\documentclass[reqno]{amsart}
\usepackage{hyperref}

\AtBeginDocument{{\noindent\small
\emph{Electronic Journal of Differential Equations},
Vol. 2016 (2016), No. 189, pp. 1--12.\newline
ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu}
\thanks{\copyright 2016 Texas State University.}
\vspace{8mm}}

\begin{document}
\title[\hfilneg EJDE-2016/189\hfil Nonexistence of positive global solutions]
{Nonexistence of positive global solutions to the differential equation
$u''-t^{-p-1}u^p=0$}

\author[M.-R. Li, T.-J. Chiang-Lin, Y.-S. Lee, D. W.-C. Miao
 \hfil EJDE-2016/189\hfilneg]
{Meng-Rong Li, Tsung-Jui Chiang-Lin, \\
 Young-Shiuan Lee, Daniel Wei-Chung Miao}

\address{Meng-Rong Li \newline
 Department of Mathematical Sciences,
 National Chengchi University, Taipei, Taiwan}
\email{liwei@math.nccu.edu.tw}

\address{Tsung-Jui Chiang-Lin \newline
Graduate Institute of Finance,
National Taiwan University of Science an Technology, Taipei, Taiwan}
\email{D9918005@mail.ntust.edu.tw}

\address{Young-Shiuan Lee \newline
Department of Statistics,
National Chengchi University,
Taipei, Taiwan}
\email{99354501@nccu.edu.tw}

\address{Daniel Wei-Chung Miao \newline
Graduate Institute of Finance,
National Taiwan University of Science and Technology,
Taipei, Taiwan}
\email{miao@mail.ntust.edu.tw}

\thanks{Submitted  May 15, 2016. Published July 13, 2016.}
\subjclass[2010]{34A34, 34C05}
\keywords{Blow-up; global solution; nonlinear differential equation}

\begin{abstract}
 In this article we consider the ordinary differential equation
 $$
 u''  -t^{-p-1} u^p =0.
 $$
 We show the blow-up for solutions of this equation, under
 certain on the initial data.
\end{abstract}

\maketitle
\numberwithin{equation}{section}
\newtheorem{theorem}{Theorem}[section]
\newtheorem{lemma}[theorem]{Lemma}
\newtheorem{remark}[theorem]{Remark}
\newtheorem{definition}[theorem]{Definition}
\allowdisplaybreaks

\section{Introduction}

In articles \cite{l1}--\cite{l6}, \cite{l8}--\cite{l10}
 we studied the semi-linear wave equation
 $\Box u+f(u)  =0$ under some conditions, and we found some
interesting results on blow-up, blow-up rate and estimates for 
the life-span of solutions, but no information on the
singular set. So we want to study some particular cases for lower
dimensional wave equations, therefrom we hope that we gain some experience for
for studying particular lower dimension later.

It is clear that the functions $t^{ -p-1}u^p$, with $p>1$, $u\geq0$ and $t\geq1$ 
is locally Lipschitz.  By standard theory,
the  existence and uniqueness of classical local solutions holds for the
equation
\begin{equation}
\begin{gathered}
u''- t^{-p-1} u^p=0,\quad p\in(1,\infty),\\
u(1)  =u_0,\quad u'(1)  =u_1.
\end{gathered}  \label{e0.1}
\end{equation}

\subsection*{Notation and fundamental Lemmas} 
First we make a substitution
\begin{gather*}
u=tv, \quad u'=v+tv',\quad u''=2v'+tv'',\\
t^{ p+1}u''  =2t^{ p+1} v'+t^{ p+2} v''=t^pv^p, \\
2tv'+t^2v''=v^p.
\end{gather*}
Set $s=\ln t$, $v(t)  =w(s)$, then $tv'=w_s$, $t^2v''=w_{ss}-w_s$.

For a given function $w$ in this work we use the following abbreviations:
\begin{gather*}
E_w(0)   =(u_1-u_0)  ^2-\frac{2}{p+1}u_0^{p+1},\quad a_w(s)  =w^2:=a(s)  ,\\
K(s)   :=K_w(s)  :=\int_0^sw_s^2(r)  dr,\quad
J(s)  :=J_w(s)  =w(s)^{-\frac{p-1}{2}}.
\end{gather*}
The equation \eqref{e0.1}  can be transformed into 
\begin{gather}
w_{ss}+w_s  =w^p,\label{e0.11}\\
w(0)  =w_0=u_0,\label{e0.12}\\
w_s(0)  =w_1=u_1-u_0. \label{e0.13}
\end{gather}
Using some elementary calculations we obtain the following lemmas.


\begin{lemma} \label{lem1} 
Suppose that $w$ is the solution of
\eqref{e0.11}, then 
\begin{gather}
K_s(s)  +2K(s)  -\frac{2}{p+1} w^{p+1}(s)  =E_w(0)  , \label{e0.14} \\
a_{ss}(s)  +a_s(s)  =2(w(s) ^{p+1}+K_s(s)  )  . \label{e0.15}
\end{gather}
\end{lemma}

\begin{lemma} \label{lem2}
Suppose that $w$ is the solution of \eqref{e0.11},  then
\begin{gather}
K(s)  =\frac{E_w(0)}{2}(1-e^{-2s}) 
 +\frac{2}{p+1}e^{-2s}\int_0^se^{2r}w^{p+1}(r)  dr,\label{e0.16}\\
\label{e0.17}
K_s(s) =E_w(0)  e^{-2s}+\frac{2}{p+1}w(s)  ^{p+1}
 -\frac{4}{p+1}e^{-2s}\int_0^se^{2r}w^{p+1}(r)  dr, \\
\label{e0.18}
\begin{aligned}
a_s(s)& =(a_s(0)  +2E_w(0)  )  e^{-s}-2E_w(0)  e^{-2s}\\
&\quad  +\frac{2}{p+1}\int_0^s(p-1 +4e^{r-s})  e^{r-s}w^{p+1}(r)  dr,
\end{aligned} \\
\label{e0.19}
\begin{aligned}
a_s  &  =-(p+1)  E_w(0)  +((p+1)  E_w(0)  +a_s(0)  )e^{-s}\\
& \quad +(p+3)  K(s)  +(p-1)  \int_0^s e^{r-s}K(r)  dr,
\end{aligned} \\
 \label{e0.20}
\begin{aligned}
J_{ss}(s)   
&  =-(p+1)  a(s) ^{-\frac{p+1}{2}-1}((-((p+1)  E_w(0)
+ a_s(0)  )  e^{-s})  )\\
&\quad  -(p^2-1)  a(s)  ^{-\frac{p+1}{2}-1}\int_0
^se^{r-s}K(r)  dr.
\end{aligned}
\end{gather}
\end{lemma}

\begin{proof}
 By \eqref{e0.14} and \eqref{e0.15} we have
\begin{gather*}
K_s(s)  +2K(s)  =E_w(0)
+\frac{2}{p+1}w(s)  ^{p+1},\\
(e^{2s}K(s)  )  _s   =e^{2s}(E_w(
0)  +\frac{2}{p+1}w(s)  ^{p+1})  ,\\
e^{2s}K(s)    =\frac{E_w(0)  }{2}(
e^{2s}-1)  +\frac{2}{p+1}\int_0^se^{2r}w^{p+1}(r)  dr.
\end{gather*}
Thus \eqref{e0.16} and \eqref{e0.17} are obtained.

By \eqref{e0.15} and \eqref{e0.16} we obtain
\begin{gather*}
e^s\big(a_{ss}(s)  +a_s(s)  \big)=2e^s\big(w(s)  ^{p+1}+K_s(s)  \big)  , \\
\begin{aligned}
e^sa_s(s)  &=a_s(0)  +\int_0^s 2e^{r}(w^{p+1}+K_s)  (r)  dr\\
&  =a_s(0)  +2e^sK(s)  +\int_0^s
2e^{r}(w^{p+1}-K)  (r)  dr,
\end{aligned} \\
\begin{aligned}
e^sa_s(s)   
& =a_s(0)  +2e^sK(s)  +\int_0^s2e^{r}w(r)  ^{p+1}dr\\
& \quad -\int_0^s2e^{r}(\frac{E_w(0)  }{2}(
1-e^{-2r})  +\frac{2}{p+1}e^{-2r}\int_0^{r}e^{2\eta}w^{p+1}(
\eta)  d\eta)  dr\\
&=a_s(0)  +2e^sK(s)  +\int_0^s
2e^{r}w^{p+1}(r)  dr-\int_0^sE_w(0)  (
e^{r}-e^{-r})  dr\\
& \quad -\frac{4}{p+1}\int_0^se^{-r}\int_0^{r}e^{2\eta}w^{p+1}(\eta)  d\eta\, dr,
\end{aligned}\\
\begin{aligned}
e^sa_s(s)   
&  =a_s(0)  +2e^sK-E_w( 0)  (e^s+e^{-s}-2)  +\int_0^s2e^{r}w^{p+1}(r)  dr\\
&  -\frac{4}{p+1}\int_0^se^{-r}\int_0^{r}e^{2\eta}w^{p+1}(\eta)  d\eta dr,
\end{aligned} \\
\begin{aligned}
e^sa_s(s)   &  =a_s(0)  +2e^sK(s)  -E_w(0)  (e^s+e^{-s}-2)  +\int_0
^s2e^{r}w^{p+1}(r)  dr\\
&  +\frac{4}{p+1}\Big(e^{-s}\int_0^se^{2\eta}w^{p+1}(
\eta)  d\eta-\int_0^se^{-r}e^{2r}w^{p+1}(r)  dr\Big)
\\
&  =a_s(0)  +2e^sK(s)  -E_w(0)
(e^s+e^{-s}-2)  +\int_0^s2e^{r}w^{p+1}(r) dr\\
& \quad +\frac{4}{p+1}\int_0^s(e^{-s}-e^{-r})  e^{2r} w^{p+1}(r)  dr,
\end{aligned} \\
\begin{aligned}
e^sa_s(s)   
&  =a_s(0)  +2e^sK(s)  -E_w(0)  (e^s+e^{-s}-2) \\
&\quad  +2\int_0^s[1+\frac{2}{p+1}(e^{r-s}-1)  ]e^{r}w^{p+1}(r)  dr\\
&  =a_s(0)  +2e^sK(s)  -E_w(0) (e^s+e^{-s}-2) \\
& \quad +\frac{2}{p+1}\int_0^s[p-1+2e^{r-s}]  e^{r}w^{p+1}(r)  dr,
\end{aligned} \\
\begin{aligned}
a_s(s)   &  =a_s(0)  e^{-s}+2(\frac{E_w(0)  }{2}(1-e^{-2s})  +\frac{2}{p+1}
e^{-2s}\int_0^se^{2r}w^{p+1}(r)  dr) \\
&\quad  -E_w(0)  (1+e^{-2s}-2e^{-s})  +\frac{2}{p+1}\int_0^s(p-1
+ 2e^{r-s})  e^{r-s}w^{p+1}(r)  dr\\
&  =a_s(0)  e^{-s}+E_w(0)  (1-e^{-2s}) \\
&\quad  +\frac{4}{p+1}e^{-2s}\int_0^se^{2r}w^{p+1}(r)
dr-E_w(0)  (1+e^{-2s}
-2e^{-s}) \\
&\quad  +\frac{2}{p+1}\int_0^s(p-1 + 2e^{r-s})  e^{r-s}w^{p+1}(r)  dr\\
&  =(a_s(0) +2E_w(0)  )  e^{-s}-2E_w(0)  e^{-2s}\\
& \quad +\frac{2}{p+1}\int_0^s(p-1
+4e^{r-s})  e^{r-s}w^{p+1}(r)  dr.
\end{aligned}
\end{gather*}
Therefore,  \eqref{e0.18} follows.

Now to prove \eqref{e0.19}. According to \eqref{e0.14} and
\eqref{e0.15}, we obtain that
\begin{align*}
e^sa_s(s) 
&=a_s(0)  +\int_0^s 2e^{r}(w^{p+1}+K_s)  (r)  dr\\
&  =a_s(0)  +\int_0^s2e^{r}\Big(\frac{p+1}{2}(
K_s+2K-E_w(0)  )  +K_s\Big)  (r) dr\\
&  =a_s(0)  -(p+1)  E_w(0)  (
e^s-1) \\
&\quad  +\int_0^se^{r}((p+3)  K_s+ 2(p+1)  K)  (r)  dr
\end{align*}
and
\begin{align*}
a_s(s)   &  =-(p+1)  E_w(0) +(a_s(0)
+ (p+1)  E_w(0)  )  e^{-s}\\
&\quad  +\int_0^se^{r-s}((p+3)  K_s
+ 2(p+1)  K)  (r)  dr\\
&  =-(p+1)  E_w(0)  +((p+1) E_w(0)+ a_s(0)  )  e^{-s}\\
&\quad  +(p+3)  K(s)  +(p-1)  \int_0^se^{r-s}K(r)  dr.
\end{align*}

To show \eqref{e0.20}, we use \eqref{e0.15} and the
definition  
$J(s)  :=J_w(s)  =a(s)^{-\frac{p+1}{2}}$,
$J_s=-\frac{p+1}{2}a(s) ^{-\frac{p+1}{2}-1}a_s$,
\begin{align*}
a_{ss}(s)   &  =-((p+1)  E_w(0)+ a_s(0)  )  e^{-s}+(p+3)  K_s(s) \\
&\quad  +(p-1)  K(s)  -(p-1)  \int_0^se^{r-s}K(r)  dr\\
&  =-((p+1)  E_w(0)  +a_s(0)  )  e^{-s}+(p+3)  K_s(s) 
  +(p-1)  \int_0^se^{r-s}K(r)  dr.
\end{align*}
\begin{align*}
 J_{ss}(s) 
&  =-\frac{p+1}{2}a(s)  ^{-\frac{p+1}{2}-2}\Big(a(
s)  a_{ss}(s)  -\frac{p+3}{2}a_s(s) ^2\Big) \\
& =-\frac{p+1}{2}a(s)  ^{-\frac{p+1}{2}-2}\Big(2a(s)  (-((p+1)  E_w(0)
+ a_s(0)  )  e^{-s})  \Big) \\
&  \quad -(p+1)  (p-1)  a(s)  ^{-\frac{p+1}{2}-1}\int_0^se^{r-s}K(r)  dr\\
&  =-(p+1)  J(s)  ^{1+\frac{2}{p+1}}\Big(-((p+1)  E_w(0)+a_s(0)  )  e^{-s}\\
&\quad +(p-1)  \int_0^s e^{r-s}K(r)  dr\Big)  .
\end{align*}
The above formulation is equivalent to assertion \eqref{e0.20}.
Thus Lemma \ref{lem2} is proved.
\end{proof}

\begin{definition} \label{def1} \rm
A function $g:\mathbb{R}\to\mathbb{R}$ has a blow-up rate $q$ means that 
$g$ exists only in finite time, that is, there is a finite number 
$T^{\ast}$ such that
\[
\lim_{t\to T^{\ast}}g(t)  ^{-1}=0
\]
 and there exists a non-zero $\beta\in\mathbb{R}$ with
\[
\lim_{t\to T^{\ast}}(T^{\ast}-t)  ^{q}g(t)=\beta,
\]
 in this case $\beta$ is called the blow-up constant of $g$.
\end{definition}

The following lemma is easy to prove so we omit its proof.

\begin{lemma} \label{lem3} 
If $g(t)$ and $h(t,r)$ are continuous with respect to their variables and the
limit $\lim_{t\to T}\int_0^{g(t)  }h(t,r)  dr$ exists, then
\[
\lim_{t\to T}\int_0^{g(t)  }h(t,r)
dr=\int_0^{g(T)  }h(T,r)  dr.
\]
\end{lemma}

\section{Nonexistence of global solution when $E_w(0) <0$}

In this section we want to show there is not global solution for \eqref{e0.1}
 under negative energy $E_w(0)<0$.

\begin{theorem} \label{thm1} 
If $T$  is the life-span of $u$  and $u$ is the positive solution of the 
problem \eqref{e0.1}  with $E_w(0)  <0$, then $T$ is finite. This means 
that the global solution of \eqref{e0.1}  does not exist for  
$(u_1 -u_0)  ^2<\frac{2}{p+1}u_0^{p+1}$.
\end{theorem}

\begin{proof}
We consider the cases $a_s(0)  >0$ and $a_s(0)  \leq0$. In the first case,
 using \eqref{e0.19} of Lemma \ref{lem2} we obtain that
\begin{align*}
a_s(s)  &=-(p+1)  E_w(0)  (1-e^{-s})  +a_s(0)  e^{-s}+(p+3)  K(s)  \\
&\quad +(p-1)  \int_0^se^{r-s}K(r)  dr>0
\end{align*}
for all $s\geq0$ and
\[
a(s) \geq-(p+1)  E_w(0)  (s-1+e^{-s})  +a_s(0)  (1-e^{-s}) 
 \geq1
\]
for
\[
s\geq s_0:=1+\frac{-1}{(p+1)  E_w(0)  }.
\]
According to Lemma \ref{lem1}, \eqref{e0.15} for $s\geq s_0$,
\begin{gather*}
\begin{aligned}
(a_{ss}+a_s)  (s)   
&=2\Big(w( s)  ^{p+1}-\frac{a(s)  }{4}\Big)  +2w_s(s)  ^2+\frac{w(s)  ^2}{2}\\
&  \geq2\Big(a(s)  ^{\frac{p+1}{2}}-\frac{a(s)}{4}\Big)  +2| w_sw| (s)  ,
\end{aligned} \\
\begin{aligned}
a_{ss}(s)   &  \geq2a(s)  \Big(a(s)^{\frac{p-1}{2}}-\frac{1}{4}\Big) \\
&  =\frac{a(s)  }{2}\Big(a(s)  ^{\frac{p-1}{2}
}-1\Big)  +\frac{3}{2}a(s)  ^{\frac{p+1}{2}}\\
&  \geq\frac{3}{2}a(s)  ^{\frac{p+1}{2}};
\end{aligned}
\end{gather*}
thus we obtain that \ there exists 
$s_1:=1-\frac{1}{E_w(0) }\frac{2^{\frac{2}{p+3}}}{p+1}a(s_0)  >s_0$ so that
\begin{gather*}
\begin{aligned}
(a_s^2(s)  )  _s  & =2a_s(s) a_{ss}(s) \\
&  \geq3a(s)  ^{\frac{p+1}{2}}a_s(s)  
=\frac {6}{p+3}(a(s)  ^{\frac{p+3}{2}})  _s,
\end{aligned} \\
a_s^2(s)   
  \geq\frac{6}{p+3}a(s)^{\frac{p+3}{2}}+a_s^2(s_0) 
  -\frac{6}{p+3}a( s_0)  ^{\frac{p+3}{2}}
  \geq\frac{3}{p+3}a(s)  ^{\frac{p+3}{2}}\,.
\end{gather*}
Since for $s\geq s_1$,
\begin{gather*}
a(s)   \geq-(p+1)  E_w(0)  (s-1 +e^{-s}) 
 \geq-(p+1)  E_w(0)  (s-1),
\\
a(s)  ^{\frac{p+3}{2}}  \geq(p+1)  ^{\frac{p+3}{2}}\big(-E_w(0)  
\big)  ^{\frac{p+3}{2}}(s-1)  ^{\frac{p+3}{2}}
  \geq2a(s_0)  ^{\frac{p+3}{2}}, \\
a_s(s)    \geq\sqrt{\frac{3}{p+3}}a(s)
^{\frac{p+3}{4}},\\
\frac{-4}{p-1}(a(s)  ^{\frac{1-p}{4}})  _s  
=a(s)  ^{-\frac{p+3}{4}}a_s\geq\sqrt{\frac{3}{p+3}},\\
\frac{-4}{p-1}a(s)  ^{\frac{1-p}{4}}    \geq\sqrt{\frac{3}{p+3}
}(s-s_1)  -\frac{4}{p-1}a(s_1)  ^{\frac{1-p}{4}},
\\
a(s)  ^{\frac{1-p}{4}}    \leq-\frac{p-1}{4}\Big(\sqrt
{\frac{3}{p+3}}(s-s_1)  -\frac{4}{p-1}a(s_1)
^{\frac{1-p}{4}}\Big);
\end{gather*}
therefore there exists
\[
S^{\ast}\leq S_1^{\ast}=s_1+\sqrt{\frac{p+3}{3}}\frac{4}{p-1}a(
s_1)  ^{\frac{1-p}{4}}
\]
such that
\[
a(s)  ^{\frac{1-p}{4}}\to
0\quad \text{for }s\to S^{\ast}.
\]
This means that the solution for of \eqref{e0.1} does not
exist for all $t\geq1$ and the life-span $T^{\ast}$ of $u$ is finite with
$T^{\ast}\leq\ln S_1^{\ast}$. Whereas, if $a_s(0)  \leq0$
using \eqref{e0.19} of Lemma \ref{lem2} again, we obtain that
\begin{align*}
a_s(s) & =-(p+1)  E_w(0)  (
1-e^{-s})  +a_s(0)  e^{-s}+(p+3)  K(s)  \\
&\quad +(p-1)  \int_0^se^{r-s}K(r)  dr>0
\end{align*}
for all large $s\geq s_2$, where $s_2$ is given by
\[
s_2=\ln(1+\frac{a_s(0)  }{(p+1)E_w(0)  })
\]
and
\[
a(s)  \geq-(p+1)  E_w(0)  (s-s_2
+e^{-s}-e^{-s_2})  +a_s(0)  (e^{-s_2}-e^{-s}) \\
  \geq1
\]
for all $s\geq s_3$, $s_3$ can be obtained by
\begin{align*}
&  -(p+1)  E_w(0)  (s_3+e^{-s_3
})  -a_s(0)  e^{-s_3}\\
&  =1-(p+1)  E_w(0)  (s_2+e^{-s_2})  -a_s(0)  e^{-s_2}
\end{align*}
According to Lemma \ref{lem1}, \eqref{e0.15}  for $s\geq s_3$,
\begin{gather*}
\begin{aligned}
(a_{ss}+a_s)  (s)   
&  =2\Big(w(s)  ^{p+1}-\frac{a(s)  }{4}\Big)  +2w_s(s)  ^2+\frac{w(s)  ^2}{2}\\
&  \geq2\Big(a(s)  ^{\frac{p+1}{2}}-\frac{a(s)}{4}\Big)  +2| w_sw| (s) ,
\end{aligned} \\
\begin{aligned}
a_{ss}(s)  
 &  \geq2a(s)  (a(s) ^{\frac{p-1}{2}}-\frac{1}{4}) \\
&  =\frac{a(s)  }{2}(a(s)  ^{\frac{p-1}{2}}-1)  +\frac{3}{2}a(s)  ^{\frac{p+1}{2}}\\
&  \geq\frac{3}{2}a(s)  ^{\frac{p+1}{2}};
\end{aligned}
\end{gather*}
thus we obtain that there exists $s_4>s_3$ such that for $s\geq s_4$,
\begin{gather*}
a(s_4)  ^{\frac{p+3}{2}}=-\frac{p+3}{3}a_s^2(
s_3)  +2a(s_3)  ^{\frac{p+3}{2}}, \\
\begin{aligned}
(a_s^2(s)  )  _s  
&  =2a_s(s) a_{ss}(s) \\
&  \geq3a(s)  ^{\frac{p+1}{2}}a_s(s) \\
&  =\frac{6}{p+3}(a(s)  ^{\frac{p+3}{2}})_s,
\end{aligned} \\
a_s^2(s)   \geq\frac{6}{p+3}a(s)^{\frac{p+3}{2}}+a_s^2(s_3)  
-\frac{6}{p+3}a( s_3)  ^{\frac{p+3}{2}}
\geq\frac{3}{p+3}a(s) ^{\frac{p+3}{2}},\\
a_s(s)  \geq\sqrt{\frac{3}{p+3}}a(s) ^{\frac{p+3}{4}}\quad \forall s\geq s_{4,}\\
\frac{-4}{p-1}(a(s)  ^{\frac{1-p}{4}})  _s  
=a(s)  ^{-\frac{p+3}{4}}a_s\geq\sqrt{\frac{3}{p+3}}\quad \forall s\geq s_{4,}\\
\frac{-4}{p-1}a(s)  ^{\frac{1-p}{4}}   \geq\sqrt{\frac{3}{p+3}
}(s-s_4)  -\frac{4}{p-1}a(s_4)  ^{\frac{1-p}{4}
}\quad \forall s\geq s_{4,}\\
a(s)  ^{\frac{1-p}{4}}   \leq-\frac{p-1}{4}\Big(\sqrt
{\frac{3}{p+3}}(s-s_4)  -\frac{4}{p-1}a(s_4)
^{\frac{1-p}{4}}\Big) 
\end{gather*}
therefore, there exists
\[
S_2^{\ast}\leq s_4+\sqrt{\frac{p+3}{3}}\frac{4}{p-1}a(s_4)
^{\frac{1-p}{4}}
\]
so that
\[
a(s)  ^{\frac{1-p}{4}}\to 0\quad \text{for } s\to S_2^{\ast}.
\]
This means that the solution for the problem \eqref{e0.1} does not
exist for all $t\geq1$ and the life-span $T^{\ast}$ of $u$ is finite with
$T^{\ast}\leq\ln S_2^{\ast}$.
\end{proof}



\section{Nonexistence of global solution when $E_w(0) >0$}

In this section we want to show there is no  global solution of 
\eqref{e0.1}  under positive energy $E_w(0)  >0$ when
 one of the following conditions holds
\begin{gather}
u_0(u_1-u_0) \geq 0,\label{ei}\\
u_0(u_1-u_0)   <0,\quad
u_1(u_1-u_0) >\frac{2}{p+1}u_0^{p+1}. \label{eii}
\end{gather}
We have the result for nonexistence of global solution of 
\eqref{e0.1}.

\begin{theorem} \label{thm2} 
If $T$  is the life-span of $u$  and $u$ is the positive solution 
of the problem \eqref{e0.1}   with $E_w(0)  >0$ and
$u_0(u_1-u_0) \geq0$, then $T$ is finite. 
This means that the global solution of \eqref{e0.1}
 does not exist for  $(u_1-u_0)  ^2>\frac{2}{p+1}u_0^{p+1}$,
$u_0(u_1-u_0)  \geq0$.

If $T$  is the life-span of $u$  and
$u$ is the positive solution of the problem \eqref{e0.1}
 with $E_w(0)>0$,  $u_0( u_1-u_0)  <0$  and $E_w(0)  +$ 
$u_0(u_1-u_0)  >0,$ then $T$ is finite.
This means that the global solution of \eqref{e0.1}  does
not exist for  $u_1(u_1-u_0)  >\frac{2}{p+1}u_0^{p+1}$.
\end{theorem}

\begin{remark} \label{rmk1} \rm 
 Under positive energy $E_w(0)  >0$, $u_0(u_1-u_0)  <0$ with
 $u_1(u_1-u_0)  \leq\frac{2}{p+1}u_0^{p+1}$ we conjecture that solutions 
of \eqref{e0.1}  exist globally, and the asymptotic behavior of such solutions
is similar to the function
\[
c+\frac{c^{-p}t^{1-p}}{p(p-1)}
\]
as $t\to\infty$, but we are unable to prove this rigorously.
\end{remark}


\begin{proof} Using Lemma \ref{lem2}, \eqref{e0.18}, $E_w(0)>0$ and
$u_0(u_1-u_0)  \geq0$ we obtain 
\begin{gather*}
e^sa_s(s) \geq(a_s(0) +2E_w(0)  )  -2E_w(0)  e^{-s}
 +\frac{2(p-1)  }{p+1}\int_0^se^{r}a(r)w^{p-1}(r)  dr, \\
A(s)  =\int_0^se^{r}w^{p+1}(r) dr,\quad
A_s(s)  =e^sa(s)  ^{\frac{p+1}{2}},\\
a(s)  =(e^{-s}A_s(s)  )^{\frac{2}{p+1}},\\
a_s(s) =\frac{2}{p+1}(e^{-s}A_s(s))  ^{\frac{2}{p+1}-1}e^{-s}(A_{ss}-A_s)  (s) ,\\
\begin{aligned}
&  \frac{2}{p+1}(e^{-s}A_s(s)  )  ^{\frac{2}
{p+1}-1}(A_{ss}(s)  -A_s(s)  ) \\
&\geq(a_s(0)  +2E_w(0)  )
-2E_w(0)  e^{-s}+\frac{2(p-1)  }{p+1}A(s)  ,
\end{aligned} \\
\begin{aligned}
&\frac{2}{p+1}(e^{-s}A_s(s)  )  ^{\frac{2}{p+1}}e^{-s}(A_{ss}(s) -A_s(s)  ) \\
&  \geq(a_s(0) + 2E_w(0)  )  e^{-2s}A_s(s)  -2E_w(0)  e^{-3s}A_s(s) \\
&\quad  +\frac{2(p-1)  }{p+1}e^{-2s}A_s(s)  A(s)  ,
\end{aligned} \\
\begin{aligned}
&  \frac{2}{p+3}((e^{-s}A_s(s)  ) ^{\frac{p+3}{p+1}}-a_0^{\frac{p+3}{2}}) \\
&  \geq\Big(\Big(a_s(0)  +2E_w(0)
+\frac{p-1}{p+1}A(s)  \Big)  e^s-2E_w(0)\Big)  e^{-3s}A(s)  \geq0
\end{aligned}
\end{gather*}
for some large $s_4$, $s\geq s_5$, since  $a_s(0)  +2E_w(0)  >0$.
Therefore, for $s\geq s_5$,
\begin{gather*}
\begin{aligned}
&  (e^{-s}A_s(s)  )  ^{\frac{p+3}{p+1}}\\
&  \geq a_0^{\frac{p+3}{2}}+\frac{p+3}{2}
\Big(\Big(a_s(0)  +2E_w(0)  +\frac{p-1}{p+1}A(s)  \Big)e^s-2E_w(0)  \Big)  
e^{-3s}A(s) ,
\end{aligned} \\
\begin{aligned}
&  A_s(s) \\
&  \geq\Big(a_0^{\frac{p+3}{2}}+\frac{p+3}{2}
\Big(\Big(a_s(0)  +2E_w(0)  +\frac{p-1}{p+1}A(s)  \Big)
e^s-2E_w(0)  \Big)  e^{-3s}A(s)  \Big)^{\frac{p+1}{p+3}}\\
&  \geq(\frac{1}{2})  ^{\frac{p+1}{p+3}}a_0^{\frac{p+1}{2}}e^s\\
&\quad +  (\frac{1}{2})  ^{\frac{p+1}{p+3}}\Big(\frac{p+3}{2}\Big(
a_s(0)  +2E_w(0)  \\
&\quad +\frac{p-1}{p+1}A(s)  \Big)   e^s-2E_w(0)  \Big)
^{\frac{p+1}{p+3}}e^{-\frac{3(p+1)  }{p+3}s}A(s)
^{\frac{p+1}{p+3}}e^s\\
&  =(\frac{1}{2})  ^{\frac{p+1}{p+3}}a_0^{\frac{p+1}{2}} e^s
+  (\frac{1}{2})  ^{\frac{p+1}{p+3}}(\frac{p+3}{2})
^{\frac{p+1}{p+3}}\Big(\Big( a_s(0) +2E_w(0) \\
&\quad  +\frac{p-1}{p+1} A(s)  \Big)  e^s- 2E_w(0)  \Big)
^{\frac{p+1}{p+3}} e^{-\frac{2p}{p+3}s} A(s) ^{\frac{p+1}{p+3}},
\end{aligned} \\
A(s)  \geq(\frac{1}{2})  ^{\frac{p+1}{p+3}}
a_0^{\frac{p+1}{2}}(e^s-e^{s_5})  +A(s_5).
\end{gather*}
By the same arguments as in the proof of Theorem \ref{thm1}, the assertions in 
can be obtained.
\end{proof}



\section{Nonexistence of global solution when $E_w(0)=0$}

In this section we want to show there is no global solution of \eqref{e0.1}
under zero energy $E_w(0)  =0$, with $u_0(u_1-u_0) >0$.

\begin{theorem} \label{thm3} 
If $T$  is the life-span of $u$  and $u$ is the positive solution of 
\eqref{e0.1} with $E_w(0)  =0$ and
$u_0(u_1-u_0)>0$, then  $T$ is finite. This means that the global solution 
of \eqref{e0.1}  does not exist for $(u_1-u_0)  ^2
=\frac{2}{p+1}u_0^{p+1},\ u_0(u_1-u_0)  >0$.
\end{theorem}

\begin{remark} \label{rmk2} \rm
 If $E_w(0)  =0$, $u_0(u_1-u_0)\leq0$ we conjecture that solutions of
\eqref{e0.1} exist globally and have the same asymptotic behavior as 
that stated in Remark \ref{rmk1}.
Yet, again, we do not have a rigorous proof.
\end{remark}

\begin{proof}
 Using the Lemma \ref{lem2}, \eqref{e0.19}, $E_w(0)
=0$ and $\ u_0(u_1-u_0)  >0$ we obtain 
\begin{gather*}
a_s(s)  =a_s(0)  e^{-s}+(p+3)
K(s)  +(p-1)  \int_0^se^{r-s}K(r) dr>0,\\
a(s)  =a(0)  +a_s(0)  (1-e^{-s})  +(p+3)  
\int_0^sK(r) dr  +(p-1)  \int_0^s\int_0^{r}e^{\eta-r}K(\eta)  d\eta dr,\\
\begin{aligned}
a(s) &=a(0)  +a_s(0)  (1-e^{-s})  +(p+3)  \int_0^sK(r) dr\\
&\quad  +(p-1)  \int_0^s(e^{-r}\int_0^{r}e^{\eta}K(\eta)  d\eta)  dr\\
&  =a(0)  +a_s(0)  (1-e^{-s}) +(p+3)  \int_0^sK(r)  dr\\
&\quad  +(p-1)  \Big(-e^{-s}\int_0^se^{r}K(r)
dr+\int_0^sK(r)  dr\Big) \\
&  =a(0)  +a_s(0)  (1-e^{-s})
+\int_0^s(2(p+1) - (p-1)  e^{r-s})  K(r)  dr\\
&  \geq a(0)  +a_s(0)  (1-e^{-s})
+(p+3)  \int_0^sK(r)  dr.
\end{aligned}
\end{gather*}
By Lemma \ref{lem2}, \eqref{e0.16},
\begin{gather*}
\begin{aligned}
a(s)   &  \geq a(0)  +a_s(0)  (1-e^{-s})  +(p+3)  \int_0^sK(r) dr\\
&  =a(0)  +a_s(0)  (1-e^{-s})
+\frac{p+3}{p+1}\int_0^s2e^{-2r}\Big(\int_0^{r}e^{2\eta} w^{p+1}(\eta)  d\eta\Big) 
 dr\\
&  =a(0)  +a_s(0)  (1-e^{-s})
-\frac{p+3}{p+1}e^{-2s}\int_0^se^{2\eta}w^{p+1}(\eta) d\eta
 +\frac {p+3}{p+1}\int_0^sw^{p+1}(r)  dr,
\end{aligned} \\
\begin{aligned}
a(s) &\geq a(0)  +a_s(0)  (1-e^{-s})  +\frac{p+3}{p+1}\int_0^s(1-e^{2r-2s})
w^{p+1}(r)  dr\\
&  =a(0)  +a_s(0)  (1-e^{-s})
 +\frac{p+3}{p+1}e^{-2s}\int_0^s(e^s+e^{r})
(e^s-e^{r})  w^{p+1}(r)  dr,
\end{aligned} \\
\begin{aligned}
a(s)   &  \geq a(0)  +a_s(0)  (
1-e^{-s})  +\frac{p+3}{p+1}e^{-s}\int_0^s(e^s-e^{r})
w^{p+1}(r)  dr\\
&  =a(0)  +a_s(0)  (1-e^{-s})
+\frac{p+3}{p+1}e^{-s}\Big(\int_0
^{s/2}+\int_{s/2}^s\Big)  (e^s-e^{r})  w^{p+1}(r)  dr,
\end{aligned} \\
\begin{aligned}
\int_0^{s/2}(e^s-e^{r})  w^{p+1}(r)  dr  
&  \geq a(0)  ^{\frac{p+1}{2}}\int_0^{s/2}(e^s-e^{r}) dr\\
&  =a(0)  ^{\frac{p+1}{2}}\big(1+\frac{s}{2}e^s-e^{\frac
{s}{2}}\big)  ,
\end{aligned}\\
\int_{s/2}^s(e^s-e^{r})  w^{p+1}(r)  dr\geq
a(\frac{s}{2})  ^{\frac{p+1}{2}}\big(\frac{s}{2}e^s
+e^{\frac{s}{2}}-e^s\big) ;
\end{gather*}
thus
\begin{align*}
a(s)   &  \geq a(0)  +a_s(0)  (1-e^{-s}) 
 +\frac{p+3}{p+1}e^{-s}\Big\{  a(0)  ^{\frac{p+1}{2}}(
1+\frac{s}{2}e^s-e^{\frac{s}{2}})  \\
&\quad +a(\frac{s}{2})
^{\frac{p+1}{2}}(\frac{s}{2}e^s+e^{\frac{s}{2}}-e^s)
\Big\}  .
\end{align*}
Further, for 
\[
s\geq s_6:=\frac{1}{2}+\frac{p+1}{p+3}(1
-a(0)  -a_s(0)  (1-e^{-s})  )a(0)  ^{\frac{p+1}{-2}}
\]
 we also have
\begin{gather*}
\begin{aligned}
a(s)   &  \geq a(0)  +a_s(0)  (1- e^{-s})  +\frac{p+3}{p+1}\int_0^s(1
-e^{2r-2s})  w^{p+1}(r)  dr\\
& \geq a(0)  +a_s(0)  (1-e^{-s})  +\frac{p+3}{p+1}a(0)  ^{\frac{p+1}{2}}
(s-\frac{1-e^{-2s}}{2}) \\
&  \geq a(0)  +a_s(0)  (1-e^{-s})  +\frac{p+3}{p+1}a(0)  ^{\frac{p+1}{2}}(
s-\frac{1}{2}) \\
&  \geq1,
\end{aligned} \\
\begin{aligned}
(a_{ss}+a_s)  (s)   
&  =2\Big(w( s)  ^{p+1}-\frac{a(s)  }{4}\Big)  
 +2w_s(s)  ^2+\frac{w(s)  ^2}{2}\\
&  \geq2\Big(a(s)  ^{\frac{p+1}{2}}-\frac{a(s) }{4}\Big)  +2| w_sw| (s)  ,
\end{aligned} \\
\begin{aligned}
a_{ss}(s)   &  \geq2a(s)  \Big(a(s)^{\frac{p-1}{2}}-\frac{1}{4}\Big) \\
&  =\frac{a(s)  }{2}\Big(a(s)  ^{\frac{p-1}{2}
}-1\Big)  +\frac{3}{2}a(s)  ^{\frac{p+1}{2}}\\
&  \geq\frac{3}{2}a(s)  ^{\frac{p+1}{2}};
\end{aligned}
\end{gather*}
thus there exists $s_7>s_6$ such that for $s\geq s_7$,
\begin{gather*}
a(s_7)  ^{\frac{p+3}{2}}=-\frac{p+3}{3}a_s^2(s_6)  +2a(s_6)  ^{\frac{p+3}{2}}, \\
\begin{aligned}
(a_s^2(s)  )  _s  &  =2a_s(s) a_{ss}(s) \\
&  \geq3a(s)  ^{\frac{p+1}{2}}a_s(s) \\
&  =\frac{6}{p+3}(a(s)  ^{\frac{p+3}{2}})_s,
\end{aligned} \\
a_s^2(s)     \geq\frac{6}{p+3}a(s)
^{\frac{p+3}{2}}+a_s^2(s_6)  -\frac{6}{p+3}a(s_6)  ^{\frac{p+3}{2}}
 \geq\frac{3}{p+3}a(s)  ^{\frac{p+3}{2}},\\
a_s(s)    \geq\sqrt{\frac{3}{p+3}}a(s)
^{\frac{p+3}{4}}\quad \forall s\geq s_{7},\\
\frac{-4}{p-1}(a(s)  ^{\frac{1-p}{4}})  _s  
=a(s)  ^{-\frac{p+3}{4}}a_s\geq\sqrt{\frac{3}{p+3}}\quad   \forall s\geq s_{7},\\
\frac{-4}{p-1}a(s)  ^{\frac{1-p}{4}}  
 \geq\sqrt{\frac{3}{p+3} }(s-s_7)  -\frac{4}{p-1}a(s_7)  ^{\frac{1-p}{4}}\quad
\forall s\geq s_{7} \\
a(s)  ^{\frac{1-p}{4}}   \leq-\frac{p-1}{4}\Big(\sqrt
{\frac{3}{p+3}}(s-s_7)  -\frac{4}{p-1}a(s_7)
^{\frac{1-p}{4}}\Big);
\end{gather*}
therefore there exists
\[
S_3^{\ast}\leq s_7+\sqrt{\frac{p+3}{3}}\frac{4}{p-1}a(s_7)
^{\frac{1-p}{4}}
\]
such that
\[
a(s)  ^{\frac{1-p}{4}}\to 0\quad \text{for } s\to S_3^{\ast}.
\]
This means that the solution of \eqref{e0.1} does not
exist for all $t\geq1$ and the life-span $T^{\ast}$ of $u$ is finite with
$T^{\ast}\leq\ln S_3^{\ast}$.
\end{proof}

\begin{remark} \label{rmk4} \rm
If we reconsider the solution behavior of the
problem \eqref{e0.1} on $(0,1]$, as one may use the
same transformations as given in Fundamental Lemmas and obtain problems
\eqref{e0.11}--\eqref{e0.13} on the interval 
$-\infty <s\leq0$. On the other hand, by changing variables 
$\tau=-s$, $w(s)  =X(\tau)  $, equation \eqref{e0.11} yields
\begin{gather}
X_{\tau\tau}-X_{\tau}   =X^p,\quad \tau\in(0,\infty), \label{e0.11+} \\
X(0)  =X_0=w(0)  =w_0=u_0, \label{e0.12+} \\
X_{\tau}(0)  =X_1=-w_1=u_0-u_1. \label{e0.13+}
\end{gather}
\end{remark}

In \cite{l7} we estimated the life-span $\tau^{\ast}$ of the positive
solution $X$ of \eqref{e0.11+} in three different cases:
\begin{itemize}
\item[(a)] $X_1=0$, $X_0>0$: $\tau^{\ast}\leq e^{k_1}$, for a suitable $k_1$.

\item[(b)] $X_1>0$, $X_0>0$:
\begin{itemize}
\item[(i)]  $E_{X}(0)  \geq0$, $\tau^{\ast}\leq e^{k_2}$, 
 $k_2:=\frac{2}{p-1}\sqrt{\frac{p+1}{2}}X_0^{\frac{1-p}{2}}$.
\item[(ii)] $E_{X}(0)  <0$, $\tau^{\ast}\leq
e^{ k_3}$, $k_3:=\frac{2}{p-1}\dfrac{X_0}{X_1}$.
\end{itemize}
\end{itemize}
Therefore, the solutions of \eqref{e0.1}  on $(0,1]  $ can not defined on
 this interval but blow up in the interior under such circumstances.


\subsection*{Acknowledgments} 
We want to thank Prof. Klaus Schmitt for his comments and improvements on
writing. We want to thank  Prof. Long-Yi Tsai and Prof. Tai-Ping Liu for
their continuous encouragement and their discussions of this work, 
We want to thank  NSC and Grand Hall for their financial support and 
the referee for his interesting and helpful comments on this work.

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\end{document}
