\eta_{d-1}$, which constitute 
a basis in the space $H_\xi:=\{x\in{\mathbb{R}^d}\mid x\cdot\xi=0\}=\{\xi\}^\bot$.
Note that, clearly,
\begin{equation}\label{cleareq}
\int_\mathbb{R} \check{a}^\pm(s)\,ds=\int_{\mathbb{R}^d} a^\pm(y)\,dy=1.
\end{equation}
Next, by \eqref{repres}, $u\bigl((s-s')\xi,t\bigr)=\phi(s-s',t)$;
 therefore, \eqref{reducingto1dim} may be rewritten as
\[
(a^\pm*u)(x,t)=\int_\mathbb{R} \check{a}^\pm(s')\phi(s-s',t\bigr)\,ds'
=:(\check{a}^\pm*\phi)(s,t),
\]
where $s=x\cdot\xi$. The rest of the proof is obvious now.
\end{proof}

\begin{remark}\label{rem:multi-one} \rm
Let $\xi\in S^{d-1} $ be fixed and $\check{a}^\pm$ be defined by
\eqref{apm1dim}. Let $\phi$ be a traveling wave solution to \eqref{eq:basic_one_dim} 
(in the sense of Definition~\ref{def:trw}, for $d=1$) in the direction 
$1\in S^0=\{-1,1\}$, with a profile $\psi\in\mathcal{M}_\theta(\mathbb{R})$ and a speed $c\in\mathbb{R}$. 
Then the function $u$ given by
\begin{equation}\label{tw1d}
u(x,t)=\psi(x\cdot\xi-ct)=\psi(s-ct)=\phi(s,t),
\end{equation}
for $x\in{\mathbb{R}^d}$, $t\geq0$, $s=x\cdot\xi\in\mathbb{R}$,
is a traveling wave solution to \eqref{eq:basic} in the direction $\xi$, 
with the profile $\psi$ and the speed $c$.
\end{remark}

\begin{remark}\label{incrinsteadofdecr} \rm
 One can realize all previous considerations for increasing traveling wave, 
increasing solution along a vector $\xi$ etc. Indeed, it is easily 
seen that the function $\tilde{u}(x,t)=u(-x,t)$ with the initial condition 
$\tilde u_0(x)=u_0(-x)$ is a solution to  \eqref{eq:basic} 
with $a^\pm$ replaced by $\tilde{a}^\pm(x)=a^\pm(-x)$; note that 
$(a^\pm*u)(-x,t)=(\tilde{a}^\pm*\tilde{u})(x,t)$.
\end{remark}

\begin{remark}\label{shiftoftrw} \rm
 It is a straightforward application of \eqref{eq:QTy=TyQ}, that 
if $\psi\in\mathcal{M}_\theta(\mathbb{R})$, $c\in\mathbb{R}$ gets \eqref{eq:deftrw} then, for any 
$s\in\mathbb{R}$, $\psi(\cdot+s)$ is a traveling wave to \eqref{eq:basic} with the same $c$.
\end{remark}

We can prove now the following simple statement, which implies, in particular, 
the property \ref{prop:Q_Mtheta} in Theorem~\ref{thm:Qholds}. 
Consider one-dimensional equation \eqref{eq:basic_one_dim}, 
where $\check{a}^\pm$ are given by \eqref{apm1dim}. The latter equality
together with \eqref{as:aplus_gr_aminus} imply \eqref{as:aplus_gr_aminus-intro} 
that is equivalent to
\begin{equation}\label{acheckpos}
 \kappa^+ \check{a}^+(s)\geq \kappa_{n\ell} \theta \check{a}^-(s), \quad \text{a.a. }
 s\in\mathbb{R}.
\end{equation}

\begin{proposition}\label{prop:Qtilde}
Let \eqref{as:chiplus_gr_m} and \eqref{as:aplus_gr_aminus-intro} hold, and 
let $\xi\in S^{d-1} $ be fixed.
 Define, for an arbitrary $t>0$, the mapping 
$\widetilde{Q}_{t}:L^{\infty}(\mathbb{R})\to L^{\infty}(\mathbb{R})$ as follows: 
$\widetilde{Q}_t\psi(s)=\phi(s,t)$, $s\in\mathbb{R}$, where 
$\phi:\mathbb{R}\times\mathbb{R}_+\to[0,\theta]$ solves \eqref{eq:basic_one_dim} with 
$0\leq\psi\in L^{\infty}_{+}(\mathbb{R})$. Then such a $\widetilde{Q}_t$ is well-defined 
and satisfies all properties of Theorem~\ref{thm:Qholds} (with $d=1$). 
\end{proposition}

\begin{proof}
Note that all previous results (e.g. Theorem~\ref{thm:existuniq}) hold
 for the solution to \eqref{eq:basic_one_dim} as well. In particular,
 properties \ref{eq:QBtheta_subset_Btheta}--\ref{prop:Q_cont} 
of Theorem~\ref{thm:Qholds} hold true, for $Q=\widetilde{Q}_t$, $d=1$. 
Moreover (see the proof of \cite[Theorems 2.2, 3.4]{FT2017a} for 
$E=L^\infty({\mathbb{R}^d})$, which implies Theorem~\ref{thm:existuniq}),
 the mappings $B$ and $\Phi_\tau$, cf. \eqref{eq:exist_uniq_BUC:B}, 
\eqref{eq:exist_uniq_BUC:Phi_v}, map the set $\mathcal{M}_\theta(\mathbb{R})$ into itself; as a result,
 we have that $\widetilde{Q}_t$ has this property as well, 
cf.\ Remark~\ref{rem:inclus}.
\end{proof}

Now we  prove the existence of the traveling wave solution to \eqref{eq:basic}. 
Denote, for any $\lambda>0$, $\xi\in S^{d-1} $,
\begin{equation}\label{aplusexpla}
 {\mathfrak{a}}_\xi(\lambda):=\int_{\mathbb{R}^d} a^+(x) e^{\lambda x\cdot \xi}\,dx\in[0,\infty].
\end{equation}
Therefore, for a $\xi\in S^{d-1} $, the assumption \eqref{aplusexpint1} 
means that ${\mathfrak{a}}_{\xi}(\mu)<\infty$ for some $\mu=\mu(\xi)>0$.
We will prove now the first statement of Theorem~\ref{thm:trwexist}.

\begin{proposition}\label{prop:trwexists}
Let $\xi\in S^{d-1} $ and  assumptions \eqref{as:chiplus_gr_m}, 
\eqref{as:aplus_gr_aminus-intro}, \eqref{aplusexpint1} hold.
Then there exists $c_*(\xi)\in\mathbb{R}$ such that
\begin{enumerate}
 \item for any $c\geq c_*(\xi)$, there exists a traveling wave solution, 
in the sense of Definition~\ref{def:trw}, with a profile $\psi\in\mathcal{M}_\theta(\mathbb{R})$ 
and the speed $c$,

 \item for any $c<c_*(\xi)$, such a traveling wave does not exist.
\end{enumerate}
\end{proposition}

\begin{proof}
Let $\mu>0$ be such that \eqref{aplusexpint1} holds. Then, by \eqref{apm1dim},
\begin{align}\notag
\int_\mathbb{R} \check{a}^+(s) e^{\mu s}ds
&=\int_\mathbb{R} \int_{\mathbb{R}^{d-1}} a^\pm(\tau_1\eta_1+\dots+\tau_{d-1}\eta_{d-1}+s\xi)
e^{\mu s}\,d\tau_1\dots d\tau_{d-1} ds\\&={\mathfrak{a}}_\xi(\mu)<\infty.\label{expintla1}
\end{align}
Clearly, the integral equality in \eqref{expintla1} holds true for any 
$\lambda\in\mathbb{R}$ as well, with ${\mathfrak{a}}_\xi(\lambda)\in[0,\infty]$.

Let $\mu>0$ be such that \eqref{aplusexpint1} holds. Define a function from $\mathcal{M}_\theta(\mathbb{R})$ by
\begin{equation}\label{defvarphi}
\varphi(s):=\theta\min\{e^{-\mu s},1\}.
\end{equation}
Let us prove that there exists $c\in\mathbb{R}$ such that $\bar{\phi}(s,t):=\varphi(s-ct)$ 
is a super-solution to \eqref{eq:basic_one_dim}, i.e.
\begin{equation}\label{supersol}
\mathcal{F}\bar{\phi}(s,t)\geq0,\quad s\in\mathbb{R}, t\geq0,
\end{equation}
where $\mathcal{F}$ is given by \eqref{Foper} (in the case $d=1$).
We have
\begin{align*}
 (\mathcal{F}\bar{\phi})(s,t) 
& =-c\varphi'(s-ct)- \kappa^+ (\check{a}^+*\varphi)(s-ct)+m\varphi(s-ct)\\
&\quad +\kappa_{n\ell}\varphi(s-ct) (\check{a}^-*\varphi)(s-ct) +\kappa_{\ell}\varphi^2(s-ct),
\end{align*}
hence, to prove \eqref{supersol}, it is enough to show that, for all $s\in\mathbb{R}$,
\begin{equation}
\begin{aligned}
 \mathcal{J}_c(s)&:=c\varphi'(s)+\kappa^+ (\check{a}^+*\varphi)(s)-m\varphi(s) \\
&\quad - \kappa_{n\ell}\varphi(s)(\check{a}^-*\varphi)(s) - \kappa_{\ell} \varphi^2(s) \\
&\leq 0.
\end{aligned}\label{suffcond}
\end{equation}

By \eqref{defvarphi}, \eqref{acheckpos}, for $s<0$, we have
\begin{align*}
 \mathcal{J}_c(s)
&=\kappa^+ (\check{a}^+*\varphi)(s)-m\theta-\kappa_{n\ell}\theta(\check{a}^-*\varphi)(s)
 - \kappa_{\ell} \theta^2 \\
&\leq \bigl((\kappa^+ \check{a}-\kappa_{n\ell}\theta\check{a}^-)*\theta\bigr)(s)
 -m\theta -\kappa_{\ell}\theta^2=0.
\end{align*}
Next, by \eqref{defvarphi},
\[
(\check{a}^+*\varphi)(s)\leq\theta \int_\mathbb{R} \check{a}^+(\tau)
e^{-\mu(s-\tau)}\,d\tau=\theta e^{-\mu s} {\mathfrak{a}}_\xi(\mu),
\]
therefore, for $s\geq0$, we have
\[
 \mathcal{J}_c(s)\leq -\mu c\theta e^{-\mu s}
 +\kappa^+ \theta e^{-\mu s} {\mathfrak{a}}_\xi(\mu) -m\theta e^{-\mu s};
\]
and to get \eqref{suffcond} it is enough to demand that 
$\kappa^+ {\mathfrak{a}}_\xi(\mu)-m- \mu c\leq0$, in particular,
\begin{equation}\label{demand}
c=\frac{\kappa^+ {\mathfrak{a}}_\xi(\mu)-m}{\mu}.
\end{equation}
As a result, for $\bar\phi(s,t)=\varphi(s-ct)$ with $c$ given by \eqref{demand}, 
we have
\begin{equation}\label{supersol2}
\mathcal{F}\bar\phi\geq0=\mathcal{F}(\widetilde{Q}_t\varphi),
\end{equation}
as $\widetilde{Q}_t\varphi$ is a solution to \eqref{eq:basic_one_dim}. 
Then, by \eqref{as:aplus_gr_aminus} and the inequality $\bar\phi\leq\theta$, 
one can apply Proposition~\ref{compprabscont} and obtain
\[
\widetilde{Q}_t\varphi(s')\leq \bar\phi(t,s')=\varphi(s'-ct), \quad \text{a.a. }
s'\in\mathbb{R},
\]
where $c$ is given by \eqref{demand}; note that, by \eqref{defvarphi}, 
for any $s\in\mathbb{R}$, the function $\bar{\phi}(s,t)$ is absolutely continuous in $t$. 
In particular, for $t=1$, $s'=s+c$, we obtain
\begin{equation}\label{mayYag}
\widetilde{Q}_1\varphi(s+c)\leq \varphi(s), \quad \text{a.a.}\ s\in\mathbb{R}.
\end{equation}
And now one can apply \cite[Theorem 5]{Yag2009} which states that, 
if there exists a flow of abstract mappings $\widetilde{Q}_t$, each 
of them maps $\mathcal{M}_\theta(\mathbb{R})$ into itself and has properties 
\ref{eq:QBtheta_subset_Btheta}--\ref{prop:Q_cont} of Theorem~\ref{thm:Qholds}, 
and if, for some $t$ (e.g. $t=1$), for some $c\in\mathbb{R}$, and for some 
$\varphi\in\mathcal{M}_\theta(\mathbb{R})$, the inequality \eqref{mayYag} holds, then there exists 
$\psi\in\mathcal{M}_\theta(\mathbb{R})$ such that, for any $t\geq0$,
\begin{equation}\label{getbyYag}
(\widetilde{Q}_t \psi)(s+ct)=\psi(s), \quad \text{a.a.}\ s\in\mathbb{R},
\end{equation}
that yields the solution to \eqref{eq:basic_one_dim} in the form \eqref{tw1d}, 
and hence, by Remark~\ref{rem:multi-one}, we will get the existence of a 
solution to \eqref{eq:basic} in the form \eqref{eq:deftrw}. 
It is worth noting that, in \cite{Yag2009}, the results were obtained for
 increasing functions. By~Remark~\ref{incrinsteadofdecr}, the same results 
do hold for decreasing functions needed for our settings.

Next, by \cite[Theorem 6]{Yag2009}, there exists $c_*=c_*(\xi)\in(-\infty,\infty]$ 
such that, for any $c\geq c_*$, there exists $\psi=\psi_c\in\mathcal{M}_\theta(\mathbb{R})$ such that 
\eqref{getbyYag} holds, and for any $c<c_*$ such a $\psi$ does not exist. 
Since for $c$ given by \eqref{demand} such a $\psi$ exists, we have that 
$c_*\leq c<\infty$, moreover, one can take any $\mu$ in \eqref{demand} 
for that \eqref{aplusexpint1} holds. Therefore,
\begin{equation}\label{cstarestimate}
c_*\leq \inf_{\lambda>0}\frac{\kappa^+ {\mathfrak{a}}_\xi(\lambda)-m}{\lambda}.
\end{equation}
The statement is proved.
\end{proof}

\begin{remark} \rm
 It can be seen from the proof above that we did not use the special 
form \eqref{defvarphi} of the function $\varphi$ after the inequality 
\eqref{supersol2}. Therefore, if a function $\varphi_1\in\mathcal{M}_\theta(\mathbb{R})$ is such 
that the function $\bar\phi(s,t):=\varphi_1(s-ct)$, $s\in\mathbb{R}$, $t\geq0$, 
is a super-solution to \eqref{eq:basic_one_dim}, for some $c\in\mathbb{R}$, 
i.e.\ if \eqref{supersol} holds, then there exists a traveling wave solution 
to \eqref{eq:basic_one_dim}, and hence to \eqref{eq:basic}, with some 
profile $\psi\in\mathcal{M}_\theta(\mathbb{R})$ and the same speed $c$.
\end{remark}

Now we  prove the second item of Theorem~\ref{thm:trwexist}. 

\begin{proposition}\label{prop:reg_trw}
Let $\psi\in\mathcal{M}_\theta(\mathbb{R})$ and $c\in\mathbb{R}$ be such that there exists a solution 
$u\in\mathcal{U}_\infty$ to  \eqref{eq:basic} such that \eqref{eq:deftrw} 
holds, for some $\xi\in S^{d-1} $. Then $\psi\in C^{1}(\mathbb{R}\to[0,\theta])$, 
for $c\neq0$, and $\psi\in C(\mathbb{R}\to[0,\theta])$, otherwise.
\end{proposition}

\begin{proof}
The condition \eqref{eq:deftrw} implies \eqref{trwvincond} for the 
$\xi\in S^{d-1} $. Then, by Proposition~\ref{prop:monot_sol}, 
there exists $\phi$ given by \eqref{repres} which solves \eqref{eq:basic_one_dim}; 
moreover, by Remark~\ref{rem:multi-one}, \eqref{tw1d} holds.

Let $c\neq0$. It is well-known that any monotone function is differentiable 
almost everywhere. Prove first that $\psi$ is differentiable everywhere on $\mathbb{R}$. 
Fix any $s_{0}\in\mathbb{R}$.
It follows directly from Proposition~\ref{prop:monot_sol}, that 
$\phi\in C^1((0,\infty)\to L^\infty(\mathbb{R}))$. Therefore, for any $t_0>0$ and 
for any $\varepsilon>0$, there exists $\delta=\delta(t_0,\varepsilon)>0$
such that, for all $t\in\mathbb{R}$ with $|ct|<\delta$ and $t_0+t>0$, 
the following inequalities hold, for a.a.\ $s\in\mathbb{R}$,
\begin{gather}
\frac{\partial \phi}{\partial t}(s,t_{0}) -\varepsilon
< \frac{\phi(s,t_{0}+t)-\phi(s,t_{0})}{t}
<\frac{\partial \phi}{\partial t}(s,t_{0})+\varepsilon,\label{firstfromeq}\\
\frac{\partial \phi}{\partial t}(s,t_{0})-\varepsilon
<\frac{\partial \phi}{\partial t}(s,t_{0}+t)
<\frac{\partial \phi}{\partial t}(s,t_{0})+\varepsilon.\label{secondfromeq}
\end{gather}

For simplicity of notation, set $x_0=s_0+ct_0$.
Take any $0<h<1$ with $2h<\min\bigl\{\delta,|c|t_0, |c|\delta \bigr\}$.
Since $\psi$ is a decreasing function, one has, for almost all
 $s\in(x_0,x_0+h^{2})$,
\begin{equation}
\begin{aligned}
\frac{\psi(s_0+h)-\psi(s_0)}{h}
&\leq\frac{\psi(s-ct_0+h-h^{2}) -\psi(s-ct_0)}{h}   \\
&=\frac{\phi(s,t_0+\frac{h^{2}-h}{c})-\phi(s,t_0)}{\frac{h^{2}-h}{c}}
\frac{h^{2}-h}{ch} \\
&\leq\Big(\frac{\partial \phi}{\partial t}(s,t_0)\mp\varepsilon\Big)
 \frac{h-1}{c},
\end{aligned}\label{ff1}
\end{equation}
by \eqref{firstfromeq} with $t=\frac{h^{2}-h}{c}$; note that
 $|ct|=h-h^2<h<\delta$, and $t_0+t>0$ (the latter holds, for $c<0$,
because of $t_0+t>t_0$ then; and, for $c>0$, it is equivalent to $ct_0>-ct=h-h^2$,
that follows from $h<ct_0$).
Stress, that, in \eqref{ff1}, one needs to choose $-\varepsilon$, for $c>0$,
and $+\varepsilon$, for $c<0$, according to the left and right inequalities
in \eqref{firstfromeq}, correspondingly.

Similarly, for almost all $s\in(x_0-h^{2},x_0)$, one has
\begin{equation}
\begin{aligned}
 \frac{\psi(s_0+h)-\psi(s_0)}{h}
&\geq\frac{\psi(s-ct_0+h+h^{2})-\psi(s-ct_0)}{h}  \\
&=\frac{\phi(s,t_0-\frac{h^{2}+h}{c})-\phi(s,t_0)}{-\frac{h^{2}+h}{c}}
 \frac{h^{2}+h}{-ch} \\
&\geq\Big(\frac{\partial \phi}{\partial t}(s,t_0)\pm\varepsilon\Big)
 \frac{h+1}{-c},
\end{aligned}\label{ff2}
\end{equation}
where we take again the upper sign, for $c>0$, and the lower sign, for $c<0$;
note also that $h+h^2<2h<\delta$.
Next, one needs to `shift' values of $s$ in \eqref{ff2} to get them the
same as in \eqref{ff1}. To do this note that, by \eqref{tw1d},
\begin{equation}\label{ff3}
\phi\Bigl(s+h^2,t_0+\frac{h^2}{c}\Bigr)=\phi(s,t_0), \quad \text{a.a. } s\in{\mathbb{R}^d}.
\end{equation}
As a result,
\begin{equation}\label{ff4}
\begin{aligned}
(\check{a}^\pm *\phi)\Bigl(s+h^2,t_0+\frac{h^2}{c}\Bigr)
&=\int_{\mathbb{R}} \check{a}^\pm (s') \phi\Bigl(s-s'+h^2,t_0
 +\frac{h^2}{c}\Bigr)\,ds\\
&=(\check{a}^\pm *\phi)(s,t_0), \quad \text{a.a.}\ s\in{\mathbb{R}^d}.
\end{aligned}
\end{equation}
Then, by \eqref{eq:basic_one_dim}, \eqref{ff3}, \eqref{ff4}, one gets
\begin{equation}\label{ff5}
\frac{\partial}{\partial t}\phi\Bigl(s+h^2,t_0+\frac{h^2}{c}\Bigr)
=\frac{\partial}{\partial t}\phi(s,t_0), \quad \text{a.a. } s\in{\mathbb{R}^d}.
\end{equation}
Therefore, by \eqref{ff5}, one gets from \eqref{ff2} that,
for almost all $s\in(x_0,x_0+h^{2})$, cf. \eqref{ff1},
\begin{equation}
\begin{aligned}
 \frac{\psi(s_0+h)-\psi(s_0)}{h}
&\geq\Big(\frac{\partial \phi}{\partial t}
\bigl(s,t_0+\frac{h^2}{c}\bigr)\pm\varepsilon\Big)\frac{h+1}{-c}\\
& \geq\Big(\frac{\partial \phi}{\partial t}(s,t_0)\pm 2\varepsilon\Big)
\frac{h+1}{-c},
\end{aligned}\label{ff6}
\end{equation}
 since $\bigl| \frac{h^2}{c}\bigr|<\delta$, one can apply the
right and left inequalities in \eqref{secondfromeq}, for $c>0$ and $c<0$.
Combining \eqref{ff1} and \eqref{ff6}, we obtain
\begin{equation}
\begin{aligned}
&\Big(\operatorname{ess\,sup}_{s\in(x_0,x_0+h^2)}
\frac{\partial \phi}{\partial t}(s,t_0)\pm 2\varepsilon\Big)
\frac{h+1}{-c}
&\leq \frac{\psi(s_0+h)-\psi(s_0)}{h}\\
&\leq\Big(\operatorname{ess\,sup}_{s\in(x_0,x_0+h^2)}\frac{\partial \phi}{\partial t}(s,t_0)
\mp\varepsilon\Big)\frac{h-1}{c}.
\end{aligned}\label{ff7}
\end{equation}
For fixed $s_0\in\mathbb{R}$, $t_0>0$ and for $x_0=s_0+ct_0$, the function
\[
 f(h):=\operatorname{ess\,sup}_{s\in(x_0,x_0+h^2)}\frac{\partial \phi}{\partial t}(s,t_0), \quad h\in(0,1),
\]
is bounded, as $|f(h)|\leq \| \frac{\partial \phi}{\partial t}(\cdot,t_0)\|_\infty
<\infty$, and monotone; hence there exists $\bar f=\lim_{h\to0+}f(h)$.
As a result, for small enough $h$, \eqref{ff7} yields
\[
(\bar f\pm 2\varepsilon)\frac{1}{-c} -\varepsilon
\leq \frac{\psi(s_0+h)-\psi(s_0)}{h}
\leq(\bar f\mp\varepsilon)\frac{-1}{c}+\varepsilon,
\]
and, therefore, there exists
$\frac{\partial\psi}{\partial s}(s_0+)=\frac{-\bar f}{c}$.
In the same way, one can prove that there exists
$\frac{\partial\psi}{\partial s}(s_0-)=\frac{-\bar f}{c}$, and, therefore,
$\psi$ is differentiable at $s_0$.
As a result, $\psi$ is differentiable (and hence continuous) on the whole $\mathbb{R}$.

Next, for any $s_1,s_2,h\in\mathbb{R}$, we have
\begin{align*}
&\big|  \frac{\psi(s_1+h)- \psi(s_1)}{h}-\frac{\psi(s_2+h)- \psi(s_2)}{h}\big| \\
&=\frac{1}{|c|}\Big| \frac{\phi\bigl(s_1+ct_0,t_0-\frac{h}{c}\bigr)
 - \phi(s_1+ct_0,t_0)}{-\frac{h}{c}} \\
&\quad -\frac{\phi\bigl(s_1+ct_0,t_0+\frac{s_1-s_2}{c}-\frac{h}{c}\bigr)
 - \phi\bigl(s_1+ct_0,t_0+\frac{s_1-s_2}{c}\bigr)}{-\frac{h}{c}}\Big|;
\end{align*}
and if we pass $h$ to $0$, we obtain
\begin{equation}
\begin{aligned}
 | \psi'(s_1)-\psi'(s_2)|
&=\frac{1}{|c|}\Big| \frac{\partial}{\partial t}\phi(s_1+ct_0,t_0)
 -\frac{\partial}{\partial t}\phi\bigl(s_1+ct_0,t_0+\frac{s_1-s_2}{c}\bigr)\Big|
 \\
& \leq \frac{1}{|c|} \Big\| \frac{\partial}{\partial t}\phi(\cdot,t_0)
 -\frac{\partial}{\partial t}\phi\bigl(\cdot,t_0+\frac{s_1-s_2}{c}\bigr)\Big\|.
\end{aligned}\label{eq333}
\end{equation}
And now, by the continuity of $\frac{\partial}{\partial t}\phi(\cdot,t)$
in $t$ in the sense of the norm in $L^\infty(\mathbb{R})$, we have that, by
\eqref{secondfromeq}, the inequality $|s_1-s_2|\leq |c|\delta$ implies that,
by \eqref{eq333},
$| \psi'(s_1)-\psi'(s_2)|\leq \frac{1}{|c|} \varepsilon$.
As a result, $\psi'(s)$ is uniformly continuous on $\mathbb{R}$ and hence continuous.

Finally, consider the case $c=0$. Then \eqref{tw1d} implies that $\phi(s,t)$ 
must be constant in time, i.e.\ $\phi(s,t)=\psi(s)$, for a.a.\ $s\in\mathbb{R}$. 
Thus one can rewrite \eqref{eq:basic_one_dim} as follows
\begin{equation}
\begin{aligned}
 0 &= -\kappa^+ (\check{a}^{+}*\psi)(s) +m\psi(s)
+\kappa_{n\ell}\psi(s) (\check{a}^{-}*\psi)(s) +\kappa_{\ell} \psi^2(s)  \\
&= \kappa_{\ell}\psi^2(s) + A(s) \psi(s) - B(s),
\end{aligned}\label{statwave}
\end{equation}
where $A(s) = m+\kappa_{n\ell} (\check{a}^{-}*\psi)(s)$ and
$B(s) = \kappa^+ (\check{a}^{+}*\psi)(s) $. Equivalently,
\begin{equation}\label{asquotient}
 \psi(s)= \frac{\sqrt{A^2(s)+4\kappa_{\ell} B(s)}-A(s)}{4\kappa_{\ell}}.
\end{equation}
Since $\psi\in L^\infty(\mathbb{R})$, then, by Lemma~\ref{le:simple}, the
right-hand side of \eqref{asquotient} is a continuous in $s$ function,
and hence $\psi\in C(\mathbb{R})$.
\end{proof}

\begin{proposition}
Let $\psi\in\mathcal{M}_\theta(\mathbb{R})$, $c\in\mathbb{R}$, $\xi\in S^{d-1} $ be such that there exists 
a solution $u\in\mathcal{U}_\infty$ to  \eqref{eq:basic} such 
that \eqref{eq:deftrw} holds. Then, for each $s\in\mathbb{R}$,
\begin{equation}
 c\psi'(s) +\kappa^+ (\check{a}^{+}*\psi)(s) -m\psi(s)
 -\kappa_{n\ell}\psi(s) (\check{a}^{-}*\psi)(s) -\kappa_{\ell} \psi^2(s)=0.\label{eq:trw}
\end{equation}
\end{proposition}

\begin{proof}
Let $c\neq0$. Then, by~Remark~\ref{rem:multi-one} and Proposition~\ref{prop:reg_trw}, 
one can differentiate $\psi(s-ct)$ in $t\geq0$. By this and Lemma~\ref{le:simple}
 we obtain \eqref{eq:trw} for all $s\in\mathbb{R}$. For $c=0$, one has \eqref{statwave}, 
i.e.\ \eqref{eq:trw} holds in this case as well.
\end{proof}

Let $k\in\mathbb{N}\cup\{\infty\}$ and $C_b^k(\mathbb{R})$ denote the class of all functions on 
$\mathbb{R}$ which are $k$ times differentiable and whose derivatives (up to the 
order $k$) are continuous and bounded on $\mathbb{R}$. The following corollary 
finishes the proof of the second item of Theorem~\ref{thm:trwexist}.

\begin{corollary}\label{cor:infsmoothprofile}
Let $\psi\in\mathcal{M}_\theta(\mathbb{R})$, $c\in\mathbb{R}$, $c\neq0$, $\xi\in S^{d-1} $ be such that there 
exists a solution $u\in\mathcal{U}_\infty$ to  \eqref{eq:basic} such 
that \eqref{eq:deftrw} holds. Then $\psi\in C_b^\infty(\mathbb{R})$.
\end{corollary}

\begin{proof}
By Lemma~\ref{le:simple}, $\check{a}^\pm*\psi\in C_b(\mathbb{R})$.
Then \eqref{eq:trw} yields $\psi'\in C_b(\mathbb{R})$, i.e. $\psi\in C_b^1(\mathbb{R})$. 
By e.g. \cite[Proposition~5.4.1]{Sta2005}, $\check{a}^\pm*\psi\in C_b^1(\mathbb{R})$
and $(\check{a}^\pm*\psi)'=\check{a}^\pm*\psi'$, therefore,
the equality \eqref{eq:trw} holds with $\psi'$ replaced by $\psi''$ and 
$\psi$ replaced by $\psi'$. Then, by the same arguments $\psi\in C_b^2(\mathbb{R})$, 
and so on. The statement is proved.
\end{proof}

Now we prove the third item of Theorem~\ref{thm:trwexist}. 
We  follow ideas of \cite{CD2007}.

\begin{proposition}\label{prop:trw_exp_est}
Let \eqref{as:chiplus_gr_m} and \eqref{as:aplus_gr_aminus-intro} hold. 
Let $\psi\in\mathcal{M}_\theta(\mathbb{R})$, $c\in\mathbb{R}$, $\xi\in S^{d-1} $ be such that there exists 
a solution $u\in\mathcal{U}_\infty$ to  \eqref{eq:basic} such that 
\eqref{eq:deftrw} holds. Then there exists $\mu=\mu( c, a^+, \kappa^-, \theta)>0$ 
such that
 $\int_\mathbb{R}\psi(s)e^{\mu s}\,ds<\infty$.
\end{proposition}

\begin{proof}
At first, we prove that $\psi\in L^1(\mathbb{R}_+)$.
Under assumptions \eqref{as:chiplus_gr_m} and \eqref{as:aplus_gr_aminus-intro}, 
define the  function
\begin{equation}\label{speckern}
 \check{J}_\upsilon(s):=\kappa^+ \check{a}^+(s)-\upsilon\kappa_{n\ell}\check{a}^-(s),
\quad s\in\mathbb{R}, \upsilon\in(0,\theta].
\end{equation}
Then, by \eqref{acheckpos}, 
$\check{J}_\upsilon(s)\geq \check{J}_\theta(s)\geq0$ for $s\in\mathbb{R}$,
$\upsilon\in(0,\theta]$.
Since $\int_\mathbb{R} \check{J}_\upsilon(s)\,ds = \kappa^+ -\upsilon\kappa_{n\ell} > m+\kappa_{\ell} \upsilon$,
one can choose $R_0>0$, such that
\begin{equation}\label{Risproper}
 \int_{-R_0}^{R_0} \check{J}_\upsilon(s)\,ds = m+\kappa_{\ell}\upsilon.
\end{equation}
We rewrite \eqref{eq:trw} as follows
\begin{equation} \label{eq:tr_w_ii}
\begin{aligned}
&c\psi '(s) + (\check{J}_\upsilon*\psi)(s)
  + \bigl(\upsilon-\psi(s)\bigr)\big(\kappa_{\ell}\psi(s) \\
& +\kappa_{n\ell}(\check{a}^-*\psi)(s)\big)
 - (m+\kappa_{\ell}\upsilon)\psi(s) = 0,\quad s\in\mathbb{R}.
\end{aligned}
\end{equation}
Fix arbitrary ${r_0}>0$, such that
\begin{equation}\label{rhocond}
 \psi({r_0})<\upsilon.
\end{equation}
Let $r>{r_0}+R_0$. Integrate \eqref{eq:tr_w_ii} over $[{r_0},r]$; one gets
\begin{equation}\label{eq:tr_w_ii_int}
c(\psi(r)-\psi({r_0}))+A+B=0,
\end{equation}
where
\begin{gather*}
A:= \int_{{r_0}}^{r}(\check{J}_\upsilon*\psi)(s)\, ds
 - (m+\kappa_{\ell}\upsilon)\int_{{r_0}}^{r}\psi(s)ds,\\
B:= \int_{{r_0}}^{r}(\upsilon-\psi(s))\bigl(\kappa_{\ell}\psi(s)
  + \kappa_{n\ell}(\check{a}^-*\psi)(s)\bigl)\,ds.
\end{gather*}
By \eqref{speckern} and \eqref{Risproper}, one has
\begin{equation}
\begin{aligned}
 A& \geq \int_{r_0}^{r} \int_{-R_0}^{R_0} \check{J}_\upsilon(\tau)
 \psi(s-\tau)d\tau ds -(m+\kappa_{\ell}\upsilon) \int_{r_0}^{r} \psi(s)\,ds \\
&= \int_{-R_0}^{R_0} \check{J}_\upsilon(\tau)
\Big( \int_{{r_0}-\tau}^{r-\tau}\psi(s)\,ds - \int_{{r_0}}^{r}\psi(s)\,ds \Big)
 \,d\tau  \\
&=\int_{0}^{R_0}\check{J}_\upsilon(\tau)
 \Big( \int_{{r_0}-\tau}^{{r_0}}\psi(s)\,ds-\int_{r-\tau}^{r}\psi(s)\,ds \Big)
 \,d\tau \\
&\quad+\int_{-R_0}^{0}\check{J}_\upsilon(\tau)
\Big( \int_{r}^{r-\tau}\psi(s)\,ds-\int_{{r_0}}^{{r_0}-\tau}\psi(s)\,ds \Big)
 \,d\tau;
\end{aligned} \label{eq:gen_est12}
\end{equation}
and since $\psi$ is a decreasing function and $r-R_0>{r_0}$,
 from \eqref{eq:gen_est12}, we have
\begin{align}
 A &\geq (\psi({r_0})-\psi(r-R_0))\int_{0}^{R_0}
\tau \check{J}_\upsilon(\tau)\,d\tau+(\psi(r+R_0)
-\psi({r_0}))\int_{-R_0}^{0}(-\tau) J_\upsilon(\tau)\,d\tau \notag \\
 &\geq -\theta \int_{-R_0}^{0}(-\tau) J_\upsilon(\tau)\,d\tau
 =:-\theta \bar{J}_{\upsilon,R_0}. \label{eq:gen_est}
\end{align}
Next, \eqref{rhocond} and monotonicity of $\psi$ imply
\begin{equation}\label{B-est}
 B\geq (\upsilon-\psi({r_0})) \int_{{r_0}}^{r} \bigl(\kappa_{\ell}\psi(s)
+ \kappa_{n\ell}(\check{a}^-*\psi)(s)\bigl) \,ds.
\end{equation}
Then, by \eqref{eq:tr_w_ii_int}, \eqref{eq:gen_est}, \eqref{B-est},
\eqref{rhocond}, one gets
\begin{align*}
 0 &\leq (\upsilon-\psi({r_0})) \int_{{r_0}}^{r} \bigl(\kappa_{\ell}\psi(s)
+ \kappa_{n\ell}(\check{a}^-*\psi)(s)\bigl) \,ds \\
 &\leq \theta \bar{J}_{\upsilon,R_0} + c(\psi({r_0})-\psi(r))
\to \theta \bar{J}_{\upsilon,R_0} + c\psi({r_0})<\infty, \quad r\to\infty,
\end{align*}
therefore, $\kappa_{\ell}\psi + \kappa_{n\ell}\check{a}^-*\psi\in L^1(\mathbb{R}_+)$.
Finally, \eqref{cleareq} implies that there exist a measurable bounded
set $\Delta\subset\mathbb{R}$, with $m(\Delta):=\int_\Delta \,ds\in (0,\infty)$,
and a constant $\mu>0$, such that $\check{a}^-(\tau)\geq\mu$,
for a.a.\ $\tau\in\Delta$. Let $\delta=\inf \Delta\in\mathbb{R}$.
Then, for any $s\in\mathbb{R}$, one has
\[
(\check{a}^-*\psi)(s)\geq \int_\Delta \check{a}^-
(\tau) \psi(s-\tau)\,d\tau\geq \mu \psi(s-\delta) m(\Delta).
\]
Therefore $\psi\in L^1(\mathbb{R}_+)$.

For any $N\in\mathbb{N}$, we define 
$\varphi_N(s):= 1\!\!1_{(-\infty,N)}(s)+e^{-\lambda(s-N)} 1\!\!1_{[N,\infty)}(s)$,
 where $\lambda>0$. By the proved above, 
$\psi,\check{a}^\pm*\psi\in L^1(\mathbb{R}_+)\cap L^\infty(\mathbb{R})$ hence,
 by \eqref{eq:trw}, $c\psi'\in L^1(\mathbb{R}_+)\cap L^\infty(\mathbb{R})$. 
Therefore, all terms of \eqref{eq:trw} being multiplied on 
$e^{\lambda s}\varphi_{N}(s)$ are~integrable over $\mathbb{R}$. 
After this integration, \eqref{eq:trw} will be read as follows
\begin{equation}
I_1+I_2+I_3=0,\label{eq:int_trw_zeta_exp}
\end{equation}
where (recall that $\kappa^- \theta-\kappa^+ =-m$)
\begin{gather*}
I_1:=c\int_{\mathbb{R}}\psi' (s) e^{\lambda s}\varphi_{N}(s)\,ds,\\
I_2:=\kappa^+ \int_\mathbb{R}\bigl((\check{a}^{+}*\psi)(s)
 -\psi(s)\bigr)e^{\lambda s}\varphi_{N}(s)\,ds,\\
I_3:= \int_{\mathbb{R}}\psi(s)\bigl(\kappa^+-m-\kappa_{\ell}\psi(s)
 -\kappa_{n\ell}(\check{a}^{-}*\psi)(s)\bigr) e^{\lambda s}\varphi_{N}(s)\,ds
\end{gather*}
We estimate now $I_1,I_2,I_3$ from below.

We start with $I_2$. One can write
\begin{equation}
\begin{aligned}
\int_{\mathbb{R}}(\check{a}^{+}*\psi)(s)e^{\lambda s}\varphi_{N}(s)\,ds
&=\int_{\mathbb{R}}\int_{\mathbb{R}}\check{a}^{+}(s-\tau)\psi(\tau)e^{\lambda s}
 \varphi_{N}(s)\,d\tau ds \\
&=\int_{\mathbb{R}}\int_{\mathbb{R}}\check{a}^{+}(s)e^{\lambda s}\varphi_{N}(\tau+s)\,ds\,
  e^{\lambda \tau}\psi(\tau)\,d\tau \\
&\ge\int_{\mathbb{R}}\Big(\int_{-\infty}^{R}\check{a}^{+}(s)e^{\lambda s}\,ds\Big)
 \varphi_{N}(\tau+R)e^{\lambda \tau}\psi(\tau)\,d\tau,
\end{aligned}\label{eq:111}
\end{equation}
for any $R>0$, as $\varphi$ is nonincreasing. By \eqref{cleareq}, one can
choose $R>0$ such that
\[
\int_{-\infty}^{R}\check{a}^{+}(\tau)\,d\tau>1-\frac{\kappa^- \theta}{4}.
\]
By continuity arguments, there exists $\nu>0$ such that, for any $0<\lambda<\nu$,
\begin{equation}\label{eq:222}
 \int_{-\infty}^{R}\check{a}^{+}(\tau)e^{\lambda \tau}\,d\tau
\geq\Bigl(1-\frac{\kappa^- \theta}{4}\Bigr)e^{\lambda R}.
\end{equation}
Therefore, combining \eqref{eq:111} and \eqref{eq:222}, we obtain
\begin{equation}
\begin{aligned}
I_2
&\geq\int _{\mathbb{R}}\Bigl(1-\frac{\kappa^- \theta}{4}\Bigr)e^{\lambda R}\varphi_{N}
 (\tau+R)e^{\lambda \tau}\psi(\tau)\,d\tau
 -\int _{\mathbb{R}}\psi(s)e^{\lambda s}\varphi_{N}(s)\,ds  \\
&=\int_{\mathbb{R}}\Bigl(1-\frac{\kappa^- \theta}{4}\Bigr)\varphi_{N}(\tau)
 e^{\lambda \tau}\psi(\tau-R)\,d\tau
 -\int _{\mathbb{R}}\psi(s)e^{\lambda s}\varphi_{N}(s)\,ds \\
&\ge-\frac{\kappa^- \theta}{4}\int_{\mathbb{R}}\psi(s)e^{\lambda s}\varphi_{N}(s)\,ds,
\end{aligned}\label{eq:trw_exp_est:i}
\end{equation}
as $\psi(\tau-R)\geq\psi(\tau)$, $\tau\in\mathbb{R}$, $R>0$.

Now we estimate $I_3$. By \eqref{eq:deftrw}, it is easily seen that the 
function $(\check{a}^{-}*\psi)(s)$ decreases monotonically to $0$ as
$s\to\infty$.
Suppose additionally that $R>0$ above is such that
\[
 \kappa_{\ell}\psi(s) + \kappa_{n\ell}(\check{a}^{-}*\psi)(s)<\frac{\kappa^-\theta}{2}, \quad s>R.
\]
Then, one gets
\begin{align*}
 I_3
& \geq \frac{\kappa^-\theta}{2} \int_{R}^{\infty} \psi(s)e^{\lambda s}\varphi_{N}(s)
 \,ds   \\
 &\quad + \int_{-\infty}^{R}\psi(s)\bigl(\kappa^-\theta-\kappa_{\ell}\psi(s)
 -\kappa_{n\ell}(\check{a}^{-}*\psi)(s)\bigr)e^{\lambda s}\varphi_{N}(s)\,ds  \\
 &\geq \frac{\kappa^-\theta}{2}\int _{R}^{\infty}\psi (s)e^{\lambda s}
 \varphi_{N}(s)\,ds,
\end{align*}
as $0\leq\psi\leq\theta$, $\varphi_N\geq0$, $(\check{a}^{-}*\psi)(s)\leq\theta$.

It remains to estimate $I_1$ (in the case $c\neq0$). Since
$\lim_{s\to\pm\infty} \psi(s)e^{\lambda s}\varphi_N(s) =0$, 
we have from the integration by parts formula, that
\begin{equation*}
I_1=-c\int_{\mathbb{R}}\psi(s)(\lambda\varphi_{N}(s)+\varphi_{N}'(s))e^{\lambda s}\,ds.
\end{equation*}
For $c>0$, one can use that $\varphi_N'(s)\leq0$, $s\in\mathbb{R}$, and hence
\begin{equation*}
 I_1\geq -c \lambda\int _{\mathbb{R}}\psi(s)\varphi_{N}(s)e^{\lambda s}\,ds.
\end{equation*}
For $c<0$, we use that, by the definition of $\varphi_N$, 
$\lambda\varphi_{N}(s)+\varphi_{N}'(s)=0$, $s\geq N$; therefore,
\begin{equation}
I_1=-c\lambda\int_{-\infty}^N\psi(s)\,ds>0. \label{eq:trw_exp_est:iv}
\end{equation}

Therefore, combining \eqref{eq:trw_exp_est:i}--\eqref{eq:trw_exp_est:iv}, 
 from \eqref{eq:int_trw_zeta_exp}, we obtain
\begin{equation*}
0\geq
-\lambda \bar{c}\int _{\mathbb{R}}\psi(s)\varphi_{N}(s)e^{\lambda s}\,ds
 -\frac{\kappa^- \theta}{4}\int_{\mathbb{R}}\psi(s) e^{\lambda s}\varphi_{N}(s)\,ds
 +\frac{\kappa^- \theta}{2}\int_{R}^{\infty}\psi(s) e^{\lambda s}\varphi_{N}(s)\,ds,
\end{equation*}
where $\bar{c}=\max\{c,0\}$.

The latter inequality can be easily rewritten as
\begin{align}
& \Bigl(\frac{\kappa^- \theta}{4}-\lambda \bar{c}\Bigr)\int_{R}^{\infty}\psi (s) 
e^{\lambda s}\varphi_{N}(s)\,ds\leq \Bigl(\frac{\kappa^- \theta}{4} 
+\lambda \bar{c}\Bigr)\int_{-\infty}^{R}\psi(s)\varphi_{N}(s)e^{\lambda s}\,ds
\notag\\
&\leq \Bigl(\frac{\kappa^- \theta}{4}+\lambda \bar{c}\Bigr)\theta \int_{-\infty}^{R}
e^{\lambda s}\,ds=:I_{\lambda,R}<\infty, \quad 0<\lambda<\nu. \label{eq:333}
\end{align}

Take now $\mu<\min\bigl\{\nu, \frac{\kappa^- \theta}{4c}\bigr\}$, for $c>0$, 
and $\mu<\nu$, otherwise. Then, by \eqref{eq:333}, for any $N>R$, one obtains
\[
\infty>\Bigl(\frac{\kappa^- \theta}{4}-\mu \bar{c}\Bigr)^{-1}I_{\mu,R}
>\int_{R}^{\infty}\psi (s) e^{\mu s}\varphi_{N}(s)\,ds\geq
\int_{R}^{N}\psi (s) e^{\mu s}\,ds,
\]
thus,
\begin{align*}
\int_{\mathbb{R}}\psi (s) e^{\mu s}\,ds
&=\int_{-\infty}^R \psi (s) e^{\mu s}\,ds
+\int_{R}^{\infty}\psi (s) e^{\mu s}\,ds\\
&\leq \theta \int_{-\infty}^R e^{\mu s}\,ds+I_{\mu,R}
\Bigl(\frac{\kappa^- \theta}{4}-\mu \bar{c}\Bigr)^{-1}<\infty,
\end{align*}
that implies the dsired the statement.
\end{proof}

By Proposition~\ref{prop:reg_trw}, a traveling wave solution to \eqref{eq:basic} 
is continuous in space as well. Because of this, to prove the fourth item 
of Theorem~\ref{thm:trwexist}, we can use the strong maximum principle. 
We suppose that $a^+$ is not degenerated in the direction $\xi$ at the origin, 
namely, there exist $r\geq0$, $\rho,\delta>0$ (depending on $\xi$), such that
 \begin{equation}\label{as:a+nodeg1d}
  \int_{\{x\cdot\xi=s\}}a^{+}(x)\,dx \geq\rho \quad \text{for a.a. } |s|\leq \delta.
 \end{equation}
Clearly, either of \eqref{as:aplus-aminus-is-pos1d}, \eqref{as:aplus-aminus-is-pos}
 or \eqref{as:a+nodeg} implies \eqref{as:a+nodeg1d}.

\begin{proposition}\label{prop:psidecaysstrictly}
 Let \eqref{as:chiplus_gr_m}, \eqref{as:aplus_gr_aminus-intro} and 
\eqref{as:a+nodeg1d} hold. Let $\psi\in\mathcal{M}_\theta(\mathbb{R})$, $c\in\mathbb{R}$, $\xi\in S^{d-1} $ 
be such that there exists a solution $u\in\mathcal{U}_\infty$ to \eqref{eq:basic} 
such that \eqref{eq:deftrw} holds.
Then $\psi$ is a strictly decaying function, for any speed $c$.
\end{proposition}

\begin{proof}
By Remark~\ref{rem:multi-one}, there exists a traveling wave solution 
$\phi(s,t)=\psi(s-ct)$ to  \eqref{eq:basic_one_dim}. 
By Proposition \ref{prop:reg_trw}, $\psi\in C(\mathbb{R})$ and hence $\phi(s,t)=\psi(s-ct)$ 
is continuous in $s$ as well.
Suppose that $\psi$ is not strictly decaying, then there exists $\delta_0>0$ 
and $s_0\in\mathbb{R}$, such that $\psi(s)=\psi(s_0)$, for all $|s-s_0|\leq\delta_0$. 
Take any $\delta\in\bigl(0,\frac{\delta_0}{2}\bigr)$, and consider the function
 $\psi^\delta(s):=\psi(s+\delta)$. Clearly, $\psi^\delta(s)\leq\psi(s)$, $s\in\mathbb{R}$.
By Remarks \ref{shiftoftrw}, \ref{rem:multi-one}, $\psi^\delta$ is a profile 
for a traveling wave solution to  \eqref{eq:basic_one_dim} 
with the same speed $c$. Therefore, one has two solutions to 
\eqref{eq:basic_one_dim}: $\phi(s,t)=\psi(s-ct)$ and 
$\phi^\delta(s,t)=\psi^\delta(s-ct)$ and hence
 $\phi^\delta(s,t)\leq \phi(s,t)$, $s\in\mathbb{R}$, $t\geq0$.
 By the maximum principle for  \eqref{eq:basic_one_dim}, 
see Theorem~\ref{thm:strongmaxprinciple} with $d=1$, either
 $\phi\equiv \phi^\delta$, that contradicts $\delta>0$ or
 $\phi^\delta(s,t)< \phi(s,t)$, $s\in\mathbb{R}$, $t>0$. The latter, however,
 contradicts the equality $\phi^\delta(s,t)=\phi(s,t)$, which holds 
e.g.\ for $s=s_0+ct$, $ct< \delta_0$. Hence $\psi$ is a strictly decaying function.
\end{proof}

To prove the last item of Theorem~\ref{thm:trwexist}, one can weaken the 
assumption \eqref{as:a+nodeg1d}, assuming that $a^+$ is not degenerated in 
the direction $\xi$ (not necessarily at the origin). Namely, we assume 
that there exist $r\geq0$, $\rho,\delta>0$ (depending on $\xi$), such that
 \begin{equation} \label{as:a+nodeg-mod}
  \int_{\{x\cdot\xi=s\}}a^{+}(x)\,dx \geq\rho\quad \text{for a.a. }
s\in [r- \delta, r+ \delta].
 \end{equation}

\begin{proposition}\label{prop:trw_willbe_incr}
 Let \eqref{as:chiplus_gr_m}, \eqref{as:aplus_gr_aminus-intro} and 
\eqref{as:a+nodeg-mod} hold. Let $\psi\in\mathcal{M}_\theta(\mathbb{R})$, $c\in\mathbb{R}$, $c\neq0$, 
$\xi\in S^{d-1} $ be such that there exists a solution $u\in\mathcal{U}_\infty$ 
to  \eqref{eq:basic} such that \eqref{eq:deftrw} holds. 
Then there exists $\nu>0$, such that $\psi(t)e^{\nu t}$ is a strictly 
increasing function.
\end{proposition}

\begin{proof}
We start from the case $c>0$. Since $\psi(t)>0$ for $t\in\mathbb{R}$, it is sufficient 
to prove that
 \begin{equation}\label{weneed}
 \frac{\psi'(t)}{\psi(t)}> -\nu,\quad t\in\mathbb{R}.
 \end{equation}
 Fix any $\mu\geq\frac{\kappa^+ }{c}>0$. Then, clearly,
 \[
 \kappa_{\ell}\psi^2(t) + \kappa_{n\ell}(\check{a}^- *\psi)(t)+m\leq \kappa^- \theta+m=\kappa^+ \leq c\mu,
 \]
 and from \eqref{eq:trw}, we obtain
 \begin{equation}
0\geq c\psi'(s)+\kappa^+ (\check{a}^+ *\psi)(s)-c\mu\psi(s), \quad s\in\mathbb{R}.
\label{ineq1}
\end{equation}
Multiply both parts of \eqref{ineq1} on $e^{-\mu s}>0$ and set
\[
w(s):=\psi(s)e^{-\mu s}>0, \quad s\in\mathbb{R}.
\]
Then $w'(s)=\psi'(s)e^{-\mu s}-\mu w(s)$ and one can rewrite \eqref{ineq1} 
as follows
\begin{equation}
 \begin{aligned}
0&\geq c w'(s)+\kappa^+ (\check{a}^+ *\psi)(s)e^{-\mu s} \\
&=c w'(s)+\kappa^+ \int_\mathbb{R}\check{a}^+ (\tau)w(s-\tau)e^{-\mu \tau}d\tau,
\quad s\in\mathbb{R}.
\end{aligned} \label{eq:w_est}
\end{equation}

By \eqref{as:a+nodeg-mod}, there exists $\varrho:=\frac{r}{2}+\frac{\delta}{4}>0$, 
such that
\begin{equation}\label{intfrom2rhoispos}
\int_{2\varrho}^{\infty}\check{a}^+ (s)e^{-\mu s}ds>0.
\end{equation}
Integrating \eqref{eq:w_est} over $s\in[t,t+\varrho]$, one gets
 \begin{equation}\label{asd3}
 0 \geq c(w(t+\varrho)-w(t))
+\kappa^+ \int_{t}^{t+\varrho}\int_\mathbb{R}\check{a}^+
(\tau)w(s-\tau)e^{-\mu \tau}d\tau ds.
\end{equation}
Since $w(t)$ is a monotonically decreasing function, we have
\begin{equation}
 \begin{aligned}
\int_{t}^{t+\varrho}\int_\mathbb{R}\check{a}^+ (\tau)w(s-\tau)e^{-\mu \tau}d\tau ds
&\geq \varrho\int_\mathbb{R}\check{a}^+ (\tau)w(t+\varrho-\tau)e^{-\mu \tau}d\tau  \\
&\geq \varrho \int_{2\varrho}^{\infty}\check{a}^+
 (\tau)w(t+\varrho-\tau)e^{-\mu \tau}d\tau  \\
&\geq \varrho w(t-\varrho)\int_{2\varrho}^{\infty}\check{a}^+
 (\tau)e^{-\mu \tau}d\tau.
\end{aligned}\label{asd4}
\end{equation}
We set, cf.\ \eqref{intfrom2rhoispos},
\[
C(\mu,\rho):=\frac{\kappa^+ }{c}\int_{2\varrho}^{\infty}\check{a}^+ (s)
e^{-\mu s}ds>0.
\]
Then \eqref{asd3} and \eqref{asd4} yield
 \begin{equation}\label{eq:ln_fy_est_i}
 w(t) -\varrho C(\mu,\rho)w(t-\varrho)\geq w(t+\varrho)>0,\quad t\in\mathbb{R}.
 \end{equation}
Now we integrate \eqref{eq:w_est} over $s\in[t-\varrho,t]$. Similarly to above,
 one gets
\begin{equation}
 \begin{aligned}
 0 &\geq c(w(t)-w(t-\varrho))+\kappa^+ \int_{t-\varrho}^{t}
 \int_\mathbb{R}\check{a}^+ (\tau)w(s-\tau)e^{-\mu \tau}d\tau ds   \\
 &\geq c(w(t)-w(t-\varrho))+\varrho\kappa^+ \int_\mathbb{R}\check{a}^+
 (\tau)w(t-\tau)e^{-\mu \tau}d\tau.
\end{aligned}\label{asda12}
\end{equation}
 By \eqref{eq:ln_fy_est_i} and \eqref{asda12}, we have
 \begin{equation}\label{eq:ln_fy_est_ii}
 \frac{1}{\varrho C(\mu,\rho)}\geq \frac{ w(t-\varrho)}{w(t)}
\geq 1 +\frac{\varrho\kappa^+ }{c}\int_\mathbb{R}\check{a}^+
(\tau)\frac{w(t-\tau)}{w(t)}e^{-\mu \tau}d\tau.
 \end{equation}
On the other hand, \eqref{eq:trw} implies that
 \begin{equation}
-\frac{\psi'(t)}{\psi(t)}
\leq \frac{\kappa^+ }{c}\frac{(\check{a}^+ *\psi)(t)}{\psi(t)}
=\frac{\kappa^+ }{c}\int_\mathbb{R}\check{a}^+ (\tau)
\frac{w(t-\tau)}{w(t)}e^{-\mu \tau}d\tau, \quad t\in\mathbb{R}. \label{eq:ln_fy_est_ii11}
\end{equation}
Finally, \eqref{eq:ln_fy_est_ii} and \eqref{eq:ln_fy_est_ii11} yield
\eqref{weneed} with $\nu=\frac{1}{\rho^2 C(\mu,\rho)}>0$.

Let now $c<0$. For any $\nu\in\mathbb{R}$, one has
\begin{equation*}
\psi'(s)=e^{-\nu s}(\psi(s)e^{\nu s})'-\nu \psi(s),\quad s\in\mathbb{R}.
\end{equation*}
Hence, by \eqref{eq:trw}, \eqref{as:aplus_gr_aminus-intro},
\begin{align*}
 0&= ce^{-\nu s}(\psi(s)e^{\nu s})'-c\nu\psi(s)+\kappa^+(\check{a}^+ *\psi)(s) \\
  &\quad  -\kappa_{\ell}\psi^2(s)-\kappa_{n\ell}\psi(s)(\check{a}^- *\psi)(s)-m\psi(s) \\
&\geq ce^{-\nu s}(\psi(s)e^{\nu s})'-c\nu\psi(s) +\kappa^+(\check{a}^+ *\psi)(s) \\
  &\quad  - \kappa_{\ell}\theta\psi(s) -\kappa_{n\ell}\theta(\check{a}^- *\psi)(s)-m\psi(s) \\
&\geq ce^{-\nu s}(\psi(s)e^{\nu s})'-c\nu\psi(s) -\kappa_{\ell} \theta \psi(s) -m\psi(s),\quad
  s\in\mathbb{R}.
\end{align*}
As a result, choosing $\nu>\frac{m+\kappa_{\ell}\theta}{-c}$, one gets
\begin{equation*}
-c e^{-\nu s}(\psi(s)e^{\nu s})'\geq(-c\nu-\kappa_{\ell}\theta -m)\psi(s)>0,\quad s\in\mathbb{R},
\end{equation*}
i.e. $\psi(s)e^{\nu s}$ is an increasing function.
\end{proof}

Combining Propositions \ref{prop:trwexists}, \ref{prop:reg_trw}, 
\ref{prop:trw_exp_est}--\ref{prop:trw_willbe_incr} and 
Corolalry~\ref{cor:infsmoothprofile}, we prove Theorem~\ref{thm:trwexist}.

\subsection*{Acknowledgments}
The authors gratefully acknowledge the financial support by the DFG 
through CRC 701 ``Stochastic Dynamics: Mathematical Theory and Applications''
 (DF, YK, PT),  by the European Commission under the project 
STREVCOMS PIRSES-2013-612669 (DF, YK), and by the ``Bielefeld Young Researchers'' 
Fund through the Funding Line Postdocs: ``Career Bridge Doctorate -- Postdoc'' (PT).

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