\documentclass[reqno]{amsart}
\usepackage{hyperref}

\AtBeginDocument{{\noindent\small
\emph{Electronic Journal of Differential Equations},
Vol. 2018 (2018), No. 97, pp. 1--13.\newline
ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu}
\thanks{\copyright 2018 Texas State University.}
\vspace{8mm}}

\begin{document}
\title[\hfilneg EJDE-2018/97\hfil
 Sublinear fractional Schr\"odinger-type  equations]
{Infinitely many solutions for sublinear fractional Schr\"odinger-type equations
with general potentials}

\author[G.-L. Hou, B. Ge, J.-F. Lu \hfil EJDE-2018/97\hfilneg]
{Gang-Ling Hou, Bin Ge, Jian-Fang Lu}

\address{Gang-Ling Hou \newline
College of Aerospace and Civil Engineering,
Harbin Engineering  University,
Harbin, 150001, China}
\email{hougl@hrbeu.edu.cn}

\address{Bin Ge (corresponding author) \newline
Department of Applied Mathematics,
Harbin Engineering  University,
Harbin, 150001, China}
\email{gebin791025@hrbeu.edu.cn}

\address{Jian-Fang Lu \newline
Department of Applied Mathematics,
Harbin Engineering  University,
Harbin, 150001,  China}
\email{1176678630@qq.com}

\dedicatory{Communicated by Vicentiu D. Radulescu}

\thanks{Submitted January 27, 2018. Published April 24, 2018.}
\subjclass[2010]{26A33, 35J60, 47J30}
\keywords{Fractional Laplacian; variational method; sublinear; genus}

\begin{abstract}
 This article  concerns the fractional Schr\"odinger type equations
 $$
 (-\Delta)^\alpha u+V(x)u =f(x,u) \quad\text{in } \mathbb{R}^N,
 $$
 where $N\geq 2$, $\alpha\in(0,1)$, $(-\Delta)^\alpha$ stands for the
 fractional  Laplacian, $V$ is a positive continuous potential,
 $f\in C(\mathbb{R}^N\times\mathbb{R},\mathbb{R})$.
 We establish  criteria that guarantee the existence of infinitely many
 solutions by using the genus properties in critical point theory.
\end{abstract}

\maketitle
\numberwithin{equation}{section}
\newtheorem{theorem}{Theorem}[section]
\newtheorem{lemma}[theorem]{Lemma}
\newtheorem{definition}[theorem]{Definition}
\allowdisplaybreaks

\section{Introduction} \label{intro}

In this article, we consider the  nonlinear Schr\"odinger-type equation
\begin{equation} \label{eP}
 (-\Delta)^\alpha u+V(x)u =f(x,u)\quad\text{in } \mathbb{R}^N,
\end{equation}
where $N\geq 2$, $\alpha\in(0,1)$, $(-\Delta)^\alpha$ stands for the fractional
Laplacian, $V$ is a positive continuous potential,
 $f\in C(\mathbb{R}^N\times\mathbb{R},\mathbb{R})$.
The fractional Laplacian $(-\Delta)^\alpha$ with  $\alpha\in(0,1)$ of a
function $\phi\in \mathcal {S}$ is defined by
$$
\mathcal{F}(((-\Delta)^\alpha)\phi)(\xi)=|\xi|^{2\alpha}\mathcal{F}(\phi)(\xi),\quad
\forall \alpha\in(0,1),
$$
where $\mathcal {S}$ denotes the Schwartz space of rapidly
decreasing $C^\infty$ functions in $\mathbb{R}^N$, $\mathcal {F}$ is
the Fourier transform, i.e.,
$$
\mathcal {F}(\phi)(\xi)=\frac{1}{(2\pi)^{N/2}}\int_{\mathbb{R}^N}e^{-2\pi
i\xi\cdot x}\phi(x)dx.
$$
If $\phi$ is smooth enough, it can also be
computed by the following singular integral
$$
(-\Delta)^{\alpha}\phi(x)=c_{N,\alpha}\operatorname{P.V.}
\int_{\mathbb{R}^N}\frac{\phi(x)-\phi(y)}{|x-y|^{N+2\alpha}}dy.
$$
Here $\operatorname{P.V.}$ is the principal value and $c_{N,\alpha}$ is a
normalization constant.

The fractional Schr\"odinger equation is a fundamental equation of
fractional quantum mechanics. It was discovered by
Laskin \cite{1,2} as a result of extending the Feynman path integral,
from the Brownian-like to L\'{e}vy-like quantum mechanical
paths, where the Feynman path integral leads to the classical
Schr\"odinger equation, and the path integral over L\'{e}vy
trajectories leads to the fractional Schr\"odinger equation.
The study of the fractional Schr\"odinger equations and the corresponding
variational problems has received more and more interest in recent years.
For example, \cite{128,124,125}
studied fractional elliptic problems with critical growth, \cite{8,129}
gave some sufficient conditions for the existence of positive solutions
to fractional elliptic equation, \cite{3,7,4,5} studied the existence of
ground state solutions on $\mathbb{R}^N$ and \cite{126} studied
fractional Kirchhoff equations. For more results about the fractional
Schr\"odinger equations, we
refer to \cite{6,123,130,127,9,10}.

It is well known, the main difficulty in treating problem \eqref{eP} in
$\mathbb{R}^N$ arises from the lack of compactness of the Sobolev
embeddings, which prevents from checking directly that the energy
functional associated with \eqref{eP} satisfies the $C$-condition. To
overcome the difficulty of the noncompact embedding, Teng \cite{11},
 Xu-Wei-Dong \cite{12}, Chen \cite{121}, Bisci-Radulescu \cite{122},
also establish a new compact
embedding theorems for the subspace of $H^\alpha(\mathbb{R}^N)$.
Furthermore, the authors able to guarantee
the existence and multiplicity of nontrivial weak solutions of \eqref{eP}
in $E=\{u\in H^\alpha(\mathbb{R}^N):\int_{\mathbb{R}^N}|
(-\Delta)^{\alpha/2}u(x)|^{2}dx
+\int_{\mathbb{R}^N}V(x)u^2dx <+\infty\}$ provided $\inf
V>0$ and the following conditions hold:
\begin{itemize}
\item[(A1)] For any  $M>0$, there exists  $r_0>0$ such that
\begin{align*}
\lim_{|y|\to\infty}\mu(\{x\in\mathbb{R}^N: |x-y|\leq r_0,  V(x)\leq M\})=0,
 \end{align*}
 where $\mu$ is the Lebesgue measure on $\mathbb{R}^N$.
\end{itemize}

We emphasize that in our approach, no coerciveness hypothesis
(A1) and not necessarily radially symmetric will be required on
the potential $V$. To the best of our knowledge, few works
concerning on this case up to now. Inspired by the above facts and
aforementioned papers, the main purpose of this paper is to study
the existence of infinitely many solutions for  \eqref{eP} when
$F(x,u)$ satisfies sublinear in $u$ at infinity. Our tool used here is the
genus properties in critical point theory. Before stating
our main results, we first make some assumptions on the functions
$V$ and $f$. For the potential $V$, we make the following
assumption
\begin{itemize}
\item[(A2)] $V\in C(\mathbb{R}^N)$ and
$V_0:=\inf_{x\in\mathbb{R}^N} V(x)>0$.
\end{itemize}

For the nonlinearity $f$, we suppose it satisfies the following
conditions:
\begin{itemize}
\item[(A3)]  (1)  $f\in C(\mathbb{R}^N\times\mathbb{R},\mathbb{R})$
and there exist constant $1<r<2$ and positive function
$a\in L^{\frac{2}{2 -r }}(\mathbb{R}^N)$ such that
$$
|f(x,t)|\leq a(x)|u|^{r-1}, \;\forall(x,t)\in \mathbb{R}^N\times\mathbb{R}.
$$
(2) There exist a bounded open set $I\subset\mathbb{R}^N$ and three
constants $\delta,\rho>0$  and $\theta\in(1,2)$ such that
$$
F(x,t)\geq \rho|t|^{\theta},\;\forall (x,t)\in I\times [-\delta,\delta],
$$
where $F(x,t)=\int_0^t f(x,s)ds$.
\end{itemize}

The same problem is studied by Shi and Chen \cite{122}. The authors established
the existence of at least $k$ distinct pairs of solutions for\eqref{eP} by
using the Clark theorem. Inspired by the above-mentioned papers,
we study problem \eqref{eP} in the different method. More precisely,
the aim of this work is to prove the existence of infinitely many solutions
by using the genus properties in critical point theory.
We are now in the position to state our main results.

\begin{theorem}\label{thm1.1}
Suppose that {\rm (A2)} and {\rm (A3)} hold.
Then  \eqref{eP} possesses at least one nontrivial solution.
\end{theorem}

\begin{theorem}\label{thm1.2}
Suppose that {\rm (A2)} and {\rm (A3)} hold,
and $f$ satisfies
$$
f(x,-t)=-f(x,t),\;\forall (x,t)\in \mathbb{R}^N\times\mathbb{R}.
$$
Then  \eqref{eP} possesses infinitely many solutions.
\end{theorem}

The rest of this article is organized as follows.
In Section 2, we state and  prove  some preliminary results that will be used later.
We will  finish the proof of our main result (Theorem \ref{thm1.1} and
Theorem \ref{thm1.2}) in Section 3.

\section{Preliminaries}

In this section we recall some results on Sobolev spaces of
fractional order. A very complete introduction to fractional Sobolev
spaces can be found in  \cite{13}.

Consider the fractional order Sobolev space
$$
H^\alpha(\mathbb{R}^N)=\big\{u\in L^2(\mathbb{R}^N):
 \int_{\mathbb{R}^N}\big(|\xi|^{2\alpha}\hat{u}^2
+\hat{u}^2\big)d\xi<+\infty\big\},
$$
where $\hat{u}\doteq \mathcal {F}(u)$. The norm is defined by
$$
\|u\|_{H^\alpha(\mathbb{R}^N)}=\Big(
\int_{\mathbb{R}^N}(|\xi|^{2\alpha}\hat{u}^2+\hat{u}^2)d\xi\Big)^{1/2}.
$$
\indent In this paper we consider its subspace:
$$
E=\big\{u\in  H^\alpha(\mathbb{R}^N): \int_{\mathbb{R}^N}V(x)u^2dx<+\infty\big\}
$$
with the norm
$$
\|u\|_{E}=\Big(
\int_{\mathbb{R}^N}(|\xi|^{2\alpha}\hat{u}^2+\hat{u}^2)d\xi
+\int_{\mathbb{R}^N}V(x)u^2dx\Big)^{1/2}.
$$
Note that, by Plancherel's theorem we have $|\hat{u}|_2=|u|_2$ and
\begin{align*}
\int_{\mathbb{R}^N}|(-\Delta)^{\alpha/2}u(x)|^{2}dx
=&\int_{\mathbb{R}^N}(\widehat{(-\Delta)^{\alpha/2}u(\xi)})^{2}d\xi\\
=&\int_{\mathbb{R}^N}(|\xi|^{\alpha}\hat{u}(\xi))^{2}d\xi\\
=&\int_{\mathbb{R}^N}|\xi|^{2\alpha}\hat{u}^{2}d\xi <+\infty, \;
\forall u\in H^\alpha(\mathbb{R}^N).
\end{align*}
Together with (A2), it follows that the norm $\|\cdot\|_E$ is
equivalent to the norm
$$
\|u\|=\Big(\int_{\mathbb{R}^N}|(-\Delta)^{\alpha/2}u(x)|^{2}dx
+\int_{\mathbb{R}^N}V(x)u^2dx\Big)^{1/2}.
$$ 
Throughout out this paper, we will use the norm $\|u\|$ in $E$.

\begin{lemma}[\cite{8}] \label{lem2.1}
$H^\alpha(\mathbb{R}^N)$ continuously
embedded into $L^p(\mathbb{R}^N)$ for $p\in[2,2_\alpha^*]$, and
compactly embedded into $L_{\rm loc}^p(\mathbb{R}^N)$ for
$p\in[2,2_\alpha^*)$.
\end{lemma}

\begin{lemma} \label{lem2.2} 
Assume that {\rm (A2), (A3)} hold. Then the functional $\varphi: E
\to \mathbb{R}$ defined by
\begin{equation}\label{2.1}
\varphi(u)=\frac{1}{2}\int_{\mathbb{R}^N}\Big[|(-\Delta)^{\alpha/2}
u(x)|^{2}+V(x)u^2\Big]dx-\int_{\mathbb{R}^N}F(x,u)dx
\end{equation}
is well defined and of class $C^1(E,\mathbb{R})$ and
\begin{equation}\label{2.2}
\langle\varphi'(u),v\rangle=\int_{\mathbb{R}^N}\Big[
(-\Delta)^{\alpha/2}u(-\Delta)^{\alpha/2}v+V(x)uv\Big]dx
-\int_{\mathbb{R}^N}f(x,u)v\,dx.
\end{equation}
Moreover, the critical points of $\varphi$ in $E$ are solutions of
problem \eqref{eP}.
\end{lemma}

\begin{proof} 
The functional $\varphi$ is well defined on $E$.
Indeed, by virtue of (A3)(1) and the Mean Value
Theorem, we have
\begin{equation}\label{2.3}
F(x,t)\leq \frac{a(x)}{r}|t|^{r}, \quad\forall
(x,t)\in\mathbb{R}^N\times\mathbb{R}.
\end{equation}

For any $u\in E$, we obtain for  (A2), \eqref{2.3},  and
H\"older inequality that
\begin{equation}\label{2.4}
\begin{aligned}
 \int_{\mathbb{R}^N}|F(x,u)|dx
  \leq&\int_{\mathbb{R}^N}\frac{a(x)}{r}|u|^{r}dx\\
 \leq & \int_{\mathbb{R}^N} a(x) |u|^{r}dx\\
    =& \int_{\mathbb{R}^N} \frac{a(x)}{V(x)^{r/2}} V(x)^{r/2}|u|^{r}dx\\
\leq& \frac{1}{V_0^{r/2}}\int_{\mathbb{R}^N}  a(x)  V(x)^{r/2}|u|^{r}dx\\
\leq& \frac{1}{V_0^{r/2}}|a|_{\frac{2}{2-r}}
\Big|V^{r/2}|u|^{r} \Big|_{\frac{2}{r}}\\
=& \frac{1}{V_0^{r/2}}|a|_{\frac{2}{2-r}}
\|u\|^{r}\\
\end{aligned}
\end{equation}
and so $\varphi$ defined by \eqref{2.1} is well defined on $E$.

Next, we prove that \eqref{2.2} holds. For any $\lambda\in(0,1)$,
one can deduce from $H(f)(1)$ and the H\"older inequality that
\begin{equation}\label{2.5}
\begin{aligned}
&\int_{\mathbb{R}^N}\max_{t\in[0,1]}|f(x,u+th)h|dx\\
&\leq \int_{\mathbb{R}^N}\max_{t\in[0,1]}|f(x,u+th)||h|dx\\
&\leq \int_{\mathbb{R}^N}a(x)(|u|+|h|)^{r-1}|h|dx\\
&\leq \int_{\mathbb{R}^N}ra(x)(|u|^{r-1}+|h|^{r-1})|h|dx\\
&=\int_{\mathbb{R}^N}r\frac{a(x)}{V^{r/2}}\Big[(V^{\frac{r-1}{2}}|u|^{r-1})(V^{1/2}|h|)+V^{r/2}|h|^{r}\Big]dx\\
&\leq \frac{r}{V_0^{r/2}}\int_{\mathbb{R}^N} a(x) \Big[(V^{\frac{r-1}{2}}|u|^{r-1})(V^{1/2}|h|)+V^{r/2}|h|^{r}\Big]dx\\
&\leq \frac{r}{V_0^{r/2}}\Big[|a|_{\frac{2}{2-r}}\big|V^{\frac{r-1}{2}}|u|^{r-1}\big|_{\frac{2}{r-1}}\big|V^{1/2}|h|\big|_2+|a|_{\frac{2}{2-r}}
\Big|V^{r/2}|h|^{r} \Big|_{\frac{2}{r}}\Big]\\
&\leq \frac{r}{V_0^{r/2}}|a|_{\frac{2}{2-r}}
\Big[\|u\|^{ r-1 }\|h\|+\|h\|^{ r }\Big]\\
&\leq \frac{r}{V_0^{r/2}}|a|_{\frac{2}{2-r}}
\big[\|u\|^{ r-1 }+\|h\|^{ r-1 }\big]\|h\|
<+\infty.
\end{aligned}
\end{equation}
Thus, by \eqref{2.1}, \eqref{2.5} and Lebesgue's Dominated
Convergence Theorem, we have
\begin{equation}\label{2.6}
\begin{aligned}
\langle\varphi'(u),v\rangle
&=\lim_{t\to
0^+}\frac{\varphi(u+th)-\varphi(u)}{t}\\
&= \int_{\mathbb{R}^N}\Big[
(-\Delta)^{\alpha/2}u(-\Delta)^{\alpha/2}v+V(x)uv\Big]dx\\
&\quad -\lim_{t\to0^+}\int_{\mathbb{R}^N}\frac{F(x,u+th)-F(x,u)}{t}dx\\
&= \int_{\mathbb{R}^N}\Big[
(-\Delta)^{\alpha/2}u(-\Delta)^{\alpha/2}v+V(x)uv\Big]dx\\
&\quad -\lim_{t\to 0^+}\int_{\mathbb{R}^N}f(x,u+t\lambda h)h\,dx\\
&= \int_{\mathbb{R}^N}\Big[
(-\Delta)^{\alpha/2}u(-\Delta)^{\alpha/2}v+V(x)uv\Big]dx
-\lim_{t\to 0^+}\int_{\mathbb{R}^N}f(x,u)h\,dx
\end{aligned}
\end{equation}
which implies that \eqref{2.2} holds. Moreover, by a standard
argument, it is easy to show that the critical points of $\varphi$
in $E$ are solutions of problem \eqref{eP} (see \cite{15}).

Next, we prove that $\varphi'$ is continuous on $E$. According to
\eqref{2.1}, it suffices to show that
\[
J'(u)=\int_{\mathbb{R}^N}f(x,u)dx.
\]
is continuous. Let $u_n\to u$ in $E$, then $u_n\to
u$ in $L^2(\mathbb{R}^N)$, since the imbedding $E\hookrightarrow
H^{\alpha}(\mathbb{R}^N)\hookrightarrow L^{2}(\mathbb{R}^N)$ is
continuous. Thus,
\begin{equation}\label{2.7}
u_n(x)\to u(x),\;{\rm a.e.}\;x\in\mathbb{R}^N.
\end{equation}
\indent We claim that
\begin{equation}\label{2.8}
\lim_{n\to+\infty}\int_{\mathbb{R}^N}\big|f(x,u_n(x))-f(x,u(x))\big|^2dx=0.
\end{equation}
Otherwise, there exists a constant $\varepsilon>0$ and a subsequence
$\{u_{n_k}\}_{k=1}^\infty$ such that
\begin{equation}\label{2.9}
 \int_{\mathbb{R}^N}\big|f(x,u_{n_k}(x))-f(x,u(x))\big|^2dx\geq\varepsilon,\; \forall k\geq 1.
\end{equation}
 Since $u_n\to u$ in $L^2(\mathbb{R}^N)$, passing to
a subsequence if necessary, it can be assumed that
\[
 C=:\sum_{k=1}^\infty |u_{n_k}-u|_2^2<+\infty.
\]
Set $w(x)=\big(\sum_{k=1}^\infty
|u_{n_k}(x)-u(x)|^2\big)^{1/2}$, $x\in \mathbb{R}^N$. Then
$w\in L^2(\mathbb{R}^N)$. Therefore,
\begin{align*}
&\int_{\mathbb{R}^N}\big|f(x,u_{n_k}(x))-f(x,u(x))\big|^2dx\\
&\leq 2\int_{\mathbb{R}^N} \big(|f(x,u_{n_k}(x))|^2+|f(x,u(x))|^2\big)dx\\
&\leq 2\int_{\mathbb{R}^N}
|a(x)|^2\big[|u_{n_k}(x)|^{2(r-1)}+|u(x)|^{2(r-1)}\big]dx\\
&= 2\int_{\mathbb{R}^N}
|a(x)|^2\big[|u_{n_k}(x)-u(x)+u(x)|^{2(r-1)}+|u(x)|^{2(r-1)}\big]dx\\
&\leq 2\int_{\mathbb{R}^N}
|a(x)|^2\big[(|u_{n_k}(x)-u(x)|+|u(x)|)^{2(r-1)}+|u(x)|^{2(r-1)}\big]dx\\
&\leq 24^{r-1}\int_{\mathbb{R}^N}
|a(x)|^2\big[|w(x)|^{2(r-1)}+|u(x)|^{2(r-1)}+|u(x)|^{2(r-1)}\big]dx\\
&\leq 4^{r}\int_{\mathbb{R}^N}
|a(x)|^2\Big[|w(x)|^{2(r-1)}+|u(x)|^{2(r-1)}\big]dx\\
&\leq 4^{r}
|a^2|_{\frac{1}{2-r}}\big[\big||w(x)|^{2(r-1)}\big|_{\frac{1}{r-1}}+\big||u(x)|^{2(r-1)}\big|_{\frac{1}{r-1}}\Big]dx\\
&=4^{r}
|a|_{\frac{2}{2-r}}^2\big[\big||w(x)|_2^{2(r-1)}+ |u|_2^{2(r-1)}\Big]dx\\
&\leq 4^{r}
|a|_{\frac{2}{2-r}}^2\big[\big||w(x)|_2^{2(r-1)}+ |u|_2^{2(r-1)}\Big]dx
<+\infty.
\end{align*}
Then by \eqref{2.7} and Lebesgue's Dominated Convergence Theorem,
we have
\[
\lim_{k\to+\infty}\int_{\mathbb{R}^N}\big|f(x,u_{n_k}(x))-f(x,u(x))\big|^2dx=0,
\]
which contradicts with \eqref{2.7}. Hence \eqref{2.8} holds.
Applying \eqref{2.2}, \eqref{2.8} and the H\"older inequality, we
have
\begin{align*}
&|\langle
J'(u_n)-J'(u),v\rangle|\\
&=\Big|\int_{\mathbb{R}^N}(f(x,u_n(x))-f(x,u(x)))v(x)dx\Big|\\
&\leq \int_{\mathbb{R}^N}|f(x,u_n(x))-f(x,u(x))||v(x)|dx \\
&\leq \Big(\int_{\mathbb{R}^N}|f(x,u_n(x))-f(x,u(x))|^2dx\Big)^{1/2} 
 \Big(\int_{\mathbb{R}^N}|v(x)|^2dx\Big)^{1/2}\\
&\leq \Big(\int_{\mathbb{R}^N}|f(x,u_n(x))-f(x,u(x))|^2dx\Big)^{1/2} 
\Big(\int_{\mathbb{R}^N}\frac{V(x)}{V_0}|v(x)|^2dx\Big)^{1/2}\\
&= \frac{1}{V_0^{1/2}}\Big(\int_{\mathbb{R}^N}|f(x,u_n(x))-f(x,u(x))|^2dx\Big)^{1/2}
 \Big(\int_{\mathbb{R}^N} V(x) |v(x)|^2dx\Big)^{1/2}\\
&\leq \frac{1}{V_0^{1/2}}\Big(\int_{\mathbb{R}^N}|f(x,u_n(x))-f(x,u(x))|^2dx
 \Big)^{1/2}\|v\|^{1/2}\\
&\to 0,\quad\text{as } n\to+\infty.
\end{align*}
This shows that $J'$ is continuous, and so $\varphi'$ is continuous.
The proof is completed.
\end{proof}

\begin{lemma}[\cite{16}] \label{lem2.3}
  Let $X$ be a real Banach space and $\varphi \in C^1(X,\mathbb{R})$ satisfies
the (PS)-condition. If $\varphi$ is bounded from blow, then
$c=\inf_{u\in X} \varphi(u)$ is a critical value of
$\varphi$.
\end{lemma}

To find multiplicity of nontrivial critical points of
$\varphi$, the following ``genus'' properties are needed in our
argument. Let $X$ be a Banach space, $\varphi\in C^1 (X,
\mathbb{R})$ and $c\in \mathbb{R}$. Set
\begin{gather*}
\Sigma=\{ A\subset X\setminus \{0\}: A\text{ is closed in $X$ and symmetric
 with respect to} 0\},\\
K_c^{\varphi}=\{u\in X: \varphi(u)=c,\,  \varphi'(u)=0\}\text{ and }
 \varphi^c=\{u\in X: \varphi(u)\leq c\}.
\end{gather*}

\begin{definition}[\cite{17}] \rm
For $A \in \Sigma$, we say genus
of $A$ is $n$ denoted by $\gamma(A)=n$ if there is an odd map $\phi
\in C(A, \mathbb{R}^n\backslash\{0\})$ and $n$ is the smallest
integer with this property.
\end{definition}

\begin{definition}[\cite{18}] \rm
  Let $X$ be a Banach space with $X^*$ being its topological dual and 
$\varphi\in C^1(X)$. We say that $\varphi$
satisfies the $Palais-Smale$ condition at level $c\in\mathbb{R}$ 
($PS_c$-condition for short), if any sequence $\{x_n\}_{n=1}^\infty\subseteq X$, 
such that
$$
\varphi(x_n)\to c,\;\;\varphi'(x_n)\to 0\;{\rm in}\; X^*,
$$
has a strongly subsequence. If this is true at every level $c\in\mathbb{R}$, 
then we simply say that  $\varphi$
satisfies the $Palais-Smale$ condition ($PS$-condition for short).
\end{definition}

The notion of genus generalizes the concept of dimension of a linear
space.

\begin{lemma}[{\cite[Proposition 4.2.15]{18}}] \label{lem2.4}
If $X$ is a Banach space and $U$ is a bounded symmetric neighborhood
of the origin in $X$, then $\gamma(\partial U) = {\rm dim} X$.
\end{lemma}

\begin{lemma}[\cite{17}] \label{lem2.5}
 Let $\varphi$ be an even $C^1$ functional on $X$ and satisfy the 
(PS)-condition. For any $n\in N$, set 
$$
\Sigma_n=\{A\in\Sigma: \gamma(A)\geq n\}\;{\rm and}\;
c_n=\inf_{A\in\Sigma_n}\sup_{u\in A}\varphi(u).
$$
\begin{itemize}
\item[(a)] If $\Sigma_n\neq\emptyset $ and $c_n\in\mathbb{R}$,
then $c_n$ is a critical value of $\varphi$;

\item[(b)] If There exists $l\in N$ such that
$c_l=c_{l+1}=\dots=c_{l+n}=c<+\infty$, then
$\gamma(K_c^{\varphi})\geq n+1$.
\end{itemize}
\end{lemma}

\section{Proofs of main results}

\begin{proof}[Proof of Theorem \ref{thm1.1}]
 We first prove that $\varphi$
is bounded from below. By (A3)(1), one yields
\begin{equation}\label{3.1}
\begin{aligned}
 |F(x,t)|=&\Big|F(x,0)+\int_0^t\frac{d}{ds}F(x,s)ds\Big|\\
         =& \Big|\int_0^t f(x,s)ds\Big|\\
      \leq&\int_0^t | f(x,s) | ds\\
\leq&  \frac{a(x)}{r}|t|^{r}
 \leq   a(x) |t|^{r},
\end{aligned}\end{equation}
for all $x\in \mathbb{R}^N$ and all $t\in\mathbb{R}$.

Hence,  from \eqref{2.4}  and \eqref{3.1}, we obtain
\begin{equation}\label{3.2}
\begin{aligned}
\varphi(u)=&\frac{1}{2}\int_{\mathbb{R}^N}\Big[|(-\Delta)^{\alpha/2}u(x)|^{2}+V(x)u^2\Big]dx-\int_{\mathbb{R}^N}F(x,u)dx\\
\geq& \frac{1}{2}\|u\|^{2}-\int_{\mathbb{R}^N}a(x)|u|^{r}dx\\
\geq& \frac{1}{2}\|u\|^{2}-
 \frac{1}{V_0^{r/2}}|a|_{\frac{2}{2-r}}
\|u\|^{ r }.
\end{aligned}
\end{equation}
Since $1<r<2$, \eqref{3.2} implies that $\varphi(u)\to+\infty$
as $\|u\|\to+\infty$. Hence $\varphi$ is bounded from below.

Next, we prove that $\varphi$ satisfies the $(PS)$-condition.
Suppose that $\{u_n\}_{n\in N}\subset E$ is a sequence such that
\[
 \varphi(u_n)\to c\text{ and }  \varphi'(u_n)\to 0,\quad \text{as }n\to+\infty.
\]
Then by \eqref{3.2}, there exist constants $C_0,C_1>0$ such that
\begin{equation}\label{3.3}
 |u_n|_2\leq C_0\|u_n\|\leq C_1,\quad \forall n\in N.
\end{equation}
So we may assume, going if necessary to a subsequence, that
 $$
u_n\rightharpoonup u_0\quad\text{weakly  in } E.
$$ 
From the choice of the function $a\in
L^{\frac{2}{2-r}}(\mathbb{R}^N)$, for any given number
$\varepsilon>0$, we can choose $R_\varepsilon>0$ such that
\begin{equation}\label{3.5}
 \Big(\int_{|x|>R_\varepsilon} |a(x)|^{\frac{2}{2-r}}
 dx\Big)^{\frac{2-r}{2}}<\varepsilon.
\end{equation}
 Since the embedding $E\hookrightarrow
L_{\rm loc}^{2}(\mathbb{R}^N)$ is compact, $u_n\rightharpoonup u_0$
in $E$ implies $u_n\to u_0$ in
$L_{\rm loc}^{2}(\mathbb{R}^N)$, and hence,
\begin{equation}\label{3.6}
\lim_{n\to+\infty} \int_{|x|\leq R_\varepsilon}
|u_n-u_0|^{2} dx=0.
\end{equation}
Let $B_\varepsilon=\{x\in\mathbb{R}^N:|x|\leq
R_\varepsilon\}$ and $B_\varepsilon^c=\mathbb{R}^N\setminus
B_\varepsilon$. By \eqref{3.6}, there exists
$n_0\in N$ such that
\begin{equation}\label{3.7}
|u_n-u_0|_{L^{2}(B_\varepsilon)}<\varepsilon,\;{\rm for}\;n\geq
n_0.
\end{equation}

Next, we prove that
  $$
\int_{\mathbb{R}^N}[f(x,u_n)-f(x,u_0)](u_n-u_0)dx\to 0,\quad\text{as } n\to+\infty.
$$ 
Indeed, by hypothesis (A3)(1), we have
\begin{equation}\label{3.10}
\begin{aligned}
&\int_{\mathbb{R}^N}|f(x,u_n)-f(x,u_0)|| u_n-u_0|dx\\
&\leq \int_{\mathbb{R}^N}a(x)[|u_n|^{r-1}+|u_0|^{r-1}]| u_n-u_0|dx\\
&=\int_{\mathbb{R}^N}\frac{a(x)}{V^{\frac{r-1}{2}}}
 V^{\frac{r-1}{2}}[|u_n|^{r-1}+|u_0|^{r-1}]| u_n-u_0|dx\\
&\leq {V_0}^{-\frac{r-1}{2}}
\int_{\mathbb{R}^N} a(x) V^{\frac{r-1}{2}}[|u_n|^{r-1}+|u_0|^{r-1}]| u_n-u_0|dx\\
&\leq {V_0}^{-\frac{r-1}{2}}\Big[
\int_{B_\varepsilon} a(x) V^{\frac{r-1}{2}}
 [|u_n|^{r-1}+|u_0|^{r-1}]| u_n-u_0|dx\\
&\quad +\int_{B_\varepsilon^c} a(x) V^{\frac{r-1}{2}}[|u_n|^{r-1}+|u_0|^{r-1}]|
 u_n-u_0|dx\Big]\\
&=: {V_0}^{-\frac{r-1}{2}}[I_1+I_2].
\end{aligned}\end{equation}

On the one hand, using the H\"older
inequality and \eqref{3.7}, we have
\begin{equation}\label{3.11}
\begin{aligned}
I_1
&= \int_{B_\varepsilon} a(x)
V^{\frac{r-1}{2}}[|u_n|^{r-1}+|u_0|^{r-1}]|
u_n-u_0|dx\\
&\leq  |a|_{L^{\frac{2}{2-r}}(B_\varepsilon)}\Big[\big|V^{\frac{r-1}{2}}|u_n|^{r-1}
\big|_{L^{\frac{2}{r-1}}(B_\varepsilon)} \\
&\quad +\big|V^{\frac{r-1}{2}}|u_0|^{r-1}
\big|_{L^{\frac{2}{r-1}}(B_\varepsilon)}\Big]|u_n-u_0|_{L^{2}(B_\varepsilon)}\\
&\leq \varepsilon|a|_{L^{\frac{2}{2-r}}(B_\varepsilon)}
 \Big[\big|V^{\frac{r-1}{2}}|u_n|^{r-1}
\big|_{L^{\frac{2}{r-1}}(B_\varepsilon)}
  +\big|V^{\frac{r-1}{2}}|u_0|^{r-1}
\big|_{L^{\frac{2}{r-1}}(B_\varepsilon)}\Big]\\
&\leq \varepsilon|a|_{L^{\frac{2}{2-r}}(\mathbb{R}^N)}
 \Big[\big|V^{\frac{r-1}{2}}|u_n|^{r-1}
\big|_{L^{\frac{2}{r-1}}(\mathbb{R}^N))}
 +\big|V^{\frac{r-1}{2}}|u_0|^{r-1}
\big|_{L^{\frac{2}{r-1}}(\mathbb{R}^N))}\Big]\\
&= \varepsilon|a|_{L^{\frac{2}{2-r}}(\mathbb{R}^N)}[\|u_n\|^{r-1}+\|u_0\|^{r-1}]\\
&\leq \varepsilon|a|_{L^{\frac{2}{2-r}}(\mathbb{R}^N)}
 \big[\big(\frac{C_1}{C_0}\big)^{r-1}+\|u_0\|^{r-1}\big]
\end{aligned}
\end{equation}
for all $n\geq n_0$.

 On the other hand, using the
H\"older inequality and \eqref{3.5}, we have
\begin{equation}\label{3.12}
\begin{aligned}
I_2&= \int_{B_\varepsilon^c} a(x)
V^{\frac{r-1}{2}}[|u_n|^{r-1}|+|u_0|^{r-1}]|
u_n-u_0|dx\\
&\leq |a|_{L^{\frac{2}{2-r}}(B_\varepsilon^c)}\Big[\big|V^{\frac{r-1}{2}}|u_n|^{r-1}
\big|_{L^{\frac{2}{r-1}}(B_\varepsilon^c)}\\
&\quad +\big|V^{\frac{r-1}{2}}|u_0|^{r-1}
\big|_{L^{\frac{2}{r-1}}(B_\varepsilon^c)}\Big]|u_n-u_0|_{L^{2}(B_\varepsilon^c)}\\
&\leq |a|_{L^{\frac{2}{2-r}}(B_\varepsilon^c)}\Big[\big|V^{\frac{r-1}{2}}|u_n|^{r-1}
\big|_{L^{\frac{2}{r-1}}(\mathbb{R}^N)}\\&+\big|V^{\frac{r-1}{2}}|u_0|^{r-1}
\big|_{L^{\frac{2}{r-1}}(\mathbb{R}^N)}\Big]|u_n-u_0|_{L^{2}(\mathbb{R}^N)}\\
&\leq C_0\varepsilon
\|u_n-u_0\|\Big[\big|V^{\frac{r-1}{2}}|u_n|^{r-1}
\big|_{L^{\frac{2}{r-1}}(\mathbb{R}^N)}
  +\big|V^{\frac{r-1}{2}}|u_0|^{r-1}
\big|_{L^{\frac{2}{r-1}}(\mathbb{R}^N)}\Big]\\
&\leq C_0\varepsilon
\|u_n-u_0\|\big[\|u_n\|^{r-1}+\|u_0\|^{r-1}\big]\\
&\leq 2C_0\varepsilon  \big[\|u_n\|^{r}+\|u_0\|^{r}\big]\\
&\leq 2C_0\varepsilon
 \Big[\big(\frac{C_1}{C_0}\big)^{r}+\|u_0\|^{r}\Big]\\
\end{aligned}
\end{equation}
for all $n\in N$.

 Since $\varepsilon$ is arbitrary, it follows from
\eqref{3.10}, \eqref{3.11} and \eqref{3.12} that
\begin{equation}\label{3.13}
\int_{\mathbb{R}^N}[f(x,u_n)-f(x,u_0)](u_n-u_0)dx\to 0\quad\text{as }
n\to+\infty.
\end{equation}
In view of the definition of weak convergence, we have
\begin{equation}\label{3.14}
\langle \varphi'(u_n)-\varphi'(u_0),u_n-u_0\rangle\to 0,\quad\text{as }n\to+\infty.
\end{equation}
Note that
\begin{equation}\label{3.15}
\begin{aligned}
&\langle \varphi'(u_n)-\varphi'(u_0),u_n-u_0\rangle\\
&= \int_{\mathbb{R}^N}\Big[
\big|(-\Delta)^{\alpha/2}(u_n-u_0)\big|^2+V(x)(u_n-u_0)^2\Big]dx\\
&\quad -\int_{\mathbb{R}^N}[f(x,u_n)-f(x,u_0)](u_n-u_0)dx\\
&=\|u_n-u_0\|^2-\int_{\mathbb{R}^N}[f(x,u_n)-f(x,u_0)](u_n-u_0)dx.
\end{aligned}
\end{equation}

From \eqref{3.13}, \eqref{3.14} and \eqref{3.15} it follows that
\begin{equation}\label{3.16}
\|u_n-u_0\|\to 0,\quad\text{as }n\to+\infty,
\end{equation}
which implies that $u_n\to u_0$ in $E$.
Therefore $\varphi$ satisfies the $(PS)$-condition. Then by
Lemma \ref{lem2.3}  we see that $c=\inf_{u\in E}\varphi(u)$ is a
critical value of $\varphi$, i.e., there exists a critical point
$u_0\in E$ such that $\varphi(u_0)=c$.

Finally, we prove that $u_0\neq 0$. Taking 
$\phi\in[H_0^{\alpha}(I)\cap E]\setminus\{0\}$ with $\|\phi\|=1$, then by
(A3)(2), for $t\in(0,1)$, we have
\begin{equation}\label{3.17}
\begin{aligned}
\varphi(t\phi)=&\frac{1}{2}\int_{\mathbb{R}^N}\Big[|(-\Delta)^{\alpha/2}(t\phi)\big|^2+V(x)| t\phi|^{2}\Big]dx- \int_{\mathbb{R}^N}F(x,t\phi)dx\\
=&
\frac{1}{2}t^{2}\|\phi\|^{2}-\int_{I}F(x,t\phi)dx\\
<&
\frac{1}{2}t^{2}-\int_{I}\rho|t\phi|^{\theta}dx\\
=&
\frac{1}{2}t^{2}-t^{\theta}\rho\int_{I}|\phi|^{\theta}dx.
\end{aligned}
\end{equation}
 Since $1<\theta<2$, it follows \eqref{3.17} that
$\varphi(t\phi)<0$ for $t>0$ small enough. Hence $c=\varphi(u_0)<0$.
Therefore $u_0$ is a nontrivial critical point of $\varphi$ with
$\varphi(u_0)=\inf_{u\in E}\varphi(u)$ and is a nontrivial
solution of problem \eqref{eP}. The proof is completed. 
\end{proof}

\begin{proof}[Proof of Theorem \ref{thm1.2}]
From the proof of Theorem \ref{thm1.1}, we know that $\varphi$ is bounded below 
and satisfies the $(PS)$-condition. It is clear from $F(x,-t)=F(x,t)$ 
that $\varphi$ is even and $\varphi(0)=0$. In order to apply 
Lemma \ref{lem2.5}, we prove now
that for any $n\in N$, there exists $K\subseteq
H^{\alpha}(\mathbb{R}^N)$ compact, and symmetric with $\gamma(K)=n$
such that $$\sup_{u\in K}\varphi(u)<0.$$
For any $n\in N$, we take $n$ disjoint open sets $I_i$ such that
$\cup_{i=1}^n  I_i\subset I$. For $i=1,2,\dots,n$, we choose
$u_i\in (H_0^{\alpha}(I_i)\cap E)\setminus\{0\}$ and
$|u_i|_{\theta}=1$. Let $E_n={\rm span}\{u_1,u_2,\dots,u_m\}$.
Because $E_n$ is a finite dimensional subspace of $E$, all norm are
equivalent and so we can find $0<C_3<1$ such that
\begin{equation}\label{3.18}
 C_3\|u\|\leq |u|_{\theta}\leq \frac{1}{C_3}\|u\|,\quad\forall
 u\in E_n.
\end{equation}
\indent From (A3)(2), and use \eqref{3.18} again we see that
for any $u\in E_n$, we have
\begin{equation}\label{3.19}
\begin{aligned}
 J(u)=&\int_{\mathbb{R}^N}F(x,u)dx
 = \int_{I}F(x,u)dx\\
\geq& \rho\int_{I}|u(x)|^{\theta}dx
 =\rho|u|_\theta^\theta\geq \rho C_3^\theta\|u\|^\theta.
\end{aligned}
\end{equation}
Set
\[
I(u)=
\int_{\mathbb{R}^N}\frac{1}{2}\Big[|(-\Delta)^{\alpha/2}u(x)|^{2}
+V(x)u^2\Big]dx.
\]
Then from \eqref{2.4} and \eqref{3.19}, it follows that for every
$u\in E_n$, 
\begin{equation}\label{3.20}
 \rho C_3^\theta\big[I(u)\big]^{\theta/2}
\leq J(u)
\leq {V_0}^{-r/2}|a|_{L^{\frac{2}{2-r}}(\mathbb{R}^N)}\big[I(u)
\big]^{r/2}.
\end{equation}

We consider the compact set 
$$
\mathcal {K}=\Big\{u\in E_n:
\big(\frac{1}{4}\big)^{\frac{\theta}{2-\theta}}\Big(\rho
C_3^{\theta}\Big)^{\frac{2}{2-\theta}}\leq J(u)\leq
\big(\frac{1}{2}\big)^{\frac{\theta}{2-\theta}}\Big(\rho
C_3^{\theta}\Big)^{\frac{2}{2-\theta}}\Big\}.
$$ 
Hence, for every $u\in \mathcal {K}$, we have
\begin{equation}\label{3.21}
\begin{aligned}
 \varphi(u)=&I(u)-J(u)\\
 \leq& \Big(\frac{1}{\rho
C_3^{\theta}}\Big)^{2/\theta}(J(u))^{2/\theta}-J(u)\\
=&\Big(\frac{1}{\rho
C_3^{\theta}}\Big)^{2/\theta}J(u)(J(u))^{\frac{2-\theta}{\theta}}-J(u)\\
\leq&\Big(\frac{1}{\rho
C_3^{\theta}}\Big)^{2/\theta}J(u)\frac{1}{2}\Big(\rho
C_3^{\theta}\Big)^{2/\theta}-J(u)\\
=&-\frac{1}{2}J(u) 
\leq -\frac{1}{2}\Big(\frac{1}{4}\Big)^{\frac{\theta}{2-\theta}}\Big(\rho
C_3^{\theta}\Big)^{\frac{2}{2-\theta}}
<0.
\end{aligned}
\end{equation}
 Because $E_n$ is isomorphic in $\mathbb{R}^n$, we can
identify $\mathcal {K}$ with a ring $\mathcal {K}'$ in
$\mathbb{R}^N$ such that$$ \partial B_1(0)=S^{n-1}=\{y\in
\mathbb{R}^n: |y|=1\}\subseteq \mathcal
  {K}'\subseteq\mathbb{R}^n\backslash \{0\}.$$
By lemma Lemma \ref{lem2.4},  we conclude that
\begin{equation}\label{3.22}
\gamma(\mathcal {K})=n.
\end{equation}
Let $c_n=\inf_{A\in\Sigma_n}\sup_{u\in A}\varphi(u)$.
 Then from \eqref{3.22} and the fact that $\varphi$ is
bounded below on $E$, we have $-\infty<c_n<0$, that is, for any
$n\in N$, $c_n$ is a real negative number. By Lemma \ref{lem2.5},
$\varphi$ admits infinitely many nontrivial critical points, and so
problem \eqref{eP} possesses infinitely many nontrivial negative energy
solutions. The proof is completed. 
\end{proof}

\subsection*{Acknowledgments}
This work was supported by the National Natural Science Foundation of 
China (Nos. U1706227, 11201095), by the Youth Scholar Backbone Supporting
 Plan Project of Harbin Engineering University, by the Fundamental 
Research Funds for the Central Universities, by the Postdoctoral research 
startup foundation of Heilongjiang (No. LBH-Q14044), and by the Science 
Research Funds for Overseas Returned Chinese Scholars of Heilongjiang 
Province (No. LC201502). 

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\end{document}
